help-23

[compact ferry]

smart

[spark yoke]

So sin^2A = sin^2(B+C)

Umm

And cosA= -cos(B+C)

Is that correct?

[compact ferry]

look honestly ive never seen anything quite like this

i think i know the identities youre using

so sounds about right but im not sure ill be of much help

[spark yoke]

No u r helping me a lot actually

[compact ferry]

alright good because i do find this interesting

[spark yoke]

Okey so

sin^2 (B+C)

This looks pain

[compact ferry]

isnt there that formula

[spark yoke]

Not sure really

But we can just multiply right?

[compact ferry]

multiply by what?

this maybe

[spark yoke]

(sinBcosC+cosBsinC)^2

Yes that

[plucky elk]

This looks most similar to the first identity in 4

[spark yoke]

The sin^2A term tho

[plucky elk]

Subtract it from both sides

[compact ferry]

actually if you add it to both sides

then sin^2(A) would always have to be 1

which is obviously false

[spark yoke]

sin^2B+sin^2C-sin^2A = 2sinBsinCcosA

[spark yoke]

Uhh I don’t get it?

[compact ferry]

alright ill type it out

might take me a bit haha

[spark yoke]

Okay sure

[compact ferry]

suppose $\sin^2 C + \sin^2 B = \sin^2 A + 2 \sin B \sin C \cos A$ then $\sin^2 A + \sin^2 C + \sin^2 B = 2 * \sin^2 A + 2 \sin B \sin C \cos A$

[flat frigate]

Gijs

[compact ferry]

oh lord

suppose $\sin^2 C + \sin^2 B = \sin^2 A + 2 \sin B \sin C \cos A$

[flat frigate]

Gijs

[compact ferry]

then

$\sin^2 A + \sin^2 C + \sin^2 B = 2 * \sin^2 A + 2 \sin B \sin C \cos A$

[flat frigate]

Gijs

[spark yoke]

Okay yes i get it

So..?

[compact ferry]

which by identity 4a implies 2sin^2(A) = 2 which is obviously false

[spark yoke]

There thats

[compact ferry]

wait i cant read

[spark yoke]

2cosAcosBcosC

We have 2sinBsinCcosA

[compact ferry]

yeah that sorry lol

my bad

[spark yoke]

Umm np

[compact ferry]

are these proofs usually relatively easy?

or pretty hard

[spark yoke]

What about we convert that cosA tho

Pretty hard maybe

$\sin^2 A + \sin^2 C + \sin^2 B = 2 * \sin^2 A - 2 \sin B \sin C \cos (B+C)$

[spark yoke]

$\sin^2 A + \sin^2 C + \sin^2 B = 2 * \sin^2 A - 2 \sin B \sin C (\cos B \cos C - \sin B \sin C)$

[foggy salmon]

hii

[compact ferry]

help

[spark yoke]

$\sin^2 A + \sin^2 C + \sin^2 B

= 2 * \sin^2 A - 2 \sin B \sin C \cos B \cos C + \sin^2 B \sin^2 C$

[flat frigate]

Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[spark yoke]

Does this make sense

[compact ferry]

yeah makes sense

[foggy salmon]

,w sin^2(A) + sin^2(B) = sin^2(A) + 2sin(B)sin(C)cos(A) where A+B+C=pi

[spark yoke]

No angles

Not lengths

[foggy salmon]

:c

oh these are angles?

[spark yoke]

Yes

Or you can do A+B+C=180

[flat frigate]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by Circle#0025

[foggy salmon]

nuu

[spark yoke]

Oof

Okey what about

[foggy salmon]

,w evaluate sin^2(A) + sin^2(B) = sin^2(A) + 2sin(B)sin(C)cos(A) where A+B+C=pi

[spark yoke]

$\sin^2 A + \sin^2 C + \sin^2 B = 2 \cdot \sin^2 A + 2 \sin B \sin C \cos A$

[flat frigate]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by Circle#0025

[spark yoke]

Here we do sin^2 A = 1-cos^2A

[foggy salmon]

for one the starting equ

cant we just del both sides sin^2 A

[spark yoke]

Uhh this is actual question

[foggy salmon]

\sin^2 B = 2 \sin B \sin C \cos A$

oh crap

its a C

mbmb

haha

[spark yoke]

I typed wrong

[foggy salmon]

$\sin^2 C + \sin^2 B = \sin^2 A + 2 \sin B \sin C \cos A$

[spark yoke]

$\sin^2 A + \sin^2 C + \sin^2 B = 2 (1-\cos^2A) + 2 \sin B \sin C \cos A$

[spark yoke]

$\sin^2 A + \sin^2 C + \sin^2 B = 2 -2 \cos^2A + 2 \sin B \sin C \cos A$

[spark yoke]

It helps?

[foggy salmon]

,w solve sin^2(C) + sin^2(B) = sin^2(A) + 2sin(B)sin(C)cos(A) where A+B+C=pi

[flat frigate]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by Circle#0025

[foggy salmon]

:c

idk man

y ur Q so hard

ill

go sleep n do more neurosci

T.T

[spark yoke]

[foggy salmon]

sry

[compact ferry]

tears

[spark yoke]

[foggy salmon]

[compact ferry]

its a fun challenge though

[foggy salmon]

gl:he

gl ❤️

[spark yoke]

If we can somehow show

$-2 \cos^2A + 2 \sin B \sin C \cos A = 2\cos A \cos B \cos C$

[compact ferry]

lol wow i was trying the same thing

you can divide by cos(A)

[spark yoke]

Yes

$-2 \cos A + 2 \sin B \sin C = 2 \cos B \cos C$

[spark yoke]

And 2

$- \cos A + \sin B \sin C = \cos B \cos C$

[spark yoke]

Wait a min

[compact ferry]

yes and then perhaps use these

[spark yoke]

Thats true

[spark yoke]

cosA = - cos(B+C)

Damn so ig we solved it

[compact ferry]

holy shit

you did it

[spark yoke]

Now i need to write it in some neat manner

[spark yoke]

No we did it

Thanks

[compact ferry]

well that was pretty cool

[spark yoke]

[compact ferry]

good luck

[spark yoke]

Thanks for being till the end

[compact ferry]

np it was fun

might send this problem to my friends haha

[spark yoke]

Yes

But you gotta prove that identity

The one i sent above

[compact ferry]

of course

[spark yoke]

Thats good exercise

[compact ferry]

it really is

where is this from anyways?

[spark yoke]

Uhh

I’m preparing for JEE

[compact ferry]

oh alright yeah that makes sense

[spark yoke]

And this was one of problems my sir gave as high level trig questions ig

[compact ferry]

isnt it deep into the night for you

[spark yoke]

It sounds weird to say high level lol

[spark yoke]

1 am lol

[compact ferry]

oh lol

[compact ferry]

well its certainly not straightforward

[spark yoke]

Well anyways i need to get sleeping haha

[fresh garnet]

Oh nice
Same here

[compact ferry]

sounds like youre gonna do well on the JEE

[spark yoke]

Ohh

[compact ferry]

gn

[spark yoke]

Gn

[spark yoke]

You should also sleep then

Anyways imma close now

.close

[safe radish]

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[lean otter]

I got this triangle, it's known that AD = BD, AE= CE, BF=CF

and we need to prove that ADFE and DECF are a parallelogram and that AC=4GH, I proved the first 2 but I am stuck at the last one

[lean otter]

F is between B and C, I forgot to mark it

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@lean otter Has your question been resolved?

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@lean otter Has your question been resolved?

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[fickle trail]

I am lost on where to put the x and y intercepts

Am I plotting the x and y intercepts on the original Cartesian plane or the new axis after the vertical shift up 1 and horizontal shift right 2?

And this is also confusing because I always thought hyperbolas never touched the origin? (0,0)

[thorn chasm]

First off not a hyperbola

[fickle trail]

…

[thorn chasm]

Second it has been shifted

So it can touch the y and x axies

[fickle trail]

It is a hyperbola just rotated 90 degrees.. we had this conversation before. It belongs to the conic sections: parabolas, ellipse, circle, and hyperbola

[thorn chasm]

I didnt have that conversation is it actually?

[fickle trail]

Yes it is

[thorn chasm]

Anyways it has been shifted so it can touch whatever

As long as you did your algebra correct you should be good

Gtg

[fickle trail]

Original plane

[thorn chasm]

The original everything you did was right

The second one is a asymptote

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[lean otter]

hey

[lean otter]

i need help with this

3 - 4i

can someone explain how to solve

[plucky elk]

what are you solving for?

3-4i is just a number

that's like saying solve 19

[lean otter]

yes

what is it

is it -1??

[plucky elk]

3-4i is just 3-4i

[analog flare]

Its a number

[plucky elk]

nothing more

[lean otter]

what if

[analog flare]

Thats like asking what is 4 + 0i

[plucky elk]

• Ask your math question in a clear, concise manner.

[lean otter]

ok

i can explain more but

i guess not

.close

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[analog flare]

I mean its 4 but it can be written like this bad example

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[limpid talon]

o

[limpid talon]

im stuck on #1

(segment addition postulate)

[foggy salmon]

oh no another of these

[limpid talon]

unfortunately... yes.

[foggy salmon]

eh u can use

[glad mist]

those are problems of multiple variables, you need to write an equation to represent each line

then you perform substitution, cancellation, addition, subtraction, multiplication of equations to cancel out variables until you get one

i wll try to do one of these

[limpid talon]

oh i tried, but i ended up with -9 and i dont think its right

[foggy salmon]

can u show ur working

[limpid talon]

ya

[glad mist]

so im starting out on problem 3, just showing you what im doing

[limpid talon]

mhm i did that trying to find the missing segments of the line so i can solve for the entire thing to get JL in #1

[safe radish]

@limpid talon Has your question been resolved?

[glad mist]

oh hey i new i did something wrong

[limpid talon]

oh dw

[glad mist]

i set up my equations wrong

[limpid talon]

OH

dw

im genuinely still lost odkdksks

[glad mist]

im pretty sure i did that one correctly

make sure you verify all your veribles hold true to the original equations

---

there is some way you can go wrong. i forget what the taboo is though

---

you should have all the variables figured out by the end. assuming you wrote correct equations and it makes sense and all variavles are valid, you should be confident in your answer

[limpid talon]

ahhh okay

im outside rn so like ima get back to u once i understand the question / finish it when i get back

thank you smn

sm!!

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[lean otter]

Hey, I've been struggling with a problem for a very long time, I'd appreciate some help.

Twice the measure of an angle is ten less than half the measure of its complement. Find each angle measure.

[warm ocean]

you can try setting up an equation

[lean otter]

Yeah I tried but none of the answers I got made any sense

Been at this for like an hour and a half so like tried every single equation in this world's existence

[royal kiln]

Do you understand the vocabulary?

[lean otter]

Well, according to what I'm seeing the two angles equal 90 degrees and 2x = y/2-10 but I'm not sure how to answer get the angle measures

[royal kiln]

Looks good

So how can you express y in terms of x, knowing that they are complementary?

[lean otter]

x+y = 90 and would I do system of equations to solve the rest?

[royal kiln]

Or substitution

[lean otter]

yh I didn't try this so let me see what I get, thanks a ton

[royal kiln]

Np

[lean otter]

I get x = 14 and y = 76, when I do 2(14)=76/2-10 they don't equal each other, am I doing something incorrect

[warm ocean]

your answers are right

are you doing your order of operations correctly

[lean otter]

I believe I am

[warm ocean]

then you should get the correct answer

2(14) = (76/2)-10

[lean otter]

Alright

.close

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[clear trench]

ik how to use definition of derivative to solve functions, however i've never done so with fractions like this.

not sure where to begin

This is what I have so far

[safe radish]

@clear trench Has your question been resolved?

[hallow blade]

Quotient rule?

u∆v - v∆u
—————
v²

Lmao I'm not a helper but I'm studying derivatives too and that's what I do when I try to find derivatives with fractions.

You could also just convert it into:((6+x)½)^-1

[clear trench]

prof says we cant use quotient rule since we havent touched it

only def of derivative

😦

[hallow blade]

Have you tried this? You can convert a square root from
√n → (n)^½

And also 1/n → (n)^-1

After that you can use power rule. And once you get the derivative you can convert it back.

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[fallen stream]

hi

[fallen stream]

problem is posting rn

need #2

[safe radish]

@fallen stream Has your question been resolved?

[fallen stream]

<@&286206848099549185> :(

this gotta be racist

[hallow blade]

Nah, it just be like this sometimes

[fallen stream]

😭

[hallow blade]

It just takes a while. I don't suggest you do your school work last minute then be asking on here for help. Lmaoooo

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[fallen stream]

.close

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[steel spruce]

is this just 1? im slightly confused, but i think its 1

[light shoal]

an equivalent question is, for which values of k is 2021 divisible by k

[steel spruce]

ah so its 2 oops

see i got that like nk = 2021 and for some reason i only considered 43 and 47, and forgot to include 47 and 43

thanks

[worthy hemlock]

#❓how-to-get-help

[light shoal]

don't forget k=1 and k=2021

[lean otter]

Ok

[steel spruce]

ahh yeah LMAO

i have to prepare for a speed contest and i have to go back from an olympiad math mindset to a speed one

not going too well

thanks tho

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.close

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[rose locust]

Which of the following is true? (there is only one): ∅ = {∅}, |∅| = 0,
|P(∅)| = 0, ∅ ∈ { }.

[rose locust]

the second one is true right?

cause an empty set is 0

so 0=0

or am I wrong?

[light shoal]

the second one is true, but i'm not sure what your explanation means

the empty set has no elements, thus |∅| is zero

[rose locust]

ty

can you help me understand the last one?

I mean the 2nd to last

[light shoal]

sure, do you know what P(∅) means?

[rose locust]

p is a function where o is the set size

[light shoal]

P means power set, doesn't it?

[rose locust]

right

forgot sorry

[light shoal]

ok, so what's the power set of ∅?

[rose locust]

1

it's 2^0?

right?

[light shoal]

well that's the size of the power set of ∅

what is the power set itself? what does it contain?

[rose locust]

it contains 1?

[light shoal]

no...

if A is a set

then P(A) is the set of all subsets of A

does that sound familiar?

[rose locust]

yes

[light shoal]

ok, so what are the subsets of ∅

[rose locust]

nothing

[light shoal]

almost true

it has exactly one subset

namely itself

(a set is always a subset of itself)

so the power set of ∅ is the set containing ∅

i.e. P(∅) = {∅}

and since the power set has one element, the size of the power set is 1

i.e. |P(∅)| = 1

[rose locust]

ohhh

ty

[light shoal]

sure

[rose locust]

.close

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[loud breach]

how do i solve number 3?

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[loud breach]

<@&286206848099549185>

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[tardy cosmos]

Hi ! I tried doing some exercices that i did in class but i failed to solve this one.

Say x belongs to R*+ such as: x + > 1/x = 5

Calculate x^2+1/x^2

How can i solve this?

[split ether]

(x + 1/x)^2 = x^2 + 1/x^2 + 2

[compact ferry]

this is classic competition problem

[tardy cosmos]

Can you explain to me why did we add x^2+1/x^2 + 2 to the other side?

And what happened to 5?

[split ether]

5?

Oh, nothing

I just expanded (x + 1/x)^2 using (a + b)^2 = a^2 + 2ab + b^2

[tardy cosmos]

Oh

Thx

[tardy cosmos]

What about +2?

Adding 2

[split ether]

(x + 1/x)^2 = x^2 + 2 * x * 1/x + 1/x^2 = x^2 + 2 + 1/x^2

[tardy cosmos]

So you already did that

[split ether]

Did what

[tardy cosmos]

The expansion

Thx so much

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[daring iron]

I need help finding the domain and range of 2.(a)

I don’t know what I’m doing

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[daring iron]

<@&286206848099549185>

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[glad dragon]

What do i do for 9? I dont think we can assume right angle

And i dont think base angles theorem really helps

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.close

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[patent vault]

this sounds like a fun problem but can i get a hint

[analog flare]

He can say them how many times?

Only once?

[patent vault]

i think only once

[rare flax]

Huh

[analog flare]

Oh then its 1 , 100 and 10000

[patent vault]

oh yeah

im so dumb

thanks

i was hoping for a hint

but thanks

[analog flare]

Oh sry xD i wasnt sure about this being the answer either

[patent vault]

no worries

.close

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[clear trench]

unsure how to solve this

[tame raft]

try combining it into one fraction and then l'hopital probs

[clear trench]

a method w/o l'hopital

[tame raft]

fine, combine it into one fraction and then use taylor series

[clear trench]

idk what you mean by combining into one fraction

1-1 / t1+t - t ?

[tame raft]

$\frac{1}{t\sqrt{1+t}} - \frac{1}{t}\ = \frac{1}{t\sqrt{1+t}} - \frac{\sqrt{1+t}}{t\sqrt{1+t}}\ = \frac{1-\sqrt{1+t}}{t\sqrt{1+t}}$

[flat frigate]

Kaisheng21

[tame raft]

i'll give you that for free

[clear trench]

ooh that looks simple

i was trying to plug 0.1 and -0.1

values around zero

what do you do after that to get -1/2?

when lim t-> 0 the answer is just 0

it seems

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[dreamy finch]

Could someone help me out with this one please:
There are 15 tennis balls in a bag. 9 have never been touched, 6 have been played with before. During round 1, 3 balls are taken out randomly, and then placed back into the bag. During the second bag, 3 more balls are taken out and played with. What is the probability during round 2 that all the balls are new?

[dreamy finch]

i dont know how to do this problem but i know the answer is .08926

rounded

please @ me if anyone helps me

[safe radish]

@dreamy finch Has your question been resolved?

[dreamy finch]

<@&286206848099549185>

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@dreamy finch Has your question been resolved?

[dreamy finch]

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[vague horizon]

hi guys i’m not completely sure if this type of question belongs here but i’d figure i’d ask anyways,

[vague horizon]

the answer says it’s x^(1/2) but i simply just have no idea how they got it

[tame raft]

which one lmao

[vague horizon]

oh i forgot 87 haha

[tame raft]

well it's the same thing as the ones above

find the limit as dx goes to 0 of: f(x + dx) - f(x)/dx

[vague horizon]

so i plugged it in and got this

[tame raft]

so what's f(x+dx) here

[sudden birch]

Delta x should be INside the square root

[vague horizon]

Oh?

is it because it’s in the parenthesis

[sudden birch]

Wdym?

[vague horizon]

the delta x

ok so i have this now

[sudden birch]

It should be 2 * square root (x+delta) not 2 * square root(x) + delta, if that’s what u mean

Yeah

And then it’s algebra time! (Hint, use difference of squares)

[vague horizon]

that’s (a+b)(a-b) right?

[sudden birch]

Yes!!!!!!!!!!!!

[vague horizon]

i feel like i did something wrong haha

[sudden birch]

Nah that’s very much the right way to do it. 👍

[vague horizon]

should i try factoring stuff out now?

[sudden birch]

U have to multiply it out

[vague horizon]

this is where i get the most confused

[sudden birch]

When u multiply it out, notice that in the numerator, the x’s cancel each other out leaving just a delta x

And just so happens that there is still a delta x in the down below denominator

Here’s the surprise: the cancel!!!!! Whaaaaaaaaaaaaaattttt!??????!???????!

[vague horizon]

oooh i see

[sudden birch]

Yup!

And I realize I’m being way too excited for just a math problem, sorry

[vague horizon]

nooo don’t worry i’m glad ur enthusiastic abt helping me lol

[sudden birch]

🙂

: )

[vague horizon]

so i should have this now?

[sudden birch]

Yup!

You can finally let delta x go to zero without worrying about any weird things

[sudden birch]

So…….close…..to the…..the answer…..I’ll assume u got it

[vague horizon]

WELLLL

kinda

like i’m seeing it but also not

i feel like this should be clicking

i can combine them right since it’s x+0 which is the same as just X?

[sudden birch]

Yup!

[vague horizon]

?

[sudden birch]

Either way works fine cuz they’re both the same

[vague horizon]

so is this the same as x^-(1/2)

because that’s what the books answer says

[sudden birch]

Wait a minute, we must have done something a tiny bit different

Lemme recheck our stuff

[sudden birch]

There’s supposed to be a 2 in the numerator at the top of the fraction, because 2*deltax/deltax is 2

And then the top 2 and bottom 2 would’ve cancelled out and we’ll get the books answer

But we basically got the same answer, basically, so we got the core concepts down in the bag

[vague horizon]

oh no i’m a little confused lol

how did we get 2 in the numerator

[sudden birch]

Wait…..

[vague horizon]

was i supposed to distribute the 4 to the delta as wel

well

[sudden birch]

Oh yeah, u right u right

[vague horizon]

ok so let’s see here

[sudden birch]

Oh it THAT is the right way to calculate it, I was off

Bro, I tell you, u got this in the bag

[vague horizon]

the 4 delta thing?

or the original answer

[sudden birch]

The 4 delta is correct

[vague horizon]

so i can cancel out a delta now?

[sudden birch]

Yup!

[sudden birch]

The 4 stays, it’s just the delta x at the top and bottom that go away

[vague horizon]

OH RIFHT

oh my gosh

so this is x^-(1/2) ?

wait

radical x over x

oh my gosh it is!!!

thank you so so much

[sudden birch]

Your very welcome. I’m happy you got it : )

[vague horizon]

oh @sudden birch i’m sorry

can i just get a confirmation that this is in fact

the same thing

because our teacher doesn’t want us leaving square roots in the denominator

[sudden birch]

Yup a Hundo percent correct

[vague horizon]

ok thanks again

[sudden birch]

Np

[vague horizon]

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[steel blaze]

Hey can someone help me with this

[steel blaze]

This is what I have to do

And I found the 10 factors of -14/3 (including positive variables) and none of them worked

Is it not supposed to be -14/3?

[jovial coral]

try small values of x to see if they make h(x) = 0

for x = -2 we get
$ 3(16) -17(-8) - 31(4)+23(-2)-14 = 48 + 136 - 124$ -46 - 14 = 0$

so x =-2 is a 0

so x + 2 is a factor use long division to simplify the quartic

[steel blaze]

oh yeah and 7 is the other one

[jovial coral]

doing long division will yield (3x^3-23x^2+15x-7)

[steel blaze]

i did it even further now

[jovial coral]

you'll find x = 7 is a factor of this too

[steel blaze]

so now I have 3x^2 -2x+1

[jovial coral]

long divide by x-7 you'll get
3x^2-2x+1

which has no real solutions as the discriminate is < 0 i.e. 4 - 4(3) = -8 < 0

so x = -2 and x = 7 are our solutions

[steel blaze]

there's no 3rd zero?

[jovial coral]

nope

[steel blaze]

i plugged it into the quadratic formula

and ended up getting

1/3 +- sqroot-8 /6

[jovial coral]

yup

but see how we have sqrt(-8)

that is a complex number

so there are no real solutions to the quadratic (should have been a little more specific sorry)

[steel blaze]

can't i boil it down to 1+isqroot2/3

[jovial coral]

sqrt function produce a real number when the input is >=0 i.e

[jovial coral]

if your class wants complex solutions sure

[thin bridge]

they're not necessarily working with only real numbers

[steel blaze]

well it gives me the option to put an i

[thin bridge]

all zeroes implies they want the complex ones too

[jovial coral]

I assumed you where working with reals sorry

[steel blaze]

its fine

[jovial coral]

yes by the fundamental theorem of algebra you will need 4 solutions

[steel blaze]

i didn't put it in yet

so would it be

1+i sqroot 2 /3

1-i sqroot 2/3

[jovial coral]

yup!

[steel blaze]

alright, lemme test it

i got it

tysm for ur help

[jovial coral]

no probs, sorry for the mix up

[steel blaze]

its fine

tysm

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[grizzled scroll]

I need help calculating e for RSA Key Generation? I'm a bit confused on some of the tutorials/instructions I see. I have a p of 11 and q of 17. So that means I have an n = 187 and T = 160. Where I'm stuck is on calculating e, I am to do

gcd(e, T) = 1 but my instructor said that the number has to be a prime of your n = 187. However the only primes for 187 are my p = 11 and q = 17. Is this allowed and what do I do if not?

[grizzled scroll]

<@&286206848099549185>

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[versed ginkgo]

I thought i knew how union and intersection works in terms of set theory and intervals but I don't understand this one
(-∞, 6] ∪ [2, ∞) ∩ (-3,11)
answer sheet tells me the answer is (−3, 2] ∪ [6, 11)

[rigid inlet]

What are you getting if not that?

[versed ginkgo]

(-3, 6) ∪ [2, 11)

[rigid inlet]

Actually there may be a typo in the question

Since (-inf, 6] U [2, inf) = (-inf, inf)

[thin bridge]

are you sure it wasnt
(-∞, 2] ∪ [6, ∞) ∩ (-3,11)

[rigid inlet]

That's my thought too

[versed ginkgo]

i got the left intervals from x <= 6 or x >= 2

[thin bridge]

what's the original question

[versed ginkgo]

i described it here.
#help-22 message

I'll post a pic of what's currently in my notebook too

[tame raft]

so you're saying (-∞, 6] ∪ [2, ∞) ∩ (-3,11)

is it ((-∞, 6] ∪ [2, ∞)) ∩ (-3,11)

or is it (-∞, 6] ∪ ([2, ∞) ∩ (-3,11))

i think it matters which one it is

[versed ginkgo]

good question

[thin bridge]

you're not doing case work properly

[versed ginkgo]

ah

[thin bridge]

for the |4-x| >= 2

case 1: 4-x >=0
4 - x > = 2
...
case 2: 4-x < 0
-(4 - x) > = 2
...

[versed ginkgo]

wait do i need to do cases for |4-x| < 7 too?

(I'll probably find out if i do bc then i need to do even more work to get an answer)

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[novel magnet]

Is the highlighted step correct?

[safe radish]

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[plain sandal]

Hey, could some one tell me if i did b right? it it right to just add zeros to make the matixes the right size?

[drowsy moss]

unless you have something that says you can do that for this purpose (i can't read that language) you generally can't add matrices of differing sizes.
Just adding rows/columns of 0's isn't typically allowed.

[plain sandal]

Just says that if i cant do the following equation i have to tell why, but i you told me the rule. So thanks😁

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[lean otter]

couldnt find anything to that so im asking here, what exactly is he doing

[lean otter]

what does delta mean in the botttom one

[solar hazel]

I imagine it's the forward finite difference operator

[lean otter]

how does it work

[solar hazel]

it must have been defined somewhere?

[slender fossil]

Need help

[lean otter]

but i dont get that either

oh

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[junior wagon]

why cant part c be (6 c?hoose 1)(7 choose 1)(3 choose 1)(13 choose 1)/(6 choose 4)

[junior wagon]

oh i see

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[latent tiger]

Hello!

[latent tiger]

Can I get sum help

Idk why this went up to two then just went side ways like that

The interval is -infinity to +infinity yet it turned sideways instead of carrying up the curve

[drowsy moss]

what interval? the domain or range?

[latent tiger]

Domain yes

First one

Domain is IR

I can't for the love of me find out why we went sideways after reaching 2

[drowsy moss]

why couldn't it? The domain is just the possible x-values. it doesn't imply anything about the range.

[latent tiger]

Shouldn't it just... go up?

Not sideways?

[green lichen]

but why

[latent tiger]

Idk I'm asking it confused me

What makes it go sideways instead of up

[green lichen]

this is what the range means

doesn’t necessarily mean it has to go up or down

[latent tiger]

Oh

[green lichen]

I think you want the range

[latent tiger]

Probs didn't study ranges ig

[green lichen]

the values y can take

[latent tiger]

Oooh

Yes.

I need to show that 2 is the maximum value

[drowsy moss]

f(x) = 1 has a domain of all reals.
it's range is only one value, 1.

[latent tiger]

Ah

So we have show Max(x belongs to IR)f(x)=2

💀

So how do I show that

[green lichen]

maybe find stationary points

[latent tiger]

I study in French so I'm not good with English versions of math words so I'm gonna have to translate that one sec

[latent tiger]

But for that I need to draw it don't I?

I don't know how to draw a curve for a fonction with a division of two polynomials

[green lichen]

oh you just differentiate

[latent tiger]

Hmm?!

My brain lol

Subtract what from what

I'm very sorry the English words in math are new to me so I have to Google them to understand

I can speak English just fine but have never studied math in english

🫂

[green lichen]

oh it’s differentiation

have you learnt calculus

like dy/dx

[latent tiger]

Oh

[green lichen]

f’(x)

[latent tiger]

Derivation

No

[green lichen]

yes

oh

[latent tiger]

Do we need that!?!?

[green lichen]

it’ll be easier

[latent tiger]

Yeah we just learnt like basics of functions

We have a very different system than calculus and algebra

We all of them in like math

One subject

It's weird but derivation no not yet

[green lichen]

ohh you’re learning functions

[latent tiger]

Yup

[green lichen]

maybe you can do long division

[latent tiger]

How would that help?

[green lichen]

then as x—> inf

that will give you the max point

[latent tiger]

😔

I give up

I just don't understand how we got a question with derivations when didn't study it

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[latent tiger]

Not yet

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[latent tiger]

.reopen

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✅

[latent tiger]

Ok so ur talking about lim x--> inf right?

I literally went and studied limits for this lmfao

[green lichen]

hmm

im also not sure tbh

are you allowed to sketch?

right now I’m only able to think of finding dy/dx

maybe call for <@&286206848099549185>

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@latent tiger Has your question been resolved?

[latent tiger]

Not yet

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[jovial grove]

hi i was wondering if you could help me see if their is anything wrong with my assignment .Is this allowed?

[marsh walrus]

its usually bad practice to ask someone to look over your entire assignment on the off chance you have mistakes

it makes it easier for people to help you if you can highlight places where you are concerned there are mistakes, and why you think you may have made a mistake

or what you are confused about

[jovial grove]

oh ok im confused on the grphing of the inequalities

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[stone nest]

On average, an adult female cat gives birth to 10 kittens per year. For every 3 male kittens there are 2 female kittens. How many female kittens will this cat give birth to in 13 years of her life?

[nova creek]

What have you tried

[stone nest]

I just know that it has to do 3m = 2f

I think we need to do proportion?

Or equations

[nova creek]

First, how many kittens are born over 13 years?

[stone nest]

10 kittens per year?

But over 13 years?

10 x 13?

[stone nest]

But that’s the total amount of kittens born?

Ok nvm I got it

3x + 2x = 130

So it’s x = 26

26 x 2

52

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[opaque sorrel]

hi can someone help me with proving this

@toxic stratus u alive?

[drowsy moss]

Hint: $cA = (cI_n)A$

[flat frigate]

Zybikron

[opaque sorrel]

hmm

okay lemme write it out

imma tag u

[toxic stratus]

oh hi

didnt we do this like

just the other day

[opaque sorrel]

HELLO

no we didnt

did we

[toxic stratus]

yes we did

[opaque sorrel]

i think it looks familiar

but

oh

[opaque sorrel]

oh yes that was det

[toxic stratus]

mhm

[opaque sorrel]

is it the same

[toxic stratus]

its the same idea

[toxic stratus]

just follow this hint

[opaque sorrel]

yesmam

wait

kinda see it now

lmao

[toxic stratus]

vision

[opaque sorrel]

$det(cI_n)$

hmm

[flat frigate]

HellO

[opaque sorrel]

lemme recal

so the

identity matrix has det 1

[opaque sorrel]

if we multiply everything by c

it would be like

2..2..2

diagonally

so its

2 * 2 * 2 * ...

[toxic stratus]

somehow your c became a 2

[opaque sorrel]

so

[toxic stratus]

but sure

[opaque sorrel]

oh yes

i made it up

anyway

so its

n times of 2

so 2^n

a ha

[toxic stratus]

yes

but

c

[opaque sorrel]

yes

I GOT IT

[toxic stratus]

amazing

[opaque sorrel]

thanks young one

[opaque sorrel]

next one

[toxic stratus]

oh theres more

[opaque sorrel]

btw yesterday was fun

[toxic stratus]

👀

[opaque sorrel]

my first time helping

someone

[toxic stratus]

LOL

poor future

[opaque sorrel]

ikr

[toxic stratus]

had such a hard time with the algebra

[opaque sorrel]

he spent more time

[toxic stratus]

future deserved better

[opaque sorrel]

formulating the result of the proof

than doing it

just realised we also did this

[toxic stratus]

yeah we did

[foggy salmon]

HAHHA

ONLY

CALLING

[opaque sorrel]

also u got the green role

[foggy salmon]

ME

TEETH

[opaque sorrel]

thief

[toxic stratus]

oh hi @foggy salmon

where did your hearts go

[opaque sorrel]

yes u are thief

[foggy salmon]

ni hao

[opaque sorrel]

nihao

[foggy salmon]

idk

[opaque sorrel]

chi zao can le ma

[foggy salmon]

i stripped em out

[toxic stratus]

konchipa

rip hearts

[foggy salmon]

im

lost

[toxic stratus]

may they rest in piece

[foggy salmon]

❤️

[opaque sorrel]

ni ma ma mei you mao

[foggy salmon]

..

[opaque sorrel]

wat

[toxic stratus]

im sorry what

[opaque sorrel]

yes

[foggy salmon]

MODS

[toxic stratus]

LOL

[opaque sorrel]

why u do dis

[foggy salmon]

phat

was

a joke

[opaque sorrel]

this is

sexual abuse

[foggy salmon]

woah woah

stop there

[toxic stratus]

D:

[opaque sorrel]

ur grooming

ANYWAY

[foggy salmon]

no

u

actually

[opaque sorrel]

THIS

we did this right

[foggy salmon]

gonna get banned at this rate

[toxic stratus]

we did do it

[opaque sorrel]

no pls

[toxic stratus]

and you probably have it

in the back of your mind

[opaque sorrel]

no ban

[opaque sorrel]

yes

emme try

[toxic stratus]

b&

[opaque sorrel]

no ban

so

[foggy salmon]

hey

[opaque sorrel]

$det(A^{-1})$

[flat frigate]

HellO

[foggy salmon]

why dont u hv

helpful role

hello

hahhaa

[opaque sorrel]

i dont

help

i suck

[foggy salmon]

ye but

i think

u r

gonna hv it

in a bit

by

[opaque sorrel]

no

[foggy salmon]

being helped

hahhahaha

[opaque sorrel]

im trash

o

wow

[foggy salmon]

just from

bein here

why

[opaque sorrel]

hurt me feelings

[foggy salmon]

[opaque sorrel]

o

good

[toxic stratus]

i think

[foggy salmon]

whyyy

what

[toxic stratus]

the bots are smart enough

[foggy salmon]

HAHHAA

i feel

[opaque sorrel]

wait

[foggy salmon]

they just count msgs

mayb

[toxic stratus]

no but

[opaque sorrel]

ur telling me they give the role via the number of msgs

[toxic stratus]

the bot knows who opened the channel

[opaque sorrel]

watafak

[nova creek]

Wow look at you cool people with your green names >:( /s

[foggy salmon]

ye

[opaque sorrel]

o

[foggy salmon]

idk if they count that

[toxic stratus]

oh its gamer dio

[opaque sorrel]

noob

[foggy salmon]

oh

why dont u hv that?

[opaque sorrel]

i think

goddess

[foggy salmon]

[opaque sorrel]

has like

50%

[toxic stratus]

yeah surely gamer dio should have green too

[opaque sorrel]

more messages

cus she sends msgs

in separate msgs

[foggy salmon]

like a bot

[opaque sorrel]

instead

of

[foggy salmon]

:D

[opaque sorrel]

one chunk

i shall

do that

too