#help-23

1 messages · Page 33 of 1

solar bramble
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well

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yeah

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but where would i use that identity in this problem?

safe radishBOT
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@solar bramble Has your question been resolved?

long copper
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you should start by splitting the fraction and then: $$\frac{\sec x - \tan x}{\sin x} = \frac{\sec x}{\sin x} - \frac{\tan x}{\sin x}$$
You can do that because of the common denominator (just reversing what you do if you wanted to subtract 2 fractions with different denominators)

flat frigateBOT
#

I can't believe you've done this

long copper
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@solar bramble

solar bramble
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That actually makes sense bruh

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I'll solve when I'm home

long copper
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yeah from there it's using the 2 identities since tanx/sin x is 1/cos x and sin x is the sqrt of 1 - cos^2 x

hazy sentinel
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genius

safe radishBOT
#

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safe radishBOT
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strong basin
#

Can someone help me with this? i can see here that the circumfrence is 2piR where 2pi is the measure of the full revolution in radians but i can't see how to write it for thetaR using propotions.

strong basin
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2piR/R = 2pi the angle of full revolution
so thetaR must give the length of the angle theta of revolution

marsh walrus
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i mean it seems like youre mostly there

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i think the proportion theyre looking for is like

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some ratio between the arc length and circumference is equal to your central angle and its ratio to the entire circle (2pi)

safe radishBOT
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@strong basin Has your question been resolved?

marsh walrus
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what bearlain

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you just said no solve

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but dont reply or anything

strong basin
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i was writing a more proper solution taking into account what you said

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so

marsh walrus
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ah, word

strong basin
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length of the 2piR (circumference)/angle of 2pi (full revolution)= 2piR/2pi = R
length revolution of angle theta/angle theta = thetaR/Theta = R

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i think is this about right no?

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i am just gonna go ahead an close this so that is becomes accessible to others i think we are pretty much done

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.close

safe radishBOT
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marsh walrus
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there are infinitely many channels

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but it sounds llike you are there happy

strong basin
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thanks bro

safe radishBOT
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prime cobalt
#

Hi

safe radishBOT
prime cobalt
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For a graph y=a^(kx), how would it look like if both a and k were <0

thick sparrow
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Exponent of negative number will extend the graph to the complex domain I think(?) So you will not be able to easily graph it on paper.

prime cobalt
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wait

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so both a and k can’t be negative

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but only one or the other can be?

thick sparrow
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Just think of a particular example maybe.

Consider $(-1)^{-0.5}$, so you are already taking square root on negative number, which means if they are both negative, the function value will be complex number at many (if not all) points.

flat frigateBOT
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jimmy1234

thick sparrow
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prime cobalt
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hi

safe radishBOT
prime cobalt
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is this true?

obsidian oracle
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Is 2x+1 always positive ?

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Because your second inequality is only true when both quantities are positive.

prime cobalt
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ah yes

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so if it’s not guaranteed that both sides are positive

prime cobalt
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Thank you for the help! 🙂

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lean otter
#

I don't understand this question 😭

safe radishBOT
obsidian oracle
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You consider a function f who takes input x in [-1,4]

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So f(x) is defined for x in [-1,4]

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So the questions are respectively :
a) f(-x) is defined for x in ?

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b) f(x-2)... etc

lean otter
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what do I do? Do I plug those numbers in the functions?

obsidian oracle
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The trick is that whatever you put in f(...), the "..." has to be in the domain of f, that is [-1,4]

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So f(flower) is defined for "flower" in [-1,4]

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So f(-x) is defined for... ||-x in [-1,4]||

lean otter
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-1? I'm confused

obsidian oracle
lean otter
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I'm still confused...

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Is -1 incorrect for 5a

obsidian oracle
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-1 is a single value, do you think that this is possible, considering that f(x) takes in infinite values ?

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Remember, f(expression) is defined for "expression" in the domain of f

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whatever that expression is

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So f(-x) is defined for -x in the domain of f

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
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@lean otter Has your question been resolved?

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latent summit
#

did I solve 10 b correctly?

safe radishBOT
latent summit
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I had to find the domain

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of the function

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I got that x is from minus infinity to 5

lean otter
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you are right

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you just have to find the intersection of the domain between those functions

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which you did correctly

latent summit
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.close

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vestal kestrel
safe radishBOT
vestal kestrel
#

Hello there ive been stuck on this question.As of now this is my only idea that i have been able to come with

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how do i proceed?

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<@&286206848099549185>

placid dock
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consider x^2 - kx - 1 = k if x^2 - kx - 1 >= 0 and -x^2 + kx + 1 = k if -x^2 + kx + 1 < 0

glass carbon
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and start from k>=0 because for k < 0 it has no sense

safe radishBOT
#

@vestal kestrel Has your question been resolved?

vestal kestrel
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im unclear about the explaination

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<@&286206848099549185>

safe radishBOT
#

@vestal kestrel Has your question been resolved?

placid dock
vestal kestrel
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okay sure thing 😄

safe radishBOT
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vestal kestrel
#

.reopen

safe radishBOT
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safe radishBOT
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safe radishBOT
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topaz glacier
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hello is the answer 43 degrees?
Looking for x

topaz glacier
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i took 180-40-46 = 94

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180 - 94= 86

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86/2 = 43

sonic spruce
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That’s seems correct to me

topaz glacier
#

thank you

safe radishBOT
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halcyon carbon
obtuse jackal
#

e^x and x ln a

halcyon carbon
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e^x is f(x) and g(x) is xlna

obtuse jackal
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For the chain rule yes

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This is exp(ln a * x)

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It's just kx

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For k = ln a

safe radishBOT
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full citrus
#

i'm trying to find the exponential form of $(1-\sqrt(3)) - i(1 + \sqrt(3))$

full citrus
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texit can you work plz x)

upbeat swan
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$(1-\sqrt(3)) - i(1 + \sqrt(3))$

split ether
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It's dead

upbeat swan
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lol

full citrus
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ok then ->

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so i found that |z| = 2sqrt(2)

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i'm trying to find the angle now

split ether
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Well you have sin(arg(z)) = -(1 + sqrt3)/2sqrt2 and cos(arg(z)) = (1 - sqrt3)/2sqrt2

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I'd try dividing the equations and taking arctan

full citrus
split ether
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After dividing you'll find the value of tan(arg(z))

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So arg(z) will be arctan of that value

full citrus
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the value is 1 - sqrt(3) / 1 + sqrt(3)

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there's no way to find the arctan of that

split ether
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Well just write arctan(whatever it is)

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There might be some way though

split ether
full citrus
#

ye well seen

devout terrace
#

a+bi=r(cosø+isinø)

safe radishBOT
#

@full citrus Has your question been resolved?

safe radishBOT
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idle forum
safe radishBOT
idle forum
safe radishBOT
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@idle forum Has your question been resolved?

safe radishBOT
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@idle forum Has your question been resolved?

safe radishBOT
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@idle forum Has your question been resolved?

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lean thorn
#

Does anyone have insight on how to prove this? I tried contradiction but it went nowhere.

lean thorn
#

someone helped me yesterday but I think I was still lost while talking to them

#

a friend of mine said

n = 1+1+ ...+ 1 (n times)
-m = -1 + -1 + ... -1 (m times)

But I'm not sure how how that helps

lean otter
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f(n)=nf(1)

arctic locust
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And f(1) =1

lean thorn
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I guess I'm not seeing it. That shows that f(x) = x is a group homomorphism (at least for plus), but how does that show that f(x) = x and f(x) = 0 are the only homomorphisms?

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the only is what is throwing me off

lean otter
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if f was a hom, then f(n) must be nf(1). So it remains to find out what f(1) can be

arctic locust
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It must send the neutral of Z to the neutral of Z

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The multiplicative neutral

lean thorn
lean otter
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I think thats fine

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I assume the zero ring is a ring for you too

arctic locust
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Yes I'm confused

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I just looked at the definition

lean otter
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homomorphisms dont need to be onto

arctic locust
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It must send 1 to 1

lean otter
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0 is the 1 of the zero ring

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f(1)=f(1*1)=f(1)*f(1)

lean thorn
lean otter
#

yes

lean otter
lean thorn
# lean otter then solve the quadratic in f(1)

so yeah that makes sense. f(1) = 1, so then f(1 * 1) = f(1) = 1. And f(1) * f(1) = 1*1 = 1. Then for the addition part of the homomorphism, then f(1 + 1) = f(2) = 2 and f(1) + f(1) = 1 + 1 = 2

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...I think

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I guess I'm just not seeing that those are the only ones. :(. All I see is that the zero and identity function are ring homomorphism for Z to Z, but not that they're the only ones

lean otter
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f hom => f(1)=f(1)*f(1) => f(1)=1 or f(1)=0 => id or zero

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if you aren't convinced, suppose f(1)=n not idempotent, then n=f(1)=f(1)*f(1)=n^2 contradicts idempotency

lean thorn
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idempotent

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sorry what does that mean?

lean otter
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its equal to it's square

lean thorn
#

okay thanks

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I'll chew on this some more

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thank you for the help

#

.close

safe radishBOT
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lean otter
safe radishBOT
lean otter
#

need help

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to find x

flat frigateBOT
lean otter
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find y and z first

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y = 45

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z = 60

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so x is 75 ?

flat frigateBOT
#

The following error occured while calculating:
Error: Undefined function arccos

lean otter
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;-;

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yes, thats correct

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can u help me one more

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sure

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i think x = 67.5

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find a, then b, then c, then d

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,calc (180-(180-45))/2+45

flat frigateBOT
#

Result:

67.5
lean otter
#

yay

#

ty

#

yw :D

#

.close

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fluid hare
safe radishBOT
fluid hare
#

It’s kinda hard to read

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But where are they getting the -108sin(-14) from

grizzled fossil
#

Impossible to read

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Take a screenshot

fluid hare
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One sec

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Idk if that’s any better 😂

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If you’re in a phone you can zoom and read it

grizzled fossil
#

A screenshot

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Google how to take a screenshot on … if you don’t know how

fluid hare
#

There is that readable

#

This is a different question but I still don’t know how they’re getting the final +144

#

.close

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runic rampart
safe radishBOT
runic rampart
#

why is it n-1 and not n?

#

Does that mean when n=4 for example, you do ar^0+ar^1+ar^2+ar^3?

safe radishBOT
#

@runic rampart Has your question been resolved?

runic rampart
#

<@&286206848099549185>

neat kiln
#

Because the first term is just a which means it has to be a * r^0 (anything ^0 = 1)

runic rampart
#

.close

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thin vine
#

Hi, how do i the asymptote of this graph?

safe radishBOT
thin vine
#

also, about D, can I have some hint pls ?

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safe radishBOT
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@thin vine Has your question been resolved?

thin vine
#

<@&286206848099549185>

safe radishBOT
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@thin vine Has your question been resolved?

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lean otter
#

Suppose that your salary in 2013 was $55000. For 2014, you negotiate an increase
of 5%. What is the actual increase in salary if you include inflation? Express the increase
in both absolute and relative terms.

lean otter
#

for this question i did this and i dont think its correct:

i first calculated the inflation rate with CPI values:
125.2 for 2014
122.8 for 2013

125.2/122.8
1.0195
1.9%

after that i calculated how much 55000 in 2013 would be in 2014
55000 x 125.2/122.8 = 56,074.91857

then i took 5% of that total and added it as the 5% increase
5% = 58911.1645

#

<@&286206848099549185>

safe radishBOT
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@lean otter Has your question been resolved?

safe radishBOT
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@lean otter Has your question been resolved?

safe radishBOT
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@lean otter Has your question been resolved?

lean otter
#

.close

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wind jasper
#

I don't understand this problem because I'm not sure if the y-int is viable or not

wind jasper
#

help

raw tusk
#

well i mean you can't have a negative amount of people coming to the beach

safe radishBOT
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@wind jasper Has your question been resolved?

wind jasper
#

Is the y intercept the ppl or temperature

safe radishBOT
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@wind jasper Has your question been resolved?

bitter aspen
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distant marten
#

Was just doing some past papers

safe radishBOT
distant marten
#

how do u do this again?

marsh shale
#

you know three edges of the triangle right?

distant marten
#

yeah

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10, 8 and 8

marsh shale
#

ok

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and AOB has two same edges

distant marten
#

yeah

marsh shale
#

so, what happens if you draw a perpendicular line from O to AB

distant marten
#

OOOOO

#

aight bro thanks

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trim swan
#

On the left, $\frac{d}{dx}x = 1$

flat frigateBOT
#

tatpoj

trim swan
#

And on the right, you need to use the chain rule.

#

$\frac{d}{dx}f(y) = f'(y) \frac{dy}{dx}$

flat frigateBOT
#

tatpoj

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strong basin
#

can anyone confirm if the area of this triangle is approx 200 (199.6..)

white hollow
#

not quite

#

you forgot to divide by 2

strong basin
#

ahh yes

#

i kept feeling it was wrong

white hollow
#

what formula did u use

strong basin
#

so 99.80 about a hunderd then

white hollow
#

ye

strong basin
#

1/2absin(k)

white hollow
#

👍

strong basin
#

😅

#

thanks a lot

#

.close

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twin lantern
#

I just have a sudden memory loss but what does f(x) do again

quasi bison
#

nothing, until you tell us what f and x are

twin lantern
quasi bison
#

did you mean f(x) = 3x + 7?

twin lantern
#

well yeah

#

im just rlly confused rn

quasi bison
#

do you have the problem exactly as it was given to you?

twin lantern
#

no but it was just a brief discussion and i didnt get a single thing

obsidian kestrel
#

they give you the x value just sub it in c:

twin lantern
#

oh so its like same as how you do y=mx+b(?)

obsidian kestrel
quasi bison
#

and that's what confusing you

#

maybe it was "Given f(x) = 3x+7, calculate f(4)" which is more transparent in what you need to do

twin lantern
#

.close

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white swallow
#

Since z is analytic everywhere here how can i do it?

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#

@white swallow Has your question been resolved?

white swallow
#

<@&286206848099549185>

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@white swallow Has your question been resolved?

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.close

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bitter mesa
#

bum bum

safe radishBOT
bitter mesa
#

2 homeless couples, Matcha and Lilnas, were arrested for trespassing private property. Matcha and Lilnas now needs to find a lawyer. Lawyer 1 charges a $200 fee plus $2 dollars per minute. Lawyer 2 charges a $800 fee plus $0 dollars per minute. Lawyer 3 charges a $400 fee plus $1.5 dollars per minute. The Judge has set a minimum of 1 hour inside the courtroom with your Lawyer. Which lawyer would be the cheapest option? Which Lawyer would be the most expensive option?

#

which method should i use? substitution, elimination or graphically?

safe radishBOT
#

@bitter mesa Has your question been resolved?

quasi bison
#

wow. what a grim setup.

quasi bison
bitter mesa
#

ok

#

.close

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frigid nebula
#

help me please

safe radishBOT
frigid trout
frigid nebula
#

so so @frigid trout

frigid trout
frigid nebula
#

i said 1>=cosx1/x^3>=-1

frigid trout
#

that's a good start

#

so you agree that |sin(x)|>=sin(x)cos(1/x^3)>=-|sin(x)| right ?

safe radishBOT
#

@frigid nebula Has your question been resolved?

frigid nebula
#

@frigid trout why

frigid trout
frigid nebula
#

why we take it out 1 and minus 1

#

im confused

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crisp plaza
safe radishBOT
crisp plaza
#

how?

winged flare
#

formula for simple interest is pnr/100

#

the interest is the amount - principal = 32062.50 - 30000 = 2062.50

#

2062.50 = pnr/100
206250 = pnr

#

hopefully this would give you enough thought process to finish this question

crisp plaza
#

slr

#

this is what I got...

#

is it correct?

#

done...

#

thanks man

winged flare
#

u should get 2.75 rt?

crisp plaza
#

yes...

#

why is interest -> amount - principal?

#

is it another way of getting the interest?

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zealous shuttle
safe radishBOT
zealous shuttle
#

I have an hour to answer this question

lean otter
#

Would u mind answering my question and I will try answering yours? (Idk if it will be right though)

zealous shuttle
#

I don't have much time sry

lean otter
#

It’s easy I just don’t know why bec I’m stupid

zealous shuttle
#

I answered it already

lean otter
#

I’m trying to answer yours wait

zealous shuttle
#

@ helpers

safe radishBOT
#

@zealous shuttle Has your question been resolved?

zealous shuttle
#

<@&286206848099549185>

#

<@&286206848099549185>

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#

@zealous shuttle Has your question been resolved?

hallow egret
#

I just multiplied both the probability of 1st scenario and 2nd scenario

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safe radishBOT
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@lean otter Has your question been resolved?

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@lean otter Has your question been resolved?

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@lean otter Has your question been resolved?

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subtle valve
#

Hi I'm in 7th grade and I need help understanding trigonometry

frozen forge
#

yep

#

what don't u understand

subtle valve
#

cos and sin

frozen forge
#

cos(x) is the x_axis part and sin(x) the y axis part

subtle valve
#

oh

#

ok

frozen forge
#

oh maybe you didn't do that in class

#

Did you do it only with right triangles ?

subtle valve
#

bro trig is high school level im trying to get an understanding of trig as a 7th grader

frozen forge
#

yes ok

#

sry i'm french I'm not used to grades and stuff

subtle valve
#

its alr

frozen forge
#

i'll not be able to explain to u sry for that

subtle valve
#

its alr thx for trying tho

frozen forge
#

because of my english

subtle valve
#

.close

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upper willow
#

.reopen

safe radishBOT
true estuary
#

am i doing it correctly?

#

and what would the prob. of F be?

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#

@true estuary Has your question been resolved?

true estuary
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.close

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craggy trout
safe radishBOT
craggy trout
#

So I'm looking for an angle between (-pi/2 , pi/2) where tan = 0?

#

I think the only two angle that meet that would be pi/2 or -pi/2

#

But that doesn't seem to be right

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naive umbra
#

Hi

safe radishBOT
naive umbra
#

(bn) is a geometric sequence with b1=-3 ,q=-2 , Is -96 a term of this sequence?

#

Pls help

plucky elk
#

b1 the first term?

#

or 2nd?

naive umbra
plucky elk
naive umbra
#

and q is common ratio

plucky elk
#

do you know the general term?

naive umbra
#

bn=b1 * q^n-1

plucky elk
#

looks right.

#

did you plug in 3 and -2?

#

and then -96 for bn to solve for n?

naive umbra
#

ik the answer is no but when i try to solve it i get n=6

#

n=6 means its a term of sequence so i dont know what im doing wrong

plucky elk
#

did you plug in n=6 to check your answer?

plucky elk
naive umbra
plucky elk
#

,calc (-3) * (-2)^(6-1)

flat frigateBOT
#

Result:

96
plucky elk
naive umbra
#

ok ty

#

.solvw

#

.solve

#

.close

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#
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stray palm
safe radishBOT
stray palm
#

what is this trying to say

#

i dont understand what this question wants me to do or say

plucky elk
#

look at the conclusion of the ratio test

stray palm
#

oh i see

#

so a is divergent, b is absolutely convergent, and we cant say anything about c?

#

.close

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wary wave
#

A box contains 6 coach bolts and 4 hex bolts. Two bolts are drawn at random one after the other without replacement. Draw a tree diagram and then use this to find the following probabilities. Give your answers as exact fractions.

wary wave
#

What is the probability that you draw out no more than one coach bolt?

#

so if there is a 6/10 chance for a coach bolt

#

and a 4/10 chance of getting a hex bolt

#

then if on the first pull u get a coach bolt

#

its a 6/10

#

and then u want a hex bolt

#

which is a 4/9

#

no?

safe radishBOT
#

@wary wave Has your question been resolved?

safe radishBOT
#

@wary wave Has your question been resolved?

wary wave
#

could someone please help with this 🙂

safe radishBOT
#

@wary wave Has your question been resolved?

tulip hearth
#

I'm not sure if I know this but I'll give it a go: we can say there were 10000 cases so it is easier to do the math. So there are 4% defective cases that is 400 and of those 400 - 300 were detected positive and 100 were falsely detected to be good. 9600 cases weren't defective and of those, 960 were detected defective and 8540 were correctly detected. If microchip was good: that are the ones falsely detected as good and the ones correctly detected as non-defective: 8540+100. And that is what goes into our denominator of probability formula. So the end expression would look like: 100/8640 because that is the number of the 'fake' good ones and total number of good ones.

#

Drawing a tree helps calculating this

#

So the result for a) should be 10/864

#

If that is correct then hopefully you can figure the logic out I will go to sleep now, if not then I'm probably wrong

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lean otter
#

how they converted it ................ that underlined part?

stray socket
#

What is f(1-sqrt3)

lean otter
#

u want question?

#

@stray socket

stray socket
#

Well yeah I know but

#

Look at the outputs of f(x)

#

Is 1-sqrt3 rational or irrational

lean otter
#

rational

#

so i don't have to figuare out the value if it is rational the answer is -1

#

is that how it works?

#

@stray socket

stray socket
#

It's not rational and don't ping me every 2 seconds

#

Why would it be rational if there's a sqrt(3)

lean otter
#

sry

stray socket
#

Is sqrt(3) a number that can be represented as a terminating decimal? No. So 1-sqrt(3) is irrational

#

That means that f(1-sqrt(3)) is 1

#

So f(f(1-sqrt(3))) is f(1)

#

But like that's also easy because is 1 rational or irrational

lean otter
#

k

stray socket
#

Is 1 irrational or rational

lean otter
#

rational

stray socket
#

So what is f(1)

lean otter
stray socket
#

Yeah

#

Therefore f(f(1-sqrt(3))) = -1

lean otter
#

k

#

thx

#

.close

safe radishBOT
#
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lean otter
#

which is the value i should consider taking here for x?

lean otter
#

that x in g(x) after '+x' is modulus right?

stray socket
#

Absolute value

lean otter
#

what is that

#

isn't that the same?

#

the answer is this

#

but if i take a -ve integer i am getting -ve value

#

or is there anything saying i have to take +ve integer?

#

<@&286206848099549185>

warm stirrup
#

modulus is bri'ish i think

warm stirrup
#

that notation is usually used for floor(x)

stray socket
#

Who the fuck calls it modulus that sounds like modulo

#

What kind of British juju is that

#

I swear the British 💀

lean otter
#

how do i slve it

warm stirrup
lean otter
#

but if i take -ve there wouldn't that ans be also -ve?

warm stirrup
#

negative of what

lean otter
#

i mean g(-2)=1-2-2=-3

warm stirrup
#

-floor(-2)=2

#

not -2

lean otter
#

k

#

.close

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#
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surreal spade
safe radishBOT
surreal spade
#

how would you do this quefstoin

#

I used u substitition

#

jbut I didn't get any of the answers

#

?

stray socket
#

Well you have a quadratic

#

Set u = cos(2x)

surreal spade
#

yes

#

i got

fickle osprey
#

problem is
the answers are not in usual range

surreal spade
#

(2u - 1)(u + 1)

stray socket
#

I mean

#

The answers are between 0 and 2Pi

fickle osprey
#

so technically 3pi/2 works
since pi/2 Is the anserr

stray socket
stray socket
#

Plug those values back into u

surreal spade
#

you need to

#

use 2x

stray socket
#

$$\frac{1}{2} = \cos(2x)$$
$$-1 = \cos(2x)$$

surreal spade
#

cosv = pi /3, 5pi/3, and pi

flat frigateBOT
#

Umbraleviathan

stray socket
#

You can solve for x

surreal spade
#

x = pi/6, 5pi/6

#

and pi/2

fickle osprey
#

yeah
since the domain is not mentioned.
you can plug infinite values.

#

so go by options

stray socket
#

Mmhm

surreal spade
#

so

#

we

#

check

#

what values

#

are coternimal with

#

whatever x is equal to

stray socket
#

Also recall that cos(x) = cos(-x)

#

So you have to choose answers coterminal to -x

fickle osprey
#

only one option has pi/6
and it's in 4th quadrant.

and other answer is odd multiple of pi/2
3pi/2 is also an answer

surreal spade
surreal spade
#

isn't that wrong though

#

like

stray socket
#

Not really

surreal spade
#

cos pi/3

#

is that the same

#

as

#

cos -pi / 3

stray socket
#

When you take the cosine of them, yeah

surreal spade
#

1/2 or 1/2

#

oh

#

nvm

stray socket
#

,w Plot cos(x)

flat frigateBOT
stray socket
#

,w plot cos(-x)

flat frigateBOT
stray socket
#

Same thing

surreal spade
#

ok ok

#

thanks

#

so far

#

3pi/2 is one answer

#

11pi / 6 should be another answer

#

so would it just be I and IV

stray socket
#

Let's check

#

,w NSolve[{2(Cos[2x])^2 + Cos[2x] - 1 == 0, 0 <= x <= 2Pi}, x]

#

Okay well what a loser

#

Watch it break

#

Yeah idk what its doing

flat frigateBOT
stray socket
#

Oh okay

#

There you go

#

@surreal spade you can check now

surreal spade
#

Ok thanks

#

.close

safe radishBOT
#
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sonic sapphire
safe radishBOT
sonic sapphire
#

wondering if I did this right

#

I guess how would I check

#

oh lorty

#

I did somethin wrong

#

I think

#

I don't get the same answer as wolfram

#

sheit

safe radishBOT
#

@sonic sapphire Has your question been resolved?

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misty marsh
#

Disregard the stuff I crossed out

safe radishBOT
misty marsh
#

Why is my work wrong

#

<@&286206848099549185>

cloud fjord
#

Like

#

Sum up the middle and bottom one

#

And then separately triplicate the middle one and substract it from the top one

#

So you have a systme of equations for x and y

#

You solve it and then you get z

misty marsh
#

I did

#

Can u figure out what specifically made my solution set wrong? Symbolab gives completely different answer

misty marsh
#

<@&286206848099549185>

cloud fjord
#

Oh.. then I'm done thonkg

#

I'm too much of a mortal yet

misty marsh
#

What’s s mortal

#

Lol

cloud fjord
#

Huh?

misty marsh
#

U type in s mortal but u edited it to a mortal

cloud fjord
#

Yeah

#

My bad

misty marsh
#

Oh it’s ok

#

Do I have to start a new post

#

For my question

cloud fjord
#

I don't think so

misty marsh
#

Ok

cloud fjord
#

You pinged twice so there must be somebody

misty marsh
#

👍 thanks for trying to help me

cloud fjord
#

Np

misty marsh
cloud fjord
#

So i suppose you can ping more than once

#

Certainly, after waiting for a while

safe radishBOT
#

@misty marsh Has your question been resolved?

misty marsh
misty marsh
#

<@&286206848099549185>

plucky elk
#

Can you clean it up and re-send

misty marsh
#

Sorry I forgot to mention just disregard the stuff that is crossed out

#

<@&286206848099549185>

misty marsh
#

<@&286206848099549185> hopefully u understand my work now

#

The stuff that crossed out is supposed to be disregarded

misty marsh
#

<@&286206848099549185>

misty marsh
#

Hello

safe radishBOT
#

@misty marsh Has your question been resolved?

safe radishBOT
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neon island
safe radishBOT
neon island
#

Just need to know if the answer is correct

#

Please

haughty flower
#

there can be no fix value to this answer

#

its based on your assumption

marsh shale
#

#1 is correct

graceful sorrel
marsh shale
#

gravity acceleration

haughty flower
#

we take the displace 0

graceful sorrel
#

no like

haughty flower
#

and gravity is about 1/2 g right?

graceful sorrel
#

is it 9.8 X 0.10?

thin narwhal
#

thats nowhere on the choices

graceful sorrel
#

also there has not been value given

#

like idk

graceful sorrel
thin narwhal
#

human reaction time: 0.10s+
gravity: 9.8m/s

#

not enough info given tbh

graceful sorrel
#

ye thats what i mean

thin narwhal
#

oh between ur fingers

#

but where between ur fingers??

graceful sorrel
#

any

#

i suppose

#

dont really matter tbh

hasty folio
#

This can be done im many ways

#

What I like doing is graphing it

#

if u have 9.8 m / s ^2

#

As you acceleration

#

And the integral of the acceleration is the velocity

#

what will your velocity be?

graceful sorrel
graceful sorrel
hasty folio
graceful sorrel
graceful sorrel
#

like saillboy says

safe radishBOT
#

@neon island Has your question been resolved?

neon island
safe radishBOT
#
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graceful sorrel
safe radishBOT
#
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autumn tendon
#

Hey does anyone know how to find the area of the triangle on the left

autumn tendon
acoustic wolf
#

1/2bh?

#

just 1/2 * 3 * 2

frozen forge
#

no

autumn tendon
#

No the 3 is not the height of the whole side

#

It's just the blue line

frozen forge
#

You want the blue triangle right ?

autumn tendon
#

Yep area of blue triangle

frozen forge
#

nos ry

acoustic wolf
frozen forge
#

cause b is the long blue side

autumn tendon
#

Because the 3 is not the whole length of the side

frozen forge
#

and h isn't 2 either

acoustic wolf
#

wdym?

autumn tendon
#

It's only the blue side

acoustic wolf
#

the base is 3?

#

for the left blue triangle

#

the height is 2

#

please explain how either arent?

autumn tendon
#

The height of the triangle is from the apex to the center of the base

frozen forge
autumn tendon
#

Yeah

acoustic wolf
#

its the perpendicular height no?

#

which is 2 in this case

autumn tendon
#

Ohhhh really

frozen forge
acoustic wolf
#

no I am not

#

the perpendicular height is the same

frozen forge
#

how is that ?

acoustic wolf
#

i cant draw it bc i broke my right thumb

#

but ill try to explain

#

the area of a triangle

#

is a half

#

multiplied by the base

#

which is 3 in this case

autumn tendon
#

Ahhh so the height used is perpendicular

frozen forge
#

yes ik

acoustic wolf
#

multiplied by the perpendicular height

#

which is 2

#

perpendicular from the base

#

you can see the right angle

#

im not counting the red area

#

but im using it to show that it is the perpendicular height

frozen forge
#

but the base isn 't 3

acoustic wolf
#

why not?

frozen forge
#

isn't my draw right ?

acoustic wolf
#

that would be correct

#

if the hypotenuse was the base

#

because your line is perpendicular to the hypotenuse

#

but in this case that is not the base

#

we are using a side of the triangle

frozen forge
#

ok i got it

acoustic wolf
#

ok cool

#

sorry if I wasn't clear

#

your questions were totally fair

#

i may have not explained it well

autumn tendon
#

So then for the right triangle

acoustic wolf
#

quick thing mate

#

in future

#

send ur question in the first message in the channel

#

so when people check pins

#

they see the diagram

#

not a big deal

autumn tendon
#

Base is 4 height is 3?

#

Oh yeah sure ok soz

acoustic wolf
#

all good

#

that is right

#

so you get 6km^2

#

the 10km is a decoy

autumn tendon
#

💀

#

Ok

acoustic wolf
#

unless you try to use pythagoras' theorem

#

to solve

autumn tendon
#

That makes sense thanks

#

Yeah

#

:P

#

You could do it using that

#

Thank you tho

acoustic wolf
#

all good mate

#

have a good evening

autumn tendon
#

You too byebye

acoustic wolf
#

can u close this room mate

safe radishBOT
#

@autumn tendon Has your question been resolved?

#
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fallen thunder
safe radishBOT
fallen thunder
#

Does anyone know how to approach this?

safe radishBOT
#

@fallen thunder Has your question been resolved?

safe radishBOT
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late lintel
#

A group of 9 friends will play two different board games at the same time. Both board games are designed to be played by a minimum of 2 and a maximum of 8 people at the same time. How many different rosters can they start the game with if everyone is playing.

Answers:
(A)282
(B)286
(C)492
(D)494
(E)526

safe radishBOT
#

@late lintel Has your question been resolved?

late lintel
#

<@&286206848099549185>

safe radishBOT
#

@late lintel Has your question been resolved?

late lintel
#

okay

#

found out this is an arithmetic problem

#

and wrote up the ways the rosters can be

#

7-2
6-3
5-4
4-5
3-6
2-7

white hollow
#

yeah

white hollow
late lintel
#

got it

#

thanks

white hollow
#

have you done anything past this?

late lintel
#

no i didn't

white hollow
#

alright

late lintel
#

i know we gotta do something with that combinatorics formula

white hollow
#

first,
we can half this in 2
7-2
6-3
5-4
4-5
3-6
2-7

late lintel
#

but i dont know how to write this things up

white hollow
#

we only need to look at
7-2
6-3
5-4

late lintel
#

yes

white hollow
white hollow
# late lintel yes

cus then we can multiply it by 2, as the board games don't distinguish in any way

#

so let's start with 7-2

#

how can we choose 2 people, from 9?

late lintel
#

9c2

white hollow
#

in how many ways

#

ye

#

which is..

late lintel
#

i hope this will work

#

,calc 9c2

flat frigateBOT
#

The following error occured while calculating:
Error: Undefined symbol c2

white hollow
#

lol

#

come on you can do it in your head

late lintel
#

36

white hollow
#

ye

#

alright, now how about 3 from 9

late lintel
#

9c3

#

84

white hollow
#

you seem like you know how to do this bro :)

#

continue the logical pattern

late lintel
#

9c4

#

126

#

,calc 36+84+126

flat frigateBOT
#

Result:

246
late lintel
#

,calc 246*2

flat frigateBOT
#

Result:

492
late lintel
#

answer 492 right?

white hollow
#

yep ;D

late lintel
#

i love you

#

ahaha

white hollow
white hollow
late lintel
#

so i should have written it like this

#

thank you for the help again

white hollow
#

no problem

#

I gotchu

late lintel
#

you are like my second teacher to me at this point

white hollow
#

ahaha

late lintel
#

i go close this chat

#

byebye

#

.close

safe radishBOT
#
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worldly remnant
safe radishBOT
worldly remnant
#

A bit confused on how to solve this

lean otter
#

,rotate

flat frigateBOT
lean otter
#

if it's 5, try to remember third angle theorem

safe radishBOT
#

@worldly remnant Has your question been resolved?

lean otter
# flat frigate

clue, the length of BG and FD are congruent. therefore, the angle DFA and GBF are also the same

safe radishBOT
#
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fading crypt
#

Hey

safe radishBOT
fading crypt
#

I have an exercise but in french

#

And i need some help

hallow egret
#

Translate it please so that others can read it, or just translate the question that you need

safe radishBOT
#

@fading crypt Has your question been resolved?

#
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arctic ingot
#

Where can i find example exercises, to check if multivariable function is differentiable in point, with solution and explanation?

safe radishBOT
#

@arctic ingot Has your question been resolved?

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lean otter
#

hello i need help with part B

safe radishBOT
halcyon carbon
#

Find the equation of the line and set y=0

lean otter
#

wouldnt it be y=mx+b

#

m is the slope so

frozen forge
#

that's the form

frozen forge
#

now u need b

lean otter
#

so it would be y=-1x+b

frozen forge
#

yes

lean otter
#

if i switch x and y for any others i would get it

frozen forge
#

get what ?

lean otter
#

so 0 and 10

lean otter
#

so 0=-1*10+b

frozen forge
#

go ahead

#

Yes that's it

lean otter
#

but how does that help with part b im still stuck

frozen forge
#

Otherwise, you can think that P is in L and as x = 0, 10 is the height of L for x = 0

#

But that's it

#

You got b=10

lean otter
#

yes

#

wait one sec

lean otter
#

wait it would still be the same

frozen forge
#

i don't really understand what you mean by switch the X and Y

#

But it works so i guess that's because i'm not english

lean otter
#

x is 0 and y is 10 in the very first equation

frozen forge
#

Yes

#

Why would you switch them ?

#

You already got 10 = 0 + b

lean otter
#

true

frozen forge
#

ok

lean otter
#

and because we finished the first equation

#

we have 0=10*-1+10

#

right?

frozen forge
frozen forge
#

I mean you always have 10 -10 = 0

lean otter
#

yeah kinds its from solving part A

frozen forge
#

Oh ok you apply the -1 of the slope

#

i got it

#

but why is it relevant ?

lean otter
#

I just didn't understand its relevance to part b

frozen forge
#

Look

#

Now you have y = -x + 10