#help-19
1 messages · Page 218 of 1
Let us take u= mgsin@ - bv
alr
But won't we need the distance from the point of banking
That is what we were taught
r = 100 worked anyways
i am not sure I haven't read the question this is a really long thread 
We assume this substitution
Now we have a simpler integral but that is not it
Our differential operator is still dv
And we need it to be du
We know du/dv = -b
Now we substitute the value of dv in the integral to get
@honest ore are all these steps clear
Our integral looks something like this
so this means dv = du/-b
But the denominator is slightly complicated
Yes
and the original was dv/u
I didn't give any context on how this came
Yes
ok i kinda get it
theres a curve on the test anyways so i just need to get most of it
whats the next step btw
alr
actually can i get context on this
u = mgsin¥ - bv
Now we differentiate it wrt v
To get du/dv = -b
?
or is wrt v short for something
With respect to
Alright the next question ?
what comes next
This one is pretty much done from here
We have ln(mgsin@ - bv) = -(C+t)m/b
yeah idk how u got there
We had integral du/-bu = mt right
Now after integrating the left side we get
(-1/b)*(lnu)
Where we substitute the value of u
To get ln(mgsin@ - bv) = -mt/u + C
wait when did the left side become -mt/u + C
yeah thats a good idea i think
I am really sorry while typing i messed it up
It was supposed to be tb/m
@honest ore
u mean -tb/m
Yes
<@&286206848099549185>
im gonna hope the reflection isnt hiding anything important
It isn't
.close
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?
What about the other questions though
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Sup
,rccw
Is the formula $\frac{1}{Req} = \frac{1}{R}+ \frac{1}{R} +\frac{1}{2R}$
Ryne___np
that is for resistors in paraellel
btw $R_{eq}$
Ann
also yeah these guys of yours are in series
Oh so in this case they are not?
.
So the sum is 4R
you would just add thme up
no prblem
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is this parallel
They said in series
I thought they were parallel because of the node
Like that
But im wrong
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,rccw
ugh
,rccw
rccw
,rccw
💀 ok
Cos and sin here must be opposite in sign yet equal in magnitude
What did you do in this question
What your attempt/thought process
Either Cos or sin here must be -ve here having same magnitude
Convert tan into sin/cos
Then take LCM you get an identity
Tan an odd function will remove - out
Ohk
Ty I'll try after supper
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how big is this number?
and how would i calculate it myself?
e7.625e6
It’s 10^(7.625 * 10^6)
damn
you're gonna break the bot
is it that big?

Yeah it didn’t compute…
well it
balatro numbers are that big.
*it’s a umber with 7,625,000 digits
at 45m calculations
Cuz you have 10⁷⁶²⁵⁰⁰⁰
doesnt help that im using a mod that needs its own system for the numbers
DAMN
this is balatro?
yes
never played it
I should tho
modded tho
yup

hope my laptop doesnt die
same here lmao
I love balatro 🔥🔥🔥🔥
you have a thousand jokers... probably you're going to be there for 2 hours.
but do you still have a question?
193
1557 jokers ?????!
Bro I think that's more than the world's GDP man😭
doesn't look like it, ma'am...
more than atoms in the universe
Dude i feel like the odd one out not knowing what yall are tallking about 
there is a /
Balatro funny card game and big number is all I know
not rn

alright.
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hi
can anyone help?
Post your question!
can you explain how to do this?
can you show the formula for Newton Quotient you were taught
f(x+h)-f(x)/h
not rlly. im trying to understand it
y(x+h) is the function y(x) except where you replace x+h wherever there is an x
consolas
?
font name
do a simpler example first
if g(x) = x^3. do you know what g(x+h) equals?
@lime merlin Has your question been resolved?
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Hello, I'm currently working with some patological cases of l'hopital's rule. And I don't know how I should describe numerator and denominator. For numerator, what becomes x^2*sin(1/x)? Since it becomes 0 x undefined I don't know how to describe it
are you REQUIRED to do it with l'hop
also whoever TeX'd this should learn that \sin exists.
I'm the one who did that sorry haha
$\lim_{x \to 0} \frac{x^2 \sin(1/x)}{\sin(x)}$
Ann
anyway again, are you required to do this with l'hop?
But yes I'm required to do it with l'hop and show that there's no answer. And I have to do it again with numerator and denominator changed, and show that it works.
uhhh
i mean like, $\lim_{x \to 0} x^2 \sin(1/x) = 0$ by e.g. squeeze theorem, so LH is \textit{applicable}.
Ann
and then there's some run-around when it comes to taking the derivatives of top and bottom and staring long & hard at the resulting limit
with the ultimate conclusion being that l'hop doesn't give us anything useful
I'm forced to solve it with l'hop for this equation, and I don't really know how I should interprete 0 muliplied by sin(infinity), like the numerator
Is it undefined?
Yes, that's in the syllabus and it's the part of training, according to professor
0*sin(∞) as-written is undefined, but this simply means you have to resort to some other means to find the limit of x^2 sin(1/x).
so by the looks of it, you've just explicitly had all means of solving this limit taken away from you
💔
and you're simply unable to do it because of red tape.
and bureaucracy.
So I can't go further with l'hop rule in this equation?
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wasnt there this one theorem where if you have lim_{x -> 0} f(x)g(x) and g(x) is bounded and lim_{x -> 0} f(x) = 0 then lim_{x -> 0} f(x)g(x) = 0??
or am i remembering wrong
and by the looks of it OP is barred from using that
ohhh shi i see
cant you say numerator lim_{x->0} sin(1/x)/(1/x^2) and LH that?
oh you still get cos(1/x) dont you
mb
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hey guys I need some help.
lim x->1 (x^x -1)/(1-xln(x))
Do I need to check left hand side and right hand side with the limit? Why/why not?
$\lim_{x \to 1} \frac{x^x - 1}{1 - x\ln(x)}$
Ann
ln(1) = 0, so -1 * 0 = 0
yeah so your denominator approaches 1 doesnt it
hold on my bad, the denominator should be 1-x+ln(x), not 1-xln(x). my bad!
please excuse, my brain is fried :(
ah that changes things doesnt it
it does x)
@native marten Has your question been resolved?
right so then for $\lim_{x \to 1} \frac{e^{x \ln(x)} - 1}{1 - x + \ln(x)}$...
Ann
i dont yet see a pressing need to consider two sides separately
huh
well when x->1, we get 1-1 = 0 on the top, and 1-1=0 in the bottom. We then apply lhospital and get ln(x) + 1 on the top and -1 + 1/x on the bottom
that's the derivative of just x ln(x)
not e^(x ln(x))
well, i suppose if you replace e^(x ln(x)) - 1 with its asymptotic equivalent then yes this is what you get
oh ure right my bad
hmm lemme try again
so the top should be exp(xln(x))*(ln(x)+1)
this is what I have then
@native marten Has your question been resolved?
@native marten Has your question been resolved?
This is fine so far
now notice that the numerator approaches 1 while the denominator approaches 0
what does that tell you
not so sure tbh
we cant insert 1 into the denominator as then we would divide by 0
This should be reminding you of a general idea
when you get a result of a/0 (where a is nonzero) after direct substitution, what does that mean
we approach the 1 from left and right?
that's what the $\lim_{x \to 1}$ is saying - you need to consider both left and right hand limits
Civil Service Pigeon
that is not what I'm asking
hmm then i dont know
no
mhm
now consider 2/0.1, 2/0.01, 2/0.001, ...
what do you notice about these quotients
they get smaller?
you sure?
I mean 2/somethign smaller and smaller gets bigger, because the denominator gets smaller
the quotients get bigger
in fact, they tend towards infinity
but here, the denominators are approaching zero from the right
but we can also have the denominators approach zero from the left
aka 2/-0.1, 2/-0.01, 2/-0.001, etc
what do we approach in this case
alright bye ig
minus infinity i think
sorry I had to leave the computer for a sec
so then we get infty and -infty, which means our thing diverges
yes
the division by zero means you approach +infty from one side and -infty from the other
hence does not exist
the idea here is that you're approaching +infty or -infty
okay. And we are approaching from left and right each because x approaches 1, which we cannot put into the denominator directly, therefore we need to approach from left and right each
the denominator approaches zero from different direction as x approaches 1 from different sides
if that's what you're going for
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I keep getting atan(-1) idk what im doing wrong
especially considering this problem is really simple
maybe try inputing an exact angle instead of relying on a function
perhaps
your problem is that (-2,2) is in the second quadrant but arctan always returns angles in the first and fourth quadrants
oh I forgot about that
so -atan(-1)?
wait no
wait yes
no
remember than tan is pi-periodic
i would advise you learn the curves for sin, cos, and tan
I swear im usually smarter than this I just stayed up late finishing a group project my friends forgot about so im currently trying to do calc III off 3 hours of sleep
fr example suppose we imagine the tan function we know it diverges at $-\pi / 2$ and $\pi / 2$
ben
and now we can invert this
yes
yes
o
uh why did it turn from pi into pi/2
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idk 3 hours of sleep does things to brain I meant pi
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is piecewise continuity mentioned so that the Reimann integral is defined?
in the Reimann integral
i remember it was mentioned in a different way
it was something like a finite amount of discontinious points or something like that
does piecewise continuity cover like the least condition
not quite the same but close enough
All sorts of weird functions are integrable
is there a case where a function can be written as this
but isnt piecewise continious
define the space
yea well cant we have a case where it is integrable
but it doesnt satisfy piecewise continuity
(although pretty much every function you work with in practice will meet this condition)
Yes you can
there are lots of weird functions which are far from continuous but integrable
then why havent we defined laplace transformation in that case
literally untrue @wierd greek name
is this not the general definition of laplace transformation?
you can define the laplace transform for all integrable functions (depending on what integral you even use!). but for an ode course you don't need to get deep into the weeds of what functions can be laplace transformed if they won't appear anyway
oh ok
so this isnt the general definition
Because those functions are edge cases and will almost surely never come up in any practical context
yes, it's general enough for the purposes of the course. the same integral always applies, just a matter of when it's defined which they don't want to get into
why dont you provide a theorem instead of something something somebody says
your fellow students will certainly prefer such a definition compared to defining it on some weird function space which they dont understand
say as a lebesgue integral with respect to some other measure and whatnot
so everyone can be precise
yea i understand why they make it simpler
im just here to understand whats true
idk the lebesgue integral
well take an analysis book and 1-2 months
hasnt come up yet atleast
okay so you do not know any measure theory
have fun
then piecewise continuous is enough and move on
and so do some people in chat
i mean i did some stuff
but like idk what lebesgue integral is inside
like what course
and what i need for it or where to start
can we close this section
there are plenty of other channels if you need to chat about something else
what is it in
like when should i learn it
and in what context
wdym i wont need it
i am
Uhm
are you sure
this is the only reason im studying math
i just mean if you close this one and a start a new one you'll get fresh eyes
ben just buzz off
my purpose and role is not to discourage math
but yea i just study math rn without being in uni for the purpose of studying math
but idk in which order to study stuff
what should i do after differential equations
dena told you here
The laplace transform is defined in the easiest and simplest way possible because that’s all you need for 99.99999% of cases
i have completed calc 1,2 i am in middle of calc 3 and im finishing differntial equations probably in the next 2 weeks
literally just pick up any RA textbook and work through it
should i finish calc 3 first?
idk if i should already know the lesbugue integral you said
or im doing something in wrong order
this whole system with doing calc without analysis is weird anyway
just follow some university recommendation for bachelors' in math
i mean i am doing analysis
you will do the relevant things when you encounter them in the book
you are doing calc
well then pick up a fucking book
but idk where to find a well documented in order course
there are a million analysis textbooks
lots
legally is a different question probably
send me one
no

idc
also is the content of real analysis same for every book or does it differ
you can if you want to
yea well im just asking what youd think is best
i could either complete calc 3 from pauls notes and excersices
since i have it in order and then find a source or do at the same time
well I mean every RA book will talk about convergence, continuity, differentiability, integrals etc
in that order
the level of detail etc will of course vary
analysis is calc but done properly
Real analysis is just rigorous calculus
well like for every proof or question i have i always end up on some real analysis thing
i have noticed that
i try to do all proofs of everything i find in calc as in theorems and it is always found in some real analysis context source
but i thought there were more complex stuff outside of convergence integrals etc i thought it was completely different just part of it had proofs
basically
damn
so instead of doing calc and for every theorem searching for proof out of that source it would be the same if i did RA
then whats the point of calc courses if RA is redoing it again properly
not all students need proofs
damn i feel stupid now
what i have been doing is following a calc course and searching outside it for proofs for everything
and it helps when you can focus on the proofs in analysis because you know the general stuff about functions and derivatives etc already
when i could have just done RA
@low locust why can you not send a free book link on RA?
It’s better if you do calc before RA, because it’s easier to prove things when you already know how they work
because maybe you could put some fucking effort into this?
but how will i know if the book is good
look at reviews
are those free?
Bro
oh wait you mean like actual published book
putting in so much effort
do we have to spoonfeed everything to you?
?
maybe recommending real analysis isn't a good idea dena
well that would prob not be free
yeah maybe not
probably not
well he wants to learn it ¯_(ツ)_/¯
why is it not
and if it isnt what is
because
real analysis requires effort
i liturately just want to know if my source is gonna be good
i am putting effort
pick up like spivak
but like for example
there you go
i found pauls notes
pick up spivak
and after i went half way yall said its bad
have you in the past 15 minutes googled for RA textbooks
damn dena
why are you asking such hard questions
what is this a real analysis course?
i found some but i havent searched somewhere to find them for free
well certain sites will have them
i found
this
nvm this isnt real analysis
ok ill check it out
it's called calculus but it's analysis.
btw literally first link is a pdf
show me a screenshot or smth blud
yes.
these are considered RA?
ok so this covers all of what we call Real analysis ?
you absolutely need to be familiar with basics like those
it may very book to book but its good for like as in what math students get taught
in the RA course
right?
...what
its an analysis text yes.
if you consider yourself proficient with basic material, you're not obliged to do it
idk sorry when i hear of Real analysis it sounds more of a way to view math than a course like calc
no i will do it i think i will have gaps in proofs and stuff like that
wow so this just goes over proofs for even very basic stuff
well
it's an analysis text
if you say so
nice thank you @signal yacht appreciate it
does this include any complex stuff aswell?
complex numbers
can you like read the contents of the book?
all books include a table of contents at the beginning
stick to freaking spivak
are they not good?
rudin is also good
baby rudin is
just pick a book
real and complex analysis is about two courses more advanced than what you're studying, it's apples to oranges
but is Mathematicl analysis something else?
you could google for reviews about those books
no.
ok so these 2 are covering the same stuff
but both spivak and rudin are names commonly thrown around when talking about good books
this red one seems good documented and has good reviews
is the mathematical analysis one a combination of RA and CA?
how about you read the table of contents
the mathematical analysis one seems more complicated
it starts with topology stuff
the other one says abstract integratino
but idk what most of what im reading mean
consider googling
well yea but the names arent gonna tell me much
if you had to put them in order
what?
which of those 2 starts earlier on
like topology
in math unis
is many semesters later than RA
so is the mathematical analysis one much more advanced than the other
……so topology is not analysis
idk what it is i just saw it inside the mathematical analysis book
did you
well
the other like this
from my perspective the second one is closer to calculus and atleast where i am now
this one is way too advanced for you
from the description the first one feels like i need a lot more knowledge to even start
like bungo said
take this or spivak
baby rudin or spivak
this is simpler?
whats that mean
pick up principles of mathematical analysis
idk if its a RA text book or something else
i mean im confused on what RA is at this point so many different titles but ill start this
since the other is more advance
do i need to do something else before starting it
in your opinion
analysis is calculus but not handwavy
or does it start with basics
idk about rudin
with stewart, no
tbh i just got scared because it mentioned topology
https://david92jackson.neocities.org/images/Principles_of_Mathematical_Analysis-Rudin.pdf this a correct pdf for it i think
i dunno
doesnt have the wallpaper
if it works it works
yea ig
but like here it says some about complex analyiss
idk if its wrong book or it just has also complex analyiss
cause you said its RA book
pretty sure thats not a part of the book
its promotion material for the publisher
have you never touched a book before? /gen
well
considering that the book is authored by rudin not rudin et al
and the list literally has 'principles of mathematical analysis' in there
no.
it says in preface that this is for first year math students
is RA not 5th semester?
or later
before calc 2/3 ?
I didnt have calc courses
calc 2 and 3 are in highschool
the ones i found from are 8 semesters
3 years. normal bachelor
i dont think series are done in highschool
oh yeah I suppose technically I had calc content in hs
well you get taught integration technicks
but not all of calc 2
but definitely not a dedicated calc course in university
theres multi variable calculus in unis here
or math 1
which begins with calc 3
and then goes into analysis territory
where are you from
india
eh
kinda
not very well
not ideas of convergence actually
so ig half of calc 2 then
ah ok here its 4 years
so you got introduced to basic topology and lesbugue theory and all these in first year?
yes
just forget that this chapter in the book is called the scary word topology
its just about open and closed sets and stuff
its really not that crazy
how can it have like at the middle of the book differntiation and continuity isnt that something ive already done
like mean value theorem is high school material
LMVT is what
oh mean value theorem
yea so because it is continious in [a,b]
it has maximum and minimum
prove that
ok
and that will rely on some other lemma etc
thats the things you do in RA
prove the things you take for granted in calc
i have done that already
well then you are in luck and can go over the relevant pages in the book quicker
we just go 'well it makes sense innit'
what does IVT stand for
this is not a sign to skip the book
oh ok
intermediate value theorem.
idk the english names fr
just because you proved some theorems from it
Using bolzano theorem
you had bolzano theorem in high school?
yes
weird
well the earlier chapters in the book will go by quicker then
but dont skip them
Μαθηματικά Γ΄ Λυκείου – Βιβλίο Μαθητή. Τα Μαθηματικά της Γ΄ Λυκείου ανήκουν στα μαθήματα προσανατολισμού Σπουδών Οικονομίας και Πληροφορικής και Θετικών Σπουδών...
this was my highschool book
it mentions ε,δ defintions too
but arent used in proofs
wdym
?????
analysis without epsilons isnt analysis
i didnt say its RA
but it doesnt have proof for bolzanos theorem
then some theorems for f'>0 f increasing etc
curvature
or whatever we call it in english
Fermat theorem
with proof
by δ definition
@low locust is LMVT supposed to not be before calc 2?
I dont fucking care if you do it before or after
i have done it
good for you
it doesnt matter
time to read #「helpers-lounge」 message
also rolle is proven by fermat theorem
someone asked before
f'(xm) = 0 and f'(xM) = 0
i have seen the Reimann integral with RA and so have i for the properties proofs
thats why i was thinking of starting this
are you even listening to us
isnt this just a Real analysis textbook
so how will it be any different if im still studying the same course
3 people have told you the book is too advanced for you
yea but then yall said idk how to prove LMVT and stuff like that
but ive done that already
like the differentiation and integration proofs a lot i have done
i had some text book irl it was covering big part of those
wdym
does this book not explain everything fully for someone to understand
you said real analysis is just calc but with proofs
like half of this book i have already seen the mathematical analysis one
ill just take this slowly ig
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what is the implicit function theorem?
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When you have a function from R^n to R^m where n > m, the IFT gives you, under a mild condition, the existence of a differentiable function g from R^(n-m) to R^m such that the graph of g are locally the roots of f.
It is mainly helpful to establish that such a g exists, even when you can't write it down explicitly, and that this g is differentiable
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I need help solving/getting the hang of this
during class, i follow through and answer all right but then when im on my own i kinda get stumped
wdym
x^2 - 81 = 0 is the same as x^2 = what?
idk :/
should i take a break? ive been doing alot of hw, i cant think without my head hurting
i obviously know what this is but its not clicking for me rn 😭
-# (well it could help if you could say what you know it to be; else Bungo can't tell whether it does click for you)
if you have something of the form
a - b = 0
that's the same as
a = b
(just add b to each side)
can you apply that to x^2 - 81 = 0?
81?
@green elm I believe that's in response to your message here
-# It's right btw @mild hemlock
like factors?
any other value for x such that x^2 = 81?
i cant think of any other
hint: are there any negative solutions?
Have u got the answer/
oh yeah!! i forgot
-9
because its -81 not +81
no...
x^2 = 81
not -81
but both x = 9 and x = -9 satisfy that equation
because (-9) squared is +81
(recall that negative times negative = positive)
that's you are done
how to u make the equation equal to 0?
subtract both sides?
or add* to make it 0
yep
and then you do the factorization
ill brb
@mild hemlock Has your question been resolved?
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I'm confused on how to go about these questions. I already found Nullspace of identity matrix but I'm having trouble finding range
Start with the null space
Can you tell me what is the null space of the identity matrix ?
N(I_n) ={x:x=0}
So what’s the dimension of the nullity ?
That's not a topic I've seen yet I've only seen range and Nullspace so far
You haven’t seen the range nullity theorem ?
No
Ok so let’s think of the range then. Take a random vector y, can you find a vector x such as Ix = y ?
it would just be x =y
Good so what does that mean for range ?
well I know definition is R(A) ={y: Ax=y} , y is like output I think
Yes basically, it means all the vectors that A can « reach »
So the fact that for any vector y, you find x such as Ix = y
What does it mean for range I
I'm not sure if I understand what you mean
Ok so you define the range of A as all the vectors y that can be written as Ax right ?
This is the definition I've been using
yes
Ok
So we just proved that for I. Any vector y can be written as Iy. So any vector y that you choose belongs to R(I)
So R(I) is the whole space
It’s R^n
dawg whut
well for Ax=y x is in R^n And y is in R^m but we are saying Ix=x and y =x so since x is in R^n then y is also in R^n?
You’re talking about R^n -> R^n here.
Because the matrices’ size is nxn
I understand that part but I don't get where the range part is coming from
Can you remove your message ?
So basically, you agree that y is in range A, if you find a vector x such as y = Ax
?
yes
So every possible vector is in range I
Because if you take any possible vector y, then y = I.y
ma bad
well x=y right can I write R(I_n) ={x: I_n x=x, x in R^n}
Which makes the range of I any possible vector. That means range of y is R^n
Yes, but that’s true for any x
Which makes R(In) = R^n
This R(In) that you defined here works for any value of x
but isn't R^n ={x: x=(x_1,....,x_n), where x_1....x_n are real numbers}?
x is a vector here not a coordinate
Yes ? So ?
how does that set equal to the other set if true
x and y are also vectors ! The ones we’ve been talking about
When I say I x = x, x is a vector
I get that
And since this equality works for any x
That means that any x is in range I
So this gives you that R^n (which is any x) is included in R(I)
Which means R^n = R(I)
so x is in the range of I and x is in R^n so range of I =R^n?
I'm trying to see this logically
No I’m saying.
If you take any x in R^n, it also belongs to R(I)
That’s the definition of R^n included in R(I)
Now since R(I) is by definition also part of R^n
That gives you double inclusion : meaning R(I) = R(n)
is R(I) part of R^n because x is part of R^n
No
R(I) is a subspace of R^n. That MUST be in your course !
Range is part of the coset. Nullity is part of the set
I haven't seen Range of I a subspace of R^n but I have seen proof of Nullspace of a m by n matrix is a subspace of R^n
It’s just by definition
A vector of the range is by definition a vector of the coset that has a preimage
Your teacher sucks. Because he should be more explicit
But he wrote it here
The range is part of R^m (which is your coset here)
By the way this a first course in lin algebra so I'm not familiar with the terms you're speaking about
No, that's the question I'm trying to figure out
Ok, let’s review. By definition, the range is included in R^n, that’s understood right ?
Because the definition of range is all vector y such as Ax = y
So we know that Ax lands in R^n
Because A transforms vectors from R^n to R^n
that's if A =I right
No that’s for any square matrix of size nxn
It takes a vector from Rn as input and gives a vector from Rn as output
in that case I agree
Here, is y in range of A ?
Yes !
If you find a vector x such as Ax = y
That’s the very definition of y is in range(A)
To put it very simply the range is all possible outputs
so since if A is n by n and y is in R^n and y is also in range of A then range of A is in R^n?
Range of A is always in R^n
Range of A is all possible outputs of A
Since A is an nxn matrix. Then it’s outputs are in Rn
well assuming if I'm on right track then I understand so far
Ok, so this is not something you need to show everytime
Just understand that range is all possible outputs ok ?
Now what are all possible outputs of I
?
all vectors in R^n
so was it right in front of me this whole time I know Ix=x so it's going from R^n to R^n so all the outputs are from R^n
Yes it is quite straightforward
Just let me give you a simple way to look at it
The nullity is all inputs that give a 0 output
The range is all possible outputs
That’s always the case
that's Ax=0 right
Yes
So all inputs (x) such as the output (Ax) is 0
So all inputs that lead to a 0 output
Nullspace is kinda weird though I found a non zero vector once that was in the nullspace
if nullity is non zero why is that important
That means that A is singular
Meaning it loses dimensions
Let’s try the other example
I've also seen this definition of range of a matrix is the span of the columns of the matrix
Yes
