#help-23
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The sign goes with the number
So if it's -z, then the number is -1, because +z and -z are two different values
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please help its a speed =d/t
Find time taken to complete race in 2014 in terms of t
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@robust quiver Has your question been resolved?
<@&286206848099549185>
thx
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how would i find the radius and interval of convergence of this limit?
ive tried using the ratio test but im getting messy algebra
!show
Show your work, and if possible, explain where you are stuck.
Looks like it may get a little messy, but algebra usually does
,rccw
i think i meant to write the (x-1) as |x-1| outside of the limit
but im still unsure on where to go from here
This is indeed kinda messy, but you can apply lhopital several times to get your final result
so i'd take the derivative of [(k+1+2^(k+1))*(k^2+3^k)] and [((k+1)^2+3^(k+1))(k+2^k)] with respect to k?
Multiplying it out first may make it easier
ah right, ill go ahead and try that rn
Good luck
@exotic dawn Has your question been resolved?
i honestly have no idea how l'hopital would help
i used it once and got this
[\frac{\left(3^k+k^2\right)\left(\ln\left(2\right){\cdot}2^{k+1}+1\right)+\left(\ln\left(3\right){\cdot}3^k+2k\right)\left(2^{k+1}+k+1\right)}{\left(2^k+k\right)\left(\ln\left(3\right){\cdot}3^{k+1}+2\left(k+1\right)\right)+\left(\ln\left(2\right){\cdot}2^k+1\right)\left(3^{k+1}+\left(k+1\right)^2\right)}]
kyIe

idk how that makes it any easier
Lemme take a look
hold on
@exotic dawn, I feel a little bad. I wasted your time there.
I found an easier way to do your limit
how did you get the first line?
oh right
and then you'd sub in infinity?
more or less
because k^2 is infinity + 3^k which is infinity too over (infinity+infinity)
ah, all good. tysm for the help
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Why are the area of the parametric equation the same?
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@fiery cosmos Has your question been resolved?
@fiery cosmos Has your question been resolved?
give some more context
ah you can just check itusing a double integral then
haven't learned double intergral yet
Its the unit calculus with parametric curves
ahh ic
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such as
all x-values y-values
min max
inflection points
i cant remember the other things but hopefully you get the idea
for specific functions?
can you be more specific in phrasing maybe give an example of what you mean
also no there probably isnt but wikipedia is out there and there are lots of videos on khan academy and youtube and stuff so you should be able to find whatever you need
my test tomorrow has me finding all of those and more from a single funtion
well do you know what the and more is
let me see
are you wanting to know how to solve for these things?
yeah while there isnt some super guide you can definitely just look this stuff up and find resources
its probably a waste of your time and other peoples if we try to explain it since guides online will do it better
ya I was having a hard time finding a function that looks like this
with the x^2 in denom
solving for concave up or down and increasing/decreasing should be the same or at the very least a similar process for all functions
just study how to solve for it and maybe what it means geometrically as sketching the graph loosely can help sometimes
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its 78?
Yeah I tried solving it and got 78
i didn’t submit an answer yet
Multiple ways
With the way you are doing this, realize that ‘c’ was angle ACB
Angle ACB and DCB make a linear pair
is the answer 145?
So, what is angle ACB + DCB= ?
… how did you get that?
…?
180-35
Why are you subtracting 35
What? No
What are you saying
Write it out clearly
Which angles are you talking about?
Okay, let’s skip this method
I can see you are getting two things mixed up
Are you aware of that exterior angle is always equal to the sum of the interior opposite angle?
yes
This
So, Can you apply this in the problem on hand?
<DCB= 67+35
It would be wrong to call angle DCB angle d
But yes, you applied it well
ok
Now do you want to go through the other way?
i want the simplest method
This is the least number of steps
now how can i move on after this
Just add em up
Yes
ok introduce me to the next one
Alr so, sum of interior angles of a triangle is 180 deg.
So, Angle CAB + ABC + BCA = 180
You already know what CAB and ABC is
So can you find BCA?
They asked for BCD
Yes, in this way we use BCA to find BCD
It’s your wish
You can use the same idea again
It’s correct so far
Now you have to find angle A
A = 5x + 2
Since you already know what x is, you can plug in the value for x into 5x+2
To get the measure of angle A
86
What? How?
Can you show your working
i’m quite in a hurry so i’m requesting to know the quickest way for the answer
Why in such a hurry?
But okay
This one is no different from what you’ve been doing so far
i’m in public
In all the other questions
ok
MEF is exterior angle
yes
yes so
yeah how can I plug that
You use exterior angle theorem
The assignment’s complete now
You too brother :))
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I'm trying to get the value of (-3/p). It equals 1 when p = 1 or 7 (mod 12) for instance
this means p = 1 (mod 4), p = 1 (mod 3) OR p = 7 (mod 3), p = 7 (mod 4)
so this means p = 1 (mod 3) AND (p = 1, 3 (mod 4))
Now, apparently this simplifies to p = 1 (mod 3)
I really don't understand why though
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@trim peak Has your question been resolved?
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Note that e^((-1+t)inf) and e^((1+t)(-inf)) are both equal to zero
Please don't occupy multiple help channels.
Is this statement true?
What's t
Some constant
Is it greater than 1 or lesser than 1
Then you can't say anything about those expressions
It really depends on the value of t
If t was -5, then the first one would be 0 but the second would be infinity
Of t was 0, then both would be 0
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do i need to algebraic division
even then it doesnt look that clear
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help
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I know the working is long but i’d be extremely grateful for someone to verify my answer
Yeah, looks good to me
just use online calculators to verify answers
Or just use adj(A)/det(A)
dont use that. that scales horribly
somewhat doable for 3x3, sure. but anything bigger is a huge pain
@tacit gyro Has your question been resolved?
use what?
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Did u use cosine rule
@patent musk Has your question been resolved?
wait is it wrong
Misachive
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can someone please walk me through how to do this
So basically you’re going to want to use the sin trig function
A good way to remember is Soh Cah Toa (sin Opposite over hyp) (cosine adjacent over hyp) (tan opposite over adjacent)
But you can’t put it in right away hold on let me get paper
sin = sin(51)?
,tex .sohcahtoa
riemann
11.66?
tytyty
Or else it’s confusing wording?
💀 what
Does it tell you what it was?
OHH @soft sail I know what I did wrong I’m sorry
When x is on the bottom you basically swap the trig function and x
So you would write it as 15/sin(51)
(For future reference)
ok ty
Sorry we did that a few units ago and I forgot about that one part 💀
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how many integer solutions are there to x1 + x2 + x3 + x4 = 12 where
x1 >= 2, x2 > -1, x3 >= -2, and x4 >= 0?
do you make so all of them are greater than or equal to 1?
so (x1 -1) + (x2 + 1) + (x3 + 3) + (x4 + 1) = 4 + 12?
and then do 16-1 choose 4-1
final answer 455?
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✅
<@&286206848099549185>
how many integer solutions are there to x1 + x2 + x3 + x4 = 12 where
x1 >= 2, x2 > -1, x3 >= -2, and x4 >= 0?
do you make so all of them are greater than or equal to 1?
so (x1 -1) + (x2 + 1) + (x3 + 3) + (x4 + 1) = 4 + 12?
and then do 16-1 choose 4-1
final answer 455?
Do you mean $x_k$ or $x^k$?
SWR
x sub k
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hey I have a question about graphing so if x axis is -4 and my y is 1/16 how would I graph that
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Prove that if X, Y are irrational numbers, X≠-Y, then X + Y is irrational
well that's false
that's false
consider something like $x=\sqrt{2}, y=1-\sqrt{2}$
bee
they're not negatives of each other, but they sum to 1, which is rational
That is a counterexample right
yes
my professor said we should consider X≠-Y
so that's false cause it is not true for the sum of every X irrational and Y irrational
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Look
look here okay
you see
the range
between 7 & 10 is what?
how far is 7 away from 0?
How much would you have to reduce to bottom and top to keep the same range
If you reduce the x value how does that affect the equation
It's been two minutes and not a single questions has been answered
good luck
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assume land given to them be 4x and 3x
times the answer of 2. by 3
Why 7 is being divided by 28 ??
because total land is 3x+4x=7x
Hmm ... Ok
2 by 3 or 4/3??
NOO
we got value of X which is 4
by 3
so 3X is 3x4=12 and 4x is 4x4=16
Yep ... Final answer is 12 , you are correct
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Hi, I need help figuring out what scenario is taking place with this question
How did u get that scenario?
The height of the ladder is just a sample
But the setup is what matters
Here's a more agnostic image
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Found two
Sinx = 1/✓7 so, it should have two solutions because other two would have negative sign
@mystic timber Has your question been resolved?
yeah
for domain of x
No
okay
No
No.
huh ?
if youre not wiling to accept what youre told here you can could just stop asking
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a function is given at f(x) = pi * sin(x). One of the 3 graphs is the graph for f. which one is it
how can I see this ?
I think it’s B but I don’t how to put it in words to explain it
not B
pi * sin(x) is just sin(x) which is upscaled by pi
so the curve will reach x-axis at points where sin(x) becomes 0 as usual..but the maxima and minima will be +pi and -pi respectively instead of +1 and -1
C curve seems to me the answer
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Hello i have two questions
First is i dont exactly understand what 2. c) is asking me to do (seems too easy) and i dont know how to do 3. c) ii)
I have done all of the other parts of the questions
is anyone here to help?
@patent lodge Has your question been resolved?
anyone here to help? itll only be quick ive already done most of it and have a vague idea of what to do
<@&286206848099549185>
:(
its asking you to express the vector v with its coordinates w.r.t. the eigenbasis
so if P is a matrix with its columns the eigenvectors of T, I think it'd just be P^{-1] v
SOMEONE HERE THANK YUO
so i hbave three eigen vectors
i thought i could just do [x; y; z] = s [eigenvector one] + t[eigenvector 2] plus u[eigenvector 3] right?
should be the same thing
its asking for a linear combination to express [x; y; z]?
yah
but what notation does it want
this seems too easy
well you'd need some expressions for [s, t, u]
why they cant just be parameters?
I assume they want them to be in terms of [a, b, c] maybe
but i cant do that
if you calculate the inverse of P, multiply it by [a, b, c] and see what you get
what is P?
a 3x3 matrix, each column is an eigenvector of T
why do i have to do that
you want to solve the system v = Pw, where w = [s, t, u] as you wrote it. the way to do that for P invertible is multiply on the left by P^{-1}
why is there a matrix now tho
its just a linear combination of three vectors making another vector
and that can be represented in terms of a matrix-vector product
yeah but why cant i represent it like this
it's the same thing. call the eigenvectors of T v1, v2, v3. then [x, y, z] = sv1 + tv2 + uv3 is the same thing as [x, y, z] = P*[s, t, u]
yeah so if its the same thing why shouldnt i just write it like that
as your answer? because that's not an answer, you haven't done anything when just writing it as that
i havent expressed v as a linear combination of other vectors?
like I said, I assume they want the coordinates to be in terms of a, b, c
I have told you, either calculate the inverse of P and multiply by [a, b, c] or solve the system by row reduction/Gaussian elimination
and P is a matrix with eigenvector collumns?>
yes
ok ill give it a go give me a few minutes
ok i gave up and used symbolab to do the inverse and it is disgusting what next?
multiply by [a, b, c]
and thats it?
yes, that should be it
choose random values for a, b, c and see if you get the same thing on both sides
yeaa ok
aight ill close this and if i have problems tomorrow ill get some more clarification
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I'm a bit lost of my old knowledge of Group Theory, what exactly is (Z/nZ)^x and (Z/nZ)*
any context?
they usually mean the same thing
its the units of Z/nZ under multiplication
which is precisely the numbers coprime to n
Context is I want to show that assuming p is prime. That if p = 1 (mod 3) then a third of the elements in (Z/pZ)* are cubes and if p = 2 (mod 3) then all elements are cubes
since n is prime, then every nonzero element is invertible (under multiplication)
So (Z/pZ)* = {1,2,...,p-1} (assuming ig p > 3 here)
Okay, any idea with the question btw?
(Z/pZ)^*?
Yeah
let x be arbitrary in (Z/pZ)*
consider the roots of (x^3-1) = 0 mod p
how could I infer to try this?
To get to that, like, obviously the x is arbitrary in (Z/pZ)* that makes sense since we want to show that such an x will be cubed for p = 2 (mod 3) and a third of them are cubes if p = 1 (mod 3), but like how could I figure out to consider that the roots of (x^3 - 1) = 0 mod p, if that makes sense? Like how would I think to myself; hm maybe I should try that
could you explain why it’s not A
restate your question and maybe tag them there, this channel is occupied
oh my bad
forget what I said for now
do you know the fact that every finite field has a primitive element?
Idk about finite field because this is all in a number theory context, but we've done "Let p be a prime. Then there exists a primitive element
g modulo p."
oh wait, theres an easier way of doing it
sorry lol
thinking on the spot
we can use euler's theorem
Hang on, let me just look that up in my notes lol
its the one that says we can look at powers mod p-1
so the cubing map is the same as multiplying by 3 mod p-1
So n is a positive integer, and a is an integer such that gcd(a,n) = 1 Then $a^{\phi(n)} \equiv 1$ (mod n)and obviously here we're working in mod p and p is a prime so $\phi(p) = p-1$ so for all a coprime to p we have $a^{p-1} \equiv 1$ (mod p)
LeftySam
So a here is just an arbitrary element in (Z/pZ)*
yeah
Okay, but what does this have to do with cubes?
I feel like you're about to blow my mind lol
that's just going to be {1,8,27, 64, ..., (p-1)^3} no?
Or am I not taking into account the mod p
everything is mod p
Okay
we want to find out whether this set has p-1 elements or (p-1)/3 elements
(or something else)
so we can use this, and we get that we want to find the set of all 3b mod p-1
Wait hang on, we want to prove that each of these are cubes; so surely we can't just cube each element?
we want to find the size of the image of the cubing map
Okay and we want to show the image is (Z/pZ)* if p = 2 (mod 3) and the image I guess is all contained in (Z/pZ)* with (p-1)/3 elements if p = 1 (mod 3)
yeah
So how do we use Euler's Theorem here?
the main step is to reduce it from cubing in (Z/pZ)^* to tripling in Z/(p-1)Z
this is similar to taking logs
and this follows from euler's theorem
I don't get what ur saying ngl
you know how log(x^y)=ylog(x)
yes
thats what we are trying to do here
a^3 in (Z/pZ)* becomes 3b in Z/(p-1)Z
maybe its useful to know about primitive elements
I know a fair bit about them
let x be primitive mod p
then x^{p-1} = 1
yeah
and then (Z/pZ)* = {1, x, x^2,...}
then if we want to cube every element, then we have {1, x^3, x^6, x^9,...}
and then we can use euler's theorem on the powers
eg, if p=7. Then x^9 = x^3 since 9 = 3 mod 6
But we wish to prove that every (Z/pZ)* is a cube no? Won't work by cubing any element in it I wouldn't have thought
if every element is a cube, then cubing is bijective
(i gtg for now, bbl)
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stuck
forget about hte vectors for a sec how do u even prove the diagonals bisect
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anyone?
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Need help with
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Any shortcuts for this kind of problem on exam?
shorter than just doing a substitution (either mentally or on paper), say y = x/a ?
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yo
yes
oh bruh
the logic I guess
is if you add 30
then you subtract 7 to get 23
bruh why did khan academy skip over these
got hard scammed
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I got a question on a test in this format:
Sasha takes 10 minutes to paint 25 square feet
Ben takes 5 minutes to paint 25 feet
Sasha says that it takes 15 minutes to paint 50 square feet together explain why she is wrong.
—————————————————
Now the obvious anwser is 10 as it would take Ben 10 minutes to finish the wall but I was stumped thinking about what the real true anwser, this is because the 10 minutes is only is Ben is painting but I want to know how fast it is together in the sense of what would be the most efficient way to paint the wall together.
And what would the formula be for finding the anwser
Does it say the square footage of 1 wall
You seemed to have assumed that 1 wall is 50 square feet
@fleet portal Has your question been resolved?
yuor obvious answer is wrong
or at least i dont get it
the obvious answer is that it would take ben 5 minutes, and then 5 minutes later Sasha finishes as well, so that's 10, not 15 and we even let Ben rest more than necessary

your reasoning is wildly different and i don;t get it
it's just it'll take at most 10 because ben can do it alone and take 10
the least time needed is gonna be like 50/(25/10 + 25/5)
i explained it once, like you calculate the painting speed, and add it together
and someone flipped out and said it's not a physics problem, i should shut up

like a different helper
that's a
moment
thanks for ur compassion
So that would be the equation in this case?
you do this
calc the speed of each person and add it together
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@lean otter Has your question been resolved?

@lean otter Has your question been resolved?
Be more specific and pick a place to start
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From the window of a building, the angle of depression of a parked car is 24 deg. From a
window 15m lower, the angle of depression of the same parked car is 19 deg. How far from the foot of the building is the parked car? Include A diagram and a full solution.
What would be an efficient way to solve this?
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find x using trigonometric ratios. write y in terms of F using trigonometric ratios. now write x+y in terms of 15+F using trigonometric ratios, you have two equations and two unknowns and you can find the value of F and y to calculate the horizontal distance between the two objects. I’m not sure if this method is the most efficient though
in these kind of questions try to establish as many relations between different variables and see where that gets you ig
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Just making sure, answer is 0 right?
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Hi, trying this one more time.
what are you looking for. t only appears twice so that's pretty nice already
Thanks. I know that t* that solves that equation is related to relative x,y,z values, and to a & b relative values, and would like to express it as directly as possible.
The uglier the better honestly.
I’m just stuck on knocking the t’s out of the exponents, then I end up with a t’th root of (5xa-5y) and just can’t get a regular old t in there.
I guess: How would you start?
I’m willing to toil over it for a while longer, it’s just for personal interest & challenge, I’m just stuck and could use a big brain hint.
do you mean t in this example?
yeah sorry
So I’ll need two different logs, correct? One to base (1+b) and one to base (1+a)?
Is this like an absolute horror of an exercise?
I’ve been calculating it in Excel for various starting values and indeed they don’t always converge.
Under assumptions that a and b are inversely related, there are a range of values of x,y,z that lead to convergence though.
just let the computer calculate it
that's what they are good at. solving for t wont give you anything valuable
No? It’s the time at which it takes the x + y term to converge with the z term. The comparative statics of that point are of interest.
Maybe this is an optimal growth problem? I remember we used a Hamiltonian for that but this was too long ago.
the current form is probably better for all kinds of things you wanna say about the equation. the solved form (if it exists) will probably be impossible to analyze
It doesn’t exist for all values of (x,y,z,a,b), that’s for sure.
How would a mathematician deduce the values for which a solution does exist? Or is that a really hard problem in itself?
Is there a general term for solving this type of equation?
Like how would I even refer to it?
Actually I just realized there should be a term on the initial x too - does that make it any more or less tractable?
This is the conjecture:
Low rates on savings make capital accumulation slow. Do increases in interest rates make it easier for savers to acquire the down payment for a home?
I’ve been able to formulate the problem like this:
I’m getting the impression that this is a much harder math problem than I anticipated.
Thanks @peak estuary , I appreciate the guidance.
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How do I do this question?
so I did |u|*|w|cos(theta) = -30
and |u|*|w|*sin(theta) = Norm(-9,18,-3)
,w sqrt(81+ 18^2 +9)
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is it asking me to draw a graph?
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(a) Argue that if X and Y are independent and identically distributed random variables, then P(X ≤ Y ) ≥ 1/2.
(bonus) (b) Would the latter inequality still hold if we removed the independence assumption?
can anyone help me with part b
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hmm im kinda stuck here
create two fractions
If you can turn the ratio on the left into a ratio ending with 12, you can say that r - 1 = the left value
so i did is i put
(r-1)=[(2)(12)]/3
(r-1)=[24]/3
(r-1)=8?
do i need to simplify the 8 one btw or thats already the answer?
<@&286206848099549185>
u dont need to
i think
simple:
2:3 = (r-1):12
2/3=(r-1)/12
so putting 12 that side,
2*12 /3=r-1
hence, r-1 =8 and r=9
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can i consider this as true?
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can someone help me with this, i dont know if im graphing correctly or not
here is my work so far:
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c i made
ty
If you dont, you should probably close the channel as help channels are for any math related questions you might have
Impressive though ngl
how will i close
“.close”
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Need help with this
@torpid flare Has your question been resolved?
No
No
<@&286206848099549185>
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ordered pair un unordered pair?
@vocal moth Has your question been resolved?
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!help
Calculate the perimeter of the following shape
this is my working
P1 = (pi * 100) / 2
P1 = 314.159265359 / 2
P1 = 157.07963268
P2 = 70 + 70 + 100
P2 = 240
Total Perimeter = 240+157.07963268
Total Perimeter = 397.08m
Ur P2 is incorrect
How come
Label which sides are 50 and 70 then show me
Yea that looks good
Yeah
Someone asked why
for the perimeter of the rectangle i only added 3 numbers
and not 4
thats because the perimeter of the semi circle took the other length of the rectangle
Yea
It’s only the outside lengths that are measured for perimeter
Ok
P1 = (pi * 28) / 4
P1 = 21.9911485751
P2 = 46 + 46 + 14
P2 = 106cm
Total P = 21.9911485751 + 106
Total P = 127.99cm (2dp)
Ur P1 is incorrect
How
Oh wait
im so sorry
forgive me
ill change it
the circle is just complex and i make these mistakes
No worries
there check
what?
but that isnt area
ohh wait
so sorry
forgive again
its just so ddamn confusing
check agian
again*
Yea looks good
@ruby oar Has your question been resolved?
Yooo
@obtuse plover
Mark it for me
@ruby oar
@obtuse plover
<@&286206848099549185>
<@&286206848099549185>
What’s the issue?
can u mark my cumulative frequency table
It’s good
Thanks
if i wanted to find median whatd i do
the median age
wait
ill learn it
then tell u answer
actually
No
I dont know
help me
ok
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@full yacht Has your question been resolved?
"linear projection on the plane" means $\vp : P \to P$
riemann
or actually $\vp : \ell_1^3 \to P$
riemann
if you can prove the problem for one projection, it's probably then simpler to prove it for an arbitrary projection
i don't know what computations you're doing
what in your image is in P and what is in ell_1^3 ?
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hey um I was given a 'Special triangle' and I dont know how to do any of it but I do know is that I was given a 45, 45, 90 triangle :/
yes it does
oh ok
180 - 90 - 45 = 45
yea sorry i suck at geometry
do you know the steps to find the variables?
it seems so confusing
What do you know about isosceles triangles
well the two angles are congruent ofc
ig thats all i know
and in this case its a right isosceles so that box means its 90 degrees
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why can't I square both sides of the equation? Why is it no longer an equivalent equation?
I get a diffrent result if I do so
(a+b)^2 isn’t a^2+b^2
Also 75² isn't 225
I think that’s a 15
Using a comma as a period is crazy
ok; that worked! but how do I decide now which value is valid from the two?
Plug each of them into the original one
Im european
Yeah sorry im@not used to that
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@gilded fiber Has your question been resolved?
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hi!

