#help-23

1 messages · Page 17 of 1

winter mirage
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yeah

worthy hemlock
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Okay, and?

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That's not really our fault that you waited last minute

safe radishBOT
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@gaunt osprey Has your question been resolved?

worthy hemlock
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.close

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devout glade
#

So I'm encountering a ton of issues trying to get euler angles into a format that is easy to implement in control theory. Right now I only have the euler angles that a 6-DOF quaternion block outputs. These angles being interdependent are making it really difficult to figure out what the output format is, and convert it to something like angle axis representation.
Basically I am getting very lost trying to convert my euler angles the block gives me into something a little easier to use like angle axis representation (example image of them).

devout glade
safe radishBOT
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@devout glade Has your question been resolved?

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@devout glade Has your question been resolved?

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@devout glade Has your question been resolved?

slate hedge
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.close

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hasty lagoon
safe radishBOT
hasty lagoon
#

hi i’m having trouble figuring out the differences between B and C

lean ruin
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read the question again. "neither is a blue" and "not a blue pair" are different things right?

hasty lagoon
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yes

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i believe the answer i have for C is the one i have right

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<@&286206848099549185>

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south linden
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how do i do this

safe radishBOT
south linden
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i have gotten to the precalculation that delta is equal to epsilon/9

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but idk what to do from here

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oh all it is asking for is that precalculation

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lol

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foggy salmon
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lol

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lime light
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what’s good

safe radishBOT
lime light
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i need help with this

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The parabolas have to hit the labeled dots on the graph

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and i have 4 equations

safe radishBOT
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@lime light Has your question been resolved?

lime light
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no lol

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@lime light Has your question been resolved?

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south linden
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how would i go about answering the first and last question?

safe radishBOT
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vast hazel
#

does this make sense or is it even correct 💀

vast hazel
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.close

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whole gale
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Can someone help me with 27-32

safe radishBOT
whole gale
#

Can you walk me through it

worthy hemlock
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,rotate

flat frigateBOT
whole gale
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can sum 1 help

tawny seal
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what have you tried so far

whole gale
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I put it in its form idk what to do now

tawny seal
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show your work

whole gale
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x-2/x^2-9 times x-3/2-x

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I have this so far

tawny seal
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$\left(\frac{x-2}{x^2 - 9}\right)\left(\frac{x-3}{2-x}\right)$

flat frigateBOT
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texaspb

whole gale
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yea

tawny seal
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ok... do you think u can simplify that any further?

whole gale
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no

tawny seal
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why not?

whole gale
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idk how

worthy hemlock
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I suggest factoring the first denominator

tawny seal
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hint: use the difference of squares formula

whole gale
tawny seal
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$a^{2} - b^{2} = (a + b)(a - b)$

flat frigateBOT
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texaspb

whole gale
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uh

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how do I use that

tawny seal
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take a look at both fractions really closely

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and you'll notice it

whole gale
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I dont see nothing

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like that

worthy hemlock
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When an expression can be viewed as the difference of two perfect squares, i.e. a²-b², then we can factor it as (a+b)(a-b). For example, x²-25 can be factored as (x+5)(x-5). This method is based on the pattern (a+b)(a-b)=a²-b², which can be verified by expanding the parentheses in (a+b)(a-b).

Watch the next lesson: https://www.khanacademy.org/m...

▶ Play video
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I suggest watching this

tawny seal
whole gale
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(x+3)(x-3)?

tawny seal
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yes

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so now you can just substitute, ending up with

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$\left(\frac{x-2}{(x +3)(x - 3)}\right)\left(\frac{x-3}{2-x}\right)$

flat frigateBOT
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texaspb

tawny seal
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what else can you do here

whole gale
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x-2 and 2-x

tawny seal
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well firstly you could simplify the two (x - 3)s terms right

whole gale
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yea

tawny seal
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so we're just left with $\frac{x-2}{(x + 3)(2-x)}$

flat frigateBOT
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texaspb

tawny seal
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then what?

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you can't just simplify the x-2 with the 2 - x

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they're not equal

whole gale
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idk

tawny seal
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do you have a guess or something

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anything that comes in mind

whole gale
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switch 2-x to x-2

tawny seal
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how so?

whole gale
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idk

tawny seal
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you can factor out a minus sign

whole gale
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how does that work

tawny seal
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like this $\frac{(-1)(2 - x)}{(x + 3)(2-x)}$

flat frigateBOT
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texaspb

tawny seal
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distribute the (-1) over the term (2 -x) and you'll get the same thing we had the last step

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now you can simplify the (2 - x)s

whole gale
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ok

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-1/x-3?

tawny seal
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we're left with $-\frac{1}{(x + 3)}$

flat frigateBOT
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texaspb

whole gale
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ok

tawny seal
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what's the domain of this new function

whole gale
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-3

tawny seal
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can you tell?

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no

whole gale
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I mean 3

tawny seal
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why 3?

whole gale
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uh cause -3+3 is 0

tawny seal
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that doesn't make any sense

whole gale
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for the denominator

tawny seal
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having 0 in the denominator is a discontinuity

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-3 shouldn't be in the domain

whole gale
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yea 3 is

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not -3

tawny seal
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so our domain is $\bR \setminus {-3}$

flat frigateBOT
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texaspb

tawny seal
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do you see the reason why

whole gale
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isnt the domain from the original function

whole gale
tawny seal
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what?

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ok

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notice that

whole gale
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I already got the domain for that

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not at the end

tawny seal
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no but you have to simplify the expression first

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it's what we've been doing this whole time

whole gale
tawny seal
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$(s \cdot t)(x) = \left(\frac{x-2}{x^2 - 9}\right)\left(\frac{x-3}{2-x}\right) = \left(\frac{x-2}{(x +3)(x - 3)}\right)\left(\frac{x-3}{2-x}\right) = \frac{(-1)(2 - x)}{(x + 3)(2-x)} = -\frac{1}{(x + 3)}$

flat frigateBOT
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texaspb

tawny seal
whole gale
tawny seal
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well

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both answers are fine

whole gale
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ok can we do the next one

tawny seal
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they're not wrong

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I won't have time

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I was hoping you get the idea

whole gale
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ok ill try the next one

tawny seal
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alright

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but did you get the idea?

whole gale
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kinda

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I just have issues with simplyfying'

tawny seal
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yeah

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it can get tricky

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gl tho

whole gale
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ok ty

safe radishBOT
#

@whole gale Has your question been resolved?

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full fox
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(23^19 + 19^19) & (23^23+19^23) what are the common factors ?

full fox
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How to approach this

safe radishBOT
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@full fox Has your question been resolved?

full fox
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<@&286206848099549185>

#

Ok so I found something,
If n is odd then hcf of (x^n + a^n ) will be (x+a) ?

visual patio
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$(23^{19}+19^{19})\ &\ (23^{23}+19^{23})$

flat frigateBOT
#

ItzAine

visual patio
full fox
visual patio
#

try plugging it into a calculator and see if the results are the same

full fox
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Yeah let me try with smaller numbers

full fox
visual patio
#

nice

full fox
#

.close

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dapper prairie
#

Differentiate pi^pi

safe radishBOT
dapper prairie
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This is 0 because pi^pi is a constant and differentiating a constant always results in 0

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Just want to confirm if this is a case

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if this is the case*

obtuse plover
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yea thats right

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unless ur using pi as a variable lol

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but i doubt it

idle parrot
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yeah that is weird

dapper prairie
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Im differentiating with respect to x

obtuse plover
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yea so ur right with it being 0

dapper prairie
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okay one more question

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pi^x = pi^x ln pi

obtuse plover
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like d/dx pi^x?

dapper prairie
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yes

obtuse plover
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yes thats right

idle parrot
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yes

dapper prairie
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okay thank you

obtuse plover
#

np

dapper prairie
#

.close

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indigo monolith
#

i have question √-18 * √-12 so result of each of them is
√-18 = 3i√2 - √-12 = 2i√3

so √-18 * √-12 = (3i√2)(2i√3)

ok but how can i solve this (3i√2)(2i√3) ???

sudden birch
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Use the fact that i * i equals -1

indigo monolith
sudden birch
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There are 2 i’s in your final expression. When u multiply them they will be -1. And then u can multiply the rest of the numbers as usual

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So the i and i become -1, 3 and 2 become 6, and sqrt 2 and sqrt3 become sqrt 6

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$\ -6\sqrt(6)$

flat frigateBOT
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Pauli Excluder

sudden birch
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Hehe first time typing latex here

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So so u understand now?

indigo monolith
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ok there another thing

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now if i did (3√2)(2√3) in calculator will be 6√6 why - 6√6?

sudden birch
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Because there was also two i’s tucked away in your (3√2)(2√3) that together equal -1.

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They multiply to be -1, you multiply that with (3√2)(2√3), you get -(3√2)(2√3), which is - 6sqrt(6)

indigo monolith
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ok where i will put the -1?

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ok do you mean -1(3√2)(2√3) ?

sudden birch
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Yup!

indigo monolith
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aha we get -1 outside and multiply all numbers by -1?

sudden birch
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Exactumundo

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Commutative property of multiplication baby

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As long all the numbers are being multiplied together, it doesnt matter what order you multiply them

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They can commute and move all around into any order you want

indigo monolith
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$\ -1(3\sqrt(2))$

sudden birch
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$\ -1(3\sqrt(2))$

flat frigateBOT
#

Pauli Excluder

sudden birch
#

?

indigo monolith
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$\ -1(3\sqrt(2)(2\sqrt(3)$

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$\ -1\ (3\sqrt(2)(2\sqrt(3)$

flat frigateBOT
#

Mohamed.
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

indigo monolith
#

$\ -1\ (3\sqrt(2)((2\sqrt(3)$

sudden birch
#

You shouldn’t be putting backslash before the parenthesis

indigo monolith
#

ok

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cool yeeeeeh

sudden birch
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Yup i think they’re cool, if that’s what you mean

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Anything else?

indigo monolith
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no thx bro

#

.close

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lean otter
safe radishBOT
lean otter
#

I am on my last attempt and need help, I don’t understand what is wrong about the answer here.

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Before it gave me a new question, this is the answer to the similar one I got wrong.

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I corrected that mistake in the newer question, just different numbers yet it states my inputted answer is incorrect

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Old & New questions work

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This is pre calc*

lean otter
# lean otter

This is the current question that I got wrong, trying to figure out what is wrong about it to fix and get correct

#

<@&286206848099549185>

thin bridge
#

-17 not 17

lean otter
#

Thank you I’m blind

#

.close

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lean otter
safe radishBOT
lean otter
#

How is this solved at the end

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Liking getting the x, y, and a part

dusk vapor
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hi deep

foggy salmon
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oh no my fairy again

dusk vapor
#

how do u get those

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tho

foggy salmon
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prob

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so

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6x=3y=2z

dusk vapor
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oh

foggy salmon
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then sub

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with

dusk vapor
#

im so dumb, the question has equal sing

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sign

dusk vapor
#

goddess help room 2

foggy salmon
dusk vapor
#

he is dying

foggy salmon
#

no

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i shant

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i hate

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chris

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jk

lean otter
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Chris is my(fairys) husband

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Anyway

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.close

safe radishBOT
#
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foggy salmon
#

WOW

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HB ME

idle parrot
#

fairylog catThink

foggy salmon
#

</3

#

💔

idle parrot
safe radishBOT
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strong tiger
#

what does lambda mean/whats does it represent

strong tiger
#

the symbol that looks like an upside down y

idle parrot
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λ

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like you said its just symbol

strong tiger
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yes that one

idle parrot
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you can use it for anything

strong tiger
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ah

idle parrot
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no context really

strong tiger
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its just like using x then

idle parrot
#

yes

strong tiger
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for example^

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ahhh okay tysm i couldnt find it on google

idle parrot
strong tiger
#

.close

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mossy gust
#

Would I round up in this situation?

safe radishBOT
mossy gust
#

Question says: Reported to the correct number of significant figures, ((0.091 + 4.78)) * (14)

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Ah

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I see what the question is really about

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4.871 is the addition

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Since the least number of significant figures is on 4.78, we round it down to two decimal places, giving us 4.87

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Multiply buy 14

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68.18

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Brain no work

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68.2?

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since three significant figures

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that's wrong too

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what

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oh

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oohhhh

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***14 ***

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TWO SIGNIFICANT NUMBERS

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you hoe HIDING FROM ME

#

.close moment

safe radishBOT
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mossy gust
#

The question is: How many square meters, m^2, are in 465 square kilometers, km^2?

idle sage
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1m^2 has 1x10^-6 km^2

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I think

mossy gust
#

So, most people know 1km is 1000m, but hypothetically speaking, would it be possible to solve this not knowing that?

grave flint
#

no

mossy gust
#

So, essentially I should memorize all of the milli, micro, nano, etc exponents

grave flint
#

no

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u should easily know the basic ones

toxic stratus
#

that's memorisation lol

grave flint
#

if its some uncommon unit the conversion should be given

toxic stratus
#

you should know milli and kilo at least

mossy gust
#

kilo is 10^3 I believe

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mega is 10^6 I got that from a previous problem

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Not sure what 4 or 5 is

toxic stratus
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4 or 5?

mossy gust
#

10^4 or 10^5

toxic stratus
#

the prefixes go in increments of 3

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at least the si standard ones do

idle sage
#

ya

mossy gust
#

Huh, interesting. Why's that?

idle sage
#

idk a name for 10^4 HAHHA

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I’m sure there’s one

grave flint
#

why do you think

mossy gust
grave flint
toxic stratus
#

having too many prefixes is redundant

grave flint
#

with incrementing every three you can use, ones, tens, hundreds

#

suitable

grave flint
#

it would just make things harder

toxic stratus
#

do you really want to change prefixes every power of 10?

grave flint
#

yes

toxic stratus
#

is that what you really want to do to yourself when you're writing down measurements

grave flint
#

no i want to change prefixes every power of 2

#

in a base 10 number system

toxic stratus
#

amazing

#

let's do it

mossy gust
#

:/

#

.close

safe radishBOT
#
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lean otter
#

need help writing the equation of curve L vs θ and creating a vertical asymptote graph

austere spade
#

ig you could start with theta = |1/L|

#

then adjust to fit the data

#

unless u want something that goes through all points

lean otter
#

how do i do that

sand minnow
#

There are fitting tools which exist that will try to find a function which will attempt to go through all the points. Like syrenate said it seems to follow a 1/x curve with some modifications needed. I dont use desmos much but id assume they have some regression tool. I would recommend plugging in all the positive points and see what it comes up with. Dont plug in all the negative points tho

lean otter
#

i have plotted my points

sand minnow
#

Lemme get on my pc and ill see if i can find the regression stuff

sand minnow
# lean otter i have plotted my points

if u have the data on a spreadsheet you can just copy paste it in to get a table like this. then you should write something along the line of
$$y_1~\frac{a}{x_1}+c$$ and see what it comes up with. the 2nd screenshot is an example of a regression

#

seems ~ does not like showing up in latex

flat frigateBOT
#

Duh Hello

lean otter
sand minnow
#

then write
y_1~a/x_1+c
below

#

so now that is a basic regression of the points that you have. u should see that the negative points are just the same as this one but negative. hence u have some okish approximations with the given function

lean otter
#

yes

#

so is that what its suppose to look like?

sand minnow
#

so the program decided that
$$y=\frac{655.233}{x}-5.65523$$is the best fitting curve. im sure there is something that will be more accurate but not sure exactly how accurate you need it

flat frigateBOT
#

Duh Hello

sand minnow
#

ye thats what i would do, there is def some more sophisticated way to get this more accurate, not sure exactly how accurate u need to be tho

lean otter
sand minnow
#

yea

lean otter
#

what about the negative points

sand minnow
#

assuming symmetry about the x axis it will just be the same but negative

#

however feel free to try and do the same for the negative points and see how similar they are

#

but i see your points are the exact same so it will be the exact same

#

so $$y_2=-y=-\frac{655.233}{x}+5.65523$$

flat frigateBOT
#

Duh Hello

lean otter
#

yep

sand minnow
#

but if i was doing this manually i would probably try to define $\frac{a}{x}=g(x)$ and then have $c=-g(90)$ as its important for u to have it be 0 as x goes to 90

flat frigateBOT
#

Duh Hello

lean otter
#

oh

sand minnow
#

but i dont really see a clean way of doing that

#

after playing around with it a bit i found that $$y=\frac{265.685}{x^{0.56}}-\frac{265.685}{90^{0.56}}$$ fits it really nicely

flat frigateBOT
#

Duh Hello

sand minnow
#

which i think should be accurate enough

lean otter
#

that's nice

#

yeah

sand minnow
#

negative points will just be the negative of this

#

and then you should have nice curves following the points

#

just changing the r is what i did till it looked nice

lean otter
#

thanks

sand minnow
#

no problem

lean otter
#

.close

safe radishBOT
#
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#
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zinc token
#

I'm a bit confused on how to construct a bijection between $[0, 1)$ and $(0, 1)$.

flat frigateBOT
zinc token
#

I tried a piecewise function at first but that didn't work obviously

#

I've also tried $f(x) = \frac{2x-1}{(2x-1)^2-1}$

flat frigateBOT
zinc token
#

I feel like I'm missing something here, am I supposed to do something with a set of open intervals?

safe radishBOT
#

@zinc token Has your question been resolved?

lean otter
#

@zinc token you are trying to proof that f is bijetive from 0,1 to 0,1?

zinc token
#

No I'm trying to find a bijection

#

That's the f I tried, which doesn't work

lean otter
#

Proving that f is bijective doesn't means there is a bijection ?@zinc token

zinc token
#

The problem is I don't think this f is bijective

#

From $[0, 1)$

flat frigateBOT
lean otter
#

It's not

zinc token
#

I'm saying that my choice of f is wrong yeah

lean otter
#

Cuz f (0) isn't 0

zinc token
#

I don't know what to choose for f

#

Yup I figured

#

Just posting what I tried

lean otter
#

It's*

zinc token
#

Yeah

lean otter
#

how about you find a bijection between [0,1) and R and a bijection between (0,1) and R

zinc token
#

Oh yeah that could work

#

I already have a bijection from $(0, 1)$ to $\mathbb{R}$

flat frigateBOT
zinc token
#

Yeah

lean otter
#

(2-1/x)/(1-x) this one?

#

or something with arctan?

zinc token
#

Let me check

lean otter
#

or tan

zinc token
#

Wait I have $f: (-1, 1) \to \mathbb{R}$

flat frigateBOT
lean otter
#

but hmm finding one for [0,1) seems tricky

zinc token
#

But that works too

#

Because I have a bijection for $(a, b) \to \mathbb{R}$

flat frigateBOT
zinc token
#

I saw on stack they constructed a bunch of open intervals or something?

#

I didn't understand it at all tho

lean otter
#

tan(πx-π/2) works for (0,1) too

zinc token
#

(This question is from understanding analysis)

lean otter
#

oh ok seems this is impossible with continuous functions, we need something more clever

zinc token
#

Yeah I thought so too hmm

#

The annoying bit is the 0 ugh

#

What if I "pull out" the rationals

lean otter
#

you could pull out all elements in the form of 1-1/n and do something different to them, while mapping all other reals to itself

zinc token
#

Yeah yeah

#

HMM

#

Yeah I think that's it

#

I'll play around with it myself for a bit, thanks!

lean otter
#

i think its for topological reasons that the preimage of an open set of a continuous function has to be open too

zinc token
#

Yeah a continuous function won't work

#

,close

#

.close

safe radishBOT
#
Channel closed

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Use .reopen if this was a mistake.

toxic stratus
#

@zinc token what if say

#

you send 0 to 1/2

#

then 1/2 to 1/4

#

and 1/4 to 1/8

#

etc

#

and keep everything else where they are

zinc token
#

Hmm

toxic stratus
#

.reopen

safe radishBOT
#

zinc token
#

So I would have f(x) if x is 1/2n n is natural then output 1/4n

#

Otherwise x

lean otter
#

send 1-1/n to 1-1/(n+1)

toxic stratus
#

you could do this a number of ways

#

the one im suggesting is

#

send 0 to 1/2

#

and 1/2^n to 1/2^(n+1)

#

and you can undo this map

#

just by sending 1/2^n to 1/2^(n-1)

#

and sending 1/2 back to 0

zinc token
#

Ok that is pretty clever

#

Thanks

#

.close

safe radishBOT
#
Channel closed

Closed by @zinc token

Use .reopen if this was a mistake.

toxic stratus
#

one of my profs taught me this

zinc token
#

im just studying this for fun so I didn't have anyone to teach me this oof

toxic stratus
#

yeah i had a class on this like 6 years ago

#

it was fun

zinc token
#

this is interesting yeah

safe radishBOT
#
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agile sable
#

For f(x)=x^2+2x and g(x)=5x+1 find (fog)(x)

lean chasm
flat frigateBOT
#

illuminator3

agile sable
#

yes

lean chasm
#

show work

agile sable
#

i just have trouble inputing f into g

#

i can solve

lean chasm
#

you have to put g into f

proper crypt
#

You need to input g into f.

agile sable
#

what should it look like after input

lean chasm
#

,, (f \circ g)(x) = f(g(x))

flat frigateBOT
#

illuminator3

agile sable
#

That’s what I got

#

<@&286206848099549185>

proper crypt
#

that's g(f(x))

#

you want f(g(x))

#

plug g(x) into the input of f(x)

agile sable
#

ahhh okay

#

so whatever i have set to x is now going to turn into g(x)?

proper crypt
#

yes

dusk vapor
#

hunter hunter be helping Mai San

#

🤡

proper crypt
#

chris what's your goal here

dusk vapor
#

quite goaless

#

to be frank

safe radishBOT
#

@agile sable Has your question been resolved?

#
Channel closed

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agile sable
#

.close

safe radishBOT
#
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fickle trail
safe radishBOT
fickle trail
#

I’m interested in the placement of the i

#

Does it matter if i is in the numerator, denominator, or in front or behind the fraction altogether?

proper crypt
#

In front or behind, no

dusk vapor
#

hunter hunter

fickle trail
#

Hmmmm

proper crypt
#

numerator and denominator, yes

dusk vapor
#

hunterX HUnter

proper crypt
#

omg

#

what

fickle trail
#

Why wouldn’t in front or behind work?

cosmic grove
#

i is just a number tho

dusk vapor
#

exactly

cosmic grove
#

doesnt matter where it is

fickle trail
#

Multiply by √3/√3 to remove radical on denominator

#

But the i started in front to begin with

cosmic grove
#

yea, why not ?

fickle trail
#

Keeping in front is not valid?

cosmic grove
#

why ?

fickle trail
#

Oh because it would say entire fraction is negative discriminant?

#

If having i in numerator only it states only numerator is negative discriminant

cosmic grove
#

??

#

i dont understand your question

fickle trail
#

Do you know what the term discriminant refers to in math?

cosmic grove
#

discriminant = b^2 - 4ac
with a polynomial ax^2 + bx +c, a=/=0

fickle trail
#

Discriminant refers to whatever value is underneath of the radicand symbol

cosmic grove
#

yea and ?

fickle trail
#

Yes exactly the quadratic formula

#

Why are you confused with my question?

cosmic grove
#

i dont understand your problem with i

fickle trail
toxic stratus
#

redstone is saying it doesnt matter

#

put it anywhere you want

#

behind

cosmic grove
#

^

toxic stratus
#

in front

#

on your head

fickle trail
#

Oh, I read this as numerator only

toxic stratus
#

wherever

#

doesnt matter

#

well

#

dont transfer something from the numerator to the denominator

#

but put it anywhere you want

fickle trail
#

“In front or behind, no” not sure what this is referring to

dusk vapor
#

snow is quite right

#

i concur with snow

toxic stratus
#

you asked "does it matter"

#

and they answered "no"

fickle trail
#

Oh I see

dusk vapor
#

snow is quite righty

fickle trail
#

Got it now thanks

cosmic grove
#

$i\sqrt{3} = \sqrt{3} i$

flat frigateBOT
#

Herels

cosmic grove
#

still the same thing i guess

flat frigateBOT
fickle trail
#

“Hunter hunter” ?

#

Why?

#

.close

safe radishBOT
#
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#
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cyan pecan
#

I am confused, Are elements of the set of natural numbers ordinals? and cardinal numbers are the cardinality of such sets

cyan pecan
#

How should one think about this

#

I know ordinals are; first, second third fourth and cardinals are; 1,2,3,4.. (The former referring to an ordering within a set and the latter refering to the cardinality of a set, hence the name)

But in ZFC we construct the Von Neuman Ordinals and declare this set to be N

#

Implying the elements of N are ordinals

#

is this correct?

safe radishBOT
#

@cyan pecan Has your question been resolved?

cyan pecan
#

<@&286206848099549185>

safe radishBOT
#

@cyan pecan Has your question been resolved?

mortal sandal
#

So well

mortal sandal
#

And in that case, every cardinal is an ordinal

#

Every natural number, ω, ω1, ... are the cardinals

#

so yeah every natural number is an ordinal and a cardinal

safe radishBOT
#
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mortal sandal
#

usually cardinals are thought of as equivalence classes on set size

#

not by their set definition

safe radishBOT
#
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mild shoal
#

I don’t know what to do for #17

safe radishBOT
terse ether
mild shoal
terse ether
#

You have the adjacent and you are trying to find the opposite of the angle

mild shoal
#

Oh ok

#

Ty

#

.close

safe radishBOT
#
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fleet folio
#

i know this is false but can someone show me how you would solve for it

fleet folio
#

like full steps

tardy mango
#

$-2 \ln 2^2 =\ln((2^2)^{-2})=\ln(4^{-2})=\ln(1/16)$ \ \ $e^{\ln(1/16)}=1/16$

flat frigateBOT
#

Civil Service Exam is good

tardy mango
#

,w e^{-2 \ln 2^2}

flat frigateBOT
fleet folio
#

.close

safe radishBOT
#
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viral gorge
#

hi

safe radishBOT
viral gorge
#

$\frac{x^2}{xy-y^2} - \frac{x^2+y^2}{x^2-y^2} - \frac{y^2}{xy+y^2}$

flat frigateBOT
viral gorge
#

I factorized them in the following way

#

$\frac{x^2}{y(x-y)} - \frac{x^2+y^2}{(x-y)(x+y)} - \frac{y^2}{y(x+y)}$

warm stirrup
#

what could be a common demoninator?

flat frigateBOT
viral gorge
#

Is it (x-y)(x+y) * y ?

warm stirrup
#

👍

viral gorge
#

so why the hell

#

my result is not right ahah

#

sending the pic

#

$\frac{x^2}{y(x-y)} - \frac{x^2+y^2}{(x-y)(x+y)} - \frac{y^2}{y(x+y)}$

#

sorry for the quality

#

are my divisions right? I don't think so

flat frigateBOT
lean otter
#

calculator

warm stirrup
viral gorge
#

the answer seems wrong

#

my calculator says its x/y

#

but I get x^3 - xy^2

lean otter
#

one second

#

ill solve

viral gorge
#

speedrun

#

xD

warm stirrup
#

you just can simplify that more

viral gorge
#

wat

#

how

warm stirrup
#

and then it cancels really nicely

viral gorge
#

they dont have the same letteral part

warm stirrup
#

what common term can you take out?

viral gorge
#

x

warm stirrup
#

ok

viral gorge
#

x(x^2 - y^2)

lean otter
#

easiest way to solve problem is to use photomath

viral gorge
#

?

lean otter
#

hacks irl

viral gorge
#

yea but I am practicing ahah

lean otter
#

ahhh

warm stirrup
viral gorge
#

yea

warm stirrup
#

then

#

do it

#

:)

viral gorge
#

x((x-2)(x+2)) ?

warm stirrup
#

not quite

lean otter
viral gorge
#

yea

warm stirrup
#

x(x+y)(x-y)

viral gorge
#

oh yea yea

#

using ^

warm stirrup
#

then just divide

viral gorge
#

I don't see it that good xD

#

what do you mean divide?

lean otter
#

divide?

#

i think u meant multiply

viral gorge
#

but I do I get x/y

lean otter
#

x^2 + xy (x - y)

#

i think

viral gorge
#

yea

#

but whats the point

lean otter
#

mobile is so hard bro

#

wtf

viral gorge
#

ahaha

#

How can I get%

#

$\frac{x}{y}$

#

from

flat frigateBOT
viral gorge
#

from

#

oh

#

ty boys

#

.close

safe radishBOT
#
Channel closed

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#
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west bough
#

is f(x+y)=f(x)+f(y)?

safe radishBOT
west bough
#

always?

cosmic grove
#

no lol

west bough
#

apparently it works only for matrixes then

#

in other words linear transformations of vectors

#

.close

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#
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lean otter
warm stirrup
#

so it's true for f(x)=ax

#

but if you invoke axiom of choice

#

then you can get some wacky discontinuous functions

west bough
#

👀 that's an answer

warm stirrup
#

it's a very interesting functional equation

west bough
#

that makes a lot of sense

#

matrices are in the form ax=f(x)

#

explains it perfectly

#

a matrix x vector

#

deamn

warm stirrup
#

but also there are some other weird solutions

#

and you can't prove if those other solutions exist or not

#

unless you assume axiom of choice

west bough
#

but they just exist and work?

#

oh ok

warm stirrup
#

I can't define a pathological solution explicitly

west bough
#

no clue what that means i gotta continue studying now tho

#

.close

#

oh already did that

safe radishBOT
#
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west acorn
safe radishBOT
west acorn
#

The awnser is -39 right?

warm stirrup
#

are you sure?

west acorn
#

Or is it 39 becayse

warm stirrup
#

what does |x| mean

west acorn
#

Theres no negatives at all

west acorn
warm stirrup
#

(hint: |x|>=0 always)

west acorn
#

Oo a face

#

=0

#

Oh ok

#

So it is just plain 39

woeful plume
safe radishBOT
#

@west acorn Has your question been resolved?

safe radishBOT
#
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lean otter
#

Can someone help me understand

safe radishBOT
#

Please don't occupy multiple help channels.

idle parrot
lean otter
#

How to find what it means , I I know I want to substitute 7 for y in the equation

idle parrot
#

okay so substitute y=7 in I=3.44y+9

lean otter
#

So 33.08 , or is that now how I’d do it

idle parrot
#

that will tell you percent of insta users in 7th year

lean otter
#

3.44x7+9

idle parrot
#

,w 3.44(7) +9

idle parrot
#

yes

#

so 33.08 % users since 7 years past 2012

lean otter
#

Oh okay so that’s what the next part was asking

idle parrot
#

yes

lean otter
#

Thank you would you be able to help me with one more it’s another word problem I don’t understand

#

I know the variable but the construct a series of expressions I don’t understand

idle parrot
#

,rccw

flat frigateBOT
safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
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lean ruin
#

read up on the algebra of polynomial functions

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im not qualified enough to talk about this lmao tbh

#

but i think the answer is d

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factorize and divide have fun

lean otter
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If you take x=1 f/g is only equal to the last answer i think

lean ruin
#

it does. f(x)/g(x) = f/g(x). write down f(x)/g(x). now to simplify factor them

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$\frac {f}{g}(x) = \frac {f(x)}{g(x)}$

flat frigateBOT
#

utrebsto

lean otter
#

You should check a video may be

lean ruin
#

oh thats just a method to factor quadratics mate!

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which gives us $\frac {2x^2-5x-3}{2x^2+x} = \frac {(x-3)(2x+1)}{x(2x+1)} = \frac {x-3}{x}$

flat frigateBOT
#

utrebsto

safe radishBOT
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lyric nebula
#

Does anyone know if I did anything wrong or is it right because I am very confused

lean otter
#

,rotate

flat frigateBOT
lean otter
#

a can be negative, in which case |a|=-a=b>0 so it's wrong

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|x| = x if x>0 and |x| = -x if x<0

lyric nebula
#

oh okay

#

thank you

#

.close

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topaz rain
#

is this actually solvable

merry sleet
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@topaz rain Has your question been resolved?

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lean otter
safe radishBOT
lean otter
#

how did they get x/2 as u here?

warm stirrup
#

the bot just picked it

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in order that the denominator be of the form sqrt(1-u^2)

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then trig sub

lean otter
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yes i am aware

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im asking where it got the x/2 from

pure agate
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$4u^{2} = x^{2}$

flat frigateBOT
#

Kookiemon

lean otter
#

ok yes i know that but like where did they pull x/2 from

pure agate
#

4u^2 = x^2
2u = x
u = x/2

lean otter
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2/2?

#

thats some wacko shit

pure agate
#

The goal with these types of integrals is to figure out a way to transform the expression into a form that you know how to solve.

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sqrt(4 - 4u^2) = 2 * sqrt(1 - u^2)

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#

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azure stone
#

i need some help with bhaskara's formula, i havent quite understood it, and it just puzzles me while doing work

azure stone
#

also please do realise that english isnt my main language, so my translation of math terms might be somewhat innacurate

merry sleet
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you mean quadratic formula?

azure stone
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ax^2 + bx + c

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second degree equation

azure stone
merry sleet
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yeah its this

azure stone
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b^2 - 4 . a . c

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my teacher says that the 4 is negative

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when multiplying

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and i cant figure out why

merry sleet
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you did the proof of this in class?

azure stone
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especially because i saw a video saying that the 4 is also negative

merry sleet
#

or did they just give you?.

azure stone
#

but i saw somewhere else that it isnt??

merry sleet
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it is negative

azure stone
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here's where im bugging

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i'll just screenshoot

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the sum of the cordinates of the vertexes

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so

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a = 2

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b = 10

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c = 12

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100 - 4 . 2 . 12

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so it'd be

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(-4) . 2 . 12

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which would be -96

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how can i differentiate the positives from the negatives

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if theres no parenthesis

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i know how to do this, but negative numbers just screw up my calculations

merry sleet
#

you have this discriminant

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i'll call D

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D = b² - 4ac right?

azure stone
#

yeah

merry sleet
#

so in our case its D = 10² - 4(2)(12)

azure stone
#

mhm

merry sleet
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i just replaced

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a by 2

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and c by 12

azure stone
#

well yes, its all fun and games until i have to put the - 4 into it

merry sleet
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alright

#

dont forget

#

that

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-4 = -1 * (4)

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so if you have

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-4 . 2 . 12

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its like

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-1 (4 . 2 . 12)

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which is like

#
  • (4 . 2 . 12)
azure stone
#

oh

merry sleet
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when you see a minus before a number

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its like that number times -1

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and since you can do multiplications in any order

#

you can do the minus one times whatever is left

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at the end

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so here

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you just do

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4 . 2 . 12 = 96

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and put the minus before it

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so D= 100 - 96

azure stone
#

well

merry sleet
#

D = 4

azure stone
#

heres what trips me up

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isnt 96 just positive at the end of the day?

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100 - 96

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just leave it at that

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forget what we did before

azure stone
#

i'll just show my thought process through this multiplication

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-4 . 2 . 12

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-4 . 2

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-8

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-8 . 12

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-96

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what did i do wrong here to find it negative

merry sleet
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nothing

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its negative

azure stone
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im going nuts

#

wait

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so

merry sleet
#

its either you think of it as

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adding -96

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or substracting 96

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but its the same

azure stone
#

so i can just do 100 + (-96)

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and it'll still be correct

azure stone
merry sleet
#

yeah

#
  • (-96) = -96
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its the same

azure stone
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this whole bimester

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since the very start

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i always did my calculations scared of doing any multiplication

#

now i understand this

merry sleet
#

just quickly if you have

azure stone
#

benjamin

merry sleet
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12 - a*b

azure stone
#

i cant thank you enough

#

on god

merry sleet
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with b = -3 and a = 2

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how would you do this?

azure stone
#

ok wait wait

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(-3) . 2

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-6

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12 - 6

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wait

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nono

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i didnt read it right

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mb

merry sleet
#

yeah

azure stone
#

ima edit messages

azure stone
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is this normal

merry sleet
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no its not

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do it with the whole expression from the beginning

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like

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12 - (-3)(2)

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go on

azure stone
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12 - (-3) . 2

merry sleet
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why did the - disapear?

azure stone
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didnt type

merry sleet
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oh yeah

azure stone
#

i edited

merry sleet
#

if you struggle dont forget about the hidden -1

azure stone
merry sleet
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its not

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12 - (-3) . 2 = 12 + (-1)(-3).2