??
#help-23
lean otter
velvet monolith
yes
lean otter
thats what i was trying to say
velvet monolith
yes and thats a condition that must be met
velvet monolith
so a must be greater than -2
velvet monolith
yes a E ( -2 , ∞)
exactly
lean otter
what ?/
lean otter
f(5) can be equal to 0
can u explain
velvet monolith
.
velvet monolith
can u explain
it can be equal or greater than 0
lean otter
it can be equal or greater than 0
still not getting it
lean otter
it can be equal or greater than 0
if its equal to zero then it must be a root but the equation is strictly greater than zero
velvet monolith
if its equal to zero then it must be a root but the equation is strictly greater...
yes ik
lean otter
so what should i do
velvet monolith
but that is for $x\in(5, +∞)$
inf is infinity
but idk how to type infinity in latex lol
velvet monolith
but that is for $x\in(5, +∞)$
not for $x\in[5, +∞)$
lean otter
ohhh
i see
at 5 it can be zero
but then how to solve it
😫
i want to know solutin
solution*
velvet monolith
well we know for sure that a>-2
velvet monolith
and that $b^2-4ac\leq 0$
flat frigateBOT
kjmkty
lean otter
yup yup
lean otter
and that $b^2-4ac\leq 0$
pls explain this one
velvet monolith
and you wrote something smart which is f'(x)<5
lean otter
i am bit confused
lean otter
and you wrote something smart which is f'(x)<5
5
velvet monolith
pls explain this one
okay in order for an equation to have no real roots or only one root is that $D\leq 0$
flat frigateBOT
kjmkty
lean otter
okay in order for an equation to have no real roots or only one root is that $D\...
ik that
flat frigateBOT
kjmkty
lean otter
yupp
lean otter
yes
velvet monolith
we have one condition as we previously said a>-2
lean otter
yupp
velvet monolith
the first case is that the equation has no real roots or one real root at x=5
velvet monolith
so we said $b^2-4ac\leq 0$
flat frigateBOT
kjmkty
velvet monolith
lean otter
yupp
velvet monolith
in other words $4-4 \cdot (a+2) \cdot 1 \leq 0$
flat frigateBOT
kjmkty
velvet monolith
a E [ -1 , ∞ )
yes this
lean otter
ya
velvet monolith
idk how to calculate a using that second case
i mean i can try to explain it to you
and i have a picture in my head
lean otter
idk how to calculate a using that second case
tell me ill get the solution
velvet monolith
ok so basically
velvet monolith
the equation can have 2 roots, the greater one being 5
bc then the rule still applies right
lean otter
maybe
velvet monolith
but actually the root doesnt have to be 5, but it must not be greater that 5
idk how to visualise this
it can be easy to undertsand if you picture the graph right
lean otter
i have pictured one in right side
f i am not getting it
yrr
i got it the answer maybe from (-2 , ∞ )
safe radishBOT
@lean otter Has your question been resolved?
covert fiber
may i get help derivate that ?
safe radishBOT
may i get help derivate that ?
covert fiber
i want to get the maximum and minimum points
covert fiber
e^ax
safe radishBOT
@covert fiber Has your question been resolved?
spiral crescent
may i get help derivate that ?
U want to find dy/dx?
covert fiber
u will help tho 😅
safe radishBOT
@covert fiber Has your question been resolved?
safe radishBOT
@covert fiber Has your question been resolved?
vast obsidian
Take the derivative of the function and set it equal to 0
safe radishBOT
@covert fiber Has your question been resolved?
covert fiber
Take the derivative of the function and set it equal to 0
I did but couldn’t solve it xd
vast obsidian
Can you show your work?
safe radishBOT
@covert fiber Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
sullen vine
What's the best way to find the tangency point for a function if I'm only given a point which lies on the tangent?
safe radishBOT
What's the best way to find the tangency point for a function if I'm only given ...
glass carbon
What's the best way to find the tangency point for a function if I'm only given ...
I'd use tangent line formula and a line equation to make a system of equation then I'd solve
sullen vine
the function is x^3+3 and the point is (0,1)
So I write y-1=m(x-1) and y=mx+1
glass carbon
my way would be
let's say point of tangency is (c, f(c)) for some c
let's say the tangent line is y = ax + b
since tangnet passes through (0,1) we have:
1 = b ---> y = ax + 1
now from the tangent line formula:
y = f'(c)(x-c)+f(c) = 3c^2 * (x-c) + c^3 + 3 = x * 3c^2 - 3c^3 + c^3 + 3 = x * 3c^2 - 2c^3 + 3
now it's enough to compare ax + 1 and x * 3c^2 - 2c^3 + 3 to solve for 'c' then for f(c)
sullen vine
ah yes that formula, forgot about it
glass carbon
it's the same as yours, I've used m = f'(c) and f(c) instead of y coord
blazing rune
safe radishBOT
quasi bison
yeah but cos(omega*t) is a horizontal compression of cos(t)
so its period is shorter
blazing rune
.close
rigid minnow
I dont see where I went wrong. here is my working:
safe radishBOT
I dont see where I went wrong. here is my working:
rigid minnow
There isn't supposed to be -2
The question is about diagonalisation using eigenvalues and eigenvectors
safe radishBOT
@rigid minnow Has your question been resolved?
rigid minnow
<@&286206848099549185>
rigid minnow
What is gauss
rigid minnow
a calculator i tried said the eigenvectors are wrong
I don't see how my working is wrong tho
grizzled shoal
row reducing
rigid minnow
Do you see where my working is wrong?
grizzled shoal
no since imo your writing to get the vectors is pretty small
rigid minnow
I'll take a closer pic
grizzled shoal
it seems you onoy used one row?
rigid minnow
it seems you onoy used one row?
wdym
Oh, right. Yes, I was taught that I can solve using one row
I can choose any of the two, all based on preference
flat frigateBOT
grizzled shoal
thats how i learned it
rigid minnow
Strange because my vectors seem to work
safe radishBOT
@rigid minnow Has your question been resolved?
rigid minnow
<@&286206848099549185>
safe radishBOT
@rigid minnow Has your question been resolved?
placid raft
Is this accurate? I don't know if I calculated everything right, do I count the bottom stem and assume it's 170?..... Or do I leave it out entirely?...
safe radishBOT
Is this accurate? I don't know if I calculated everything right, do I count the ...
safe radishBOT
@placid raft Has your question been resolved?
placid raft
i dont really understand the table
That's all it has, that's the full page
safe radishBOT
That's all it has, that's the full page
placid raft
What do I do with the bottom stem?
safe radishBOT
@placid raft Has your question been resolved?
tardy mango
What do I do with the bottom stem?
Pretty sure it means there's just no data for that
Cause if there was 170, the leaf would be 0
placid raft
Ah, so I can leave it out?
tardy mango
Yeah
safe radishBOT
safe radishBOT
Available help channel!
patent vault
howww do i do this
safe radishBOT
howww do i do this
patent vault
The following cards are dealt to three people at random, so that everyone gets the same number of cards. What is the probability that everyone gets a red card?
anyone pls?
is 3/56 right?
<@&286206848099549185>
safe radishBOT
@patent vault Has your question been resolved?
patent vault
what is 9!
but does order matter?
patent vault
is that dealing three cards?
smoky shard
Hi
safe radishBOT
@smoky shard Has your question been resolved?
dense galleon
Find the fraction of white circles and black circles, and add them together
smoky shard
Find the fraction of white circles and black circles, and add them together
uh but how
dense galleon
Do you know the fraction of white shapes
smoky shard
nope
dense galleon
The ratio of white to black shapes is 5:11
So if you had 5 white shapes, and 11 black shapes, it would satisfy that ratio
When you have 5 white shapes, and 11 black shapes, what fraction of shapes are white?
smoky shard
When you have 5 white shapes, and 11 black shapes, what fraction of shapes are w...
but how do i convert that to circles
safe radishBOT
safe radishBOT
Available help channel!
unkempt epoch
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lean otter
you can make it so there's only one x on the bottom
flat frigateBOT
Toby
lean otter
use the quotient rule
sudden knot
.close
safe radishBOT
Available help channel!
timid goblet
safe radishBOT
nova creek
!15m
safe radishBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
nova creek
Show exactly what you put in
timid goblet
timid goblet
Am dumb
worthy hemlock
I mean your r's do look like y's
nova creek
I thought it was γ 👀
dapper sinew
confused what the difference is
nova creek
f(x) + 3 = f(x) - (-3)
dapper sinew
.close
safe radishBOT
safe radishBOT
Available help channel!
fallen grotto
So my book defines simple random sampling as "every group of n individuals has an equal chance of being selected"
For example, they have the question: "A corporation employs 2000 male and 500 female engineers. A stratified random sample
of 200 male and 50 female engineers gives each
engineer 1 chance in 10 to be chosen. This sample
design gives every individual in the population the
same chance to be chosen for the sample. Is it an
SRS? Explain your answer."
And the answer is: "No. In an SRS, each possible sample of 250 engineers is
equally likely to be selected, including samples that aren’t exactly
200 males and 50 females."
But, if it's a random sample, shouldn't the probability that you get for example, 230 males and 20 females be higher than 200 males and 50 females?
safe radishBOT
So my book defines simple random sampling as "every group of n individuals has a...
buoyant shadow
can you just read it again or something?
fallen grotto
can you just read it again or something?
That really helps.
buoyant shadow
you missed a question mark
fallen grotto
like, "that really helps?"
I was being sarcastic cause I’ve read it multiply times already but I found something else explaining it
.close
craggy quiver
safe radishBOT
stray socket
I mean the easiest way is to set the independent variable as t
And then go from there on
craggy quiver
im just confused as to how to go from the start
stray socket
Wdym go from the start
craggy quiver
like where do i start
stray socket
It doesn't specify an initial value or direction
stray socket
I mean the easiest way is to set the independent variable as t
_ _
craggy quiver
so -3t^2?
stray socket
z(t) = t
stray socket
Yeah it isn't linear so
Im not sure how to vectorize quadratics
I can help you find the two parametric equations but combining them seems rather dumb
I'm not sure if you're dealing with 3D
craggy quiver
yeah its 3d
stray socket
Alright you can try uh
craggy quiver
i think i figured it out
stray socket
r(t) = {-3t^2, 0, t}
craggy quiver
yeah
i did that
just no j value
and got it
its so weird but thank you
got it correct
craggy quiver
.close
safe radishBOT
safe radishBOT
Available help channel!
mighty rover
hey i need some help understanding how to evaluate this limit
safe radishBOT
hey i need some help understanding how to evaluate this limit
mighty rover
i am confused on this step
i dont understand how diving both the numerator and denominator by x^3 u get 7/x^2
and the other values in the numerator
how does this work?
flat frigateBOT
mighty rover
wdym
oh wait
in order to make sure that im diving by x^3 in the numerator
i have to do that bc its in a sqrt?
flat frigateBOT
lean otter
I need help solving 7
safe radishBOT
I need help solving 7
lean otter
idk how
lean otter
Ok so through watching his first example
I think my only question is
How do I deal with the fraction within g(x)
last heart
you have to find a common denominator
then you will be able to combine the fractions because they have the same denominator
lean otter
so the two goes into the 1?
wait wait wait
-1/3 would become 6/3x?
where did the extra three come from
lean otter
:o
last heart
because 9/3 is still 3 we just want to make it a fraction because the other side is a fraction
last heart
the next thing I would do is distribute the negative
last heart
so if we distribute the negative we get
then (9/3x-2)+(1/3x-4)
which makes it easier to solve
now we just combine like terms
last heart
ok
this one is a little bit harder
oh no nvm
this one is ez
it is asking us f(2)*g(2)
lean otter
we replace the x with 2 and then solve?
lean otter
so 2f=2
last heart
ok
last heart
yes
lean otter
then we multiply 2 times the fraction then add four?
last heart
yes
lean otter
but I already added it by four though?
last heart
because it asked f(2)*g(2)
last heart
yes
lean otter
40/3?
lean otter
uhhhh
40/3 for the final answer seems off
wait no nvm
it makes it seense
I need your help with one more if you wouldn't mind
ok so for this graph im looking for the min and max and also which f is increasing in interval notation
;-; which yknow idk how to do
last heart
max is the high point of the curve
min is the lowest point of the curve
the point where the f is increase is between the min and the max
last heart
if you need to round to two decimals look at the number behind it
lean otter
1.66 seems fine the way it is
last heart
if it is 5 and above round up
lean otter
which number has to be 5 though
last heart
so fits the first you you would look at the 2
last heart
yes
last heart
yes
last heart
ok
safe radishBOT
safe radishBOT
@lean otter Has your question been resolved?
tired widget
safe radishBOT
@lean otter Has your question been resolved?
safe radishBOT
@lean otter Has your question been resolved?
opaque sorrel
safe radishBOT
opaque sorrel
am i right if i say that to prove that something has infinite solutions/a set of solutions, i need to introduce an arbitrary real number?
quasi bison
not in general, no.
but in your case, ie specifically for linear systems, if such a system has more than one solution, then it has uncountably many and it is convenient to parameterize them with one or more real-valued parameters.
quasi bison
better in what sense?
opaque sorrel
ermm maybe less lengthy
quasi bison
you could perhaps try to find a phrasing of this proof that communicates the same idea in less symbols
but that's kind of silly
this proof is short
inner zealot
safe radishBOT
inner zealot
ind a better lower and a better upper bound for the integral than 0 and 3.
this is the problem i am dealing with. I dont how to find a better under and upper limit for the function
v(t) is the function
can you guys give me any guidance for solving the problem?
safe radishBOT
@inner zealot Has your question been resolved?
cloud elm
how to do b) iv)
?
safe radishBOT
how to do b) iv)
?
quasi bison
2 ways to seat Feng and George, some number of ways to pick seats for Hannah, Alice and Barney w/ 2 orientations for each (A-H-B or B-H-A), then 3! ways to seat the rest...
cloud elm
pls explain further the answers 144 but i still dont know 😢
quasi bison
which part of my message is confusing you?
cloud elm
i dont know the arrangements for Hannah Alice and Barney
this is the provided solution but it makes no sense to me
quasi bison
you can either have A, H, B sit consecutively or two seats away
A H B _ _ _
_ A H B _ _
_ _ A H B _
_ _ _ A H B
A _ H _ B _
_ A _ H _ B
do you understand that these are all the possible arrangements (with the possibility of swapping A and B in each)?
quasi bison
ok so is there anything in what i said and/or in the provided solution that makes no sense to you?
cloud elm
no i get it 🙂
solution is 2! x 3! x 6 x 2! and that equals 144
quasi bison
yes that's right
lucid abyss
how is the domain for a square root function (0,infinity), but not [0, infinity)?
safe radishBOT
how is the domain for a square root function (0,infinity), but not [0, infinity)...
lucid abyss
doesnt the 0 count
lunar flume
The 0 is included. The domain is [0, +inf)
lunar flume
Any certain restrictions?
lucid abyss
it just says "over what intervals is the sr function increasing"
could it be cuz x=0 is at 0,0 and not rlly "increasing"
lunar flume
It definitely includes 0. Think of it this way, if x = 0 which would be (0,0) is an ordered pair, the notion of increasing value comes from comparing the (x,y) value as you plug values for f(x).
I suggest you try making a table of values to see immediate relationships between x and y for the square root function
lucid abyss
i get it it just might be the answer key is wrong
lunar flume
Yes, its most likely incorrect. Unless there are certain restrictions you left out
proven wren
I'm trying to compare this to a function, imagining a x^3 or something function. The turning points wouldn't count in the "increasing"
Or like x^5 - x
The inputs for this function decreasing would be (-0.6687, 0.6687)
Is the square root function tryna say the same thing?
lucid abyss
yes
proven wren
But a square root doesn't have turning points, they can't have a slope of 0
It most likely includes 0
lucid abyss
👍
alright, thanks for the clarification. I have to get ready for school, cya
.close
magic marten
- Salde is 15 years older than Sonny. If the product of their ages is 54. Find the ages of the two students?
safe radishBOT
3. Salde is 15 years older than Sonny. If the product of their ages is 54. Find ...
magic marten
.close
random merlin
For positive real numbers a, b, c, if the conditions a+b+c=10 and ab+bc+ca=25 are fulfilled
Find the maximum possible value of the set of numbers ab, bc, and ca.
safe radishBOT
For positive real numbers a, b, c, if the conditions a+b+c=10 and ab+bc+ca=25 ar...
quasi bison
what's the value of a set of numbers?
quasi bison
maximum possible value of the set of numbers ab, bc, and ca.
random merlin
ohj
quasi bison
it's a little unclear what this refers to
random merlin
u want to find the max possible value of the lowest number in that set of numbers
random merlin
screenshot maybe
its in Mongolian
quasi bison
so you want $\max_{\substack{a,b,c>0 \ a+b+c=10 \ ab+bc+ca=25}} (\min {ab, bc, ca})$
flat frigateBOT
Ann
quasi bison
is that right?
random merlin
yeah
quasi bison
hmm
intuitively it feels like a, b and c should be close to each other so that ab, bc and ca are as close as possible to 25/3
random merlin
yeah
quasi bison
ok so i found a graphical solution but it is ugly and WA is giving some crazy exact form for it
wait
hold on
i fucked up
random merlin
ae
quasi bison
ok so heres what i did
i took x and y as a and b
expressed c in terms of those as 10-x-y
and plotted the other constraint as a curve
then i plotted min(xy, x(10-x-y), y(10-x-y) ) ≥ c and gradually decreased c until the region touched the green curve
(yes i know this is dirty)
(no i can't think of any more elegant solution rn)
random merlin
then i plotted min(xy, x(10-x-y), y(10-x-y) ) ≥ c and gradually decreased c unti...
;-;
fallow oriole
oh wait Im dumb you're trying to find the maximum of the minimum
random merlin
oh wait Im dumb you're trying to find the *maximum* of the minimum
yeah
fallow oriole
For positive real numbers a, b, c, if the conditions a+b+c=10 and ab+bc+ca=25 ar...
hopefully this proof works
I hate working with anything involving WLOG
fallow oriole
i was trying to use AM GM inequality backwards
oof
sage finch
yeah me too lol
reef basin
safe radishBOT
reef basin
Can someone help me solve this?
I'm stuck on a equation with 2 variables ;-;
safe radishBOT
@reef basin Has your question been resolved?
idle parrot
@reef basin you still here?
reef basin
yep
flat frigateBOT
flat frigateBOT
idle parrot
You get this?
reef basin
im stuck here
I just did it till equation and put it in Wolfram cause I had no idea how to solve this further
the answer seems to be 37.0156%
but idk how to solve this question without using wolfram and i need to solve this under 100 secs
;-;
idle parrot
Okay so we get (100+p)(100-q)=10000
Or we can write it as
(100-q)=10000/(100+p)
Right?
reef basin
yes
idle parrot
And we given that p-q >= 10
reef basin
yes
reef basin
ok makes sense
idle parrot
Okay so can you solve it from here on?
reef basin
ill try one sec
idle parrot
Lemme add some more brackets
reef basin
ok im stuck again ;-;
Do i use the quadratic equation now
This will take forever to solve @.@
flat frigateBOT
idle parrot
,rotate
flat frigateBOT
reef basin
im pretty sure i didnt make a mistake o.o
flat frigateBOT
reef basin
idk if this question seems doable in 100 secs
idle parrot
,calc 5(1-sqrt(401))
flat frigateBOT
Result:
-95.124921972504
Hmm
reef basin
,calc 5(1+sqrt(401))
idle parrot
,w p^2 -10p-10000>=0
idle parrot
,w p -(100-(10000/(100+p)))>=10
flat frigateBOT
flat frigateBOT
idle parrot
,calc 5(1+sqrt(41))
flat frigateBOT
Result:
37.015621187164
idle parrot
reef basin
how would i do it by hand in 100 secs ;-;
reef basin
CAT
idle parrot
Ohh i see
reef basin
JEE is usually more lenient with time limits
idle parrot
Good luck buddy 
safe radishBOT
idle parrot
Your welcome
reef basin
thank you <33333
idle parrot
safe radishBOT
Available help channel!
wicked night
Can anybody please help me solve for x
safe radishBOT
Can anybody please help me solve for x
proud hedge
i may be wrong, but don't you have to multiply by the conjugate to get rid of the radical on the right side
prime nacelle
cant u just square both sides
prime nacelle
yea..
proud hedge
o yes u can square both sides
wicked night
u would get 9 + x - 2 on the right
and 2x + 5 on the left
but thats not right
i dont know why ts not rght but its not
because x has 2 answers
proud hedge
sqrt?
wicked night
where
proud hedge
because once you remove a square root, you may need to add +/-
wicked night
+/- 2x + 5?
photomath solved it a really weird way and gott he right answer but i couldnt understand it
proud hedge
hm
wicked night
ohhhhh
prime nacelle
remember
prime nacelle
$(a+b)^2=a^2+2ab+b^2$
flat frigateBOT
Mothy
prime nacelle
(3 + root x-2)(3+ rootx-2)
mhmmhm
lean otter
I would do it exactly like photomath
wicked night
i just dont understand what they are doing
lean otter
what is your last line
wicked night
how do they get the 9+6 root(x-2) + x + 2
my last lline rn is
2x +5 = (3 + root(x-2))(3 + root(x-2))
lean otter
you need to simplify the right side
wicked night
how
lean otter
develop it
lean otter
(2-x)²=?
wicked night
Yeah (2-x)(2-x)
But when I foil and collect like terms
It’s wrong
Let me try again
And that doesn’t factor into the right x values
Oh wait I think ik where I made my mistake
Wait but
When u square
-6root(x-2)
How do u its its 36(x-2) and not 36x - 2
lean otter
-6 * root(x-2) * (-6)*root(x-2)
wicked night
Ohhhh so it’s like there are brackets when there’s a root
lean otter
yeah root is power 1/2
lean otter
sure
wicked night
.close
earnest trout
safe radishBOT
gaunt venture
LoL
gaunt venture
Wait
earnest trout
$8x + 10y=130$
flat frigateBOT
Zaid
earnest trout
Oh
safe radishBOT
@earnest trout Has your question been resolved?
thin bridge
did you try anything after this?
silk ruin
can someone help? thank you in advance
safe radishBOT
can someone help? thank you in advance
steep dove
okay, so first off use the definition of the set difference
steep dove
LMAO
toxic stratus
$\and$
steep dove
then use demorgan's
toxic stratus
hmmm
toxic stratus
i dont have it defined
steep dove
HA
steep dove
¯_(ツ)_/¯
steep dove
then use demorgan's
should be clear from there
toxic stratus
why not just write something like
flat frigateBOT
toxic stratus
he do be de morganin
steep dove
facts
silk ruin
can u help me to find my mistake i think i have wrong step or smth
steep dove
cant you just distribute the and over
toxic stratus
you mean the land*
steep dove
steep dove
federal government moment
safe radishBOT
@silk ruin Has your question been resolved?
silk ruin
cant you just distribute the and over
sorry i dont really understand can you show me the step?
toxic stratus
did you just unwind
steep dove
wait i might have wtf
silk ruin
may i know where is this from? I only can find this
flat frigateBOT
safe radishBOT
@silk ruin Has your question been resolved?
white umbra
it says "using boolean identities" so I don't think they want you to consider subsets/elements of the sets
white umbra
may i know where is this from? I only can find this
yeah that's correct, so what's B - A?
terse ether
$(\sqrt{2}+x)^5 - (\sqrt{2}-x)^5$
safe radishBOT
$(\sqrt{2}+x)^5 - (\sqrt{2}-x)^5$
flat frigateBOT
ahmed349
terse ether
I just wanna confirm this, the terms with even powers will be positive and the odd powers would be negative in the 2nd binomial, but the - in the middle will invert them, so the odd ones are positive and the even ones would be negative, so the negative terms in the 2nd binomial cancel out with the positives in the 1st, now we are left with the terms with odd powers, so basically the 2nd, 4th, 6th terms
Multiplied by 2
terse ether
Ah uh I wanted to do this with binomial theorem
safe radishBOT
safe radishBOT
Available help channel!
lean otter
If i have a limit where in a part of it i get infinity/infinity than the whole limit is undefined?
safe radishBOT
If i have a limit where in a part of it i get infinity/infinity than the whole l...
glass carbon
If i have a limit where in a part of it i get infinity/infinity than the whole l...
it depends on the limit, inf/inf is indeterminate form, but can give a result
lean otter
see the limit of x/x as x goes to infinity
the limit is 1 right?
Part of my limit is ln(infinity^2+7)/x-7
foggy salmon
theres l hopital
toxic stratus
there's also order hierarchy
steep dove
how can part of it be infinity?
are you applying the limit only to one specific thing
lean otter
and what is x
toxic stratus
projective plane 
steep dove
this is kinda awful not gonna lie front man sir
lean otter
Front?
steep dove
boss
toxic stratus
that's a lotta terms man
lean otter
Pls no
toxic stratus
first and last i think you can deal with individually
steep dove
i dont want to think about it either
toxic stratus
middle two you can do continuity
lean otter
Yes
toxic stratus
is the x in the arctan on the whole fraction?
lean otter
Wdym?
toxic stratus
you need to acquire yourself some auto resizing brackets man
lean otter
oh it's root of 7 times x
toxic stratus
oh
flat frigateBOT
lean otter
Yes
steep dove
ok cool
toxic stratus
well this has taken an unexpected turn
steep dove
it really doesnt look like that in ur pic 😂
steep dove
gigatroll
toxic stratus
okay so that's easy
lean otter
I said sorry hehe
steep dove
use that
flat frigateBOT
lean otter
What about the first term
steep dove
doesnt matter how the x is scaled as long as its positive
toxic stratus
the first term is easy
it's easy
steep dove
i think u can lhopital that
lean otter
Oh so
toxic stratus
lim = easy
lean otter
I can lhopital the first term
steep dove
answer = easy
lean otter
And dont have to lhopital othee terms?
toxic stratus
you should at least know growth of log is slower than linear
then the first term is just 0
steep dove
you should at least know growth of log is slower than linear
l'hopital without l'hopital 🤣
toxic stratus
lhopital is too much
lean otter
Thanks guys
steep dove
well i dont think you need to in this case because since the limits definitely exist (1st, last, 2nd+3rd)
you can split them up
toxic stratus
do it all together 
steep dove
wolfram enters
toxic stratus
no, appreciate yourself
lean otter
??
steep dove
nah dw thats the point of this server
toxic stratus
LOL
steep dove
🤣
toxic stratus
jk just messin w ya
steep dove
LOL
toxic stratus
lean otter
I don't even understand what he was trying to say lol
Okay okay i'll stop
See you later and thanks
./close
steep dove
no slash
lean otter
/close