What
#help-23
fringe silo
indigo tundra
Trigonometry
fringe silo
It is goniometeic functions
indigo tundra
O k
fringe silo
Angle functions
There are cyclometric functions
Used in integral
Like
Cotangens
Arcus sinus
indigo tundra
O k
fringe silo
Arcus cosinus
indigo tundra
What does this have to do with 9th grade level math
indigo tundra
Someone plz help🙏
indigo tundra
This is highschool 😭
indigo tundra
<@&286206848099549185>
indigo tundra
<@&286206848099549185>
I went to Roblox to beg people for help and they all quit so far mid problem 😔
<@&286206848099549185>
steel dragon
Can you send the problem again?
steel dragon
What type of comparisons are made in these steps?
indigo tundra
A measure length and length again
indigo tundra
oki
steel dragon
First in step 9 You have m1 = m2
indigo tundra
Fr
steel dragon
Lets note step 11 is almost the same that step 10
indigo tundra
So true
steel dragon
The only difference is that they replaced m2 with m1
Why do you think that is legal?
Or in what step did they mention something like that
indigo tundra
Cuz they are the same thing
steel dragon
Yea they said that in step 9
safe radishBOT
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lean otter
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lean otter
i dont know an equation for these
junior smelt
Do you know how pH is defined?
lean otter
yes
5 is 10 x more acidic than 6
it has to be solved using this equation
Ao is the initial value
A is the final value
G.r is growth rate
D.r is decay rate
t is total time
T is time of recorruing period or sum
how often the cycle is
how many days or hours or months the cycle repeats
or some shit
idk how to solve those two usin that equation
junior smelt
hmm, wonder why they expect you to use that 
junior smelt
Would have thought that using that the pH is $-\log_{10}[H^+]$ would have been better
flat frigateBOT
@junior smelt
junior smelt
Well I guess seeing that you know that a pH of 6.4 would be 10 times more acidic than the normal pH of 7.4, probably along those lines then
Hi @empty gyro 
lean otter
then..?
junior smelt
Well if you know that a pH decrease of 1 corresponds to an acidity increase of 10x, you want to find the pH decrease that corresponds to an acidity increase of 3x
Not too sure how to suggest anything more, that wouldn't be basically the whole solution
junior smelt
Well if you have to use that formula, can't lie, not too sure how you would 
empty gyro
I 100% doubt you are using this formula. There is no mention of time anywhere.
lean otter
it doesnt have to be time
empty gyro
This is all you need
empty gyro
okay, then use what you know about precalc to figure out proportionality
lean otter
bro we didnt learn this
empty gyro
5 is 10 x more acidic than 6
You literally described it here
safe radishBOT
@lean otter Has your question been resolved?
lean otter
if i didnt have a calculator, how am i suppose to determine the greatest value?
lofty adder
you can try to find the nearest value you know
for example, you might dont know the actual value of A
but you know log3,27 right?
its 3
umbral swan
yes you just define boundaries where you know the integer solutions
log3(30) thereby lies between 3 and 4 as above mentioned
lofty adder
yes
and log2,9 is more then 3, less than 4 also
however you can find that 3^3 = 27, 3^4 = 81
2^3 = 8, 2^4 = 16
and try to determine which side does the value close to
safe radishBOT
@lean otter Has your question been resolved?
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tribal grove
any ideas/help
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@tribal grove Has your question been resolved?
limpid trellis
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limpid trellis
Angle AOB = Angle COB
vertically opp
i know the other ones are proportionate
like line od is double ao
and co is double bo
how do i phrase this
cuz u can't use half the similarity AAA proof with half the propotionate side proof
safe radishBOT
@limpid trellis Has your question been resolved?
limpid trellis
<@&286206848099549185>
safe bluff
cuz u can't use half the similarity AAA proof with half the propotionate side pr...
do you know about SAS similarity?
safe bluff
yes
limpid trellis
i know about it
safe bluff
sorry?
safe bluff
oh thats weird
limpid trellis
yeah
limpid trellis
yeah thats why im confused
also when im writing the proof
on paper
would i do something like
In triangle AOB and triangle COD:
AO ∝ OD
OB ∝ OC
angle aob = angle cod (vertically opp)
therefore aob and cod are similar
limpid trellis
alright thanks
i was just stuck cuz the program doesn't let me give the direct proportionality reasoning
safe bluff
it really only lets you use AAA similarity?
eager torrent
(by SAS similarity)
i haven't even looked at you answer but since half the population makes this mistake, is SAS congruency in order or not are they all related, is the intersect point of the 2 sides, the angle point
safe bluff
i haven't even looked at you answer but since half the population makes this mis...
sorry?
the two sides im talking about are next to each other and the angle is between them
eager torrent
ita not really by congruenby which this is solved, its by side angle side similarity and BTW you can't call this SAS as thats more of a congruency rule
safe bluff
sas is a similarity rule as well...
there are several congruency rules that share acronyms with similarity rules
thats why you specify similarity or congruence
safe radishBOT
@limpid trellis Has your question been resolved?
viscid echo
Hi
quasi bison
!15m
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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
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@viscid echo Has your question been resolved?
fringe silo
@viscid echo
fringe silo
The 1st question is 5³
viscid echo
The answer is 3380
fringe silo
?
viscid echo
Yeah it is confusing
viscid echo
Yes
fringe silo
How did you get number 3380
astral loom
hi guys can i can ask physic related here
safe radishBOT
hi guys can i can ask physic related here
astral loom
this is an essay im required to do and i need to calculate something somewhere
and i have no idea what im suppose to be doing honestly
shadow glade
can you be a bit more specific, what is your question exactly?
quasi bison
"i need to make an essay completely from scratch"
astral loom
oh sorry
like im pretty sure these are the option
but idk how theyre related to houses and how im suppose to calculate
sorry let me clarify; these are the formulas and up there is the requirement for my essay u dont need to help me with the essay i sent it so you get the idea
shadow glade
you still haven't asked a question : )
lean otter
lol
@astral loom what is the question. We can help until you ask the question
!status
safe radishBOT
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
sorry i dont exactly have a question with numbers in in im just confuse all the way on what the formula relating to calculating home insulation are
shadow glade
astral loom
😭😭😭
hard crest
you probably should also review your notes and your book
lean otter
proceed to type .close
astral loom
my teacher is rushing this she did not teach anything at all since were switching subject right agter this😭😭
how do i close the thing again
stray warren
astral loom
.close
safe radishBOT
shadow glade
it's also a bit of a skill that you can work on to ask good questions. If you just kind of say "im confused by a formula" without even giving the formula its difficult for people to help you. if you give us the formula and say more specifically "ok i don't know what this letter represents, i do understand this one part" you will be more likely to get help. it's good to be clear with yourself exactly what you underswtand and what you don't and formulate a clear question @astral loom
lean otter
my teacher is rushing this she did not teach anything at all since were switchin...
give the question a longer think. We are unable to help you currently because you being very confused about what to do also makes us very confused, so we don't even know what you need help with. Take a deep breath and relax yourself and just try to take in what they're trying to say.
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Available help channel!
shadow glade
sorry we couldn't be more helpful : (
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sorry we couldn't be more helpful : (
shadow glade
.close
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lean otter
lol
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unborn wigeon
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frigid spruce
$x^2 y^2+x^2+y^2+1$\
$$x^2(y^2+1)+1(y^2+1)$$\
$$(x^2+1)(y^2+1)$$
flat frigateBOT
🐱!Yajat! 【Catfan1398】🐱
frigid spruce
@unborn wigeon
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@unborn wigeon Has your question been resolved?
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fallen thunder
For a certain probability, the probability that event A will occur is 0.6 and the probability that event B will occur is 0.8. Which of the following values could be the probability that both the event A and the event B will occur? Indicate all such values.
A) 0.1
B) 0.4
C) 0.48
D) 0.6
E) 0.8
safe radishBOT
For a certain probability, the probability that event A will occur is 0.6 and th...
fallen thunder
,, 0 \leq \mbb{P}( A \cap B) \leq \mbb{P} \operatorname{min} { \mbb{P}(A), \mbb{P}(B)} = 0.6
flat frigateBOT
斗地姿
flint wave
It's just 0.6*0.8 lol
fallen thunder
It's just 0.6*0.8 lol
no
That's one of the answers
There's more
Anyway
Isn't the answer ABCD instead of BCD
fallen thunder
,, 0 \leq \mbb{P}( A \cap B) \leq \mbb{P} \operatorname{min} \{ \mbb{P}(A), \mbb...
or is this wrong?
glacial cairn
Are you saying that BCD is supposed to be the answer and you want to understand why?
fallen thunder
Are you saying that BCD is supposed to be the answer and you want to understand ...
BCD is the answer
but i think it should be ABCD
glacial cairn
I think the min is 0.4 because if A and B are as far apart as possible, you still get an overlap of 0.4
fallen thunder
But you can construct a case wher ethe overlap is 0.1, no?
glacial cairn
I don't exactly know how to translate that formally, I guess there is a min for P(A|B) = P(B|A)
Not if you want each probability independently to be 0.6 and 0.8
fallen thunder
fallen thunder
Not if you want each probability independently to be 0.6 and 0.8
I'm not sure what you mean
fallen thunder
,, 0 \leq \mbb{P}( A \cap B) \leq \mbb{P} \operatorname{min} \{ \mbb{P}(A), \mbb...
i got the min here because they're mutually exclusive (assuming)
max is when one set is contained inside another basically the 0.6 thing is inside 0.8 thing
glacial cairn
The union would be > 1 in this case
Incredible paint skills
Green is A, blue is B
You see that 0.6 - (1-0.8) = 0.4
fallen thunder
The union would be > 1 in this case
oh yeah
glacial cairn
It's not, but it's not a tight lower bound
fallen thunder
so what's the correct one?
the min and max is right yeah but not sure how to connect the inequalities
glacial cairn
I don't know
fallen thunder
Oh
glacial cairn
I guess for 2 events it would be max(0, P(A) - (1-P(B)))
= max(0, P(A) + P(B) - 1)
fallen thunder
= max(0, P(A) + P(B) - 1)
by the way
1 = P(A) + P(B) - P(A and B)
the 1 here is everything in the sample space right
so pictorially this means
the sample space is just the two venn diagrams and nothing else?
glacial cairn
If there is no possibility that neither A nor B happened
fallen thunder
If there is no possibility that neither A nor B happened
i mean that's the point of the 1 instead of P(A or B), no?
glacial cairn
That's why I used max(0, something)
glacial cairn
If A is contained in B then the probability neither happened is 0.2
glacial cairn
If A is contained in B then P(A) + P(B) - P(A and B) = P(B), not P(omega)
fallen thunder
If A is contained in B then P(A) + P(B) - P(A and B) = P(B), not P(omega)
right i see your point
fallen thunder
If A is contained in B then P(A) + P(B) - P(A and B) = P(B), not P(omega)
so how was i supposed to do the question?
P(A) * P(B) is for independent events so that gives 0.48 okay i get C
if A is contained within B i get 0.6 so i get D too
B i did - (1 - 0.6 - 0.8) but i used the logic that P(omega) = 1
was it supposed to be P(A u B)?
glacial cairn
I guess you can say that if P(A) + P(B) >= 1 then the min for P(A and B) is found when P(A or B) = 1
P(A and B) is minimal when P(A or B) is maximal
fallen thunder
I guess you can say that if P(A) + P(B) >= 1 then the min for P(A and B) is foun...
fair enough
what about P(A) + P(B) < 1
oh then you're dealing with other elements in the set?
glacial cairn
Then surely you can find a scenario where P(A and B) = 0
fallen thunder
Then surely you can find a scenario where P(A and B) = 0
why? I'm confused
glacial cairn
Not sure how to prove it but if P(A) + P(B) < 1 then P(A|B) can be 0
fallen thunder
Not sure how to prove it but if P(A) + P(B) < 1 then P(A|B) can be 0
my headddd
I don't see how tbh ughh
glacial cairn
Same diagram as earlier, just with P(A) + P(B) < 1
You can clearly see there is no intersection
fallen thunder
Not sure how to prove it but if P(A) + P(B) < 1 then P(A|B) can be 0
anyway for my question it can't be 0.1 because:
1 = 0.6 + 0.8 - 0.1 + other elements
-0.4 = -0.1 + other elements
-0.3 = other elements (doesn't make sense)
Is this good reasoning?
fallen thunder
Same diagram as earlier, just with P(A) + P(B) < 1
ah okay yeah now i can see why
fallen thunder
Not sure how to prove it but if P(A) + P(B) < 1 then P(A|B) can be 0
or would i just go something like 0.6 + 0.8 - 0.1 > 1 so it doesn't work unless we're in some weird measure
glacial cairn
Ok so if P(A) + P(B) >= 1 then P(A or B) can be 1, right?
fallen thunder
sure
glacial cairn
And we know P(A or B) = P(A) + P(B) - P(A and B)
So P(A and B) = P(A) + P(B) - P(A or B)
P(A and B) = 0.6 + 0.8 - 1 = 0.4
fallen thunder
you mean 0.1?
glacial cairn
No
fallen thunder
but why subtract by 1?
fallen thunder
P(A and B) = 0.6 + 0.8 - 1 = 0.4
yes this one i get
glacial cairn
I mean the minimum for P(A and B) is 0.4 and is achieved when P(A or B) = 1
If you take P(A or B) < 1 then it becomes P(A and B) > 0.6 + 0.8 - 1
fallen thunder
I mean the minimum for P(A and B) is 0.4 and is achieved when P(A or B) = 1
yeah okay
that just means
P(A or B) is the sample space?
i get the 0.4 part
glacial cairn
In this case yes
glacial cairn
The counterargument is just that 0.1 < 0.4...
fallen thunder
oh lol
fallen thunder
I mean the minimum for P(A and B) is 0.4 and is achieved when P(A or B) = 1
i forgot about this
i need to find some info on this
never knew about this tbh
okay thanks ig i'll check it out later
glacial cairn
P(A and B) is minimal when P(A or B) is maximal
I know intuitively that this is true, and the special case is when P(A) + P(B) >= 1 then you can take P(A or B) = 1
safe radishBOT
@fallen thunder Has your question been resolved?
crude vault
Does the sun exert equal gravitational force on the earth as the earth exerts on the sun? since newtons third law?
safe radishBOT
Does the sun exert equal gravitational force on the earth as the earth exerts on...
tardy laurel
I Ain’t in school fuck this I randomly joined
main mural
Does the sun exert equal gravitational force on the earth as the earth exerts on...
what's the formula for force?
crude vault
what's the formula for force?
F= MA
crude vault
sorry, should've specified. the formula for gravitational force
F = GM m / r^2
crude vault
yeah m1 m2
crude vault
because of newtons law?
main mural
both the sun and the earth experience the same force
main mural
because of newtons law?
yes
main mural
np
crude vault
or newtons law of gravitation right?
f= g m1m2/r^2 * r12
whats the difference with that equation
crude vault
?
main mural
what's r_12?
main mural
ah okay
crude vault
so what is r12
main mural
this law is not one of newtons three laws
but it just happens to be discovered by newton
main mural
so what is r12
huh? unit vector from object 1 to object 2
crude vault
or the star and the planet*
main mural
this law is the consequence of the third law
crude vault
i see so these are both occuring
crude vault
main mural
third law is the fact that these forces exist in the first place
gravitational law is saying what's their magnitude
hopefully this makes sense
crude vault
yes
so are the equations the same
that one and F = GM m / r^2
or is the one i provided more specific?
crude vault
hopefully this makes sense
?
crude vault
Note that the blue force arrow on Earth is the same size as the blue force arrow on the Sun. Why is this so? What law(s) is (are) being illustrated?
main mural
third law
crude vault
the blue force arrow is gravity
main mural
just that
main mural
apologies for confusing
crude vault
so no gravitation
crude vault
apologies for confusing
what would be one period of rotation around this setup? a year from my understanding?
main mural
what would be one period of rotation around this setup? a year from my understan...
yes
main mural
365.2425 days to be exact
sinful zodiac
Note that the blue force arrow on Earth is the same size as the blue force arrow...
NEWTON'S 3RD LAW IS BEING DISPLAYED: FOR EVERY FORCE, THERE IS AN EQUAL OPPOSITE REACTION FORCE.
THERE ARE DIFFERENT TYPES OF FORCES, AND NEWTONS 3RD LAW WORKS FOR ALL.
THE SPECIFIC FORCE HERE IS THE GRAVITATIONAL FORCE. (NEWTON'S LAW OF GRAVITATION)
crude vault
NEWTON'S 3RD LAW IS BEING DISPLAYED: FOR EVERY FORCE, THERE IS AN EQUAL OPPOSITE...
appreciate that aswell!
i got shanked
oh no
crude vault
365.2425 days to be exact
So why with an object half the size earth is that period the same?
sorry i rephrased that
nvm
.close
paper storm
What is the accumulated value of periodic deposits of $30 at the beginning of every month for 23 years if the interest rate is 4.96% compounded monthly?
Round to the nearest cent
safe radishBOT
What is the accumulated value of periodic deposits of $30 at the beginning of ev...
paper storm
<@&286206848099549185>
static igloo
Yes?
real mauve
!noadvert
safe radishBOT
Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, and no one person can be prioritized over other people, so please patiently wait. Anyone who chooses to help you is a volunteer who is doing so out of their own kindness.
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
granite flower
i am stuck in all of my questions
so at what step are you
paper storm
and my homework is due tonight
idk any of them
i just wanna know the steps
from the begining to the end
granite flower
so in that specific question you asked above at what step you are now in these steps
safe radishBOT
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2. I have begun but got stuck midway.
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5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
granite flower
do you know the formula of the interest rate
paper storm
sort of
granite flower
if you really know the interst rate fromula then you gotta know how to solve this question as it is just a quick substitution in it
safe radishBOT
@paper storm Has your question been resolved?
bright carbon
How do I prove this?
safe radishBOT
How do I prove this?
hazy elbow
multiply the RHS by (1-cos(x))/(1-cos(x))
uncut drum
in vectors, why is i x j = 0 when i x i = 1 and j x j = 1
safe radishBOT
in vectors, why is i x j = 0 when i x i = 1 and j x j = 1
safe radishBOT
@uncut drum Has your question been resolved?
uncut drum
<@&286206848099549185>
obsidian oracle
i and j are what we call orthogonal
their dot product between them is 0
I'm guessing you're in 2 dimensions
so $\vec{i} = \begin{pmatrix}1\0\end{pmatrix}$ and $\vec{j} = \begin{pmatrix}0\1\end{pmatrix}$
flat frigateBOT
rafilou2003
obsidian oracle
To find the dot product of 2 vectors, we multiply the coordinates between them, and then we sum them
$\vec{i} \cdot \vec{j} = 1\cdot 0 + 0\cdot 1 = 0$
flat frigateBOT
rafilou2003
obsidian oracle
Whereas $\vec{i} \cdot \vec{i} = 1\cdot 1 + 0\cdot 0 = 1$
and $\vec{j} \cdot \vec{j} = 0\cdot 0 + 1\cdot 1 = 1$
flat frigateBOT
rafilou2003
safe radishBOT
uncut drum
.close
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flat frigateBOT
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amber timber
I multiplied both sides with (x+4)
amber timber
**🐱!Yajat! 【Catfan1398】🐱**
Doing this i get the same result
frigid spruce
yea mb, your answer should be correct then
amber timber
c
frigid spruce
,w \frac{3x+1}{x+4}=(x-1)
flat frigateBOT
frigid spruce
this
amber timber
What about -sqrt(5)
Or oh then the ln would be undefined
That might have been what i said wrong
And on b) -48 is undefined
Ahh
Lets see
exotic nymph
How
exotic nymph
wait
just tell me if its ordered sampling with replacement or ordered sampling without replacement or unordered sampling without replacement.
south path
definitely without replacement
cause the question says so
can you figure out whether its ordered or unordered?
"two balls of the same colour" what does that mean?
safe radishBOT
@exotic nymph Has your question been resolved?
lean otter
The regulation soccer ball is made of leather or a similar material. Its perimeter measures between 68 cm and 70 cm (diameter between 21.65 cm and 22.29 cm), its mass varies from 410 g to 450 g, and its inflation pressure ranges from 1.6 to 2.1 atmospheres.
Although they are also called spherical, the most common soccer balls are shaped like truncated icosahedrons with regular pentagons and hexagons.
Find out how many pentagons and hexagons there are in a soccer ball. Likewise, it determines the number of vertices and edges.
safe radishBOT
The regulation soccer ball is made of leather or a similar material. Its perimet...
lean otter
Is there a mathematical way to resolve this? (formula)
lean otter
I have never heard about that
tame raft
where V is the number of vertices, F is the number of faces, E is the number of edges
wait no
ok that isn't perfect
i think maybe it just wants you to google it?
lean otter
Mm perhaps
do you also get these values: There are 20 hexagons and 12 pentagons. There are 60 vertices and 90 edges.
?
tame raft
i mean yeah that's gonna be correct
tranquil steppe
How do I evaluate this? I keep getting 49/2
safe radishBOT
How do I evaluate this? I keep getting 49/2
peak estuary
what is f(x)
tranquil steppe
9 I think
safe radishBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
tranquil steppe
I don’t really understand how integrals work
This is an example problem I’m trying to understand how they got 26
tranquil steppe
Why do we add them lol?
viral venture
Would you agree that from 0 to 7 is like going from 0 to 5, then from 5 to 7
Think of the number line
Walk to 7 or walk to 5 and then walk from 5 to 7
Isnt it the same
tranquil steppe
When you put it like that it makes sense
Huh it makes sense now I’m upset I couldn’t get that on my own thanks though
.close
remote dust
Can someone help?
safe radishBOT
@remote dust Has your question been resolved?
unreal kindle
hello, if |X|=5 and |Y|=3, then |XY|=15?
safe radishBOT
hello, if |X|=5 and |Y|=3, then |XY|=15?
unreal kindle
groups
lean otter
safe radishBOT
lean otter
median vigil
!status
safe radishBOT
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4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
multiply by cuberoot(4/4)
lean otter
multiply by cuberoot(4/4)
how is cube root 2 times by cuberoot 4 = 2
median vigil
2^3 = 8
median vigil
if a^3 = b
then cuberoot(b) = a
cube root is the inverse function of cube
lean otter
yh
lean otter
2^3 = 8
how does that explain that cube root 2 times by cuberoot 4 = 2
acc it makes sense now
cuz i can convert cube root into 1/3
and just add them
median vigil
$\sqrt[3]{2}\cdot\sqrt[3]{4}=\sqrt[3]{2\cdot4}=\sqrt[3]{8}=2$
flat frigateBOT
cloud
crisp mural
safe radishBOT
crisp mural
does this hold generally? If not generally then atleast for arithmetic and gemoetric sequences?
final halo
Does what hold generally? You've just written two expressions with an implication inbetween them
crisp mural
I mean to ask, for any sequence <an>
the sum of the terms of the sequence from a to b is the same as that from 0 to a subtracted from 0 to b, for b>a and b,a are natural numbers
does the above statement hold true for any sequence in general? If not then atleast for arithmetic and geometric progressions?
exotic nymph
does the above statement hold true for any sequence in general? If not then atle...
probably not
obsidian oracle
It's not true in general unless you write n=0 to n=a-1 on the second sum
crisp mural
i made a little error, the second limit should be n=a-1
crisp mural
It's not true in general unless you write n=0 to n=a-1 on the second sum
yes, i just realised that, thanks for pointing it out
crisp mural
probably not
it does hold for Geometric sequences
obsidian oracle
$a_0 + a_1 + ... + a_b = (a_0 + ... + a_{a-1}) + (a_a + ... + a_b)$
flat frigateBOT
rafilou2003
exotic nymph
i mean if n starts with a and goes to b and a is not 0 then n = 0 could be a unkown value, its what i think but imma go chow
obsidian oracle
**rafilou2003**
$\sum_{n=0}^ba_n = \sum_{n=0}^{a-1}a_n + \sum_{n=a}^ba_n$
flat frigateBOT
rafilou2003
south path
It does hold for all sequences. There's no concern about convergence or anything since this is just a finite sum. This is more or less true by definition!
crisp mural
**rafilou2003**
oh yea this works as well
thanks, I could prove it generally but I was having trouble trying to do a question using the similar way, now I know there's nothing wrong with the proposition
crisp mural
It does hold for all sequences. There's no concern about convergence or anything...
thanks :>
.close
lean otter
safe radishBOT
vast obsidian
would this be 4 and 7?
Do you mean everything, but 4 and 7? And are you sure that these are the roots of the denominator?
lean otter
yeah everything but 4 and 7
i set the bottom to equal to 0
then factored and got 4 and 7 because 4x7 = 28
and 4+7 = 11
from the 11x
vast obsidian
So you can factor it as (x+4)(x+7)
lean otter
yup got that part
vast obsidian
But that doesn't mean that x = 4 is a root
lean otter
great so theres more steps?
lean otter
i see
but how would i check it
because when i plugged into calc
it wasnt giving me 0
vast obsidian
Yeah, because 4 and 7 are obviously wrong
lean otter
I tried neg too
vast obsidian
,calc (-4)^2+11(-4)+28
flat frigateBOT
Result:
0
oh ok
safe radishBOT
vast obsidian
You're welcome
safe radishBOT
Available help channel!
broken elm
I'm stuck on this problem. I'm using the formula P-1 * A * P where P matrix is the matrix of the basis vectors and A is the transformation matrix. The software won't let me enter any fractions but I am getting a fractional answer
safe radishBOT
I'm stuck on this problem. I'm using the formula P-1 * A * P where P matrix is t...
lofty flower
safe radishBOT
lofty flower
Roughly translated it says to find the reason for each statement
devout shale
Which step is confusing you?
devout shale
This is how
lofty flower
Somebody answered
lofty flower
This is how
Ok
lofty flower
Which step is confusing you?
To be honest I’m not sure on what to do with this problem
devout shale
Yes but there are like 5/6 boxes to fill in, which step are you stuck on
lofty flower
I think all
devout shale
We can only do 1 step at a time
flat frigateBOT
Austin
devout shale
the problem is asking you to explain the step/reason that happens here
it is just asking you why it is valid to rewrite the top line as the bottom line
do you know why?
devout shale
yes
devout shale
now answer similarly for the other steps
lofty flower
I’m not sure of the last one
My teacher talked about this for like 20 minutes and never talked about it again
devout shale
$$6x=-12$$
$$x=-2$$
flat frigateBOT
Austin
devout shale
What happens in between these two lines
devout shale
yes
so that is the reason
you can divide both sides of the equation by the same value
safe radishBOT
@lofty flower Has your question been resolved?
safe radishBOT
@lofty flower Has your question been resolved?
split bear
how can i find the # of digits a number has with its prime factorization?
plucky elk
take the log base 10
safe radishBOT
@split bear Has your question been resolved?
plucky elk
split bear
well its not like a prime factorization
wait lemme take a look
it talks about its use in coding but if we had a string of numbers multiplied together, how would we find it
for example like 4^6 * 9^5 * 5^12
split bear
but how would u do that
split bear
yes but i dont have a calculator or any resources that i can use during the pop quiz
plucky elk
then just leave it in exact form and take the floor or ceiling
surely you're not supposed to memorize log_10 (p) for every prime p
safe radishBOT
safe radishBOT
Available help channel!
indigo tundra
safe radishBOT
indigo tundra
This would be outside the circle right?
Cuz the y cordinent of point z seems to be outside the circle radius
Idk
swift hare
do you know the radius of the circle?
swift hare
thats right
indigo tundra
9.43...
swift hare
now, whats the distance from z to the origin
swift hare
its the same thing you did for the circle
indigo tundra
But I got this stuff fr
indigo tundra
its the same thing you did for the circle
Oh
Uhh I got a negative number but it's like the absolute value right
It's less fr
So it's inside????
indigo tundra
Oh
I made a mistake
Uhhhhhhhh I got 59💀
7.68....
So it's inside right fr
Less than the radius
Frfr
swift hare
what is (-sqrt15)^2+(sqrt74)^2
indigo tundra
I did the negative root
swift hare
what?
indigo tundra
what is (-sqrt15)^2+(sqrt74)^2
59
plucky elk
$(-\sqrt{a})^2 = (-1)^2 \sqrt{a}^2 = a$
flat frigateBOT
riemann
swift hare
yeah
safe radishBOT
safe radishBOT
Available help channel!
lean otter
safe radishBOT
lean otter
how do i start this problem
ive been stuck on it for so long
please any help would be appreciated .....
rough storm
!status
safe radishBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I assume 1, but do you have any work you've written so far?
lean otter
yeah
i was following this video
on a similar problem
and first they got the rotation speed by doing 2pi over the minutes it takes for a full revolution in this case 31 minutes
then they multiplied that number by the diameter
so 2pi/31 * 125
that gives you the speed of the passenger i think
and i got 25.335 meters per minute
divide by 60 to get meters per second
i got .4225
meters per sec
and then they did sqrt(speed of passnger)^2 - (speed of passenger rising in the problem it says its 0.042)^2
and i did that
and its wrong
so idk
what to do
i could write down the process too if thats easier to understand
this problem is really some bs
i just
dont know where to start
ive never done a problem like this
safe radishBOT
@lean otter Has your question been resolved?
frigid dagger
heyo, trying to get the derivative of sin(x^2y^2)=x
i got an answer of y'=((xcos(x^2y^2))/2xy)-y, but the calculator is showin something completely different. i'm definitely isolating the y' incorrectly, but i'm not sure how to do it correctly
frigid dagger
i got to the (2*x^2*y*'diff(y,x,1)+2*x*y^2)*cos(x^2*y^2)=1 successfully by myself
but that's where i start messing up
i tried distributing it like this but it didn't really help
frigid dagger
i got to the `(2*x^2*y*'diff(y,x,1)+2*x*y^2)*cos(x^2*y^2)=1` successfully by mys...
$\left(2x^2yy'+2xy^2\right)\cos\left(x^2y^2\right)=1
obtuse plover
U can press the ✅ to see if ur answer is same as the one they got
On derivative calculator site
frigid dagger
they didn't match
flat frigateBOT
Stephen
frigid dagger
i erased most of it, let me try doing it one more time
obtuse plover
Know that u can’t distribute the argument of the cos function to the expression that precedes
It just becomes
2x^2 yy’* cos() + 2xy^2 * cos() = 1
frigid dagger
gotcha 👍
did it correctly now—the reason i kept getting it wrong was because i kept trying to isolate an added term by dividing
did it by subtracting like you're supposed to, now i finally got the correct answer
frigid dagger
did it correctly now—the reason i kept getting it wrong was because i kept tryin...
this pretty much
thanks stephen btw
obtuse plover
Np
frigid dagger
.close
tranquil rover
Can someone help me with this? I have no idea what it means and I'm not very good at exponents.
safe radishBOT
Can someone help me with this? I have no idea what it means and I'm not very goo...
halcyon carbon
Can you prime factorise 125
tranquil rover
yeah i think so
i know that 125/5 is 25 so 5 and 25, 1 and 5
sorry if what im saying doesn't make sense
i think the prime factor would be 5
icy lance
well, yeah but express 125 as a product of its prime factors
safe radishBOT
@tranquil rover Has your question been resolved?
lean otter
safe radishBOT
lean otter
im assuming the problem is somewhere between the conversion from the 20 min intervals to hours
but i cant quite figure out how im supposed to solve the right k value
if i use only the initial and t=20
i get k=ln2/20
wouldnt that be the per minute growth rate?
can i just mult that by 60?
making 3ln2?
<@&286206848099549185>
.close
safe radishBOT
safe radishBOT
Available help channel!
plush depot
hi, i'm not sure what this Q means
safe radishBOT
hi, i'm not sure what this Q means
torpid fable
At what time does it reach the maximum height? Plug that into the v(t) equation
Or if v(t) refers to only vertical velocity then you can intuitively think about what the speed should be
safe radishBOT
@plush depot Has your question been resolved?
lean otter
safe radishBOT
safe radishBOT
@lean otter Has your question been resolved?
rare dove
Hey can someone tell me what I did wrong with this set-builder notation problem? the set is : {19, 28, 37, 46, 55, 64, 73, 82, 91} I wrote {x ∈ Z : 0<= x <= 8 and 19 + 9x} got marked wrong twice for it
safe radishBOT
Hey can someone tell me what I did wrong with this set-builder notation problem?...
devout shale
19+9x | x in Z | 0<=x<=8
quasi bison
19+9x | x in Z | 0<=x<=8
second | wants to be replaced with a comma
devout shale
second | wants to be replaced with a comma
is that necessary?
devout shale
looks bad or is incorrect
rare dove
What's the correct form ?
devout shale
19+9x | x in Z | 0<=x<=8
I thought this was fine, @quasi bison could you clarify?
rare dove
ok thank you
I was confused by this example in my book : {x ∈ Z : 0<= x <= 20 and x is prime}
I thought that an equation would kind of replace the condition on the right side that x is prime
there are a lot of conflicting styles/conventions that I've seen in set-builder
.close
cunning lagoon
Need help don't really understand the question
safe radishBOT
Need help don't really understand the question
woven hull
try expanding it?
cunning lagoon
quasi bison
,rccw
flat frigateBOT
woven hull
you could try taking the derivative of (x+1)^3/(x-1)^2
and the resulting zeros of that equation is x=-1, 5 correspondingly
anything smaller than -1 goes on to -infinity so m can't be smaller than -1
we know that as x approaches infinity, so does teh equation
as x approaches 1, the equation also approaches infinity