help-23

[round rover]

H goes to H'

and I goes to I'

look at each of their coordinates before and after the transformation

[fading iris]

Ok

[safe radish]

@fading iris Has your question been resolved?

[fading iris]

.close

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[near echo]

Hi I am wondering how I can prove that the series (∑ 1-cos(1/n))_n (infinity sum) converges.

[lean otter]

,,\sum_{n\in\Z_{\ge0}}1-\m\cos{\41n}

this is it yes?

[eternal carbon]

hm it says cos(1/n)

[eternal carbon]

and presumably n is indexed from the natural numbers

v minor note

[lean otter]

anyways this is an easy application of comparison test

[lean otter]

yeah that's fine

[lean otter]

do you have an Idea with this in mind? @near echo

[near echo]

yes

[near echo]

well i was going to compare to 1/n^2 because 1/n^2 >= 1-cos(1/n) on (0, inf) but i can't prove that

[lean otter]

use limit comparison test then

good thing about limit comparison is that u don't really need to know which one is bigger or not

you just need to verify if the limit goes to something other than infinity

[near echo]

yeah thats also another place i got stuck

i thought about doing limit comp but what do i compare it to

[lean otter]

try out 1/n^2

that's something that converges

[near echo]

ok so i can compare to 1/n^2 but then i have to use lhopital twice, is there a different way? i feel like i remember my professor doing this in class briefly with a different method

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@near echo Has your question been resolved?

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[spark thicket]

I need help solving D.

[spark thicket]

I need help solving D.

[lean otter]

how many rattle sankes were reported in 2018?

[spark thicket]

yes in %

because idk

[lean otter]

no just tell me in numbers rn

9, right?

how many of them were from bald mountain, 6, right?

[spark thicket]

yes corrct

[lean otter]

Now try finding what percent of 9 is 6

lets say that x percent of 9 is 6, so that is $\frac{x}{100} * 9=$6

[flat frigate]

EinPest

[spark thicket]

6.6666666 right?

[lean otter]

point mistake

66.6

[spark thicket]

yay thank you!!!!

.close

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[lean otter]

welcome

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[brazen parrot]

excuse me

[brazen parrot]

i have one angle which is 32 but i cant find the other angle

[shadow sparrow]

hi

[brazen parrot]

hi

[shadow sparrow]

sorry, AB and BC are tangent to the circle so they should only touch at one point right?

nice 🌲

[brazen parrot]

sorry no understand

can u pls draw ?

i an visual learner

[shadow sparrow]

tangent means only touching at one point

like this, touching at only one point. in this case AC and BC are tangents to the circle

[brazen parrot]

oh i see

did i draw my diagram wrong

i drew the 90 degrees in da middle

[shadow sparrow]

at least to me it looked like the lines were touching the circle at more than one point

[brazen parrot]

oh!

so what it mean by angle in segment

when there is no segment

[brazen parrot]

liek dis

[shadow sparrow]

hm no idea haha

[brazen parrot]

):

[shadow sparrow]

normally I see the points being labelled and they'll ask for an angle 😭

[brazen parrot]

cat:D

[brazen parrot]

wow

they love word problems

where i live

from year 9 all the tests were spammed with word problems

[shadow sparrow]

unfortunate. why are you sending pics of your house lol

[brazen parrot]

to be honest i have given up with math

i ripped out so many eyebrows

[shadow sparrow]

same

[brazen parrot]

bc of this question

so im distracting myself

even though i have to wake up at 5:30 am to go to school esrly

[shadow sparrow]

copium

[brazen parrot]

to woro

work

😭😭😭😭😭😭😭😭😭😭😭😭😭

[shadow sparrow]

good luck

[brazen parrot]

noo u have to help me

no one understands these questions i swear

they were never taught circle theorems or something

[shadow sparrow]

you've to wait for someone with better english

[brazen parrot]

like b4 i had this question in for 2 hours

and bo one could figure it out

[shadow sparrow]

it don't look too bad

[brazen parrot]

can u pls try it

[shadow sparrow]

sorry I really am unsure what they are asking for

[brazen parrot]

the angles

w y z and x

[shadow sparrow]

whichhh

[brazen parrot]

the ones with letters

[shadow sparrow]

oh this?

[brazen parrot]

oh yea

[brazen parrot]

bru ikr

i wish there was an AI

that could draw diagrams for u

[shadow sparrow]

x is trivial, just use sum of angles =180

[brazen parrot]

yea

[shadow sparrow]

you got x?

[brazen parrot]

yea

omg it is so hot

[shadow sparrow]

I hate how the diagram doesn't label the points...

[brazen parrot]

Did u get the other angles

[shadow sparrow]

I'm trying

[brazen parrot]

It is hard right

[shadow sparrow]

use this to find w

[light shoal]

your temperatures and mine average out to something comfortable!

[brazen parrot]

omg

i have never been in the negatives befire

[shadow sparrow]

I'm the only one doing math here 😭

[brazen parrot]

but its not a quadrilateral

it a triangle innit

wait

omg

i see

[light shoal]

yours looks scary and horrid though

[brazen parrot]

wait but W isnt in the

[shadow sparrow]

connect the two sides to the dot with w to form a quadrilateral

[brazen parrot]

circle

so they cant

[shadow sparrow]

whattt

[light shoal]

just kidding, ha
but i'm not a big fan of geometry

[brazen parrot]

it only applies to cyclic quadrilaterals

[shadow sparrow]

w is, y and z isnt

[shadow sparrow]

n dimensional geometry

[brazen parrot]

w looks like its outside the circle wut

wait do u mean

the alternate segment theorem

[shadow sparrow]

oh well if it is them nvm

we can find it after finding y and z

[brazen parrot]

ok lets find y and z

[shadow sparrow]

draw lines from the centre of the circle to the 3 points in the triangle (embedded in the circle)

[brazen parrot]

what 😔

you know what its ok

u can have a rest

math is hard

[shadow sparrow]

from this you'll see you have 3 kites and each of them, the angle at the outer one is and inner thing totals 180

hahaha what

[brazen parrot]

its my bed time

i have work at 5:30 am

[shadow sparrow]

ok gnite

[brazen parrot]

GNITE :P

Rhanks anyways!

It was helpful

[shadow sparrow]

this was a fun time lol

[brazen parrot]

And it made me pick out less of my eyebrows

[shadow sparrow]

you have been interesting

[brazen parrot]

And lashes

[brazen parrot]

Aww thank u

U are very

Intelligent

Is english ur first langiage

Cause it is DAMN good!!!

[shadow sparrow]

it's my only language 😭

[brazen parrot]

GIRL

I THOUGHT U SAID

U WERENT GOOD AT ENGLISH OR SMT

[brazen parrot]

sheiduehdhd

WHY WOULD U SAY THIS

[shadow sparrow]

I'm bad at math questions which use english

[brazen parrot]

IF ITS UR ONLY LANGUAGE GIRLLL THAT IS BASIC COMPREHENSION

[shadow sparrow]

in weird ways

[brazen parrot]

so

ur bad ar word problems

[shadow sparrow]

hey don't say that 😭

[brazen parrot]

ITS OK GORL

WE ARE ALL BAD AT WORD PROBLEMS

[shadow sparrow]

[brazen parrot]

.close

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[grave moss]

can someone explain me what is happening on the last two fractions? as in, how to go from one to the other

[grave moss]

i was under the impression that a^m/a^n = a^m-n, which would be 2^2-(n-1)

[thin bridge]

divide numerator and denominator by 2^2

(essentially subtract 2 from each power)

[grave moss]

ahh i see

but why are we doing that?

if its to simplify, why not just do 2^2-(n-1)?

@thin bridge

its supposed to be the formula that defines a sequance btw, if that helps explain

[thin bridge]

the expression they have doesn't have a negative on the variable

which is nicer to look at

[grave moss]

okay that makes sense

thanks @thin bridge 😄

.close

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[real bluff]

Im having trouble figuring out the integral for the this question.

[real bluff]

So far i got this but it doesn’t work. What im i doing wrong?

[compact pelican]

How did you get 5 x^-2

[real bluff]

Cause thats the variable force

[compact pelican]

Oh, sorry, you're doing #3, one sec

[real bluff]

Its the same question

pdf separated it

[compact pelican]

I get it.

OK, so, for the first few meters, what is the strength of the force?

[real bluff]

1/2?

[compact pelican]

No, it's going to be an equation because it changes from 0m to 4m, right?

[real bluff]

So 5/2x^-2

[compact pelican]

You know what, I think I'm in too deep here, sorry. I'll let someone else help

[earnest wagon]

From the graph, won't the area under the curve be the answer?

Or am I missing something

[real bluff]

Its asking for work not area

And i tried that but not same answer as book

[earnest wagon]

Integration graphically means the area under curve

Isn't that graph given in above image the graph of the y=-5/x^2

I see

[earnest wagon]

Which it doesn't seem to be

[real bluff]

And thats why im having trouble figuring out what the graph is representing

[earnest wagon]

If the object is moving in St line when it is x feet from origin

The x is not horizontal distance of object but distance literally

Never mind

[safe radish]

@real bluff Has your question been resolved?

[safe radish]

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[wooden umbra]

You have 500 dots of each of the the two colours, and you want to make the largest possible "house number".
How many dots of each colour remains?

[wooden umbra]

I got the right answer for the amount of remaining blue dots

by doing
sqrt(500) = 22,3

22^(2) = 484

500 - 484 = 16

16 remaining blue dots

but I'm unsure of what I should do with the one for red dots

[toxic stratus]

notice that for each house theres 2 copies of the red dots inside the blue dots

[wooden umbra]

okay hold up

so this

is the right way to do it

[toxic stratus]

ye

[wooden umbra]

omg

[toxic stratus]

gj

[wooden umbra]

that's so simple

[toxic stratus]

[wooden umbra]

thank you so much

[toxic stratus]

np

[wooden umbra]

looking at it like that makes SOOOOOOOO much more sense

[toxic stratus]

the red numbers are called the triangle numbers

[wooden umbra]

yes yes

[toxic stratus]

you can find a formula for them using the same method

[wooden umbra]

this one

right?

[toxic stratus]

ye

the nth house has the (n-1)th triangle number

so your formula was (n-1)n/2 = (n^2 - n)/2

n was 22

[wooden umbra]

oh wait

the formula uses -1

and not +1?

[toxic stratus]

cuz your nth house had the (n-1)th triangle number, not the nth

its offset by 1

the nth triangle number is indeed n(n+1)/2

[wooden umbra]

oh okay

[toxic stratus]

[wooden umbra]

thank you so much^^

[toxic stratus]

[wooden umbra]

this one gave me a hard time

[toxic stratus]

glad you got through it

[wooden umbra]

ah

I wrote down the wrong formula in my book

;-;

[toxic stratus]

happens to the best of us

[wooden umbra]

wouldn't have realized without your help though

so thanks again^^

[toxic stratus]

np

[wooden umbra]

.close

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[wooden umbra]

wait I'm confused again ;-;
what does this mean

[toxic stratus]

.reopen

[safe radish]

✅

[wooden umbra]

.reopen

huh

[toxic stratus]

the triangle side is 1 shorter than the square

thats what im trying to say

[wooden umbra]

OMG YES

[toxic stratus]

so for the 4th house, youre calculating the 3rd triangle number not the 4th

thats where you get the offset by 1 from

[wooden umbra]

the 1th doesn't even have a triangle

[toxic stratus]

ya

[wooden umbra]

GOT YA GOT YA

(sorry to bother you again)

[toxic stratus]

np

[wooden umbra]

thank you so much^^

[toxic stratus]

yw

[wooden umbra]

.close

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[sudden marsh]

i am struggling to get a final answer from this exercise

[vale niche]

what have you tried

[sudden marsh]

expanding them and then checking the function formulas but i kept getting stuck at

i’ve tried the integration by parts but still got back to initial form of the equation

[vale niche]

you could do this, but yeah IBP would be tough

look at the original integral

do you notice anything about the two terms

[sudden marsh]

can it be u^n and u^prime?

[vale niche]

yes, we can do a u sub

[sudden marsh]

i’m sorry but did you mean substitution?

[vale niche]

oh sorry, yes i did. is that what you were explaining?

[sudden marsh]

well yes but there aren’t any powers on the equation for me to use u to the power n * u prime

[vale niche]

ohh i see what you mean

[sudden marsh]

ahh i apologize if it wasn’t clear

[vale niche]

what's the difference between
e^x - x^2
and
e^x - 2x

[sudden marsh]

i’m not quite sure but the 2x is the derivative of x^2 is what i can tell you

[vale niche]

good

but also notice that e^x is the derivative of e^x

[sudden marsh]

oh yeah!

but how do you imply it in order to solve the problem?

[vale niche]

we can let u = e^x - x^2

do you see where to go from here?

[sudden marsh]

i’ll try and solve it and get back is that okay?

[vale niche]

ofc!

[sudden marsh]

ty!😭

here’s what i came back with, although i don’t feel like that’s the final answer 😀

[vale niche]

that's correct!

[sudden marsh]

let’s gooo!

[vale niche]

dont forget to evaluate at 1 and 0

[sudden marsh]

ah yes thank you for reminding me and teaching me 😭

[vale niche]

no problem!!

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@sudden marsh Has your question been resolved?

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[meager dagger]

!status

[safe radish]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[meager dagger]

@little night

[little night]

I don't know where to begin

[meager dagger]

Try finding probability of equation having 3 distinct solutions

[lean otter]

you would compute the discriminant of an arbitrary cubic of that form

and then figure out the percentage of numbers where the discriminant would show that there are 3 solutions

[safe radish]

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[modest portal]

do i just plug in 3

[plucky elk]

depends on your definition of continuity

[modest portal]

i tried to factor, and when u factor there is no like terms

[lime dust]

Please, stop closing and opening new channel to ask the same question, you did this 3 times in a row.

[modest portal]

so at this point i just think i have to plug in 3

my fault gang

pls help tho 🙏

[plucky elk]

what is your class's definition of continuity

[modest portal]

1 sec lemme check

function 𝑓(𝑥) is continuous at a point a if and only if the following three conditions are satisfied:
𝑓(𝑎) is defined
lim𝑥→𝑎𝑓(𝑥) exists
lim𝑥→𝑎𝑓(𝑥)=𝑓(𝑎)

[plucky elk]

yea check all those

[modest portal]

ok x=3 means its defined

its allg

this is hard

ima ask my tutir

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[late briar]

I have to make a tree diagram for question 3

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@late briar Has your question been resolved?

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@late briar Has your question been resolved?

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[modern socket]

does anyone understand what is meant by "typical solution set"

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[steel forge]

hello

can anyone answer this

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[drowsy karma]

you need to use such a fact, based on Lindeberg-Levy Theorem:

[unique basalt]

oh then is just N(0, 1/n)?

[drowsy karma]

yes ofc

[safe radish]

@unique basalt Has your question been resolved?

[drowsy karma]

and what I gave you before ? can you read it ?

[unique basalt]

not really lots of jargon 😭

(n-1)S^2

(n - 1) x o^2?

[drowsy karma]

S^2 as i wrote, is called unbiased estimator of an unknown variance

and that is the same as you were writng as small sigma

hence the distribution you search is chi-kwadrat

n-1

[unique basalt]

X^2(n-1)

[drowsy karma]

yes that is small greekl letter chi

[drowsy karma]

and this method, also called :normalisation, you need to apply to the inequality X =< a

in other words, you need to translate X into the Z term

that is the basis, extremely important when we talk about normal distribution if it comes to the probability and or statistics

[unique basalt]

2.5 = (a - 1)/2

5=a-1

a=6

P(X<=6) = P(Z <= 2.5)?

[drowsy karma]

yes a - 1 = 2b , hence a = 6, then P( X =< 6 ) = P ( Z = < 2.5)

and that you can find in normal tables

you know what i mean

the tables of CDF of Z

[unique basalt]

good draw?

[drowsy karma]

well, you are not Picasso :)))

i write density fucntion fo ryou

X ~ N ( 1, 4 ) and Z ~ N ( 0, 1) , use desmos to sketch both graphs there

and then you use 6 or 2.5

and you shade appropriate area udner the Gaussian curve

[unique basalt]

So I used that method, but do u know what P(X<=6) = P(Z <= 2.5) looks like?

Like I know how to sketch P(X <=6) and P(Z<=2.5) but idk what P(X<=6) = P(Z <= 2.5)

[drowsy karma]

if you use pdf = density function, then the probability is value of the area under curve

better sketch two graphs

and asuem you ve got Z ~ N ( 0 , 1 )

then P ( Z < 2.5) , you must set piont 2.5 on x axis

and you shade area from minus infinity to 2.5 under the curve

the same process you repeat with X~ N ( 1,4)

you set x = 6 on x axis

and you shade area from minus infitniy to 6

and those two area on two sepearate grpahs

are equal

that is proved using normalisation

[unique basalt]

good? took too long to figure out how to shade curve in desmos LOL

ohh so u say the two shaded area are equal?

interesting

[drowsy karma]

eys)

and i show you second oen too

so you see read value

of are the same

red*

[unique basalt]

So I give my final ans
P(X <= 6) = P(Z<=2.5)

[drowsy karma]

0.99379

ok

you can us emine too

use*

[unique basalt]

final one for tonight

tysm for help

[drowsy karma]

super)

[safe radish]

@unique basalt Has your question been resolved?

[safe radish]

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[warm fractal]

How do i seperate x/(3x-1) into partial fractions?

[warm fractal]

symbolab says its long division but i dont see how

(i have no prior experience with partial fractions in general)

[plucky elk]

whenever you have the same degree, you should do some algebraic manipulation to get 1 + (lower degree) / (degree)

[warm fractal]

yeah thats my goal

no clue how to start though..

[plucky elk]

since x and 3x-1 have the same power, find a way to get 3x-1 into the numerator

use 3 / 3 = 1 and -1 + 1 = 0

[warm fractal]

im sorry i dont understand

i suppose i multiply top and bottom by 3x-1?

[plucky elk]

no

x * (3x-1) would not give you 3x - 1

[warm fractal]

lemme think

ty for the hints tho

ah

3x/3(3x-1) - 1/3(3x-1) + 1/3(3x-1)?

and then it cancels out

1/3 + 1/3(3x-1)?

dude thats awesome

tysm

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[rugged surge]

I am not sure if i am allowed to take help for a physics problem

but

[rugged surge]

i needed help with the math of this problem

of side a

so i thought we should first start with finding the electric field for one side

and this is the integral i set

this is my reasoning behind this

so basically i am setting up my integral from 0 and thats why i am getting a/2-x so can someone help me identify why my method is giving the wrong answer

[safe radish]

@rugged surge Has your question been resolved?

[safe radish]

@rugged surge Has your question been resolved?

[safe radish]

@rugged surge Has your question been resolved?

[safe radish]

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[prisma spruce]

helloo

[lean otter]

hi do u have a question to ask

[prisma spruce]

i cannot understand this step

[prisma spruce]

yess

the differentiation

[lean otter]

alright what issue do u have with it

they use the product and chain rules

[prisma spruce]

how

[lean otter]

like

[prisma spruce]

i cant get it

[lean otter]

the product rule is [
(\c r u \c b v)' = \c r u' \c b v + \c r u \c b v'
]
so apply the same idea for [
\p{\c r{\3{1+x^2}}\c b{\dv[y]x}}'
]

[lean otter]

Does this give you an idea now

[prisma spruce]

yeah let me try

thank youu so much !!!!

[lean otter]

aye

[prisma spruce]

[lean otter]

do u have any other doubts?

[prisma spruce]

yes

[lean otter]

alrighty ask away

[prisma spruce]

the differentiation of u part

[lean otter]

ok what confuses u about it

[prisma spruce]

im not getting the 2x. im getting x there

[lean otter]

yeah i think they messed up there

[prisma spruce]

the diff root under any funtion = 1/2 root that function

[lean otter]

you are right

[prisma spruce]

and the 2 will be cancelled with 2x

[lean otter]

yeah

[prisma spruce]

i am right?

[lean otter]

you are right

[prisma spruce]

okay thanks

[lean otter]

they like

[dull sequoia]

Yeah looks like it

[lean otter]

fix it in this step

[prisma spruce]

oh yeah

right

thank you so much

[lean otter]

no worries. Anything else that is confusing you still?

[prisma spruce]

nope!!

[lean otter]

alright u can close this then if u want

type .close

[prisma spruce]

.close

[safe radish]

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[harsh sapphire]

hi all. math homework question 1 billion here. just not sure how to approach this ??? this is all of the explanation i got. thank you

[harsh sapphire]

i have no idea where to start

ohh hm

[tranquil tendon]

choose one of the two parameters (say, "number of adult tickets") and assign it to a variable

you should be able to find expressions, in terms of that varialbe, for all of the facts given in the problem

and from there solve for the unknowns

[harsh sapphire]

ah okay thank you

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[vast obsidian]

I suppose you're talking about binomial distributions here?

Then the 0.5 gives the probability of a hit

Ja

Der Name kommt nicht von dem Mathematiker nehme ich an?

Ah, der Mathematiker wird sogar mit doppelten p geschrieben

Sorry, da kann ich dir leider nicht weiterhelfen. Ich habe erst Stochastik 1 gehört.

In welchem Semester bist du?

Interessant. Haben wir noch nicht gemacht. Sorry

Viel Glück bei den Klausuren

Die Verteilung der einzelnen Lampen hast du bereits aufgestellt nehme ich an?

Jaein, hier solltest du wahrscheinlich ein Resultat besitzen für die du die einzelnen Verteilungen nicht unbedingt aufstellen musst über die Dichte. Aber was sind denn die Kennzahlen einer Normalverteilung?

Ouh, hast du es mit Faltung versucht?

Wahrscheinlich wurde es nur anders genannt

[vast obsidian]

X ist hier die Summe der B?

Hat sich geklärt wie du X definiert hast

Ich muss mir mal ein Blatt holen

Achso, warum verwendest bereits hier die 3200? Die bezieht sich ja auf die Verteilung der Summe

Ist klar, dass der Wert sehr klein wird, wenn du das hier schon einsetzt

Sagen wir uns ist eine einzelne Lampe erstmal egal. Wir wollen ja etwas über die Verteilung der Lebensdauer aller 3 Lampen zusammen aussagen

Was kannst du mir über die Verteilung der Summe Normalverteilter Variablen sagen?

Sorry, dass ich dich abbrechen muss, aber warum rechnest du die ganze Zeit mit einer Lampe? Du sollst doch 3 betrachten?

Okay, du solltest wahrscheinlich den Satz kennen, dass die Summe von normalverteilten ZF normalverteilt ist?

Aus irgendeinem Grund dauert das Bilder teilen gerade sehr lange

Der Satz könnte dir helfen

Okay, jetzt nehme ich an, dass du es lösen kannst? Weil wenn du die Verteilung von den 3 Lampen hast kannst du genau das machen, was du vorhin mit einer Lampe gerechnet hast

,rotate

[vast obsidian]

xd

Okay, ich kriege das Ergebnis

Warum hast du überhaupt P(X>3200) bestimmt?

Weil P(3200<X<3800) = F(3800)-F(3200)

Ob < oder <= macht ja kein Unterschied, weil absolutstetig

Dann ist die erste Zeile schon sehr merkwürdig. Weil F(3200) = P(X<3200)

Einfach F(3800)-F(3200)

Die erste Zeile stimmt schonmal nicht. Eine Verteilungsfunktion ist ja F(3200) = P(X<=3200). Dann wofür brauchst du P(X>= 3200) überhaupt? Kann es sein, dass du dich da einfach verschrieben hast?

Okay, und der 2. Wert passt nicht

Da hast du dich einfach vertippt

1-F(3200)

An sich hast du richtig gerechnet. Nur das eine > passt nicht und beim letzten Wert hast du dich vertippt glaube ich

Bei der 0,93. Da sollte etwas mit 0,87 rauskommen

[brazen parrot]

what in the germany

[vast obsidian]

?

Hast du die gerundeten Werte in die Phi's eingesetzt?

Bitte

In einer Stochastik Klausur ist entweder der Wert gegeben oder du darfst die Phis stehen lassen

Bitte

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[gray crypt]

3/5 quintal of wheat costs Rs.210. Find the cost of:
(i) 1 quintal of wheat (ii)0.4 quintal of wheat

[pliant egret]

so 3/5 of wheat = 210 rs find the number to multiply both sides of an equation and get 1 of wheat on left side

[gray crypt]

1 wheat= 3/5*210=126

is it correct?

[gray crypt]

.

[pliant egret]

no

3/5 * 5/3 = 210 * 5/3

do that

[gray crypt]

I should divide?

ok

[pliant egret]

and see that you get 1 on the left side

[gray crypt]

5/3*210=350

[pliant egret]

yes

sp 1 wheat = 350 rs

[gray crypt]

now should i multiply by 0.4?

[pliant egret]

yes

[pliant egret]

the same like you did here with 5/3

do with 0.4

[gray crypt]

sure

350*0.4=140 rs.

[pliant egret]

yes

thats all

[gray crypt]

there is also one more thing i wanna ask

[gray crypt]

suppose it is this question

36 men can do a piece of work in 7 days .How many men will do the same work in 42 days?

How would I know it a question of inverse variation or direct variation?

[pliant egret]

really depends on the context

i dont have a general rule and use reasonal thinking

here, if there is more people the work is done faster = less time

its just common sense

if you think about this and u see word "more" with "less" its inverse

and when u see word "more" with "more" its direct ( or "less" with "less")

[pliant egret]

so here u use inverse since as we reason that more people is less time

i hope that helps

[gray crypt]

let me see

[gray crypt]

oh yeah thankyou buddy it really helped

[gray crypt]

you are from where

[pliant egret]

from poland

but i dont think we should chat here

[gray crypt]

true bye

.close

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[wise shuttle]

I don't get why did they take the slope

And how did they come up with w

And how can I proof this

[tawny knoll]

Cuz it needs to be parallel and after, perpendicular

[wise shuttle]

.

[safe radish]

@wise shuttle Has your question been resolved?

[safe radish]

@wise shuttle Has your question been resolved?

[plucky elk]

rise / run = slope. what's the slope of w?

[wise shuttle]

6

[safe radish]

@wise shuttle Has your question been resolved?

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[chrome granite]

No, it's B.

[drowsy heath]

Why

[safe radish]

Show your work, and if possible, explain where you are stuck.

[drowsy heath]

Ohh I see lmaoo

.close

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[cobalt reef]

what am i doing wrong here?

[cobalt reef]

@bleak delta maybe you would notice

[tame raft]

idk wtf is happening here

what is a

what do you mean by a

[cobalt reef]

i assume triangles with AB and KL base have the same height so their bases ratio would give me the areas ratio. same for triangles with EF and DC bases

a is S1

[tame raft]

ok

S_1 = 5 looks right

shouldn't S_2 just be 10 then

oh wait that's not an answer

hmm

maybe it's not 15

[cobalt reef]

i found s_2 as 20

because those triangles are similar triangles square of their bases ratio should give the ratio of their areas

[tame raft]

if S_1/15 = 1/3

[cobalt reef]

maybe my approach is entirely wrong?

[tame raft]

i don't understand why S_2/15 wouldn't be 2/3

by the same logic

[cobalt reef]

true

then it's a wrong approach

[tame raft]

i don't see why it's wrong though... it looks right...

[cobalt reef]

height of the triangles probably aren't the same?

but it should be the same

[tame raft]

congruent

very strange

the diagram is weird too, i don't see how KL can be different to EF if EL and FK are straight lines

because if they're straight lines, in my head the top half and the bottom half are just completely congruent

[cobalt reef]

that also makes sense

[tame raft]

maybe it's a typo and it's meant to be KL = 1/3 AB also and then it's just 5 + 5 = 10 lol

i don't know

[cobalt reef]

let take a 3rd opinion on it before i move on

<@&286206848099549185>

[plucky elk]

why

[cobalt reef]

idk just to make sure we're not doing the same mistake?

you seem to be really mathing can you take a look at it?

[bleak delta]

@cobalt reef are you okay bro

[cobalt reef]

i'm fine just wondering over this problem right here

[bleak delta]

okay

lol

[cobalt reef]

what do you think of it?

[bleak delta]

let me think

there is 1/4 ratio

between areas

you know

[cobalt reef]

yes

[bleak delta]

okay so,

2k×h/2 = kh = S2

kg/2 = kh/4 = S1

g/2 = h/4, g = h/2

h+h/2 we have = 3h/2

3k×3h/2 = 9kh/2 = 60cm²

kh = 120cm²/9

kh/4 = 120cm²/36

120cm²/9+120cm²/36 = 600cm²/36 = 300cm²/18 = 150cm²/9 = 50cm²/3

EF tabanına ortadan inen yüksekliğe g dedim haberin olsun

h türünden yazdım daha sonra

@cobalt reef

then i find the paralellogram's height

and find its area also

3k×paralellogram's height = 60cm²

and according to this, i find the area of s1 and s2 and add them together

there may be different solutions you know

but this is also practical i think

[cobalt reef]

what answer do you get at the end

[bleak delta]

if there is something that you didnt understand

50cm²/3

[bleak delta]

ask to me

[cobalt reef]

ok give me time to understand your work

[bleak delta]

okay

[bleak delta]

maybe this would be more clear

[cobalt reef]

yeah thanks

[bleak delta]

2kh/2 = kh = S2

kg/2 = s1

and we know that s1/s2 = 1/4

so (kg/2)/(kh) = 1/4

2kg = kh

then g = h/2

and sum of these heights is h+h/2

which is paralellogram's height

3h/2

and 3k×3h/2 = 60cm²

the rest is easy anyway

[cobalt reef]

hmm that makes sense give me more time to fully follow your method

[bleak delta]

okay

h+g is paralellogram's height, because they intersect at the same point and they are perpendicular to the edges

and if g = h/2 (we proved this)

h+g = h+h/2 = 3h/2

i'm writing random information to make it more understandable but it's always better to think for yourself

you know

[cobalt reef]

why did you do 3k×3h then /2 here? you don't need to divide by 2 when calculating area of parallelogram

[bleak delta]

3h/2 is the

height

itself

i didnt divide

@cobalt reef

h+g = 3h/2

that's why i wrote like that

[bleak delta]

didnt divide as an extra

[cobalt reef]

g/h is 1/2 right?

so if g = x then h = 2x

[bleak delta]

yes

yes

then total height is 3x

[cobalt reef]

area of parallelogram is 3k.3x = 60 so k.x = 20/3

[bleak delta]

While the height of one triangle is 2x, the height of the other triangle is x

yes

kx/2 = 10/3 and 2k×2x/2 = 2kx = 40/3

add them

50/3

[cobalt reef]

yo that's brilliant again

have you got the highest grades in your school?

but i didn't understand why solution i did is flawed

it seems applicable

[bleak delta]

Did you find a solution?

[bleak delta]

no bro just love math xD

I failed biology

and philosophy

you know

lol

@cobalt reef if you can show me your solution probably we can find a way

[cobalt reef]

Diagonals at the median divide the area into four equal parts. so if A = area 4A = 60 then A = 15. so k.h/2 = 15 kh = 30?

no wait not k.h/2

[bleak delta]

3kh/2?

[cobalt reef]

yea so kh = 10

i'm kind of having a brain fart here after thinking over it too much

[bleak delta]

let's check it bro dont think like that xD

I will call the midpoint P

otherwise it will be difficult

to explain

okay?

you know where they intersect

is P

from now on

[cobalt reef]

my only guess in midpoint is not the intersection point of diagonals

[bleak delta]

oh yes

ahaha

[cobalt reef]

because nothing suggest it to be

[bleak delta]

yes

I just realized this

[cobalt reef]

lol makes sense now

[bleak delta]

If that were the case, the heights would be equal

you know

but they are not

[cobalt reef]

true that's was my error to assume that

thank you for helping

learned a lot lol

[bleak delta]

So mutual heights would be equal

and the other two among themselves

not four of them

because it is not square or

equilateral parallelogram

or rhombus they say

it is same

[bleak delta]

but there is a 1/2 ratio

in here

[bleak delta]

if it was a midpoint

[bleak delta]

you are welcome btw

[cobalt reef]

i knew i was doing mistake somewhere

because nothing i did matched

[bleak delta]

yes need to think carefully before making assumptions

[cobalt reef]

true

[bleak delta]

so if you have more quests

feel free to write to me

[cobalt reef]

my math wasn't mathing

[bleak delta]

on dm

don't worry about it you'll just improve

i'm improving while solving these problems with you

and i love this of course

[cobalt reef]

thank you

[cobalt reef]

that's amazing

[bleak delta]

one question solved by thinking and understanding is more valuable than 1000 questions solved without understanding, just by memorizing knowledge

So i recommend you to be like this in maths

If you know the question like your neighborhood, you will somehow find your way to home

I don't know if it will be difficult or easy but you can improve these skills by solving more questions

After all this is also a fact

to solve quickly and easily

you know

But understanding is more important than anything

[cobalt reef]

yeah that's true

though after solving lots of question my brain just shots itself down

[bleak delta]

ahaha it's not a big problem

so this happens to everyone

but looking at mathematics just as a lesson is also the beginning of this

you need to get rid of your worries

you know

Of course not everyone is the same at some point, but i believe you can achieve it

Just get rid of negative and stupid thoughts

i said it as really

If you can find your way home somehow, you can also do geometry

Because when you start solving questions, you build everything on simple informations

You can't go 10 meters up in one step

But if you build 20-30 stairs, you can climb 10 meters easily

just continue step by step

If you noticed, we talked about the area of ​​the triangle, we didn't do anything too difficult

There are even more fundamental things before this

before area of triangle

I know i talked too much

but this is what it is

@cobalt reef see you later then bro

goodnight

[cobalt reef]

alright thank you for the inspiration too dude. have a good night.

.close

[safe radish]

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[normal torrent]

are there any danes who can help me?

[normal torrent]

cus idk what these words mean

hvad er incidensgeometri, kan ikke google det, og hvad er et affint plan

[safe radish]

@normal torrent Has your question been resolved?

[normal torrent]

mb for writing in a language that isnt english

but idk what it means, and when i gogole i dont get anything

[merry pelican]

Incidensgeometri er blot det område af matematik som studerer incidensstrukturer, altså tripler på formen (P, L, R) hvor P er en mængde af 'punkter', L er en mængde af 'linjer' og R en relation på P × L (altså en relation om hvordan punkterne relaterer sig til linjerne i din incidensstruktur)

Et affint plan definerer de i billedet du har sendt

[normal torrent]

ok tak

hvad betyder incidens

[merry pelican]

Ved sgu ikke lige hvor ordet kommer fra

Hvilken kontekst er det du læser om det?

[normal torrent]

jeg er blevet sendt nogle opgaver som jeg skal løse

men jeg har aldrig nogensinde hært ordet før

sp jeg blev lidt forvirret

[merry pelican]

Hvem har dog sendt dig dem lmao

[normal torrent]

min lærer

det er en del af en ansøgning som jeg laver så jeg kan deltage i en sommercamp

der får jeg lov til at lave universitets niveau matematik

med vlagfagene ringteori eller gauge symmetrier

jeg ved ikke så meget om fysik så jeg valgte ringteori

[merry pelican]

Cool

Held og lykke

[normal torrent]

tak lmfao

.close

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[lean otter]

These are my notes- I was confused as to where the 1/2 next in the Mx equation came from

[lean otter]

the last word in the question is x-axis

[last wren]

the center of mass formula usually divides by the mass, which in this case is 2

[lean otter]

is it by the mass or just 2 in generali js saw another section in my notes-

[humble pawn]

Is that something from calc 3?

[lean otter]

calc 2

[last wren]

oh you divided by the mass at the end, I see

[humble pawn]

Then im behind rn

[lean otter]

yes

[lean otter]

what are you in

[humble pawn]

Calc 2

[lean otter]

maybe its different where u r, im in advanced college cal II

[last wren]

well it looks like you answered your own question right? I see a delta(x)/2 in the moment formula

[lean otter]

how do u know what delta x

in this case it was 1

ig

or js cuz its constant?

im doing a similar problem

[last wren]

density function is 1 since it's constant density yes

[lean otter]

ohhh okok

i also have

1 other question

[last wren]

sure

[lean otter]

and dont mind my work, js the answer, i realized i had the metrics wrong and fixed everything in the calculator rather than on paper

sorry its all sideways btw

😭

[last wren]

,ccw

okay that didn't work

[lean otter]

lol

[last wren]

,rotate

[lean otter]

ohhh nice nice

so yh, all my work in the wrong measurements

i realized too late, but the answer at the bottom, is after fixing it

[humble pawn]

If the window it’s talking about is the bottom wouldn’t you multiply it by the density of water and gravity

[lean otter]

the equation the professor gave didnt include gravity

[last wren]

imma be honest, physics is not my field of expertise, so idk where the 2y comes from there

[lean otter]

ig cuz its the side window

not bottom

[last wren]

oh that's the length of the window ic

[lean otter]

cuz, the center of mass is directly in the middle

yes

[last wren]

what's your question exactly

[lean otter]

my question is

i have no idea what im doing.

i based this off a different question but the question itself here, didnt quite make sense to me

[last wren]

well this def works out unit-wise

it looks correct

[lean otter]

if u say sooooo!

[humble pawn]

If I can see the Original equation I can make a (plausible) explanation of it

[lean otter]

sure, lemme get a pic

the equation is at the top, i based it off the 1st problem under it

im confused cuz wouldnt u need the 3rd dimension of the tank like in the 2nd pic it was needed

[humble pawn]

I don’t recognize this equation although google found a 300 pg pdf of fluid flow theory

[lean otter]

😭

its mostly supposed to be based around differential cal or sm

[humble pawn]

That’s something my school says you need calc 3 before hand for

[lean otter]

im not sure, ive heard cal 3 and 4 r easier, this is college cal ii so idk if itd be different or not

[humble pawn]

Do you know what the w is for?

[lean otter]

as far as ik

its the density of the water

[humble pawn]

That makes sense

[lean otter]

is how it was used underneath

in the newer problem, its seawater

idk why, my professor uses a new symbol for density every class

[humble pawn]

Lol

[lean otter]

oh yh

[humble pawn]

Whats it mean by strip because I see the 2y and I assume the 2 is apart of the “strip”

[lean otter]

i remember my professor said

this isnt taught in most cal ii classes

js cuz its never in ap tests at the end or any other tests

but its in our curriculum test so he has to teach it

[humble pawn]

Ok

[lean otter]

i think 2y is related to the L(y)