#help-19
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Professor X, how would you have phrased it?
The first right should be a left
But you got the idea so I said good enough and didn't focus on the semantics much
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hello
I have a very hard time understanding this part in calc 3
Just for future reference, do you mind posting the image/question as your first message so the bot doesn’t pin greetings? This way, if the conversation continues for long, helpers don’t have to dig. 
say i have a equation f(x,y,z) = (x^2)/3 + y^2 - z
at (3,0,3) the tangent plane is is z=2x-3
and at (3,0,3) the plane that contains the vector of the gradient is z = -x/2 + 9/2
You can just pin messages
He can't
I don’t have permissions to.
You'll get there
I know 😈

@dense temple continue your question
why is gradient
normal to tangent
like is 2d calc
its the same shit
and
look the black line is the gradient vector
how tf is that supposed to be the direction of max increase in z
are you asking why the gradient vector is normal to the tangent plane?
@dense temple Has your question been resolved?
ye
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Right now I have this triangle try to ignore the blue markings (sorry for them)
I used area of a triangle with height being 15 because 1/2bh where b is 4 and area is 30 so we know height is 15
I’m trying to solve for the slope between A and B
I figured to plug (x,15) into the f(x) equation but my issue is that I don’t want to use the quadratic formula and I feel like there’s another way to do this
@midnight jasper Has your question been resolved?
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I lwk forgot how to do ts
Google "exponent laws"
$$x^{-a}=\frac{1}{x^a}$$
Good
brainfuck
honestly yeah I forgot how to get rid of that
I know this but idk how on a curved bracket
if you know not to make condescending remarks in the future then all good
Google "exponent laws"
do I just add a huge slab of 1_ under it and then flip it?
I did it didn't show me for a negative power on a curved bracket
check out the yt channel The Organic Chemistry Tutor if you haven't already
it's better if you do that instead of having some random strangers yap at you
@mystic saffron Has your question been resolved?
,tex .exp rules
riemann
same rule they told you here
@mystic saffron Has your question been resolved?
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hellooo, i need to calculate the volume of a sliced up spherical cap
do you know the depth?
I need to calculate the volume between the planes
Preferably the surface area as well
and to do its as simply as possible
have you learnt calculus?
only the basics 😭 I havent touched multivariables stuff
i see
i might be having the dunning kruger effect
how hard is this?
its for a math report, im modelling the shape of an object
do you know how to get the volume of a sphere through integration?
many classmates are modelling through rotations
because if ye then you can just use that, change its limits then be done for the vol b/w the blue planes
purple*
@small fulcrum Space is as hot as my?
haha
xD
i put that there like a year or two ago and completely forgot
is the light blue plane also important?
yepppp, thats the base
its a spherical cap sliced up
let me show you what im trying to model
oki
let me look up an explenation real quick 😭
OHHH
?
okay gotcha
not much if you know how to find the vol of a sphere through integration
what's the radius?
like as someone who has such limited knowladge of calc. I think if i have the fucntion that models a spherical cap, i can just take the definite integral from x=-s to x=s, where s here is d/2 and boom volume, right??
uff okay okay then its not that bad
u can see specific measuremnts in the geogebra pic, 30.875
haha im not used to using online tools
and for the base, you'd use the same method
yooo, yeah yeah i think im getting it
(as in integration)
https://www.youtube.com/watch?v=nHC92J8rNZs im looking at this proof of voluem
Hi friends! This video is about deriving and finding the volume of a sphere by using integral calculus!
The formula for the volume of any shape is the definite integral from one end of the shape (let's call it "a") to the other end of the shape (let's call this "b"). So the integral is from a to b of the area of the cross-section (If you cut o...
should be fine
you could always use archimedes too
but thats not math
more so physics
but thats always a less maths heavy option compared to this
use a testube or something with it to calculate the volume easily ig
nah i kind of need more of mathematical method 😭
anyways you can use the same method but by just using the area between the planes instead to calculate what you want then
@safe pivot Has your question been resolved?
problem is still not compeletly solved
okay so looking at proofs fro the volume of a spherical cap, tehy all do it with circular disc, easiest way obsiusly
but is there a way to do it with cirucalr sectors?
how would the area of a sector be calculated?
you would need to construct a function yes
use sectors and find it that way
yeahhh thats what im tryng to do
instead of using the entire circle
i found a math stack exchange with the queestion https://math.stackexchange.com/questions/2135065/volume-of-part-not-necessary-the-half-of-spherical-cap?utm_source=chatgpt.com
!solved
how do i solve it lol?
gimme a sec
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whats the range guys?
@dry moon Has your question been resolved?
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Hi guys what does /3 rad imply? I'm taking trigo and the given for our assignment by our prof are like this, does this mean π/3? Or something else?
It's /3 rad
if it’s /3 rad then it’s most likely 𝜋/3 rad
Ohh alright2 thanks
anything else? Otherwise, you can use .close. 
Last one question

If the given is 2 rad, is it just 2 or 2π?
Ohhhh okok thanks very much
if you are done, use .close 
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Here's what ive done so far:
im not sure if what i have is on the right track, but im struggling to manipulate LHS to progress
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<@&286206848099549185>
@light hawk Has your question been resolved?
got it, thanks
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i have a doubt
me too
The answer is 16N, i solved it in a way
but the issue is if I apply 16N of force, the friction on B is 8N at its maximum, the reaction of the friction force from B is the driving force for A, the max value of friction of A is 2N, so the net force on A is 6N, so wouldn't A fall off if it keeps moving?
ik its basic stuff but has eaten up my brain.........
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Let E be a non empty subset of R. Prove that diam(E)= sup E-inf E . I took a bounded set E and from completeness property i said a = sup and b = inf.... i am into the idea of diam( E closure )= diam (E) and intuitively its known that a\in closure of E and b also but i dont get how should i write it
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I got to a(x-9)/x-3
,rccw
put the value of x as 3 as we are checking in the neighborhood of 3, soo
you will get an equation
then you can differentiate the two parts of f(x) to get the other equation
2 equations and two things to find, easy calculation forward
Yes, that's what I did but I got stuck when I tried to simplify
show your work, please
you will directly get the value of a when you differentiate the first and second part and equate them
then you can find the value of b further by plugging in any of the equations
Im confused?
okay answer my questions buddy
what will you get when you plugin 3 in the first part
( checking continuity first of all)
3a+b?
Yes
you'll get 9 right ?
Yes
for continuity the value of all the part in neighbor of 3 should be equal so
so 3a + b = 9
this is the first equation
Wait I got it now
now we're done with the continuity of the function
now move on to differentiability
differentiate the first and second part then plugin the value of x ( that is 3)
and then you have another equation
perfect ✨
Does differentiable actually mean
for single var calc purpose, derivative exists there
When finding multiple derivatives i just keep plugging in the previous derivative right? What is this even used for
usually
depends on the case
multiple derivative is used to find rate of rate of rate of ... something
acceleration is the best example
acceleration is the derivative of velocity, but velocity is itself the derivative of position/displacement
this makes acceleration the second derivative of position/displacement
Im lowkey bad at factoring help pls
one quick look confirms that you have one very prominent common factor here
(amongst the remaining terms)
that being said, there is something wrong with this expansion. there is a notable lack of $t^2 h$ terms.
fox(x, y); ∂(fox)/∂x (Flower)
?? Idk what im doing
this looks more correct
now, your only term that doesn't have a h is balanced out by the -t^3 at the end
so you should be able to tell what factor is common to the remaining terms
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. @vernal garnet post here
Why there is adding root3 in 6 and root3
Why there is adding root3 in 6 and root3
What do you mean
it’s called rationalizing; you multiply by sqrt(3)/ sqrt(3) ( which is essentially just 1) to get rid of the irrational number (sqrt(3)) in the denominator.
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@vernal garnet Has your question been resolved?
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how do I find derivatives of exponetial fractions?
That's a bad crop 
can we see the exponents of the e's please
Im trying to solve d
Differentiate f(x) twice and see thats equal to f(x)
Well, usually for fractions you go quotient rule, but here notice the denominator is 2, that means it‘s just a constant factor
yeah
what I tried is pulling 2 at the numerator
so it becomes
2^-1
However, I dont think thats valid since theres no x
what makes you think that
Yes
That is indeed what 1/2 equals yes
noo, notice how it‘s not x to some power, it‘s e^x
so you use the "formula" for derivative of e^x
do you remember that?
Right. And recall that you can move constants out of the derivative if they‘re multiplying
ie $\dv{x}\left(a\cdot f(x)\right) = a\cdot\dv{x}f(x)$
Well, right up until the second to last step you were fine
where did you get this guy from?
probably thought e^(-x) = 1/e^x (which is true) but they combined the fractions improperly
What’s wrong with that?
The E is raised to a negative X
So I brought it in the denominator
you combined the fractions improperly
$-\frac{e^{-x}}{2} = -\frac{1}{2e^x}$
Alberto Z.
This is correct, but it's not what you have done @shrewd trellis
(considering the question, i wouldn‘t do that though)
well- you cant do that with addition
Awful mistake!!
the "flipping the negative x to the denominator"
only applies when there's no addition or substraction
h, you could have stopped one step before that, you were done
You just had to show it was = to f(x)
ohh
then thats just the answer if I cancel the last step
yeah. You did what was asked
or it could be e^x/2 - 1/(2e^x)
I mean, they are equal, but you wanted to show that f''(x) = f(x), so just stop when it looks like f(x) 
also if f'(x)>0 for exponentials
does it mean it will rise to the right?
if f'(x) < 0, then it will dip to the right
the confusing part is, I dont know how to graph this
I could look at e^x
and apply transofrmations
but man, this is a tricky one
oh they‘re asking you to sketch this. Interesting. I‘m not sure how to intuitively find this. You could plug a few values in I guess and sketch from that
I want to know the best method
uh, this is a hyperbolic trig function
wai, not the time for that 
I think you messed up with negative values
I suggest using the $\frac{e^x-e^{-x}}{2}$ form for your calculations as it‘s less calculator error prone imo
Yours is a bit yeah. The left side
One way to know that the function is always increasing is looking at f'(x). It‘s always positive, so f(x) is always increasing
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Yo guys
I want an An alternative to stupid chatgpt
why do you think this server exists?
Have you tried stupid deepseek or stupid claude?
that alternative would be us
I don't want make you tired 😇
!nogpt
you know the server has close to 300k people?
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
they’re all dumb
Ok then i have question
post it an let a helpful pin it
try alphageometry for Euclidean Geo
I want to find the solution of
|x+2|>|3x+5|
To find the solution we need to assume that predicate is true right?
what predicate?
P(x): |x+2|>|3x+5|
I don't know why you're bringing logic into an algebra question, but sure I guess?
Gpt said no
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
This is the original question
when I use that command, I'm usually asking for a picture of the question
Just find x
then what the hell are we supposed to do with the fact that GPT said no? said no to what? what was the original context of the question?
and what did you prompt GPT with?
we want the values of x that makes it true
of course this inequality is not true for literally every x (just try x = 1)
And to get x we need to suppose it true?
in a way yes, I suppose? you can keep the inequality sign and suppose that it's true, and if you get a contradiction later, then you can conclude that no value of x makes the inequality true
(assuming you didn't bomb the algebra)
To solve every inequality we must do that?
I don't like the concept of "assuming it as true", but yes, I suppose
You mean the concept isnt correct ?
I won't say it's entirely incorrect as per how I think you are viewing it. I just won't even think of this as a logical statement
Explain please
or rather, I won't be thinking of truthiness when it comes to solving inequalities, because that's unnecessary
I mean, how do you solve an equation?
if I have an equation, say, x + 5 = 4
how would you solve it?
Using connectors
...what are "connectors"?
x+5=4 => x=5-4
not sure again why logic is coming into algebra, but sure
but you have to make this implicit assumption that the equation you started with is true in the first place
But all mathematics concepts built as logics
and that's a universal assumption across algebra
if you started with a "false" equation then what's the point
No sense
ok, but doesn't mean that we have to overcomplicate an algebra problem
The same with inequality?
the same with everything that you want to solve for. what's the point of solving for a known false statement? you know it's false!
I want to understand mathematics more abstractly.
So we suppose to be true
sure. abstract algebra it is then. overcomplicating regular algebra problems is still not my recommendation
(not gonna say you can't do it though)
So then
Where do you think I can use logic?
You mean what did i send not supposed to be statement we want to prove it?
I never said your original question was a proof
that's why I recommended against using logical concepts here
your original question was a simple algebra question
Look honestly i want to understand logic, i know how to solve this simple inequality but i want to know if the steps which I'm doing to solve this is correct logically
show your work then
so what seems to be the problem here?
also, you don't have to ping with every reply
I don't know why that > 0 is there from the start, and I presume that interval is French notation for (-7/4, -3/2)
if my presumption is correct, your answer is as well, but the right side of line 2 is a clusterfuck and I can't see most of the things towards the end
Dont care about the right side
also, if you want to use $\Rightarrow$ to denote a new step, that's a good thing, but make sure each $\Rightarrow$ is on a new line
Look i know that my solution right
Tairin
But logically, is that true?
in this case, you're not looking for logical truth. you're looking to see if the steps are algebraically correct
yes, the steps are indeed algebraically correct, except for that > 0 that has plagued the first three steps
Well keeping thinking about this makes me confused
I know it's a wrong way of thinking, but for me it's the way to understand mathematical steps and if they're right.
Like i said mathematics concepts all built as logic
if that's how you wish to view algebra, sure I guess.
It’s perfectionism i guess
turns out math doesnt give a fuck about what you think is correct
take higher math classes
like
How it doesnt give a fuck
this logic is good to learn before you really dive into proofs, since your different proof strategies rely on understanding basic logic (and doing a proof is just a series of steps)
writing stuff like this is just obtuse and weird for solving an inequality
and if you wanna do higher math then you should learn the basics therein first
So am I on the right road?
i think the op is just trying to understand the hypothesis of the theorems disguised in logic which isnt wrong at all
personally i think you should once you pick up basic logic, start looking at set theory and writing the basic proofs there
this.
Yeah that’s it
I want to know what happens logically
anyways no, we dont assume the predicate is true. we are actually finding the set of solutions for which the inequality is true
^
now suppose the question was if |x+2| > |3x+5| then show that
|x+2| +3 > |3x+5| + 2
then u do assume that the predicate (the original inequality) is true and prove the next statement
And to find that we use implication connector
Which we need to assume P to be true
yeah if P(x) is the original inequality and Q(x) is the following statement then u'd want to prove P(x) -> Q(x) for all x in domain
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why am I able to scale them like this?
My calculator and answer just say 2, 6, 1
when doing rref
Can you post the original question as well?
Linear depedence and Linear Independence of Vectors
Express vector t as a linear combination of the vectors u, v , and w.
- $\vec{t} = (0,0,19) , \vec{u} = (1,4,3), \vec{v} = (-1,-2,2), \vec{w} = (4,4,1)$
I wrote this as see image to start
smeagol
Since
$a \vec u + b \vec v + c \vec w = \vec t$
smeagol
oh your mistake is on the 2nd step
you said 2 - 3*(-1) = -1 when it's 5
one thing i'd really recommend doing out of habit is saying where your reduction is going since then it's harder to follow
it's -2 - 3(-3) though
no on R3 - 3R1
ooh
you should write this as R3 - 3R1 -> R3 i think
like it's just easier for someone else reading it to follow, they don't have to look at the resulting matrix to figure out where you're sending it
and if you're reading your own work later on
gotcha
Yeah, even if it seems obvious to you that R3 - 3R1 is working on R3, it's not good notation
thank you!
especially if you're doing multiple steps at one time like the first one
If you know a bit of programming, you might have encountered a -= operator; R3 -= 3R1 would be ok assuming the reader knows about that symbol
I prefer that over
R3 = R3 + R1
R3 += R1 (better imo)
My teacher did it confusing to me where he lined them up in the same row
we were taught this in my linear algebra course
Oh yeah that's kinda ugly
Thank you both for advice, I gotta eat lunch now -- I'll redo the second half in a bit
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ive only just started a levels so i havent been taught this but i want to give it a go anyways, I started expanding and googled u have to take the derivative but i think i made an error in expanding and even after that im not sure what to do 😭
pls help
use chain rule for derivative instead of expanding
i dont know what that is sorry
…CP server tag… 
Chain rule tells you how to take a derivative of a composite function
erm
If y=f(g(x)), then chain rule is that
y'=f'(g(x)) * g'(x)
were you not taught the chain rule before?
im 16 we started like a week ago
im fresh out of gcse
basically just do power rule and times it by the derivative of the inside of the bracket
this is taught before a level stuff at least for me
theyre actually ttrolling you if they didnt teach chain rule and giving u that question
💔
probably further maths i only locked in a week before gcse
im cooked ngl
so wait
i would do
4 times that thing
anf make the ^3 a ^2
yes
and then you times it by the derivative of (x-2)
which is 1
so the answer is just 4(x-2)^3
why do i do the derivative of (x-2)
because the chain is y' = f'(g(x)) * g'(x)
thx twin
no thats ur m
frick
thats like ur gradient
okay yeah
u need to find what y is when x = 0
omg im an idiot
ohhhhh
do u know how make
theres like
-32x
a formula
y = -32x + 16
do u know point gradient formula
nope
or point slope
no 🥺
y-y1 = m(x-x1)
why did my teacher give me ts
idk
ive never seen that before
maybe it's just a difference in curriculum 
am i going to fail
they troll u
do you have notes on this topic?
everything should be in your notes
no i started last week all we have done is uhmmm quartics
well how does she do those types of questions without knowing chain rule or point gradient bruh
its gonna be so tedious
if she has to expand allat
y - y_1 = m(x - x_1) is technically not necessary
you can use y = mx + c
?
my notes is just graphs 🥺
my teacger is dookie
substitute y, m, and x and solve for c
i mean i guess
but y - y_1 = m(x - x_1) is just faster tho
yeah
i give u practise question morri
yes
5(3x-1)^4 * 3
btw in general for most functions $f(x)$ the derivative
[\dv{x}[f(x)^n] = nf'(x)f(x)^{n-1}]
ok so trying to be fancy
what derivatives and integrals do you know rn?
idk what an integral is and i taufht myself an hour ago how to do derivatives
😅
integral is like opposite of derivative
do you know all of these already?
but u prob dont need to know now
i dont know any of them
well you know the last one, don't you ;)
u know power rule
🧍♂️
yes
oh yeah
sowwy
dude i hate quotient rule
quotient rule is pretty easy
why is it so long im going to ksm
$\dv{x}[cf(x)] = cf'(x)$
derivative
another notation for the derivative
okay so the derivative of that
is the same as putting an apostrophe
like in front of its x
im so tuff
what do i do with that though
$f'(x)$ and $\dv{x}[f(x)]$ both mean the same thing
bro what
oh yeah
yeah thats what i meant pal
and y'
you can differentiate something like $f(x) = 6(7x + 3)^4$
with chain?
chain and product
🥺
product?
bro have you had to self-study your math class like all year 😭
constant multiple* sorry
example of the constant multiple rule: $\dv{x}{5e^x} = 5 \dv{x}{e^x}$
you can put the 5 "outside" of the derivative operator
im confused sorry
but the formating hates me
😭
u could write on paper and send photo
$\dv{x}[5e^x] = 5\dv{x}[e^x]$
third time's the charm
what is the e
do you know the mathematical constant $e$?
no 😭
oh boi
i mean
frick
you'll get there 😭
idk pal
@fast bolt try this:
differentiate $\frac{3}{x} + \sqrt[3]{x} + \sqrt{2}$ with respect to x
no..
what the hell
yeah
-3x + 1/3x
huh
🥺
write out the whole equation with x in exponent form
not just 3/x
3x^(-1) + x^(1/3) + sqrt2
now use your power rule to differentiate each term
very good :)
thanks
now simplify
if you remember your exponent rules, it should be easy to simplify
btw im not asking you to simplify for fun, in exams (at least, a levels i think) , the final answer must be simplified
yeah my teacher said that
im stuck sorry
im eating my dinner at the same time 😭
waitr when i have
1/3x^2/3
$\frac{1}{3} x^{-\frac{2}{3}} = \frac{1}{3} \times \frac{1}{x^{\frac{2}{3}}}$
pls compile
what the heck
so 3 to the power of 3/2
$x^{\frac 23} = ?$
3x^(3/2)
so $\frac{1}{3} x^{-\frac{2}{3}} =$ ?
yes
where 😔
why are you turning the -2/3 into 3/2
i was taught to flip everything to remove the negative
so 1/3 becomes 3/1
and -2/3 becomes 3/2
nono the power of -2/3 applies to only the x not the 1/3
$\frac{1}{3 \sqrt[3]{x^2}}$?
yes
that's correct ✅
are you sure ur not saying that to make me feel better
yes
3 marks
it’s from a past paper i think
lol ez 3 marks amirite
still the same concept of power rule, just with another twist
close, but not quite
oh where did i mess up
8 and 3x are being divided by sqrt(x)
oh 😭
if they were being multiplied by sqrt(x), you would be correct
i’m not sure where to start then
i’m trying to do it in my head because i don’t have paper rn 😭 this is hell
wait
8/sqrtx + 3x/sqrtx
so 4x^(-1/2) + 4.5x^(1/2
hmm not quite
no, but close
where did i mess up 😔
where you are
$\frac{3x}{\sqrt x} = 3x^{1-\frac{1}{2}} = 3x^{\frac 12}$
from here you can just apply power rule
simplify that?
-4 times 1/x^3/2
and then
-4/sqrt of x cubed
plus
1.5 x 1/x^1/2
so 1.5/sqrt of x
i’m cracked
u guys should become tutors
you can also write that as $\frac{3}{2\sqrt{x}}$
$1.5 \times \frac{1}{\sqrt x} = \frac{3}{2} \times \frac{1}{\sqrt x}$
1.5 = 3/2
loll of course not
the full expression is $-\frac{4}{\sqrt{x^3}} + \frac{3}{2\sqrt{x}}$
@fast bolt here's another question, this time more in tune with the style of an exam: \
Find the gradient of the curve $y = \frac{x-1}{x^2}$ at the point where the curve crosses the $x$-axis.
i have to go can i add you and dm my answer later 😭
my dad is making me play a board game
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Please help I got E and the answer is D
How are we supposed to help when you aren't telling us how you got to E?
sorry
I drew triangles ORQ and POQ next to eachother and used cosine rule to find the straight line that connects P to the midpoint of OR
that's a path right through the pyramid though. Not along the outer surface of the pyramid, which is what the exercise asked for
Can you show your calculation
this is what i drew
It's not, he is correct
i think maybe i assumed the angle is 120 when its not
but i just cant visualise it or something
No, it is 120º
.
yes 1s
ah wait nvm
sorry i just did the wrong value of cos
i thought cos 120 was -sqrt3 / 2
when it was -1/2
the straight line that connects P to the midpoint of OR
no such thing exists in the sketch above. Not unless you have a really interesting definition of straight lines in 3d space or pass through the pyramid
i drew 2 faces of the net of the pyramid
along the outer surface
You can definitely define straight lines on surfaces, even of a polyhedron
@glad kestrel Has your question been resolved?
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i keep get stuck on these kind of questions, maybe it's the tiredness but please someone help
hmm imo in such cases check when the term is free from the variable
then add the values of those terms
!status
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1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
all of the above uhhh 1.
So what does the constant term mean? It means that the xs cancel out
Try to find where $x^n \cdot (\frac{1}{x^3})^{12-n} = 1$
Crackhex
right
hmm how do i use this bot
Once youve done that you reduce your answer down to two choices, and then remembering the sign rule for binomial distribution will give you one option left
i got to (12 C k ) (2^(12-k))(x^-4k) (-5^k)
and now i have no idea what
I flipped this accidentally I meant it to be $x^{12-n} \cdot (\frac{1}{x^3})^{n} = 1$
Can you solve for n here?
Crackhex
I stripped the constants away for the moment because theyre entirely unimportant to the fact the xs cancel out in the constant term
n = 12
righhhhhttttt..........??????
no
what am i on
am i stupid??
well i know n = 9 but i am trying to justify it
no
n = 3
what am i on
N=3 yes
but how
can i use ln(x) to find this
No need, just exponent laws: $(\frac{1}{x^3})^n = x^{-3n}$, then $x^{12-n} \cdot x^{-3n} = 1 \implies x^{12-4n}=1$, thus $12-4n=0$ and $ n=3$
Crackhex
So now we know n=3, calculate the third term in the expansion
And see which answer you get
@mystic saffron Has your question been resolved?
one more thing; i did this
and i got the right answer
but in the wrong way
is this valid to keep doing it like this since i can't see what i did wrong
ye
you removed A and B since K is a positive integer
C gives a valid value for K so C has a constant term for it
whatever i did i dont think it was intntional
hmm so what you did here is check wether a constant term exists
or to say if any term gets free of x
or to say if this happens for any value of n
now here n is a positive integer acc to the binomial theorum
so whenever we dont dont get a value of n thats a positive integer , hence we dont satisfy the condition , hence we dont have a constant term
and when something doesnt exist it means its coefficient is 0 or to say it is 0
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losing my mind over part 3!
@wheat magnet Has your question been resolved?
!xy - that can't be the full question, surely
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
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this is a physics question but it has math involved so
my question is how did get the equation sb + sc-sb
@wary tide Has your question been resolved?
@wary tide Has your question been resolved?
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I am meant to find the vector and parametric equations of the line R^2 that passes through the origin and is orthogonal to the vector v, where v = (-2, 3)
Here's what I tried. Book said it's wrong
yes, I know that that would make the line parallel to v, not perpendicular like it wants of me
(I cannot use cross products because they haven't been taught to us)
nvm, I just used the fact that the normal u is -1/slope of v with (0, 0) as the starting point for both vectors
.close
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how can i prove that AB, DM, EN converge at K
Given two parallelograms ABCD and ABEF not lying in the same plane.
@worthy root Has your question been resolved?
Ehhh, what is this
!original please
