help-23

[rigid saddle]

y is the # of points missing

[tidal gust]

ah

so that means

that

I would have to find y

Y = 58

so then I would divide 58 by 2 and I would get z, which is the amount of 2 pointers?

[rigid saddle]

u forgot to subtract 7

[tidal gust]

oh

so it would be 129-78

?

or

I just subtract from 58?

[rigid saddle]

yes

divide

not subtract

[tidal gust]

oh

so 58/7 = z?

[rigid saddle]

58/2

o wait im dumb

sry

58-7

first

then divide by 2

[tidal gust]

ohhh alright

[tidal gust]

lol ur good

so

51/2

= 25.5

round up = 26

so 26 2 pointers

so if we add up all the points

26x2= 52

26x3 = 78

plus the 7 free throws

that = 137

I got the main question, that’s good

[rigid saddle]

yea remember that u need more 2 pointers than 3 pointers

[tidal gust]

oh

yea

dang that got me

how would I get that tho

[rigid saddle]

just add another 2 pointer

[tidal gust]

oh

[rigid saddle]

cuz if u subtract a 3 pointer

[tidal gust]

alright

[rigid saddle]

u go below 136 points

[tidal gust]

ohh okay

[rigid saddle]

so u can only add 1

[tidal gust]

alright thank you

that’s it I think

thank you so much bro

really appreciate you and apologize for my dumbness my brain can’t handle this stuff sometimes

[rigid saddle]

np

[tidal gust]

ima have this open for like a couple more mins just to write down everything then I will manually close it

ty

@rigid saddle

just to confirm

the final answer would be

27 2 pt shots right?

[rigid saddle]

yea

[tidal gust]

alright thank you bro

much love

[rigid saddle]

np

[tidal gust]

god bless you

ima close it nkw

bye

.close

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[verbal wren]

Can someone help me with these questions

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@verbal wren Has your question been resolved?

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@verbal wren Has your question been resolved?

[verbal wren]

Can someone write down the steps to solve the last one

[spiral bane]

No

What have you tried so far for the first one

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[normal summit]

Hello can anyone help me with this question?

[normal summit]

This is what I did but the answer is weird

And I struggle to understand what the second question is asking, the question: "State the maximum value of..."

this is the description

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[lean otter]

Hello, why do we not take the derivative of the bottom of this equation ?

[final halo]

It is a constant

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[patent topaz]

Can someone explain to me the intuition behind "representing a vector with regards to the eigenbasis"? I know that if you have 2 bases and a vector in the first basis, you can perform a basis transformation for this vector by creating the change of basis matrix - that is, you represent the basis elements of the first basis with regards to the second basis and create a matrix out of it.

The examples I have seen for "representing a vector with regards to the eigenbasis" pretty much entail the following only: creating a matrix made out of linearly independent eigenvectors and multiplying it with the vector that is supposed to be transformed; how do the 2 differ from one another?

[patent topaz]

Context: the discrete fourier transform is used to represent a discrete signal with regards to the eigenbasis of complex pointers with varying frequency by multiplying it with the dft matrix, a matrix made out of linearly independent eigenvectors. What do we actually get after the transformation? How is that useful to us?

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[patent topaz]

<@&286206848099549185>

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[compact ferry]

.close

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[late crypt]

is there a diagram given??

[supple anchor]

oh wait nvm man i got it

.close

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[supple anchor]

.reopen

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✅

[supple anchor]

<@&286206848099549185>

[pliant cairn]

use the AB+BC>AC inequalities ig

and ud get some ranges for the x

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[tawdry salmon]

is abc divided by d also a/d * b/d * c/d?

[royal breach]

no

$$\frac{abc}{d}\neq\frac{a}{d}\frac{b}{d}\frac{c}{d}=\frac{abc}{d^{3}}$$

[flat frigate]

Михаил Колесников

[tawdry salmon]

coool

thx

.close

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[empty inlet]

Hi guys, how do you integrate x^2secx(x)? I tried many techniques but they all seem to not work

[empty inlet]

integration by parts makes my thing more complicated

Not sure how a trig sub would be even possible here

[final halo]

where did you get this problem from?

[empty inlet]

U sub is ??

My teacher just randomly wrote it and erased it

[final halo]

also was "secx(x)" a typo and you mean sec(x)?

[empty inlet]

O ye

Mb

[idle pulsar]

x^2 secx(x)
Did you mean x^2 * sec(x)
Or x^3 * sec(x)?

[final halo]

okay well this is not a standard integral

[empty inlet]

Yes I meant x^2sec(x)

[thin bridge]

it's not a nice integral

[empty inlet]

Bruh

Is it something you can't do with cal 2

[pseudo scroll]

$\int x^2 \sec x dx$

[final halo]

yes

[flat frigate]

NEONPerseus

[pseudo scroll]

Is this what it is?

[empty inlet]

Yea

[thin bridge]

def not calc 2 material

[pseudo scroll]

Have fun

[empty inlet]

Moyai

[thin bridge]

,W integrate x^2sec(x)

[idle pulsar]

You sure it's not sec^2?

[flat frigate]

Results provided by WolframAlpha

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Requested by ramonov#0921

[empty inlet]

No he wrote just sec

[pseudo scroll]

Special functions

But sometimes Wolfram throws those in unneccesarily

[idle pulsar]

It must be sec^2

[junior smelt]

Probably erased it because they realised it was a mistake and hard to do

[pseudo scroll]

If it was sec^2 then integration by parts

[empty inlet]

He said that youre gonna try to integrate hard functions and wrote this cuz it's the first day of class and no one was able to do it then he erased and continued on talking about easy functions

I did some calc 2 during break so I tried it and it did not work 💀

[idle pulsar]

If you're in high school he must have meant sec^2

[thin bridge]

having sec^2 doesn't help

it's just as borked

[empty inlet]

No he just gave us an example of something he probably thought no one could do (he's right)

Thanks guys

[idle pulsar]

You're right... 💀

The answer becomes easier, but still is not in the realm of calculus 2

[empty inlet]

Rip

[idle pulsar]

I think just nevermind it.

[empty inlet]

It looks so simple that's why I thought I could do iy

[thin bridge]

maybe they mistakenly wrote the ^2 on the x instead of the sec

[idle pulsar]

If you're new to integration, you wouldn't need to even look at those things.

[thin bridge]

if it were integral of
x * sec^2(x)
it's be within the realm of calc 2

[idle pulsar]

This sounds much more reasonable as "harder integrations" when teaching integration for the first time

[empty inlet]

Yes but he like said it in 3 seconds so I think he was just trying to joke

[idle pulsar]

try solving the integration of (x.sec^2(x))

If you wanna practice parts

It's a good example

[empty inlet]

I think I could do that you just set u to x

And then dv is sec^2x

Then v would be tan x

Anyway thanks guys

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[idle pulsar]

Yes exactly

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[uneven jacinth]

50%

the rectangles area is 640

$flip

$flip$

[flat frigate]

7351

[uneven jacinth]

hm

pythagorean theorem

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@lean otter Has your question been resolved?

[uneven jacinth]

oh you're right silly me

i forgot that the line which is 12 inches long overlaps

640-336=304

304/640=47.5%

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[vivid pivot]

Hi I need help solving this ode with power series solution

[plucky elk]

,rotate

[vivid pivot]

oh my bad

[plucky elk]

so you're just supposed to plug in a generic power series for y?

did you try that already?

[vivid pivot]

its supposed to be of this form because its a regular singular point

the r is confusing me

[plucky elk]

,rotate

[plucky elk]

where did r come from

[vivid pivot]

the teacher just said it was supposed to be of that form

we need to solve for r but I have no idea how and I dont have an example

[plucky elk]

try plugging in your expression into the differential equation

you'll get an equation in terms of r

[vivid pivot]

.rotate

[plucky elk]

,rotate

[vivid pivot]

this is the theorem we learned in class

and I did that here it is

[plucky elk]

plug your y, y', and y'' into here

[vivid pivot]

kk gimme a sec

nice

[plucky elk]

#chill for spam

[vivid pivot]

,rotate

[vivid pivot]

I got here and Im not sure how to move forward

[plucky elk]

collect powers of x together

[vivid pivot]

meaning?

[plucky elk]

since you know the series is 0, every coefficient for each power of x must be 0

$2x^3 + 4x^3 = ?x^3$

[flat frigate]

riemann

[vivid pivot]

like this here?

[plucky elk]

,rotate

[plucky elk]

right so you have an equation in r for all your coefficients

[vivid pivot]

,rotate

[plucky elk]

,w solve 2x d^2y/dx^2 + 5dy/dx + xy =0

[flat frigate]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[plucky elk]

pain

[vivid pivot]

isnt the solution supposed to be a power series?

[plucky elk]

J and Y are special functions and can be expressed in power series

[vivid pivot]

yeah I havent seen that😭

,rotate

[vivid pivot]

I got here but seems like Im going in circles

[plucky elk]

oh C1 is not 0

r = -1 also satisfies your first equation

[vivid pivot]

shit

so then what is c1 equal to?

[plucky elk]

no idea

do you have boundary/initial conditions

[vivid pivot]

nah I dont thats all they gave me

[plucky elk]

https://math.libretexts.org/Bookshelves/Analysis/Supplemental_Modules_(Analysis)/Ordinary_Differential_Equations/6%3A_Power_Series_and_Laplace_Transforms/6.2%3A_Series_Solutions_to_Second_Order_Linear_Differential_Equations

i didn't check that 0 was a singular point

[vivid pivot]

I did though

0 is a singular point

[plucky elk]

maybe try following Example 6.2.2 and using the shifted power series

[vivid pivot]

okay Ill look into that thanks so much for your help

[plucky elk]

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[tardy rampart]

Can someone please explain what we did here

[unreal fiber]

u substitution?

or do you have a problem at a particular step

[tardy rampart]

I know we did u substitution but i dont understand how we chose u

[unreal fiber]

I guess first trying u = x - sqrt(x) then failing and realising you can factor out a sqrt(x)

and that works

idk if you could come to that by simply observing as it is but I guess depends on how much experience you have on integrals similar to this

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[patent musk]

am i right wit 4/3

<@&286206848099549185>

[empty gyro]

!15m

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[patent musk]

my bad

[supple shore]

u know that cosinus of an angle is adjacent/hypothenus

[patent musk]

dude i already got the answer i jus need to make sure 😭

[supple shore]

so i would say 3/5

[patent musk]

are you doing the adjacent divide hypothenuse?

[supple shore]

because cosinus of this angle is AC/BC with AC is adjacent and BC the hypothenuse

[patent musk]

thats true

it wouldnt be 4/5 too right

[supple shore]

no because AB are the opposite of the angle

but if the question is determine the sinus ratio so it would be AB/BC

[patent musk]

yeaa thats what i thought too

thank you

[supple shore]

because sinus of an angle is the opposite divide by the hypothenuse

np good luck 🙂

[patent musk]

i got like 3 more are u free to help?

[supple shore]

yes

[patent musk]

thanks really ive been looking for help all day

[supple shore]

but try before just send the question i want to watch what you have done

[patent musk]

wymm

yeah i already solved it

[supple shore]

ok that's what i said ok it's good 🙂

[patent musk]

okay ty one sec

its either C or A here right?

[supple shore]

ok so we now that tan = opposite/adjacent

maybe i don't understand the question but i would say that tan angle D = 3/2 so tan angle A would be 6/4

so maybe the B ?

[patent musk]

wait i didnt even read it properly 😭 i thought it said sin* instead of tan

[patent musk]

yeah it has to be B

[supple shore]

np i read all fast too and i makes some mistakes sometimes

make *

sorry my english is not very good

[patent musk]

you straightt

this is my last one

[supple shore]

you got it man 🙂

[patent musk]

its says tangent ratio so it has to be 12/5 right

[patent musk]

alright thank you so mch bro

which grade you in?

[supple shore]

don't know what's corresponding in england but like in highschool

[patent musk]

oh bet

im in 9th

[supple shore]

12th grade

[patent musk]

damnnn so you graduating soon

[supple shore]

yes 🙂

[patent musk]

hey @supple shore u still here? do you agree with this one?

[supple shore]

no

cosinus is equal to adjacent/ hypothenuse right

what's the adjacent and the hypothenuse of the angle here

[patent musk]

wait is it C?

[supple shore]

maybe, why do you think it's C

[patent musk]

idk i jus guessed that one cuz its the only other valid one i feel like lol

[supple shore]

what information do you have here, the angle , DE that the opposite and the hypothenuse do you know a formula with opposite and hypothenuse that implies our angle ?

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[tidal slate]

Not sure how to do this

[tough spruce]

if polynomial long division isn't your style try find a polynomial that multiplies by z-1-3i to give P(z)

[tidal slate]

i know how to do long division not sure how to do it with 1+3i

[tough spruce]

work through it same as normal, it's just a bit lengthier

[tidal slate]

ok thnx

.close

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[toxic junco]

How do I find the average?

Im doing Binary search and got confused on how to find the average

[safe radish]

@toxic junco Has your question been resolved?

[lost yacht]

Binary search works like this:

Input: Sorted List of length n, with indices 0, ..., n-1
Algorithm:
1. leftmost_index = 0, rightmost_index = n-1, list = (number_0, ..., number_(n-1)), searched_value = x
2. If leftmost_index = rightmost_index, check if element leftmost_index of list is equal to x. If so, leftmost_index is the index of x in the list. Otherwise x doesn't exist in the list. If leftmost_index is not equal to rightmost_index, continue with 3.
3. middle_index = floor((leftmost_index + rightmost_index)/2)
4. If element middle_index of list is > x, repeat from 2. with leftmost_index = leftmost_index and rightmost_index = middle_index. Otherwise repeat from 2. with leftmost_index = middle_index + 1 and rightmost_index = rightmost_index.

[flat frigate]

Cyrol

[lost yacht]

with l being your current leftmost index, and r being your current rightmost index

all clear?

[flat frigate]

Cyrol

[lost yacht]

So you'd look at index 3 and continue from there.

[toxic junco]

Thank you

But the explainaion is so confusing to me

I saw a youtube video where he found the mid and stuff and the average

I just wanted to know how do you even find the average

Average is 6 but idk where he gets
number rom lol

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[junior wagon]

Is this right?

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[trim swan]

,rccw

[frigid plinth]

#1 is obviously wrong

How are they both 48 degrees

One is literally bigger than the other

@lean otter

💀💀💀

It's 180 - 48 = 132 degrees

That's ur answer

#2 same thing

Cmon no offense but use your common sense

54 + 7x = 180
7x = 126
x = 18

#3 is right nice job

X is 30

#4 is good too

#5 is wrong

You started out right

Just bad algebra

X is 59 💀💀

Bro don't complain

I'm genuinely trying to help u get better

I even gave u all the answers

#6 same thing

Literally use your eyes and you can see that they are not equal

💀💀

One is clearly acute and one is clearly obtuse

Come on bro

@lean otter do u still need more help

[safe radish]

@lean otter Has your question been resolved?

[dense stump]

@lean otter what grade are you in

ok

im not too good at algebra but ill see what i can do

omg nevermind i cant do anything with angles i got no idea

[safe radish]

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✅

[frigid plinth]

Why does nobody want to actually learn tho

I'm just telling you a super easy way to check your work

Look and see if the angles are bigger than the other

And that's how you check your work!

I know

But it's the best way to teach

[trim swan]

It's not really good practice to assume the figure is to scale

[frigid plinth]

Yes but I'm just saying you can't just set an angle equal to anotuer

I'd argue what you said too

You can't just look at it and see that they're look similar

[trim swan]

Yes you're right, you definitely shouldn't just assume two things are equal either

[frigid plinth]

You have to use mathematical knowledge

If it helps derive the properties in your head

Like know that vertical angles are congruent

Then know that corresponding angles are congruent

Then you can find out if two angles are congruent or if they are supplementary

That's what I did in geometry honors and precalculus honors

Haha

But like

Math is annoying and it always helps to be more skeptical than not

So from my advice

While you shouldn't use looks to determine if two things are equal

You can most definitely use them to determine that two things may NOT be equal and check from there

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

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[lean otter]

I resolved this question but I'm not sure if I'm right, I would appreciate it if someone tells me whether I'm right or not 🙏

[lean otter]

For me the right answer is C

But I'm having a problem trying to figure out how to solve this

[stray socket]

tangent of an angle gives slope of a line set upon that angle

Since 7% is basically rise/run, where the rise is 7 and the run is 100

The slope can also be described as components of a right triangle, with an adjacent side equal to the run and an opposite side equal to the rise

Therefore the arctangent of rise/run gets you the angle

[frigid plinth]

Sorry below it you said x = 144

I don't know which one you meant

I did u wrote two answers

[lean otter]

So basically am I right? The correct answer is C?

[frigid plinth]

No

That's the supplement

Wait no it isn't

Wheee did u get that from again

You plugged it back in

Right

Your teacher was double checking

By plugging it back in

[lean otter]

Tan-1 (7/100)

Is it the correct answer? Right? 😅

[stray socket]

yeah

[lean otter]

Thanks

🙏

[frigid plinth]

No it's not correct

They are not equal to each other, rather supplementary

Add them both and set them equal to 180 and lmk what you get for x

I'm tok lazy to scroll up lol so I'm doing this off of memory

Seems right

[safe radish]

@lean otter Has your question been resolved?

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[autumn monolith]

how do i decide if $a_n = (2-\sqrt5)^n$ is diverge or converge?

[flat frigate]

Sas

[final halo]

You need to check if $|2 -\sqrt{5}|$ is bigger than 1, or less than or equal to 1

[flat frigate]

ΣAC

[final halo]

Hopefully it's clear to you which one implies convergence

[autumn monolith]

it is smaler then 1

-0.236

it keep getting smaller

[final halo]

Its magnitude keeps getting smaller yes

[autumn monolith]

so how do i explain it

that it goes -> 0

[final halo]

Well what ways have you been taught

[autumn monolith]

$if |T| <1, so \displaystyle\lim_{n=\infin} T^n = 0$

[flat frigate]

Sas
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[final halo]

Well then that's it you're done

[autumn monolith]

converge

but is there a way to show it

like prof it

all i did was put random number for n

and saw it got smaller each time

[final halo]

Well where are you getting this from

If you've been told this result then you can use it

[autumn monolith]

okei

$a_n = (2-\sqrt5)^n \displaystyle\lim_{n=\infin} (2-\sqrt5)^n = 0$ like this

[flat frigate]

Sas
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[autumn monolith]

is this good enough?

[final halo]

Well you haven't written any explanation you've just written the result

[autumn monolith]

exactly

that is what i want to explain it

we did not learn how

just the teorem

[final halo]

You've done all the steps already

T = 2 - sqrt5

Just show that |T| < 1

[autumn monolith]

how?

i dont know the right way

[final halo]

You already did it

[autumn monolith]

Where?

you told me i wjust say its 0

so i did all the steps?

i dont get it

[final halo]

Well where did you get -0.236 from

[autumn monolith]

calculator

n =1

[autumn monolith]

?

[peak estuary]

You have to show that 2-sqrt5 is between -1 and 1

So you have to show that sqrt5 is between 1 and 3

Can you do that

Without calculator

[autumn monolith]

okei

il try

$2- (5)^{-\frac12} = \frac {2}{5^{\frac12}}$

[autumn monolith]

this show that its bellow 1 and between -1

right?

[flat frigate]

Sas

[autumn monolith]

$|\frac {2}{5^{\frac12}}| <1 \Rightarrow \displaystyle\lim_{n\rightarrow\infin} (2-\sqrt5)^n = 0$

is this good explained?

[autumn monolith]

.

[flat frigate]

Sas
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[peak estuary]

that is not how fractions work

[peak estuary]

do this. and don't overthink

1 < sqrt(5) < 3

how can you show this is true

[autumn monolith]

sqrt(5) = 2.236 ...

[peak estuary]

without a calculator

[autumn monolith]

5^1/2

[peak estuary]

sqrt(5) = 5^1/2, yes

[autumn monolith]

so does that explain it?

[peak estuary]

no you just rewrote it

how can you show sqrt(1) < sqrt(5) < sqrt(9)

[autumn monolith]

1^1/2 < 5^1/2 <9^1/2

[peak estuary]

again, that's just rewriting it. does not show it

[autumn monolith]

1<5<9

[peak estuary]

yes

and that is clearly true

[autumn monolith]

yeah

[safe radish]

@autumn monolith Has your question been resolved?

[autumn monolith]

.close

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[split meteor]

can some one help me with this? I’m not sure how to find the permitir and area

[worthy hemlock]

Do you know distance formula?

[split meteor]

no i dont

[worthy hemlock]

So something like this is unfamiliar?

[split meteor]

yes its unfamiliar

[worthy hemlock]

What about Pythagorean theorem?

[split meteor]

yea, i know that one

[worthy hemlock]

Distance formula is just an application of Pythagorean theorem

[random star]

Have you done point A btw? Kinda curious how you demonstrated that it's a square

[split meteor]

ohh, okay thank you

[split meteor]

no i havent yet

[random star]

Perhaps you should first demonstrate that it's a square and then use the various formulas for calculating the area and perimeter

[worthy hemlock]

The best way to demonstrate that is to see if all the lengths are the same, aka using distance formula to find the lengths of the sides

[random star]

shouldn't you also demonstrate that the angles are 90°?

[worthy hemlock]

There's probably an easier method to finding the the side lengths, I just defaulted to distance formula

[worthy hemlock]

If all the side lengths are the same, then it indirectly proves that all the angles are the same

[random star]

well

side lengths tho

[worthy hemlock]

Lmao forgot rhombuses were a thing tbh

[unreal fiber]

hmm

[worthy hemlock]

But it asks to check if it's a square or not, no need to go into details about the other shapes in my opinion

[unreal fiber]

maybe diagonals help to confirm that the all angels are 90° after finding sll the side lengths first

[random star]

i was thinking of calculating the eq for a line that goes thru A and D, one that goes from D thru C and show that their angular coefficients are anti-reciprocal

m * m' = -1

[unreal fiber]

oh yeah that works too

so either,
-see if the pythagorean theorem holds for the diagonals
-see if the lines that construct one angle have angular coefficients that are anti-reciprocal

for the first one, you need the side lengths first

[safe radish]

@split meteor Has your question been resolved?

[split meteor]

thank u guys for the help!! I got it

[safe radish]

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[lean otter]

no clue on how to solve this

.close

[safe radish]

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[sonic spruce]

... why'd you close immediately?

[lean otter]

i figured it out after and realized i was just being stupid

thank you though

[safe radish]

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[hollow scaffold]

ayo could someone tell what the "me" stands for in here?

[hollow scaffold]

in statistics ofc

[safe radish]

@hollow scaffold Has your question been resolved?

[hollow scaffold]

<@&286206848099549185>

[modern fractal]

mathematical expectation?

https://www.toppr.com/guides/fundamentals-of-business-mathematics-and-statistics/probability/mathematical-expectation/#:~:text=Mathematical expectation%2C also known as,observed occurrence of the event.

[hollow scaffold]

ty

.close

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[stray socket]

What's the objective

[fickle trail]

After factoring I got x is greater than or equal to -4

Finding domain

[stray socket]

I'd use analysis

[fickle trail]

Line graph?

[stray socket]

$x^2 + 4x \geq 0$

[flat frigate]

$e^{\text{Umbraleviathan}}$

[stray socket]

Nah

Multiplicity of roots

Since the leading coefficient is positive and the roots are 0 and -4, I can understand how that affects function behavior and easily state that x >= 0 and x <= -4

[fickle trail]

Hmmm

[stray socket]

,w graph x^2 + 4x

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Umbraleviathan#3607

[fickle trail]

I think it would be less confusing for me to put the x intercepts on the line graph and test with numbers to the left and right if the intercepts

[safe radish]

@fickle trail Has your question been resolved?

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[hidden steppe]

hello, how can I solve this?

[faint seal]

write 125^x as (5^3)^x

[hidden steppe]

(5^3)^x?

[frank glen]

$a^{b+c} = a^b a^c$

[hidden steppe]

oh that was the same

[flat frigate]

VulcanOne

[hidden steppe]

yeah I know those properties

but I can never figure out how to solve these kind of problems

they are all the same but I never learn how to actually solve it

[faint seal]

a^b / a^c = a^(b-c)

so try to get the numerator and denominator with the same base

in the exponent

[frank glen]

This requires personal motivation

You need to convince yourself to try it yourself

Without help

[hidden steppe]

the problem is not with motivation I spend hours trying to solve

I try to break down the problem

and use everything I have learned

[frank glen]

Then what goes wrong?

[hidden steppe]

I don't know. I guess I don't know a good approach on how to solve this

[frank glen]

Actually you have but you didn't look at it from a different angle

[spice grove]

I'd like to add. You should have your work to offer each time you seek help. Anything at all you've tried. It would help you analyse what you tried. And what you were asked to do each time. You can compare those to see where you were lacking.

I see here you didn't have any work to show.

You just went with whatever others suggested you to do.

[hidden steppe]

I always show my work if I have any

I don't even know where to start with this

[spice grove]

Did you not know 5^3 = 125?

[hidden steppe]

no

[spice grove]

Oh.

[hidden steppe]

I didn't know to do that step

actually I still don't see how that would help

[spice grove]

You need 5^f(x)

So try generating 5s

[frank glen]

You have $5^{-4x+7}$ up top

[flat frigate]

VulcanOne

[spice grove]

125 surely looks like it's divisible by 5. You could prime factorise in all these questions.

[frank glen]

And 125 = 5^3 will help

[hidden steppe]

I know but how would it help?

[spice grove]

Again, you need 5^f(x) anything you turn into a 5 will help.

[hidden steppe]

I'm not following. I need to get the value of f(x). why would 5 help?

you're skipping steps

[spice grove]

Well ultimately you need 5^f(x) yes?

[flat frigate]

What the hell am I doing here?

[hidden steppe]

okay thank you that was well explained

but how can I come up with that solution on my own?

I should have known that

[spice grove]

When dealing with Exponents. Make sure you know your base.

Sometimes you'll have multiple bases.

For example, 2 and 3.

And your answer would require you to combine those.

That you'll know if you notice a 6 anywhere.

So anyways, once you know what base you're dealing with. Stick to it. Convert all the large numbers as exponent of that number.

For example, if you have 1024 and your base is 2. Don't do 1024 = 32^2 and then in some other step 256 = 16^2
This will only slow you down. Try to have everything in terms of 2 strictly.

And just don't give up too soon I guess.

That's all.

[hidden steppe]

how do I add these together?

[spice grove]

...

[hidden steppe]

yeah

how to add them?

[spice grove]

What do you mean?

[hidden steppe]

can I add the x terms?

and what about the 7

[spice grove]

Yes.

well

x + 7 is just x + 7

You just let it be.

[spice grove]

yeah.

That would be it.

[hidden steppe]

and now I am stuck

[spice grove]

But...

But the problem is over.

[hidden steppe]

I have not found the value of f(x)

I still have 5^f(x) on the RHS

[spice grove]

you didn't get the question perhaps.

There's no rhs.

The question was asking you to first write

5^(something)

[hidden steppe]

well I made equation of it to find unknown

[spice grove]

And then, it's asking you what that "something" is.

So 7-7x would be that something.

f(x) = 7-7x

[flat frigate]

What the hell am I doing here?

[hidden steppe]

so f(x) is the same as the exponent on the LHS?

[spice grove]

right.

[hidden steppe]

alright

thank you very much. Your help is much appreciated

.close

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[safe radish]

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[serene aspen]

I study maths in French, so its would be better if the person who's gonna answer understands it,
been looking for some geometry questions to solve "plans dans l'espace" and i dont know how to solve a certain question

[serene aspen]

1-b)

after I remove the alphas etc
by doing x+2y or x+2z or x+y+z, what am i supposed to do

how do i form the equation

[nova nest]

hi...

Nice to meet you.

[serene aspen]

hi

@nova nesture still here ?

<@&286206848099549185>

[vestal sedge]

ping after 15 minutes with no answe

[serene aspen]

IM SCREAMING

[vestal sedge]

bro thats french tf u on

[serene aspen]

PLZZZZ

[serene aspen]

yea well, got someone that said nice to meet you and left 💀

[sudden vigil]

If you understand the language, then feel free to help him.

[nova nest]

sorry to bother you...

[vestal sedge]

im still studying french in school so im not that confident in my translation skills

ill try tho

[serene aspen]

i asked for french because i needed someone to understand the question in the pic, thats all

[nova nest]

You are expert...

👍

[serene aspen]

IM SCREAMING WHAT IS THIS

[vestal sedge]

i have no clue tbh

they did join yesterday so you never know

[serene aspen]

this explains alot

[vestal sedge]

ok so if i translated correctly, at 1 b it asks to make a system of equations for AB right?

cartesian, not parametric

[vestal sedge]

oh wow i translated it correctly

yippie i remember some french from the last 4 years

[serene aspen]

yes

[serene aspen]

purrr

[vestal sedge]

did you do a?

[serene aspen]

yes

[vestal sedge]

well what did you get?

[serene aspen]

gimme a sec its sending

[vestal sedge]

alr

[serene aspen]

this internet is driving me crazy i stg

i write using my legs, dont judge me

[vestal sedge]

what kinda z is that

[serene aspen]

Cursive. 🥰

[vestal sedge]

bro i write cursive to thats not how i do it

that looks like zeta

[serene aspen]

IM WHEEZING, My handwriting is shit af when it comes to solving problems, I sometimes dont even know what the numbers are ☠️

[vestal sedge]

do you mind doing a latex representation of it?

i legit cant understand

[serene aspen]

What is that

[vestal sedge]

nvm then

[serene aspen]

Mate here’s the whole paper

Idk if thats how B is supposed to be done

.close

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[compact ferry]

$C \subset [0,1] \subset \mathbb{R} \in \mathbb{B}(\mathbb{R})$

[flat frigate]

heavy

[compact ferry]

is that enough

or need i deal with openness

seems like its quite trivial

or even easier actually

$C$ is closed hence $\mathbb{R} \setminus C$ is open hence $\mathbb{R} \setminus C \in \mathbb{B}(\mathbb{R})$ hence by the sigmaness of $\mathbb{B}(\mathbb{R})$ we have that $(\mathbb{R} \setminus C)^{C} = C \in \mathbb{B}(\mathbb{R})$

[flat frigate]

heavy

[compact ferry]

and then $\lambda(C_{n}) = (\frac{2}{3})^{n-1}$

[flat frigate]

heavy

[compact ferry]

.close

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[prime geyser]

I need to find the limit of the attached sequence but without using integrals

[frank glen]

n goes to what?

[prime geyser]

to infinite

[frank glen]

Okay

[unreal fiber]

is the last term 2n or is it something else

[prime geyser]

2n

[frank glen]

Okay

Consider the limit of each term alone

[prime geyser]

considering the limit of each term alone didn't help (tried it and teacher said it shouldn't be done like that, not quite sure why)

[unreal fiber]

do they want the sum in summation notation or something

and then the limit

[prime geyser]

yes

[unreal fiber]

it's not that hard to write it in summation notation when you realise 2n is n + n

[prime geyser]

i did the summation but cannot find the limit

[unreal fiber]

can you show you work so far then

[prime geyser]

one sec

[unreal fiber]

that's like almost completely different than your original question

[prime geyser]

the other part where i get to that is messy

i was trying to that so i could use a formula but that was no use either

[frank glen]

$\lim_{n \to \infty} \frac{1}{n+1}$

[flat frigate]

VulcanOne

[frank glen]

Do you know how to solve this alone?

[prime geyser]

lim equals to 0?

[frank glen]

Approaches** 0 yesr

[prime geyser]

got it

[frank glen]

Now

$\lim_{n \to \infty} \frac{1}{n+2}$

[flat frigate]

VulcanOne

[frank glen]

What's this?

[prime geyser]

also approaches 0

[frank glen]

Okay

If you added the first limit and the second limit together

What will you get?

[prime geyser]

0 but the answer which teacher told us is not 0 but log(2)

[frank glen]

[unreal fiber]

I don't think what you have send first and next are equivalent at all

[frank glen]

[prime geyser]

i dont know if its completely correct what i've done in the second one

[unreal fiber]

the first is a simple limit expression, second is a well known sum for log(2) which has all sorts of explanaons with and without integrals

I don't even know how did you manage to derive the second one from the first one

nor why

[prime geyser]

on the first pic i need to find the limit of it but teacher clarified the answer is not 0 but log(2)

[frank glen]

That's not true

It approaches 0

[unreal fiber]

are you sure the question is certainly the first screenshot

because answers don't match and it has a rather poor notation

[prime geyser]

okay. thats what messed me up i got 0 but the teacher said no, i'll require from her some explanation rather

[prime geyser]

yep

[unreal fiber]

hmm

looks like an issue on the teacher's side then

[prime geyser]

tbh might be true some teachers make quite mistakes in my country so

i'll ask the teacher for the full answer when on uni,
thanks for your time guys!

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[little sorrel]

how would i do (a)(ii)

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[crimson oar]

When working out the integrating factor using this question as an example, why does the IF not include +c (so IF = e^(sin(t)+c))

[lean otter]

you can include the +c

but you are multiplying everything by the IF

so it cancels anyways

[crimson oar]

ahh, fair point. thanks

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[raw pivot]

How can I check if the derivative exists on R ?

I know that it exists for all Values except 0

[lean otter]

how formal do you need to be?

you can use the fact that each of the piecewise parts are differentiable

[raw pivot]

and its continues?

so Its derivative exists on R?

is that enough

[lean otter]

continuous does not imply differentiable (think of |x|)

an exponential is always differentiable

and 1/x is differentiable away from 0

[raw pivot]

yes but both parts are differentiable

[brave wolf]

You have to check if both parts have same derivative at x=0

[raw pivot]

so dont I only need to look if its continues in this one example

[brave wolf]

and also same value

[raw pivot]

with the limit from the right and from the left?

[mortal sandal]

you want the values to match up and the derivatives to match up

[vestal sedge]

if its differentiable from both sides at a specific point, it's derivatives being the same, then its differentiable over R

or whatever interval its defined on

[mortal sandal]

so look at limit of e^(-1/x) as x->0+ and also the limit of the derivative

[raw pivot]

so do I first differentiate e^(-1/x) and then look at what happens with

d/dx e^(-1/x) lim x ->0

[mortal sandal]

yeah

[vestal sedge]

you'd use the limit to check if its continuous, if you've done that just do the derivative

[brave wolf]

The limit of derivative doesn't exist. It must be derivative from right

[mortal sandal]

that was implied, yes

and that statement is debatable

well no

isn't it just wrong

[vestal sedge]

well wouldnt the derivative at a point be $\lim_{n\to a} \frac{d}{dx} f(n)$?

[mortal sandal]

limit of the derivative does exist

[flat frigate]

Kel.plush

[brave wolf]

It does exist, but just from right. And the limit is 0

[mortal sandal]

??

,w plot e^(-1/x)

[flat frigate]

Results provided by WolframAlpha

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Requested by monikanicity#0205

[brave wolf]

Here is how the function looks like

[mortal sandal]

ah

yes only from the right then

Which was the intended interpretation of my statement in the first place

[brave wolf]

So in conclusion. You already know all points except x=0. As you can see the limit of e^(-1/x) as x approaches 0 from RIGHT=0. So both parts of the piecewise functions match at values. Now you have to check if they also match in derivative. The screenshot shows derivative of the 2nd part of the function. Again, take the limit as x approaches 0 from right. Again, it's 0. So both function match at derivative, and value on the intersection point. So we can conclude that it's differentiable at R.

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[raw pivot]

thanks!

.reopen

[safe radish]

✅

[raw pivot]

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[uneven jacinth]

how do i prove that the abscissa of point S is 180 less than than point r and the ordinate is the negative of point R

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[uneven jacinth]

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[mossy holly]

Help, show step by step

[tardy mango]

Angles in a quadrilateral add to 360 deg 🤷‍♂️

[mossy holly]

wait thats it?? 😳

[uneven jacinth]

add them all, you get 8x-32 =360

solve for x

2x-19+x+17+3x+7+2x-37=8x-32

the sum of all angles in a quadrilateral equal 360

8x-32=360

8x=392

x=49

now they ask you to find the sum of angles A and B

[mossy holly]

yes

[uneven jacinth]

A = 2x-19
B=x+17

plug in x= 49

98-19 + 49+17

[mossy holly]

thats it?

[uneven jacinth]

yup

[mossy holly]

THANK YOUUU

SAVED MY LIFE

[uneven jacinth]

💋

[mossy holly]

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[desert apex]

Determine the parameter a so that the lines (a-1)x + ay - 5 = 0 and ax + (3a-1)y -7 =0 intersect on the x-axis

[clear blade]

the x-axis is where y = 0

so substitute y = 0 and make sure the x-values are the same

[desert apex]

idk how to start'\

what should be my first step

[brave wolf]

Take (a-1)x + ay - 5 = 0 and ax + (3a-1)y -7 =0 and replace all the Ys with 0s.

So it would result in (a-1)x + 0a - 5 = 0 and ax + 0(3a-1) -7 =0

Since 0*anything is 0, you can simplify furthermore

(a-1)x- 5 = 0 and ax -7 =0

[desert apex]

can i ask why we puted y = o

[brave wolf]

For the equations to intersect on x-axis, you need to satisfy 2 conditions. 1) Y must be equal to 0, which is why you can substitute it

Once you substitute it, you just need to make them equal, which is the second condition

[desert apex]

okey thanks

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[brave wolf]

(a-1)x- 5= ax -7 is the next step. It seems unsolvable but if you expand it, it can be solved for x. Once you solve it for x, substitute back and you're done.

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[silent scaffold]

is there a reason why the p is above p->q at modus ponens

[quasi bison]

p and p->q are two premises

[clear blade]

,rccw

[silent scaffold]

why is !q below p->q for modus tollens

(is there a reason for it or can i ignore it?)

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[lilac widget]

How do I approach this?

[lilac widget]

Heres what i did

But apparently its wrong

[hardy lion]

you forgot your variable of integration

at the end

also its the area bounded by the two curves

so you need the stuff below the x axis as well

[lilac widget]

so what is the limit? 4 and -4?

[hardy lion]

yes

[lilac widget]

and then i can solve?

@hardy lionplease lmk

if i do u sub it gets weird

[hardy lion]

you should be able to