help-23

[static vale]

If p(h) is head and p(t) is tail

Their union

Is the total sample space

So kinda p(h)+p(t)=1

[austere turret]

oh I get it now

thanks for help

[static vale]

Also exhaustive means atleast one of the events will occur

Like in a coin

Ya will atleast get a head or a tail

[austere turret]

basically exhaustive means 1?

[static vale]

It can't be like ya tossed a coin

[austere turret]

like 100%

[static vale]

And it gave u nothing

💀

[static vale]

Kinda

[austere turret]

that coin landed on it's side 💀

[static vale]

Lol

Exceptional cases

If two events and mutually exclusive and exhaustive, then the sum of probability of events occurring will be 1

[austere turret]

sum of probability of events occurring will be 1 because it's exhaustive, right?

[static vale]

Yee

[austere turret]

okay got it thanks

.close

[safe radish]

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[noble sail]

why?

[quasi bison]

can you write this with less incomprehensible handwriting

[wild basin]

whats that

writing

[safe radish]

@noble sail Has your question been resolved?

[noble sail]

if a and m are coprime then m-a and m are coprime

[quasi bison]

gcd(a, m) = gcd(m-a, m) for any a and m

[noble sail]

y

[quasi bison]

any common divisor of a and m is also a common divisor of m-a and m and vice versa

[noble sail]

yeah i am asking why

bezout?

[quasi bison]

you can prove it directly from the defn of divisibility

[noble sail]

thanks

.close

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[lean otter]

The context doesn't really matter for this equation but how would i go about solving -1 [ (2- 𝜆)(0) -20 ]

[lean otter]

would the (2 - 𝜆) (0) just cancel eachother out and make the whole thing = to 20 ?

[quasi bison]

wdym by "solving"?

do you mean simplifying?

[lean otter]

Yeah my apologies, Basically just simplifying

[quasi bison]

(2 - λ) * 0 = 0, yes. "cancelling out" is not an apt description for that.

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[sour gull]

Hello, I am unsure of my answer here. can I please have someone to help me clarify this question?

[sour gull]

My answer is 0.85N

I have used this formula

[mint lake]

seems correct

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[jaunty elbow]

,tex At a wedding there are 30 guests and 3 tables of 10 people. By how much
ways we can split them into 3 groups of 10 so that Jos is not sitting with Janne at the table and Luc is not sitting at the table with Louise. (The order of the groups
doesn't matter, the place at the table doesn't either)

[flat frigate]

Magnus

[velvet nebula]

hmm, principle of inclusion and exclusion?

[jaunty elbow]

how

how would i even implement that

<@&286206848099549185>

i cant find on the internet any reproduction of such a problem either

the professor can suck my dick

making it hard for no reason

[quasi bison]

what ways are there to seat the 4 named people?

it feels to me like there's either one table with a J person, one with an L person, and one with both a J and an L, or there are two tables each with a J and an L and one table with neither

[safe radish]

@jaunty elbow Has your question been resolved?

[jaunty elbow]

,tex $\binom{26}{9} \cdot 1 \cdot \binom{16}{9} \cdot 1 \cdot \binom{6}{6} \cdot 1$ is the one with one table with J, one with L and one with J and L?

[flat frigate]

Magnus

[jaunty elbow]

I just dont know

[jaunty elbow]

I can visualize it but i dont know how to implement it

[jaunty elbow]

Since the first one we can choose 9 of 26 and then times one because its a J and then 16 out of 9 times one and that one is an L and then choose 6 out of 6 i dont know just because its 16-10 i guess

And times one is J and L at that one table

[wheat cave]

if you're still stuck you could try a smaller sample size like 9 total people

[safe radish]

@jaunty elbow Has your question been resolved?

[safe radish]

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[jagged finch]

How do j fully simplify this?

Into

This form?

[junior smelt]

Are you sure?

[jagged finch]

Oh is that not how you simplify?

Like i had to differentiate and simplify

How do i do it?

[knotty sigil]

follow chain rule

[junior smelt]

I meant, are you sure that what you wrote is the differential? (Hint: you have a function of a function)

[jagged finch]

Hmmm

Im not too sure 😭

[junior smelt]

The answer is no. (Why?)

(Hint 2: me and @knotty sigil have said why)

[jagged finch]

Because the function isnt x?

And you have to use chain rule?

[knotty sigil]

yass

[jagged finch]

OHHH

I SEE

THANKYOU SMM

leme try it one second

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[lost palm]

How do i do this?

[lost palm]

the hint was to use conservation of energy

[wild basin]

hi

[lost palm]

Before the system evolves there is only GPE

after there is GPE and KE

but how do i used this?

[wild basin]

we have holy names

hmm

[lost palm]

I also am confused on how to evaluaate the GPE of a mass hanging on both sides of the peg

[wild basin]

lemme see

peg mean?

[lost palm]

like

so the chain is hanging over this

with half of it on one side and half on the other

[lost palm]

like in here

[wheat cave]

you have any glue with what force the heavier side is pulled down?

[lost palm]

nope

[wheat cave]

mhm well

[lost palm]

unless you know the mass of the chain

[wheat cave]

is the answer expected to have a variable inside it?

[lost palm]

no

[wheat cave]

since the chain is not evenly distributed during the process, a heavier chain will increase the speed I recon

[wild basin]

i can solve this

but lemme eat first

i am eating srry

[lost palm]

lol np

ill wait

[wild basin]

did you tried

using other methods

like

NLM

[lost palm]

Yh

but coudlnt find any method

honestly without the hint of using energy

i wouldnt even know how to start

[wild basin]

WELL

you can do this using simple concepts of physics

well

lemme

give you some thinking

modify the diagram

[lost palm]

?

uh

alr lemme c i guess

[wild basin]

take

two blocks

of masses

[wheat cave]

I think the dude is trolling

[wild basin]

at end of chain of masses m and 3m

[wheat cave]

I can find an answer in with a variable

I can even make a function v(t)

but it all depends on some constant M=mass of the chain

[wild basin]

okk you find it

i am leavig

[lost palm]

did u use energy?

[wild basin]

this chatrooom

[lost palm]

brruuh

[wheat cave]

I used gravitational force

and force is acceleration

[lost palm]

i didnt say anything

[lost palm]

can i see your working?

[wheat cave]

I sure can give you hints

[lost palm]

alr

[wheat cave]

did you do derivatives in school already?

[lost palm]

no

[wheat cave]

mhm

[lost palm]

only know the power rule so far

[wheat cave]

then maybe not

[lost palm]

do you know how to find the GPE of this ?

I think i can do it

[wheat cave]

at the start its easy, but the problem is that acceleration isn't linear

[lost palm]

like find the total energy in terms of M (mass of chain) and equal it to the total energy in terms of the Ke of the the whole chain and the GPE of mass m and then id guess that M cancels out and i can solve for v

[lost palm]

yh

[lost palm]

But i dont know how to think of the GPE in the first case

and last case

[wheat cave]

M doesn't cancel out is the problem

[lost palm]

its supposed to

[wheat cave]

if the velocity was constant, it would be 1/4M

uh

[lost palm]

It should do if you work with energy according to the hint of the question=

the hint is here

https://www.youtube.com/watch?v=vpZCWcEy8sw&t=38s&ab_channel=IsaacPhysics

[wheat cave]

well, at the start its 2m*9.18 m/s^2
at the end its (2m+M)*9.18 m/s^2

[lost palm]

idk

maybe there is a mistake in you working or logic?

[wheat cave]

where would that be

of the chain is equal on both sides, only 2m pulls

if the chain is at the end, M and 2m pulls

[wild basin]

well can i say something?

[wheat cave]

go ahead

[wild basin]

if you have to find the GPE

you have to define the reference line

[wheat cave]

please do that

[wild basin]

so if you will take the

reference

line

in this part

as you know the PE in the reference line is to be taken as zero

[lost palm]

3m will fall below the line

[wild basin]

yes

[wheat cave]

shush

I wanna know

this is some high level stuff

[wild basin]

if an object falls below the gravitational acceleration to be take n as +ve

[wild basin]

no this is simple if you know potential energy very well

[wheat cave]

don't let yourself be stopped, write some formula that will help

[wild basin]

if an object falls below the gravitational acceleration to be take n as +ve

[wheat cave]

go on

[lost palm]

huh?

[wheat cave]

dont interrupt

they are talking

[wild basin]

so

as you know the gravitational potential energy is mgh

@wheat cave ru on?

are you guys online

[wheat cave]

yes

please

[wild basin]

?

[wheat cave]

continue

I have yet to see something that would help

[wild basin]

ok

[wild basin]

see this

so green box

is saying

that we need

here

[wheat cave]

https://cdn.discordapp.com/attachments/903481106819612714/1051526949257871360/image.png
so this task, please tell us the velocity

[wild basin]

we need to convert GPE into KE

mgh

= 1/2mv^2

mgh2-mgh1=1/2mv^2

use this

put the values

here

mg2a-mga=1/2mv^2

mga =1/2mv^2

the answer is

12.52

m/sec^2

[wheat cave]

hey

where did the mass of the Chain go?

[wild basin]

well thats

the thing

mass

velocity

[wheat cave]

literally what we were talking about...

[wild basin]

dont depend upon mass

[wheat cave]

you only considered the 3.14

yes it does

[wild basin]

no but not in the conservative forces

are present

[lost palm]

@wheat cave what speed do you get when the mass of the chain is 1 kg

the mass of the whole chain

@wheat cave Are you there

?

[wheat cave]

yes second

[lost palm]

oh ok

[wheat cave]

i have no calculator so its annoying to do

[lost palm]

alr np

[wheat cave]

I must've made a mistake

i get 641 m/s

thats not... likely

[lost palm]

wow

lol

yh

i did the energy way and got

oh hold on i turned of my calcualtor

gimme a second

5.41 m/s

but thats for mass of chain of 1kg

the question sais its wrong

but i think you are right and it does depend on the mass of the chain =

i asked an AI and it said it doesnt depend on the mass of the chain but the height of the peg?

it said "
To solve this problem, we need to apply the conservation of energy. The initial potential energy of the system is equal to the sum of the potential energies of the two masses. The potential energy of each mass is equal to the product of its mass, the acceleration due to gravity, and its height above the peg. Since the length of the chain on each side of the peg is equal, the initial potential energy of the system is equal to the product of the total mass of the system, the acceleration due to gravity, and the height of the peg.

At the bottom, the potential energy of the system is zero, since the two masses have reached the same height as the peg. Therefore, the kinetic energy of the system at the bottom must be equal to the initial potential energy of the system. The kinetic energy of the system is equal to the sum of the kinetic energies of the two masses, which is equal to the product of the total mass of the system, the square of the speed of the system, and one half.

We can now set up the following equation to solve for the speed of the system at the bottom:

(m + 3m) * g * h = (m + 3m) * v^2 / 2

where g is the acceleration due to gravity and h is the height of the peg.

Solving for v, we get:

v = sqrt(2 * g * h)

Since the length of the chain on each side of the peg is equal, the speeds of the two masses at the bottom must be equal. Therefore, the speed of the mass m at the bottom is also equal to sqrt(2 * g * h).

To find the value of this speed, we need to know the value of the acceleration due to gravity and the height of the peg. The acceleration due to gravity on Earth is approximately 9.8 meters per second squared. Since the problem does not specify the height of the peg, we cannot determine the exact speed of the mass m. However, we can say that it is equal to the square root of two times the acceleration due to gravity times the height of the peg."

but its obviously wrong

[wheat cave]

it doesnt seem to take in the mass of the chain at all?

[lost palm]

yh

but it has to be wrong

[wheat cave]

v = sqrt(2 * g * h) bruh

[lost palm]

it implied that if the system was 2 meters above the ground it would have a different outcome then if it were 3 meters up of the ground

[wild basin]

@ duckholy

i said everything was right

according to your AI

the mass gets cancelled out

so the velocity is depend only on g and h

[wild basin]

i said that here

if you put m-3m in the place of m

its even cancelled out

so the velocity would be

v=sqrt(2ga)

[lost palm]

the ai is wrong

[wild basin]

why

no he is right

[lost palm]

it sais that the system behave differently depending on the altitude of the system relative to some reference point

and aslo

[wild basin]

cuz the system wa released if any system released from any hight

it should independent of mass

[lost palm]

i typed your anser into the website and it said wrong aswell

[wild basin]

wait

lemme

explain

[lost palm]

gimme your answer to like 5 decimal places

[wild basin]

do u know the famous galileo

[lost palm]

yh

[wild basin]

experiment

[lost palm]

the mass drop experiment

[wild basin]

of feathers and mass

[lost palm]

?

yh

[wild basin]

yes

that represent the same situation here

[lost palm]

it doesnt

[wild basin]

it is

[lost palm]

how

[wild basin]

cuz the system is released

or dropped

[lost palm]

the system is not dropped

[wild basin]

so initial velocity of the system is zero

[lost palm]

what

[wild basin]

so by using

[lost palm]

are you high?

[wild basin]

what

?

dude

the initial velocity is zero and the final velocity is v=sqrt(2gh)

put all the values here

you will get your answer

@lost palm can you send me the website where you checking my solution?

[lost palm]

https://isaacphysics.org/questions/chain_on_peg_num?board=6553211f-d11a-4a67-b99f-e843898d2c7d&stage=all

[safe radish]

@lost palm Has your question been resolved?

[safe radish]

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[umbral solar]

Partial derivative of y(x)=3x^2 is 6x?

[next echo]

uhhh

yes?

not sure what the question here is

[umbral solar]

hmm

you know partial derivative?

did i translate not good?

the inverse 6

[stark idol]

partial derivative and derivative are the same in this case

cuz only 1 variable

[umbral solar]

oh

I thought i need to apply derivative

the question is if x goes up 1 % how much the function goes up aproximately

i need to use elasticity?

[regal girder]

isn't this just y(x + 1) - y(x) then?

[next echo]

what

[umbral solar]

that's elasticity right?

[regal girder]

what

[umbral solar]

i fail?

[junior smelt]

Don't you try substituting 1.01x instead of x and compare that to the original?

[umbral solar]

hmmm

[safe radish]

@umbral solar Has your question been resolved?

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[safe radish]

Please don't occupy multiple help channels.

[primal oak]

pls help 😔😔 anyone

[wild basin]

hmm

alyssa

r u

[winged cloak]

ok

[wild basin]

crying??

what is U

i mean which sequence

[winged cloak]

question A) U2 = u(1+1) = 4U1 -15

[wild basin]

is it talking about

[winged cloak]

and U2 = U1 so U1 = 4U1 - 15

solve for U1

b) U3 = U(2+1)= 4U2 - 5 (you have U2 = U1)

c) prove that Un = 5 for any n>=1 by proving that U(n+1) = 5

@primal oak

[primal oak]

hi

[primal oak]

yes

[winged cloak]

hi, i gave you what to do

[primal oak]

tysm 😍

[winged cloak]

:)

[primal oak]

.close

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[queen tendon]

Need help answering this question

[wild basin]

simple

f=ma

112=26.6*a

a=4.21

a=v2-v1/t

4.21=813-577/t

find t

[queen tendon]

Damn aight appreciate

How woudl you find t

[wild basin]

dude

you now

[regal girder]

cross multiply

[wild basin]

calc

doggo:).

[queen tendon]

Cross multiply?

I missed 4 lectures

[wild basin]

solve this

[queen tendon]

So I'm quite behind sorry

OK I've minused it

[regal girder]

A/B = C/D you can cross multiply to get BC = AD

[wild basin]

236/4.21 is the answer

[queen tendon]

Appreciate it homie

.close

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[loud mirage]

Could someone help me make sense of this problem and solution

[loud mirage]

Why does the Uw(v,w) - kUvv(v,w) = 0

from the bottom line

[safe radish]

@loud mirage Has your question been resolved?

[floral willow]

because she intergrated it

then used the limit as v approached w to partially differentiate it

[safe radish]

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[hearty egret]

because the last term is the heat equation

[hearty egret]

.close

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[sour robin]

imaginary numbers shit

how am i meant to simplify the first one under a)

[quasi bison]

do you know generally how to divide complex numbers?

[sour robin]

not really no i slept through that class 😭

[wise frost]

Imaginary numbers are numbers that have a square root of a negative number. To simplify an expression involving imaginary numbers, you can use the properties of complex numbers. For example, the first expression under a) is (1+i)(1-i). To simplify this expression, you can use the distributive property to expand the expression and then use the property of complex numbers that states that i^2 = -1. Thus, the expression simplifies to (1+i)(1-i) = 1 - i^2 = 1 + 1 = 2.

[sour robin]

hold on let me log on pc

[quasi bison]

i was going to suggest that you multiply the top and bottom by the conjugate of the bottom.

[wise frost]

No problem! Take your time.

Yes, multiplying the top and bottom by the conjugate of the bottom is a great way to simplify an expression involving imaginary numbers. The conjugate of a complex number is the complex number with the same real part and the opposite imaginary part. For example, the conjugate of 1+i is 1-i. So, if you multiply the top and bottom of an expression by the conjugate of the bottom, it will simplify the expression.

[sour robin]

i still have no idea what to do here 😭

[wise frost]

If you are still having difficulty simplifying the expression, you can consult a math textbook or look for tutorials online. Additionally, you can try breaking down the expression into smaller parts and then simplifying each part. This can often make an expression easier to understand and simplify.

[regal girder]

(a + b)(a - b) = a^2 - b^2
this is basically what is being used here. By multiplying by the conjugate you get rid of the imaginary part in the denominator.

[sour robin]

i am having difficulty understanding what part of -15+5i/1-2i i need to conjugate or simplify

[wise frost]

Yes, that is correct! When you multiply the top and bottom of an expression by the conjugate of the bottom, it simplifies the expression by getting rid of the imaginary part in the denominator.

[regal girder]

think of it like rationalizing the denominator

[quasi bison]

does

multiply the top and bottom by the conjugate of the bottom.
make sense to you?

[sour robin]

not at all

[quasi bison]

which part is escaping you?

[wise frost]

Yes, you can think of it like rationalizing the denominator. Multiplying the top and bottom of an expression by the conjugate of the bottom is similar to rationalizing the denominator in that it simplifies the expression by getting rid of the imaginary part in the denominator.

[quasi bison]

i.e. which part do you not understand?

[sour robin]

the word conjugate

english isnt my first language

[quasi bison]

what is your first language?

[sour robin]

macedonian

[quasi bison]

okay, nevermind

[wise frost]

The word conjugate refers to the complex number with the same real part and the opposite imaginary part. For example, the conjugate of 1+i is 1-i.

[quasi bison]

^

the conjugate of a + bi is a - bi

[wise frost]

Yes, that is correct! The conjugate of a + bi is a - bi.

[sour robin]

so it would be -15-5i/1+2i?

[wise frost]

Yes, that is correct! The expression -15-5i/1+2i is the simplified version of the expression (1+2i)(-15-5i)/(1+2i)(1-2i).

[violet thorn]

-5 - 5i

[quasi bison]

...??

[sour robin]

from then on where

[quasi bison]

what

no

[violet thorn]

express i as sqrt(-1) and rationalize

[quasi bison]

it isn't

you just conjugated the whole thing

[sand minnow]

think they are using some bot or something to type the messages

[sour robin]

voice to text

[quasi bison]

also ffs use some parentheses with fractions

[wise frost]

To simplify the expression -5 - 5i/1 + 2i, you can use the property of complex numbers that states that i^2 = -1. Thus, the expression simplifies to -5 - 5i/1 + 2i = -5 - 5(-1)/1 + 2(-1) = 5 + 5/ -1 - 2 = 5 - 5/-3 = 15/-3 = -5.

[violet thorn]

yea they are instant

[sour robin]

are you using chat ai

[wise frost]

Yes, they are instantiating the rule that i^2 = -1 to simplify the expression -5 - 5i/1 + 2i.

[quasi bison]

...

[sour robin]

lmao

[quasi bison]

@wise frost are you a bot?

[violet thorn]

do you know how to rationalize

[sour robin]

i dont

@wise frost 01100001 01110010 01100101 00100000 01111001 01101111 01110101 00100000 01100001 00100000 01100010 01101111 01110100 00100000 01100010 01110010 01101111 00001010

[quasi bison]

okay, let's cut the tomfoolery

[sour robin]

fr im actually confused

[quasi bison]

yeah, no wonder. churnos is almost definitely an AI.

[sour robin]

i thought it was voice to text at first

[quasi bison]

let's go back to the beginning, ok?

[sour robin]

yes sure

[quasi bison]

$\frac{-15+5i}{1-2i}$

this is your fraction

[flat frigate]

Ann

[sour robin]

the original problem

yes

[quasi bison]

which, by the way, is properly written as (-15+5i)/(1-2i) in plaintext.

just to get that out of the way.

[sour robin]

okay go on

[quasi bison]

now, as i suggested earlier, the standard technique for these is to multiply the top and bottom by the conjugate of the bottom

in this case, your denominator is 1-2i and so you will want to multiply the top and bottom of your fraction by 1+2i

thereby getting $\frac{(-15+5i)(1+2i)}{(1-2i)(1+2i)}$

[flat frigate]

Ann

[quasi bison]

do you follow thus far?

[sour robin]

yes i think im getting it

[quasi bison]

can you continue from here?

or should we keep going together

[sour robin]

so if we multiply it by the denominator we get I^2 right which would just be 1or (-1) right

[quasi bison]

i^2 is not "1 or -1". i^2 is -1.

also it's lowercase i

[sour robin]

yes sorry my bad

[quasi bison]

simplify the numerator and denominator separately.

if you do it correctly you'll get a real number in the denominator

[sour robin]

can we cut out the 1 from (1+2i) completely?

[quasi bison]

no, we cannot.

[sour robin]

okay i wrote that down but im not sure where to go from there

please dont get frustrated im trying 😭

[violet thorn]

expand

[quasi bison]

simplify the numerator and denominator separately.

let's start w/ the denominator because there is more nice simplification that'll happen there

are you able to simplify (1-2i)(1+2i)?

do it slowly and carefully.

[sour robin]

2i^2?

[quasi bison]

no

[sour robin]

i dont know what im doing

[quasi bison]

...

okay

let's backtrack

do you know the distributive law?

[sour robin]

the what law

hold on lemme google this

okay i got it

[quasi bison]

,w distributive law

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[quasi bison]

this

WA gives the overly-general answer but ok

you googled it anyway

[sour robin]

...now?

[quasi bison]

if the letter i was just a variable, would you be able to expand (1-2i)(1+2i)?

[sour robin]

ohhh fuck i studied these last year i just remember

yeah

lemme write it down and ill send

so would it be 2*2i?

or am i being stupid again

[quasi bison]

you are being stupid again.

[sour robin]

im sorry

[quasi bison]

write it down, do it slowly and carefully, and send the result here...

[sour robin]

1^2-i^2

[quasi bison]

what part of "write it down" and "do it slowly and carefully" do you not understand

[sour robin]

OKAY OKAY SEC

wrong pic

@quasi bison like this?

[quasi bison]

yes

[sour robin]

okay so now what 😭

[quasi bison]

well what is (2i)^2?

[sour robin]

4

since i^2 is 1

so it would be 1+4?

[quasi bison]

no, (2i)^2 is -4, not 4. but your expression becomes 1 - (-4), which is equal to 1 + 4.

so you've committed an even number of mistakes

[sour robin]

im so stupid im smart

[quasi bison]

yes, 1^2 - (2i)^2 is 5.

[quasi bison]

does not work this way.

[sour robin]

its just a joke

i got the right answer somehow by being an imbecile

so now uh

i got this

[quasi bison]

bad!

(-15+5i)(1+2i) ≠ -15 - 5i - (1+2i).

[sour robin]

its not a -

its a dot

we use dots for multiplication

my bad i guess

[quasi bison]

it's ok to use a dot for multiplication. it's not okay to make it look like a minus sign and it's also not okay to rip off the parentheses like you did

[sour robin]

my bad 😭

now where do i go though

from (-15+5i)(1+2i)/5

[safe radish]

@sour robin Has your question been resolved?

[sour robin]

i guess so

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[thin narwhal]

what

[pliant pendant]

Do you know how to multiply fractions?

[crude geode]

Nvm

.close

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[quiet cypress]

what

[safe radish]

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[high wharf]

anyone understand this

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[whole gale]

how do I find c

I know it has sometime to do with calc in ti-84

[drowsy moss]

the MATH button and one of the options should be "zero"

then it asks you for lower and upper bounds, so choose points on either side of the 0

[whole gale]

any points?

what points should I do

[drowsy moss]

any point on either side of the 0

[hardy lion]

Lower bounds is to the left of the desired zero, upper is to the right

[drowsy moss]

you're given then interval [1,2]
so 1 and 2 should be good choices

[hardy lion]

Yes

[whole gale]

ok I got it thanks

[hardy lion]

You can do it closer if you want to

[whole gale]

.close

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[random rivet]

how is the equation of axis -2

and not 2

im confused

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[wise hemlock]

I did 27k=20k*x^4 and solved it. But thats Not the right answer

[safe radish]

@wise hemlock Has your question been resolved?

[thin bridge]

x wouldn't represent the interest rate in your equation, you'd need more work

[wise hemlock]

I really dont know how. Can you give me any more tips?

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[sand condor]

Solve
x+y +2z=9
x+2y+z=6
2+3y+3z=7

[worthy hemlock]

What level math are you in?

[sand condor]

Wym?

[worthy hemlock]

Like is the linear algebra?

[sand condor]

Yes

[worthy hemlock]

Do you know how to apply gaussian elimination?

[sand condor]

I learned it awhile ago

But i forgot about it tbh

Well actually maybe not

[worthy hemlock]

If that question is linear algebra related, I suggest using gaussian elimination

[sand condor]

So basically
1 1 2 9
1 2 1 6
2 3 3 7

But i forgot the next part

[worthy hemlock]

If you don't recall gaussian elimination, I suggest reviewing it

[sand condor]

Ah ok want me to go?

[worthy hemlock]

You can review it, try it out with your problem then post your work

You can close the channel, and open a new one

[sand condor]

Ok thanks

.close

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[void tangle]

@random pulsar do u think u could help I have final tmr?

[frank glen]

Hmm

Do you know how to integrate?

[random pulsar]

no

I am busy

[void tangle]

Np

@frank glen I think

Would I solve the standard way without looking at graph, just take derivative, plug in b and a, then subtract?

Let me test and see if that would give the area

[frank glen]

Okay

But I am now confused: why do you need to take the derivative in the integral?

It's just a polynomial

$$\int x^n , dx = \frac{x^{n+1}}{n+1} + c$$

[flat frigate]

VulcanOne

[frank glen]

n here can be any number

Even constants can work that way.

Because n = 0 for them

Except if you have 0 as the constant

[void tangle]

Yeah you use reverse power rule

I’m dumb and made it more complicated on myself

They were just teaching us to plug-in area formulas when it’s a circle or half circle

[frank glen]

Ayo pls don't say that. You're not like that. You just need practice.

[frank glen]

Hmm

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[signal glade]

Can someone help me verify this, I feel like i did something wrong

[frank glen]

Ok so there is a Leibniz method to find the derivative of the integral

[signal glade]

whats that??

[nova creek]

$\frac{d}{dx} \int^{g(x)}_{h(x)} f(t) dt = f(g(x)) * g'(x) - f(h(x)) * h'(x)$

[flat frigate]

Gamer Dio

[signal glade]

i think what i did is almost the same its just that i put the g(x) in front?

but did i do it correctly tho? including the evaluating part?

[safe radish]

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[mint bluff]

Hey everyone, this is a practice test. Not sure about this one here

[mint bluff]

Is it just simply 1,2,3?

[frank glen]

Damn been a long time since I looked at eigen values

[mint bluff]

fair

[dire spoke]

exactly right

Personally, easiest to think about it in terms of the characteristic polynomial, and the minimal polynomial

[mint bluff]

No idea what that means but

epic

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[mint bluff]

thanks

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[floral hornet]

I really do not understand this problem at all y=e^x+y

[floral hornet]

basically i did chain rule on e^x+y

and got (1+dy/dx)(e^x+y)

[plucky elk]

Did you mistype this

[floral hornet]

no

okay then i did (e^x) and (e^y)

[plucky elk]

Can you take a picture of the original problem or screenshot

[floral hornet]

cant im on my pc

[frank glen]

$$\frac{d}{dx} e^{x+y}$$

[final bay]

can you type out the problem without mistakes

[flat frigate]

VulcanOne

[frank glen]

Is that itv

[plucky elk]

Oh that makes more sense

[floral hornet]

y=e^x+y

find dy/dx

idk what u mean by mistakes thats the problem lmao

[frank glen]

@floral hornet

[plucky elk]

This is interpreted as
$y = e^x + y$

[unique bison]

Use parentheses

[flat frigate]

riemann

[unique bison]

Damn finally texit works

[frank glen]

Always did lmao

It just dies randomly

[floral hornet]

no the problem is e^x+y lmao

[frank glen]

https://cdn.discordapp.com/attachments/903481106819612714/1051699725339992176/1000057838007226480.png

[unique bison]

It's this?

[floral hornet]

dy/dx

[final bay]

WIHCH ONE IS IT...

[frank glen]

Is this the problem?

[plucky elk]

@floral hornet not this?

[floral hornet]

its find dy/dx given e^x+y

[frank glen]

[plucky elk]

Stop typing it and answer

[unique bison]

Lol

[frank glen]

Are the pictures not loading?

[floral hornet]

its dy/dx

[plucky elk]

Open paint and write it out with your mouse

[unique bison]

Say which picture it is

[floral hornet]

instead of d/dx its dy/dx

thats what im saying

[frank glen]

Okay that's fine

[plucky elk]

We get that

[frank glen]

Ok so

[plucky elk]

Write out the whole equation

[floral hornet]

gurl

[final bay]

ok

@floral hornet

[frank glen]

Separate e^x and e^y since they are added on exponents

[plucky elk]

If you'd learn to use parentheses or answer us, we wouldn't be confused

[floral hornet]

yeah thats what i did

[unique bison]

$y = e^{x + y}$?

[final bay]

$the question is: Find \frac{dy}{dx}, given y=e^{x+y}$

[flat frigate]

ed

[final bay]

i threw

[flat frigate]

giannis_money

[final bay]

the question is: Find $\frac{dy}{dx}$, given $y=e^{x+y}$

[flat frigate]

ed

[frank glen]

You then use product rule

[floral hornet]

its literally this one except its dy/dx

[final bay]

@floral hornet is it what i just wrote

[frank glen]

Oki

[unique bison]

That wouldn't make sense

[floral hornet]

yes

[final bay]

OK OK

[plucky elk]

Yea but you typed this

[final bay]

use product rule

$y=e^x\cdot e^y$

[flat frigate]

ed

[final bay]

agree right?

[floral hornet]

gurl im just trying to get my question answered pls leave me alone

[floral hornet]

yes i did that

[unique bison]

Lmao she called you a girl

[frank glen]

You then use product rule

[unique bison]

Jk

[plucky elk]

Yea and like I said, we're trying to help but you kept ignoring everyone

[floral hornet]

would chain rule not work

[frank glen]

You will use it in the middle of the product rule

[floral hornet]

can you explain that in more detail

[final bay]

ok $\frac{dy}{dx}= e^x\cdot e^y +e^xe^y \frac{dy}{dx}$

[flat frigate]

ed

[frank glen]

$$u' \cdot v + v' \cdot u$$

[flat frigate]

VulcanOne

[frank glen]

so

Our u = e^x

And our v = e^y

[final bay]

bro who's helping this person

me or you

because like

[frank glen]

Both lol

[final bay]

lel

sure

[frank glen]

Whoever gets looked at

Anyways

Since e^x 's derivative is e^x, we write it like normal

If we apply chain rule to it, we will get 1

[floral hornet]

yep

[frank glen]

We then multiply it by e^y

That's the first half done

[floral hornet]

okay

[frank glen]

Now moving on to e^y

Derivative = e^y

Multiplied by derivative of y

dy/dx

[floral hornet]

okay

[frank glen]

Multiply it together

With e^x

All in all, we get

https://cdn.discordapp.com/attachments/903481106819612714/1051701450650173490/310599340961955840.png

[final bay]

lol what i wrote 🙂

that shuld all make sense

[frank glen]

Yeah thank you for the help

[floral hornet]

wait i thought u said with chain rule e^x is 1

[frank glen]

Yep

[floral hornet]

so where'd the one go

[frank glen]

1 multiplied by x equals x

[floral hornet]

ohh ok

[frank glen]

e^x • 1 = e^x

Alrighty?

[floral hornet]

yea

[frank glen]

Anything you still don't understand?

[final bay]

theres still more

$\frac{dy}{dx}(1-e^xe^y)=e^xe^y$

[flat frigate]

ed

[frank glen]

Huh what?

[floral hornet]

im confused from where the first e^x and e^y come from

like in the first half

[final bay]

the question asks you to find dy/dx

so you have to rearrange

ayeesni

[frank glen]

Hmm

[final bay]

for product rule

we differentiated e^x to get e^x then multeplied by e^y

thats where the first bit camefrom

[frank glen]

Ok you know the formula for product rule?

[floral hornet]

yes

[frank glen]

It's u' • v + v' • u

Right?

[floral hornet]

yep

[frank glen]

Ok

And originally it was u • v

Right?

[floral hornet]

yeah

[frank glen]

Ok simple

Let e^x = u

And e^y = v

[floral hornet]

ok

[frank glen]

And apply the derivative of each separately

And use the formula for product rule

[floral hornet]

ohh ok

got it

[frank glen]

Send us the answer you got

When you finish it

[floral hornet]

k

[frank glen]

Because we wanna make sure

:)

[floral hornet]

alright

[frank glen]

Also please when you ask questions, don't be rude because then no one will answer you. No one likes a person with bas attitude yknow.

[floral hornet]

when did I have a bad attitude lol

[frank glen]

This

Lol

[floral hornet]

huh I wasn't ignoring anyone I gave you guys the question

[frank glen]

Well

Repeating the same thing won't get anything anywhere you know

[floral hornet]

Wym I just said I couldn't take a picture cause I was on my pc😭

[frank glen]

riemann said you could open paint and write it with your mouse

[floral hornet]

I dont have that on pc

i had to delete it cause of storage

[frank glen]

Hmm

Well there are websites too

You can draw on them

[floral hornet]

I mean no offense but it wasn't that hard to understand

[frank glen]

Sometimes it is

Syntax matters

$$e^x+y$$

[flat frigate]

VulcanOne

[frank glen]

$$e^{x+y}$$

[flat frigate]

VulcanOne

[frank glen]

Simple inclusion of parentheses could have saved time

[floral hornet]

on my paper its not written with parenthesis

and I was confused about the whole equation in the first place

[frank glen]

Of course

But when typing it on text, you will need to include parentheses because text doesn't work like math notation

[dire spoke]

https://www.codecogs.com/latex/eqneditor.php

very simple latex is very very easy to learn and makes a massive difference!

This discord is amazing for help so being able to just write

[floral hornet]

I'm literally telling u I was confused about the whole problem

[dire spoke]

$a^{b+c}$

[flat frigate]

todadqa

[floral hornet]

so how would I have known to put parenthesis

[frank glen]

We know that and we were trying to help out

[plucky elk]

It isn't, you just didn't know how to communicate the difference.

[frank glen]

But to help out, we needed to find out what was the problem exactly

[floral hornet]

idk I asked a question about the same problem and they understood

[plucky elk]

And saying that is a pretty bad attitude contrary to what you think

Because they guessed your mistake

[final bay]

^

[plucky elk]

That's like saying other people in your class understands how to find dy/dx but not you

[final bay]

yes we guessed your mistake @floral hornet

[floral hornet]

bruh I didn't know if I was supposed to put parenthesis cause I'm not that good at math thats literally why I'm literally in this server cause I'm not the best at math💀

[plucky elk]

Yea and we get that. But when we ask questions to clarify what you mean, don't be rude and say "it's not that hard to understand"

[floral hornet]

Ok no offense but yall were saying I had a bad attitude even though I was just asking a question of course I'd be a little ticked off

[plucky elk]

Lol ok I'm done

[floral hornet]

yeah cause u were being rude bro

[dire spoke]

Okay at this point, there are too many people here just trying to get you to understand that you were a bit rude

Just take the note and try to be more careful next time

[frank glen]

Well when you discussing something with someone, do you like that person being rude or do you like that person being calm and collected?

[plucky elk]

When you think everyone else in the room is being a jerk to you, you're probably the problem

[frank glen]

Yes exactly

[floral hornet]

yeah but ur all friends so ofc ur sticking up for each other lmao😭

[frank glen]

Nope I don't know anyone here lmao

[dire spoke]

i get it might feel like that but we have no idea who eachother are haha

[frank glen]

We are just pointing out the obvious

Point is, please don't take it for granted that everyone will understand you

[plucky elk]

No one is out to get you. People are trying to tell you that you had an attitude problem and you refuse to accept the possibility of it so you invent things like "you guys are friends" even though you have no evidence of that

[frank glen]

We just want you to be better

That's all

I'd favor someone who'd make me and make others cry for me than someone who'd make me laugh and make others laugh on me.

Everyone would

You should listen to people who tell you that there is a problem

Hopefully you learned something

[floral hornet]

Y'all were literally bombarding me with questions and giving me an attitude in the beginning so idk what u expected

[dire spoke]

woah i can get that this is a bit much with all these ppl telling u stuff now but wtf what you said there is too much. You wanted help, people helped you. they didn't need to. i can't believe you are complaning

[plucky elk]

Nobody gave you attitude in the beginning. All the questions were clarifying questions because you didn't know you were making a notification mistake. It's clear you won't change your bad attitude and you're paranoid that people are out to get you. Nobody is.

[floral hornet]

and im not saying im ungrateful for that

[plucky elk]

.close

[safe radish]

Channel closed

Closed by @plucky elk

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[foggy ore]

if the formula is 1/2(a x b) + 3/2(b x s), which are the a, b, etc which numbers go where basically? i’m not too sure which one is a or b

[safe radish]

@foggy ore Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty topaz]

is my proof correct?

[safe radish]

@dusty topaz Has your question been resolved?

[dusty topaz]

<@&286206848099549185>

<@&286206848099549185> ??

[plucky elk]

.close

[safe radish]

Channel closed

Closed by @plucky elk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim mesa]

hello

[dusk iron]

Yea

[slim mesa]

is there such clacualtor out there that knows how to find range of a graph

[dusk iron]

[0, inf)

[slim mesa]

i could promise its not to cheat

well technically it is

but

[dusk iron]

U don't need a calculator

[slim mesa]

wdym

how do u know its 0,inf

[dusk iron]

All u need is to think of the graph as mosquitoes

[slim mesa]

how do u know which one it is

[dusk iron]

And beat them with this huge huge sandal/slipper

On to the y axis wall

The blood of the mosquitoes give the range

[slim mesa]

that made it more confusing lmao

the blood could spat everywhere though

wouldnt it

[dusk iron]

No the y axis attracts haemoglobin

[slim mesa]

i dont know what haemaglobin is

[dusk iron]

And also the slipper

Basically compress or push the graph onto the y axis

Like every point

[dusk iron]

Stufff in bllood

[slim mesa]

could u call?

[dusk iron]

Ehh?

[slim mesa]

could u just explain without the musquito stuff

[dusk iron]

Ook

[dusk iron]

C

Tats 0,inf

[slim mesa]

if i continuisly send u questions where from this website, could u give me answers?

[dusk iron]

Maybe

[dusk iron]

D

@slim mesa

[dusk iron]

Go on

[slim mesa]

I FUCKING