help-23

[merry sleet]

when theres a -

you can always have

+(-1)

so -1 * -3?

[azure stone]

3

just to confirm, 12 + (-6) would also be wrong in this situation right

[merry sleet]

it would be since its the same

as this

[azure stone]

12 - (-6)?

it'd be 18 tho

hold on

bruhhh wait its 12 - (-6) right

🤡

my brain just fast fowarded the question to equaling 6 so it didnt think that 18 could also be the answer

[merry sleet]

it is

[azure stone]

if i thought slower i'd have found it

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[lean otter]

I am unsure how this happened

[lean otter]

derivative of sin is cos, and we are doing chain rule. that’s all I know I get lost in the midst of the work

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[topaz wolf]

Hi im confused about radicals

[stray socket]

what about them specifically

[foggy salmon]

what about them

[topaz wolf]

I really just dont understand the concept of them

but here's a problem from one of my hw 6 v/329

[stray socket]

i mean its just a square root

[topaz wolf]

ohh mk i think i might be overthinking about it then

thank you

[stray socket]

Wait hold on

[topaz wolf]

Ah alright

[stray socket]

did you mean $6\sqrt{329}$ or $\sqrt[6]{329}$

[flat frigate]

Umbraleviathan

[topaz wolf]

first one

[stray socket]

okay then its just 6 times the square root of 329

[topaz wolf]

ohhhh

that makes a bit more sense

[stray socket]

if youre done, close the channel

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[dusty scarab]

so you need to choose delta in the domain s.t. the function in that punctured domain is less then one away from 2 in value

no

if you pick 1.5

than this does not check out

|f(0.5) - 2| = 1.5 > 1

thus the point 0.5 should not be in your scope

yes

so you need to tick 0.5, 0.7 and 1

no this is too far

every delta bigger than 1 will get you to domains in which the function is too far from 2

f(x) should be between 1 and 3 exclusive

no, you are talking about delta = 2.5

not x =2.5

delta <= 1

1 < x < 3

bcs if delta = 1 this still holds

the < comes in the restriction of |x-2| being strictly smaller than delta

so delta can be 1

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[near moon]

Hey, I don't know if I can ask for physics help but I need it. There was an assignment that I did and I had a question that goes: In the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. In one event, the sled reaches a top speed of 9.2 m/s before starting down the initial part of the track, which is sloped downward at an angle of 8.0 ∘. What is the sled's speed after traveling 140m? I got the question wrong and I am wondering how I do this? I felt that I had a decent idea of what to do but clearly I was wrong.

[nova creek]

Start by drawing a picture

[near moon]

Alright, should I draw a model of it? Or more of a graph?

[nova creek]

Just a little picture of the situation. Enough to get an idea of what's happening

[near moon]

Alright so Ive got a poorly drawn model, my drawing is not the best

Would you like me to send it?

[nova creek]

Yes

[near moon]

very small

[nova creek]

I can see it fine

[near moon]

Alright

[nova creek]

When the sled is on the slope, what forces are acting on it?

[near moon]

Wouldn't we have Gravity, Normal force, and Friction? Or is there something else that I am missing?

[nova creek]

Yes

Though friction can be assumed to be negligible

And the normal force won't have any affect on the sleds acceleration

Gravity is acting on the sled with a force of mg straight downwards

How much of that force is acting in the direction of the sleds motion?

Aka, along the slope?

[near moon]

Wouldn't all of the force be acting in the direction of the sleds motion? Since we're going down hill and gravity is pushing it downwards?

[nova creek]

Gravity is pushing directly downwards

But the sled isn't moving directly downwards

Only a part of that downwards force is acting in the direction of the slope

[near moon]

Ah alright, so would it be 92% of the force? Since there's an 8 degree slope?

[nova creek]

Not quite

Sorry for the very not to scale drawing

We effectively have a triangle

With a hypotenuse mg

We want the "length" of that blue line

Which we can find with trig

[near moon]

Alright, sorry if I'm wrong I'm quite new to both trig and physics, so I will use the 8 degrees and the 140m to find the length of the blue line?

[nova creek]

No, the 140 m isn't coming to play yet

[near moon]

Alright, so could you explain on how I find the length of the blue line? Or at least how to set up a way to find the length of the blue line?

[nova creek]

First, what's that blue angle?

[near moon]

Would it be 10 degrees? Or 80?

[nova creek]

Where are you getting those from?

Note that gravity (mg) points straight down, and that top line points directly horizontal

Thus there's 90 degrees between them

[near moon]

Well, looking at the triangle I had originally assumed that the 80 and the blue were equal than I quickly changed my mind on that because I noticed a difference between the two, and I got 10 because I had assumed that the 80 was the the angle caused by the Hypotenuse and the Adjacent lines meeting. If you cannot tell, Trig is not my strong suit, I'm trying to learn though!

[nova creek]

Note that the blue angle plus the 8 degree angle add to 90 degrees

So what must the blue angle be?

[near moon]

82 degrees?

[nova creek]

Yes

Now, do you know SOH CAH TOA?

[near moon]

Yeah

[nova creek]

We have the hypotenuse, and we want the length of the side adjacent to the 82 degree angle

What trig function relates the hypotenuse and the adjacent side?

[near moon]

Wouldn't it be the Cosine?

[nova creek]

Yes

So using soh cah toa, what should cos(82°) be in terms of our triangle?

[near moon]

Would it be 0.14?

Or like 0.139

[nova creek]

Thats the numerical value of cos(82°)

But I want the value in terms of our triangle

Remember, cos = adjacent/hypotenuse

[near moon]

Ohhh alright

Wait, I don't understand, could you explain?

[nova creek]

We want to find the adjacent side, let's call it x

And we know the hypotenuse is mg

So if cos(82°) = adjacent/hypotenuse, how can we write that knowing those two facts?

[near moon]

Would it just be x/mg?

[nova creek]

Yep

And solving for x?

[near moon]

Yes?

[nova creek]

What's x?

[near moon]

Ohhh thats the question alright

Then wouldn't it be 0.14mg?

[nova creek]

Yes

Though I'd be a bit happier if you used a few more decimal places, if you don't want to keep it as cos(82°)

[near moon]

Alright so 0.1392mg?

Or more?

[nova creek]

That should be plenty

That's the force in the direction of the sleds motion

And F = ma

So what's the acceleration of the sled?

[near moon]

How could we find that? I do not understand how we implement that into our formula

I know we'd change it to be a=f/m right?

[nova creek]

F = ma

We know the force is 0.1392mg

[near moon]

Alright

[nova creek]

So what does that equation become

[near moon]

0.1392mg=ma?

[nova creek]

Yep

So what's a?

[near moon]

Would we isolate the variable? Turning it into a= 0.1392/m mg?

[nova creek]

Do you see anything that cancels out?

[near moon]

Ohhh

So just a=0.1392g?

[nova creek]

Yes

Now

We know the initial velocity of the sled

We know the acceleration of the sled

We know the distance the sled travelled

We want the final velocity of the sled

Do you know any equations of motion that relate these 4 quantities?

[near moon]

vf^2=vi^2+2ad?

[nova creek]

Yes

What do you get when you plug in the known quantities?

[near moon]

Would it be 466.995? Or did I plug them in wrong?

[nova creek]

Let me check

I didn't exactly get that, but I got something very close

What value did you use for g?

[near moon]

Op whoops

I accidentally put 9.81

[nova creek]

That's good

9.81 is more accurate than 9.8

[near moon]

Did you use 9.8?

[nova creek]

I did

Did you accidentally put 9.81 without realizing gravity is more specifically 9.81 (on average)?

Cuz thats pretty lucky if so

[near moon]

No, I put 9.81 and tried to cover up my what I believed to be mistake lol

[nova creek]

I see

Well, we know what v_f^2 is

So what's v_f?

[near moon]

21.610?

[nova creek]

Yep

There's our final answer

Give or take for rounding errors

[near moon]

For the assignment they rounded it to 22 for some reason

[nova creek]

Probably sig fig stuff

9.2 is 2 sig figs

So they probably rounded to 2 sig figs

[near moon]

Ahh that makes sense

[nova creek]

Welp, I gotta sleep now

See ya

[near moon]

Thank you so much! Sleep well man!

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[ripe crystal]

I'm confused because I thought the rule would make it 2pir not r^2

That's the answer key BTW I'm just confused how the derivative of that formula resulted in a 2/3pi * r ^2 * dr/dt when its multiplying h by the derivative of r^2 but the result is still r^2 in the answer key

I'm sure the answer key is correct just not sure where i'm not understanding

[warm stirrup]

you're correct that's a mistake in the answer key

[ripe crystal]

Ok thank you

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[tidal bay]

I need some help on my math Mobius homework, its based on functions precalc 12

[tidal bay]

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[pallid night]

whats 2+1

[scenic gull]

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[zenith hare]

can this problem be done without the triangle area formula?

[idle parrot]

well i know a pain ass method

||heron’s formula||

[zenith hare]

oh

[zenith hare]

lemme try that

[idle parrot]

first thing is to calculate all 3 lengths

by distance formula

then apply heron

but you can simply use determinant formula for area, life’s much easier that way

[zenith hare]

yeah i wanted to see if i could do it that way too

thanks

actually why im get such wild values

from distance formula

[idle parrot]

because i told you, it is pain in ass method

[zenith hare]

nah i didnt even apply herons yet

and already got 2 values in underroot💀

[idle parrot]

[zenith hare]

well i do it form the formula anyways

btw can u check my answers

[idle parrot]

uhh okay

[zenith hare]

wait let me click a pic

@idle parrot

Did I get it wong?

Wrong

[idle parrot]

,w distance between (3,0) and (8,4)

[flat frigate]

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[idle parrot]

seems wrong

,w distance between (7,0) and (8,4)

[flat frigate]

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[idle parrot]

25+16=41

[upbeat swan]

sqrt 49 is 7 btw

[idle parrot]

you don’t need to know that btw

[upbeat swan]

rly

[idle parrot]

yes we don get sqrt 49

[zenith hare]

oh yeah it was 41

[idle parrot]

we get 41

[zenith hare]

i wrote it 41

[idle parrot]

lol

[zenith hare]

so yeah as i said i got 2 underroot values

now i learned the formula

[idle parrot]

now use herons

[idle parrot]

told you

[zenith hare]

nah i ain't underrooting those underroots

[idle parrot]

not the easy

well you can just approximate

,w sqrt 41

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[idle parrot]

,w sqrt 17

[flat frigate]

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[idle parrot]

not that hard ig

[zenith hare]

the answers tthen would be too far off then lmao

[idle parrot]

just computational part

[zenith hare]

not hard but annoying ngl

[lean otter]

It gets better with time lol

You just need to know the nearest perfect square

And then you just approximate

[zenith hare]

Is this correct

[idle parrot]

how is it different than approximate

[zenith hare]

What do I approximate of √41

[lean otter]

Didnt say it is

[idle parrot]

lol

6.40

[lean otter]

So nearest perfect squares are

6²

And 7²

[idle parrot]

,calc 6.4*6.4

[flat frigate]

Result:

40.96

[lean otter]

And it falls between them

So the square root should roughly fall between them

Around 6.5

Ish

[idle parrot]

or just use newton’s method to calculate sqrt

ez

[lean otter]

Can also

Use that

Long div

Method

[idle parrot]

[lean otter]

7th class one

Bt i Forgor

[zenith hare]

underroot by long divison?

[idle parrot]

i don’t even remember being taught that

[zenith hare]

what is it

[lean otter]

[lean otter]

Dont remember the name

Precisely

Gimme a sec

[idle parrot]

oh it is nice way to approximate , most calculators use it

u can lookup

[lean otter]

https://youtu.be/jUpPiNLb5wM

[zenith hare]

ah i know this method

i also forgor it

but learnt it again like 5 days ago

for exams 💀

[lean otter]

🤣

[zenith hare]

well im done here so

thanks guys

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[plucky moon]

What was the equation for solving a side

when hypotenuse and angle are known?

We know R and that the angle is 45 for both a and b

[silver dragon]

Either cos(angle)=adjacent/hypotenuse or sin(angle)=opposite/hypotenuse

If the angle is know, we can take the inverse sine or cosine

[plucky moon]

aight

so 45=(1/2x)/R

[silver dragon]

Well for what value are you solving for

[plucky moon]

1/2x

half of x

which can be used to calculate x

[silver dragon]

And angle a is 45?

[plucky moon]

since well, its half

yeah

[silver dragon]

Ok

[plucky moon]

I mean its a question from my calculus course, so Idk if im doing this right

Or with the way its intended

But you know

fuck it lmao

aint no correct way mentioned

or the way you have to do it

[silver dragon]

So it would be if you want to find that side in general, it would be Rcos(angle)=1/2x

[plucky moon]

aight

Thanks

[silver dragon]

Ye

[plucky moon]

gigachad gaming indeed 💀

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[zenith glen]

I'd like to understand how to factorise cubic expressions, 2x³ + 9x² + x - 12 for example

[burnt bloom]

rational roots theorem

[thin bridge]

if you can't factor by grouping, approach with rrt and hope for the best

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[zenith glen]

I forgot I even asked. Thanks, I'll check further

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[spark bobcat]

is the graph a function and how do I know?

[cinder viper]

Vertical line test

Take some vertical line and pass it through the graph

[spark bobcat]

so what do you think the answer is, im a little confused

[cinder viper]

If the vertical line touches the graph at two points then its not a function

[foggy salmon]

the constant fn cant be a fn

inverse doesnt exist

[spark bobcat]

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[lean otter]

can someone explain why we cant have a 6,4,10 triangle?

[tulip arrow]

Yeah so

[glass carbon]

because the longest side isn't greater than the sum of the others

[warm stirrup]

6+4<=10

so it's degenerate

(line)

[tulip arrow]

It should be greater than the third side

[lean otter]

how line

they have the same lengths, so why cant it form a triangle?

[tulip arrow]

I doubt if they’ll understand that bcuz they seem young

[warm stirrup]

they aren't allowed to be equal

[burnt bloom]

degen

[tulip arrow]

Sum has to be greater than the third side

[lean otter]

That is what I dont get

[thin bridge]

consider triangle construction with a compass and ruler

[lean otter]

I know the principle but it does not make sense to me.

[tulip arrow]

It uses the pythagoras theorem

https://youtu.be/gSmuLNGpf_E

Have a look at this video

[lean otter]

I want an inituitve understanding

[lean otter]

a+b>c where C is the opposite side. I know this, but I dont understand it

[lean otter]

okay

thanks

I get it.

they never meet.

[thin bridge]

the arcs/circles meet on the line/base

[lean otter]

okay.

.close

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[lean otter]

Hello

I dont even know where to start

this is a practice problem for an upcoming calc 3 exam

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

<@&286206848099549185>

[fickle axle]

I'd suggest to make a 3d graph of it, and see if you can find a line that parametrize the intersection.

[lean otter]

so a cylinder about the z axis within 2 , -2 for x and y

[fickle axle]

Yes, and there's a plane cutting through it. We are looking for where the cut (intersection) is

Are you allowed to use graphing calculator i.e. geogebra 3d for this? Visualizing should help.

[lean otter]

no i can not but i do have it graphed

not in the exam i cant

[fickle axle]

Ok.

We know that the cut is on the cylinder, so for our line L(t)=(something, something, something), the x, y coordinate must trace the circle x^2 + y^2 = 4 that is used to make the cylinder (Imagine looking down onto the xy plane.
We know how to parametrize a circle, so we have the x and y component for L(t)
Now we know x + z = 7, z can be represented by x, then use what we know about x, we can know the z component

[lean otter]

i dont even know what a parametric is man lol

z= 7-x

?

then what

[fickle axle]

Yeah this is right

By parametric I meant a function that can represent a line. For example:
A(t)=(t,2t)
Since this is not the problem itself, you can try see it on desmos (t,2t). You should see the point going on a straight line when you move t around.

Another example is a circle:
(cos(t), sin(t)). Again, try it in desmos, the line should trace out a unit circle.

If that makes sense, the problem asked you to find something that can trace out the intersection given from the problem.

[lean otter]

ok and now what is the next step

[fickle axle]

The next step is

z can be represented by x (which you have found: z = 7 - x), then use what we know about x, we can know the z component.

[lean otter]

oh

ok i got it

thanks

[lean otter]

this helped

z=7+sq(2)+sq(2)t

[fickle axle]

Make a check, plot some points in and see if it satisfies x^2 + y^2 = 4 and x + z = 7

[lean otter]

i can get z from this

but idk how to get x and y

[fickle axle]

The intersection is on the cylinder, so it must look like the circle on the xy plane
So you need ( something for x, something for y) to trace out that x^2 + y^2 = 4

[fickle axle]

Then again, back to this step, you use your "something for x" to get "something for z"
Once you get all of them, you have
(Something for x, something for y, something for z)

Remember, you're after all tracing a closed loop or some sort, so the (Something for x, something for y, something for z) must be periodic

[lean otter]

x=7-z

y=7-z

x=-sq(2)-sq(2)t

but then for y i would get the same thing

?

oh wait

y=x-2

y=2-x

[fickle axle]

My time is limited.
I recommend looking up some video about parametrization. Say, parametrization of a circle. This should help with the problem and ones of its kind

[lean otter]

thank you very much friend

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[fleet sentinel]

alright 2 questions sory guyz i didnt pay enough attention in class

[fleet sentinel]

a) did i do the first part correctly b) how would i go about the second part

idek what dy/dt means tbh

like derivative of y with respect to t or osmething

[dusty scarab]

exactly

and i think you did the first part correctly

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[teal linden]

How would I find the slope of a graph like this?

[fathom lake]

Slope of any point?

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[teal linden]

the whole thing

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[shy garnet]

i can’t look back so if someone could help me

[worthy hemlock]

Why can't you look back?

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[full citrus]

why 2cos(pi/12) and not 2cos(-pi/12)
i mean what do we choose

[full citrus]

is it not because cos(pi/12) = cos(-pi/12)?

[obtuse jackal]

cos is an even function so they're equal. Since you can choose either one, you might as well choose the simplest to write/understand

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[eternal briar]

I’m in algebra 2 and I have trouble doing this problem

[eternal briar]

I know I need to move the 7 to 3 so it’ll be 4z^2 + 15z -4

[grave flint]

do you know how to factor non monic quadratics @eternal briar ?

[eternal briar]

I forgot

Algebra is too hard!

[eternal briar]

Can you show me or help me how?

[grave flint]

have you been taught?

[eternal briar]

Yea

I just don’t remember

[grave flint]

https://www.youtube.com/watch?v=vjjWf5a1_Wk&t=3s

https://www.youtube.com/watch?v=vt491JmFgP0

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[fleet chasm]

What is the density of hydrogen at 20°C and 101.3 kPa if air is taken as
reference at 4°C and 101.3 kPa. What are the volumic mass of the two gases at these conditions?

I found density by doing 0.09/1.293 which are the values for the hydrogen and air

But for the vol masses I am just unable to land on the answers of 1.27kg/m3 for air and 0.0838 for the h2

[fleet chasm]

I know that the formula should be d = M/Mair

I think so

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[mighty sundial]

I was doing linear functions when i found the problem of tabulating x= 3 , y= -1, there was no equation included

[foggy salmon]

whats the

full Q

[mighty sundial]

it says:
Tabulate

x=3
y=-1

nothing else

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[mighty sundial]

<@&286206848099549185>

[dusty mauve]

isnt a tabulations like

u just make a table with the values

[mighty sundial]

ye but how

💀

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[mighty sundial]

WELP

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[patent crescent]

I’m stuck here I don’t know exactly how I should find my answer for this I’m trying to find 2x I believe so what i thought was to do 2x+x+x=180 is this how I should start

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[patent crescent]

I did 180 divided by 2 which equals 90 I believe I got my answer for x I think

[foggy salmon]

this

channel is closed

also

#❓how-to-get-help

@patent crescent

[patent crescent]

👍

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[night grail]

I'm not sure what I did wrong here 😭 My answer and the book answer are almost identical, I'm just not sure how they got 2y-1/8 and 7/8

[night grail]

<@&286206848099549185>

[worthy hemlock]

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[night grail]

15mins?

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[hot scaffold]

how can i eliminate the arbitrary constant?

[foggy salmon]

whats the 3 methods

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[hot scaffold]

by differentiation and combination, isolation method anf by determinants

I have tried to differentiate the given equations according to the number of arbitrary constants. but I don't know how to eliminate the arbitrary constants using algebraic manipulation.

<@&286206848099549185>

<@&286206848099549185>

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[lean otter]

The answer is 300 but idk how to get it

area of parallelogram = l x w right? APD = 39cm^2, then a line from AB or DC passing through P then would make another parallelogram with area 78cm^2 ...

im not sure if i am on the right track

[foggy salmon]

um

so

notice that

APD and BPC take up a total of half of the para area

it takes up half of the pink area

and half of the blue area

uk that those 2 total 50% of the para area

BCP is 37%

so APD is 13%

n also has area of 39cm2

so u think u can work from here?

[lean otter]

is it really half or we just assumed its half D:

[foggy salmon]

its half

the

due to the property of the parallelogram

that pink line i drew in the middle

let it be para to AD and BC

so then it has the same len as well

as AB and CD are also para

so then u can see that

that pink thing is like a parallo

so that tria

ADP is just half of it

cuz ADP is just

half of base * height

area of para is just

that same base * height as total area

so its literally half

[lean otter]

which property? im confused

[foggy salmon]

similar arg to bottom half

um

the fact u can just

split it at that pink line

where that pink line is also para

n of same len

[lean otter]

yes, but it doesnt look half of the whole para

[foggy salmon]

..

well

my drawing is bad ok

[lean otter]

no i mean in the original figure

because APC and BPD are not straight lines

so i didnt think it would be half

[foggy salmon]

yea just

split it into two other parallelograms as i did

to show it

if u wanna show it

but generally showing it is a bit excessive unless they explicitly ask u for it

[lean otter]

oh wait i think im getting ur point

i'll try to solve again

[foggy salmon]

yayyy

[lean otter]

@foggy salmon

[foggy salmon]

um

seems nearly right

just that

i would recommend not putting units if u arent gonna put em right

or consistently

so like

just dont put them throughout

or consistently use

cm^2

like the first 2 u used cm

which is wrong

the last one u didnt put units

anyway

but the numbers are correct

good job on that

[lean otter]

ty! gr5 is hard

[foggy salmon]

yes

[lean otter]

.close

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[rugged vault]

Why is this considered wrong?
If I solve for 0 in the bottom it gives -7/2. The fraction is (3x+2)/(2x+7)

[timber atlas]

Those negative looks sus

Maybe look at the graph of this function

Sorry, i meant these ones

[rugged vault]

I think that is just how the program formats it. it worked for all the other questions

[timber atlas]

Hmm.. weird

[rugged vault]

Does it have to be an intersection rather than a union?

[timber atlas]

If it maybe works for the program, then

[rugged vault]

.close

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[lean otter]

How did it end up as g(x) = 5x +1

[lean otter]

try writing out f(g(x))

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[burnt ridge]

So I have always had trouble with decimal multiplication (Ik Im dumb lol) and I can’t figure out what I did wrong with this question. (The answer was 22.496) (My writing is wonky lemme know if you need help reading it)

[foggy salmon]

WOW

[burnt ridge]

lolol

[foggy salmon]

the amount of self deprecation

is unreal

[burnt ridge]

I have been told all these things (besides dumb other then my friends teasing me)

[foggy salmon]

ur friends bit mean

,calc 5.92*3.80

[flat frigate]

Result:

22.496

[thin bridge]

,calc 3*592

[flat frigate]

Result:

1776

[foggy salmon]

,calc 5.92*.80

[flat frigate]

Result:

4.736

[foggy salmon]

ok for one, uve to put the decimal place in the

4th spot

like

after the 4th digit to the right

cuz thrs 2 from the first decimal n another 2 from the 2nd

,calc 5.92*3

[flat frigate]

Result:

17.76

[foggy salmon]

also u forgot to +2 here

[burnt ridge]

alr Ima send a picture of what I think you mean

[burnt ridge]

oh ye lol

[thin bridge]

you don't really need to worry about putting the decimals in the intermediate work depending on how you set it up
you can write out a multiplication table for 592 * 380
since there are 2dp in each of the numbers being multiplied,
you would be shifting a total of 2+2 = 4dp at the end

[burnt ridge]

Like that? (Because there are 2 numbers past the point we put the decimal point two numbers inward on the answer?)

[foggy salmon]

nono

like

that pjink dot

u want 4 digits

after the decimal

cuz its 2+2=4 fo the decimal bit

[burnt ridge]

ohhhh

so you go inward from the right 4 times because there are 2 numbers past the decimal point for each number? So if I had 2.22 and 3.3 would it still be 4 because you have to do 2.22 x 3.30? or would it be 3?

[thin bridge]

depends on how you set up your multiplication

there's no real need to use 3.30

[burnt ridge]

because the 0 is just a placeholder, so it wouldn't count?

[foggy salmon]

so

[thin bridge]

if you set up your multiplication table with 222 * 330, you'd shift by 4
where as you could just use 222 * 33 and shift by 3

[foggy salmon]

the reason why we use

btw use

triple `

anyway

yea u can think of it as multiplying as some base of 10

like

2.22 is 222 * 10^-2

so we just approriately apply the decimal place after

or during idk

[burnt ridge]

ok so I did a few of the practice questions after that, and I got them correct. Thx for helping me with simple math! :P

[foggy salmon]

hais

dont

self depricate so much

np

[burnt ridge]

lol its my thing

.close

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[foggy salmon]

i meannn

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[viscid gate]

Hello I need help I’m solving for y=mx+b but I have no idea how to solve the 16=-2(2)+b part and I somehow got (-4)

[green lichen]

yes that’s right I think

:)

[viscid gate]

Thanks I figured it out

How do I close the help thing

[green lichen]

.close I think

[viscid gate]

.close

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[viscid gate]

Thanks 😊

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[glass carbon]

as I've said mark voltage drops in opposite direction

[lean otter]

ok then

[glass carbon]

then form a system of equations

using Kirchhoff's laws

[lean otter]

should i take it as -30 or +30 while applying kcl

kvl i mean

is this correct

[glass carbon]

yes, it's about 1st loop

[lean otter]

but cell is from - to +ve ryt so it should be +30 ryt

thats my doubt

[glass carbon]

u can do it in opposite direction (anticlockwise) also, but you're wrong anyway

then it would be 30 - v1 - v2 = 0

but it's the same thing, it's enough to multiply equation they got by (-1)

[lean otter]

ok thanks

[glass carbon]

apply KVL to loop 2 and KCL to upper node

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[mighty cypress]

i need help please

my deadline is freaking in 3 hours

[foggy salmon]

[mighty cypress]

ok true kinda sus

BUT ME NEED HELP

PLEASE

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[sudden birch]

U is like a cup: you pour all of the (unique) elements that belong to A and B together

Upside down cup is opposite: you slam the cup down and get into ur cup a limited number of elements, elements that are only shared between a and b

[edgy cloud]

Deadline for what? Is this a take-home test where you're not supposed to receive outside assistance?

[safe radish]

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[pine pumice]

I'll be trying my luck and see if anyone can help me figure this out:

I'm trying to understand the effects of a gabor kernel convolved over an image on that image's magnitude spectrum. For context, I am starting out with this image.

[pine pumice]

now I convolve it with this kernel

the left portion is somewhat intuitive to me as convolving with a gabor kernel lets you detect edges (although I might have chosen the kernel poorly for this example)

I am failing to grasp in what ways it affected the spectrum

and/or if there is any intuition as to how the spectrum is affected at all

e.g. convolving with a guassian kernel should lead to a loss in details, which should be reducing brightness around the edges

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@pine pumice Has your question been resolved?

[burnt bloom]

this qn straight up sus...

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@pine pumice Has your question been resolved?

[fathom temple]

what are you even talking about my guy

[spiral crescent]

||amogus||

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[opal parrot]

?

[fathom temple]

if two lines are perpendicular then m1 * m2 = -1

that is the multiplication of the two respective slopes

[opal parrot]

ohh

would it just be 1/4 too tho

[proper crypt]

no

They need to multiply to -1.

slope of A times slope of B = -1

[opal parrot]

ohh

[prisma trellis]

The slope of line B would be the reciprocal of the slope of Line A but negative

So just flip the fraction upside down, which gives you 4 but you have to make it negative as it's perpendicular to A

[dusk vapor]

Hunter

[opal parrot]

i got 0.25

[opal parrot]

oh so -4/1

[dusk vapor]

Hunter

[prisma trellis]

Right!

[opal parrot]

:D

[proper crypt]

@dusk vapor can u stop messaging me in other help channels

[dusk vapor]

My bad

[proper crypt]

for no reason

just DM

[opal parrot]

btw love ur pfp 🫡

.close

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[proper crypt]

ty

[safe radish]

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[wraith swift]

can someone elaborate

i was studying chemistry and came across two graph for Pressure vs volume(boyles law)

so how? isnt it the smae thing

[long wigeon]

I'm not too advanced in chemistry

[broken yew]

the graphs certainly arent the same?

[long wigeon]

but I did notice that,

yx = k

[wraith swift]

i can see that but how

[broken yew]

yx = k
y = kx are different

[long wigeon]

solving for gives y = k/x

rational function^

[broken yew]

divide the top equation by x on both sides

[long wigeon]

compared to a linear function y = kx

[broken yew]

yh

[wraith swift]

didnt notice

mb

[long wigeon]

y = k/x and y =kx are completely different

[wraith swift]

made a fool out of myself

[long wigeon]

it's all good

[wraith swift]

thnx

.close

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[fickle trail]

Is this legal what I did?

I’m not used to canceling numbers with a different sign..

[spice grove]

ye

$\frac{4(-1 \pm \sqrt{2})}{4}$

[flat frigate]

What the hell am I doing here?

[spice grove]

Is what it becomes

[fickle trail]

Ahh yes Ty I forgot I could distribute

That makes sense when I see it that way

.close

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[opal parrot]

.close

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[lean otter]

Hello!

I am stuck at a problem where we have to find the largest integer smaller than $\sqrt{n^2 + 6n}$.

Can anyone, please, help me ?

[flat frigate]

trololol !

[split ether]

Find the maximum of n^2 + 6n

[lean otter]

maximum ?

thats infinity

[split ether]

smaller than or equal to?

[lean otter]

btw, forgot to mention that n is an integer

[split ether]

ah

Any integer?

[lean otter]

yes

[split ether]

Alright

Find minimum then

[lean otter]

0

[split ether]

And what's the largest integer smaller than 0?

[lean otter]

-1

no, no

okay so

treat n as a constant

we have to find it in terms of n

we don't know the value of n

[split ether]

So it's some integer, not any?

[lean otter]

yeah, sorry

what i thought of is

$x \le \sqrt{n^2 - 6n} < x + 1$

[flat frigate]

trololol !

[lean otter]

now, we could square it

[split ether]

-?

[lean otter]

but then i get stuck

and idk what to do

• i don't even know if i approached the problem right

[split ether]

Well sqrt(n^2 + 6n) = sqrt((n + 3)^2 - 9) < |n + 3|

But I don't think this helps

[lean otter]

another thing i thought of is

$(n + 2)^2 \le n^2 + 6n < (n + 3)^2$

this is true, and works, except for n = 1

[flat frigate]

trololol !

[lean otter]

(if we put each term inside a square root, that n + 2 would be the greatest integer smaller than the term from the middle)

but idk what to do if n = 1

[split ether]

(n + 2)^2 <= n^2 + 6n
n^2 + 4n + 4 <= n^2 + 6n
4 <= 2n
2 <= n

[lean otter]

yeah

so it doesnt work for all natural numbers

so n + 2 is not the solution, unfortunately

it needs to work for n = 0 and n = 1 too

[split ether]

Are we talking about integers or natural numbers?

[lean otter]

n is a natural

oooh

i could simply split it into three cases: x n = 0; n = 1; n >= 2

and give a separate answer for each

idk if this is the way im supposed to answer it, but i literally see no other option

[safe radish]

@lean otter Has your question been resolved?

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[lean otter]

Urgent

[final halo]

why urgent?

[lean otter]

ima be late for science hw

[foggy salmon]

write out the formula for

slope given 2 pts

its

$m=\frac{y1-y2}{x1-x2}$

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

oh

uh

sooo

@foggy salmon

isn't it that?

not y1-y2

y2-y1

not x1-x2

x2-x1

[lean otter]

m = -2

?

[dire fjord]

Hi

[lean otter]

hey

[dire fjord]

This and the one above are the same bc both the numerator and denominator are in the same order

So for example (2-3)/(4-6)=(3-2)/(6-4)

[lean otter]

is this for every instance?

[dire fjord]

Do you mean for any numbers ?

[lean otter]

yeah

[dire fjord]

Yea that's true for all of them bc if you take it in general then you will have the following :(y2-y1)/(x2-x1)=-(y2-y1)/-(x1-x2) and now the minus sign in both the num and denom cancels to give you (y2-y1)/(x2-x1)=(y1-y2)/(x1-x2)

[lean otter]

ah, alright

you do calc?

im in y11 rn, teach me

[dire fjord]

No m is the gradient which is 3/4

[lean otter]

i meant c

[dire fjord]

Do you mean that you are in grade 11 rn ?

[lean otter]

not c

a

[lean otter]

ye

[dire fjord]

Yea that's true

[lean otter]

sixth form next

[dire fjord]

I am in grade 11 too

[lean otter]

college next

[lean otter]

and you know calculus??

[dire fjord]

Yea I self study

Ik calc 1 and some of calc 2

[lean otter]

guy, right?

[dire fjord]

Yea

[lean otter]

what's that

[dire fjord]

Where r u from

You are Arabic but from where

I am from Lebanon

[lean otter]

not arabic

urdu

im from pakistan

muslim too

[dire fjord]

Oh I thought you are Arabic from Ur user

[lean otter]

no

i have to study arabic

[dire fjord]

So you r a guy too right ?

[lean otter]

read the qur'an 3x

ye

[dire fjord]

Quran is the best

[lean otter]

muslim?

[dire fjord]

Yea sure

[lean otter]

which sect?

[dire fjord]

I am from shiaa in South lebanon

What about you ?

[lean otter]

sunni from pak

i hope we don't encounter any issues, considering from different sects

[dire fjord]

No that's not a problem for me

We are all people after all its just that we have different thinking and opinions in religion

But we are doing math right here XD

Look I'll give you the name of a book to start calculus ok

You can watch yt vids or ask me if there are ideas that you didn't fully understand

The name of the book is Stewart calculus early transcendentals 7th edition

You can download it from a site named z-library

I gtg sleep now byeee

And please don't forget to type .close when you are done with the channel

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

Ight

Jazakallah Khairan

.close

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[cerulean root]

can somebody tell me on the yellow highlighted area

how they did not put theta on the top