#help-23

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silent gulch
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Helpers

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?

vapid folio
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yeah sure

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its been 8 mins

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ig you could

silent gulch
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<@&286206848099549185>

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.close

safe radishBOT
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zinc moat
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can someone explain to me how to do this im really bad at graphs

lean otter
zinc moat
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a point where its not on the graph or a hole on the graph

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i just cant get c i tried DNE -9, and 7

chilly lance
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c is dne lol

zinc moat
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let me try it again

chilly lance
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Oh

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Read the directions LOL

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"none"

zinc moat
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oop

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not gonna lie didn't see that XD

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thank you

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steep plover
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A state Senate has 230 Senators. On Wednesday several senators were absent due to the business trips. On thursday at the number of Senators asked to illness was five more than the number of absent ones on Wednesday. On Friday three Senators who are ill and absent on Thursday returned. 188 senators were present on Friday. How many senators were absent on Wednesday?

safe radishBOT
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@steep plover Has your question been resolved?

safe radishBOT
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@steep plover Has your question been resolved?

safe radishBOT
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@steep plover Has your question been resolved?

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dull cliff
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Discrete Math 7b and 7d

safe radishBOT
dull cliff
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quick question: can i just say that for b, "for all comedians they are funny" and for d "there exists a comedian and they are funny

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or would i have to write "for all people, they are comedians and they are funny"?

safe radishBOT
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@dull cliff Has your question been resolved?

dull cliff
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.close

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stone tendon
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The goal is to rotate (1,4) by 50 degrees, and I started but I'm not sure if this is the right path/what to do next

stone tendon
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how do i share it without it being a donwload

lean otter
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use a regular image format

stone tendon
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basically stuck because i feel like im in a loop if i multiply yk

lean otter
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Do you have to use linear algebra?

stone tendon
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yes

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i think i figured it out tho

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dont i just multjply it by 1,4 in a matrix representation

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and then just add the values to get a 2x1 matrix

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and thats my x and y

lost patrol
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Why are you using a 2x2 matrix to write the coordinates pandaHmm

stone tendon
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idk thats how my my teacher showed me

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no wait thats a lie

lost patrol
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Isn't rotation like

I don't think it make a difference anyway

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Makes

stone tendon
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the correct line is the bottom one

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the left one is the rotation matrix, and the right one would be (1,4)

lost patrol
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But well

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It does.

stone tendon
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wdym

lost patrol
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You'd get a 2x2 matrix again

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Well.

stone tendon
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thats why im confused

lost patrol
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$\begin{bmatrix}x'\ y'\end{bmatrix}=\begin{bmatrix}\cos \theta & -\sin \theta \ \sin \theta & \cos \theta\end{bmatrix}\begin{bmatrix}x\ y\end{bmatrix}$

flat frigateBOT
stone tendon
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yes

lost patrol
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This is the format you gonna be using for rotations.

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So well

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X' and y' are the rotated coordinates

stone tendon
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ohhhhh

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i see now

lost patrol
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You just put in values on the rhs

stone tendon
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yes ye asyes

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than kyou

lost patrol
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Also check your matrix multiplication it seems faulty

stone tendon
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sounds about right

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.close

safe radishBOT
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agile stream
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me no undertsand on how to approach or do this wizardry

quiet plume
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Well you have a polynomial and the table gives you three roots of the polynomial

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So you can write it as a*x(x+2)(x-1)

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Where a is some value

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Then you can plug in a non zero value from the table to find a

worthy hemlock
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You can do that way, but the slightly easier way, is that it's multiple choice, just plug in one or the of the x values, like -3 and 2, into each choice, and see which equation gives the proper y value

worthy hemlock
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The table

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If you plug in -3 and get -24, from one of those equations, you found the choice

agile stream
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ohh kk

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.close

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worthy hemlock
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Btw if you find multiple choices that results in -24 when you plug in -3, plug in a different x value

safe radishBOT
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zinc moat
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im not sure which one is wrong

safe radishBOT
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@zinc moat Has your question been resolved?

zinc moat
#

.close

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dusty bramble
safe radishBOT
dusty bramble
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need help on where to start and finish

dull sequoia
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do you know what b is?

dusty bramble
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i don’t

dull sequoia
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do you know what this P (X < x) notation means?

dusty bramble
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is it 0.9634

dull sequoia
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im asking about the notation

dusty bramble
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it means the probability right

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b is 0.9634

dull sequoia
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probability of what

dusty bramble
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that a variable falls between 0.9634?

dull sequoia
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forget the 0.9634

dusty bramble
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😭

dull sequoia
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if you want to answer the question you need to understand what it's asking

dusty bramble
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it just means that a variable falls between b and -b

dull sequoia
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it's the probability your RV falls between those values

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yes

dusty bramble
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right so in this case would it be the 0.9634

dull sequoia
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or more formally we can define it as $P(X<x)=\int_{-\infty}^xf_X(t), dt$

flat frigateBOT
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Frosst

dusty bramble
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right

dull sequoia
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so for the question

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they are scuffed because they used small x to represent an RV

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which is not convention

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we normally like to use capital letters for random variables

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it'd be nicer if they wrote P(-b < X < b) = bla bla bla

dusty bramble
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right cuz i’m confused

dull sequoia
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they used b for small x

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and small x for big x

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so they've done

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$P(x<b)=\int_{-\infty}^bf_x(t), dt$

dusty bramble
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i see i see

flat frigateBOT
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Frosst

dull sequoia
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which is scuffed because by convention we like capital letters

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but whatever that is their choice

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so for the question $P(-b<x<b)$

flat frigateBOT
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Frosst

dull sequoia
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we have $P(-b<x<b)=\int_{-b}^bf_x(t), dt$

flat frigateBOT
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Frosst

dull sequoia
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we know what f_x(t) is

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$x \sim N(0, 1)$ meaning that $f_x(t)=\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}t^2}$

flat frigateBOT
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Frosst

dusty bramble
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wtfff😭

dull sequoia
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have you not seen this before

dusty bramble
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not what i expected

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a little bit

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it’s my first couple days working on these types of problems

dull sequoia
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tell me what you dont understand

dusty bramble
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on my own

dull sequoia
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that's ok

dusty bramble
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i understand but i don’t get where the (0,1) is from

dull sequoia
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ah

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have you seen $X \sim N(\mu, \sigma^2)$

flat frigateBOT
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Frosst

dusty bramble
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yes

dull sequoia
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what does it mean

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can you tell me?

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(it's fine to say no)

dusty bramble
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i think i can

dull sequoia
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ok go ahead

dusty bramble
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doesn’t it mean distribution

dull sequoia
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it does! it means X has a distribution

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what distribution?

dusty bramble
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hmmm

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i’m not too sure

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just normal distribution?

dull sequoia
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yes, N stands for normal distribution

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what about the µ and σ²?

dusty bramble
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mean and variance

dull sequoia
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of X

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right

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ok

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great

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let's look at the question

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it is a NORMAL distribution

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with MEAN 0 and STANDARD DEVIATION of 1

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and we know that std dev = √var

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so std dev of 1 means var = 1

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so then X ~ N(0, 1)

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i've just plugged in the values given in the question

dusty bramble
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ohhhh i see

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😭makes sense

dull sequoia
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it all makes sense you just have to go step by step and understand what oyu're looking at

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going back to this then

dusty bramble
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that’s true

dull sequoia
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do you understand the second part?

dusty bramble
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yes

dull sequoia
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that's just the pdf but i've plugged in the parameters of mean = 0 and var = 1

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ok so then our problem is now this

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$P(-b<x<b)=\int_{-b}^bf_x(t), dt = \int_{-b}^b\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}t^2}, dt$

flat frigateBOT
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Frosst

dull sequoia
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agree?

dusty bramble
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yes

dull sequoia
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ok good news and bad news

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bad news is

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we cant solve this analytically

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it has no closed form

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😦

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good news, we have z tables!

dusty bramble
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i see i see

dull sequoia
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ok but first we want to recognise something as well

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do you notice anything interesting about f_x(t)

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something that's useful for evaluating integrals going from -b to b

dusty bramble
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i don’t think so

dull sequoia
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Hmm do you know about odd and even functions?

dusty bramble
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i might think so

dull sequoia
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if i asked you

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Evaluate $\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\sin(x), dx$

flat frigateBOT
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Frosst

dull sequoia
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how would you do this?

dusty bramble
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that’s where i’m stuck

dull sequoia
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,w graph sinx from -pi/2 to pi/2

dull sequoia
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anything cool about this integral?

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(if not that's fine)

dusty bramble
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probably cuz the negative and positive

dull sequoia
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yeah

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so we can notice that sin(-x) = -sin(x)

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yeah?

dusty bramble
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yes

dull sequoia
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and odd functions have a very good property for integration

dusty bramble
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yes

dull sequoia
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if $f(-x) = -f(x)$ then $\int_{-a}^af(x), dx = \int_{-a}^0f(x), dx + \int_0^af(x), dx=-\int_{0}^{a}f(x), dx + \int_0^af(x), dx= 0$

flat frigateBOT
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Frosst

dull sequoia
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hmm that's a bit wack

dusty bramble
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i think i got one answer

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0.4817?

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not sure if that’s correct

dull sequoia
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anyhow the point is that f(t) that you have is an even function

dull sequoia
dusty bramble
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right okay i had this written down from earlier when i tried

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but anyways i think i understand what you saying

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we’re

dull sequoia
dusty bramble
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were

dull sequoia
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$\int_{-\infty}^a f_x(t), dt$

flat frigateBOT
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Frosst

dull sequoia
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this is what's on the z tables

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so we need to transform $\int_{-b}^b\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}t^2}, dt$ into that

flat frigateBOT
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Frosst

dull sequoia
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first thing is that this is an even function

dusty bramble
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yes?

dull sequoia
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$\int_{-b}^b\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}t^2}, dt=2\int_0^b\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}t^2}, dt$

flat frigateBOT
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Frosst

dull sequoia
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and then we observe that the integral from -inf to inf is 1

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and it's symmetric about x = 0

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which means the integral from -inf to 0 is 0.5

dusty bramble
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i see i see

dull sequoia
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then we can simply write it as $\int_{-\infty}^{-b}f_x(t), dt + \int_{-b}^0f_x(t), dt = 0.5$

flat frigateBOT
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Frosst

dull sequoia
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then by simply rearranging the integrals we have

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$\int_0^bf_x(t), dt = \int_{-b}^0f_x(t), dt = 0.5- \int_{-\infty}^{-b}f_x(t), dt$

flat frigateBOT
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Frosst

dusty bramble
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that makes sense

dull sequoia
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if we just multiply this by 2 we can get the left hand side we want

dull sequoia
dull sequoia
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so the answer is simply $2\left(0.5- \int_{-\infty}^{-b}f_x(t), dt\right)$

flat frigateBOT
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Frosst

dull sequoia
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as in this is equal to 0.9634

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then just rearrange to get the integral by itself

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then look at the z-table

dusty bramble
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hmmmm

dull sequoia
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let me draw you something

dusty bramble
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would it be 1.94

dull sequoia
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this is what we're looking at

dull sequoia
dusty bramble
dull sequoia
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that's good

dusty bramble
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i don’t think i got the right answer

dull sequoia
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,w P(X<k)=0.0183

flat frigateBOT
dull sequoia
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,w P(Z<k)=0.0183

dull sequoia
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did you do 1 tail

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,w P(Z<k)=0.0366

dull sequoia
dusty bramble
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😭i don’t know at this point i’ll probably get back to this tomorrow but i appreciate ur help and i’m screenshotting what you sent for help

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.close

safe radishBOT
#
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coarse heron
#

hey is any one on?

safe radishBOT
coarse heron
#

I needed help with a question in discrete math

pine pine
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how discrete

coarse heron
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I have this question, is it possible to prove this statement true or false formaly?

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Like with some actual supposition etc to prove that this is true

stoic dune
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People normally define "prime" as "not composite", no?

coarse heron
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yeah

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actually

stoic dune
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Or the other way around maybe

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Do you have a definition for both words?

coarse heron
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prime and composite are the opposite in a sense

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sure

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prime is number x whose multiple are either itself or 1

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that means a number x that can only be divided by x or 1

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composite number y is a number which has more more than one multiples z, p such that z * p = y

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informaly 14 would be composite

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15 would be compsite as well

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since u can do 3 * 5

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but 3 is prime

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5 is also prime

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because there is not any two integers that can be multiplied to produce 5

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other than 1 and 5 itself

untold inlet
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I mean really 1 is the only integer that would be considered not a prime nor composite, so the statement is incorrect (also depends on your institutions definitions)

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@coarse heron

coarse heron
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Oh I see okay i was thinking about the same thing

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but like is it possible to prove it tho?

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the question in my homework is just true/false question but i wanna know if it'd be possible to prove it

untold inlet
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I mean you can prove it via contradiction

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assume there exists some integer n which is both a prime and a composite => state the definitions of prime and composite numbers => a number must either be a composite number or prime number => contradiction

coarse heron
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here u said either

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would it be 'and' ?

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like assume there is a integer n such that n > 1 which is neither composite nor prime

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then state definitonns

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even with definition how would we prove it

untold inlet
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why would it be and?

coarse heron
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sry mb ur right

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but

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still how would we prove it using defs

untold inlet
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in order for a number to be prime it must have only exactly 2 divisors (itself and 1), in order for a number to composite then it must have more than 2 divisors, so you can't have a number that has exactly 2 divisiors but also more than 2 divisors it doesnt make sense

coarse heron
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compsite number would be 15 for example

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3 * 5

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5 * 3

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yeah

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I see,

untold inlet
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well, yea 15 has 4 total factors

coarse heron
untold inlet
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pre much, you can formalise it a bit more but thats essentially the definition

coarse heron
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I see, lol idk why but I can understand it informally/intuitively but not like formally etc

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idk how

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thnx for explaining tho

untold inlet
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Writing formal proofs comes with experience, its completely normal. All I can say is practice and you'll get the hang of it

coarse heron
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I see, but understanding wise is that how usually students feel or something wrong w me lol

untold inlet
#

Nothing is wrong with you, its very common to have difficulty translating your thoughts into coherent proofs

coarse heron
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I see, but like what is is it that initially makes it hard to translate it into coherent proofs, from ur xp

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xp/understanding

untold inlet
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lack of experience, school's not teaching correct notation.

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also high school's based on doing not understanding so theres that

coarse heron
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I see, is it that most us atleast initially don't have clear deep understanding through definitions

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like we know how 1 + 1 = 2

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cuz 1 apple + 1 apple = 2 apples

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but we're not quite taught the 'why' of it

untold inlet
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yea precisely, but like i said the more you do the better you become, math is just practice practice practice

coarse heron
#

I see, thanks for some insight tho :]

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appreciate it

safe radishBOT
#

@coarse heron Has your question been resolved?

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final rain
#

is this right

safe radishBOT
final rain
#

.close

safe radishBOT
#
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quartz ridge
safe radishBOT
quartz ridge
#

help

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pleas

#

e

dapper venture
#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
quartz ridge
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idk where to begin

dapper venture
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let's write everything in equations first

dapper venture
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the question told you the length of fences

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and the pen is rectangular

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also we want area

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Try to put these into equations

quartz ridge
dapper venture
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yea

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you can set the length of fence on opposite side of house wall be x

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the other two sides be y

quartz ridge
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ok

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then

quartz ridge
dapper venture
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we know the fence is 60m long

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form a equation of the sides of the fenc

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e

quartz ridge
dapper venture
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we want to maximize area

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so what's area in terms of x and y

quartz ridge
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area

dapper venture
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hmm

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have you learnt differentiation

quartz ridge
dapper venture
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yes

quartz ridge
dapper venture
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yes

quartz ridge
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ok so now what

dapper venture
quartz ridge
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ohj

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no

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whats that

dapper venture
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a part of calculus

quartz ridge
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😭

dapper venture
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ok

quartz ridge
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do i needa know that to solve this

dapper venture
#

we have a simpler way

quartz ridge
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ok

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what is it

dapper venture
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first write the area in terms of

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x

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only

quartz ridge
dapper venture
#

we know x+2y=60

#

and Area = xy

quartz ridge
#

so x = 2y - 60

#

o wait

#

onb

#

x = -2y + 60

dapper venture
#

good

#

so what's the area

quartz ridge
#

(-2y + 60) y = a

#

-2y^2 + 60 y = a

dapper venture
#

we want to maximize area

#

so try to maximize y(60-2y)

quartz ridge
#

what does maximize mean

dapper venture
#

find the highest possible value of y(60-2y)

#

maybe you are more familiar with the vertex

quartz ridge
#

ya

#

i am familar

dapper venture
#

find the y value of the vertex

quartz ridge
dapper venture
#

you have a quadratic equation area = y(60-2y)

#

if we change the notation a bit it's equivalent to y=x(60-2x)

quartz ridge
#

tho

dapper venture
#

Area = y(60-2y)

#

I just changed area to y and y to x

#

so it looks more standard

quartz ridge
#

ohhhh

#

ok

#

mb mb

quartz ridge
dapper venture
#

no

#

we're not looking for roots

#

but vertex

#

how familiar are you with quadratics

quartz ridge
#

ya

quartz ridge
dapper venture
#

then it shouldn't be hard to find the vertex

quartz ridge
dapper venture
#

you can either turn the quadratic into vertex form

#

or use the roots to find the vertex

#

or just memorize the vertex formula

quartz ridge
#

vertex formula is y= a(x-h) + k

#

right

dapper venture
#

clos

#

e

#

y= a(x-h)^2 + k

quartz ridge
#

o ya

#

how do we put it in

#

vertex form

dapper venture
#

complete the square

quartz ridge
#

is that the fastest way to do it

dapper venture
#

no

quartz ridge
#

or is the roots faster

dapper venture
#

let's use the roots

quartz ridge
#

ok

#

so you set a to 0

#

?

dapper venture
#

yes first find the roots

#

since parabola are symmetric, the x value of vertex would be the mid point of the roots

quartz ridge
#

(0,0) right

dapper venture
#

what's the other root

quartz ridge
#

wait

#

o ya

#

ok

#

(30,0)

#

?

quartz ridge
dapper venture
#

that's the x value of vertex

quartz ridge
#

ya

dapper venture
#

we want the y value

quartz ridge
#

and u just plug back in

dapper venture
#

yea

#

15 would be the length of shorter side of fence

quartz ridge
dapper venture
#

remember how we got our quadratic?

#

we wrote area in terms of length of shorter side of fence

quartz ridge
#

o ya

#

wait

#

so the area i got is 450

dapper venture
#

correct

quartz ridge
#

so then y * 15 = 450

#

and then just solve

#

ok

#

thank u

#

fr

dapper venture
#

no problem

quartz ridge
#

oh wait the answer is 450 cus its asking for area

dapper venture
#

we want the maximum area so the answer is just 450

#

ya

quartz ridge
#

alr bet

#

ty

#

sm

#

u the goat

#

.close

safe radishBOT
#
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mellow mountain
#

need help on 10

safe radishBOT
mellow mountain
#

10th grade math

thin bridge
#

did you do Q9?

mellow mountain
#

i know that the y=mx+b equation comes to y = 5x -6, so the perpendicular slope is -1/5. plugging -4 = -1/5(-10) + b, b comes to -6

mellow mountain
#

yes i nkow i do it the same way

#

its the numbers that trip me up

thin bridge
#

there's a more efficient formula that gives you the distance directly

mellow mountain
mellow mountain
thin bridge
#

it may have been taught to you if given this type of question

mellow mountain
#

i might not be remembering it atm

thin bridge
#

look up perpendicular distance from point to a line

mellow mountain
thin bridge
#

ok.

mellow mountain
#

unfortunately i have to do the long way round

thin bridge
#

take a pic of your work
its a bit hard to read it like this

mellow mountain
#

neever mind

#

i ended up solving

#

.close

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sonic night
#

help

safe radishBOT
sonic night
#

Can anyone help me find the global minmimum of

#

i found the global maximum

#

but cant seem to show the global minimum

dapper venture
#

what's the minimum value you can get from a square root

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@sonic night Has your question been resolved?

sonic night
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humble maple
#

I need help with how to find the 2 blanks

humble maple
#

i have gotten this previously but it e=was incorrect for both

little mesa
#

can you show your working

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#

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humble maple
#

figured it out, thanks though

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viscid tartan
safe radishBOT
viscid tartan
#

\rotate

#

Stuck on how to show a= -b part , I've shown that a=b

peak estuary
#

well then you have made a mistake

#

!show

safe radishBOT
#

Show your work, and if possible, explain where you are stuck.

viscid tartan
#

Ok

#

One sec

#

I did the case where b < 0 , to get the result but don't think I can do that since both a and b are just integers

peak estuary
#

y=1 and x=1 is not the only solution to a+b=ax+by

#

for example a=2, b=3 then you also have 5=4*2-3

#

instead, try pluggin (1) into (2)

viscid tartan
#

Hmm I see alright thanks will try

#

I get a= a(xy) , showing that a is a factor of itself

#

Ig comparing it to (2) it shows a =b xy= y , but not sure where to go

peak estuary
#

a=axy implies xy=1

#

i.e. x and y are integers which multiply to 1

#

which options are there for what x and y can be

viscid tartan
#

Ayyy I see , didn't catch that , then we have 1,1 and -1,-1 for y

#

Then subbing in we get the answer , thanks for making me go through the steps

Thanks

peak estuary
#

you're welcome

safe radishBOT
#

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winter kernel
#

Not able to solve factorization question

winter kernel
#

Just give me some hints, and I'm sorry for making you solve this

#

also post answer in spoilers I'll check after an hour

quasi bison
#

$5t^2 + 6t - 8$

factorize this

flat frigateBOT
quasi bison
winter kernel
winter kernel
rare plinth
#

hoi

#

need help

safe radishBOT
winter kernel
#

$5\left(3x+y\right)^2+6\left(3x+y\right)-8$

factorize this

flat frigateBOT
winter kernel
#

the bot gave up on me

quasi bison
#

well i mean i gave you a suggestion for how to start

#

wdym the bot gave up on you

winter kernel
#

I tried factorizing via bot lol

quasi bison
#

that's not what that command did

#

that command just wrote it in LaTeX

winter kernel
#

ohh ok

#

That was dum sry

little mesa
#

do it yourself kek

quasi bison
winter kernel
#

that was just simple split the term tho?

#

the question I asked was wayy harder

real iris
#

You can sub in t as 3x+y

winter kernel
#

hmm

quasi bison
winter kernel
#

oh.. k

#

ohhhhh ok got it

#

It was easy 😄

#

Thanks

#

.close

safe radishBOT
#
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lean otter
safe radishBOT
lean otter
#

I do not understand this intuitively

#

I sort of get why number of 5s = numbers of 10s

#

So if I understand correctly

#

if we take 100

#

we can divide by 5

#

divide by 25

#

hence 2 0s

#

and for 1000 for example, it is divisbe by 5,25,125 but not 625, hence only 3 0s

lean otter
#

thanks

#

@grim plover yes I understand the process

#

but I don't understnad why

#

why is it that for $1000 \cdot 999 \cdot 998 ...$ we can just look at 1000

#

and ignore the rest

flat frigateBOT
#

Mushaar

thin bridge
#

dividing 1000 by 5 tells you the multiples of 5 between 1 and 1000 inclusive
dividing 1000 by 25 tells you the multiples of 25 between 1 and 1000 inclusive (since 25=5^2, these will contribute another 0 to the product)
etc

thin bridge
#

which part

lean otter
#

first sentence

#

why does dividing 1000 by 5 tell you multiples of 5 in 999

thin bridge
#

wdym in 999

lean otter
#

so there 1000/5 tells you multiples of 5 for 999 if my reading comprehension isn't failing

thin bridge
#

why are you considering the difference here

#

lets use a smaller example like multiples of 5 between 1 and 15 inclusive

lean otter
#

ah I see

thin bridge
#

starting from 1, and 15 being a multiple of 5,
15/5 gets you the number of multiples of 5

#

5,10,15

lean otter
#

so you were saying that dividing 1000 by 5 tells you all the multiples of 5 from 1 to 1000

thin bridge
#

yes

lean otter
#

what I don't understand is

#

why that enables us

#

to ignore the factorial bit

thin bridge
#

we're not

#

each factor of 5 in the prime factorisation will contribute to a trailing 0 in the product

lean otter
#

so if we have 1000 * 999 * 998 * 997 * 996 * 995, etc, 200 of those numbers are divisble by 5

thin bridge
#

yes

lean otter
#

ok and then for 975, it is also divisibley by 25

thin bridge
#

don't forget the 1000

lean otter
#

so we need add 1

thin bridge
#

1000 is also divisible by 25

lean otter
thin bridge
#

yes, each multiple of 25 will contribute (at least) one more 0

#

similar with 5^3

#

etc

lean otter
#

ok that makes sense

#

thank you

#

.close

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#
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manic path
#

I have a question, when you differentiate tan(x) you get sec^2(x)

manic path
#

but when you differentiate sec^2(x), why do you get 2sec^2(x)tan(x)?

#

is it because of that power of 2?

peak estuary
#

what do you mean with why. you just do

#

what does it have to do with sec^2 being the derivative of tan

manic path
#

because my logic says when you differeniate sec^2(x) =tan(x)

peak estuary
#

why should that hold

manic path
#

because like differentiation of sin(x) is cos(x)

peak estuary
#

yes but tan and sec are not sin and cos

manic path
#

so its just like that

#

you have to use... chain rule for sec^2(x)

#

and same applies for when you intergrate right

peak estuary
#

yes

#

well you could also use product rule or quotient rule to diff sec^2. but same result anyway

manic path
#

wait

#

intergration of sec^2(x) is tanx + c

lost patrol
#

Integration is the inverse process of differentiation, kinda

peak estuary
#

are you confused about the +c?

manic path
#

no

lost patrol
#

kinda: family of curves

manic path
#

ok how I imagine intergration and differentiation is like levels on a building

#

so you go up its intergration go down is differentiation

#

I can't comprehend how intergration sec^2(x) is tanx + c

peak estuary
#

well from tanx going down is sec^2

thin bridge
#

because differentiating tan(x) gives sec^2(x)

peak estuary
#

so going up gives tanx. but going up also always gives the +c

manic path
#

just to be clear

frigid locust
manic path
frigid locust
#

differentiating sec^2(x) gives 2sec^2x secxtanx

#

cuz derivative of secx is not tan x, its secxtanx

#

nvm im wrong , i forgot how power rule works

lost patrol
#

Sorry for the very sloppy handwriting using a mouse

manic path
#

just to be clear

#

if we derive all the way down, there is nothing saying it should repeat on itself right

peak estuary
#

yes

manic path
#

oh

peak estuary
#

only for very few functions it repeats

#

for most functions it tends to get very complicated

manic path
#

huh, I kind of assumed since cos and sin do that they ALL do that

#

guess not

#

welp thanks for the clarification

#

.close

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#
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supple rover
#

can anybody help me with this question?

safe radishBOT
safe radishBOT
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@supple rover Has your question been resolved?

supple rover
#

channel occupied

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quaint vault
#

I don’t know what this problem is asking me

urban eagle
#

Differentiate it with respect to x and then plug in that value

quaint vault
#

Oh

#

Ok thank

#

.close

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burnt nest
#

An algorithm that needs no inputs is : ambiguous?

peak estuary
#

can you give context

safe radishBOT
#

@burnt nest Has your question been resolved?

burnt nest
#

Hmm , they give us question and some options. Without algorithm 🥹

Ambiguous
General
No general
No ambiguous
All previous answers

This is the options

#

@peak estuary

#

An algorithm that needs no inputs is :

This is the question

burnt nest
#

.close

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cerulean tusk
#

So in this I have differentiated with chain rule to get the answer at the end, however, the mark scheme shows something completely different and I dont understand how they got there

cerulean tusk
#

That should be a 2x^2

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@cerulean tusk Has your question been resolved?

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@cerulean tusk Has your question been resolved?

idle grove
#

what is going on here, there is not even a single question in the picture

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lean otter
#

I am very confused by this practice SAT question

lean otter
#

I simply am choosing the first one because if a is 29 then it doesn't fullfil a>30?

#

but if someone could show a process or walk me through the process of arriving tot he correct answer that would be great

granite idol
#

I think it's asking you to solve for x

#

so III would be x=29. is that the correct interpretation?

#

so your answer is not right

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

that is what I am asking

graceful imp
#

And set a range of a

#

So its like 31≤a≤10000 or something

#

Then just play around

#

U will see that a+1 is a solution and 29

#

I think idk i did it like 15 min ago

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karmic garden
#

why do they IGNORE the 2+ and 2- when finding out what k (the constant) is in this problem

karmic garden
#

ik how to do the math but i just don't understand why they're ignoring it and j setting whatever is in the sqrt = to 0

little mesa
#

if the square root =0, then 2+() and 2-() are the same solution
that's what you want for there to be only one solution

#

These two values are equal and represent exactly one solution when sqrt(8-k/5)=0

karmic garden
#

okay

#

but i don't get why they took the 2's out

#

in the first place

#

when x = 0 we have one solution

#

that's what ik ab these problems

thin bridge
#

when the root and/or stuff under the root is 0, you'll have one solution

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amber geyser
#

i got 55

safe radishBOT
amber geyser
#

am i correct ?

safe radishBOT
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solar needle
#

do you prove this with induction

safe radishBOT
thin bridge
#

no

#

that's show that it'll be true for integers

solar needle
#

whats the proof method?

solar needle
#

i wouldnt have thought of that

thin bridge
#

simplify the inequality,
show something like strictly increasing

#

or otherwise

solar needle
#

it says no calculus

thin bridge
#

ok, simplify and solve the quadratic inequality

eager dock
#

hi

solar needle
#

then x^2(3 + x) >= 0

#

is this then proof by cases sorta deal

solar needle
#

like i imagine thats a way more difficult inequality to work with

#

oh u need the. binomial theorem

#

i forgot about this

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#

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safe radishBOT
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wise schooner
safe radishBOT
wise schooner
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wouldn't I need to divide matrices here? how do I do this

safe radishBOT
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@wise schooner Has your question been resolved?

sage shore
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We don't really have "division" of matrices, like real numbers

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What we have is, multiplication by inverse

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it's kinda the division in the matrices world

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So, when you have matrices A, B, and C such that: BA=C

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What you want to do is, multiply both sides by the inverse of B

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On the left

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$$B , A = C$$
$$B^{-1} , B , A = B^{-1} , C$$

flat frigateBOT
wise schooner
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right, so B and B inverse cancel out right

sage shore
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Yes, they become the identity matrix

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Disappears

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And you're left with

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$$A = B^{-1} , C$$

flat frigateBOT
wise schooner
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ok another question, how do I know if I do B^-1 * C or C * B^-1

sage shore
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Very good question

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you had

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$$B , A = C$$

flat frigateBOT
sage shore
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imagine if you multiplied by the inverse of B ON THE RIGHT

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$$B , A , B^{-1} = C , B^{-1}$$

flat frigateBOT
sage shore
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What would happen now?

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Nothing!

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No cancellation

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And therefore, you can't get the A

wise schooner
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makes sense, thanks.

sage shore
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Multiplication in this case must be on the left

sage shore
wise schooner
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btw is there like a shortcut to finding the inverse of a matrix

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or do I just have to augment it with the identity matrix until I get it to reduced row echelon form

sage shore
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for 2x2 matrices, yes

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$$A=\begin{pmatrix} a ,, b \ c ,, d \end{pmatrix}$$

flat frigateBOT
sage shore
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$$A^{-1}=\frac{1}{det(A)} , \begin{pmatrix} d ,,,,,,, -b \ -c ,,,,,,, a \end{pmatrix}$$

flat frigateBOT
sage shore
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Basically, you swap a and d

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And negate b and c

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And as always, divide by the determinant

sage shore
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Or you can use the adjoint matrix method

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You find the cofactor matrix, then the adjoint matrix, and then the inverse

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i prefer this myself!

wise schooner
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is it faster?

sage shore
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i mean, the first times, it will look slow and complicated

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but with practice, yes, definitely faster for me!

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it's so tedious for me to transform random matrices into indentity

wise schooner
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yeah it takes me like half an hour 🤣

sage shore
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😂

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The matrix in the exercise does not look very random

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i mean, only 2 and 1

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Try rref

wise schooner
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aight will try it now

sage shore
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i gotta go @wise schooner

wise schooner
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aight its all good im nearly done I think I've figured it out

sage shore
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i won't be here to check whether what you will find will be correct or not

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The inverse is

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1.5 2 1

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2 3 1

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1 1 0

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You should be finding this

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Otherwise, you're wrong somewhere

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And don't forget to multiply too 😛

wise schooner
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ty

safe radishBOT
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@wise schooner Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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fleet pine
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can someone explain this to me? how do you determine what numbers will be on the integral

plucky elk
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The question is a template for multiple problems. There are more you're not showing after a)

fleet pine
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no this is everything

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there are just multiple questions below

plucky elk
# fleet pine

Yes these are the multiple problems I was talking about

fleet pine
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and the -

plucky elk
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Yes

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They use symmetry

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Oh

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It's a typo

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Or no

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Not a typo

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Total area is different from integral

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Integral is signed area

fleet pine
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yea

plucky elk
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So they took -(negative integral) to get +

fleet pine
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yes

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what about the 0 and 1?

plucky elk
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What about it

fleet pine
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how and why did they get to 0 and 1

plucky elk
plucky elk
fleet pine
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is it possible to do that without graphing?

plucky elk
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Yes

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What does it mean for f(x) to be negative?

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Can you write an inequality

fleet pine
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do you mean like x-1>0

plucky elk
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That's positive f(x)

fleet pine
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oh <

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do you know what they did here?

plucky elk
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What part of that is confusing

fleet pine
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why are there 3 parts

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and how did they get those numbers

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when i plug in the integrals i dont get that

plucky elk
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What do you get for the x=0 endpoint

plucky elk
fleet pine
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i get 0, right?

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i think so

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idk my english is not very great when it comes to math terms, i'm dutch

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nvm i get it

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ty though

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.close

safe radishBOT
#
Channel closed

Closed by @fleet pine

Use .reopen if this was a mistake.

safe radishBOT
#
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Ask your math question in a clear, concise manner.
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young yacht
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I would like help with these problems particularly part B

normal moss
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!noclopen

safe radishBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

quasi bison
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op said his friend showed him the solution

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in the last channel

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when i had to disappear

young yacht
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it was wrong though

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when i typed it out

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into the online thing

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im sorry if it came off as rude

quasi bison
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can you show a screenshot of what you typed and what the feedback was

young yacht
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sure

quasi bison
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@young yacht so...?

young yacht
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im back

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sorry i had to finish my laundry

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This is what my friend sent to me

quasi bison
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ok so your friend assumed $\nrm{3u+4v} = \nrm{3u} + \nrm{4v}$

flat frigateBOT
quasi bison
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this is incorrect, as u and v are not parallel

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(not merely not known to be parallel, they definitely aren't parallel)

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u and v are perpendicular

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AND u · v is not 1, for that precise reason... the dot product of two perpendicular vectors is 0.

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between you and your friend, have either of you done anything involving vectors before?

young yacht
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we started learning about vectors a week ago

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so i guess we both are pretty new

safe radishBOT
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@young yacht Has your question been resolved?

young yacht
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im still working on the problem

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i got this final answer but im not sure if i know what im doing

young yacht
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<@&286206848099549185>

little mesa
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assuming you did dot product here, you need to denote that with

flat frigateBOT
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chlamydia

young yacht
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ok

little mesa
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yeah v^2 is not the same as v.v

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squaring vectors isn't a thing

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but it looks ok

young yacht
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so is it wrong then ?

little mesa
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no it's right, your notation is wrong

young yacht
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what would the correct npotation be in that case

little mesa
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you did that on the left hand side, but not on the right of each equation

young yacht
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oh okay

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how about the squaring vector thing you mentioned ?

little mesa
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you can't square this

young yacht
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so it would 3 u' u'?

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would that be the correct notatiion in which u' is representing a vector ?

little mesa
young yacht
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got it

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tysm!

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i really appreciate your help

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.close