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seems like the text is wrong
So there are infinitely many such functions
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how would i do this
Expand LHS of equation so (x+y)^2=x^2+2xy+y^2
Yes, what you then do is minus x^2+y^2 on both sides of the equation
to get 2xy=0
or xy=0
xy = 0?
by null factor law, either x=0 or y=0
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hello can somebody please help me with a combinatorics question?
A student learns that in a multiple choice test, the correct answer to each question always has a different number. There are 6 questions, each with 6 choice answers, and the student has studied nothing, so he responds essentially at random. What is his best strategy (which maximizes the number of correct answers) between (i) always answer “1” (ii) roll a die for each question and give the answer corresponding to the number that comes out (iii) randomly choose a permutation of the numbers {1, . . . 6} and respond following this permutation. Generalize this problem to the generic case of n questions, with n choices per answer.
in the first case since all the questions have different answers the student guesses 1 out of 6 questions
i think we have to use derangements (?)
@storm maple Has your question been resolved?
<@&286206848099549185> sorry for the ping
@storm maple Has your question been resolved?
yes
i got that in the first and second case the expected value is 1, whereas in the third case it is approx. 3,792
there exist 6! possible permutations and 265 derangements (6! / e)
the probability of getting a derangement is 265/720 = 0,368 therefore the expected value of correct answers is 6 x (1 - 0,368) = 3,792
idk if this is right
by the way in yesterday's problem, the professor was wrong. he mixed the solutions to two different problems
that's not how it works
you don;t get 6 right answers as long as you didn't pick a derangement
you can get 6,1,2,3,4
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to check if it converges or not
Did i do it correctly?
In the last step, where did the exponent go?
you forgot to write it
but yes the limit is 1/e
seems correct to me
@modern pier Has your question been resolved?
oh i forgot it...but thanks
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there is some kind of operation here but i can't find it
@cobalt reef Has your question been resolved?
<@&286206848099549185> any idea?
Istg
I came up with this problem
2 days ago
Still no response
really exactly this one?
This type of
can you send it here?
Not exactly this one
i can take a look
aight
😫 what is this??
W
lol you're welcome
i get these type of problems alot
ping me if you get any of them again i can try
.close
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....any clue how to solve this? dont really wanna know the solution ,just a clue, feels so simple but i havent done geometry in like 4-5 years -_-
Hello can someone check if these are correct please. I also need help with the last question
Bud, you posted ur question 3 times relax and be patient
do things properly
sorry about that....
I didnt do random things
u did
What are tou sauing bruh
on a)
How is it random
I multiplied by 2^a
since when 3 = 9?
why did you write 2^9 = 2^3 ? ofcourse thats not true -_-
Yeah its probably not right
i told u already. Dont do random things, and study the exponential properties
Saying i didnt do random things, otherwise i wouldnt be here
u are doing random things. And for the third time, study exponential properties
So the answer is 6.
so can you explain why you wrote 2^9 = 2^3???
you kind of forgot to write a everywhere, it should be 9 = 3a and then you get a = 3
Omg
im talking about 1)
I think i see what i did wrong
Was i supposed to write 2^3 x 2^a?
On the ones side
???
yeah better do that, no clue what you re saying lol
i wont repeat again @buoyant solar . STUDY EXPONENTIAL PROPERTIES
What is the one you are talking about
$2^3 * 2^a = ?$
Aza
Guy im doing logs
????
wdym logs
oh god
hes right
u dont even know what u are doing
You know them logs
ur using the wrong exponential property
and u saying u arent doing random things xd
I know he is but i dont understand
see he said
2^3*2^a = 2^3+a
thats hwo it is supposed to be done
and ur doing it 2^3a
Oh
which is wrong
first study the theory and formulas, then do exercises
i have just told u to not spoonfeed, and u come here and do it again? @hidden mist
rlly, shut up wtf?
I already did the topic last year
didnt he just mess 3 times already
so?
and u tried making him understand thric
as if he needs to mess 100 times
and nothing helped
Yeah
spoonfeed?
yeah cuz im not spoonfeeding him. I told him to study, and he doesnt care
he only comes here to see if someone else solves his problems
he doesnt care about why
but whatever
do what u want
xDDDDDDDDDDDDDDDDDDDD
Sorry im not as good at maths as u
Shi idk what that is
idk, @tawny knoll ,that atitude just gets people away from math,right?
then STUDY. Dont come here hoping for others to tell u the answers
So i can do other problems
also maybe stop talking like you re on a tiktok -_-
?
I dont use that app bro
For braindead ppl
K well none of you are really usefull
idk if its just the slang but it makes you sound bad, like "fax", " shi"....
Tell me the answer so i can work backward
Thats just how i thpe
Say what a is equal to
thats not how it works
Not how it is done
Well my teachers have said the best way to figure something out is to try and do the problem backward
And im in my final year
do that for the ones you got in class or just google some examples
then try applying the same logic to your problem
no its not :/
Wasup
anyway, if someone could help with this, it would help a lot
hi
Wikipedia sucks
dude, think about that logically, you put 2 * 2, 3 times and then you put 2 * 2, a more times, how many times did you put 2*2?
Reddit is better
Yes it is 2x2x2
yeah 2^(3+a)
but its not the answer to your original problem
well, gl, im just gonna leave
@buoyant solar Has your question been resolved?
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If x = 4/x+y and y+5/y+x where x and y are non-zero real numbers, then the absolute value of the difference of the two numbers is equal to?
<@&286206848099549185>
!15m
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2. I have begun but got stuck midway.
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7. None of the above
Did you mean y=5/y+x?
And you want to find |x-y|?
thats right
I wold solve for x-y in both equations, then go from there. That seems to be the best route
wdym both ecuations
didnt u specify 2 equations in the quetion
question
oh those two
makes sense
x-y = 4/x
x-y = -5/y
right? @empty gyro
okay
does that mean 4/x = -5/y
now i'm stuck again 😭
@empty gyro what should i do now
?
solve for x or y, then put it back in first equation and solve for the other variable
well x = 4y/5
so we'd replace in the second one
double check your math
what is this?
x-y
x-y=x+4/x won't help you. You broight the unknown y back
You're trying to solve for x
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can someone help me with this question pls
@severe moon Has your question been resolved?
<@&286206848099549185>
well you have:
- number of women = 4/5ths * number of men
and - number of unmarried woman = 40%
- 30 unmarried woman
so 30 = 40% of x (x being the number of women)
x = 75
from here you can calculate the number of men
i may have perceived the question wrong
40% of the men were unmarried or 40% of the women?
i also didnt get that part
i think its %40 of women
i know this question is a bit ambiguous
but i think it's 40% of the men
as men was the last subject mentioned
yeah i think its men as well coz why else would they mention the stuff about the married women being with their husbands etc
exactly
ok then u gotta solve it a different way
how
well you'll take %40 of the men
not the women
which would obviously change the amount of people
@severe moon Has your question been resolved?
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I know I have to use some directional calculation but I'm kinda stuck on how to approach this
I think I need to calculate the partial derivative of x and y
but
given the two points
I don't know if it's possible
@sullen hill Has your question been resolved?
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what's up with the radical.
looks like they skipped some steps
They just skip over the simplification because it's not important I assume
If you're doing calculus, this isn't the main focus
Just plug and evaluate, that's all
how do you even simplify that equation to get that answer is the question
Find cos(19pi/6)
Subtract 2pi, so that's equal to cos(7pi/6)
Which is equal to -cos(pi/6)
And cos(pi/6) = sqrt(3)/2
Do a similar thing with sine
Is there an easy way to think about trig functions on radians
I get degrees, but radians hurt my head
@lean otter Has your question been resolved?
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Can someone explain me why it equals to 0 in both sides here?
because the LHS must be >= 0 and the RHS is <= 0
you have an even root of a positive number on one side and an even root of a negative number on the other
Ohh I see
And does it apply to every quadratic equation? Or is it because I took the root from both sides?
I expanded s.t $(3x^2 + 6)^2 = -9x^2 \Rightarrow 18x^2+36x+36 = 0$
g3
Then you see that $\sqrt{b^2 - 4ac} < 0 \Rightarrow x \in \mathbb{C}$
g3
I see now that's because this, right?
The only way we can have equality is at the intersection, 0
Righttt
That makes it more clear
Thanks y'all!
No
Only in this very specific case
I see
Best is to use other methods above
Yeah, like discriminant right?
I used that and I got the solution also
But now I get why you can also equal all to 0
Well, thank you very much
.solved
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How?
vandermonde's identity
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the degree of the numerator and denominator are not both n in the derivative.
@next oar Has your question been resolved?
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Hi
Is 1.d answer just nothing ?
Yes
Reducing is performing a certain operation to both the numerator and denominator
They are asking what the operation was
Yeah
@rough matrix Has your question been resolved?
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How do you do these again?
You were close, but the first issue that f'(x)=-1, not +1. Next, you can actually calculate g'(3) because it's the slope of the line at x=3. Looking at the part of g(x) around x=3, the slope is 2, so you can plug that in to get just a number for the answer
OH
So the answer is 4
Darn it!
I think it's -1 + 2*3 + 3 = 8
Wat
So re-writing your work a bit, you got that h'(3) = f'(3) + g'(3)*3+g(3). Then plugging in h'(3) = -1 + 2*3 + 3
Why did you add 3?
You told me the slope is 2
Oh sorry if I'm not writing it well. g'(x) is the slope, but there's also just g(x) which is the actual value of the function. So the 3 on the end there is from the actual value of g(3), not the slope
OHHH that makes sense
Thank you so much Don!
Glad to help! It's a weird one haha
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is anyone fluent in statistics (ap statistics specifically would be even better)
i need help studying
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
soooo that’s the command 
does anyone know about sample proportions
i think you need to read what the bot said again
yo... ask the question
i’m just curious about how they work
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What would my first step be since i cant cross multiply
get all your x stuff on one side
why can't you? try it and see what happens!
or multiply both sides by (x+4) and get rid of the denominators
several ways to go about it
Wouldnt i have x^3 then too?
If i multiplied both sides
Man i have no idea lol
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Why need to divide by 18
you divide by 2 because if you reflect the necklace, you can get the same bead pattern
you divide by 9 because if you rotate the necklace, you can get the same bead pattern
in total, you divide by 18
though it looks like the book has a typo… extra 0 at the end of the answer 🤔
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d
hello i have a limits question
if i have something like lim x -> 3, (x^2-9)/(|x-3|)
how do i go about solving it
it has no limit
can u pls explain i understand its because its divided by absolute value of that
but i dont understand exactly why that is
because the right limit and left limit are not equal
x^2-9=(x+3)(x-3)
lim x->3+ (x-3)/|x-3| = 1, lim x->3- (x-3)/|x-3| = -1
wdym
lets say i had a question on a test and the denom was an absolute value
if a factor of the numerator was the same thing it means theres no limit
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hi
ok
Do you have no question to ask?
can you help me ? 5
Post your question
post in one of your two channels and close the other
And don't occupy 2 channels
bro i dont have any question my maths is week so everyone make fun of me and i work so hard but im not geting result
what are you talking about
Type the following
.close
it may be worth getting a private tutor, you could seek tips for how to improve in #discussion #serious-discussion
these channels are intended for help on specific problems
ok
You shouldn't occupy the help channel then, other channels would be more helpful
.close
@minor rapids
@minor rapids Has your question been resolved?
@minor rapids It's been 20 minutes, do you still need assistance or can you .close this help channel to open it for others?
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Hi
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How do you go about solving this? I tried to use disc method but I couldn't integrate it
trigonometric substitution is a good place to start
What type of trig sub would I use for this integral
Wait but you do use disc method for this question right?
disk method will work fine here
although in that case i suppose trig sub is a bit overkill
you would get it with trig sub, just more work than strictly necessary
@amber sky Has your question been resolved?
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No idea how to go from here
I've seen that when you have an 1/x^2 you usually use (Ax+B)/x^2 instead of B
maybe that method is also valid(?) I haven't see it
mmm maybe you can just separate it more
x^2(x-1)^2 = xx(x-1)(x-1)
wait, why squared? you end up with a term of x x^2 x^2 x^2
its a coefficient for each factor
No clue on this one, i know when you have "Repeating Factors" you should do A+B+...but the difference here is that I have 2 repeating factors 💀
un-repeat it
when you wrote it the denominator would end up with at max a 1+2+2+2 degree instead of degree 4
x^2(x-1)^2 gives x^4 at max LHS (only focussing at biggest x)
RHS gives x^7, (after you add up all the fractions you multiply all fractions, and that x will be as big as x^7)
fwof-wogypajkhogwoajhkoj k this in few words
a coefficient for each factor
ok lemme give this a shot, thank you
don't thank me because its wrong
forget everything
imma see what you can do with what you had
///////////////////////
i have an idea
expand everything
dang im actually frustrated right now
im trying to FOIL it out
see if that brings me somewhere
an match every coefficient with the one correspoding to eat
it
let me explain
once you know b = 1 and d = 1 is easier
i figured it out
but wait let me send ss
okay I think I screwed it up in some term
but this is what you have to do
you match the coefficient of each term
let me try again
i notice this but I missed my lecture yesterday and Im reading the notes but I dont understand the matching the coefficients part.
i mean
rewrite the 1 as 0x^3 + 0x^2 +0x^1 + 1
so you want the coefficients of the term x^3 be equal to 0, same for x^2 and 0x^1, BUT YOU WANT THE ALONE COEFFICIENT BE EQUAL TO A
okay give me few minutes
ok i see this a lot clearer, this is the example I get when he talks about the coefficients.
of i didn't mean it like that
but that works
give different values for x that doesn't delete the terms
okay that might work there too
if you let x = 2 and x = 3 for example, you find a system of equations and solve for A,C
imma send it with both methods
omg too many terms
wait im almost done
ok its fine, its getting really late for me but its good imma stay up a little longer
first way
you write 1 = 0 + 1
and because multiplying by 0 doesn't change the expression
rewrite it as 0x^3+0x^2+0x+1 = ...
then match every coefficient, so you find whose values of A,B,C,D cancels make 0 those x^3 + x^2... and so on, so it only leaves you with 0 + 0 +... + 1 = 1
hmm ok i dont really understand this entirely since its 12am for me but i will go over this again tmr and try to understand it.
its funny because i skipped this and the question right after i got the answer in literally 2m
im going to log off for now but do you mind if I add you through discord?
thank you so much
.close
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can i get a step by step help as to how to solve this?
also what am I typing wrong here?
symbolabs gives the wrong answer
or maybe they're equivalent but it says its wrong when i try 8/81
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what is 8+8
first answer my question 8+8
Compound interest formula = (1+p/n)^n where n is number of times compounded in one period (usually a year) and p is the % change
n = 4 in this case
yeah compounded 4 times in one year —> % increase in one year = (1+0.25/4)^4
find the % increase for one year and then find the % increase for 6
quarterly refers to specifically four times per ywar
well its just multiplying the power by 6 after that but im talking more about the thought process
so…?
multiply the % increase after six years by the original amount?
an increase of (1+0.25/4)^4 per year for six years
compounded quarterly
i.e. compounded four times a year
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prove that the power of P is 3
@spiral ermine Has your question been resolved?
Assume P to be nth degree ,now equate the highest degree term
2power n= 8
Therefore n=3
what??
what is nth degree?
Power, the highest exponent of the variable
Assume it to be n
Now equate that highest power term from both sides(lhs and rhs)
Lhs you will have the coefficient 2 power n and rhs 8
Hope it helps
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What does the following iteration calculate?
Bob Goldham
@hardy vapor Has your question been resolved?
this is known as a fixed point iteration
if you have something of the form f(x) = x, then $x_{n+1} = f(x_n)$ converges to the solution $x^$, as long as $|f'(x^)| < 1$
doaby
so this converges such that for a sufficiently large n (likely the limit towards infinity) x_n=G(x_n)?
And I'm assuming we could analytically determine what it converges towards by setting x=G(x) and solving for x?
(Not that that's very efficient, hence the numerical approach?)
yes exactly
you got it
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np! :)
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so im trying to find the derivative of this using the f(x+h)-f(x)/h
I'm having a tough time though
Is the sqrt for the entire thing or just 3x?
I radicized the numerator but now the denominator is sq
the whole thing
$\frac{\sqrt{3(x+h)+2}-\sqrt{3x+2}}{h}$
Lorentz
You can just substitute after that
sustitute with what
can you show your work
k one sec
@thin bridge @potent seal
please note that 3 at the bottom shouldnt be neg
Just substitute h=0 after that
also there's no need/point in distributing the h to the conjugate
more ideal to leave it unexpanded, especially for more complicated limit problems
where
in your denominators
Note that the derivative would be the limit of this as h tends to 0
no need to expand to
$$h\sqrt{3(x+h)+2} + h\sqrt{3x+2}$$
just leave it as
$$h(\sqrt{3(x+h)+2} + \sqrt{3x+2})$$
ℝαμΩℕωⅤ
also in the first line
makes sense actually
don't be lazy with notation

make sure you write the multiplication to both the numerator and denominator
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Consider
n and k are positive integers
moriaritie
Well what exactly would you consider a closed form
that pretty much is- ye
If you're allowed to use something like floor() then yes I guess
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Somebody help with my math ts impossible
ask your question
,rotate
add and square root
What do i add
144 and 64
Oh ok
4root13
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
did u get why
okay so see
u need to find only x
not x^2
amd
applying pythagoras theorem
do u know it
?
pythag was already applied
but he/she didnt square root
im explaining why square root should be applied
so thst they dont make same mistake again
Did i gettit
yes
yes
no mistakes were made, work was just incomplete
dude
i didnt say its a mistake
i said
they shouldnt forget to square root
you'll lose marks if you keep in it x2 form
but someone here thinks
otherwise
....
Thank u
you literally said mistake
raq its okay she meant she didn't want him to make the mistake of forgetting the root
not a literal mistake
have you been introduced to sohcahtoa
and/or what sin, cos, tan do in a right triangle?
Yeah
are you able to set up an equation that relates the
30° angle, x and 33?
oops, i was gone. ok you can use floor, what would be it then?
The solution to n = k(k + 3)/2 in terms of k is a whole number when a_n = 1
and not a whole number when a_n = 0
So you can use that
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im not getting the same cords
-x^2 isn't 4 when x=2
Then what is it
recall order of operations
got it, thanks!
SOHCAHTOA
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whats the i in riemann sum
and why does it always = to 1
yea it’s just the index
like which rectangle
so ur adding up the first second third and so on
rectangle
and ur taking the limit as we get infinite rectangles
so starting at 1 rectangle we go up to n rectangles
for the approximation
and the integral represents having infinitely many rectangles
to get a precise area
You start from i = 1, and increment it by 1 each time until you get to n
For each i, you sum up f(x_i) * delta x
So this just means f(x_1)delta x + f(x_2)delta x + ... + f(x_n)delta x
ah
so if it says
i=2
does it jump from every 2 rectangles?
so the x_i
can the i just be like a symbol for all constants?
1,2,3 etc
well if it starts at i=2 but it won’t
you always sum from the first rectangle
it’s an approximation
which gets better and better the more rectangles you add
hence why n goes to infinity
@dense wadi Has your question been resolved?
ah okay ty
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why is c wrong
i got 2/5 on question one
but wouldnt finding the average cost just be the cost of producing 100 phones plus producing 1 more devided by the total amount of phones made
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Can someone help me with my geometry homework 😭😭 we are learning about cross sections
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how to find upper and lower boundaries? wasn't it getting the iqr, multiplying the iqr by 1.5, and subtracting for the lower bound/adding for upper bound?
the upper and lower boundaries are usually just the lowest and highest data points. however, you may be required to exclude outliers, which we can define to be any points outside the 1.5*IQR range
if you do have outliers you would normally plot them as individual points, and the upper and lower bounds would be the highest/lowest non-outliers
ok so it should be 10.5 and 54.5?
i'm actually getting -10.5 though it feels weird for the entire graph to be apart of the plot
where are you getting those numbers from?
the iqr minus 26 and plus 38
so those aren't the upper and lower bounds of your box plot, that's the boundary which we find for outliers
right
this is what i meant to be asking
so any data point outside that range is an outlier (you plot with a point) and anything inside that range is not an outlier (covered with the graph)
alright, yea I was just making sure if those numbers were correct if i was looking for the outliars
but that is the correct range for finding outliers, yes
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im not sure what to do here
when a function increases it means that, going from left to right, the y value increases
and when it decreases, the y value decreases
so from question one we can see the function increases from negative infinity to somewhere before 0
and increases from like 1 to positive infinity
and what am i suppose to do with the numerical thing
you have the equations of the two functions
idk what your teacher may be looking for, but if i got this question this is what i would do. if i thought the function stopped increasing at -0.5, i would calculate. f(-0.5). after that, i would get a number smaller than -0.5, and greater than -0.5, and plug them into f, for example f(-0.6) and f(-0.4). if i see that both f(-0.6), and f(-0.4) are smaller than f(-0.5), then i know that it stops increasing at -0.5
@eager garden Has your question been resolved?
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I assume I distribute the e^2x to the x+2, and then take the antiderivative, is that correct?
use integration by parts, your integral si typical for that
the UV - integral of vdu?
I'm not very good at that, so I was afraid that was the case lol- I'll try it with this new info and get back to you haha
ok) but no other emthod , becasue
if you have polynomial
and
exponentuial fucntion
binded togetehr as multiplicaiton
then you must integrate by parts
no exception
very well 🙂
Do I distribute the 1/2e^2x to the x+2?
yes you may
like this?
ye sbut it does nto look nice
do other thing
if yoru exp2x
is everywhere
then take it out
in front of parenthesis
you understand me ?
2Pi exp(2x) ( ... )
that is more consistent notation
nicer
when you show me all yoru final results, i will show you my version too, to compare
Here you go!
yes 🙂
that is method to calculate all in same time
but you can do as you did, first indefinite integral and next definite
So now I plug in what I got into the definite integral?
yes it is,
Like this?
your bracket must surrond all expression
2Pi can be outsid
but exp must be isnide
correct)
Okay, let me try to calculate it
ok
I got 57.821
but can you get precise form ?
as me ?
the last form on my photo
shud be the same at you
I don't understand where the e^2 - e^2 come from, everything else I think I understand how you got there
exp(2x)
if you put x = 1
then you have e^2
if you put x = -1
you hav exp(-2)
agreed ?
Oh, I see it now! Thank you.
yvw)
If I may ask you another question- how would I set this particular problem up? Would I solve for x and proceed to solve it the same way I did the last problem?
one moment )
that is your region :
and you rotate it around x-axis
Oh, because if you simplify the y^2-4y you get y= 0, -4
So the constraints are from -4 to 0
Okay, let me see if I can set this up properly
Is this correct?
no, because, you used formula, when your function is of the form y = f(x)
and you have:
x = f(y)
Would x=y^2 - 4y become y = x+4?
no ) look, you have parabola, so it cant become a straight line
i shwo you :
hence:
the upper branch is y = 2+...
the lower bramch is y = 2- ...
What did you do in order to create the (y-2)^2 - 4 ?
it is called : a canonical form of the trinomial, or in your language it can be called: a vertex form of the trinomial
ahve you heard about it durign lecture of square trinomials ?
a square trinomial = a quadratic function
there is a very known formula fo rthat in school
I think I just forgot about that, or maybe I know it and it's just not clicking right now for me
Yes please!
ok minute plz
of course, it also works when you change x with y
that is super easy formula, and no need to spend time to combine on creatign it
ppl often spedns much of time to reach it
I see
y = 2- square root of x+4 would be what I use for this equation yes?
