#help-23

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arctic locust
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Yup

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Because there was an exercise like that in one of their homeworks

safe radishBOT
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jagged sequoia
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anyway thanks 🙌

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lean otter
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open wing
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Hello

lean otter
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hi

open wing
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Does anyone know electronic

lean otter
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.

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lean otter
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lean otter
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bro aint no way

bold ferry
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my final statement on this: if you want help understanding how to solve this, we're here for you, but no one in this server is going to merely give you the answer (it isn't allowed anyway).

lean otter
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nah i might have to server hop then cause aint no way ima get no where by dudes tryna explain this junk to me ☠️

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torn yoke
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Is there such thing as a function that is differentiable nowhere on the real line but everywhere on the complex plane?

lean otter
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the real line is a subset of the complex plane

torn yoke
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well i mean excluding the real line

peak estuary
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do you still want it defined on the real line? continuous?

torn yoke
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i mean sure

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it doesn't really affect my question

peak estuary
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well if it is allowed to not be defined on the real line then the answer is trivial

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just don't define it there

torn yoke
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ah i see

lean otter
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and if defined but not continuous on R, maybe this works? 0 on C\R, 1 on Q, 2 on R\Q

torn yoke
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like a relatively well known function

lean otter
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it's a function already

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what do you mean by well known?

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most well known functions are holomorphic

peak estuary
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the point is, if you don't actually put requirements on the function on the real line, then coming up with counterexamples is not hard. take any function that is holomorphic on all of C and just change their definition on R "randomly"

torn yoke
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I see

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thank you

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south linden
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beyond confused on how to solve

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south linden
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my work so far ^

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@south linden Has your question been resolved?

sharp crane
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hey @south linden

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i recommend extending your sketch to include the shadow tip first :)

south linden
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yes ended up figuring it out

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wooden shell
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Hello Im having a problem with this image

safe radishBOT
wooden shell
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This

sharp crane
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whats the problem

wooden shell
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I really don't understand it

sharp crane
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you want the blue area right?

wooden shell
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Idk

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It's my teacher

sharp crane
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blue area = area of square - area of circle

wooden shell
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I really don't know

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But maybe

wooden shell
sharp crane
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hi yes

wooden shell
sharp crane
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for?

wooden shell
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I'm confused

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Can you explain?

sharp crane
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if you have a square shape and you cut out a circle from it, then you get the blue area

wooden shell
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So 28×28?

sharp crane
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that would be the square's area

wooden shell
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Half?

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.close

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sonic sapphire
safe radishBOT
sonic sapphire
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when you sub dx with du, do you need parentheses?

sudden birch
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Isn’t the derivative of x+5 is 1?

lean thorn
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check your du calculation

sonic sapphire
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o shet

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brain is poops today

lean thorn
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also, you need to get rid of that x

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similar to the previous problem

sonic sapphire
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ty ty

lean thorn
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$u= x + 5 \implies x = u - 5$

flat frigateBOT
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MellowDramaLlama

lean thorn
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for a substitution

sonic sapphire
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ty

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u r goated mr or misses llama

lean thorn
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llamas transcend gender expression

sonic sapphire
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ic ic, well the llama is goated

lean thorn
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we simply are

lean thorn
sonic sapphire
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sonic sapphire
safe radishBOT
sonic sapphire
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I hecked somethin up

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rofl I see my mistake

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solid shell
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How do I go about converting a three-dimensional parametric equation into a x+y+z=0 sorta equation?

solid shell
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I have $\alpha (t) = (2t+1, 3t, -4t+1)$

flat frigateBOT
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lexitorius

solid shell
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And I want to find the point in xy where that line intercepts the z=0 plane

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So I figured I'd plug z=0 into it, but I'm not sure how to do that when it's in parametric form

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I could turn $\alpha (t) = (2t+1, 3t)$ into slope-intercept form via substitution, just not sure how to do it in 3d

flat frigateBOT
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lexitorius

solid shell
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Oh durr I figured it out

trim swan
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It's never gonna be in a form like Ax+By+Cz = 0 because that's a plane

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and your parametric equation is a line

solid shell
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Just had to find what value of t made z = 0

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Being 1/4

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Then plug 1/4 into the parameters for x and y

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Lol I always do this, make a help channel right before I figure it out myself

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Sorry to waste your time lmao

trim swan
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To find where it intersects the xy-plane, right?

solid shell
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Yeah

trim swan
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You didn't waste my time lol

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no problem

solid shell
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👍

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jaunty sandal
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Solving quadratic equations by factoring

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plucky elk
jaunty sandal
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2s^2-4s=70

compact ferry
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s^2 - 2s - 35 = 0

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now use that

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(s-1)^2 = s^2 - 2s + 1

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s^2 - 2s - 35 = (s-1)^2 - 1 -35 = 0

compact ferry
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(s-1)^2 - 36 = 0

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(s-1)^2 = 36

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s-1 = 6 or s - 1 = -6

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s = 7 or s = -5

jaunty sandal
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Ok

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how do I solve 42= x^2 -x

compact ferry
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same way

jaunty sandal
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What’s it called ion really get it

jaunty sandal
thin bridge
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rearrange to general form

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note that all terms have a common factor and the equation can be simplified

jaunty sandal
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How do u get to that after the general form and doing all that

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Like what do I do now with 3x^2+9x=30

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Into x^2 +3x -10 =0

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Is x=2 and x=-5 the right x intercepts for it being solved ?

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Think I got it

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On C what do I do with the fractions

safe radishBOT
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@jaunty sandal Has your question been resolved?

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lean otter
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quick chemistry question

safe radishBOT
lean otter
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if I have 0.75M of HCl

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does that mean I have 0.75 moles of HCl?

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I know M is molarity

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which is Moles/Liter

lean thorn
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yep basically

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$0.75 M = \frac{0.75 \text{Moles}}{\text{Liter}}$

flat frigateBOT
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MellowDramaLlama

lean thorn
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It also means $\frac{\text{3 \text{ Moles}}}{4 \text{ Liters}}$

flat frigateBOT
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MellowDramaLlama

lean thorn
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or 3 moles of HCL per 4 liters

lean otter
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Ok next part

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there’s my balanced equation

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There are two moles of HCl

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That’s the question being asked

lean thorn
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oh that I have no idea. This is mostly for math. I just know ratios and units lol

lean otter
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oh okay

lean thorn
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I haven't done chemistry in so long I couldn't tell you if that's right or wrong

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there's a discord called Homework Help though

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they're great with chemistry questions

lean otter
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do you have a link inv?

lean thorn
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I'll send you a DM w/ an invite

lean otter
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ah okay

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thanks

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I have one more problem after this one then ill be done

safe radishBOT
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@lean otter Has your question been resolved?

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ionic juniper
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ok i solved the derivative of this

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wait

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wrong one

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ionic juniper
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.close

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.close

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opal cairn
#

Let $\vec{G}$ be a digraph that is not Eulerian, but where its underlying (undirected) graph $G$ is Eulerian. Show that $\vec{G}$ does not have a directed Eulerian trail.

flat frigateBOT
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e57721

opal cairn
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I think $\vec{G}$ is weakly connected and have the result:

a weakly connected digraph $\vec{G}$ has a directed Eulerian trail if and only if at most two vertices have their indegree and outdegree unequal in which case for one of them $u \in V(\vec{G})$ : $d^+(u)-d^-(u)=1$

i don't know how to apply it though

flat frigateBOT
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e57721

safe radishBOT
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@opal cairn Has your question been resolved?

safe radishBOT
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@opal cairn Has your question been resolved?

opal cairn
#

<@&286206848099549185>

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@opal cairn Has your question been resolved?

safe radishBOT
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@opal cairn Has your question been resolved?

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hushed pier
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How do I develope (3x + 5)^2.
I am stuck on the formula of (a+b)^2= a^2 - 2ab + b^2

quasi bison
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you misquoted the formula

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you write

(a+b)^2= a^2 - 2ab + b^2
when the correct formula would be
(a+b)^2 = a^2 + 2ab + b^2

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aside from this, a simple careful application of this formula should get you what you want.

safe radishBOT
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hard bobcat
safe radishBOT
hard bobcat
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How would I set up the mass formula?

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I'm confused on the formatting

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@hard bobcat Has your question been resolved?

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@hard bobcat Has your question been resolved?

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upbeat peak
#

What does it help me to know AC and BD are perpendicular? BE = DE is also given ABCD is a square prove ABCD is a kite

upbeat peak
#

?

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???

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<@&286206848099549185>

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@upbeat peak Has your question been resolved?

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lean otter
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lean otter
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correct?

safe radishBOT
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tall cedar
safe radishBOT
tall cedar
#

help please

marsh shale
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what did you try?

tall cedar
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i got something like bc+1+c /abc = 25/36

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how do i proceed from here

marsh shale
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ok, maybe share your progress from the start?

lean otter
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i will write that on my ipad

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give me a sec

tall cedar
marsh shale
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ok, your result is correct, with the right bracket

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so, it's three variables and two equations correct?

tall cedar
lean otter
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try this

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i am not sure, but it might be help you

marsh shale
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bc + c + 1 = 25
abc = 36

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right?

tall cedar
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it doesn't look correct

tall cedar
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but

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it could also be like

marsh shale
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yeah that's true

lean otter
marsh shale
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but still the above could be true

tall cedar
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bc+c+1/bc = 25 and 1/a = 1/36

marsh shale
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yeah but a,b,c are all integers

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so, this kind of combination won't be possible

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only possible scenario other than my equations above is
bc+c+1 = 50
abc = 72
etc

tall cedar
lean otter
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o yes

marsh shale
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it doesn't

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no proof whatsoever. I just feel it

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so, instead of thinking about all possible scenarios, as I suggested, just think of one solution

tall cedar
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this just leaves me in more doubt

dry hazel
#

(1+c)b = 24
abc = 36
36 has factors 1,2,3,4,6,9,12,18,36
24 has factors
1,2,3,4,6,8,12,24

If you look at the first equation c+1 tells you that you probably want factors that differ by 1 so that places a limit on what c can be

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wait uh

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ywah so c is a factor of 36
c+1 is a factor of 24
the only value for c that makes this possible is 1

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actually

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theyre all greater than 1 i did something wrong holup

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doing math on a phone sucks

marsh shale
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as I said, there are many different ways that the equation (bc+c+1)/abc = 25/36 could work, and I'm not saying the only possible way for it to be true is bc+c+1=25 and abc=36. it's one potential way for it to work, so first calculate it, and then go from there

dry hazel
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yeah

marsh shale
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and again, I know almost certainly that abc=36

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i don't have a proof yet but

dry hazel
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oh silly me its not (1+c)b its (1+b)c

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and I somehow forgot 3 is a factor of 36

tall cedar
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i also wanted to ask

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when is √x + √y = √(x+y) true?

dry hazel
#

anyways if we assume abc=36 and bc+c+1=25

(1+b)c = 24
abc=36

so you have that b is a factor of 36, and b+1 is a factor of 24

marsh shale
tall cedar
dry hazel
#

yeah and if you look at all the factors theres only a few available choices

tall cedar
marsh shale
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of course not

tall cedar
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is there a proof or something ?

dry hazel
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try squaring both sides

tall cedar
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what about it

marsh shale
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and the right side will be x+y

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so...

tall cedar
#

oh 0 = 2√xy

dry hazel
#

yep

marsh shale
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the first value I mean

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which means bc+c+1/bc is always a fraction

tall cedar
#

got it

#

.close

safe radishBOT
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unique basalt
#

how to understand derivatives of e?

safe radishBOT
#

Please don't occupy multiple help channels.

unique basalt
#

for example why is

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why is this equal to

flat frigateBOT
#

cookie2

unique basalt
#

due to power rule

tall cedar
plucky elk
safe radishBOT
#

@unique basalt Has your question been resolved?

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split ether
#

Where did you get x^2 from

lapis pulsar
#

ah u did (x+4)(1+x)

split ether
#

Where do you see x being multiplied by x?

lapis pulsar
#

na its x + 4(1+x)

#

only the 4 is multiplying (1+x) not (x+4)

safe radishBOT
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brittle crystal
safe radishBOT
brittle crystal
#

how would i start this

#

or at least what does the top part mean

plucky elk
#

use the definition?

#

evaluate [-3.5] and [-3.1] and [-3.01] first if it helps

brittle crystal
#

so just sub those values in for x?

plucky elk
#

that's just the start.

#

once you have an idea for the answer, then you prove it using the definition

brittle crystal
#

where did you get those numbers from though

plucky elk
#

this is your definition

#

have you never done one-sided limits?

brittle crystal
#

not really i might just watch a few videos on it

plucky elk
#

yea do that

marsh shale
#

so it's asking "what's the limit of floor(x), when x approaches -3, from the left side (lower side)?"

#

which means you're increasing x from -100, -90, ... ,-4, -3.5, -3.2, -3.1, -3.09, -3.0001, -3.000000000000001, etc

#

but not -3 itself

plucky elk
#

yes

marsh shale
#

sometimes both "lower limit" and "upper limit" may exist or only one of them

brittle crystal
#

yea i understand all that with a graph and stuff but i have no idea what do to with these questions when its worded differently

marsh shale
#

if both exist, we say the (general) limit exists

brittle crystal
#

like what you said makes perfect sense

marsh shale
#

ok, so what's the limit from the question?

brittle crystal
#

then i look at the question and im lost as to how to start it

marsh shale
#

just calculate floor function value of each of these values: -100, -90, ... ,-4, -3.5, -3.2, -3.1, -3.09, -3.0001, -3.000000000000001

#

and see if it converges into a certain number

brittle crystal
#

so just sub those numbers in for x

marsh shale
#

yeah

brittle crystal
#

but when you sub it in theres no x value so what do you do then

#

.close

safe radishBOT
#
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hollow bison
#

Hello! Got a little problem to solve here and I can't wrap my head around it.

f belonging to C^4[0, 1]. calculate the estimate of the interpolation using hermite interpolation

hollow bison
#

the problem is already solved, but i still dont understand what's going on

#

spline interpolation is too much for my small brain...

#

it's in romanian, but if you need translation i can help

safe radishBOT
#

@hollow bison Has your question been resolved?

hollow bison
#

<@&286206848099549185>

#

still stuck without understanding how can i calculate the error of this hermite interpolation

arctic locust
#

Could you please translate it (at least the question)?

hollow bison
#

it says that i need to calculate the error of the hermite interpolation (using Hermite cubic spline)

#

the function is a 4th order polynom

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#

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hollow bison
#

.close

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viscid spire
#

I was thinking of doing 1/n which would be bigger than 1/n!. but that diverges

#

so I don't think that would help me

stray socket
#

Okay well

#

I mean it's one of those sum identities

#

So if you what it converges to you can just say that

#

Otherwise you can use ratio test

viscid spire
#

i have to use the direct comparison test though

#

oh I got it nvm

#

thanks though

#

.close

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flint abyss
#

Please help I don’t know what I did wrong

plucky elk
#

what's the period of the wave?

#

and what's the period of your equation?

flint abyss
#

Never mind I figured it out instead of pi/3 it was pi/5

#

Thank you Riemann for the fast reply

#

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viscid tartan
#

trying to prove sequence sin(pie N/7) dosent converge using subsequence collerary

viscid tartan
#

need help

#

need to find 2 sub sequences where they both converge to 2 diff limits

#

used sub sequnce a_7n = sin(pie N) = 0 for all N? which converges to 0

#

cant find other sequnce

obtuse jackal
#

The sequence is periodic and nonconstant. Isn't that simpler ?

viscid tartan
#

yh but we have to use this method

#

of subsequnces

obtuse jackal
#

I guess technically you just use that knowledge to find another subsequence

viscid tartan
#

yh

obtuse jackal
#

Since then any sequence of the form (14N + k) will lead to a constant subsequence. That gives you 7 different limit points

viscid tartan
#

?

#

subsequnce must be of single varibale

#

either n or k not both

obtuse jackal
#

Take k = 1 then

#

Try to understand the object you're working with

safe radishBOT
#

@viscid tartan Has your question been resolved?

viscid tartan
#

Yeah thanks

safe radishBOT
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tame charm
safe radishBOT
tame charm
#

How do I solve for p and q?

#

(Assume that all variables are known except for the primes p and q. Also, N is large, so taking eth roots mod N is infeasible.)

peak estuary
#

do you have a reason to think this should be easily solvable?

#

seems like it is essentially equivalent to taking e'th roots in the end

tame charm
#

It’s a challenge on this website

peak estuary
#

well it just says rearrange

safe radishBOT
#

@tame charm Has your question been resolved?

tame charm
#

the data.txt file has the actual numbers for N, c1, c2, e1, e2

#

So I have to actually calculate p and q

peak estuary
#

well rearrange could just mean symbolically

#

but ok if you actually have to calculate it..... hmm

#

how big is N

tame charm
#

Like massive

#

Like 70 digits or more

peak estuary
#

and are e1, e2 "random" ?

tame charm
#

Yeah, and they are coprime

#

And each is coprime to N

peak estuary
#

well most numbers are coprime to N

#

but ok hmm

#

interesting

#

this feels like it shouldn't be possible

tame charm
#

Ikr

peak estuary
#

cause it feels like you should be able to then just calculate any e'th root

tame charm
#

Yeah

#

I tried this

#

Essentially I raised the first equation to e2, and the second to e1

#

And multiplied them

#

but what do you do after that…

peak estuary
#

hmm I'll think about it. but in the end while 70 digits is massive, with a dedicated program it should be doable in reasonable time. although that's clearly not in the spirit of the problem

tame charm
#

600 digits, sorry

#

Lmao

peak estuary
#

well ok not then

#

lmao

tame charm
#

Just checked

#

Yeah

peak estuary
#

what the fuck

tame charm
#

Yeah so

#

No brute force lol

safe radishBOT
#
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#

tame charm
#

.close

safe radishBOT
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lean otter
#

Is this symbolically correct?

safe radishBOT
#

@lean otter Has your question been resolved?

grizzled shoal
#

i would personally write it as

#

$x_{1}=3, x_{2}=-3$

#

at the end

flat frigateBOT
#

~Martin

grizzled shoal
#

as the way you wrote it kinda implies that x=3=-3

#

also, you don't have to include the +- in front of the square root

#

at least i never saw anyone else do that

#

i guess it doesn't hurt

safe radishBOT
#

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lean otter
#

Thank you @grizzled shoal

safe radishBOT
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rain flare
#

How to solve this?

safe radishBOT
rain flare
#

It’s a square and there is only one point given

safe radishBOT
#

@rain flare Has your question been resolved?

rain flare
#

<@&286206848099549185>

safe radishBOT
#

@rain flare Has your question been resolved?

safe radishBOT
#

@rain flare Has your question been resolved?

rain flare
#

!close

#

.close

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lean otter
safe radishBOT
lean otter
#

I have half of the curve, but idk how to incorporate the negative half!

#

(this is what i have)

#

yes but im not sure how to incorporate that into a cartesian equation

#

anyone?

#

<@&286206848099549185>

marsh walrus
#

what is with those boundaries

#

you can get equivalently to x=y^2-4y+1

#

but the interval has me second guessing

#

I guess it just comes from the t restriction?

marsh walrus
#

well thats a dumb way to say it

#

you need to discard half of the solutions to make sqrt a function

safe radishBOT
#

@lean otter Has your question been resolved?

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wet wave
#

Can someone explain the (0, -0.5 + 0.5sqrt(5) part? Why isn’t it (-0.5 + 0.5sqrt(5) , infinity)? Because that’s when the right part becomes 0 while the left part is already positive. If you fill in x = 1000 then the numerator is positive aswell. Is the answer key wrong or am I missing something?

safe radishBOT
#

@wet wave Has your question been resolved?

wet wave
#

<@&286206848099549185>

safe radishBOT
#

@wet wave Has your question been resolved?

azure basalt
#

can you give a better picture like a screenshot?

#

its hard to read

wet wave
#

Is it?

#

Let me see

#

If I can get a screenshot

azure basalt
#

oka yeah the solution is missing x<1

#

i mean x>1

#

or (1,infinity)

wet wave
#

Okay perfect thought so, thank you

azure basalt
#

@wet wave you can always check with symbolab btw

#

just do domain calculator

wet wave
#

Oh yeah good one

#

.close

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raven saddle
safe radishBOT
raven saddle
#

how can you find the interval of convergence

#

because the radius is c isnt it

coral ibex
#

the interval of convergence are the bounds for the values of c that make the sum converge

#

for example if a random summation converges when c is between 1 and 5 then the interval can be written as 1<c<5

#

and the radius of convergence is 2 because (5-1)/2 is 2

#

the way you find the interval of convergence is the ratio test for convergence and then solve for c

#

let me know if you need any other help

raven saddle
#

oh okay thanks

#

.close

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hazy rivet
#

Did I do something wrong here? I tried so many things couldn't solve the integral so I put it in a calculator and it said it wasn't possible

thin bridge
#

you messed up the derivative of 1/(4x)

hazy rivet
#

I’m blind, mb

#

Ty

#

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rough briar
#

Can anyone explain how they moved the y^2 in the denominator to the right hand side of the equation?

wet wave
#

Multiplied both sides by y^2

rough briar
#

they multiplied it out of the denominator and then did the same to the other side?

wet wave
#

Yup

rough briar
#

oh wow

#

why didnt they just move it up to the numerator? why did they have to move it to the other side?

plucky elk
rough briar
#

would you be able to do that by making it y^-2?

plucky elk
#

yes but that's not helpful

#

you can try your own way and see if you can isolate for y'

#

it might be possible, but just not as simple as the solution presented

rough briar
#

i see

#

thank you riemann

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#

@rough briar Has your question been resolved?

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devout harbor
safe radishBOT
devout harbor
#

Is there a formula for this I forget

#

like what does 1/x^n have to be for something to converge?

#

is it just n > 1?

lean otter
#

It's asking if the improper integral $\lim_{n \to \infty} \int^n_1 x^{-1} - x^{-2.5} \dd{x}$ converges or not

flat frigateBOT
devout harbor
#

well yes but if x^-1 diverges I don't think it matters yeah?

lean otter
#

I guess there's only one way to find out for sure

#

but yes, the linearity property of integrals can be used here

lean otter
#

an integral is a continuous sum

#

this doesn't apply here

devout harbor
#

sure

#

and I did that

#

I'm curious for 1/x^p

#

what value of p does something have to be to converge?

lean otter
#

p > 1

devout harbor
#

awesome thank you

#

.close

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devout harbor
safe radishBOT
devout harbor
#

I need serious assistance haha

#

My other attempt

plucky elk
#

where did you get this formula from

#

this one doesn't have the 15+ all your other answers have. also the 30 that was correct in your other answers became 15

devout harbor
#

oof it was - 15 not plus 15

#

.close

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regal granite
#

im lost, idk how to do this, i took the second derivative but got a weird answer

regal granite
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scenic gull
safe radishBOT
scenic gull
#

Hi! I'm looking for a way to prove that the line PC bisects the angle APM

#

In the question I want to prove distance BC = 2AC

#

And I lost all marks since I assumed triangle APC and triangle MPC are congruent. Which they are if there's a bisection or APM because of the SAS

#

The only thing we know is that distance 2AP=PB and that AP=PM

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#

@scenic gull Has your question been resolved?

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scenic gull
#

.reopen

safe radishBOT
#

upbeat yarrow
#

Helllo!

#

I joined because i wanna get higher grades

#

can you please explain how to divide integers and negative numbers?

lean otter
#

Please open a new help channel

safe radishBOT
#

@scenic gull Has your question been resolved?

safe radishBOT
#

@scenic gull Has your question been resolved?

outer lynx
#

If i dont assume its a right triangle, this is what we have

#

That gives us two contradicting cases for a few triangles where i can move the arm PM (while constructing the triangle)
Changing angle MPC but not angle APC

#

So i guess i am forced to assume its a right triangle

#

Nevermind

#

I was wrong

scenic gull
#

You don't get any info on it.

#

But you could construct a right angle that follows all the rules

outer lynx
#

Ah, that makes it easier but it makes us prove the thing only for a right triangle

#

What about a scalene triangle

safe radishBOT
#

@scenic gull Has your question been resolved?

outer lynx
#

In the question I want to prove distance BC = 2AC. The only thing we know is that distance 2AP=PB and that AP=PM

#

Something is wrong

#

I can have cases where this thing you want to prove is not valid

#

@scenic gull can we have the actual question? Maybe there is something thats missing

scenic gull
#

I can see if i can get it when get back tomorrow

scenic gull
#

Also you get that M is the midpoint between BC

safe radishBOT
#

@scenic gull Has your question been resolved?

safe radishBOT
#

@scenic gull Has your question been resolved?

outer lynx
#

you can use the Proportionality Theorem

outer lynx
#

You csn prove AC = 2PM but not BC = 2AC

safe radishBOT
#
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turbid jetty
#

for the domain, I am a bit confused on the set notation but
${x\in\mathbb{R}|0<x<1}$\newline
${x|x\in\mathbb{R},0<x<1}$\newline
i am unsure which one is better

flat frigateBOT
#

notnick

marsh shale
#

first one is a wrong notation

turbid jetty
#

for some reason my textbook shows answers with that

#

and its making me confused on the correct notation

solar hazel
#

umm the first one is fine

turbid jetty
#

what

#

im so confused now

solar hazel
#

and I'd say better

turbid jetty
#

oh really

solar hazel
#

yep

turbid jetty
#

alright thanks

#

.close

safe radishBOT
#
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gloomy scaffold
#

A, B and C are on line l and X, Y and Z are on line m. The line segments AY , AZ, BX, BZ, CX and CY intersect
each other at three points P , Q and R. Those points lie on the Pappus line.
If ℓ and m intersect, when does the Pappus line go through the intersection of ℓ and m?

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#

@gloomy scaffold Has your question been resolved?

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lean otter
safe radishBOT
lean otter
#

saying its 2.7

#

But its saying it’s incorrect

#

Am i right?

quasi bison
#

,calc 10/3.6

flat frigateBOT
#

Result:

2.7777777777778
quasi bison
#

you misrounded @lean otter

lean otter
#

wym

#

whats the awsner

rugged radish
#

what does 2.777 round to ?

lean otter
#

3

rugged radish
#

using 1 decimal place

#

round to nearest tenth

lean otter
#

im not that good in math

#

i did

#

its 3

rugged radish
#

You rounded to the ones

#

Round to the tenths

lean otter
#

2

#

2.4?

#

bro this not helping at all

#

i came for the answer

thin bridge
#

do you know your rounding rules

lean otter
#

No

#

6+ is 10

#

anything lower is low

#

right

#

rounding

thin bridge
#

not quite

lean otter
#

im not bulit for math lol

#

how do you round

#

use 2.7

thin bridge
#

why are you using 2.7 when you have 2.7777...

lean otter
#

i need first 2 numbers

#

thats why

thin bridge
#

rounding is not the same as truncating

lean otter
#

2.7 rounded is 3

#

You dont know how confused i am

thin bridge
#

did you say that 2.7 rounds to 2 (to the nearest integer) because you only needed the first number?

lean otter
#

yeah

quasi bison
#

but you don't want to round to the nearest integer

#

and besides, you are dealing not with 2.700 but with 2.777...

lean otter
#

2.7777777 rounded

#

is?

quasi bison
#

it's never just "rounded"

#

it's always "rounded to [place]"

#

you want to round to the nearest tenth

lean otter
#

yup

thin bridge
#

to consider how you'd round
2.77...
to 1dp, you'd consider whether the bolded digit is greater or equal to 5

lean otter
#

im so confused

#

look can i just get the answer i still need to complete this and its due in a few mins

quasi bison
#

no

lean otter
#

ok give me steps

#

and ill get it

quasi bison
#

we are trying to

thin bridge
#

we are...

quasi bison
#

what part of ramonov's message is confusing you?

lean otter
#

everything

#

the full number is 2.777777777777778

#

so do I divide it or what?

quasi bison
#

no,

#

you round it to the nearest 0.1

lean otter
#

and how do i do that?

quasi bison
#

you consider the digit after the place to which you want to round

#

if it is 5 or greater, you round up,
if it is not, you round down

#

hence why ramonov bolded the 7 in

2.7**7**7777...

#

do you understand what i said just now? yes or no

lean otter
#

kinda

#

2.8 is what I got

#

i think i did something wrong

thin bridge
#

yes, good

lean otter
#

correct?

thin bridge
#

yes, good

lean otter
#

.close

safe radishBOT
#
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lean otter
#

Could of just said 2.8

safe radishBOT
#
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sacred vale
#

anyone know
how we start to solve this question
i drew a diagram but idk what to do

sacred vale
#

<@&286206848099549185>

#

.close

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#
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swift blaze
#

can someone explain to me how to factor this out pls

swift blaze
plucky elk
#

Try x=1

swift blaze
#

is that the only way to do it

#

cus i know the answer but i wanna know how to get there

plucky elk
#

There are lots of ways

#

Guessing simple numbers is the simplest and the intended way

swift blaze
#

what's the algebraic way cus i can't seem to find it online

#

it's always with gcf

plucky elk
#

I'm sure you're not supposed to use the cubic formula

#

But that would be the "algebraic way"

swift blaze
#

could you tell me the cubic formula anyways

plucky elk
swift blaze
#

i regret asking but thank you

#

.close

safe radishBOT
#
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spare sedge
#

hi, i wanted to ask

safe radishBOT
spare sedge
#

how do we go from this to this?

bold ferry
#

both sides were divided by 10

spare sedge
#

oh ok

#

how about now?

regal girder
#

$10^{\log_{10}(x)} = x$

flat frigateBOT
regal girder
#

so raising 10 to the power of both sides you get to the next step

spare sedge
#

i don't get it :/

regal girder
#

log and exponents are inverses

#

so raising 10 to the power of both sides, you cancel the log on the left and on the right you have $10^{-1}$

flat frigateBOT
regal girder
spare sedge
#

ah ok

#

thanks

#

how do i move on?

#

how can I get 5 to the other side?

regal girder
#

you multiply both sides by 5

#

once you get rid of the logarithm, it's a regular first degree equation

spare sedge
#

Ok good

#

thanks a lot

safe radishBOT
#

@spare sedge Has your question been resolved?

#
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#
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split fulcrum
#

I need help with a couple questions,

safe radishBOT
split fulcrum
#

What does Question 7 mean?

next plinth
split fulcrum
#

yeah i know that but idk what it means by

#

reciprocal of the other

next plinth
#

Okay

#

So lets say

#

x1 = a

#

So x2 is basically 1/x1= 1/a

#

Reciprocal means raised to power -1

split fulcrum
#

so would u say

#

x2 is reciprocal to x1 or something

next plinth
#

Reciprocal of any value say H is 1/H

next plinth
split fulcrum
next plinth
#

Do u sum of root and product of root?

split fulcrum
#

ye

#

-b/a

#

c/a

next plinth
#

Yeah

split fulcrum
#

25x/1 is sum

#

12/1 is product

next plinth
#

Not 1

#

But P

split fulcrum
#

oh

#

p

next plinth
#

Now u can solve?

split fulcrum
#

what do we do to sum and product like

#

do we raise it to -1

next plinth
#

Consider some variable as root

#

Wait im joining with laptop my phone is kinda hanging

split fulcrum
#

ok

#

so x is root?

next plinth
#

ignore

#

lets say a , b are the roots

#

now a + b = 25 / p and a * b = 12 / p

#

since you know that one of the root is reciprocal of other so we can say that b = 1 / a

#

put this thing in 2nd equation

#

a * 1 / a = 12 / p

#

now you get it right ?

#

@split fulcrum

split fulcrum
#
  • is multiply?
next plinth
#

yes

split fulcrum
#

i dont think i understand the b = 1/a part

next plinth
#

okay,

#

do you understand what is reciprocal mean by now ?

split fulcrum
#

is a + b - 25/p and a x b = 12/p the same?

split fulcrum
next plinth
#

what is reciprocal of 5 ?

split fulcrum
#

its 5 to the power of -1 right?

next plinth
#

yeah, how much is that ?

split fulcrum
#

ill check

next plinth
#

lol

#

its just 1 / 5

split fulcrum
#

oh i thought u want me convert to decimal

#

lol

next plinth
#

no

#

similarly its says that one of the root is reciprocal of other

#

so if we consider 'a' to be one of the root, what will be the other root ?

split fulcrum
#

b?

next plinth
#

will it not be reciprocal of 'a' ?

split fulcrum
#

woulldnt reciprocal of a be

#

1/a

next plinth
#

yes

#

so that will be the other root

#

if you are finding it difficult , we can start again.

split fulcrum
#

so are we trying to find reciprocal of both roots

next plinth
#

nope

#

its the information given to us

split fulcrum
#

ok

next plinth
#

one of the root is reciprocal of other root

split fulcrum
#

ohh ok

#

we just need to find one root?

next plinth
#

we need to find the value of P

#

we don't need to find any root here

split fulcrum
#

Ok

next plinth
#

so by product of root we have -> a * (1 / a) = 12 / p

split fulcrum
#

right

#

what is next step

next plinth
split fulcrum
#

Ok

next plinth
#

👍

split fulcrum
#

1 = 12/p

#

p = 12

next plinth
#

YES

split fulcrum
#

yayyy

#

thank you very much for helping me understand

next plinth
#

np

split fulcrum
#

and also

#

are you able to help with a graph question?

next plinth
split fulcrum
#

it looks like this

next plinth
#

send the question.

split fulcrum
#

i am very confused by find values when there is no measurement only equation

next plinth
#

okay

#

OC is basically when x = 0 right ?

#

C (0, y) and you can get this y if you put 0 in the parabola equation

#

same is true for OA and OB, if you put the value of y = 0, you get OA and OB

split fulcrum
#

so

#

OA is x = 0

next plinth
#

no

#

point A(x, 0) ?

next plinth
split fulcrum
#

yes A would be x = 0

next plinth
#

not x

#

y = 0

split fulcrum
#

ohh yeah

#

i forgot

#

so b, o and a have y = 0?

next plinth
#

yeah

#

so if you put y = 0 in the given equation

#

you get the two values of x

#

smaller one is for A and larger one is for B

split fulcrum
#

oh like

#

one value for A

#

one value for b?

next plinth
#

yes

#

one value is for point A(x, 0) and other for point B (x, 0)

split fulcrum
#

so how do we find value of OC

#

the graph has no numbers

#

but wait

#

it is +9 right

#

so it goes up to 9?

#

and that is value for oc?

next plinth
#

true

split fulcrum
#

but what about OA

#

how do we find that

next plinth
#

put y = 0

#

get the point A and B

split fulcrum
#

how do we get numbers from that

split fulcrum
hidden oriole
#

no way you don't know how to plug in y=0 and x=0

#

if u are learning this

#

and do u know Vieta's formuals

#

formulas

#

to solve bcd

#

in an easy way

split fulcrum
safe radishBOT
#

@split fulcrum Has your question been resolved?

safe radishBOT
#
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#
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bold orbit
safe radishBOT
bold orbit
#

How am I supppsed to find y0, after I have found the solution to the differential equation?

bold orbit
#

Plugging for t=0 we get that y0 = c+21/8 => c = y0 - 21/8

#

But I have no clue on how to proceed from there

safe radishBOT
#

@bold orbit Has your question been resolved?

safe radishBOT
#

@bold orbit Has your question been resolved?

safe radishBOT
#

@bold orbit Has your question been resolved?

safe radishBOT
#

@bold orbit Has your question been resolved?

inner nest
#

You can use a graphing software @bold orbit

bold orbit
#

Yeah but it's asking for an exact value

#

So there should be an analytical way to find it

inner nest
#

Well, the value should be a range of values

#

BTW, @bold orbit I am assuming that you are just starting out on ODEs

bold orbit
#

Yeah

inner nest
#

Ok

#

so, do as what I say

bold orbit
inner nest
#

TBH, by mean value theorem it should yield a family of solutions for that

#

anyways

#

listen

#

I understand that how they have proceed to the answer

#

You do a derivative to the solution function

#

once done, knock me @bold orbit

bold orbit
#

Ok might take a few minutes though since I am a tad bit busy rn

inner nest
#

😑

bold orbit
#

Ok so found the derivative

#

Ah I don't know how to use the latex bot here

#

!tex

inner nest
#

😑

#

send a pic

inner nest
#

@bold orbit

#

May I have your attention please?

#

I do not wanna your suffocation to be lengthy

#

for not finding help

#

or you can do a VC with me in this server's voice channels

inner nest
#

Hello? @bold orbit