help-23

[marsh walrus]

[bold ferry]

wait so it works if we do 1 + cos(theta) = 1 - cos(theta)

and then for the left side

we flip the signs

-1 - cos(theta + pi)

= -1 + cos(theta)

set that = to 1 - cos(theta)

and that works out

but what if we do it the other way?

1 + cos(theta) = 1 - cos(theta)

we do the stuff on the right side

1 - cos(theta)
= -1 + cos(theta + pi)
= -1 - cos(theta)
1 + cos(theta) = -1 - cos(theta)
2 = -2 cos(theta)
cos(theta) = -1

wtf am i doing wrong?

should i write this on paper

this is getting very lengthy lol

oh no his sleeping pills kicked in

[safe radish]

@bold ferry Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert cedar]

“The equation x2 = -1 has real solutions.”

[desert cedar]

Would that be true or false?

[stray socket]

Graph x^2 and y = -1 and see if they intercept on the Cartesian plane

[bold ferry]

or try finding the square root of -1

[safe radish]

@desert cedar Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[river yoke]

Each number in a list is obtained as follows: The first two numbers are 2 and 3; then each number is the units digit of the number obtained by multiplying the previous two in the list. For example the first 5 numbers in the list are: 2,3,6,8,8. What number appears in position 2023?

[spiral bane]

extend the pattern and see what happens

[river yoke]

2,3,6,8,8,4,2,8,6?

[spiral bane]

keep going

[river yoke]

2,3,6,8,8,4,2,8,6,8,8,4,2,8,6,8,8,4,2

[spiral bane]

okay so clearly a pattern

[river yoke]

yep 6,8,8,4,2,8

[spiral bane]

yeah

that should be all you need to find the 2023rd term

[river yoke]

How?

[spiral bane]

well you know that the 3rd term is 6 right

also the 9th term is 6

[river yoke]

I dont get it, I mean what is the relation there, both are divisors of 3? but 2023 is not

[spiral bane]

well you know it repeats

so you can use the fact that 3 + 6n will be 6

so the start of the pattern

[river yoke]

Yes, but how do that helps?

[river yoke]

I understand why, but how that helps with that 2023 term

[spiral bane]

Well you can find a term near 2023 and finish the sequence

Like if you know term 2022

Go to the next number in the pattern

[river yoke]

Is it 4?

[spiral bane]

idk i didnt solve it

I got 2

[river yoke]

Im dumb I guess

lol hehehe

But how?

May you elaborate a little bit?

[spiral bane]

okay so

3rd term is 6

9th term is 6

2019th term is 6

becuase (2019-3) % 6 = 0

so

2020th is 8

2021th is 8

etc

[river yoke]

I get it now, thanks!

.close

[safe radish]

Channel closed

Closed by @river yoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint beacon]

I need help with this please

[verbal vault]

.close

[safe radish]

Channel closed

Closed by @verbal vault

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold temple]

I forget how to do 1b with variables on both sides. Help?

[desert pasture]

transpose

for instance, re-write it as 7n-2n=16+4

so 5n=20

ergo, n=4

[bold temple]

Damn I don’t remember that at all

I’ll brush up on this topic

Thanks

[desert pasture]

transpose is just a fancy word for performing teh same operation on both sides

instead, you could say, subtract 2n from both sides

then add 4 to both sides

which is what you're doing here

[desert pasture]

once your doubt is cleared, remember to close the chat.

[bold temple]

Ok

Thanks

.closw

.close

[safe radish]

Channel closed

Closed by @bold temple

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[peak crane]

#help-15 message

[peak crane]

.close

[safe radish]

Channel closed

Closed by @peak crane

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west lily]

Need some help with Complex Exponentiation

[west lily]

how would you find (z1)^7

[split ether]

Consider rewriting z1 in polar coordinates

[west lily]

haven't learnt all of those yet

i think the expectation for us atm is to just do it step by step

like this was what the professor did during lecture

[safe radish]

@west lily Has your question been resolved?

[west lily]

.close

[safe radish]

Channel closed

Closed by @west lily

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty glacier]

Find $\sin [\arccot {\cos (\arctan 1)}]$

[flat frigate]

bettim

[gritty glacier]

Is it $\frac{1}{\sqrt{2}}$

[flat frigate]

bettim

[thin bridge]

no

how are you getting that

[gritty glacier]

So

Arctan 1 is pi/4

Nvm

I took hypotunes as base

Mb

.close

[safe radish]

Channel closed

Closed by @gritty glacier

Use .reopen if this was a mistake.

[gritty glacier]

.reopen

[safe radish]

✅

[gritty glacier]

Wait no

So

Cos of pi/4 is 1/√2

I entered this in a triangle

I got base and opposite to be 1

And hypote5to ne root 3

Hypotenuse is root 2

Now cot is

1

Arccot is pi/4

Sin of that is 1 by to2

Root2

@thin bridge

[thin bridge]

I got base and opposite to be 1
you don't really care about the triangle where cos(pi/4) is 1/sqrt(2)

[gritty glacier]

So what do I do

[thin bridge]

you're interested in a right triangle where cot(theta) = 1/sqrt(2)

[gritty glacier]

So theta is pi/4 ?

[thin bridge]

no

[gritty glacier]

Okay sry right

Opposit dis root 2

[thin bridge]

you determined that arctan(1) is pi/4
and that cos(pi/4) is 1/sqrt(2) right?

[gritty glacier]

Ye

[thin bridge]

applying that your expression simplifies to

$\sin(\arccot(\frac{1}{\sqrt{2}}))$

[flat frigate]

ℝamonov

[gritty glacier]

Okayy

Now what should I do

Convert to rad?

[thin bridge]

no

[gritty glacier]

Wait

It doesn't give a regular angle

[thin bridge]

let $\theta = \arccot(\frac{1}{\sqrt{2}})$ \
(do NOT make any attempt to determine the numerical measure of $\theta$) \
draw a right triangle where $\cot(\theta) = \frac{1}{\sqrt{2}}$

[flat frigate]

ℝamonov

[gritty glacier]

So opposite is root 2 , base is 1, hypotenuse is root 3?

[thin bridge]

yeh,
and what's the sin of theta in that triangle

[gritty glacier]

$\sqrt{\frac{2}{3}}$

[flat frigate]

bettim

[gritty glacier]

Thanks

.close

[safe radish]

Channel closed

Closed by @gritty glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[light harness]

Hello, limx->pi/3 sin(3x)/1-2cos(x)

I did that and got 0, am I correct?

[lean otter]

Is that really sin(3x)/1-2cos(x) or is it rather sin(3x)/(1-2cos(x))?

[gritty glacier]

You means x tends to 0?

[lean otter]

He wrote x->4 so no

[light harness]

My bad

X means to pi/3

I got confused with another exersise

[lean otter]

x means to? Don't you mean x tends to?

[gritty glacier]

Direct substitution

[light harness]

Another error haha, sorry

[gritty glacier]

Wait

[brave wolf]

doesnt seem correct

[light harness]

So I don't need to use sin3x = 3sinx -4sin^3x?

[gritty glacier]

You may have to but sorry direct sub doesn't work

[light harness]

Hm

[lean otter]

Probably wrong... sin(3pi/3) is 0, and 1-2cos(pi/3) is also 0, and since they're both trig-based I would be surprised if the limit was 0 because that'd mean sin(3x) shrinks faster than 1-2cos(pi/3)

@light harness Can you show your workings?

[light harness]

Give me a sec

It's the B) one

Sen = sin

[lean otter]

,rotate ccw

[lean otter]

Since when does it actually rotate the way I asked it to

Anyways

How did you get that 2cos(x)=2cos^2(x)-1?

[light harness]

Isn't that an identity?

[lean otter]

Close enough

[light harness]

Oooooh

I see I see

So what do I do with the 1-2cosx?

[gritty glacier]

Again you wrote the question wrong,?

Was is 2cosx or cos2x

[light harness]

2cos

[gritty glacier]

Then how can you use the formula?

In denominator in second step

[gritty glacier]

Ye

Your step is incorrect ig

[light harness]

So whats the correct thing?

[gritty glacier]

2cos²x-1 is not correct formula for 2cos x

Afaik there isn't any formula for 2cosx

[light harness]

So, for this problem what am I supposed to use or do?

[safe radish]

@light harness Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[south linden]

could someone help me understand what is going on in this question?

im not entirely sure how to solve?

[faint seal]

did you understand what the top part means

[south linden]

i think it may mean i use that in the limit instead of the e^3x^3

[faint seal]

but did you understand what it MEANS

[south linden]

not quite

[faint seal]

how would you represent e^(x^2) using that expansion?

[south linden]

series of (x^2/n!)^n right?

if im understanding right

[faint seal]

well

what about the power of n

[south linden]

oh right i forgot about that

i currently have this

[faint seal]

the power of n doesn't cover the denominator

just the numerator

[south linden]

oh yeah cant read lol

alright so ive fixed that

[faint seal]

try writing out the first few terms

in that summation

remember that 0! = 1

[south linden]

i have a strong feeling it may be the terms to the right of it?

but will write some quickly

[faint seal]

that seems like a good guess

[south linden]

so its that but opposite signs

so assuming the first 3 terms cancel

i now rewrite the summation starting at 3?

possibly like this

[faint seal]

well

you can't just assume it

[south linden]

):

[faint seal]

but you're right

[south linden]

ok yeah i did the first two

so assuming the pattern

[faint seal]

notice that after n=3, all the resulting terms will have a power of x greater than 9

[south linden]

yup

so degree num>denom

or would there be some cancellation i could do?

i dont think so

[faint seal]

*except for the first term

[south linden]

right first term is same degree

[faint seal]

correct

so all the later terms are going to tend to 0

since x goes to 0

[south linden]

would it not be inf in this case?

since the numerator is increasing in exponents?

oh

[faint seal]

why would it be infinity

[south linden]

as x goes 0

sorry

[faint seal]

yes

[south linden]

read wrong

so the overall limit would just be 0

[faint seal]

so you only have to consider the first term of the summation

which would be?

[faint seal]

no

[south linden]

oh

oh right

[faint seal]

remember the first term will have the same degree

[south linden]

first is same deg

it will be that

which is

one second

[faint seal]

should be -9/10

I believe

[south linden]

maybe i messed up

[faint seal]

show your work

[faint seal]

yes

that's the same as -9/10

[south linden]

oh wait

/3

yeah

ok makes sense

so would there be a way to show all other terms tend to 0, or is it sort of trivial by showing deg P >deg Q

[faint seal]

you can take an x common in the other terms

[south linden]

ok

thank you

.close

[safe radish]

Channel closed

Closed by @south linden

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic ledge]

Hey! Why is Pi an irrational number when its clearly depictable in 22/7, a form of p/q where q is not 0?

[brave wolf]

pi=3.141592653589... 22/7=3.142857142857...

so they are not same

[hollow prawn]

22/7 is a round-off

fun fact; there are better fractional round-offs too like 355/113 approximation is accurate to six decimal places

[marble hamlet]

High school students can't handle that big of a value

Since 22/7 is mostly used in highschools

[elfin yew]

i used pi

in hs

[safe radish]

@mystic ledge Has your question been resolved?

Channel closed

Closed by @mystic ledge

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse widget]

i just need help on what type of shape this is, dont need help solving for variables

[wheat osprey]

How do I solve this

(Ignore my writing beside the question)

[obtuse widget]

<@&286206848099549185>

[granite tiger]

I don't get what you ask

[obtuse widget]

what type of shape is it

is it a square

or rhombus

i cant tell by the diagnols

[granite tiger]

A rectangle or a square, in my opinion

[obtuse widget]

how

[granite tiger]

More likely a rectangle

[obtuse widget]

a rectangle has congruent diagnols

[granite tiger]

I thought the angles could vary

Well, if the diagonals cannot be touched

Then it is likely a trapezoid

[obtuse widget]

oh

ok thx

.close

[safe radish]

Channel closed

Closed by @obtuse widget

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair leaf]

how do I turn this into a better equation that I can plug into a calculator and solve for. I have a duct tape solution using a spreadsheet that is just awful.

[spiral bane]

solving for what

[fair leaf]

solving for Pn

a is some constant I insert

[spiral bane]

okay so

I think it would be best to write out some terms

its not the simplest sequence that you can figure out in your head

[fair leaf]

like right out what P(2) would look like?

[spiral bane]

yeah

P3, P4, etc

[fair leaf]

assuming a is 55

[spiral bane]

okay dont do that

do it by hand

the whole point is that you dont simplify anything

[cold scaffold]

I need help

[spiral bane]

so that you can see the pattern

#❓how-to-get-help

[cold scaffold]

Can you help me plz?

[spiral bane]

no

[fair leaf]

\

[spiral bane]

😔

thats not what I meant

keep a as a variable

dont write any other decimals aside from 0.1 and 0.001

in fact

set 0.1 to a variable

and 0.001 to another

[fair leaf]

like this ?

[spiral bane]

okay thats a lot better

but now plug in P2, P3

[fair leaf]

what does that mean

[spiral bane]

well you still have a recursive sequnce here

you want to not have any value of P be dependent on other values of P

[fair leaf]

I don't get how you can remove P(2)

if you replace it with something else isn't that just still P(2) with a different name?

[spiral bane]

not really

the whole point here is that you want to find an explicit function

so for example P3

you dont want P2 in there

[spiral bane]

you want to use P(3) = (z + q(a^2/z) + q(a^2/((z + q(a^2/z)))

you want P(n) to be a function of just z, q, and a

$P(3) = (z + q(a^2/z)) + q(a^2/((z + q(a^2/z)))$

[flat frigate]

Kefir

[spiral bane]

hmm actually idk anymore

[fair leaf]

?

[spiral bane]

yeah

I think I got it

instead of z + q(a^2/z)

nope nvm

the issue is that there are two places to use z

so it gets really confusing

cause then you get an infinite fraction

[safe radish]

@fair leaf Has your question been resolved?

[wheat osprey]

<@&286206848099549185>

[spiral bane]

@wheat ospreythis channel is occupied

[wheat osprey]

Ahh

[wheat osprey]

Idk I sent my question much earlier tho when it wasn't occupied

[spiral bane]

it was though

[wheat osprey]

Idk 😐

[wheat osprey]

Anyways I'll send my prob in another channel

[fair leaf]

<@&286206848099549185>

[spiral bane]

is this hw

[fair leaf]

solving for Pn, a is some constant I insert

[spiral bane]

or your own question

[fair leaf]

my own question

[spiral bane]

it may not be solvable by hand

I was trying to solve it algebraically

if its your own question ig you can just do what you were doing before and plug into excel/sheets

[safe radish]

@fair leaf Has your question been resolved?

[spiral bane]

@fair leaf

[safe radish]

@fair leaf Has your question been resolved?

[safe radish]

@fair leaf Has your question been resolved?

[spiral bane]

@fair leaf I responded to you

[safe radish]

@fair leaf Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hallow quartz]

my tired brain can't comprehend. how do u go from top to bottom?

[hallow quartz]

more context

[empty gyro]

,w (k^(1/3))/(k^(3/2))

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by SWR#8588

[hallow quartz]

ok yeah 1/k^7/6 was what i got

[hallow quartz]

so this is just incorrect?

[empty gyro]

You can't go from top to bottom

[empty gyro]

On the second one here, looks like divided to and bottom by cbrt(k)

That would be my guess

[hallow quartz]

yeah, i divided by k^1/3, in order to get it in a format of a P-series test

and i got 1/k^7/6

which converges

and that's what the text book says

so i guess this explanation has a typo or smth then

.close

[safe radish]

Channel closed

Closed by @hallow quartz

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lament hazel]

In which case A and B can have infinite common multiples?

[lament hazel]

Where a and b are whole numbers

[quasi bison]

are you sure you asked exactly the question you wanted to ask?

[lament hazel]

Yes

[quasi bison]

"Let a, b ∈ Z. When do a and b have infinitely many common multiples?"

[lament hazel]

Yes

[quasi bison]

the answer is: whenever they are both nonzero

[lean otter]

Well well look who it is again

[quasi bison]

and i am not convinced there wasn't some kind of mistake

[lean otter]

A pair of positive integers always has infinite common multiples

[lament hazel]

[quasi bison]

||inb4 it turns out that yes there actually was a mistake in wording||

[lament hazel]

No there is not, i just reframed one of the questions in our text book.

[quasi bison]

reframed, you say.

are you 100% certain you did not make a mistake when reframing it?

can you show the original?

[lament hazel]

I just wanted to see a general case of this, as the answer of this is infinite but i wrote 3

[faint seal]

Any two non zero whole numbers will have infinite common multiples

I think you gave the answer 3 since you thought it was common factors

[lament hazel]

Got it

[lament hazel]

Yesss

That is what i thought

[faint seal]

But even if it was common factors, 3 is not the fight answer

[lament hazel]

Its 2

1 and 3 right?

[lean otter]

Nay, 2 doesn't divide 15

It's actually one you might not've thought of

[lament hazel]

3 and 1*

[lean otter]

✅

[lament hazel]

Yes

So 2 points more to mention in my notes

1 is the factor of all numbers

And number of non zero whole nos will have infinite common multiples

[lean otter]

That's not valid English but you got the idea

[lament hazel]

[safe radish]

@lament hazel Has your question been resolved?

Channel closed

Closed by @lament hazel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow knoll]

Did I get the surface area for this shape correct

[fallow knoll]

*The top side of the rectangular prism isn’t considered

[cold thunder]

What do you meen by the topside

Can you color it...?

[fallow knoll]

The side between the two shapes

And don’t worry about the top 2 equations

[cold thunder]

Okk

[fallow knoll]

Why is it w^2/4

[cold thunder]

Wait

The top triangle is isocele right ?

[fallow knoll]

No I just drew it weird

The slant heights are equal

I think you forgot to include the bottom side as well

Actually it could be isosceles

Because I’m optimising it to have the lowest surface area

[cold thunder]

Ooooh I see

[cold thunder]

True

[fallow knoll]

I just wanted to check if my formula was right

[cold thunder]

I think its correct

Just add wl to what I wrote ig

[fallow knoll]

Yeah cause w/2 all squared is same as w^2/4

[cold thunder]

Yup

[fallow knoll]

Alright thanks

.close

[safe radish]

Channel closed

Closed by @fallow knoll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cold thunder]

@fallow knoll just wondering because you said you want the smallest area what if it an equilateral triangle ?

[frank glen]

Hmm

If optimizing for lowest surface area then the triangles are preferred to be turned closer into the flat rectangular surface

[safe radish]

@cold thunder Has your question been resolved?

[cold thunder]

But then he won't have a lowest area for the rectangle ( roof) ?

[fallow knoll]

I don’t really think it matters if I get the smallest one possible

Just my working out

For that specific shape

[cold thunder]

okkk

[safe radish]

Channel closed

Closed by @cold thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[peak lily]

hey

[peak lily]

i've been working on this problem: , for all positive integers d, there exists an integer n such that ⌊(n+1)/d⌋ = ⌈n/d ⌉

<@&286206848099549185>

[dry trench]

are you asking for values of n?

[peak lily]

it's a proof, and i'm asking for the steps

[dry trench]

or both n and d

[peak lily]

don't want solution

i'm proving whether it's true

[dry trench]

sorry then

[peak lily]

all good

[safe radish]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[zinc token]

so basically, you want the full proof

which is the solution.

[dry trench]

@peak lily do you know mathematical induction?

[zinc token]

Is this proposition even true?

[supple shore]

Hum yes I'm not sure it's even true

Like if I take d=1 it's impossible ?

[safe radish]

@peak lily Has your question been resolved?

[peak lily]

no

[supple shore]

No what ?

@peak lily

Maybe it's more something like for all positive integers d>2

[peak lily]

.close

[safe radish]

Channel closed

Closed by @peak lily

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque pasture]

I need help solving this. I don't know where to start, I am not skilled in algebra. I will need step by step help from the beginning.

[hexed dune]

@opaque pasture f(2)

means

put 2

where x is

[opaque pasture]

3*2

?

[hexed dune]

yh

but obv the rest aswell

[opaque pasture]

-1.4

how do I get it as the fraction

[eternal fjord]

Replace all the x with 2. f(x) means a function that takes in a value and assigns it to x (in this case).

[opaque pasture]

i just did that..

[wraith locust]

Solve it

[opaque pasture]

-1.4

is what I got

[opaque pasture]

..

[wraith locust]

change it to fraction form

[opaque pasture]

..

[eternal fjord]

6 - 8 + 3 all over 5

[quasi bison]

!nosols

[safe radish]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[wraith locust]

-1.4 is -14/10

Then simplify

[opaque pasture]

I'd already solved it genius.

[tall bough]

how did u get to 1.4

[opaque pasture]

-1.4

[tall bough]

how did u get it

[eternal fjord]

Lexa show your work

[wraith locust]

Maybe the calculator does not have fraction form. It gives the answer in linear or decimal form

[opaque pasture]

3x2-2x2^2+3/5

that is what i input

[wraith locust]

use parenthesis when typing math equations hehe

[eternal fjord]

All of that is over 5, not just the 3

[tall bough]

thats not -1.4

[opaque pasture]

it is for me

[tall bough]

then keep living in that delusion

[wraith locust]

use parenthesis

[opaque pasture]

bruh its what im getting

[wraith locust]

That's why

[opaque pasture]

where

[wraith locust]

Use parenthesis

[opaque pasture]

@tall bough fuck off nerd

[alpine path]

Chilll

[eternal fjord]

Wrap the top part of the fraction with parenthesis

[opaque pasture]

alr

[tall bough]

theres no really need to use a calculator for this

[eternal fjord]

Like (…..) / 5

[opaque pasture]

ok well idk math

so

[opaque pasture]

uhuh i got u

alr I got the answer right

thanks @eternal fjord

and u can @tall bough suck my dick

.close

[safe radish]

Channel closed

Closed by @opaque pasture

Use .reopen if this was a mistake.

[tall bough]

😆

[eternal fjord]

But yes you don’t need a calculator. Just try 32 - 22^2 + 3 then put that all on top of 5

[wraith locust]

[eternal fjord]

Aww it messed up my *

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken yew]

<@&268886789983436800>.
dk if its a joke between friends but inappropriate here anyways...

[broken yew]

.close

[safe radish]

Channel closed

Closed by @broken yew

Use .reopen if this was a mistake.

[tall bough]

Theyre too young to be my friend

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wet gust]

so

[wet gust]

i got this problem

ive done steps a-d but the last step is confusing

im given 251.3g mass with a string that is 1.3m long and a speed of 1.3

its a pendulum swinging in a circle motion

i have to calculate the centripetal acceleration with fc=mac=mV^2/r

using the last part i get centripetal acceleration = .33

i find the tension with t=m((v^2/r)+g) and get 2.8N

the last problem wants me to determine the centriepetal force acting on the mass

[misty coral]

how did you get this?

[wet gust]

t=.2513(1.3^2/1.3+9.8) = 2.8

my bad wrong part

.2513*(1.3^2/1.3)=.33

[misty coral]

so that would be the centripetal force

[wet gust]

that is centrieptal acceleration isnt it ? or are they the same thing

[misty coral]

no not the same thing, if we say Σ F = ma_r = mv^2 / r , then a_r = v^2 / r

[wet gust]

Fc is centripetal force Ac is centripetal acceleration

and im at the Fc=Mac im just confused ngl

[misty coral]

sure, and the centripetal force is given by mv^2/r

[misty coral]

hence this

[wet gust]

i did it backwards

[misty coral]

yep

[wet gust]

lol oopsies

thanks

so the Ac

is just V^2/R correct ?

[misty coral]

yes

[wet gust]

ugh i went and confused myself again

so no.1 says calculate the centripetal acceleration of the mass

is the answer to that just V^2/R ?

[misty coral]

yes

[wet gust]

and the Fc is m(V^2/R)

[misty coral]

yes

[wet gust]

okay thanks so i now have ac = 1.3 t = 2.8 and fc = .33

[misty coral]

what are you doing for the tension?

[wet gust]

t=m((v^2/r)+g)

[wet gust]

this

[misty coral]

I would disagree I think

[wet gust]

did i calculate wrong ?

thats the formula it gives me to use for tension

[misty coral]

oh sorry I see the mass is factored out

sure

👍

and im assuming this is when the pendulum is at the lowest point?

[wet gust]

okay thanks for the help greatly appreciated and yes

.close

[safe radish]

Channel closed

Closed by @wet gust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fresh finch]

Name a segment that is a radius. How long is it?
Show or explain your reasoning.

[fresh finch]

I'm confused, and don't know where to start.

I need help ASAP.

[mortal topaz]

If diameter is 15=2r , then radius is 7.5 cm AC=AD

[fresh finch]

So it would be 7.5.cm?

but its asking for the radius

[bold ferry]

Radius is half of the diameter

[twin bough]

you have to measure with the ruler the radius

(i dont speak english very well..)

[fresh finch]

But it asking for one of them

[bold ferry]

lol I doubt it, this is an online image

[twin bough]

oh

[mortal topaz]

Radius is the same from the center point

[bold ferry]

the diameter of 15cm is given, so radius is half

[fresh finch]

half of 15?

[bold ferry]

yes

15 / 2

[fresh finch]

Divided?

[twin bough]

yes, its 7.5

[fresh finch]

so the answer is 7.5

[mortal topaz]

Yes

[fresh finch]

ok.

thank you

[twin bough]

u´re welcome

[fresh finch]

Wait

[twin bough]

what?

[fresh finch]

Its asking to my work

[twin bough]

yes and?

[fresh finch]

how can i show my work

[river sky]

Look

Diameter = 15cm

Diameter/2 = radius

15/2 = radius

7.5= radius

Simple

That's all the work

That you need

[twin bough]

you have to measure with the ruler the radius, like if is the G or something else

[river sky]

Every segment there is a radius too

AC=AD=AE=AG=AB = 7.5cm

[fresh finch]

ok.

[river sky]

Indicating they all are radii

[fresh finch]

one more thing

[river sky]

Agreed

Ruler is good too

[fresh finch]

Name a segment that is a diameter. How long is it?

This is the last question

[river sky]

CD is the only diameter in this picture

[twin bough]

is it not the A?

the middle point?

[river sky]

A is the centre of the circle

A is Mid Point generally

[fresh finch]

Ooh

So it would be C-D conneting

[twin bough]

okay

[river sky]

Yes

[fresh finch]

But its asking how long is it

[river sky]

It's 15cm

CD is 15

[twin bough]

its 15

[river sky]

It's given

Right below CD it's written 15

Meaning

CD is 15cm

[fresh finch]

Ok.

Thank you

[river sky]

Alright

[twin bough]

u´re welcome!

[river sky]

.close

[safe radish]

Channel closed

Closed by @river sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent tendon]

I feel like this is more of a "am i reading the problem correctly for a mathematical problem", so heres my question. There are the equations given to me: (1st page) and these are the data given to me (page 2) so is ra, r1 rb, r3 and c is c1
Image
Image

[latent tendon]

I assume so because

[safe radish]

@latent tendon Has your question been resolved?

[safe radish]

@latent tendon Has your question been resolved?

[safe radish]

@latent tendon Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar spade]

This is what I've done so far. I just wanted to know if I'm going about the problem correctly, as this is the first question of the assignment.

[safe radish]

@pulsar spade Has your question been resolved?

[safe radish]

@pulsar spade Has your question been resolved?

[safe radish]

@pulsar spade Has your question been resolved?

[safe radish]

@pulsar spade Has your question been resolved?

[spiral bane]

this looks like pain

see if you can just get a online calc to do it

like wolframalpha

[safe radish]

@pulsar spade Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frosty granite]

For part c u get x squared =144

[frosty granite]

I’m confused about why x would be -12 rather than 12 given the domains

[safe radish]

@frosty granite Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[frosty granite]

.reopen

[safe radish]

✅

[frosty granite]

<@&286206848099549185>

[alpine path]

The function is the composition of f and g, so f(g(x)) = 17.

The function goes from the domain of g to the range of f.

[frosty granite]

okay hm

[alpine path]

Still confused about something?

Better explanation maybe:

If x^2 = 144 (what you said) Is the answer.

x has two possible answers. Check if both these values plugged in g, give a value that is in the domain of f. If both happen to fall in the domain of f, then both values are correct. Since both values can be chosen to get f(g(x)) = 17.

@frosty granite

Always be careful when squaring roots though, since you might get an answer that is not a real number, when plugging that number back into the square root.

[frosty granite]

ohhh ok

yeah that makes way more sense

[frosty granite]

calm

thanks

[alpine path]

good luck!

[frosty granite]

.close

[safe radish]

Channel closed

Closed by @frosty granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upbeat swan]

Is TREE(3) closer to TREE(2) or to TREE(4)?

[tall bough]

difference between tree(3) and tree(4) is way larger than the difference between tree(2) and tree(3)

[upbeat swan]

Why

[tall bough]

The sequence of TREE(n) grows incredibly quickly as n increases

[safe radish]

@upbeat swan Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty glacier]

$\arctan ( 1-x), \arctan (x) , \arctan(1+x)$ are in AP , find $x^3 +x ^2$

[flat frigate]

bettim

[upbeat swan]

.close

[gritty glacier]

bruh smh

[upbeat swan]

Sry lol

I thought it was my channel

[gritty glacier]

its okay :3

<@&286206848099549185>

[lean otter]

What is AP?

[gritty glacier]

arithmetic progression

[lean otter]

That means that

arctan(1-x) + arctan(1+x) = 2 arctan (x)

[gritty glacier]

yes

i did that

[lean otter]

Have you seen something about formulas of the sum of the arc?

arctan(x+y) in terms of arctan(x) and arctan(y)

[gritty glacier]

$\arctan x + \arctan y = \arctan (\frac{x+y}{1-xy})$

[flat frigate]

bettim

[gritty glacier]

this?

[lean otter]

Formulas like that

[gritty glacier]

in terms of arctan x and arctan y?

np

nop

[lean otter]

I would try to consider this to write arctan(1+x) + arctan(1-x)

Considering 1+x instead of x and 1-x instead of y

[gritty glacier]

im getting $\arctan(\frac{2}{-x^2})$

[flat frigate]

bettim

[gritty glacier]

is that right?

[lean otter]

Maybe arctan(2/x²)

[gritty glacier]

so xy would be (1-x)(1+x)

that is (1+x-x-x^2)

no?

so 1 - xy would be -x^2

[lean otter]

we have that

2 arctan(x) = arctan(x)+arctan (x)

So 2 arctan x = arctan (2x/(1-x²))

[gritty glacier]

you told to consider the other two arctans

[gritty glacier]

i did this

[lean otter]

1-xy = 1 - (1+x)(1-x) = 1-1 +x²

[gritty glacier]

we have to take the - sign inside oh got it

so it is x^2 only

right?

[lean otter]

In the denominator yes

[gritty glacier]

tahnks got it

is the final answer 1?

[lean otter]

So we have

arctan(2/x²) = arctan(2x/(1-x²))

Do you agree?

[gritty glacier]

e

ye

i did it all

i got

$x^3 + x^2 = 1$

right?

[flat frigate]

bettim

[lean otter]

Right

That is it

[gritty glacier]

thnks

.close

[safe radish]

Channel closed

Closed by @gritty glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty glacier]

helo

[gritty glacier]

find $\frac{dy}{dx}$ if $ 2x+y =\sin y$

[flat frigate]

bettim

[gritty glacier]

i got $\frac{2}{\cos y-1}$

but answer says wrog

[flat frigate]

bettim

[jade magnet]

i think is -2 not 2?

[gritty glacier]

how?

[jade magnet]

oh nvm i just did it the other way around 💀

[gritty glacier]

💀

is the -1 in denominator right?

it is given as -3

[jade magnet]

i got -2/1-cos(y) which is the same so i dont know lol

[thin bridge]

can you show what you're entering into the system

[gritty glacier]

nvm the pdf's fuked up i guess

[gritty glacier]

?

[thin bridge]

thought you were entering that into some online thing and that came out as wrong

[gritty glacier]

also $2x + 3y = sin x$

[flat frigate]

bettim

[gritty glacier]

it as a practice pdf

[gritty glacier]

what is dy/dx

im getting

$\frac{1-x\cos x}{x}$

[jade magnet]

through what steps?

[gritty glacier]

wait

wrong ques

it is 3x not 3y

so no y terms

so dy/dx is 0?

.close

[safe radish]

Channel closed

Closed by @gritty glacier

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive palm]

i need help here

[final plinth]

D=0

[misty coral]

what are the conditions for the discriminant if the function touches the x -axis at one point

[restive palm]

that the discriminant = 0

[misty coral]

apply that here then

what are your a,b,c values?

[restive palm]

a = 1
b = -k + k
c = 8

?

[misty coral]

I would say no.

[obsidian oracle]

Look at your expression of b

That would just make b = 0

[misty coral]

your a value is the coeff of your x^2 term, your b value is the coeff of your x, and then c is the rest of the jargan , just constants

[restive palm]

oh

a = 1
b = 0
c = 8

like that?

[misty coral]

k still exists

[obsidian oracle]

But the coefficient in x isn't 0, is it?

[restive palm]

c is 8 + k then?

[misty coral]

yes.

that makes b?

[restive palm]

b = 0?

[misty coral]

no.

[obsidian oracle]

.

[restive palm]

oh k

[misty coral]

close

[restive palm]

um

x?

wait no

1?

[obsidian oracle]

You want to write ax² + bx + c

So far we have a = 1

C = k+ 8

So that's x² + bx + k + 8

[restive palm]

the coefficient of x in b is k right?

[misty coral]

not just k

[obsidian oracle]

That would make it x² + kx + k + 8

[restive palm]

-k?

[misty coral]

yes

[obsidian oracle]

Yes!

[restive palm]

ah nice

let me solve now

so the eq looks like

-k - 4(1)(k+8)^2

just to make sure

oh one sec

wait what's wrong here

[misty coral]

what do your notes say the discriminant is given by

[restive palm]

b-4ac^2?

[misty coral]

no, did you refer back to your notes

[restive palm]

oh I think I wrote it wrong

[misty coral]

its given by b^2 - 4ac,

[restive palm]

alr thanks

so the eq after simplifying is k^2-4k+32

?

[lean otter]

k^2-4(k+8) =/= k^2-4k+32

[misty coral]

^

[restive palm]

is that the same?

[lean otter]

Not equal bro

[restive palm]

ohh

[lean otter]

What is negative 4 times k? what is negative 4 times 8?

[restive palm]

oh -32

[lean otter]

keep going you almost have the solution.

[restive palm]

so the answer is 4 and -8

for D

[lean otter]

???

[restive palm]

right?

[lean otter]

(k+4)(k-8) is indeed the factor but not the roots

[misty coral]

the factors would be (k+4)(k-8) = 0 yes

[lean otter]

If we are looking for k we need to find the roots.

[restive palm]

alrr

another q sry lol

[misty coral]

wait

you havent finished this one

[restive palm]

-4 and 8?

[misty coral]

alr sure

[lean otter]

Broooo

[restive palm]

lol

[misty coral]

same concept

I think you could do this one on your own

[lean otter]

𝐁𝐎𝐌𝐁𝐀𝐒𝐓𝐈𝐂

[restive palm]

the answer is +-9?

o wait 3

[lean otter]

My dumbass set it equal to (x-a)^2 and then had to undergo 2 variable changes.

[restive palm]

lol

[misty coral]

and?

[restive palm]

3 and -3?

[misty coral]

yes

[restive palm]

ah great

thank you all

ill close now

.close

[safe radish]

Channel closed

Closed by @restive palm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank musk]

Can someone help me/tell me what is missing in my proof?

[frank musk]

I've been told it does not cover all cases, but I don't see it.

The proposition I'm trying to prove is

Show that no number n with n ≅ 3 (mod 4) can be written as a sum of two integer squares

[white hollow]

present your proof

[frank musk]

Is it visible?

[white hollow]

yes that's essentially the proof

actually I don't see a problem with it

let me check again

[frank musk]

The feedback I got was

"The assumption that m and n have to be odd and even respectivly does not cover all cases."

[white hollow]

uhh

I don't understand that feedback, what you wrote seems perfectly fine

(odd, odd) (odd, even) (even, odd) and (even, even) are the possibiltiies for m and n and you covered all of them

[frank musk]

Yeah that's what I thought as well. I'm not sure what's wrong

if anything is wrong at all. I was only given 50%

[white hollow]

I believe whoever gave you that feedback is mistaken

[frank musk]

Is there any cases at all where this doesn't apply?

[white hollow]

perhaps they expected you to explain why both m and n having the same parity does not work

[frank musk]

But why give me that feedback then?

[white hollow]

it does cover all cases

I don't know why they gave you that feedback

[frank musk]

It spesifically said that id doesn't cover all cases, which is weird

[white hollow]

the only perceivable issue I can come up with is what I just mentioned

[white hollow]

there are no other possibilities for a pair of integers, so you need not worry

[frank musk]

Ok, thanks!