#help-23

1 messages · Page 222 of 1

brittle raptor
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So I just use

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Wolfram alpha

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Input the percentile and I'll get my answer..

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OKAY, I THINK THAT'S ALL

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THANK YOU SO MUCH SOUTH!

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Have a wonderful day!

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.close

safe radishBOT
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vagrant ice
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No worries

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Have a great day, you too!

safe radishBOT
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leaden glade
safe radishBOT
leaden glade
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i just want someone to confirm part b) for me

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is the reason for it because d(x) is not a factor of p(x) and therefore cannot share a common zero?

long oracle
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Intuitively yes, since if they shared a root, the "remainder" polynomial would be zero too.

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Which I assume u didnt get in a)?

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This fact is due to the factor theorem (for polynomials)

leaden glade
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yes in a)

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im left w

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a remainder of 25

leaden glade
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could i have some help w part a)

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im a bit confused

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what does it mean use long divison

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what am i dividing by?

long oracle
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Have you not used the long divion algo. before?

leaden glade
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i have

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but like

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im not sure what im dividng by

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like

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how do i find K

long oracle
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Right, so notice that the equation in a) is solved for k, and if you compare with the equation given there's now a missing x. This confirms our suspicion because the expression on the right of k in a) has one degree lower than the one given..

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What do you think we need to divide by now?

leaden glade
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wait um what does 1 degree lower mean?

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like as in what does it show for polynomials

long oracle
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Do you know what the degree of a polynomial represents?

leaden glade
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um

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well

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it shows if its odd or even right

long oracle
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Odd or even in what sense?

leaden glade
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well

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wait could u jsut tell me

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please

long oracle
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So it's just the highest exponent in the expression (for the x terms in this case)

leaden glade
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yes

long oracle
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So they say cubic, and we see that x^3 is the highest one

leaden glade
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i might be a bit slow

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i think its dvided by x correct?

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but probably smth more like x-2 or smth?

long oracle
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So dividing a polynomial by another polynomial with degree 1 like ax + b for example lowers the degree of the "highest exponet by 1"

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Right!

leaden glade
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yes!

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i got that

long oracle
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So solve for k and make sure thats what you have to divide by

leaden glade
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wait um

long oracle
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in the equation given

leaden glade
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so do i just divide by

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x?

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is that all?

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cos what if its lke x-2 or x-3

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or smth

long oracle
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Not quite, it seems you might have some leftover constants too

leaden glade
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yeah

long oracle
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When solving for k

leaden glade
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how do i find the constant?

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like

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thats my biggest quesiton

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i understnad dividing by x now cos it lowers the power by 1

long oracle
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So while solving for k you'll notice that you have to divide by an expression; it will arrive naturally you dont really to figure out how it'll look as long as you do the algebra right. You'll most definitely get somethhing of degree 1 however like we noted above.

leaden glade
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wait so im a little confused now

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how do i solve for k then?

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do i just do

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divided by x?

long oracle
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Try to move the terms without the k coeffient and see if you can maybe factor out a k and then divide by whatever you have to solve for k

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And when we do this we'll have to use long division which is why that was hinted at

leaden glade
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im sorry im so lost 😭

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if u have the itme

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could u like write out the working out and send it to me

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OH WIAT

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DO U MEAN

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make k the subject?

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and thennn use long division

long oracle
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It's perfectly fine to feel that way, but its worth thinking it trhough

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Yes exactly!

leaden glade
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OHHH

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OKOK

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thank u so much

long oracle
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Ur welcome you managed to get it by yourself!

leaden glade
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wait soryr

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im not stuck on part 2

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😭

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ive maanged to prove k

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how would i find this

long oracle
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Since they're using the word "Hence" it makes it seem like the calculation done in part a) makes b) easier now.

Some first thoughts of mine:
Since k and x>0 are integers and x^2 + x + 1 in such case also must be an integer (mult. and addition of integers is an integer).

Then the only concern is 12/(x-1) which has to be an integer since LHS must = RHS, so x -1 must only be positive divisors of 12.

Hopefully this is enough for you to start!

leaden glade
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ohhh

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wait that helps a lot

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thank u

long oracle
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Ur welcome!

leaden glade
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wait when the quesiton says

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the equation has one postive integer solution for x

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does that mean x>0

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is that the point of that line

long oracle
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Yes and note however that they say at least one, meaning you might have more such x's that give the same k integer if that makes sense

leaden glade
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ohhh

long oracle
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But its not important

leaden glade
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so does

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so basically if i see

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the euqatoin has at least one positive integer solution for x

long oracle
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As long as you find what x's and theyre integers and positive its fine, now you know all k

leaden glade
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that means the x has to above zero

long oracle
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Yeah

leaden glade
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also what exactly

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does solution mean

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in this case

long oracle
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positive meaning strictly above 0

leaden glade
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like

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why does one positive integer solution for x mean x has to be positive

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i thought it mean that only k had to be positive or msth

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oh does solution kind of mean like

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find the values of x where it is a positve integer, and k will also be a integer?

long oracle
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Yes! just that the equation is valid. We can find any such x's and k's but while the equation is not actually LHS = RHS.

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Also I think it might help to think of this akin to equations such as x - y = 0.
Solving for y we just get y = x where the solution can be interpreted as all the points that lie on the line y = x, the solution of which are the infinite pairs (x, x). And even if x and y here was integers we would still have infinite solutions.

In our case however the restriction is quite important and makes it possible to concretely express all solutions to the equation. Maybe a shift of perspective that helps.

safe radishBOT
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@leaden glade Has your question been resolved?

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wide obsidian
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need some help proving this question

safe radishBOT
wide obsidian
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I know A* = A+ y and A+ = (At A)^-1 At

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but how A*A = I can prove this

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<@&286206848099549185>

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@wide obsidian Has your question been resolved?

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glossy cedar
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Yo

safe radishBOT
peak estuary
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are you gonna post a question?

limpid light
versed wave
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wheres the question

glossy cedar
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Yo

safe radishBOT
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@glossy cedar Has your question been resolved?

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fossil nimbus
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I've read some explanations but still don't really understand

fossil nimbus
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pls give me a detail one

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narrow vault
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how is this the magnitude?

safe radishBOT
narrow vault
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I would assume the magnitude is just each term squared

hoary wind
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You can factorise what's inside the square root, so as far as I can see it's the same answer just in a different form

narrow vault
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I dont get how to factorize this and get rid of the square root

hoary wind
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It's a quadratic in $v^2$, $\sqrt{(v^2 + 2u^2)^2} = (v^2+2u^2)$

flat frigateBOT
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TayBee

narrow vault
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oh true

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thanks

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.close

safe radishBOT
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haughty pewter
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How do I get the bounds for phi (I got less than pi/3) but idk if it’s right

safe radishBOT
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wind echo
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Is linear algebra worth taking after multivariable?

wind echo
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maybe topology instead?

peak estuary
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just take both

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linear algebra is pretty important. you should have noticed that during multivariable calc

safe radishBOT
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craggy trout
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How many different ways can you seat 11 men and 8 women around a circular table? Only relative positions in the circle can be distinguished

I'm not entirely sure what this is asking? At least the part about relative positions. Can someone point me in the right direction?

safe radishBOT
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@craggy trout Has your question been resolved?

chilly lance
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Relative positions means it's relative to each other and not their absolute positions.

craggy trout
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Right I am maybe not understanding how that would affect the problem?

craggy trout
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@craggy trout Has your question been resolved?

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signal cove
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helolo

safe radishBOT
signal cove
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how did he know to look at this table this sspecfifc one

inner parrot
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what alpha value does a 90 percent confidence interval correspond to?

signal cove
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i do not know

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can you elebaorat epleas

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please

inner parrot
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alright so $\alpha = \frac{1-C}{2}$

flat frigateBOT
inner parrot
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where C is the confidence level

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that table doesn’t contain the confidence level but rather the alpha value, so we have to use this equation

signal cove
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what is the thing that looks like a

inner parrot
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alpha

signal cove
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what does it represnt

inner parrot
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the cut off value that we use for hypothesis testing, or the tail probability at a certain level of confidence

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you don’t really need to know what that is for this

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but the table is using this number instead of the confidence level

signal cove
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so (1 -0.90)/2

inner parrot
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yep

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which would correspond with

signal cove
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0.05

inner parrot
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yep

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do you know why we look at the infinity row?

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or are you good now

signal cove
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i dont know why please explain please

inner parrot
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well a t distribution as the degrees of freedom (the numbers on the left most column) goes to infinity approaches a normal distribution

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since we are doing a one proportion z interval

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we need to use the z score and not the t score

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in simpler words, the infinity row shows all the z scores

signal cove
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is that why we dont look at this page instead

inner parrot
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you definitely can

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but you would have to find 0.05 as the area

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and get the z score that way

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it’s just more convenient to use the other table

signal cove
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that makes sense thank you very much

inner parrot
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ywyw!

signal cove
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.clsoe

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.close

safe radishBOT
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pastel sinew
#

braindead rn,

how do i prove that a product of cyclotomic polynomials of orders d|n is x^n-1?

pastel sinew
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that is, $\prod\limits_{d\vert n} \Phi_d(x) = x^n-1$

flat frigateBOT
#

🇵🇸Mína🔆

pastel sinew
#

well, the way i define a cyclotomic polynomial is $\Phi_n(x)=\prod\limits_{\substack{k=0\ \gcd(n,k)=1}}^{n-1} (x-\zeta_n^k)$ where $\zeta_n^k=e^{\frac{2k\cdoti\cdot\pi}{n}}$

halcyon flame
flat frigateBOT
#

🇵🇸Mína🔆
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

pastel sinew
#

correct, thank you

flat frigateBOT
#

Daddy_314

pastel sinew
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i know that in $\mathbb{C}\ x^n-1$ has $n$ nth rooths of unity, thus
$x^n-1=\prod_{k=0}^{n-1}(x-\zeta_n^k)$

flat frigateBOT
#

🇵🇸Mína🔆

pastel sinew
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$\prod_{d\vert n}\Phi_d(x) = \prod_{d\vert n}\prod_{\substack{k=0\ \gcd(k,n)=1}}(x-\zeta_d^k)$

flat frigateBOT
#

🇵🇸Mína🔆

halcyon flame
#

Do you know the group of roots of unity

pastel sinew
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getting back on track has not been easy

halcyon flame
#

Yea its not that easy

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But a big classic

pastel sinew
halcyon flame
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And usually utilizes some results

pastel sinew
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okkk

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$\sum\limits_{k\vert n}\varphi(k)=n$

flat frigateBOT
#

🇵🇸Mína🔆

pastel sinew
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there is $\varphi(n)$ different primitive nth rooths of unity

flat frigateBOT
#

🇵🇸Mína🔆

pastel sinew
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the degree holds

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i am just

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so

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stupid

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@raven vessel

halcyon flame
#

What are you trying to do...

pastel sinew
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trying to prove this

halcyon flame
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Or proved from scratch

pastel sinew
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i can't click through the replies to a bot

halcyon flame
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In an easy way

pastel sinew
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can you give me a concrete thing please

halcyon flame
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Which has nothing to do here

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It's either a result you proved or a result you deduce after

pastel sinew
safe radishBOT
#

@pastel sinew Has your question been resolved?

pastel sinew
#

let's denote the group of n-th roots of unity $G_n$ and the set of primitive n-th roots of unity $\Omega_n$.
If $a\in G_n$, there exists some $d\vert n$ such that $a\in\Omega_d$ and on the other hand, for all $d\vert n$ if $a\in\Omega_d$ that means that $a\in G_n$. From that it should follow that $G_n$ is a disjoint set union $\bigcup\limits_{d\vert n}\Omega_d$ but I don't immediately see how that should be disjoint.

flat frigateBOT
#

🇵🇸Mína🔆

pastel sinew
#

<@&286206848099549185>

safe radishBOT
#

@pastel sinew Has your question been resolved?

safe radishBOT
#

@pastel sinew Has your question been resolved?

safe radishBOT
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plain spear
#

How do we solve fraction equations to solve for a variable in grade 9 algebra. Like an example is -11/5 = -2 + n

plain spear
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so we first move the n to the left?

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and it becomes -n

acoustic kestrel
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Ideally you'd keep n on the side that keeps it positive. That just makes it simpler to think about.

plain spear
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ohhh m mb

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so you put the = sign to the right side

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of the equation

acoustic kestrel
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No, you never move the equals sign

plain spear
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oh

acoustic kestrel
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You move numbers to either side of the equals sign

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Does that make sense?

plain spear
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ohhhhhhh

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yea yeah

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mb

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right

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where did the 2/1 come from

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wait wait

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so

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u did

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-11/5 = -22/10

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and then

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2/1 = -22/10

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wait no

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BRO IM SO LOST HOLY FCK

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wait

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OH RIGHT

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RIGH

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yeah cause

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ok

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ok

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yeah

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right

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-1/5

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so thatsd the answer?

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ok ok ok

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thanks g

safe radishBOT
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plain spear
#

.close

safe radishBOT
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lean otter
#

I don't know how to approach this question

safe radishBOT
hoary wind
#

What do you understand by the phrase 'comes to rest'?

safe radishBOT
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@lean otter Has your question been resolved?

safe radishBOT
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fickle rapids
safe radishBOT
fickle rapids
#

how to get area of rectangle

safe radishBOT
#

@fickle rapids Has your question been resolved?

fickle rapids
#

<@&286206848099549185>

bright bramble
#

try sine theorem

fickle rapids
bright bramble
#

I'm just Grade 9

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I only know this method may help you

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I don't know how to apply it on radians

safe radishBOT
#

@fickle rapids Has your question been resolved?

fickle rapids
#

<@&286206848099549185>

proud vessel
#

Trace or graph the¿alture?

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I don't know the name of It in this language but basically graph the line with is perpendicular to QS

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Starting from the Vertex R

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With that you can do realize the length of QS in terms of x (the angle you put)

safe radishBOT
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@fickle rapids Has your question been resolved?

safe radishBOT
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leaden glade
safe radishBOT
icy lance
winged flare
leaden glade
#

yes i do

winged flare
#

if x - a is a factor of f(x), then f(a) = 0

leaden glade
#

but it has p inside it

winged flare
#

then here if you substitute p, it should evaluate to 0

leaden glade
#

so would i just keep testing values basically?

winged flare
#

just here a = p

leaden glade
#

is that all?

winged flare
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yep

leaden glade
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has p as well

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like its on the other side of the equation

winged flare
#

4p^3 - (10p - 1)p^2 + (6p^2 - 5)p + 6 = 0

leaden glade
#

i thought normally for x-1

winged flare
leaden glade
#

oh

winged flare
leaden glade
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ohhh

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ok so i just

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keep testing

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basically

winged flare
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wdym keep testing

leaden glade
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wait

#

so

#

can u explain

#

what i would have to do again>

#

?

#

do i just set the whole thing has to equal zero ?

#

and then solve for p?

leaden glade
winged flare
#

so i substitute p for x and set the equation to 0

leaden glade
#

ohhh okok

#

thank u

#

i got it now

safe radishBOT
#

@leaden glade Has your question been resolved?

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leaden glade
safe radishBOT
#

@leaden glade Has your question been resolved?

spice furnace
#

You have made no attempt

leaden glade
#

.close

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honest sequoia
#

Hi all

safe radishBOT
honest sequoia
#

I have a doubt

#

Can anyone clear it

#

??

desert pasture
honest sequoia
#

Thanks !

desert pasture
#

ask, if anyone can help, they will

honest sequoia
#

What is the answer of 8/2(2+2) ?

#

This literally has two answers

light shoal
#

no trolling in the doubt channels

honest sequoia
#

This question came in the exam man

light shoal
#

what exam

honest sequoia
#

My final term exam

light shoal
#

and how did you clear the doubt on that exam

honest sequoia
#

Bro ...

#

I am asking the doubt as it is not cleared

#

Plz help me

light shoal
#

what do you think the answer should be

frozen marlin
#

okay first of all

#

this is what u mean right

flat frigateBOT
honest sequoia
#

Yes\

frozen marlin
#

i mean

#

this is self explanatory

rose plume
#

is 10

frozen marlin
#

fr fr

honest sequoia
#

Bruh

light shoal
#

if it was stated as 8/2(2+2) then that's not the right interpretation

frozen marlin
#

ik

light shoal
#

would be (8/2)(2+2) under the usual rules of precedence

frozen marlin
#

?

honest sequoia
#

@light shoal you are right I agree

light shoal
#

but it's also a standard meme/troll style question

frozen marlin
#

eh

#

is fine

honest sequoia
#

No man I am not used to trolling people

frozen marlin
#

"not used to trolling ppl" opencry

honest sequoia
#

I actually hate trolling

rose plume
#

.close

frozen marlin
#

ok ok whatever

#

doesn't matter

light shoal
frozen marlin
honest sequoia
#

Oh

light shoal
#

the answer is that it's ambiguous

rose plume
#

im helpful the asnswer is 10

frozen marlin
#

anyway, back to the question

frozen marlin
honest sequoia
#

BRO MAYBE MY TEACHER IS TROLLIN ME IN THE EXAM

frozen marlin
#

yo alex

#

!xy

safe radishBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

honest sequoia
#

WTH

honest sequoia
#

Ok my doubt is cleared

#

Thanks all !

frozen marlin
#

...?

#

.close

safe radishBOT
#
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trail otter
#

$(1+x)\sum^{\infty}{k=0}(-1)^k\frac{x^k}{k!}-(1-x)\sum^{\infty}{k=0}\frac{x^k}{k!}=\sum^{\infty}{k=0}((-1)^k-1)\frac{x^k}{k!}-\sum^{\infty}{k=0}((-1)^k+1)\frac{x^{k+1}}{k!}$\\

how come these two are equal?

flat frigateBOT
#

Slowaq

safe radishBOT
#

@trail otter Has your question been resolved?

trail otter
#

<@&286206848099549185>

safe radishBOT
#

@trail otter Has your question been resolved?

mental needle
#

Like k=0 solve for it

safe radishBOT
#

@trail otter Has your question been resolved?

safe radishBOT
#

@trail otter Has your question been resolved?

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fair steppe
#

Yo

safe radishBOT
fair steppe
#

I need help with this

lean otter
#

?

fair steppe
#

I dont get it

#

I want someome to do an example or 2 for me and explain along the way

fair steppe
#

k

lean otter
#

do you understand a domain and a range?

vagrant ice
#

Do you understand what the domain and range are

vagrant ice
#

I know

fair steppe
vagrant ice
steep kite
# fair steppe

Domain is all possible values of x and range is all possible values of y

fair steppe
#

😭

#

I have it on my notes

#

We did it today

lean otter
#

ok @fair steppe look
Domain is the set of all x-coordinates like (1,1) (2,1) (3,1) etc
Range is the set of all y-coordinates (1,2) (1,3) and so on

vagrant ice
vagrant ice
lean otter
vagrant ice
#

The domain would just be {-3, 1, 1, 3, 5}

steep kite
vagrant ice
#

The domain can't be a set of coordinates

fair steppe
lean otter
fair steppe
fair steppe
#

Ok

vagrant ice
#

It of course depends on the function

fair steppe
#

Alr

vagrant ice
#

So when you have points, the domain and range are just a collection of numbers

#

But when your function is continuous

fair steppe
#

I see

vagrant ice
#

As in it's a curve

#

You have like $3 \le x \le 5$ etc

flat frigateBOT
vagrant ice
#

Or you can have the real numbers as your domain

#

Most of the time, the domain will be the real numbers, so all possible x

fair steppe
#

Yep I learned about the real numbers today

vagrant ice
#

You will also have functions like $\frac{1}{x}$ where the domain is just all real $x$ except $x = 0$

flat frigateBOT
vagrant ice
fair steppe
#

Alr

vagrant ice
#

And there's functions like y = ln(x) where the domain is x > 0 for real x

vagrant ice
vagrant ice
# fair steppe Alr

So in summary, for a table or for when the graph has isolated points, just look at the possible x-values (domain) and y-values (range) for the points

#

For a continuous function you do the same thing, but you have infinitely many points, so your domain and range will be inequalities

steep kite
#

Here is an example of continuous curve, shape of curve doesn't matter

vagrant ice
#

For a continuous function you can imagine trying to draw a rectangle around your function

vagrant ice
fair steppe
vagrant ice
steep kite
fair steppe
#

I see

vagrant ice
#

And then the range of x and y values of the rectangle is your domain and range

fair steppe
#

What about one that isn't?

vagrant ice
#

Anything you can't draw without your pen leaving the paper isn't continuous

fair steppe
#

Oh ok

#

So how would I answer that?

steep kite
#

Then you have to write seperate domain and ranges and use AUB if there are multiple curves

fair steppe
#

AUB?

steep kite
#

You know set theory right?

fair steppe
#

Idk that

steep kite
#

Oh you'll study that later

fair steppe
#

Alr hopefully

#

My teacher is ass

#

4 out of 31 students are passing with 50s

#

Highest mark is a 70 and the student is cheating 😭

#

Anyways I appreciate your guys help

#

Ima also ask a teacher for help during lunch in a bit

vagrant ice
#

No worries

#

There's a lot of videos and examples online also

fair steppe
#

Yeah ima watch them

vagrant ice
#

Cool

fair steppe
#

I got them saved to watch later

safe radishBOT
#

@fair steppe Has your question been resolved?

#
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lean otter
#

im doing combinatorics and im stuck on why Σ(j=0 to infinity):[n k]*t^k= 1/(1-t)^n where [n k] = (n+k-1 choose k) nεN

vagrant ice
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#

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fair crane
#

is this wrong

safe radishBOT
steel stag
#

I don't think I believe the djvj to dj^2 step

#

it'd probably be an inequality there I'm guessing

#

yea it's this, called cauchy-schwarz inequality

#

although if you're maxing it I guess it is equals and fine?

#

guess it's all true

fair crane
steel stag
#

oh true I wonder what that's called

fair crane
#

its jsut the norm isnt it?

#

this is the whole question, maybe im going about it wrong

steel stag
#

like for n=2 this isn't always true right

fair crane
#

oh wait yeah its wrong

#

ur right

#

i see

safe radishBOT
#

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fluid escarp
#

Hi can some one solve this?

safe radishBOT
median vigil
#

do you know what kind of series this is?

safe radishBOT
#

@fluid escarp Has your question been resolved?

eternal carbon
fluid escarp
fluid escarp
median vigil
#

there is a formula for geometric series

safe radishBOT
#

@fluid escarp Has your question been resolved?

fluid escarp
median vigil
#

find what is a and what is r, then apply the formula

safe radishBOT
#

@fluid escarp Has your question been resolved?

fluid escarp
jolly shard
fluid escarp
jolly shard
fluid escarp
fluid escarp
jolly shard
fluid escarp
#

Then multiply 3
The answer is 4 right?

safe radishBOT
#

@fluid escarp Has your question been resolved?

wispy portal
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obsidian fractal
#

idk where to start w/ this question

safe radishBOT
lost forum
#

Hey khat!

#

I’d start as follows:

#

The question is asking you “how to do something” so that profit is maximized. Therefore I should be able to calculate profit (no matter what the something is, I’m gonna need to be able to calculate profit to deal with it)

#

So, how would you calculate profit?

#

Say the profit of the company if they make 60 cars per month and sell them at 800+fp where fp is the factory price

#

The profit would then be 800*60

#

Per month

#

So say that they mark up by 20c where we are trying to find c

fathom pine
#

find the direction in which the Uf of f(x,y)=ye^-xy at (0,2) has value of 1

lost forum
#

The new profit would be ||(60-c)(800+20c)||

#

Maximize that

obsidian fractal
lost forum
#

But you have paid fp to make the car!

#

So your clear profit is only the 800

#

That’s why they don’t specify the value of fp

#

You can think of it like this:

#

To make a car you pay fp and you get 800+fp so that the profit would be (800+fp-fp)60

safe radishBOT
#

@obsidian fractal Has your question been resolved?

obsidian fractal
#

im still confused

#

maybe im js not reading something properly or im just tired af but i dont rly get either explanation for why u dont add fp or how u get the equation from the question

exotic cypress
#

thw question is asking about how much profit you get

#

like if you buy something for $5 and sell it for $15 (geez how much did you rip someone off), your profit is $15-$5 ($5 is your 'fp'), which is $10, not $15 that you sold it

#

oh texit never needed u here bro i was just talking about money

obsidian fractal
#

so the fp is completely irrelevant to the question

#

?

exotic cypress
#

yea

#

it is just logical context

obsidian fractal
#

why did the other dude even mention it then

exotic cypress
#

s/he didn't need to but just telling you what profit meant

#

cuz if you didn't know the definition of profit or how to work it out you can't understand the question

obsidian fractal
#

well thats one thing

#

but i also dont get how i make the equation with the stuff given

exotic cypress
#

so the profit would you gain from 1 car is 800, where you sell 60 cars per month, right? then, every extra $20 you make from 1 car will decrease the total sales by 1 car

#

thats all the information you need to make the equation from

obsidian fractal
#

ok i have the equatio

#

n

#

(60-1x)(800+20x)

#

how do i find x so profit is maximized

exotic cypress
#

now its hard to explain but you can see that for exery extra $20 you lose 1 car so the money difference = +20(60) and -1(800+20x) or -1(800) + 20*(59)

#

so like u find a point where when u take away 1 car and times it by 800+20x is the same as the cost of 1 car (sry im bad at explaining thiscatscream )

obsidian fractal
#

obsidian fractal
#

<@&286206848099549185>

storm sleet
#

?

ionic lark
#

?

obsidian fractal
#

i can do that right

#

after 15 minutes ping helpers

storm sleet
#

yes

ionic lark
#

but why did you ping when someone else is helping you?

#

oh wait, that's 15 mins ago

#

Makes sense

obsidian fractal
#

what do i need to do when its asking me to maximize profit

#

i dont understand

proper spindle
#

So calculate other value of x for which profit is same

#

Then divide x by half

obsidian fractal
#

.close

safe radishBOT
#
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crisp gyro
#

How would I do this q? I did u=ln(x) and then I got intergral of u/x du but idk if I did anything wrong

eternal carbon
crisp gyro
eternal carbon
#

so that is recommended method of solving integral such as this

tall bough
#

Actually u can sub 1/x

#

,w derivative of 1/x

tall bough
#

Okay nvm I can't do derivaives anymorw

split fulcrum
crisp gyro
split fulcrum
split fulcrum
#

Alright 👍

safe radishBOT
#

@crisp gyro Has your question been resolved?

versed wave
#

me personally i prefer IBP

split fulcrum
#

what’s IBS

versed wave
#

int by sub

split fulcrum
#

oh I’ve only ever seen people call it u sub

safe radishBOT
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untold oyster
#

could someone explain the step made in red?

cloud citrus
#

Expanding (2m+1)!

#

(2m+1)!=(2m+1)(2m)(2m-1)(2m-2)(2m-3)...(2)(1)

We can notice that (2m-2)(2m-3)...(2)(1) is actually (2m-2)!

untold oyster
#

ah yes that makes sense

#

thank you very much

#

.close

safe radishBOT
#
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empty marten
#

there are 2 boys and 4 girls, they will be in groups of 3, what is the chance of the 2 boys being together in a group

lime dust
#

What did you try?

empty marten
#

i tried to find the total number of groups

#

6C3 = 20

lime dust
#

Now calculate the number of groups that contains 2 boys

empty marten
#

4C1 = 4?

lime dust
#

Yes

#

So what can u do now

empty marten
#

4/20?

lime dust
#

You have found all the info

#

Yes

empty marten
#

but answer is 0.4

lime dust
#

Rly? Let me check

empty marten
#

what did you get?

lime dust
#

I still get this, can u show a picture

#

Of the original problem

empty marten
#

it was an instagram post lol

lime dust
#

Maybe i am getting braindead but i get 20%

empty marten
#

i also get 0.2

#

let me ask the creator

#

i was thinking

lime dust
#

You count the two boys as 1

empty marten
#

ye it isnt permutation

lime dust
#

Maybe he forgot about that

empty marten
#

i consider one group only

#

oh

#

wait

#

total number of groups might be 10

#

because there are 2 of them

#

its repeated

#

imagine ABC, DEF

lime dust
#

Oh we treated differently in both scenarios

empty marten
#

DEF is already counted

empty marten
lime dust
#

That is forgot about that

#

So yes, it is 10 groups

empty marten
#

thanks, i havent learnt about combinations yet but im interested in it

lime dust
#

I tricked myself xd

empty marten
#

i watched many youtube videos but they are all about letters

safe radishBOT
#

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#
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lean otter
#
  1. Idk where to start
#

Do you know the Quadratic formula?

#

Yep

#

Do I use that?

#

You can

thin bridge
#

using the discriminant component is enough

lean otter
#

Yeah

lean otter
#

So, if the general solution of this equation is $\frac{-b (+-) \sqrt{b^2-4ac}}{2a}$

flat frigateBOT
#

Palahoo

thin bridge
#

discriminant is the part under the root

#

i.e. the
b^2 - 4ac

lean otter
#

denoted by D

#

Or Delta, depending on the country

lean otter
lean otter
#

The discriminant (D) is equal to b²-4ac

#

So, as the equation has only one solution, the discriminant needs to be equal to zero

#

So (k)^2-4(4)(9)?

#

Yes

#

It needs to be equal to zero

#

k^2-144=0?

#

Yes

#

Notice that k has two solutions

#

So if I factor it’s gonna be (k-72)(k-72)=0

#

12

#

Oh

#

(k-12)(k+12)

#

It has the solutions 12 and -12

#

Can I find the roots dividing it by 2?

#

And i got 72

#

Is there another way

#

To find roots

#

With big numbers like that

lean otter
#

?

#

No like 144

#

How do I factor this fast

#

Cuz I divided it by 2

#

To find the factor

#

Remarkable products

#

(a+b)(a-b)=a²-b²

#

Oh idk that maybe I should study that first

#

Ohhh

#

So (k-144)(k+144)=k^2+144^2?

#

To find the root of 144?

lean otter
#

Not plus

#

But -(-144)

#

Since its k^2-144=0

#

?

#

No

#

How?

#

(a+b)(a-b)=a²-b², so we can conclude that a²=k² and b²=144

#

?

#

Oh

#

(-144)^2= -(144)=-144

#

(k+12)(k-12)=k²+12k-12k-12.(+12)=k²-144

#

No

#

Like how do u find the root

#

Of 144

#

That fast

#

That’s just expansion

#

Yes

#

?

#

No I’m talking abt 144

lean otter
#

Then what were all those

#

😭😭

lean otter
#

Ok helper is gone

#

.close

safe radishBOT
#
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tight scroll
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How to do this?

safe radishBOT
patent flame
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Let y=vx

tight scroll
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I don't understand

tepid walrus
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They‘re suggesting a substitution

tight scroll
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Substitute what?

tepid walrus
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y/x = v

tight scroll
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Ohh

tepid walrus
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So you get a more manageable form

tight scroll
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Okay

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Now it's dy/dx=v + tanv

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We take derivative of v + tanv?

tepid walrus
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you shouldn‘t have dy/dx, it should be something with dv no? Unless I‘m missing something

tight scroll
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We have to change that y/x to v too?

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@tepid walrus

tepid walrus
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Well, I don‘t have much experience with differential equations, but I think you‘d want to have a dv/dx there?

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Then you should be able to integrate both sides

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But I may be wrong, so I‘ll go ask in the helper channel if someone wants to fact check this and help you :)

tight scroll
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Okay

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I also don't know much about this

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I only know basic derivative

placid oak
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we have y = vx

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so you can find dy/dx in terms of dv/dx via product+chain rule

tight scroll
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Okay

placid oak
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the result should be separable once you rearrange everything

tepid walrus
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Okay so I wasn‘t just blurting out random crap. Thanks Desync

tight scroll
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Thank you

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.close

safe radishBOT
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Channel closed

Closed by @tight scroll

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safe radishBOT
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Available help channel!

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reef flax
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Help anyone? I've been trying to desperately find what this equation even is like i've searched youtube and google, some modules and there's NONE. Does anyone know what type this is? Example problem: If sin β = - 3/5 and tan β > 0, what is the exact value of cos² β-sin² β?

rich shuttle
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Hmmm

reef flax
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also the next step for the solution to that problem is like sin β = - 3/5 cos β = - 4/5 but where did they get the 4?

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oops wrong numbers fixed

rich shuttle
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Oh

placid oak
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by drawing a 3-4-5 right triangle

reef flax
rich shuttle
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so like

reef flax
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i'm sorry i'm slow but what do you mean by drawing a right triangle, like literal? cause it was just numbers

rich shuttle
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yes

placid oak
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trig functions relate angles to the sides of triangles

rich shuttle
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draw right angle triangle

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abc

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with b as the right angle

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hpy is 5

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and opp of angle beta is -3

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by Pythagorus

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we get 4

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not -4

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hm

reef flax
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wait let me type in the solution, It doesn't say to make a triangle, its so confusing. Give me a few seconds please

rich shuttle
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ok

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you have to make a triangle

reef flax
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here

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sin β = - 3/5 cos β = - 4/5
cos² β - sin² β = (- 4/5)² - ( - 3/5 )²
= 16/25 = 9/25 = 7/25
= 7/25

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I kind of do get it but can't comprehend where the 4 was taken

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is it pythagoras?

rich shuttle
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yes

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see If we take AC to be the larger side

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AC^2=AB^2+BC^2

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you can move AC and other sides

reef flax
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I'm sorry but what does that mean, what AC?

rich shuttle
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the sides let me send a pic

reef flax
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okay

rich shuttle
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its not -4 but root 34

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we saw that tanB > 0

reef flax
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/yes?

rich shuttle
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wait

rich shuttle
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reason why its root 34

reef flax
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you mean the overall answer would be 34?

rich shuttle
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no

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the other side would be root 34

reef flax
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wait a sec let me try

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huh wait I'm confused

rich shuttle
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final answer

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43/25

reef flax
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but the choices were either a.) - 1/5 b.) 7/25 c.) 1 d.) -1 (By the way I am not cheating this is a reviewer with already provided answers)

rich shuttle
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it wont be same since of the -3

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is it -3 or 3

reef flax
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wait

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I can't make an over but its like negative 3/5

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like both?

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let me write it i'll send a picture

rich shuttle
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ok send

reef flax
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like that negative

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help someone, I'm losing my minddd

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how did 4 get there when and why

graceful forge
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We have sin(x) to be negative, which means x cannot be in the first or second quadrant , also tan(x) is positive means x must exist in the third quadrant only .
And in the third quadrant cosine(x) is negative.
So cos²(x)=1-sin²x
=16/25
=>cos(x)=4/5 or -4/5 .
But we know cosine(x) is negative. So cos(x)=-4/5

graceful forge
safe radishBOT
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@reef flax Has your question been resolved?

safe radishBOT
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Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

reef flax
safe radishBOT
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reef flax
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what did you mean by the x?

safe radishBOT
reef flax
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I didn't get the 4

graceful forge
graceful forge
reef flax
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No

graceful forge
# reef flax No

Well then can you tell me exactly how much trigonometry you know ? Because, these are very basic things.

reef flax
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I actually don't know any, I'm in a strand that removed math and I'm trying to know all these equations for a try in scholarship

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I don't even know why they removed it, its literally so important

graceful forge
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Do you know what sine of an angle is ? Like it is opposite over hypotenuse that much ?

reef flax
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not really no, i'm sorry

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wait so the equation isn't pythagoras?

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oh it is

graceful forge
# reef flax not really no, i'm sorry

I would recommend you pick up any book on trigonometry and read the first few pages .. the. You can have a solid idea .

If they will be asking questions on the scholarship test , it is best to skip the parts you are weak in like trigonometry, and focus on your strong areas .

reef flax
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its more like a written test

graceful forge
reef flax
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won't I fail though? math is like a major subject especially if the ones they accept are pretty much stem students

graceful forge
reef flax
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well I'm going to be honest, I don't really excel at math and I focus on English more but I'll try searching trigonometry, calculus and such, the other problems here I'm so not sure what equation they even are though

graceful forge
graceful forge
reef flax
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oh, I'll try that but usually whenever I read through a book and they give a few solutions, the practice problem always comes out different? Example is the equation I gave earlier, its gonna say cos β (sample number) and sin β < 0 and so on, are they supposed to have the same solution format? if that makes any sense (sorry not my native language)

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it like, switched it up, is it supposed to be different?

graceful forge
reef flax
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happens to every single module I come up with

vagrant ice
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For trig you definitely need to know the unit circle in all four quadrants

graceful forge
vagrant ice
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cos theta is the x-coordinate of a point with angle theta, and sin theta is the y-coordinate

reef flax
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but is their solution format the same? but how do I know which is which? for example the other person that said about a triangle with A, B, and C. Lets say they 2 numbers are on A and B as the problem with solution was given, the next problem they make me solve is through B and C, its confusing (not accurate just example)

reef flax
graceful forge
vagrant ice
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So yeah, you can break down your study approach into:

  1. Unit circle: signs of sin, cos, and tan for all 4 quadrants (and these are the same signs of csc, sec, and cot as the reciprocal 1/x doesn't change the sign of a number)
  2. Using trig identities: Pythagorean identity cos^2 x + sin^2 x = 1, double-angle identities, and sin(A + B) and cos(A + B) if you have time
  3. Solving trig equations such as sin x = sqrt(3)/2: group sin and cos together cause their period is 2pi, and do tan separately cause its period is pi
safe radishBOT
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@reef flax Has your question been resolved?

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Channel closed

Closed by @reef flax

Use .reopen if this was a mistake.

safe radishBOT
#
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frozen marlin
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*algebra

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one sec, lemme just scan this rq

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what have you tried

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...?

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what do you mean it's a test

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<@&268886789983436800>

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bro

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we can't help with tests

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im sorry

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why would it be

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no

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we want to help others learn

simple oak
frozen marlin
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we aren't here to do your homework for you or hand out free marks

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well, my guy, then use your learnt material to do the test

ionic lark
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Then come with the same question after school

frozen marlin
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i'm afraid we cannot, and will not, aid you in this task

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goodbye

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yea exactly

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you're worried abt marks not abt the actual question

quasi plume
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.close

safe radishBOT
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Channel closed

Closed by @quasi plume

Use .reopen if this was a mistake.

frozen marlin
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well, there they go

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thanks

vagrant ice
safe radishBOT
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Available help channel!

Send your question here to claim the channel.

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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ember finch
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I think i'm stupid

safe radishBOT
ember finch
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I knew how to do this before but i forgot

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can someone help me real quick please

vagrant ice
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Then your particular solution is going to be in the form $y_p = ax^2 + bx + c$

flat frigateBOT
vagrant ice
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A quadratic double-differentiates down to a constant

vagrant ice
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Sub the particular solution in and compare coefficients to find a, b, c

ember finch
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is that always the case when the right side is a constant?

vagrant ice