#help-23

1 messages · Page 101 of 1

dapper mango
#

I keep getting one yet it’s wrong. What am I supposed to do?

hot thistle
#

can you show your work?

dapper mango
#

I don’t really know how to start the problem

pseudo scroll
#

$$\int_a^b f(x) \dd x = -\int_b^a f(x) \dd x$$
$$\int_a^c f(x) \dd x + \int_c^b f(x) \dd x = \int_a^b f(x) \dd x$$

flat frigateBOT
#

NEONPerseus

pseudo scroll
#

Do you know these properties

dapper mango
#

Yeah

pseudo scroll
#

Have you tried using them

dapper mango
#

I just don’t understand how you would get 15

pseudo scroll
#

You don't need to nvm you can

#

$\int f(x) \dd x = F(x) + C$

flat frigateBOT
#

NEONPerseus

pseudo scroll
#

Assume this

#

You need $F(8) - F(1)$

flat frigateBOT
#

NEONPerseus

pseudo scroll
#

Using the two given integrals can you find F(8) and F(1)?

dapper mango
#

I’m blanking

pseudo scroll
#

Hmm

#

If I say the integral of f(x) is F(x), what would the first integral evaluate to

hot thistle
#

i think there's an easier way to visualize this than with F(x)s

pseudo scroll
hot thistle
#

(it's the same thing but keeping it as an integral)

pseudo scroll
#

Try to get the bounds of the two integrals in the way that second property is laid out

hot thistle
#

yeah i think that's enough

dapper mango
#

Wouldn’t integral 8 to 1 of f(x) just equal 1 tho

hot thistle
#

how did you get that

dapper mango
#

After combining the two integrals

hot thistle
#

ye

pseudo scroll
#

Also do you mean 1 to 8

hot thistle
#

so we have $\int_1^8 f(x), dx = 1$

flat frigateBOT
#

maximo

dapper mango
#

Yeah

pseudo scroll
#

Just the 2 bit

dapper mango
#

But wouldn’t your final answer be 3 because you just add them or am I in the complete wrong direction

hot thistle
#

well

pseudo scroll
#

You need to make sure the bounds match up

#

What you did was correct by flipping the bounds on the first I assume

#

You're integrating from 1 to 5 and adding on the area from 5 to 8

hot thistle
flat frigateBOT
#

maximo

pseudo scroll
#

Oh

dapper mango
#

Yea

pseudo scroll
#

nvm

#

It's too early

#

For me to be doing math

#

Maximo have fun KEK

hot thistle
#

sorry for barging in neon

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but thanks

hot thistle
#

except

pseudo scroll
hot thistle
#

have you heard of this $$\int(f(x) + g(x)), dx = \int f(x), dx + \int g(x), dx$$?

flat frigateBOT
#

maximo

hot thistle
#

it's part of the linearity of the integral

dapper mango
#

Yeah

hot thistle
#

we should apply this here

dapper mango
#

I still just don’t know where 15 comes from at all

hot thistle
#

well we're about to get there

#

we have $\int_1^8(f(x) + 2), dx$

flat frigateBOT
#

maximo

hot thistle
dapper mango
#

Ohhhhhhhh

#

I forgot that the limit of a number is not the number itself

hot thistle
#

by limit you mean integral yeah?

dapper mango
#

Yeah

hot thistle
#

if so yes, it's not just the number (usually)

dapper mango
#

I’m reviewing all the units right now

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They’re mixing together

#

Thank you for the help

hot thistle
#

no problem

dapper mango
#

.close

safe radishBOT
#
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safe radishBOT
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void agate
#

I need help with number 9

safe radishBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
void agate
#

1

icy lance
#

start by finding the inverse of h

void agate
#

Let me try

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h^-1(x) = 1/2?

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Would it be that?

#

@icy lance

icy lance
#

how did you get h^-1(x) = 1/2?

void agate
#

Am I wrong?

icy lance
#

yes, h^-1(x) would not be a constant

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say x=2y-1 and make y the subject

void agate
#

Oh

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I'm not really getting it...

void agate
#

Sorry my mistake for doing it carelessly

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@icy lance

#

Sorry for pinging you alot..

icy lance
#

its alright

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yeah h^-1(x)=(x+1)/2

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now just use the function as per the question and then solve for m

void agate
#

Oh so would it be like this..

h^-1(5m - 1) - h^-1 (9 + 1)/2 =15?

safe radishBOT
#

@void agate Has your question been resolved?

void agate
#

@icy lance

#

.close

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sour hornet
#

Hello

safe radishBOT
sour hornet
#

I have a query regarding Pythagoras' theorem

hazy elbow
#

Just ask

hazy elbow
sour hornet
#

PQRS is a rectangle in which PQ= 9 cm and PS=6cm. T is a point on PQ such that PT= 7cm and RV is the perpendicular from R to ST. Calculate ST and RV.

hazy elbow
#

Notice PTS is a right triangle

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same for SVR

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SVR is a bit tricky. It'll require construction

weary blaze
#

or you can get angle VSR and use trig to find the side RV

hazy elbow
#

tanx=7/6

safe radishBOT
#

@sour hornet Has your question been resolved?

hazy elbow
#

@sour hornet You there?

sour hornet
#

Yes I am

hazy elbow
#

Yeah so you need to connect R and T

sour hornet
#

Ok... and then?

hazy elbow
#

Use pythagoreas theorem to find RT

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from triangle TQR

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and yeah find ST also using pythagoreas

sour hornet
#

Listen... If you look closely, the triangle TQR is a triangle but I will need at least 2 sides to apply the Pythagoras' theorem

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This is the diagram that is supposed to form according to the question and told by my teacher

hazy elbow
#

qr is 6 and tq is 2

sour hornet
#

Ok... I got it

#

thanks

#

The answer came out wrong actually

hazy elbow
#

Well the answer isn't over

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we need to find vr and we have only found tr

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Now vr is perpendicular to st

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so area of triangle str can be given by 1/2xSTxVR

sour hornet
#

ok

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let me try

hazy elbow
#

But area of triangle str is just area of rectangle- area of pts- area of tqr

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so equate them

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assuming vr=x

sour hornet
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What are you labelling as x here?

hazy elbow
#

side vr

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well, its not necessary

sour hornet
#

ok got it

hazy elbow
#

Yeah good

sour hornet
#

thanks

safe radishBOT
#

@sour hornet Has your question been resolved?

safe radishBOT
#
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faint raptor
#

No idea where to start with this question, can someone walk me through the process?

compact ferry
#

Partial fraction decomposition

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Probably

faint raptor
#

nvm i figured it out

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i was simplifying my partial sums wrong

#

i found the pattern

#

.close

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frosty granite
#

dumb but would sin6theta= 2 sin3theta cos3theta

frosty granite
#

nvm

#

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obtuse plover
#

Let’s ask mathway

#

Ok

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unreal spoke
safe radishBOT
unreal spoke
#

I need a little clarification to help my understanding of the last sentence.

#

secx = 1/cosx. So if secx = 1 does that mean then that I'm just looking for where cosx = 1?

tiny wraith
#

Yes

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Which is x = 0

unreal spoke
#

Thanks 🙂

#

.close

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#
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unreal spoke
safe radishBOT
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unreal spoke
#

I thought tan(0) was undefined at the values where sec=0 which is pi/2 and 3pi/2

unreal spoke
#

zesty&festyII — Today at 2:34 PM
I thought tan(0) was undefined at the values where sec=0 which is pi/2 and 3pi/2

thin bridge
#

what you said made no sense

#

can you clarify what you mean

unreal spoke
#

Yep.

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So, this is the check against a larger problem given

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Where we get x=o

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so secx = 1 at (1,0)

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And the screen shot above is checking to remove erroneous solutions.

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It's saying to plug in 0 into the Pyth ID that was used earlier in the problem.

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sec(0) is showing in the check as =1

thin bridge
#

,W sec(0)

thin bridge
#

tan(0) is defined, it's value is 0

unreal spoke
#

sec0 is 1/cos right, so wouldn't I be looking at where sec is 0?

thin bridge
#

sec(x) = 1/cos(x)

unreal spoke
#

Right, so.

#

if it's sec0, then it would be 1/cos0

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cosine is 0 at (0,1) and (0,-1)

thin bridge
#

so what?

unreal spoke
#

I'm explaining my thought process, which is obviously wrong somewhere.

#

tan0 is undefined at those values.

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(0,1) and (0,-1)

thin bridge
#

tan(0) is defined, it's value is 0

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you don't really care about where cos(x) is 0 here

unreal spoke
#

tangent of (0,1) is sin/cos = 1/0 = undefined

thin bridge
#

you don't have those values in your potential solutions

unreal spoke
thin bridge
#

you can express that in standard trig functions when evaluating/solving you find that more convenient

unreal spoke
thin bridge
#

overcomplicating/overthinking

unreal spoke
#

tan0 but I guess, maybe it seems like I need to be looking at where tan is = 0, which is (1,0) and (-1,0)?

#

I know, this is a tough subject for me.

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I don't get a lot of explanations in this class so I have no idea what the bounds or rationale should be.

thin bridge
#

why do you keep typing tan0

unreal spoke
thin bridge
#

tan(0) is defined, it's value is 0

faint raptor
#

im getting confused just reading this lol

unreal spoke
#

I know.

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I just don't understand how this check is supposed to be helpful for me. It has very little context.

#

It's in the book, and it's about all I have to rely on.

thin bridge
#

checking is what you do if you aren't confident with your work and/or if there are certain steps that potentially generate extraneous solution

unreal spoke
#

Yes, I get that, but this particular check. tan0 is defined at -1 and 1. I don't see how that's helpful for me to understand generally why this calculates correctly.

thin bridge
#

no

#

for the 5th? time?

tan(0) is defined, it's value is 0

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tan(0) is defined, it's value is 0

#

tan(0) is defined, it's value is 0

#

tan(0) is defined, it's value is 0

unreal spoke
#

right, what I'm saying is, tan 0/1 = 0. I know that the value is 0.

plucky elk
#

,calc tan(0)

flat frigateBOT
#

Result:

0
thin bridge
#

then why do you keep saying stuff like
tan(0) is defined at -1 and 1

#

that makes no sense whatsoever

unreal spoke
#

Because it's only defined at -1 and 1.

thin bridge
#

tan(0) is defined, it's value is 0

plucky elk
unreal spoke
#

its undefined at (0,1) and (0,-1)

plucky elk
mortal fern
#

i think i get what he says

unreal spoke
# plucky elk What do you think this means?

Means it can produce a legitimate value at that location on a graph. sin/cos = 0/1 = 0. But you can't divide by zero, so at the other locations -1/0 is not a valid value.

unreal spoke
mortal fern
#

it's undefined at π/2 by your reasoning, which is right.

unreal spoke
#

Yes, thank you.

plucky elk
faint raptor
# unreal spoke

i think you're misunderstanding something here? at no point do you find sec=0 for pi/2 and 3pi/3. you're just plugging x in for sec(x) - 1 = tan(x)

unreal spoke
#

Ok, please help me.

mortal fern
#

And -π/2

plucky elk
#

,w plot tan(x)

unreal spoke
faint raptor
#

ok wait

thin bridge
#

you don't seem to be using correct terminology which is making it very difficult to understand what you're trying to say

faint raptor
#

perhaps it would be helpful to start over from the beginning cause everyone's getting confused here

plucky elk
thin bridge
#

post the original and highlight the first thing line you have an issue with

unreal spoke
plucky elk
#

Ramonov and others here can't both help you and decipher the stuff you're saying at the same time

unreal spoke
#

in my mind - what I think I am supposed to do to check is to figure out where sec = 0.

faint raptor
#

that's not what you're doing

#

you have a value of x

#

x=0

thin bridge
#

checking is what you do if you aren't confident with your work and/or if there are certain steps that potentially generate extraneous solution

faint raptor
#

you just plug it in to sec(x) - 1 = tan(x)

#

if it matches up

#

it works

#

if it doesnt

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its invalid

thin bridge
#

the original question that you didn't explicitly post seemed to be solve
sec(x)-1 = tan(x)

squaring both sides of an equation may lead to extraneous solutions so it's a good idea to check here

unreal spoke
# faint raptor that's not what you're doing

Ok hear me out. I guess, it's I"m thinking not just of this problem. But other problems in the future I will need to perform the check for. If somehow the value is 5 instead of 0. I'd need to know what sec(5) is, just as an example. Right?

faint raptor
#

what is this check for

unreal spoke
faint raptor
#

??

thin bridge
#

not limited to trig

faint raptor
unreal spoke
#

(secx-1)^2 = (tanx)^2 for ex.

faint raptor
#

huh

unreal spoke
#

When you square a function, it says you should check it.

faint raptor
#

i think the checks just saying

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for f(x)^2 = g(x)^2 f(x) = g(x)

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at the x value where

#

ok disregard me

#

im confused now

thin bridge
#

but none of this addresses why you kept saying stuff about

tan(0) is defined at -1 and 1

unreal spoke
#

Because when I think of where I need to look at values of zero for tan, I'm looking at where on the unit circle that might be.

#

Unless I am just fundamentally missing something.

thin bridge
#

tan(0) = sin(0)/cos(0)

faint raptor
#

i think maybe you're trying to talk about arctan(0)

thin bridge
#

if you really want to use the unit circle
tan(0) is the ratio of the y and x coord of (1,0)

unreal spoke
#

Yes, but you can't divide by zero. So for places on the circle that cosine is 0, there can't be a tan value, is that not right?

mortal fern
#

no, you need to look at the angle

thin bridge
#

but there is no division by 0

#

here

mortal fern
#

not the value on the circle

faint raptor
#

i think you may have a fundamental misunderstanding of how the unit circle works

thin bridge
#

and that's all you really consider here when checking whether x=0 is a solution here

#

you don't need to concern yourself with anything else

mortal fern
#

cos0 is not where cos is 0

thin bridge
#

you don't need to concern yourself with stuff like pi/2 when that doesn't come even up in the solving process

unreal spoke
thin bridge
#

no

mortal fern
#

no, i would consider watching a slow and easy YouTube video on unit circle in trig.. it will make it easier

unreal spoke
mortal fern
#

and youll be able to answer 90% of questions like these

#

instantlu

thin bridge
#

your seem to have a major confusion with the inputs and outputs of a function

mortal fern
#

or just understand them at meast

#

least*

unreal spoke
#

k, thank you.

mortal fern
#

if you have any other problems just ask again but i suggest you watch a video : )

faint raptor
#

i think your issue is just a misunderstanding of how trig functions work

#

cos(x) does not mean you find the angle of where cos = x

thin bridge
#

functions in general

unreal spoke
unreal spoke
#

in this check problem though, x was 0, and zero was put back into the problem as sec(0) - where otherwise it would be secx.

unreal spoke
thin bridge
#

cos(t) when t = 0
is cos(0)
which gives the x cood of the point on the unit circle with an angle (anticlockwise from the positive x-axis) of 0

unreal spoke
thin bridge
#

should change a variable there to make it clearer

faint raptor
#

the unit circle is derived from special triangles (30/60/90) and (45/45/90) so i would suggest looking at that too

thin bridge
#

and avoid using a variable to represent different things

unreal spoke
#

Alright, yes, agree. Thanks everyone, I really appreciate you. I'll move along!

#

.close

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#
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unreal spoke
unreal spoke
#

that's all, thank you 🙂 .close

#

.close

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viral beacon
#

The exercise is: There is a new food which includes three ingredients (A, B, C). The ingredients can have the vitamins B1, B6 and B12 (From the picture you can read which ingredients have how much of the vitamins; The Values are in %, so 0,1 is 0,1%). The new food has a total 0,05% B1 and 0,075% B6
Now we have to find out,

  1. how big the portion of ingredient B in the new food is
    (Output in %)
  2. and what the portion of B12 in the new food is
    (Output in %)

My problem is:
There are three equations and four unknown variables. The output for B12 can't be a clear percentage. There will always be a dependency.
Am I wrong ? Can anyone help me find a solution?

obtuse jackal
#

Indeed. You could take 1 of C then 1.5 of B, or 0.5 of A then 0.5 of B
They don't give the same amount of B12

viral beacon
obtuse jackal
#

Just because I answered doesn't mean I speak german fluently though

viral beacon
# obtuse jackal Just because I answered doesn't mean I speak german fluently though

Oh, I am so sorry 😶 (saw your name and thought you were from Germany)

So I have to continue calculating here depending on a certain variable.
Could I now say: (the first row - second row) 0.1a + 0b + 0.05c - ( 0.1a + 0.05b + 0c) = 0.05-0.075
=> b = (0.025+0.05c)/0.05
Would "(0.025+0.05c)/0.05" then be the proportion B in the new feed?

obtuse jackal
#

It's a joke with eigenrocket and eigenzeta

obtuse jackal
obtuse jackal
viral beacon
#

I created a "System of linear equations" and tried to get the variables a, b and c

obtuse jackal
#

A, B and C are more like vitamin vectors though

#

Operations on columns make sense

#

Rows, not so much

viral beacon
#

This is what I thought.
Now you could use Gaussian elimination and try to get the value of the variables

#

Why isn't it allowed to say I - II or II - I and then solve for b

obtuse jackal
#

Yeah actually

viral beacon
#

"yeah actually it is"

obtuse jackal
#

Yeah you can

viral beacon
#

hmm, ok!
Thx for your help

obtuse jackal
#

When it shouldn't

viral beacon
#

.close

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#
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modern nymph
safe radishBOT
modern nymph
#

I don't understand what you would do here

#

arg(z-8) - arg(z-2) = pi/2

#

The points 8,0 and 2,0 are on x axis so how can there be an angle between them

#

also the angle pi/2 would just be a verticle line upwards so how would that work

safe radishBOT
#

@modern nymph Has your question been resolved?

safe radishBOT
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vagrant pasture
#

(A) ∀x∃y (x ≥ y) (B) ∃y∀x (x ≥ y), x and y are natural numbers

vagrant pasture
#

A entails B, B doesn't entail A

#

am i right?

safe radishBOT
#

@vagrant pasture Has your question been resolved?

safe radishBOT
#

@vagrant pasture Has your question been resolved?

faint raptor
#

A. For all x there is some y such that x >= y B. For some y all x are >= y
is that what it's saying

#

shouldn't b entail a too

vagrant pasture
#

.close

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paper dagger
#

I have kinda no idea how to start this problem. I recognized it as a M/G/1 queue with arrival rate 8 and service rate 2k but I'm not sure what to do with that information

paper dagger
#

I'm thinking for part (a) by PASTA principle we can find $\pi(0)$ to find the time that the professor is idle and the stationary distribution of the number of letters to be written is just $1 - \pi(0)$

flat frigateBOT
#

heheitsop

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#

@paper dagger Has your question been resolved?

paper dagger
#

<@&286206848099549185>

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#

@paper dagger Has your question been resolved?

paper dagger
#

<@&286206848099549185>

safe radishBOT
#

@paper dagger Has your question been resolved?

paper dagger
#

<@&286206848099549185>

safe radishBOT
#

@paper dagger Has your question been resolved?

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lusty spear
#

I have a questoin on the following probability exercise

lusty spear
#

you have to pick one of these boxes with closed eyes and then pick a ball out of that box you've chosen previously. Whats the probability to pick a white ball

#

now the point I am struggling with is, I need the probability of each box, and my brain tells me its 1/3 each but my math tells me that bs because then I always end up with false probabilites

quasi bison
#

what "false probabilities" are you ending up with, and how?

lusty spear
#

so lets say we name the boxes B1 B2 and B3
then I calculate
P(W | B1) so the probability to pick a white ball given I picked box 1 and that probability is greater than 1

#

which, afaik, is bs

quasi bison
#

P(W | B1) so the probability to pick a white ball given I picked box 1 and that probability is greater than 1
how is that happening?

lusty spear
#

so

#

my calculation ist this

#

maybe I am getting something else wrong

quasi bison
#

yeah P(W&B1) is not 5/6

#

P(W|B1) is 5/6

#

P(W|B1) is the probability to pick a white ball given that you already know your box is #1

lusty spear
#

but what is W n B1 even ?

#

yes

quasi bison
#

it's the probability that you get the first box AND draw a white from it

lusty spear
#

hm I always thought of it like, what are the elements that are both in W and B1

quasi bison
#

P(W n B1) would actually be 5/18 here

lusty spear
#

oh because

#

oh no

#

i dont really understand that

quasi bison
#

there are in fact 18 balls to choose from that are all equiprobable

#

(because all the boxes have an equal number)

lusty spear
#

I think I am having something mixed up in my head

#

one second

#

this is another exercise I did previously

#

we have 640 females and 360 males

#

and 15% of F smoke and 20 % of M

#

now that would make 96 female smokers in total

quasi bison
#

R = smokers?

lusty spear
#

here I imagined it like we have a pool of 640 females and I intersect it with those who smoke

#

yes in german it is raucher

#

and now here it was totally clear to me what the intersection would be

#

but with the boxes and balls I am a bit confused

#

or no, I think I can work with that. I'll just accept this for now. 5/18 is not too incomprehensible for me.

#

thank you for your help !!

#

.close

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open wren
#

\

safe radishBOT
open wren
#

what exact topics should i go over to be able to solve questions like these

#

Q 9

granite idol
#

i've seen this exact question posted before I think

#

but the topic is combinatorics/counting

open wren
granite idol
#

I don't know of any personally, sorry. I don't know if Khan Academy has any videos for it. You could try seeing if Harvard's course STAT110 has any videos/lectures online

#

well, there you have it lol

open wren
#

Oh yeah i see

#

Thanks guys

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floral valley
#

Hi can someone help me with question 1

safe radishBOT
floral valley
faint seal
#

do you know about the unit circle?

floral valley
#

Yep

#

Hello?

#

@faint seal

blissful harness
#

if u say u know about the unit circle, what value of angle (x) has their cosine value = cos ( pi/3 )?

#

find those x that lies within the interval u want

floral valley
#

60 degrees

blissful harness
#

what else?

floral valley
#

1/2

blissful harness
#

there are more than one such x if we consider from 0 to 2pi

#

do u know how sine and cosine function value oscillate between -1 and 1?

floral valley
#

Oscillate?

blissful harness
floral valley
#

No

blissful harness
floral valley
blissful harness
#

sine is essentially the y value and cosine is the x value in the graph, (tangent = y value / x value)

floral valley
#

Ye ye I know that

blissful harness
#

so in what degree/ radian that share the same cosine value as pi/3

#

other than pi/3

#

just between 0 to 2pi

floral valley
#

5pi/3

blissful harness
#

yes

#

and if we consider larger interval or in real number every 2pi the pattern repeats

#

ur question ask for 3pi/2 to 2pi so udh to consider others but in generally there is more roots

floral valley
#

Oh okay so I’m essentially using the value given and I’m just adding/subtracting 2pi until it fits into the domain

#

/restriction

blissful harness
#

not rly adding or subtracting 2pi, it depends on the function

#

sine, cosine, tangent each has different pattern

#

for example for tangent, u just keep adding/subtracting pi

floral valley
#

Wouldn’t it be easier just to subtract the maximal value from pi/3

blissful harness
#

$cos (x) = cos (k)$,
$x = 2n\pi \pm k$

floral valley
#

So in the case the maximum value has to be less than 2pi

#

So I would do 2pi - pi/3

flat frigateBOT
#

wannabe

floral valley
#

And even in the next question for sine pi/4, I would just do pi-pi/4

blissful harness
#

not like this

floral valley
#

Wdym

blissful harness
#

if next question change to cos x = cos (pi/4), find x in (pi/2, pi)

#

there would be no solution

#

i mean u can argue that ur hw wouldnt have "no solution" as ans

floral valley
blissful harness
#

and what if ur question doesnt give "nice" interval, like sin x = sin(pi/4), find x in (2pi, 4pi)

blissful harness
floral valley
#

Oh okay

floral valley
#

Because even if you try to fit that into the given domain

#

You cannot

#

Based on adding/subtracting pi

blissful harness
#

its better to understand the concept or pattern behind instead of, trial and error for each npi +- k

#

like if the range get rly large, u dont rly want to find them one by one

floral valley
blissful harness
#

the easiest way it is to visualize it like how sine, cosine, tangent value changes if u dw to memorize the formula

floral valley
#

So what’s n?

blissful harness
#

any integer

floral valley
#

For example?

blissful harness
#

cos x = cos (3pi/2) = 0
x = 2npi +- 3pi/2 for all integer n

#

..., -3pi/2, -pi/2, pi/2, 3pi/2, ... are all possible ans for x

#

then just pick those that lie in the interval u want

#

if $sin (x) = sin(k), k\in[-\pi,\pi]$, then
$x = n\pi + (-1)^{n}(k)$

flat frigateBOT
#

wannabe

floral valley
#

So I’d just let n = -3 to 4 (for example)

#

Depending on my domain

#

then I would find the values of x that locate within my domain

blissful harness
#

if $cos (x) = cos(k), k\in[0, 2\pi]$, then
$x = 2n\pi \pm k$

flat frigateBOT
#

wannabe

blissful harness
floral valley
#

Just an example

#

Like if my domain was very big

blissful harness
#

yea sure

floral valley
#

👍

#

.close

safe radishBOT
#
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little sorrel
safe radishBOT
little sorrel
#

can someone confirm this didnt get integrated properly

#

as the two 1/2's didnt get integrated properly and ones missing

lean otter
#

1/2 + 1/2 = 1

#

the antiderivative of 1 is x

little sorrel
#

o

#

i see

#

mb

glacial bronze
little sorrel
#

im a bit silly

#

.close

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warm oriole
safe radishBOT
warm oriole
#

,rotate

flat frigateBOT
warm oriole
#

Q8

#

<@&286206848099549185>

safe radishBOT
#

@warm oriole Has your question been resolved?

orchid dust
#

Which one is the problem you need help with?

full horizon
warm oriole
#

Nvm guys, I did it on my own

#

.close

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twilit trail
#

I’m confused on whether to use shell or washer method here ?

safe radishBOT
#

@twilit trail Has your question been resolved?

twilit trail
#

Nvm , it was washer method

#

i got it

#

.close

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zealous mason
#

Did I do this well?

Q: Adam lives in Bocianowo, and his friend Bartek - in Zabno. Adam made an appointment with Bartek in Zabno at 18:00. He left Bocianowo on a scooter at 17:20. Adam's average speed was 25 km
On a square grid, Adam shows a diagram of the route he is following.
What time did Adam arrive to meet Bartek? Save calculations.

hazy elbow
#

Distance from stawisko to bajorko can be calculated using pythagoreas theorem

#

like this

zealous mason
#

4 kms

#

@meager igloo help me

safe radishBOT
#

@zealous mason Has your question been resolved?

hazy elbow
#

it is 4 km up and 3 km right

#

so a 3 4 5 right triangle

#

distance between stawisko and bajorko is 5

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#
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frosty granite
#

if ur integrating ln x all squared

safe radishBOT
frosty granite
#

would u split into

#

lnx times lnx

#

and use by parts

split ether
#

Seems like a valid approach

frosty granite
#

is that the only way?

#

oh

#

could u split into 1 and ln x all squared

#

not sure

split ether
#

That works as well, cause you will then have to integrate 2lnx

#

In fact that is the better way

frosty granite
#

yeah

#

thanks

#

.close

safe radishBOT
#
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viscid quest
#

Two numbers, x and y are positive integrals. Which numbers are x and y if, x/3 + y/11 = 31/33

viscid quest
#

I've first gotten a common denominator: 11x/33+3y/11 = 31/33

#

(11x+3y)/33 = 31/33

#

So 11x+3y = 31

subtle steppe
#

yea

viscid quest
#

How do I solve

still charm
#

Theres only a few cases

subtle steppe
viscid quest
#

is that the only solution

subtle steppe
#

no

viscid quest
#

can't I do it another way

subtle steppe
#

but that's the easiest

viscid quest
#

yea ofc

still charm
#

You know that 0<=x<=2, because if x is 3 then it's bigger than 33

viscid quest
#

But I want to know how

#

right

#

so x is anything under 3

#

positive

still charm
#

You could use a greedy algorithm here

#

Find out how many 11s go into 31

#

Then find out how many 3s go into whats left

viscid quest
#

Two elevens

#

then 3 threes

#

oh

#

and thats 31

#

So x = 2, y=3

still charm
#

Yes

viscid quest
#

just a question, when do I know when I should use a greedy algorithm

still charm
#

In general its a good starting point for question like these

#

You might have to modify it a bit

viscid quest
#

got it thanks mate

still charm
#

Like for instance if you instead had 11x + 3y = 23

#

Then two 11s would give you 22, and 23-22=1, and 3 doesnt go into 1.
So then try one 11, then 23-11 = 12, and 3 goes into 12

#

So that works

#

It's an iterative process

viscid quest
#

but it works for all equations with two variables?

still charm
#

Yeah you'll eventually get the right answer, it's an algorithm

viscid quest
#

alright thanks for the help

#

.close

safe radishBOT
#
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lean otter
#

how come

safe radishBOT
lean otter
#

-29 mod 3 = -1 and not -2

#

I understand there is some formula or whatnot but I can't understand it logically

#

if 29 mod 3 = 2

#

because you can fit 3, 9 times inside

#

then have remainder of 2

opal zodiac
#

-29=-(3 * 9) -2

#

-2 =1[3]

#

Is -2 or +1

light shoal
lean otter
#

conceptually

light shoal
#

also, beware that different programming languages (and maybe different calculators) will have different conventions for this

lean otter
#

I can understand with the formula and the explanation

light shoal
#

a mathematician would expect the result to be 0, 1 or 2

#

but computer people have their own weird desires

lean otter
#

ah gotcha

#

I'm learning modular arithmetic for math competitions

#

not interested in programming or any of the sort

light shoal
#

what source is telling you that the answer is -1?

lean otter
#

Khan Academy

light shoal
#

interesting

lean otter
#

wait nevermind

#

it says

#

1

#

but I still don't understand it conceptually

#

how it's 1

light shoal
#

ah that's correct then

#

the idea is this:

#

add or subtract multiples of 3 to -29 until you get a number between 0 and 2

#

in this case:

#

-29 + 3x10 = 1

lean otter
#

ah gotcha

#

that makes sense

#

cuz remainder has to be between 0 and divisor - 1

light shoal
#

yep exactly

lean otter
#

gotcha

#

and an alternative way to do it

#

would be

#

-29 + (9*3) = -2

#

-2 mod 3

#

subtract a 3

#

-2 = -3 + R

#

R = 1

light shoal
#

yep that works too

lean otter
#

thank you for your help

#

.close

safe radishBOT
#
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light shoal
#

sure, cheers

safe radishBOT
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wintry radish
safe radishBOT
flat frigateBOT
#

Stephen

wintry radish
#

oh hey you again

#

but i don't understand

#

<@&286206848099549185>

plucky elk
#

,tex .diff rules

flat frigateBOT
#

riemann

wintry radish
#

huh

#

I am as lost as possible right now with the problem

#

<@&286206848099549185> (sorry for the second ping but i really really need help)

safe radishBOT
#

@wintry radish Has your question been resolved?

wintry radish
#

😭

spiral bane
#

@wintry radish!show

#

godamn I never learn

#

!show comes before the ping

safe radishBOT
#

Show your work, and if possible, explain where you are stuck.

wintry radish
#

I have no idea where to start

spiral bane
#

its asking for the rate of change at some time

#

how do you find the rate of change at a time

wintry radish
#

you derive?

spiral bane
#

the word derive isnt a calculus thing

#

derive just means like figure out

#

i think you mean differentiate

wintry radish
#

oh yeah

spiral bane
#

and how do we find the rate of change at a specific time t

wintry radish
#

dD/dt?

#

I have no idea

#

This is all new to me

spiral bane
#

it would just be dD/dt and you plug in some number for t

#

dD/dt is some function of t

wintry radish
#

uh huh

spiral bane
#

so do you know how to take these derivatives

wintry radish
#

sure

spiral bane
#

what is dD/dp and dp/dt

wintry radish
#

7225/(3p+13) => -21675/(3p+13)^2

#

and
1/12 * t^(3/2) + 6 => sqtr(t)/8

spiral bane
#

,w derivative of 7225/(3p+13)

flat frigateBOT
wintry radish
#

thats what i got

spiral bane
#

okay cool just checking

wintry radish
#

cool

spiral bane
#

alright so what are you stuck on

#

it looks like you got it down

wintry radish
#

getting the rate

#

what is p and t???

spiral bane
#

so what is dD/dt

#

uh

#

p = f(t)

#

t is just time

wintry radish
#

so t is 36 and p is 24?

#

so then that means that the rate of change is like -9/4?

#

that makes no sense how can there be negative blenders

spiral bane
#

wait slow down

wintry radish
#

ok

spiral bane
#

how did you get -9/4

#

also we are looking at the rate of demand

wintry radish
#

I plugged the values

spiral bane
#

which is just the instantaneous slope of demand

wintry radish
spiral bane
#

so that can be negative

wintry radish
#

oh

#

OHHHh

#

wait what

spiral bane
#

any decreasing function that has a positive value has negative slope

wintry radish
#

i suppose it makes sense now then

spiral bane
#

okay cool

wintry radish
#

I have another question i was wondering if you could help with this one too

#

or do i need another help channel

#

helloooo

spiral bane
#

!volunteers

safe radishBOT
#

Helpers are just people volunteering their time to help you. Be polite.

wintry radish
#

Oh sorry my bad

spiral bane
#

watch some videos on related rates

#

these are honestly annoying to explain every time

wintry radish
#

Ok

#

.close

safe radishBOT
#
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strange plaza
safe radishBOT
strange plaza
#

I have 2 more questions at the end of this practice test that I could not solve.

#

The first one, I was able to understand how to get the final answer

#

just now how to elaborate

#

let me get the table

#

I understand that X can represent the "questions correct"

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but I wanted to know a better way to word this

lean thorn
#

One way to consider it is you have a binary choices. A coin flip has either H and T. True or false has either T or F. Yes no has yes and no. 2 options only

When you flip the coin n times and you want x of an outcome, you have a probability of nCx/2^n. The 2^n is there because we have 2 options with n trials.

heady bobcat
#

Help me to do this

lean thorn
heady bobcat
#

Sorry I'm new

lean thorn
#

np! Head to that channel and it'll explain how to get help 🙂

lean thorn
#

For example, if you were to ask 10 people which ice cream they'd prefer: vanilla or chocolate, you are only providing 2 choices.

strange plaza
#

Or 2 marks, I assume the final answer is the last mark

lean thorn
#

I would use the term "binary choice". You get one or the other. Something like: "When flipping a coin, we have a binary option between heads and tails. Since answer can only be true and false, this is also only two options, so you would use the same combination of 10Cn/2^n for each P(X=x)". To find out the probability of getting five or more questions, we get: (10C5 + 10C6 + 10C7 + 10C8 + 10C9 + 10C10)/2^10 = (252 + 210 + 120 + 45 + 10 + 1)/1024 = 638/1024 ≈ 62.34%"

#

or something to that degree

strange plaza
lean thorn
#

yep np!

strange plaza
#

.close

safe radishBOT
#
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whole gale
#

wwwwwwww

safe radishBOT
whole gale
#

What are the answers

spiral bane
safe radishBOT
# whole gale What are the answers

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

whole gale
#

then how would I find the answers

spiral bane
#

brute force

whole gale
spiral bane
#

find all the zeroes

whole gale
#

How

#

@spiral bane

spiral bane
#

@whole galeyou have a quadratic

#

find the zeroes

safe radishBOT
#

@whole gale Has your question been resolved?

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daring edge
#

. help

sturdy briar
#

How can the common denominator be xy when the numerator only has an x???

thin bridge
#

not sure what you mean

maiden fossil
#

if you multiply 4/y by x/x

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and 3/x by y/y

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you get 4x/xy and 3y/xy

thin bridge
#

they employed the idea of multiplication by 1 to simplify the fraction

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in this case they multiplied the numerator and denominator of the big fraction by the lcd which in this case is xy

sturdy briar
flat frigateBOT
#

Azka Aska

sturdy briar
maiden fossil
#

no

sturdy briar
#

That was easy

#

Could you by any chance help me with one more thing that's been stumping me for 3 hours now?

#

I have no clue what to do next

maiden fossil
maiden fossil
#

okay i did it out

#

good

#

from here

#

simplify numerator on your left hand side

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2(x-2)-x =??

sturdy briar
#

x-4

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Is that right?

maiden fossil
#

yes

#

and now you can cancel out x-2 on both sides

#

leaving you with x-4/x=-4/(x+2)

sturdy briar
#

Alright, got that

maiden fossil
#

now cross multiply

sturdy briar
#

Can I do that even though they're on opposite sides of the = sign?

maiden fossil
#

yes that's precisely the case to cross multiply

sturdy briar
#

Would I be left with a denominator, or is (x-4)(x+2)-4x all that I'm left with now?

maiden fossil
#

yeah you got it

#

if you're meaning

#

(x-4)(x+2)=-4x

sturdy briar
#

Would my final answer be (x-2)(X+4) = 0

#

Which gives me teh solutions x=2,-4?

#

It is

#

You actually made my life a million times easier

#

thanks so much

#

.close

safe radishBOT
#
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wise venture
safe radishBOT
wise venture
#

How did we end up with (a.c)(a.c) here?
Shouldn't it be [(a.c)a].c

wise venture
#

😮

plucky elk
#

an easy way to see that is to let some other variable t=a.c

#

then [(a.c)a].c = [ta].c = t[a].c = t(a.c)

wise venture
#

Assuming that t is some scalar right.

plucky elk
#

if a.c is dot product of a with c, then a.c is a scalar yes

wise venture
#

Thank you for your time and assistance.

#

.close

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#
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lean otter
#

what is the highlighted part in set symbols ??

lean otter
#

is it (X union Y union Z)'

#

?

brave wolf
#

p=|(X u Y u Z)'| I guess

brave wolf
#

the cardinality (number of elements) would then be denoted with | |

#

so p = |(X union Y union Z)'|

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lean otter
#

A coin is tossed 3 times then the total possible number of events is ( 2^3 = 8 ).... right??? (just confirming)

lean otter
#

yea its correct

#

(HHH, TTT, HTT, THT, TTH, THH, HTH, HHT)

#

The outcomes

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#

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inland ibex
#

there is a x,y function contained in this area (im working with joint functions, statistics) and im trying to get the y function from that function, how do I do this?

inland ibex
#

lets call that function idk f(x,y)=1/2, just to make it simple?

#

I know that I need to take integrate x away from that joint function but idk how

#

I tried integral(1/2) dx from x=y+1 to y-1 but that doesnt seem right at all

split ether
#

I would let x go from -1 to 1 and y go from x-1 to x+1

#

But what you said seems to be right as well, except it should be from y-1 to y+1

inland ibex
#

Im more confused with the actual solution:

inland ibex
# inland ibex

im struggling to understand what he means by taking the integral from x=y-1 to 1, what does this exactly mean?

#

also the function was a bit more complicated than 1/2, I dont really care about solving the integral, im stuck understanding the boundaries and what the integrals are trying to do

split ether
#

First they integrated the area above x-axis and then the one below x-axis it seems

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But that is a really weird step

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What's the final answer btw?

split ether
#

Here is what letting y go from -1 to 1 and x go from y-1 to y+1 yields

inland ibex
inland ibex
split ether
#

So we are just doing the inner integral? (the one with respect to x)

inland ibex
split ether
#

Ah, so integrate that from y-1 to y+1?

#

That seems wrong though

split ether
inland ibex
split ether
#

Oh I think I see what they did now

#

Like I was thinking, they simply cut the shape in half

#

And integrated each separately

inland ibex
# split ether

wait I dont get how for example for y=0to2, that integrating from x=y-1 to 1 gets you that purple area

#

wont you get that 1 square minus the area under y-1, that you form the triangle above that purple triangle/area?

#

I was looking online for similar problems and it seems I dont understand this one thing

#

solution was

#

and I again thought that it was 0 to y

#

so why are we doing the 'opposite'?

split ether
split ether
#

Not between x = y and x = 0

#

Then it would be the other triangle yeah

inland ibex
inland ibex
#

altho I think I still have a question, why split the 2 areas up from y -2 to 0 and y=0 to 2?

inland ibex
split ether
#

Why are you subtracting purple from the green?

inland ibex
#

isnt that what we basically do when integrating from y=x to, oh, I might see my mistake, wait a sec

#

ok yeah now Im confused how that blue/purple area gets defined from x=y to x=1?

#

please explain like im 5 lmao

split ether
#

Can you name the lines between which that triangle is located?

inland ibex
#

y=0, x=y and x=1

split ether
#

Right, so it's between x = y and x = 1 (and y = 0)

inland ibex
#

yeah

split ether
#

Meaning x goes from y to 1

inland ibex
#

yes

split ether
#

Hopefully it's clear now

inland ibex
#

so what do you get if you do 1 to y

split ether
#

From 1 to y?

#

Then you will get minus the actual thing

inland ibex
# split ether

and so we split this in 2 because there are to many lines for an integral with 2 boundaries?

split ether
#

Yeah

#

You can do it as one integral but

#

That would involve min and max functions

#

Which require dividing the shape anyway

inland ibex
#

oookkk ill just keep it at, possible but diff

#

all in all thank you

#

🙏

#

.close

safe radishBOT
#
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eager prawn
#

i am given a function $k(x_1, x_2, x_3, T)$, each argument except for T has an absolute error value. T is given as 5 possible values and i can calculate k 5 times. I can also calculate the gaussian error (based on error propagation of uncertainty using $ \delta k = \sqrt{\sum_i (\frac{\partial k}{x_i} x_i)^2}$).
I need to present k as its average over thsoe 5 possible T values, how can i get the guassian error of the average then?

flat frigateBOT
#

derdotte

eager prawn
#

I remember that i can not simply average all 5 errors as that isnt how this works. Do i take the largest error of the prior k and add/subtract it to δk?

safe radishBOT
#

@eager prawn Has your question been resolved?

eager prawn
#

<@&286206848099549185> anyone mind helping?

lusty shell
#

Yes

eager prawn
#

.close

safe radishBOT
#
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safe radishBOT
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native storm
#

$$\forall n\in Z \text{ : } n\ge Z\implies n^2\ge 4$$

flat frigateBOT
#

BachToReality

native storm
#

I was watching a lecture online, where the professor gave this as an example for implication.
How does this hold true, for say n=0 or n=1?
1 >= 1 implying that 1*1 >= 4? Am I doing this right?

compact ferry
#

This is wrong in a lot of ways

split ether
#

Did you mean n >= 2?

peak estuary
#

are you sure you didnt misread what they wrote?

compact ferry
#

Are you sure you wrote it right

peak estuary
#

n>=Z makes no sense at all

#

n>=2 would make much more sense and additionally would make the implication true

native storm
#

devastation You might be right.
I would've mistook it for 2. It's a lecture from MIT OCW, guess my wet dream of disproving MIT profs will never become reality.
Thanks for your help!

#

.close

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#
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whole merlin
safe radishBOT
whole merlin
#

Confused on what this is asking for

worthy hemlock
whole merlin
#

No

worthy hemlock
#

Then that is where I suggest you start looking into

#

It wants that system of equations in augmented matrix form