#help-23
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Wolfram alpha
Input the percentile and I'll get my answer..
OKAY, I THINK THAT'S ALL
THANK YOU SO MUCH SOUTH!
Have a wonderful day!
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i just want someone to confirm part b) for me
is the reason for it because d(x) is not a factor of p(x) and therefore cannot share a common zero?
Intuitively yes, since if they shared a root, the "remainder" polynomial would be zero too.
Which I assume u didnt get in a)?
This fact is due to the factor theorem (for polynomials)
okok
could i have some help w part a)
im a bit confused
what does it mean use long divison
what am i dividing by?
Have you not used the long divion algo. before?
Right, so notice that the equation in a) is solved for k, and if you compare with the equation given there's now a missing x. This confirms our suspicion because the expression on the right of k in a) has one degree lower than the one given..
What do you think we need to divide by now?
wait um what does 1 degree lower mean?
like as in what does it show for polynomials
Do you know what the degree of a polynomial represents?
Odd or even in what sense?
So it's just the highest exponent in the expression (for the x terms in this case)
yes
So they say cubic, and we see that x^3 is the highest one
how does that link to here?
i might be a bit slow
i think its dvided by x correct?
but probably smth more like x-2 or smth?
So dividing a polynomial by another polynomial with degree 1 like ax + b for example lowers the degree of the "highest exponet by 1"
Right!
So solve for k and make sure thats what you have to divide by
wait um
in the equation given
so do i just divide by
x?
is that all?
cos what if its lke x-2 or x-3
or smth
Not quite, it seems you might have some leftover constants too
yeah
When solving for k
how do i find the constant?
like
thats my biggest quesiton
i understnad dividing by x now cos it lowers the power by 1
So while solving for k you'll notice that you have to divide by an expression; it will arrive naturally you dont really to figure out how it'll look as long as you do the algebra right. You'll most definitely get somethhing of degree 1 however like we noted above.
wait so im a little confused now
how do i solve for k then?
do i just do
divided by x?
Try to move the terms without the k coeffient and see if you can maybe factor out a k and then divide by whatever you have to solve for k
And when we do this we'll have to use long division which is why that was hinted at
im sorry im so lost 😭
if u have the itme
could u like write out the working out and send it to me
OH WIAT
DO U MEAN
make k the subject?
and thennn use long division
It's perfectly fine to feel that way, but its worth thinking it trhough
Yes exactly!
Ur welcome you managed to get it by yourself!
wait soryr
im not stuck on part 2
😭
ive maanged to prove k
how would i find this
Since they're using the word "Hence" it makes it seem like the calculation done in part a) makes b) easier now.
Some first thoughts of mine:
Since k and x>0 are integers and x^2 + x + 1 in such case also must be an integer (mult. and addition of integers is an integer).
Then the only concern is 12/(x-1) which has to be an integer since LHS must = RHS, so x -1 must only be positive divisors of 12.
Hopefully this is enough for you to start!
Ur welcome!
wait when the quesiton says
the equation has one postive integer solution for x
does that mean x>0
is that the point of that line
Yes and note however that they say at least one, meaning you might have more such x's that give the same k integer if that makes sense
ohhh
But its not important
so does
so basically if i see
the euqatoin has at least one positive integer solution for x
As long as you find what x's and theyre integers and positive its fine, now you know all k
that means the x has to above zero
Yeah
positive meaning strictly above 0
like
why does one positive integer solution for x mean x has to be positive
i thought it mean that only k had to be positive or msth
oh does solution kind of mean like
find the values of x where it is a positve integer, and k will also be a integer?
Yes! just that the equation is valid. We can find any such x's and k's but while the equation is not actually LHS = RHS.
Also I think it might help to think of this akin to equations such as x - y = 0.
Solving for y we just get y = x where the solution can be interpreted as all the points that lie on the line y = x, the solution of which are the infinite pairs (x, x). And even if x and y here was integers we would still have infinite solutions.
In our case however the restriction is quite important and makes it possible to concretely express all solutions to the equation. Maybe a shift of perspective that helps.
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need some help proving this question
I know A* = A+ y and A+ = (At A)^-1 At
but how A*A = I can prove this
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Yo
are you gonna post a question?
Yo
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I've read some explanations but still don't really understand
pls give me a detail one
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how is this the magnitude?
You can factorise what's inside the square root, so as far as I can see it's the same answer just in a different form
I dont get how to factorize this and get rid of the square root
It's a quadratic in $v^2$, $\sqrt{(v^2 + 2u^2)^2} = (v^2+2u^2)$
TayBee
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How do I get the bounds for phi (I got less than pi/3) but idk if it’s right
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Is linear algebra worth taking after multivariable?
maybe topology instead?
just take both
linear algebra is pretty important. you should have noticed that during multivariable calc
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How many different ways can you seat 11 men and 8 women around a circular table? Only relative positions in the circle can be distinguished
I'm not entirely sure what this is asking? At least the part about relative positions. Can someone point me in the right direction?
@craggy trout Has your question been resolved?
Relative positions means it's relative to each other and not their absolute positions.
Right I am maybe not understanding how that would affect the problem?
Like does that mean there are only 11+8 ways that can be distinguished?
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helolo
what alpha value does a 90 percent confidence interval correspond to?
alright so $\alpha = \frac{1-C}{2}$
y0shi
where C is the confidence level
that table doesn’t contain the confidence level but rather the alpha value, so we have to use this equation
what is the thing that looks like a
alpha
what does it represnt
the cut off value that we use for hypothesis testing, or the tail probability at a certain level of confidence
you don’t really need to know what that is for this
but the table is using this number instead of the confidence level
so (1 -0.90)/2
0.05
i dont know why please explain please
well a t distribution as the degrees of freedom (the numbers on the left most column) goes to infinity approaches a normal distribution
since we are doing a one proportion z interval
we need to use the z score and not the t score
in simpler words, the infinity row shows all the z scores
is that why we dont look at this page instead
you definitely can
but you would have to find 0.05 as the area
and get the z score that way
it’s just more convenient to use the other table
that makes sense thank you very much
ywyw!
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braindead rn,
how do i prove that a product of cyclotomic polynomials of orders d|n is x^n-1?
that is, $\prod\limits_{d\vert n} \Phi_d(x) = x^n-1$
🇵🇸Mína🔆
well, the way i define a cyclotomic polynomial is $\Phi_n(x)=\prod\limits_{\substack{k=0\ \gcd(n,k)=1}}^{n-1} (x-\zeta_n^k)$ where $\zeta_n^k=e^{\frac{2k\cdoti\cdot\pi}{n}}$
Before anything this should be:
$\prod\limits_{d\vert n} \Phi_d(x) = x^n-1$
🇵🇸Mína🔆
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
correct, thank you
Daddy_314
i know that in $\mathbb{C}\ x^n-1$ has $n$ nth rooths of unity, thus
$x^n-1=\prod_{k=0}^{n-1}(x-\zeta_n^k)$
🇵🇸Mína🔆
ok, i wanna get the same product from that, as from this
$\prod_{d\vert n}\Phi_d(x) = \prod_{d\vert n}\prod_{\substack{k=0\ \gcd(k,n)=1}}(x-\zeta_d^k)$
🇵🇸Mína🔆
It's not about being braindead, it's actually not that trivial without some group theory
Do you know the group of roots of unity
yeah i am, is because this is my thesis which i've let to rot for 3 months xd
getting back on track has not been easy
Yes, they form a subgroup of the multiplicative group of the field over which the polynomial x^n-1 splits into linear binomials
And usually utilizes some results
🇵🇸Mína🔆
there is $\varphi(n)$ different primitive nth rooths of unity
🇵🇸Mína🔆
This one is easier to prove, or are you wanting to deduce this from the above
What are you trying to do...

trying to prove this
i can't click through the replies to a bot
In an easy way
can you give me a concrete thing please
I was trying to understand what you were going for and then you sent this
Which has nothing to do here
It's either a result you proved or a result you deduce after

@pastel sinew Has your question been resolved?
let's denote the group of n-th roots of unity $G_n$ and the set of primitive n-th roots of unity $\Omega_n$.
If $a\in G_n$, there exists some $d\vert n$ such that $a\in\Omega_d$ and on the other hand, for all $d\vert n$ if $a\in\Omega_d$ that means that $a\in G_n$. From that it should follow that $G_n$ is a disjoint set union $\bigcup\limits_{d\vert n}\Omega_d$ but I don't immediately see how that should be disjoint.
🇵🇸Mína🔆
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@pastel sinew Has your question been resolved?
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How do we solve fraction equations to solve for a variable in grade 9 algebra. Like an example is -11/5 = -2 + n
Ideally you'd keep n on the side that keeps it positive. That just makes it simpler to think about.
No, you never move the equals sign
oh
ohhhhhhh
yea yeah
mb
right
where did the 2/1 come from
wait wait
so
u did
-11/5 = -22/10
and then
2/1 = -22/10
wait no
BRO IM SO LOST HOLY FCK
wait
OH RIGHT
RIGH
yeah cause
ok
ok
yeah
right
-1/5
so thatsd the answer?
ok ok ok
thanks g
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I don't know how to approach this question
What do you understand by the phrase 'comes to rest'?
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how to get area of rectangle
@fickle rapids Has your question been resolved?
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try sine theorem
how
I'm just Grade 9
I only know this method may help you
I don't know how to apply it on radians
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Trace or graph the¿alture?
I don't know the name of It in this language but basically graph the line with is perpendicular to QS
Starting from the Vertex R
With that you can do realize the length of QS in terms of x (the angle you put)
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do you know the factor theorem?
yes i do
if x - a is a factor of f(x), then f(a) = 0
but it has p inside it
then here if you substitute p, it should evaluate to 0
so would i just keep testing values basically?
just here a = p
is that all?
yep
because the inside
has p as well
like its on the other side of the equation
4p^3 - (10p - 1)p^2 + (6p^2 - 5)p + 6 = 0
i thought normally for x-1
doesnt matter
oh
youd get this
wdym keep testing
wait
so
can u explain
what i would have to do again>
?
do i just set the whole thing has to equal zero ?
and then solve for p?
wait how come x becomes p?
because f(p) = 0
so i substitute p for x and set the equation to 0
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You have made no attempt
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Hi all

Thanks !
ask, if anyone can help, they will
no trolling in the doubt channels
This question came in the exam man
what exam
My final term exam
and how did you clear the doubt on that exam
what do you think the answer should be
ren
Yes\
is 10
fr fr
Bruh
if it was stated as 8/2(2+2) then that's not the right interpretation
ik
would be (8/2)(2+2) under the usual rules of precedence
?
@light shoal you are right I agree
but it's also a standard meme/troll style question
No man I am not used to trolling people
"not used to trolling ppl" 
I actually hate trolling
.close
no i'm not saying you are, but this type of question shows up in memes all the time
u cant do that helpfuls can
Oh
the answer is that it's ambiguous
im helpful the asnswer is 10
anyway, back to the question
shhhhh
BRO MAYBE MY TEACHER IS TROLLIN ME IN THE EXAM
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
WTH
do this please
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$(1+x)\sum^{\infty}{k=0}(-1)^k\frac{x^k}{k!}-(1-x)\sum^{\infty}{k=0}\frac{x^k}{k!}=\sum^{\infty}{k=0}((-1)^k-1)\frac{x^k}{k!}-\sum^{\infty}{k=0}((-1)^k+1)\frac{x^{k+1}}{k!}$\\
how come these two are equal?
Slowaq
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@trail otter Has your question been resolved?
@trail otter Has your question been resolved?
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Yo
I need help with this
?
I dont get it
I want someome to do an example or 2 for me and explain along the way
ok b4 i help
k
do you understand a domain and a range?
Do you understand what the domain and range are
...
Yes
Okay, so tell me what a domain is then
Domain is all possible values of x and range is all possible values of y
Ffs
ok @fair steppe look
Domain is the set of all x-coordinates like (1,1) (2,1) (3,1) etc
Range is the set of all y-coordinates (1,2) (1,3) and so on
Fair enough, just trying to make sure we're all on the same page
That's not quite right actually
it is .....
Yea I understand
The domain would just be {-3, 1, 1, 3, 5}
Yeah you wrote both coordinates
The domain can't be a set of coordinates
Is the 1 always on the right side for domain?
depends on the coordinates
Here's the thing is it always those numbers?
No
Ok
No
It of course depends on the function
nope
Alr
So when you have points, the domain and range are just a collection of numbers
But when your function is continuous
I see
south
Or you can have the real numbers as your domain
Most of the time, the domain will be the real numbers, so all possible x
Yep I learned about the real numbers today
You will also have functions like $\frac{1}{x}$ where the domain is just all real $x$ except $x = 0$
south
Nice
Alr
And there's functions like y = ln(x) where the domain is x > 0 for real x
(ln(x) is the mirror image of y = e^x across the line y = x cause it's the inverse function, you might get to that one later)
So in summary, for a table or for when the graph has isolated points, just look at the possible x-values (domain) and y-values (range) for the points
For a continuous function you do the same thing, but you have infinitely many points, so your domain and range will be inequalities
Yeah I don't get that exactly
Here is an example of continuous curve, shape of curve doesn't matter
For a continuous function you can imagine trying to draw a rectangle around your function
You'll come to it if you haven't studied logs and exponential functions yet
Oh so the shape doesn't matter?
The smallest rectangle actually
Yeah I haven't yet
If it is continuous
I see
And then the range of x and y values of the rectangle is your domain and range
What about one that isn't?
So the ones with dots aren't continuous
Anything you can't draw without your pen leaving the paper isn't continuous
Then you have to write seperate domain and ranges and use AUB if there are multiple curves
AUB?
You know set theory right?
Idk that
Oh you'll study that later
Alr hopefully
My teacher is ass
4 out of 31 students are passing with 50s
Highest mark is a 70 and the student is cheating 😭
Anyways I appreciate your guys help
Ima also ask a teacher for help during lunch in a bit
Yeah ima watch them
Cool
I got them saved to watch later
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im doing combinatorics and im stuck on why Σ(j=0 to infinity):[n k]*t^k= 1/(1-t)^n where [n k] = (n+k-1 choose k) nεN
Please use proper formatting, LaTeX / MathJax etc
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idk how to do that
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is this wrong
I don't think I believe the djvj to dj^2 step
it'd probably be an inequality there I'm guessing
yea it's this, called cauchy-schwarz inequality
although if you're maxing it I guess it is equals and fine?
guess it's all true
it isnt the whole thing squared though is it? its just (uivi)^2?
oh true I wonder what that's called
like for n=2 this isn't always true right
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Hi can some one solve this?
do you know what kind of series this is?
@fluid escarp Has your question been resolved?
@fluid escarp ?
Geomerric?
Geometric?
there is a formula for geometric series
@fluid escarp Has your question been resolved?
Yes
But how it solvea with it
@fluid escarp Has your question been resolved?
Ok but it didnt worked
What did you get?
1-(1/4)^infinity
Over
1-1/4
Two mistakes, what is a, and why do you have infinity in your answer?
Oh ok i find my mistake
I use this formula:
It should be 4/3 right?
No, what is r?
No
It was the answer
Then multiply 3
The answer is 4 right?
@fluid escarp Has your question been resolved?
That is correct
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idk where to start w/ this question
Hey khat!
I’d start as follows:
The question is asking you “how to do something” so that profit is maximized. Therefore I should be able to calculate profit (no matter what the something is, I’m gonna need to be able to calculate profit to deal with it)
So, how would you calculate profit?
Say the profit of the company if they make 60 cars per month and sell them at 800+fp where fp is the factory price
The profit would then be 800*60
Per month
So say that they mark up by 20c where we are trying to find c
find the direction in which the Uf of f(x,y)=ye^-xy at (0,2) has value of 1
Or do that…
isnt it (800+fp)*60
But you have paid fp to make the car!
So your clear profit is only the 800
That’s why they don’t specify the value of fp
You can think of it like this:
To make a car you pay fp and you get 800+fp so that the profit would be (800+fp-fp)60
@obsidian fractal Has your question been resolved?
im still confused
maybe im js not reading something properly or im just tired af but i dont rly get either explanation for why u dont add fp or how u get the equation from the question
thw question is asking about how much profit you get
like if you buy something for $5 and sell it for $15 (geez how much did you rip someone off), your profit is $15-$5 ($5 is your 'fp'), which is $10, not $15 that you sold it
oh texit never needed u here bro i was just talking about money
why did the other dude even mention it then
s/he didn't need to but just telling you what profit meant
cuz if you didn't know the definition of profit or how to work it out you can't understand the question
well thats one thing
but i also dont get how i make the equation with the stuff given
so the profit would you gain from 1 car is 800, where you sell 60 cars per month, right? then, every extra $20 you make from 1 car will decrease the total sales by 1 car
thats all the information you need to make the equation from
ok i have the equatio
n
(60-1x)(800+20x)
how do i find x so profit is maximized
good thats ur 1st step
now its hard to explain but you can see that for exery extra $20 you lose 1 car so the money difference = +20(60) and -1(800+20x) or -1(800) + 20*(59)
so like u find a point where when u take away 1 car and times it by 800+20x is the same as the cost of 1 car (sry im bad at explaining this
)
❓
<@&286206848099549185>
?
?
yes
but why did you ping when someone else is helping you?
oh wait, that's 15 mins ago
Makes sense
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How would I do this q? I did u=ln(x) and then I got intergral of u/x du but idk if I did anything wrong
are you familiar with integration by parts
I've done it before but I wouldn't say I'm too good at it
so that is recommended method of solving integral such as this
Okay nvm I can't do derivaives anymorw
You know the formula uv - integral vdu?
Ngl I need to go over this again
Okay, do you still need help with the problem or do you just want to take time and learn IBP urself
I'll redo the chapter
Alright 👍
@crisp gyro Has your question been resolved?
either you can do IBP, or IBS
me personally i prefer IBP
what’s IBS
int by sub
oh I’ve only ever seen people call it u sub
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could someone explain the step made in red?
Expanding (2m+1)!
(2m+1)!=(2m+1)(2m)(2m-1)(2m-2)(2m-3)...(2)(1)
We can notice that (2m-2)(2m-3)...(2)(1) is actually (2m-2)!
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there are 2 boys and 4 girls, they will be in groups of 3, what is the chance of the 2 boys being together in a group
What did you try?
Now calculate the number of groups that contains 2 boys
4C1 = 4?
4/20?
but answer is 0.4
Rly? Let me check
what did you get?
it was an instagram post lol
Maybe i am getting braindead but i get 20%
You count the two boys as 1
ye it isnt permutation
Maybe he forgot about that
i consider one group only
oh
wait
total number of groups might be 10
because there are 2 of them
its repeated
imagine ABC, DEF
Oh we treated differently in both scenarios
DEF is already counted
what do you mean?
thanks, i havent learnt about combinations yet but im interested in it
I tricked myself xd
i watched many youtube videos but they are all about letters
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- Idk where to start
Do you know the Quadratic formula?
Yep
Do I use that?
You can
using the discriminant component is enough
Yeah
Idk that one
So, if the general solution of this equation is $\frac{-b (+-) \sqrt{b^2-4ac}}{2a}$
Palahoo
So I can only use this instead?
It's the same thing
The discriminant (D) is equal to b²-4ac
So, as the equation has only one solution, the discriminant needs to be equal to zero
So (k)^2-4(4)(9)?
Yes
It needs to be equal to zero
k^2-144=0?
Yes
Notice that k has two solutions
So if I factor it’s gonna be (k-72)(k-72)=0
12
Oh
(k-12)(k+12)
It has the solutions 12 and -12
Can I find the roots dividing it by 2?
And i got 72
Is there another way
To find roots
With big numbers like that
You mean dividing (k-12)(k+12) by 2 and get (k-72)(k+72)
?
No like 144
How do I factor this fast
Cuz I divided it by 2
To find the factor
Remarkable products
(a+b)(a-b)=a²-b²
Oh idk that maybe I should study that first
Ohhh
So (k-144)(k+144)=k^2+144^2?
To find the root of 144?
-144²
Not plus
But -(-144)
Since its k^2-144=0
?
No
How?
(a+b)(a-b)=a²-b², so we can conclude that a²=k² and b²=144
?
Oh
(-144)^2= -(144)=-144
(k+12)(k-12)=k²+12k-12k-12.(+12)=k²-144
No
Like how do u find the root
Of 144
That fast
That’s just expansion
Yes
?
No I’m talking abt 144
When you get used with numbers, you find the things faster
Then what were all those
😭😭
So that’s the only way?
Ok helper is gone
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How to do this?
Let y=vx
I don't understand
They‘re suggesting a substitution
Substitute what?
y/x = v
Ohh
So you get a more manageable form
you shouldn‘t have dy/dx, it should be something with dv no? Unless I‘m missing something
Well, I don‘t have much experience with differential equations, but I think you‘d want to have a dv/dx there?
Then you should be able to integrate both sides
But I may be wrong, so I‘ll go ask in the helper channel if someone wants to fact check this and help you :)
Okay
the result should be separable once you rearrange everything
Okay so I wasn‘t just blurting out random crap. Thanks Desync
Ohh kkay
Thank you
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Help anyone? I've been trying to desperately find what this equation even is like i've searched youtube and google, some modules and there's NONE. Does anyone know what type this is? Example problem: If sin β = - 3/5 and tan β > 0, what is the exact value of cos² β-sin² β?
Hmmm
also the next step for the solution to that problem is like sin β = - 3/5 cos β = - 4/5 but where did they get the 4?
oops wrong numbers fixed
Oh
Pythagoras
by drawing a 3-4-5 right triangle
wait i'll check
so like
i'm sorry i'm slow but what do you mean by drawing a right triangle, like literal? cause it was just numbers
yes
trig functions relate angles to the sides of triangles
draw right angle triangle
abc
with b as the right angle
hpy is 5
and opp of angle beta is -3
by Pythagorus
we get 4
not -4
hm
wait let me type in the solution, It doesn't say to make a triangle, its so confusing. Give me a few seconds please
here
sin β = - 3/5 cos β = - 4/5
cos² β - sin² β = (- 4/5)² - ( - 3/5 )²
= 16/25 = 9/25 = 7/25
= 7/25
I kind of do get it but can't comprehend where the 4 was taken
is it pythagoras?
yes
see If we take AC to be the larger side
AC^2=AB^2+BC^2
you can move AC and other sides
I'm sorry but what does that mean, what AC?
the sides let me send a pic
okay
/yes?
you mean the overall answer would be 34?
but the choices were either a.) - 1/5 b.) 7/25 c.) 1 d.) -1 (By the way I am not cheating this is a reviewer with already provided answers)
wait
I can't make an over but its like negative 3/5
like both?
let me write it i'll send a picture
ok send
like that negative
help someone, I'm losing my minddd
how did 4 get there when and why
We have sin(x) to be negative, which means x cannot be in the first or second quadrant , also tan(x) is positive means x must exist in the third quadrant only .
And in the third quadrant cosine(x) is negative.
So cos²(x)=1-sin²x
=16/25
=>cos(x)=4/5 or -4/5 .
But we know cosine(x) is negative. So cos(x)=-4/5
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sorry can you explain it again? I really can't understand i'm bad at math
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what did you mean by the x?
I didn't get the 4
Well x is just β , we can write anything, writing x is faster than writing β
Do you know about sin²x+cos²x=1??
No
Well then can you tell me exactly how much trigonometry you know ? Because, these are very basic things.
I actually don't know any, I'm in a strand that removed math and I'm trying to know all these equations for a try in scholarship
I don't even know why they removed it, its literally so important
Do you know what sine of an angle is ? Like it is opposite over hypotenuse that much ?
I would recommend you pick up any book on trigonometry and read the first few pages .. the. You can have a solid idea .
If they will be asking questions on the scholarship test , it is best to skip the parts you are weak in like trigonometry, and focus on your strong areas .
its more like a written test
Trigonometry is based entirely on Pythagoras, but for that you have to know what basic definitions of sin(x) , cos(x) , tan(x) are
won't I fail though? math is like a major subject especially if the ones they accept are pretty much stem students
What topics in math are you strong in then ? Otherwise your chances to get the scholarship are dim .
well I'm going to be honest, I don't really excel at math and I focus on English more but I'll try searching trigonometry, calculus and such, the other problems here I'm so not sure what equation they even are though
Yeah in any examination, it is the best strategy to excel in your strong points , and maybe ditch the parts you are weak in , myself I have given multiple exams in STEM that's why I know this .
I will give you a brief preface of what's going on , but here's your strategy if you want to do something with math :
- get past math questions from the test
- identify which topics they ask the most
- pick up a book (download pdf) and read the basics of that particular topic and practice a few questions
oh, I'll try that but usually whenever I read through a book and they give a few solutions, the practice problem always comes out different? Example is the equation I gave earlier, its gonna say cos β (sample number) and sin β < 0 and so on, are they supposed to have the same solution format? if that makes any sense (sorry not my native language)
it like, switched it up, is it supposed to be different?
Yeah sin and cos can switch up definitions based on the β they take in ..
happens to every single module I come up with
For trig you definitely need to know the unit circle in all four quadrants
You have to know what sin and cos really are . There are some tutorials on YouTube which you can follow , like Khan academy is good for basics
cos theta is the x-coordinate of a point with angle theta, and sin theta is the y-coordinate
but is their solution format the same? but how do I know which is which? for example the other person that said about a triangle with A, B, and C. Lets say they 2 numbers are on A and B as the problem with solution was given, the next problem they make me solve is through B and C, its confusing (not accurate just example)
Oh thanks, I'll look into their content
Just watch the first few videos on trigonometry, they will clear all your doubts on what trigonometry is , you won't have any doubts with solution formats anymore .
So yeah, you can break down your study approach into:
- Unit circle: signs of sin, cos, and tan for all 4 quadrants (and these are the same signs of csc, sec, and cot as the reciprocal 1/x doesn't change the sign of a number)
- Using trig identities: Pythagorean identity cos^2 x + sin^2 x = 1, double-angle identities, and sin(A + B) and cos(A + B) if you have time
- Solving trig equations such as sin x = sqrt(3)/2: group sin and cos together cause their period is 2pi, and do tan separately cause its period is pi
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*algebra
one sec, lemme just scan this rq
what have you tried
...?
what do you mean it's a test
<@&268886789983436800>
bro
we can't help with tests
im sorry
why would it be
no
we want to help others learn

we aren't here to do your homework for you or hand out free marks
well, my guy, then use your learnt material to do the test
Then come with the same question after school
i'm afraid we cannot, and will not, aid you in this task
goodbye
yea exactly
you're worried abt marks not abt the actual question
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Brooooo
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I think i'm stupid
Solve y'' + 3y' + 2y = 0 first
Then your particular solution is going to be in the form $y_p = ax^2 + bx + c$
south
A quadratic double-differentiates down to a constant
how do you know this
Sub the particular solution in and compare coefficients to find a, b, c
is that always the case when the right side is a constant?
Yeah, it's going to be another polynomial for sure if the RHS is a polynomial