#help-23

1 messages · Page 135 of 1

somber widget
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bisector?

hasty falcon
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what kind of it?

somber widget
#

divides the angle in half?

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so its equal angles?

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if that is the case would this mean CD and DB are the same?

hasty falcon
hasty falcon
hasty falcon
#

this can be solved without this

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tell me the definition of sin, cos and tan now

somber widget
#

sin= o/h cos = a/h tan = o/a

hasty falcon
#

what are this o, h and a?

somber widget
#

opposite hypotenuse adjacent

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how can we find CD though?

hasty falcon
#

hmm..that's correct then

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you tell me

somber widget
#

uhm...

hasty falcon
#

can you find BD?

somber widget
#

yeah

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i did

hasty falcon
#

how?

somber widget
#

tan ratio

hasty falcon
#

great!!

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how about BC?

opaque bolt
somber widget
opaque bolt
#

ohh w8 AD is bisector got it

hasty falcon
#

why were you stuck then at all?

somber widget
#

5.6!

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i think i just forgot them all tbh

hasty falcon
#

cool

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you can close this!

somber widget
#

thank you btw

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great help work

#

.close

safe radishBOT
#
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lament delta
#

@hasty falcon You're very good at explaining math, just like a teacher!

somber widget
#

agreed

safe radishBOT
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hasty falcon
#

thanks a lot!

safe radishBOT
lament delta
#

:)

hasty falcon
#

.close

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inland orchid
#

What do i do next?

safe radishBOT
idle relic
#

Are you able to evaluate (2/5)^3? Also, I'm guessing calculators are not allowed.

safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lament delta
#

Oops I didn’t know that tho

#

Just new here

safe radishBOT
#

@inland orchid Has your question been resolved?

idle relic
#

Then you can first calculate 0.4^3, then divide 8 by that number.

safe radishBOT
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keen steppe
safe radishBOT
#

Please don't occupy multiple help channels.

keen steppe
#

.status

#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
keen steppe
#

1

burnt notch
#

You're asked for the minimum perimeter, right?

#

So first of all, find the expression of the perimeter 😅

keen steppe
#

oops

burnt notch
flat frigateBOT
burnt notch
#

Yes, now you have to find the minimum of this (hence this should ring you a bell about optimization problems)

keen steppe
#

to find minimum perimeter we prolly need to differentiate P with respect to theta

twilit spindle
keen steppe
#

set it equal to 0

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;v

burnt notch
#

Yes (or better, study its sign)

safe radishBOT
#

@keen steppe Has your question been resolved?

keen steppe
keen steppe
keen steppe
flat frigateBOT
keen steppe
keen steppe
flat frigateBOT
keen steppe
#

,rcw

flat frigateBOT
keen steppe
#

<@&286206848099549185>

#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
keen steppe
#

4

keen steppe
keen steppe
burnt notch
#

Yes, it's correct 💪

#

Sorry for the delay

#

,w minimize 90 tan(x) + 40cotan(x) for 0 < x < pi/2

flat frigateBOT
burnt notch
safe radishBOT
#

@keen steppe Has your question been resolved?

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safe radishBOT
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timber gate
#

can someone help me with this question taht is definitelly a math equation

burnt notch
timber gate
#

oh

#

oop

fast jungle
burnt notch
#

Ahn I noticed it right now lol

timber gate
#

oh i actually solved it nice

fast jungle
#

Oh

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great

timber gate
#

dont think anyone would be curious but !

#

.end

#

.close

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fast jungle
safe radishBOT
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bold skiff
#

i need help with arithmatic sequences.

(a_n) is an arithmatic sequence. The common difference of (a_2n) is 8. What is the common difference of arithmetic sequence (a_3n+1)?

bold skiff
#

how would i go about solving this? it would be good to mention that i have no idea where to start solving

#

solved

#

.close

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bold skiff
#

another sequences 😭

safe radishBOT
bold skiff
#

a_n is an arithmatic sequence such that (a_2 + a_4):(a_3 + a_7) = 1:5. find the integer n such that a_16 =na_1

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
bold skiff
#

1

tardy mango
#

Consider rewriting the terms in terms of $a_1$ and $d$

flat frigateBOT
#

Civil Service Pigeon

tardy mango
#

See if you know what to do after that

tardy mango
safe radishBOT
#

@bold skiff Has your question been resolved?

bold skiff
safe radishBOT
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safe radishBOT
#

@lean otter Has your question been resolved?

fallow cairn
#

Would you be able to provide more context?

safe radishBOT
#

@lean otter Has your question been resolved?

frozen summit
#

Instantaneous velocity is the tangent line of the graph given by position over time
If there are two lines, then your graph is wrong or something

safe radishBOT
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granite cape
#

Could someone help me out with this problem?

granite cape
#

How would I find the other two solutions?

thin bridge
#

apply factor theorem, do division

#

determine zeroes of the quadratic factor

safe radishBOT
#

@granite cape Has your question been resolved?

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lean otter
#

Hello.

So sometime a ATGM ( Anti Tank Guided Missile ) is lauched by someone i need to destroy this missile before it hit my tank and destroy it. On my tank i dispose of a turret on the top of my tank i want to destroy that missile with it. For that i need the angle predicted with the speed of the bullet in my turret and destroy the missile.

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

<@&286206848099549185>

safe radishBOT
#

@lean otter Has your question been resolved?

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granite cape
#

Just had a quick question regarding complex numbers

granite cape
#

I'm aware that if the real part = imaginary part of a complex number the angle formed between the x-axis and the complex number will be 45 degrees

#

However what if the two numbers are the same although one of them is negative like this for example:

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z = m - mi

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will the arguement in this case be -45 degrees?

plucky elk
#

Use demoivre's formula

#

,tex .demoivre

flat frigateBOT
#

riemann

plucky elk
#

x=-45 degrees and n=1

safe radishBOT
#

@granite cape Has your question been resolved?

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open laurel
#

Need help

safe radishBOT
open laurel
final bay
#

how do you find the perimeter of a polygon

open laurel
#

I don’t know

frigid locust
#

perimeter is the boundary of the polygon or u add up all the sides

final bay
#

^

open laurel
#

So would it be like

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15.9

final bay
#

yes

open laurel
#

.close

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safe radishBOT
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lofty ivy
safe radishBOT
lofty ivy
#

Im lost

snow robin
#

,rotate ccw

flat frigateBOT
lofty ivy
#

i need help

frigid spruce
#

why does this look like a test paper🤔🤨

compact canyon
# flat frigate

You could connect 'P' to the very top right corner then making another triangle and figure out the angles and side lengths from there

lofty ivy
#

ok

#

how tho

compact canyon
frigid spruce
#

whats a trial paper, like a practice paper

#

?

compact canyon
#

Basically ye

frigid spruce
#

oh

lofty ivy
#

idk what to do after

#

<@&286206848099549185>

minor ore
#

Use cosine law

lofty ivy
#

ok

#

is the equation:

minor ore
#

If 3 sides are given in a triangle you can find its angles by cos law

lofty ivy
#

8^2 = 20^2 + 15^2 - 2x20x15cosx

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?

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the bottom left?

minor ore
#

Yes

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But use × not x

lofty ivy
#

for what?

minor ore
#

For multiplication

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Because x is usually a variable

lofty ivy
#

oh ok

#

how do u do that symbol

minor ore
#

Idk i have samsung and its just here

lofty ivy
#

oh ok

#

btw is the answer 69 degrees?

minor ore
#

I dont know the exact answer but ill check

lofty ivy
#

aight

minor ore
#

Hmm i got something else but maybe im wrong

lofty ivy
#

what u get

minor ore
#

Ohh yeah its 69 i realised what i did wrong 69.23 to be exact

lofty ivy
#

oh ok thx

#

.close

safe radishBOT
#
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safe radishBOT
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spice kiln
#

Hi! Can someone help me to understand gen. math? I was absent on the first day of class for this subject so I am confused on what my friend have sent me.

spice kiln
#

I am not sure if it is solved or not because I couldn't understand it at all

minor ore
#

They just plugged in values for x

#

$f(x)=x^2+2x+3$

$f(-2)=(-2)^2+2(-2)+3=3$

flat frigateBOT
spice kiln
#

Is it already given of what x is?

#

I'm confused where to find it

minor ore
#

The task was to find f(-2)

#

Aka find f(x) when x=-2

spice kiln
#

so where did the following g came from?

minor ore
#

Pls rephrase your question because i dont get it

spice kiln
#

after the f theres a g and an h solving

minor ore
#

First column f(x) second g(x) third h(x) not rows

spice kiln
#

oh okay okay mb

#

how did the g column became (-1)?

minor ore
#

It was the question to find g(-1) and your friend solved it by plugging in -1 for x in the function 3x-7

spice kiln
#

ohh okay okay

#

i get it now

#

thank you sm!

minor ore
#

You can close with .close

spice kiln
#

.close

safe radishBOT
#
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safe radishBOT
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rare vale
#

How do I get the critical points of $f'(x)=2sin(x)cosh(x)$ to fin the relative extrema?

flat frigateBOT
frigid locust
#

do u know how to find critical points?

rare vale
#

by looking for values that will make the function 0?

frigid locust
#

yeah (f(x)` = 0

rare vale
#

I'm not sure how to do that with cosh x

#

sin(x) = 0 when x=0, right?

frigid locust
#

yes

rare vale
#

how about cosh(x)=0?

#

I saw the answer key in my book. they used pi but Idk where they got it

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i forgot there was a condition

frigid locust
#

im pretty sure cosh(0) is 1

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wait , sin (0) multiplies with the rest , so the answer is 0

#

i only know maxima and minima by 2nd order derivative test and that cannot go future , sorry

rare vale
#

i just learned that sin(Pi) is also zero

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and 2pi gives 0 as well

frigid locust
#

yeah

#

pi is 180 degree

#

2 pi is 360 , sin when parallel to x axis gives 0

rare vale
#

maybe the reason 2pi was not included in the critical points is because there was the -4<=x<=4 condition

frigid locust
rare vale
#

yes. i checked it

#

$f'(x)=2sin(x)cosh(x)$

flat frigateBOT
rare vale
#

okay

#

how do I know what sign im getting when i substitute values to trigonometric functions and hyperbolic functions? is there like a technique?

rare vale
calm bridge
#

sin is 0 at +- pi

#

interval given is -4 to 4

#

so -pi is included

frigid locust
rare vale
#

I see tysm! I finally got it now

#

.close

safe radishBOT
#
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frozen harbor
safe radishBOT
frozen harbor
#

Can someone help me think through a and b

#

Because i keep thinking about them and i feel like they have the same answer but i dont think thats right

#

I dont really know how to think about it

safe radishBOT
#

@frozen harbor Has your question been resolved?

safe radishBOT
#

@frozen harbor Has your question been resolved?

frozen harbor
#

No sir

safe radishBOT
#

@frozen harbor Has your question been resolved?

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little cipher
#

how can i simplify $64^{-\frac{2}{3}}$

safe radishBOT
flat frigateBOT
#

张元英

raw tusk
#

do you know what raising a number to a negative whole power is equal to?

little cipher
#

do i simpliy $\frac{3}{2}?$

flat frigateBOT
#

张元英

raw tusk
#

do you know what raising a number to a negative whole power is equal to?

little cipher
raw tusk
#

wdym this

#

do you know what $x^-1$ is equal to?

flat frigateBOT
raw tusk
#

hell

little cipher
#

1/x

raw tusk
#

apply the same logic to your fraction in order to remove the negative sign from the power

calm bridge
last heath
little cipher
#

so is that the answer

#

3/2

raw tusk
#

no

little cipher
#

64^(3/2)

last heath
#

,tex .exp rules

flat frigateBOT
#

Akira 🍉

last heath
#

apply the last rule

little cipher
#

i still have a doubt

raw tusk
#

use the second and last rule to solve this

little cipher
#

$\frac{64^3}{64^2}$?

flat frigateBOT
#

张元英

little cipher
#

64^1?

raw tusk
little cipher
#

i flipped it

raw tusk
#

flipping doesn’t work here

#

if you have a fraction raised to a negative power then yes tou can flip

little cipher
#

that is what i did

little canyon
#

But it isn't a fraction raised to a negative power

little cipher
#

-2/3?

little canyon
#

You just have 64

raw tusk
#

$64^{-1} = 1/64^{1}$

little cipher
#

dud

flat frigateBOT
little cipher
little canyon
#

You're raising 64 (which isn't a fraction) to the fractional power

#

Only 64/1 is flipped to 1/64

little cipher
#

so how do i do it?

little canyon
#

The fraction 2/3 stays the same

little cipher
#

just give me a step by step

raw tusk
last heath
#

you need to factor the number of 64

little cipher
#

2^3*2^3

raw tusk
#

lets take another approach

#

screw negative exponets

last heath
raw tusk
#

$Whats 64^{1/2}$

flat frigateBOT
raw tusk
#

i love texit

little canyon
#

Lmao

last heath
#

$64^{\frac{1}{2}}$

raw tusk
#

@little cipher do you know how to solce the thing above

last heath
#

ah

little cipher
#

$\sqrt{64}$

flat frigateBOT
#

Akira 🍉

raw tusk
#

perfect

flat frigateBOT
#

张元英

little cipher
#

o

#

wait

little canyon
#

Yes that's right

raw tusk
#

now whats $27^{2/3}$ the same as?

flat frigateBOT
little cipher
#

3^2

raw tusk
#

what

little canyon
#

Where did the 27 go

little cipher
#

no?

#

3^3

raw tusk
little canyon
little cipher
#

but i cancel the threes

raw tusk
little cipher
#

does that mean a no?

#

$\sqrt[3]{27^2}$

flat frigateBOT
#

张元英

little canyon
#

That's actually correct

#

My fauly

last heath
little cipher
#

wdym

raw tusk
little canyon
#

So now, again $whats 64^{-1}$

flat frigateBOT
#

OhmzWithBerries

little cipher
#

1/64

raw tusk
#

brilliant

little canyon
#

Exactly, now combine these 2 rules

little cipher
#

what is $64^{-2}$?

raw tusk
#

use the second rule

flat frigateBOT
#

张元英

last heath
little cipher
#

1/64^2?

raw tusk
#

$x^{-y} = 1/x^{y} no matter what y is$

flat frigateBOT
raw tusk
#

wrong reply

raw tusk
#

Start by «removinh» the negative sign from your exponent

little cipher
#

2/3

raw tusk
#

yes but what does the equation become

little canyon
flat frigateBOT
#

OhmzWithBerries

last heath
#

what

raw tusk
little cipher
#

$\sqrt[3]{2^{12}}$

#

2^3?

last heath
#

oh my days

little cipher
#

lets just forget 2^3

little canyon
#

No it's $\sqrt[3]{64^2}$

flat frigateBOT
#

OhmzWithBerries

last heath
#

no

flat frigateBOT
#

张元英

last heath
#

if your question is asking you to simplify it you need start to factor the number of 64

little canyon
#

Yes

last heath
#

@little cipher do you know how to factor 64

raw tusk
#

i think providing a step by step will make it more understandable for her

little canyon
#

@last heath

last heath
#

it should 6 not 12

#

be

#

,w factor 64

little cipher
#

64^2

#

dud

#

64^2

last heath
#

thats wrong

#

okay here's a hint

raw tusk
little cipher
#

ok

little canyon
raw tusk
#

it’s 2^12

last heath
little cipher
#

you know what

raw tusk
#

oh no

little cipher
#

its called programming and not coding

last heath
#

thats give you something else

little canyon
#

Wrong reply

last heath
little cipher
#

2^3*2^3

last heath
#

no

little canyon
#

Yes

little cipher
#

oh my lord

raw tusk
#

oh no

last heath
#

I asked you to give me two same number that is equal 64

#

number times number

#

like that

little cipher
#

bruv

little canyon
last heath
#

nice

#

so my guess is use 8^2

little cipher
#

i mean youre not finished factoring

little canyon
#

Whats the difference between 2^12 and (8^2)^2

#

She was right

last heath
#

,calc 2^12

flat frigateBOT
#

Result:

4096
last heath
#

,calc 2^6

flat frigateBOT
#

Result:

64
little canyon
#

?

raw tusk
#

i start to question akiras understanding of exponets

#

Time to boot discord on pc

#

mobile cant be used to explain a shit

little canyon
#

Sorry @little cipher well start from the beginning really quickly

little cipher
#

np

little canyon
#

Let's stop arguing about the difference between exponents to the power of exponents

raw tusk
#

Okay, let's go, you're question is the following:
$64^{-\frac{2}{3}}$

flat frigateBOT
last heath
#

it also could be 4^3

raw tusk
#

We first "remove" the negative exponent by following this law:

$x^{-y} = 1/x^{y}$

flat frigateBOT
little cipher
#

x/64^2

raw tusk
#

This means that $64^{-\frac{2}{3}} = 1/64^{\frac{2}{3}}$

flat frigateBOT
last heath
raw tusk
little cipher
#

oh

#

ahh

raw tusk
#

we're one step closer to the mystery

little canyon
raw tusk
#

now that we threw the negative sign in the trash, we begin to try to simplify $64^{\frac{2}{3}}$

flat frigateBOT
raw tusk
#

then just substitute it for the denominator in the fraction $1/64^{\frac{2}{3}}$

flat frigateBOT
little cipher
#

$\sqrt[3]{2^6}$

flat frigateBOT
#

张元英

last heath
flat frigateBOT
#

Akira 🍉

feral relic
#

ah yes here we go again

raw tusk
little cipher
#

(4)(4)(4)

#

so is the answer 1/4?

little canyon
feral relic
#

you can just power it after

#

you root it

last heath
#

uh k

feral relic
#

nvm

little cipher
#

it's you again

feral relic
#

yeps

raw tusk
#

$64^{2/3} = \sqrt[3]{64^2}$

flat frigateBOT
raw tusk
#

Understand that

little canyon
#

^^^^

little cipher
#

i forgot that

#

the squared

little canyon
last heath
feral relic
#

this help channel is becoming a battlefield

raw tusk
little canyon
last heath
#

$64^{-\frac{2}{3}}$

flat frigateBOT
#

Akira 🍉

little cipher
raw tusk
#

akira do you mind letting me take over the explanation then hand it over to you if it doesn't work for me

feral relic
#

doesn't it

raw tusk
#

$64^{2/3} = \sqrt[3]{64^2}$

#

@little cipher do you understand this

flat frigateBOT
little cipher
#

yes

little cipher
raw tusk
#

Okay, let's now try to know what $\sqrt[3]{64^2}$ is equal to

flat frigateBOT
little cipher
#

$1/2^6$?

flat frigateBOT
#

张元英

last heath
little cipher
#

,calc 2^6

flat frigateBOT
#

Result:

64
little cipher
#

aj

last heath
#

,w simplify 64^{-2/3}

raw tusk
#

akira

little cipher
#

brub

raw tusk
#

can we agree that I can take over and then you take once i fail

#

that assumes that i fail

feral relic
#

and 1/16

#

isn't it?

little canyon
little cipher
#

1/2^4

#

2^4^3

#

,calc 2^4^3

flat frigateBOT
#

Result:

1.844674407371e+19
little cipher
#

,calc (2^4)^3

flat frigateBOT
#

Result:

4096
little cipher
#

what am i even solving lol

#

2^4 is the answer?

raw tusk
#

welp
$\sqrt[3]{64^2} = \sqrt[3]{64^2} = \sqrt[3]{4096} = \sqrt[3]{2^{12}}$

flat frigateBOT
raw tusk
#

do you understand this @little cipher

little cipher
#

yes

raw tusk
#

i need another yes to really confirm

little cipher
#

1/2^4

raw tusk
#

do you understand this

feral relic
little canyon
#

I hate texit

little cipher
#

,calc 2^4

flat frigateBOT
#

Result:

16
feral relic
#

screw latex

little cipher
#

i think i am right

#

1/16

flat frigateBOT
#

OhmzWithBerries
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

feral relic
raw tusk
#

$ \sqrt[3]{2^{12}} = \sqrt[3]{2^{4} * 2^{4} *2^{4}}$

#

texit aint responding

#

even texit left this chat

feral relic
raw tusk
#

someone help

feral relic
#

fantastic

little cipher
#

because

#

$\sqrt[3]{2^{12}} = \sqrt[3]{2^{4} * 2^{4} *2^{4}}$

flat frigateBOT
#

张元英

raw tusk
#

$\sqrt[3]{2^{12}} = \sqrt[3]{2^{4} ^ {3}} $

little cipher
#

no space between text and "$"

feral relic
raw tusk
little cipher
#

np

raw tusk
#

THEN WE KNOW THAT $\sqrt[3]{2^{12}} = 2^{4}$

little cipher
#

bro no SPACE

raw tusk
#

god hlep me

flat frigateBOT
raw tusk
#

YES

little canyon
#

yipee

little cipher
#

AIY

#

OK

#

AMAZING

little canyon
#

now add the negative back

#

sorry

little cipher
#

WE SOLVED IT NO?

#

OR DID I MISS SOMETHING

raw tusk
#

you tell us the answre

feral relic
#

the answer is simply 1/16

raw tusk
#

tell us the answer

raw tusk
little cipher
feral relic
raw tusk
#

ok i assume this case closed

#

i need sleep

little cipher
#

I AM THE ONE WHO TOLD HIM IN DMS

little canyon
raw tusk
little cipher
#

STOP USING THAT

little canyon
feral relic
#

||it was a sdsfd*x film||

little cipher
#

ait

#

.close

safe radishBOT
#
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limber pine
safe radishBOT
#

Please don't occupy multiple help channels.

limber pine
#

can someone help

obsidian oracle
#

Write it as cos(...) = ...

limber pine
#

so get rid of the 4 first?

obsidian oracle
#

Even -4

limber pine
#

so rewrite the rhs as 2sqroot(3)/-4?

obsidian oracle
#

You should get $\cos\Big(150+\frac{\theta}{4}\Big) = -\frac{\sqrt{3}}{2}$

flat frigateBOT
#

rafilou2003

limber pine
#

how?

#

whered the 4 go?

obsidian oracle
#

$\frac{2\sqrt{3}}{-4}$ can be simplified...

flat frigateBOT
#

rafilou2003

limber pine
obsidian oracle
#

/2

obsidian oracle
#

So simplify

#

$\frac{2\sqrt{3}}{-4} = -\frac{(-2)×\sqrt{3}}{(-2)×2} = -\frac{\sqrt{3}}{2}$

flat frigateBOT
#

rafilou2003

limber pine
#

when i solved both on the calculator, i got different answers

obsidian oracle
limber pine
#

yes

#

you can do it on your calculator if you want

#

wait

obsidian oracle
#

I know my calculator will give me the same thing, i don’t have to try

limber pine
#

wait nevermind

#

i forgot 1 parenthesis...

#

ill try to solve the rest of the requation now

#

equation*

obsidian oracle
#

Do you know by chance what cos(150) is ?

#

Or cos(30)

limber pine
#

yes

#

i memorized the unit circle.

#

luckily sqroot(3)/2 is a special angle as well

obsidian oracle
#

Yes

#

And so cos(150) = ?

limber pine
#

sqroot(2)/2

#

wait ni

#

wrong thing

#

-sqroot(3)/2

obsidian oracle
#

Yes

#

So we're solving $\cos\Big(150+\frac{\theta}{4}\Big) = \cos(150)$

flat frigateBOT
#

rafilou2003

limber pine
#

ok lemme write this all down

#

back

limber pine
#

?

#

dude...

plucky elk
#

.close

safe radishBOT
#
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kind dove
#

What is meant by effective matrix powering (exponetiation)?

sweet mica
#

A polynomial-time algorithm for calculating Aⁿ

#

That's the common meaning of effective, but it can be different in some cases

kind dove
#

i think they mean this: A^2 = AA, A^4 = A^2 A^2, A^* = A^4 A^4, etc...

sweet mica
#

That's more efective than
A²=AA
A³=A²A
A⁴=A³A
yes

#

But MFEA is more efective xD

safe radishBOT
#

@kind dove Has your question been resolved?

safe radishBOT
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mystic marsh
safe radishBOT
mystic marsh
#

so for #2.

#

teacher wrote parent graph: y = e^x

#

and Im just wondering why he wrote it and drew it

#

why is it important?

jagged vault
#

Because y = e^x is the exponential function in its purest form without any modifications

#

So your teacher wrote it to help you visualize the modifactions made in the problem function

lean thorn
#

a parent function is basically the "base" function of which you do your transformations to.

Same thing with something like y = 3x - 2. Here, y = x is the parent function

mystic marsh
#

ooooh wait

#

so it's like

#

shifted up by 1

#

and shifted right by

#

umm

#

3?

lean thorn
#

bingo!

mystic marsh
#

ooh i see why it's important now lol

mystic marsh
#

alrighty thanks guys

#

🙂

#

.close

safe radishBOT
#
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safe radishBOT
#
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jolly violet
#

How does step 3 work I think im reading it wrong

quasi bison
#

,rcw

flat frigateBOT
quasi bison
#

it's completing the square, twice in parallel

jolly violet
#

wdym by twice in parallel

quasi bison
#

you complete the square twice

#

once with the x's and once with the y's

jolly violet
#

OHHH

#

also wait how do u cts again I kinda forgot

quasi bison
jolly violet
#

mhm wait so in application how eill it look like

#

Do u have an example

safe radishBOT
#

@jolly violet Has your question been resolved?

safe radishBOT
#
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fast sage
#

how would i find these things using my bivariate data set?

safe radishBOT
#

@fast sage Has your question been resolved?

fast sage
#

.close

safe radishBOT
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pliant void
#

Hello! I need to prove this

safe radishBOT
pliant void
#

is this

#

I did this but now I'm a bit stuck on how to eliminate the y

quasi bison
#

what do these overlines mean?

pliant void
#

vectors

quasi bison
#

ok so x, y and v are vectors

pliant void
#

yes

quasi bison
#

and what does ( , ) mean?

pliant void
#

it's the dot product

quasi bison
#

also it's unclear what is to be proved from what

#

you want to prove that if x = v then (x,y) = (v,y) ?

pliant void
#

I want to prove that (x,y) = (v,y) becomes x = v

quasi bison
#

it doesn't.

#

unless there's something else that you aren't sharing.

pliant void
#

that's all I was given

quasi bison
#

are you sure

#

post the entire worksheet with the problem on it.

pliant void
#

oh forgot that lil thing there

quasi bison
#

oh so for all y in R^n

#

yeah that's super important lmfao

pliant void
#

oops :D

#

sorry!

quasi bison
#

ok so you got that x-v is orthogonal to y

#

again for every y

#

do you know which vector is orthogonal to everything?

pliant void
#

v is the "shadow vector" right?

#

not like this?

quasi bison
#

x-v is orthogonal to y, yes. for every y ∈ R^n.

safe radishBOT
#

@pliant void Has your question been resolved?

pliant void
#

So does the y even really matter?

quasi bison
#

you didn't answer my question:

do you know which vector is orthogonal to everything?

pliant void
#

oh sorry I misread your question. I think it's x?

safe radishBOT
#

@pliant void Has your question been resolved?

pliant void
#

Well thanks for checking and answering my problem! I'm going to free up this space and think well all the things you said. Thanks again! :)

safe radishBOT
#
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slim crypt
#

I have these two statements where i need to put equivalent or implication sign between A and B, since these two suggests that there are no implication or equivalence what sign am i supposed to write inbetween?

slim crypt
#

I got that in A, x can only be -3 or 0 and in B: it is -8 so im confused

#

Is it possible to write an equivalence sign and write a line through it to show that there are none?

#

Like this

#

nvm ill just put it like this and ask my classmates how they did it

#

.close

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past halo
#

Hello, can anyone solve this linear equation with the Gaussian algorithm?
And show me how you did it, because I couldn't find any solution...

plucky elk
# past halo Hello, can anyone solve this linear equation with the Gaussian algorithm? And s...
Khan Academy

Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere.

past halo
#

thanks, i will try it

#

.close

safe radishBOT
#
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full grove
#

question B

safe radishBOT
tall crow
#

Can’t even read this hand writing

full grove
#

that’s what i did i was wondering if there was another way to do it bc it’s 4 marks and all i had to do was use a calculator i’m not sure if there js another way

full grove
#

<@&286206848099549185>

safe radishBOT
#

@full grove Has your question been resolved?

safe radishBOT
#

@full grove Has your question been resolved?

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lean otter
#

What is υ, ρ, and φ used for?

safe radishBOT
lean otter
#

And ε too

lilac patio
#

in what context

#

electricity?

final halo
#

whatever you want them to be used for

lean otter
#

Physics? I don't know.

lilac patio
#

rho is usually density

lean otter
#

I know.

lilac patio
#

flux is the third one

lean otter
#

m = ρh

lilac patio
#

awesome

lean otter
#

So υ is for velocity

#

a = ∆υ/t

lilac patio
#

who uses u for velocity

lean otter
#

I don't know. I learned this from some AI stuff.

lilac patio
#

bruh

#

why is this important?

lean otter
#

Idk

lilac patio
#

I dont see any reason for knowing symbols that can be anything

hard crest
#

that's not even u that's upsilon
and also don't learn physics from the lying machine AI

#

usually v for velocity, m for mass, ρ (rho) for density

lean otter
#

Lmao but I like to use these symbols more than the Latin letters to make it look more genius

#

It's kinda cool tho

lean otter
#

Ok

#

Anyways, this conversation is over.

#

See you next time.

hard crest
#

i don't even bother to use μ for micro most of the time

lean otter
#

Scientific terms?

lilac patio
hard crest
#

like if i'm talking about micrograms i'll just say ug

lilac patio
burnt notch
#

.close

safe radishBOT
#
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clear gazelle
#

how did 2/3 b become 5/3 b??

safe radishBOT
exotic snow
#

Read the steps

clear gazelle
exotic snow
#

Are you sure?

lean thorn
# clear gazelle i did,

(2/3)b + b is the same thing as (2/3)b + (3/3)b = (5/3)b since we can the implicit 1 as (3/3)

lilac patio
#

1 = 3/3

clear gazelle
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im sorry, im not very experience in math, even at this level😅

lean thorn
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$\frac{2}{3}b + b$ is the same thing as $\frac{2}{3}b + \frac{3}{3}b$. Now you combine like terms to get $\frac{2 + 3}{3}b = \frac{5}{3}b$

flat frigateBOT
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MellowDramaLlama

clear gazelle
exotic snow
clear gazelle
exotic snow
#

Divide 3 by 3

clear gazelle
#

oh

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i see,

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but why cant i just do b/1+2/3?

clear gazelle
exotic snow
#

yes, any number divided by itself is 1, (as long as the number is not 0)

clear gazelle
#

ok

#

thx

exotic snow
clear gazelle
exotic snow
#

Not sure where you're getting examples from

clear gazelle
exotic snow
#

the denominator of 2/3 is 3, you add any fraction with a denominator of 3 to it, you can change 2/3 to 4/6 or 6/9 etc, but for the problem it's easiest to leave everything with denominator 3

clear gazelle
#

how is it -7/2? i got -5/2?

safe radishBOT
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winged widget
#

why is cos() equal to the x-coordinate of any given point on the unit circle?

peak estuary
#

what is your definition of cos

#

if you just go with the triangle definition of adj/hyp, it's pretty clear as soon as you draw the triangle

winged widget
#

yes thats my definition

winged widget
#

oh

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yeah that really clears things up

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thanks

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keen steppe
#

When dividing by Ruffini's method, the following scheme is obtained:

keen steppe
#

If Y = -A, find the value of D + A + G + E + N + P + R + Y.

A) 2
B) 8
C) 1
D) 4
E) 6

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sweet mica
#

So do Ruffini

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For example D=2

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Then 2A=-6 and so on

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Keep doing and you'll reach the solution

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@keen steppe

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keen steppe
keen steppe
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<@&286206848099549185>

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trim jackal
#

Is there a term that is commonly used for the result of any binary operation? Like a non-specific version of product or sum that could be said about any arbitrary group?

fiery merlin
#

The output.

trim jackal
#

That seems like something I should have been able to figure out lol thank you!!

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fiery merlin
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No problem.

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upper aurora
#

Ive been doing research for a while and i seem to cant find any real life example of “power of a product”. Is there any?

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fleet tendon
glad pagoda
#

ah i see you mean $(xy)^n = (x^n)(y^n)$

flat frigateBOT
#

most likely to honorable

upper aurora
glad pagoda
#

okay this isnt really a great example but say you own a company and you have some number of employees. say you have a bizarre policy where every christmas you pay every employee 1 dollar for every employee you have. so if you have 100 employees, you pay each of them $100 every christmas. now, say you have 8 departments in your company, each of which has 7 employees, and you want to figure out how much money you are gonna have to spend this christmas
your number of employees is 8 * 7, so you need to pay them each 8 * 7 dollars. therefore your total cost is (8 * 7)^2.
alternatively, you could apply this rule to conclude that you are in total going to owe (7)^2 * (8)^2 dollars

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this doesnt make much sense im sorry it isnt a super applicable concept

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woven hare
safe radishBOT
woven hare
#

How do you do number 45?

still charm
#

find f(0) and f(1)

#

@woven hare

woven hare
#

Ok

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f(0)=-1 and f(1)=(10)

hard crest
# woven hare f(0)=-1 and f(1)=(10)

so you know that there's a root in between there since the signs are different
take a guess where it might be and evaluate f at that guess

woven hare
#

Wdym by a root?

#

f(x)=0?

#

There’s a point where x=0 according to ivt since it changes sign from - to +

still charm
#

Yes

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Guess

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Then refine your guess

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Or in fact just use a few iterations of newtons method

woven hare
#

I guess f(0.2) is valid?

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tardy copper
#

$\int_{5}^{3}x^{2}\sqrt{3}$

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flat frigateBOT
tardy copper
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.close

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keen steppe
#

.reopen

#

When dividing by Ruffini's method, the following scheme is obtained:

keen steppe
#

If Y = -A, find the value of D + A + G + E + N + P + R + Y.

A) 2
B) 8
C) 1
D) 4
E) 6

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This is what ive done but we have more variables than equations

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<@&286206848099549185>

sweet mica
#

Ruffini is not done like that

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D=2 then you have 2A=-6.
Then G-6=1 and 1·A=N. Then E+N=-4 and -4A=R. Finally P+R=Y

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@keen steppe

keen steppe
keen steppe
#

I’m so confused

#

<@&286206848099549185>

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lusty spear
#

Can someone please help me with the following exercise ?
In a box there are 6 red 3 white and 1 black balls, where each individual ball is equally as likely to be picked, so (1/10).
You pick 3 times with putting the picked ball back each time.
Random variables:
Y : number of white picks
X : number of red picks

What is P(Y>X)? meaning the probability that you pick more white than red balls.

I figured I might do something like
P(Y>X) = P(Y-X>0) and then say Z = Y-X and Z(Omega) = {-3,-2,-1, 1, 2, 3}
and now I'd have to determine
P(Z>0) = P(Z=1)+P(Z=2)+P(Z=3) but then again I struggle with determining each of these because I dont really know how to handle those two random variables at once.
I wanna note that in this chapter of the book I use the concept of two random variables at once hasnt been introduced therefore this should be solvable without stuff like
P(Y=3, X=0) .

Thanks for your help !

west hedge
west hedge
lusty spear
west hedge
#

i can't understand it

west hedge
lusty spear
#

the probability that one picks more white than red balls

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tbh I think they messed something up and put that exercise in the wrong chapter because I see no way of solving this without the knowledge about joined distribution and stuff like that

safe radishBOT
#

@lusty spear Has your question been resolved?

quasi bison
#

I wanna note that in this chapter of the book I use the concept of two random variables at once hasnt been introduced therefore this should be solvable without stuff like
P(Y=3, X=0) .
i think the problem becomes impossible if you forbid yourself from using such events in any capacity.

lusty spear
quasi bison
#

i mean come on, even analyzing anything about a 2d6 roll becomes impossible with such a prohibition in place!

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i would write out a joint-distribution-table-in-all-but-name for X and Y tbh

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then just add up all the probabilities corresponding to cells with Y>X

lusty spear
#

what exactly does " joint-distribution-table-in-all-but-name" mean ?

#

I mean I know what a joint distribution table is

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but what is in-all-but-name

lusty spear
quasi bison
#

it just means you do not call it a joint distribution table

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so that you do not incur the wrath of your professor for using unauthorized concepts

lusty spear
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oh no no dont worry

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the exercise is just for myself

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thank you very much for your help !!

#

.close

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mint spindle
#

Find the surface area of a cone with a vertex of 50 degrees and a slope length of 4.8 cm
My main problem here is what the vertex being 50 degrees actually means for calculations as well as what the formula for surface area of a cone is and Google hasn’t been particularly helpful based on the information given

tame raft
#

draw the triangle

split ether
tame raft
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put more triangles in

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that's always the answer

split ether
#

thonk I think one triangle is enough

tame raft
#

if you're lame, sure

split ether
#

Draw a line from the top of the cone to the center of the base circle, you have formed a right triangle where you know one of the acute angles and the hypotenuse