help-23

[toxic stratus]

.close

[lean otter]

......

i swear i knew it before

i just forgot

[toxic stratus]

happens to the best of us

[steep dove]

i see what ur doing here man

👀

[lean otter]

hehehe

.close

[safe radish]

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[idle veldt]

.open

Q: how to calculate the angles of a trapezium (quad with 1 set of parallel lines) if given all 4 sides?
It should be possible with cosine theorem (not sure what it is called in English, basically calculating the third side of a triangle if you have 2 sides and the angle between them)

a = 12
b = 7
c = 4
d = 5

What I did, was use the cosine theorem to do:

1) a^2 + b^2 - 2bc * cos(beta) = e^2 = c^2 + d^2 - 2 cd * cos(180-alpha)
2) b^2 + c^2 - 2bc * cos(180-beta) = f^2 = a^2 + d ^2 - 2ad * cos(alpha)

add them together, cancel out a few things and get the formula:

(b^2 - d^2) / (a - c) = b * cos(beta) - d * cos(alpha)

however, I don't know where to go from there? Do I try to insert it in the basic cosine theorem again? But wouldn't that create a monstrosity of a formula?

[idle veldt]

I need alpha and beta

[idle veldt]

this is my derived formula, not sure if it is correct, but I can't see any flaws in the process

the green circles show what i know

<@&286206848099549185>

[safe radish]

@idle veldt Has your question been resolved?

[idle veldt]

i have to go so goodbye. If anyone can answer, that would be great. The derived formula is probably wrong and yeah. Anyway, have a nice day.

(and @ me if you have the solution / hits / whatever)

[safe radish]

@idle veldt Has your question been resolved?

[tame beacon]

Plugged it into Wolfram|Alpha and got the following solutions:

[safe radish]

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[lean otter]

Can someone maybe help me with this please

There is a solution

But this confuses me

[teal whale]

Uh, I mean x=0 and y=0 are the obvious solutions. Perhaps use them to get the other values for x and y which are also valid soloutions

[lean otter]

.close

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[winter forge]

I need assistance

[winter forge]

If you’re able to help me with a few word problems dm or somethin

[lean otter]

Word problem?

[winter forge]

Yeah

[wooden garnet]

Post the problem here someone can help you

[winter forge]

There’s like 3

[wooden garnet]

Have you attempted them?

[winter forge]

Yeah

She said it was T right

Wasnt*

[wooden garnet]

Ok what’s the first one

[winter forge]

I need help with 4 and 5

[wooden garnet]

Ok post them

[wooden garnet]

First work out how much she can withdraw until she gets a fee

[winter forge]

She can use 276

If she uses more she would get a fee

So

If she would wanna withdraw 25 a week

[wooden garnet]

Yeh how many weeks at 25 per week

[winter forge]

It would be 11 weeks

[wooden garnet]

Yeh

[winter forge]

Alright, so that was fairly easy. Now with the harder one

heh

[wooden garnet]

Yeh ok

[winter forge]

Whic would be

2 long shirts that total 48

Which leads the rest to being shore

Short

Because he want's to buy two mroe

Wow, I feel really stupid. I'm really sorry.

[wooden garnet]

Don’t be sorry it’s cool, I don’t rlly understand the question tho, do you have the original one

[winter forge]

Nope, we solve word problems in my school. You basically pick out the detail from the text and find out the equation

I wish that it was only numerical, I'd be so much better then-

[wooden garnet]

Wdym by 2 long shirts that total 48

As in they cost 48

[winter forge]

Yeah

He wants to but two more short sleeve shirts than long sleeve

Thus making it so as the total being 120

We could subtract 48 and divide the rest

Which would leave 4 short sleeve shirts

[wooden garnet]

How much are short sleeve shirts

[winter forge]

28

I mean

18

[wooden garnet]

Yeh 4 short sleeve

[safe radish]

@winter forge Has your question been resolved?

[safe radish]

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[fickle trail]

Did I solve this correctly?

It is not a function

Because I can get two output from one input

But is this the correct way to write it with distribution?

The final answers would be y=3-2x and y=-3+2x?

I also used my own sqrt to this question so therefor I must include two possible answers

[idle sage]

oh it’s not right

[fickle trail]

Shit

Why not?

[idle sage]

u need to square root ur square root

[fickle trail]

Oh yeah lol

So what would that equal?

^1/4

But it would still be +-

Let me add photo again

Like this?

Why does y also not get +-?

[idle sage]

yeshh

[idle sage]

it is

u wrote it down

[fickle trail]

y itself on the LHS

[lean otter]

do you want
±y = (3-2x)^(1/4)?

[idle sage]

oh but y is equal to the rhs

[lean otter]

cause thats the same

[idle sage]

so ure saying that y can take both +ve and -ve

[fickle trail]

I want to add +- to anything I use an even radical on

It is following the rules of math

[idle sage]

i mean u can if u want

but it’s the same meaning

[fickle trail]

Lol

I wonder if instructor would get upset with this

[idle sage]

HAHAHA we don’t rly write it down

[lean otter]

yes if you have an equation you know both terms are positive, you can apply a sqrt on both sides and need to add a ± on one of the terms

[fickle trail]

What is ve?

[idle sage]

oh +ve means positive

[fickle trail]

Ok

[idle sage]

and -ve means negative HAHA

[lean otter]

x² = y
<=>
x = ±sqrt(y)
<=>
x = sqrt(y) or x = -sqrt(y)

[idle sage]

srysry where im from we use that

[fickle trail]

What is <=>?

[lean otter]

it means all statements are equivalent

[fickle trail]

Oh

[lean otter]

if A <=> B, that means A follows from B and B follows from A

its A if and only if B

[fickle trail]

You could also say it this way?

x² = y
<=>
±x = ±sqrt(y)
<=>
x = sqrt(y) or -x = sqrt(y)

[lean otter]

not really

[fickle trail]

Why not tho? If it’s still true

[lean otter]

±x = ±sqrt(y)
depending on the interpretation could also just mean
x = sqrt(y) or -x = -sqrt(y)

[idle sage]

^^

[fickle trail]

So there could be 4 possible answers

[lean otter]

usually you decide whether its + or - for the whole equation

[fickle trail]

x = sqrt(y) or -x = sqrt(y) or x = -sqrt(y) or -x = -sqrt(y)

[lean otter]

that has two redundant statements

[fickle trail]

https://tenor.com/view/calculation-math-hangover-allen-zach-galifianakis-gif-6219070

[idle sage]

yep

sqrt of a real number can’t be negative

[fickle trail]

Imaginary

[idle sage]

HAHAHAHA

[fickle trail]

Why laughing

It’s real math

[idle sage]

ur working w imaginary numbers?

[fickle trail]

Yes

[idle sage]

show me ur qn

[fickle trail]

x² = y
<=>
±x = ±sqrt(y)
<=>
x = sqrt(y) or -x = sqrt(y) or x = -sqrt(y) or -x = -sqrt(y)

[idle sage]

btw I haven’t started on complex numbers so I can’t help with imaginary stuff

[lean otter]

or lets say we have 1±1±1, we can only interpret it as either 1+1+1 or 1-1-1, but not mix both of them

[onyx birch]

bruv y u overthinkin

[fickle trail]

Lol isn’t all math overthinking?

[onyx birch]

nah

[safe radish]

@fickle trail Has your question been resolved?

[safe radish]

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[plain shuttle]

can someone explain how this is separable?

[tame jay]

I don't understand whats happening with the notation here

oh

whoops

[plain shuttle]

looks like you beat me to it somehow

[tame jay]

My bad

.close

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[tame jay]

.reopen

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✅

[tame jay]

im having trouble understanding the notation here

[plush saddle]

What is confusing you

[tame jay]

if m and n are unrelated indices, how can you show the first part, for example?

i just dont really understand what the m and n subscripts are denoting

[plush saddle]

This is the same as inf A

This is the infimum of the set containing each an + bn for each natural number n

wait a minute

This here is confusing because it includes n under here but n is not involved in the expression after it

I'm pretty sure it means an + bm

or am + bn

It means all combinations of m and n

The m and n are like the part after the | in the set notation I'm pretty sure

[tame jay]

is inf_m a_m = inf_n a_n = inf A?

[plush saddle]

Yes

I think they put different variables so that you know the first term inf_m a_m is unrelated to the second term inf_n b_n

[tame jay]

so if a_m and b_n are differently indexed, why are a_m and a_n the same?

[plush saddle]

They are the same because m and n are just letters

Like if I wrote the set of m+1 for all natural numbers m is the same as the set of n+1 for all natural numbers n

[tame jay]

gotcha

thanks

i guess the proof for the first part would go something like

$\inf_m a_m +\inf_n b_n \le a_m + b_n$

[flat frigate]

QUATTRO BAJEEN

[tame jay]

and

$\inf_n (a_n + b_n) \le a_n + b_n$

[flat frigate]

QUATTRO BAJEEN

[tame jay]

then can i say from here that

$\inf_m a_m +\inf_n b_n \le \inf_n (a_n + b_n)$

?

[flat frigate]

QUATTRO BAJEEN

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@tame jay Has your question been resolved?

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[frozen birch]

Is a^-n a geometric sequence?

[thin bridge]

that's just an expression by itself

its a sequence of one term

[frozen birch]

sorry, sum of that

[thin bridge]

wdym by sum of that

can you post the full original thing without parts being cut off

[frozen birch]

\sum_{n=1}^{\infty} (1+2^n)/(3^n)

[thin bridge]

$\sum_{n=1}^{\infty} \frac{1+2^n}{3^n}$

[flat frigate]

ℝamonov

[frozen birch]

Yeah lol, stil learning to use texit lol

[thin bridge]

this can be expressed as a sum of two geometric series
$$\br{\sum_{n=1}^{\infty} \frac{1}{3^n}} + \br{\sum_{n=1}^{\infty} \frac{2^n}{3^n}}$$

[flat frigate]

ℝamonov

[frozen birch]

Oh that makes more sense

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@frozen birch Has your question been resolved?

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[lean otter]

find derivative

[nova creek]

What have you tried

[lean otter]

i tried using chain rule

gave me a weird answer

but not sure what i did wrong

[nova creek]

Show your work

[nova creek]

Where's x⁵cosx/x coming from

[lean otter]

chain rule

oh

allg, got it

figured it out

ty

[safe radish]

@lean otter Has your question been resolved?

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[crude prism]

i can find two points on the intersecting line, but what do i do now?

i'm thinking i should probably find a point where the perpendicular plane meets but i don't know how to do that

[safe radish]

@crude prism Has your question been resolved?

[crude prism]

<@&286206848099549185>

[safe radish]

@crude prism Has your question been resolved?

[marsh walrus]

something tells me that like

youll want to use the normal vector for the proposed plane

and the direction vector for the line

[crude prism]

fuck, i’m so dumb

[marsh walrus]

youre not dumb i had to look it up

[crude prism]

LMAOOO

[marsh walrus]

but this vector 3d stuff is hard

i forget every time

[crude prism]

where did u look it up from?

[marsh walrus]

MSE

[idle parrot]

Yes 3d vec so hard

[marsh walrus]

but it should make sense hopefully

you have like

the direction vector of your line

you have some plane

the normal vector of the plane points directly away from plane

so if the normal vector and the direction vector are parallel

then the line is perpendicular

does that make sense at all

[crude prism]

yeah the normal vector of the perpendicular plane, would be parallel to our plane so the cross product of both of those guys would be the normal to our plane

wait i have a couple more questions, while u 3d vector experts are here

[marsh walrus]

[marsh walrus]

is this good?

they are checked

what are you asking

[crude prism]

oh right, i don't understand why these are true (they gave like five attempts lol so i got them right at the second one)

second one is really odd tho

what would a counter example be

[marsh walrus]

hrm

well

im imagining this like

you have a line right

say its flat and just

normal ass line

flat

then a plane above it

at idk 1

and a plane below it

at idk -1

[crude prism]

mhm

[marsh walrus]

@crude prism now rotate the upper plane 45 degrees one way

and the lower plane 45 degrees the other way

but you know, along the line

so like, the planes still never intersect the line

theyre just skewy

and now, they intersect each other

lets say uhh

line is <x,0,0>

[crude prism]

wait what

okay

[marsh walrus]

upper plane is <x,1,0>

[crude prism]

okay

[marsh walrus]

lower plane is <x,-1,0>

i believe this fits the like

this fits the original whole set up yea

parallel

does the image in your mind make sense

lets just be sure im describing a situation where there is a line, then 2 parallel planes

with one above and one below the line

[crude prism]

wait wait wait

[crude prism]

this would be a line

[marsh walrus]

oh

youre right

okay line is

<x,0,0>

upper plane is

[crude prism]

oh but no i understand what you're trying to say

[marsh walrus]

<x,1,z>

lower plane is

<x,-1,z>

this is right, yea

yea

its a plane of any x and z

but fixed at y = 1 or -1

[crude prism]

i think i get it now

[marsh walrus]

okay now change them

this is the skew bit

change the upper plane to <x,1,-x>

and the lower to <x,-1,x>

they still dont intersect the line, i think

[crude prism]

yeah yeah yeah i got it

[marsh walrus]

[crude prism]

if we have two non-parallel planes tho, they will always intersect right:?

[marsh walrus]

eventually yea

[crude prism]

okay and what does it mean for a line and a plane to be parallel?

that part to me is a little confusing

[marsh walrus]

probably that the direction vector and the normal vector have a dot product of 0

thats how id think of it

then it splits into a case of like

either the line is just on top of the plane forever

[crude prism]

oh interesting

[marsh walrus]

or they never touch

because they have no chance to change relative each other

but thats fine

a line is parallel to itself

so both work

[crude prism]

so a plane and a line that are not parallel would intersect right?

[marsh walrus]

eventually, yea

think if they are not parallel, then their distance is changing

for all time

idk how to make the uhhh

spatial intuition come across

like you and your friend are walking the same direction at constant speeds around a circular track

only 2 possibilities are your speeds are different and at some point one of you laps the other

or you have the exact same speed and your relative distance never changes

its the same thing, just in more dimensions

[crude prism]

okay okay, i think i got it now!

thank you so muchh!

also bonus points for the cat pictures (emojis?) (stickers?)

[marsh walrus]

okay by me

[crude prism]

.close

[safe radish]

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[stray jewel]

Help

[stray jewel]

Don’t get skull question 3 and 4

Please help

[lean chasm]

context?

[stray jewel]

Factorisation

.rotate

[lean chasm]

144 = 12^2

[granite rover]

how did you get that and how is it relevant to the question

[stray jewel]

Not that question @lean chasm

The skull questions

3 and 4

[granite rover]

do you understand what they want?

[stray jewel]

Me?

[granite rover]

ye

[stray jewel]

For 3 or 4

[granite rover]

ye

[stray jewel]

Nvm I don’t quite get what they ask for in both

[granite rover]

so they want you to factorize the given equation with 2^x with the largest x possible

in 3

[stray jewel]

Uh huh

So how do I build the equation

[teal whale]

3. 127*127 -1 = 16128 = 2^x

Are you allowed to use a calculator?

[stray jewel]

I think so

[granite rover]

used log before?

[stray jewel]

I know how to do it

[teal whale]

log2 16128 = x

[stray jewel]

But teacher didn’t taught

So prob can’t use

[granite rover]

have your teacher taught you any other methods?

[teal whale]

Well you could just break up 16128 instead

divide by 2 until you reach 2, the amount of divisions = power

[stray jewel]

He said for these set of questions

Just use pair method of factorisation

[teal whale]

16128/2, 8064/2, 4032/2, 2016/2, 1008/2, 504/2, 252/2,128/2,64/2,32/2,16/2,8/2,4/2,2

[granite rover]

not sure if it's bc I haven't been needing to use it for like 5+ years or if I'm just bad at english but idk what that is

[stray jewel]

?

It’s like

(16-x)
(4+x)(4-x)

And so on

[granite rover]

oh yeah that

it's a language thing then

[teal whale]

If you are not supposed to use log that is how I would solve for 2^x, x being how many times we divided until we reach 1

[stray jewel]

Yeah

But don’t think log is needed

Whatever I’ll ask tmr

[granite rover]

127^2-1=(127+1)(127-1)

[stray jewel]

Do y’all know 4 than?

[stray jewel]

Yeah Ik but idk how to find the 2 to the power of something is the biggest factor

[granite rover]

128 and 126 might be easier to factorize than when they're multiplied idk

[stray jewel]

I think the answer is to the power of 7

But idk how to show me working

Anyone know the next one

The 4 prime one

[granite rover]

I'd try to get an equal factor of both that's large enough that you can start addition to find primes

like

wait nvm

[stray jewel]

?

[teal whale]

Does this make sense for you on 3) ?

[stray jewel]

Yeah I get it now

Thanks

So the answer is 2^7

But how do I show that that’s the answer

[teal whale]

Just write down what I did if you understand it. The answer should be 2^14 no? Since that will be equal to the original sum of 127^2 - 1

[stray jewel]

Wait so the answer is 14?

[teal whale]

yes

[stray jewel]

But isn’t it asking for the biggest?

Ohhh

They are asking for highest

Nvm

I get it

Tytyty

[teal whale]

Glad to help

[stray jewel]

Do you thing I can just write the first line

That say

Chnage base to 2 💀

[teal whale]

Yeah

[stray jewel]

Aight thanks

[teal whale]

I just wrote it like that to clarify

[stray jewel]

👍

Hey @teal whale

[teal whale]

Yea?

[stray jewel]

But for the firsts step

When u toke out the first 2

Isn’t it suppose to be 8064?

[lean chasm]

jesus christ

127^2 - 1 = 127^2 - 1^2 = (127 - 1) * (127 + 1)

[stray jewel]

Yeah that why it looked weird

Haha

So I think answer is 2to the power of 7 no?

[teal whale]

Why you gotta do me like that 😩

[stray jewel]

Damn

So anyone know how to solve?

[lean chasm]

you're shooting with canons on pigeons

[safe radish]

@stray jewel Has your question been resolved?

[safe radish]

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[lean otter]

Use difference of two squares

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[safe radish]

Please don't occupy multiple help channels.

[fickle trail]

Sorry closed prior channel

Thank you @quasi bison for answering the question regarding i

I am curious about these two question I circled with a blue highlighter

Did I solve them correctly?

[lean otter]

a^2-b^2 = (a+b)(b-a)
a^2 =127; b^2=1 (because 1x1=1)
(127+1)(127-1) = 128(126)
128 = 2^7
126= 2*63
128(126)=2^7(2*63)=2^8(63)
hence 2^8 is a factor of 127^2-1
4. this would be too long to solve on the internet, however, I had 5,13, 97 and & 17 as the factors. I am not too sure about 17```

[final halo]

why did you square root?

[fickle trail]

Me?

[final halo]

yes

for g(x^2)

[idle sage]

also ur -g(x) denom shd be x-5 I think

[fickle trail]

Hmmm good question.. I saw x^2 and want to find x.. but f(x^2) is actually just y= and not y^2= either just y=

[final halo]

yes g(x^2) is just the function g evaluated at x^2

no square rooting needed

[fickle trail]

Oh yeah for this I wasn’t sure if I apply -1 to numerator, denominator, or both

When I put the entire fraction in brackets like this and distribute -1 don’t I need to apply -1 to everything? Top and bottom

[final halo]

$-\frac ab = \frac{-a}{b} = \frac{a}{-b}$

[flat frigate]

ΣAC

[idle sage]

it goes to the numerator it this case

[fickle trail]

Oh OK

[idle sage]

bec it’s times -1

[final halo]

it can go on either

but only one of them

[fickle trail]

OK

So I can only get domain and range from the second question? Or all 4

(0, -1/5) interval notation for the second question but I’m wondering if It’s possible to do this for all 4? Or with set notation too

I don’t know if it’s possible to know domain and range of f(x) function without a value added for x?

.close

[safe radish]

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[hardy atlas]

hey

[hardy atlas]

Wow i thought u left

lemme see it

u said common factor in all 3 of em , it will be in the 3 ?

[burnt bloom]

there is no 3 in xy

[hardy atlas]

No i meant to something else

u said that the common factor XY is in all 3 of them right?

[burnt bloom]

yes

[hardy atlas]

then im asking will i be always have to check 3 of em?

or it might be somtimes more or less

[burnt bloom]

you could solve them separately in some cases

[hardy atlas]

i dont understand, thank u for ur tim

bye.

!close.close .close

close.

.close

[safe radish]

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[hardy atlas]

finally

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[lean otter]

Hello guys I need some help with this(xii)

[lean otter]

I get 18.77 and 78.77 as my answer but the book has more than 2 answers

[final halo]

because youre looking for 0 < x < 360, this means 0 < 3x < 1080

so when solving for 3x you're looking for solutions in that range

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

Can u explain me a bit more

[final halo]

what doesnt make sense to you

[lean otter]

Sorry I went to eat
Why am should I get more than 2 answers and how do I get them

[final halo]

you look for solutions for 3x in the range 0 < x < 1080

[lean otter]

Alr bro i think I got it

Thanks

.close

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[real geyser]

Hello kind stranger,

I have the following problem:

I am trying to write a program that will calculate how long a marble will go around a small round circuit before it eventually stops. So if you input Y, it will calculate how many round the marble will do before it stops.
I am timing the ball with a stopwatch and therefore can't get exact lap times.
I am trying to get an equation from the moving average. But I have no idea where to start. Is this possible? I mean the equation doesn't have to be perfect but it needs to be close enough. I tried it with the polynomial equation but that does not work.

[safe radish]

@real geyser Has your question been resolved?

[real geyser]

<@&286206848099549185>

Seems to be a though one eh... : \

[peak estuary]

what do you mean with "does not work"

that dotted line looks like a decent enough approximation

[real geyser]

Yeah but it is a polynomial equation, so it wont tell you when the ball stops since the eqation doesnt have an end point

[peak estuary]

hmm ok. I think you need to change your model. did both of the marbles stop after those 18 rounds?

[real geyser]

1 after 17,5 and one after around 18

It might seem a bit confusing the screehot that I sent

The marbles basically get shot around the track, but they do not have the same speed at the start. They do however slow down in the same manner, and there should be an equation to be found in the way they slow down.

[peak estuary]

well you could record the first round, check how long it takes, compare with your reference values of how long each round takes and then go from there

[real geyser]

But that won't give me a equation. I need an eqaution because I am writing a program that will calculate where the marble will eventually end if you insert the lap time of the first lap.

[peak estuary]

that does not mean that you need an equation

or at least not something that I would call equation

just means that you need to find some algorithm

[real geyser]

Hmmm interesting.

Yeah, right. Do you know how?

[peak estuary]

.

[real geyser]

But the first round for the algoritm isn't really interesting right?

It is all about calculating backwards

So from the last round (which should be the same time as all other last round)

[peak estuary]

you just said that you want your program to only work based on the first lap time

[real geyser]

Correct. But to know how many round the ball will make after the first lap, we need to know how fast it will slow down from a certain pace right?

And the first round could be highly different than other first rounds because the ball gets shot onto the track with different speeds.

So one time it might take the ball 2.3 seconds to finish the first round and an other time it could take 2.8 seconds. Comparing those wouldn't be usefull right?

[peak estuary]

no but you could for example check when that first marble took 2.8 seconds

maybe the fourth round took that long.

then the first round of the second marble is roughly equivalent to the fourth of the first

so if the first stops after 18 rounds, the other would maybe stop after 14

[real geyser]

Ah okay

Like finding the round time that is closest to round time given.

Interesting, haven't thought about it like that.

[feral blaze]

Hi.

625 = x^2

[safe radish]

@real geyser Has your question been resolved?

[safe radish]

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[nimble olive]

it rigth to do it?

[lean otter]

yes

[nimble olive]

thx

.close

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[craggy trout]

Hi

[craggy trout]

To solve this would I set h(t)=0?

$-16t^2 + 96t = 0$

[flat frigate]

dopediscorduser

[craggy trout]

$4t(-4t +24)=0$

[flat frigate]

dopediscorduser

[craggy trout]

$4t=24$

[flat frigate]

dopediscorduser

[craggy trout]

$t=6$

[flat frigate]

dopediscorduser

[craggy trout]

$-16(6)^2 +96(6) = 0$

[flat frigate]

dopediscorduser

[craggy trout]

$576-576=0$

[flat frigate]

dopediscorduser

[craggy trout]

Does that look right?

Solution of t<=6?

[lean otter]

not really

look think about it

height can never go below 0 ?

makes sense?

[craggy trout]

Right

[lean otter]

alright

then what you are supposed to do is solve for
h(t)>=0

[craggy trout]

Wouldn’t that be the same answer?

[lean otter]

yes perhaps

No

the answer will be 0<x<6

@craggy trout

[craggy trout]

Ah

That makes sense

Quick question

So

[lean otter]

ok

ask

[craggy trout]

$-16t^2 + 96t \geq 0$

[flat frigate]

dopediscorduser

[craggy trout]

$4t(-4t+24) \geq 0$

[flat frigate]

dopediscorduser

[craggy trout]

Am I still solving this the same way?

[lean otter]

yea

[craggy trout]

By factoring it out like that

[lean otter]

yea

but you have to be extra careful when it comes to this\

[spiral crescent]

what is the question

[spiral crescent]

the domain of the function?

[craggy trout]

Yes

[craggy trout]

$-4t \geq -24$

[flat frigate]

dopediscorduser

[lean otter]

No

you cant get rid of it like that when solving quadratic inequalitoes

[craggy trout]

I am stuck then

[lean otter]

Plot a graph

its the easiest and best way

[craggy trout]

A graph for this?

[lean otter]

yes

plot it

[craggy trout]

Okay

It’s symmetrical around t=3

I guess yeah that clearly shows it’s at 0 at t=0 and t=6

[lean otter]

yeah

but more importantly

you can test the region of x coordinates

and see if it satisfied the inequality

[craggy trout]

In what case is it best to plot the function and which is it best to try and solve it as an equation?

I don’t think I would’ve thought to plot it to find the solution on my own

[lean otter]

no

when its quadratic inequality

plot it

[craggy trout]

Gotcha

Thanks for the help

.close

[safe radish]

Channel closed

Closed by @craggy trout

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[lean otter]

ok

[safe radish]

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[golden meteor]

i need help with discrete mathematics

[golden meteor]

and understanding truths

i understand some of it but some of the questions i have i dont understand

SO i know the answer

all of them except e and f

are propositions

wht im confused on is the second part

are they asking for a truth table bc theyll all be P im assuming

or do they mean what makes the statement true? im new to this subject so i dont understand fully wht they mean

for example

d is false

bc 5 + 7 does not = 10

but idk if thats wht makes a proposition true or false

this is not P

i need help understanding what is considered a truth value and what isnt

[safe radish]

@golden meteor Has your question been resolved?

[golden meteor]

no one came

<@&286206848099549185>

T_T HEYYY

<@&286206848099549185> hiii

[lean otter]

Okay, so do you know what a propostion is?

[golden meteor]

yes

[lean otter]

Tell me what it's.

[golden meteor]

a declarative statement

true or false

[lean otter]

Okay, so lets start with first is Boston the capital of Massachussets?

[golden meteor]

its ok if you dont know this stuff, you can try to help me find someone here to help

[lean otter]

Nah, this is simple stuff I guess.

[golden meteor]

o

[lean otter]

I read an article, can basically pick this up.

Okay, so the first one is a true fact so there is no option.

[golden meteor]

._. but the stuff gets more complex

[lean otter]

So, it cannot be a propostion.

[golden meteor]

all of them are propositions

except e and f

oh btw

[lean otter]

Yes, that seems to be the case.

[lean otter]

mhm

[golden meteor]

i need help <@&286206848099549185>

[lean otter]

Okay, I am helping.

Ask the next question.

You said the first couple right.

[golden meteor]

i thought they were all right

from wht i said, no?

[lean otter]

Yes, they are correct.

[golden meteor]

oki

[lean otter]

What do you still need help for?

[golden meteor]

the second part

[lean otter]

Resend here.

It's too far away, cannot see.

[golden meteor]

arent they all truths except .. 3

D

[lean otter]

3?

You mean C?

C is true as well.

D is false

[golden meteor]

e and f dont count bc theyre not

uj

[lean otter]

E could be either or.

[golden meteor]

ya

[lean otter]

Also wait, I think you made a mistake D is not a proposition either.

[golden meteor]

yes it is

[lean otter]

Cause that can never be true.

So it cannot be either or.

It's solely FALSE.

[golden meteor]

<@&268886789983436800> this man is helping me and he doesnt know wht he's talking about

[lean otter]

What?

[golden meteor]

its a proposition

propositions can be true OR false

[lean otter]

So, they don't have to both.

That's what I asked you up top and you said that they are either or...

Bruh...

You literally telling me stuff and then saying I AM WRONG...

[golden meteor]

please help me get someone else bc you dont understand the material

which is okay

i just need a helper here

[lean otter]

Okay, make another ticket!!

Then you can get on the top charts and someone can help...

[golden meteor]

okay, ill try again

[lean otter]

YES! MAKE ANOTHER TICKET.

[golden meteor]

thank you busty ❤️

[lean otter]

What?

Okay... don't give me that.

[golden meteor]

lol

[lean otter]

You literally blackmailed me...

[golden meteor]

no i didnt

hi tox

[lean otter]

Yes, you did bruh...

[lament creek]

@lean otter don't try to help people if you don't know the material to begin with

[golden meteor]

liar liar, was reporting you anyways

[lament creek]

@golden meteor do not abuse the helper ping

[lean otter]

Dude she literally was blackmailing...

[golden meteor]

i didn't mean to, i'm sorry

no i was not

[lean otter]

But yes, I will stop.

[golden meteor]

i'll just report you to the mods

[lean otter]

LMAO. Look at this... ^^^ @lament creek

Perfect example.

[golden meteor]

please go, people are trying to get help

.close

[safe radish]

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[meager coral]

calculate the length of the catheters if the hypotenuse is √13

[light shoal]

that's a catheter?!

[meager coral]

google translate

i mean the a lines

[light shoal]

huh, i never knew that term, catheter is also something they stick up your peepee in a hospital 😁

[meager coral]

damn

[pearl blade]

seems like you would know that

[light shoal]

can't tell for sure from the font, is that "a + 1" (the number 1) on the vertical side?

[meager coral]

yes

[pearl blade]

yeah; pythagoras

[light shoal]

yep pythag that puppy

[meager coral]

its tricky

[pearl blade]

why?

[meager coral]

√13= √(a^2(+1)+b^2

isnt that the way to do it

[pearl blade]

Start by just filling in pythagoras

you'll see you'll get a quadratic (a²), which you can then solve with the quadratic formula

[light shoal]

pythag is z^2 = x^2 + y^2, in particular the left hand side should just be 13, not sqrt(13)

and similarly, no square roots on the RHS

[pearl blade]

he tried to root both sides

[light shoal]

yea, no need, that makes it intractable

[pearl blade]

true

[meager coral]

so a2+(a+1)2=13

a2+a2+12+2a=13

2a2+2a+1=13

2a2+2a=12

and then a quadratic sentence

[pearl blade]

Ye

[meager coral]

thanks

.close

[safe radish]

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[modern crane]

so i know that we have to use f(a+h)-f(a)/h to solve this

and i ask my friend

they basically gave me the answer up above but its wrong

i want to learn how to solve it

[hardy lion]

the power is negative

oh wait this the limit definition huh

[modern crane]

i think so

this was an example problem they showed me

[hardy lion]

what part of that do you not understand

i know theres a lot of variables and stuff flying around

[modern crane]

yea

so im stuck at

lemme write it down and send it

I’m stuck here

I don’t know what’s the next step

like did they cross multiple or

[rigid inlet]

,rotate

[rigid inlet]

You want to make a common denominator

[modern crane]

how do i do that

[rigid inlet]

I guess that's what cross multiplying means

[modern crane]

okay

So I have this

[rigid inlet]

Good

[modern crane]

so

how do i solve it

how is the sqrt removed from the top

[rigid inlet]

You notice that the numerator is in the form (a-b)(a+b)

[modern crane]

yes

[rigid inlet]

What is (a-b)(a+b)?

[modern crane]

a^2-b^2?

so the top is squared?

[rigid inlet]

That's where the sqrt goes

[modern crane]

how would i write that?

[rigid inlet]

Write what?

[modern crane]

is the sqrt removed since its squared

[rigid inlet]

Yes

[rigid inlet]

Numerator should be -(a+h+1)

[modern crane]

okay

then the top would be -h

[rigid inlet]

Indeed

[modern crane]

okay...

what happens with the denominator?

[rigid inlet]

For now, nothing

[modern crane]

wait wait

the h

[rigid inlet]

You can keep simplifying

[modern crane]

we cancel the h's

so then its -1

[rigid inlet]

Indeed

[modern crane]

okay

so what do we do with the denominator

[rigid inlet]

You can try plugging in 0 for h

Now that there is no h in the numerator your answer won't be indeterminate

So you'll get a valid answer

[modern crane]

I have this…

[rigid inlet]

(a+1)(2sqrt...)

[modern crane]

yea i put that in ()

[rigid inlet]

Your first part is not

[modern crane]

ohhh

[rigid inlet]

a+1 must also be in parentheses

[modern crane]

okay

is that final

or still have to solve

[rigid inlet]

You can simplify once more

[modern crane]

okay...

im confused in how i would do that

[rigid inlet]

Then look at the example

[modern crane]

Would it be that

[rigid inlet]

That second term should bd $2\sqrt{a+1}$ not $2\sqrt a +1$

[flat frigate]

Steakanator

[rigid inlet]

be*

[modern crane]

okay so

the final answer would be

[rigid inlet]

Looks like you misunderstood what I said

[modern crane]

oh the sqrt is over the one two

too*

[rigid inlet]

After taking the limit, your last result should be $\frac{-1}{(a+1)(2\sqrt{a+1})}$

[flat frigate]

Steakanator

[modern crane]

oh

so would that be final?

[rigid inlet]

No

As I said, you can simplify once more

And my hint was to look at the example because they do said simplification

[modern crane]

would it be 2(a+1)^2?

[rigid inlet]

Not quite

You have (a+1) and (a+1)^1/2

[modern crane]

uhh

then

would the sqrt be 1/2 or 3/2

[rigid inlet]

sqrt is 1/2

[modern crane]

so its -1/2(a+1)^1/2

[rigid inlet]

No

You have (a+1)*(a+1)^(1/2)

When you multiply two things with the same base, what do you do with their exponents?

[modern crane]

add it

then it becomes 1/4

[rigid inlet]

No it does not

(a+1) = (a+1)^1

What is 1 + 1/2

[modern crane]

3/2

[rigid inlet]

That's your exponent

[modern crane]

okay so the final answer is -1/2(a+1)^3/2?

[rigid inlet]

Yes

[modern crane]

okay okay

thank you for your help!

[rigid inlet]

Np

[modern crane]

.close

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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac widget]

How do I solve this problem

[lilac widget]

how do i convert this to sine

[lean otter]

what have you tried?

@lilac widget He tried to ask the question.

[lilac widget]

turns out the answer is the product of limits rule

[lean otter]

@lilac widget Congratz!

[lilac widget]

.close

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[lean otter]

looking for some help please

for A I found 200 / x km/h

for B I'm having problem though

so i thought about first doing 250km / 3.5 hours = ( 4x km/ h ) + (x-40 km / h)

don't really know what to do

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

.close

[safe radish]

Channel closed

Closed by @elder thicket

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[lean otter]

wtf are they asking me to do here

[safe radish]

@lean otter Has your question been resolved?

[rigid inlet]

Factor the numerator and denominator, then cancel the common term(s)

[lean otter]

denominator can't be factored

prime number

[rigid inlet]

It can't be factored because you made a mistake with your removal of the absolute value signs

When x=7, what is x^2-100?

[ornate lark]

ive seen this app before

need left and right limits to solve

[rigid inlet]

That's not at all what they're asking for

[safe radish]

@lean otter Has your question been resolved?

[ornate lark]

well to solve absolute value limits u need to know the left and right limit

left and right limit are both gonna yield negative in absolute value

[rigid inlet]

Please read the questions again

At no point does it ask about left and right limits

[ornate lark]

but to evaluate the limit u need to use left and right limits

but in this case it doesent matter

[rigid inlet]

We're not evaluating any limits yet

@lean otter are you still here?

[lean otter]

I'll be back in a few hours

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

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[safe radish]

Available help channel!

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tender shell]

😓

[blissful gate]

What have you tried

And where did you get confused

[tender shell]

i like dont understand what i have to do...

like how to get the answer and the steps to take

[blissful gate]

https://thirdspacelearning.com/gcse-maths/number/factor-tree/

[tender shell]

oh ty

so do i read it then understand what i have to do?

[blissful gate]

Yes

If you prefer a video, Google "prime factorization trees khan academy"

[tender shell]

okay tysmmm

.close

[safe radish]

Channel closed

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[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

hello!

[lean otter]

I’ve been stuck on these 3 problems for the past 5 hours… with no exaggeration

for question 4 I attempted to find the inverse function of f(x) but I realized that that would basically lead to nothing however Im not sure if it would lead to nothing as I stopped halfway through when I started the process

For question 5 should I just be applying the g(x) transformations to each of the individual points on the first graph?

and for question 13… I just don’t understand the question or what it wants me to do

i think you just wrote magic symbols

[steep dove]

correct?

[lean otter]

...

potentially?

[steep dove]

what does f inverse really mean?

[lean otter]

i have no idea

i just know how to find the inverse of a function

[steep dove]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:functions/x2f8bb11595b61c86:inverse-functions-intro/v/introduction-to-function-inverses

[lean otter]

but to be honest

i dont know what an inverse actually is

its like the reverse of the operations