#help-23

1 messages · Page 102 of 1

whole merlin
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Oh alright

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So for example would the top row be [1 1 1 1] or [1 1 -1 1]

worthy hemlock
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The sign goes with the number

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So if it's -z, then the number is -1, because +z and -z are two different values

whole merlin
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Got it, thanks

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robust quiver
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robust quiver
#

please help its a speed =d/t

hazy elbow
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Find time taken to complete race in 2014 in terms of t

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robust quiver
safe radishBOT
robust quiver
#

so far

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how?

safe radishBOT
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@robust quiver Has your question been resolved?

robust quiver
#

<@&286206848099549185>

barren magnet
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im imo particapiant

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so i can help u.

robust quiver
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thx

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exotic dawn
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how would i find the radius and interval of convergence of this limit?

exotic dawn
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ive tried using the ratio test but im getting messy algebra

empty gyro
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!show

safe radishBOT
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Show your work, and if possible, explain where you are stuck.

empty gyro
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Looks like it may get a little messy, but algebra usually does

exotic dawn
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.flip

fast gazelle
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,rccw

flat frigateBOT
empty gyro
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You don't keep (x-1)

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Ratio test is of just the coefficients

exotic dawn
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but im still unsure on where to go from here

empty gyro
# flat frigate

This is indeed kinda messy, but you can apply lhopital several times to get your final result

exotic dawn
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so i'd take the derivative of [(k+1+2^(k+1))*(k^2+3^k)] and [((k+1)^2+3^(k+1))(k+2^k)] with respect to k?

empty gyro
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Yes

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Tedious, but that's the best approach I have

empty gyro
exotic dawn
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ah right, ill go ahead and try that rn

empty gyro
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Good luck

safe radishBOT
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@exotic dawn Has your question been resolved?

exotic dawn
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i used it once and got this

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[\frac{\left(3^k+k^2\right)\left(\ln\left(2\right){\cdot}2^{k+1}+1\right)+\left(\ln\left(3\right){\cdot}3^k+2k\right)\left(2^{k+1}+k+1\right)}{\left(2^k+k\right)\left(\ln\left(3\right){\cdot}3^{k+1}+2\left(k+1\right)\right)+\left(\ln\left(2\right){\cdot}2^k+1\right)\left(3^{k+1}+\left(k+1\right)^2\right)}]

flat frigateBOT
empty gyro
exotic dawn
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idk how that makes it any easier

empty gyro
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Lemme take a look

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hold on

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@exotic dawn, I feel a little bad. I wasted your time there.

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I found an easier way to do your limit

exotic dawn
empty gyro
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ratio test

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Oh I made a typo

exotic dawn
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oh right

empty gyro
exotic dawn
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and then you'd sub in infinity?

empty gyro
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more or less

exotic dawn
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wouldnt that just be 1 then?

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because both limits = 1 when you sub in infinity?

empty gyro
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I gtg sorry

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<@&286206848099549185>

exotic dawn
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because k^2 is infinity + 3^k which is infinity too over (infinity+infinity)

exotic dawn
safe radishBOT
#

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safe radishBOT
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fiery cosmos
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Why are the area of the parametric equation the same?

safe radishBOT
#

@fiery cosmos Has your question been resolved?

safe radishBOT
#

@fiery cosmos Has your question been resolved?

safe radishBOT
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@fiery cosmos Has your question been resolved?

spiral bane
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ah you can just check itusing a double integral then

fiery cosmos
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haven't learned double intergral yet

spiral bane
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hm

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i have no idea what either of those things are

fiery cosmos
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Its the unit calculus with parametric curves

spiral bane
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as in I haven't learned it

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I just graphed it

fiery cosmos
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ahh ic

spiral bane
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area is approx 6-7

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so its not pi/2

fiery cosmos
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ahh ty thats all I needed to know

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thanks for helping me

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dusty talon
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.

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Is there an "ultimate" guide to what you can do with a function?

dusty talon
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such as

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all x-values y-values

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min max

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inflection points

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i cant remember the other things but hopefully you get the idea

sour abyss
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for specific functions?

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can you be more specific in phrasing maybe give an example of what you mean

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also no there probably isnt but wikipedia is out there and there are lots of videos on khan academy and youtube and stuff so you should be able to find whatever you need

dusty talon
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my test tomorrow has me finding all of those and more from a single funtion

sour abyss
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well do you know what the and more is

dusty talon
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let me see

sour abyss
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are you wanting to know how to solve for these things?

dusty talon
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yes, I guess this is the best example

sour abyss
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yeah while there isnt some super guide you can definitely just look this stuff up and find resources

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its probably a waste of your time and other peoples if we try to explain it since guides online will do it better

dusty talon
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ya I was having a hard time finding a function that looks like this

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with the x^2 in denom

sour abyss
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solving for concave up or down and increasing/decreasing should be the same or at the very least a similar process for all functions

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just study how to solve for it and maybe what it means geometrically as sketching the graph loosely can help sometimes

dusty talon
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buoyant mural
safe radishBOT
buoyant mural
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help pls

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180

crimson locust
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its 78?

buoyant mural
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Yeah I tried solving it and got 78

crimson locust
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is that the answer?

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i think its supplementry

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however u spell it

buoyant mural
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i didn’t submit an answer yet

sonic spruce
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Can you show your work?

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Angle BCD is not 78

buoyant mural
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Add 67+ 35+ c= 180
102+c=180
180-102=78

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oh

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how can I solve it?

sonic spruce
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Multiple ways

sonic spruce
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Angle ACB and DCB make a linear pair

buoyant mural
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is the answer 145?

sonic spruce
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So, what is angle ACB + DCB= ?

sonic spruce
sonic spruce
buoyant mural
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180-35

sonic spruce
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Why are you subtracting 35

buoyant mural
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67+c+35 (ACB)

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=180

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D+C+35=180 (DCB)

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am I doing this correct?

sonic spruce
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What are you saying

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Write it out clearly

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Which angles are you talking about?

buoyant mural
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<ACB= m<67 + m<c + m<35

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now how can I get to finding the angle <BCD

sonic spruce
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Okay, let’s skip this method

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I can see you are getting two things mixed up

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Are you aware of that exterior angle is always equal to the sum of the interior opposite angle?

buoyant mural
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yes

sonic spruce
sonic spruce
buoyant mural
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<DCB= 67+35

sonic spruce
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But yes, you applied it well

buoyant mural
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ok

sonic spruce
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Now do you want to go through the other way?

buoyant mural
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i want the simplest method

sonic spruce
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This is the least number of steps

buoyant mural
sonic spruce
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Just add em up

buoyant mural
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Sure, let me finish knowing this method

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=102

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final answer?

sonic spruce
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Yes

buoyant mural
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ok introduce me to the next one

sonic spruce
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Alr so, sum of interior angles of a triangle is 180 deg.
So, Angle CAB + ABC + BCA = 180

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You already know what CAB and ABC is

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So can you find BCA?

buoyant mural
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They asked for BCD

sonic spruce
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Yes, in this way we use BCA to find BCD

buoyant mural
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yes you add 35 + c +67 =180 ?

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Hey can we skip this one

sonic spruce
sonic spruce
buoyant mural
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What’s next

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sorry I was afk

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@sonic spruce

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<@&286206848099549185>

sonic spruce
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It’s correct so far

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Now you have to find angle A

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A = 5x + 2

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Since you already know what x is, you can plug in the value for x into 5x+2

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To get the measure of angle A

buoyant mural
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oh thx!

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67

sonic spruce
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Go through this one on your own

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What did you get?

buoyant mural
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86

sonic spruce
buoyant mural
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how can I get to the answer

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i tried multiple ways

sonic spruce
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Can you show your working

buoyant mural
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i’m quite in a hurry so i’m requesting to know the quickest way for the answer

sonic spruce
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Why in such a hurry?

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But okay

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This one is no different from what you’ve been doing so far

buoyant mural
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i’m in public

sonic spruce
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In all the other questions

buoyant mural
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ok

sonic spruce
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MEF is exterior angle

buoyant mural
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yes

sonic spruce
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EFG and FGE are the interior angles opposite to MEF

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#

What do you get?

buoyant mural
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yeah how can I plug that

sonic spruce
buoyant mural
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94= F + 54

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40?

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@sonic spruce

sonic spruce
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Yes

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Nice

buoyant mural
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Yes

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Thank you

sonic spruce
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No problem:)

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Have a good day

buoyant mural
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The assignment’s complete now

buoyant mural
sonic spruce
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Good jobhappy

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Close the channel if you don’t have any other questions

buoyant mural
#

.close

safe radishBOT
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sand ember
#

I'm trying to get the value of (-3/p). It equals 1 when p = 1 or 7 (mod 12) for instance

sand ember
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this means p = 1 (mod 4), p = 1 (mod 3) OR p = 7 (mod 3), p = 7 (mod 4)

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so this means p = 1 (mod 3) AND (p = 1, 3 (mod 4))

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Now, apparently this simplifies to p = 1 (mod 3)

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I really don't understand why though

peak estuary
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p=1,3 mod 4 just means that p is odd

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which assuming p is prime and not 2 is given

sand ember
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trim peak
#

Pls help

safe radishBOT
safe radishBOT
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safe radishBOT
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@trim peak Has your question been resolved?

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real charm
#

Note that e^((-1+t)inf) and e^((1+t)(-inf)) are both equal to zero

safe radishBOT
#

Please don't occupy multiple help channels.

real charm
#

Is this statement true?

pseudo scroll
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What's t

real charm
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Some constant

pseudo scroll
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Is it greater than 1 or lesser than 1

real charm
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It can be any value

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Arbitrary constant

pseudo scroll
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Then you can't say anything about those expressions

real charm
#

This is the context

pseudo scroll
#

It really depends on the value of t

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If t was -5, then the first one would be 0 but the second would be infinity

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Of t was 0, then both would be 0

safe radishBOT
#

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frosty granite
#

do i need to algebraic division

safe radishBOT
frosty granite
#

even then it doesnt look that clear

real charm
#

Just simplify it

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Then match up the coefficients on each side of the equation

frosty granite
#

yh that works thanks

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steep gust
safe radishBOT
steep gust
#

with this

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this is my expression

safe radishBOT
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steep gust
#

?

safe radishBOT
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tacit gyro
#

I know the working is long but i’d be extremely grateful for someone to verify my answer

restive creek
#

Yeah, looks good to me

peak estuary
#

just use online calculators to verify answers

restive creek
#

Or just use adj(A)/det(A)

peak estuary
#

dont use that. that scales horribly

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somewhat doable for 3x3, sure. but anything bigger is a huge pain

safe radishBOT
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tacit gyro
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patent musk
safe radishBOT
patent musk
#

am i right wit C?

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<@&286206848099549185>

modest field
#

Did u use cosine rule

safe radishBOT
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@patent musk Has your question been resolved?

patent musk
modest field
#

Yeah

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$c^2=a^2+b^2-2ab\cos(C)$

flat frigateBOT
#

Misachive

modest field
#

Cosine rule ^

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Use tgat

#

That*

safe radishBOT
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soft sail
#

can someone please walk me through how to do this

junior basalt
#

So basically you’re going to want to use the sin trig function

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A good way to remember is Soh Cah Toa (sin Opposite over hyp) (cosine adjacent over hyp) (tan opposite over adjacent)

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But you can’t put it in right away hold on let me get paper

soft sail
#

sin = sin(51)?

plucky elk
#

,tex .sohcahtoa

flat frigateBOT
#

riemann

junior basalt
#

Put it in your calculator like that

soft sail
#

11.66?

junior basalt
#

Make sure to round to tenths place as asked by the question

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So put it in as 11.7

soft sail
#

tytyty

junior basalt
#

Or else it’s confusing wording?

soft sail
#

i wasnt sure how to do it

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11.7 was wrong opencry

junior basalt
#

💀 what

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Does it tell you what it was?

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OHH @soft sail I know what I did wrong I’m sorry

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When x is on the bottom you basically swap the trig function and x

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So you would write it as 15/sin(51)

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(For future reference)

soft sail
#

ok ty

junior basalt
#

Sorry we did that a few units ago and I forgot about that one part 💀

safe radishBOT
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dreamy finch
#

how many integer solutions are there to x1 + x2 + x3 + x4 = 12 where
x1 >= 2, x2 > -1, x3 >= -2, and x4 >= 0?

dreamy finch
#

do you make so all of them are greater than or equal to 1?

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so (x1 -1) + (x2 + 1) + (x3 + 3) + (x4 + 1) = 4 + 12?

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and then do 16-1 choose 4-1

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final answer 455?

safe radishBOT
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dreamy finch
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.reopen

safe radishBOT
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dreamy finch
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<@&286206848099549185>

#

how many integer solutions are there to x1 + x2 + x3 + x4 = 12 where
x1 >= 2, x2 > -1, x3 >= -2, and x4 >= 0?

#

do you make so all of them are greater than or equal to 1?
so (x1 -1) + (x2 + 1) + (x3 + 3) + (x4 + 1) = 4 + 12?
and then do 16-1 choose 4-1
final answer 455?

empty gyro
#

Do you mean $x_k$ or $x^k$?

flat frigateBOT
dreamy finch
safe radishBOT
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true frigate
#

hey I have a question about graphing so if x axis is -4 and my y is 1/16 how would I graph that

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valid mauve
#

Prove that if X, Y are irrational numbers, X≠-Y, then X + Y is irrational

fast gazelle
#

well that's false

buoyant shadow
#

that's false

valid mauve
#

That might be the reason why I can't prove it

#

Why is it false?

fast gazelle
#

consider something like $x=\sqrt{2}, y=1-\sqrt{2}$

flat frigateBOT
fast gazelle
#

they're not negatives of each other, but they sum to 1, which is rational

valid mauve
#

That is a counterexample right

fast gazelle
#

yes

valid mauve
#

my professor said we should consider X≠-Y

#

so that's false cause it is not true for the sum of every X irrational and Y irrational

safe radishBOT
#

@valid mauve Has your question been resolved?

safe radishBOT
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royal arch
safe radishBOT
royal arch
#

how did my teacher get that answer?

lavish remnant
#

look here okay

#

you see

#

the range

#

between 7 & 10 is what?

#

how far is 7 away from 0?

#

How much would you have to reduce to bottom and top to keep the same range

#

If you reduce the x value how does that affect the equation

#

It's been two minutes and not a single questions has been answered

#

good luck

safe radishBOT
#

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safe radishBOT
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lean otter
safe radishBOT
obsidian hedge
#
  1. add 4 and 3 togeather
#
  1. divide 28 by 7 (the answer to 1.)
hazy elbow
obsidian hedge
#

times the answer of 2. by 3

lean otter
hazy elbow
lean otter
#

Hmm ... Ok

lean otter
hazy elbow
obsidian hedge
hazy elbow
#

so 3X is 3x4=12 and 4x is 4x4=16

obsidian hedge
#

beard im right not u

#

and then add ^2 after the answer

lean otter
#

.close

safe radishBOT
#
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waxen moon
#

Hi, I need help figuring out what scenario is taking place with this question

waxen moon
empty gyro
#

The height of the ladder is just a sample

#

But the setup is what matters

#

Here's a more agnostic image

safe radishBOT
#

@waxen moon Has your question been resolved?

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mystic timber
safe radishBOT
mystic timber
#

Found two

#

Sinx = 1/✓7 so, it should have two solutions because other two would have negative sign

dusk wharf
#

but sin can indeed have negative sign

#

but yeah there are 2 solutions

safe radishBOT
#

@mystic timber Has your question been resolved?

dusk wharf
#

talk

#

mate talk

maiden star
#

there are four solutions

#

because of its periodic nature

#

observe the interval

dusk wharf
#

yeah

maiden star
#

for domain of x

dusk wharf
#

im sorry

#

yeah

mystic timber
#

No

dusk wharf
#

okay

mystic timber
#

No

dusk wharf
#

No.

maiden star
dusk wharf
#

if youre not wiling to accept what youre told here you can could just stop asking

safe radishBOT
#
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dreamy hornet
#

a function is given at f(x) = pi * sin(x). One of the 3 graphs is the graph for f. which one is it

dreamy hornet
#

how can I see this ?

obsidian oracle
#

Try to find f(0) and f(1)

#

You will have to process by elimination

dreamy hornet
lean otter
#

not B

#

pi * sin(x) is just sin(x) which is upscaled by pi

#

so the curve will reach x-axis at points where sin(x) becomes 0 as usual..but the maxima and minima will be +pi and -pi respectively instead of +1 and -1

#

C curve seems to me the answer

safe radishBOT
#

@dreamy hornet Has your question been resolved?

#
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patent lodge
safe radishBOT
patent lodge
#

Hello i have two questions

#

First is i dont exactly understand what 2. c) is asking me to do (seems too easy) and i dont know how to do 3. c) ii)

#

I have done all of the other parts of the questions

#

is anyone here to help?

safe radishBOT
#

@patent lodge Has your question been resolved?

patent lodge
#

anyone here to help? itll only be quick ive already done most of it and have a vague idea of what to do

#

<@&286206848099549185>

#

:(

granite idol
#

its asking you to express the vector v with its coordinates w.r.t. the eigenbasis

#

so if P is a matrix with its columns the eigenvectors of T, I think it'd just be P^{-1] v

patent lodge
#

SOMEONE HERE THANK YUO

#

so i hbave three eigen vectors

#

i thought i could just do [x; y; z] = s [eigenvector one] + t[eigenvector 2] plus u[eigenvector 3] right?

granite idol
#

should be the same thing

patent lodge
#

yah

#

but what notation does it want

granite idol
#

well you'd need some expressions for [s, t, u]

patent lodge
#

why they cant just be parameters?

granite idol
#

I assume they want them to be in terms of [a, b, c] maybe

patent lodge
#

but i cant do that

granite idol
#

if you calculate the inverse of P, multiply it by [a, b, c] and see what you get

patent lodge
#

what is P?

granite idol
#

a 3x3 matrix, each column is an eigenvector of T

patent lodge
#

why do i have to do that

granite idol
#

you want to solve the system v = Pw, where w = [s, t, u] as you wrote it. the way to do that for P invertible is multiply on the left by P^{-1}

patent lodge
#

its just a linear combination of three vectors making another vector

granite idol
#

and that can be represented in terms of a matrix-vector product

patent lodge
granite idol
#

it's the same thing. call the eigenvectors of T v1, v2, v3. then [x, y, z] = sv1 + tv2 + uv3 is the same thing as [x, y, z] = P*[s, t, u]

patent lodge
#

yeah so if its the same thing why shouldnt i just write it like that

granite idol
#

as your answer? because that's not an answer, you haven't done anything when just writing it as that

patent lodge
#

i havent expressed v as a linear combination of other vectors?

granite idol
#

like I said, I assume they want the coordinates to be in terms of a, b, c

patent lodge
#

ahhh

#

ok

#

ok

#

so

#

how do i do that

granite idol
#

I have told you, either calculate the inverse of P and multiply by [a, b, c] or solve the system by row reduction/Gaussian elimination

patent lodge
#

and P is a matrix with eigenvector collumns?>

granite idol
#

yes

patent lodge
#

ok ill give it a go give me a few minutes

#

ok i gave up and used symbolab to do the inverse and it is disgusting what next?

granite idol
#

multiply by [a, b, c]

patent lodge
#

and thats it?

granite idol
#

yes, that should be it

patent lodge
#

huh ok thanks

#

is there a way i can check my answer?

granite idol
#

choose random values for a, b, c and see if you get the same thing on both sides

patent lodge
#

yeaa ok

#

aight ill close this and if i have problems tomorrow ill get some more clarification

#

.close

safe radishBOT
#
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sand ember
#

I'm a bit lost of my old knowledge of Group Theory, what exactly is (Z/nZ)^x and (Z/nZ)*

lean otter
#

any context?

#

they usually mean the same thing

#

its the units of Z/nZ under multiplication

#

which is precisely the numbers coprime to n

sand ember
# lean otter any context?

Context is I want to show that assuming p is prime. That if p = 1 (mod 3) then a third of the elements in (Z/pZ)* are cubes and if p = 2 (mod 3) then all elements are cubes

lean otter
#

since n is prime, then every nonzero element is invertible (under multiplication)

sand ember
#

So (Z/pZ)* = {1,2,...,p-1} (assuming ig p > 3 here)

#

Okay, any idea with the question btw?

lean otter
sand ember
lean otter
#

consider the roots of (x^3-1) = 0 mod p

sand ember
lean otter
#

how to get to that?

#

or what to do with that?

sand ember
#

To get to that, like, obviously the x is arbitrary in (Z/pZ)* that makes sense since we want to show that such an x will be cubed for p = 2 (mod 3) and a third of them are cubes if p = 1 (mod 3), but like how could I figure out to consider that the roots of (x^3 - 1) = 0 mod p, if that makes sense? Like how would I think to myself; hm maybe I should try that

lean otter
#

ah sorry

#

should be x^3=y lol

#

wait

dreamy hornet
sand ember
dreamy hornet
#

oh my bad

lean otter
#

do you know the fact that every finite field has a primitive element?

sand ember
#

Idk about finite field because this is all in a number theory context, but we've done "Let p be a prime. Then there exists a primitive element
g modulo p."

lean otter
#

oh wait, theres an easier way of doing it

#

sorry lol

#

thinking on the spot

#

we can use euler's theorem

sand ember
#

Hang on, let me just look that up in my notes lol

lean otter
#

its the one that says we can look at powers mod p-1

#

so the cubing map is the same as multiplying by 3 mod p-1

sand ember
#

So n is a positive integer, and a is an integer such that gcd(a,n) = 1 Then $a^{\phi(n)} \equiv 1$ (mod n)and obviously here we're working in mod p and p is a prime so $\phi(p) = p-1$ so for all a coprime to p we have $a^{p-1} \equiv 1$ (mod p)

flat frigateBOT
#

LeftySam

sand ember
#

So a here is just an arbitrary element in (Z/pZ)*

lean otter
#

yeah

sand ember
#

Okay, but what does this have to do with cubes?

#

I feel like you're about to blow my mind lol

lean otter
#

calm lol

#

we want to find all cubes

#

so we want to find the set of a^3 for all a

sand ember
#

that's just going to be {1,8,27, 64, ..., (p-1)^3} no?

lean otter
#

yeah

#

mod p

sand ember
#

Or am I not taking into account the mod p

lean otter
#

everything is mod p

sand ember
#

Okay

lean otter
#

we want to find out whether this set has p-1 elements or (p-1)/3 elements

#

(or something else)

lean otter
sand ember
#

Wait hang on, we want to prove that each of these are cubes; so surely we can't just cube each element?

lean otter
#

we want to find the size of the image of the cubing map

sand ember
#

Okay and we want to show the image is (Z/pZ)* if p = 2 (mod 3) and the image I guess is all contained in (Z/pZ)* with (p-1)/3 elements if p = 1 (mod 3)

lean otter
#

yeah

sand ember
#

So how do we use Euler's Theorem here?

lean otter
#

the main step is to reduce it from cubing in (Z/pZ)^* to tripling in Z/(p-1)Z

#

this is similar to taking logs

#

and this follows from euler's theorem

sand ember
#

I don't get what ur saying ngl

lean otter
#

you know how log(x^y)=ylog(x)

sand ember
#

yes

lean otter
#

thats what we are trying to do here

sand ember
#

in what sense?

#

We don't have logs no?

lean otter
#

a^3 in (Z/pZ)* becomes 3b in Z/(p-1)Z

sand ember
#

Why?

#

Also is not presupposing our result?

#

*this not

lean otter
sand ember
#

I know a fair bit about them

lean otter
#

let x be primitive mod p

sand ember
#

then x^{p-1} = 1

lean otter
#

yeah

#

and then (Z/pZ)* = {1, x, x^2,...}

#

then if we want to cube every element, then we have {1, x^3, x^6, x^9,...}

#

and then we can use euler's theorem on the powers

#

eg, if p=7. Then x^9 = x^3 since 9 = 3 mod 6

sand ember
#

But we wish to prove that every (Z/pZ)* is a cube no? Won't work by cubing any element in it I wouldn't have thought

lean otter
#

(i gtg for now, bbl)

safe radishBOT
#

@sand ember Has your question been resolved?

safe radishBOT
#
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frosty granite
safe radishBOT
frosty granite
#

forget about hte vectors for a sec how do u even prove the diagonals bisect

safe radishBOT
#

@frosty granite Has your question been resolved?

safe radishBOT
#

@frosty granite Has your question been resolved?

frosty granite
#

anyone?

safe radishBOT
#

@frosty granite Has your question been resolved?

safe radishBOT
#

@frosty granite Has your question been resolved?

naive arch
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fleet jay
#

Need help with

safe radishBOT
safe radishBOT
#

@fleet jay Has your question been resolved?

safe radishBOT
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somber void
safe radishBOT
somber void
#

Any shortcuts for this kind of problem on exam?

light shoal
#

shorter than just doing a substitution (either mentally or on paper), say y = x/a ?

safe radishBOT
#

@somber void Has your question been resolved?

safe radishBOT
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lean otter
#

yo

safe radishBOT
lean otter
#

this guy on youtube

#

said

#

23 mod 30

#

is equal to -7

#

and 23

#

is he frp

hardy lion
#

yes

lean otter
#

oh bruh

#

the logic I guess

#

is if you add 30

#

then you subtract 7 to get 23

#

bruh why did khan academy skip over these

#

got hard scammed

#

.close

safe radishBOT
#
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fleet portal
#

I got a question on a test in this format:

Sasha takes 10 minutes to paint 25 square feet

Ben takes 5 minutes to paint 25 feet

Sasha says that it takes 15 minutes to paint 50 square feet together explain why she is wrong.
—————————————————

Now the obvious anwser is 10 as it would take Ben 10 minutes to finish the wall but I was stumped thinking about what the real true anwser, this is because the 10 minutes is only is Ben is painting but I want to know how fast it is together in the sense of what would be the most efficient way to paint the wall together.

fleet portal
#

And what would the formula be for finding the anwser

mint holly
#

Does it say the square footage of 1 wall

dull sequoia
#

You seemed to have assumed that 1 wall is 50 square feet

safe radishBOT
#

@fleet portal Has your question been resolved?

fleet portal
#

Sorry meant to say 50 square feet

#

Not one wall

#

I fixed it

buoyant shadow
#

yuor obvious answer is wrong

#

or at least i dont get it

#

the obvious answer is that it would take ben 5 minutes, and then 5 minutes later Sasha finishes as well, so that's 10, not 15 and we even let Ben rest more than necessary

toxic stratus
buoyant shadow
#

your reasoning is wildly different and i don;t get it

toxic stratus
#

it's just it'll take at most 10 because ben can do it alone and take 10

buoyant shadow
#

okay yeah

#

thanks

toxic stratus
#

the least time needed is gonna be like 50/(25/10 + 25/5)

buoyant shadow
#

i explained it once, like you calculate the painting speed, and add it together

#

and someone flipped out and said it's not a physics problem, i should shut up

toxic stratus
buoyant shadow
#

like a different helper

toxic stratus
#

that's a sully moment

buoyant shadow
#

thanks for ur compassion

fleet portal
toxic stratus
#

calc the speed of each person and add it together

fleet portal
#

Thanks

#

.close

safe radishBOT
#
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#

@lean otter Has your question been resolved?

plucky elk
smoky hamlet
#

whats the question?

#

what dont you understand

safe radishBOT
#

@lean otter Has your question been resolved?

plucky elk
#

Be more specific and pick a place to start

safe radishBOT
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crude phoenix
#

From the window of a building, the angle of depression of a parked car is 24 deg. From a
window 15m lower, the angle of depression of the same parked car is 19 deg. How far from the foot of the building is the parked car? Include A diagram and a full solution.

crude phoenix
safe radishBOT
#

@crude phoenix Has your question been resolved?

crude phoenix
#

<@&286206848099549185>

safe radishBOT
#

@crude phoenix Has your question been resolved?

atomic jackal
# crude phoenix What would be an efficient way to solve this?

find x using trigonometric ratios. write y in terms of F using trigonometric ratios. now write x+y in terms of 15+F using trigonometric ratios, you have two equations and two unknowns and you can find the value of F and y to calculate the horizontal distance between the two objects. I’m not sure if this method is the most efficient though

#

in these kind of questions try to establish as many relations between different variables and see where that gets you ig

safe radishBOT
#
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vapid knoll
#

Just making sure, answer is 0 right?

safe radishBOT
vapid knoll
#

.close

safe radishBOT
#
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royal elm
#

Hi, trying this one more time.

safe radishBOT
peak estuary
#

what are you looking for. t only appears twice so that's pretty nice already

royal elm
#

Thanks. I know that t* that solves that equation is related to relative x,y,z values, and to a & b relative values, and would like to express it as directly as possible.

peak estuary
#

ok so you want to solve this for t?

#

that will probably be some horrible expression

royal elm
#

The uglier the better honestly.

#

I’m just stuck on knocking the t’s out of the exponents, then I end up with a t’th root of (5xa-5y) and just can’t get a regular old t in there.

#

I guess: How would you start?

#

I’m willing to toil over it for a while longer, it’s just for personal interest & challenge, I’m just stuck and could use a big brain hint.

peak estuary
#

get all terms involving x on one side, the rest on the other

#

take logs

royal elm
#

do you mean t in this example?

peak estuary
#

yeah sorry

royal elm
#

So I’ll need two different logs, correct? One to base (1+b) and one to base (1+a)?

#

Is this like an absolute horror of an exercise?

peak estuary
#

I'm not even sure this has an analytical solution

#

also I made a mistake in my head

royal elm
#

I’ve been calculating it in Excel for various starting values and indeed they don’t always converge.

#

Under assumptions that a and b are inversely related, there are a range of values of x,y,z that lead to convergence though.

peak estuary
#

just let the computer calculate it

#

that's what they are good at. solving for t wont give you anything valuable

royal elm
#

No? It’s the time at which it takes the x + y term to converge with the z term. The comparative statics of that point are of interest.

#

Maybe this is an optimal growth problem? I remember we used a Hamiltonian for that but this was too long ago.

peak estuary
#

the current form is probably better for all kinds of things you wanna say about the equation. the solved form (if it exists) will probably be impossible to analyze

royal elm
#

It doesn’t exist for all values of (x,y,z,a,b), that’s for sure.

#

How would a mathematician deduce the values for which a solution does exist? Or is that a really hard problem in itself?

peak estuary
#

well I dont know really hard

#

but definitely nontrivial

royal elm
#

Is there a general term for solving this type of equation?

#

Like how would I even refer to it?

#

Actually I just realized there should be a term on the initial x too - does that make it any more or less tractable?

#

This is the conjecture:
Low rates on savings make capital accumulation slow. Do increases in interest rates make it easier for savers to acquire the down payment for a home?
I’ve been able to formulate the problem like this:

#

I’m getting the impression that this is a much harder math problem than I anticipated.

#

Thanks @peak estuary , I appreciate the guidance.

#

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#
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midnight patio
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midnight patio
#

How do I do this question?

#

so I did |u|*|w|cos(theta) = -30

#

and |u|*|w|*sin(theta) = Norm(-9,18,-3)

#

,w sqrt(81+ 18^2 +9)

flat frigateBOT
midnight patio
#

But I don't know why this is wrong?

#

,w sec(arctan(3*sqrt(46)/-30))

flat frigateBOT
safe radishBOT
#

@midnight patio Has your question been resolved?

midnight patio
#

@sonic wadi

#

<@&286206848099549185>

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@midnight patio Has your question been resolved?

midnight patio
#

<@&286206848099549185>

midnight patio
#

.close

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lean otter
#

is it asking me to draw a graph?

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fleet current
#

(a) Argue that if X and Y are independent and identically distributed random variables, then P(X ≤ Y ) ≥ 1/2.
(bonus) (b) Would the latter inequality still hold if we removed the independence assumption?

fleet current
#

can anyone help me with part b

safe radishBOT
#

@fleet current Has your question been resolved?

fleet current
#

<@&286206848099549185>

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compact folio
#

hmm im kinda stuck here

safe radishBOT
elfin yew
#

create two fractions

lost lodge
compact folio
#

so i did is i put
(r-1)=[(2)(12)]/3
(r-1)=[24]/3
(r-1)=8?

#

do i need to simplify the 8 one btw or thats already the answer?

#

<@&286206848099549185>

grim plover
#

i think

strong tendon
#

simple:
2:3 = (r-1):12
2/3=(r-1)/12
so putting 12 that side,
2*12 /3=r-1
hence, r-1 =8 and r=9

compact folio
#

.close

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lean otter
#

can i consider this as true?

safe radishBOT
lean otter
#

.close

safe radishBOT
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lucid charm
#

can someone help me with this, i dont know if im graphing correctly or not

lucid charm
#

here is my work so far:

safe radishBOT
#

@lucid charm Has your question been resolved?

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lean otter
#

c i made

safe radishBOT
sonic spruce
#

Damn that’s really cool

#

But do you have a question to ask?

lean otter
#

ty

sonic spruce
sonic spruce
lean otter
#

how will i close

sonic spruce
#

“.close”

lean otter
#

".close"

#

not close

sonic spruce
#

.close

safe radishBOT
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torpid flare
safe radishBOT
torpid flare
#

Need help with this

safe radishBOT
#

@torpid flare Has your question been resolved?

torpid flare
#

No

torpid flare
#

<@&286206848099549185>

safe radishBOT
#

@torpid flare Has your question been resolved?

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vocal moth
#

ordered pair un unordered pair?

safe radishBOT
#

@vocal moth Has your question been resolved?

vocal moth
#

.close

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ruby oar
#

!help

safe radishBOT
ruby oar
#

Calculate the perimeter of the following shape

#

this is my working

#

P1 = (pi * 100) / 2
P1 = 314.159265359 / 2
P1 = 157.07963268

P2 = 70 + 70 + 100
P2 = 240

Total Perimeter = 240+157.07963268
Total Perimeter = 397.08m

obtuse plover
#

Ur P2 is incorrect

ruby oar
#

How come

obtuse plover
#

Label which sides are 50 and 70 then show me

ruby oar
#

Ok

#

let me redo it

#

check that

obtuse plover
#

Yea that looks good

ruby oar
#

Yeah

#

Someone asked why

#

for the perimeter of the rectangle i only added 3 numbers

#

and not 4

#

thats because the perimeter of the semi circle took the other length of the rectangle

obtuse plover
#

Yea

ruby oar
#

👍

#

Can I try one more to see your opinion

obtuse plover
#

It’s only the outside lengths that are measured for perimeter

obtuse plover
ruby oar
#

P1 = (pi * 28) / 4
P1 = 21.9911485751

P2 = 46 + 46 + 14
P2 = 106cm

Total P = 21.9911485751 + 106
Total P = 127.99cm (2dp)

obtuse plover
#

Ur P1 is incorrect

ruby oar
#

How

#

Oh wait

#

im so sorry

#

forgive me

#

ill change it

#

the circle is just complex and i make these mistakes

obtuse plover
ruby oar
#

there check

obtuse plover
#

More incorrect

#

We want the external circumference, not area

#

Of a quarter circle

ruby oar
#

what?

#

but that isnt area

#

ohh wait

#

so sorry

#

forgive again

#

its just so ddamn confusing

#

check agian

#

again*

obtuse plover
#

Yea looks good

ruby oar
#

Im scared for my test

#

because it has those questions

#

and u saw how i mixed up a lot

obtuse plover
#

Double check ur work

#

Write out formulas

ruby oar
#

Yeah

#

Yo

#

i got a few more quetions

#

this scares me

#

I have no clue how to do it

obtuse plover
#

Just search it up on yt

#

Or google

#

Plenty of tutorials

ruby oar
#

Wait is it like?

#

Ok ill try to learn it

safe radishBOT
#

@ruby oar Has your question been resolved?

ruby oar
#

Yooo

#

@obtuse plover

#

Mark it for me

#

@ruby oar

#

@obtuse plover

#

<@&286206848099549185>

#

<@&286206848099549185>

lean hound
#

What’s the issue?

ruby oar
#

can u mark my cumulative frequency table

lean hound
#

It’s good

ruby oar
#

Thanks

#

if i wanted to find median whatd i do

#

the median age

#

wait

#

ill learn it

#

then tell u answer

#

actually

#

No

#

I dont know

#

help me

#

ok

safe radishBOT
#

@ruby oar Has your question been resolved?

safe radishBOT
#
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safe radishBOT
#

@full yacht Has your question been resolved?

plucky elk
#

"linear projection on the plane" means $\vp : P \to P$

flat frigateBOT
#

riemann

plucky elk
#

or actually $\vp : \ell_1^3 \to P$

flat frigateBOT
#

riemann

plucky elk
#

if you can prove the problem for one projection, it's probably then simpler to prove it for an arbitrary projection

#

i don't know what computations you're doing

#

what in your image is in P and what is in ell_1^3 ?

safe radishBOT
#

@full yacht Has your question been resolved?

safe radishBOT
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cold cradle
#

hey um I was given a 'Special triangle' and I dont know how to do any of it but I do know is that I was given a 45, 45, 90 triangle :/

plucky elk
#

45-45-90 triangles are iscocoles

#

does that help?

cold cradle
#

i dont know :/

#

wait does that mean the other angle is 45 too

plucky elk
#

yes it does

cold cradle
#

oh ok

plucky elk
#

180 - 90 - 45 = 45

cold cradle
#

yea sorry i suck at geometry

#

do you know the steps to find the variables?

#

it seems so confusing

mortal sandal
#

What do you know about isosceles triangles

cold cradle
#

well the two angles are congruent ofc

#

ig thats all i know

#

and in this case its a right isosceles so that box means its 90 degrees

#

.close

safe radishBOT
#
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formal crest
safe radishBOT
formal crest
#

why can't I square both sides of the equation? Why is it no longer an equivalent equation?

#

I get a diffrent result if I do so

mint holly
#

(a+b)^2 isn’t a^2+b^2

empty gyro
final halo
#

Also 75² isn't 225

mint holly
#

I think that’s a 15

formal crest
mint holly
#

Using a comma as a period is crazy

formal crest
#

ok; that worked! but how do I decide now which value is valid from the two?

mint holly
#

Plug each of them into the original one

formal crest
mint holly
#

Yeah sorry im@not used to that

formal crest
#

ok, thanks y'all, you have answered all of my questions

#

how to I end this?

mint holly
#

Np

#

.close

formal crest
#

oh

#

.cloase

#

.close

safe radishBOT
#
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gilded fiber
safe radishBOT
gilded fiber
#

How do I turn this into a series

#

(2x)/(1+x^2)

safe radishBOT
#

@gilded fiber Has your question been resolved?

safe radishBOT
#

@gilded fiber Has your question been resolved?

gilded fiber
#

.close

safe radishBOT
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safe radishBOT
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verbal adder
#

hi!

safe radishBOT
verbal adder
#

really quick question: Is the limit comparison test true if you take the inverse?

#

((: Σan / Σbn = C > 0, they either both converge or diverge. Is this true for Σbn / Σan too?