help-23

[safe radish]

@stone nest Has your question been resolved?

[light shoal]

any thoughts about how to approach this?

[stone nest]

Hmm I wanted to make a chart and add all the percentages onto the chart and then add/subtract to find the answer

[light shoal]

do you know any formulas that might help?

[stone nest]

The only formulas I know about percentages is percent increase and percent decrease

[light shoal]

what's the context, is this a probability class?

[normal shard]

is the answer 40%?

[stone nest]

Yeah but why?

I need to show work though

[normal shard]

okay i just wanted to confirm

so i said we have 100 people

3 of them didnt vote for any

so 97 people voted for either A or B or both

65 voted A, 72 voted B so 65+72 = 137

how many votes are extra?

137-97

40

that means 40 people voted both

or 40% (because i used 100 people)

[stone nest]

Thanks

.close

[safe radish]

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[lean otter]

heyy, im kind of brushing up with equivalence classes and cosets of subgroups

[lean otter]

and im confused by this

Let (G, •) be a group, and H a subgroup of G. Let g₁, g₂ ∈ G be elements of the group.

g₁~ g₂⇔g₂⁻¹g₁ ∈ H

so next the guy in the video starts provinv that it is indeed an equivalence relation

so to prove that it satisfies the symmetric property, he starts with

wait actually im better off sending a screenshot lol

so my question is

how does he get that g₁~ g₂ is the same thing as g₂⁻¹g₁

[light shoal]

isn't that how he defines ~

[solar hazel]

that's how the relation is defined

[lean otter]

OH

[light shoal]

but you omitted a bit

g₁~ g₂ is the same as g₂⁻¹g₁ ∈ H

which in turn is equivalent to saying that g₁ and g₂ are in the same coset of H

[lean otter]

ohh

makes sense now

thanks

.close

[safe radish]

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[white field]

how do I make a sign scheme from a derivate function?

[white field]

here's an example

I know how to find out whether it's + or -, ascending or descending and whether it's maximum or a minimum but I don't remember how to find the zeros of the function

[spiral crescent]

The zeroes of f'(x)?

[white field]

yes

[spiral crescent]

Just set f'(x)=0, you should get two solutions

[white field]

so just use the quadratic formula?

[spiral crescent]

Or you could factor, whatever takes less time

[white field]

alright

if I have a cubic function or higher, and I can't factor further, do I still use the quadratic formula

I haven't done maths in a while

[safe radish]

@white field Has your question been resolved?

[white field]

and how do I detect inflection points

[safe radish]

@white field Has your question been resolved?

[lean otter]

you gotta take the first derivative and then find the points where the derivative is equal to 0

oh wait nvm

you gotta look for the intervals where the second derivative is positive or negative iirc

[safe radish]

@white field Has your question been resolved?

[safe radish]

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[void patio]

to find PQ do I have to add 1 7/8 + 1 7/8

and for the segment Bisector wouldn't it just be MN

[safe radish]

@void patio Has your question been resolved?

[void patio]

<@&286206848099549185>

[hardy wedge]

on 1., that's right

since PM and MQ are given to be equal

[void patio]

alr

so for example

would the bisector

I can just say MN is the bisector

[hardy wedge]

since it's a line that is cutting the segment in half

[void patio]

so if it were to come up on a test

thats all id have to say?

"segment besctor is MN"

[hardy wedge]

MN is a segment bisector since it crosses the midpoint of segment PQ, thus dividing it into two segments equal in length

[void patio]

ik

[hardy wedge]

yeye

[void patio]

so like yeah?

[hardy wedge]

if they ask you to justify, give a short explanation on why

[void patio]

ok

also for # 2

isnt the segment bisector M

and PQ is 4 4/7

bc PM +MQ =PQ

[hardy wedge]

yup

and PM = MQ

[void patio]

alrrr

creeper

i got a question

@hardy wedge

[hardy wedge]

?

[void patio]

can I add u so I can close this?

cause ima need to ask sum else later

[hardy wedge]

I suggest just opening another ticket when you need it

feel free to ping me then

[void patio]

alr thanks

[hardy wedge]

(if I'm online)

[void patio]

@hardy wedge

[hardy wedge]

hello

[void patio]

How do I do a question like this

[hardy wedge]

is it asking for the value of p?

[void patio]

yeah I assume

[hardy wedge]

okay

so, what is preventing you from getting the value of p, i.e: what do you need to get rid of

[hardy wedge]

yes yes

so p isn't alone

there is a +3.9

how do we get rid of it, to isolate p

$p + 3.9 <-- (this is bothering us) = -6.5$

[flat frigate]

fedeCreeper

[hardy wedge]

hi?

[void patio]

im looking

lol

[hardy wedge]

oh ok lol

[void patio]

idk

[hardy wedge]

imagine a scale

where on one side we have p + 3.9

and on the other we have -6.5

now since they are equal, they have the same amount, so the scale must be balanced, right?

if we take out the 3.9 from p (by substracting), we have a problem

the -6.5 becomes heavier than the other side

so we should substract from the other side too so we conserve the equality

like this:

$p+3.9-3.9=-6.5-3.9$

[flat frigate]

fedeCreeper

[hardy wedge]

so we end up with
$p = -10.4$

[flat frigate]

fedeCreeper

[hardy wedge]

do you have another exercise you could try?

@void patio

[void patio]

sorry I was doing something

let me read rq

let me try it out rq

p = 10.4

[hardy wedge]

almost

remember it's -6.5 - 3.9

wait

no

[void patio]

im right

[hardy wedge]

lol

no you're not

[void patio]

💀

how

[hardy wedge]

let me show you

so

$p+3.9=-6.5$

[flat frigate]

fedeCreeper

[hardy wedge]

right?

so to get rid of the 3.9, we substract 3.9 like we did earlier

[void patio]

$-6.5 = p +3.9$

[hardy wedge]

$p+3.9-3.0=-6.5-3.9$

[flat frigate]

fedeCreeper

anthonyr2

[hardy wedge]

imagine the 3.0 is 3.9

typing error

yup!

[void patio]

wouldn't you add 6.5 on both sides

to get rid of -6.5

[hardy wedge]

but then you get $p+10.4=0$

[flat frigate]

fedeCreeper

[void patio]

3.9 + 6.5 = 10.4

bring down p

[hardy wedge]

so you substract 10.4 from both sides

[void patio]

so p = 19.4

[hardy wedge]

$-6.5 = p+3.9$ then
$-6.5-3.9=p+3.9-3.9$ then
$-6.5-3.9=p$ then
$-10.4=p$ then

[flat frigate]

fedeCreeper

[hardy wedge]

by getting rid of the -6.5, you get p+10.4 = 0

so to solve that, you substract 10.4

and get p = -10.4

and when you check it, it should work

-10.4+3.9 is indeed -6.5

so the equality is true

if you do 10.4+3.9, you don't get -6.5

[void patio]

been tryna comprehend this

[hardy wedge]

okay

perhaps we can try another one

for example $x+3=5$

[flat frigate]

fedeCreeper

[hardy wedge]

how would you solve that algebraically?

[void patio]

🤓

uhhh

get x by itself?

[hardy wedge]

yes!

we need to isolate x

but how?

[void patio]

subtract 5 from both sides?

[hardy wedge]

how would the equality end up?

[void patio]

easy term plz

im not smart 💀

[hardy wedge]

how would the equation look like

we have x + 3 - 5 = 5 - 5

right?

if we substract, what do we get?

[void patio]

x= -2?

[hardy wedge]

not quite

think of it like a scale

we have x+3 on one side and 5 on the other side

x+3 5

if we take out the 3, x is left alone right?

but if we take out 3, now 5 is heavier

so we need to take out 3 from 5 as well

so that they weigh the same

so x+3-3 = 5-3

x=2

our goal when solving equations should be getting rid of anything surrounding x (isolate it), and make sure that anything on the other side remains equal

so that when we get x by itself, we know that it will be equal to whatever we get on the other side

does that make sense?

[safe radish]

@void patio Has your question been resolved?

[safe radish]

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[novel magnet]

i dont understand how the right side was simplified

[fair dagger]

First partial integration

then just fractions

[novel magnet]

ye i dont understand the fraction part

oh wait

oh i get it XD

[fair dagger]

👀

I think you must have been massively overthinking it.

[novel magnet]

ye lol

whaaat

how did the denom become 49

[fair dagger]

7 * 7 = 49

you just gotta integrate the power

[novel magnet]

isnt the power rule just x^n+1/n+1

ohhh

[fair dagger]

yeah

[novel magnet]

ok

[fair dagger]

and n = 6

here you get more 7

[novel magnet]

man i googled power rule and th pic i looked at missed some info

ya

alright

.close

[safe radish]

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[neon bear]

j

[fair dagger]

Ask your math question in a clear, concise manner.

[neon bear]

how do i prove

the linear transformation of T

show that T is a linear transformation

[fair dagger]

Get this definition and verify both substatements about it.

[neon bear]

so like...

what definitions

[fair dagger]

linear transformation

[neon bear]

whats the next step

j

[fair dagger]

Now just compute this and see that is is true

[neon bear]

how do i compute

what do i compute

[fair dagger]

this with your T

[neon bear]

give me a example

[fair dagger]

Compute aT(x) + bT(y)

[neon bear]

i am unsure of how to do that

thats why i am stuck

j

[fair dagger]

Why do you keep saying j? 👀

Well you start by plugging in T and you use computation rules of inner procudt

[neon bear]

ah

i see

[fair dagger]

such as (x + y) * z = x * z + y*z

[neon bear]

a( (x . u ) u) + b ((y . u)u)

right?

[fair dagger]

ye

[neon bear]

ohhhhhh

a( (x . u ) u) + b ((y . u)u) = (ax . u + by.u)u

[fair dagger]

yeah

[neon bear]

thank you so much

https://tenor.com/view/cute-aww-gif-22471511

[fair dagger]

lol

[safe radish]

@neon bear Has your question been resolved?

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[safe radish]

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[keen pebble]

We need some help

[keen pebble]

With a homework like it doesnt make sense

not at the beginning and at the end

There are equations like y= 0,5f(x) -4

And we should like literally assign that to 5 different graphs

But they dont make any sense

Not in geogebra

not in the calculator with table function

Im loosing my mind over this

Here

@ me pls when someone answer this because i have time til wednesday

i dont really like wanna just get through this work i wanna learn that stuff but this one really makes no sense at all to me

ty

[tall fern]

I probably can’t help but I would translate to English

[keen pebble]

What do you mean

[tall fern]

You textbook isn’t in English

[keen pebble]

Ik

Im german xd

[tall fern]

This is an English discord so I would translate the problem to English

[keen pebble]

But i can write and talk english to a certain way

[keen pebble]

the problem is just equations

Nothing to read

It says like "Assign these equations to these graphs"

[lean otter]

f(x) is the blue curve. This question is asking you to think about transformations of f, I assume the transformations are explained in the table above.

[keen pebble]

WOW

LIKE OMG

But still

they dont make any sens

[lean otter]

For example, for part 5, y=f(-x) is the reflection of f(x) along the y axis (last thing in the table). So looking at the picture, which thing is the reflection of f

[keen pebble]

C

[lean otter]

yup

[keen pebble]

Literally the only one

[lean otter]

now how about part 2, lookup that transformation in the table and see if you can figure out which curve it corresponds to

[keen pebble]

I would say A

Cause its like the half of f

1f(x) is the same as f(x)

2f(x) is like it would get higher

isnt it?

[lean otter]

yup exactly

[keen pebble]

DAIMN

IM CRACKED

But the 3rd and 4th

These are the real hard ones wich makes the least sense

[lean otter]

for the third, first think about f(x+7). It's not drawn there, but can you try describing this transformation?

[keen pebble]

I asume that it is D because its the only negative f(x) one

Wait

Its not drawn there?

And i would say that the 4th one is b

Because its like postponed

but its still looks like the regular f(x)

[lean otter]

yeah thats correct

[lean otter]

I was talking about without the minus sign

[keen pebble]

Yea but the +7 makes no sense at all

[keen pebble]

ah

[lean otter]

f(x+7) is a shift of f to the left by 7 units

[keen pebble]

and the deepest point of that is 5 or what?

is that why the -5 is there?

But that would mean you only look for the minima and maxima

wait nvm

but 4 is confusing again

there is like -5

that is probably for the point P(5/1)

but the -1?

[lean otter]

f(x-5) is a shift of f to the left by -5 (aka shift to the right by 5)

[keen pebble]

But why to the right here?

is it like the opposite

[lean otter]

because -5 to the left means 5 in the opposite direction (right)

[lean otter]

ye

[keen pebble]

AH

So

1. is E
2. is A
3. is D
4. is B
5. is C

[lean otter]

yup perfect 👍

[keen pebble]

I love you

Literally can i hire you as my personal math coach

Even tho problems like that are ez af for you

Probably

Thanks man

Like fr

You saved my motivation for maths lmao

[lean otter]

lol, yw :)

[keen pebble]

whats yw

[lean otter]

you're welcome

[keen pebble]

Your welocme

Yeeeee

Thanks man

[lean otter]

feel free to ask more questions here :D

[keen pebble]

Have a really gr8 day i hope you win the lottery tomorrow

Ngl

[lean otter]

lmao thanks

[keen pebble]

Are you like a maths prof or something like that? @lean otter

[lean otter]

nah

I think there are some profs here tho

[keen pebble]

But your really cracked at maths

man like fr

[lean otter]

i try my best

[keen pebble]

Nah bruv i love you for that

[safe radish]

@keen pebble Has your question been resolved?

[safe radish]

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[dire crypt]

how can i solve this integral

[tall bough]

apply logarithmic idenenejtitesitzs

identities

[plucky elk]

what lesson are you learning?

[dire crypt]

definate integration

[plucky elk]

the integrand doesn't have an elementary antiderivative

are you learning series?

[dire crypt]

series ?

[tall bough]

log(x)/(1+x²) ibp wont work?

,w integral of log(1+x)/(1+x²)

[dire crypt]

why's there a pi term in the options

[flat frigate]

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Requested by Gruba#1234

[tall bough]

bruh

[plucky elk]

this is worth trying @dire crypt

[tall bough]

integral of sqrt(tanx) is a baby compared to that

yes ibp will work 100%

[plucky elk]

https://math.stackexchange.com/questions/768332/liate-how-does-it-work

[dire crypt]

ohk ill try ibp

[tall bough]

but wait

how to solve this without taylors

quadrature?

[dire crypt]

for integral arctanx/1+x i should use ibp again?

[tall bough]

u have to do something else i think

[dire crypt]

i got the ans

.close

[safe radish]

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[tall bough]

,w integral of log(1+x)/(1+x²) from 0 to 1

[flat frigate]

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Requested by Gruba#1234

[safe radish]

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[summer coral]

How do you solve this

[summer coral]

I guess it has to be put in a matrix form??

Like with a vector Ui = (xi, yi)

[plucky elk]

What are you solving for

[summer coral]

x_i and y_i sorry

I want a formula that only depends on p

for x_i and y_i

If I build a vector U_i I have U_i = A x U_i+1 + B x U_1 + C

which i think is particulary clever

but i'm stuck there

[safe radish]

@summer coral Has your question been resolved?

[plucky elk]

you still haven't explained $x_{i+1}, y_{i+1}$ or $x_1$

[flat frigate]

riemann (eric tao for honorable)

[summer coral]

sorry?

they are sequences sorry

i don't know if that makes sense?

[plucky elk]

they're recursively defined?

are you given $y_1, x_1$?

[flat frigate]

riemann (eric tao for honorable)

[summer coral]

I'm not :/

[plucky elk]

maybe you should show the full problem

[summer coral]

yes! sorry I didn't explain it very well

we do know x_5 = 0 and y_5 = 0 though

i didn't think it'd help, but maybe it does?

---

Let me rephrase the whole problem:

We are trying to solve for x_i and y_i. i being between 0 and 5 (both included).

with x_5 and y_5 = 0
both recursively defined

not defined for i > 5

not defined for i < 0

[plucky elk]

nah just show the whole original question. don't type it

picture or screenshot is best

[summer coral]

well i'm trying to understand a cross validated post

lemme link it to you

https://stats.stackexchange.com/questions/253650/when-can-i-expect-to-get-5-heads-in-a-row-when-tossing-a-coin the first answer

He just says I solved the recurrence relation for general n.

But I'm slightly confused as to how he did it

[plucky elk]

did you learn the requisite material? markov chains etc

[summer coral]

Also I don't understand why this answer is different from this one:
https://math.stackexchange.com/questions/364038/expected-number-of-coin-tosses-to-get-five-consecutive-heads#:~:text=The sequence is 1%2C3,we get the answer%3A 62.

which is so much easier

[summer coral]

yes I know them but I didn't think we would need them? I understand how he infers the system of equation

[plucky elk]

It essentially constructs a Markov chain that has states (e.g., 3 consecutive heads), and transition probabilities for moving between states (e.g., a probability of 1−𝑝 of moving from 3 consecutive heads to 1 tail).

[summer coral]

yes, I understand that

[plucky elk]

did you write down the markov matrix? or draw the state diagram?
https://phys.libretexts.org/Bookshelves/Mathematical_Physics_and_Pedagogy/Computational_Physics_(Chong)/12%3A_Markov_Chains/12.01%3A_The_Simplest_Markov_Chain-_The_Coin-Flipping_Game

[summer coral]

This is how (except with p and 1-p) the 2 equations are obtained

[plucky elk]

yes i agree this is much simpler. just go with that solution if you understand it

[summer coral]

if I understand correctly

[summer coral]

Surely there is a reason why the other is explained right?

I can't find why though

[plucky elk]

lol no

[summer coral]

oh

lol

fair enough

[plucky elk]

there are many ways to do problems. just pick the solution that you best understand

[summer coral]

although i'm still interested in how this can be solved

[plucky elk]

this is not necessary anymore

[summer coral]

when you know the vecotr U_5

I mean

I still want to know how to solve closed form of sequences when the sequences are matrices defined recursively

if my sentence makes sense

[plucky elk]

https://www.math.ucdavis.edu/~gravner/MAT135B/materials/ch13.pdf

[safe radish]

@summer coral Has your question been resolved?

[plucky elk]

i think you need to rephrase your question more thoroughly. what are you trying to achieve with recursion? you say you know markov chains, but that's basically all you're doing

[summer coral]

mm i'm trying to find x_0 and y_0

I'm trying to go through the link you've solved but I think this is too advanced for me

I've written down the equation in matrix form (with the vector U_i = (x_i, y_i))

[plucky elk]

write the transition matrix

[summer coral]

A, B or C?

[summer coral]

from this*

A is
p 0
0 1-p

B is
0 1-p
p 0

C is

1
1

[plucky elk]

you should have $U_{i+1}$ on the left side and everything else on the right

[flat frigate]

riemann (eric tao for honorable)

[plucky elk]

follow this pattern
https://codeforces.com/blog/entry/79819

https://math.unm.edu/~jvassil/Recurrence Relations.pdf

[summer coral]

Oh yes my bad that makes more sense

It's quite late where I live but I'm going to look at this tomorrow morning. Thanks for the resources.

[safe radish]

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[eternal sparrow]

Hello, can anyone please check if I did this question correctly below?

[eternal sparrow]

Did I answer the question correctly?

Wdym

Yes

I don’t know the ratios of these angles?

[eternal sparrow]

Did I ??

<@&286206848099549185>

Thanks so much for checking

Could you please tell me the ratios of the 30-60-90 triangle?

So instead of x I just put 1 right?

[brave edge]

Yup you did

[eternal sparrow]

Thanks so much guys

[brave edge]

Yeah you just needed a confirmation lmao

Think about closing the channel please

[eternal sparrow]

.close

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[winter olive]

the formular is u=Q-W so why is it 60 +30 shouldnt it be 60 - 30

[safe radish]

@winter olive Has your question been resolved?

[winter olive]

<@&286206848099549185>

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@winter olive Has your question been resolved?

[winter olive]

please can i have some help

[obtuse plover]

Work on vs work by

This is physics btw

@winter olive

[winter olive]

i though i could ask pphysics here too

soz

[obtuse plover]

Change in internal energy = Heat + work done on

It’s fine

Work done on the system = (-) work done by the system

[obtuse plover]

it’s negative for work done by the system

That’s why they added

Work done on the system is added to heat to find delta U

[winter olive]

so when the syustem is poerforming work

then it is minus but when its absorbing its +

[obtuse plover]

iirc yes

[winter olive]

thanks

.close

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[onyx wolf]

I need someone to check my work if possible plz and thank you. the subject is discrete mathematics

[safe radish]

@onyx wolf Has your question been resolved?

[onyx wolf]

<@&286206848099549185>

somebody save me

[lean otter]

q5 should be A

and q6 should be B

rest looks fine i think

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[onyx wolf]

ohhh okay

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[obtuse plover]

believe so

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[mellow rune]

how would i prove there are no vertical asymptotes for this?

[crimson field]

Maybe write the function as a piecewise function and look at the left and right limits of g(x) goes to 2- and 2+.

[mellow rune]

i've already done that, do i just say that there is no VA cause x is defined at all vals

also, would there be a hole at x=2?

or is there none since x=2 has a defined value

[tame charm]

“x is defined at all vals”

[crimson field]

I think by vertical asymptote they mean it doesn't go to infinity or - infinity as x goes to 2.

[tame charm]

Do you mean f(x) is defined for all values of x? That would be false

f(2) is undefined

[mellow rune]

f(2)=4

?

if u change to a piecewise

[lean otter]

Oh yeah

[mellow rune]

wait nvm

cause on the graph

there aren't any values defined vals for x=2

so is that a VA or holes?

[crimson field]

Desmos shows me that the left and right limits are not the same.

[mellow rune]

yeah i know that

but is x=2 a VA or are there just holes

[crimson field]

Let's go to a definition of what a vertical asymptote is.

[mellow rune]

ah

so it's a hole?

[lean otter]

Yes

[mellow rune]

can i ask another question?

[crimson field]

One definition I find says that the graph approaches the asymptote but the other says the graph contains a vertical line which is not part of it. I think you need to know what definition you're meant to use.

[mellow rune]

how would i approach this type of problem?

[lean otter]

Put x=-pi/2 -h

Where h tends to zero

So it would be cot(pi -2h)

[mellow rune]

i mean can i split it up

into

[lean otter]

Whdym

[mellow rune]

-2 * lim cot2x?

[lean otter]

Yes ofc

[mellow rune]

then how would u take the lim of cot 2x

[lean otter]

Just see what I said

What's cot(pi-2h)

Or cot(pi-theta)

[mellow rune]

is there a different way to do this?

cause i can't learn this method this close to a test

ik it's -cotx

but this is really awkward to do

.close

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[open urchin]

what is the problem asking? how do i fill out this chart?

[open urchin]

please @ when reply!

[fossil shell]

isn’t it self explanatory?

@open urchin

[open urchin]

no, i’m in seventh grade lol and i’m asking cause i’m confused as to what this even means

i don’t understand how to fill the chart out

it’s my first week of school, my teacher just gave us this worksheet without explaining anything

[lean otter]

u calculate the area of a circle for ever radius given, put it in the form (radius, Area) and plot it in the coordinate system

[open urchin]

so i would multiply the number in the first column squared by pi?

and put that answer in the second column?

and then put the first columns number next to the second columns for the third columns answer?

[lean otter]

yes

[open urchin]

wouldn’t that give me a decimal though?

[lean otter]

u can just use pi or round it

[open urchin]

it’s super faint but i tried that and got decimals

[lean otter]

if u round it u do ≈ tho right

[open urchin]

oh okay

there isn’t a place to put ≈ though

it’s kinda just a chart

i swear i’m not this stupid i’m just lost

[lean otter]

yea just put it in front so u know

[open urchin]

tysm

[lean otter]

or use pi

or do 3.14...

[open urchin]

what do you@mean?

i’m using a calculator

[lean otter]

like 3pi

[open urchin]

can i keep this open? i’ll most likely have more questions soon 😭

wait

sorry

one last thing

i found to the nearest one?

[lean otter]

yess

hmm?

Oh it says round to the nearest whole number

didnt see that

so when u got 3.5 u write 4 and if u got 3.4 u write 3

[open urchin]

oh my god

i didn’t see that

i love you oh my god

thank you so much

you’ve SAVED me from my horrifying math teacher

[lean otter]

fhfh

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[toxic socket]

how to solve this

[foggy salmon]

so

uve the formula for an

so for a3

plug in n=3

n u shld get a value

i cant read the last one,

[toxic socket]

a6 = ?

the part im confused at is what will i do after i solved the 2n
----
n+1

how do i type it

2n/n+1

lmao

the answer is 6/4 right

or no

on A3 = ?

omg i thought its 10 mins

so it's 10 mins

im sorry

15*

help pls T_T <@&286206848099549185>

.close

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[vast obsidian]

<@&268886789983436800>

[safe radish]

@lean otter Has your question been resolved?

[plucky elk]

is this a test?

[safe radish]

@nocturne quartz Has your question been resolved?

[cedar rover]

profile picture

[safe radish]

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[lethal torrent]

could i have help with c?

[lethal torrent]

what i did was i first found the limit for f(x)

which is 8

then i'd make the limit approach 8 instead

would the answer just be dne?

<@&286206848099549185>

[safe radish]

@lethal torrent Has your question been resolved?

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@lethal torrent Has your question been resolved?

[plucky elk]

Correct

[lethal torrent]

okay thank you

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[lean otter]

This is really basic algebra 2 but im lost because of online schooling. Would this be correct? I think it is infinite solutions

[lean otter]

And idk how to get the and or or and if its infinite solutions or not

[stray socket]

Write it neater

I can't tell what you wrote lol

[lean otter]

Alr gimme a few

[lean otter]

^^

[stray socket]

All that lol

Was in a diff channel, someone beat me to it

[lean otter]

Lol thx how do i write the solution part the 0<_d<_10/3 and how do i tell if thats an and or or equatooom?

[stray socket]

Well it's inclusive

So just draw a closed-dot line segment from 0 to 10/3

[lean otter]

Yh i did and from 10/3 to 0 which determined it was infinite but like how do i know if its an and or or solution to determine if its infinite, one or no solution.

[stray socket]

Wdym and or

[lean otter]

An And or an Or solution because if both on the line are headed towards each other its a infinite solution if its greater than or equal to but its a normal one somution if its a and equation thats less than or equal to

[stray socket]

Oh

Your answers are closed so

It's and

[lean otter]

Anytime its closed its and? If not its or?

So would this be a no solution?

[lean otter]

^^

[stray socket]

I mean is it infinite for all values?

Then it's just infinite

[lean otter]

See like im confused how she got which was or

And and

[stray socket]

I don't understand why it's "or" either Ive been taught if it has 2 solutions then it's "and"

Since it's two different sets

[lean otter]

Florida frfr😭

[stray socket]

Florida 💀

[lean otter]

We have high standards but horrible teachers

Also

How would the solution be if its p<2 and p>2

@stray socket

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@lean otter Has your question been resolved?

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

@lean otter Has your question been resolved?

[foggy salmon]

p can be anything but 2 in R

[safe radish]

@lean otter Has your question been resolved?

[stray socket]

p≠2

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[white flower]

I need help figuring out when the 56 came from

[lean otter]

8= 40/5

40/5+16/5=56/5

[white flower]

huh

that was very quick

[lean otter]

Indeed

[white flower]

wait where did the 40 come from

all I have is the 4x/5 + 16/5 + 8

@lean otter

[lean otter]

$\frac{16}{5}+8=\frac{16}{5}+\frac{40}{5}=\frac{56}{5}$

[flat frigate]

Jin឵

[lean otter]

Like @lean otter said

[white flower]

oh you

cross multiply the 8 and the 5

[lean otter]

Yes

40/5 is the same as 8

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[lone grove]

Someone help me with this one

[tall bough]

,rotate

[tall bough]

lambda=dm/dV = > dm=lambda2pixdx => dm=(a+bx)2pixdx i guess

with dV=Adx=2 * pi * x* dx

[lone grove]

Huh where does dv come from? Lambda = dm/dx not dm/dv

[tall bough]

isnt mass density m/V

if it says dm/dx in your notes then its 10 times easier

[humble oracle]

That’s volumetric mass density, rho

[lone grove]

This rod is not 3 dimensional so volume can't come in place

[humble oracle]

This is linear mass density

[lone grove]

Yeah

oh I got it

[tall bough]

dm=lambdadx then

[lone grove]

Dm = lambdadx just put a+bx instead of lambda then integrate with limit 0 to l

[tall bough]

yes

[lone grove]

.close

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[zealous dawn]

How does this equal this

[whole acorn]

ok so

first of all

expand the (x - 3)^2

[zealous dawn]

I get the -2x^2 and the -18

I forget how the 12x gets there

[whole acorn]

expand the (x-3)^2 first

and tell me what you get

[zealous dawn]

x^2 +9

[worthy hemlock]

No

[whole acorn]

yeah no

[zealous dawn]

Maybe I forgot some algebra 1

[worthy hemlock]

$(a + b)^2 \neq a^2 + b^2$

[flat frigate]

dldh06

[worthy hemlock]

Do you know what 2^2 is equivalent to?

[zealous dawn]

4

[worthy hemlock]

What I mean is, exponents represent repeated multiplication

[zealous dawn]

Ok im not stupid i just missed a big chunk of algebra 1 a few years back

[worthy hemlock]

Meaning 2^2 = 2 * 2

[zealous dawn]

I know

[worthy hemlock]

How can you represent (x - 3)^2?

Using what I just stated?

[zealous dawn]

oh

its just

a^2 - 2ab +b^2

perfect square formula

[worthy hemlock]

Yes

[zealous dawn]

I told you i just forgot some algebra 1 lol

[worthy hemlock]

And what I was trying to show you, all you needed to do is distribute

[zealous dawn]

yea

x^2 -6x+9

then 2x^2 +12x -18

cause -2 distribute

yeah I just need to go refresh

on some basic algebra

thanks

.close

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[gentle geode]

this is what i tried

[low widget]

Simplify it.

[gentle geode]

?

[low widget]

Your steps are correct, you just need to simplify your answer to 1 + 5sqrt(3)i

(10/2 = 5.)

[low widget]

And minus.

Plus or minus.

[gentle geode]

like that?

[low widget]

That should be fine.

[gentle geode]

It says it’s wrong ;-; I’ve been trying to do this problem for like the last 10mins

[low widget]

...Take the i out of the square root?

[gentle geode]

it says in a +/- bi form

so i think the i is fine

maybe the square root?

[low widget]

Try putting the i right behind the sqrt. Might be formatting.

Not under the sqrt.

[gentle geode]

it says “error - invalid formerror - invalid form”

okay i’ll try that, it have to get a new problem tho

[low widget]

The i isn't under the square root for the answer. Or it shouldn't be correct if it is.

For example, the square root of -10 is not the square root of 10i.

It would be i * the square root of 10.

[gentle geode]

like this?

[low widget]

That should work.

Wait.

[gentle geode]

YES! Thank you

[low widget]

Okay, good.

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[reef basin]

Can someone tell me how to make the equation to solve the inequality?

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Please don't occupy multiple help channels.

[tardy mango]

.close

[storm valve]

bruh lol

[tardy mango]

I sense I am bad

[storm valve]

lol

idk

[tardy mango]

🤷‍♂️

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[bold aurora]

Can someone give me a hand with finding the surface area of a sphere using a surface integral?

[bold aurora]

Here is the idea I’ve been trying but I’m having trouble making it work

I know it might work better if I use spherical coordinates instead of cylindrical ones, but this has to work too, no?

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@bold aurora Has your question been resolved?

[bold aurora]

<@&286206848099549185>

Nvm, made it work. Small simplification I missed at the end

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[pseudo scroll]

$\lim_{t \to \infty^{+}} [2(1 - e^{-3t})]$

[flat frigate]

NEONPerseus

[pseudo scroll]

Full context; I got this equation from a physics problem

And I needed to find the "terminal speed"

So I thought it would be the value for the function as t approaches infinity

If this is right I got galaxy brain

But I haven't evaluated a limit like this before

So..?

[dire crypt]

its 2

lim t approaching inf, e^-t is 0

[pseudo scroll]

well that was fucking easy 😄

Thanks for your help anyways xd

.close

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[vestal rampart]

h

[vestal rampart]

@dire crypt need goku's help again

composition of function btw

[dire crypt]

why's it so blurry

[vestal rampart]

which part can't u see well

@dire crypt

[worthy hemlock]

In my opinion, everything

[vestal rampart]

@worthy hemlock how bow now

im sorry im quite stupid lads

bear w my cognitive thinkin

[dire crypt]

in 4th line its x^2-x

[vestal rampart]

where

[lean otter]

4th

[vestal rampart]

o

[safe radish]

@vestal rampart Has your question been resolved?

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[wary veldt]

Hi, how am I supposed to do this? Did implicit differentiation and still couldn’t get close to what it wanted me to prove

[wary veldt]

The end result was
3(y+1)^2 (dy/dx) = 2(x-2)

[safe radish]

@wary veldt Has your question been resolved?

[wary veldt]

<@&286206848099549185>

[charred crest]

did you try taking ln on both sides

[wary veldt]

Wasn’t taught that yet

[charred crest]

oh

well i recommend you learn it asap coz in sums like this where you need to do implicit differentiation on higher powers, it's gonna be useful

[safe radish]

@wary veldt Has your question been resolved?

[safe radish]

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[safe radish]

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Remember:
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[limpid pewter]

Hey, how do I find x?

[limpid pewter]

i dont have any other additional details

[foggy salmon]

lol

use a compass

[limpid pewter]

oh and i know the lenght of a bottom line

length of the "top" line

and i know that

this point is in the centre of the bottom line

[foggy salmon]

yea

i think u cant work with that info

just use a compass

[stray socket]

Inverse trig functions

Well

Hm

Not really

[foggy salmon]

length of lines dont tell u anything

[stray socket]

You know their slopes lol?

You can use vectors

[foggy salmon]

lol

thats totally

[stray socket]

Totally

[foggy salmon]

so much info from ive no other info

[stray socket]

(Just use a protractor)

[foggy salmon]

OH YES

[limpid pewter]

nah, can't do that

[stray socket]

Well it's impossible then

[limpid pewter]

👍

[blazing sable]

If you think of it conceptually, knowing the length of a line is like knowing it's end point is in a circle

[stray socket]

Not unless you know the distance from the top line to the right end of the horizontal line

[blazing sable]

Not very useful for an angle without further constraints

[stray socket]

Do you know the distance from the top of the sloped line to the rightmost end of the horizontal?

[limpid pewter]

nope

[stray socket]

Then you can't find x

[ivory gate]

you can

with a potractor

[limpid pewter]

yeah i said already that i cant use it

[ivory gate]

you can eyeball it

its about 30deb?

deg*

[stray socket]

Take a shot every time someone says "use a protractor"

[ivory gate]

27 i would say

[stray socket]

Driving will be fun

I swear

[muted ibex]

use a protractor

[stray socket]

That's another shot of vodka

[ivory gate]

do you want it in radians?

or gradians if ur french

[foggy salmon]

OH

CAN U USE A COMPASS

[ivory gate]

perhaps its PI/6 rad

[foggy salmon]

LOL

[ivory gate]

or 35grad

maybe you can make it a triangle

π
∫ln(1-2 αcosx+ α ²)dx for lαl ≥1
0

oops

if you know the sidelengths

you can turn it into a triangle and ols

solve

[muted ibex]

differentiate under the integral sign

[ivory gate]

the angles in a triangle sum up to 200 gradiens

[foggy salmon]

um

[ivory gate]

?

[muted ibex]

Albert Einstein right here