help-23

[timid goblet]

Where do I get the r from

Do I just do x-x?

[frosty skiff]

R(x) is just a function that is defined by 550*x^3-12000x^2+83000x+7000

[timid goblet]

Oh

So what your saying is that

I Plug in the function RX

[frosty skiff]

Yes

[timid goblet]

550x^3-12000x^2+83000x+7000?

Right

Do I put the C(x) at Y2?

@frosty skiff

[frosty skiff]

Yes

And then in Y3 you put Y1-Y2

[timid goblet]

Which is 2 and 16 correct?

2-16

Right

[frosty skiff]

No 2 and 16 are the intervals which means that we let x be equal to any value between 2 and 16

[timid goblet]

Oh

What’s the y1 and y2 then

[frosty skiff]

Y1 = to a y value depending on x

It's a function

[timid goblet]

What number do I type in for y

Y1

@frosty skiff

[frosty skiff]

Y1 is like your function name

Y1 is like R(x)

[timid goblet]

So I just type in “y” and “1”

Oh

Wait

Rx is 550x^3-12000x^2+83000x+7000
But what’s Y1?

?????

[frosty skiff]

Y1 is R(x)

Y1 is just the calculator showing it this way

[timid goblet]

Could’ve said that earlier 💀

Ok

[frosty skiff]

Sorry

[timid goblet]

550X^3-12000X^2+83000X+7000- 880X^3-21000X^2+150000X-160000 right?

[frosty skiff]

You forgot the parentheses so it's 550X^3-12000X^2+83000X+7000-( 880X^3-21000X^2+150000X-160000)

This is P(x)

[timid goblet]

Oh

So parentheses for both

(550X^3-12000X^2+83000X+7000)- (880X^3-21000X^2+150000X-160000)

[frosty skiff]

Yes

[timid goblet]

@frosty skiff then j graph right

I*

[frosty skiff]

?

[timid goblet]

What do I click after this?

[frosty skiff]

I think you press -> graph

Then you will see 3 curves

[timid goblet]

Tf

[frosty skiff]

The value are realy high

[timid goblet]

So I scroll down

)??

Nah doesn’t do anything

[frosty skiff]

The lowest one is 15557.489

If you divide by 10^5 you will maybe see it

I reproduced it in geogebra and it gave me this

[timid goblet]

Dawg so imma have to type all that out again

💀💀💀💀

[frosty skiff]

No

[timid goblet]

Oh

[frosty skiff]

You can edit them

[timid goblet]

So I divide instead of subtracting

[frosty skiff]

Just press the right arrow and it should be editable

Do (550x^3-12000x^2+83000x+7000-(880x^3-21000x^2+150000x-160000))/(10^5)

The / 10^5 is just to scale down the curve so we can see it

[timid goblet]

Ok

Aren’t we supposed to put a parenthesis at 7000-?

7000))-

?

@frosty skiff

[frosty skiff]

Not realy you can write it down but it's just a simplification

[timid goblet]

Ok

I still see the same thing

😭

No wait no I see 1 black line

[frosty skiff]

You are in the negative

If you go to the right

It will be fine

[timid goblet]

?????????

Ok

Wel i went to the right

@frosty skiff

[frosty skiff]

The black line is P(x)/10^5

[timid goblet]

Also where did 10^5 come from

[frosty skiff]

It's so we can see the curve

[timid goblet]

Let’s say in the future imma have to do something like this

How would I know to use 10^5

Or not

Or something else

[frosty skiff]

If you don't see the curve try dividing by 10 or more

So you can see it

[timid goblet]

Oh ok

Now what do I do

We’ve been doing this for 1+ hours

💀

I forgot what we did this all for

[frosty skiff]

We are drawing P(x) so we can say at wich point it is the lowest and highest

[timid goblet]

Ok

So I draw the

Wave

[frosty skiff]

Yes

[timid goblet]

Does it even have to be accurate

[frosty skiff]

You don't need to be precise

Just make it look like it

[timid goblet]

Alr

Nowwwwwwwq

Finally

Wat do I do now

😢

Took 1+ hour to draw this goofy ass wave

[frosty skiff]

It's fine at least we do it step by step

[timid goblet]

Yea

What do I do next

[frosty skiff]

Now we search the lowest and highest point

[timid goblet]

Oh

How

??

[frosty skiff]

I search the minimum value of the function between 2 and 16

I did it in a spreadsheet

It gave me for the lowest value 0.1575 wich land on x=5

[timid goblet]

Ok

Thanks for saving me time

Ye

[frosty skiff]

But remember we scale down it by 10^5 so we have to multiply it byt 10^5

[timid goblet]

Oh

[frosty skiff]

And it is 15750

[timid goblet]

0.1575x10^5?

[frosty skiff]

Yes

[timid goblet]

And then

Wat do I do next

[frosty skiff]

And the highest is 0.9199 for x=13

But we have to do 0.9199*10^5 = 91990

[timid goblet]

And then we multiply that

Ok

Ye

And then

What do I do next

[frosty skiff]

That's all i think they just aksed you to find what's the lowest and highest value and for which x

So we finished

[timid goblet]

LETS GOOOO

THANKS

SSSS

S

S

.close

[safe radish]

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[safe radish]

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[tiny parrot]

how do i go about part a?

x = (1+t)
y = (-t)
z = 2

then do i do the dot product
1 x
0 . y
2 z

x+2z=0 and then do i solve for t?

[lament echo]

damn

let me guess

A-levels?

[grim plover]

well put value of z in x+2z? that'd be x+4 = 0

[tiny parrot]

yes hate vectors

[tiny parrot]

thank you just making sure tbh.

[lament echo]

mhm

disgusting things

wait till uni

they just get worse

[tiny parrot]

damm tbf i do wanna take maths at uni

[lament echo]

my cousin took maths

its a good choice

[grim plover]

I am a cs guy

[tiny parrot]

you can pretty much do anything

[lament echo]

CE over here!

[grim plover]

but maths is my hobby

[grim plover]

Computer Engineering Ig?

[lament echo]

yeah just get your bachelors , then find out what you like , that just master in that

[lament echo]

mhm

[grim plover]

I love computers in general, but computer hardware makes my brain partially explode, hence CS ( I anyways like CS more)

[lament echo]

DUDE ikr , it's difficult as well

switching from electronics to CS every lecture

[tiny parrot]

i took cs at gcse in like year 9 dropped it 1 month aftert lmao

[lament echo]

i dropped out of A-level chem in the first month

[grim plover]

And btw jsyk, I am not in uni, am in 9th grade (by cs guy I meant I am doing CS courses)

[lament echo]

took physics instead XD

[grim plover]

.........

[lament echo]

OHHH haha

[tiny parrot]

i wanted to do physics but couldnt lmao had to do economics instead

[lament echo]

you doing CS at uni i take haha

[tiny parrot]

gcse grades werent looking hot

[grim plover]

Nah

But I am trying to

[lament echo]

maths and economics is great if you want to get into finance

big money as well

[tiny parrot]

well i do maths further maths and economics, economics idk its just full of graphs and essay writing

[lament echo]

ew

essay writing

[tiny parrot]

IK

[lament echo]

i hated doing that

[tiny parrot]

i can barley write LMAO

[lament echo]

opens doors at least

[grim plover]

I hate languages other than jap

[tiny parrot]

and spell lol grade 4 in english lang lol

[lament echo]

you can do pretty much any STEM course + economics courses in uni

[lament echo]

im not much better grade 5 💀

[tiny parrot]

wereas my juicy grade 7 in maths

[tiny parrot]

i got 5 in lit some how lol

i hated lit

[grim plover]

what do you mean by grade...??

[lament echo]

we're graded 1-9 instead of A* - E

so 4/5 is just a pass

[grim plover]

ah, we are graded till 4th, after that its marks

[grim plover]

ah

[tiny parrot]

4 is a c and 5 is c+

[lament echo]

^

[tiny parrot]

getting bs in my mocks atm

[lament echo]

thats good

[tiny parrot]

true. havent been revising latley got a social life lmao

[lament echo]

got a D in my physics mock 💀

[tiny parrot]

what year u in?

12

[lament echo]

university haha

[tiny parrot]

ohhhh

ye but i bet that shit is hard as

[lament echo]

it is haha

[tiny parrot]

phyiscs tho ewww. i hate mechanics as it is

pure all the way

[lament echo]

you do it in maths anyway

[tiny parrot]

ye ik. got a good teacher for it tho. my pure teach just follows a power point

[lament echo]

if you can pass maths , you can pass physics legit the same thing with equations

[lament echo]

all my teachers were ass

besides my math ones

my CS teacher didnt teach for shit

[tiny parrot]

my economics teacher is great. makes the time go well fast she funny as lol

[grim plover]

I am so confused rn

[lament echo]

hahah

where did you apply for uni

if you dont mind me asking c;

[tiny parrot]

who me?

[lament echo]

yes haha

[tiny parrot]

only in year 12 lol dont apply till later this year

idk even know wher i wanna go

[lament echo]

OHHHH

year 12??

[tiny parrot]

yes

[lament echo]

just wait till year 13

you'll be depressed

[tiny parrot]

I cant wait till year 13

[lament echo]

maths just gets harder

[tiny parrot]

CALCULS MAN

[grim plover]

year 12..? Means class 12 in school?

[lament echo]

ITS GREAT HAHA

TRUST ME

calculus will be the easiest marks

[tiny parrot]

ive seen it lmao

[grim plover]

I like it but its difficult to do without looking

I recommend watching 3b1b's series

Its AMAZING

[tiny parrot]

would make sense theres so many rules you need to remeber

like chain rule quotient rule

[lament echo]

mhm

[grim plover]

Yeah

then comes implicit differentiation

[lament echo]

it just gets worse man XD

[tiny parrot]

defferentitation from first principles is fun

[lament echo]

but it comes to you easier

[grim plover]

thats a topic I can never wrap my head around

[grim plover]

true

[tiny parrot]

but now im stuck doing vectors

doing matrices after half term thats gonna be intresting

[lament echo]

yeah , i regret not doing further maths

i had to learn pretty much the whole course in the first term of uni

[tiny parrot]

tbf futher maths is better than normal maths

[lament echo]

it is haha

[tiny parrot]

more intresting lol

even tho in year 13 you do 3d vectors in normal maths

[grim plover]

what is year 13/???

[lament echo]

senior i think

[tiny parrot]

think its sophmore in america?

[lament echo]

last year before uni/college

[tiny parrot]

senior ye

[grim plover]

ah in my case its 12

[tiny parrot]

year 12 is junior apperntly

[grim plover]

Thats..different

welp ig you should close

this is becoming a chat channel instead of help 😂

[tiny parrot]

true

thanks for the chats:)

.close

[safe radish]

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[lean otter]

This does not seem right

[grim plover]

the quarter circle area computer is wrong

[grim plover]

shaded = 16-4pi

finaly answer = 3.436 cm^2

[grim plover]

Dont write pi*4^2 as 50 times 27 (you cant do that anyways)

do pir^2 upon 4

it becomes 4pi

then compute it with pi's value calculated to the third decimal

@lean otter

[safe radish]

@lean otter Has your question been resolved?

[urban ibex]

Again wrong calculations
50.27/4 = 12.5675 @lean otter

[lean otter]

AH

Sorry

I was afk

[lean otter]

Aah

[lean otter]

Ohhh

[lean otter]

Wait I’m a little confused for this

[grim plover]

pi = 3.141 apprx

3.141 * 4 equal 12.564

little less than @urban ibex

[urban ibex]

approx.... @grim plover

[grim plover]

but how do you get 50*27/4 from pir^2/4? (Ignore me just got dumb)

[grim plover]

right

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[unique abyss]

In triangle ABC is |BC| = 6 , |AC| = 9 and |Â| = 30°. Which of the following statements is correct?

(A) Angle B is acute (B) Angle B is obtuse (C) Angle B is straight

(D) Angle B can be acute or obtuse. (E) Such a triangle cannot be constructed.

[ornate gulch]

(A) is correct

[wintry condor]

!nosols

[safe radish]

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[unique abyss]

how do you know???

[unique abyss]

<@&286206848099549185>

In triangle ABC is |BC| = 6 , |AC| = 9 and |Â| = 30°. Which of the following statements is correct?

(A) Angle B is acute (B) Angle B is obtuse (C) Angle B is straight

(D) Angle B can be acute or obtuse. (E) Such a triangle cannot be constructed.

the correction says its D but idk why

[sick zephyr]

use law of sines

maybe helps

[lost hinge]

B or D

[unique abyss]

why D

[lost hinge]

I don't have a notebook near me, so I can't give you the proof

[unique abyss]

in words?

[sick zephyr]

.

you know that?

[unique abyss]

yeah

[sick zephyr]

use it

[unique abyss]

to get what

is B 42 degrees?

[lost hinge]

Sorry, it should be (A) Angle B is acute

[sick zephyr]

what did you find for sinB

[unique abyss]

42

[sick zephyr]

for sinB

not the length

[unique abyss]

42 degrees

[sick zephyr]

6/sin30 = 9/sinB

right?

sin30=1/2 so we can say that 12=9/sinB

hence sinB=3/4

there are two solutions for the angle B in [0,180]

[unique abyss]

why are there two

?

[unique abyss]

why is that 9? isnt c equal to 9?

[safe radish]

@unique abyss Has your question been resolved?

[safe radish]

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[lean otter]

in a triangle BAC were BC=4 AC=5 and AB=3, le point I is in the middle of the segmen BC. The cos BAC= 3/5, i need to find AI and i need to use the scalar product

[quasi bison]

do you have a diagram

[lean otter]

no

[quasi bison]

make a diagram

[lean otter]

okey and then?

[quasi bison]

show it here

maybe something will jump out at you, maybe it won't

but with ANY geometry problem you should always make a diagram

[lean otter]

i not gonna lie i dont know how to make one

or at least i dont know what is

<@&286206848099549185> sorry but i am no sure of how to make one

.close

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[lean otter]

.reopen

[safe radish]

✅

[near cave]

@lean otter

[lean otter]

i am stuck in that because the longer of the vectors tell me that is a triangle rectangle

[near cave]

can i explain this yo u on call

[lean otter]

please

[near cave]

call me

[safe radish]

@lean otter Has your question been resolved?

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[lean otter]

help

[vapid anvil]

Well guess he passed out and hit his head on the keyboard before we could help

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

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[queen knot]

how do i simplfy this?

[safe radish]

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[manic horizon]

I'm a bit confused with this

I tried changing the base of log_9(32)

To 4

But now I'm unsure of what to do

[stray socket]

Have you tried turning each log into a fraction

Like

Shit I wonder if the bot stil works

$a$

[flat frigate]

Umbraleviathan

[stray socket]

Aight so

Recall that $\log_b(a) = \frac{\ln(a)}{\ln(b)}$. See if that helps

[flat frigate]

Umbraleviathan

[rich elm]

also it may help knowing what form the final answer wants it in

because u could "simplify" this in several ways

[manic horizon]

Yeah I used that formula

[rich elm]

what did u change each term into?

[manic horizon]

Fraction

[rich elm]

im assuming over 4?

[stray socket]

Probably reduce the bases or something

[spice grove]

Simplest fraction. I suppose that's what it means, pretty clearly.

[manic horizon]

log_4(3) x log_4(32)/log_4(9)

[stray socket]

Because some things will get cancelled out

[hot thistle]

i believe you want to write 32 = 2^5 = 4^{5/2}, then raise the log to the other one

[stray socket]

That also works but getting the fractional power can be a pain

[hot thistle]

well it's just a square root

it's not really that bad

[stray socket]

I'd rather split it and then simplify each log factor and then notice that some things cancel out

[rich elm]

ok ik im not supposed to talk about asnwer rn

[stray socket]

Well for this case yeah

[rich elm]

but just checking i didnt do it wrong myself

5/4 is correct right?

[manic horizon]

So I change both of them?

[manic horizon]

Yeah

That's what the answers say

[rich elm]

well like what others have suggested

[stray socket]

Yeah

[rich elm]

start by expressing each term in a different base

[manic horizon]

So I could do something random like 7?

[rich elm]

try reduce b to something similar

[stray socket]

Or actually there might be a more direct easier way

[rich elm]

*simpler

[stray socket]

Withoit going into natural log

There's a lotta methods

[rich elm]

hint: 4 & 9 are both square numbers

[manic horizon]

I've only learned some basic log rules and the base conversion formula so far

[rich elm]

that should be enough for this question

[manic horizon]

Ok

A side question, does it matter what I change the base to?

Could I change it to anything

[stray socket]

You could change it to anything

[rich elm]

well not really but for the question

ideally

[manic horizon]

Or is it easier if I change it to something like 2

[rich elm]

u want to reduce it to something that can simplify b or a

[manic horizon]

Thanks

[rich elm]

simplifiyng the denominator would be easier

[stray socket]

I use ln since it's easier to write

[rich elm]

but it doesnt matter in the end

[manic horizon]

I changed the base of both of them to 2

So now I have

log_2(3)/log_2(4) x log_2(32)/2log_2(3)

[rich elm]

are u familiar with the power rule

at least i think thats what they call it

[manic horizon]

so I think I can cross multiply log_2(3) and 2log_2(3)

[stray socket]

Cancel out factors

[manic horizon]

Not by name no

Maybe if you explain it I might know

[stray socket]

My guy the log_2(3) will cancel each other out

[manic horizon]

Yeah that's what I said

So I have 2

[stray socket]

You said to cross multiply

[manic horizon]

oh

[rich elm]

the bottom one in this image

sorry its bad quality

[manic horizon]

Wrong wording but that's what I meant

[rich elm]

i just found a random one

[stray socket]

That doesn't apply

[manic horizon]

Yea

[stray socket]

Oh wait power rule

[rich elm]

try changing ln 32

[stray socket]

My dumb ass thought product

[rich elm]

and ln 4

[manic horizon]

To 4x8?

[rich elm]

well what are factors of 4 and 8

[manic horizon]

So log_2(4) can cancel out

[rich elm]

what are the factors of 4 and 8

the smallest factor thats not 1

[manic horizon]

2

[rich elm]

how many times would u have to multiply 2 to get 32?

[manic horizon]

So 5log_2(2)

[rich elm]

yep

[manic horizon]

Oooooooohhhh

[rich elm]

which can be further

[manic horizon]

Wait I get it now

Thanks

Right I got 5/4

Thanks

[rich elm]

👍

[manic horizon]

.close

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[fickle trail]

How does this table work? I put the answers above but still not getting it

[thin bridge]

which part don't you get

[empty gyro]

[fickle trail]

All of it, how are they plugging in values to solve?

[thin bridge]

the table indicates the output at each value of x

is indicating that
when x=-2, f(x) = 1
i.e. f(-2) = 1

etc

so for a)
f(g(-1))
you'd first determine the value of g(-1) from the table
and then use the table again to determine f(whatever that is)

[fickle trail]

you read it as columns? i must be reading it incorrectly, I don't see how f(f(-1) = -2

[thin bridge]

well what's f(-1)

[fickle trail]

0, i think?

[thin bridge]

yes

$f(\underbrace{f(-1)}_{0}) = f(0) = ,?$

[flat frigate]

ℝamonov

[fickle trail]

oh

so you always go back to x

[thin bridge]

wdym

[fickle trail]

like f(-1) i'm not finding -1 for f(x) i'm finding -1 for x

[thin bridge]

the use of variable is arbitrary

f(-1), you're finding the output when you shove -1 into the function

[fickle trail]

working inside first and moving out

so for f(g(0)) for example, something not on the answers

I would first find x = 0

g(x) = 0 when x is 0

f(x) is -2 when x is 0

so f(g(0)) = -2
kinda like that?

[thin bridge]

yeh

[fickle trail]

OK

[thin bridge]

I would first find x = 0
scrap that though

[fickle trail]

never done them with tables before, good to know

[fickle trail]

wrong wording?

[thin bridge]

yeh

[fickle trail]

how would you phrase it?

[thin bridge]

find g(x) when x=0,
which was nicely summarised in that subsequent line

[fickle trail]

OK

.close

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[fringe cypress]

You are given three numbers: x, y, and z. In one step you can increment/decrement a number by one, and the number should be greater than zero after performing the operation. Find min number of steps need to make gcd(x, y) = y and gcd(y, z) = y.

[fringe cypress]

How do I approach this? The best I've got is trying all possible values for y, which is quite bad :/

[white hollow]

x=y=z?

[fringe cypress]

We have to minimise the number of steps. This won’t work for most of the cases.

[quasi bison]

pretty sure you'd want to find the closest multiples of y to x and z resp and adjust x and z to those

but maybe adjusting y itself could save some steps...?

hm

[white hollow]

oh right I misunderstood, so you want to find a method?

[fringe cypress]

exactly, we might need to change all three of them in some cases

[fringe cypress]

I want to find what the final triplet or number of steps will be.

[safe radish]

@fringe cypress Has your question been resolved?

[fringe cypress]

<@&286206848099549185>

[safe radish]

@fringe cypress Has your question been resolved?

[safe radish]

@fringe cypress Has your question been resolved?

[safe radish]

@fringe cypress Has your question been resolved?

[toxic raft]

Ummm I'm not really sure what the constraints are? Am I not allowed to just "mentally" decrement/increment a number and see what happens?

Also, is this a cs question? Cause the problem can be solved pretty easily using a search algorithm

[fringe cypress]

Not sure what you mean by “mentally” increment/decrement

[toxic raft]

Like uh

Hmmm I'm finding it hard to put into words

Hm ok.
So like:
Let x, y, z be something. Can I like, decrement y, see if that solves the problem and then be like "nah, I didn't mean to do that, I take it back"

[fringe cypress]

yea there was some problem around it. Also, what algorithm are you thinking about?

[toxic raft]

Ok, so it was a CS question. Then yeah, there's plenty of ways to do this

[fringe cypress]

but that will be really sub-optimal right?

[toxic raft]

yeah it doesn't matter. The CS context makes everything make sense

[fringe cypress]

Let’s assume that 1 <= x, y, z <= N. You can iterate over all possible y’s and find best x and z for that y

This solved my problem, but I am trying to find something better.

[toxic raft]

That disregards the increments you can do to x, z

[fringe cypress]

nope? You can find the closest factor of current y to x and similar closest multiple to z

Example: Let’s say you’ve chosen some value for y. Then best_x can be x * (y / x) or x * (y / x) + x

and we can add difference of x and best_x to number of steps used

[toxic raft]

Nah I get it

ok this is kinda hard

I'll ping you if I get an idea

[fringe cypress]

thanks!

[safe radish]

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@fringe cypress Has your question been resolved?

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[lean otter]

A woman with a broken neck is falling off a 150 meter building, Superman swoops in to rescue her but she can’t exceed 3g or it will kill her, what’s the lowest she can fall at which Superman can save her

[lean otter]

Im not sure how to start it to be honest, I have a graph of velocity to time but the time is not known so it’s not very helpful

Im not sure which kinematic to use

[merry sleet]

superman cant slow more than 3g

[lean otter]

Yea

[merry sleet]

so for any velocity v

calculate what distance is needed

to slow down at 3g

then calculate v in terms of the distance traveled

then you'll have one equation with the distance traveled

which you solve

[lean otter]

I got 58.8y = v^2

Not sure if I’m doing this correctly

[merry sleet]

what is y?

[lean otter]

The height

[merry sleet]

so a distance is equal to a speed squared?

[lean otter]

Required for slowing down I think

[merry sleet]

m= m²/s²?

show your work

[lean otter]

Im honestly just using kinematic equations so I’m probably restricting myself

Let me rethink this through

[merry sleet]

dv/dt = a

basically you need to integrate the acceleration twice

[lean otter]

Wait what equations do I integrate with?

So like do I integrate the 3g?

And then integrate that again?

And plug in values or?

[merry sleet]

a(t) = 3g

v(t) = 3gt + v_catch

v(t_0) = 0

solve for t

gets you the time at which superman stops

then x(t) = 3/2gt² +v_catch *t + x_catch

and sub in t_0

with v_catch and x_catch the speed and distance when superman catches

[lean otter]

Sorry, I’m not very good at this, ok so the catch values are for the time at the position where it is caught right?

Ok

[merry sleet]

then do the same kind of thing but when its free fall

a(t) = -g

v(t) = -gt +v_initial

but v_initial=0

[lean otter]

Ok so for the time being the catch values are in terms of t right?

[merry sleet]

v_catch and x_catch depend on t_catch yeah

gotta go good luck

[lean otter]

Ok thanks

Yeah not getting it

Damn I’m bad at this

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

<@&286206848099549185>

Ik I got so much help but I actually don’t know how to progress

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

I guess I’ll ask my professor in the morning

.close

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[cloud elm]

how do i use 5a) to do 5b)

[thick sparrow]

Integrate both sides of (a), then you should have it. 🙂

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[boreal cypress]

why are these statements true?

[split ether]

As n -> 0, the top approaches something nonzero and the bottom approaches zero

So the first limit diverges

You can solve the second limit by dividing the top and bottom by n

$\lim_{n\to\infty}\frac{95n+13000}n=\lim_{n\to\infty}(95+\frac{13000}n)$

[flat frigate]

A Lonely Bean

[boreal cypress]

did you mean (95n+1300)/n

[split ether]

Hm?

[boreal cypress]

in the far right

[split ether]

No

Just divide 95n + 13000 by n

[boreal cypress]

i got 95 but like

i wont have calculator

on exam

so how would i know this

well

i guess

i need to learn

how to separate a fraction

like yuo did

[boreal cypress]

here

1300/ infinity would be 0

@split ether can you tell me how you broke those two apart?

(95n+1300)/n into 95 + (13000)/n

[split ether]

$\frac{95n+13000}n=\frac{95n}n+\frac{13000}n=95+\frac{13000}n$

[flat frigate]

A Lonely Bean

[boreal cypress]

tyvm

[safe radish]

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[boreal cypress]

.close

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[carmine portal]

Can someone help me with q7 please

[carmine portal]

<@&286206848099549185>

[safe radish]

@carmine portal Has your question been resolved?

[carmine portal]

<@&286206848099549185>

Am saveddd

[misty bay]

7a or 7b

[carmine portal]

Both

My friend told me the teacher hasn't taught us this yet but am just feeling uncomfortable not doing it

[misty bay]

highly doubt you haven't been taught how to do trigonometry

[carmine portal]

Well idk it doesn't seems familiar

I can do everything but q7

[misty bay]

then you've been taught enough to do it

do you understand what 7a is saying

[carmine portal]

Not rly

[misty bay]

do you understand what it's asking

[carmine portal]

I know its tell me to find sin a which should be opposite/hypotenuse

[misty bay]

okay

that's a pretty good start

[carmine portal]

But there's no like values or anything so idk

[misty bay]

you don't need the specific numbers

some things are given names

it's like if I tell you to say the number I say, but plus one

you can understand that instruction without my having to provide you values, yeah?

[carmine portal]

Ye

[misty bay]

same thing here

you're given names for the lengths of certain line segments

just use the names instead of their numbers

[carmine portal]

So then which one is Q

[misty bay]

Q refers to the vertical distance of the end of the hypotenuse from the x-axis

[carmine portal]

The bold vertical line or the kinda dotted horizontal

[misty bay]

P refers to the horizontal distance

or in other words, the end of that radius of the circle is at (-P, Q)

[safe radish]

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[untold topaz]

.close

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[pine tulip]

Hello guys, can someone please help me understand what to do here?

[flat frigate]

Lyuka

[safe radish]

@pine tulip Has your question been resolved?

[safe radish]

@pine tulip Has your question been resolved?

[velvet nebula]

probably some dot/cross product thing. Consider perhaps doing a dot product with the normal vector to the plane, how do you interpret this result? How can this be used to help cancel out the component of P going out of the plane?

[safe radish]

@pine tulip Has your question been resolved?

[safe radish]

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[lean otter]

.reopen

[safe radish]

✅

[deep depot]

If you reopened another channel now bro it would be really bad for you@lean otter

.close

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[lean otter]

idk how to open my own

[sand minnow]

read this #1021175428326633542

oh wait

#❓how-to-get-help

this

[deep depot]

Go to #help-27 and post your question

[safe radish]

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[jovial forge]

need help me

[plucky elk]

[jovial forge]

where

[plucky elk]

here

this channel is yours as indicated by the name

use google's calcualtor

.close

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[rose schooner]

my teacher be giving me such random questions lol i have never seen this before, and he refuses to help sooooo please help some kind person

[empty gyro]

Is this a number theory problem?

[rose schooner]

i have no clue sir

i am as clueless as you

[empty gyro]

Do you know about modulo?

[rose schooner]

idk if thats related to modulus the absolute function thingy |x|

but otherwise no

[empty gyro]

Nah it's not like that

Yeah if you don't know it, then I don't know a way to solve it 😦

[rose schooner]

i am doomed braH

[empty gyro]

Do you know summation?

[flat frigate]

SWR

[empty gyro]

hmm nvm that may not help

[rose schooner]

welp

ig i'll leave the question (its v imp but i have no choice life sucks i cudnt care less atp)

thanks for trying to help

u r gigachad u look beautiful goodbye

.close

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[sinful oyster]

Does anyone know how to answer this question?

[rich elm]

it may help if u draw a diagram to help u visualize

[sinful oyster]

I tried but I'm still clueless

[rich elm]

first figure out the rough direction

if q is 65 degrees from p

and 0 degrees is directly upwards

where do u think q roughly is

[sinful oyster]

about the top right

of P

[rich elm]

yeah roughly

it’s somewhere between 0 and 90

now where is r from q?

@sinful oyster

[sinful oyster]

around the bottom right of Q

[rich elm]

yep

and then connect all the points to form ur triangle

now try to mark out all the information u have

ie: angles and length etc

[sinful oyster]

ok

what do I do next?

[rich elm]

can u find the third side?

and use sin rule to find the angle

i have to go now, but gl with ur question

[sinful oyster]

I'm so confused 😭

<@&286206848099549185>

.unopen

.close

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[brave panther]

please

[brave panther]

help

[split fulcrum]

Do you know what the mean is

[brave panther]

yes

please

[split fulcrum]

So what are you stuck on if you know the definition of mean

You know what it is right?

[brave panther]

oh sorry

i thought you said "do you want to know what the mean is"

im kind off dyslexic sorry

[split fulcrum]

It’s alright

But do you know what it is?

[brave panther]

nope

[split fulcrum]

It’s taking the sum of all the values and then dividing by how many values there are

So how many days start with T and S?

[brave panther]

4

[split fulcrum]

Yes

Now add the total amount of emails that those 4 days have

[brave panther]

ok

19

[split fulcrum]

then divide that number by 4 and you have the mean

[brave panther]

but you cant

its a deciman

decimal

[split fulcrum]

Did you count it correctly?

You counted it incorrectly

It’s 20 emails

Not 19

[brave panther]

oh

thank you

so it would be 5?

[split fulcrum]

Yes

[brave panther]

because there is this really hard question which me and others got stuck on

<@&286206848099549185>

[safe radish]

@brave panther Has your question been resolved?

[brave panther]

HEKO

HELP

SOMEONE

[brave panther]

please

HELLO

SOMEONE HELP ME

PLEASE

a.) B
b) E

c) C

is this correct???

SOMEONE FUCKING HELP ME

IT AINT HARD

PLEASE

I NEED HELP

I HAVE BEEN WAITING FOR 2 HOURS

BRUH

[safe radish]

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[safe radish]

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[wicked ledge]

Is this correct?

[wicked ledge]

Equation is cos(arccos x - arcsin x)

We were told to solve using sum difference

!flip

Idk how to do it

[rigid inlet]

,rccw

[rigid inlet]

[wicked ledge]

It is? Thank you

Just seems like a little bit of a peculiar answer

!close

[rigid inlet]

oh idk about the actual work, I just rotated it

[wicked ledge]

Oh lol

How do I unclose

[rigid inlet]

it never closed

the command is .close

[wicked ledge]

Oh

[rigid inlet]

when it closes you'll get a notif

.close

[safe radish]

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[rigid inlet]

.reopen

[safe radish]

✅

[wicked ledge]

Ohhh

[rigid inlet]

anyway that looks alright, what do you find peculiar about it?

[wicked ledge]

I don’t know it’s just that all the denominators were 1

But thank you my friend

.close

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[flat spoke]

Did you do the long division? Are you able to show your work?

You forgot to distribute the negative.

[worthy hemlock]

Distribute the negative

[flat spoke]

it's 5x^2 - (-4x^2)

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[flat spoke]

Np

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[alpine hornet]

WOOOOO back for more help

[alpine hornet]

This question doesn’t feel right, anyone want to look it over for me and let me know if I did good or not? 😙

It seems reasonable but with all the big numbers I worry it’s wrong

x = 1320 if you couldn’t read that

[misty bay]

,w 16500/12000 * 960

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by Saccharine#3780

[misty bay]

you got it right

[alpine hornet]

Oh cool

Another one I was unsure of

Wait lemme get a pic

And also I don’t know how I would even start this can someone walk me through this one please

[misty bay]

this one is right

[misty bay]

so if you know the gas mileage, what else do you need to calculate how much gas you need?

[safe radish]

@alpine hornet Has your question been resolved?

[alpine hornet]

I’m not sure?

[misty bay]

let's say you're going on a drive somewhere

how do you figure out how much gas you might need

[alpine hornet]

How far you are traveling

?

[misty bay]

and what else

do you think the answer will be the same if you're driving a monster truck or a compact sedan?

[alpine hornet]

Distance a gallon?

[misty bay]

that's called gas mileage yes

[alpine hornet]

Crap

[misty bay]

how would you figure out how much gas it takes, given how far you're traveling

[split kettle]

so you see this ratio right. 1/4 inches on a map = 15 miles irl. so how many miles would 6 inches(on map) be irl?

[alpine hornet]

I’m slow I’m sorry

[misty bay]

and the gas mileage

[misty bay]

pls we're not there yet

[alpine hornet]

240?

I think)

[split kettle]

understandable

[misty bay]

how would you figure out how much gas you're going to use from how far you're traveling and the gas mileage?

[alpine hornet]

Multiply?

Orrrr

Divide??

[misty bay]

you tell me

do a little thinking and see if you can figure it out

if it helps, think about what happens if your gas mileage is really high

should the amount of gas used be high or low?

[alpine hornet]

High

[misty bay]

so when you go to buy a car, do you want high or low gas mileage?

[alpine hornet]

Low

[safe radish]

@alpine hornet Has your question been resolved?

[safe radish]

@alpine hornet Has your question been resolved?

[safe radish]

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[safe radish]

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[fickle trail]

when we say this thick red line is the "secant" line

[fickle trail]

that means it is 1/cos

so 1/x?

[quasi bison]

no

[devout shale]

it's called a secant line because it intersects the curve at 2 points

[fickle trail]

the line between two points, the secant line

oh, the red line is called the hypotenuse?

[quasi bison]

"secant" as in secant line does not have anything directly to do with "secant" as in the reciprocal of cosine

and you should not be looking for any connections there

full stop

[fickle trail]

why are they named the same thing?

i always thought it meant the same thing

[devout shale]

The word secant comes from the Latin word secare, meaning to cut.

[fickle trail]

what about the tangent line? same thing, not related to trig function tangent?

[quasi bison]

there is somewhat of a geometric relationship there

[fickle trail]

why oh why would we have trig function secant, and line identity secant

totally different

[quasi bison]

nobody gives a shit about secant anyway.

[devout shale]

lolz

[fickle trail]

which secant?

[devout shale]

both

[fickle trail]

"nobody gives a shit"?

why do they teach this stuff in math class

if it's a complete waste of time

[devout shale]

to learn mathematical reasoning, and it isn't completely useless but some things you learn have much less application than others

[quasi bison]

heres the tangent thing

for a point (cos(phi), sin(phi)) on the unit circle, drawing a line through it and the origin and finding its intersection with the line x=1, tangent to the circle, gives the point (1, tan(phi))

so there's that tangent connection

[quasi bison]

they teach a lot of stuff in math class that is of questionable utility later on.

[fickle trail]

what's "phi"?

[devout shale]

a variable for the angle

[quasi bison]

phi is a greek letter

[fickle trail]

ive only heard theta

[flat frigate]

AustinU

[quasi bison]

there are 22 more letters in the greek alphabet, avidrunner.

[fickle trail]

phi and theta are the same thing? they look very similar

[quasi bison]

they are not the same thing.

[devout shale]

theta doesn't cross through the circle

[quasi bison]

they are different letters.

[flat frigate]

AustinU

[fickle trail]

oh right

[quasi bison]

the correct way to write phi is $\varphi$ anyway tbh

[flat frigate]

Ann

[devout shale]

I like that one much better

I use the other one for phase lag

[quasi bison]

$\phi$ looks too much like russian ф

[flat frigate]

Ann

AustinU

[devout shale]

Psi doesn't get used enough for how cool it is

[quasi bison]

i am serious about the "acquaint yourself with the greek alphabet" thing by the way

it is shorter than the latin alphabet

[devout shale]

never seen that one before

[devout shale]

you get acquainted after about 2 years of math with like 50% lol

[quasi bison]

and i am saying there is value in expediting that process.

[quasi bison]

that is a letter from a south asian script, i think. i do not remember which one.

[devout shale]

I'd agree, just making a quip

[fickle trail]

Hic textus latinus est, intellegis?

.claudere