#help-23

1 messages · Page 22 of 1

nova creek
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Yes

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So conversely

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What's 1/x^n?

lean otter
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x^-n

nova creek
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And so what's 1/x³?

lean otter
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X^-3

nova creek
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And what's 2/x³?

lean otter
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2^x^3?

nova creek
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$\frac{2}{x^3} = 2^{x^3}$?

flat frigateBOT
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Gamer Dio

lean otter
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I’m not sure

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2x^3?

nova creek
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$\frac{2}{x^3} = 2x^3$?

flat frigateBOT
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Gamer Dio

lean otter
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2x^-3?

nova creek
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Yes

lean otter
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Ok

nova creek
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So what's -(2/x³)?

lean otter
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I’ve gotta get better at algebra

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-2x^-3

nova creek
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Yes

lean otter
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Awesome. Now I’ve just gotta get better at algebra. Thank for your help

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.close

safe radishBOT
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plush lantern
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Hello, finding x for this equation is not possible, right? Teacher said all the equations given are possible.

lean otter
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yeah

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just multiply x by the paranthesis

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and continue from there

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it becomes this:

5x + 10 -3x = 2x + 14

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wait wtf

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thats not possible

lusty elbow
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Lmaooo

plush lantern
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yeah lol.. just wanted to make sure 😑😑😑

lusty elbow
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2x+10=2x+14

plush lantern
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yup.

worthy hemlock
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Could be a typo, ask your teacher

plush lantern
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Wanted to make sure I wasn't doing a big silly.

Yeah will do, thanks

Solved

lean otter
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.close

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how

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nvm

worthy hemlock
lean otter
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i figured

worthy hemlock
worthy hemlock
lean otter
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hes still here

worthy hemlock
#

Anyways, guess it's solved

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.close

safe radishBOT
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urban heart
#

Is there a map between set $\mathbb{R}^2$ and set $\mathbb{Q}$?
In other word, given an open set $A \in \mathbb{R}^2$. $A$ is open so by definition this gives a neighborhood $N_r(x)$.
How can we prove that this $N_{r}(x)$ belong to $\bigcup_{a \in \mathbb{Q}} N_r(a)$?

plucky elk
worthy hemlock
flat frigateBOT
urban heart
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i tried....

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I think i got it

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safe radishBOT
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reef spindle
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Having trouble finding the raw score with just the mean and the standard deviation

reef spindle
safe radishBOT
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@reef spindle Has your question been resolved?

safe radishBOT
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@reef spindle Has your question been resolved?

reef spindle
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<@&286206848099549185>

reef spindle
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rugged mason
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a fountain shoots water 9 feet into the air and it lands 6 feet away, what is the equation of the parabola that models this path?

safe radishBOT
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@rugged mason Has your question been resolved?

rugged mason
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<@&286206848099549185>

lean otter
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Can you find any points belonging to the parabola?

safe radishBOT
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@rugged mason Has your question been resolved?

rugged mason
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no

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the question was all that was given

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i know the 9 is the value of k

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and that's about it

rugged mason
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broken saffron
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Hello, I'm in calc 2 and need help on a problem that I'm not sure even involves any calc concepts. The background says: The included angle of the two sides of a constant equal length s of an isosceles triangle is (theta)

broken saffron
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Part A of the question asks: Show that the area of the triangle is given by A = (1/2)s^(2)sin(theta)

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how am i supposed to show that exactly

safe radishBOT
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@broken saffron Has your question been resolved?

broken saffron
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<@&286206848099549185> hello, i was wondering if I could get help for what i believe is a geometry proofs thing

last tundra
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Triangle area = 1/2 x base x height is going to help you here.

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Working backwords, you can try to retrofit $ \frac{1}{2} s^2 \sin \theta $ as $\frac{1}{2}$ base x height.

flat frigateBOT
last tundra
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Redraw the triangle so you have s as the base in the shape most familiar to you.

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If s is the base, what's the height?

broken saffron
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wait

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is the height just sin(theta) then

last tundra
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Yeah, but can you see why?

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s sin theta, not just sin theta

broken saffron
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i apologize, give me one sec to try and think about it with your diagram

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oh i think i see why now

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so the height is the red line, and using sin(theta) = opp/hyp, but since we want to get the height we can cancel the "/hyp" by just multiplying by s on both sides

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since the hypotenuse and base both are s

last tundra
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Yes, the hypotenuse of the right-angled triangle used to define that sin ratio is s, and the line you are looking for is opp, correct.

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Just be careful not to confuse the "base" of the right angled triangle used to define the sine ratio with the "base" of the triangle whose area you seek.

broken saffron
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wait but then how would i actually go about writing out the proofs or whatnot

last tundra
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Start with that diagram.

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Pieces of information you know:

(1) The area of this triangle is 1/2 times the red line segment's length times the blue line segment's length.
(2) The blue line's length is s.

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So you just need to find the red line's length.

broken saffron
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so then plugging in s we have A = (1/2)bs

last tundra
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However, you also know
(3) The red line segment is the side opposite theta in a right angle triangle with hypotenuse s. Therefore red line / s = so on and so on.

broken saffron
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so then i could just do b = s and for height:

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h/s = sin(theta), h = s*sin(theta)

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then just write out A = (1/2)bh, and replace b and h with their respective values, and it would be as simple as that?

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alright well thank you for the help, i really appreciate it

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safe radishBOT
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safe radishBOT
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indigo flame
safe radishBOT
indigo flame
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Tips for 39pls

plucky dew
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try u = sqrt(1/x -2)

indigo flame
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alright

plucky dew
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yeah got the same thing

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u forgot the dx at end tho

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and rmb once u intergrated it, convert all u back to x and add constant

indigo flame
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Alright

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Is there a quicker way

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Just kinda curious

plucky dew
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i dont think there is, usually w sqrts like these letting u as the sqrt part makes it easy

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i dont think trig sub is suitable here and u cant rly change the sqrt part by factorizing or expanding

indigo flame
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I see

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Tks

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full horizon
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Can someone explain to my why the group ${e, x, y, z, t, u}, *$ such that $x^2 = y^2 = z^2 = t^2 = u^2 = e$, $x * y =z$ doesn't define a group? This shouldn't be possible because a group of order 6 can be proven to have an element of order 3, but I'm unable to reach a contradiction

flat frigateBOT
full horizon
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(Note that it also follows that $x * t = u$ because that's the only thing it $\textit{can}$ still equal)

flat frigateBOT
full horizon
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Ah, I think I got it, so I'll still leave the room open for someone to confirm: the contradiction is that in this case, ${e, x, y, z}$ would be a subgroup, but this can't be the case because it's order (4) isn't a divisor of the order of the original group (6) which contradicts Lagrange's theorem

flat frigateBOT
safe radishBOT
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@full horizon Has your question been resolved?

safe radishBOT
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weary osprey
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.close

safe radishBOT
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lean otter
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where is my mistake?

safe radishBOT
dense coral
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we know sin(theta + 90) = cos x

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here theta is A

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therefore option a is correct

lean otter
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.close

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supple monolith
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How would one find the value set of this function -2x^2 + 4x + 8?

supple monolith
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The definition set is easy, all real values

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But you could derive this function and find the value set that way to see where the derivative is zero and thats where u could find min and max

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but isnt there any easier way

keen comet
supple monolith
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yea i guess completing the square is the way to go on easier functions like this

safe radishBOT
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@supple monolith Has your question been resolved?

safe radishBOT
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fickle trail
safe radishBOT
fickle trail
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I am trying to figure out why x + 1/2 is the same thing as 2x + 1

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Cross multiplication?

white hollow
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one is just a scalar factor of the other

near cave
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(2x+1)/2

fickle trail
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But when I plug in values such as 6 + 1/2 it doesn't make sense

white hollow
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6 + 1/2 doesn't equal 13

fickle trail
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oh so it's not cross multiplying

white hollow
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it equals 13/2

fickle trail
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Yeah I know lol

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oh..

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I forgot the /2

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So I almost had it..

near cave
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ye

fickle trail
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Hmmm

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I still don't see it..

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How did you get (2x+1)?

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To begin with

white hollow
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you need a coefficient of 2

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for the x^2

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f(-1/2) = 0

fickle trail
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why are we adding a power to x?

white hollow
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therefore x + 1/2 is a factor

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which is the same as 2x + 1

white hollow
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that you were factoring

fickle trail
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oh sorry, I'm just looking at the light blue text on the right

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I should have cropped that better

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Lemme resend the screenshot

white hollow
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2f(x) and f(x) can have the same factors

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for polynomials

fickle trail
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But if 12+1 is correct for the numerator.. why do I need to add the denominator? /2

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if 2x + 1 doesn't need the denominator

white hollow
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huh

fickle trail
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I was using cross multiplication which is just wrong

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I assumed that was the correct way but I don't even know if I can do that

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I'm just trying to get from (x + 1/2) to (2x + 1)

white hollow
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why

fickle trail
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and plug in other values to do the same thing

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to understand why they are the same thing

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and how to get there

white hollow
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they are the same thing because x is the same

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in both of them

fickle trail
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but in my example with 6 + 1/2 it doesn't work unless i add a denominator of 2 for some reason

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i didn't add a denominator for 2x + 1

white hollow
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they're the same thing whwen they equal 0

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the y coordinate is set to 0

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so you find the x coordinate

fickle trail
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Oh

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Lemme rephrase the question, ignore everything else above, just this

white hollow
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multiply by 2

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but it only works because it's 0 on the RHS

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you can't exclude that

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as 2x0 = 0

fickle trail
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no I'm saying ignore the above, we don't know it's 0

white hollow
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what

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just multiply by 2

fickle trail
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Hmmm

white hollow
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I don't understand

fickle trail
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Ty

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Does it matter if a factor includes 1/2?

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Do you try to make factors whole numbers always

white hollow
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it doesn't matter

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iit only matters if it doesn't expand to the cubic

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which is why it is sometimes necessary to multiply by a scalar

safe radishBOT
#

@fickle trail Has your question been resolved?

safe radishBOT
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Please don't occupy multiple help channels.

nova creek
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Is the maximum less than or equal to every element in the set?

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Yeah my bad

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But it is ≥ every other element right?

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Is there any smaller element that's also ≥ every other element?

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Then it's the supremum

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In the field of reals, yes

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In the field of rationals, the supremum doesn't exist

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Well, the supremum is a number

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So if the number isn't in the field, it doesn't exist

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99.99% of the time though the field is the reals

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So yeah, the supremum would be ³√29

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Yep

safe radishBOT
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cobalt flint
safe radishBOT
cobalt flint
#

hello I feel like somethings a bit off with my answers

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can someone let me know if they’re wrong and some point in the correct direction

hollow oak
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3y²-3 for fy

cobalt flint
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I thought you had to multiply 3(2y)

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or would that be the next step

hollow oak
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For fyy it will be 6y

cobalt flint
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Oh okay

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And then fox would be 6

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Fyx*

hollow oak
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Yeah so in the next step it's just normal differentiation keeping the other variable constant

cobalt flint
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what about fxy?

hollow oak
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Fyx would be 0

cobalt flint
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Ohhhh

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Okay nice

hollow oak
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0

cobalt flint
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they would both be zero makes sense thank you

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lethal scaffold
safe radishBOT
lethal scaffold
#

i need an original function with at least one asymptote

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.close

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lethal scaffold
#

.reopen

safe radishBOT
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neat kiln
#

Easy just place x in the denominator and you get vertical asymptote x,=0

safe radishBOT
#

@lethal scaffold Has your question been resolved?

lethal scaffold
#

like this

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or this

safe radishBOT
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@lethal scaffold Has your question been resolved?

lethal scaffold
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.close

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lucid atlas
safe radishBOT
lucid atlas
#

I’ve gotten to this point

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But I’m not sure how to write it in terms of an inequality

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I searched online and it said x<-3/4

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But when I put it into original equality I got 0 so I’m not sure how that works

proper crypt
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Try graphing the parabola using the roots

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See where it's positive/negative.

lucid atlas
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How would I do this without doing all that eg in an exam

sleek plank
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you could use quadratic formula

lucid atlas
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Right and it would get me x =-3/4 and x=2 right?

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How would I put this into the inequality form

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Online says x<-3/4 x>2

toxic stratus
sleek plank
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plug in 0, 0 and see if it satisfies the inequality

lucid atlas
toxic stratus
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graph the parabola

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and see when it is above the x axis

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this will tell you the values for which it is >0

lucid atlas
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Is there any other way to do it?

toxic stratus
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you have already calculated the intercepts

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you can plug in values in each interval that the intercepts split the real line into

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but that's is more tedious than simply graphing

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you already know the intercepts presumably from solving the quadratic =0

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or perhaps just factoring

toxic stratus
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so just draw a rough shape of the parabola

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and determine when it is above the x axis

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x axis

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not y

sleek plank
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if it's shaded inside or outside the parabola

toxic stratus
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shading?

lucid atlas
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Is that how you would do it in an exam?

sleek plank
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that's how i would

sleek plank
lucid atlas
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Is there any other way to do it instead of graphing it

sleek plank
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instead of graphing it, you can just plug in the coordinates 0, 0 to see what part you shade

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inside or outside

lucid atlas
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I’m sorry I don’t get it

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How do you mean

sleek plank
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take the example above

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if you plug x = 0 and y = 0 in the inequality, it wouldn't become true

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after you evaluated it

toxic stratus
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the original inequality has no y in it

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we are not concerned about the y values

sleek plank
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y is only there so it shows up

toxic stratus
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it is just along the x axis

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no no

sleek plank
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desmos doesn't graph it without the y being there

toxic stratus
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that's

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not the inequality we're solving

sleek plank
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it's just an example as to what shaded parabolas look like

lucid atlas
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I’ve got the two x values, now how do I put it into the inequality form

toxic stratus
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you don't shade parabolas for these inequalities

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the parabola tells you whether the values are greater than or less than 0

lucid atlas
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I also know what the inequalities are I just don’t understand how to get that answer

toxic stratus
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when it's above the x axis then the quadratic is >0

lucid atlas
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X<-3/4 x>2

toxic stratus
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yes

lucid atlas
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Yes but how can I do this without using the parabola

toxic stratus
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you should draw the parabola

lucid atlas
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Is that the only way?

toxic stratus
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no

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you can plug in values

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in each interval

sleek plank
toxic stratus
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that the intercepts split the real line into

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but it is more tedious as i have said

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you want to draw the parabola

lucid atlas
toxic stratus
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you know the intercepts

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so you know when the quadratic changes signs

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i.e when it switches from being <0 to >0

#

so you just have to check whether it's >0 or <0

#

you do this by plugging in a value in the interval you want to check

#

so say for example you plug in x=0

#

then you just get -6

#

so you know that on the interval -3/4 < x < 2 the quadratic is negative

#

so that means outside that interval it'll be non-negative

lucid atlas
#

Right sorry i understand partially up to the last two parts

#

If I plug in x=2

#

I get 0

toxic stratus
#

yes that's what you worked out

#

from the fact that it's an intercept

safe radishBOT
#

@lucid atlas Has your question been resolved?

lucid atlas
#

Okay this whole thing confused me

#

I’ve got it now but without the plotting on the graph thing

#

I did it with a bit of trial and error

#

Thank you very much for your time anyway!

#

.close

safe radishBOT
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bright turtle
#

I don’t understand how this got 9.33?

safe radishBOT
bright turtle
#

Help pls

sleek plank
#

6/18 = 1/3

#

1/3 = 0.3333...

#

9 + 0.33333... = 9.33333....

bright turtle
#

?

#

How is it 1/3

sleek plank
#

6/18 simplifies to 1/3 because both 6 and 18 are divisible by 6

#

when you divide both 6 and 18 by 3 you get 1 and 3 respectively

bright turtle
#

Alr thanks

#

.close

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keen agate
#

, my teacher explained a identical question on the board but i learned nothing from it, im supposed to expect a question like so on the test

sleek plank
#

the trajectory of the bounce angle will be equal to the 90 - the angle of impact

#

ur supposed to use trigonometry to find this angle

#

and then subtract what you got from 90

#

then you subtract THAT by 180

#

and draw a line at that angle

safe radishBOT
#

@keen agate Has your question been resolved?

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foggy salmon
#

hm

fickle trail
#

.close

#

Sorry, using iPad and Discord, it wants to create a new channel when I add screenshot

#

.close

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opaque sorrel
safe radishBOT
opaque sorrel
#

hi can someone help me with this?
i did part a i and ii

#

but im not sure how to do b

#

my idea is to do by cases, like
cases where all letters are distinct + cases when there are 2 Es or 2Ls + cases where there are 2 Es and 2Ls + cases where there are 3 Es

merry sleet
#

you are talking about iii?

opaque sorrel
#

yes

merry sleet
#

yeah i think its a good way of doing it

#

gets you to the result quickly

opaque sorrel
merry sleet
#

i'm not sure about all of them

foggy salmon
#

its u

opaque sorrel
#

hi

foggy salmon
#

hi

merry sleet
#

like first is right

#

adele joke

opaque sorrel
merry sleet
#

last one i would have had 5c1 for the choice of the letter that isnt E and also 4C1 for its place inside the codeword

opaque sorrel
#

thats why i did 2!

#

to move it about

merry sleet
#

i dont get what you mean

opaque sorrel
#

oh like

#

so for the last one

#

when there are 3 Es

#

i selected the last one with 5c1

#

wait

#

oh it should be 6c1

#

wait

merry sleet
#

it cant be E

opaque sorrel
#

but theres alr 3 Es

#

J E W L R Y
E L
E

#

i selected all the Es so i just counted everything else

merry sleet
#

yeah so there are 5 possible letters remaining

#

wer'e not doing probabilities

#

where each letter has equal chance of being drawn

#

so its 5C1

opaque sorrel
#

oh

#

OH

#

eh wait

#

ok that makes sense

#

okay yes

#

then i multiplied by 2!

merry sleet
#

why by 2! ?

opaque sorrel
#

oh

#

lmao

#

wait

merry sleet
#

there are 4 spots for the non E letter

opaque sorrel
#

4!/3!

merry sleet
#

yeah

#

or 4c1

opaque sorrel
#

ahhhh

merry sleet
#

or 4C3

#

if you want to talk about the spots occupied by the Es

opaque sorrel
#

hmm answer is wrong though

#

i got 582

#

answers 626

merry sleet
#

yeah its not the end

opaque sorrel
#

oh wut

merry sleet
#

the other ones a wrong too

#

but the last one was the easiest to do

opaque sorrel
#

oh..

merry sleet
#

and im lazy

opaque sorrel
#

hmmmm

#

lemme write everything down frist

merry sleet
#

lets do 2 Es and 2 Ls then

#

its easy aswell

opaque sorrel
#

oki

#

so uh

merry sleet
#

so we have to chose 2 spots for the Es

#

among 4

opaque sorrel
#

yes

merry sleet
#

the Ls spots are determined by the Es

#

so?

opaque sorrel
#

would it work if i choose the Es first

#

wait

#

oh wait

#

i dont have to

#

cuz theyre all the same

merry sleet
#

you dont have to

#

yeah

opaque sorrel
#

ohhh

#

could i do

merry sleet
#

its just about knowing their place

opaque sorrel
#

4!/2!2!

merry sleet
#

yeah

#

its 4c2

opaque sorrel
#

so 6

#

oh yes

merry sleet
#

chose 2 spots among 4

opaque sorrel
#

righty

#

okay now two Es or two Ls

merry sleet
#

xor*

opaque sorrel
#

ah yes

#

okay

#

0k so

#

lets say we only have Es

merry sleet
#

you had a good idea with your 2

#

yeah

opaque sorrel
#

so firstly i dont have to choose the Es

#

so ill get rid of 3c2

merry sleet
#

you have to chose their spots though

opaque sorrel
#

(6C4 * 4!) + 2 * [(3C2 * 5C2 * 3!) / 2!]

#

ill permute them later

#

hmm

#

so i need to choose others

#

so

merry sleet
opaque sorrel
#

2 others

#

hm

#

oh i didnt change it

#

lol

#

2 * [(5C2 * 3!) / 2!]

merry sleet
#

do it from the beginning i think

opaque sorrel
#

lets just

#

2 * []

#

Yes

merry sleet
#

yeah

opaque sorrel
#

then uh

merry sleet
#

so 5C2 is right

#

you have to chose the 2 other letters

opaque sorrel
#

yes

#

2 * [5C2]

merry sleet
#

then you have chosen all the letters

opaque sorrel
#

then now i need to permute the 3 of them

#

so 3!

merry sleet
#

its all about placing

#

what?

opaque sorrel
#

ah wait

merry sleet
#

there are 4 spots in your word

opaque sorrel
#

4!

#

2 * [5C2 * 4!] / 2!

merry sleet
#

but the Es are equivalent

opaque sorrel
#

yes

#

so i divide by 2!

merry sleet
#

yeah

#

that should be good

opaque sorrel
#

ayeee

#

ok now

#

all letter are different

#

this cant be wrong lol

merry sleet
#

this is good

#

first thing i said

opaque sorrel
#

wtf

#

the

#

answer is off

#

by 4

#

bruh moment

merry sleet
#

rewrite everything pls

#

bruh moment indeed

opaque sorrel
#

hmm

#

the EEE is wrong

#

its 6C1 * 4 = 24

#

right

#

ah wait

#

bruh

#

5C1

#

bruh

#

bruh

merry sleet
#

yeah so its your fault

#

:p

opaque sorrel
#

aye its done

#

noice

#

thanks sir

merry sleet
#

got ideas for b?

opaque sorrel
#

oh u wanna continue

#

sure

#

hmm

merry sleet
#

lets place the two parents first

opaque sorrel
#

total number of ways when mr lee sits with mrs lee - number of ways mr lee sits with mrs lee and the children are all sat together

merry sleet
#

why -?

opaque sorrel
#

err

#

cuz we dont want them seated together

merry sleet
#

only the children right?

opaque sorrel
#

yyea

merry sleet
#

i would just proceed as we did

#

how many choices for them sitting together

opaque sorrel
#

wait why wont my method work tho

#

like it makes sense to me

merry sleet
#

it would need to be

#

total number of ways when mr lee sits with mrs lee - number of ways (mr lee sits with mrs lee are sat together) and (the 3 children are sat together)

opaque sorrel
#

yea

#

wait isnt that wat i said lol

merry sleet
#

you said all 5 together

#

or maybe i misunderstood

opaque sorrel
#

oh

#

LOL

#

yea

#

i did

#

oopsie

#

lets do it

#

so total number of wyas with mr lee and mrs lee sitting toegther

#

its uh

#

so i fix the parents

#

then just permute the rest

#

so for the rest it would be 8!

#

with parents 9!

#

then because its a circle

#

so (9-1)!

#

so 8!

merry sleet
#

they are 8 in total

opaque sorrel
#

wut

merry sleet
#

oh nvm

opaque sorrel
#

lmao

merry sleet
#

im tired

#

10

opaque sorrel
#

wait so 8! is correct?

merry sleet
#

*2!

#

the two parents are not the same

opaque sorrel
#

heh

#

oh right

#

then for the

#

parents together and children are sat together case

#

its uh

#

parents is one group

#

children is one group

#

so 7! in total

#

but circle so 6!

merry sleet
#

dont be confused

opaque sorrel
#

then permute parents

#

6! * 2!

merry sleet
#

the children themsleves dont form a circle

#

they are separated by the parents

#

that are sat together

opaque sorrel
#

wait wat

#

separated by parents?

#

i thought im finding if the children are sat together

merry sleet
opaque sorrel
#

yea

merry sleet
#

in both cases the parents are sat together

opaque sorrel
#

yes

merry sleet
#

so you treat the childrens not as a circle

opaque sorrel
#

i didnt tho

merry sleet
opaque sorrel
#

thats for uh

#

the whole thing

#

like everything

merry sleet
#

everything?

opaque sorrel
#

so lets say the red circles are children

merry sleet
#

okay

opaque sorrel
#

so there are 5 other circlees

#

so 5!

#

then there are two "groups"

#

children and parents

#

so 7!

#

then because its a circle

#

6!

merry sleet
#

oh ok

opaque sorrel
#

then the parents can change places

#

so 6! * 2!

merry sleet
#

its right then

opaque sorrel
#

then the red people can change as well

#

so 6! * 2! * 3!

merry sleet
#

yeah

opaque sorrel
#

aye its right

#

thanks

merry sleet
#

how many was that?

opaque sorrel
#

72000

merry sleet
#

yeah they got plenty of room

opaque sorrel
#

ye boii

#

thanks alot boss

merry sleet
#

this kind of thing is always tedious

opaque sorrel
merry sleet
#

sadly this isnt recursive

opaque sorrel
#

thanks for th ehelp

#

.clsoe

#

.close

safe radishBOT
#
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untold wadi
#

Hello I was wondering if someone could verify if this problem is correct?

untold wadi
#

This is probability and I worked on it with a friend but am not sure if it's correct or not

unreal dock
#

it looks right to me

safe radishBOT
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@untold wadi Has your question been resolved?

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untold wadi
#

.reopen

safe radishBOT
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untold wadi
unreal dock
#

🫡

safe radishBOT
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@untold wadi Has your question been resolved?

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@low jungle Has your question been resolved?

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dense compass
#

Can someone explain why it goes from 144 to 169?

hot thistle
#

it’s completing the square

#

do you know what that is?

dense compass
#

Arent you supposed to set it equal to 0?

hot thistle
#

set what to 0

dense compass
#

the right side

hot thistle
#

no

dense compass
hot thistle
#

do you know the equation for a circle?

dense compass
#

x^2 + y^2 + 2gx + 2fy + c = 0

hot thistle
#

or more common is $(x-h)^2 + (y-k)^2 = r^2$

flat frigateBOT
#

maximo

hot thistle
#

actually it may not be more common but it’s more helpful here

#

anyhow, we want to get the equation you’re given into that form

#

to do so we want to get (x-something)^2

#

since we have x^2 - 6x, that something has to be a 3

#

since (x-3)^2 = x^2 - 6x + 9

#

so it’ll look like this:
x^2 - 6x =
x^2 - 6x + 0 =
x^2 - 6x + (9 - 9) =
x^2 - 6x + 9 - 9 =
(x-3)^2 - 9

#

do you understand how i got here so far

dense compass
#

think thats the part im stuck on

hot thistle
#

(a+b)^2 = a^2 + 2ab + b^2

#

(a+b)^2 =/= a^2 + b^2

#

sometimes it works but far from always

dense compass
#

Ok so you can kinda just leave 2ab out

#

gotcha

hot thistle
#

nono

#

you can’t

#

that’s the point

#

so we get (x-3)^2 = x^2 - 6x + 9

#

but we start with only x^2 - 6x

#

do we add 9 and subtract 9

dense compass
#

we + (9 - 9)

hot thistle
#

yes

#

so then we get (x-3)^2 - 9

dense compass
#

Ok I think im starting to understand

#

I just need to look at it more

#

wait @hot thistle why are we adding the 9's? I get its converting x to square form, but why 9 specifically?

hot thistle
#

it’s the number that lets us write (x-something)^2

#

for example if we had x^2 + 2x

#

we want to add 1

#

so we get (x+1)^2 - 1

dense compass
#

how do we know what number to add

#

is what im asking

hot thistle
#

well we want a number so that when we expand it out we get -6x

#

so since (x-a)^2 = x^2 -2ax + a^2

#

we want -6x = -2ax

#

so a = 3

#

so we add and subtract a^2=9

dense compass
#

ok its like 12am so ill have another crack at it in the morning, getting close though. Thank you!

#

.close

safe radishBOT
#
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trim jackal
#

For 7 part (g), I believe the statement is true. If I was going to prove that it was true, could I use a contrapositive or maybe a contradiction?

tiny wraith
#

the biggest number in S(x) is always x

trim jackal
#

Right

tiny wraith
#

so if S(a) = S(b) their biggest numbers would also be equal, and thus a = b

trim jackal
#

In terms of a contrapositive, right?

tiny wraith
#

you could say that if a weren't equal to b and S(a) did equal S(b) that would imply that a = b, so the statement that a is not equal to b and S(a) is equal to S(b) could never be true

trim jackal
#

Okay for sure, thank you!

#

.close

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lean otter
#

hello little boys

safe radishBOT
lean otter
#

how do i move y^2 to the other side and x also

#

to get y^2=ax

#

i mean like whats the metho to rearrange it

#

it just shows they rearranging it

lilac reef
#

multiply both side by 40?

lean otter
#

okay is that the only method

stray bluff
#

thats the easiest

lean otter
#

so if it was 40 in the original equation i would multiply both sides by 1/40?

lilac reef
#

yes

stray bluff
#

yea or just divide by 40

lean otter
#

that would be 40/1 times 1/40 and how does that work

#

like i dont understand the logic behind it could u explain pls

#

multiplYING 2 fractions

lilac reef
#

40/1 * 1/40 = (40 * 1) / (1 * 40) = 40/40 = 1

#

sorry, i forgotten latex already, so I can't give proper format

lean otter
#

when multiplying fractions do i cross multiply?

#

wait

#

oh

#

do i

#

when multiplying 2 fractions do i cross multiply or multiply straight through

#

multiplying numberators by eachother

#

and denominators by achother

lilac reef
#

I am sorry, I am not a native english speaker

lean otter
#

ok i will send photo

lilac reef
#

I am not too familiar with the terms cross or straight multiplication

lilac reef
lean otter
#

which is correct understanding\

lilac reef
#

can you include answer also?

#

though I assume the second one is correct

lean otter
#

oh the top would result in 1/1600

#

so bottom is method thats correct i guess

lilac reef
#

yeah

lean otter
#

when do u cross multiply

#

because thats something i remember but dont know when to use it

lilac reef
#

i am not too sure... I assume if you cross multiply, you divide

lean otter
#

ok

#

thank u for helping me

lilac reef
#

yeah

#

if its on the other side of the equal sign

#

you cross multiply

#

or division

lilac reef
lean otter
#

.close

safe radishBOT
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@timber briar Has your question been resolved?

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@timber briar Has your question been resolved?

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@timber briar Has your question been resolved?

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@timber briar Has your question been resolved?

lean otter
#

Where have you seen that cube before?

peak estuary
#

I'm just gonna throw the words menger sponge into this thread although I doubt you mean those

void plank
#

Something about this reminds me of fractals tho I don't know what

void plank
#

This looks very similar to a merger sponge

safe radishBOT
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pliant inlet
safe radishBOT
pliant inlet
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b) onwards

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i have a strange solution

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no clue how to proceed

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proofs are not my strong suit

foggy salmon
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hm factorised u get

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2x(x+2)(x+1)

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yea?

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2x(x+1)(x+2)

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imma reorder that

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so for any arbitrary int a

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like if we take a mod 3 we would get either 0,1,2

pliant inlet
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yeah

foggy salmon
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we can use case by case

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if its 0 then its div by 3

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if its 1 then a+2 is div by 3

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if its 2 then a+1 is div by 3

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n that covers all the cases

pliant inlet
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wait wait

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wait

pliant inlet
foggy salmon
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yes

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um

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like cuz

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if u take mod n of some int

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ull get stuff from

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0,1,2,..., n-1

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n would reduce back to 0

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like a cycle

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so in this case mod 3 will just be

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0,1,2

lean otter
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i don't think they are supposed to use mod to explain the proposition

foggy salmon
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oh?

pliant inlet
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i dont remember using mod in the textbook

foggy salmon
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hm

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lol

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oops

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well

grave flint
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poopy mod

foggy salmon
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u can just do the same thing

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but with

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a = 3k

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or

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a = 3k + 1

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or

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a = 3k + 2

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for some k

pliant inlet
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right

foggy salmon
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for some integer k

pliant inlet
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mhm

foggy salmon
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yea

pliant inlet
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so i can start with

foggy salmon
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then

foggy salmon
pliant inlet
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a = 3k, a= 3k + 1 a = 3k+2

foggy salmon
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um

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yea

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i would say

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OR

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tho

pliant inlet
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OR right

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mb

grave flint
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each is a case

foggy salmon
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then show with all cases tgt

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one of em is div by 3

pliant inlet
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by subbing in

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0 into the first

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case

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1 into the second

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and 2 into the third?

foggy salmon
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umm

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well

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like

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if

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a = 3k

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then a is div by 3

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if

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a=3k+1

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then a+2 = 3k+1+2

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=3(k+1)

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and k+1 is an int

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thus a+2 is div by 3

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last case,

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if a=3k+2

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then

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a+1=3k+2+1

pliant inlet
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a + 1 3k + 1

foggy salmon
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=3(k+1)

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ditto

pliant inlet
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right...

foggy salmon
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and those r the 3 cases

pliant inlet
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hm

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OK

foggy salmon
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also

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k is an int

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say that at the start

pliant inlet
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right

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ok

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thats explains b)

foggy salmon
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essentially the same as mod lol

pliant inlet
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that makes sense

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just a question though

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oh waiit

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its the same as mod right?

foggy salmon
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um

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ye

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lol

pliant inlet
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is that how you derived

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the solution?

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i guess?

foggy salmon
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um

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i mean

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it was kinda

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intuitive

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that 1 of em wld b divisible

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so just add some dummy var to

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um

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idk

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beef it up

pliant inlet
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yeah but proving it is hard lmao

foggy salmon
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make a complete proof ig

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well

pliant inlet
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alright

foggy salmon
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complete explaination anw

pliant inlet
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gotcha

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any hints for c?

foggy salmon
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um

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well

pliant inlet
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or d

foggy salmon
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its similar to the b

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where u got

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a,a+1 and a+2

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so 1 of em wld div by 3

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so therell b nth in the denom

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n itll div n give u an int

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from part b

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and as x in N

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when div 3 u get some int >=0

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then

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multiplication is preserved in N

pliant inlet
foggy salmon
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um

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when u multiply stuff in N

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u get stuff in N

pliant inlet
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right multiplicative

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identity

foggy salmon
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ok

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i think

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preserved is not the right word

pliant inlet
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held?

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unter multiplication

foggy salmon
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closed under?

pliant inlet
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right closed under multiplication

foggy salmon
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yea its closed under

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oops

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anyway

pliant inlet
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hmm

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this is for 3/