Fixed.
#help-23
past aurora
dreamy ferry
01 will match a but not b
cant think of any that will match b nut not a
for 01 ,0 is r followed by 0 things, i.e. 1 that match r
no?
dreamy ferry
my bad 1 is not present inside the set a*
past aurora
Right
So can you find any other examples that match one but not the other expression?
past aurora
Does that help shed light on why they're equivalent?
past aurora
Keep on mathin'!
hot nacelle
would D be 44? it doesnt look that way do its confusing me.
safe radishBOT
would D be 44? it doesnt look that way do its confusing me.
tranquil sentinel
Yes, D is 44°, that's because D and B are opposite angles, so D=B
@hot nacelle
lone glacier
Yes, D is 44°, that's because D and B are opposite angles, so D=B
.reopen
leaden scaffold
needing help with part b
safe radishBOT
needing help with part b
leaden scaffold
So I've decided to split the function up and graph 4x, and also graph - square root 25-x^2
But I'm confused on why my shading is considered incorrect
final bay
Thats looks correct
Oh wait it’s not
That area isn’t the integral
Maybe just do each function separately and subtract after
leaden scaffold
Maybe just do each function separately and subtract after
What does this mean? Like, shade the area of each function separately?
leaden scaffold
then substract the areas
Is my shaded area correct for any of the parts of the function?
I’m guessing no?
pure agate
As ed said, part a) and part b) look like two different math problems.
leaden scaffold
As ed said, part a) and part b) look like two different math problems.
They are, part b is an entirely separate problem. I’m just confused on how to graph it
pure agate
Well, the square root you should recognize as a semicircle. Because it is negative, it is the lower half of the circle.
leaden scaffold
Well, the square root you should recognize as a semicircle. Because it is negat...
So I should shade the lower half of the circle for the square root part, but I should leave the shaded part for 4x?
pure agate
No. Are you allowed to use a graphing application to graph the equation?
leaden scaffold
No. Are you allowed to use a graphing application to graph the equation?
Not on exams. For homework I don’t see why not
pure agate
Are you taking an exam right now?
leaden scaffold
Are you taking an exam right now?
No. lol. This is written homework
pure agate
Ok, well the first thing you need to consider is how to graph a function. Pay particular attention to the square root. What is its domain?
leaden scaffold
Ok, well the first thing you need to consider is how to graph a function. Pay p...
I thought my graph was right…square root is 5,-5…
pure agate
Yes. Now consider how adding 4x to the end points of that interval affect where the end points are plotted on a graph.
x = -5 and x = 5.
leaden scaffold
x = -5 and x = 5.
I thought I plotted that on graph
pure agate
If by the red arc, no.
leaden scaffold
If by the red arc, no.
???? My x intercepts are both at -5 and 5..
pure agate
What does 4x - sqrt(25-x^2) equal for x=-5?
leaden scaffold
What does **4x - sqrt(25-x^2)** equal for **x=-5**?
-20-(square root(50))
pure agate
sqrt(25 - (-5)^2) = ?
leaden scaffold
sqrt(25 - (-5)^2) = ?
0
pure agate
So what does 4x - sqrt(25-x^2) for x=-5 equal?
leaden scaffold
So what does **4x - sqrt(25-x^2)** for **x=-5** equal?
-20
pure agate
That means the left side of the semicircle is at (-5,-20).
What about the right side for x=5?
leaden scaffold
What about the right side for **x=5**?
I feel so arithmetically challenged…right side will still 20
So 5,20…
pure agate
Yes, do those end points of the circle match up with what you drew?
leaden scaffold
Yes, do those end points of the circle match up with what you drew?
No.. but why would we be subbing in -5?
pure agate
Because that is the domain of the the integral in b).
leaden scaffold
Because that is the domain of the the integral in b).
I’m confused, so you want me to plot the points (5,20 and (-5,-20)? Wouldn’t that affect the shape of the semicircle
pure agate
Yes. Which highlights the fact that you drew the graph incorrectly.
leaden scaffold
Yes. Which highlights the fact that you drew the graph incorrectly.
Just for r clarification, you’re referring to part b of question 1, right?
pure agate
Yes.
pure agate
Plot a point for x=0.
And you know that it curves upward because it is a semicircle.
safe radishBOT
@leaden scaffold Has your question been resolved?
mortal arrow
Why is x^1/2 = sqrt(x)
safe radishBOT
Why is x^1/2 = sqrt(x)
mortal arrow
???
empty summit
oh sorry i thought i was the only one typing
mortal arrow
Same
empty summit
we sent message at same time
empty summit
its fine
frozen harbor
safe radishBOT
frozen harbor
Can someone explain what these things mean in this explanation?
In the begenning it replaced 3x^4 (the inside of the sin) with a u
glass carbon
I guess domain
glass carbon
until you don't do anything with the derivative I'd say no
shadow topaz
shadow topaz
very confused about this one because the probability keeps changing
junior smelt
Please stick to the channel you already have #help-14 or close the other one, thank you 
safe radishBOT
@shadow topaz Has your question been resolved?
plucky elk
.close
granite cape
hey guys could anyone help me out with this
safe radishBOT
hey guys could anyone help me out with this
granite cape
I'm doing (iii)
just not sure what is meant by"in the first quadrant"
does it mean the graph will have no negative side?
@shut inlet
plucky elk
just not sure what is meant by"in the first quadrant"
x >= 0 and y >= 0
final halo
the first quadrant is just the "north east" quadrant
plucky elk
<@942843959783333890>
also don't ping individual people
granite cape
ok
granite cape
the first quadrant is just the "north east" quadrant
yeah, I know so does that mean the graph will only lie in the first quadrant?
and will have no negative side?
shut inlet
<@942843959783333890>
yes ?
final halo
i mean the functions exist whereever they exist, its just telling you to only consider it in quadrant 1
final halo
you can if you want, no one is forcing you to
granite cape
but I mean if I draw the negative portion as well the graph will have more points of intersection
so I'm guessing the two points of intersection in quadrant 1 will be at x=0 and x=2
final halo
well yeah you know you can just disregard intersections with negative x values
unique bison
With respect to?
granite cape
x
shut inlet
ok so now I setup an integral with limits 0-2
did you find the points of intersection ?
shut inlet
the x coordinates for which are x = 2 and x = 0
are you sure for x=2 ?
How did you manage to get that @shut inlet ?
granite cape
hmm, well....
ok so I know x = 0 is definitely one
although how would I find the second point?
oh no actually when I got x=2 I got y = 8
for the cubic graph
shut inlet
yes , that what i'm trying to say to you
granite cape
so then isn't it correct?
shut inlet
so then isn't it correct?
x=2 isn't correct
granite cape
why?
shut inlet
we say that two graph f(x) and g(x) are intersect when
f(x) = g(x)
in your case :
f(x) = x³
g(x) = x
shut inlet
Oh I think I may have graphed it wrong
yes
shut inlet
Ok I retried it
what are the intersection points first ?
granite cape
x=1 and x=0
shut inlet
x=1 and x=0
yes
flat frigateBOT
Mehdi_Moulati
shut inlet
For the area I got 1/4 units squared
correct
azure frigate
i need to know these because i forgor
safe radishBOT
i need to know these because i forgor
azure frigate
i just need 1 - 2 of these questions answered
or steps on how to do it
and im good
mortal sandal
show OAC congruent to OBC is an important step
azure frigate
like how do i find the lengths
because these man havent provided me with a lesson to this
nvm got it
.close
safe radishBOT
safe radishBOT
Available help channel!
amber glade
Hi, I'm trying to figure out the process of using long division for polynomial functions, and I was wondering if I needed an '0x^3' as well as a '+0' (or blank spaces) in order to properly move onto the next step.
safe radishBOT
Hi, I'm trying to figure out the process of using long division for polynomial f...
amber glade
And would I be adding 3 to 2x^2 as well as increasing the power by 1? Would the same be applied to the 10x?
stray socket
Hi, I'm trying to figure out the process of using long division for polynomial f...
If it helps you organize your thinking then sure
Also is that a Faith pfp
Personally I like to manipulate the numerator
So like
amber glade
Okay, so would I split it up into individual sections, like (x-1)(x-1)+10x? I'm not very familiar with how manipulating the numerator would impact the equation.
stray socket
Gimmie a sec
amber glade
I think it's just the '+3' that's throwing me off, do I add 3 to anything that doesn't have an 'x' attached to it?
stray socket
$$\begin{align*}
\frac{2x^2 + 10x}{x+3} &= \frac{2x^2 + 6x + 4x}{x+3}\
&= \frac{2x^2 + 6x}{x+3} + \frac{4x}{x+3} \
&= 2x + \frac{4x + 12 - 12}{x+3}\
&= 2x + \frac{4x+12}{x+3} - \frac{12}{x+3} \
&= 2x + 4 - \frac{12}{x+3}
\end{align*}$$
Bruh w
flat frigateBOT
Umbraleviathan
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
stray socket
@amber glade hopefully my process makes sense
amber glade
I wouldn't have thought to split the ten like that, but where did you get the -12x from?
amber glade
sorry, I meant just the -12
stray socket
Oh that's because 4x = 4x + 12 - 12
I'm manipulating a 0
4x = 4x + 0
4x = 4x + 12 - 12
unreal fiber
it may be hard to see at the first glance but so that we can make it look like a constant multiple of x+3
stray socket
Why would we be adding in the 0 in this case?
Makes it easier to split the fraction
amber glade
oh because 12 is divisible by 3
unreal fiber
kinda
amber glade
oookay, I don't entirely get it, but I see where it's going
unreal fiber
ratio between x and 3 is like 1:3 and that ratio is equavilent to 4:12
4 because we have 4x
it is equavilent to many things, but 4:12 is the one we care about here
so we add a 12 there and then subtract that so our value doesn't actually change
amber glade
Alright, would there be a way to get rid of the - 12 / x+3 at the end there?
unreal fiber
no that is the remainder
stray socket
That's why I stopped there
amber glade
Alright, thank you @unreal fiber & @stray socket for the help, I'll try and take the reins from here, I might pop up in another help board eventually
stray socket
As soon as the numerator's leading power is smaller than the denominator's, you stop
stray socket
Alright, thank you <@893445345458126888> & <@349354952961032192> for the help, I...
Make sure to close this one first
amber glade
I just do .solve, right?
unreal fiber
.close
safe radishBOT
unreal fiber
also epic faith pfp
amber glade
thank you
safe radishBOT
Available help channel!
tulip briar
This is abt vectors.. Need help in part d.. i didn't draw the extensions properly btw cus there wasnt enough space.. pg2 is my working but im not sure if im doing it right
safe radishBOT
This is abt vectors.. Need help in part d.. i didn't draw the extensions properl...
@tulip briar Has your question been resolved?
tulip briar
<@&286206848099549185>
I dont think i got the method right but if I did idk how to continue on it cus the equation has k and im trying to find what k is
Anyone?
<@&286206848099549185>
safe radishBOT
@tulip briar Has your question been resolved?
safe radishBOT
is this right?
crude star
my fault for the bad handwriting
tulip saddle
looks all right to me
and your handwriting is decent
not perfect, but legible, esp up close
junior smelt
,w int sqrt(x)*sqrt(3 + x^(3/2)) from 0 to 1
flat frigateBOT
junior smelt
hmm I got (4/9)(8-3sqrt(3))
Looks the same on rationalising denominator?
tulip saddle
am I stupid? yes :D
I missed that they had gotten rid of the /9 for the second term (they being wolfram)
anyways @crude star it's all correct, both us and, more reliably, the bot agrees :D
crude star
anyways <@925451734380318801> it's all correct, both us and, more reliably, the ...
last quesrion
,rotate
flat frigateBOT
crude star
again sorry for the handwriting
😭😭😭
im like trynna speedrun thru these questions bcz I got a midterm tmrw
tulip saddle
beyond that ngl would've just used tabular integration to integrate
instead of a u sub
crude star
beyond that ngl would've just used tabular integration to integrate
not allowed yet
lol
thats next chapter
so next midterm
tulip saddle
oh I was wondering how you got 3 terms anyways lol
crude star
4th line
tulip saddle
should've read further
tulip saddle
ok you're integrating u^5/2+4u^3/2+4u^1/2
crude star
I am integrating
tulip saddle
which gives 2/5u^7/2+8/3u^5/2+8/3u^3/2
crude star
$\int x^2 \sqrt{x-2} , dx$
flat frigateBOT
Worth
crude star
this was my question
tulip saddle
[\int{(u+2)^2\sqrt{u}}]
flat frigateBOT
Scythe
tulip saddle
[\int{u^{\frac{5}{2}}+4u^{\frac{3}{2}}+4u^{\frac{1}{2}}}]
flat frigateBOT
Scythe
tulip saddle
[\frac{2}{7}u^{\frac{7}{2}}+\frac{8}{5}u^{\frac{5}{2}}+\frac{8}{3}u^{\frac{3}{2}}]
there we go
flat frigateBOT
Scythe
crude star
bro how do u do it so fast goddammmm
crude star
oh wait a min
tulip saddle
bro how do u do it so fast goddammmm
magic fingers P:
and copy paste u^{\frac{5}{2}}, which I modify really fast
crude star
wait shit
that was
a 5
8x^2(sqrt(x))/5
the last one
let me see what was goij thru my head one second
oh oh
so I accidently did
tulip saddle
mate why would you expand it lol
crude star
x^3/2
tulip saddle
leave it in fraction power form
crude star
wym
tulip saddle
but yeah all that needs to change is
tulip saddle
third term here goes to ^5/2 isntead of 7/2 and /5 instead of /7
crude star
yeah I just got it
tulip saddle
fraction power
I meant for your final answer smh
tulip saddle
what kind of person ""simplifies"" (x+2)^7/2 to (x+2)^3sqrt(x+2)
crude star
I meant for your final answer smh
oh truee
oh no I alrdy did
x^2sqrtx before
i just copied it from there and wrote it
in a previous question
junior smelt
[mind you, you could factor out a square root for all of those, but, like, 
]
crude star
also tysm
tulip saddle
[mind you, you could factor out a square root for all of those, but, like, <:no:...
2sqrt(x+2)(1/7(x+2)^3+4/5(x+2)^2+4/3(x+2))
lean otter
$3x^2+(3k-2)x-2k$
safe radishBOT
$3x^2+(3k-2)x-2k$
flat frigateBOT
AllUtility
devout shale
lol
no one answers your modular arithmetic question in less than 1 minute
and thats your response
astral matrix
Am I correct?
Could someone please check my work?
safe radishBOT
Am I correct?
Could someone please check my work?
@astral matrix Has your question been resolved?
astral matrix
.close
safe radishBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
hardy lion
uhh
zinc token
separate out one variable get y in terms of x or something
hardy lion
elimination
add the two equations
its 2x+4y
youre close though, you need to fix your value for y and then your x value can be found from there
looks good
safe radishBOT
Available help channel!
worldly marten
why is the answer to this -x^9 ? shouldnt it be +x^9? because -x^6 turns into a positive number since 6 is an even number? and then x^6 * x^3 is x^9
safe radishBOT
why is the answer to this -x^9 ? shouldnt it be +x^9? because -x^6 turns into a ...
potent current
-x^2 = +x^2 no?
wintry condor
(-x^2)^3 is basically {(-1)(x^2)}^3=(-1)^3(x^2)^3=-1 * x^6=-x^6
potent current
but you are taking out de -1 of x and x its 1 whats x if you take de -1?
main ice
yeah but the answer is -x^9 to the entire thing
yes that’s correct
worldly marten
and i dont understand why thats the answer
main ice
(-x^2) = -1 * (x^2)
potent current
aaa ok beacuase its a negative number my bad
main ice
you’re thinking of (-x)^2 = x^2
wintry condor
(-x^2)^3 = (-1)^3(x^2)^3
Ullr do you get this?
stray socket
Split it up like this:
$$(-1\cdot x^2)^3 \cdot x^3$$
flat frigateBOT
Umbraleviathan
potent current
yeah i understand now
stray socket
That's what Jay is tryna get you to see
worldly marten
(-x^2)^3 = (-1)^3(x^2)^3
Ullr do you get this?
why ^6? other than that i get it now
main ice
2 times 3
worldly marten
3 from the outside x? i dont think you can add it up like that
main ice
worldly marten
ah ok
well i get it now. thanks guys, appreciate it
ill be here for another 6 months or so for my university entrance exams
cya guys later. ty again
.close
safe radishBOT
lean otter
why is the answer to this -x^9 ? shouldnt it be +x^9? because -x^6 turns into a ...
[-1x^2]^3 x x^3
-1^3 * x^6
-x^6x^3
-1 (x^6*x^3)
-x^9
worldly marten
[-1*x^2]^3 x x^3
-1^3 * x^6
-x^6*x^3
-1 (x^6*x^3)
-x^9
ye understood now
is the channel closed like this btw? or do i need to do smthing else
lean otter
idk i just joined
safe radishBOT
Available help channel!
vestal edge
hi
vestal edge
wait im gona send a screenshot of my questins
i have 35 questions
in this essay
i only have 2 essays
wintry condor
can't you just post the questions?
vestal edge
im abt to sorry
i think this is geometry according to what my google document says
wintry condor
do you know the definition of x and y intercepts?
vestal edge
nope.
i have never focused on math ;-; i mostly focused on P.E and other classes
math is too hard
;-;
wintry condor
an x-intercept is where the function meets the x-axis
and the y-intercept is where the function meets the y-axis
wintry condor
an axis is a line
vestal edge
the ones here?
vestal edge
yellow?
vestal edge
red
wintry condor
great
now the x-intercept is the place where the function (blue line) meets the x-axis (the yellow line)
can you tell me where the x-intercept is?
wintry condor
yeah
vestal edge
-1?
@wintry condor
<@&286206848099549185>
can i have straightforward answers instead? so i can do this quick since i have a 2hr deadline ;-;
rough cedar
Yes U Want Me To Help You?
vestal edge
Yes U Want Me To Help You?
yes pls
rough cedar
send
sharp silo
[3 (4) - 2] - [3 (-2) - 2]
lean otter
18 for tghe first
vestal edge
[3 (4) - 2] - [3 (-2) - 2]
which is this
sharp silo
1st one
rough cedar
yes
sharp silo
I gave answer for this one
vestal edge
so its 18 ?
vestal edge
18 for tghe first
according 2 this guy
lean otter
-3,4
sharp silo
yes
sharp silo
<@742317651065569361> ?
are you doing a test?
wintry condor
do your own assignments 
vestal edge
do your own assignments <:unamused:1012005358442655784>
i went here to look for help
wintry condor
"can i have straightforward answers instead?" doesn't seem like asking for help
lean otter
o-o
vestal edge
"can i have straightforward answers instead?" doesn't seem like asking for help
then what is it
hm @wintry condor ?
vestal edge
i dont see ur reason on how asking for answers isnt asking forhelp?
safe radishBOT
@vestal edge Has your question been resolved?
safe radishBOT
@vestal edge Has your question been resolved?
vestal edge
no
crude quiver
This one is C isn't it
vestal edge
This one is C isn't it
not sure
safe radishBOT
@vestal edge Has your question been resolved?
lost lichen
Guys, is there a middle school math chat or discussion or group?
sacred vale
tawdry plover
theres 3 i can see
sqrt 9sec^2x is not 9sec^x
thats 3 sec x
also please use different variables when u sub
its kinda confusing to write x = cos x 💀
final halo
you are missing dx or du on some of your integrals, please dont forget those as it will confuse you
sacred vale
what
zinc berry
You did not "see" that. You are asking the exact same question again and making two people repeat the same advice you were already given.
sacred vale
You did not "see" that. You are asking the exact same question again and making ...
why are u complaining here if ur not here to help
someone told me before
i was asking about if my other work was correct
final halo
- Take square roots properly
- Don't leave out the dx or du
- If you make a subtitution to the variable u, everything inside your integral should then be in terms of u
fix those things
tawdry plover
can you
redo the problem
with the suggestions that have been given?
the work is somewhat difficult to go through
and out of context photos are a bit difficult to follow
sacred vale
sacred vale
i have no idea what you've done or why you've done it
here
final halo
you should have a 3 up top too no?
sacred vale
final halo
right, too many 3s going on for my head
tawdry plover
right, too many 3s going on for my head
literally, trig subs suck so much
tawdry plover
seems like theres a bit of an error here
sacred vale
what error
tawdry plover
when u divide by a fraction ur multiplying by a reciprocal
so its not 1/cos * sin^2/cos^2
flip the second fraction
tawdry plover
there you go
now can you integrate that?
(either through u sub or maybe anither trig identity)
sacred vale
there you go
tawdry plover
yuup
plucky elk
d theta should be du
sacred vale
oops
plucky elk
when you find the antiderivative (-1/u), you don't need to keep writing the integral symbol anymore. you've done the integration
sacred vale
ok
sacred vale
when you find the antiderivative (-1/u), you don't need to keep writing the inte...
is this so far correct
tawdry plover
is this so far correct
looks right yeah
sacred vale
hypotenuse is wrong
tawdry plover
yeah
sacred vale
whats your substitution?
this is correct?
tawdry plover
remove the integral sign but yeah that looks alright
when you get to cotangent i mean
shut inlet
this is correct?
if x between -9 and 9 , yes
tawdry plover
the triangle for this one
look back at ur sub
sacred vale
look back at ur sub
sin
safe radishBOT
@sacred vale Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
echo sequoia
A fair die is rolled repeatedly. Let be the random variable for the number of times the die is rolled before a six appears. What are the probability function and the cumulative distribution function for ?
safe radishBOT
A fair die is rolled repeatedly. Let be the random variable for the number of ti...
echo sequoia
I got p(X) as .1389 on the first roll. 0.1157 on roll 2. 0.0965 on roll 3. And 0.0804 on roll 4.
echo sequoia
Then for F(X) I got 0.3056 for roll 1, 0.4213 on roll 2. 0.5177 on roll 3. And 0.5981 on roll 4.
The 0.3056 doesn’t make sense to me though. Am I doing something wrong?
buoyant shadow
uh
wouldn;t you just sum them for cdf
how did you get 0.3056
and your p(X) very much looks off by one
oh i see
echo sequoia
1-(5/6)^{k+1}
buoyant shadow
right, that's definitely wrong
flat frigateBOT
Result:
0.30555555555556
okay "before a six appears" includes the six
i think
that's why it doesn't exactly work
i expect it go like
0.166667 0.138889 0.115741 0.0964506
and
0.166667 0.305556 0.421297 0.517748 0.598123
but could be shifted otherwise
hard to guess where each one starts
echo sequoia
Oh, so in other words start on k= 0 for p(x)?
buoyant shadow
yeah, you have to start at 0
because zero unsuccessful throws is obviously possible, and it says k is unsuccessful
it doesn;t depend on how you interpret "before"
but i meant for F(x)
i'm not super sure where the p should start
echo sequoia
Aahh. I didn’t think about it like that. It is talking unsuccessful, not throws total. Wow thank you.
P would start at 1/6 like you said. It makes more sense now.
molten elm
(-3,4) (-8,2) can someone help me figure this out with the x1-x2 over y1-y2 method?
safe radishBOT
(-3,4) (-8,2) can someone help me figure this out with the x1-x2 over y1-y2 meth...
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
3
molten elm
<https://www.mathsisfun.com/algebra/line-equation-2points.html>
i know how to do it but that question i dont
lean otter
!show
safe radishBOT
Show your work, and if possible, explain where you are stuck.
molten elm
alr
so basically
i do y2-y1 then x2-x1 so i mark -3 as x1 4 as y1 -8 as x2 and 2 as y2 and i do 2-4= -2 and after -8+3 is 5 so i got 5/-2
lean otter
-8+3 is not 5
lean otter
,calc -8+3
flat frigateBOT
Result:
-5
yeah, thats right
molten elm
ima confirm with 1 extra person alr
final halo
confirmed
molten elm
alr
final halo
eh actually your answer is wrong
go through it again and just be careful about what goes where
molten elm
eh actually your answer is wrong
so
its the y2-y1 over x2-x1 method
im not sure how to do it
final halo
you basically did it you just put things in the wrong place
final halo
!nosols
safe radishBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
final halo
the way you carried out the method was incorrect
you got the numbers -5 and -2
but how did you get -5/-2?
molten elm
i do y2-y1 then x2-x1 so i mark -3 as x1 4 as y1 -8 as x2 and 2 as y2 and i do 2-4= -2 and after -8+3 is 5 so i got -5/-2
final halo
you have not explained how you arrived at -5/-2
molten elm
so
-8 and - -3 the -- is a + so its -8+3 is -5 and for -2 its 2-4 is -2
@final halo
final halo
i am happy with that
final halo
why -5/-2?
final halo
but why are you specifically putting -5 on top and -2 on bottom?
molten elm
so -5/2
bc then the whole equation is negative
correct?
wait
oh
bc of the x1 and x2 method
final halo
and what is your y2-y1?
molten elm
uhm its
(-3,4) (-8,2)
is the question
and
my y1 is 4 and y2 is 2
my x1 ix -3 my x2 is -8
final halo
yes
final halo
so the -2 goes on top
final halo
what is your x2-x1?
molten elm
my x2 is -8 my x1 is -3
and
its -8 - -3
and 2 -- is a +
so its -8+3
and thats 5
final halo
nearly
molten elm
am i stupid
final halo
-8+3 = 3-8 = ?
molten elm
-8+3 is -5 and
final halo
yes
final halo
yes
molten elm
so 2/5
final halo
you're good dw you got it
molten elm
not -2/5
final halo
indeed
final halo
no worries
molten elm
also
@final halo \
i did a questionm
it was
y= 2/3x
and i got rise run method
so i put 0,0 on cordinates
then 2,3
and on the bottom its -,-
bc i like 3 points for safety
final halo
i have no idea what the question is
final halo
right
final halo
"on the bottom"?
molten elm
on the -- box
final halo
no idea what you mean
final halo
but (2,3) is not a point on the graph
final halo
thats tiny
molten elm
lol
final halo
the slope being 2/3 means for every 3 you go along the x axis, the y goes up by 2
final halo
right so i dont know why you wrote (2,3)
final halo
?
molten elm
i mean
it starts at 0,0
and goes up 2 on the y axis and 3 on the x
each tikme
time
final halo
(2,3) would be x coordinate 2 and y coordinate 3
which is not what you just described
molten elm
i meant it like that mb
final halo
it is always (x coordinate, y coordinate), dont mix em up
molten elm
ty for the help
spring horizon
quesiton 9
safe radishBOT
quesiton 9
spring horizon
im confused
spring horizon
<@733851428388601968> are you there?
yes hi
warm vault
hi
spring horizon
let me help you
tyy pls help im so confused
warm vault
writing down equations for points is ideal for this types of questions
spring horizon
no i know but what does it mean
warm vault
also what dose it mean with like a and b
it means you need an answer like 5a + b
spring horizon
oh
warm vault
So, could you write equations for the M and N
warm vault
So how to get mid point of two dots
spring horizon
which dots
warm vault
B and A
spring horizon
oh
warm vault
like what is in middle of 8 and 5
spring horizon
?
spring horizon
Guys help me <#359052604149465088> , it’s 9th grade mathematics.
can u not please.
warm vault
What number is in the middle of 8 and 5?
spring horizon
like 6.5?
spring horizon
oh ok
warm vault
how do you reach this answer?
spring horizon
i just thought that 8 and 5 has like a number close to each other which is
7 and 6
so i found the middle number of that
idk if that makes sense
idk. how to example
spring horizon
ohh ok
spring horizon
ohh
warm vault
do you understand now?
spring horizon
yes kinda
spring horizon
7
warm vault
nice job
warm vault
quesiton 9
now let's look at the point M
spring horizon
okk
spring horizon
(A+B)/2 = M?
spring horizon
(C+D)/2 = N
warm vault
now write what is a and b
bronze wind
warm vault
no just write down what is a
spring horizon
no just write down what is a
oh lowercase a?
warm vault
yes
warm vault
and what is the length of MN?
spring horizon
(A+B)/2 * (C+D)/2
warm vault
okay
warm vault
(C+D)/2 - (A+B)/2
simplify this
spring horizon
a = C+D/2 - A+B/2?
warm vault
make it only one fraction
spring horizon
oh
warm vault
oh sorry i may confused you by saying "get rid of the parentheses"
now lets look at what does the question wants from us
the lenght of AD
what is the length of AD?
spring horizon
okk
warm vault
what is the length of AD?
?
spring horizon
oh
warm vault
do you understand
spring horizon
kinda