#help-23

1 messages · Page 147 of 1

round tiger
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idk if this helps

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and this is like a related example of what i’m trying to do

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but basically im trying to create an equation that would suit a predicted population of a city

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do you think something like this would work?

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this is what bing ai is suggesting

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but what do you think?

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ples come back

safe radishBOT
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@round tiger Has your question been resolved?

safe radishBOT
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@round tiger Has your question been resolved?

safe radishBOT
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@round tiger Has your question been resolved?

safe radishBOT
#

@round tiger Has your question been resolved?

safe radishBOT
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@round tiger Has your question been resolved?

willow gust
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actual question?

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@round tiger

safe radishBOT
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@round tiger Has your question been resolved?

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@round tiger Has your question been resolved?

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round tiger
#

.close

safe radishBOT
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marble moss
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i need help with solving the fist interval

safe radishBOT
bright nacelle
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Domain is correct but in range it should be (-4,-1)U(3,8]

safe radishBOT
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marble moss
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-1 should have a ] because its including it

safe radishBOT
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rotund harbor
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rotund harbor
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How is this done?

frank glen
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Looks like a Maclaurin Series

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rotund harbor
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@rotund harbor Has your question been resolved?

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wanton remnant
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Yo guys how do I find the range again

safe radishBOT
little mesa
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do you know how to find the vertex

safe radishBOT
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@wanton remnant Has your question been resolved?

wanton remnant
little mesa
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bro what

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it's literally y>=-9

wanton remnant
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☠️☠️☠️

flat frigateBOT
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Spooderman

little mesa
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k

wanton remnant
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Chlamydia

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Das crazy

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Anyway

wanton remnant
little mesa
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ohh i didn't even notice the domain restriction

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for x<3, the parabola ends at y=-7

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which is why y>-7

flat frigateBOT
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Spooderman

little mesa
wanton remnant
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Yoooo

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I just plugged 3 into the thing

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How do I determine the inequality sign again

quasi bison
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posting chatGPT output is a bannable offense

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<@&268886789983436800> 2 channels of this crap

twilit moat
wanton remnant
quasi bison
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i'm not a guy.

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  1. that's a question you should take up with the moderators
  2. please edit out the "guy" in your message.
wanton remnant
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Wait could u help me real quick

quasi bison
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honestly i dont have much energy for that sorry

wanton remnant
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Oh

quasi bison
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will wait for @rotund harbor to fix his misgendering of me tho.

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oh so you're openly transphobic

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fuck you then

wanton remnant
quasi bison
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<@&268886789983436800> get this transphobe out of here please

little mesa
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is he cooking or is he using gpt

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nope lol

quasi bison
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<@&268886789983436800> double ping but please deal with the transphobe here

wanton remnant
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Blud had to ask chapgt to put a typo and grammatical error just in case

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Oh ok

little mesa
wanton remnant
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Ok guys

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I think I figured it out

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❤️❤️❤️❤️

little mesa
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goddamn

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that's fucked up

wanton remnant
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.close

safe radishBOT
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exotic nymph
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how to find the domain?

safe radishBOT
icy lance
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when could y not be defined

autumn iris
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as long as the denominator is not equal to 0, that’s ur domain

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so in this case as long as x is not equal to 5 or -5

tiny wraith
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*and the inside of the sqrt isn't negative

exotic nymph
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alr i will try again

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ok i got 5

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so its D: [3,5] or (-infinite, -3] or [5, infinite)

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.close

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undone stirrup
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undone stirrup
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How would I go about solving these type of questions? Graphing calculators are allowed for these questions.

elfin sinew
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Identify the type of function and substitute the values

elfin sinew
safe radishBOT
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@undone stirrup Has your question been resolved?

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manic heart
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I have a question, like this equation is normal

x + 2y = 2 and 3x +5y = 4

manic heart
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I know how to do that but

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the teacher added another number to the equations

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which doesn't include a variable

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like for example

3x + 5y - 13 = 0
and
2x - y + 5 = 0

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as I always thought there's only supposed to be x and y =

glass carbon
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you can always move the numbers to the another side

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to get it

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like

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3x + 5y = 13
and
2x - y = - 5

manic heart
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ohh

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another question, if I get x as a fraction, how would i get y

glass carbon
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same as if x wasn't a fraction

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it doesn't matter what's x, even if it's irrational

quasi bison
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unless you're allergic to fractions or don't know how to do arithmetic with them

manic heart
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so if we use 3x + 5y = 13
so for example, if we know the x value, how would we figure the y? as you'd have to plug in many numbers in your calculator to figure it out

quasi bison
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you don't need your calculator at all

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do you know how to isolate y in the equation 3x + 5y = 13?

manic heart
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yes

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you'd have to put 3x to the other side

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and then divide y by 5 and the others by t

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5*

quasi bison
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you would subtract 3x from both sides and then divide both sides by 5.

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to get y = (13 - 3x)/5

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notice that at no point did you need to know whether or not x was a fraction

manic heart
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I got y = 13/5 - 3/5x

normal moss
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Moving a term from one side to another is actually substracting or adding it to both sides of the equation

manic heart
normal moss
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So, if you've got $y + x = 0$

flat frigateBOT
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USS-Enterprise

quasi bison
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i said to subtract 3x

manic heart
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oh

normal moss
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To isolate y, you move x to the right (and change its sign), but this means you substract both sides of the equation by x

quasi bison
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that's the proper way of saying what you phrased as "putting 3x on the other side"

quasi bison
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you should never think of this as "putting stuff to the other side". it's (a) horribly ambiguous, and (b) breaks down with the slightest increase in complexity

manic heart
quasi bison
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your answer is correct

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i am criticizing your wording

manic heart
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ohh

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so now I just replace the x with the value

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and it = y?

quasi bison
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yes of course

manic heart
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tysm

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.close

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dapper cradle
#

$x^2 - 1 +(x+(-x)) = 0 \Rightarrow x^2 - 1 +x+(-x) = 0$

can i just do that or is that some axiom

flat frigateBOT
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aaaaaaaa

dapper cradle
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in a proof btw

peak estuary
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well you need associativity. but that's assumed anyway cause otherwise you would need much more brackets here

dapper cradle
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$x^2 = 1$

We can add the additive inverse to both sides

$x^2 + (-1) = 1+(-1)

\Rightarrow x^2 - 1 = 0$

As we know 0 is an additive identity we can add it to the equation

$x^2 - 1 + 0 = 0$

Note that $x+(-x)$ equals 0 so,

$x^2 - 1 + (x+(-x) = 0$

flat frigateBOT
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aaaaaaaa

$x^2 = 1$

We can add the additive inverse to both sides 

$x^2 + (-1) = 1+(-1) 

\Rightarrow x^2 - 1 = 0$

As we know 0 is an additive identity we can add it to the equation 

$x^2 - 1 + 0 = 0$

Note that $x+(-x)$ equals 0 so, 

$x^2 - 1 + (x+(-x) = 0$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.62 
     
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```
dapper cradle
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@peak estuary i have to explain every axiom

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is my proof proepr till now

peak estuary
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no you would need brackets around x^2-1

dapper cradle
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which line

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$x^2 = 1$

We can add the additive inverse to both sides

$x^2 + (-1) = 1+(-1)

\Rightarrow x^2 - 1 = 0$

As we know 0 is an additive identity we can add it to the equation

$x^2 - 1 + 0 = 0$

Note that $x+(-x)$ equals 0 so,

$x^2 - 1 + (x+(-x) = 0$

$x^2 - 1 +x+(-x) = 0$

$(x^2 + x) + (-1 + (-x)) = 0$

$x(x+1) -1((1+x) = 0$

$(x-1)(x+1) = 0$

flat frigateBOT
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aaaaaaaa
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

dapper cradle
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i didnt add explnaations

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need help with adding them

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im stuck

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idek if my other explanatiosn are correct

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have to use thiw

flat frigateBOT
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aaaaaaaa

dapper cradle
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@peak estuary is this good

safe radishBOT
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@dapper cradle Has your question been resolved?

dapper cradle
#

.close

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molten hawk
#

struggling with an epsilon-delta proof

safe radishBOT
molten hawk
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wintry holly
safe radishBOT
#

Please don't occupy multiple help channels.

wintry holly
#

I got 1 and 1/2 but the website is telling me its wrong

flat frigateBOT
pseudo scroll
wintry holly
#

can you please help show me the work because I'm confused

safe radishBOT
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jovial orchid
#

What theorem says if a=b and b=c, a=c

safe radishBOT
icy lance
#

the transitivity of '='

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= is an equivalence relation and is so transitive

safe radishBOT
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lean otter
safe radishBOT
lean otter
#

Is this right? Someone double check por favor

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Just to be clear Is horizontal asymptote where the numerator equals 0

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All values that make it 0

safe radishBOT
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@lean otter Has your question been resolved?

lean otter
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honestly, i just started learning vertical asymptotes, but wouldn't the restrictions just be 7 and -2

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im prolly not qualified though

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lean otter
#

Is this correct ?

safe radishBOT
rocky ferry
#

if the LHS doesn't use f'(t) but rather f(t) then i believe so

lean otter
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what is the LHS ?

rocky ferry
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left hand side

lean otter
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No it wouldn't be correct

celest ember
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it would be correct if f(0)=0

rocky ferry
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i think hes referring to this part of FTC

lean otter
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if the integral cancels the derivative

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but it doesn't since Kushu pointed out that it shall be f(x) -f(0) on rhs

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sad but that's the way

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Thank you

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errant rain
#

I've been stuck on this for a while, I got help earlier, still didn't get it.

errant rain
rocky ferry
#

by set of solutions does it want a parametric vector eq?

errant rain
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Like this:

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Yeah I think

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So first I would make a augmented matrix right?

rocky ferry
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yes

errant rain
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| -2 1 2 0 | 1 |
| 0 0 -3 1 | -4 |

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Now we reduce it

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So, uhh

rocky ferry
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row operations

errant rain
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Do I divide the first row by -2

rocky ferry
errant rain
#

Ok so:

| 1 -1/2 -1 0 | -1/2 |
| 0 0 -3 1 | -4 |

rocky ferry
#

seems like you understand, show me your reduced matrix when you're done.

errant rain
#

Divide second row by -3

| 1 -1/2 -1 0 | -1/2 |
| 0 0 1 -1/3 | -4/3 |

rocky ferry
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its not in RREF yet.

errant rain
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Add R2 + R1

rocky ferry
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good

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with row operations you always want to mark where you are placing the result

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R2 + R1 -> R1

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i've also seen R1 -> R2 + R1. whichever you prefer.

errant rain
#

| 1 -1/2 0 -1/3 | -1/2 |
| 0 0 1 -1/3 | 4/3 |

rocky ferry
errant rain
#

4/3

rocky ferry
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it also changes the result of R2 + R1

errant rain
#

| 1 -1/2 0 -1/3 | 5/6 |
| 0 0 1 -1/3 | 4/3 |

rocky ferry
#

alright, so we have our reduced matrix. do you know what to do next?

errant rain
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So we solve for x1, x2, x3, x4, right?

rocky ferry
#

right, technically we already did

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we found Ax = b by virtue of reducing the matrix.

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only thing to do is write it out in the form you want

errant rain
#

Okay so first row:

x1 - (1/2)x2 - (1/3)x4 = 5/6

Second row:

x3 - (1/3)x4 = 4/3

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There is more than 1 variable, what should I do?

rocky ferry
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we have x2 and x4

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what happened to those

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to get it into the form you showed me we have to write out all 4

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you might be wondering "how do i write out x2 and x4 if they aren't defined?" easy we just write x2 = x2 and x4 = x4

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whatever they are doesn't matter to us, we just know they are a part of the solution

rocky ferry
errant rain
#

So x2 = s1 and x4 = s2

rocky ferry
#

yes, thats what they are asking you. since there are infinitely many solutions ( there are 1 or more free variables ). in this case we got 2

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so now solve x1 and x3

errant rain
#

First row (x1):
x1 - (1/2)s1 - (1/3)s2 = 5/6
-> x1 = (1/2)s1 + (1/3)s2 + 5/6

Second row (x3):
x3 - (1/3)s2 = 4/3
-> x3 = (1/3)s2 + 4/3

rocky ferry
#

yes, good. but conventionally, we always keep the constants as the first terms

errant rain
#

[x1, x2, x3, x4] = [ 5/6+ (1/2)s1 + (1/3)s2, s1, 4/3+ (1/3)s2, s2]

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Okay

rocky ferry
errant rain
#

So question.

rocky ferry
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shoot

errant rain
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Infinite solutions means that there are ONE or MORE free variables (the number after the pivot)

rocky ferry
#

yes, one or more free variables means infinite solutions if the resulting matrix is consistent.

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free variable is any column without a pivot

errant rain
#

Ok got it. Thanks for the help

rocky ferry
#

np

safe radishBOT
#

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heavy glade
#

why do we care about the mass of m1?

safe radishBOT
heavy glade
#

for acceleration

jaunty owl
#

because

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both boxes are accelerating

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so we need to factor in both masses

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it's not only m2 that is moving

heavy glade
#

yeah but I thought since the table is frictionless no matter the mass of m1 it will accelerate the same

jaunty owl
#

if I'm pulling on two objects attached by like a string on a flat frictionless table

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I need to consider both masses

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it's the same thing here except now I'm not pulling on the system, gravity is.

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and the force with which it is doing so is = m2g

heavy glade
#

okay so since Fg is interacting with m1 we just use sum of m for F?

#

I think I get it now thank you

#

.close

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mystic marsh
safe radishBOT
mystic marsh
#

How do I solve this equation?

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Quadratic formula?

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Factoring by grouping?

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Factoring?

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Idk what to do

twilit spindle
#

are you setting this equal to 0?

mystic marsh
#

Yeah

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What should I do to solve it?

twilit spindle
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that x-2 in the denominator is making things very unfortunate

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are you only interested in real solutions? i.e. where it intersects the x-axis?

mystic marsh
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Yes real

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I want to solve to get that

twilit spindle
#

ah ok then

mystic marsh
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I don’t know how to

twilit spindle
#

so first we have $x^2-2x+1+\frac{5}{x-2}=0$

flat frigateBOT
#

FancyBredFries

twilit spindle
#

now we can multiply everything by x-2 :)

mystic marsh
#

And you get

#

x^3-4x^2+5x+3=0?

twilit spindle
#

that's not factorable... so you'll have to use the cubic formula...

mystic marsh
#

Wtf

twilit spindle
#

which looks like this

#

$\displaystyle x=\sqrt[3]{\left(\frac{-b^3}{27a^3}+\frac{bc}{6a^2}-\frac{d}{2a}\right)+\sqrt{\left(\frac{-b^3}{27a^3}+\frac{bc}{6a^2}-\frac{d}{2a}\right)^2+\left(\frac{c}{3a}-\frac{b^2}{9a^2}\right)^3}}+$\$\displaystyle\sqrt[3]{\left(\frac{-b^3}{27a^3}+\frac{bc}{6a^2}-\frac{d}{2a}\right)-\sqrt{\left(\frac{-b^3}{27a^3}+\frac{bc}{6a^2}-\frac{d}{2a}\right)^2+\left(\frac{c}{3a}-\frac{b^2}{9a^2}\right)^3}}-\frac{b}{3a}$

mystic marsh
#

What is the cubic formula

flat frigateBOT
#

FancyBredFries

mystic marsh
twilit spindle
#

so I'm assuming you don't wanna use that kek

mystic marsh
#

😭

twilit spindle
#

,w x^3-4x^2+5x+3=0

#

WolframAlpha to the rescue! hype

flat frigateBOT
mystic marsh
#

Ahh thank you!!!!

twilit spindle
mystic marsh
#

Well before i had no idea what to do

twilit spindle
#

here is the full solution Wolfie gives

mystic marsh
#

But now i know such a thing as

#

Cubic formula’ exists

twilit spindle
#

it's long...

mystic marsh
#

Ah i see

twilit spindle
#

but the Quintic doesn't exist fun fact

#

the Quartic is the highest you can you can solve "in radicals"

#

you can prove that with something called "Galois Theory" which is a very advanced mathematical field

mystic marsh
#

Damn

#

Is that gonna be covered in pure math in college

#

Sounds interesting

twilit spindle
#

after Ring Theory, Group Theory, Linear Algebra, etc.

mystic marsh
#

How long do those take for someone to fully comprehend/understand the concept?

#

Like a whole semaster?

twilit spindle
#

depends Galois made the field at age 18

mystic marsh
#

Or a year?

twilit spindle
mystic marsh
#

Damn

#

I still have long way to go

twilit spindle
#

really depends on how mathematically intuitive you are

mystic marsh
#

Prolly not gonna major in pure math tho

#

Lol

twilit spindle
mystic marsh
twilit spindle
#

trying out Calc III/Complex Analysis rn

#

and I've doing it for like a year on and off

#

but yeah you got Alg II, PreCalc, Calc I/II/III, Stats, Combinatorics, Set Theory, Linear Algebra, Analysis (Complex, Real, Functional), Number Theory, Group Theory, Ring Theory, Topology, Category Theory, Galois Theory, Differential Geometry, etc

mystic marsh
#

Ah

#

Ummm

#

After all those

#

What do you get

#

A job?

#

Do you become a mathematician

#

My life will be miserable if i become a mathematician ngl

#

I just want a job that utilizes math not studies math😭

#

Imagine working for math after 6 years of math in university

safe radishBOT
#

@mystic marsh Has your question been resolved?

mystic marsh
#

anyways thanks for your help with cubic formula! @twilit spindle

safe radishBOT
#
Channel closed

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Use .reopen if this was a mistake.

safe radishBOT
#
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safe radishBOT
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devout shale
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@twilit spindle

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dull sequoia
safe radishBOT
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Helpers are just people volunteering their time to help you. Be polite and patient.

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Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, and no one person can be prioritized over other people, so please patiently wait. Anyone who chooses to help you is a volunteer who is doing so out of their own kindness.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

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Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#
What step are you on?
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4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
#

@twilit spindle Has your question been resolved?

devout shale
#

@twilit spindle

twilit spindle
devout shale
twilit spindle
#

actually kinda

#

You see, I have: $\frac{\sum_{n=0}^{\infty}\frac{n^{p+1}\cdot2^{n+1}}{3^n}}{\sum_{n=0}^{\infty}\frac{n^p\cdot2^{n+1}}{3^n}}\approx\frac{2(p+1)}{\ln3}$ but I'm interested in: $\frac{\sum_{n=0}^{\infty}\frac{n^{p+1}}{3^n}}{\sum_{n=0}^{\infty}\frac{n^{p}}{3^n}}$

flat frigateBOT
#

FancyBredFries

twilit spindle
#

any chance I could get the desired ratio?

devout shale
#

yea

#

.close

safe radishBOT
#
Channel closed

Closed by @devout shale

Use .reopen if this was a mistake.

twilit spindle
#

.reopen

safe radishBOT
#

devout shale
#

sorry minor typo

twilit spindle
#

bro why was the bot typing a whole ass essay 😭

tepid walrus
#

I was wondering that too like tf

#

someone tested every helper factoid ever

twilit spindle
#

yk what

#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

devout shale
#

yeah that is so weird

#

why would it do such a thing

#

@worthy hemlock

twilit spindle
#

@worthy hemlock

#

.reopen

safe radishBOT
#

twilit spindle
#

@worthy hemlock Please stick to your channel.

#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

twilit spindle
#

.reopen

#

.close

safe radishBOT
#

twilit spindle
#

.reopen

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

twilit spindle
#

.close

safe radishBOT
#

#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

twilit spindle
#

.reopen

#

.close

safe radishBOT
#

#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

twilit spindle
#

.reopen

safe radishBOT
#

twilit spindle
#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

twilit spindle
#

damn was trying to confuse the bot 😭

worthy hemlock
#

.reopen

safe radishBOT
#

worthy hemlock
twilit spindle
#

.close
.reopen

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

worthy hemlock
#

@devout shale

devout shale
#

@solar hazel

worthy hemlock
#

.reopen

safe radishBOT
#

worthy hemlock
#

.close

safe radishBOT
#
Channel closed

Closed by @worthy hemlock

Use .reopen if this was a mistake.

twilit spindle
#

@tepid walrus

worthy hemlock
#

.die

twilit spindle
#

.reopen

safe radishBOT
#

tepid walrus
twilit spindle
#

all helpers just got tagged in this aneurysm of a channel KEK

devout shale
#

@wraith prism

twilit spindle
#

Guys how do I solve tangent(radical(x+5))=pi/2

#

PLEASE HELP

#

HELP

#

@worthy hemlock

#

@tepid walrus

tepid walrus
#

are you good...?

worthy hemlock
twilit spindle
tepid walrus
#

i see that..

twilit spindle
#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

hardy lion
#

.reopen

safe radishBOT
#

twilit spindle
#

AUGHHHH

hardy lion
#

We need to stop fooling around ohmy god

twilit spindle
#

ikr @safe radish stop fooling around

#

@stable estuary you silly goose

devout shale
#

bruh

twilit spindle
safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

worthy hemlock
twilit spindle
#

.loose

hardy lion
#

.roopen

twilit spindle
#

.noose

worthy hemlock
#

.reclose

twilit spindle
#

.clopen

devout shale
#

.reoplaeena

twilit spindle
#

.reclopen

safe radishBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

safe radishBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

twilit spindle
#

interesting

#

didn't know that was one of them

#

very useful! helper_smile

safe radishBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

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Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

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Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

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Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

twilit spindle
#

giga fail

worthy hemlock
twilit spindle
#

.close

safe radishBOT
#

twilit spindle
safe radishBOT
#
Channel closed

Closed by @granite flower

Use .reopen if this was a mistake.

#

edgy pendant
#

What happened here?

twilit spindle
safe radishBOT
twilit spindle
#

people keep trying to reopen it 😭

#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

#

twilit spindle
#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

#

twilit spindle
#

AUGHHH

#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

#

twilit spindle
#

$\int_{0}^{\infty}\frac{\sin(x)\cdot e^{-x}}{\sqrt{x}}\dd x$

flat frigateBOT
#

FancyBredFries

twilit spindle
#

may as well ask a question

#

how do I evaluate this integral?

#

I tried $\sqrt{x}=u$

flat frigateBOT
#

FancyBredFries

twilit spindle
#

this gives $\int_{0}^{\infty}\frac{\sin(u^2)\cdot e^{-u^2}}{2u^2}\dd u$

flat frigateBOT
#

FancyBredFries

twilit spindle
#

but now I have no clue how to proceed kek

safe radishBOT
#
Channel closed

Closed by @worthy hemlock

Use .reopen if this was a mistake.

twilit spindle
#

.reopen

safe radishBOT
#

worthy hemlock
#

Oh

twilit spindle
#

lmao

worthy hemlock
#

I forgot it says the name of who closes it

#

Lmao

#

I was trying to sneak in

safe radishBOT
#

@twilit spindle Has your question been resolved?

twilit spindle
#

.close

safe radishBOT
#
Channel closed

Closed by @twilit spindle

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

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sick cape
#

How do i solve the bottom part to find the value of a, also a note that the value is a number without variables

safe radishBOT
#

@sick cape Has your question been resolved?

safe radishBOT
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@sick cape Has your question been resolved?

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safe radishBOT
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Available help channel!

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glad agate
#

help

safe radishBOT
glad agate
#

idk where to begin

sudden forum
#

u know the formula for cos a cos b + sin a sin b

glad agate
#

what!?

#

this is supposed to be done without a calculator btw

lean otter
safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

sudden forum
#

$\cos a \cos b + \sin a \sin b = \cos (a + b)$

flat frigateBOT
glad agate
lean otter
#

Oh

glad agate
#

where do you learn this?

lean otter
#

yea xd

glad agate
#

like at what level of school

sudden forum
#

i do believe u have to use that property to find the answer

glad agate
#

i have an olympiad in a month idk where to prepare all these topics our schoolt eaches us nothing

wet wigeon
sudden forum
#

check your textbooks perhaps

wise oyster
glad agate
sudden forum
glad agate
#

im asking for general advice how do i learn these theorems properties and where from cuz im confused. i have an olympiad and it cant be done using gcse maths only

#

im in AS

thin bridge
#

khan can give you a basic intro

wet wigeon
#

You can google proof of angle formulas

thin bridge
#

you'd pretty much want to be well versed in basic stuff
and then fancy tricks for olympiad level stuff

glad agate
glad agate
thin bridge
#

khan can give you a basic intro

glad agate
thin bridge
#

or look up dedicated you tube videos

glad agate
#

OH KHAN ACADEMY

wet wigeon
#

Its taught in high school in my country

glad agate
#

sorry

wet wigeon
#

In grade 12

glad agate
#

i wanna learn stuff early to win comps

wet wigeon
#

So its not a secret of a sort

thin bridge
#

prof leonard / organic chem tut come highly recommended

fluid token
#

you shouldve done trig by now, if youre in year 11

glad agate
#

our year just started

wet wigeon
#

Turkey is one

fluid token
#

true i guess

fluid token
glad agate
#

i know indentities cos2x+sin2x waghaira

glad agate
fluid token
#

oh ok

glad agate
#

wanted to take further maths but its really time intensive i have phy math cs and chem alr

fluid token
#

good luck with those lmao

glad agate
#

thank you

fluid token
#

alevels is on another level

glad agate
#

(im gonna die)

fluid token
#

real

glad agate
fluid token
#

its pretty much first year uni math

glad agate
#

feeling for the ppl who didnt 👆💯

#

.close

safe radishBOT
#
Channel closed

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safe radishBOT
#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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dire escarp
#

can someone explain how to do

safe radishBOT
dire escarp
#

ping me if youre here

quasi bison
#

!status @dire escarp

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
dire escarp
#

1

quasi bison
#

do you know how to write down the equation of motion for an object in free fall

dire escarp
#

yes the 4 equations right

#

i know acceleration is 9.81

quasi bison
#

"the 4 equations"...?

dire escarp
#

one sec

quasi bison
#

you only really need the first two here

#

do you know what $x_0$ and $v_0$ stand for, and (separately) what their values are in this problem?

flat frigateBOT
dire escarp
#

x is 24 and v is 0?

#

initial displacement and initial velocity

quasi bison
#

x_0 is 24 m but v_0 isn't 0 !

#

the bolt falls off the rising rocket, and that matters.

dire escarp
#

but its at the very top right

#

isnt the max height velocity 0

quasi bison
#

the rocket is rising steadily, not in freefall

dire escarp
#

then 20?

quasi bison
#

the bolt, upon detaching from the rocket, shares its upward velocity of 20 m/s

dire escarp
#

but the bolt isnt it going down

#

the 20 is going upwards

quasi bison
#

the bolt first goes up but then goes down

#

$x = 20 + 24t - 4.9t^2$

flat frigateBOT
dire escarp
#

will final velocity be negative then

quasi bison
#

of course it will!

#

how can you slam into the ground with upward velocity?

dire escarp
#

🗿

#

how did you get negative 4.9

quasi bison
#

acceleration due to gravity is -9.8 m/s^2

dire escarp
#

if it goes up then positive?

dire escarp
flat frigateBOT
quasi bison
#

oh oops yes

#

typo on my part

quasi bison
dire escarp
#

what about part b

#

i dont get how its 44m when the bolt only travelled 24m

quasi bison
#

no, the bolt did not travel only 24m

dire escarp
#

oh did it continue going up before falling down

quasi bison
#

of course it did...

dire escarp
#

didnt thought of that

#

alls good now, tysm! :)

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polar forge
#

hello I need help with a question in maths :

Let f(x) = integrate e^(-(t²/2)) dt from x to +∞.
Calculate for all A > 0, the integral of f(x) dx from 0 to A in terms of f(A).

grim plover
flat frigateBOT
#

ItzKraken

grim plover
#

to find $\forall A \int_{0}^{A} f(x) dx$ in terms of f(A)

flat frigateBOT
#

ItzKraken

grim plover
#

right?

#

@polar forge

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unreal stump
#

how is 6x-x^2 = x(6-x) = -(u+3)(u-3) if u= x-3?

quasi bison
#

u = x - 3 => x = u + 3

#

and 6-x = 6-u-3 = 3-u

unreal stump
#

holy shit

#

im in college and have never though of it that way

#

wtf

#

im shit at factoring HAHA

#

thanks!

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narrow vault
#

anyone here that has taken the dynamics course in engineering and wants to help me out?

safe radishBOT
#

@narrow vault Has your question been resolved?

narrow vault
#

I will wait patiently for someone who studied engineering 🙂

#

hey!

narrow vault
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fleet stirrup
#

i need help with this question

safe radishBOT
fleet stirrup
#

i know i need to find the vertex and can do it on my calculator but cant do it manually

#

i got a standard form of y=x^2-0x-70

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@fleet stirrup Has your question been resolved?

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@fleet stirrup Has your question been resolved?

polar forge
#

Sry I was AFK

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restive briar
#

Hey I got this algebra problem for determining the inverse but it uses "completing the square". Im stuck on one of the steps can you help explain it to me?

restive briar
#

After I factored out the 3 I dont understand why we add the +1, -1 and the -3 outside the brackets

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@restive briar Has your question been resolved?

restive briar
#

<@&286206848099549185>

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proper nymph
safe radishBOT
proper nymph
#

I tried this

fossil shell
proper nymph
fair hound
#

nope you're wrong, that's why he posted this

proper nymph
#

so then how would it look

fair hound
#

the same as on the image he posted

#

the angle of depression is above the slope

proper nymph
#

like that?

fair hound
#

it's 26 not 28

#

but yeah now these angles are where they should be

proper nymph
#

so do i have to find both the adjacent angles

fair hound
#

you can calc the distance between the 2 rocks directly

#

that's the length of the horizontal line

proper nymph
#

tan26=14/x
tan20=14/x1

x+x1

fair hound
#

it's 26

#

still not 28

proper nymph
#

oh yeah

#

so is that right?

fair hound
#

yes

proper nymph
#

so 67

fair hound
#

yes

proper nymph
#

how would u drfaw that

fair hound
#

draw a right angled triangle, the rope is the hypothenuse, the pole makes a right angle with the ground

proper nymph
#

106.8^

cyan shard
#

Isn't the rope is supposed to be 56.4 ft away from bottom of pole?

#

Like the horizontal length

#

Coz 56.4 isn't the height of the pole

proper nymph
cyan shard
#

Yep

#

That's right

proper nymph
#

.close

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lean otter
safe radishBOT
lean otter
#

I dont understand what to do

safe radishBOT
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tight oak
#

How do I find the domain of square root of -x^2

lean otter
#

You mean to say √(-x)²

#

??

tight oak
#

No

#

Well maybe

#

I have to find f composed with g

#

F of x equals square root of 2-x and g of x equals x squared + 2

lean otter
#

f(x) = √(2-x)
g(x) = x² + 2

You have to find f(g(x))

#

Hmm?

lean otter
#

Yeah f(g(x)) = √(-x²)

#

@tight oak

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leaden scaffold
#

Hey! Could I walk through this problem and someone tell me if im on right track?

leaden scaffold
#

So, so far, I have this approach for a: I'm gonna be using points at t=20 and t=22 months.

#

From there, I get f_t(20,6) = f(22,6)-f(20,6)/22-20

#

and from the table, we know f(22,6) = 86% and f(20,6) = 90%

#

substituting the values, we get ft(20,6)=(86-90)/(22-20) =-4/2=-2

#

Does this make sense?

#

So we get: f_t(20,6)≈−2.0

little barn
#

yes

#

You could get a possibly better estimate using both the forward and backward difference, but I'm not sure that's needed

leaden scaffold
little barn
#

That would give another estimate. I could only say if I knew more context

leaden scaffold
#

Okay

little barn
#

What have you been taught? what does the teacher expect

#

etc.

#

I think what you have is good enough

leaden scaffold
little barn
#

Here's the conceptual picture, but practically, yes, you want the central diff.

#

or an average of the forward and backward

leaden scaffold
#

I got -1.75 when I averaged both forward and backward

little barn
#

yes

#

i.e. the rats are dying

leaden scaffold
little barn
#

yes, but I may not be around to help, gotta go

leaden scaffold
safe radishBOT
#

@leaden scaffold Has your question been resolved?

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lean otter
safe radishBOT
#

@lean otter Has your question been resolved?

gentle oak
#

they're all parallels so 3x-18=5x+14

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median totem
#

someone can help me?

safe radishBOT
median totem
#

y = (this shit)

rigid inlet
#

What's the question?

karmic ocean
#

can i ask a question here?

median totem
unique bison
#

That's not a question lol

#

It's an expression

rigid inlet
#

What are you asked to do with this thing?

median totem
#

determine the domain of this function

#

better?

rigid inlet
#

Much better

#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
median totem
#

1

#

1

#

1

#

iausdasudhasu

#

step 1

gentle oak
#

,rotate

flat frigateBOT
#

Couldn't find an attached image in the last 10 messages.

unique bison
#

Lmao

rigid inlet
#

So, the sqrt provides a very straightforward domain restriction

#

Your goal is to find what x values satisfy $2^x - 2^{1-x} \ge 0$

flat frigateBOT
#

Steakanator

median totem
#

i know the result is [1/2]

#

but the way to find...

rigid inlet
#

That's the x value that makes the expression 0, I wouldn't call it "the result"

rigid inlet
# median totem

This should give you a hint. When is the product of two numbers positive?

safe radishBOT
#

@median totem Has your question been resolved?

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fickle trail
safe radishBOT
fickle trail
#

is this literally all that an integral means?

#

the change in y multiplied by the change in x

#

ΔyΔx

#

but specifically, the area under the curve, to the derivative axis, in this case dx, so the x-axis

#

or instead of using variables
ΔheightΔwidth

deep matrix
#

Integrals are area under the curve

fickle trail
#

right

deep matrix
#

But more like sum of the integral areas

fickle trail
#

and the product of ΔheightΔwidth is how we find them?

#

oh right

#

that would always be rectangle

#

so it's the sum of infinitely small rectangles

#

all added up

final halo
#

Go back and look at the riemann sum definition yeah

deep matrix
#

Yeah

fickle trail
#

but same premise, just infinitely many rectangles to allow for any curves

deep matrix
#

That's the rectangle part

fickle trail
#

does anybody know if Issac Newton or Gottfried Wilhelm Leibniz understood right away that the derivative and integral were one-to-one inverses to one another? or took some time to find that part out

#

it still kinda blows my mind lol

deep matrix
#

You ought to read their books to find out

#

Maybe Newton had a different approach

#

Idk

fickle trail
#

(area under the curve)^-1 = (slope at any given point on the curve)
and
(slope at any given point on the curve)^-1 = (area under the curve)

final halo
fickle trail
#

does anybody visualize the inverse when they do inverse of f'(x) or F(x)? or you just follow the math, and trust the math

#

trying to find out if 3B1B has done a video on this

#

this is a graph of f(x) to f(x)^-1

#

this is a graph of f'(x) to F(x)?

#

(3b1b did do a video)

#

One view on why integrals and derivatives are inverses.
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Special thanks to these supporters: http://3b1b.co/lessons/area-and-slope#thanks

Full series: http://3b1b.co/calculus


3blue1brown i...

▶ Play video
#

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olive stump
safe radishBOT
olive stump
#

can i get some help witht he second half

#

yim pretty sure A is correct but what other boxes appl

#

i cant really think of anythin

#

i was thinking about a and e too but it doesnt work

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#

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gentle valley
#

hello

safe radishBOT
gentle valley
#

I am wondering what does dash or prime indicate, like if we have x, what does x' imply? does it only mean the derivative of x or are there any other meanings?

#

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void cosmos
safe radishBOT
void cosmos
#

Hello there so I answered the question and got it right. I don't think this really matters, but just want to clarify. So in the answer key part a) on my worksheet it shows = x +- (pi)n where n is any integer, and same thing for pi/2 +- (pi)n where n is any integer. Also note I'm using radians. Now everything is fine, except the answer key said x = pi(n) where n is any integer and pi/2 + (pi)n, where n is any integer.

safe radishBOT
#

@void cosmos Has your question been resolved?

void cosmos
#

I don't think it matters as the answer key recognized that there are numerous answers and that the answer listed is not always the direct answer.

safe radishBOT
#

@void cosmos Has your question been resolved?

safe radishBOT
#

@void cosmos Has your question been resolved?

safe radishBOT
#

@void cosmos Has your question been resolved?

little mesa
#

the plus-minus in your answer is not necessary, especially for any integer n, including negatives

void cosmos
little mesa
#

redundant

void cosmos
#

So it would still be correct, but its just more unecessary work and the goal is efficiency at the end of the day right.

#

?

#

I'm just confused chjlamydia cus I scenarios where +- is used and where its not used.

little mesa
#

in an area of study that appreciates simplicity, elegance and brevity, adding a plus-minus where it doesn't need to be there is goofy

#

yes it's still correct

void cosmos
#

Thank you very much.

#

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weak spire
safe radishBOT
fleet gale
#

Did u try rationalizing it?

weak spire
fleet gale
#

No try it

#

There will be 2x³ on numerator i think

#

U can cancel the x²

#

Ans should be 0

weak spire
fleet gale
#

Show me how u rationalized it

weak spire
#

x{sqrt(1+x³) + sqrt(1-x³)}

#

Right?