#help-23

1 messages · Page 201 of 1

misty blade
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Exactly

hearty egret
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seems like the text is wrong

misty blade
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So there are infinitely many such functions

misty blade
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.close

safe radishBOT
#
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brazen parrot
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how would i do this

safe radishBOT
brazen parrot
small epoch
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Expand LHS of equation so (x+y)^2=x^2+2xy+y^2

brazen parrot
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why?

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what about the x= 0 or y = 0

small epoch
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Yes, what you then do is minus x^2+y^2 on both sides of the equation

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to get 2xy=0

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or xy=0

brazen parrot
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xy = 0?

small epoch
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by null factor law, either x=0 or y=0

brazen parrot
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oh

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how am i supposed to think of that during a test

small epoch
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its quite easy

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just expand everything out

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then subtract the like terms

brazen parrot
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.close

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storm maple
#

hello can somebody please help me with a combinatorics question?

storm maple
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A student learns that in a multiple choice test, the correct answer to each question always has a different number. There are 6 questions, each with 6 choice answers, and the student has studied nothing, so he responds essentially at random. What is his best strategy (which maximizes the number of correct answers) between (i) always answer “1” (ii) roll a die for each question and give the answer corresponding to the number that comes out (iii) randomly choose a permutation of the numbers {1, . . . 6} and respond following this permutation. Generalize this problem to the generic case of n questions, with n choices per answer.

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in the first case since all the questions have different answers the student guesses 1 out of 6 questions

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i think we have to use derangements (?)

safe radishBOT
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@storm maple Has your question been resolved?

storm maple
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<@&286206848099549185> sorry for the ping

safe radishBOT
#

@storm maple Has your question been resolved?

buoyant shadow
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i think they mean permutations

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just what option 3 says

storm maple
storm maple
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there exist 6! possible permutations and 265 derangements (6! / e)

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the probability of getting a derangement is 265/720 = 0,368 therefore the expected value of correct answers is 6 x (1 - 0,368) = 3,792

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idk if this is right

storm maple
buoyant shadow
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that's not how it works

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you don;t get 6 right answers as long as you didn't pick a derangement

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you can get 6,1,2,3,4

safe radishBOT
#
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modern pier
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to check if it converges or not

safe radishBOT
modern pier
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Did i do it correctly?

proper crypt
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In the last step, where did the exponent go?

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you forgot to write it

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but yes the limit is 1/e

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seems correct to me

safe radishBOT
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@modern pier Has your question been resolved?

modern pier
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oh i forgot it...but thanks

safe radishBOT
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cobalt reef
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there is some kind of operation here but i can't find it

safe radishBOT
#

@cobalt reef Has your question been resolved?

cobalt reef
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<@&286206848099549185> any idea?

sage robin
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I came up with this problem

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2 days ago

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Still no response

cobalt reef
sage robin
cobalt reef
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can you send it here?

sage robin
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Not exactly this one

cobalt reef
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i can take a look

sage robin
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Ait

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Wait*

cobalt reef
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aight

terse sleet
sage robin
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A dude told me to solve this

cobalt reef
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let me try this one

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damnn that's hard

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ok i found it

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@sage robin

cobalt reef
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finally found it

sage robin
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Holy shit thanks

sage robin
cobalt reef
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lol you're welcome

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i get these type of problems alot

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ping me if you get any of them again i can try

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.close

safe radishBOT
#
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safe radishBOT
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lost spruce
#

....any clue how to solve this? dont really wanna know the solution ,just a clue, feels so simple but i havent done geometry in like 4-5 years -_-

buoyant solar
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Hello can someone check if these are correct please. I also need help with the last question

buoyant solar
tawny knoll
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do things properly

lost spruce
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sorry about that....

tawny knoll
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and learn exponential properties

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dont do random things

buoyant solar
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I didnt do random things

tawny knoll
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u did

buoyant solar
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What are tou sauing bruh

tawny knoll
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on a)

buoyant solar
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How is it random

tawny knoll
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u end up with 3=9

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and u have to ask if it is correct?

buoyant solar
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I multiplied by 2^a

tawny knoll
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since when 3 = 9?

lost spruce
buoyant solar
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Yeah its probably not right

tawny knoll
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i told u already. Dont do random things, and study the exponential properties

buoyant solar
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Saying i didnt do random things, otherwise i wouldnt be here

tawny knoll
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u are doing random things. And for the third time, study exponential properties

buoyant solar
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So the answer is 6.

lost spruce
buoyant solar
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For a

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Its 2^9= 2^3a

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You take base away and its 9=3@a…

lost spruce
buoyant solar
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Omg

buoyant solar
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I think i see what i did wrong

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Was i supposed to write 2^3 x 2^a?

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On the ones side

lost spruce
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???

buoyant solar
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Hmm

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I’ll write it on paper

lost spruce
buoyant solar
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The one on the right

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Is new

tawny knoll
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i wont repeat again @buoyant solar . STUDY EXPONENTIAL PROPERTIES

buoyant solar
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What is the one you are talking about

tawny knoll
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$2^3 * 2^a = ?$

flat frigateBOT
buoyant solar
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Guy im doing logs

tawny knoll
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????

hidden mist
tawny knoll
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oh god

hidden mist
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hes right

tawny knoll
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u dont even know what u are doing

buoyant solar
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You know them logs

hidden mist
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ur using the wrong exponential property

tawny knoll
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and u saying u arent doing random things xd

buoyant solar
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I know he is but i dont understand

hidden mist
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see he said

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2^3*2^a = 2^3+a

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thats hwo it is supposed to be done

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and ur doing it 2^3a

buoyant solar
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Oh

hidden mist
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which is wrong

lost spruce
tawny knoll
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i have just told u to not spoonfeed, and u come here and do it again? @hidden mist

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rlly, shut up wtf?

buoyant solar
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I already did the topic last year

hidden mist
tawny knoll
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so?

hidden mist
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and u tried making him understand thric

tawny knoll
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as if he needs to mess 100 times

hidden mist
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and nothing helped

buoyant solar
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Yeah but i can just find new problems to practise

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No biggie

hidden mist
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Yeah

tawny knoll
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yeah cuz im not spoonfeeding him. I told him to study, and he doesnt care

hidden mist
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I dont know why this guy has some high anger issues

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well cool

tawny knoll
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he only comes here to see if someone else solves his problems

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he doesnt care about why

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but whatever

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do what u want

buoyant solar
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Aza bro if u get mad just leave

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Cant teach a person like that

tawny knoll
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xDDDDDDDDDDDDDDDDDDDD

buoyant solar
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Sorry im not as good at maths as u

tawny knoll
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okey mister logarithms

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u are gonna tell me how to teach

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wp wp

buoyant solar
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Shi idk what that is

lost spruce
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idk, @tawny knoll ,that atitude just gets people away from math,right?

buoyant solar
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Fax bro

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Im trynna fix my shi and people telling me what to do actually helps

tawny knoll
buoyant solar
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So i can do other problems

lost spruce
buoyant solar
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I dont use that app bro

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For braindead ppl

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K well none of you are really usefull

lost spruce
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idk if its just the slang but it makes you sound bad, like "fax", " shi"....

buoyant solar
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Tell me the answer so i can work backward

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Thats just how i thpe

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Say what a is equal to

lost spruce
buoyant solar
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Not how it is done

lost spruce
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literaly just google exponential properties

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and solve it

buoyant solar
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Well my teachers have said the best way to figure something out is to try and do the problem backward

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And im in my final year

lost spruce
lost spruce
buoyant solar
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Ez stuff

lost spruce
buoyant solar
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I swear

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Thats what i’ve been taught

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I have it on my notes

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Damn bro

steep flicker
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Wasup

lost spruce
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anyway, if someone could help with this, it would help a lot

lost spruce
buoyant solar
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Oon god bro

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Wait

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I said 2

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I meant 3

steep flicker
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Wikipedia sucks

lost spruce
# buoyant solar It issss

dude, think about that logically, you put 2 * 2, 3 times and then you put 2 * 2, a more times, how many times did you put 2*2?

steep flicker
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Reddit is better

buoyant solar
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Yes it is 2x2x2

lost spruce
buoyant solar
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Bro can you just write it

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Ok

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Yes i know that

lost spruce
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but its not the answer to your original problem

buoyant solar
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Ok

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Give me a second

lost spruce
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well, gl, im just gonna leave

buoyant solar
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I got a=6

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As final answer

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@hidden mist

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Can you check pls

safe radishBOT
#

@buoyant solar Has your question been resolved?

safe radishBOT
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delicate fjord
#

If x = 4/x+y and y+5/y+x where x and y are non-zero real numbers, then the absolute value of the difference of the two numbers is equal to?

delicate fjord
#

<@&286206848099549185>

empty gyro
safe radishBOT
# delicate fjord <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

delicate fjord
#

my bad

empty gyro
#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
delicate fjord
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I don't know where to begin

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i replaced the x in 5/y+x with 5/x+y

delicate fjord
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like

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5/(y) + x

empty gyro
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And you want to find |x-y|?

delicate fjord
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thats right

empty gyro
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I wold solve for x-y in both equations, then go from there. That seems to be the best route

hidden mist
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question

delicate fjord
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makes sense

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x-y = 4/x

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x-y = -5/y

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right? @empty gyro

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okay

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does that mean 4/x = -5/y

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now i'm stuck again 😭

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@empty gyro what should i do now

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?

empty gyro
delicate fjord
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so we'd replace in the second one

empty gyro
delicate fjord
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-4y/5

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so 4/x = -y

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what would I do now @empty gyro

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oh wait

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x-4/x

empty gyro
delicate fjord
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x-y

delicate fjord
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it's actually x+4/x

empty gyro
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x-y=x+4/x won't help you. You broight the unknown y back

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You're trying to solve for x

delicate fjord
#

this is frustrating

#

.close

safe radishBOT
#
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safe radishBOT
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severe moon
#

can someone help me with this question pls

safe radishBOT
#

@severe moon Has your question been resolved?

severe moon
#

<@&286206848099549185>

grave lodge
# severe moon <@&286206848099549185>

well you have:

  • number of women = 4/5ths * number of men
    and
  • number of unmarried woman = 40%
  • 30 unmarried woman

so 30 = 40% of x (x being the number of women)
x = 75

#

from here you can calculate the number of men

grave lodge
uncut gate
#

i think its %40 of women

severe moon
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but i think it's 40% of the men

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as men was the last subject mentioned

grave lodge
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yeah i think its men as well coz why else would they mention the stuff about the married women being with their husbands etc

severe moon
#

exactly

grave lodge
#

ok then u gotta solve it a different way

severe moon
#

how

uncut gate
#

well you'll take %40 of the men

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not the women

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which would obviously change the amount of people

safe radishBOT
#

@severe moon Has your question been resolved?

safe radishBOT
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sullen hill
#

I know I have to use some directional calculation but I'm kinda stuck on how to approach this

sullen hill
#

I think I need to calculate the partial derivative of x and y

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but

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given the two points

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I don't know if it's possible

safe radishBOT
#

@sullen hill Has your question been resolved?

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severe moon
#

.reopen

safe radishBOT
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lean otter
#

what's up with the radical.

safe radishBOT
lean otter
#

looks like they skipped some steps

proper crypt
#

They just skip over the simplification because it's not important I assume

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If you're doing calculus, this isn't the main focus

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Just plug and evaluate, that's all

lean otter
#

how do you even simplify that equation to get that answer is the question

proper crypt
#

Find cos(19pi/6)

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Subtract 2pi, so that's equal to cos(7pi/6)

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Which is equal to -cos(pi/6)

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And cos(pi/6) = sqrt(3)/2

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Do a similar thing with sine

lean otter
#

Is there an easy way to think about trig functions on radians

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I get degrees, but radians hurt my head

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

no

#

eh fine

#

.done

#

.solved

safe radishBOT
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marble aspen
#

Can someone explain me why it equals to 0 in both sides here?

clear blade
#

because the LHS must be >= 0 and the RHS is <= 0

hardy lion
#

you have an even root of a positive number on one side and an even root of a negative number on the other

marble aspen
#

Ohh I see

#

And does it apply to every quadratic equation? Or is it because I took the root from both sides?

wind dove
#

I expanded s.t $(3x^2 + 6)^2 = -9x^2 \Rightarrow 18x^2+36x+36 = 0$

flat frigateBOT
wind dove
#

Then you see that $\sqrt{b^2 - 4ac} < 0 \Rightarrow x \in \mathbb{C}$

flat frigateBOT
marble aspen
#

Oh I saw that yeah

#

But it's only that I didn't know why it equaled 0 in both sides

marble aspen
clear blade
#

The only way we can have equality is at the intersection, 0

marble aspen
#

That makes it more clear

#

Thanks y'all!

clear blade
#

Only in this very specific case

marble aspen
#

I see

clear blade
#

Best is to use other methods above

marble aspen
#

Yeah, like discriminant right?

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I used that and I got the solution also

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But now I get why you can also equal all to 0

#

Well, thank you very much

#

.solved

safe radishBOT
#
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south epoch
safe radishBOT
#

@south epoch Has your question been resolved?

eternal carbon
south epoch
#

ok

#

.close

safe radishBOT
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lean otter
#

.close

next oar
safe radishBOT
next oar
#

wouldnt n - n be 0

#

becauses they are both of degree n

drowsy moss
#

the degree of the numerator and denominator are not both n in the derivative.

safe radishBOT
#

@next oar Has your question been resolved?

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rough matrix
#

Hi

safe radishBOT
rough matrix
#

Is 1.d answer just nothing ?

mortal sandal
#

no

#

do you have answers for the other parts?

#

For 1d I would start by factoring

rough matrix
#

I factored

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The fractions are equal after reducinh

mortal sandal
#

Yes

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Reducing is performing a certain operation to both the numerator and denominator

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They are asking what the operation was

rough matrix
#

O division

#

Ic

mortal sandal
#

Yeah

safe radishBOT
#

@rough matrix Has your question been resolved?

safe radishBOT
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lean otter
safe radishBOT
lean otter
#

How do you do these again?

left karma
# lean otter How do you do these again?

You were close, but the first issue that f'(x)=-1, not +1. Next, you can actually calculate g'(3) because it's the slope of the line at x=3. Looking at the part of g(x) around x=3, the slope is 2, so you can plug that in to get just a number for the answer

lean otter
#

So the answer is 4

#

Darn it!

left karma
#

I think it's -1 + 2*3 + 3 = 8

lean otter
left karma
# lean otter Wat

So re-writing your work a bit, you got that h'(3) = f'(3) + g'(3)*3+g(3). Then plugging in h'(3) = -1 + 2*3 + 3

lean otter
#

You told me the slope is 2

left karma
#

Oh sorry if I'm not writing it well. g'(x) is the slope, but there's also just g(x) which is the actual value of the function. So the 3 on the end there is from the actual value of g(3), not the slope

lean otter
#

Thank you so much Don!

left karma
#

Glad to help! It's a weird one haha

lean otter
#

yeah it is

#

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flat bramble
#

is anyone fluent in statistics (ap statistics specifically would be even better)

flat bramble
#

i need help studying

safe radishBOT
split fulcrum
flat bramble
#

does anyone know about sample proportions

rigid inlet
#

i think you need to read what the bot said again

steel granite
flat bramble
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glad linden
safe radishBOT
glad linden
#

What would my first step be since i cant cross multiply

dusk gate
#

get all your x stuff on one side

small epoch
#

maybe just write 5 as 5(x+4)/(x+4)

#

and then see the denominators are the same

sullen ravine
dusk gate
#

or multiply both sides by (x+4) and get rid of the denominators

#

several ways to go about it

glad linden
#

Wouldnt i have x^3 then too?

#

If i multiplied both sides

#

Man i have no idea lol

#

.close

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fallow minnow
#

Why need to divide by 18

safe radishBOT
eternal carbon
# fallow minnow Why need to divide by 18

you divide by 2 because if you reflect the necklace, you can get the same bead pattern
you divide by 9 because if you rotate the necklace, you can get the same bead pattern

in total, you divide by 18

#

though it looks like the book has a typo… extra 0 at the end of the answer 🤔

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hoary lotus
#

d

safe radishBOT
hoary lotus
#

hello i have a limits question

#

if i have something like lim x -> 3, (x^2-9)/(|x-3|)

#

how do i go about solving it

severe lark
#

it has no limit

hoary lotus
#

can u pls explain i understand its because its divided by absolute value of that

#

but i dont understand exactly why that is

severe lark
#

because the right limit and left limit are not equal

#

x^2-9=(x+3)(x-3)

#

lim x->3+ (x-3)/|x-3| = 1, lim x->3- (x-3)/|x-3| = -1

hoary lotus
#

so would you use test values?

#

if it wanst apparent

severe lark
#

it....is apparent

#

or

hoary lotus
#

yes i understand

#

but i mean for another question

severe lark
severe lark
hoary lotus
#

lets say i had a question on a test and the denom was an absolute value

#

if a factor of the numerator was the same thing it means theres no limit

severe lark
#

yep

#

...

#

not always

#

it depends

hoary lotus
#

alright thanks

#

.close

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minor rapids
#

hi

safe radishBOT
#

Please don't occupy multiple help channels.

minor rapids
#

ok

pseudo pulsar
#

Do you have no question to ask?

silver whale
#

can you help me ? 5

minor rapids
#

no but i need your help

#

in maths

pseudo pulsar
#

Post your question

thin bridge
#

post in one of your two channels and close the other

pseudo pulsar
#

And don't occupy 2 channels

minor rapids
#

bro i dont have any question my maths is week so everyone make fun of me and i work so hard but im not geting result

silver whale
#

what are you talking about

pseudo pulsar
#

Type the following
.close

silver whale
#

yo zap

#

can you help 5

thin bridge
#

it may be worth getting a private tutor, you could seek tips for how to improve in #discussion #serious-discussion
these channels are intended for help on specific problems

minor rapids
#

ok

pseudo pulsar
#

.close

#

@minor rapids

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#

@minor rapids Has your question been resolved?

lean otter
#

@minor rapids It's been 20 minutes, do you still need assistance or can you .close this help channel to open it for others?

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round yoke
#

Hi

safe radishBOT
round yoke
#

Sorry ...how to do this question? 😅 which part was wrong

#

nvm get it

#

.close

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amber sky
safe radishBOT
amber sky
#

How do you go about solving this? I tried to use disc method but I couldn't integrate it

median vigil
#

trigonometric substitution is a good place to start

amber sky
#

What type of trig sub would I use for this integral

median vigil
#

the table at the end has a list

rose plume
#

but the volume of the solid has x^2 isnt it?

#

im blind

#

i didnt read everything

amber sky
#

Wait but you do use disc method for this question right?

median vigil
#

disk method will work fine here

median vigil
rose plume
#

still being a trig

#

i mean

#

ok not a trig sub

#

but a trig

median vigil
#

you would get it with trig sub, just more work than strictly necessary

safe radishBOT
#

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sacred socket
#

No idea how to go from here

safe radishBOT
rose plume
#

I've seen that when you have an 1/x^2 you usually use (Ax+B)/x^2 instead of B

#

maybe that method is also valid(?) I haven't see it

#

mmm maybe you can just separate it more

#

x^2(x-1)^2 = xx(x-1)(x-1)

#

wait, why squared? you end up with a term of x x^2 x^2 x^2

#

its a coefficient for each factor

sacred socket
rose plume
#

un-repeat it

#

when you wrote it the denominator would end up with at max a 1+2+2+2 degree instead of degree 4

#

x^2(x-1)^2 gives x^4 at max LHS (only focussing at biggest x)

#

RHS gives x^7, (after you add up all the fractions you multiply all fractions, and that x will be as big as x^7)

rose plume
#

a coefficient for each factor

sacred socket
#

ok lemme give this a shot, thank you

rose plume
#

don't thank me because its wrong

#

forget everything

#

imma see what you can do with what you had

#

///////////////////////

#

i have an idea

#

expand everything

sacred socket
#

dang im actually frustrated right now

#

im trying to FOIL it out

#

see if that brings me somewhere

rose plume
#

an match every coefficient with the one correspoding to eat

#

it

#

let me explain

#

once you know b = 1 and d = 1 is easier

sacred socket
#

hold on i think i got it

#

nvm i cant

rose plume
#

i figured it out

#

but wait let me send ss

#

okay I think I screwed it up in some term

#

but this is what you have to do

#

you match the coefficient of each term

#

let me try again

sacred socket
rose plume
#

i mean

#

rewrite the 1 as 0x^3 + 0x^2 +0x^1 + 1

#

so you want the coefficients of the term x^3 be equal to 0, same for x^2 and 0x^1, BUT YOU WANT THE ALONE COEFFICIENT BE EQUAL TO A

#

okay give me few minutes

sacred socket
rose plume
#

of i didn't mean it like that

#

but that works

#

give different values for x that doesn't delete the terms

#

okay that might work there too

#

if you let x = 2 and x = 3 for example, you find a system of equations and solve for A,C

#

imma send it with both methods

#

omg too many terms

#

wait im almost done

sacred socket
#

ok its fine, its getting really late for me but its good imma stay up a little longer

rose plume
#

first way

#

you write 1 = 0 + 1

#

and because multiplying by 0 doesn't change the expression

#

rewrite it as 0x^3+0x^2+0x+1 = ...

#

then match every coefficient, so you find whose values of A,B,C,D cancels make 0 those x^3 + x^2... and so on, so it only leaves you with 0 + 0 +... + 1 = 1

sacred socket
#

hmm ok i dont really understand this entirely since its 12am for me but i will go over this again tmr and try to understand it.

#

its funny because i skipped this and the question right after i got the answer in literally 2m

#

im going to log off for now but do you mind if I add you through discord?

#

thank you so much

#

.close

safe radishBOT
#
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opal moat
#

can i get a step by step help as to how to solve this?

opal moat
safe radishBOT
opal moat
#

also what am I typing wrong here?

#

symbolabs gives the wrong answer

#

or maybe they're equivalent but it says its wrong when i try 8/81

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@opal moat Has your question been resolved?

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opal moat
#

.reopen

safe radishBOT
#

#

@opal moat Has your question been resolved?

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@opal moat Has your question been resolved?

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formal blaze
#

what is 8+8

safe radishBOT
formal blaze
#

first answer my question 8+8

teal pollen
#

Compound interest formula = (1+p/n)^n where n is number of times compounded in one period (usually a year) and p is the % change

#

n = 4 in this case

#

yeah compounded 4 times in one year —> % increase in one year = (1+0.25/4)^4

#

find the % increase for one year and then find the % increase for 6

#

quarterly refers to specifically four times per ywar

#

well its just multiplying the power by 6 after that but im talking more about the thought process

#

so…?

#

multiply the % increase after six years by the original amount?

#

an increase of (1+0.25/4)^4 per year for six years

#

compounded quarterly

#

i.e. compounded four times a year

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spiral ermine
#

prove that the power of P is 3

safe radishBOT
spiral ermine
#

if (look pic) find P

#

<@&286206848099549185>

safe radishBOT
#

@spiral ermine Has your question been resolved?

charred niche
#

2power n= 8

#

Therefore n=3

spiral ermine
charred niche
#

Assume p to be of nth degree

#

Now what will be the degree of P(x+6)

#

?

spiral ermine
#

what is nth degree?

charred niche
#

Assume it to be n

#

Now equate that highest power term from both sides(lhs and rhs)

#

Lhs you will have the coefficient 2 power n and rhs 8

#

Hope it helps

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#

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hardy vapor
#

What does the following iteration calculate?

hardy vapor
#

for a>0

#

$x_{k+1}=G(x_k)$

flat frigateBOT
#

Bob Goldham

safe radishBOT
#

@hardy vapor Has your question been resolved?

last wren
#

if you have something of the form f(x) = x, then $x_{n+1} = f(x_n)$ converges to the solution $x^$, as long as $|f'(x^)| < 1$

flat frigateBOT
hardy vapor
#

so this converges such that for a sufficiently large n (likely the limit towards infinity) x_n=G(x_n)?

#

And I'm assuming we could analytically determine what it converges towards by setting x=G(x) and solving for x?

#

(Not that that's very efficient, hence the numerical approach?)

hardy vapor
#

alright thanks!

#

.close

safe radishBOT
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last wren
#

np! :)

safe radishBOT
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dusk stratus
#

so im trying to find the derivative of this using the f(x+h)-f(x)/h

dusk stratus
#

I'm having a tough time though

potent seal
#

Is the sqrt for the entire thing or just 3x?

dusk stratus
#

I radicized the numerator but now the denominator is sq

dusk stratus
potent seal
#

$\frac{\sqrt{3(x+h)+2}-\sqrt{3x+2}}{h}$

flat frigateBOT
#

Lorentz

potent seal
dusk stratus
#

sustitute with what

potent seal
#

The denominator will be the conjugate of numerator

#

h=0 i mean

thin bridge
#

can you show your work

dusk stratus
#

k one sec

#

@thin bridge @potent seal

#

please note that 3 at the bottom shouldnt be neg

potent seal
#

Just substitute h=0 after that

thin bridge
#

also there's no need/point in distributing the h to the conjugate

#

more ideal to leave it unexpanded, especially for more complicated limit problems

thin bridge
#

in your denominators

potent seal
thin bridge
#

no need to expand to
$$h\sqrt{3(x+h)+2} + h\sqrt{3x+2}$$
just leave it as
$$h(\sqrt{3(x+h)+2} + \sqrt{3x+2})$$

flat frigateBOT
#

ℝαμΩℕωⅤ

dusk stratus
#

ohh

#

okay

#

thank you

thin bridge
#

also in the first line

dusk stratus
#

makes sense actually

thin bridge
#

don't be lazy with notation

dusk stratus
thin bridge
#

make sure you write the multiplication to both the numerator and denominator

dusk stratus
#

okay ill do that

#

thanks guys

#

.close

safe radishBOT
#
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hybrid plover
#

Consider

safe radishBOT
hybrid plover
#

n and k are positive integers

flat frigateBOT
#

moriaritie

proper crypt
#

Well what exactly would you consider a closed form

eternal carbon
#

that pretty much is- ye

proper crypt
#

If you're allowed to use something like floor() then yes I guess

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#

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magic willow
#

Somebody help with my math ts impossible

faint seal
#

I highly doubt it is "impossible"

main mural
magic willow
desert pasture
#

,rotate

flat frigateBOT
main mural
#

lol

lean otter
magic willow
#

What do i add

lean otter
#

144 and 64

magic willow
#

Oh ok

lean otter
#

4root13

safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lean otter
#

did u get why

magic willow
#

I added

#

208=x square

#

Now what

lean otter
#

okay so see

#

u need to find only x

#

not x^2

#

amd

#

applying pythagoras theorem

#

do u know it

#

?

thin bridge
#

pythag was already applied

lean otter
#

but he/she didnt square root

#

im explaining why square root should be applied

#

so thst they dont make same mistake again

magic willow
#

Did i gettit

lean otter
#

yes

unborn spade
#

yes

lean otter
#

do u understand why

#

we square root?

thin bridge
lean otter
#

i didnt say its a mistake

#

i said

#

they shouldnt forget to square root

unborn spade
#

you'll lose marks if you keep in it x2 form

lean otter
#

yeah

#

thats what i was tryna explain

unborn spade
#

don't forget to square root be careful that's all

#

ggs

lean otter
#

but someone here thinks

unborn spade
#

sid

#

shush

lean otter
#

otherwise

lean otter
magic willow
#

Thank u

thin bridge
unborn spade
#

raq its okay she meant she didn't want him to make the mistake of forgetting the root

#

not a literal mistake

magic willow
#

Who tryna help me wit this one

#

Number 2

thin bridge
#

have you been introduced to sohcahtoa
and/or what sin, cos, tan do in a right triangle?

thin bridge
#

are you able to set up an equation that relates the
30° angle, x and 33?

hybrid plover
proper crypt
#

The solution to n = k(k + 3)/2 in terms of k is a whole number when a_n = 1

#

and not a whole number when a_n = 0

#

So you can use that

safe radishBOT
#

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eager garden
#

im not getting the same cords

safe radishBOT
thin bridge
#

-x^2 isn't 4 when x=2

eager garden
#

Then what is it

thin bridge
#

recall order of operations

hybrid plover
sly rose
safe radishBOT
#

@eager garden Has your question been resolved?

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dense wadi
#

whats the i in riemann sum

safe radishBOT
dense wadi
#

and why does it always = to 1

severe pond
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it starts at one

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i is just a subscript

dense wadi
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so lets say in this

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what does the i stand for

severe pond
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yea it’s just the index

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like which rectangle

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so ur adding up the first second third and so on

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rectangle

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and ur taking the limit as we get infinite rectangles

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so starting at 1 rectangle we go up to n rectangles

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for the approximation

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and the integral represents having infinitely many rectangles

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to get a precise area

proper crypt
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You start from i = 1, and increment it by 1 each time until you get to n

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For each i, you sum up f(x_i) * delta x

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So this just means f(x_1)delta x + f(x_2)delta x + ... + f(x_n)delta x

dense wadi
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ah

dense wadi
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i=2

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does it jump from every 2 rectangles?

dense wadi
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can the i just be like a symbol for all constants?

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1,2,3 etc

severe pond
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you always sum from the first rectangle

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it’s an approximation

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which gets better and better the more rectangles you add

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hence why n goes to infinity

safe radishBOT
#

@dense wadi Has your question been resolved?

dense wadi
safe radishBOT
#
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neat rover
safe radishBOT
neat rover
#

why is c wrong

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i got 2/5 on question one

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but wouldnt finding the average cost just be the cost of producing 100 phones plus producing 1 more devided by the total amount of phones made

safe radishBOT
#

@neat rover Has your question been resolved?

neat rover
#

.close

safe radishBOT
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barren hollow
#

Can someone help me with my geometry homework 😭😭 we are learning about cross sections

safe radishBOT
#

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wide cloud
#

how to find upper and lower boundaries? wasn't it getting the iqr, multiplying the iqr by 1.5, and subtracting for the lower bound/adding for upper bound?

median vigil
#

the upper and lower boundaries are usually just the lowest and highest data points. however, you may be required to exclude outliers, which we can define to be any points outside the 1.5*IQR range

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if you do have outliers you would normally plot them as individual points, and the upper and lower bounds would be the highest/lowest non-outliers

wide cloud
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i'm actually getting -10.5 though it feels weird for the entire graph to be apart of the plot

median vigil
#

where are you getting those numbers from?

wide cloud
median vigil
wide cloud
#

this is what i meant to be asking

median vigil
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so any data point outside that range is an outlier (you plot with a point) and anything inside that range is not an outlier (covered with the graph)

wide cloud
#

alright, yea I was just making sure if those numbers were correct if i was looking for the outliars

median vigil
wide cloud
#

ok sounds good, I appreciate it

#

.close

safe radishBOT
#
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eager garden
#

im not sure what to do here

safe radishBOT
neon summit
#

when a function increases it means that, going from left to right, the y value increases

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and when it decreases, the y value decreases

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so from question one we can see the function increases from negative infinity to somewhere before 0

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and increases from like 1 to positive infinity

eager garden
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and what am i suppose to do with the numerical thing

neon summit
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you have the equations of the two functions

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idk what your teacher may be looking for, but if i got this question this is what i would do. if i thought the function stopped increasing at -0.5, i would calculate. f(-0.5). after that, i would get a number smaller than -0.5, and greater than -0.5, and plug them into f, for example f(-0.6) and f(-0.4). if i see that both f(-0.6), and f(-0.4) are smaller than f(-0.5), then i know that it stops increasing at -0.5

safe radishBOT
#

@eager garden Has your question been resolved?

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misty ember
safe radishBOT
misty ember
#

I assume I distribute the e^2x to the x+2, and then take the antiderivative, is that correct?

drowsy karma
misty ember
drowsy karma
#

u = x + 2

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dv = exp

misty ember
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I'm not very good at that, so I was afraid that was the case lol- I'll try it with this new info and get back to you haha

drowsy karma
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if you have polynomial

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and

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exponentuial fucntion

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binded togetehr as multiplicaiton

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then you must integrate by parts

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no exception

misty ember
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Is this correct so far?

misty ember
misty ember
drowsy karma
misty ember
misty ember
drowsy karma
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do other thing

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if yoru exp2x

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is everywhere

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then take it out

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in front of parenthesis

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you understand me ?

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2Pi exp(2x) ( ... )

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that is more consistent notation

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nicer

misty ember
#

Lemme rewrite it

drowsy karma
#

when you show me all yoru final results, i will show you my version too, to compare

misty ember
drowsy karma
#

that is method to calculate all in same time

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but you can do as you did, first indefinite integral and next definite

misty ember
drowsy karma
misty ember
misty ember
drowsy karma
#

2Pi can be outsid

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but exp must be isnide

misty ember
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Like this?

drowsy karma
misty ember
drowsy karma
misty ember
drowsy karma
#

as me ?

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the last form on my photo

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shud be the same at you

misty ember
drowsy karma
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exp(2x)

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if you put x = 1

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then you have e^2

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if you put x = -1

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you hav exp(-2)

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agreed ?

misty ember
drowsy karma
misty ember
# drowsy karma yvw)

If I may ask you another question- how would I set this particular problem up? Would I solve for x and proceed to solve it the same way I did the last problem?

drowsy karma
#

and you rotate it around x-axis

misty ember
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So the constraints are from -4 to 0

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Okay, let me see if I can set this up properly

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Is this correct?

drowsy karma
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and you have:

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x = f(y)

misty ember
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Would x=y^2 - 4y become y = x+4?

drowsy karma
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i shwo you :

drowsy karma
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hence:

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the upper branch is y = 2+...

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the lower bramch is y = 2- ...

misty ember
drowsy karma
#

it is called : a canonical form of the trinomial, or in your language it can be called: a vertex form of the trinomial

drowsy karma
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a square trinomial = a quadratic function

drowsy karma
misty ember
drowsy karma
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if you want i can write this formual for you

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you like?

misty ember
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Yes please!

drowsy karma
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ok minute plz

drowsy karma
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of course, it also works when you change x with y

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that is super easy formula, and no need to spend time to combine on creatign it

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ppl often spedns much of time to reach it

misty ember
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I see

drowsy karma
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and it always always works 🙂

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even if you have very ugly numbers)

misty ember
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y = 2- square root of x+4 would be what I use for this equation yes?

drowsy karma
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you saw my photo with graph ?

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the upper red part of parabola

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is y = 2+ ...

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the lwoer part is y = 2-..