help-23

[slim mesa]

LOVE YOU

FOR THIS HELP

[dusk iron]

D

[slim mesa]

its people like you that help people making their day

[solar hazel]

at least one of the given answers has been wrong

that's all i'll say

[slim mesa]

yeah i got it wrong for the prevcious one

[dusk iron]

Whhy

[slim mesa]

but

continue

[dusk iron]

Ohh shoot it's domain

Mybadddd

[dusk iron]

D

[dusk iron]

D

[dusk iron]

D

[dusk iron]

B

[dusk iron]

D

[slim mesa]

isnt this fun

[dusk iron]

Hahha

Yes

[slim mesa]

helping a stranger u met 5 mins ago

[dusk iron]

@slim mesa C

[slim mesa]

if i complete these i get extra credit basically

[dusk iron]

D

[dusk iron]

C

[dusk iron]

B

[dusk iron]

B

[dusk iron]

C

[dusk iron]

A

[dusk iron]

D

[dusk iron]

B

[slim mesa]

YOU DID IT

[dusk iron]

Congrats to u and me lolzzzzz

[slim mesa]

hmmmmmmmmmmmmmmmm

down for another?

[dusk iron]

This is not the point of this server tho

[slim mesa]

i'll pay you 5$ an hour

lmfao

uh

[dusk iron]

What the lolol no I'll do it for free
But I'm not good with all topics

[slim mesa]

am i breaking server rules by saying this oh no

do u have zelle

[dusk iron]

Maybe DM me

[slim mesa]

can i send u money

[dusk iron]

What the noo

[slim mesa]

how are u not hungry for money, who ARE you

[wild basin]

which website is this

[dusk iron]

@slim mesa we shdnt do thus is this server (homework help)

[slim mesa]

ixl

[slim mesa]

sure

[dusk iron]

We're supposed to make u independent

[slim mesa]

ixl

[dusk iron]

Dm me if u want to get direct help
I can't violet rules here any more

[wild basin]

lol

i can help u too:).

if you want

[dusk iron]

Direct help => answer's without hints... Just answers

[wild basin]

thanks for the website

btw

now i can enhance my skills

@slim mesa i send you frnd request

[safe radish]

@slim mesa Has your question been resolved?

[safe radish]

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[wise hemlock]

Pls help me

[rugged ice]

so its 54 months in total

and 27.000 dollars

so

so 27.000 is 135 procent of 20.000

[narrow folio]

He can use the simple interest formula to find rate too I think

[rugged ice]

ye you can do that

but i like over thinking things

[narrow folio]

But you'd have to use 6.5 years rather than months as it asks annual rate

[rugged ice]

oh ye

[narrow folio]

Well I checked both our methods gave the same answer

Just use years though

[wise hemlock]

I tried what you Said but its Not the solution to my level

[safe radish]

@wise hemlock Has your question been resolved?

[narrow folio]

So u have the solution?

Ohhh

Wait I still dont get it

[wise hemlock]

No

[narrow folio]

Wdym then

[wise hemlock]

The solution you presented me is Not the solution to my level

[safe radish]

@wise hemlock Has your question been resolved?

[wise hemlock]

<@&286206848099549185>

[wise hemlock]

<@&286206848099549185>

[safe radish]

@wise hemlock Has your question been resolved?

[safe radish]

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[vestal saddle]

Oops wrong picture

[safe radish]

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[obsidian vapor]

Hi is it possible to rewrite this to the red part? On the second integral I tried to switch the intervals and rewrite the interval from -inf to 0 but that didn't seem to work (bc of the minus when switching the interval)

[obsidian vapor]

I also tried to apply the improper integral theorem (I think it's called) and change the variables as well but it got very messy with the substitutions and it didn't seem to work either in the end

The original question is to show that this holds by using the Inverse Fourier Transformation

[safe radish]

@obsidian vapor Has your question been resolved?

[safe radish]

@obsidian vapor Has your question been resolved?

[safe radish]

@obsidian vapor Has your question been resolved?

[safe radish]

@obsidian vapor Has your question been resolved?

[safe radish]

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[sharp cypress]

if the first line is correct when its a symmetrical function

can we in the opposite side

[static shore]

$\int_{-\infty}^{\infty}e^{-\lambda x},\mathrm{d}x$ doesn't even converge

[deep apex]

yes because it's an equality

[flat frigate]

(DEN) / (J / I)

[deep apex]

convergence depends the value of lambda no ?

but probably doesn't as you said

[vestal sedge]

the literal only value it converges on is 0

[static shore]

It doesn't converge for any real value of $\lambda$

[cosmic grove]

kinda but here its still diverges

[flat frigate]

(DEN) / (J / I)

[static shore]

not even 0

[deep apex]

ah yeah it diverges

[sharp cypress]

why would convergence matter

[cosmic grove]

?

[cosmic grove]

what are you trying to do ?

[sharp cypress]

solving the integral

wait a min i'll show you

[deep apex]

for some other example where the integral is convergent, the rule above is indeed an equality

[cosmic grove]

not solvable, it diverges

[static shore]

It matters because $\int_{0}^{\infty}e^{-\lambda x},\mathrm{d}x$ does converge for positive values of $\lambda$

[flat frigate]

(DEN) / (J / I)

[cosmic grove]

I want the police of your latex

,w \int_{-\infty}^{\infty} e^{-\lambda x} dx

[deep apex]

instead of -inf +inf take -1 and +1 as bounds of the integral, then you can in fact write the equality

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by Ｈｅｒｅｌｓ#1420

[sharp cypress]

we had this at first

[static shore]

Yes

That seems about right

[sharp cypress]

we said it equals zero because when we graph it both parts cancel each other

[static shore]

Ok yeah I can see that

And then?

[sharp cypress]

then i had this

we solve it using integration by parts

then we get to

[static shore]

this is a different integral

[sharp cypress]

then we get to this so i wanted to use that trick again

[static shore]

Why did it change from x to x² back to x

[sharp cypress]

when we integrate it by parts

we find that

[static shore]

can you show me that process?

[static shore]

That's yet another integral

Let's pick one integral to solve first so that we don't get confused

[sharp cypress]

no its the same

its just multiplied by x^2

then changed the bounds to remove the absolute value

but i think i can change bounds

but not put the absolute value

thats why that trick wasn't used

[static shore]

Ok

[sharp cypress]

thank you

.close

[safe radish]

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[light crater]

I wanna show that g(x, y) is injective. I assume it is.

But I dont know how to proof it, as it returns a triple, so I dont know how to transform it

[junior smelt]

Looks like a linear map

[light crater]

huh?

[junior smelt]

What topic is this from, btw?

[light crater]

Analysis

/ special functions

[junior smelt]

Ah, never mind me then, I was gonna suggest a cheat 😂

I'd say solve that for $x_1 - x_2$ and $y_1 - y_2$ then tbh...

[flat frigate]

chartbit

[light crater]

But how to solve this for a triple

[junior smelt]

Just equate them and you have three equations to deal with

[safe radish]

@light crater Has your question been resolved?

[light crater]

Like this? @junior smelt maybe

[junior smelt]

Hmmm, don’t agree that your implications are right…

[light crater]

damn

[junior smelt]

Try this out, if you get me?

[light crater]

How?

[junior smelt]

Rewrite the first one as $x_1 - x_2 = y_1 - y_2$ and so on…

[flat frigate]

chartbit

[light crater]

That’s wrong right

[junior smelt]

That looks all fine to me

Try the same for (ii) and (iii)

[light crater]

yes

This @junior smelt

[junior smelt]

Looking good

Now the second one is the same as the first, yea?

[light crater]

Is it?

[junior smelt]

Multiply both sides by -1

[light crater]

in i?

[junior smelt]

Wait hold up a minute

[light crater]

for me ii and iii look the same

but i isnt the same I guess

[junior smelt]

Yea I was thinking about what I did 😂

It’s second and third that are

Cause I copied out and worked from yours, then had my steps in my head, I’m slow today 😂

[light crater]

dw :=

:)

[junior smelt]

Anyways second and third are the same, buttttt

[light crater]

(i) is not

[junior smelt]

I see what I was thinking before

Check this?

Think that RHS should be $y_1 - y_2$…

[flat frigate]

chartbit

[junior smelt]

Same here

$x_1 - x_2$

[flat frigate]

chartbit

[junior smelt]

Last one I have no objections to

[light crater]

But I dont know what I have done wrong

[light crater]

How to transform this to y1 - y2

[junior smelt]

…or you can leave it as $-y_2 + y_1$ if you want

[flat frigate]

chartbit

[light crater]

Okay

So I still have this. Can I work with that?

[junior smelt]

F for algebraic manipulation

[light crater]

huhh

So I did the mistake

[junior smelt]

Think so 🤔

Check my purple

[light crater]

Yes

[junior smelt]

Am I right, or am I being silly? (as that’s always a possibility!)

[light crater]

Hmm well I can also transform x1-x2 = y2-y1 to x2-x1 = y1-y2 by multiplying it by -1

[junior smelt]

That was something I wanted to hint at, but flopped at earlier

To make sure, are you saying the first and second are the same?

[light crater]

yes

[junior smelt]

Now let’s think about these

[light crater]

thinking

[junior smelt]

Looks like we have $y_1 - y_2 = -(x_2 - x_1)$ and also $y_1 - y_2 = x_2 - x_1$…

[flat frigate]

chartbit

[junior smelt]

Sheeeiittt I’ve turned Green

[light crater]

Congrats!!!

But why -(x2-x1)

I thought its -x2 + x1

[junior smelt]

Factor a (-1)

[light crater]

eh okay

[junior smelt]

You agree that I’m right?

[light crater]

but why is y1 -y2 still the same then?

[junior smelt]

…because I’ve kept them the same, because I want to say something

[light crater]

okay

[junior smelt]

Tell me what $y_1 - y_2$ is now then…

[flat frigate]

chartbit

[junior smelt]

Hint: what real number is equal to its negative?

[light crater]

0

[junior smelt]

Yep, keep that in mind for a second

[light crater]

ok

[junior smelt]

What’s $x_1 - x_2$?

[flat frigate]

chartbit

[light crater]

y2-y1

[junior smelt]

Yea, and that is…?

[junior smelt]

Hint

[light crater]

y1+y2?

sorry i have no idea D:

[junior smelt]

I mean, you literally said it a few seconds ago…

[junior smelt]

Guess you didn’t keep that in mind then, how could you betray me like this 😭

[light crater]

y1 - y2 is 0 we said

[junior smelt]

Yea, $x_1-x_2 = y_1 - y_2$, and $y_1 - y_2 = 0$, so $x_1 - x_2$ is…

[flat frigate]

chartbit

[light crater]

0

[junior smelt]

Good, therefore what can we conclude if both $x_1 - x_2$ and $y_1 - y_2$ are zero?

[flat frigate]

chartbit

[junior smelt]

Seeing we want injectivity, after all…

[light crater]

x1 = x2

and y1 = y2?

[junior smelt]

[light crater]

Yes

Wow thx, now I have to write that shit down somehow

[junior smelt]

Please do, or at least screenshot the messages 😂

At this point, I’m gonna end up making live lectures tbh 😂

[light crater]

👏🏼

[junior smelt]

Still can’t believe I’ve turned green, damn it

[light crater]

Why is x1 - x2 = y1 - y2 here @junior smelt

[junior smelt]

Here @light crater

Top one

[light crater]

Sorry I dont get it

it says y1 - y2 = -(x2 + x1) = x2 - x1

@junior smelt

[junior smelt]

Meant the top line of the pic I did

[light crater]

Sorry what?

[light crater]

Yes

[junior smelt]

And you should know that -a+b=b-a for any variables…

(Too lazy to typeset LaTeX on mobile)

[light crater]

isnt it -a+b = a -b?

[junior smelt]

Noooooooo

Fine, -a+b=b+(-a)

[light crater]

So like this

[light crater]

yes

but in (iii) we have y1-y2 = x2-x1

isnt that a contradiction?

[junior smelt]

I see what you’re thinking, but we basically used that to figure out that those differences were 0

If you have a=-a, then a=0

[light crater]

ahhh okay

[junior smelt]

https://tenor.com/view/big-shaq-mans-not-hot-math-gif-10285836

[junior smelt]

So you get what we’ve done then?

[light crater]

Uhm yes. Thanks so much :)

[safe radish]

@light crater Has your question been resolved?

[safe radish]

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[north ocean]

Okay this is a simple problem, and I've seen the answer but I don't know how it got to it, so it's a/b = 3, and b/c = 4 and it asks me to calculate a/c = ?
And I honestly don't know where to begin, do I do with the divided equals dividend times quotient plus remainder?

[robust finch]

just multiply both the equation

[north ocean]

So 3 times 4 which is 12 but why?

[robust finch]

$$a/b * b/c$$

[flat frigate]

notsogood

[north ocean]

so it's ab/bc

[robust finch]

it will cancel b

actually yes

[north ocean]

yeah

Alright, I sorta understood how it got to it but how do you figure out that you need to multiply? Just math intuition?

In the same example there is a problem that states a/b = 3 and a/c = 6, b/c = ?
Do I divide a/b to a/c?

.close

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[stoic pilot]

https://media.discordapp.net/attachments/656282361851412501/1051986149121462352/image.png

[stoic pilot]

How would you solve this using integrals?

Maybe assuming the radius is like 9 or something instead but just generally how would you go about it

[safe radish]

@stoic pilot Has your question been resolved?

[fickle axle]

I would integrate a quarter of it then x4

Or, without integral, we can find area of 1/6 of the circle.
Take the area of the equilateral triangle with radius as its length side, we can get the area of that little chip (minor segment).
Then add together the area of how many chips and triangles in the overlap, we get its area.

[safe radish]

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[little token]

hi how solve this exercise

[stray socket]

Factor out 5x

[little token]

thx

[stray socket]

Lucifer pfp

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[dapper bear]

Would someone be able to help me setup this related rates problem

[spring wasp]

draw out your box

[safe radish]

@dapper bear Has your question been resolved?

[dapper bear]

I see

Thank you

appreciate the help

[safe radish]

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[lean otter]

Change the following into spherical coordinates

Limits are in dz dy dx order

For z: 2-sqrt(4-x^2 -y^2) to 2+sqrt(4-x^2 -y^2)

For y: - sqrt (4-x^2) to sqrt(4-x^2)

And for x: -2 to 2

Can someone please tell me how to figure out range of phi

[snow robin]

Phi in your case is on the xy plane?

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

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[obtuse harbor]

Help me how do I solve this

[lean otter]

You need to isolate x

I'll give you an example where we can isolate x

Suppose you have 3 +( x/ 4) = 4

We can subtract 3 from both sides of the equation
3-3 + (x/4) = 4-3
0 + x/4 = 1
x/4 =1

Now there is a four in the denominator of x
To get rid of 4 we can multiply 4 on both sides of the equation

So we get

4 times x/4 = 4 times 1
x=4

Now try using similar logic on ur qs

[safe radish]

@obtuse harbor Has your question been resolved?

[safe radish]

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[untold totem]

im trying to understand how they did the last part

[untold totem]

of this integral

in the symmetry one how did the 2 carry to the outside?

and somehow still say on the inside?

[high dome]

if u doubt it, u can just do it without doing that step

its because the integral from -3 to 3 is -3 to 0 and 0 to 3

-3 to 0 is the same as -(0 to -3) whcih is the same as (0 to 3) so theyre just both 0 to 3

[untold totem]

ohhh

[untold totem]

could you explain this why is it just to put -(0 to -3) ?

[high dome]

ur flipping the bounds

so from a to b

if u go from b to a

then its negative

(a to b) = -(b to a)

if ur confident in doing the integration without steps like this i would just recommend skipping

because theres no difference if u just solve for the antiderivative and plug in values

[untold totem]

im confused as well in

[untold totem]

their final answer

using 3 how do they get that answer

[high dome]

hm maybe i can draw it

hard to typoe

[untold totem]

sorry thank u

[high dome]

i rlly hope this is right and im not feeding u wrong info

[safe radish]

@untold totem Has your question been resolved?

[safe radish]

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[balmy marlin]

How do I do this. Ignore the info

[unique bison]

Did you write the blue text?

[balmy marlin]

No

Prof did, but i wasnt able to follow

because im used to tangent lines being the derivative and plugging in the value to get slope

<@&286206848099549185>

[pure agate]

What are you having difficulty with?

[balmy marlin]

solving the question

is there like a formula for finding thr equaion of the tangent line

[pure agate]

You would use the Point-Slope formula to find a tangent line at any given point on a function's graph.

[balmy marlin]

is that what he used in the bottom equation

[pure agate]

Yes.

Allow me to elaborate on what your professor did. It should become clear.

[balmy marlin]

why didnt he first find the values of y1 and m

then use point slope

by plugging in x as 0

[pure agate]

Because you are trying to find those points. The cart cannot come before the horse.

Allow me to explain what your professor did. It will become apparent.

[balmy marlin]

okay

i feel like i dont know the true meaning of point slope form

rather than just plugging in values

[pure agate]

A point is represented by the pair (x,y).

[balmy marlin]

ok

[pure agate]

When we restrict those points to a function, the y value is determined by the function f(x).

(x,y) = (x, f(x))

[balmy marlin]

ok

[pure agate]

What do you need to determine the slope of a line?

[balmy marlin]

derivative

or y2-y1/x2-x1

[pure agate]

The second part.

[balmy marlin]

okay

[pure agate]

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

[balmy marlin]

thats two points tho

[flat frigate]

Kookiemon

[balmy marlin]

okay

[pure agate]

Well, you want the tangent line to go through the origin which you can make one of your points.

[balmy marlin]

hold up

u right

keep going

[pure agate]

So we can remove (x1, y1) because they are (0,0).

$m = \frac{y_{2}}{x_{2}}$

[flat frigate]

Kookiemon

[balmy marlin]

yea yea

[pure agate]

So what is (x2, y2)? They are points on the function.

[balmy marlin]

yea yea

[pure agate]

What does x2 equal? Just x.

[balmy marlin]

yea yea

[pure agate]

What does y2 equal? It's the function equation.

[balmy marlin]

yea

[pure agate]

$m = \frac{x^{2} - 8x + 16}{x}$

[flat frigate]

Kookiemon

[pure agate]

What does m equal?

[balmy marlin]

2x-8

[pure agate]

And you have all you need to solve for x.

[balmy marlin]

this part is insane

[pure agate]

🙂

[balmy marlin]

so 2x-8 equal to the equation u showed above?

[pure agate]

Yes

[balmy marlin]

then u find the value of x

[pure agate]

$2x - 8 = \frac{x^{2} - 8x +16}{x}$

[flat frigate]

Kookiemon

[balmy marlin]

and find y

and use point slope form?

and the slope ofc

[pure agate]

Oh, yeah.

[balmy marlin]

yea same thing no?

[pure agate]

So you can use those points and the slope to find the tangent line.

[balmy marlin]

cool

very good explanation tysm

[pure agate]

yw

[balmy marlin]

u a tutor or smthn?

[pure agate]

Tutor. I do this to brush up on my math and find gaps I need to fill.

[balmy marlin]

ah. finished college?

[pure agate]

It also helps to increase my understanding of math by learning how to explain it to others.

Yes.

[balmy marlin]

i see. well i wont be taking up ur time anymore. ty man take care

[pure agate]

yw, enjoy your evening. 👍

[safe radish]

@balmy marlin Has your question been resolved?

[safe radish]

Channel closed

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[safe radish]

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[humble surge]

How do I solve this?

[humble surge]

I only have 2 equations so far

[humble surge]

so

I find the max of this eq?

[turbid raven]

it's a pretty hard question now that I look at it,

my first reaction was to give you the kite equation bcs you were doing something else

but, lol, it looks like another one of those optimization nightmares

[river wharf]

to find the biggest area

you need to use derivative

when first derivative x=0 that determines the maximum of the area

[humble surge]

ye so I find the derivative of this?

[river wharf]

sorry when first derivative is 0 find the x its y is zero at

[toxic stratus]

seems kinda

excessive

[river wharf]

that has to have another simplified form

[river wharf]

that's what i can recall when we did these types of problems

[toxic stratus]

looks like am-gm

[humble surge]

wdym

[toxic stratus]

dw about it lol

anyway

[turbid raven]

for all I know if a=d1*d2/2 doesn't matter how you cut it lol

[river wharf]

OHHHH

[humble surge]

oh yeah no ik how to do like normal optimization problems lol i just don’t know where to go with this one after those first 2 eqs

[toxic stratus]

yeah well

[river wharf]

yeah but the only way to get biggest value would still be first derivative tight

[toxic stratus]

the rest is simple

[river wharf]

right*

unless you wanna brute force it lmao

[humble surge]

hmm

[humble surge]

ye but for thsi problem what would the answer be?

[toxic stratus]

i mean

[humble surge]

like after that super big eq

[toxic stratus]

this is literally the solution

x = 5, y = 5

[river wharf]

you don't use that equation

[toxic stratus]

so cut it right in the middle

quadratic optimisation is like the simplest you can do

no derivatives needed at all

y'all forgetting about completing the square

[river wharf]

i mean derivative method is still cool ;'(

[toxic stratus]

but not elementary

[river wharf]

i did that in highschool i think

but true

wait so you just completed square but that's still guessing

on the "massage" part

[toxic stratus]

theres no guessing in completing the square

its guaranteed to work

[river wharf]

i gotta try that

i remember having problems with getting best area with a limited circumference

and we only did the derivative thing

@humble surge did you follow?

[humble surge]

yeah I did, thanks

[river wharf]

I'll repeat that

so basically the problem says

[humble surge]

I just didn’t wanna close the channel while u guys were talking lol

[river wharf]

we have 10 meters or whatever measurements of material

to use to build a kite

which is the diagonals of the shape

which means

D1+D2 can't exceed 10

x+y=10 is first equation

now problem states that you need to get the most of Area with 10 meters of diagonals

area of kite is xy/2

to have a 1 term expression

you use x+y=10

and get y=10-x

put it inside the other expression

and you get the equation 1/2x*(10-x)

now are you in highschool or elementary?

if you have taken derivative class

[humble surge]

hs

I’m a junior

and ye we learned derivatives

[river wharf]

you will most likely be asked to solve it using the derivative method if not, snow showed the square method

okay with derivatives

5-(x/2)^2

has a derivative

you will find at which point the equation has it's max value

and it is when y prime=0

[humble surge]

bet, thanks!

/close

[river wharf]

lmao

aight gn

[humble surge]

How do u close it

[river wharf]

idk

[stiff inlet]

.close

[humble surge]

ok thanks gn

.close

[safe radish]

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[blazing scarab]

How can I solve a question like this?

[untold sky]

u-sub

[light shoal]

nice gratuitious $-\sqrt{4 - x^2}$ they threw in there 😀

[flat frigate]

Bungo

[safe radish]

@blazing scarab Has your question been resolved?

[safe radish]

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[surreal spade]

I got 4/root3

But the correct answer is -4/root 3

Where did the negative come from

[final bay]

$\frac{1}{x}\neq \frac{1}{sqrt{x^2}}$

shit

[lean otter]

It is going to minus infinity

[final bay]

$\frac{1}{x}\neq \frac{1}{\sqrt{x^2}}$

[flat frigate]

ed

[final bay]

doesn't this answer his question better

[surreal spade]

then how do you do it

if 1/x doesn't = 1/root x^2

[final bay]

you see

it does when x is positive

[surreal spade]

so like

for positive infinity

[lean otter]

Well just trying to make him deduce it himself

[surreal spade]

then how do you solve it

[final bay]

$\frac{1}{x}= \frac{1}{\sqrt{x^2}}$for $x<0$

oops

[surreal spade]

when its going to negative infinity

[final bay]

there should be a minus

$\frac{1}{x}= \frac{-1}{\sqrt{x^2}}$for $x<0$

there we go

[flat frigate]

ed

[final bay]

@surreal spade

[surreal spade]

ohh

thanks

[final bay]

do you know what an alternate expression for $\sqrt{x^2}$ is?

[flat frigate]

ed

[surreal spade]

idk

plus or minus x?

[lean otter]

$\abs{x}$

[flat frigate]

♡LexQa♡

[final bay]

^

[surreal spade]

ok

[final bay]

in the second line there should be a negative somewhere

from the first line to the second you assumed 1/x=1/sqrt{x^2}

but since x is negative its negative that

does that make sense?

[safe radish]

@surreal spade Has your question been resolved?

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[cobalt saddle]

im having trouble telling exactly what a "sample space" is

[cobalt saddle]

for example, I'd imagine the sample space for flipping a coin is (H, T)

[final bay]

thats corerct

[cobalt saddle]

but if it's flipping the same coin 3 times in a row...

would it not still just be (H,T)?

[final bay]

no it wont

[cobalt saddle]

since you can only list a possible outcome once

[final bay]

how can you flip 3 coins and get one head?

[cobalt saddle]

HHH

[final bay]

yes but is HHH in the set (H, T)?

[cobalt saddle]

no

[final bay]

exactly

[cobalt saddle]

but you can still only flip a head at a time

[final bay]

yes but thats not what a sample space is

a sample space is the set of possible outcomes

[cobalt saddle]

what am i talking about then?

[final bay]

you mean what is (H, T) in the context of flipping a coin n times?

[cobalt saddle]

yeah

[final bay]

im not sure theres a word for that

its most related to binomial probability

when you repeat an event with 2 outcomes n times

[cobalt saddle]

hmm, how is an "outcome" different than sample space then?

[final bay]

from the sounds of it you dont need to know this

sample space is a set of outcomes but not all outcomes are in a sample space???

idk

its just wording

for flipping a coin 3 times the sample space is (HHH, HHT, HTH, HTT, THH, THT, TTH, TTT)

[cobalt saddle]

oh, is it that sample space doesnt have repeats, but outcomes can?

.close

[safe radish]

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[turbid raven]

what grade is this. also, are you posting all questions from this paper here in separate channels until we solve the whole thing for you

[lean otter]

The graph tells you that x can't be__ than x = -6 and that x can't be __ than x = 0

Fill in the gaps

[obtuse harbor]

bro nah

i just tryna un derstand bruh

stop roasting m,e

[lean otter]

Can you try answering my question, jack?

[obtuse harbor]

yes sir

lesser and lager

[lean otter]

Correct

So your x can't be larger than 0 and it can't be smaller than - 6

[obtuse harbor]

yeah

so that would be

[lean otter]

Yes. Now can you represent that mathematically using the two symbols of
[ \geq, \leq ]

[flat frigate]

♡LexQa♡

[obtuse harbor]

yews yes

is x is lesser tan or equl to 0 and larger than or euql to -6

[sharp tiger]

Yea, now write it in 1 expression

Something like <=x<=

[lean otter]

Correct!

[obtuse harbor]

so wait what is a comound inequality looking like

[lean otter]

You just have to write a compound inequality of the form
[ c \leq x \leq b ]

[flat frigate]

♡LexQa♡

[obtuse harbor]

i see yes thank you lexqa for the time and undertsnaidng and help man thank you

[lean otter]

Yeah but what did u get?

[obtuse harbor]

Ok so this is correct right this hwat i get

[lean otter]

Yep! You got it!

Great work

[obtuse harbor]

thank you

[safe radish]

@obtuse harbor Has your question been resolved?

[safe radish]

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[candid ocean]

Question b)

how is that the answer

oh

nvm

common factor

byebye

.close

[safe radish]

Channel closed

Closed by @candid ocean

Use .reopen if this was a mistake.

[candid ocean]

bruh

.reopen

[safe radish]

✅

[candid ocean]

how do u do this

b)

:P

[final bay]

using quadratic formula?

[candid ocean]

yep

first do u write the common factor?

[final bay]

show me what you have done so far

[candid ocean]

ok well first i took 3 from all of them

do u do that when they ask for quadratic formula??

like factor it first

or do i use quadratic formula right away..

[final bay]

if there aren't any common factors then you use it right away

[candid ocean]

ok so theres a common factor of 3 here

[final bay]

does 3 divide 8?

[candid ocean]

oops

HEP

HELPP

HWLLO

BRO

ITS 3 AM OK IM SORRY

[final bay]

its fine

[candid ocean]

ok theres no common factors

but my equation still didnt work before that

one sec

@final bay i get

x = 8 square root 172 / 18

oh

ya

how does that work

they got 4, i got 8, they got 43, i got 172, and they divide by 9, i divide by 18

u,mm can someone help ;-;

[deep depot]

,w 9x²-8x-3=0

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[deep depot]

Yeah your answer is correct

[candid ocean]

uh???

how

my answer is wrong

[candid ocean]

how do i get this answer

[deep depot]

Oh sorry it's the textual answer

Well

[candid ocean]

i got this

[deep depot]

$\frac{8\pm\sqrt{8²-4×9×(-3)}}{18}$

Wait

[candid ocean]

-(-8) +- /(-8)^2 - 4(9)(-3)

/ 2 (9)

[flat frigate]

Arnab Pal

[deep depot]

Yeah

Solve this

Show me your process

,w 8^2-4×9×(-3)

[flat frigate]

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Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[deep depot]

Oh I see

Your √172 was right

But you forgot to simplify

,w √172

[flat frigate]

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Requested by 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛#6985

[candid ocean]

uh

[deep depot]

43×4=172

[candid ocean]

wdym by simplify

[deep depot]

√172=√(43×4) roght

Right*

[candid ocean]

do i have to simplify....

i wrote

8√172

18

--- is the division line

[deep depot]

No not required

[candid ocean]

kk

[deep depot]

Your answer is also correct

[candid ocean]

hm weird

so do i just leave it like that?

[deep depot]

What's your answer?

[candid ocean]

8+-√172

[deep depot]

(8±√172)/18

[candid ocean]

yep

but cant i continue?

why did they stop

if you can find the 2 x intercepts...

[deep depot]

How you got 8√172/18?

[candid ocean]

ill send a pic

[deep depot]

Ok

[deep depot]

$\frac{4}{9}\pm\frac{\sqrt{172}}{8}$

[flat frigate]

Arnab Pal

[candid ocean]

hm?

[deep depot]

,w 4/9 - √172/8

,w 4/9 + √172/8

[candid ocean]

this is how the teacher tells us to do it

[deep depot]

Well yeah but how you took out the x intercept?

[candid ocean]

soo idk

wdym

i did it after

x = 8 +√172/18

and second x intercept is

[deep depot]

And why you don't have to take out the x intercept your question dosen't require one

[candid ocean]

oh.

ummmmm

ok

[deep depot]

Yes your question has asked you to solve the equation

[candid ocean]

but is this still right??

[deep depot]

(8±√172)/18 is right

[candid ocean]

yes

ok good

[deep depot]

Not 8√172/18

[candid ocean]

yeahh yeah ikik lol

thx

thanks for proving me right

[deep depot]

Welcome

[candid ocean]

.close

[safe radish]

Channel closed

Closed by @candid ocean

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[safe radish]

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[humble raptor]

can someone explain?

[humble raptor]

how can this?

to this?

[knotty sigil]

do u know integration by parts ?

take int e^xsinx = I

so now

[lean otter]

help

[knotty sigil]

#❓how-to-get-help

[humble raptor]

is that = 1?

[knotty sigil]

I = -e^xcosx +e^xsinx - I

2I = -e^xcosx+e^xsinx

I = ( -e^xcosx+e^xsinx)/2

[knotty sigil]

I bro I (I for ice cream)

[humble raptor]

ok i understand

[humble raptor]

but where this one go?

[humble raptor]

bro go to #help-22

[junior smelt]

That's the same thing you had at the beginning, $I$

[flat frigate]

chartbit

[junior smelt]

Remember that $I = \int e^{x} \sin(x) dx$

[flat frigate]

chartbit

[humble raptor]

ooo thank u bro

[knotty sigil]

alr

wlc

[humble raptor]

.close

[safe radish]

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[solemn kestrel]

is this right?

[knotty sigil]

no

think again

[solemn kestrel]

im thinking 180 clocwise or 270 counter

[knotty sigil]

like

move it with ur hands and see

what direction are ur hands turning

[solemn kestrel]

ohhh

[knotty sigil]

now think n tell ans

[solemn kestrel]

90 counter clockwise

[knotty sigil]

nice !!

good job

@solemn kestrel

[solemn kestrel]

yay

thanks you

.close

[safe radish]

Channel closed

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[knotty sigil]

alr cool wlc @solemn kestrel

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[clear blade]

what does a 180 degree rotation do to an arbitrary point (x,y)?

[safe radish]

@solemn kestrel Has your question been resolved?

[solemn kestrel]

.close

[safe radish]

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[solemn kestrel]

is the answer (2, 2), B′(−3, −3), C′(−2, 5) ?

[safe radish]

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[lean otter]

decimal expansion means base-10

[safe radish]

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[buoyant oar]

anyone help me with this?

[buoyant oar]

i tried doing 23.6(1/2)e^22.7/12 but i don't get any of the answers

[sand minnow]

you need to find the derivative of the function first

$N(t)=N_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}$ then take the derivative wrt to $t$

[flat frigate]

Duh Hello

[sand minnow]

to make that easier to do you could use the other 3rd formula here and use that $\lambda=\frac{\ln 2}{t_{1/2}}$

[flat frigate]

Duh Hello

[buoyant oar]

Im a bit confused about the formula tho

[sand minnow]

which formula?

[buoyant oar]

to me it kind of looks like theres a subscript in the thirrd formula and the first one

like t/t1/2

[sand minnow]

$t_{1/2}=$half life

[flat frigate]

Duh Hello

[buoyant oar]

and ln2 / t/1/2

ohhh okay

Im not getting it

I tried using the third one

I got B @sand minnow is that right?

[sand minnow]

havent done the problem but at least you got a negative answer which it will be, can check just gimme a moment

ye B is correct

[buoyant oar]

alright thank you

.close

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[onyx mountain]

i dont know how to do rate of change

[onyx mountain]

how would i set that up

[obtuse plover]

Interval is [a, b]

Go from there

[onyx mountain]

so x=-3-4/-3-4

[obtuse plover]

No

Interval is [a,b]

What’s f(b)

Or for ur problem

[onyx mountain]

-5x?

[obtuse plover]

g(b)

[onyx mountain]

-5x?

[obtuse plover]

How’d u get that

[lean otter]

a=-3 b=4

[onyx mountain]

so a(x)=f(4)-f(-3)

[obtuse plover]

Yea that’s the numerator

What about the denominator

[onyx mountain]

4--3

[obtuse plover]

Yea

[onyx mountain]

then what do we do

[obtuse plover]

Solve it?

What’s g(4)

Given our function g(x)

[onyx mountain]

x^2

[obtuse plover]

Wat

Ok

If I gave u the problem: f(x) = x + 2. Whats f(2) ?

[onyx mountain]

-2?

[obtuse plover]

How did u get that

[onyx mountain]

finding

inverse

[obtuse plover]

When it asks for f(2), u have to replace every x with a 2

[lapis shadow]

rate of change means something like finding by how much ur function's value changes when u change the input by a certain amt

[obtuse plover]

Then Solve

So knowing that, what would f(2) be

[lapis shadow]

do u know that speed is the rate of change of distance?

[onyx mountain]

ohh

[lapis shadow]

idk im trying to give u like an example if u dont know what rate of change is asking for

[onyx mountain]

i got it now

thanks

.close

[safe radish]

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant sphinx]

Finding the area underneath

[velvet nebula]

between the functions?

[buoyant sphinx]

yea but I think I found my mistake lol

Hold on lemme try it

like it was an algebraic mistake finding the intercepts

Yea no. I got -1 and 2 as my intercepts and I don't think it's right

Do I not combine them to get x^2+x-2?

Like in the end

.close

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zealous ore]

Help with i ii and iii

[safe radish]

Please don't occupy multiple help channels.

@zealous ore Has your question been resolved?

[safe radish]

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[mint crown]

hallo

[mint crown]

.close

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[iron glacier]

How would I solve lim x->inf 12x^3(1/x - sin(1/x))?

[iron glacier]

(1/x -sin(1/x))/(1/x^3)

[split ether]

Have you tried squeeze theorem?

[iron glacier]

nope

[split ether]

Oh nvm that doesn't seem to help