#help-23

1 messages · Page 136 of 1

split ether
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So you can solve for its legs

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Which happen to be the height of the cone and the radius of the base circle

mint spindle
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Would I half the 50 for the angle? So 25 degrees in the right triangle

split ether
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Yes

mint spindle
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Alright, so I have the radius and height but what’s the formula for the surface area of a cone? Like Google gives me a long thing with a square root but surely there’s an easier to remember formula or something?

split ether
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It's just $\pi r^2 + \pi r l$ where $l = \sqrt{r^2 + h^2}$

flat frigateBOT
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A Lonely Bean

split ether
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If google gave you this then no you can't simplify this

mint spindle
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Ok that first one makes more sense- Google gave me which is the same thing but makes less sense at first glance

split ether
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Since it's just base area + lateral area

mint spindle
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Thank you so much!

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.close

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ebon heath
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Where did the integral of 2 1(big f thingy)-1 change into 4 1(big f thingy)0?

calm bridge
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even function

final halo
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Since your function is even (symmetric around the y axis) the area from -1 to 1 is twice the area from 0 to 1

ebon heath
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Oh and so I can just half the range kinda

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I get it now

calm bridge
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range?

ebon heath
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Domain ig

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From -1 to 1

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From 0 to 1

calm bridge
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bounds

ebon heath
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👍

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Tysm!

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.close

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static token
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hello guys

safe radishBOT
static token
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can i multiply the question to make it easier to do the quadratical formula

obtuse leaf
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yup

static token
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is it right

obtuse leaf
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why not dont be scared bro its just those loser math laws

static token
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yeah I'm actually just trying to help my friend but i want to make sure im right

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thanks ig

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hexed geyser
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i need help on items 10-16

G8 laws of exponents

hexed geyser
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starting with number 10
x³y⁴

x²y⁷

obtuse leaf
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no spoonfeeding her

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here

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show work

fickle yew
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When you divide, you subtract exponents with same base. When you multiply, you add the exponents with same base.

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Sample: x^2 times x^3 = x^2+3 , x^3 divided by x^2 = x ^3-2

hexed geyser
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so all the variables become x?

fickle yew
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Nope, it's only applicable to the ones with the same variable. In that case, you have to repeat the same process if theres another variable

hexed geyser
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so what will the answer of the fraction look like with two different variables

fickle yew
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For example in number 10, you have 2 variables present, x and y

hexed geyser
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yea?

fickle yew
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They'll just be side by side with each other.

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If the other variable has a negative exponent, you have to put it in the denominator

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Example y^-1 = 1/y

hexed geyser
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so it would be

xy⁷

xy⁹
?

fickle yew
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x^-2 = 1/x^2

hexed geyser
fickle yew
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it's y^4-7

hexed geyser
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ohhh

fickle yew
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Yesyes you put negative exponent in the denominator

hexed geyser
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il do that with both sides?

fickle yew
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Yes

hexed geyser
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alright hold on

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x

y³ ?

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or just xy³?

fickle yew
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The first one, it's correct

hexed geyser
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ohhhhhhhhhhhhh

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thats the final answer right?

fickle yew
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Yess

hexed geyser
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yay

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will you help me with the rest

fickle yew
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To the other items, just take note of pemdas rule and order of operations

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It's essentially the same process

hexed geyser
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oh ok

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thank you

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have a nice day or night

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!!

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.close

safe radishBOT
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fickle yew
#

welcome🤗

safe radishBOT
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upbeat peak
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ABCD is a square AF vertical to BE how to prove 1. AF=BE 2.DE+DF=BC

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Thanks

safe radishBOT
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@upbeat peak Has your question been resolved?

upbeat peak
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<@&286206848099549185>

upbeat peak
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???

safe radishBOT
#

@upbeat peak Has your question been resolved?

minor ore
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Is where AF and BE meet a 90° angle?

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@upbeat peak

upbeat peak
minor ore
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Ok then lets call angle EBA x

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What is EBC?

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In terms of x

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Are you here?

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@upbeat peak

upbeat peak
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Yes sorry

upbeat peak
minor ore
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Ok now youre free?

upbeat peak
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1 min

minor ore
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Ok

upbeat peak
minor ore
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Yes

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Now what is AFC

upbeat peak
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Wait a second

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Let me get a paper

minor ore
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No

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No

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Lets call the intersection point P

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What are the angles in PBCF

upbeat peak
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90 90 x-90 and f

minor ore
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90-x not x-90

upbeat peak
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Oh yes my vas

minor ore
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What does that equal to

upbeat peak
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360=270-x

lean otter
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i think we can prove the angle DAF and ABE equal

minor ore
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Yes simplify a bit

minor ore
lean otter
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then we can prove the triangle abe equal to triangle daf

minor ore
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No

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360=90+90+90-x+angle AFC

upbeat peak
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Yeah

lean otter
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so angle PAB + ABP = 90
and DAF + PAB = 90
then PBA = DAF

minor ore
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What is angle AFC in terms of x then?

lean otter
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sry if my english is bad

upbeat peak
lean otter
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we have: ADF = BAE = 90
AD = AB (ABCD is square)
DAF = ABE (has proved)
=> Triangle DAF = ABE
=> AF = BE

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is that right? anything wrong?

upbeat peak
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mmmm

upbeat peak
minor ore
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90+x

upbeat peak
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that is what I thought

minor ore
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360=90+90+(90-x)+(90+x) so the x cancels out and we have 90+90+90+90=360

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Now we have angle AFC what is angle AFD

upbeat peak
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I have a lesson rn sorry

minor ore
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Ok

upbeat peak
#

Thanks

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🙏

safe radishBOT
#

@upbeat peak Has your question been resolved?

safe radishBOT
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static finch
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what does the double vertical line mean? In this example

static finch
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I assume it is not simply a sum notation, but rather some kind of an operation on the vector w

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is it a modulus of this vector?

peak estuary
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its called a norm

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"length"

static finch
peak estuary
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yes

static finch
#

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wraith prism
safe radishBOT
wraith prism
#

can anyone tell me in easy way to remember these 3 terms

safe radishBOT
#

@wraith prism Has your question been resolved?

wraith prism
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<@&286206848099549185>

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very strange

wraith prism
#

. close

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.close

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slate heart
safe radishBOT
slate heart
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bro

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yall finna help?

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like I ain got all dayy

plucky elk
safe radishBOT
slate heart
plucky elk
#

also still not a good reason to be rude and entitled

slate heart
#

bro thinks I know how long an hour is

plucky elk
plucky elk
worthy hemlock
plucky elk
flat frigateBOT
#

Result:

3600
plucky elk
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correct

worthy hemlock
safe radishBOT
#

@slate heart Has your question been resolved?

safe radishBOT
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teal gate
safe radishBOT
teal gate
#

not sure if i did either right

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im p sure i got the graph right but i have no idea how to do the second one i just kind went for it :p

safe radishBOT
#

@teal gate Has your question been resolved?

teal gate
#

<@&286206848099549185>

oak urchin
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yes.

kind fractal
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yeah your graph is correct, so follow it. You have 3 different intervals here

kind fractal
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each of these intervals have a top function and a bottom function

teal gate
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ohhhh so i solved for the first interval

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kinda

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just for the bounds

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which would be 4, 2

kind fractal
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ok those are the intersections of the parabolas

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the first interval from the left would go from x=1 to ...

teal gate
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2? ish

kind fractal
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yes

teal gate
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ohhh yeah we just solved for that

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🤦‍♂️

kind fractal
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so those are the bounds for the integral

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(first integral)

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when calculating are, the integrand is top - bottom

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do the same for the other regions

teal gate
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so the bounds for each three respectively are 2 and 1, 4 and 2, and 5 and 4

teal gate
kind fractal
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follow your shetch

teal gate
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ohhhhhhhhhhhhhhh

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i see

teal gate
kind fractal
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by 2,1 you mean..

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$\int_1^2$

flat frigateBOT
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ELeonardo

kind fractal
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?

teal gate
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yeah

kind fractal
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ok

teal gate
#

sorry idk how to do that

kind fractal
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well you usually write it all in the same integral

teal gate
#

so like int2,1 (x^2-6x+10) - (-x^2+6x-6)dx

kind fractal
#

yes

teal gate
#

ohhh okay

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i think i get it

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so smt like that should be the answer

kind fractal
teal gate
#

cool cool

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tysm

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.close

safe radishBOT
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honest mortar
#

how do I interpret this x|x≠2

safe radishBOT
buoyant shadow
#

maybe it's a set that has everything except 2

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if it's {x|x≠2}

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i guess it can;t be that without {} so no need to guess

honest mortar
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{x|x≠2}

buoyant shadow
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right, so it's a set that has no 2, but has everything else

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U \ {2} in other words

honest mortar
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so ≠ means the number can't be used?

buoyant shadow
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no it measn not equals

honest mortar
#

that's what I mean, x can be very number but 2?

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nvm I get it thank you

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.close

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teal gate
#

hey!

safe radishBOT
teal gate
#

im pretty sure i found a, i have the integrals for b setup (hopefully) i just have no idea if i got a right or my setup for b right and any help would be great

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ill send a pic of my work <3

tardy mango
teal gate
tardy mango
#

oh oop

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mb

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ok that's fine

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lemme check b

teal gate
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no its okie :)

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so A is completely right then?

tardy mango
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ok hello discord decided to die

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a is fine

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for b these two should be switched

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y=x makes a larger solid than y=x^3

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also I don't think you need the third integral

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but I could be wrong

safe radishBOT
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@teal gate Has your question been resolved?

teal gate
#

ohhhh

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uhmmm

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why wouldnt i need the third

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or idk

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thanks tho

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wait yeah when u reflect over a point that isnt touching i think id need to have the r(3)

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is there anyway someone else can look at it to see if the third integral is needed

safe radishBOT
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teal gate
#

.reopen

safe radishBOT
#

teal gate
#

can someone look at it when u have a chance!

safe radishBOT
#

@teal gate Has your question been resolved?

teal gate
#

:,(

#

.close

safe radishBOT
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nimble tartan
#

Hey I was hoping someone could help me with these concepts. They're from an economics textbook but this discord is more active than the econ one and it's pretty much all math.

nimble tartan
#

I was hoping someone could help me with the difference between strong monotonicity monotonicity, and local non satiation
in principle I get the definitions
but, say we have a vector of two goods. if we assume strong monotonicity, then y>=x means y is preferred to x
this condition implies monotonicity, and local nonsatiation
so say we have two bundles (x_1, x_2) and (y_1, y_2)
let x = (1, 1) and y = (1, 1+e/2) for any e>0
as far as I understand the definitions, y would be preferred to x under strong monotonicity AND under local nonsatiation, but not under monotonicity

#

sorry I should mention that squiggly > is a binary relation

safe radishBOT
#

@nimble tartan Has your question been resolved?

safe radishBOT
#

@nimble tartan Has your question been resolved?

final halo
#

well what does >> mean

nimble tartan
#

a vector is strictly larger to the other vector

final halo
#

based on what?

nimble tartan
#

[1 , 1 , 1] >> [0, 0, 0] but [1,0,0] is not >> than [0, 0, 0]

safe radishBOT
#

@nimble tartan Has your question been resolved?

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winter whale
#

x^x^3 = 36

safe radishBOT
opaque bolt
#

$x^x^3 = 36$

flat frigateBOT
#

Jatin
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

opaque bolt
winter whale
#

The first one

lean otter
#

write it as (x^x^3)^3 = 36^3

then try msking both sides of the form y^y for some y each side

quasi bison
#

@winter whale do you mean $(x^x)^3$ or $x^{(x^3)}$? these are not the same.

flat frigateBOT
opaque bolt
#

@winter whale whats the ans?

quasi bison
opaque bolt
quasi bison
#

i was asking OP what they meant. i was not asking you, @opaque bolt.

opaque bolt
#

i alrdy asked whats the que he said me that only

quasi bison
#

oh yes sorry i see it now

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scrolled right past it

opaque bolt
#

-__-

#

Mistav Ded GGs

fleet tendon
#

tetration problem?

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Oh nvm it's nested

opaque bolt
safe radishBOT
#

@winter whale Has your question been resolved?

desert juniper
#

how are you allowed/expected to solve it? what's the syllabus that you're currently on?

opaque bolt
#

i have a soln but dont know it right or wrong

desert juniper
#

i do have an exact solution, but i want to know what he is expected to do

opaque bolt
desert juniper
#

we're not supposed to give the answer directly

opaque bolt
#

dm ?

winter whale
#

Here

opaque bolt
#

u got it right?

winter whale
#

I knew it

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I was just asking yall

desert juniper
#

that would be correct

winter whale
#

This was an Olympiad question

desert juniper
#

the way i solved it initially would not be accepted on the olympiad :3

winter whale
#

Well regardless yall ggs

opaque bolt
winter whale
#

💀

desert juniper
#

what, you dont like being tested to keep sharp?

opaque bolt
#

anyways if its done the .close?

winter whale
#

.close

safe radishBOT
#
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dull sequoia
#

ok so i need some help clarifying these wack ass words in logic:
A only if B means A => B
A if B means B => A
A if and only if B means A <=> B
A unless B means A => B

are these right?

dull sequoia
#

mostly just the only if and unless parts

static flame
#

A only if B means B has to happen for A but B can happen without A

A if B means A has to happen for B but A can happen without B

A if and only if B means if one or the other condition is satisfied, the other condition must exist, so in that way it’s “bidirectional”

A unless B means A happens in all scenarios except those where B happens

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but still if you think of them as A —> B and B—> A it makes more sense why if and only if could be an arrow pointing in both directions

desert juniper
#

So you want to translate the plain english to logic, correct?

#

The first three would be somewhat right (you'd use A -> B, B -> A and A <-> B in logic usually, the double line usually is used in maths because typically assumes that you already come from true statements)
The fourth one would be:
¬B -> ¬A

wet pecan
#

I think fourth is (not A only if B) i.e. (not A -> B)

static flame
#

Yeah you’re right

safe radishBOT
#

@dull sequoia Has your question been resolved?

dull sequoia
#

no wait that's not right

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not B => A

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you can't win unless you finish first

you didn't finish first => you cant win

#

hmm that's true

safe radishBOT
#
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normal cloud
#

I asked this question earlier but the anwser we came to as a conclusion was wrong

normal cloud
#

MelMetal was helping me i think

harsh parcel
#

is it wrong?

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huh

normal cloud
#

yea the anwser is 17496

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omds

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im so sorry

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i literally came in to check the anwser

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and i remembered it wrong

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then i checked my work

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because im driving

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ahh

harsh parcel
#

4 x 6 x9 x9 x9 is right

normal cloud
#

so sry

harsh parcel
#

i didnt

normal cloud
#

its right

harsh parcel
#

calculate it

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but logically right

normal cloud
#

yes it is

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sorry

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.close

safe radishBOT
#
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elfin badge
#

Well in the above question the cylinder cut's the another one and my teacher told me that the sphere is obtained and the projection will be circle But I think that we will get cylinder as a cutted region what do you think about the answer

lethal musk
#

,rotate

flat frigateBOT
elfin badge
#

<@&286206848099549185>OhNo_cat

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

elfin badge
#

Ok sorry about that I was a little impatient

sweet mica
#

It is the projection on the plane

#

It can't be a cylinder

elfin badge
#

Well I know the projection is cylinder
But I am talking about the cutted region whether it is cylinder or sphere
But both the 3d shapes have same projection and that is circle

#

<@&286206848099549185>
now I can use this tag right

rich meteor
#

can u help me

#

😭😭

safe radishBOT
#

@elfin badge Has your question been resolved?

elfin badge
#

No

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red talon
safe radishBOT
red talon
#

is this correct

glad gyro
#

Have you tried to verify with a truth table?

#

It looks correct though yes

red talon
#

I did all in my head just making sure

#

👍

#

how about this one

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strange glade
safe radishBOT
strange glade
#

Where did I go wrong in part b

#

I feel like I did it correctly

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craggy trout
#

I dont understand why this evaluates to b and not d?

haughty fern
#

show ur work

craggy trout
#

There was no work really. I just used theorem 1 here

calm bridge
#

those are not theorems.

calm bridge
#

x = (3sinu)/2

craggy trout
calm bridge
haughty fern
#

its not same

craggy trout
#

Ah, my bad

clear blade
#

factor out sqrt(4) from the denominator

#

then use your theorem

craggy trout
#

Will give it a shot, thanks!

#

[\int \frac{1}{3-2x}dx]

flat frigateBOT
#

dopediscorduser

craggy trout
#

Like this?

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dusky harbor
#

Hello. Calculus questoin, I got confused by this "prove" question.

dusky harbor
#

Prove that $\overline{z+w} = \overline{z}+\overline{w}$

#

wait

flat frigateBOT
#

HqppyFeet

dusky harbor
#

there

#

I didn't fully understand how to proceed with this. I made it so that z=x+yi and w=a+bi

#

thereafter the conjugates of these two would be \bar{z}=x-yi and \bar{w}=a-bi... but what

twin jetty
#

How would you express z+w in (...)+i(...) form?

dusky harbor
#

the |r|(cos(theta) + isin(theta))?

#

hmm

twin jetty
#

You could, but it's easier if you keep things in Cartesian form

dusky harbor
#

hm? didn't understand. without the r?

#

Or how do i keep it in cartesian form?

forest sorrel
#

can someone help lol

twin jetty
#

z + w = x + iy + a + ib = (x + a) + i(y + b)

dusky harbor
twin jetty
dusky harbor
#

thank you ❤️

twin jetty
#

No worries! It's easy to overthink proofs

dusky harbor
#

.close

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dusky harbor
#

nvm

#

hehe

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faint hazel
#

hi i need help with math can i send it here?

spare forum
#

yes

faint hazel
#

I need to calculate the length x of the segment marked in red

earnest mica
#

Start by calculating the side lengths in each right angled triangle starting from the biggest one the one with 36,39

faint hazel
#

but i don't understand how

earnest mica
#

Using pythagorean theorem

faint hazel
#

i don't understand pythagorean theorem

#

is there another way?

earnest mica
#

I don't think i know any other ways no

safe radishBOT
#

@faint hazel Has your question been resolved?

spare forum
#

for this youre gonna need the Pythagorean theorem, which states:

c^2 = a^2 + b^2
c is the longest side of the triangle (the hypotenuse) and its opposite to the right angle
a & b are the two other sides which are next to the angle

faint hazel
#

Like this?

#

Is it right?

spare forum
#

careful we said c is the side opposite to the right angle

#

in this case we can see that the side opposite to the right angle (c) is 39, so you just have to solve for a

faint hazel
#

So I got the answer of the largest triangle wrong?

spare forum
#

yeah you need to solve for a since you have c already

#

again c is the longest side and is opposite to the right angle

faint hazel
#

Is it right now?

#

nvm

#

it s not

spare forum
#

yes!

faint hazel
#

Yassssss

#

But it s not done right?

spare forum
#

you gotta repeat it a few more times but its the same thing just different numbers

#

now using the new a = 15 side you continue with the next smaller triangle as rosa said

#

and remember to check which side is the c side for the next triangle 😉

faint hazel
desert pivot
#

then x =

#

@faint hazel

faint hazel
#

I got

desert pivot
#

no

#

it's +

#

n0t -

#

@faint hazel

faint hazel
#

Ohhhh yeaaa

#

Sorry

#

I forgot

#

Okayy nice, Thank you very much. @spare forum and @desert pivot

#

But I have one more task that I don't understand

desert pivot
faint hazel
#

I need to calculate the ABC of a triangle
a) Angle sizes
b) Edge lengths
c) And the inside of the triangle

desert pivot
#

the total of angels = 180

#

then we got x

#

ok

faint hazel
#

But how do you do solve it?

desert pivot
#

get the x first

#

??

faint hazel
#

Where is x?

desert pivot
#

x =13

faint hazel
#

I don't understand

desert pivot
faint hazel
#

How did you get the answers?

faint hazel
spare forum
#

what Ali or Alj im not sure is saying is that the three angles A B C when added are equal to 180 degrees, so

A + B + C = 180

then we substitute the equations for A B and C in there, solve for x and youre good to go from here :)

#

also for the sides you use the pythagorean formula again but this time solving for y

faint hazel
#

But how do you know that angle A is 53

spare forum
#

so in the formula A + B + C = 180 substitute all the info of the picture in there and solve the equation for x

#

then plug in that x to the individual formulas for A B and C to find them

faint hazel
#

Ok

#

Thank you very much for your help

#

.close

safe radishBOT
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chrome berry
safe radishBOT
chrome berry
#

I thought average velocity is slope

stray socket
#

It is

#

Show me your work

chrome berry
#

i tried the first one

#

where it'd be (2,28) and (3,54)

#

then did slope formula of
54-28 / 3-2

#

got 26, it wasnt right

stray socket
#

It's asking for the 3s starting from t = 2

#

So you need to find the slope between t = 2 and t = 5

chrome berry
#

So find slope with (2,28) and (5,102)

#

ah okay got it

#

@stray socket could you explain this one please?

#

I thought it'd be (x+h) (or a+h) bc 1 = a

#

With that problem, it leads me confused onto this one also

stray socket
#

Think about that

safe radishBOT
#

@chrome berry Has your question been resolved?

chrome berry
#

(x)^13?

#

hmm thats right but that makes no sense ot me

stray socket
#

$\lim_{h\to 0}\frac{(x+h)^{13} - x^{13}}{h}$

flat frigateBOT
#

Umbraleviathan

stray socket
#

Now look at the limit on your screen

#

What does x =

chrome berry
stray socket
#

So what the function, and where is it evaluating its derivative at?

chrome berry
#

(x)^13

chrome berry
#

@stray socket

stray socket
#

Same deal. 16 = 2^4

chrome berry
#

rather I get how theres 16

#

got it

#

okay thank you

#

.close

safe radishBOT
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random rivet
#

how do i do 14

safe radishBOT
azure horizon
#

If the cosine of theta is root 3 / 2, then you can use the inverse cosine of root 3 / 2 to find theta

lilac patio
#

do you know your unit circle?

random rivet
#

yes

#

i kinda forgot

#

this is like a review sheet

#

i just inverse right

lilac patio
#

,tex /.unitcircle

#

oops

#

,tex .unitcircle

random rivet
#

yea i got it ty

#

i think

#

its just

#

inverse

#

right

#

i forgot

lilac patio
#

no you should have those values memorized

#

from the unit circle

random rivet
#

ouh

#

help

#

acc

lilac patio
#

look up the unit circle

random rivet
#

ouh shoot

#

i remmeber

random rivet
lilac patio
#

cos is x sin is y for the ordered pairs

random rivet
#

wait

#

can u explain that again

#

i dont get that

#

😭

random rivet
lilac patio
#

there's ordered pairs for specific angles

random rivet
#

yes

lilac patio
#

as you can see from the image

#

in the form of (x,y) since its cartesian coordinates

random rivet
#

yes

lilac patio
#

the costheta is the x values

#

sintheta is the y values

random rivet
#

ouhh

lilac patio
#

so for 30 degrees

random rivet
#

x

lilac patio
#

cos30 is sqrt3/2

#

sin30 is 1/2

random rivet
#

how did yk sin

#

bec theres diff sqrt3/2

#

on it

#

why not -1/2

random rivet
lilac patio
#

it tells you

random rivet
#

but theres diff

#

sqrt 3/2

lilac patio
#

cos150 is also sqrt3/2 yes

random rivet
#

😭

lilac patio
#

in your problem it says theta is from 0-90

random rivet
#

yea

#

ouuh

#

that one is over

#

330

#

okok ty

#

.close

safe radishBOT
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lean otter
safe radishBOT
lean otter
#

How do I make L a single surf

#

Sure

#

Surd

safe radishBOT
#

@lean otter Has your question been resolved?

outer robin
#

don't you have it written correctly there?

lean otter
#

<@&286206848099549185>

outer robin
#

buddy I think that's a single surd unless you're looking for sqrt(288)

lean otter
#

That

#

Is the answerkey

#

How to get that

outer robin
#

when you went from sqrt(4) * sqrt(3) = 2* sqrt(3)

#

you converted sqrt(4) to 2*sqrt(1)

#

sqrt(1) = 1

#

so to put something back under that root sign (forgetting what it's called right now)

#

you'd square it

#

i.e. 2 = sqrt(2^2) = sqrt(2 * 2) = sqrt(4)

#

so do you see what doing the same to 12 would look like?

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

Wait i still@dont get it

outer robin
#

sqrt(288) = sqrt (2 * 144) = sqrt(2) * sqrt(144) = sqrt(2) * sqrt(12 * 12) = sqrt(2) * sqrt(12^2) = sqrt(2) * 12

#

@lean otter

safe radishBOT
#

@lean otter Has your question been resolved?

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frail trench
#

What mistake did I do in tryna solve for x

empty gyro
#

I can't read your last line

rocky ferry
#

how did you get from -5x + 42 = 12 to 5x=54

frail trench
#

Subtract 42 from both sides

#

Ohhh

#

Tht was negative

#

Mb gang

#

.close

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cobalt acorn
#

Factor 4x^2-27x-40 = 0. Answer is (x-8) (4x+5) = 0 at least without fully solving it's the answer. My question is why isn't it (2x and (2x since 4 is factorable by 2 and 2

quasi bison
#

well you could write it as (2x - 16)(2x + 5/2) but that is a lot uglier

cobalt acorn
#

I had another question where 6x^2 was 6x and x instead of 2x and 3x

#

So I need to understand why

quasi bison
#

it's entirely a matter of convenience and desire for integer coefficients, nothing more..

#

i really don't know what else to say, sorry.

cobalt acorn
#

Ok well thanks for trying I still didn't understand but thanks

safe radishBOT
#

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oak ledge
safe radishBOT
oak ledge
#

Hello I have put images of my working and the answeri

#

I would like to know where the sin(X) went

sinful grove
#

u-substitution while integrating sin(x)e^(-cos(x))dx
u = -cos(x) du = sin(x)dx --
y = (e^u)du = (e^u) + C = e^(-cos(x)) + C

oak ledge
#

Oh I see thanks for help

#

.close

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safe radishBOT
flat frigateBOT
#

choufleur
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wise sky
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.reopen

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amber timber
safe radishBOT
amber timber
#

How do you simplify this?

#

I dont see how i can do that

#

I got it to this

flat frigateBOT
#

September 1 enjoyer

amber timber
#

RHS and LCM?

#

What does it stand for?

flat frigateBOT
#

September 1 enjoyer

amber timber
#

Sorry i study in sweden

#

Yea

#

And lcm

#

Thx

#

Hmm

flat frigateBOT
#

September 1 enjoyer

#

September 1 enjoyer
Compile Error! Click the errors reaction for more information.
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amber timber
#

,rotate

flat frigateBOT
amber timber
#

,rotate

flat frigateBOT
amber timber
#

,rotate

flat frigateBOT
amber timber
#

I have no idea what to do from here

sinful grove
#

You can cancel (s+t)

amber timber
#

Really?

#

But its addition

#

Oooh

#

Wait

#

Aaaaaah

#

Got it

#

Thanks!

#

.close

safe radishBOT
#
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wraith prism
#

I didn't understand the argument

safe radishBOT
wraith prism
#

They should use [] bracket?

wind stream
#

well if both endpoints are included, it wouldn't be a function anymore

wraith prism
#

But why?

#

I didn't understand it

wind stream
#

For example, with their first definition, if it were to be [-pi, pi], Arg(-1) could be pi or -pi

#

And then again, this wouldn't make Arg(z) a function at all

wraith prism
#

Ohh bijective

#

It should be one one?

wind stream
#

that's not what bijectivity is...

#

what I'm saying is that for z=-1, the function Arg would have two outpus if the range were [-pi, pi]

#

Bijectivity on the otherhand says that every element in the codomain can be mapped to

#

and to be clear, the definition of "function" that I'm talking about here is a single-valued function

wraith prism
#

Yes i was thinking that the function should get one value only

#

Okay so another question is (0,2π]

#

Why are we using two different terms for range?

wind stream
#

two different terms for range?
Can you specify what these are? Since I don't understand what you mean by "different terms"

wraith prism
#

(0,2π] and (-π,π]

#

Why don't we take one interval?

wind stream
#

we actually do. Generally, the defintion for principal argument will output values in the interval of (-pi, pi]. But you can also use another definition that suits your preference.

#

But of course, be consistent with it

#

like they said

...there is no general convention about the definition of principal value...

wraith prism
#

Can we not see e^(ithita)

#

Range

wind stream
#

I don't think I get your question
Are you asking if we can find what the range of f(theta) = e^(itheta) is or...

wraith prism
#

I meant can we not find a range of this function?

#

Pr interval for this function like period?

#

@wind stream

#

Period of it?

#

,w period of e^(i thita)

flat frigateBOT
wind stream
wraith prism
#

In the file it is just euler formula

wind stream
#

alright, so you are asking about the range of e^(itheta) = cos(theta) + isin(theta)?

#

it's not really something that has a "range"

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it's not really a function that outputs anything, just an equality that is true

wraith prism
#

I see

wind stream
#

if you are asking about the function f(theta) = e^(itheta) for real values of theta however. This function outputs complex numbers that has magnitude of 1

wraith prism
#

,w range of arctanx

wraith prism
#

Why are we using interval (-π,π] it should be (-π\2, π\2]?

wind stream
#

I don't see why it should be (-pi/2, pi/2]

wraith prism
#

Is it not arctan (y/x)

wind stream
#

no, generally Arg(z) != arctan(y/x) for z = x+iy

#

you will see why this is a problem for complex numebrs that lie in the second and third quadrant on the complex plane

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and of course, evidently through your wfa search

wraith prism
#

I can't search for it

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Can you please do it for me?

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So that i can visualise

#

Thanks for that complicated part explanation

wind stream
#

Iirc, there is a MathStackExchange for this discussion

wraith prism
#

Please provide that link

wind stream
#

or you can search it...

wraith prism
#

I can but i wanted it from you

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Thanks

wind stream
#

oh wait nvm, it's not that

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There was one where they had a derivation for it

#

oh well. Can't find it.
Anyway, the derivative is as simple as considering cases. The first obvious one is complex numbers that is in first and fourth quadrants. Meaning their real parts is positive. And these numbers have argument ranging from (-pi/2, pi/2)
Then, the second case if for numbers that are in second quadrant, these have arguments ranging (pi/2, pi], Hence you want to add pi, giving you arctan(y/x) + pi
And similarly, you have a case for complex numbers in the fourth quadrant
Then consider the cases where z is (pure) imaginary as well, since this is the case where the real part (i.e x) is 0

#

You actually don't need to specify that Arg(z) is undefined for x=y=0. This is already implied if you don't specify it

safe radishBOT
#

@wraith prism Has your question been resolved?

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magic tusk
#

how to simplify to simplest form

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magic tusk
flat frigateBOT
#

Dyssrupt

calm bridge
#

use the first one.

magic tusk
#

then what?

#

a = 30?

calm bridge
#

no

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its simplified

magic tusk
#

oh

#

so keep it in log form

calm bridge
#

yeah

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karmic glacier
#

Hello

safe radishBOT
karmic glacier
#

If I were to use the integral formula for finding the length of a curve

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To solve for y(x) = 2 + 5x^3/2, for 0 ≤ x ≤ 10

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Would I just integrate the 5x^3/2 then apply the limits to find the solution

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so for example 7.5x^1/2 into the formula

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sqrt(1+(7.5x^1/2)^2))

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sqrt(1+(7.5(10)^1/2)^2))-sqrt(1+(7.5(0)^1/2)^2))

little venture
#

You integrate the whole expression, not just the stated derivative.

karmic glacier
#

So I would sub u for 1+(7.5x^1/2)^2)?

little venture
#

You are trying to solve $\int_{a}^{b}\sqrt{1+\left(\frac{15}{2}\sqrt{x}\right)^{2}}dx$

flat frigateBOT
#

Chixen

little venture
#

I guess u sub would work

karmic glacier
#

$\int_{0}^{10}\sqrt{1+\left(7.5x^(1/2))^{2}}dx$

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fug, im not good with that bot

little venture
#

Try $\frac{p}{q}$ instead

flat frigateBOT
#

Chixen

little venture
#

or $\sqrt{x}$

flat frigateBOT
#

Chixen

#

Asahi
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karmic glacier
#

Anyways, all I wanted to know was weather I could just sub the limits in at that point or weather u needed to be subbed in

little venture
#

Oh, that’s what you were asking

#

I think integrating first is quite important.

karmic glacier
#

Yeah, sorry if I phrased it badly

#

So I'm on the right track with it being u = 7.5x^1/2?

little venture
#

Yeah that for 1+ that.

karmic glacier
#

ofc ofc

#

thanks

little venture
#

Wait no

#

nonono

karmic glacier
#

oh?

little venture
#

There’s a square

karmic glacier
#

u = (1+7.5x^1/2)^2?

little venture
#

No, where is the square in the integral?

karmic glacier
#

2 + 5x^3/2 should equal 7.5x^1/2 when integrated no?

#

dropping the power of 3/2 infront of the number (5x) and then reducing the power by 1

karmic glacier
#

.close

safe radishBOT
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tepid walrus
#

Sending this again cause I forgot to say "no" to the bot >_> Basically, new to complex analysis, cauchy residue theorem and whatnot. Tried this integral, and the result I get is not the same as wolfram's. So I need help understanding what I did wrong. Don't hesitate to ask me to clarify bits of the image as it's not very good :)

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@tepid walrus Has your question been resolved?

pseudo scroll
tepid walrus
#

Oh perhaps yeah

safe radishBOT
#

@tepid walrus Has your question been resolved?

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@tepid walrus Has your question been resolved?

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@tepid walrus Has your question been resolved?

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native robin
safe radishBOT
native robin
#

how to do part D

outer robin
#

what did you get for (c) ?

native robin
outer robin
#

so the function for chloe's velocity between 0 and 2 is te^(4-t^2)) and you can use MVT to get B for that interval

#

then you use an equality and solve for t in chloe's equation

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and see if that t is within the range

native robin
#

dont i have to find if there is a t such that B(t)=C(t)

outer robin
#

yes

#

ah I messed up one piece but there's an easier way

native robin
outer robin
#

using the intermediate value theorem

#

yeah

#

if you plug in values of 0, 1, and 2 into C(t)

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then you can see the values of B(t)-C(t) and see if they would go through 0

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tacit cosmos
#

How do you integrate

safe radishBOT
tacit cosmos
#

f'(x)/f(x)?

#

In terms of x?

fleet tendon
#

consider ln f(x)

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what's the derivative of that w.r.t. x?

tacit cosmos
#

1/x?

fleet tendon
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not quite

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This can be any f

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so you must use chain rule

tacit cosmos
#

hmm...

#

Oh

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f'(x)/f(x)?

fleet tendon
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Yes

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So does that give you any ideas?

tacit cosmos
#

But we solved this in reverse, like how are we supposed to know we start from ln f(x)

solid shell
#

One of the first integration methods we learn is a great tool for that situation

fleet tendon
#

When you do u-substitution

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what do you do?

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You solve for u'

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then obtain du

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then how do you plug that back in the integral?

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in particular, what is du

tacit cosmos
#

Hmm

#

Just a replaced version of whatever was in the integral?

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Like dx?

solid shell
#

$\int{\frac{f'(x)}{f(x)}}dx$, let $u=f(x)$ and $du=f'(x)dx&, $\implies \int{\frac{1}{u}}du$

flat frigateBOT
#

lexitorius
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fleet tendon
#

👆

tacit cosmos
#

Oh

fleet tendon
#

Do you understand now?

tacit cosmos
#

So the answer is we just solve it using u sub

#

Yeah

fleet tendon
#

Cool

tacit cosmos
#

Got it thanks

safe radishBOT
#

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clear mist
#

Using interval notation, describe the set of all numbers x such that |x^2 + 8x| > 8

clear mist
#

not too sure on how or where i should start

#

need some guidance

clear blade
#

write it as two inequalities without the absolute value

#

if you’re unsure on how to do this, think about how you would do it for |x| > a

safe radishBOT
#

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@clear mist Has your question been resolved?

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@clear mist Has your question been resolved?

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orchid glen
safe radishBOT
orchid glen
#

Help, what is this

#

What am i supposed to do here

bold ferry
#

speed = distance / time

orchid glen
#

Ok

#

I understood that part

#

This is supposed to be Solve inequalitys, and I’ve literally got no Idea what to do with this one question

bold ferry
#

you are given the distance and the time

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and I guess they want an inequality, so it would be speed >= distance / time

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as it says at least 250 miles

orchid glen
#

Im sorry I have a smooth brain, Ima need a tiny bit more help

bold ferry
#

well

#

where exactly are you confused?

orchid glen
#

Everything, I only got 2 numbers to work with, and it’s telling me to find the average speed with only those 2 numbers

bold ferry
#

yeah

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do you understand that the speed of something is equal to its distance divided by time?

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like your car

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drives at speeds in km per hour

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(or miles per hour)

orchid glen
#

I dont have a car

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Im sorry but uhhh, this is Sophomore homework

bold ferry
#

:/

orchid glen
#

I am desperate

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Otherwise i wouldnt be here

orchid glen
#

Its a No

bold ferry
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what part do you not understand

orchid glen
#

Never mind im sorry for wasting your time

bold ferry
#

no you aren't wasting my time lol

#

i'm here to help