help-23

[opaque pasture]

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[unkempt aspen]

13(a)

i got this so far

how do i find x???

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[wooden palm]

help with this not sure how to do it no clue

[obtuse plover]

Which one

[wooden palm]

A the first one

[obtuse plover]

Find the antiderivative of each term individually

Or u can break up the integral if u so desire

[tidal imp]

u’ll need substitution too

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[wooden palm]

oh ok

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[sudden sparrow]

can someone help me with this?

[wispy sentinel]

$\frac{a^{3}}{\left2(3ab\right)^{2}}=\frac{a^{3}}{18a^{2}b^{2}}=\frac{a}{18b^{2}}$

[flat frigate]

ayushch80
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[sudden sparrow]

thats how you solve it?

[wispy sentinel]

y

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@sudden sparrow Has your question been resolved?

[sudden sparrow]

what

how you solve it

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@sudden sparrow Has your question been resolved?

[stark idol]

do you know the laws of exponents?

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[vagrant marlin]

Calculate z^n + z^(-n), knowing that z + 1/z = -2cos(x), where z is a complex number

[vagrant marlin]

Could someone help me out with this?

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[vagrant marlin]

<@&286206848099549185>

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[solid pawn]

Determine the rate of change of volume of a cube with respect to its diagonal if its
edge is 8 cm.

[pseudo scroll]

You've not been given the rate of change of any other element?

[solid pawn]

none

[pseudo scroll]

$\frac{dV}{dt} = \frac{dr^3}{dt} = 3r^2\frac{dr}{dt}$

[flat frigate]

NEONPerseus

[pseudo scroll]

wrt to the diagonal?

:/

$D = \sqrt{3}r$

[flat frigate]

NEONPerseus

[solid pawn]

yes '

[pseudo scroll]

$\frac{dV}{dt} = \frac{1}{3\sqrt{3}}\frac{dD}{dt}$

[flat frigate]

NEONPerseus

[pseudo scroll]

Honestly idk what the question is even asking for 🗿 You need the rate of change of SOMETHING

[solid pawn]

rate of change of the volume with respect to diagonal given with 8cm edge

[pseudo scroll]

😭

[toxic stratus]

you need to have at least the rate of change of the edge to calculate anything

the edge itself being 8cm tells you nothing about its rate of change

could be expanding at 42069 cm/s for all i know

[solid pawn]

its too high

[pseudo scroll]

:/

Point is

Insufficient data

[solid pawn]

Thanks for the help

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[lean otter]

i can’t

[lean otter]

solve this integral

I expanded and solved

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[lean otter]

Hello can you help out with this question

[lean otter]

2^4times3^8=9^n times6^4.

the question is needed to be solved without digital tools

[wheat cave]

$2^4\times 3^8=9^n \times 6^4$

[flat frigate]

Jigglyproff

[wheat cave]

how far did you get

[lean otter]

3^8 can be represented as 9^4

[wheat cave]

sure, but wouldn't you want to reduce the numerals, not increase them?

aka, make 9^n to 3^something

[lean otter]

The question has been solved for me by a teacher. Thanks for helping out anyways.

uh

what

your teacher gave it, why would they solve it

like immediatly

sure i guses

do .close ifyou're done

.close

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[lean otter]

i need help with this one integral

it's involved with the volume of revolution on the y axis

[wheat cave]

go to empty help channel then

[lean otter]

he just closed

[wheat cave]

its not ready yet

its reopen period

in case it was mistkae

[lean otter]

mhh

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[lean otter]

i got to 0

seems wrong but any ideas?

4 * 5 * -1 - 2 * 3 * 2

7?

[lean otter]

did it say anything else

or

nope

[lean otter]

-32

df * g - dg * f

ty ❤️ will try

how would i do it

in maple?

or any calculator?

Trying to do it in maple, but not sure if i did it right

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[lean otter]

.reopen

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✅

[quiet cypress]

take the derivative

use the quotient rule

[lean otter]

-2?

correct?

[quiet cypress]

no idea

is that how you got that

[lean otter]

this one right?

is that the one u talking about

[quiet cypress]

like I said, did you take the derivative ?

[lean otter]

yea but not sure if i did it correctly

[quiet cypress]

show it then

[lean otter]

• 2/(x-1)^2

[lean otter]

Seems okay I think

,w derivative of (x+1)/(x-1)

[quiet cypress]

yea

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ♡LexQa♡#5050

[quiet cypress]

its -2

[lean otter]

Appreciates it, i just got one more question

I got this question

I wanted to put it in maple

But unaware how to do it

[quiet cypress]

I have no idea how to use maple. sorry

[lean otter]

do u know how to solve it without maple?

[winged cloak]

derivative of f/g where f and g are given functions is

(f'g - g'f)/g²

[quiet cypress]

yeah, you're already given the functions, now use the quotient rule

which is (f'g - g'f)/g²

[lean otter]

so

(5*-1 - 3*2) / -1^2

right?

[winged cloak]

Oh be careful

-x² and (-x)² arent the same thing

The minus enters the square too

[lean otter]

confused, how would it look like then

and thanks for helping ❤️

[winged cloak]

(-1)² in the denominator

[lean otter]

oh

[winged cloak]

Which gives you 1

Otherwise -1² = -1

Because you're doing 1²

[lean otter]

so

does it give 11?

[winged cloak]

Then you negate it

-11

[lean otter]

oh yes my bad

@winged cloak

i got this one too -32

that would be my last question

Could you confirm that it is -32?
Thanks in advance

[winged cloak]

Nope i found 14

How did you do it

[lean otter]

.

[lean otter]

.

[winged cloak]

No

The function is 4f - 2g

It's subtracting the functions not multiplying them

You simply do 4f' - 2g'

The other guy thought it was the multiplication rule

[lean otter]

how would it look like then?

just so i know how its getting solved in the future

Appreciated a lot btw ❤️ @winged cloak

[quiet cypress]

what other guy💀

[winged cloak]

4f'(3) - 2g'(3)

[winged cloak]

.

[lean otter]

Thank you very much!

.close

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[floral breach]

Hello

[floral breach]

@winged cloak

[winged cloak]

i don't use excel and i haven't studied stats in a hot minute

can't help you srry

[floral breach]

no way

[quiet cypress]

use excel? do you have excel

[verbal marten]

Hey this is inappropriate behavior

@floral breach You see someone who is writing before you, you should respect that

[quiet cypress]

what?

[floral breach]

@verbal marten Get out of here I was here first

[verbal marten]

Not jump from no where and write hello to reserve the channel

[floral breach]

@verbal marten you are in my chat now

@quiet cypress

sorry for the confusion

[floral breach]

this is buried question

[verbal marten]

You should be banned for that

[quiet cypress]

do you have excel?

[glacial island]

I don’t think you understand what’s going on

Anyone can give help here

[floral breach]

Yes

[quiet cypress]

okay, copy the table and put it on your excel sheet

[verbal marten]

Where are the moderates

[quiet cypress]

you can ping them, but I don't see anything wrong with this channel

[floral breach]

@verbal marten I didnt see you in the chat therefore I posted my question

[verbal marten]

I didn't say anything and I won't do because I am not such a person but I was writing my problem and @floral breach jumped from no where and wrote "hello" to reserve the channel for him, is this good thing to do?

[floral breach]

@verbal marten Please join the other Available math Help slots

[quiet cypress]

#❓how-to-get-help

[floral breach]

@quiet cypress

I pasted the chart

[verbal marten]

Excuse me I should tell you sorry for that

[floral breach]

No problem I appreciate your appology

[verbal marten]

OK, world is full in people who don't respect others so you aren't not new for me

[glacial island]

Oh I see what happened now. Simply ninja’d unintentionally

[floral breach]

Exactly

[floral breach]

are you able to assist me with my question

please

This is the problem

[wind agate]

Use excel

[glacial island]

Most graphing calculators have a function that can analyze data like this and give you mean, median, standard deviation, all that, although I can give you the standard deviation formula directly if you give me a second

[wind agate]

.

[floral breach]

Yes

@wind agate

[glacial island]

I didn’t read all the way through, you do need to use excel, and unfortunately I am not an excel wizard

[floral breach]

@wind agate are you good at excel

<@&286206848099549185>

@glacial island

[glacial island]

I’m not good with excel, sorry

[floral breach]

can you give the standard deviation formula directly

[glacial island]

I don’t know the language that draws the formulas in plaintext, but I’ll do my best to describe it

[floral breach]

ok

can you figure out this than

[glacial island]

It’s the square root of the sum of the square of the distance from each point to the mean, with the summation divided by the number of points

[glacial island]

The number labeled SD is the standard deviation if that’s what you’re looking for

[floral breach]

yes this is for another question

but can you see if the bar and whisker chart is ok

[glacial island]

I’m not sure what the question itself is asking, but why did you need to take the differences?

[floral breach]

this is the question

The table at the right shows the time spent waiting in line (in minutes) at a local supermarket

Perform a one-variable analysis of this data by finding the mean, median, mode, variance,
standard deviation, range, and first and third quartiles. You are welcome to use Excel to do so- if you do please include a screen shot of your Excel work showing all your work.

Determine if there are any outliers. Explain how you did this. (4 marks)

Lower Outlier Q1 - (1.5 x IQR)
Upper Outlier Q3 - (1.5 x IQR)

Create a modified box-plot for this data. You are welcome to use technology to do this; please include what program/app you used to produce your plot.

[glacial island]

So, the differences are not necessary, and you should use the unmodified min, q1, etc for the box plot. As for the outliers, all you need to do is check for points lower than q1 -1.5(iqr) and higher than q3 + 1.5(iqr)

[floral breach]

"all you need to do is check for points lower than q1 -1.5(iqr) and higher than q3 + 1.5(iqr)"

which in this case are

@glacial island are you still there

[glacial island]

Yes I am here

[floral breach]

Thanks alot for help me but Im still confused

[glacial island]

You already have the IQR, it is at the bottom of the list

[floral breach]

ok

[glacial island]

Multiply it by 1.5

[floral breach]

ok

[glacial island]

Subtract from q1

Are there any points lower than the result?

[floral breach]

1.125

yes

[glacial island]

What’s q1 from the list

[floral breach]

0.1,0.2,0.3, 0.3

are lower than the result

[glacial island]

Ah, I see what happened

It isn’t 1.5(iqr)-q1, it’s q1 - 1.5(iqr)

[floral breach]

Is my horizontal axis correct

[glacial island]

The vertical axis is definitely correct, I don’t think you need to label the horizontal axis though

[floral breach]

ok

@glacial island can we audio call

[glacial island]

I’m waiting for my lunch right now, sorry

[floral breach]

Ohh ok

[glacial island]

It’s loud in here lol

[floral breach]

I sent you a message on your private

on @glacial island

[glacial island]

Anything else you need help with?

[floral breach]

Yes

@glacial island this one as well

[glacial island]

Since the median is close to q1, what does that say about the distribution of data points?

[floral breach]

its the same

[glacial island]

Not exactly

Since the median is the middle of the data, and it’s much closer to q1 than q3, where is most of the data located?

[floral breach]

in the middle

[glacial island]

A similar distribution is actually the other store, where most of the data is packed together between the minimum and the median

Which is a much smaller gap than between the median and the max

[floral breach]

ok

[glacial island]

This is known as the data being skewed right, since there is a large tail in the direction of larger numbers

[floral breach]

this is for a correct

[glacial island]

When comparing two distributions, you want to give the approximate/exact values for the centers, whether or not they are skewed in either direction, and the range in both IQR and max-min

I can’t write that for you, learning how to word this stuff is very important

Statistics is a math based writing class, after all

[floral breach]

right

Can you please write it for me

[glacial island]

I cannot

[floral breach]

I will promise to utilize it for the better

[glacial island]

It’s a pretty simple task though, once you have the numbers all you need to do is to say ‘the median for distribution 1 is x and for distribution 2 is y, 1 is skewed left/right and 2 is skewed left/right’, etc

Being able to do that on the fly is always good, and it’s the same writing for any question like it

It is, without exaggeration, a copy paste with changing the variables to fit the context

[floral breach]

But are you able to help me write it for this question

So far I wrote most of the data is packed between the med and MIN

[glacial island]

I already did, I gave the general form for median and skew, apply it to range and put in the variables and relevant names

Instead of saying packed data, say skewed left or right

[floral breach]

can you please plug them in for me for just this one time

[glacial island]

The whole point is to help you figure it out so that you can do it on your own in the future

[floral breach]

please

[glacial island]

You have the numbers, you have the general form

You got this

[floral breach]

just tell me what to plug in for this question than

Compare and contrast the centres and the spreads of the data for these two grocery stores’ wait times. Be sure to refer to specific statistics.

[glacial island]

You already have numbers for store 1, and for store 2 the median appears to be 1.5, min appears to be 0.5, q1 appears to be 1, q3 appears to be 4.2, and max appears to be 6.6

That’s done by looking at the lines for the box plot

[floral breach]

ok so what does the question want

[glacial island]

The question wants you to compare the two using specific statistics, like the ones in excel and from the boxplot

[floral breach]

can you please show me how Im so confused

[glacial island]

It’s 3 sentences, the first compares the two medians, the second compares skew, and the third compares range and IQR

[floral breach]

okok

thanks

[glacial island]

No problem

[floral breach]

alright

for B

[glacial island]

The other two parts are based on the data for the stores

[floral breach]

Based on wait times alone, why might someone choose to shop at the first store?

[glacial island]

B and c are closely related

There are two reasons, median and max

Whichever has the lower median, state that as the reason for going to that store, and the same for max

[floral breach]

Store 2 has the lower Med

[glacial island]

Yes it does

[floral breach]

ok so the med means the wait time is lkess

less***

[glacial island]

You would say that the wait time is typically less than that of store 1 since the median is lower

But for store 1 the max wait time is almost guaranteed lower than the max wait time for store 2

[floral breach]

but the max is higher

[glacial island]

The max of store 1 is 4.8, and store 2 is 6.6

[floral breach]

right]

but store ones median is 1.7

[glacial island]

Correct

[floral breach]

therefore making store two having a median of 1.5

which is lower

[glacial island]

Yes

[floral breach]

ok

[glacial island]

B and C ask for reasons to go to each store based on wait time

[floral breach]

so which wait time is less 1.5 or 1.7

[glacial island]

1.5 is less, which is why you’d go to store 2

[floral breach]

ok

no the max for store two is higher than store 1

being 6.6

[glacial island]

And that’s a reason to go to store 1

That’s part b

A reason to go to store 2 is part c

[floral breach]

ok

[glacial island]

And that’s how you compare and interpret two distributions

[floral breach]

so If I write the wait Store 1 is typically less than that of store 2 since the median is lower
But for store 1 the max wait time is almost guaranteed lower than the max wait time for store 2

thats it

[glacial island]

Swap store 1 and store 2 for the first part and it’s gold

[floral breach]

ok

thanks

[glacial island]

No problem

[floral breach]

but you still have to explain part a

[glacial island]

You need to write three sentences that compare the medians, the skews, and the ranges and iqrs of each distribution. You’ve already done the interpretation of the comparison, so you just need to write the comparison now

[floral breach]

can you kindly show me

[glacial island]

So an example of a sentence that compares the medians would be: “Distribution 1 has a median of x, and distribution 2 has a median of y.”

In this case, distribution 1 and 2 would be replaced by the distribution of store 1 and 2

Alternatively, you could say store 1 has a median of x and store 2 has a median of y, which is much shorter

[floral breach]

Ok So Distribution 1 has a MED of 1.7, and distribution 2 has a Med of 1.5

[glacial island]

Correct

You can do the same thing for the ranges

[floral breach]

ok

[glacial island]

Just replace median with range

[floral breach]

does it only want the MED and Range

[glacial island]

And for detail’s sake, include the max and min for each

[floral breach]

okok

[glacial island]

It isn’t particularly useful now, but it’s good practice to also include the skew of each distribution

[floral breach]

whats the range for dist 2

[glacial island]

In this case it’s easy, since they’re both skewed in the same direction

6.6-0.5

[floral breach]

so6.1

[glacial island]

Yeah

Now that you know how to compare and interpret, you can use the exact same general formula for any question like this one

[floral breach]

Distribution 1 has a MED of 1.7, Distribution 2 Has a MED of 1.5
Distribution 1 has a Range of 4.7, Distribution 2 has A range of 6.1
Distrubtion 1 has a MIn of 0.1, distribution has a Min of 0.1
Distrubtion 1 has a Max of 4.8, Distrubtion 2 has a Max of 4.8

is this good

[glacial island]

Very good! If you want, you can replace distribution 1 and 2 with store 1 and 2

Just to fit the context

Otherwise that’s perfect

You can use that answer for any question like it, just change the variables to fit the context

[glacial island]

Perfect!

[floral breach]

alright for the last question

can I present it to you

[glacial island]

Go ahead

[glacial island]

Again, I’m not great with excel, but can you tell if there was any function that calculated it in the store 1 info for the first question?

[floral breach]

can you please try your best I know u can do help me

So what i did already Is

[glacial island]

Looks like if you enter the numbers into one row you can do =STDEV.S(1:5)

[floral breach]

I organized it ascending

12,12,15,16,20

[glacial island]

What I believe you need to do is enter that into one column and then in the square below the last data point you need to do =STDEV.S(1:5)

[floral breach]

@glacial island are you there

[glacial island]

I am here

I’m attempting to test if it works

[floral breach]

okok

[glacial island]

Looks like the function I found works

[floral breach]

perfect

is my work relevant

[glacial island]

Under the column with the raw data, just type =STDEV.S(1:5)

That will give the sample standard deviation

[floral breach]

which is the raw data

[glacial island]

12,12,15,16,20

However

[floral breach]

ok

[glacial island]

It may also be asking for the st dev for reading hours

[glacial island]

That would be the standard deviation for number of students

[floral breach]

is that correct

[glacial island]

I ran another distribution for minimum hours read per student

[floral breach]

are you using excel

[glacial island]

Yes I am

[floral breach]

can you show me ur excel page

[glacial island]

One sec, need to connect to the internet on my laptop

[floral breach]

okok

[glacial island]

I’m not entirely sure what it wants the distribution of, but reading it again makes me assume that it wants the standard deviation of the hours read

[floral breach]

yes

[glacial island]

So my current list is very long and this is only part of it

There's 12 2s, 15 3s, 20 4s, 16 5s, and 12 6s

[floral breach]

how did u come up with this list

[glacial island]

Since they’re grouped into small intervals based on how long they read, I put in the minimum value of each interval as many times as there were students in the interval

Fun fact, changing it to the maximum value of the interval does not change the standard deviation because the spacing does not change with addition

But that’s off topic for now

[floral breach]

so you got 1.3099

[glacial island]

I would go with 1.31 instead of 3.31

But if you are unsure, include both

[floral breach]

do I have make any sort of chart for this question

[glacial island]

Yeah, you’ll need to manually input the numbers for the new list

[floral breach]

what do you mean can you show me on your excel

[glacial island]

Other than that there’s nothing else to do

Just put the 12 2s, 15 3s, 20 4s, 16 5s, and 12 6s in one column and then recalculate the standard deviation with a new range

Just a reminder, the function is =STDEV.S(startnum:endnum)

[floral breach]

so I just do =STDEV.S and highlight the whole list

[glacial island]

Yes

[floral breach]

I got this

@glacial island

Include a final statement in which you state the approximate standard deviation.

[glacial island]

That's the answer

It's basically just due to slight differences in how some standard deviations are calculated

[floral breach]

what should I write for the final statment

[glacial island]

You would write "The approximate standard deviation is 1.31." And include the image

Anything else?

[floral breach]

Thanks Alot

[glacial island]

No problem

[floral breach]

I appreciate you

Can I resort to you some other time

as well

[glacial island]

I'm always willing to help when needed

But for today, is that everything you need here?

[floral breach]

can you accept my friend request

[glacial island]

I did that already

[safe radish]

@floral breach Has your question been resolved?

[safe radish]

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[lean otter]

So y = root(x)

y = x/3

$2\pi \int_{0}^{9} x (\sqrt{x} - \frac{x}{3})$

[flat frigate]

hibyehibye

[lean otter]

,w 2pi * integral from 0 to 9 of x(sqrt(x) - x/3)

[flat frigate]

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[lean otter]

does that seem right?

[safe radish]

@lean otter Has your question been resolved?

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[lean otter]

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[oak skiff]

For the chart on c. Does anyone know what the formula is to find msec.

[oak skiff]

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[zenith hull]

Can someone help me find where I've done something wrong?

[zenith hull]

I'm supposed to find the inverse of this matrix

This is the progress

[final loom]

._.

[plucky elk]

just screenshot and upload

[zenith hull]

I know theres another method to do it by making small 2x2 matrixes etc, but I wanted to try this method

[final halo]

Bottom right entry in second matrix

[zenith hull]

i swapped places

[final halo]

?

Yeah you do that after

[zenith hull]

Changed the 2nd and 3rd row

[final halo]

I'm saying check the bottom right entry in your second matrix

[zenith hull]

Ffs how's my english this bad, hold on

Oh, okay, so the step before

i see

its supposed to be nr 1 there

right?

[final halo]

Yes

[zenith hull]

bottom right corner in 2nd matrix

thank you

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[delicate pumice]

How are you able to just move the 1/ to the other side

Why is this possible

[final halo]

Times both sides by e², then divide both sides by 3e^t

[delicate pumice]

oh wow

that made me look real dumb

the way my professor did it made it look like it was a rule he used

where he skipped over it

which is why i got confused

[plucky elk]

maybe it was cross multiplication

[final halo]

The more you do it the more you can just skip the steps

#❓how-to-get-help

[delicate pumice]

fair enough

alright thanks

.close

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[mental vortex]

not sure how to do this

<@&286206848099549185>

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@mental vortex Has your question been resolved?

[mental vortex]

<@&286206848099549185> please

😭

[winged cloak]

ok so basically

x^3 - 8x² +17x = 0

after factoring that

you get x(x² - 8x + 17) = 0

x = 0 or x² - 8x + 17 = 0

solve the second equation

and you'll get all 3 solutions

(ps: yes, b² - 4ac will be what you will find, don't be surprised)

[mental vortex]

solve x(x² - 8x + 17) = 0?

im confused

how do I find the zeros

because I thought the only zero would be 0.

than i have to factor completely, but I'm unsure on how to factor x(x² - 8x + 17) = 0 anymore

because of the 17

[winged cloak]

You dont have to

A x B = 0 means A = 0 or B = 0

[mental vortex]

im sorry, im so lost

[mental vortex]

so what is wrong with my answers here

[mental vortex]

i've found the zeros

its 0, 4+i, and 4-i

but I still need help factoring

.close

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[coral nimbus]

is it possible to calculate the area underneath a simple exponential curve (1.04^x) in constant time, given the two x values to measure between? (without looping over coefficients, for example)

[gilded pilot]

yes, you must take the integral from x initial, to x final

[coral nimbus]

is it possible to calculate the integral in constant time?

[gilded pilot]

when x is constant?

[coral nimbus]

or does that always require looping over (measuring area of many smaller rectangles, etc.)

[plucky elk]

if you have an antiderivative, yes

[gilded pilot]

the defitinion of a Definite Integral is, the limit of the riemman sum, as N approaches infinity

[plucky elk]

,w integral a^x

[coral nimbus]

x is not constant, and actually nor is the percentage of change (0.04 in the above case)

[flat frigate]

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[gilded pilot]

so i believe you would need to loop through the rectangles

[plucky elk]

you plug your limits into that antiderivative

[plucky elk]

can you write mathematically exactly what you're trying to calculate

[safe radish]

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[lean otter]

Can someone help me find which one of these is correct I struggle with point slope

[lean otter]

@lean otter can you explain it a little bit it doesn't need to be a long one just enough that might help me understand point-slope better

[swift fjord]

point slope form is

y = m(x-x1)-y1

you notice that for every increase in x, f(x) decreases by 5

this means

m = -5

then you can chose any point (x,y) and x1=x and y1=y

[lean otter]

so what is the difference between x and x1 and y and y1

Also is d the correct answer for this one?

[swift fjord]

x is the ijnput for the equation and x1 is a specific value

x1 is kinda like b in y = mx + b

x1 is a number

x is an input

[lean otter]

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[foggy linden]

on all sides. What is the conditional probability that the sum of the numbers that
come up on the two rolls will be greater than seven, given that the first roll is 5?```
I'm not sure how to solve this if we're not given the the number of die?

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[hollow idol]

Simplify:

[hollow idol]

(1+tanx) ÷ (1 + cotx)

The answer is tanx

But idk how

[hollow idol]

(I found it graphically)

[serene stream]

i can show you how to start

so

cot is 1/tan

so

you do

(1+tanx)/1+1/tanx

then you can simplify

[hollow idol]

Thats what Im stuck on 🥲

[serene stream]

oh

uh

so

[hollow idol]

Wait

If i multiply

The whole fraction

By

Tanx/tanx

It may work

[serene stream]

you can also do the simpler but longer way

by converting everything into sin and cosin

[hollow idol]

Yup im lost

[hollow idol]

Trying that rn

[serene stream]

1+tanx/1 + cotx = (1 + sin/cos)/(1+ cos/sin)

which is

((cos + sin)/cos)/(sin + cos)/sin

simplify

you get

(1/cos)/(1/sin)

which is equal to sin/cos

which is tan

[hollow idol]

How did you rrmove the 1 on top

[serene stream]

bc it doesnt change

cuz

[hollow idol]

Nvm common denominator

Ty for helping me

[serene stream]

yea

np

[hollow idol]

This hw is humbling

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[lament nebula]

hm

[lament nebula]

@twilit cargo did u check my answer?

[twilit cargo]

Could you post here again ?

Also I’m not sure how ur getting the log function there as there was no ln or log in ur equation

I did the question using percentage and got my answer

@lament nebula

[lament nebula]

A computer that was purchased for $6000 depreciates at a rate of 13.4% per year. An equation modeling this is, f(x)=6000(0.866)x, where x is the number of years.

What is the computer worth after 2 years?
After two years, the computer will be worth 6000 * .866 * .866 = 6000 * .866^2 = 4499.736.
Using the following formula, you can find how long the computer will take to equal 2530.
2530 = 6000 * .866 ^ n
In this case, n represents the number of years. divide both sides of the equation by 6000
to get: 2530/6000 = .866 ^ n
Calculate the log of both sides of the equation to get, log(2530/6000) = log(.866 ^ n)
by log rules, this becomes
log(2530/6000) = n * log(.866) solve for n to get n = log(2530/6000) / log(.866) = 6.002209934.
confirm by replacing n in the original equation to get: 2530 = 6000 * .866 ^ 6.002209934.
this becomes 2530 = 2530, confirming that the value of n is correct.
The solution is that the value of the computer will be 2530 in 6.002209934 years.
When will the value of the computer be $2530?
In 6 years

I was told to use log

in a other math server

[lament nebula]

So should I do the way you did

also can u check my other answers https://docs.google.com/document/d/1ef8dbDEexrS8XS3AQhptDk16NlzZx8uihO9ZdBDuSdE/edit?usp=sharing

[twilit cargo]

Can’t check atm have an exam tmrw

If it’s due later tmrw I can go over it

Ping helpers maybe someone else can help

[lament nebula]

oh

@twilit cargo I'll wait for u

just come help in the doc, when ur free

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@lament nebula Has your question been resolved?

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@lament nebula Has your question been resolved?

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@lament nebula Has your question been resolved?

[safe radish]

@lament nebula Has your question been resolved?

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[granite crane]

is there a technique for solving this?

[lean otter]

Probably no trivial way, but you can see that it will only have one solution

So you can just plug in numbers if that's faster for you don't

[stray bluff]

huh

its (3x+7) and (3x+1)

[solemn vault]

Oh

Sry

My bad

I didn't see the question properly

[safe radish]

@granite crane Has your question been resolved?

[rugged ice]

x is a little below 168, we don't know the calculation for it, but this is the answer anyway

[granite crane]

yeah but I want to know how can I solve it

[rugged ice]

first you converd the powers to roots

then take away the 3 power roots

so you get = 3 power root 88

[granite crane]

should I cube both sides?

[toxic stratus]

is this a typo?

the two brackets should actually be the same?

[granite crane]

why?

[toxic stratus]

or is it actually like this

[latent prairie]

wait hold on

lemme write this

[toxic stratus]

this is surely a typo

[toxic stratus]

of the two which do you mean

[rugged ice]

ist the first one

i think

[latent prairie]

ok so

ok nvm i've gone braindead

[granite crane]

A friend sent it to me he wanted help but now I think he's trolling me

[delicate parcel]

Yes and its called ninja technique

[granite crane]

what is it

[toxic stratus]

well your original question is like

insanity to solve by hand

[granite crane]

yeah

[toxic stratus]

whereas the two i sent are doable

[granite crane]

I think too

[delicate parcel]

Website cant solve it either

[rugged ice]

my calculator can solve it

its around 168 but like how are you canna get that by hand

[granite crane]

yeah lmao

[rugged ice]

oke so their 2 solutions

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[granite crane]

.close

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[split iron]

can anyone help walk me through this

i got a completely diff answer

[quasi bison]

so you did this problem and got an answer but were told it's wrong?

@split iron

[split iron]

well i know its wrong

the answer came out sloppy

if that kinda makes sense

[quasi bison]

show your work so we can look for errors.

[split iron]

Ill rewrite it quickly

[quasi bison]

rewrite it slowly instead

[split iron]

Okay

Bottom rite is the answer i got

[wild basin]

what did you do with the deominator u

in first step

[split iron]

Idk i guess i just tried itegrating it

[wild basin]

tell me the correct answer

?

[split iron]

-76

[wild basin]

ok i am getting it

right yeeee!

lemme show you

solution

[split iron]

Ok

Ty

[wild basin]

but i have to write

it

clean

[split iron]

Take ur time!

[wild basin]

lemme send you

[split iron]

Ok

Dm or here?

[wild basin]

wait

i think

there is

prblm

in sending

image

@split iron hey

see this

sol

[split iron]

TY

So the u in the denom just cancels out?

[wild basin]

yup

cuz 2/2 is 1

[split iron]

Ohhhh

[wild basin]

first you have to separate the u from denomiantor

toboth memebers

then use some then solve it

did you understand

?

[split iron]

Yep yep

I get it now

Tysm

[wild basin]

np

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[split iron]

can someone help explain these two for me?

[lean otter]

use the fundamental theorem of calc

[split iron]

I get it now lol

Thanks

.close

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[wild basin]

.reopen

@split iron

[split iron]

.reopen

[wild basin]

here i can help u

[safe radish]

✅

[split iron]

i get it jus took me a min

[wild basin]

okk

you just have to solve it very easily

by using simple calc

[split iron]

yep i jus had to remember the first park of ftoc

[wild basin]

ohh

nice

then

[floral willow]

DRAING GANG

DRAIN GANGGGGG

[split iron]

U DRAIN

[floral willow]

YESSIR

DRAIN 4 LIFE

[split iron]

HAHA FAV SONG?

[floral willow]

https://cdn.discordapp.com/attachments/903481106819612714/1050370681612816514/image.png

https://cdn.discordapp.com/attachments/903481106819612714/1050370734846922812/image.png

so

to get g' you would derive both sides yes?

[split iron]

yes when you derive it i got f(t) dt

i think thats right

then i plug in x right?

[floral willow]

i messed up i see waht x they want

they want this x

the 2nd terminal

basically what it is saying that

what could you put in the second terminal so that the area from -4 to a terminal, x, on the graph of f(t) is equal to 1

[split iron]

wait im confused now

sorry can you explain what you mean by terminal

[floral willow]

these are both called terminals

[split iron]

alr

can you explain why when you do ftoc that the problem comes out like this?

wait

nvm i see

LOL sorry

[floral willow]

yeah jsut rememebr

x is a constant

so you don't need to worry about getting it in terms of dt or anything

[split iron]

just say for the sake of this example it was a function instead of just f(t)

[wild basin]

yup

[split iron]

is that possible for a problem like this or no?

[wild basin]

in terms of t

[split iron]

like idk f(t^2 + t)

[floral willow]

yes it is

because essentaily it is a bit confusinf they used x in the terminal

as we're used to seeing it in equations like x^2

but say you got

3t-3t^2

[wild basin]

do u know derivative is the reverse of integration

use that

[floral willow]

you could still sub in the value you find for x

as its just a constanty

constant

they only rule with this kinda ithing is that you can never intergrate with a variable with respect to another

so you can't intergrate x^2 dt

[split iron]

ok ok i get it kinda

thanks u guys!

ima head to bed for my test in tha morning gn!

.close

[wild basin]

np

[safe radish]

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[rare folio]

Any ideas how i can reshape this so it says:

1/(s -/+ something)

R,C and L are just constants

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[cyan crescent]

How to do 3a?

[lean otter]

To find the roots find the derivative of f(x) and set it equal to 0

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[cyan crescent]

No. I think there should be IVT done for it.

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[cyan crescent]

<@&286206848099549185>

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[shut inlet]

@cyan crescent
calculate f '(x)

when :
f '(x) > 0 means that f(x) is increasing
f '(x) < 0 means that f(x) is decreasing

try to find the interval for each of the above

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[unkempt hemlock]

Hey guys i got a physics question regarding Work

[unkempt hemlock]

and was thinking of using this equation

W = F x D

W = F x cos(theta) x D

since we have work already

and the angle

I changed

from there I was confused on howto solve just for Force

Where am I wrong?

<@&286206848099549185>

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<@&286206848099549185>

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[unkempt hemlock]

.close

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[latent bronze]

What is the name of this convergence criterion? It looks similar to the ratio test but it looks stronger.

[latent bronze]

a_n!=0 for all numbers bigger than a sufficiently large number*

Not just one number but the sufficiently large is for all numbers greater than that number.

Might just say that each term of the sequence is unequal to 0. Should be the same statement I think

[quasi bison]

feels similar to raabe's i think?

or wait

[latent bronze]

Thanks. Seems similar.

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[rigid sapphire]

why does the limit of a_n lead to 1^infinity

infinity over infinity is already indeterminate isnt it

and not 1

[deep apex]

because $\frac{n+1}{n-1}$ converges to 1 when n goes to infinity

[flat frigate]

Assass!n

[rigid sapphire]

huh

[deep apex]

1 powered to infinity is equivalent to $\exp(\infty \dot \log(1))$ which is indeterminate

[rigid sapphire]

isn't that the same thing as saying lim of (n+1)/(n-1) is 1

[flat frigate]

Assass!n

[deep apex]

yeah ofc

[rigid sapphire]

i thought it would be undefined

[deep apex]

why

[rigid sapphire]

1sec ill show

[rigid sapphire]

hm i guess the use case is different

table is probably just simply wrong

ty

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[lean otter]

i can't go any further some one plz help

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[lean otter]

i need to simplify this

[wild basin]

ohh

its easy

take the -1 common from top

from this

then cut it

lemme show you my work first

@lean otter hold my beer🍺

[lean otter]

thx

[lean otter]

.close

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[wind robin]

Can i just use substitution on all integral questions?

[wind robin]

Do i have to memorize all these for integration?

[solid shell]

Substitution acts to undo the chain rule

There are many integrals where it will not be as helpful

[wind robin]

I suck at integration like when i try to solve i dont get the idea to solve it

[solid shell]

However you can usually apply it in some way to almost any integration problem

,rccw

[solid shell]

Definitely make sure you get down the basic ones

[wind robin]

isnt there anything like the product rule and quotient rule?

[wind robin]

which?

[solid shell]

Yes, there's a method called Integration by Parts which undoes the product rule, and Partial Fraction Decomposition which can work with quotient rules

[wind robin]

so i can just learn those and use them?

instead of trying to get an idea from the formulas

?

[solid shell]

Um the formulas with radicals you can technically apply the power rule of integration since sqrt{a} = a^1/2

But most of those you will probably want to memorize, or at least be familiar with

Like I don't have all the trig ones memorized but I still know them enough to work with them

Are you taking an integral calculus class right now?

[wind robin]

No im taking more advanced stuff

but im too late

[solid shell]

Okay good to know

[wind robin]

im trying to cope in