help-23

[lean otter]

that are occuring

on a function

[safe radish]

@lean otter Has your question been resolved?

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[near moth]

anyone know what i did wrong? im stuck

[wind stream]

We cant really know what you did wrong until you have shown your working

[safe radish]

@near moth Has your question been resolved?

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[scarlet talon]

I need help with understanding this discrete math problem

i know about propositions, connectives and logic

but this word problem has me stuck

i tried denoting "B is a knight" as a p

and q denote "not a knight"

and r denote "I am a knave"

[nova creek]

I feel like you could quickly solve this via trial and error

Like, assume A is a knight and see if there's a contradiction. Then assume A is a knave.

[scarlet talon]

Ohhhh

so i make some reasonable assumptions

and attempt to solve the problem

[nova creek]

It helps that there's so few possible options

You can easily exhaust them all

[scarlet talon]

so can A be either a knight or a knave

is it possible they're both knaves ?

[nova creek]

You tell me

Is there a contradiction if they're both knaves?

[scarlet talon]

i think it's possible

a knave could lie abt being a knight

and another knave could lie abt the two of them being opposite

bc they're a knave as well

[nova creek]

Yep

[scarlet talon]

but the same cannot be said if A and B are knights

bc one knight would be lying by saying "the two of us are oppoiste"

[nova creek]

Mhm

[scarlet talon]

when the other claims to be a knight

if A was a knave and B was a knight

then that would make sense

[nova creek]

How so?

Note that A is saying B is a knight, not that A is a knight

[scarlet talon]

ohhh right right

ohh so if A was a knave and b was a knight

they'd be a contradiction

[nova creek]

Yep

[scarlet talon]

bc A(a knave) is claimig B(a knight) to be a knight

so the knave wouldnt be lying

ahhh so that's where the contradiction is

i see i see

so last case is if A is a knight and B is a knave

there is no contradiction

i think

oh wait there is

A(a knight) is claiming that B(a knave) is a knight

so when B says we're the opposite

then the knave is not lying

[nova creek]

Yep

[scarlet talon]

wow thanks dude

I like you're style of teaching/explaining

10/10

[nova creek]

You mean like saying "yep" and "mhm" over and over?

[scarlet talon]

ye that one ☠️

[nova creek]

Well I pride myself in my hard work

[scarlet talon]

lmaoo alr thanks bro appreciate it

.close()

.close

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[stuck spruce]

Hello?

[safe radish]

@stuck spruce Has your question been resolved?

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[safe radish]

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[finite whale]

hello

[finite whale]

.close

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[clear trench]

hewwo

[clear trench]

i need help with this

f(-1) = 3 + the limit x-> -1 g(x) = DNE

so 3 + DNE = ????

wait thats 2 isnt it

.......................

[prime kelp]

But limit x -> -1 g(x) does exist. Looking at the graph of g(x), as x approaches -1, g(x) approaches 2

[clear trench]

brain fart

thanks

.close

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[cunning linden]

hi

[cunning linden]

im so sorry but can I ask for help again

<@&286206848099549185>

[royal ivy]

log(ab)=log(a)+log(b)

This is true for any log base and any a,b

[cunning linden]

how do i apply it here?

[royal ivy]

log(p²/81)=2log(p)-log(81)

[cunning linden]

is this right?

[royal ivy]

yes

[cunning linden]

tq!

.close

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[loud breach]

Hello! Have you any idea how to start solving this problem? Thank you so much.

[safe radish]

@loud breach Has your question been resolved?

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[fickle trail]

The definition of an even function is just monomial, binomial, or polynomial with a term to the power that is even, correct?

[fickle trail]

and the term must be in the numerator or could it be in the denominator instead? lets say for example x^2 or 1/x^2 as a simple example

and what about 3x^2y^3

3x^2y^3 would be an odd function right? because y is the highest power

[ashen creek]

wud this be F(x,y)?

How wud you write tht?

[fickle trail]

oh

so it also matters how the function is written to determine if it's odd or even?

f(x)=

f(x+y)=

i was thinking f(x)= for the examples above

[ashen creek]

Well it wontbe f(x) coz it has two variables right?

[fickle trail]

oh

[ashen creek]

Yeah

So its actually f(x,y)

[fickle trail]

unless another function has declared f(y)=?

you can plug that function in

but anyways, sorry i'm making this more complicated for no reason

let's just ignore the 3x^2y^3 for now

[ashen creek]

Yeah simpler to jus write the input as an ordered pair

[ashen creek]

Okie

even function is f(x) = f(-x) right?

[fickle trail]

so 3x^2x^3 would be an odd function because x^3 is odd or because x^5 is odd? either way it's odd i'm just wondering if you combine exponents first or no need

[fickle trail]

hmmm i think so?

[ashen creek]

Yes

[fickle trail]

because it would have a vertical asymptote i believe

[ashen creek]

that is when the power wud be an even number

[ashen creek]

Whts tht?

[ashen creek]

Wudnt this actually be a even function

(3x ^ 2x) ^ 3 = 3x^6x

[fickle trail]

vertical asymptote would be something the function can't touch

[ashen creek]

Okie

[fickle trail]

(3x^2)(2x^3)

sorry forgot brackets

[ashen creek]

Oh....

OKie

[fickle trail]

you would say 6x^5 for the answer

and that would be an odd function because 5 is the highest power of the function

[ashen creek]

No

Wudnt it be 9 * 8 * x^5

[ashen creek]

THts correct

f(x) * g(x)= (f*g)(x)

[fickle trail]

Oh yeahh

[ashen creek]

So it wud be 72x^5 ryt?

[fickle trail]

Not multiplying 3*2

[ashen creek]

Yes

[fickle trail]

That looks weird when typed

I get messed up

When I write it I think it helps

[ashen creek]

Hmmm..

OK

But yes it is odd

[fickle trail]

OK

[ashen creek]

👍

[fickle trail]

and what if there are multiple exponents on a polynomial?

you just go with the highest power, right?

to determine if it's odd or even

[ashen creek]

Yup

[fickle trail]

ignore the rest

OK

[ashen creek]

Coefficients dont matter

[fickle trail]

right

[ashen creek]

👍

[fickle trail]

it could have 100 terms with powers, it's whatever is the highest power that counts

ignore the other 99

[ashen creek]

Yeah

[fickle trail]

OK

[ashen creek]

Wait

nooo

[fickle trail]

lol

[ashen creek]

It wud be sum of all powers right?

[fickle trail]

That's what I mean, do you add first or no need?

[ashen creek]

Coz x^2 * x^3 * x^3

Wud be x^8

[fickle trail]

right

not 3

[ashen creek]

So its even

Yup

[fickle trail]

OK

[ashen creek]

Addd

[fickle trail]

thanks, I think I get it now

[ashen creek]

Sorry for the confusion

Its add

[ashen creek]

K

[fickle trail]

No problem

https://tenor.com/view/okay-ok-see-what-i-did-there-jim-carrey-thumbs-up-gif-15801589

.close

[safe radish]

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[fickle trail]

How did I get two completely different answers here?

[foggy salmon]

math is flawed

[fickle trail]

For the top attempt in dark blue I used FOIL to multiply the numerator of binomials and distribution to multiply the denominator

For the bottom attempt I canceled the numerator with the denominator

I know the bottom solution is correct but I don't know where I went wrong with the top solution

[quasi bison]

,w (6x^2 + 5x - 6)/(12x^2 - 8x) - (2x+3)/(4x)

[foggy salmon]

i think

[flat frigate]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[quasi bison]

you did not

[foggy salmon]

ye

[quasi bison]

the top is just unsimplified

[foggy salmon]

u just didnt simplify

looks messier

[fickle trail]

woah..

so how can I simplify top to be the bottom?

because i really don't see how to at all

i would have just assumed those were completely different answers to the same equation lol. but i guess i didn't do anything wrong with the math, i just need to simplify the top somehow to be the bottom, or expand the bottom somehow to be the top.

also not sure if I am using "expand" in the right context here. (making the bottom answer look like the top answer)... maybe "convert" is better?

[quasi bison]

factorize.

[foggy salmon]

:0

factory

zoom zoom

[safe radish]

@fickle trail Has your question been resolved?

[fickle trail]

Is there an easy way to factorize (3x-2) in the numerator?

Unfortunately I just don't see it yet

[foggy salmon]

cry

factorising is hard

idk maybe let the top b

= (ax + b)(cx + d)

and equate n try to find values of a b c d

but well

gl

[fickle trail]

yeah, I know it is (2x + 3)(3x - 2) but I wish there was an easier way to find it..

[foggy salmon]

yea expand

equate

[fickle trail]

i guess I can try to bring the same (3x - 2) up to the numerator and plug in numbers until I find something that works.. eventually landing on (2x + 3)

[foggy salmon]

no

[foggy salmon]

expand this first

like

multiply the stuff

u get acx^2+x(ad+bc)+bd

then equate

ac=6
ad+bc=5

bd=-6

then u do ur usual solving

[fickle trail]

I see that the domain cannot equal 0

but i don't understand how there can be more limits than 0 for this domain

[foggy salmon]

this is

a totally different Q now right

[fickle trail]

it's the same actually

[foggy salmon]

no

u were

asking about factoring earlier

[fickle trail]

want me to start a new thread?

[foggy salmon]

i mean

its

[fickle trail]

factoring but getting to the domain

[foggy salmon]

a different part of the same Q

[fickle trail]

OK..

I can start a new thread

.close

[safe radish]

Channel closed

Closed by @fickle trail

Use .reopen if this was a mistake.

[foggy salmon]

no its fine just

ok sure

[fickle trail]

.reopen

[safe radish]

✅

[fickle trail]

ok

[foggy salmon]

i just meant

u didnt even

[foggy salmon]

comment on my part on how to find how to factorise

n u just went on to ask smt else

[fickle trail]

factoring is hard, i get it 🙂

unfortunately i don't know if there is a precise formula to follow.. just gotta get good at it

look for patterns

[foggy salmon]

yea so

like

did u kinda get it

[fickle trail]

i think so

thank you

[foggy salmon]

or did u just move on n

ok cool then

well i kinda gave u a method of solving that isnt guessing

btu is kinda hard to do

[foggy salmon]

so now u wanna find the

?

why did u suddenly mention limits

i dont get how there can be more limits than 0 for this domain

why do u mean by that

[fickle trail]

err, i think i used the wrong word there

limits would be for calculus right?

[foggy salmon]

yea its ok

maybe just try saying it again

[fickle trail]

i just want to find out why the domain must exclude more than just 0 for this

[foggy salmon]

oh

idk draw the graph

one part will be

max of something

then the other is min of something

so itll be some range

i think

from what ive seen b4

i can graph it

oh wait

domain

nvm

yea idk

i think domain just is R\ {0}

all real numbers excluding 0

idk

range seems similar but excluding 1 as its the asymptote

[fickle trail]

well, the instructor is saying domain cannot equal 2/3

but when i plug in x=2/3 i get 39/24

[foggy salmon]

yea

oh

its probably

from some stuff u cancelled out

but u kinda

croppped the question into nothing

[foggy salmon]

like if u have

yea

that think u cancelled

its 0

when x=2/3

so u cant cancel zeros

[foggy salmon]

tho i guess u can just show its a removable singularity and take it for the maximal domain

yea i just said

[fickle trail]

this is what happens when I replace x with 2/3

[foggy salmon]

u cant cancel zeros

[fickle trail]

I get 39/24

[foggy salmon]

so like

eh

eg

x^2/x

so this is =x

but is not defined at x=0

as its a division by 0

if u substitute it into the original equ

u would probably get

infinity

or 0/0

the limit exists

but the value at the point doesnt

[fickle trail]

So the issue is actually with the root function

[fickle trail]

it's hidden in this

[foggy salmon]

..

u

[fickle trail]

but it's because the root function has a domain of 2/3

[foggy salmon]

didnt listen to what i said right

[fickle trail]

i didn't understand it

[foggy salmon]

..

say something rathe than

ignoring it completely

[fickle trail]

i dunno what to say to it

i don't understand it ^

but i'm still learning

maybe it will click the more i practice with dividing functions by functions

dividing functions by functions appears to be the only thing that can make the domain grow larger

adding, subtracting and multiplying functions keeps the same domain as the original functions

[thorn chasm]

You mean smaller right?

[fickle trail]

domain can never shrink

yeah

domain can only grow based on quotient of functions, but it can never get smaller

this is because the original functions always come along for the ride and retain their domain

[thorn chasm]

Normally you start with everything in the domain and then you exclude stuff if it makes illegal math things happen

So domain shrinks because some numbers arent included

So why do you say domain gets larger?

[fickle trail]

the way Professor Leonard explains it: domains will never shrink, they will only stay the same or grow larger

[fickle trail]

function divided by function can make a domain larger (function quotient)

[thorn chasm]

Thats the entire explanation?

Domain is the set of accepted inputs

[fickle trail]

yes, adding, subtracting and multiplying functions will always retain the original domains of the functions. it will never shrink smaller

[thorn chasm]

Yes but it will if you divide by 0 for some input x

Cuz then that input gets excluded from the domain

[fickle trail]

divide by zero is undefined

[thorn chasm]

Yes so then the x that makes that happen gets excluded from the domain

[fickle trail]

Hmmm

[thorn chasm]

So then the domain is less

[fickle trail]

Interesting, I don't think I have learned this yet

i have been taught you can't divide by 0, domain must be real numbers

[thorn chasm]

Yes

[fickle trail]

but we haven't made it to imaginary or complex yet

maybe this /0 is going into that territory?

[thorn chasm]

But the real number input that makes a undefined or imaginary output gets excluded from the domain

No

[fickle trail]

can you give an example of addition, subtraction, or multiplication of functions where the domain will get smaller?

[thorn chasm]

No

For those its always fine

[fickle trail]

it can only happen with division of functions?

[thorn chasm]

Or roots or logs

As far as i know

[fickle trail]

can you give an example of division, log, or root of functions where the domain will get smaller?

[thorn chasm]

Yes x/x

[fickle trail]

= 1

[thorn chasm]

The domain is the set of reals except 0

Technically its undefined at 0

[fickle trail]

right, so x cannot be 0

that makes sense

[thorn chasm]

And so not included in the domain

[fickle trail]

but how did the domain shrink?

it was always x cannot equal 0, wasn't it?

[thorn chasm]

Wdym

[fickle trail]

i mean after you do the division

how does the domain of the function shrink?

that is what Professor Leonard is trying to explain

[thorn chasm]

It cant shrink after ive already put out the equation

But it can be less the all the reals

[fickle trail]

here I will give a screenshot to help explain, keep in mind the domain x cannot equal 2/3 comes from the original functions

Here are the original functions f(x) and g(x)

both have the same domain where the denominator cannot equal 0, pretty standard stuff

both share the same denominator

when you divide these functions, the domain does not shrink

in other words, x cannot equal 2/3 does not go away

even though i may look like that from (2x + 3)/4x

[thorn chasm]

Yep

Thats right

But the domain did shrink in the sense that x now cant equal 0 as well

[fickle trail]

ohhh, i think that maybe we are talking about the same thing but from different perspectives

[thorn chasm]

Probs

[fickle trail]

when I say domain doesn't shrink, I mean you cannot remove values from the domain

sorry, my bad

[thorn chasm]

Btw i gtg soon

[fickle trail]

OK

so you are correct the domain does get larger, where you add an extra value of 0

but you cannot remove from the domain

[thorn chasm]

?

Im still so confused

[fickle trail]

you cannot remove 2/3 from the domain

even though it looks like you can

[thorn chasm]

You mean you cant put it back

[fickle trail]

it looks like this domain should just be x cannot equal 0

but its more than that

due to the original functions

[thorn chasm]

The domain is all the ok inputs

[fickle trail]

{x | x cannot equal 2/3, x cannot equal 0}

[thorn chasm]

And yes you cant say that it works to use 2/3 now

Yep

[fickle trail]

this is the correct answer to (2x+3)/4x

Not {x | x cannot equal 0}

[thorn chasm]

For that specific one yes

[fickle trail]

Yeah, so the original domain is still there, it hasn't been removed. That's what the video is trying to explain.. I think I'm finally understanding it now. I need to look at the original functions to determine the full domain

[thorn chasm]

Yes

And any new issues

Anyways i gtg

[fickle trail]

OK

https://tenor.com/view/okay-ok-see-what-i-did-there-jim-carrey-thumbs-up-gif-15801589

.close

[safe radish]

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[deft pivot]

how much less 4 is than 8 in percentages / and another question : how much bigger 8 is than 4 in percentages

[foggy salmon]

50%, 100%

[deft pivot]

Yes i also thought so but why ?

I think in first question you assume that 4 is 100% and that makes 8 200% / and in the second question 8 is 100% and 4 is 50 %

but why we assume these conditions ?

why 4 is 100 % in the first question and 8 is 100% in the second ?

@foggy salmon

[foggy salmon]

first q u assume 8 is 100%

generally when than appears

eg

than x

u take x as 100 %

and everything is relative to that

[deft pivot]

ok i got this

but why you assume that ?

@foggy salmon is this some sort of general agreement?

[foggy salmon]

yea idk i learnt it sometime

n i think it kinda always held

so i guess?

like if i say

made $1 yesterday

then i say i made 100% more than yesterday

means 2 dollars

or 200% same thing, 3 dollars

[deft pivot]

OK thnx

.close

[safe radish]

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[safe radish]

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[feral mason]

HELP ME

[feral mason]

Helppp

I need help

Hello

I need

Help

[quasi bison]

do you want to yell "HELP" or do you want someone to actually help you

[unique bison]

Are you drowning or smth

[quasi bison]

with this many messages in a row it's starting to look like spam

[feral mason]

I said I need help dude

[quasi bison]

why aren't you posting your question?

[feral mason]

It say that

Look it say thats

[feral mason]

Look it

[quasi bison]

what do you need help with?

[feral mason]

It tell mes

A lorry is travelling at 13.5 m/s along a stretch of road where the speed limit us 50km/h

Then

1 likometer = 1000 meter
1 hour= 3600 seconds

Then

Show that the lorry is travelling below the speed limit

Where you go?

[quasi bison]

i didn't go anywhere. why do you presume i was gone?

i was even typing a message...

[feral mason]

The type was gone

[quasi bison]

A lorry is travelling at 13.5 m/s along a stretch of road where the speed limit us 50km/h
ok, before we begin, you should know that on this server the math problem should be your FIRST message.
do not just scream "help help help help" over and over. do not do that.

[feral mason]

I need help

[quasi bison]

you keep doing it.

anyway, on to the problem.

[feral mason]

Thay what I need help with

Actual let me tell you

[quasi bison]

your problem asks you to prove that 13.5 m/s is less than 50 km/h.

[feral mason]

Does it

No it says

[quasi bison]

A lorry is travelling at 13.5 m/s along a stretch of road where the speed limit us 50km/h
Show that the lorry is travelling below the speed limit

this is what it says.

[feral mason]

Show that the lorry is 54aveling below the sped

[quasi bison]

yes, to show that the lorry's speed is less than the speed limit.

[feral mason]

Yes it is

It's on the screen

Mmm

Where you go

Hey

Hello?

[quasi bison]

i was gone for all of two minutes! why the panic??

[feral mason]

Because you just leaved

[quasi bison]

so what, i can't go to the bathroom now?

anyway.

[feral mason]

Ok I'm sorry

[quasi bison]

this is a unit conversion problem.

[feral mason]

Yes

[quasi bison]

would you like the short answer that makes you memorize an easily forgettable fact,
or would you like me to take you through a longer solution that hopefully makes more sense?

[feral mason]

The short

I remeber

[quasi bison]

1 m/s = 3.6 km/h, so 13.5 m/s = (13.5*3.6) km/h.

multiply it out and see that the result is less than 50.

done.

[feral mason]

Pardon

Multiply what

[quasi bison]

so 13.5 m/s = (13.5*3.6) km/h.

there is a multiplication symbol in there.

[feral mason]

13.5 × 3.6

[quasi bison]

i'm leaving it to you to do the simple task of multiplying two numbers together.

or "timesing" two numbers together if you prefer to call it that.

[feral mason]

That is not multiply

That is a stat

Star

[quasi bison]

yes, it's an asterisk. using an asterisk for multiplication is common. it originated from programming languages.

[feral mason]

No

×

I get 48.6

Yes

[quasi bison]

No
do you mean "No, I think that using any symbol other than × for multiplication is WRONG and BAD and ILLEGAL"?

[feral mason]

No

Is ×

[quasi bison]

then what does your earlier "No" mean?

[feral mason]

Not a star

No star in math

+×÷ look it

See I tell you

[feral mason]

NO

I'm right

This is +×÷

No stars

They silly

What kind

[quasi bison]

well you can do the "la la la can't hear you" thing all you want, but star for multiplication is a common usage that you will see many times, especially on the internet.

[wooden garnet]

This is a joke right?

[quasi bison]

there's really no use in deliberately refusing to accept it, imo. next thing i know, you'll be rejecting my use of the forward slash / as a symbol for division!

[feral mason]

No jokes

None laughed

No I useb+×÷

You can do stars

[quasi bison]

not to mention that all this time you've somehow excluded the symbol for subtraction.

[feral mason]

But they will say

Why drawing on the maths

Not using the real ones

I will say I told you

[quasi bison]

haykan, do you believe that i literally told you to copy what i said symbol-for-symbol? with the star and all?

because that's not the case at all...

[feral mason]

Actually no

Stars are not in maths

Only +×÷

[quasi bison]

so subtraction is "not in maths" either, is it

[feral mason]

This mean oh I make mistakesn*

Yes subtract

[quasi bison]

"Only +×÷", after all.

[feral mason]

Is thisone

[quasi bison]

but you said it's "Only +×÷"!

[feral mason]

Forget

+×÷-

But ok you not wanna listen to ke

Me

[quasi bison]

projecting much?

[feral mason]

I also I have another question

[quasi bison]

thank god. save us from this madness.

[feral mason]

What that mean ?

[quasi bison]

post your question.

just post your question.

[feral mason]

My question is

I actually have 2

But 1 is for not maths

But I do the maths

The question is very long and I don't want to type it

[quasi bison]

ok then take a picture and send the picture here.

[feral mason]

Ok I eat rice so it might be not clean ok

Is a

I tell me I'm wrong

Hello?

[quasi bison]

i was, once again, gone for less than 2 minutes.

why the DEVIL do you make it seem like i've abandoned you?

[feral mason]

No I thought you not want yo help me

[quasi bison]

if i didn't want to help you i would've said that already.

[feral mason]

No somtimd they leave

And is my bedtime in 5 minutes

[quasi bison]

anyway, yeah, you are wrong. you say faris will take only 1 hour to travel.

but you can't travel 195 miles in 1 hour at 50 mph!

[feral mason]

Yes

Why

[quasi bison]

50 miles per hour means that in 1 hour you travel 50 miles

NOT 195 miles!

[feral mason]

Woahhh

I see what they did there

I know I know

[quasi bison]

they didn't "do" anything there, this is literally the definition of "miles per hour"

[feral mason]

3 hours

[quasi bison]

no, it won't be 3 hours. in 3 hours you'll only travel 150 miles.

[feral mason]

No I see

4 hours

[quasi bison]

no, it won't be 4 hours either. in 4 hours you'll travel 200 miles, MORE than the 195 distance.

[feral mason]

3 hrs and 30 minutes

[quasi bison]

no

stop guessing.

[feral mason]

Yes

It's the asbwe

Mhm

But

[quasi bison]

no, 3 hours and 30 minutes isn't the answer either.

[feral mason]

Yes it is

[quasi bison]

do you just want to be contrarian or what?

[feral mason]

What us that

[quasi bison]

somebody who disagrees with things just for the sake of disagreeing

[feral mason]

No

BUT my calculator

Said 3.9

[quasi bison]

3.9 hours is not 3 hours and 30 minutes.

[feral mason]

It 4 hours

But you said no

[quasi bison]

no, 3.9 is not 4.

[feral mason]

Look it

Oh

I never heard of 3 hours 90 minutes

[quasi bison]

because it's not 3 hours and 90 minutes either!

there aren't 100 minutes in an hour!

[feral mason]

It's 60

[quasi bison]

yes, there are 60 minutes in an hour!

[feral mason]

I divid by 195

Yes

[quasi bison]

so that fractional hour (0.9) should be multiplied by 60 to get the number of minutes!

[feral mason]

3 hours 25 minutes

[quasi bison]

no.

[feral mason]

Oh

[quasi bison]

0.9 hours is not 25 minutes.

[feral mason]

There no such thing

As 0.9 hours

[quasi bison]

how much is one-tenth of an hour?

[feral mason]

I sont know

[quasi bison]

an hour is 60 minutes

[feral mason]

10 divid by 60

[quasi bison]

how much is one-tenth of 60

[feral mason]

0.1

[quasi bison]

one-tenth of 60 is not 0.1

[feral mason]

What is a tenth

[quasi bison]

when you divide something into ten equal pieces and you take one piece, that's called a tenth.

...how old even are you that you're struggling with fractions, if you don't mind me asking?

[feral mason]

What

I'm in grade 10

In america

So actually year10

I'm actually learn thT in primary

Year ago

[quasi bison]

last time you came here, you complained that the server didn't cater to some UK-specific things. now you claim to be in the USA?

[feral mason]

So I can't remember

No I convert

In America I be 10 grade

I think

[quasi bison]

doesn't tell me much...

and that's plenty old to know your way around fractions, imo.

[feral mason]

Google say I'm in 9th grade

[quasi bison]

definitely old enough not to have to ask "what is a tenth" as if you've never heard such a thing before in your life.

9th, 10th, whatever. you're not a kindergartener.

[feral mason]

I don't remember what is a twnth

[quasi bison]

anyway!

[feral mason]

😦

I don't like you anymore

[quasi bison]

0.9 of an hour is 0.9×60 minutes.

0.9 × 60 = 54.

[sweet pike]

Am I allowed to help address some of the ridiculous things (no offense) haykan has said in here Ann?

[quasi bison]

see? i even didn't use the "star" you threw a tantrum at.

[quasi bison]

by all means!

[feral mason]

No you can't

Go away

Is not a tantrum is just not math

[sweet pike]

It is literally the math

[feral mason]

😡

Go away

[quasi bison]

well, you keep plugging your ears every time someone keeps trying to tell you that, yes, actually, people use stars that way.

nobody has died from it.

[sweet pike]

No one's obligating you to stay lol

[feral mason]

Go away

I tell you gi

[quasi bison]

haykan, you can just leave.

you don't need to stay here and shoo people off.

[feral mason]

I was actually here first

[sweet pike]

High chance they're just in it for the memes imo

[feral mason]

What's imo

[sweet pike]

In my opinion

[feral mason]

You rong

I actually struggle in mathmatics

Not everyone like you😡

[sweet pike]

It's just not reasonable that you're approaching high school and don't know what fractions are.

[quasi bison]

well, you'll struggle less if you stop shutting your ears whenever someone uses a symbol you're unfamiliar with and then keep shouting that it's "not in maths"!

[feral mason]

We not leaving them in the school

We do algerbra

And I'm actually in secondary school

FYI

[quasi bison]

all the more reason you should know what fractions are

[feral mason]

No

I'm actually in set 5

We not learn there that why I'm try to go 4

They throw rubbers at each other

And the teacher cried

😡😡😡

[sweet pike]

Rubbers?

[feral mason]

Yes

[quasi bison]

erasers

[feral mason]

Whiteboard

No

White board

[quasi bison]

or do you mean the things you wipe whiteboards with

[feral mason]

Yes

[sweet pike]

They throw entire whiteboards at each other?

Oh

Mvm

[feral mason]

No

[sweet pike]

Nvm

[feral mason]

Lol

[quasi bison]

this conversation has run its course

i'm out

[feral mason]

It my bath time

😡

[quasi bison]

probably want to close this then

go take your bath

[feral mason]

No I need find the answer

[quasi bison]

WHAT bloody answer

[sweet pike]

Ann gave you it.

[feral mason]

Thus

54 minutes

[quasi bison]

well no, haykan REFUSED to believe that "0.9 of an hour" was a sensible thing to talk about.

[sweet pike]

Yeah, put it in a calculator. It's true

[quasi bison]

flat out says "no such thing!!! no such thing!!!"

[feral mason]

It sound more resonanle

54 minutes I heard of thst

[tranquil sentinel]

It was 3h54m btw

[sweet pike]

Any unit can be subdivided. This is a fact. 54 minutes is 9/10 of an hour, end of story

[feral mason]

Oh thank you

[quasi bison]

yeah but you couldn't even answer that splitting an hour into 10 equal pieces and taking one of them will give 6 minutes

[feral mason]

I belive andrea

[tranquil sentinel]

Since you had to do 195miles, not just 45

[tranquil sentinel]

I'm saying the same thing they are saying, so you believe them too

[spiral crescent]

Its past bedtime

[feral mason]

They say 0.9

[quasi bison]

noooo, don't you know, i'm the big bad mean lady who tells haykan off. @tranquil sentinel

[sweet pike]

Ahhh yep

Totally

[feral mason]

It's my bathtime

[quasi bison]

OK THEN GO TAKE YOUR BATH.

we have nothing more to discuss here.

.close

[safe radish]

Channel closed

Closed by @quasi bison

Use .reopen if this was a mistake.

[feral mason]

I AM

😡😡

[quasi bison]

get OFF the computer.

[feral mason]

I'm om phone

[tranquil sentinel]

Tbh I don't know how you have so much patience, I would have left way before

[quasi bison]

ok then get off the phone.

[feral mason]

Also my one question

Is

[quasi bison]

get

off

the

phone

[sweet pike]

🤦‍♂️ I join this server and this is the first convo I see lmao

[feral mason]

Is there English version of this

[quasi bison]

get off the phone

[tranquil sentinel]

Lol

[feral mason]

I need help with macbeth

[quasi bison]

get off the phone

[feral mason]

No it my question

[quasi bison]

get off the phone

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[feral mason]

😔

[feral mason]

.close

[safe radish]

Channel closed

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Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[drowsy hill]

hello

[drowsy hill]

i can prove the serie converge using the d'alembert theorem

but how can i calculate the sum?

i mean i got abs( un+1 / un ) ---> 0

but how can i calculate 1+3e

[unique bison]

Separate the numerator then use the taylor series for e

[drowsy hill]

could you show me the dem pls?

[steep dove]

instead, you can try and do it iteratively

[quasi bison]

it will work with some modification actually

$\frac{n^2 + 2n - 1}{n!} = \frac{n^2 - n}{n!} + \frac{3n}{n!} - \frac{1}{n!}$

[flat frigate]

Ann

[steep dove]

^^

[unique bison]

Ye that's clever

[quasi bison]

with some suitable series fuckery, you can turn this into some series that sum to e or almost sum to e save for one easily-accountable-for term

[unique bison]

Or u can just re index stuff

[drowsy hill]

oh wow ty! what made you think abt taylor?

[unique bison]

The fact that you can cancel n

And n! in the denominator

(Plus there was an e in the answer given)

[drowsy hill]

ye but we didnt know the answer before

[unique bison]

Which is why I put it in parentheses lol

[drowsy hill]

oh ok

btw gg ty vry much

[safe radish]

@drowsy hill Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

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[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

Is this correct?

someone 😭

<@&286206848099549185>

[steel stag]

no, radius is wrong

[lean otter]

isnt radius r^2

so the sqrt of 36 is 6

[steel stag]

yea but it's doubled

[lean otter]

i dont understand sorry

r^2 is basically diameter which is 36

r itself is the radius

so we sqaure root both sides to find radius which is 6

[steel stag]

in the question

[lean otter]

so is the radius 3?

ohhh lmao im blind

i also changed the 6 in the new equation to 3

would that make everything else correct now

[steel stag]

other way around

6 goes to 12

so (x+6)^2+(y+3)^2=144

[lean otter]

i see now

thank you 🙂

.close

[safe radish]

Channel closed

Closed by @radiant tangle

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[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac patio]

What is the original equation used?

I've been stuck for a while

[final halo]

$\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}$

[flat frigate]

ΣAC

[final halo]

compare with what you have

[lilac patio]

I know

Maybe its tanπ/4*x

Honestly have no clue

[final halo]

what is the exact question

[lilac patio]

To evaluate it but my teacher doesn't want us to use lhopitals

she said to find the original equation then differentiate that

[final halo]

$f'(c) = \lim_{h\to 0}\frac{f(c+h)-f(c)}{h}$

[flat frigate]

ΣAC

[final halo]

again, just compare

[lilac patio]

I'm thinking tan3π/4+πx

[final halo]

you're overthinking

[lilac patio]

its not tanx

The answer is 2

derivative of tanx is sec^2x

[final halo]

and sec^2(5pi/4) is?

[lilac patio]

(1/√2)^2?

or uh (√2)^2

oh

so what is the original equation? Then

[final halo]

tan(x)

[lilac patio]

but why the 5π/4

[final halo]

because you're evaluating the derivative at 5pi/4

[lilac patio]

I didn't know you could do that with the definition

I see

Thank you

.close

[safe radish]

Channel closed

Closed by @lilac patio

Use .reopen if this was a mistake.

[final halo]

no worries

[safe radish]

Available help channel!

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Remember:
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[pliant elk]

Hi

[pliant elk]

Can you do this to vectors?

[final halo]

well the a and bs are just normal numbers not vectors, so yeah you can do that

[pliant elk]

Ah ok

[pliant elk]

Is this correct?

[final halo]

thats a lot to look through, if you arrived at LHS = RHS then you're probably right

[pliant elk]

OK thx

.close

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[slender reef]

how would i factor x^2-20x+25

[upbeat ridge]

Quadratic formula

[slender reef]

i did that and i got 10+- 5sqrt(3)

but

ohhh

wait

mbmb

i messed up on a calculation

[upbeat ridge]

nw

gl

[slender reef]

thanks

.close

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[fickle trail]

Why would this be (-4,3) for vertex? If we need “a” to be positive to find vertex don’t we need to multiply the entire equation by -1?

“a” being -2 in vertex form

and if we change the RHS we must also make that same change to the LHS, so wouldn’t it be -y= if we are multiplying both sides by -1 to make “a” positive?

Wait nvm

.close

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[drifting dew]

I need help with a.

[burnt bloom]

ok

[drifting dew]

Fr

[burnt bloom]

where A is the value of the computer after n years
P is the principal cost which is 1500
r is the rate of depreciation which is 18

sub in

[drifting dew]

Ohhhhhhhhh

I see now thanks for helping me set it up

[burnt bloom]

then for b just sub in n = 6

[drifting dew]

b?

Oh

Thanks

[safe radish]

@drifting dew Has your question been resolved?

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[earnest pond]

I need help in solving these please

[rigid inlet]

what's giving you issue?

[earnest pond]

I dont know how to solve it

It was given to us without them explaining how to solve it we gotta figure it out ourselves but i cant really solve it

They are all false

[rigid inlet]

so, a few things

1. you're not supposed to give the answers

2. you're not answering the question as the question asks you to

anyway geiko, your goal is just to construct a counterexample. For the most part you're just playing around with numbers

for example, take the first one. Try plugging in two numbers for x and y, see what happens

any two numbers, it doesn't matter (though smaller ones make the calculation easier)

(except 0, don't use 0)

[earnest pond]

I’m sorry i dont really understand, so for example x, -x < x. Ill put any numbers like
5, -8 < 13 ?

Yes

[rigid inlet]

well no, x is one number. You choose a specific x and ask "is -x < x?" If no, you've found your counterexample

[earnest pond]

Wait im trying to solve itt

[rigid inlet]

"it looks like your explanation isn't working so I'll give them the answers"

[toxic stratus]

the rules explicitly say not to provide answers

[nova creek]

This server does not run on giving away answers

You may prefer that way, but that's not how we do things

[toxic stratus]

plus giving away answers removes the opportunity to critically think for yourself

[rigid inlet]

yea, so you give an example. You don't do the questions for them

[toxic stratus]

[rigid inlet]

those are two very different things