#help-23

1 messages Ā· Page 40 of 1

quiet cypress
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to simplify

swift palm
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Actually a lot of that doesn't make sense. Where did 12^x come from in second to last line.

quiet cypress
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what is 2*6?

livid sparrow
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Yes

quiet cypress
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Distribute

livid sparrow
swift palm
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There is no powers of x in that entire question so it makes no sense that 12^x would ever be a term

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What you said is right purple don't worry

livid sparrow
swift palm
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I'm just not sure what is going on in that working out

quiet cypress
swift palm
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Yes that's right it's not what I'm talking about.

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Just that working out at the beginning is wrong

quiet cypress
swift palm
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The initial working out that you are confused about is wrong purple.

livid sparrow
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Lmao guys chill you're making my head hurt lol

quiet cypress
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what is the beginning of the problem? like what is starting point?

livid sparrow
quiet cypress
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2+2x(2(3x+2)+2)
??

livid sparrow
quiet cypress
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or is there something before ?

livid sparrow
quiet cypress
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okayt

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so what is the goal?

livid sparrow
quiet cypress
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to find x?

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okay

swift palm
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Mostly in the transition from 3rd last to 2nd last line of working.

quiet cypress
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this 2+(12x^2+12x)?

swift palm
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This can never be a term

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Yet somehow it is in the working out.

livid sparrow
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Ahhh guys my bad

quiet cypress
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Is the + supposed be = ? becasue you can't really divide 2 in this case if it was a +

livid sparrow
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I just made a type

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typo

livid sparrow
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12x^2/2 + 12x/2 + 2/2

swift palm
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Ohh ok.

livid sparrow
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But still I dont understand why this

swift palm
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Do you have the textbook or something where it came from because it's still a bit hard to understand

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If it's put equal to 0 then you can divide by 2

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But otherwise it makes no sense

quiet cypress
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Because if you divide 2 you can simplify it to the right answer

livid sparrow
# swift palm Do you have the textbook or something where it came from because it's still a bi...

Simplifying Expressions – Explanation & Examples Learning how to simplify an expression is the most important step in understanding and mastering algebra. Simplification of expressions is a handy mathematics skill because it allows us to change complex or awkward expressions into simpler and compact forms. But before that, we must know what an a...

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example 2

livid sparrow
quiet cypress
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This expression can be simplified by dividing each term by 2 as;

livid sparrow
quiet cypress
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you are missing 6x. so the answer is 6x^2+6x+1

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there is no rule

livid sparrow
quiet cypress
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Its okay man.

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Glad everything worked out

livid sparrow
quiet cypress
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So if your goal is to simply then you do whatever you can do make it more simpler

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So in this case, dividng by 2 makes it better than 2 + 12x 2 + 12x

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2 + 12x 2 + 12x becomes 6x^2+6x+1 which is easier to do if you have to use the quadratic equation

swift palm
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Actually I'm going to have to somewhat disagree unfortunately. Symbolab and wolfram alpha keep a factor of 2 outside brackets.

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Try it on both and yes they divide by 2 to simplify but they keep the final answer as 2(6x^2+6x+1)

livid sparrow
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I have no clue what im talking about though

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But it is becoming clearer

swift palm
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That is the only way it makes sense but the website doesn't keep the factor. I am actually unsure about what the website is doing...

livid sparrow
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Or symbolab/wolfram?

swift palm
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Yeah.. maybe killer can explain it to me better but I'm working through y12 and this shouldn't be something I'm failing.

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If I'm wrong

quiet cypress
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So from the website you showed me it the part where it says, "Now eliminate the parentheses by multiplying any number outside it;" that is where hydro is taking about. The final answer is 2(6x^2+6x+1). The expression itself can be simplify to 6 x^2 + 6x + 1 and that is where the 2 comes from (12x^2/2 + 12x/2 + 2/2)

swift palm
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Yeah, I get that but here's my confusion. For an equation equal to 0, so for example 12x^2+12x+2 = 0, you can divide both sides by 2 easily. If you have an expression though, like 12x^2+12x+2, dividing by 2 gives you a different expression totally.

livid sparrow
swift palm
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As you can see from desmos, 12x^2+12x+2 and 6x^2 +6x+1 are completely different expressions however they do have identical x intercepts. So the solutions are the same but substituting values of x give different values of y. What is wrong with my logic killer?

quiet cypress
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Ahh, based on the graph I see. Gotcha. Yeah, I guess is not totally worth simplifying then. I guess it will depend on the teacher

swift palm
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This is a really unsatisfying conclusion

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I actually think the website is objectively poorly worded, where did you find it @livid sparrow

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If it's official then maybe I'm just thinking about this wrong, but otherwise I think they could improve wording...

livid sparrow
quiet cypress
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Khan academy is a good one

swift palm
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Definitely

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Also MathIsFun is what I used to teach myself definite integration

livid sparrow
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What would I search on there to find this?

quiet cypress
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Google

swift palm
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Simplification of expressions or simplification of equations

livid sparrow
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Thanks for the help fellas, appreciate it

quiet cypress
swift palm
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Honestly though you seem to understand it fine and just got tripped up by the website which would have happened to me too.

quiet cypress
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I will ask my mentor about this tho. It seems interesting

swift palm
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Can you show me the other website with that example?

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I'm guessing they have it as an equation not an expression but maybe not.

livid sparrow
swift palm
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A polynomial is just an expression with 2 or more terms.

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Algebraic expression to be specific

livid sparrow
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Okay thank you

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Do either of you have any textbooks you would recommend?

quiet cypress
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Yes, one of my favorite

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let me check the Arthur

swift palm
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I assume you live in the US right?

livid sparrow
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Nope, New Zealand

swift palm
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I use the Australian mathematical curriculum textbooks

livid sparrow
quiet cypress
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College Algebra by Robert F. Blitzer . You might have a good luck finding it online but its an amazing book with good explanation

quiet cypress
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Anytime!

swift palm
quiet cypress
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If you want, I can create a group chat here. If Hydro is fine with it. There you can ask all the questions you need. Good to see people come back to math after years.

swift palm
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If you go to haesemathematics.com that has yrs1-12 of Australian math curriculum including specialist pathways.

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I'm fine with it 100%

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https://www.haesemathematics.com/ that has the aus textbooks

quiet cypress
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Just added you both

livid sparrow
livid sparrow
quiet cypress
# livid sparrow šŸ™‚ I'll try not to pester you too much!

You're fine! You are actually motivating me to teach again. I am hoping to get my masters in math soon! I am taking a break from school now and just enjoying life. But man I do miss helping people out. I was a TA for calculus 2 in grad school for one semester but didn't do well in my classes so I had to leave.

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I taught it last year so not quite a break from school.

livid sparrow
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Nice man, glad to have someone knowledgeable on my contact list

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Having someone explain things can be really helpful

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You guys want to make a group chat?

quiet cypress
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I did but didn't send a message yet

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haha

livid sparrow
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Alright cool beans

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ill close this channel now then

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.close

safe radishBOT
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plucky elk
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W_n are usually already column vectors

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That's awkward phrasing

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R^n exists outside the scope of W_n

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lean otter
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Is there a difference between saying perpendicular vs orthogonal or is it just semantics?

lean otter
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I have seen some people divided on it online

vestal sedge
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depends on the context

cosmic grove
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kinda the same thing, but I use "perpendicular" for lines and orthogonal for vectors

vestal sedge
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perpendicular is orthogonal in planar geometry

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orthogonal isnt perpendicular necesarily in spatial geometry

cosmic grove
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orthogonal is best suited for vectors

vestal sedge
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yes agreed

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and when reffering to orthogonal matricies you cant say perpendicular matricies

cosmic grove
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perpendicular is a geometry term

vestal sedge
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even in geometry it's not quite the same

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perpendicular is just that perpendicular
orthogonal involves perpendiculars but isnt necesarily perpendicular on its own

cosmic grove
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for example ?

vestal sedge
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orthogonal projections in 3d space

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the segment projected isnt perpendicular on the plane

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but the ends of it that determine the projections are

vestal sedge
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a contradictory example would br orthodiagonal quadrilateral which by definition have perpendicular diagonals

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
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Will keep this channel open for you guys to discuss about it lol

cosmic grove
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or did I miss something

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The projection of the segment isnt perpendicular to the segment itself of course

safe radishBOT
#

@lean otter Has your question been resolved?

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proven zephyr
safe radishBOT
proven zephyr
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found out d²y/dx² but cant prove = 0

hybrid osprey
proven zephyr
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-sin theta / (1+ cos theta)

safe radishBOT
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@proven zephyr Has your question been resolved?

proven zephyr
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<@&286206848099549185>

proven zephyr
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nvm i got it i forgot to multiply by dĪø/dx when taking the higher derivative

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.close

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pseudo scroll
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$\int \tan^5 \theta d\theta$

safe radishBOT
flat frigateBOT
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NEONPerseus

pseudo scroll
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How do I even start man :/

vestal sedge
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god what kind of integral homework do you have

pseudo scroll
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Ah welcome back

vestal sedge
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yeah lol

pseudo scroll
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My teacher said the x^5 one was too hard and they assigned it as a joke šŸ’€

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They said that this was within scope though

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So...

vestal sedge
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hmm

pseudo scroll
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I know there exists a reduction formula for tangent but can't use it at school

vestal sedge
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oh sad

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thought of that exactly lmao

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like you cant use sec²x-1 = -tan²x

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1

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sorry

pseudo scroll
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maybe we can?

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tan^2 x * tan^3 x

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And then

vestal sedge
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yeah but u said the formula is off bounds

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thats what i thought you meant

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you can square the ahole thing to get tan⁓x

pseudo scroll
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the reduction formula is off bounds

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not that identity

vestal sedge
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ooh like complex?

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yeah ok

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well thats what im thinking of atm

pseudo scroll
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$\int \tan^m x dx = \frac{\tan^{m - 1} x}{m - 1} + \int \tan^{m - 2} x dx$

flat frigateBOT
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NEONPerseus

pseudo scroll
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This is the reduction formula

vestal sedge
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oh

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ive never seen that before thats cool

pseudo scroll
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its fun yeah

vestal sedge
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anyways i believe you can work with that identity

pseudo scroll
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Yeah

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Somehow :/

vestal sedge
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you can u sub to help i think

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id u sub sec x

pseudo scroll
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lets see what that does

vestal sedge
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im actually at shool rn lmal

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lmao

pseudo scroll
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holy shit I think its working

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$\frac{1}{2}\int \frac{(u - 1)^2}{u}du$

flat frigateBOT
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NEONPerseus

vestal sedge
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how the heck do u use that tho i gebiuanely dont know

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yeah i think thats right

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like the bot

pseudo scroll
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$\int (1 - \sec^2 \theta)\tan \theta d\theta$

flat frigateBOT
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NEONPerseus

pseudo scroll
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So secant squared is u

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$$\sec^2 \theta = u$$ $$2\sec^2 \theta \tan \theta d\theta = du$$

flat frigateBOT
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NEONPerseus

pseudo scroll
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$d \theta = \frac{du}{2u\tan\theta}$

flat frigateBOT
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NEONPerseus

pseudo scroll
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and then put that in and it all adds up :)

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thanks for the help

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.close

vestal sedge
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mhm

safe radishBOT
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violet owl
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hello

safe radishBOT
violet owl
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the answer’s (-infinity,-3)U(9,infinity)

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however none of these seem to represent the correct answer

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😭i just need someone to confirm tht wat i did is correct

trim swan
violet owl
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divide bith sides by 2
then set two possibilities
3x-9>18 then x=9
3x-9<-18 , x=-3

trim swan
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oh. Yeah, you're right

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None of these are right :x

violet owl
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what does d translate to all real numbers except the region -9,3 inclusively

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okayy

violet owl
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oh okay

trim swan
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For example R - [-3,9] would be correct for this inequality

violet owl
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yeahh ill just switch the signs for d

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mustve been a mistake

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thanks a lot!

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.close

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elfin cove
#

so i have to show this identity step by step but i am confused how i would write the first part in the gauß formula

elfin cove
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for e.g. this is understandable:

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but with n+1 and v=1 i'm confused how it becomes (n+1)(n+2)/2

safe radishBOT
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@elfin cove Has your question been resolved?

jade gust
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I probably won't be much help cause 1. I'm dookie at maths 2. 12 am

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Probably perform an index shift

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after doing that use the commutativity and associativity property

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Index Shift: \[\sum^t_{n=s}[f(n)]=\sum^{t+p}_{n=s+p}[f(n-p)]\]
Commutativity and Associativity: \[\sum^t_{n=s}[f(n)]\pm\sum^t_{n=s}[g(n)]=\sum^t_{n=s}[f(n)\pm g(n)]\]
flat frigateBOT
elfin cove
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sadly i never heard of the index shift 🄲
and the thing is my prof skipped this part [induction] in uni whysoever

jade gust
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damn don't you learn mathematical induction during highschool

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but it's not like i listened anyway

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Basically induction is just tryna prove some formula works for all natural numbers

safe radishBOT
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jade gust
#
The simplest and most common form of mathematical induction infers that a statement involving a natural number \(n\) (that is \(n\in\mathbb Z\geq0\lor 1\) holds \(\forall n\). The proof consists of two steps:

\begin{enumerate}
\item The \textbf{base case} (Synonym: \textbf{initial case}): prove that the statement holds for \(0\lor 1\) or both.
\item The \textbf{induction step} (Synonyms: \textbf{inductive step}, or \textbf{step case}): prove that \(\forall n\), if the statement holds for \(n\), then it holds for \(n+1\). In other words, assume that the statement holds for some arbitrary \(n\in\mathbb N\), and prove that the statement holds for \(n+1\).
\end{enumerate}
The hypothesis in the induction step, that the statement holds for a particular \(n\), is called the \textbf{induction hypothesis} or \textbf{inductive hypothesis}. To prove the induction step, one assumes the induction hypothesis for \(n\) and then uses this assumption to prove that the statement holds for \(n+1\). \\~\\
Authors who prefer to define natural numbers to begin at \(0\) use that value in the base case; those who define natural numbers to begin at \(1\) use that value.
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flat frigateBOT
south skiff
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What is the inclusion exclusion formula for n(A and not B

south skiff
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so n(A and B with a line on top )?

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sorry how would i do n(A and not B and not C)>

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?*

safe radishBOT
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@south skiff Has your question been resolved?

safe radishBOT
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@south skiff Has your question been resolved?

south skiff
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.close

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orchid wave
#

How do I do this question ?

safe radishBOT
orchid wave
#

When I try to get the area while using an integration of the equation, I get the result as 3/2

obtuse plover
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What was ur integration equation

orchid wave
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I checked it using the calculator too

obtuse plover
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Notice how part of ur curve goes under the x-axis

orchid wave
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Doesn’t the equation account for that ?

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Sorry, I’m quite new to integration

obtuse plover
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No need to apologize. Yes it does, it adds the areas above the x-axis and subtracts from it the areas underneath the x-axis

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But we just want a sum of everything shaded

orchid wave
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Ohhhh

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I see

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How can I amend that ?

obtuse plover
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Try manipulating ur bounds on the integral, u will be using 3 integrals, 1 for the first area above the x axis , the next for the area under the x axis, and one finally for the last area above the x axis

orchid wave
#

Alright
I’ll try and let you know

obtuse plover
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Sounds good

orchid wave
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Well I tried it and it doesn’t work
I basically took the integral of x^2 -3x +2 (which is [x^3]/ 3 - [3x^2]/2 + 2x
Then I equated it to a function which I called f(x)

Then I did the following
f(1) -f(0) + f(2) - f(1) + f(3) - f(2)
which results in my answer being 3/2

obtuse plover
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What did u get for the f(2)-f(1)

orchid wave
#

-1/6

obtuse plover
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There’s ur problem

orchid wave
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Ahhh

obtuse plover
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That’s the area under the x axis

orchid wave
#

I see

obtuse plover
#

So take abs value of it, and add it to the other values

obtuse plover
#

Which woulda worked if there was an absolute value around the f(2) - f(1)

orchid wave
#

Now I get 19/6

obtuse plover
#

Hmm

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What did u get for each of the areas

orchid wave
#

f(0) = 0
f(1) = 5/6
f(2) = 2/3
f(3) = 3/2

So 5/6 + 1/6 + 3/2 - 2/3
= 11/6

obtuse plover
#

There u go

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That shd be the right answer

orchid wave
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Ohhh okay

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Thanks

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One more thing

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Isn’t there a way to find the area of a curve for a specific range without considering whether the curve dips below the x axis or not ?

obtuse plover
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I’m not sure I’m understanding

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So the area under the curve above and below the x-axis added together?

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All as positive ur asking?

safe radishBOT
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@orchid wave Has your question been resolved?

safe radishBOT
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@orchid wave Has your question been resolved?

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pallid spade
#

Could anybody explain what I'm doing wrong? I checked wolfram alpha and synolab, and both say that it's 1/sqrt(2x-1) but I'm not quite sure how do they get to that solution as there is 1/2

split ether
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Chain rule

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Multiply that by the derivative of (2x - 1)

pallid spade
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Ah my brain is not working anymore, yeah that

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Thx šŸ’€

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coral meadow
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wheat cave
# coral meadow help

You could write as
a+0.5b=p
b+0.5c=p
c+0.5a=p
and solve the equation, I believe?

coral meadow
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damn that was easier than I thought

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I'm dumb thanks

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.clse

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lean rover
safe radishBOT
lean rover
#

The 2nd one

safe radishBOT
#

@lean rover Has your question been resolved?

wheat cave
#

also, with 2nd, do you mean ii, (b) or the entire 2. task?

lean rover
#

I’m not even sure what question 2 is asking

wheat cave
# lean rover I’m not even sure what question 2 is asking
In mathematics and particularly in algebra, a linear or nonlinear system of equations is called consistent if there is at least one set of values for the unknowns that satisfies each equation in the system—that is, when substituted into each of the equations, they make each equation hold true as an identity. In contrast, a linear or non linear equation system is called inconsistent if there is no set of values for the unknowns that satisfies all of the equations.

Stolen from wikipedia

#

tl;dr, is it possible to solve them

lean rover
#

Ah

#

So do I just do what i would for 1

#

Find the values XY

wheat cave
#

wait so where are you now

#

at b) ?

lean rover
#

Not A

wheat cave
#

ah I see

#

well, just a simple check, you could try multiplying the left side by 2

lean rover
#

O

#

It has to be matrices

wheat cave
#

?

#

You mean this right

lean rover
#

Yh

#

But I have to use cramers rule

wheat cave
#

no, cramers rule was the first task

#

here you can prove very fast that this is not a possible equation

lean rover
#

Yh and my teacher wants us to use matrices as that is what the modules is about

#

We unfortunately can’t use any other ways

wheat cave
#

Well then write it like that

#

i) 2 -3 8
ii) 4 -6 9

#

you can multiple i) with 2 to find out that its not possible

lean rover
#

Hold on let me do it quickly with the way my teacher told me to do it give me 1 second

wheat cave
#

sure, and can you send an example so I know how to explain better?

lean rover
#

Yh sure

#

I’ll send you my previous work

#

Ok

wheat cave
#

its basically saying 18=9

lean rover
#

I know the determinant has to not equal Zero

#

For Cramer rule to be applicable

#

Is that my answer

#

Probably not since it talk about consistency

wheat cave
#

ah wait

#

Cramer rule assumes solvability of equations

lean rover
#

Yh

wheat cave
#

Since D=0, you know that its not solvable for any numbers, meaning its just not consistant

lean rover
#

Which this does not satisfy

#

Yh so I say not consistent because Cramer rules needs D≠0

wheat cave
#

Yupp

#

I think you could've stopped after the first line, finding out that D=0 and Dx!=0 means its not solvable

lean rover
#

I don’t know why I continued but yh

#

Is the same for B

wheat cave
#

tbh when we did cramers rule we always simplified first so our divisions in the end weren't that big, but I guess you have to do it this way

lean rover
#

Yh my teachers we quite adamant on us doing it this way

#

May I ask for help on another question?

wheat cave
#

sure

lean rover
#

A

#

I haven’t really done much studying on so it maybe be best I learn to do it

#

What is question A called so I can watching some videos on before asking you as it maybe easier on you

wheat cave
#

What do you mean called?

lean rover
#

The topic

wheat cave
#

Well, since you know you have to use cramers rule, its cramers rule

lean rover
#

3A?

wheat cave
#

I believe?

lean rover
#

O

#

It says prove tho not solve

wheat cave
#

ah true

#

I'm not sure myself..

lean rover
#

Ah not an issue

safe radishBOT
#

@lean rover Has your question been resolved?

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tawdry hornet
safe radishBOT
tawdry hornet
#

<@&286206848099549185>

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@tawdry hornet Has your question been resolved?

tawdry hornet
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<@&286206848099549185>

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<@&286206848099549185>

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oh lord

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peak estuary
#

general note: dont expect people to download random files to help you

rancid lion
#

i can stream it

#

im not good at showing my work so i need someone to help me with that

#

<@&286206848099549185>

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mental patrol
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rigid inlet
#

What's giving you issue?

mental patrol
#

I was thinking B but not sure

rigid inlet
#

-29.29 is the y-intercept

mental patrol
#

Yes

rigid inlet
#

It's the estimated value of Y when you set X=0

mental patrol
#

Okay :/ I don’t really understand

rigid inlet
#

What don't you understand?

mental patrol
#

The negative does not matter then?

#

The negative makes me think that it will be a negative relationship

rigid inlet
#

I wouldn't say it doesn't matter

#

Does it make sense for a donation rate to be negative?

mental patrol
#

No but some of the answers say that the college would be expecting fewer alumni to donate, not that there would be negative donations I think?

rigid inlet
#

Well I'm trying to illustrate what the -29.29 represents

mental patrol
#

I think the Answer is A I just don’t understand what -29.29 is

#

I know it is Y

#

But like what does the number come from/what is is representing

rigid inlet
mental patrol
#

That I don’t understand

rigid inlet
#

An important concept in regression is the idea of a relevant range

#

There's a relevant range on the output (it must be in [0,1]) and there's one on the input (SAT scores have bounds)

#

However, a line is continuous for all real numbers, and thus it has to have a y-intercept if it has finite slope

#

So while it may physically be nonsense (a donation proportion of -29.29% makes no sense), it needs to exist for the regression line to be an actual line

mental patrol
#

Okay, I see

#

So the -29.29 is supposed to be the donation percentage?

rigid inlet
#

Y is the donation percentage

mental patrol
#

Yes I thought -29.29 is Y?

rigid inlet
#

We're estimating Y through Yhat = -29.29 + 0.05X

mental patrol
#

What is -29.29 then

rigid inlet
#

It's the y-intercept

mental patrol
#

I know but what is it for, donation, score, etc?

rigid inlet
#

It's the value of Y when X=0

mental patrol
#

That is part I do not get

rigid inlet
#

So the donation percentage when we look at SAT scores of 0

mental patrol
#

If an SAT is 0, the donation is -29.29?

rigid inlet
#

Yes

mental patrol
#

Okay

#

Thank you

#

I think answer is A then?

rigid inlet
#

Yes

mental patrol
#

Thank you!

rigid inlet
#

Np

mental patrol
#

.close

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sinful tinsel
#

Hi, i understand case 1 and 2, but how did they get 4C1 in case 3?

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#

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winged fern
#

Need help proving for n > 16, φ(16) < n -4 where φ is the eulur toitent function

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#

Please don't occupy multiple help channels.

winged fern
#

woops leftthe other help channel

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@winged fern Has your question been resolved?

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wise field
#

How do I get the equation x^5-k=0 to equal the iterative formula shown in the picture.

wise field
#

I've found the derivative to be 5x^4

#

and the Newton Raphson Formula is xn+1 = xn - f(x)/f'(x)

#

but i still can get the answer

#

<@&286206848099549185>

safe radishBOT
#

@wise field Has your question been resolved?

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#

@wise field Has your question been resolved?

modern pollen
#

Simplify: -12/25+3/-5-1/15

wise field
#

.close

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naive agate
#

How do you find the inverse of this exponential (and logs) function?

merry sleet
#

you isolate the 2^x

#

and then apply log 2 on both sides

naive agate
#

Can you show me all the steps

merry sleet
#

can you solve for 2^x?

#

on your own

naive agate
#

I thought you had to

merry sleet
#

like replace 2x by a

naive agate
#

Swap the x and y

merry sleet
#

oh you can do that first

#

so ok swap them

naive agate
#

And then multiply the 4, 4x = -2y

#

Or something

merry sleet
#

then replace 2^y by

#

a

#

and solve for a

naive agate
#

You are saying.. 4x = a?

merry sleet
#

4x?

#

if you replac

#

e

naive agate
#

You move 4 to the other side

merry sleet
#

yeah

#

but theres the -

naive agate
#

So it’s

#

-4x?

merry sleet
#

a=-4x right

#

but we re not done

#

lets replace a by its value

#

2^y = -4x

#

now we can apply log 2 on both sides

naive agate
#

Question

#

Why is 2 not negative

merry sleet
#

wdym?

naive agate
#

-2/4

#

Only the 4 stays negative

merry sleet
#

if you have

#

-2/4

#

you only have to count opne of them as negative

#

because if its negative divided by negative

#

the result is positive

#

it doesnt matter which

merry sleet
#

you just have to multiply by -1 on both sides

#

to see its the same

naive agate
#

So it doesn’t matter?

merry sleet
#

yeah

naive agate
#

Wouldn’t that be log-2(4x)??

merry sleet
#

log -2 doesnt exist

naive agate
#

So why must it be positive 2 and negative 4

#

I don’t get it

merry sleet
#

it must not be

#

just you cant use log-2

merry sleet
#

i'm not sure if you dont understand the algebra i did before

#

or the log thing

naive agate
#

I literally just learned logarithms like a week ago

merry sleet
#

yeah but for now

#

if you ignore the next part

#

which is taking a log

#

there shouldnt be any confusion

naive agate
#

You need log to inverse an exponential don’t you though?

merry sleet
#

yeah

#

ln

#

or log base e

#

is the inverse of the exponential function

#

and log base a

#

is defined as

#

log_a(x) = ln(x)/ln(a)

#

and log_a is the inverse of a^x

naive agate
#

Ok

merry sleet
#

you can verify it by decomposing a^x

#

into

naive agate
#

Can you do one more

#

So I get it

#

?

merry sleet
#

exp(a ln(x))

#

we are not finished though

naive agate
#

Ok

#

Continue

merry sleet
#

we were at -2^y = 4x

naive agate
#

Right

merry sleet
#

you could apply log2 directly here

#

but to be sure about things

#

and not make a mistake in general

#

its better to have the power isolated

naive agate
#

If it was 2y instead of -2y, would it still be log2

merry sleet
#

it would

#

but as i said

#

the best practice if you are starting with logs

#

is to isolate 2^y completely

#

so multiply on both sides by -1

naive agate
#

4x and -2y…?

merry sleet
#

yeah

naive agate
#

I multiplied both

merry sleet
#

2^y =-4x

naive agate
#

Ok

merry sleet
#

now we can apply log2

#

we get

#

y = log2(-4x)

naive agate
#

Yea that’s the right answer

merry sleet
#

and if you know rules about logarithm

#

you can simplify

#

what is the log of a product?

naive agate
#

Uh

#

Idk

merry sleet
#

log(a*b) =log(a)+log(b)

naive agate
#

I know almost nothing on logs

merry sleet
#

so here you can do

#

y = log2(-4)+log2(x)

#

hummm maybe we messed up somewhere

naive agate
merry sleet
#

ok

#

then all good

#

if you dont need more

naive agate
#

Can you do one rq?

merry sleet
#

also maybe you need to be careful about the domain

naive agate
#

Domain??

merry sleet
#

since we are talkiung about a function

naive agate
#

Like the X axis stuff

merry sleet
#

which values are possible for x

#

yeah

#

,w plot -2^x/4

flat frigateBOT
merry sleet
#

basically the domain of the inverse is the same as the rangez of the original funciton

#

function*

#

so here its non positive numbers

naive agate
#

Cool

safe radishBOT
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dark sluice
#

hi can someone help me with a proof

safe radishBOT
dark sluice
#

.close

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lean otter
#

.close

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stray bluff
#

what is $x * x$

flat frigateBOT
#

cantprogram

safe radishBOT
#

@formal pumice Has your question been resolved?

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fiery tree
#

How exactly do I factorise this expression?

safe radishBOT
violet sundial
#

to make it easier to understand let n= (y+1)

#

so it looks like n^2 - 4n

#

@fiery tree

fiery tree
#

Yupp makes sense

violet sundial
#

alg

fiery tree
#

uh then where do I go from there šŸ˜…

violet sundial
#

make it n(n-4)

#

like n^2 -4n simplifies to n(n-4)

#

thoughts?

fiery tree
#

Still a lil confused šŸ˜•

violet sundial
#

then you have to substitute (y+1) back into n

#

from n(n-4) you get ((y+1)(n-3)

#

MAKES SENSE

fiery tree
#

Ahhh

violet sundial
#

sry for caps

fiery tree
#

Yup I've got the hang on it now I think

violet sundial
#

alr i gtg now

#

gl with it

fiery tree
#

Thanks for your help :)

#

.close

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molten finch
safe radishBOT
molten finch
#

Hello guys

#

I am not sure what the question is asking in this problem am I just need to take the derative of the function twice

#

Or do I need to find the anti deravativr#e

#

<@&286206848099549185>

static ledge
molten finch
#

So I take the anti derativr

#

And and take the anti derativr of thsy

static ledge
#

yup

molten finch
#

Is this the awnser

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#

@molten finch Has your question been resolved?

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austere kestrel
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austere kestrel
#

can someone verify my answers to see if they’re correct šŸ˜…

lean otter
#

umm

#

first pic is really hard to see

#

oh actually its gucci

austere kestrel
#

is this better?

lean otter
#

yea dw

#

@austere kestrel

#

in number 5

#

it says

#

use the number in number 5?

#

šŸ˜…

austere kestrel
#

i think that was a typo

#

it’s supposed to be 4

#

bc in our worksheets we used 33

lean otter
#

yeah i mean 1-7 seems fine if u managed to figure out the formula

#

which seems like u did

austere kestrel
#

okay okay thankss

#

i left number 8 blank bc im unsure

lean otter
#

well it just means that

#

as t increases, v decreases

#

and as d increases, v increases

#

reverse is true too

#

so what do u think it is? @austere kestrel

austere kestrel
#

is this D?

#

is it*

lean otter
#

yep

#

u r right

austere kestrel
#

ohhh okay tysm

#

hb 9 to 15?

lean otter
#

mm going over them, i am kind of doing it in my head doe so might not be completely right proofreading

#

not sure what 11 is asking for

austere kestrel
#

alright alright i’ll see tomorrow

#

I’ve already reviewed everything

#

tysm 🄰

lean otter
#

yeah i went over it

#

it seems correct for the most part, even if u did something wrong, it is probably something minimal i didn't notice

#

good job

safe radishBOT
#

@austere kestrel Has your question been resolved?

safe radishBOT
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fiery valley
#

why is 1/2?

safe radishBOT
quasi bison
#

the permutations in which z comes before a can be matched up one to one with the ones in which z comes after a

fiery valley
#

Can you please do an example?

lean otter
fiery valley
#

permutation in which z preceds a = 24! ?

#

permutation with all the letters at the same position but that of z and a interchanged = 1?

#

<@&286206848099549185>

safe radishBOT
#

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safe radishBOT
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noble sail
#

When is the algebraic multiplicity greater than the geometric multiplicity for an eigen vector

noble sail
#

what's the intuition

safe radishBOT
#

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floral hornet
#

Where did the 4/3 come from

safe radishBOT
vestal pagoda
#

volume formula

lean otter
#

hmmm i think if you are asking for its derivation, integrating using disk method is what i can think of

#

but i bet thats not what you are looking for haha

vestal pagoda
#

its a volume formula discovered by this person

floral hornet
#

Ohhhh

#

Lmfao

lean otter
#

big A šŸ˜Ž

vestal sedge
#

ive always wondered where the volume for a sphere is derived from

floral hornet
lean otter
#

can really only think of cross sections

vestal sedge
floral hornet
#

Ok also where did the x^2 + y^2 come from

#

I thought that was for a circle

lean otter
#

i mean um

#

Pythagorean theorem?

vestal sedge
floral hornet
#

Bro i rly don’t remember anything from alg😭😭😭

#

Tysm

#

Wow this was embroiled

#

Embarrassing

lean otter
#

calculus be like: i forgor šŸ’€

floral hornet
#

😭😭😭😭

#

Thank u

vestal sedge
lean otter
#

also never said it, but cultured kel enjoyer šŸ™šŸ» @vestal sedge

floral hornet
#

.close

vestal sedge
#

ty ty

safe radishBOT
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leaden scaffold
#

Is this just finding the derivative of the function or is there more to it?

vestal pagoda
#

finding derivative and settings x to 1

pseudo scroll
#

yeah

vestal pagoda
#

f'(1) = f'(x = 1)

leaden scaffold
pseudo scroll
#

no you sub x = 1

leaden scaffold
pseudo scroll
#

differentiate first

#

and in the derivative sub x = 1

leaden scaffold
#

thanks!

safe radishBOT
#

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ashen gust
#

I have a packing problem where I want to find an optimal layout for maximizing the number of nodes in a 3D grid where the rule is that nodes should be within a taxicab distance of at least 5 of each other. Any idea how to go about it? And do you expect that for this distance it's intractable?

buoyant shadow
#

it's like packing octahedrons

#

or something, there must be some shape like that

ashen gust
#

Yes, I feel like it should be some way to find it. In one dimension, the repeating pattern has 2 nodes, for 2D it has 4 nodes. I am assuming I need a pattern of 8 nodes.

#

The only way I can think of solving this problem is to maybe brute force it but... That's probably not a good idea.

#

(I have zero experience with packing, maybe there are better approaches.)

buoyant shadow
ashen gust
#

How does one even prove what the optimal packing is other than going through all permutations?

buoyant shadow
#

so like "the lattice generated by the vectors (2/3,1,1/3), (āˆ’1/3,āˆ’2/3,1), and (āˆ’1,1/3,āˆ’2/3)" may mean you;re right, it's a pattern of 4 nodes

#

i don't know

safe radishBOT
#

@ashen gust Has your question been resolved?

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@ashen gust Has your question been resolved?

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@ashen gust Has your question been resolved?

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compact ledge
#

help pls

safe radishBOT
vestal sedge
#

whats the question?

safe radishBOT
#

@compact ledge Has your question been resolved?

compact ledge
vestal sedge
#

so you figured it out yourself?

compact ledge
#

yes

safe radishBOT
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flint coyote
safe radishBOT
flint coyote
#

someone help me simplify this please

#

answer is -9 3sqrt4

untold sky
#

factorize the insides of the cuberoots to find things you can pull out of them

flint coyote
#

you cant cube 32 or 108 though right

#

oh you mean prime factorization

#

?

untold sky
#

yes and yes

flint coyote
#

ok

#

then what do I do

#

so its 3*2

#

and a 2 stays on the inside

#

for the first one would it be 6 3sqrt2^2

untold sky
#

correct, what about the second term?

flint coyote
#

then would i just simplify the numbers on the outside of sqrt since the numbers in the square root are the same

#

so final answer -9 3sqrt4

untold sky
#

also it's cube root, if you keep calling it square root it might lead to some issues eventually

flint coyote
#

oh, right

#

thanks

#

.close

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fierce stirrup
#

Hi, how do I do linear extrapolation?

safe radishBOT
fierce stirrup
#

I have one point which is x0=1 and I have the function f(x)=x^3

#

I need to find the approximation at f(x) when x = 1.01

#

is it just f(x0) = 3 and since x0=1 then we can have g=0.01 and then that would be 0.01*x0

#

1.03?

lean otter
#

Are u talking about linearization?

#

Ig that's the same name

#

I have a general question. Is the Jacobian matrix thought of as a linear transformation that changes the unit basis vectors at each point in space to create a new coordinate plane?

#

Anyways @fierce stirrup

#

where those unit vectors may or may not be "similar" at each point

#

L(x) = f(a) + f'(a)(x-a)

#

Take a = 1

obtuse plover
fierce stirrup
#

so L(1.01) = f(1) + f'(1)(1.01-1)

#

So I got L(1.01) = 3 + 3(0.01)

#

which is 3.01

#

3.03

lean otter
#

Yeah I mean

#

Approximate enough

#

Linearization is just first order Taylor series but thats a spoiler for the future catThink

fierce stirrup
#

well

#

that's the next question so xd

lean otter
#

Oh lol

fierce stirrup
#

I'm going to watch the recorded lecture for this, hopefully it is helpful, if not I'll be back šŸ™‚

#

thanks for the help

#

.close

safe radishBOT
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split fulcrum
safe radishBOT
split fulcrum
#

For part B it’s the same steps as part A?

#

But how would the line y = -1/2x change this equation formula wise

safe radishBOT
#

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split fulcrum
#

.close

safe radishBOT
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lean otter
#

Doing rational root theorem. If the problem in question has no trailing coefficient (shouldn’t be a x term) what do I do?

safe radishBOT
#

Please don't occupy multiple help channels.

lean otter
#

ignore the +0 at the end i did that

untold sky
#

well, if the coefficient is 0 you can factor out x from each of the terms and obtain a smaller polynomial with a constant coefficient

lean otter
#

I’m trash without an example for it usually just words don’t work for me

#

like in the context of above what should I try to do

untold sky
#

for example:
a polynomial x^3-5x^2+6x

as there are no constant coefficient, you can factorise x from each of the terms to get

x(x^2-5x+6)

notice how you now have a polynomial of degree 2 with a constant coefficient inside the brackets

lean otter
#

oh so it’s like you

#

moved it down a power

#

that’s all I gotta do?

#

okay

lean otter
#

Bottom question

#

Past the squiggly line

safe radishBOT
#

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compact egret
#

I'm so

safe radishBOT
compact egret
#

I'm so stuck on this shit $$(P \land R) \lor [ \neg R \land (P \lor Q)]$$ $$[(P \land R) \lor (\neg R \land P) \lor (\neg R \land Q)]$$

flat frigateBOT
#

studying lang calculus

compact egret
#

<@&286206848099549185>

safe radishBOT
#

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lean otter
#

Help me

safe radishBOT
lean otter
#

Someone anyone

#

I have proportional

#

Someone

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

I need help

safe radishBOT
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@lean otter Has your question been resolved?

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uneven gale
#

So our math teachers decieded to ruin our week by telling us to explain a picture using ratio, fractions, probability, and rates

uneven gale
#

no idea what this means

#

also its due tommorow

trim swan
#

um

#

to explain a specific picture?

uneven gale
#

yeah

#

basically anything

#

just not a.i generated

heavy terrace
#

just put a picture of a piechart lol

safe radishBOT
#

@uneven gale Has your question been resolved?

uneven gale
#

i mean

safe radishBOT
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short sparrow
#

I've asked this before but I only know how to prove it for a chosen n, not all.. here it is again:\
\
Let $A \subseteq \mathbb{R}$ be nonempty and bounded. Show that there are monotone sequences $(a_n){n\in \mathbb{N}}$ and $(b_n){n\in \mathbb{N}}$ with $a_n, b_n \in A$ for all $ n \in \mathbb{N}$ with
$$
\lim \limits_{x \to \infty} a_n \text{ sup}A \quad \text{ and } \quad \lim \limits_{x \to \infty} b_n \text{ inf}A
$$

flat frigateBOT
#

Levens

solar hazel
#

did you understand what i wrote before?

short sparrow
#

yeah not really.. i didnt quite understand how that squeeze theorem was connected to that one line youve written.. wait let me look it up

#

here it is

ashen kraken
#

Help

short sparrow
#

also, idk if im even allowed to use that squeeze theorem, if we havent addressed it yet in our lectures

toxic stratus
#

you dont have to use squeeze theorem to show the limit

#

just epsilon-N is enough

solar hazel
#

can you at least see why (a_n) converges to sup A?

short sparrow
solar hazel
#

like even if you don't have proof yet

short sparrow
#

you mean by looking at the question?

solar hazel
#

just from looking at the way i constructed the sequence

toxic stratus
#

basically "do you understand why it should work"

short sparrow
#

no actually

solar hazel
#

ok let's say A = (0,1)

#

so sup(A) = 1

short sparrow
#

ye

solar hazel
#

the sequence (a_n) whatever it is will satisfy
1 - 1/1 <= a_1 <= 1
1 - 1/2 <= a_2 <= 1
1 - 1/3 <= a_3 <= 1
1 - 1/4 <= a_4 <= 1

#

and so on

#

do you see why those conditions force it to converge to 1?

short sparrow
#

okay i see that

solar hazel
short sparrow
#

yeah, if it's monotonically increasing

solar hazel
#

yea that's the other thing

#

so you need another condition on the a_n's

short sparrow
#

where $a_n < a_{n+1}$

solar hazel
flat frigateBOT
#

Levens

short sparrow
toxic stratus
#

no need for monotonic

solar hazel
#

the question requires them to be monotone

short sparrow
#

oh

toxic stratus
#

oh it does ig

#

convergence doesnt require it tho

short sparrow
#

but it doesnt say whether theyre increasing or decreasing

solar hazel
#

yea

short sparrow
short sparrow
solar hazel
#

wdym?

solar hazel
short sparrow
#

what do you have instead? infA + (1/n) >= b_n >= infA?

solar hazel
#

sure

short sparrow
#

how did you come up with that tho

solar hazel
#

idk, i think i had this exact same problem once without the monotone requirement