#help-19

1 messages · Page 225 of 1

short terrace
#

Good enough

woven stag
#

Professor X, how would you have phrased it?

short terrace
#

The first right should be a left

#

But you got the idea so I said good enough and didn't focus on the semantics much

woven stag
#

Okay, thanks.

#

Have a nice day!

#

.close

odd edgeBOT
#
Channel closed

Closed by @woven stag

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dense temple
#

hello

odd edgeBOT
dense temple
#

I have a very hard time understanding this part in calc 3

stoic cloud
#

Just for future reference, do you mind posting the image/question as your first message so the bot doesn’t pin greetings? This way, if the conversation continues for long, helpers don’t have to dig. catlove

dense temple
#

say i have a equation f(x,y,z) = (x^2)/3 + y^2 - z

#

at (3,0,3) the tangent plane is is z=2x-3

#

and at (3,0,3) the plane that contains the vector of the gradient is z = -x/2 + 9/2

short terrace
#

He can't

stoic cloud
short terrace
#

You'll get there

proven harbor
stoic cloud
proven harbor
#

@dense temple continue your question

dense temple
#

why is gradient

#

normal to tangent

#

like is 2d calc

#

its the same shit

#

look the black line is the gradient vector

#

how tf is that supposed to be the direction of max increase in z

quasi sparrow
#

are you asking why the gradient vector is normal to the tangent plane?

odd edgeBOT
#

@dense temple Has your question been resolved?

odd edgeBOT
#

@dense temple Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight jasper
odd edgeBOT
midnight jasper
#

Right now I have this triangle try to ignore the blue markings (sorry for them)

#

I used area of a triangle with height being 15 because 1/2bh where b is 4 and area is 30 so we know height is 15

#

I’m trying to solve for the slope between A and B

#

I figured to plug (x,15) into the f(x) equation but my issue is that I don’t want to use the quadratic formula and I feel like there’s another way to do this

odd edgeBOT
#

@midnight jasper Has your question been resolved?

odd edgeBOT
#

@midnight jasper Has your question been resolved?

midnight jasper
#

.close

odd edgeBOT
#
Channel closed

Closed by @midnight jasper

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
odd edgeBOT
mystic saffron
#

I lwk forgot how to do ts

wooden python
honest turtle
#

$$x^{-a}=\frac{1}{x^a}$$

clever fjordBOT
mystic saffron
wooden python
#

inappropriate comment!

#

<@&268886789983436800>

stoic cloud
#

!!!

#

My bad?

mystic saffron
#

honestly yeah I forgot how to get rid of that

mystic saffron
blazing shuttle
wooden python
mystic saffron
mystic saffron
wooden python
#

check out the yt channel The Organic Chemistry Tutor if you haven't already

#

it's better if you do that instead of having some random strangers yap at you

mystic saffron
#

alr

#

but after this I just flip right?

odd edgeBOT
#

@mystic saffron Has your question been resolved?

mystic saffron
#

no no one telling me how get rid of a the power to -3

#

I have 0 abstract thinking

clever fjordBOT
#

riemann

quasi sparrow
odd edgeBOT
#

@mystic saffron Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

safe pivot
#

hellooo, i need to calculate the volume of a sliced up spherical cap

small fulcrum
safe pivot
#

I need to calculate the volume between the planes

#

Preferably the surface area as well

#

and to do its as simply as possible

small fulcrum
#

have you learnt calculus?

safe pivot
small fulcrum
#

i see

safe pivot
#

i might be having the dunning kruger effect

#

how hard is this?

#

its for a math report, im modelling the shape of an object

small fulcrum
#

do you know how to get the volume of a sphere through integration?

safe pivot
#

many classmates are modelling through rotations

small fulcrum
#

because if ye then you can just use that, change its limits then be done for the vol b/w the blue planes

#

purple*

outer peak
#

@small fulcrum Space is as hot as my?

small fulcrum
#

xD

#

i put that there like a year or two ago and completely forgot

#

is the light blue plane also important?

safe pivot
#

its a spherical cap sliced up

#

let me show you what im trying to model

small fulcrum
#

oki

safe pivot
safe pivot
small fulcrum
#

OHHH

safe pivot
small fulcrum
#

okay gotcha

#

not much if you know how to find the vol of a sphere through integration

#

what's the radius?

safe pivot
#

like as someone who has such limited knowladge of calc. I think if i have the fucntion that models a spherical cap, i can just take the definite integral from x=-s to x=s, where s here is d/2 and boom volume, right??

safe pivot
small fulcrum
#

ye

#

for between the planes

safe pivot
small fulcrum
#

haha im not used to using online tools

#

and for the base, you'd use the same method

safe pivot
#

yooo, yeah yeah i think im getting it

small fulcrum
safe pivot
#

https://www.youtube.com/watch?v=nHC92J8rNZs im looking at this proof of voluem

Hi friends! This video is about deriving and finding the volume of a sphere by using integral calculus!

The formula for the volume of any shape is the definite integral from one end of the shape (let's call it "a") to the other end of the shape (let's call this "b"). So the integral is from a to b of the area of the cross-section (If you cut o...

▶ Play video
small fulcrum
#

should be fine

small fulcrum
#

but thats not math

#

more so physics

#

but thats always a less maths heavy option compared to this

#

use a testube or something with it to calculate the volume easily ig

safe pivot
small fulcrum
#

i see

#

teachers be like haha

small fulcrum
odd edgeBOT
#

@safe pivot Has your question been resolved?

safe pivot
#

problem is still not compeletly solved

#

okay so looking at proofs fro the volume of a spherical cap, tehy all do it with circular disc, easiest way obsiusly

#

but is there a way to do it with cirucalr sectors?

#

how would the area of a sector be calculated?

small fulcrum
#

use sectors and find it that way

safe pivot
small fulcrum
#

instead of using the entire circle

safe pivot
#

!solved

#

how do i solve it lol?

small fulcrum
odd edgeBOT
safe pivot
#

.close

odd edgeBOT
#
Channel closed

Closed by @safe pivot

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dry moon
odd edgeBOT
dry moon
#

whats the range guys?

odd edgeBOT
#

@dry moon Has your question been resolved?

odd edgeBOT
#

@dry moon Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed by @dry moon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

glacial grove
#

Hi guys what does /3 rad imply? I'm taking trigo and the given for our assignment by our prof are like this, does this mean π/3? Or something else?

stoic cloud
#

3 rad, or /3 rad?

#

Odds are your prof means 𝜋/3

glacial grove
stoic cloud
#

if it’s /3 rad then it’s most likely 𝜋/3 rad

glacial grove
stoic cloud
#

anything else? Otherwise, you can use .close. catlove

glacial grove
#

Last one question

stoic cloud
glacial grove
#

If the given is 2 rad, is it just 2 or 2π?

stoic cloud
#

2 rad

#

it’s just 2 rad

glacial grove
#

Ohhhh okok thanks very much

stoic cloud
#

if you are done, use .close catlove

glacial grove
#

.close

odd edgeBOT
#
Channel closed

Closed by @glacial grove

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

light hawk
odd edgeBOT
light hawk
#

Here's what ive done so far:

#

im not sure if what i have is on the right track, but im struggling to manipulate LHS to progress

odd edgeBOT
#

@light hawk Has your question been resolved?

light hawk
#

<@&286206848099549185>

quasi sparrow
#

just expand this using the entries of z, v, and D

#

try to prove it for just n=2

odd edgeBOT
#

@light hawk Has your question been resolved?

light hawk
odd edgeBOT
#
Channel closed

Closed by @light hawk

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

paper sentinel
#

i have a doubt

odd edgeBOT
novel abyss
#

me too

paper sentinel
#

The answer is 16N, i solved it in a way

#

but the issue is if I apply 16N of force, the friction on B is 8N at its maximum, the reaction of the friction force from B is the driving force for A, the max value of friction of A is 2N, so the net force on A is 6N, so wouldn't A fall off if it keeps moving?

#

ik its basic stuff but has eaten up my brain.........

odd edgeBOT
#

@paper sentinel Has your question been resolved?

odd edgeBOT
#

@paper sentinel Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stray knot
#

Let E be a non empty subset of R. Prove that diam(E)= sup E-inf E . I took a bounded set E and from completeness property i said a = sup and b = inf.... i am into the idea of diam( E closure )= diam (E) and intuitively its known that a\in closure of E and b also but i dont get how should i write it

stray knot
#

.close

odd edgeBOT
#
Channel closed

Closed by @stray knot

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

blissful falcon
#

I got to a(x-9)/x-3

odd edgeBOT
vernal yacht
#

,rccw

clever fjordBOT
vernal yacht
lilac sandal
#

put the value of x as 3 as we are checking in the neighborhood of 3, soo
you will get an equation
then you can differentiate the two parts of f(x) to get the other equation
2 equations and two things to find, easy calculation forward

blissful falcon
#

Yes, that's what I did but I got stuck when I tried to simplify

unkempt lichen
#

show your work, please

lilac sandal
blissful falcon
#

Im confused?

lilac sandal
#

what will you get when you plugin 3 in the first part

#

( checking continuity first of all)

blissful falcon
#

3a+b?

lilac sandal
#

right
and what will you get when you plug it in second part

#

x = 3

blissful falcon
#

Yes

lilac sandal
#

you'll get 9 right ?

blissful falcon
#

Yes

lilac sandal
#

for continuity the value of all the part in neighbor of 3 should be equal so
so 3a + b = 9
this is the first equation

blissful falcon
#

Wait I got it now

lilac sandal
#

now we're done with the continuity of the function
now move on to differentiability
differentiate the first and second part then plugin the value of x ( that is 3)
and then you have another equation

lilac sandal
blissful falcon
#

Does differentiable actually mean

narrow crypt
#

for single var calc purpose, derivative exists there

blissful falcon
#

When finding multiple derivatives i just keep plugging in the previous derivative right? What is this even used for

narrow crypt
#

usually

#

depends on the case

#

multiple derivative is used to find rate of rate of rate of ... something

unkempt lichen
#

acceleration is the best example

#

acceleration is the derivative of velocity, but velocity is itself the derivative of position/displacement

#

this makes acceleration the second derivative of position/displacement

blissful falcon
#

Im lowkey bad at factoring help pls

unkempt lichen
#

one quick look confirms that you have one very prominent common factor here

#

(amongst the remaining terms)

#

that being said, there is something wrong with this expansion. there is a notable lack of $t^2 h$ terms.

clever fjordBOT
#

fox(x, y); ∂(fox)/∂x (Flower)

blissful falcon
#

?? Idk what im doing

unkempt lichen
#

this looks more correct

#

now, your only term that doesn't have a h is balanced out by the -t^3 at the end

#

so you should be able to tell what factor is common to the remaining terms

odd edgeBOT
#

@blissful falcon Has your question been resolved?

blissful falcon
#

Okay thank you everyone

#

.close

odd edgeBOT
#
Channel closed

Closed by @blissful falcon

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal yacht
#

. @vernal garnet post here

vernal garnet
#

Why there is adding root3 in 6 and root3

vernal garnet
#

Why there is adding root3 in 6 and root3

lethal spoke
odd adder
odd edgeBOT
# vernal garnet Why there is adding root3 in 6 and root3
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
#

@vernal garnet Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shrewd trellis
odd edgeBOT
shrewd trellis
#

how do I find derivatives of exponetial fractions?

acoustic nexus
#

That's a bad crop bmo_pog

shrewd trellis
frank tide
shrewd trellis
#

Im trying to solve d

woeful briar
shrewd trellis
#

I know

#

but

#

how can i do that

dawn scarab
shrewd trellis
#

yeah

#

what I tried is pulling 2 at the numerator

#

so it becomes

#

2^-1

#

However, I dont think thats valid since theres no x

dawn scarab
#

what makes you think that

shrewd trellis
#

2^-1

#

is that valid?

woeful briar
#

Yes

dawn scarab
#

That is indeed what 1/2 equals yes

shrewd trellis
#

ah right

#

and then i just apply the power rule?

dawn scarab
#

noo, notice how it‘s not x to some power, it‘s e^x

#

so you use the "formula" for derivative of e^x

#

do you remember that?

shrewd trellis
#

yea

#

its e^x

#

but it was f(x)=some constant * e^x

dawn scarab
#

Right. And recall that you can move constants out of the derivative if they‘re multiplying

#

ie $\dv{x}\left(a\cdot f(x)\right) = a\cdot\dv{x}f(x)$

clever fjordBOT
shrewd trellis
#

ohhh I think i got it right

dawn scarab
#

Well, right up until the second to last step you were fine

frank tide
#

where did you get this guy from?

dawn scarab
#

probably thought e^(-x) = 1/e^x (which is true) but they combined the fractions improperly

shrewd trellis
#

The E is raised to a negative X

shrewd trellis
#

So I brought it in the denominator

frank tide
#

you combined the fractions improperly

tacit wasp
clever fjordBOT
#

Alberto Z.

tacit wasp
shrewd trellis
dawn scarab
frank tide
tacit wasp
frank tide
#

the "flipping the negative x to the denominator"

#

only applies when there's no addition or substraction

dawn scarab
#

h, you could have stopped one step before that, you were done

#

You just had to show it was = to f(x)

shrewd trellis
dawn scarab
#

yeah. You did what was asked

shrewd trellis
#

or it could be e^x/2 - 1/(2e^x)

dawn scarab
#

I mean, they are equal, but you wanted to show that f''(x) = f(x), so just stop when it looks like f(x) catthumbsup

shrewd trellis
#

also if f'(x)>0 for exponentials

#

does it mean it will rise to the right?

#

if f'(x) < 0, then it will dip to the right

dawn scarab
#

yes

#

proper words for that are increasing and decreasing if you care.

shrewd trellis
#

the confusing part is, I dont know how to graph this

#

I could look at e^x

#

and apply transofrmations

#

but man, this is a tricky one

dawn scarab
#

oh they‘re asking you to sketch this. Interesting. I‘m not sure how to intuitively find this. You could plug a few values in I guess and sketch from that

shrewd trellis
#

I want to know the best method

frigid canopy
shrewd trellis
#

this is an exponential

#

whats a hyperbolic trig function

dawn scarab
#

wai, not the time for that opencry

shrewd trellis
dawn scarab
#

I think you messed up with negative values

#

I suggest using the $\frac{e^x-e^{-x}}{2}$ form for your calculations as it‘s less calculator error prone imo

clever fjordBOT
shrewd trellis
#

I used desmos calc

dawn scarab
#

Grmmgngo

#

Sorry, i had anothee function in mind, you‘re right i think

shrewd trellis
#

this is defintely an incorrevt sketch

dawn scarab
#

Yours is a bit yeah. The left side

#

One way to know that the function is always increasing is looking at f'(x). It‘s always positive, so f(x) is always increasing

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

shrewd trellis
#

Ill come back to it

#

.close

odd edgeBOT
#
Channel closed

Closed by @shrewd trellis

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

prime falcon
#

Yo guys
I want an An alternative to stupid chatgpt

unkempt lichen
#

why do you think this server exists?

stoic cloud
#

OH WAIT

#

HE’S NOT ASKING FOR ANOTHER AI

#

IM STUPID

tepid pelican
stoic cloud
prime falcon
stoic cloud
unkempt lichen
odd edgeBOT
# prime falcon I don't want make you tired 😇

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

stoic cloud
#

they’re all dumb

prime falcon
#

Ok then i have question

stoic cloud
#

post it an let a helpful pin it

acoustic nexus
prime falcon
#

I want to find the solution of
|x+2|>|3x+5|
To find the solution we need to assume that predicate is true right?

plucky eagle
#

what predicate?

prime falcon
#

P(x): |x+2|>|3x+5|

plucky eagle
#

I don't know why you're bringing logic into an algebra question, but sure I guess?

unkempt lichen
#

!original

odd edgeBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

prime falcon
unkempt lichen
#

when I use that command, I'm usually asking for a picture of the question

prime falcon
#

Just find x

stoic cloud
#

…picture or screenshot is best.

#

we need more context.

plucky eagle
# prime falcon Gpt said no

then what the hell are we supposed to do with the fact that GPT said no? said no to what? what was the original context of the question?

#

and what did you prompt GPT with?

prime falcon
#

We assume this inequality to be true?

plucky eagle
#

we want the values of x that makes it true

#

of course this inequality is not true for literally every x (just try x = 1)

prime falcon
plucky eagle
#

in a way yes, I suppose? you can keep the inequality sign and suppose that it's true, and if you get a contradiction later, then you can conclude that no value of x makes the inequality true

#

(assuming you didn't bomb the algebra)

prime falcon
plucky eagle
#

I don't like the concept of "assuming it as true", but yes, I suppose

prime falcon
plucky eagle
#

I won't say it's entirely incorrect as per how I think you are viewing it. I just won't even think of this as a logical statement

prime falcon
#

Explain please

plucky eagle
#

or rather, I won't be thinking of truthiness when it comes to solving inequalities, because that's unnecessary

#

I mean, how do you solve an equation?

#

if I have an equation, say, x + 5 = 4

#

how would you solve it?

prime falcon
#

Using connectors

plucky eagle
#

...what are "connectors"?

prime falcon
#

x+5=4 => x=5-4

plucky eagle
#

not sure again why logic is coming into algebra, but sure

#

but you have to make this implicit assumption that the equation you started with is true in the first place

prime falcon
plucky eagle
#

and that's a universal assumption across algebra

#

if you started with a "false" equation then what's the point

prime falcon
#

No sense

plucky eagle
prime falcon
#

The same with inequality?

plucky eagle
#

the same with everything that you want to solve for. what's the point of solving for a known false statement? you know it's false!

prime falcon
plucky eagle
#

sure. abstract algebra it is then. overcomplicating regular algebra problems is still not my recommendation
(not gonna say you can't do it though)

prime falcon
#

Where do you think I can use logic?

plucky eagle
#

in proofs

#

(and, well, logic itself of course)

prime falcon
plucky eagle
#

I never said your original question was a proof

#

that's why I recommended against using logical concepts here

#

your original question was a simple algebra question

prime falcon
plucky eagle
#

show your work then

jaunty hollow
#

so what seems to be the problem here?

plucky eagle
#

also, you don't have to ping with every reply

prime falcon
plucky eagle
#

I don't know why that > 0 is there from the start, and I presume that interval is French notation for (-7/4, -3/2)
if my presumption is correct, your answer is as well, but the right side of line 2 is a clusterfuck and I can't see most of the things towards the end

prime falcon
plucky eagle
#

also, if you want to use $\Rightarrow$ to denote a new step, that's a good thing, but make sure each $\Rightarrow$ is on a new line

prime falcon
#

Look i know that my solution right

clever fjordBOT
#

Tairin

prime falcon
#

But logically, is that true?

plucky eagle
#

in this case, you're not looking for logical truth. you're looking to see if the steps are algebraically correct

#

yes, the steps are indeed algebraically correct, except for that > 0 that has plagued the first three steps

prime falcon
#

Well keeping thinking about this makes me confused

#

I know it's a wrong way of thinking, but for me it's the way to understand mathematical steps and if they're right.

#

Like i said mathematics concepts all built as logic

plucky eagle
#

if that's how you wish to view algebra, sure I guess.

prime falcon
signal yacht
signal yacht
signal yacht
prime falcon
#

How it doesnt give a fuck

stray arch
#

this logic is good to learn before you really dive into proofs, since your different proof strategies rely on understanding basic logic (and doing a proof is just a series of steps)

signal yacht
#

writing stuff like this is just obtuse and weird for solving an inequality

#

and if you wanna do higher math then you should learn the basics therein first

graceful viper
#

i think the op is just trying to understand the hypothesis of the theorems disguised in logic which isnt wrong at all

stray arch
#

personally i think you should once you pick up basic logic, start looking at set theory and writing the basic proofs there

prime falcon
#

I want to know what happens logically

graceful viper
graceful viper
#

now suppose the question was if |x+2| > |3x+5| then show that
|x+2| +3 > |3x+5| + 2

then u do assume that the predicate (the original inequality) is true and prove the next statement

prime falcon
#

Which we need to assume P to be true

graceful viper
#

yeah if P(x) is the original inequality and Q(x) is the following statement then u'd want to prove P(x) -> Q(x) for all x in domain

prime falcon
#

.close

odd edgeBOT
#
Channel closed

Closed by @prime falcon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

magic dome
#

why am I able to scale them like this?
My calculator and answer just say 2, 6, 1
when doing rref

magic dome
#

Process:

#

Why does the answer simplify it?
But I got that 1 a is -38/17 think

late dust
#

Can you post the original question as well?

magic dome
#

Linear depedence and Linear Independence of Vectors

Express vector t as a linear combination of the vectors u, v , and w.

  1. $\vec{t} = (0,0,19) , \vec{u} = (1,4,3), \vec{v} = (-1,-2,2), \vec{w} = (4,4,1)$
#

I wrote this as see image to start

clever fjordBOT
#

smeagol

magic dome
#

Since
$a \vec u + b \vec v + c \vec w = \vec t$

clever fjordBOT
#

smeagol

magic dome
#

can be a system of linear equations

#

since a u.x + b v.x + c w.x = t.x
etc.

stray arch
#

oh your mistake is on the 2nd step

#

you said 2 - 3*(-1) = -1 when it's 5

#

one thing i'd really recommend doing out of habit is saying where your reduction is going since then it's harder to follow

magic dome
stray arch
#

no on R3 - 3R1

magic dome
#

ooh

stray arch
#

you should write this as R3 - 3R1 -> R3 i think

#

like it's just easier for someone else reading it to follow, they don't have to look at the resulting matrix to figure out where you're sending it

#

and if you're reading your own work later on

magic dome
#

gotcha

late dust
#

Yeah, even if it seems obvious to you that R3 - 3R1 is working on R3, it's not good notation

magic dome
#

thank you!

stray arch
#

especially if you're doing multiple steps at one time like the first one

late dust
#

If you know a bit of programming, you might have encountered a -= operator; R3 -= 3R1 would be ok assuming the reader knows about that symbol

magic dome
#

I prefer that over
R3 = R3 + R1
R3 += R1 (better imo)

late dust
#

Right

#

It's rather uncommon in maths though

magic dome
#

My teacher did it confusing to me where he lined them up in the same row

stray arch
magic dome
#

like this

#

I prefer writing R3 += 3R1 than the :

late dust
#

Oh yeah that's kinda ugly

stray arch
#

yea that's um

#

not ideal

magic dome
#

Thank you both for advice, I gotta eat lunch now -- I'll redo the second half in a bit

#

.close

odd edgeBOT
#
Channel closed

Closed by @magic dome

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fast bolt
#

ive only just started a levels so i havent been taught this but i want to give it a go anyways, I started expanding and googled u have to take the derivative but i think i made an error in expanding and even after that im not sure what to do 😭

fast bolt
#

pls help

woeful briar
#

You are on the right track

#

Do you know what to do with the derivative?

fast bolt
#

no 😔

#

i tried subsitituting x

tepid glen
#

use chain rule for derivative instead of expanding

fast bolt
stoic cloud
tepid glen
#

club penguin bro club penguin

#

🥹

tepid glen
#

what the hell

fast bolt
#

teach me 🥺

#

pls or im cooked

woeful briar
#

Chain rule tells you how to take a derivative of a composite function

tepid glen
#

y' = 3(x-2)^4 * 1

#

bruh

#

idk what im saying

#

thats wrong

fast bolt
#

erm

tepid glen
#

y' = 4(x-2)^43* 1

#

oh my god

#

y' = 4(x-2)^3 * 1

#

i cant type

woeful briar
fast bolt
#

what the hell

#

what am i looking at

#

ok wait give me a second

#

😭

brazen hare
#

were you not taught the chain rule before?

fast bolt
#

im fresh out of gcse

tepid glen
#

basically just do power rule and times it by the derivative of the inside of the bracket

brazen hare
#

this is taught before a level stuff at least for me

tepid glen
#

theyre actually ttrolling you if they didnt teach chain rule and giving u that question

#

💔

fast bolt
fast bolt
#

so wait

#

i would do

#

4 times that thing

#

anf make the ^3 a ^2

tepid glen
#

ok do the power rule on (x-2)^4

#

and it would become 4(x-2)^3 right

fast bolt
#

yes

tepid glen
#

and then you times it by the derivative of (x-2)

#

which is 1

#

so the answer is just 4(x-2)^3

fast bolt
#

why do i do the derivative of (x-2)

tepid glen
#

because the chain is y' = f'(g(x)) * g'(x)

fast bolt
#

OH

#

okay yeah i get you

tepid glen
#

g(x) is x-2

#

🥹

fast bolt
#

thx twin

tepid glen
#

ur welcome twin

#

now sub in where x = 0

fast bolt
#

-32

#

OH so is that like my y

tepid glen
#

no thats ur m

fast bolt
#

frick

tepid glen
#

thats like ur gradient

fast bolt
#

okay yeah

tepid glen
#

u need to find what y is when x = 0

fast bolt
#

uhnmm

#

how do i do that

tepid glen
#

y = (0-2)^4

#

= 16

fast bolt
#

omg im an idiot

tepid glen
#

now u have ur y, m and x

#

now make equation 🥹

fast bolt
#

ohhhhh

tepid glen
#

do u know how make

fast bolt
#

uhmmmmm

#

let me try

tepid glen
#

theres like

fast bolt
#

-32x

tepid glen
#

a formula

fast bolt
#

plus

#

ok idk what else

tepid glen
#

keep going

#

oh

fast bolt
#

😭

#

sorry pal

tepid glen
#

y = -32x + 16

fast bolt
#

OH

#

oh yeah

tepid glen
#

do u know point gradient formula

fast bolt
tepid glen
#

or point slope

fast bolt
#

no 🥺

tepid glen
#

y-y1 = m(x-x1)

fast bolt
#

why did my teacher give me ts

tepid glen
#

idk

fast bolt
tepid glen
#

dude

#

ur teacher sucks

#

why give that without teaching chain rule

#

stupid teacher

brazen hare
fast bolt
#

am i going to fail

tepid glen
#

they troll u

brazen hare
#

everything should be in your notes

fast bolt
tepid glen
#

its gonna be so tedious

#

if she has to expand allat

brazen hare
#

you can use y = mx + c

tepid glen
#

?

fast bolt
#

my teacger is dookie

tepid glen
#

how

#

what if x is not 0

#

then she cooked

brazen hare
tepid glen
#

i mean i guess

brazen hare
#

but y - y_1 = m(x - x_1) is just faster tho

tepid glen
#

yeah

fast bolt
#

atleats i know now

#

thanks pal

tepid glen
#

i give u practise question morri

fast bolt
#

yes

tepid glen
#

what is derivative of (3x-1)^5

#

use chain rule

fast bolt
#

5(3x-1)^4 * 3

tepid glen
#

🥹

#

yes

brazen hare
clever fjordBOT
fast bolt
#

wtf

#

guys im ceying what is that

brazen hare
#

im just formalising it

tepid glen
#

its literallu just what i said to u

#

but like

#

yeah

fast bolt
#

ok so trying to be fancy

tepid glen
#

well no

#

bc thats the proper way of writing it lmao

#

but look scary

brazen hare
fast bolt
#

😅

tepid glen
#

integral is like opposite of derivative

brazen hare
tepid glen
#

but u prob dont need to know now

fast bolt
brazen hare
tepid glen
#

u know power rule

fast bolt
#

🧍‍♂️

tepid glen
#

yes

fast bolt
#

oh yeah

tepid glen
#

and cahin rule

#

baka

fast bolt
#

sowwy

tepid glen
#

dude i hate quotient rule

brazen hare
#

quotient rule is pretty easy

fast bolt
#

why is it so long im going to ksm

tepid glen
#

but it sucks

brazen hare
#

ig it's long

#

@fast bolt do you know the constant multiple rule?

tepid glen
#

i js change it to product rule

#

heh

brazen hare
#

$\dv{x}[cf(x)] = cf'(x)$

clever fjordBOT
fast bolt
#

what is d/dx

#

dih

tepid glen
#

derivative

north sparrow
#

another notation for the derivative

fast bolt
#

okay so the derivative of that

#

is the same as putting an apostrophe

#

like in front of its x

#

im so tuff

#

what do i do with that though

brazen hare
#

$f'(x)$ and $\dv{x}[f(x)]$ both mean the same thing

tepid glen
#

bro what

clever fjordBOT
tepid glen
#

oh yeah

fast bolt
#

yeah thats what i meant pal

tepid glen
#

and y'

brazen hare
clever fjordBOT
fast bolt
#

with chain?

tepid glen
#

67

#

🥹

brazen hare
fast bolt
fast bolt
tepid glen
#

sir ur so tuff

#

67

brazen hare
brazen hare
fast bolt
#

all three weeks

#

not a yeae yet

north sparrow
#

example of the constant multiple rule: $\dv{x}{5e^x} = 5 \dv{x}{e^x}$

#

you can put the 5 "outside" of the derivative operator

fast bolt
#

im confused sorry

north sparrow
#

but the formating hates me

fast bolt
#

😭

fast bolt
brazen hare
clever fjordBOT
brazen hare
#

third time's the charm

fast bolt
#

what is the e

brazen hare
clever fjordBOT
fast bolt
#

no 😭

north sparrow
#

oh boi

brazen hare
#

i mean

fast bolt
#

frick

brazen hare
#

you'll get there 😭

fast bolt
#

idk pal

brazen hare
#

@fast bolt try this:
differentiate $\frac{3}{x} + \sqrt[3]{x} + \sqrt{2}$ with respect to x

clever fjordBOT
fast bolt
#

um

#

okay

tepid glen
#

😭

#

bro

fast bolt
#

1.5x + 1/3x

#

di i do it

brazen hare
fast bolt
#

what the hell

tepid glen
#

change 3/x and cube root of x into exponent form

#

and try again

fast bolt
#

i forgot

#

3/x is like

#

uhm

#

3x^-1

#

right

tepid glen
#

yeah

fast bolt
#

-3x + 1/3x

tepid glen
#

huh

fast bolt
brazen hare
#

not just 3/x

fast bolt
#

3x^(-1) + x^(1/3) + sqrt2

brazen hare
fast bolt
#

-3x^(-2) + 1/3x^(-2/3)

#

YES

brazen hare
fast bolt
#

thanks

brazen hare
#

now simplify

tepid glen
#

🥹

#

not bad, kid.

fast bolt
#

thanks twin

#

ok this looks hard

#

indont know ho

brazen hare
#

if you remember your exponent rules, it should be easy to simplify

#

btw im not asking you to simplify for fun, in exams (at least, a levels i think) , the final answer must be simplified

fast bolt
#

-3/x^2 +

#

uhm

fast bolt
#

im stuck sorry

#

im eating my dinner at the same time 😭

#

waitr when i have

tepid glen
#

1/3x^2/3

brazen hare
#

$\frac{1}{3} x^{-\frac{2}{3}} = \frac{1}{3} \times \frac{1}{x^{\frac{2}{3}}}$

#

pls compile

tepid glen
#

what the heck

fast bolt
#

so 3 to the power of 3/2

clever fjordBOT
fast bolt
#

oh yeah

#

i forgot x

brazen hare
#

$x^{\frac 23} = ?$

fast bolt
#

3x^(3/2)

clever fjordBOT
fast bolt
#

ohhhhhhhh

#

i understand

brazen hare
#

so $\frac{1}{3} x^{-\frac{2}{3}} =$ ?

clever fjordBOT
fast bolt
#

wait sorry

#

3x^(3/2) so (sqrt3x)^3

#

did i mess up

brazen hare
fast bolt
#

where 😔

brazen hare
#

why are you turning the -2/3 into 3/2

fast bolt
#

i was taught to flip everything to remove the negative

#

so 1/3 becomes 3/1

#

and -2/3 becomes 3/2

brazen hare
#

nono the power of -2/3 applies to only the x not the 1/3

fast bolt
#

OOPS

#

1/3(cube root of x squared)

brazen hare
#

$\frac{1}{3 \sqrt[3]{x^2}}$?

clever fjordBOT
fast bolt
#

yes

brazen hare
#

that's correct ✅

fast bolt
#

wow 🤩

#

thanks pal

#

maybe i’m not as cooked

brazen hare
#

fr

#

these are some tough questions as well

#

i think this is like what 3 marks?

fast bolt
#

are you sure ur not saying that to make me feel better

fast bolt
#

3 marks

#

it’s from a past paper i think

brazen hare
#

lol ez 3 marks amirite

fast bolt
#

can i bring u into the exam

brazen hare
#

Given that $f(x) = \frac{8 + 3x}{\sqrt x}$, find $f'(x)$

#

try this

clever fjordBOT
brazen hare
#

still the same concept of power rule, just with another twist

fast bolt
#

8x^(1/2) + 3x^(3/2

#

is first step

#

rigjt

brazen hare
fast bolt
#

oh where did i mess up

brazen hare
#

8 and 3x are being divided by sqrt(x)

fast bolt
#

oh 😭

brazen hare
#

if they were being multiplied by sqrt(x), you would be correct

fast bolt
#

i’m not sure where to start then

#

i’m trying to do it in my head because i don’t have paper rn 😭 this is hell

#

wait

#

8/sqrtx + 3x/sqrtx

#

so 4x^(-1/2) + 4.5x^(1/2

brazen hare
fast bolt
#

😭😭

#

let me try again

#

did i get first half

brazen hare
#

no, but close

fast bolt
#

where did i mess up 😔

north sparrow
#

where you are

fast bolt
#

wait how do i get

#

to 3x^(1/2

#

OH

#

wait

#

ok nvm

brazen hare
#

$\frac{3x}{\sqrt x} = 3x^{1-\frac{1}{2}} = 3x^{\frac 12}$

fast bolt
#

yes i see

#

thank you

clever fjordBOT
brazen hare
fast bolt
#

-4x^(-3/2) plus 1.5x^(-1/2

#

yesss

#

😆😆

brazen hare
#

simplify that?

fast bolt
#

-4 times 1/x^3/2

#

and then

#

-4/sqrt of x cubed

#

plus

#

1.5 x 1/x^1/2

#

so 1.5/sqrt of x

#

i’m cracked

#

u guys should become tutors

brazen hare
#

you can also write that as $\frac{3}{2\sqrt{x}}$

clever fjordBOT
fast bolt
#

i don’t understand

#

cube second fraction?

#

and then add and simplify

brazen hare
#

$1.5 \times \frac{1}{\sqrt x} = \frac{3}{2} \times \frac{1}{\sqrt x}$

clever fjordBOT
brazen hare
#

1.5 = 3/2

fast bolt
#

ahhhhh

#

i thought y meant the entire thing 😭

brazen hare
#

loll of course not

#

the full expression is $-\frac{4}{\sqrt{x^3}} + \frac{3}{2\sqrt{x}}$

clever fjordBOT
north sparrow
#

Recap:

brazen hare
#

@fast bolt here's another question, this time more in tune with the style of an exam: \
Find the gradient of the curve $y = \frac{x-1}{x^2}$ at the point where the curve crosses the $x$-axis.

clever fjordBOT
fast bolt
#

i have to go can i add you and dm my answer later 😭

#

my dad is making me play a board game

brazen hare
#

of course

#

xD have fun

fast bolt
#

thanks 🤩

#

.close

odd edgeBOT
#
Channel closed

Closed by @fast bolt

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

glad kestrel
#

Please help I got E and the answer is D

exotic bobcat
#

How are we supposed to help when you aren't telling us how you got to E?

glad kestrel
#

sorry

#

I drew triangles ORQ and POQ next to eachother and used cosine rule to find the straight line that connects P to the midpoint of OR

exotic bobcat
#

that's a path right through the pyramid though. Not along the outer surface of the pyramid, which is what the exercise asked for

glad kestrel
#

this is what i drew

glad kestrel
#

i think maybe i assumed the angle is 120 when its not

#

but i just cant visualise it or something

late dust
#

No, it is 120º

late dust
glad kestrel
#

yes 1s

glad kestrel
#

sorry i just did the wrong value of cos

#

i thought cos 120 was -sqrt3 / 2

#

when it was -1/2

exotic bobcat
# late dust It's not, he is correct

the straight line that connects P to the midpoint of OR
no such thing exists in the sketch above. Not unless you have a really interesting definition of straight lines in 3d space or pass through the pyramid

glad kestrel
#

i drew 2 faces of the net of the pyramid

late dust
#

You can definitely define straight lines on surfaces, even of a polyhedron

odd edgeBOT
#

@glad kestrel Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
#

i keep get stuck on these kind of questions, maybe it's the tiredness but please someone help

mystic saffron
#

i have the formula

#

but i just don't know what goes where and stuff

worn saddle
#

then add the values of those terms

odd edgeBOT
stray arch
#

So what does the constant term mean? It means that the xs cancel out

#

Try to find where $x^n \cdot (\frac{1}{x^3})^{12-n} = 1$

clever fjordBOT
#

Crackhex

mystic saffron
#

right

worn saddle
stray arch
#

Once youve done that you reduce your answer down to two choices, and then remembering the sign rule for binomial distribution will give you one option left

mystic saffron
#

i got to (12 C k ) (2^(12-k))(x^-4k) (-5^k)
and now i have no idea what

stray arch
# clever fjord **Crackhex**

I flipped this accidentally I meant it to be $x^{12-n} \cdot (\frac{1}{x^3})^{n} = 1$

Can you solve for n here?

clever fjordBOT
#

Crackhex

stray arch
#

I stripped the constants away for the moment because theyre entirely unimportant to the fact the xs cancel out in the constant term

mystic saffron
#

n = 12

#

righhhhhttttt..........??????

#

no

#

what am i on

#

am i stupid??

#

well i know n = 9 but i am trying to justify it

#

no

#

n = 3

#

what am i on

stray arch
#

N=3 yes

mystic saffron
#

but how

stray arch
#

its just exponent laws

#

1/x³ = x^(-3)

mystic saffron
#

can i use ln(x) to find this

stray arch
#

No need, just exponent laws: $(\frac{1}{x^3})^n = x^{-3n}$, then $x^{12-n} \cdot x^{-3n} = 1 \implies x^{12-4n}=1$, thus $12-4n=0$ and $ n=3$

clever fjordBOT
#

Crackhex

stray arch
#

So now we know n=3, calculate the third term in the expansion

#

And see which answer you get

mystic saffron
#

oh

#

i see that now

odd edgeBOT
#

@mystic saffron Has your question been resolved?

mystic saffron
#

one more thing; i did this

#

and i got the right answer

#

but in the wrong way

#

is this valid to keep doing it like this since i can't see what i did wrong

worn saddle
#

you removed A and B since K is a positive integer

#

C gives a valid value for K so C has a constant term for it

mystic saffron
worn saddle
#

or to say if any term gets free of x

worn saddle
#

now here n is a positive integer acc to the binomial theorum

#

so whenever we dont dont get a value of n thats a positive integer , hence we dont satisfy the condition , hence we dont have a constant term

#

and when something doesnt exist it means its coefficient is 0 or to say it is 0

mystic saffron
#

ahok

#

thanks

#

think we be done here

#

?close

#

!close

#

.close

odd edgeBOT
#
Channel closed

Closed by @granite grove

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wheat magnet
#

losing my mind over part 3!

odd edgeBOT
#

@wheat magnet Has your question been resolved?

sturdy cape
#

!xy - that can't be the full question, surely

odd edgeBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wary tide
#

this is a physics question but it has math involved so
my question is how did get the equation sb + sc-sb

odd edgeBOT
#

@wary tide Has your question been resolved?

odd edgeBOT
#

@wary tide Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rustic maple
#

I am meant to find the vector and parametric equations of the line R^2 that passes through the origin and is orthogonal to the vector v, where v = (-2, 3)

rustic maple
#

Here's what I tried. Book said it's wrong

#

yes, I know that that would make the line parallel to v, not perpendicular like it wants of me

#

(I cannot use cross products because they haven't been taught to us)

#

nvm, I just used the fact that the normal u is -1/slope of v with (0, 0) as the starting point for both vectors

#

.close

odd edgeBOT
#
Channel closed

Closed by @rustic maple

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

worthy root
#

how can i prove that AB, DM, EN converge at K
Given two parallelograms ABCD and ABEF not lying in the same plane.

worthy root
#

AM/AC=MN/BF=1/3

#

thats all the question provides

odd edgeBOT
#

@worthy root Has your question been resolved?

acoustic nexus
#

!original please