#help-23
1 messages · Page 19 of 1
this one
they added 5 theta to the denominator
but they added 5 to the top
same for the 2 theta
how come? i understand that we are trying to get sinx/x
so we seperate
as sin5t / 1 and 1 / sin2t
they mutliplied by theta/theta and 5/5 and 2/2
yes
but where is the theta on 5sin5t
that was multiplied
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How do I factor this?
Is there any variable common to all of the terms?
So factor that out
But like the answer sheet has an answer that doesnât have a common factor
So thatâs why Iâm confused
Can I see the answer on the sheet
Itâs (ab+a)(1-c)
Alright letâs try this
Split up the first two terms and the last two
So a+ab and -ac-abc
Then factor both of them individually, tell me what u get
thatâd be a*1b which is ab
Sorry a(1+b)
Weâre trying to get a+ab
-ac(1+b)
Perfect
Now we have a(1+b) -ac(1+b)
Because the insides of the parentheses are the same, we can combine whatâs on the outside
And it becomes (a-ac)(b+1)
But thatâs different than this tho?
So a(1+c)
Sorry a(1-c)
Ok so now we have a(1-c)(b+1)
How would we get from here to the answer keys solution?
Distribute a into brackets?
common ac from last 2 terms, and a from first 2
Try distributing it to the last term
The (b+1)
And see what u get
So technically the answers (a-ac)(1+b) and (ab+a)(1-c) are the same thing?
Yes
Np man
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Hey was just wondering how I can save an answer
And recall it
Using my calculator
Like memory recall and such
M+ I think
@ebon ibex Has your question been resolved?
ok an M pops up but how do I paste it
Does M- not remove it?
what's wrong with mine? 
you could read the manual
perhaps
I don't have one
maybe online will
I think m saves it but I am trying to paste now
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hlep
<@&286206848099549185> what do i call a thing that is inf like 3+4k=4k+3
Commutative property
is there a shorter thing?
No
?
for the answer
What do you mean with inf? What you wrote there is just an equality like 5=5
This equation you wrote holds for all k
so u can write anything for k it would be the same
Yes
ok
OHH
I thought like 3+5=5+3
k = 1:
7=7
k = 2:
11=11
Etc.
Oh for all real numbers k
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"how can 5 blue balloons, 4 green balloons, and 3 red balloons be arranged"
Not sure how to solve this
12! is definitely too high
im thinking maybe i have to do something like 3 times 3 times 3, for the 3 red balloons and then 2 times 2 times 2 times 2 for the green balloons and then 5^5 for the blue balloons
wait no
3^3 because there's 3 balloon slots that could be any colour, and then there'll be 4 slots that can be green so multiply by 2?
im not sure tbh
yes
the goddess has arrived
âïž
notice how
for every arrangement
its possible to permute say the 5 blue balloons
but because theyre indistinguishable
all of those permutations are actually the same arrangement
yes
so we need to divide out the repeats if we were to just blindly permute everything
you have 12 ballons, there are 12choose5 ways to arrange the blue balloons, this leaves 7 places. Now there is 7choose4 ways to arrange the green balloons, leaving 3 spaces left. Now there are 3choose3 ways for the red balloons to be arranged
so the total number of ways is 12choose5 * 7choose4 * 3choose3
there is
a very straightforward way of doing this
without the iterated binomial coefficients
the strategy is to just blindly permute
then divide out the repeats
these r the 4 options
there is another way but i find this to be the most straight forward
12P5 * 7P4 * 3P3 = 479 001 600
yes
now the 5 blue balloons can be permuted in 5! ways
but we dont distinguish between them
so we divide out 5!
same goes for the 4 green and 3 red
so the answer is simply
why do we multiply 5! 4! and 3!
divide*
i mean like why do we divide all those by 12 together
because we dont distinguish between the 5! permutations of the 5 blue balloons
they are one and the same arrangement
since they are indistinguishable
so there are 5! copies of each arrangement if you will
=27720*
same goes for the 4 green balloons
there are 4! copies of the same arrangement because we can permute the 4 green balloons 4! ways
and then the 3 red ones
so we divide out the copies
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what is y^a * y^b
.close
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I think these 2 are saying completly diffrent stuff and the one that I underlined with red confused normal distribution with standard normal distribution.... can I please have confirmation? Im pretty confused..
@dense island Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
@dense island Has your question been resolved?
@dense island Has your question been resolved?
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Need to find x using sin or cos theorem
But the thing is that those theoremas only works with triangles so i have to make a triangle from the trapezoid?
yes
can u draw how to make it?
ok and what now?
yes,
would you be able to express it in another way using the 50° triangle?
i.e. focusing on just this triangle, blue = ? (in terms of x)
looks ok
wait i got another idea
solving it with cos theorema
nah this doesnt work
can u tell me solution?
aproximately i get that x=5,25
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Hey calculus question here! I have 2 derivatives, one is an explicit [y=2x (from y = x^2)] and one is implicit [(-x+6)/(-3+y) (from (x-6)^2 + (y-3)^2 = 16)]. How would I find there the gradients are parallel to each other?
Just set the derivatives equal
Yeah but one has x and y in it
Does it equal to 16 too?
It's fine if the equation has both x and y
That equation still represents the points that you're looking for
$2x = \frac{-x+6}{-3+y}$
mchw
the solve for x?
or y, as you wish
I got $x = \frac{6}{2y-5}$
mchw
This doesnt seem appropriate
Does it work like that? Can i just sub it in
Uhhh i got a cubic...
-2x^3 + 5x +6 = 0
Any neat tricks to solve this?
look at the last number
and see if any of its factors give you 0
so try x= (+-) 1,2,3,6
if any gives you 0, then itâs a factor
then you can use that to divide and find other factors
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How to find the equation of the derivative?
@main carbon Has your question been resolved?
<@&286206848099549185>
@main carbon still need help?
Ok so what do u know abt a horizontal tangent
They have a slope of 0
Yes
So another way we can find horizontal tangents on graph of f is to find where fâ = 0
Do u know how to do this
I donât think so
So if we have the graph of fâ
How do we find where fâ(x)=0?
Perhaps rephrasing it may help
You look at zero
On the x value and then look at the ys at zero
So based on ur graph, where is fâ=0
Is it -1?
4?
8, -7
There u go
So -7,-1,4,8?
Yes
Is that it
Are there any more places where fâ(x)=0?
I donât think so
Then thereâs ur answer
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What is the contrapositives of this statement: Let a, b, c â Z. If a|b and a|c, then a|(b + c).
would it be if a does not divides (b+c) then a does not divide b and a does not divides c?
hey
pls
<@&286206848099549185>
There's a symbol for "doesn't divide"
It's like | but with a line through it, kinda like â
@shadow steeple Has your question been resolved?
ok so i have the right answer than?
Oh you're asking for contrapositives
Sorry I didn't read clearly đ
Lemme check
No
The negation of (a|b and a|c) is not (a doesn't divide b and a doesn't divide c)
Remember demorgans laws
so would the contrapositives be a does not /b and a does not divide be so a does not /(b+c)
The contrapositive of p -> q is ~q -> ~p
.
so the contrapositive is a doesnt divide b and a doesnt divide c
but isnt that the opposite
.....
Remember DeMorgan
p in this case is a/b and a/c right?
? how
doesnt negate mean the oppoosite
would it be b does not divide a and c does not dived a?
^
What are DeMorgan's laws @shadow steeple
i mean a doesnt divide b or a doesnt divide c?
This is correct, but it should be "or"
ok so the answer would be a doesnt divide b+c then a doesnt divide b or a doesnt divide c?
as the full contrapositive
Yes
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what would be the best way to go about this
need to see why they have or have not the properties of reflexivem symmetric, anti symmetric and transitive
it might help you to just view each person as being represented by the number that is their height and then (a,b) [heights of person a and b] is in R iff a >= b
well is a person at least as tall as themself?
yes
so reflexive
how would i write that down
height of a >= height of a
so just for object in relation R
a >= a
sure
well you just need to justify that (a,a) is in R for all a
how will that work
a is as tall as someone in a
or as tall as themselves
wait so my answer for if it is reflective or not is just
a is in set A, a >= a, a is in set R?
therefore its reflective?
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Alix
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
hello, you have to use the recurrence principle (or induction principle, whatever you call it)
Also I'm noticing some french words amongst the english ones xd
On peut faire en français stv
ok t'as quoi comme valeur de C0 ? ensuite on pourra faire la récurrence
tu peux me donner la def de Cn ?
ok
Donc
tu veux qu'on commence par quoi ?
donc montrer la formule Cn = (2n n) - (2n n-1)
alors, récurrence = initialisation + hérédité
ah bah
on est d'accord que les nombres de la forme k parmi n sont entiers ?
xd
idem par récurrence
ah non j'ai rien dit
juste une rĂ©currence bĂȘte et mĂ©chante
mais simple
je traite pas l'initialisation parce que voilĂ c'est 1 = 1 - 0 quoi
donc hérédité : soit h dans N tel que P(h) est vraie.
soient i,j tels que i+j = h+1 et j =< i
distingue les cas i=j, i=0 et le reste (0<i<j), tu pourras appliquer la relation ai,j = ai,j-1 + ai-1,j
et tiens donc ! i + (j-1) = (i-1) + j = h
sacré coup de bol, on se sert de P(h)
un peu de calcul et ça devrait ĂȘtre bon
de rien
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Is this 56°?
,w find 2(2x+8) if 2x+8=4x-12
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im still confused on this
This geometry video tutorial provides a basic introduction into the exterior angle theorem for triangles. It explains how to use it solve for x and y. It describes the difference between interior angles and exterior angles as well as the remote interior angles. It contains plenty of examples and practice problems.
My E-Book: https://amzn.t...
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Given this equation, I need to find n values of k where each value of k is equal to the same value of f(k).
$f(k) = ((2971k + 101923) \mod 128189) \mod n$
aiden
I am completely lost on where to begin here or if it is even possible to do algebraically.
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statistics/probability. i completely forgot how to do this and i cant find it in my notes. any guidance? ignore B i just need guidance for A
it's asking about expectation of a binomial distribution
if you know the probability of an event is p, and there are n trials, then the expectation is np
the number of trials expected to result in that event
so .553*300?
yep
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Wilder
So itâs y=3/4x -5 ?
Not quite
Ummmm
You may have misunderstood the problem
Yeah
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could someone help me out with this one please:
I think i know how to do A. A is just the prob of getting 1 head, right? So that would be (.6)(.7)+(.4)(.3)=.54
I dont really understand Expectations though, especially in this context
please @ me if anyone responds
Is B .9?
.close
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How to solve this?
wouldn't it be 1-(45000/52000)^(1/32)
45000 = 52000 * x^32
how would I input in my calc? ti-84
,w (45000/52000)^1/32
huh
ig my teacher put the wrong ans?
what is the time period?
like its not said in the question that it should be monthly
is it monthly?
i guess so
,w (45000/52000)^1/(32/12)
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Cant to understand
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I need help with this problem
ok so
u want to find P(n)
u know
P(22)=280
P(40)=1000
so u can use equations of a line and find that line to find P
p=40n ?
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why isnt it, $$b^4+b^2-5-(-b^4-b^2-5)$$
Mothy
because (-b)⎠â -b⎠and (-b)ÂČ â -bÂČ
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hello i dont understand this question. I understand how to find the answer 9, but im not sure what the second half of the answer is supposed to be. Does anyone know? this is for my precalc class (this is an exam review question)
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first step is change variable, u = ln x
du = 1/x dx
then trig substitution
actually u = 6 ln x might be a better substitution
then du = 6/x dx and you end up with $\int \frac{1}{\sqrt{7^2 - u^2}} du$ which is a fairly straightforward trig sub
rome of oxtrot
-
move 6 out
-
let u1 = ln(x) , du1 = 1/xdx. Rewrite
-
let u2 = 6u1, du2 = 6du1
-
simplify and sub in
@stuck spire Has your question been resolved?
thank you
I really like your pfp!!
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I dont understand the question tbh
wdym it gets straighter?
Ok that makes sense but whats ur question then?
ur already doing it no ?\
Abs(Sin^-1(Opposite/Hypotenuse))
wait why do u want this to be 0
and not 90 ?
are u not the light blue object looking towards the dark blue object?
yea that makes sense bec ur angle is 90 at that moment
just find the other angle then?
wait
if the blue part is the destination
why dont u want it to be 90
but u need to go directly upwards to get to the destination at that point
does urs not work exactly like this?
what i dont understand is why u would want it to be 0 in this case
bec if the destination is directly above
isnt that what you'd need to do with ur model
can u send a gif of how the angles should change for this model
with it being on different y levels
what happens in this model if the the white object is directly below the blue object ?
i meant in the correct model
here ur not moving the direction its facing but in the example gif u are
if the y axis is the same then the angle will always be 0
like ur not moving in the direction the object is facing
ur just moving along the x axis
ok im lost
in this correct model what happens if the white obejct is directly below the blue object
like in ur examples ur not moving in the direction the object is facing which is why u have the 90 degree tilt at the end
in ur example gif u are moving in the direction the object is facing
this doesnt make sense though whats the point of the angle at all in that case ?
if ur just trying to get below it ?
do 90 - (arcsin(opp/hypo)) then?
its just 90-what u have now so its decreasing instead of increasing
theres no point but u can if u want
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@civic marsh
ok
hm
yeap
we have $2^{4x +3 -(1-x)} > 2^{3x}$
duckiescute!
maybe you can try simplify
yes
that's all? what about the sign ?
okok, thank you!!!
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consider what's happening with a smaller sample like 20
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Ooh theyâre square numbers?
yes
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Thatâs great thank you very much
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Does that mean there will be 30 cells unlocked? If thereâs 100 cells in total
I got 3 cells if thereâs 10 in total so I just multiplied by 10 đ€Ł sorry I clearly canât do maths
The largest square below 10 is 9 which is just 3ÂČ, while the largest square below 100 is 81 which is just 9ÂČ
I got 3 cells if thereâs 10 in total so I just multiplied by 10 đ€Ł sorry I clearly canât do maths
what happened to the consideration of perfect squares
did that just go out the window?
Thanks this is helpful
So the answer is 10?
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As in 10^2 = 100
yes
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Lovely thank you sir xx
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Hi, i have this function here.

Do they just mean that i erase the (x-1) lol?
just define it as the val it approaches
YES
should be 2.5
Lmao
LOL
LMAO
GOOD U KNEW
LMAO

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help D:
i tried crossing out multiples of 63?
the highest multiple of 63 is 945
so i thought i would add 2 or 4
im not sure anymore
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<@&286206848099549185>
@lean otter Has your question been resolved?
maybe try like this
let the three digit number be x then
x - 2 = 7a
x - 4 = 9b
where a and b are some constant
you can get a relation between a and b
and you can set lower and upper limits to a and b using the âthree digit numberâ condition
then ig we can do trial and error starting from the upper limits of a and b
its okay now ^^ i got it using lcm and modulo ^^
ooo ok
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if we have 2 matrixes A and B
A is R^4x3
B is R^3x1
the result of A.B is a matrix of ?
4x3 and 3x1 ?
Ah ok
sorry yeah
In one place I read that the result of the product of two matrices will have as rows, the number of columns in the left, and as columns the number of columns in the right
rightt?
Each row * column multiplication creates a new cell
but in other places I read other things :/
so in this case, it would be a 4x1 matrix?
so R^4x1
meaning this is ok
yep
each row in the first matrix produces a cell, each column in the second produces a cell so there are 4*1 cells ie. its a $4\times 1$ matrix
nice job
Max..
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is there any method that can help me solve guassian elimination more easier
cuz there are some problems that I cant solve
Well first of all rewrite it as a matrix
Then I like to work from the top down but sometimes it makes more sense to swap rows
let me sceeen shot wat I did
Idk if I can do this
I tried coming up with a way simular to how u solve fractions but it just makes it more complicated
sometimes no way round it
idk wat to do anymore I practically going to fail this class
so many different ways to solve a problem and I have no clue why doing it a certain way is correct
that's the beauty of linear algebra
dont view it as 1 way to solve, linear algebra there are loads and all correct
You know what row operations are @plain hedge ?
swap, multiply,add?
yeah
Your goal is to make the first number in one of the rows equal to 1
even if it means dividing by 5
yes your working will be messy but there is no way around it
this would be my first step
then you can minus the first row from the second twice
and the same for the third row
and boom it is simplified slightly
then when u do that this is what the equations mean
see how that system is much simpler thanbefore?
Linear algebra doesn't exist, it is a nice for human friendly way of solving simultaneous equations
as it's easier to follow than 200 variables and gives a algorithmic approach rather than a random approach
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is this limit proof correct? i tried following a YT video. if its correct. how does it actually prove the limit?
I can't really follow this proof
I guess you're trying to find an M, given epsilon, so that for n>M the function is less than epsilon
?
But what's the value of M
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A water tube in the form of a cylinder with a length of 12 meters and a radius of 1 meter filling with water so that the height increases at a speed of 3/4m/h Find the rate of change in the surface area of ââthe water when the height of the water becomes 1/2m
can someone show me how can i draw this
i don't need the answer just how to draw it
forget it ^
.close
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broo i dont know how to get the answer
i know how to complete the table but i dont know how to do the second answer
$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$
VardhanR
have you come across this b4? if not i'll explain in a different way
i have but i dont understand
Okay, so, $(x_1, y_1)$ and $(x_2, y_2)$ are points that they have given. In this case, $(-1, 5)$ and $(1, 1)$ is what they have given. So here, $x_1 = -1, y_1 = 5, x_2 = 1$ and $y_2 = 1$. Substitute this in the eqn and solve for $y$.
VardhanR
So the eqn is used like this... when (x1, y1) and (x2, y2) (two points) are given, we can substitute those given values into this formula and rearrange the eqn to find "y".
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Iâm trying to find dr/rt
Help me solve the 4th Q
But this wonât work idk why
<@&286206848099549185>
,rotate
This is mine
oh wait okay
Wow here itâs Friday 9:30 pm
suppose rational number $a / b$ where $b\neq 0$ and $a,b$ are ints. notice that this satisfies the eq bx-a=0
VardhanR
@sharp nimbus
Wow first he steals my channel next he gets an answer before me
i know the ans to that one XD
@outer apex can u really not help me regardless
dr/dt or dR/dx?
Dr rt
Then I donât know because thereâs no small r and nothing dependent on t
How about dr dx
Oh wait
dR/dt
dR/dx?
No
But R(x) is a function of x not t
It says find the rate in revenue when production is 1000 switches per day
Tell me dR/dx then
Did you already cover derivatives in school
What is the derivative of 12x - x^2?
Thatâs how I got here
Itâs supposed to be a number
Plug in 1000 for x
Wtf does the sentence âProduction is increasing at 100 switches per day when production is 1000 switchesâ mean
Ok so letâs say production(x) = 100x + 1000
Actually, no
I donât get the task yet
Do they mean âcost is increasingâŠâ instead of production is increasing? Because that would make more sense
Maybe itâs a typo
$\frac{\dd P}{\dd t}=100\vline_{x = 1000}$ i think
Iâm trying to upload a pic hold on
VardhanR
Yes maybe but we donât have any info about production in the text at all. Only that x is the daily production
Wonât upload sadly
ohhhhh so production is "x"?
Yep
ohhh yaa
They talk about increase in production and in the sentence about increase in cost I think production is a typo
given
C(x)
R(x)
dx / dt at x = 1000
find dC / dt at x = 1000
this is what i interpreted
x is a variable
t is nonexistent in this exercise
so find dC / dx at x = 1000 and do that times (dx / dt at x = 1000)
the final ans would be dC / dt so time is relevant rgt?
No x is just daily switch production we donât need to introduce a t
Yes but we donât need to introduce time as a new variable
x is already per day
ohhh right
Yeah I donât understand the exercise I think itâs badly worded
same
@wide finch
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@outer apex found this on math stack exchange
I tried to replicate it
<@&286206848099549185>
Hello
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Our teacher has never actually shown us how to write a Big-Oh proof
Is this format acceptable? And, are these correct
Mind the little mistake in the last part of the second image. Just noticed and fixed that
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Bro im gonna die
Some sources of google say its that soem say its that im so annoyed
Someone help
Is this rifht
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do you know your trig functions?
also pls start by posting your work so we know where we start
@wicked whale
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if you distribute $-(x^2+2x)$ you get $-x^2 -2x$. $11x - (-2x)$ which is $13x$ not $9x$?
kangaroo rat
$(x^2 + 11x + 18) - (x^2 + 2x) = ...$
Gijs
i did it vertically
and here the - isn't being distributed?
$(x^2 + 11x + 18) - (x^2 + 2x) = (x^2 + 11x + 18) + (-x^2 - 2x)$
Gijs
doesnt matter actually, its the same thing
I thought you distribute them then subtract them?
okay suppose (1+2)
so you can distribute a negative then add or subtract
and you want to subtract (1+1) from (1+2)
then would you subtract (-1 -1) from (1+2)?
no you would just do (1+2) - (1+1)
Oh yeah so that was the problem, thanksss
@compact ferry So where did I go wrong?
how would i subtract
How would I subtract 11x-(-2x)
okay suppose you have a term lets call it x
then you want to subtract y from x
so you find x - y
thats it
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A cubic function with a negative leading coefficient and only one zero at đ„ = 4 and two non-real zeros
what is a non-real zero?
imaginary roots I think
A non real solution can be geometrically viewed as not touching the x-axis
adenine is right
HAHAH
do you have an example i dont really understand
ai+b
Suppose if you have a quadratic equation $x^2+4x+5=0$
The classic factoring idea wonât work, as you can see; there is no two real number which we can multiply to get to 5 and add to get to 4 (why?)
so obviously the solution cannot belong to the set of real numbers
cause discriminate<0
Moreover i can see, if those numbers were 1,5 i could only add to get a bigger number
So it wonât makes sense with real numbers to go back while adding making the product stays positive
,w plot x^2+4x+5
Graphically, the curve will not intersect the X-axis giving a root
so if i was to graph this,
would it look something like this?
the question i have is to graph that equation and it says theres a zero at x=4
i meant to put it at 4 not 3.1 :p
how would i get 2 non zeros
So it will cross through x=4
You can plot any cubic function that crosses with x axis only once
so the function has 1 real zero solution and 2 non real zero solutions right?
but im really shit at proofs


