help-23

[lean otter]

L(y) being the length of the object

side to side

strip depth is how far below its submerged

[humble pawn]

Which question?

[lean otter]

the 1st one

about the triangular pane

[humble pawn]

I don’t see anything about a triangular plane

You mean the “window”?

[lean otter]

?

in the 1st question on my notes

i based the original question on that

the window question on the pane question

[humble pawn]

I am really bad at understanding things, you mean the bottom question?

[lean otter]

no

the top one

[humble pawn]

What are you having a issue with because you seemed to understand it fine

[lean otter]

i was js thinking that

if ur mesasuring the force pushed by the water on the pane

wouldnt u need the 3rd dimension on the tank

[humble pawn]

Ok

[lean otter]

like the pane in the 1st question, its being pushed on both sides, s idk if it matters

in the 2nd one, it was only psuhed on on 1 side so a 3rd dimension was needed

but it was backwards, they gave the force already, u were finding the height

or strip depth or wtv

[humble pawn]

I thought one of the dots between strip depth was a multiplication symbol which is why I was confused on that

[lean otter]

oh

yh no

its js 1 thing

[humble pawn]

Ok so what is Your question now?

[lean otter]

^

[humble pawn]

No because its spread out along that dimension and its equal across

[lean otter]

so it wouldnt matter the volume the f water

whether it goes 20 feet back or js 5 feet

[humble pawn]

Btw im kinda dyslexic each time you said this I thought you said you wouldn’t need the third dimension

[lean otter]

lolll

no, i was wondering if i would need it

[humble pawn]

Not if you’re calculating the force

[lean otter]

okkkk

[humble pawn]

Well my response is kind of misleading if you’re calculating the total force you would but since its on 1 area you don’t

[lean otter]

well

imma js submit the answer

and see ig

i js needa finish the last question

its always the simple trig that stumps me so its taking forever

[humble pawn]

My calc teacher just has us do like 20 questions on a section on Pearson for homework on every section like 6.1 and then another 20 on 6.2

[humble pawn]

And that normally continues to like 6.7 which is what we end on in the 6th section

[lean otter]

same, on pearson, but its 10-15

but we only have 4 modules and 1 semester

so this is module 2 quiz

halfway thru

[humble pawn]

In calc 1 I we had 5 modules and in calc 2 only 2 so I finished 6 and below already

[lean otter]

ohh fair

i took cal i like a yr ago and it was competition season so i never was in state for lectures or nth

so ion remember anything

[humble pawn]

I don’t pay attention to lectures I normally just get stuff done by going to our school’s math lab

[lean otter]

our school has nth

cal ii js recently got offered

to select students only

[humble pawn]

Oh

Well theres only 3 calc professors so only 1 is in there on a blue moon

[lean otter]

lmaoooo

our school is brand new, so we have the 1 cal ii professor

and i go to the younger math teacher cuz he studied rocket science

and took the class

[humble pawn]

Other than a professor who took calc in the 1980s so she is sometimes helpful

[lean otter]

fair

surprising if she remembers it

[humble pawn]

So your school doesn’t offer calc based physics?

[lean otter]

no, i took algebra based physics in person at the local college

our school's slowly expanding their classes

its relatively new

4 yrs old

[humble pawn]

I think that what my friend that dropped calculus is taking

[lean otter]

calc based physics ive heard is ass

[humble pawn]

It is

[lean otter]

my calc professor for calc ii said its basically whats im doing rn

[humble pawn]

Imagine a science like class but for math so we get 1 lecture and then homework with no other ways we can understand it and half the time its on something else thats not even calc either

[lean otter]

ur in cal based physics?

[humble pawn]

Ye

[lean otter]

dang

sounds

frustrating

[humble pawn]

It is

[lean otter]

what grade r u

[humble pawn]

I also have linear algebra which also had calc as a requirement (idk why tho)

[lean otter]

linear algebra?

what do u wanna major in

[humble pawn]

Well 11th or freshmen depending on things

[lean otter]

fair

smart

[humble pawn]

Mechanical engineering

[lean otter]

ohhh makes sense

[humble pawn]

Im gonna get my associates before my diploma cause college ends sooner 😁

[lean otter]

i wish my school allowed all that

i took pre cal twice and was forced to put a yr long gap between cal i and ii cuz they dont have any other math classes

otherwise, i woulda done all this like 2 yrs ago

[lean otter]

ohhh fair fair

same

[humble pawn]

I didn’t have to take pre calc twice cause I got a 26 on the math portion of my act

[lean otter]

SEE

LISTEN

I DID TOO

BUT THEY DONT HAVE CAL III AND IV AND LINEAR ALEGBRA OR NTH

[humble pawn]

Lol

[lean otter]

so i was forced to stick to pre calc for 2 yrs

[humble pawn]

My school doesn’t have calc 4 but im gonna goto a different school for my bachelors anyway

[lean otter]

ohhh fair

im going to a different one for my bachelors next yr

so

hopeuflly better classes

🤞

[humble pawn]

Btw guess how old I am

[lean otter]

16?

[humble pawn]

Ye

[lean otter]

nice nice

wait so

whens ur bday

[humble pawn]

June 28

[lean otter]

so generally on the younger side of ur grade i assume

[humble pawn]

Im gonna get my associates while im still 17

[humble pawn]

Yes

[lean otter]

did u skp a grade or js the dumb aging thing

omg 1 sec

pause

[humble pawn]

the aging thing ig

[lean otter]

whats

tan^3 of pi/6

😭

[humble pawn]

Probably 0

[lean otter]

....

[humble pawn]

Nvm its not 0 but close

[lean otter]

i literally only have a lil bit of trig left till i can submit this

and

its

OK SO

tan pi/6 is

[lean otter]

sqrt3/3

so 3sqrt3/27?

[humble pawn]

Idk

[lean otter]

yes

it is

ok

[lean otter]

well, thats cool

[last wren]

yall still here damn

[humble pawn]

Idk how trig functions work no one taught me

[lean otter]

i keep reading ur name as dolby

[lean otter]

i had a trig test for an academy i wanted to go to and spent 2 days straight, no sleep, teaching myself it

[humble pawn]

Hm

[lean otter]

legit in my room with my crystal lamp and notebooks

i borderline passed

why go for ur associated in high school tho

[humble pawn]

Saves time

[lean otter]

cuz a lot of unis, even if u have ur associates done during high school, still make u take that many more co-ops, internships, or extra classes

ik my friend's gettng her bachelors degree b4 she completes high school

[humble pawn]

Thats if they get the credits not the degree itself

[lean otter]

so the gen ed degree would transfer

cuz im getting my associates degree but

sm unis r only taking sm of the credits and r still saying i have to attend for 4 yrs

[humble pawn]

Well I have college full time I don’t even go to the high school

[lean otter]

ohh s u an

early colly kid

[humble pawn]

Ye

[lean otter]

i did dual cred

i finished my credits last yr tho so i only rlly go to high school for fun to hang and took this class for shits and giggles

dual cred seemed more reasonable since i started freshman yr

already had a lot of my hs credits outta the way

[humble pawn]

How many credit hours do you have?

[lean otter]

i think im 62 or sm

idk

and like 50 high school credits

so 67 adding this one

[humble pawn]

Per semester are you still in hs?

[lean otter]

i didnt take any classes last semester

[lean otter]

oui

ion have any classes

i dont rlly have to go either

[humble pawn]

Ok

[lean otter]

im js enrolled

cuz i didnt feel like graduating

[humble pawn]

Lol

[lean otter]

[humble pawn]

How many college credit hours do you have?

[lean otter]

^

so 67 with this class

[humble pawn]

Thats not possible in 1 Semester

[lean otter]

wym

[humble pawn]

How many college classes do u have rn

[lean otter]

im talking over the course of 2 yrs i got 62

i have 1

cuz ive got nth else to do and they finally offering cal II

[humble pawn]

So 15.5 per semester

[lean otter]

yh

watch me spend 8 hrs on this quiz and get a 30%

imma cry

[humble pawn]

I am required to have 17 per semester so I normally have 18

[lean otter]

they dont allow us to have above 19

so i think 2 semesters i took 19

they dont have a minimum requirement tho

[humble pawn]

I didn’t know my calc test was timed so I didn’t finish it and got a 56 and then retook it and got a 100 (2 attempts max)

[humble pawn]

Its for my Highschool its a very academic highschool

[lean otter]

lmaoo

ours was timed

for M1

and the highest score was i think a 40%

the persn had cheated

[humble pawn]

Well ours didn’t display a timer

[lean otter]

nobody finished more than i wanna say 7 of the 20 questions

[humble pawn]

40 with cheats 💀

[lean otter]

and the test wasnt curved

[lean otter]

fair, ours is career based. generally i think there r requirements but i got special uhhh

procedures

i basically do wtv i want

everyone knows me as the senior for 4 yrs

[humble pawn]

calc 1 when I think on the second test everyone failed so he let us take it home and redo it

[lean otter]

ah

he didnt

let us redo

calc i

ion remember nth from

.close

[safe radish]

Channel closed

Closed by @ionic timber

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense wadi]

idk what it is asking me to do

[somber cape]

I believe trigonometric substitution

[versed wave]

evaluate the integral by drawing it out

[somber cape]

oh

nvm says geometry

[versed wave]

draw sqrt(49-x^2)

[somber cape]

or well

[versed wave]

confine the graph from -7 to 7

and use geometry to solve the integral

[versed wave]

hint: the graph is a semicircle

[safe radish]

@dense wadi Has your question been resolved?

Channel closed

Closed by @dense wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen steppe]

,align
\lim_{x \to 0^-} e^\frac{x-1}{x} , \quad \lim_{x \to 0^+} e^\frac{x-1}{x}

[flat frigate]

レナト (renato , ping if reply)

[earnest rapids]

Well x-1 -> tends to -1 and 1/x is 1/0- which tends to -infinity
So basically -1 * -inf = +infinite
Hence

e^infinite = infinite

[keen steppe]

,align
\lim_{x \to 0^-} e^\frac{x-1}{x} , \quad \lim_{x \to 0^+} e^\frac{x-1}{x}

[flat frigate]

レナト (renato , ping if reply)

[keen steppe]

I made an error in tha latex code, sorry

[earnest rapids]

Aight

First one is infinite though

Try doing same for 2nd case

[keen steppe]

,, x - 1 \quad tends \quad to -1 \quad and \quad \frac{1}{x} is \frac{1}{0^+} which \quad tends \quad to +\infty \
so \quad basically -1 * +\infty = -\infty

[earnest rapids]

-1 * inf = +inf?

last line check again

[flat frigate]

レナト (renato , ping if reply)

[earnest rapids]

Yea

e^(-inf)

[keen steppe]

ohh

0

[earnest rapids]

yep

As we approach from both sides lim is diff, limit DNE at x->0

[keen steppe]

I see it clear as water now

tyvm mr perfect

[earnest rapids]

Indeed

[keen steppe]

I am closing this, thanks mr perfect you are my lord and savior

.close

[safe radish]

Channel closed

Closed by @keen steppe

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

Hi can someone help what am i doing wrong

[lean otter]

The question is the first thing

<@&286206848099549185>

[urban breach]

Send the original question

!original

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[lean otter]

Ok

Its the second one

[humble pawn]

Multiply the coefficients and add the exponents with the same base

[lean otter]

? Wdym

Can you show it

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[somber heath]

Solve the ecuation in Z.

[slender pendant]

Normally i would look at the discriminant

But maybe you can factor something

[somber heath]

My idea was adding an xy

and squaring up

[slender pendant]

Did you try like modular arithmetics?

[somber heath]

No. How would that be?

[slender pendant]

You look at parity for example

You can get that x and y are even

[somber heath]

Right.

<@&286206848099549185>

[tranquil tendon]

this is a quadratic diophantine equation. there is no "general approach" to solving quadratic diophantine equations although there is an algorithm for some such equations, and this one does fall within that scope. in order to usefully proceed i need to know what context you've encountered this problem in and the level of study you've attained

[stable oyster]

I have a solution!

complete the square first

you already have x^2 and 2x so what do you have to add to complete the square? @somber heath

[somber heath]

1

[stable oyster]

yup

and then you can factor x^2 + 2x + 1 to (x + 1)^2

and factor out y in -xy - 3y

[stable oyster]

sorry 2x

so you end up with (x + 1)^2 - y(x + 3) = 7 right because you have to change - to + in the 2nd term

and then you want the (x + 1) to kind of become (x + 3) in a way so you can factor everything in the equation

[somber heath]

Yes

I ended up with -x-3 too lol

[stable oyster]

oh did you?

how lol

[somber heath]

When i factored out y in -xy - 3y

Made a mistake

[stable oyster]

Ohh alright

[somber heath]

So like

[stable oyster]

how can you do that?

[somber heath]

I have no idea

[stable oyster]

difference of 2 squares

[somber heath]

like a²-b²

[stable oyster]

yup

[somber heath]

It is (a+b)(a-b)

[stable oyster]

Yes

[somber heath]

Do we multiply by y?

Not really

[stable oyster]

I don't think you can

But you want to subtract something so ( x + 1)^2 - something squared is (x + 3) * something else

What can you subract with

[somber heath]

Is it (x-2²)

(x-2)²

@stable oyster

[stable oyster]

nah not really i did this

(x + 1)^2 - 2^2

btw does both x and y have to be integers?

[safe radish]

@somber heath Has your question been resolved?

[stable oyster]

@somber heath

nevermind you only get integers i think

[somber heath]

Yes

[stable oyster]

alright cool

[stable oyster]

what do you get here?

(x + 3)(x - 1) right?

and your 2nd term is -y(x + 3)

so you can factor (x + 3) out of everything because you have (x + 3) in both terms

so the equation is (x + 3)(x - 1 - y) = 7 - 4 which is 3

@somber heath sorry for pinging you so much bro

now if x and y weren't integers this would have infinitely many solutions but because they are integers the parentheses must be the prime factors of 3

because the prime factors of 3 are the only integers that give 3 when multiplied together

and 3 is a prime number so the prime factors are 1 and 3 (and -1 and -3)

if one of the parentheses is one prime factor then the other parentheses must be the other prime factor

[safe radish]

@somber heath Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[somber heath]

.reopen

[safe radish]

✅

[somber heath]

No worries, I was doing some chemistry.

[safe radish]

@somber heath Has your question been resolved?

[safe radish]

@somber heath Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour violet]

I’m having some trouble with the back velocity formula

[sour violet]

The back, center, and ,forward

Formulas

The back velocity formula im given is

Xi-Xi-1/delta(t)

So initial position-Initial position-1/ change in time

Am I just reading this wrong?

<@&286206848099549185>

[safe radish]

@sour violet Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred compass]

can someone explain that step please?

[charred compass]

where did the e go?

[sturdy totem]

e^c is a constant

so putting C instead of e^c is basically the same thing

just a constant

[charred compass]

ouh okay, but if I have given an initial condition for the differential equation, this is not the case, is it?

[empty gyro]

Depends on your initial condition, but it really shouldn't make a difference. You'll get the same final equation.

[safe radish]

@charred compass Has your question been resolved?

Channel closed

Closed by @charred compass

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter orbit]

I am trying to prove my new theorem, that if the rise between a pair of points is the same as the rise between another pair of points, and the run between the first pair of points is the same as the run between the second pair of points is the same, then the length of the hypotonuse (distance between both points) is the same for both pairs of points.

Can someone help me write the proof?

[median vigil]

you could use triangle congruence

[bitter orbit]

Can you elaborate?

[lean otter]

so let A and B be your first pair and D and E be your second pair, now C is the point that makes ABC right, and same for F and DEF

so prove ABC and DEF congruent

[bitter orbit]

Side angle side would work, right?

[wheat locust]

distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ in the plane can be defined as $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$. You could look at this like $\sqrt{(\operatorname{run})^2 + (\operatorname{rise})^2}$

[lean otter]

yes use that

[flat frigate]

soulgazer

[bitter orbit]

What should I call the theorem and what should the theorem state?

And, in the given, if I state that the rises and runs are equal, then cant I use substitution property of equality to set the distances =?

[wheat locust]

sure

[bitter orbit]

What should I name it and what should it state?

[wheat locust]

idk here's an example... Let $(x_1,y_1)$, $(x_2,y_2)$, $(a_1,b_1)$, $(a_2,b_2)$ be points such that $|x_1 - x_2| = |a_1 - a_2|$ and $|y_1 - y_2| = |b_1 - b_2|$. Then the distance between $(x_1,y_1)$ and $(x_2,y_2)$ is the same as the distance between $(a_1,b_1)$ and $(a_2,b_2)$

|x_1 - x_2| is the "run" between the first two points, etc

difference between the x coordinates

[flat frigate]

soulgazer

[bitter orbit]

Statement: Let ΔABC and ΔDEF be two right triangles. If the height and base of ΔABC are congruent to the height and base of ΔDEF, respectively, then the hypotenuses AC and DF are congruent.

[wheat locust]

added absolute values but you could take them out and still says pretty much the same thing

[bitter orbit]

Alright, I am going to try writing this proof, I will let you know how it goes

[safe radish]

@bitter orbit Has your question been resolved?

[bitter orbit]

@wheat locust How could I prove that the run and rise of a hypotonuse is equal to its base and height

[wheat locust]

i don't really think that's something that needs proof

[bitter orbit]

In the proof I wanna convert the rise and run to the length of the base and height. In the proof, can I insert the rise and run into the pythagoream theorem without saying the base and height are congruent to the rise and run?

@wheat locust so what would the given be?

[wheat locust]

yea that sounds kinda excessive

[safe radish]

@bitter orbit Has your question been resolved?

Channel closed

Closed by @bitter orbit

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[polar wraith]

The second bullet has been driving me crazy. I know that the first bullet has no solutions since gcd(12,22) does not divide 3, but I'm having a really hard time using the Euclidean Algorithm for finding gcd to then determine the format of the solutions. My work so far will follow shortly.

[polar wraith]

The first photo is my neat work that I'm entirely confident in, the second photo is most of what I've tried so far without much luck.

[slender pendant]

Its in Z or N

Guessing Z

[round shore]

diophantine means z

[polar wraith]

Yeah in terms of integers

[slender pendant]

Why doesnt the first bullet have a solution?

[polar wraith]

Based on the most recent lecture, I'm supposed to reverse engineer the gcd stuff to come up with the answer in terms of 1200 and 22. Problem is though that I can't seem to get it just in those terms

The first bullet doesn't have a solution in terms of Z because gcd(12,22)=2, which does not divide 3.

[slender pendant]

Ok ye nvm i just understood you wrongly.

[polar wraith]

Np!

[slender pendant]

Well if gcd(1200 , 22) divides 32. Then the second bullet has solution

You can find all solutions with modular arithmetic

[polar wraith]

Yeah it does since 32 is a multiple of the gcd. So I should be able to scale once I find a combination of 1200x+22y that =2

[slender pendant]

So you are stuck at that part?

[polar wraith]

Not sure that I covered modular arithmetic in class, so I don't think I could use it.

I'm stuck at finding one of the combinations in the first place. The general rule comes after that

[wheat locust]

that's only really helpful (and not necessary) for describing all the solutions after you find one anyway

[slender pendant]

Well first divide by 2 to make it easier

$600x + 11y = 1$

[flat frigate]

casework

[polar wraith]

So that'd give me 2(600x+11y) = 2

[slender pendant]

Now all you need to try is all x from 0 to 10

One of them will have the sol

[round shore]

Really, you are finding x and y such that 1200x + 22y is some factor of 32, not necessarily 2.

[slender pendant]

Fyi you can write 600 mod 11

[round shore]

(because we divided, it should be a factor of 16)

[wheat locust]

you really take your name to heart huh

[polar wraith]

I'm finding for 2 because that's how it was done in class. I need to use the gcd algorithm or it's wrong

[slender pendant]

,calc 600 mod 11

[flat frigate]

Result:

6

[slender pendant]

$6x \equiv 1 \pmod {11}$

[polar wraith]

Here let me see if I can find notes from a similar example to show what I mean

[flat frigate]

casework

[slender pendant]

Shouldnt be that hard to solve

[polar wraith]

Please stop using modular algebra, it's entirely unhelpful since I can't use it

[slender pendant]

Ok then you can always do casework

[round shore]

Looking at your work, it seems that you only checked values for y, keeping x constant at 1.

That is what is most detrimental to your solve

[polar wraith]

Here's a similar example from class that shows how I need to get to my answer

[round shore]

You know that you have to find some x,y such that 600x + 11y = 1

When you try x = 1, you get

600 + 11y = 1, or 599 = -11y

599 is not divisible by 11, so this is impossible

Trying x=2, we get 1200 + 11y = 1, or 1199 = -11y

[slender pendant]

Is that some algorithm or pure guessing?

[round shore]

We see that 1199/-11 = -109, so x = 2, y = -109 is a solution to the equation

[polar wraith]

Okay, but how would I put that into the format I showed above? I can't just guess and check.

I need to work with the numbers in my gcd algorithm, as I've said before. I can't just skip steps.

[round shore]

This seems like a lot of guesswork, and not a lot of algebra

The only way I can see to logically show steps without guesswork is with modular arithmetic, something that will hopefully be covered later in your course.

[polar wraith]

https://en.wikipedia.org/wiki/Euclidean_algorithm

[round shore]

I think he was referring to the second part of the solve

(the part after you find gcd)

[slender pendant]

Yes the last part

Im looking at all tb books i have if there is some algorithm

[polar wraith]

The numbers I'm getting are from the algorithm.

Ex: 3 = 15-18 is from the second line in the algorithm (18 = 15(1)+3)
15 can then be expanded into (123-18(6)) based on the first line in the algorithm.
Then I combined like terms to get the equaation into terms of 123 and 18.

[round shore]

How would you get (123 - 18*6) = 15 without guesswork?

Its another diophantine

123x + 18y = 15

[slender pendant]

I think the algo is like

ax + by = c
c = a - r
c = a - (b - r_2)
...

Where r is just some remainder to get to that num

[round shore]

Yea this method should work

I just think that it is impossible to do without at least a little bit of guesswork

[slender pendant]

Its like reverse gcd or something

[polar wraith]

In the first line in the algorithm, 123 = 18(6) + 15 can be rearranged to 15 = 123 -18(6) with basic algebra.

[polar wraith]

As I have said multiple times now, that's exactly what it is.

[round shore]

oh i figured it out

this is what euclids gives you

1200 = 22 * 54 + 12
22 = 12 * 1 + 10
12 = 10 * 1 + 2
10 = 2 * 5 + 0

[polar wraith]

yes, following so far :)

[round shore]

So we have that 2 = 12 - 10

[polar wraith]

mhm!

[round shore]

wait

first, we have that 1200 - 22 * 54 = 12

[polar wraith]

yeah I'm getting stuck there too

[round shore]

Then, we have that 10 = 22 - (1200 - 22*54)

So 2 = 1200 - 22 * 54 - (22 - (1200 - 22*54))

And that is what we were looking for all along

Do you understand what I did there?

@polar wraith

[polar wraith]

probably, let me write that out to be sure :)

Have a hard time reading out math, gotta write it out to fully absorb lol

[round shore]

Take your time

All I did was a couple of substitutions

The main thing that I (and probably casework) were missing was how you got 18 * 6 - 123

We thought it was guesswork

[polar wraith]

I see. Sorry if I wasn't being super clear, didn't mean to be vague.

[slender pendant]

I just forgot that gcd algo is used for solving this things. Once you learn the easier ways. You forget the hard ones.

[polar wraith]

Looks like it ended up working! I got 1200(2)+22(-109)=2 after combining like terms. Now I just have to scale, which I know how to do. Thank you!

I checked with my TA about the "all solutions" part, since if I were to guess, it's probably the modular algebra you mentioned before. My prof has been rushing the past few classes, so I wouldn't be surprised if he just didn't cover it.

[round shore]

real

[polar wraith]

I think I'll wait for my TA's response on the rest for now. Thank you so so much both of you! :)

.close

[safe radish]

Channel closed

Closed by @polar wraith

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

So, I had to solve 2log₂(x) = log₂(4) - log₂(x). So I did everything correctly till I had to work only with x and 4 only, so I had:
x² - x = 4
But here's the thing, I factorized x and passed the exponent to the side, but I don't know if I actually can do both of these things, so I had:
x(x - 1) = ±√4
Can I actually do both of these things? Thanks

[lean otter]

Just a curious high school student whos currently learning pre-calculus on her own cause I find math amusing

[placid oak]

how did you get to x^2 - x = 4?

[devout shale]

but also going from
x^2-x=4
to
x(x-1)=+/- sqrt(4)
is incorrect

x^2-x=x(x-1)

so if x^2-x=4 then..

[lean otter]

2log₂(x) = log₂(x²)
2log₂(x²) = log₂(4) - log₂(x)
log₂(x²) = log₂(4.x)
x² = 4x```

[placid oak]

going from third to fourth line is wrong

log(a) - log(b) is log(a/b) not log(ab)

[lean otter]

oh yeah you're right

well that would be

2log₂(x) = log₂(x²)
2log₂(x²) = log₂(4) - log₂(x)
log₂(x²) = log₂(4/x)
x² = (4/x)```
right?

[placid oak]

yes

but it might have been easier just to do
\begin{align*}
2\log_2(x)&=\log_2(4)-\log_2(x)\
3\log_2(x)&=\log_2(4)\
3\log_2(x)&=2\
\log_2(x)&=\frac{2}{3}\
x&=2^\frac{2}{3}\
\end{align*}

[flat frigate]

Desync

[lean otter]

but it says here the answer is just 2

[placid oak]

you can immediately see that shouldn't work since if you substitute x=2 into the original expression you have log(4) on both sides and an extra log(2) on the right

so the equality doesn't hold

[lean otter]

weird

thanks for your help

.close

[safe radish]

Channel closed

Closed by @onyx drift

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne blaze]

can someone help

[nocturne blaze]

i do not understand how the sin2x

becue sin2x/4

[hot thistle]

can you rephrase your question

[thin bridge]

1/2 from chain rule
the other 1/2 from the factor of 1/2 outside the integral

[versed wave]

he probably meant how $\frac12 \frac{\sin2x}2 = \frac{\sin2x}4$

[flat frigate]

FungusDesu

[nocturne blaze]

chain rule?

i am finding antideriviative

how chain rule

[devout shale]

you're undoing the chain rule

[nocturne blaze]

anti deriviatve of 1 is x, -cos(u) = -sin(u)

[versed wave]

integration by substitution is also known as reverse chain rule

[devout shale]

if you think it should just be sin(2x)

check by taking the derivative of that

[nocturne blaze]

yes

[devout shale]

you'll see the derivative is 2cos(2x)

[nocturne blaze]

-sin2x/2

what did i do wrong in my u sub

u substitution

because i do not get -sin(2x)/4

[median vigil]

there is a constant 1/2 in front of the integral

[nocturne blaze]

i did u = 2x
1/2 du = dx

[nocturne blaze]

yes

[nocturne blaze]

i took the 1/2 outside the intergal here

[thin bridge]

there's another 1/2 from the original integral

[nocturne blaze]

so it should be 1/4x * sin2x/4?

[thin bridge]

wdym by the x 0

still no

what's with the
1/4**x**

what's that x doing there

[nocturne blaze]

i do not get you

now we have 1/4 outside the intergal

1/2 from the du , and 1/2 from the original function

[thin bridge]

from what you typed, you're saying that you would have
$$\frac14x \frac{\sin(2x)}{4}$$

[flat frigate]

ℝαμΩℕωⅤ

[nocturne blaze]

yes

[thin bridge]

is incorrect

[nocturne blaze]

• c

[thin bridge]

lets break this down from the very start

first applying linearity will give you
$$=\blue{\frac12 \int 1 \dd{x}} - \red{\frac12 \int \cos(2x) \dd{x}}$$

[flat frigate]

ℝαμΩℕωⅤ

[thin bridge]

can you integrate the blue and red separately

[nocturne blaze]

1/2 x - 1/4 (sin2x)

oh i think i got it

its 1/4 because i pulled out another 1/2 from the du

can i ask another quesiton please

this is so hard

i do notknow how to start

[thin bridge]

the work is all there, which step(s) do you have an issue(s) with?

[nocturne blaze]

ok first how did 1-2sin^2 become cos^2x - sin^2x

[thin bridge]

pythagorean trig identity 1 = s^2 + c^2

their work there is actually a bit inefficient

[nocturne blaze]

so they used 2 identities

double angle identity

and the pathagorean

rip to me, i do not have them memorized

[thin bridge]

1 - 2sin^2(x) is one of the forms for the double identiy

that can be converted to cos(2x) directly

[nocturne blaze]

so cos(2x) * sin(2x)

u = 2x
1/2 du = dx?

i am lost

how do i use u substitution here

[thin bridge]

well from that step, they just used another double angle identity (the one for sine)

[nocturne blaze]

so cos^2x * 2sinx*cosx

so u = sinx
du = cosxdx

cos^2x = ( 1-sin^2)

(1-u^2)( u)

right so far?

u - u^3 = u^2/2 - u^4/4

sin^2 - sin^4/2 + c

lol

i messed up

can you please solve it for me

[thin bridge]

identities go in both directions

[nocturne blaze]

so my answer is correct?

[thin bridge]

no, looks like a complete mess

$$\sin(2\theta) = \blue{2\sin(\theta)\cos(\theta)}$$

[flat frigate]

ℝαμΩℕωⅤ

[thin bridge]

if you start from the right side, you can apply the identity to get the left side

note that here you have
sin and cos of the same thing being multiplied together

also it looks like you mixed cos(2x) up with cos^2(x) in the very first line

[safe radish]

@nocturne blaze Has your question been resolved?

[nocturne blaze]

yes my bad

ok so after sin2x * cos2x

i do , 2sinxcosx * cos2x

u = cos
du = sin dx

i am lost after that

[thin bridge]

no

if you start from the right side, you can apply the identity to get the left side

sin and cos of the same thing being multiplied together

that double angle identity allows to you to express that as a single trig function

to make it clearer
$$\sin(2\theta) = \blue{2\sin(\theta)\cos(\theta)} \implies \red{\sin(\theta)\cos(\theta)} = \frac{\sin(2\theta)}{2}$$

[flat frigate]

ℝαμΩℕωⅤ

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense wadi]

WHat does it mean to give the values of the sums in terms of n

[hot thistle]

the answer can't be just a number, it depends on n

since the summation is going up to n

[dense wadi]

oh so

\for examp[le this

[hot thistle]

yes

[dense wadi]

what is this ever useful for

to convert riemann sum to n

[hot thistle]

im not sure what kind of answer you're looking for

[dense wadi]

ah nvm i just found out ty

.close

[safe radish]

Channel closed

Closed by @dense wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white mirage]

im not sure how to find the 11th vector

[spice furnace]

I don't think there is a 11th but I can't think of rigorous proof.

[white mirage]

there is an 11th (so says the textbook)

[buoyant shadow]

there is

i don't know how to find it, it's boring

[white mirage]

bruh

[buoyant shadow]

start with 2d

it's in the middle of two vertically

so we know the y

we need x

it's already boring

[white mirage]

im not sure why u have 5sqrt(2)/2

[safe radish]

@white mirage Has your question been resolved?

[safe radish]

@white mirage Has your question been resolved?

Channel closed

Closed by @white mirage

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber patio]

For b look at the box where the column for large cafeteria meets the row Senior
You can then solve it similarly to how you did A

Yes

I think it should be (635+595)/2640
But I'm not too sure
Haven't done these types of Q's in a while

[safe radish]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Please don't occupy multiple help channels.

[humble helm]

Send me if they send you

[charred warren]

sure

[dense wadi]

pretty sure there is one on khan academy

and its pretty structured as well

like list of courses

[humble helm]

Anything else?

[dense wadi]

not really it has the major topics

[humble helm]

K

I'll use khan academy

[safe radish]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense wadi]

it seems to me that its just -4 + 2?

[humble helm]

Well

You entered -2

He says the correct answer is –2

Maybe because of it

-2 and –2

Or —2

[dense wadi]

no he said -2 is wrong

-3 is wrong too

[humble helm]

Well

[torpid fable]

I think ur reading axis wrong

Area of bottom triangle is not 4

[dense wadi]

today i leanrde desmos squared are not to be trusted

answer is 0.75

.close

[safe radish]

Channel closed

Closed by @dense wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dull stratus]

why is this 0.02A and not 1.02A?

[sharp tiger]

because da/dt denotes the change in some time, 1.02 would the new amount after a second not the actual change (which is current-initial)

[safe radish]

@dull stratus Has your question been resolved?

[dull stratus]

oh ok thankss

[safe radish]

Channel closed

Closed by @dull stratus

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[versed wave]

Evaluate $\int_0^3 \frac{dx}{1+f(x)}$

[flat frigate]

FungusDesu

[versed wave]

$f(x)$ is continuous on [0; 3] and $f(3-x)f(x) = 1$, $\forall x \in [0; 3]$

[flat frigate]

FungusDesu

[versed wave]

tried subbing and didnt work out

i did get $\int_0^3 \frac{f(t)}{f(t) + 1}dt$

[flat frigate]

FungusDesu

[versed wave]

which is equivalent to the original integral

t = 3 - x

[spice grove]

$\int_a^b f(x) \dd x = \int_a^b f(a+b-x) \dd x$

[flat frigate]

! What the hell am I doing here?

[spice grove]

yeah this

[versed wave]

this is an actual property?

[spice grove]

It is.

[versed wave]

whats its name

[spice grove]

Don't know properties by name, but it's easy to prove.

[quartz canopy]

I think it's called king property

[quartz canopy]

Use this then simplify the integral and add the original integral with this

[versed wave]

learned something new today

alright, let me try real quick

[quartz canopy]

Answer should be 3/2 maybe

[spice grove]

This is what you got already, which is the same as what you'll get afer using this.

The idea is that the integral is going to be the same either way, so like stated already you can add the two and say the new integral (the sum) is actually twice the required integral.

[versed wave]

alright, i think i got it now

thanks for the help

.close

[safe radish]

Channel closed

Closed by @versed wave

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd topaz]

-2 isnt a tan value

5pi/4 being -2 doesnt make sense

[sonic sierra]

it is

[shrewd topaz]

where

[sonic sierra]

range of tan is R

[halcyon carbon]

,w plot y=tanx

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by pure1144

[sonic sierra]

tan can range from +infinity to -infinity

[shrewd topaz]

so how do i find it on the unit circle

(-sqrt2)/2 * -2/(Sqrt2) is -1

the question is asking me "find the angle at which tan is -2"

[halcyon carbon]

It is wrong.

You need a calculator.

[shrewd topaz]

did tan^-1(-2) and got -63.43

[halcyon carbon]

In radians

[shrewd topaz]

how come its in radians

is there a way to know when to use degrees/radians when the question doesnt specify

like does radians apply for certain questions

[shrewd topaz]

how did they find 5pi/4 as the exact value is what im asking

[safe radish]

@shrewd topaz Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic vale]

i get a different solution, i get sin instead of cos

[safe radish]

@mystic vale Has your question been resolved?

[safe radish]

@mystic vale Has your question been resolved?

[plucky elk]

cosine and sine differ by just a phase shift

[mystic vale]

yea

i tought so

but this means that phi needs to have a pi/2 shift

but i don't know ....

how do they get cos then?

[safe radish]

@mystic vale Has your question been resolved?

[mystic vale]

the phase shift is still the same, doesnt include the pi/2.

[safe radish]

@mystic vale Has your question been resolved?

[safe radish]

Channel closed

Closed by @mystic vale

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal pivot]

Hello, my question has to do with the definition of exponential growth, which I realized I might not be understanding correctly.
Bluntly, is y = 200*(x^4) an exponential function?

More details:
I'm playing a game where you create warehouses.
The more warehouses you have, the more they cost.
For fun we figured out that the cost (y) relates to the number of existent warehouses (x) following the function y=200(x^4) where x > 0 and is part of "ℤ*+"

Can we classify this cost as exponentially growing?

[zinc hornet]

No that is a polynomial function

[vestal pivot]

So we can't really call it exponential growth then?
Would it be then...polynomial growth?

[zinc hornet]

yes

[vestal pivot]

Thank you.

.close

[safe radish]

Channel closed

Closed by @vestal pivot

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal kindle]

In the ring $A = \mathbb{Q}[X]$, consider for all $\alpha \in \mathbb{R}$ the set $I_{\alpha}$ of polynomials P belonging to A such that $P(\alpha) = 0$. $I_{\alpha}$ is an ideal of A. Determine a polynomial P of A such that $I_{\alpha}$ is the principal ideal PA for $\alpha = 1$ and $\alpha = 2$

[flat frigate]

lilisworld.

[unreal kindle]

what is P

I_1 = ?

<@&286206848099549185>

[junior smelt]

Factor theorem maybe?

Especially as 1 and 2 are rational themselves...

[unreal kindle]

yes makes sense

[unreal kindle]

so (X - 1)P(X) = 0 for alpha=1 because P(1)=0?

[junior smelt]

Basically any polynomial P such that P(1) = 0 has (X - 1) as a factor

[unreal kindle]

and for alpha = sqrt(2)?

[junior smelt]

So P(X) = (X - 1)Q(X) for some other polynomial Q

[unreal kindle]

is it X - sqrt(2)?

[junior smelt]

Not quite exactly, as sqrt{2} isn't rational

But you can find some other polynomial which has sqrt{2} as a root and has rational coefficients too

[unreal kindle]

ok so i just need to find a polynomial that only has rational coefficients and sqrt2 as a root, x² - 2?

@junior smelt

[junior smelt]

That would do

[unreal kindle]

ok tnakss 🙂

.close

[safe radish]

Channel closed

Closed by @unreal kindle

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wise shuttle]

Why here its just "one" horizontal "one" vertical
Not 2 horizontal 2 vertical

Since we have 2 theta values

[faint seal]

Because both the theta values for each case define the same line

The vertical line containing point (2,0) and (-2,0) is the same

[junior smelt]

(that’s for the horizontal tangents though, isn’t it?)

[faint seal]

Yeah confused x and y mb

[safe radish]

@wise shuttle Has your question been resolved?

[spice furnace]

You can do sketch on desmos. At first it will seem like there two vertical tangents however note that theta< 7pi/4

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warped moat]

Hellooooo,, i need help with properties of circle 😭

[warped moat]

Im very confused if OAC is an isosceles...😂

I meaN i think it iss but im not sure if OBC is a right angle

[little cosmos]

what is the length of OA equal to

in terms of the circle

?

[warped moat]

Its equal to the uM radiuS?🤣

[little cosmos]

correct

what is the length of OC equal to

in terms of the circle

[warped moat]

Also the radiussss

So its an isosceles then?

[little cosmos]

yes

additionally, what is OB's length equal to?

[warped moat]

Also radiusss?

[little cosmos]

yes

[warped moat]

OHHHH

WAIT i gEt it nowwww

[little cosmos]

yes

[warped moat]

soooooo i minus 67° by 22° to get x??

[little cosmos]

yes

[warped moat]

AH okaaayyyy TYTY omggg😂😭

[safe radish]

Channel closed

Closed by @warped moat

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

is the answer for m +-4 or just -4?

[safe radish]

Please do not ping individual helpers unprompted.

@lean otter Has your question been resolved?

[lean otter]

neither?

well if we put substitute 4 into f(x) and 0 into x we get 4 = |m|

[tardy mango]

Ignore that

[lean otter]

ah

[tardy mango]

You have that $m=\pm 4$

[flat frigate]

Civil Service Pigeon

[tardy mango]

You also have that the x-intercept is positive

So this allows you to eliminate one of the possibilities

[lean otter]

how does having a positive x-intercept allow me to eliminate one of the possibilites?

oh wait

hmmm

if f(x) = 0

then m has to be negative, since 2x must be positive

ohhh yeah that makes sense

thanks

[safe radish]

Channel closed

Closed by @gentle wren

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe needle]

is any of those okay?

[low raft]

Hey dude can you explain this

Article are marked at a price which gives a profit of 25%. After allowing a certain discount,the profit reduces to 12½%. Find the discount percent.

[ruby bolt]

!occupied

[safe radish]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[ripe needle]

25% --- 100%
12.5% --- x?

i guess thats the answer, im not sure

@low raft

[thin bridge]

you should be using the right Venn

[ripe needle]

okay

[ripe needle]

is it even allowed to make the venn without all three thingies intercepting at the middle?

[thin bridge]

probably not

[ripe needle]

[pfelfpa'pflds';lf's;laf

someone help me

[low raft]

@ripe needle The answer is 10%

[ripe needle]

okay

[low raft]

Can you tell me the full solution

[ripe needle]

if this gave you 10, it is wrong

@low raft

[low raft]

Oo

Pls tell me the right one

[ripe needle]

no

do it

you have to 12.5 x 100 / 25

@low raft

[low raft]

50

[ripe needle]

yes

if the price of the product went down 50%, what discount was applied?

[safe radish]

@ripe needle Has your question been resolved?

Channel closed

Closed by @ripe needle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal drift]

I have the first image as a solution to the problem in the second image, however the answe sheet says the solution is (x-3)(x+3), why am I wrong?

[vestal drift]

The question says find a factorization so I feel like that implies there are multiple, and this is the way that is outlined, however I'm stressing that it doesn't align with the answer sheet

am I right? is the answer sheet right? are we both right?

[safe radish]

@vestal drift Has your question been resolved?

[vestal drift]

<@&286206848099549185>

[safe radish]

@vestal drift Has your question been resolved?

[safe radish]

@vestal drift Has your question been resolved?

[vestal drift]

I just need to know if Im in the wrong

Wait, both answers are correct I believe since in Z_7 4=-3

I just want confirmation still though

Please

[safe radish]

@vestal drift Has your question been resolved?

[vestal drift]

Begging atp

[low canyon]

Yes

[vestal drift]

perfect

.close

[safe radish]

Channel closed

Closed by @vestal drift

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grim fjord]

Need help on 3 and 4 physics plz ( Momentum and Impulse)

[safe radish]

Please don't occupy multiple help channels.

[grim fjord]

<@&286206848099549185>

W 0 help 😭

[safe radish]

@grim fjord Has your question been resolved?

[safe radish]

@grim fjord Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile lodge]

Please help I don’t understand how to get these two answers I’m grade 10

[lean otter]

@agile lodge use this

u opened

[agile lodge]

Ok thank u

[lean otter]

np

[agile lodge]

Please help I don’t understand how to get these two answers

I don’t really know where to begin other than multiple by the two conjugates

[terse lichen]

what was the question to begin with

[agile lodge]

Rationalize the denominator

Denominator

It’s textbook question I know the answer just not how to get there

Lol sorry

[terse lichen]

are the pictures you posted the question or the answer

[agile lodge]

The question

[terse lichen]

i see

well just split the roots

[agile lodge]

4root and 3 root

So I get two

But don’t I multiply it by the -2/3

[terse lichen]

!showwork

[safe radish]

Show your work, and if possible, explain where you are stuck.

[agile lodge]

It’s kinda hard to understand my writings bad but I tried to get 2 root of 3 but if I multiply by 4 I get -4/3

I think I gotta go to bed it’s late for me but I will probably join again tomorrow to ask whoever is available for help but thank u anyways

[terse lichen]

hold on lemme try it for a bit

[safe radish]

@agile lodge Has your question been resolved?

[safe radish]

@agile lodge Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mental ether]

is there a function thats equivalent to a*b^n, but between each multiplication, apply the ceiling function, i.e. f(2) = ceil(ceil(a*b)*b) f(3) = ceil(ceil(ceil(x*b)*b)*b) etc. i had this equation, ((1-p)^(n-1))x = 2, rearranged for n = log_(1-p)(2/x) + 1, im trying to calculate the number of rolls in this game im playing, needed to use up x attempts, when you use a percentage px attempts per roll, with a minimum of 2 attempts per roll (hence the = 2), but then i realised, it rounds px up, each time you press roll, so i need some function f, that captures that behaviour

[mental ether]

(apologies for the lack of LaTeX, im terrible at it)

[hot thistle]

you can certainly define it inductively, but if youre trying to solve for n i don’t think that’ll be much help

[mental ether]

yeah, that was the issue 😅

[hot thistle]

even if the function was
ceil((1-p)^nx)= 2, would you be able to somehow solve for n?
ceil doesn’t have an inverse function

[mental ether]

hm, yeah you're right,, perhaps i should just write a python function to do it

[safe radish]

@mental ether Has your question been resolved?

[mental ether]

from math import ceil

def rollsNeeded(attempts, p, n=0):
    attempts -= min(attempts, max(2, ceil(attempts*p)))
    n += 1

    if attempts == 0:
        return n
    else:
        return rollsNeeded(attempts, p, n)
```idk if you know python, but this should be relatively easy to understand... does this look right to you? given the problem i described

i don't know how i would test if its correct 😭

oh, well wait, i can just say, okay with 1000 attempts, p = 0.5, and work out, thats.... 10 rolls, and plug it in

okay yeah it seems correct

.close

[safe radish]

Channel closed

Closed by @mental ether

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe radish]

Please don't occupy multiple help channels.

[timid scroll]

I dont understand any of this?

[versed wave]

!1c

[safe radish]

Please stick to your channel.

[timid scroll]

no

.close

[safe radish]

Channel closed

Closed by @timid scroll

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen parrot]

Hello

[brazen parrot]

Is 1:3 same as 1/3?

[frozen marlin]

yes

[desert pasture]

yes

[brazen parrot]

1/3?

[frozen marlin]

yep

[brazen parrot]

how come the answer is 1/4

[frozen marlin]

no no no

what they mean

is that one side

is 1/3 of the other

so 3/4 and 1/4