#help-23
crimson idol
fallen elm
can someone teach me calculus
thin bridge
can still be simplified further
thin bridge
pi, not pie
also please write you pi better
crimson idol
is that pie over 3/6?
i wish
thin bridge
also, that's still just V
crimson idol
wdym
thin bridge
no differentiating has happened yet
crimson idol
is it h^2/4
thin bridge
yes (h/2) ^2 is h^2/4
safe radishBOT
@crimson idol Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
main rivet
A ball was thrown from a cliff and is accelerating downward at a rate of -0.08 m/s^2, had an initial velocity of -0.064 m/s, and was thrown from 3.5128 meters high. Find when the ball hits the ground
safe radishBOT
A ball was thrown from a cliff and is accelerating downward at a rate of -0.08 m...
main rivet
I have to solve this using 2 methods and 1 must be through quadratic formula
main rivet
Mate im not helperπ
heady torrent
aw
median vigil
!status
safe radishBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
do you know the equations of motion?
lean otter
<@&286206848099549185>
have you tried using kinematic equations to solve this
first convert this -0.08 m/s^2 to m/s
substitute into one of the kinematic equations and ggs
safe radishBOT
@main rivet Has your question been resolved?
main rivet
substitute into one of the kinematic equations and ggs
Ive never done kinematic bro
I just got given this equation
Got told to solve it using the quadratic formula and any other method
lean otter
._.
median vigil
can you post the equation you were given
lean otter
ok since we got the i-velocity, acceleration and distance
using which kinematic equation to suit this problem
safe radishBOT
this is due in like 1 hour
noble fern
<@&286206848099549185>
safe radishBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
quiet juniper
r u allowed to just invoke triangle congruence theorems?
Cus that's p much all you need for question 6 if so. It's like one line.
noble fern
Cus that's p much all you need for question 6 if so. It's like one line.
i... dont know
quiet juniper
well do you have a way to find out what you can use
otherwise we can't help even if we wanted to :p
noble fern
yes
ok
so basically
(let just focus on 7)
i can use any angle basic theorem
i can use any simple segment theorem
triangle congruence (SAS, SSS, ASA)
basic equality
and
oh yeah simple construction
(any point is on a line, midpoints exist, 2 points define a line)
noble fern
well do you have a way to find out what you can use
thats pretty much it
theres
like more
quiet juniper
damn
noble fern
midpoint congruence
VAT
Pons asinorum
like
really
really
confusing stuff
we have decat + concat for segments + angles
we can add segments
quiet juniper
What's decat and concat
noble fern
What's decat and concat
and the decat means you have one big angle and one small, and you know the other small is congruent
quiet juniper
Are you allowed to like, draw circles
quiet juniper
Rip
Cus if you were allowed to, you could start by drawing a line segment from P to an arbitrary point on the line. Then draw a circle centered around P of that radius. It will intersect the line at another point. Then the midpoint. Then the line segment connecting that midpoint and P would be your altitude
noble fern
right. if only
i think the most annyoing part sabout this
is that we told teach
"hey man, we dont get this"
noble fern
Cus if you were allowed to, you could start by drawing a line segment from P to ...
and he got pissed off, declared new homework and a "work day", said he would extend the due date until tongight at 11:59p.m, didnt give us an iota of help or hints and then started scrolling freaking reddit
quiet juniper
wow wtf
noble fern
and i dont even care that hes not helping us- thats not the point
i expect that from him
hes just so....
patronizing
"oh its easy once you figure it out"
"you jsut need to think about this a different way, and its easy"
quiet juniper
lol
noble fern
π
quiet juniper
I've resorted to googling cus I can't think of how to do this without making circles xd, but first video so far assumes use of a compass
noble fern
compass? what is that? maybe he renamed it weird or somethng
quiet juniper
compass is just a tool for drawing circles
noble fern
im literally a 9th grader this has to be mental harassment
quiet juniper
noble fern
compass is just a tool for drawing circles
darn
lean otter
you mean a protractor
noble fern
yuh
quiet juniper
It's called a compass too I think
quiet juniper
Then just a compass
Oh u mean him
yeah straightedge and compass constructions don't assume you can measure specific lengths
anyways do you have an answer for this 
noble fern
if only the man let me draw virvles
lean otter
...spare me
this looks like a job for pthag
noble fern
i have 40 minutes left please help
safe radishBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
this man was NOT feeling generous
noble fern
```
What step are you on?
1. I don't know where to begin.
2. I have begun but go...
1
:D
lean otter
ggs
noble fern
this class is ensuring that im never becoming a math major
i saw the horror stories, but now?
lean otter
as it is a theory we can say trig
noble fern
i see?
quiet juniper
R u talking about
noble fern
trig?
quiet juniper
6 or 7
noble fern
yeah..
quiet juniper
6 I think skye is good with?
noble fern
the congruency lines?
lean otter
they mean that they are the same length
quiet juniper
that's the ez q
noble fern
<:devastation:898725325335298088> that's the ez q
listen man help is help
lean otter
so they are the same length π
noble fern
so they are the same length π
thats literally the definition of congruent segments
lean otter
ik
quiet juniper
yeah once u do 7 we'll start worshipping u
noble fern
π
noble fern
call the helpers
what do you think ive been doing?
lean otter
wait we are the helpers hehe
noble fern
bro takes me for a fool
welp guess im a college dropout
cant even pass math class π
lean otter
you in hs?
noble fern
27m
noble fern
year 9 doing advanced 11 math?
welcome to my hellhole of borderline child abuse
pleasr
im pinging helpers again
<@&286206848099549185>
noble fern
...spare me
please
lean otter
protractor*
lean otter
then use a ruler to measure distance
quiet juniper
R u stupid
Do u know what straightedge and compass constructions are for one π€¦ββοΈ
Wait actually
@noble fern can u use a ruler 
noble fern
20 mins
noble fern
<@731279601774362684> can u use a ruler <:bleakkekw:913344117981999125>
no :)
i can make a line
though
like
create a point
and be like
"2 points define a line"
NINETEEN
omfg
nerjgnwort
<@&286206848099549185>
pPLEPLDPEWKLP
times to be a degenerate and spam my friends?!!!
HELP THEY ARENT ANSWERING
THERE GOES HARVARD
I WASNT GETTING INTO PRINCETON ANYWAY
ADHABDJSJKADHAK
quiet juniper
R u sure there isn't something ur missing
quiet juniper
Every link I've found uses a compass or a ruler
noble fern
ruler how
quiet juniper
Well the only thing u need to do is make an isosceles triangle ultimately
With P as the peak
quiet juniper
Will be the thing in the line
noble fern
Q?
quiet juniper
Q is the point on the line that exists
Such that PQ is an altitude
If you can pick two points on the line
noble fern
?
quiet juniper
The angle is a right angle cus SSS congruence
Segments around midpoint are equal cus that's what a midpoint does
quiet juniper
Lateral sides are equal by assumption of making an isosceles triangle
And PQ is a shared side
quiet juniper
I thought you said you could make an isosceles triangle
quiet juniper
Oh well you need an isosceles triangle for this to work 
quiet juniper
Nah cus 6 assumes that you know that angle is a right angle alreadg
noble fern
I HAVE 12 MINUTES
UGHEUASVGB'
this is not good for my mental health
we should be friends or something
because
i...
desperately need them
quiet juniper
rip lol
noble fern
fuck this im turning it in as-is
this man can suck a dick
actually that hits different after his allegations of being seen at a gay bar
which is weird because he has no wife or children
and his family is gone
his life is kinda....
quiet juniper
damn
quiet juniper
ye 
noble fern
now i feel bad for telling him to suck it
quiet juniper
Sounds like his family disowned him after finding out he was gay?
quiet juniper
lol
noble fern
Sounds like his family disowned him after finding out he was gay?
nah hes moved to make high schoolers miserable
because some deranged thought in his mind thought he should be a MATH MAJOR.
if i ever try to become a math major please slap some sense into me
quiet juniper
lean otter
hello
quiet juniper
hi
lean otter
sorry
I've just enter the discord server
i was wondering where i can make some questions math related
quiet juniper
!help
safe radishBOT
To ask for mathematics help on this server, please open your own help channel or help thread. See #βhow-to-get-help for instructions.
lean otter
thanks
noble fern
giving up with 7 minutes to spaere
well...
thats all folks
(am i allowed to say that? legally?)
lean otter
,w (0,-1, -9+x, 6) -1/4(0, -4, -14, 5)
flat frigateBOT
lean otter
the last operation
where you did Z3 -> Z3 - 1/4Z2
(-9 + x) - 1/4(-14) = ?
for you to get row 3 entry 3
can i see your working
lean otter
[0, 0, -4 + Ξ», 4.75]
im telling you, you did your row operations incorrectly
flat frigateBOT
lean otter
and show what you did for every entry
?
yh yh
so now going through each entry
Entry 1:
-1/4(0) + 0 = 0
Entry 2:
-1/4(-4) + -1 = 0
Entry 3:
-1/4(-14) + (-9+Ξ») = ?
-1/4(-14)=?
$$-\frac{1}{4} . -14$$
flat frigateBOT
lean otter
positive
in fraction
14/4
14/4 - 9 + Ξ» = ?
dude
check your work
π shld i keep walking you through arithmetic
3.5 - 9?
now look at what you did
,w 19/4
flat frigateBOT
lean otter
you're done after fixing that
do you see any errors
no for the error fixing or the question
yh go on then
safe radishBOT
If you are done with this channel, please mark your problem as solved by typing .close
lean otter
okay
split fulcrum
in a class of 40 students, 34 like bannanas, 22 like pineapples and 2 dislike both fruits. a student is selected at random. FInd the probability that the student likes
a) both fruits
B) at least one fruit
c) bananas given that he or she likes pineapples.
d) dislikes pineapple given that he or she likes bananas
safe radishBOT
in a class of 40 students, 34 like bannanas, 22 like pineapples and 2 dislike bo...
split fulcrum
how do I find the intersection thingy for my ven diagram
im getting 16 but thats not right
how 2 account for the 2 dislike both frutisds
quasi bison
$|B \cup P| = 40 - 2 = 38$
flat frigateBOT
AnnGhost
quasi bison
also btw your textbook is cringe for "he or she"
also part b is easier to do first from the data than part a
quasi bison
"they" is right there.
quasi bison
in fact if your reading comprehension isn't 0 you might notice i even solved part b for you.
split fulcrum
does AnB mean everything in a, b
split fulcrum
quasi bison
i'm not quite sure which
"everything in a, b" is very easy to misinterpret
do you want to try and correct yourself or do you want me to tell you the proper wording
split fulcrum
"All of thy objects which I trow to be in both thine sets A and B"
split fulcrum
LMAO
split fulcrum
quasi bison
i know this was 100% on purpose and specifically to annoy me because you like being mean to people.
or you like being mean to me specifically because it's funny when i'm upset.
idiot.
split fulcrum
relax
plucky elk
or you like being mean to me specifically because it's funny when i'm upset.
Just block and move on.
quasi bison
i know i won't resist the temptation to interact so there's no point.
split fulcrum
i was just tired of you always grilling me about my wording all the time
plucky elk
i was just tired of you always grilling me about my wording all the time
If you want help, but don't want people to understand what you're saying, then you're just making it harder for people to help you
quasi bison
on purpose, too.
split fulcrum
thats what youre assuming
i am not intentionally making statements that can be interperated as ambiguous
as someone who is not high level in mathematics something like that makes sense to me
plucky elk
Yes it was purposeful poor communication which is what Ann was emphasizing
dull sequoia
dull sequoia
yes but her point was that it's easy to misinterpret
it's ambiguous whether , means AND or OR
is it everything in A OR in B?
or did you mean both in A, AND in B at the same time?
quasi bison
yes but her point was that it's easy to misinterpret
don't you know? it doesnt matter what other people think
in fact it matters with a negative coefficient maybe
dull sequoia
saying fuck you, and telling people to fuck off and being an idiot after ridiculing their wording isn't the best way to communicate your ideas
split fulcrum
it's ambiguous whether , means AND or OR
well i wish someone said that earlier
dull sequoia
it just sounds very condescending to me, i wouldn't want to be talked to that way either
quasi bison
you're not harsh enough to me @dull sequoia
where is the cursing and the admonishment and calling me a bad person
cause i sure am one for doing this
and i apologize
but it is pointless and fruitless and my apology obviously doesn't count etc etc.
dull sequoia
literally no one said that
quasi bison
doesn't need to be said to be true
@split fulcrum sorry for lashing out at you earlier
split fulcrum
i appreciate that.
quasi bison
i don't know if you meant this, but if you didn't, there's no need to lie.
twilit kayak
@split fulcrum has your question been answered?
Okay, then please close the help channel with .close
split fulcrum
.close
lean otter
safe radishBOT
lean otter
<@&286206848099549185> help
upbeat bison
Stres
cinder geyser
$= 2 \int \frac{1}{t^{\frac{3}{2}} + \sqrt{t}}$
flat frigateBOT
SKELEROY
cinder geyser
then let $u = \sqrt{t}$
flat frigateBOT
SKELEROY
cinder geyser
thus you have $2 \int \frac{2u}{u^3 + u}$
flat frigateBOT
SKELEROY
cinder geyser
which then gives $4 \int \frac{1}{u^2 + 1}$
flat frigateBOT
SKELEROY
cinder geyser
which evaluates to $4 \arctan{(\sqrt{t})} + c$
flat frigateBOT
SKELEROY
lean otter
Thanks so much
cinder geyser
Allll good
lean otter
.close
cerulean agate
Quadtratics/Discriminant:
When finding the values of k for there to be real solutions, I do not understand what "There is only ONE phi" means. Why can k not equal 0? You can rearrange so k^2 = +/- 2 + 2. Would it not be possible that k= -2,2 when u use +2, and k=0 for -2. So the solutions can be k=-2,0,2?
safe radishBOT
Quadtratics/Discriminant:
When finding the values of k for there to be real solu...
median vigil
look back at the original function. if you put in k=0, you'd be dividing by 0
safe radishBOT
@cerulean agate Has your question been resolved?
cerulean agate
look back at the original function. if you put in k=0, you'd be dividing by 0
THANK YOU!
reef quartz
Can someone help me with question a and possibly b?
safe radishBOT
Can someone help me with question a and possibly b?
little mesa
part a looks ok?
and then you just sketch that for b
it's just a parabola with the x and y coordinates swapped, so it's horizontal instead of vertical
reef quartz
aight
reef quartz
and then you just sketch that for b
do you know how to show question b
little mesa
have you got the sketch?
little mesa
now can you draw in arg(z)=+-pi/4
reef quartz
now can you draw in arg(z)=+-pi/4
I don't know what that is
little mesa
the line with angle pi/4 from the x axis
i.e. gradient of tan(pi/4)=1
safe radishBOT
@reef quartz Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
timber basin
timber basin
How to solve this?
upbeat bay
WE can imagine x being very very small like 1^-9999999. Hence, on adding or subtracting x will result in 1, -1. When further multiplied by x, it will result in 0 as x tends to zero.
flat frigateBOT
flat frigateBOT
quiet juniper
they both seem to be approaching 0 tho don't they
Anyways it might be easier to see if you make the variable change $x = 1/y$. Then it's equivalent to finding and comparing the limits as y goes to infinity and negative infinity
flat frigateBOT
992qqoloy
flat frigateBOT
992qqoloy
quiet juniper
In other words it's a constant value
So when you rewrite you have to find the limits of $\frac{1}{y}(1 - \frac{1}{y})^{[y]}$ as y goes to infinity and negative infinity
And the 2nd term in the product now looks awfully familiar
While the first tends to 0 as y goes to infinity or negative infinity
flat frigateBOT
992qqoloy
quiet juniper
what do u think x should be
timber basin
What do you mean?
e^x if x is 0 then 1
x tends to 0+ then it will give + infinity
xtends to 0- then it will give -infinity
1/y will give us 0
And inside will be e^-inifity
e^-inifnity
quiet juniper
Sigh I'll just tell u
timber basin
But we have multiple 0 so it will give both same
flat frigateBOT
992qqoloy
quiet juniper
Tbh it doesn't matter much that it's that value tho, just that it tends to a constant
Cus 1/y will go to 0
So limit of 1/y times that is 0 (comming from the positive direction)
A similar thing happens comming from negative direction (as y goes to negative infinity)
timber basin
**992qqoloy**
Hmm
What about -infinity now?
I guess it give e^1
I am not understanding
π₯²
I guess the answer will be A
,w (-1)^infinity
,w -0.00001(-0.00001)^[1/-0.00001]
upbeat bay
,w (-1)^9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
flat frigateBOT
Requested by kavy_ondhia
little mesa
-1 π
timber basin
Guys can we do the question again from start?
If anyone has any short trick in mind
.close
lean otter
can somebody help me prove these two :3
safe radishBOT
can somebody help me prove these two :3
thick otter
What have you tried?
lean otter
!status
safe radishBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I don't know where to begin
thick otter
Do you know the definition of, say, $\mathcal{P}(E)$?
flat frigateBOT
wlmmm
lean otter
it's the power set of E
thick otter
Yes, and so here I would use the definition of equality of two sets
That is $A = B$ if (and only if) $A \subseteq B$ and $B \subseteq A$
flat frigateBOT
wlmmm
lean otter
yes and how can I prove that?
thick otter
So, for (a), you can first start with an element into $\mathcal{P}(E \cap F)$, and show that it also belongs into $\mathcal{P}(E) \cap \mathcal{P}(F)$.
flat frigateBOT
wlmmm
thick otter
You can denote $X$ an element from $\mathcal{P}(E \cap F)$ (remember that $X$ is a set).
flat frigateBOT
wlmmm
thick otter
And since we want $X$ to belong into an intersection of two sets, we need to show that $X \in \mathcal{P}(E)$ and $X \in \mathcal{P}(F)$.
flat frigateBOT
wlmmm
thick otter
Does this make sense?
lean otter
I get this so far but using power sets is confusing me
does it work the same as normal sets?
thick otter
What makes it confusing is that you have a set of sets... π (you see it?)
thick otter
does it work the same as normal sets?
What do you mean by this?
lean otter
if I say A β© B that means that there exist an x which belongs to A and also belongs to B. so when I say P(A β© B) what would that mean?
thick otter
Ok, so $\mathcal{P}(A \cap B)$ is the powerset of $A \cap B$. It is a set containing every subsets of $A \cap B$
flat frigateBOT
wlmmm
lean otter
I understand this
lean otter
**wlmmm**
how can I start proving this
oh should I say that X belongs to P(E) and X belongs to P(F)?
thick otter
That's what you need to prove π
You can start with an arbitrary element $X$ belonging into $\mathcal{P}(E \cap F)$. Recall that $X$ is a set. It is a subset of $E \cap F$, so it contains elements from $E \cap F$.
flat frigateBOT
wlmmm
thick otter
So do you agree that all elements of X belongs to E in particular?
If so, you are agreeing in other words that X belongs to P(E)
lean otter
uuuuhhh maybe yes? I'm lost
thick otter
Don't blame yourself, it's easy to get lost in these situations (again, since we have sets of sets)
But the answer is yes
If you are confused, maybe we can work with an explicit example if you don't mind
Often writing down simple and small examples help to find a path for a good reasoning
lean otter
okay let's go
flat frigateBOT
wlmmm
thick otter
We have $E \cap F = {1,2}$
flat frigateBOT
wlmmm
thick otter
So $\mathcal{P}(E \cap F) = {\emptyset, {1}, {2}, {1,2}}$.
flat frigateBOT
wlmmm
thick otter
Do you agree so far?
lean otter
yess
thick otter
Ok, so in our previous reasoning, we first start with an arbitrary element $X$ of $\mathcal{P}(E \cap F)$
flat frigateBOT
wlmmm
thick otter
Again to see what's really going on, let's take a particular example, say, X = {2}
And we need to show that X (so {2}) belongs to P(E) and P(F)
Does {2} belong to P(E)?
lean otter
yes it does
thick otter
Ok, why?
lean otter
because.. I can see that it does...
thick otter
Ok, but also because 2 belongs to E, right?
lean otter
yes
thick otter
so {2} is a possible subset of E
And {2} belongs to P(F) too right? because 2 belongs to F
lean otter
yes
thick otter
So the key here is no matter which elements X you take from P(E n F), all elements of X will belong to E, and also to F.
So X will belong to P(E) and X will belong to P(F)
Does this make more sense now?
lean otter
oh okay so any subset X from P(E β© F) is a subset of E β© F? which means it belongs to E and to F ?
thick otter
Any set X from P(EnF) is a subset of EnF
Which means that X is also a subset of E
Which means that X is also a subset of F
So X belongs to P(E), and X belongs to P(F)
So X belongs to P(E) n P(F)
And so you've shown that $\mathcal{P}(E \cap F) \subseteq \mathcal{P}(E) \cap \mathcal{P}(F)$
flat frigateBOT
wlmmm
thick otter
Does this make sense?
lean otter
okay I think I get it
thick otter
Super!
So, half of part (a) is tackled now
It remains to show that $\mathcal{P}(E) \cap \mathcal{P}(F) \subseteq \mathcal{P}(E \cap F)$
flat frigateBOT
wlmmm
lean otter
wait gimme a min
lean otter
okay so, for every x that belongs to P(E) and P(F) => X belongs to E and F
=> X belongs to Eβ©F
=> X belongs to P(Eβ©F )
@thick otter
thick otter
Try to be more precise when you write, for example use capital letter X, as X is a set (and not a variable for example)
You want to show that X belongs to P(E n F)
(for the converse, which I assume you are trying right now)
lean otter
oh yes! I forgot we are working with sets here
thick otter
Here it is very important to clearly distinguish
So starting with X that belongs to P(E) n P(F),
you can say that X is a subset of E and that X is a subset of F
That should be the beginning ^
lean otter
okay so X is an elements when talking about power sets but it is a set when we are talking about non power sets
thick otter
X is an element of a power set, but X is in fact a set too
lean otter
for every X that belongs to P(E) and P(F) => X is a subset of E and of F
=> X is a subset of Eβ©F
=> X belongs to P(Eβ©F )
is this more correct?
thick otter
Nailed it!
lean otter
okay so we are done proving (a)
thick otter
Yep π
lean otter
can u help me with (b) too :>
thick otter
sure!
lean otter
so, for every X that belongs to P(EβͺF) => X is a subset of EβͺF
=> X is a subset of E or X is a subset of F
=> X belongs to P(E) or X belongs to P(F)
=> X belongs to P(E)βͺP(F)
is this correct?
thick otter
X is a subset of EβͺF => X is a subset of E or X is a subset of F
Counterexample:
E = {1,3}
F = {2,4}
X = {1,2}
X is a subset of EuF = {1,2,3,4}
But X is not a subset of E, neither of F
lean otter
oop
thick otter
So this is a bit harder!
lean otter
I don't have the brains for this
lean otter
whaat
thick otter
Yes... !
Using the same counterexample above
E = {1,3}
F = {2,4}
If we choose X = {1,2} which belongs to P(EuF)
Then X is neither in P(E), and X is neither in P(F)
This is a counterexample
lean otter
are u saying my professor is lying to us
lean otter
Is that a homework?
yess
thick otter
Maybe you should email your professor to tell him/her about the mistake
Or you simply write: it is not true, here is a counterexample
lean otter
okay thankss for the help!
oh wait, it can also be a subset of both E and F together no?
so X is either a subset of E or F or both
or what im saying isnt correct?
thick otter
It isn't correct, if you take X = {1,2}
E = {1,3}
F = {2,4}
Then X is a subset of EuF
But X is neither a subset of E, of F, of EnF
lean otter
oop okay thanks
thick otter
you're welcome!
lean otter
.close
serene spoke
safe radishBOT
serene spoke
marginal pmfs need not add upto 1 right
lean otter
iit madras π
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timber basin
Right tan comes inside
Then take common
2tan(1-tan^2)-tan=0
tan(2-2tan^2-1)=0
Did you understand?
timber drum
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timber drum
any app to give me more practise questions related to this
icy lance
just google: Evaluating trig functions questions
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serene spoke
how is fxy(1,1) = 1/2
safe radishBOT
how is fxy(1,1) = 1/2
vague coral
I dont really follow how the first line was formed
safe radishBOT
I dont really follow how the first line was formed
vague coral
can someone explain it to me and also help me construct the matrix please
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vague coral
<@&286206848099549185>
vague coral
i just posted it
vague coral
go to linear algebra channel
but do u understand what's going on
it's talking about splines/interpolation
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crude vault
.close
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frigid spruce
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frigid spruce
how is the angle in red equal to the angle in green circle
ping when reply please
.lose
.close
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uneven vessel
why is a_0=46 and a_1=20? how was this solved? ;-;
safe radishBOT
why is a_0=46 and a_1=20? how was this solved? ;-;
uneven vessel
k is 3 and n is 10
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obsidian oracle
for t = 0
the only numbers i between 0 and 10 such that i mod 8 = 0 are 0 and 8
so $a_t = \binom{10}{0} + \binom{10}{8} = 1 + \frac{10\cdot 9}{2} = 46$
flat frigateBOT
rafilou2003
obsidian oracle
See if you can complete this next one :
For t = 1, the only numbers i between 0 and 10 such that i mod 8 = 1 are ...
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uneven vessel
For t = 1, the only numbers i between 0 and 10 such that i mod 8 = 1 are ...
9
tysm omg ππ
I finally understood, I was trying to find out how that worked the whole night
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hallow anchor
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hallow anchor
how would I find the determinant
(I think that's what it's called)
quasi bison
yeah that does look like a determinant
what methods do you know of for finding those?
hallow anchor
I know how to find one for a 2d and 3d matrix, but not for 4 or more
quasi bison
I know how to find one for a 2d and 3d matrix, but not for 4 or more
have you been taught stuff like row reduction / gaussian elimination
that sort of stuff
and laplace expansion maybe
hallow anchor
I don't remember learning something like that
which one of those should I try using here?
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lavish osprey
Yes
You are trying to find future value
The trickiest part is that you're given an APR but it compounds semiannually
lavish osprey
what is r? and what is n?
wind abyss
r would be 0.0625?
lavish osprey
yes, and what about n?
wind abyss
the semiannual part right
lavish osprey
Yes
lavish osprey
n is the number of compounding periods per year
so how many times does it compound in 1 year?
wind abyss
2
lavish osprey
yes so in part A, t = 4
now you have everything in the equation, just plug in the numbers
wind abyss
Perfect thnxs
lavish osprey
np
lavish osprey
Show me your steps :3
wind abyss
I started to plug with my calculator after the equation was made
it loading
i did the divison then add 1
square it by 8
and multiply 7000
maybe i think i have to put 7000 where A is?
wind abyss
for th edivision
i get the 0.03125
then i add 1
equal to 1.03125
then the exponent of 8 make it
1.279121187
then i multiply 7000
and got 8953.848309
lavish osprey
Yeah they want to the nearest cent
lavish osprey
do you know what a cent is?
coarse trail
can someone walk me thru this pls
safe radishBOT
can someone walk me thru this pls
uncut juniper
have u calculated the volume of the through
coarse trail
i have not
uncut juniper
do so
coarse trail
is the formula v=1/3 * s^2 * h
uncut juniper
yes
uncut juniper
yes
coarse trail
okay
uncut juniper
now we know the shape can contain 12 m of space
how long would it take to fill up this space if the through happened to be empty?
coarse trail
4 min?
uncut juniper
yes
but since the trough already contains water, itβs prob logical to assume that itβs gonna take less time to fill it up
uncut juniper
oh
iβ kinda half asleep
i didnβt read the question
youβre prob gonn have to derive something
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fickle trail
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fallow cairn
this looks good to me
fickle trail
area enclosed = (integral of higher function) - (integral of lower function)?
ty
.close
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devout peak
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little mesa
$\frac{5t^3\pi}4=\frac{15t^3\pi}{12}$
flat frigateBOT
chlamydia
little mesa
lol
lean otter
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lean otter
Help please π
lavish osprey
Which question do you need help with?
lean otter
10*
lavish osprey
Ok so firstly one of the sides is in a fraction, is there a way to get rid of the fraction?
fathom hull
Is that good
yes, the right side can be simplified to x+2
then distribute the 6 on the left side to get 18x+24
then add like terms
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fickle trail
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fickle trail
do you have to keep negative sign inside the integrand? or could it be written this way to get same result with Partial Fraction Decomposition?
notice: the example above is (-4x + 5)/[x(x+1)]
final halo
you can keep the minus outside the integral yeah
final halo
Good luck
fickle trail
fickle trail
you can keep the minus outside the integral yeah
I got a different answer tho
because -4 + 5 = 1
instead of -4(-1) + 5 = 9
final halo
it's -( 4x +5) not - 4x +5
fickle trail
ooo
fickle trail
it's -( 4x +5) not - 4x +5
so this is wrong
but if x is -1
wouldn't it still be -(4(-1) + 5) = -(-4+5) = -(1) = -1?
somehow they got -9
final halo
yes bc you're still doing +5
final halo
Yes because if you bring the minis inside the integral you're now doing PFD on the fraction with numerator -(4x +5) = -4x+5
ugh
-4x-5*
on mobile sorry
final halo
the way you originally did it would have been -4(-1) + 5
what you just did is correct
fickle trail
but that's through keeping the minus sign in the integrand
i must do that for PFD?
final halo
no
final halo
again bc what you just sent is wrong
fickle trail
which part?
final halo
the numerator
fickle trail
this?
final halo
TThats not what you just sent
if you bring the minus in the numerator is -(4x +5) = - 4x-5
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crude star
for this question, I was told that for the inductive step that I should use the recursive formula given in the question and plug in mu I.H and work backwards to get 5k
safe radishBOT
for this question, I was told that for the inductive step that I should use the ...
crude star
but I dont understand why we are trying to get 5k
obsidian oracle
but I dont understand why we are trying to get 5k
if k is a power of 5, what is the next power of 5?
is it k+1?
crude star
uh idk
crude star
1, 5, 25, 125
crude star
5^(x + 1)
obsidian oracle
so you would compute 5^4 on its own?
you wouldn't use the previous powers to help?
obsidian oracle
no
crude star
5^a * 5^b ?
crude star
5^x * 5
obsidian oracle
yes
So if I gave you a power of 5, say 5^x, and I asked you to give me the next power of 5, how would you do it?
crude star
5^(x + 1)
obsidian oracle
which is...
crude star
5^x * 5
obsidian oracle
exactly
crude star
wait one more question
crude star
for this question, I was told that for the inductive step that I should use the ...
so for this question
my base case is incorrect?
obsidian oracle
wait
crude star
for base case I need to show its a multiple of 5 and then the inductive step 5^(k + 1)?
obsidian oracle
the first thing you did wrong was write T(k) instead of T(n)
crude star
in the inductive step?
obsidian oracle
in everything