help-23

[coarse trail]

i did it w a tutor yesterday and we got two different answers but couldnt figure out what was wrong with mine

my answer doesnt match wolframalpha and the graphs of our two answers dont align

[eternal carbon]

what was the other answer?

[coarse trail]

hold on

its whatever wolframalpha gives

[eternal carbon]

ah alright

no issue then

because the answer you have is definitely correct

it's just written in a different form i suppose

[coarse trail]

(tan^4(x))/4 +constant

[coarse trail]

but the graphs dont match for some reason

[eternal carbon]

if they don't match then they're off by a constant

notice the + C that comes from evaluating integrals

sometimes, you will see that you can solve an integral in different ways and get different answers that are off by a + C

[coarse trail]

oh

so their C values r different

[eternal carbon]

in this case, 1/4 (secx)^4 - 1/2 (secx)^2 + 1/4 = (tanx)^4 / 4

[coarse trail]

i always thougth every answer of the same integral would have the same C

[pliant egret]

c is not a certain number

it says you can add any constant number to your result

[coarse trail]

okay

i see

one more question

it this solveable with the shell method and would i use (2-x) ?

ik my error in that attempt but i tried solving it again and got a negative value

[eternal carbon]

shell method, yes
2 - x, yes

[eternal carbon]

(sqrtx) is greater than (x) on the interval 0 to 1

are you using (sqrtx - x) ?

[coarse trail]

yes

integral from 0 to 1 of 2pi(2-x)(sqrtx - x) dx

[eternal carbon]

hmm answer shouldn't be negative

but that integral does give u the right answer!

[coarse trail]

hmm

so my evaluation has to be messed up somewhere

i think so actually

[safe radish]

@coarse trail Has your question been resolved?

Channel closed

Closed by @coarse trail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[amber glen]

This is the answer key for problem 4 and I don’t get why there are two 9s beside the 16

[safe radish]

@amber glen Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[amber glen]

.reopen

[safe radish]

✅

[amber glen]

<@&286206848099549185>

[safe radish]

@amber glen Has your question been resolved?

[amber glen]

<@&286206848099549185>

[steel stag]

the trapezoid top is 16, then linearly expands to the middle 25, then to the bottom something

since it's linearly expanding it'll just continue the pattern, 16+9=25, 25+9=34

so the bottom is 34, which is 9+16+9, and the 9's are the bottoms of those triangles

[amber glen]

Oh ok thanks

And I have another question

Would this be a 45 45 90 triangle

So could I divide it by square root of 2

And add all the sides

[steel stag]

yup exactly

[amber glen]

K thanks

.close

[safe radish]

Channel closed

Closed by @amber glen

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager sphinx]

Hii! I'm not sure if I'm doing this right, but I need to find X value.

[safe radish]

@eager sphinx Has your question been resolved?

[eager sphinx]

.close

[safe radish]

Channel closed

Closed by @eager sphinx

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid creek]

Did I do this right?

[torpid creek]

.close

[safe radish]

Channel closed

Closed by @torpid creek

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray palm]

I have no clue how to relate the angle to differentials??

[faint seal]

The angle of inclination, theta, is just given by arctan(y/x)

You would like to find dtheta/dt when x=4

[stray palm]

Oh okay, so i dont need differntials and tangent?

Like the rate of change thing

[faint seal]

You do, you need to find dtheta/dt

Which is given by $$\frac{d}{dt}(\tan^{-1}(\frac{y}{x}))$$

[flat frigate]

kheerii

[stray palm]

Sorry i was confusing this question with differential linear approximation thing. Does this look right?

I thought i had to draw tangent line and some other crazy stuff

[faint seal]

Yeah looks good to me

[faint seal]

Yeah no this seems like smth different

[stray palm]

Okay thank you @faint seal !

Sorry last thing i got a negative answer and it’s asking for how fast. Do i conclude it’s decreasing in speed or say it’s a clockwise that’s why it’s negative?

[safe radish]

@stray palm Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dull heron]

Need help with Q1

[frigid locust]

Let cetain fraction be $\frac{x}{y}$
When one is added to the numerator , it becomes
$$\frac{x+1}{y} = \frac{1}{5}$$
$$\implies 5(x+1) = y$$
When one is removed from the denominator , it becomes
$$\frac{x}{y-1} = \frac{1}{7}$$
$$\implies 7(x) = y-1$$

[flat frigate]

JustToPro

[frigid locust]

solve the simultaneous equations for value of x and y

[dull heron]

Thank you

[safe radish]

@dull heron Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour karma]

For this, why is x = 0 in the interval of increasing and decreasing?

[sour karma]

D is the answer for the intervals of increasing and decreasing

[upper hatch]

the point where the monotony of the function changes can be included in both sides

typically i woudlnt use to do that when these exercises popped up, id have one closed and one open interval just to be typical

but theres nothing really particularly wrong with it

since its a single value it doesnt matter too much

[sour karma]

I’m just kinda confused cause another question like this doesn’t use square brackets

[upper hatch]

its probably not significant, i wouldnt lose sleep over it, but youre free to ask your teacher as well, maybe he does it for a reason

but my guess is its just a random inconsistency

if anyone disagrees speak now or forever hold your peace

[safe radish]

@sour karma Has your question been resolved?

Channel closed

Closed by @sour karma

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven ice]

solve the ratio

how does this ai work?

[safe radish]

@raven ice Has your question been resolved?

[raven ice]

no

can you solve it?

[safe radish]

@raven ice Has your question been resolved?

[safe radish]

Channel closed

Closed by @raven ice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spare grotto]

can someone help me solve this? "A triangle has corners in P = (1, 1, 1) Q = (2, 4, 3) and R = (1, 4, 2).
(a) Determine the matrix A into the linear mapping F : R^3 → R^3
which depicts PF→ Q, QF→ R and RF→ P.
(b) Show that the locus vector to the centroid M of the triangle is an eigenvector of the matrix A.
Tip: Also measures the intersection of the medians and has the location vector−→IF=13−→OP+13−→OQ+13−→OR.

[safe radish]

@spare grotto Has your question been resolved?

[safe radish]

@spare grotto Has your question been resolved?

[safe radish]

@spare grotto Has your question been resolved?

[finite yacht]

How is F written with respect to the basis {P,Q,R}?

[finite yacht]

First find this and then undo the change of basis

[spare grotto]

Hmm i am not sure

[finite yacht]

Each vector is written as a combination of P, Q and R

[spare grotto]

P=q q=r and r=p?

[finite yacht]

No, I mean the matrix

F can be represented as a matrix A

such that A times P equals Q

A times Q = R

[spare grotto]

Oh yes that’s what I meant

[finite yacht]

The problem is to find that matrix

But instead of finding it with respect to the canonical basis, try to find it first for the basis {P,Q,R}

[spare grotto]

Can we write A = (a b c, d e f, g h I)?

[finite yacht]

Yes but that is not useful

[finite yacht]

For example, the image of P = (1,0,0) is Q = (0,1,0)

So the first column is (0,1,0)

[spare grotto]

Okay and since q=(2,4,3) can we write r as r=(1,4,2)?

[finite yacht]

Yes, but that is with respect to the canonical basis

[spare grotto]

Hmm okay

(0,0,1) = (1,1,1)?

[finite yacht]

No
Also do not write it like that

For example, consider the following matrix
1 2 2
0 1 0
-1 0 2

It sends the vector (1,0,0) to (1,0,-1), right?

Because it is the first column

[spare grotto]

Yes

[finite yacht]

And (0,1,0) -> (2,1,0), and (0,0,1) -> (2,0,2)

And saying what is the image of those three points completely determines the transformation

In a similar way, you can describe a transformation saying what is the image of any three linearly independent vectors

[finite yacht]

For example, these three

You write in the first column the image of the first vector, which is P

Et cetera

But you have to write it using the basis {P,Q,R}

[finite yacht]

With respect to this basis, P is written (1,0,0), Q is written (0,1,0) and R is written (0,0,1)

So what would be the matrix?

[spare grotto]

Q=(0,1,0) is R=(0,0,1)?

R=(0,0,1) is P=(1,0,0)?

So the matrix is (1 0 1, 0 0 0, 0 1 0)?

Do we determine the image of this now?

How do we change back the basis now? @finite yacht

@snow robin

[snow robin]

you need to find the matrix that transforms P in the PQR basis to P in x, y, z basis

canonical

so P in PQR is 1,0,0

and P in xyz is 1, 1, 1

[spare grotto]

Okay do you mean that (0,1,0) in the matrix we have that is Q becomes (2,4,3) instead?

[snow robin]

so you write a matrix such that $\begin{pmatrix} 1 \ 1 \ 1 \end{pmatrix} = \begin{pmatrix} a & b & c \ d & e & f \ g & h & i \end{pmatrix} \begin{pmatrix} 1 \ 0 \ 0 \end{pmatrix}$

[flat frigate]

Katharine

[snow robin]

and using that same matrix on Q and on R

will give you it

and multiplying that will give you the matrix that maps P to Q to R to P

if that's possible

that's what d was trying to say

[spare grotto]

Okay but is the abc matrix our matrix that we have

Or what do I write there?

[snow robin]

you gotta find what those letters are

you have 3 equations

ignoring the fact that matrix equations are multiple in one

3 matrix equations

$\begin{pmatrix} 1 \ 1 \ 1 \end{pmatrix} = \begin{pmatrix} a & b & c \ d & e & f \ g & h & i \end{pmatrix} \begin{pmatrix} 1 \ 0 \ 0 \end{pmatrix}$
$\begin{pmatrix} 2 \ 4 \ 3 \end{pmatrix} = \begin{pmatrix} a & b & c \ d & e & f \ g & h & i \end{pmatrix} \begin{pmatrix} 0 \ 1 \ 0 \end{pmatrix}$
$\begin{pmatrix} 1 \ 4 \ 2 \end{pmatrix} = \begin{pmatrix} a & b & c \ d & e & f \ g & h & i \end{pmatrix} \begin{pmatrix} 0 \ 0 \ 1 \end{pmatrix}$

[flat frigate]

Katharine

[snow robin]

i posted it too early

accidentally :D

that's why

you solve these

and then multiply the found matrix with this one

i think this one should be on the left

as it's applying to the PQRP matrix

[spare grotto]

Okay in the equation for p I got a b and c to 1 and the rest to 0

[snow robin]

$\begin{pmatrix} 1 & 1 & 1 \ d & e & f \ g & h & i \end{pmatrix}$

[flat frigate]

Katharine

[snow robin]

like this?

[spare grotto]

Yes

But should I not write defghi as 0?

[snow robin]

that does not seem correct

for the first 1 in the xyz basis

what is the equation in terms of components for that?

1 = a ...

[spare grotto]

Or wait maybe a d and g is 1 and the rest is 0

[snow robin]

why is the rest 0?

you're correct about adg

[spare grotto]

Because I take a1 b0 and c*0

Does that not become 0

Or do they just become b and c?

[snow robin]

does b * 0 mean b = 0?

[spare grotto]

Maybe not

[snow robin]

:D

[spare grotto]

But I thought it did

[snow robin]

no it means b can be anything

if b = 5

[spare grotto]

Ohhh okay

[snow robin]

b * 0 = 0

if b = 457298347541098327409123

same thing

[spare grotto]

Oh okay

[snow robin]

now you can use equation 2 to find the next column

[spare grotto]

Ohh okay!

B=2 e=4 h=3

[snow robin]

nice

can you guess what the last column is gonna be?

[spare grotto]

1,4,2?

[snow robin]

yeah :D

the reason that we get just the vectors

is because we've defined our PQR basis as P = 1,0,0 Q = ...

[spare grotto]

Yes I see!

[snow robin]

and so in order to go from PQR to xyz we just need to use the vectors in the xyz basis as columns

now the next step is to multiply the change of basis matrix with the PQRP matrix

[spare grotto]

Yes okay!

[snow robin]

such that the PQRP basis gets transformed from the PQR basis to the xyz basis

matrix

the first basis

is matrix

i wrote basis i meant matrix

:D

[spare grotto]

A question tho, is (0,1,0) vertical or horizontal in the matrix we had from the beginning?

[spare grotto]

Is this right

[snow robin]

i don't know i haven't checked

why not try it out and see if you did it correctly

[spare grotto]

Yes okay!

I get the same answer either way but I got (2 0 1, 5 0 1, 3 0 1)

[snow robin]

hold up i need to check if we've done the change of basis correctly

i think we did it correctly

we'll see

[spare grotto]

Yay!

Thank you so much for the help!

[snow robin]

we can apply the matrix you've found on P

to see if we get Q

[spare grotto]

Yes okay hold on!

Wait do we just take our matrix times (1,1,1) then?

[snow robin]

yes but i just tried using both matrices and it did not give me a correct result

[spare grotto]

No me neither

[snow robin]

Your original one is incorrect :S

[spare grotto]

Oh no

Why

[snow robin]

You found the matrix $\begin{pmatrix} 1 & 0 & 1 \ 0 & 0 & 0 \ 0 & 1 & 0 \end{pmatrix}$

[flat frigate]

Katharine

[snow robin]

right?

[spare grotto]

Yes

[snow robin]

i'm an idiot

the way you apply the change of basis matrix to a matrix is different

so we did it wrong

the things you forget

:D

[spare grotto]

Oh okay

[snow robin]

So we need to find the inverse of the change of basis matrix

and then we need to multiply them like $P^{-1}MP$

[flat frigate]

Katharine

[spare grotto]

Oh okay so we need to find the inverse of the original matrix or the one made by vectors?

[snow robin]

the one made by the vectors

[spare grotto]

Okay!

Okay I have to go now unfortunately but I will continue tomorrow but thank you for the help!

.close

[safe radish]

Channel closed

Closed by @spare grotto

Use .reopen if this was a mistake.

[snow robin]

@spare grotto I made a mistake it's $P M P^{-1}$ not the other way around

[flat frigate]

Katharine
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery ibex]

I need help with finding the tensor product

Im confused why these are wrong, since order of multiplication shouldnt mathematically matter for the tensor product right? and option D is basically expanding on each item, and the last one is basically the fully simplified and solved version

[safe radish]

@fiery ibex Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[urban cradle]

i have a simple question

i can't read my teacher's handwriting

what's after this?: Observation: pasticle...?

particle...?

[ivory obsidian]

particle can be a the same location at different times

[safe radish]

@urban cradle Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic gorge]

I did the problme in the center

and got

4 rad 6 +6 rad 5

but the answer key says its 4 rad 6 +26 rad 5

[hardy lion]

show your work

[scenic gorge]

nvm

i fixe dit

sorry

how do I close this

[hardy lion]

use .close

[scenic gorge]

.close

[safe radish]

Channel closed

Closed by @scenic gorge

Use .reopen if this was a mistake.

[urban cradle]

thank you btw!

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush ember]

i need someone to check sum

[plush ember]

just to double check it cuz im certain that im right

i just need someone to check the calculations

[icy lance]

what calculations

[plush ember]

on the left

[pliant egret]

what the hell are you calculating

[plush ember]

of the line

perpendicular bisectors

[plush ember]

thats what i thought at first aswell

my teacher gave me this braindead test

and i have 3 sets of coordinates

which are the first 3 on the left

then i found the midpoing

then the equation of the line

then i had to use negative reciprocal and midpoint to find perpendiculars

[safe radish]

@plush ember Has your question been resolved?

[safe radish]

@plush ember Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[finite geyser]

Answer is B, but I can’t find out why, SAT questions

[steel stag]

like this

[finite geyser]

really? that simple?

but it wont work for other dots

ohhh wait, greatest expense

[steel stag]

it's asking for the point with the greatest percent (y-axis)

yaya

[finite geyser]

omg, sat really messes with the brain with the wording

thx

[safe radish]

@finite geyser Has your question been resolved?

Channel closed

Closed by @finite geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crude vault]

create a tool using either excel or python that will translate
two axis of rotation and their length of arms (input) to a location in X and Y
space ((x,y) output) and vice versa. The tool will generate both kinematics
and inverse kinematics for a parallel SCARA robot. We are then going to
test the tool by building an example according to the tool data for
validation.
I know how to do the python writing i just need to understand the trig involved. The L1,L2 can be filled with any values along with the rotation i just need to understand how this works.

[safe radish]

@crude vault Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[verbal salmon]

can someone explain to me how the 56 just spawned

[verbal salmon]

is it so that they can get it to equal 1/2 in the third step

[bold prairie]

56g is half of the original 112g

because one half-life has passed so half of the nuclei have decayed

[verbal salmon]

ohhhh

ok

u just saved my test tmrw

thx

.close

[safe radish]

Channel closed

Closed by @verbal salmon

Use .reopen if this was a mistake.

[untold sky]

it’s worth pointing out that that step is equivalent to transforming the equation to y=112(0.5)^(t/2.4)

[verbal salmon]

oh ok

thx

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stark laurel]

can sm help me solve this

[stark laurel]

i wanna know how to solve it

[light shoal]

surely there is not enough info to solve this

[light shoal]

ok

what is there to calculate, it's right there in the table isn't it?

[stark laurel]

huh

[stark laurel]

i dont know what the formula is

[stark laurel]

the comprehensive form for that question it’s $346 but i don’t know if i subtract or add or multiply

[light shoal]

isn't the premium $346

if not, what are the entries in the table

[stark laurel]

i have to use that table for standard or comprehensive forms in the question

[light shoal]

what are the entries in the table

what is the table showing

[stark laurel]

whats a deductible

[light shoal]

the heading at the top says $500 deductible, isn't that what you want

it's the amount that the person has to pay if they make a claim

[stark laurel]

for that question i have to use these numbers

[light shoal]

!original

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[stark laurel]

because it’s says 55000 so i use the comprehensive because it says to

[stark laurel]

ok so i dont know what youre asking 😭

what is that supposed to mean

i don’t know what the formula is 😭

this the original question

[devout shale]

!noping

[safe radish]

Please do not ping individual helpers unprompted.

[stark laurel]

sorry didnt know

[devout shale]

You can find the answer to this problem in the table you have already posted here

No need for any formulas or calculations

[devout shale]

This table specifically

[stark laurel]

so.. does that mean do i add or subtract or multiply....

[stark laurel]

JUST SAY

😔

do i add

subtract

or multiply

[devout shale]

No need for any calculations

[stark laurel]

how do i find the answer then

[devout shale]

Use your eyes to locate it on the table

[safe radish]

@stark laurel Has your question been resolved?

[safe radish]

@stark laurel Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic jackal]

are just vertices enough to uniquely identify a convex polyhedron?

[manic jackal]

like if i say "the solid whose vertices are (0,0,0), (1,1,0), (1,-1,0), (1,1,1), and (1,-1,1)" would i be clearly indicating a particular solid

[steel stag]

think so, since convex hull is unique

[manic jackal]

alr ill hope so

im trying to make a multiple part question for triple integrals in spherical and cylindrical coordinates and the only thing i could come up with was asking to describe different solids with inequalities

cause basically every problem in the chapter is just solve this integral

.close

[safe radish]

Channel closed

Closed by @manic jackal

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle star]

I've been trying to figure out some matrices A and B that work, but the closest I've gotten is having one nonzero entry

[subtle star]

The instructions had also said that if it's not possible explain why, but I'm wondering if it is possible and I'm just missing something

[icy lance]

(0 1) (0 -1)
(0 0) (0 0)

is one that works i guess

i just thought make AB the zero matrix and A and B also cancel out

i know (0 1)
(0 0) squared is the zero matrix so just popped a - one it

could replace those 1's with any number, and also shift them to different corners, as long as theyre in the same one

[subtle star]

True

I'll try that out

Okay awesome that does work

Man idk why I couldn't see that earlier

Thank you!

.close

[safe radish]

Channel closed

Closed by @subtle star

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winter quiver]

the question is "a vehicle travelling at 10ms-1 undergoes an acceleration of 2ms- for 3 seconds, and then an acceleration of 3ms-2 for the next 4 seconds. calculate the final veloctiy and the total distance travelled. I've already calculated the final velocity but i cant manage to calculate the total distance (based using kinematic equations)

I AM AWARE THIS IS PHYSICS NOT MATHS BUT THE PHYSICS SERVER IS DEAD AND THIS LOWKEY URGENT

[icy lance]

split it up
the first 3 seconds s=? u=10 v=x a=2 t=3
then the 4 seconds s=? u=x v=/ a=3 t=4

you could find x

[safe radish]

@winter quiver Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cobalt saddle]

Help needed with 16

[icy lance]

(to do what)

[cobalt saddle]

Simplify

[icy lance]

hidden quadratics seems to be the theme here

try factorise the numerator

[cobalt saddle]

Is that even possible

[icy lance]

of course

[cobalt saddle]

Quadratic formula?

[icy lance]

let u=x^{1/5} if it makes it clearer

[icy lance]

if you really want

i wouldnt say its necessary

[cobalt saddle]

What does this mean

[icy lance]

means literally replace x^1/5 with u

[cobalt saddle]

Couldn't it be x^1/3

[icy lance]

ah right sorry, ive been looking at 14

[icy lance]

yeah you can do this yeah

you can also factorise the numerator here though if you know the difference of cubes formula

[cobalt saddle]

Like this?

[icy lance]

nearly

they should all be cube roots

,rccw

[cobalt saddle]

What do I do now

Do I rationalize

[icy lance]

no

[cobalt saddle]

The denominator

[icy lance]

no need to

[icy lance]

the right part is your denominator

it just cancels out

[cobalt saddle]

With the nominator?

That's weird since it not the same value

[icy lance]

$$\frac{(\sqrt[3]{x}-1)(\sqrt[3]{x^2}+\sqrt[3]{x}+1)}{\sqrt[3]{x^2}+\sqrt[3]{x}+1}$$

[flat frigate]

AℤØ

[icy lance]

is what you have

[cobalt saddle]

How did you get that

[icy lance]

wdym

[cobalt saddle]

And is that the answer?

[icy lance]

no

[icy lance]

this is the factorised numerator

and the denominator was always that

[cobalt saddle]

But this is the original equation

[icy lance]

i mean, i know???

whats your point

[cobalt saddle]

Can you explain this

[icy lance]

youre the one who factorised it, i just corrected it

theres not much for me to explain

[icy lance]

^

[cobalt saddle]

OK then what is the answer

[icy lance]

think

ive literally told you what happens

[icy lance]

just simplify it

[cobalt saddle]

Is this the answer

[icy lance]

sure

[safe radish]

@cobalt saddle Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic moss]

.open

[muted apex]

hello can someone help me with this problem

i just started learning complex numbers

and i'm confused with this one cz it has sin and cosine theta in

[icy lance]

may want to research polar form of complex numbers

[muted apex]

ok thank you

I'm doing it on a book

but it hasn't taught polar form yet

and it just tells me to do this question

[icy lance]

theta is the arg

[muted apex]

yeah

yeah it taught arg

[icy lance]

you can just do the usual multiplying by the conjugate

[muted apex]

wait does that work?

i tried it

[icy lance]

should do

[muted apex]

so is it just {cos(theta) - i sin(theta)}/{cos(theta) + i sin(theta)} {cos(theta) - i sin(theta)}

[icy lance]

my poor eyes

its not subtraction its multiplication

[muted apex]

oh wait mb

[icy lance]

yeah thats fine

[muted apex]

yeah i meant multiplication cz i just copied paste the first part

[icy lance]

just expand the denominator

[muted apex]

wait so how do you times the cos(theta)?

does it just become that squared

[icy lance]

mhm

[muted apex]

so cos(theta)^2

[icy lance]

indeed

[muted apex]

so is it cos(theta)^2+sin(theta)^2?

[icy lance]

it is

[muted apex]

cz the -i^2 turns into +

[subtle robin]

u can just convert it into 1/cis(theta)

then evaluate it fom there

much easier

[muted apex]

uhh okay

i'm confused

[icy lance]

dw about it

cis(x)=cos(x)+isin(x)

[muted apex]

so is the answer cos(theta)-i sin(theta)/cos(theta)^2 + sin(theta)^2

[muted apex]

ohh ty

[icy lance]

the denominator simplifies

[subtle robin]

yeah

[muted apex]

so how do you simplify it

is it just taking away the top?

[icy lance]

sin^2+cos^2=?

[muted apex]

oh I see

1

[icy lance]

yup

[muted apex]

ohh I know now

tysm

.close

[safe radish]

Channel closed

Closed by @muted apex

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[weary osprey]

Can you please check the proof?

attempted a proof by contraposition

[fleet orbit]

its a little bit confusing since you are using the "k" symbol twice

in two different places

[safe radish]

@weary osprey Has your question been resolved?

[weary osprey]

ahh my bad

oops

Thanks for catching it

i really mean m-k=dm for some m in Z

I really appreciate you for catching that one

I’ll note that in future

[fleet orbit]

i think its true

but it also has a general form

(a,b) = (a +- nb, b +- ma)

[weary osprey]

yep, any linear combination works

I wanted specifically prove this one

for an abstract algebra course

essentially to show, if k is a generator then (m-k) is also a generator for Z_m

[fleet orbit]

true

[weary osprey]

This proof works fine right?

[fleet orbit]

i think so

its a bit overkill

[weary osprey]

idk is there a better way to prove?

[fleet orbit]

direct way is just fine

[weary osprey]

prove (a,b)= d implies (a-b,b)=d?

[fleet orbit]

true

its very simple

[weary osprey]

I think proof is little longer, because we have to suppose (a-b,b)=d’ and show d divides d’ and d’ divides d hence d=d’

[fleet orbit]

d|a d|b => d|a-b = > d|(a-b, b) => (a-b, b) = d

i think you need to get more familiar with |

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[weary osprey]

.reopen

[safe radish]

✅

[weary osprey]

how does d|(a-b,b) implies (a-b,b)=d?

[fleet orbit]

oops mb

wait

[weary osprey]

d|(a-b,b) implies (a-b,b)= dl for some l

[fleet orbit]

nvm mb ( sorry i thought i had proved it before )

i dont think there is another way

its ok 👍

[safe radish]

@weary osprey Has your question been resolved?

Channel closed

Closed by @weary osprey

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fringe pine]

I think something is wrong with the question?
Find angle COD if AB, BC, CD and AD are tangents

[vapid cypress]

why?

[fringe pine]

I cannot solve it

But i am not sure

[vapid cypress]

,w 125/2

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by magnusop

[vapid cypress]

idk how to prove it but i think \this is the ans

[fringe pine]

It is one of the options, but the answer is given 55

[vapid cypress]

oh nvm

[fringe pine]

If it is 55, then we have to prove that AOD and BOC are right angles

[vapid cypress]

i'd suggest u join the POCs of all the tangents and centre of the circl

and work out all the angles

[fringe pine]

POCs? Not familiar with that

[chrome saffron]

its 180-125=55

thats how u get 55

[fringe pine]

not sure why that must be performed, can you tell me why we subtract it?

But still, if the subtraction is to be performed, then it is by proving that AOD and BOC are right angles, then adding all the angles to bring a rotation of 360. Then you will get 180 - 125, but we dont know if AOD and BOC are right angles

[chrome saffron]

its because of a theorem

the opposite sides of any quadrilateral which is circumscribing a given circle will subtend supplementary angles at the center of the circle.

AB and DC are opposite sides

[vapid cypress]

point of contacts

[fringe pine]

Thank you very much then, I was not familiar with that theorem, but now i know.

.close

[safe radish]

Channel closed

Closed by @fringe pine

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old bloom]

For any three square matrices of order 3. verify A(B+C) = AB + AC and A(BC) = (AB)C.

[old bloom]

For any three square matrices of order 3. verify A(B+C) = AB + AC and A(BC) = (AB)C.

How do I solve this?

[desert pasture]

I'd probably consider a general 3 by 3 matrix

one min

[old bloom]

Are there similar questions I can look at

[desert pasture]

\begin{array}{ccc}
element_{1,1} & element_{1,2} & element_{1,3} \
element_{2,1} & element_{2,2} & element_{2,3} \
element_{3,1} & element_{3,2} & element_{3,3}
\end{array}

[old bloom]

IT dosent matter If I copy answers I just have to complete this assignment

[desert pasture]

basically consider 3 general matrices

and verify

[safe radish]

@old bloom Has your question been resolved?

[old bloom]

Do you have an example of how to solve this?

[desert pasture]

not really

[old bloom]

I dont know how to solve this

[proper crypt]

@old bloom We will not solve it for you.

You were given a general approach, all you have to do is write it down.

Try it yourself

No one is going to write it for you

[rough storm]

!noans

[safe radish]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

@old bloom Has your question been resolved?

Channel closed

Closed by @old bloom

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite oak]

Hello I am quite unsure what this question is asking me to do here could anyone help?

[granite oak]

sinh(2x) = (e^2x - e^-2x)/2
cosh(2x) = (e^2x + e^-2x)/2

I don't know what to do after this step

[obsidian oracle]

You wrote sinh(x) and cosh(x), not for 2x

[granite oak]

Oh my bad

Fixed

but I already knew that I just mistyped

[obsidian oracle]

Yes ok

Name A = cosh(2x), B = sinh(2x), C = e^2x, D = e^-2x

[obsidian oracle]

Rewrite those equations with our new notations

[granite oak]

B = (C-D)/2

A = (C+D)/2

[obsidian oracle]

Yep

Now, solve for C and D

[granite oak]

2B = C-D -> 2B + C = D

like that?

[obsidian oracle]

Sure that's the first step

But I want both C and D only in terms of A and B

[granite oak]

C-D = 2B
C+D = 2A

[obsidian oracle]

And then?

How do we isolate C from D and vice versa

What I want :
C = ...A + ...B

Same for D

[safe radish]

@granite oak Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad nebula]

hey haazit, i need some help with trig pls

[glad nebula]

pls...

🙂

[inner parrot]

alright so let’s draw a right triangle and the label the angles and sides that we know

[glad nebula]

ok cool, and then?

[inner parrot]

can i see what you labelled?

[glad nebula]

oh wait, i got it!

im unsure abt this one tho

[inner parrot]

ah

so $cos(x)=sin(\frac{\pi}{2}+x)$

[flat frigate]

y0shi

[glad nebula]

woah wait howd u get that?

[inner parrot]

how would you use this identity to solve this

well cos is really a translation of sin

and they’re offset by pi/2

or 90 degrees

[glad nebula]

is there another way to appooach this bc we havent been taught this in school, so i doubt they'll accept that method

oh wait

[glad nebula]

now when u say that, maikes sense

[inner parrot]

alright

so sin(128 degrees) would be the same as

[glad nebula]

ok cool, so its basically just cos 38?

[inner parrot]

yep

[glad nebula]

🙂 thanx

u mind helping me with a few more?

[inner parrot]

ywyw

yeah sure

[glad nebula]

wait, is the first part tan^2 (38)?

[inner parrot]

yep

exactly that

[glad nebula]

so its 2tan^2(38)

but how would u do that using the triangle that u would have drawn?

[inner parrot]

well don’t we already know what tan(38) is?

tan^2(38) is the same as (tan(38))^2

[glad nebula]

oh yeaaaaa

so its just a^2?

wait, 2a^2?

[inner parrot]

yep

[glad nebula]

ok, and so given this:

how would u do 1

[inner parrot]

alright so let’s draw a right triangle

with the line given up there

make sure that one of the legs is on the x axis

since that would be our reference angle

[glad nebula]

ok, i got that, and dw, ik its correct bc thats the easy part 🙂

[inner parrot]

alright

[glad nebula]

but whats confusing is that beta is now an obtuse angle-

[inner parrot]

it shouldn’t change much

since if we drew that triangle

the reference angle is the same as cos beta

because cos is positive in that quadrant

[glad nebula]

wait, so u saying the acute angle in that triangle = beta?

[inner parrot]

well kinda

[glad nebula]

even tho beta = obtuse angle?

[inner parrot]

it’s the reference angle

[glad nebula]

ok, so just explain then i'll catch along

[inner parrot]

when we take sin or cos of bigger angles than 90

we look at the reference angle of that big angle

[glad nebula]

wdym reference angle, so like whatever the obtuse angle is, minus 90?

[inner parrot]

well the reference angle always has an adjacent side to the x axis

so let’s say we have 150 degrees

[glad nebula]

mhm

[inner parrot]

and we draw a right triangle with a side adjacent to the x axis

that angle we created

would be the reference angle

[glad nebula]

oooohk

[inner parrot]

but obviously all the different trig functions would either be negative or positive in certain quadrants

[glad nebula]

so in this case, what would the reference angle be? just the unknown angle between the x axis and the hypotenuse in the 4th quadrant?

[inner parrot]

exactly

[glad nebula]

oohk, but now how do we apply that to solve for cosB

[inner parrot]

so let’s say the reference angle is A

[glad nebula]

ok

[inner parrot]

cos B would be equal to cos A

but that’s not true for all quadrants

[glad nebula]

howd u figure that?

[inner parrot]

this is only true because cosine is positive in that quadrant

so cos B = either +/-cos A

generally for all quadrants

[glad nebula]

okayy

[inner parrot]

but depending on which quadrant we’re in, cosine might be positive or negative

[glad nebula]

ok, im following

[inner parrot]

and in quadrant 4 cosine would be positive

[glad nebula]

but then now the actual value of cosB?

OOHHH WAITT

[inner parrot]

yeah

[glad nebula]

So its just the usual a/h

[inner parrot]

cos A = cos B in this case

[inner parrot]

yep

now you just need the opposite side

to complete the triangle

[glad nebula]

ok, then now number 2?

[inner parrot]

so let’s draw 180 + B

it’s basically a reflection with the origin

[glad nebula]

i just know that it would be in 3rd quadtant

[inner parrot]

not exactly

[glad nebula]

hmm-

[inner parrot]

it should be in the second

since if we add 180 to B

[glad nebula]

is 180-B in third?

[inner parrot]

it should be move two quadrants over

[inner parrot]

yeah

[glad nebula]

ok, so then 180+B is in second quad, but how does that help?

oh wait, then it would just be sinB?

which is 21/29?

[inner parrot]

yep

you got it

[glad nebula]

cooool

then just 1 more before i gotta leave

thanx for all ur help so far btw

[inner parrot]

ofcofc

[inner parrot]

so if we negate B

[glad nebula]

So bc B is in 4th, tan is negative, so it will be -tanB?

[inner parrot]

what quadrant would it be in

[inner parrot]

actually that’s right

[glad nebula]

K cool, so from there, its just tanB, with a negative?

[inner parrot]

yep

[glad nebula]

So all like this?

[inner parrot]

yeah looks good

[glad nebula]

It says theres smth wrong somewhere-

idk where tho

[inner parrot]

oh wait the last should be positive

since tan(b) is negative

-tan(b) would be positive

[glad nebula]

wait how come?

[inner parrot]

tangent is negative in the 4th quadrant

[glad nebula]

mhm

[inner parrot]

so if B is in the 4th quadrant

tan has to be negative

[glad nebula]

mhm

but then the answr is +?

[inner parrot]

yeah

because we’re evaluating -tan(B)

[glad nebula]

Oh waittt, i get it, the y value is negative in the fraction

ok coool i get it now

[inner parrot]

alright nice

[glad nebula]

thanks so much man, really appreciate it

[inner parrot]

ywyw

[glad nebula]

have a good morning/evening

byee

[inner parrot]

you too

[glad nebula]

.close

[safe radish]

Channel closed

Closed by @glad nebula

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne blaze]

how do we solve this

i did y = √(-x^2 +z^2)

[random topaz]

hi i am new here

[nocturne blaze]

then dy/dt = (-2x+2z)/(2√(-x^2+z^2)) * dx/dt * dz/dt

i do not even know where dt came from

[light shoal]

implicitly differentiate?

[bleak delta]

if dx/dt = -1, then x = -t right?

and if dz/dt = 5, then z = 5t

right?

[light shoal]

you don't need to integrate in order to solve this

[bleak delta]

how else

[light shoal]

implicitly differentiate

[bleak delta]

how's it works

[nocturne blaze]

hmm seems that i solved wrong

[light shoal]

well that's for sprites to discover hopefully

[nocturne blaze]

chatgpt showed a way easier to solve it

[nocturne blaze]

i did that

[light shoal]

don't use chatgpt for math, it is almost always wrong

[light shoal]

show what you did

[nocturne blaze]

thats what i concluded at the end: dy/dt = (-2x+2z)/(2√(-x^2+z^2)) * dx/dt * dz/dt

[light shoal]

and when you plug in the given values?

[nocturne blaze]

i get -5/2

[indigo birch]

if the variables are dependent on t

then 2x dx/dt + 2y dy/dt = 2z dz/dt

[nocturne blaze]

the answer is 7

[nocturne blaze]

thats what chatgpt did

but why is my way wrong

[nocturne blaze]

i started like this

[indigo birch]

ur better off doing it the way chatgpt did

its more direct

[light shoal]

you still didn't show your work, only your final answer

how can we know what you did wrong if you don't show the work?

[nocturne blaze]

but why is mine wrong

[nocturne blaze]

is howed you

i showed

i substituted at the end

z = 5 , x=3 , and y = 4

[light shoal]

you showed a total of two lines

did you do it in your head or what?

if so, that's probably where you made the mistake

[nocturne blaze]

i substituted at the end

[indigo birch]

the dx/dt and dz/dt shouldnt be oustide the bracket

they should each multiply -2x and 2z respectively

[nocturne blaze]

i didnt understand

please rexplain

[indigo birch]

dy/dt = (-2x dx/dt +2z dz/dt)/(2√(-x^2+z^2))

it should be this

dx/dt and dz/dt should nto be outside

z=5 btw

dy/dt = (6+50)/(2(sqrt(25-9))

56/(2*4)=7

@nocturne blaze

[safe radish]

@nocturne blaze Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin stump]

Hi

[elfin stump]

Just a quick rational expressions question about factoring

Why wouldn’t you factor 4a-8

The answer in my booklet says it’s

-10

[narrow violet]

Hi! I also get -10.

[strong bison]

Hi

[narrow violet]

I factored 4a-8, like you thought

Let me check your calculations

[elfin stump]

Damn okay so I must’ve just done something wrong

[strong bison]

Blade

[elfin stump]

Yo

[strong bison]

Can u help

[elfin stump]

What no I asked a question

[narrow violet]

h, you have to start a new help channel

[strong bison]

Oh mb

[narrow violet]

You're all good!

okay so @elfin stump I'm not too sure what's happening in the last row

You can actually factor another 2 from your yellow marked expression

[elfin stump]

Oh my god

You’re right

Thanks I’ll redo the question

[narrow violet]

No problem. Hit me up if you need help again!

[elfin stump]

Okay I will! Thanks a lot

.close

[safe radish]

Channel closed

Closed by @elfin stump

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine hornet]

How do I find the Sec270 without using a calculator using reference angles

[alpine hornet]

<@&286206848099549185>

[lusty ridge]

There's some formulas, like sec ( x+180)

[lusty ridge]

I have been summoned

[alpine hornet]

Hi

We are doing reference angles

[lusty ridge]

Yeah

[alpine hornet]

And I have to find the trig ratios exact value using reference angles

[lusty ridge]

Yes

[alpine hornet]

Like sin 120 ,
Sin -60
Cos -225

[lusty ridge]

So you've to find em using just these 3?

If not

Memorise one quarter of the unit circle

[alpine hornet]

No I have a whole paper of ones I have to find

I do

ASTC

Quad one all positive quad Two only sin quad three only tan quad four only cos

Yes

Quadrantal

Its on the line?

it’s on the Y-axis

Which means it’s not in one or the other it’s literally right in between

0

So that one is undefined

What about for one like sin120

2

60

Positive

I’m not sure…

Yes

OHHHHH

That makes sense

[lusty ridge]

You can complete the rest of the unit circle if you learn a quarter

[alpine hornet]

Wait one sec

[lusty ridge]

They just change signa

Signs

[alpine hornet]

You mean this??

Okay! We learned that TODAY lol

[lusty ridge]

This is a 60-30-90 trianfle

What I meant is

The unit circle

[alpine hornet]

So my sin 120 is sqt3/2?

[lusty ridge]

Yup

[alpine hornet]

That’s the answer? Exact value?

[lusty ridge]

This is the unit circle

The values just repeat

[alpine hornet]

Holllytyy crap…

What about pos and neg?

[lusty ridge]

Just memorise the basic 5 - 0,30,45,60,90

[alpine hornet]

So wait okay so like cos300 would be cos60

Which is 1/2

Is it positive?

Ohhh cuz cos is only positive in quad 1 and 4

I think I kind of understand actually!

So it will only ever be like 0,30,45,60,90?

It won’t ever be like.. 48

Wait I’m curious. Can you explain that to me a little how you would break that down?

Also sin45 would be -sqt2/2 right??

OHH

Yeah yeah I gotcha

All positive in quad one

For tan -60 would my angle be 60 or -60

If that makes sense

Okay…. But… using my 0,30,45,90….

So tan-60 is just tan60?

Right so whatever tan60 is but with a negative in front

I don’t think in this kind of format no

I think we did a little but like .. months ago

That makes sense 😃

-sqt3?

Right so… using my tan-60 how would we do this

Okay,

Oh

Crap dude and I went through all the trouble of erasing it lmao

All good!

I really appreciate the help I know I’m kinda hard to work with

So cos-45 would be… -cos45 would be… -sqt2/2?