help-23

[plucky yarrow]

Okay so do I put -2 for the first row?

Y = -2 (-2) + 4

Yes?

[lean otter]

uh im not sure about the value you've put for -1 either

[lean otter]

thats 8 now

[plucky yarrow]

Y = -2 (-1) + 4 = 6

Apparently

[lean otter]

yupp

the equation is y=-2/5x+5...

[plucky yarrow]

What

[jade magnet]

theyre doing it for y=-2x+4 i think

[plucky yarrow]

No thats a completely different question lol

That's a note my friend

Example on how to graph with the denominator

The equation we're using is the one on the right

[jade magnet]

for a linear function you only need 2 points

just do one more

and draw a line

[plucky yarrow]

My teacher says we need 5

With 0 in the middle on the x side

Idk I'm in grade 10 math cause I failed while doing online school

[jade magnet]

theres a difference of needing 5 and your teacher wanting you to do 5

you definitely dont need 5

[plucky yarrow]

I lose marks if no 5 on tests

[jade magnet]

ok just do them all

[plucky yarrow]

Yippee

Row 3: Y = -2 (0) + 4
Row 4: Y = -2 (1) + 4
Row 5: Y = -2 (2) + 4

Yes ?

[jade magnet]

yes

[plucky yarrow]

I put value of x in the y = mx + b spot

Oke epic

Saved my life thank you 🙏🏻🙏🏻

-close

Help idk the command

[jade magnet]

.close

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[lean otter]

Hello

[lean otter]

I'm really confused about where I went wrong

Q:
Mrs JOnes has some tropical fish. SHe has fewer fish than her neighbhour, Mrs Smith, who has 20 fish. If you choose 2 fish at random amongst Mrs Jones Fish, the probability tghat both of them have blue fins is exactly one half.

What I did was

(y/x)^2 = 1/2
where x = number of mrs jones total fish
and y the number of fish that have blue fins

[grizzled shoal]

Cant do that i think

[jade magnet]

mrs jones total fish and blue fin fish changes

after you pick the 1st

1 less total and 1 less blue fin

[grizzled shoal]

Chance for the first is y/x
Chance for the second is (y-1)/(x-1)
So we get
y(y-1)/x(x-1)

[lean otter]

oh yes

I'm an idiot

thank you

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[plucky yarrow]

What does 2 mean by undo the operation ?

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[lime monolith]

cos(a-b)=cos a cos b + sin a sin b

so this is basically

cos(2x-x)

[golden solstice]

Oh

[lime monolith]

cos x=1

[golden solstice]

Got it

[lime monolith]

though

there is no theta in the question

the range given is for theta

[floral osprey]

true so the actual solution is 0, 2pi, -2pi…

[lime monolith]

yes

and if we think that it is a misprint

then yeah x=0

[golden solstice]

Tysm

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[old lynx]

I need help with geometry

isosceles triangle ABC with sides AC=BC=30 AB=48. Find the radius of the inner circle.
What I tried is the pitagor theorem I found CH which is 18, but I cant find the radius, (the answer is 8)

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[old lynx]

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[rancid star]

when solving for the radius and interval of convergence do u always use the ratio test?

[rancid star]

like finding the lim of the absolute ratio an+1 / an?

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[lament tide]

<@&286206848099549185>

[outer raven]

show your work. what you tried before.

[plucky elk]

,w arcsin((1/2) * (1-sqrt(5/6)))

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[lament tide]

I want simplification

[pseudo scroll]

,w 0.043578 rad to degrees

[flat frigate]

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[pseudo scroll]

Yeah I don't think that's a standard angle

[plucky elk]

the angles inside the cotangent add up to a known constant. have you tried drawing a triangle where the sine of one angle is (1/2) * (1 - sqrt(5/6)), cosine is sqrt(2/3), and secant is sqrt(8/3)

,calc asin(0.5 * (1-sqrt(5/6))) + acos(sqrt(2/3)) + asec(sqrt(8/3))

[flat frigate]

Result:

1.5707963267949

[plucky elk]

,calc pi/2

[flat frigate]

Result:

1.5707963267949

[lament tide]

Calculator not allowed

[plucky elk]

that's why you draw the triangle

[lament tide]

How can we simplify it

[plucky elk]

.

[lament tide]

I didn't get
how triangle will give answer

[plucky elk]

draw it and you'll find out

[lament tide]

What next

[plucky elk]

.

[lament tide]

Can you explain to me more what steps should I do?

[plucky elk]

Do you know how to draw a triangle where the cosine of one angle is sqrt (2/3)

Right triangle*

[lament tide]

Cosine is adjacent/ hypotenuse

[safe radish]

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[lament tide]

Is this steps are wrong?

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[proud zealot]

How do i solve number 8?

[proud zealot]

Is it 48*64?

Hm

[weary osprey]

use trig

?

[proud zealot]

Explain?

[weary osprey]

What's sin thetha?

the definition?

[proud zealot]

What

[weary osprey]

Have you learned sin x, cos x, such functions?

[proud zealot]

Yes

[weary osprey]

You can identify x as opposite side to angle 90, and 9 as adjacent side

find the trig function which connects opposite and adjacent

[proud zealot]

Lost me

[weary osprey]

Do you know, sin thetha = opposite/hypotenuse

SOH CAH TOA

[proud zealot]

Yeah

I think 8th grade? Or was it 10th? Eh

[weary osprey]

So which trig function connects opposite and adjecent?

[proud zealot]

...

<@&286206848099549185>

[proud zealot]

Where did 9 come from?

Welp

Periods over

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[scenic holly]

Could someone explain this? :
(angle A) / 360° = s / (2 * pi * r)
What does 's' mean?

[lean otter]

whats the context to this?

[scenic holly]

One moment

[lean otter]

s is the arc length

[scenic holly]

Could you give me a full name of s?

[quasi bison]

what "full name" are you looking for

[scenic holly]

I mean, like A - area, C - circumference, r - radius, s -?

[quasi bison]

arc length is arc length

are you asking where the letter s comes from?

[scenic holly]

Yes

[quasi bison]

¯_(ツ)_/¯

i've seen it denoted as L for length

i've also seen s used as a letter for distance

probably by analogy with that

[scenic holly]

But what is a full word?

Space?

[lean otter]

Arc lengths are denoted by s, since the Latin word for length (or size) is spatium.
https://en.wikipedia.org/wiki/Arc_length

[scenic holly]

Thank you Toby!

[lean otter]

np

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[final goblet]

hi

[final goblet]

I need help asap

im so confused

[halcyon fractal]

Do you know how to write the given vector a on paper?

@final goblet

[final goblet]

no

its just that question thats annoying me

Ive done all the others

just not that

would it be

-10
6

[halcyon fractal]

Since the vector a is going 5 blocks left (direction of the negative x axis) and 3 blocks up (positive y), it can be written as (-5, 3)

[final goblet]

yea

then it says B is twice as long

so is that the first number or both?

[halcyon fractal]

So since b is double that it should be (-10, 6), yes

[final goblet]

alright ill see

correct

thank you

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[light lark]

how did they get the range -4

[light lark]

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[inner urchin]

so i think i have the right bounds for this problem, but would the integrand be 10-2x-y

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[golden hill]

is this just solving this matrix here?:

for c1, c2, c3, c4 or is it asking about something else?

[granite idol]

I think you have the right idea. you can multiply out your matrix equation to see if the coefficients match up

[still charm]

yeah just solve the augmented system

ain't nothing more to it

[golden hill]

Ok yeah I was just unsure about the setup thanks!

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[safe radish]

Please don't occupy multiple help channels.

[ionic bronze]

Can someone please check if that’s 3/4

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[devout raven]

Why does this not work for distance

[twilit spindle]

send problem?

[devout raven]

Am sending

[twilit spindle]

👍

[devout raven]

@twilit spindle

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[stone wadi]

is my solution correct? https://cdn.discordapp.com/attachments/1085261555307909131/1100640096413290506/IMG_0106.jpg

[mortal frost]

what are you trying to solve exactly

[stone wadi]

x = pi/3, am i correct?

i'm trying to solve for x

[mortal frost]

then yes ur right

[stone wadi]

so all i do is just use the sum formula for sin

[mortal frost]

x = pi/3

[stone wadi]

yay thanks

[mortal frost]

wait

[mortal frost]

come back

[stone wadi]

ok

[fluid token]

lmao

[mortal frost]

ur missing some stuff

[stone wadi]

like what

https://media.tenor.com/2Po0J643GRkAAAAC/caterpillar-smoking-catterpillar.gif

how do u steal mogolia @mortal frost when it dont exist

[mortal frost]

ur missing the 2pin

[stone wadi]

wachu mean homie

[mortal frost]

sorry $2\pin$

[stone wadi]

sorry 2

https://tenor.com/view/sanzmeme-moai-batu-emot-batu-gif-23675752

[mortal frost]

$2\pi n$

[flat frigate]

ᴊᴀᴄᴋ

[mortal frost]

there

[stone wadi]

brug

howd you get 2pin

[mortal frost]

it also has 2 answers

[stone wadi]

how

im naturally bad at math

[mortal frost]

this is trig right?

[stone wadi]

explain

yes and i suck at it

https://tenor.com/view/xd-gif-25311943

[mortal frost]

just look over ur formulas im sure theres one in there

[stone wadi]

dawg there's only 1 answer

[stone wadi]

u blind its just x = pi/3

[mortal frost]

ur missing something, you used the wrong formula most likely

[stone wadi]

bruh wachu on it's just``` sin (a + b) = sin a cos b + cos a sin b

[mortal frost]

so in ur problem sinxcos pi/2(equals 0) + cosx sin pi/2 (equals 1) = 1/2?

that doesnt make any sense

u would be left win sinx + cosx = 1

[stone wadi]

bro can u speak english

[stone wadi]

u just smashing words on a keyboard dont make sense'

give me a 32 pixel windows ms drawing at least

[mortal frost]

stop acting dumb bro, its clear as day

[stone wadi]

aight lmfao brodie thinks smashing trig functions into a sentence would be comprehensible

[mortal frost]

its so clear bro

but since you insist

[stone wadi]

i insist

prove me wrong

[mortal frost]

$sin(x) cos(\frac{\pi}{2}) + cos (x) sin(\frac{\pi}{2}) = 1$

[flat frigate]

ᴊᴀᴄᴋ

[mortal frost]

here

[stone wadi]

You just rewrote the problem

i dont see it

the magical solution you've been talking about

[mortal frost]

what you wrote was wrong, the above is what the formula gives you

[stone wadi]

bruh i wrote the same exact thing

[mortal frost]

you are left with $sin(x) + cos(x) = 1$

[flat frigate]

ᴊᴀᴄᴋ

[stone wadi]

youre tripping bruh

[mortal frost]

no you wrote it with 1/2

[stone wadi]

sin ^2 + cos ^2 = 1

what u just wrote is FALSE

[mortal frost]

nothing is squared'

parentheses do not = ^2

[stone wadi]

bro wdym wrong??

thats part of the problem

[mortal frost]

BRO

[stone wadi]

BRO

it's part of the problem

read the line above

noob

https://media.tenor.com/2Po0J643GRkAAAAC/caterpillar-smoking-catterpillar.gif

[mortal frost]

bro

this makes no sense then

[stone wadi]

im not the one who made these problems

also

the formuls youre using

[mortal frost]

because that is equals to sinx+cosx=1

[stone wadi]

sound like complete bogus

[mortal frost]

dude use the stupid unit circle

[stone wadi]

unit circle and trig is dumb

some old guy went like

lets put a triangle in a circle

[fluid token]

https://www.desmos.com/calculator/vjfa04keju

[mortal frost]

are you gonna go to college?

ur gonna need trig

[stone wadi]

duh

[mortal frost]

for some stuff

[stone wadi]

never heard of an undergrad not using trig

[mortal frost]

unless you wanna be some major that barely gets paid

[stone wadi]

u cant major without finishing ged

[mortal frost]

bro a GED is if you drop out of highschool

[stone wadi]

undergrad general ed?

[mortal frost]

u get a diploma for graduating HS

[stone wadi]

im not talking about that ged

[mortal frost]

What

thats not a thing

[stone wadi]

yes it is

for your undergrad years youre required to take some science classes]

math, and english

to fulfill your undergrad gen ed requirements

[mortal frost]

not for all majors

it just depends on the major

if ur STEM then yeah science and math

Art and English dont

[stone wadi]

jack

i have a question

[mortal frost]

what

[stone wadi]

y u such a nerd

[fluid token]

damn

[stone wadi]

if u r real u should help me

[mortal frost]

why dont you want to learn

[stone wadi]

with more trig

i like learning

now help me

you get paid $0 an hour to do this

[mortal frost]

ive tried bro

[stone wadi]

diff problem

much harder

[mortal frost]

i got a cal 2 test tmr so nah im hittin the hay

[stone wadi]

das crazy

im taking discrete maths so

get on my level kid

[mortal frost]

finals coming soon

discrete is easy

cal 2 is hard

u use some trig functions in cal and cal 2 btw

[stone wadi]

L finals

gl

[mortal frost]

ty bro

btw if you wanna get ahead or understand stuff better use Khan academy or the For Dummies books

they are very useful

also youtube in general

[stone wadi]

Yes ok

[mortal frost]

also read the math chapters

just read bro

its all there

alright gn bro

[stone wadi]

Bro I can’t read Elon musk

Gn

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[lament tide]

b-c=a-b

A+B+C=180⁰

a/sinA = b/sinB=c/sinC

How to reach possible answer

<@&286206848099549185>

[whole acorn]

i'd say try writing a, b, c as two variables

since they're in an arithmetic progression

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[mystic silo]

i have no idea how to solve this problem, the directions are "Find the area of the shaded region. Round to the thousandths."

[mystic silo]

so far i've found the radius with pythagorean theorem

(10)

[steep pewter]

ok

so the radius

take the lower side of the square

and raise it up

till it passes the center of the circle

u can use the radius

now

also probly thats the diameter

[mystic silo]

wdym

[steep pewter]

the line that says 16

not the 16 long part

the whole line

take it and raise it up

till its a radius of the circle

[mystic silo]

okay but what does that do

[floral veldt]

since you have the radius we need to find the unknown distance between the cut off points for our distances so we can get the area of the square. If we find the area of the square we can subtract the area of the triangle and half circle to find the remaining area.

We know the unknown distance, horizontally, which we'll call x, must conform to 8 + x = 10 as half the distance of our 16 will be 8 and the radius extends to the edge of the square. Therefore, we can find x to be 2. You can use the same process to find the vertical unknown (or use the fact that it's a square) and find the area that way

if you want me to draw a visual for what I'm talking about lemme know

[glad swan]

here's a visual. u can create a similar triangle using AAA

[safe radish]

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[safe radish]

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[tardy copper]

Is there something im missing about solving this intigral?

[tardy copper]

Here is my work:

its correct but I feel like there is a simpler way im missing

[pseudo scroll]

Integration by parts

[tardy copper]

hmm?

both sin for u and dv?

[pseudo scroll]

Differentiate sin^3 and integrate sin yes

[tardy copper]

ah hmm one sec let me try that

wait that still wont work

oh hmm

[pseudo scroll]

,w sin reduction formula

[flat frigate]

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Perhaps try rephrasing your question?
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Requested by NEONPerseus#2128

[pseudo scroll]

:/

,w sine integration reduction formula

[flat frigate]

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Requested by NEONPerseus#2128

[pseudo scroll]

Just google it

It's derived from integration by parts

You can "easily" compute the integral of sin^100 x by applying it

[tardy copper]

ah ok

I mean

I was trying this:

[pseudo scroll]

I'm not sure what you're doing here

[tardy copper]

its just int by parts

[pseudo scroll]

Oh wait was this for sin^4

Mb

[tardy copper]

yup

[pseudo scroll]

I asked you to integrate sin and differentiate sin^3

You seemed to have done it the other way round

[tardy copper]

deriving sin^3x would be more complicated no?

is this the formula you were trying to find btw

[pseudo scroll]

Not really

It sure as hell is easier than integrating it

$\dv{x} \sin^n x = n\sin^{n - 1} x \cos x$

[flat frigate]

NEONPerseus

[tardy copper]

hmm

yeah ur right, i need to review some of the derivative stuff idk why I thought it was more complicated

wait so the sin reduction formula is just

int by parts

[pseudo scroll]

Yes

Packaged neatly

[tardy copper]

alr that makes more sense

ill try it out

tyty

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[somber comet]

can someone teach me how to use emathhelp

basically i wanna input this to emathhelp and try it out

<@&286206848099549185>

[simple compass]

A

[somber comet]

A

need help

😦

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[polar cloud]

I need help showing that xlnx is uniformly continuous on ]0,1]

[polar cloud]

I know because it's continuous on [0,1] it's uniformly continuous but I'd like to do it using an epsilon delta proof

[empty gyro]

wdym? Continuity does not imply uniform continuity

[obtuse jackal]

Heine's theorem

Is what's referenced here

[polar cloud]

yea i'd like to do it without it

[empty gyro]

bruh what? I'm 0 for 2 today

[obtuse jackal]

Heine's theorem: continuous on a compact => UC on that compact

Do you want strictly e-d or just not Heine?

[polar cloud]

preferably only e-d

wait i have an idea

[obtuse jackal]

|x ln x - y ln y| <= |x ln x - y ln x| + |y ln x - y ln y| <= -ln x |x - y| + |y| |ln x - ln y|
you can probably make that work around 0

Because just not Heine is rather easy imo

Because no computations

[polar cloud]

|xlnx-ylny|<x|lnx|+y|lny|<x^2+y^2<(|x-y|)^2+2xy<delta^2+2

is this right?

[obtuse jackal]

That last line isn't < epsilon

2xy is nice around 0 though

then ofc anywhere but 0 is fine

[obtuse jackal]

Because it's lipschitz on any [a, 1]

[obtuse jackal]

I still prefer the computation free way though

[polar cloud]

didn't quite follow what you mean by that

[obtuse jackal]

Is it clear that this gives a neighborhood ]0, a] on which it's < e ?

For delta small enough

[polar cloud]

no

[obtuse jackal]

< d^2 + 2xy < d^2 + 2a^2 < e

For d and a < e/2 each for instance

[polar cloud]

oh got what you mean now

[obtuse jackal]

Personally I'd just say f(x) -> 0 so |f(x) - f(y)| < e if x and y are close enough to 0
And that gives a all the same but no computations

[obtuse jackal]

Then I impose d < a/2
I apply this property to [a/2, 1] to find d' <= d such that it works on that segment

Then you can check that d' works

No computations involved

[polar cloud]

mm intereseting

[obtuse jackal]

Yet this can be made into e-d by finding these deltas using the proofs of the properties

[polar cloud]

I like it

alright thank you

[obtuse jackal]

Notice the generality of this method btw

It works on anything you can extend by continuity

So basically just like Heine's theorem

But you could apply it to sqrt without any changes

[polar cloud]

i'd like to see it written

if you have any references

[obtuse jackal]

To this proof overall ?

I just made it up

[polar cloud]

I mean about this

[obtuse jackal]

You know that lipschitz -> UC

And bounded derivative => lipschitz

And continuous derivative on a compact => bounded derivative

[polar cloud]

yes

[obtuse jackal]

That's what's behind it

1+ln x is obviously continuous

(or just a product of C1 functions is C1)

[polar cloud]

yes we call it the inequality of the mvt

[obtuse jackal]

More like this right ?

The one you replied to is just a property of continuity

[polar cloud]

yea you're right

i meant that one

[polar cloud]

where did the a come here

[obtuse jackal]

a small enough with x and y <= a

[polar cloud]

nvm

just saw it

[obtuse jackal]

Hence me saying it works on]0, a]

And on [a/2, 1]

Then since I said d < a/2, if |x-y| < d, I guarantee it falls in one of these 2 cases

So I get away with an epsilon delta proof computation free

[polar cloud]

okay what about how do you continue from this

[obtuse jackal]

It totally works everywhere but 0 in fact

Cause you can't bound that ln x

[polar cloud]

yea i can see that

[obtuse jackal]

I just can't avoid falling back to this argument lol

Why compute, when you can see

[polar cloud]

this is just like heine's

right?

[obtuse jackal]

I only know one proof of Heine's and it looks nothing like that

[polar cloud]

i don't mean it like that

i mean this is extend continuity

[obtuse jackal]

In a way yes

Basically saying that if you swap the order in the definition of UC, then every continuous function verifies that property (letting d depend on x). And actually using that in a proof of UC

[polar cloud]

is it the one where we use sequences?

[obtuse jackal]

Yes

[polar cloud]

we did the same proof

[obtuse jackal]

By contradiction, construct a sequence with no convergent subsequence

[polar cloud]

one more thing in a normal uc proof d depends only on eps right?

[obtuse jackal]

Ofc

[polar cloud]

this is wrong because in this eps need to be >2 and we are trying to prove it for all eps

right?

[obtuse jackal]

That's why I made this correction, introducing a in the process

[polar cloud]

i'm finally seeing it now

would you mind if i send you a friend request

[obtuse jackal]

Just reminded me I need to clean my DMs

[polar cloud]

so...

[obtuse jackal]

I'm pretty busy most of the time, especially now so you probably won't get much out of it best scenario. It's always best to ask in the server

[polar cloud]

fine

have a good day

.close

[safe radish]

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[lean otter]

Derivative of 1/x^2

[lean otter]

I got -2/x^3

Is that correct

,w differentiate 1/x^2

[flat frigate]

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[lean otter]

yes

Damn

This calc will be very useful

,w slope -3x^2+(6/x^2) when x=3

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[lean otter]

God damn

,w differentiate 6/x^2

[flat frigate]

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[lean otter]

,w differentiate x^1/2

[flat frigate]

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[lean otter]

.close

[safe radish]

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[modern nymph]

what does x^y times by x^y equal

[modern nymph]

Is it x^2y?

[lean otter]

yes

[faint raptor]

yea

[modern nymph]

How come?

[lean otter]

remember the brackets though

,tex .exp rules

[faint raptor]

for (x^a)(x^b) x^(a+b)

[flat frigate]

Toby

[faint raptor]

think of it this way if it helps

x^a means you’re multiplying x by itself a times, x^b means you’re multiplying it by itself b times

overall you’re multiplying x by itself a+b times

for example

[modern nymph]

Oh yeah thanks that makes a lot of sense

[faint raptor]

x^2 * x^3 = xx * x*xx = x^5 = x^(2+3)

uh

forgot it made italics

[modern nymph]

Thank you I get it now

have a good day

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[peak crane]

whats the lcd of x, x-1, x^2-x

[peak crane]

is it just x(x-1)

[drowsy sparrow]

x^3-x^2

[peak crane]

no

i think your wrong

[floral osprey]

yep

[peak crane]

yea idk what hes wafflin about

thx tho

.close

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[safe radish]

@magic saffron Has your question been resolved?

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@magic saffron Has your question been resolved?

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@magic saffron Has your question been resolved?

[zinc heron]

@safe radish how do conversions work
like
if i say
a car goes 60 mph
how many feet
does it travel
per sec
like
how does that work again?

[safe radish]

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[cinder jasper]

ABC is an acute-angled triangle.
D and E are points lying on AC and BC respectively such that BD bisects AC and AE bisects BC.
AE and BD meet at the point H.
Let AH be x cm. It is given that HE = (4x^2 - 9) cm and BH = (4x + 6) cm.

Find BC:CD

[cinder jasper]

no idea where to start with

[loud patrol]

why did you draw right trianlgle angles?

also what is BC:CD

is that 2 seperate line segments?

[cinder jasper]

lines bisect

I am indicating it

bc cd is the side length

[loud patrol]

it doesnt say they bisect perpendicularly

[cinder jasper]

bc/cd

[loud patrol]

wait bc divided by cd?

[cinder jasper]

yes

[loud patrol]

ohh

[cinder jasper]

idk then

thr teacher drew the same thing

I think

[loud patrol]

ok

hold on

[cinder jasper]

alright

[loud patrol]

AH and BH should be equal

however

[cinder jasper]

why?

[loud patrol]

AH = x and BH = 4x+6

[loud patrol]

because the lines bisect each other

[cinder jasper]

x = 4x + 6??

[loud patrol]

yes

but the solution to that is negative

so it doesnt make sense

negative distance

[cinder jasper]

ac bisects dB, cb bisects ae

doesn't mean dB bisects ae

[loud patrol]

oh i see

but what im looking at is the right angles

the right angles indicates the triangle is isocoles

so the AC and BC are equal

[cinder jasper]

ah yes

[loud patrol]

so the bisectors are equal

[cinder jasper]

then whats the next step

[loud patrol]

so

(x) + (4x^2 -9) = (4x+6) + (4x^2 -9)

wait

cancel the 4x^2 - 9

and we are left with

x=4x+6

again

this problem doesnt make sense

[cinder jasper]

ugh

):

I'll talk to the teacher

[safe radish]

@cinder jasper Has your question been resolved?

[safe radish]

@cinder jasper Has your question been resolved?

[cinder jasper]

not yet

[safe radish]

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@cinder jasper Has your question been resolved?

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[fossil knoll]

help

[fossil knoll]

I dont know which one is easier to solve so I solved -x+y=15
and did -x=15-y
where do I put that?
wait ill recheck first

[grim plover]

Try adding ur two equations together

[fossil knoll]

this sysyem linear equation btw

the 2 equations are -4x-y=10 and -x+y=15

im using substitute

[grim plover]

Don't

Add them

And it's better to add x to both sides in 2nd one

If u want to use substitute

[fossil knoll]

meaning?

sorry me dumb

[grim plover]

Do y = 15 + x instead of -x = 15 - y

So sub for y instead of x

[fossil knoll]

ok

-4x-15+x?

[grim plover]

Mhm

[fossil knoll]

brb

[granite idol]

didn't you do this problem yesterday?

[safe radish]

@fossil knoll Has your question been resolved?

[fossil knoll]

this is no.4

[granite idol]

don't close another user's help channel

[plucky pagoda]

k

[fossil knoll]

for -4x-15+x

do I add -4x and x

[grim plover]

Yeah ofc

[safe radish]

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[fluid pecan]

someone help me with this

[fluid pecan]

please

[plucky pagoda]

if it decreased by 8%

that means it lost 8% value

so it is now 92% of the original value

and do the simple subtraction 319000 - 293480 = -----

[safe radish]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[plucky pagoda]

ok i changedi t

[safe radish]

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[native nebula]

help

[native nebula]

how do i model this

which one

[safe radish]

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[safe radish]

@solid token Has your question been resolved?

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[fluid pecan]

can someone help me with a math question?

[safe radish]

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[normal gyro]

I have to find that delta is equal to the underlined formula with the two formulas above, I tried to factor everything, to rotate everything, I can't find it, do you think there is an error or else how do you manage to demonstrate this?

[safe radish]

@normal gyro Has your question been resolved?

[plucky elk]

unclear what's given and what your work is. can you show original question and equation

[normal gyro]

yes

In french

But you see the two equation

I have to deduce from the two framed equations the equation of delta

this is just turning the two formulas to find

@plucky elk

[plucky elk]

solve for D in terms of v and Delta in the first equation and plug into 2nd. then solve for Delta

[normal gyro]

like this @plucky elk ?

[safe radish]

@normal gyro Has your question been resolved?

[plucky elk]

Yes

Are you able to solve for Delta

[normal gyro]

I try but i dont find the answer with 1/100 @plucky elk

because i have two delta (one on right side) and (one on left side)

[plucky elk]

use algebra?

$d + d \cdot\ x = d(1 + x)$

[flat frigate]

riemann

[normal gyro]

ahhh ok

to have only one delta

I try !

it work!

thank you @plucky elk

.close

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[mellow star]

in dire need to prove my friend wrong

please help

i did it and got 144 degrees for theta and 25cm for r

she got some other rounded numbers

Ok nvm she realised her mistake

.close

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[mellow star]

1-0 for me lets go

.reopen

[safe radish]

✅

[mellow star]

.close

[safe radish]

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[gilded fiber]

I’m stuck on how to integrate this (no calculator)

[bold ferry]

You don't really need to do the whole square and square root

Instead, you could find where the function hits 0 and do two integrals

And absolute value the negative area

[ember sphinx]

That works

[ember sphinx]

If you do want to stick to that horrible square root try putting everything in the root in the form (ax +b)^2(cx+d)^2 where a b c d are integers

If you see it that is

[safe radish]

@gilded fiber Has your question been resolved?

[gilded fiber]

Thanks guys

[safe radish]

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[safe radish]

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[waxen delta]

x^2+3x+1 how to comeplete the awuare

[waxen delta]

how do i complete the square when the b number isnt divisible by two

[dusty fiber]

you leave it as an improper fraction

like 3/2

[waxen delta]

it doesnt worek

[dusty fiber]

show me

[dusty fiber]

x²+3x+1=0

x²+3x=1

so just put the 3 over the 2

then square it

[waxen delta]

9/2

doesnt work

[dusty fiber]

$(\frac{3}{2})^2=\frac{3}{2}\frac{3}{2}=\frac{33}{2*2}=\frac{9}{4}$

[flat frigate]

CrEpasPmkinPie

[dusty fiber]

The equation now looks like $x^2+3x+\frac{9}{4}=1+\frac{9}{4}$

[flat frigate]

CrEpasPmkinPie

[dusty fiber]

$(x+\frac{3}{2})^2=\frac{13}{4}$

[flat frigate]

CrEpasPmkinPie

[dusty fiber]

$x+\frac{3}{2}=\pm\sqrt{\frac{13}{4}}$

[flat frigate]

CrEpasPmkinPie

[safe radish]

@waxen delta Has your question been resolved?

[waxen delta]

yes

[solid token]

help

[worthy hemlock]

Fyi .close to close the channel

[safe radish]

Please read #❓how-to-get-help

[solid token]

mb

is this occupied?

[safe radish]

@waxen delta Has your question been resolved?

Channel closed

Closed by @waxen delta

Use .reopen if this was a mistake.

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• Show your work, and if possible, explain where you are stuck.
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[granite totem]

Hello, can someone tell me what steps i need to take to solve this? im stuck

[stray socket]

Try the second derivative test

[granite totem]

what about min/max?

i found max to be

(4/45, 16/151875)

@stray socket

so would the max be the 16/151875? = .000105?

[stray socket]

Well that's a relative max yeah

It is a global maximum for x > 0

[granite totem]

ok but thats none of the answers?

from the multiple choice

[stray socket]

It wants you to find the location of the max

Look at the units

The dosage of x (cc)

The answers are in cc

They want you to find the location of the max

[granite totem]

i did

[stray socket]

4/45 ≈ 0.09

[granite totem]

here

[stray socket]

You found the value of the max

You didn't find the location

Well you did find the location

[granite totem]

how is the x value

our answer

[stray socket]

You took the value of the max instead of the location

Because it's asking which cc of a certain drug will maximize the blood pressure

[granite totem]

if its 4/45

then we plug that into x

for c(x) ?

[stray socket]

B(x)

[granite totem]

yea

[stray socket]

Idk what c(x) is

[granite totem]

we plug that in?

4/45

[stray socket]

It literally says verbatim:

Find the dosage at which the resulting blood pressure is maximized

It's NOT asking you for the maximum blood pressure

[granite totem]

ok

so its 4/45 then?

[stray socket]

You really confirmed that (4/15, 16/151875) is a maximum point. The dosage is 4/15 cc

[granite totem]

ty thats very helpful

i've got another one lol ... where do i start?

[stray socket]

Differentiate each variable with respect to time

This is just differentials

[granite totem]

uhm

whats the formula here

i see constant decrese of 9 a/s

-9, while it remains at 10v? so is it y=10v-9?

@stray socket

[stray socket]

Did you do what I told you to do

[granite totem]

too many variables

im confused man

@stray socket

[stray socket]

Product rule

You don't need to ping me every 2 minutes

[granite totem]

product rule

of what?

& sorry of ping

[stray socket]

Product rule for differentiation

[granite totem]

yes

but what variables

[stray socket]

Every single one

[granite totem]

9a/s

10v

and 52a?

[stray socket]

no

Like for example

[granite totem]

there is none

[stray socket]

If I differentiate AB with respect to t, it would be A' B + B' A

Where A' is dA/dt and B' is dB/dt

The same concept here applies

[granite totem]

idk what variables

to use man

ngl

can you point me in the right direction

whats a and whats b

soi can apply A' B + B' A

[stray socket]

Ohm's law is V = IR

Which part do you think is analogous to AB

[granite totem]

52a and 10v?

[stray socket]

...

Which part or side

Of Ohm's law

Has literally two factors

[granite totem]

not sure what ohm's law is tbh

9a/s * 52a ?

[stray socket]

THEY GAVE YOU OHMS LAW

V = IR

[granite totem]

yes

now what

?

v=ir now what

[stray socket]

_ _

Like I'm trying to show you there are two factors on one side of Ohm's law

[granite totem]

clearly

its not obvious

and u need to step in?

[stray socket]

IR = I*R

[granite totem]

i cant figure it out

[stray socket]

Analogous to AB = A*B

[granite totem]

ok

whats i

and whats r

i=9a/s?

[stray socket]

I is current and R is resistence

[granite totem]

r= 52a?

[stray socket]

They told you what I and R is

Let's start with identifying what V, I, and R is at the given scenario

They tell you V = 10 and I = 52. What would R be

[granite totem]

936a/s?

= d/da?

[stray socket]

V = IR

If V = 10 and I = 52, what is R

[granite totem]

520?

v'=0?

[stray socket]

dude im asking you one algebra question. This is literally one step in how to solve this. If you don't even know how to solve for R when V = 10 and I = 52 then idk how long it'll take for me finish this

Because then after that you'd need to differentiate both sides of Ohm's law

And then apply the rates appropriately

And then more algebra to find dR/dt

But im more concerned that it's difficult to find R when V = 10 and I = 52

[granite totem]

okwe ll

we're screwed

can u just tell me

what to do?

i can calculate the rest

i learn from your guidance

cause clearly ive never done this before

after you show me, it will be easier next time

[stray socket]

I've already told you what you need to do. The questions wants you to find dR/dt when V = 10, I = 52, dA/dt is 9

V is held constant which implies dV/dt = 0.

You can find R when V = 10 and I = 52. This part is literally basic algebra.

After finding R you need to differentiate V = IR with respect to time (t) and make algebraic substitutions. This should only leave you with dR/dt as the unknown variable

Need I spoonfeed you more?

And I already showed you to do the product rule for differentials

You'll always be thrown new scenarios and you'll need to know how to tackle them. Not every menial scenario needs a specific formula to solve.

[hot thistle]

the main takeaway should be that if you don’t know definitions and intuition for the material, you won’t be able to apply it, so make sure you’re actually understanding as you go along with a course

[granite totem]

hmm

ty

.close

[safe radish]

Channel closed

Closed by @granite totem

Use .reopen if this was a mistake.

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Remember:
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.