#help-19
1 messages · Page 208 of 1
yes
right
ok
so why not figure out what happens with X's finances then
cause his stuff is known and can be calculated in full
(im still shaky if we want the principal + (post-tax interest) to be the same, or only the post-tax interest. but at this point i am afraid to ask)
you dont need formulas, you need some understanding of what is actually happening money-wise and to communicate it sensibly enough for someone else (me) to understand 😭
whats happening? why are they both withdrawing?
because of the financial crisis two years prior
Beautiful command of language there /s
yeah ngl like
the math is less complicated than the communication
also like
the way im trying to solve it
it looks as if the 30% tax rate just ends up irrelevant to the problem
"We want the amount of money Y deposits, so that post-taxation Y ends up with the same amount of money that X does, assuming they both withdraw at the end of 2010"
same post-tax interest == same pre-tax interest, or something
Is probably how I would resolve the question
.
!xy is in order, perhaps
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
i.e. send a photo or a screenshot, ideally
so let me try to dumb this down for myself and hopefully for anybody else reading
its not english
what language is it
the photo
if it's got euros it is most likely some european language
yea
ahem
ok what language
and post it anyway
not what we're asking for 😭
post the original French please
or German or Spanish or Italian or whatever
En quelle langue
-# in what language
graaaaaaaaaaaaaaaaaaaaaaaaah
ok
anyway
i think i have managed to dumb it down for us stupid anglos
X has a bag of money with €8440 in it.
At the end of '06, he puts it into a deposit account @ 4% p.a.
At the end of '10, X withdraws the entire sum from his deposit account.
30% of the INTEREST goes to the tax man; the rest remains with X.
X ends up with some amount of money.
Y also has a bag of money with €???? in it.
At the end of '08, she puts it into a deposit account @ 2% p.a.
At the end of '10, she also withdraws the entire sum from her account.
30% of Y's INTEREST goes to the tax man, and the rest remains with Y.
Y ends up with the SAME AMOUNT OF MONEY AS X.
How much money did Y start with?
if you're so insistent on not giving us the original, untranslated problem text,
then you will have to read through this and tell us whether it is correct or not.
and you will have to make DAMN SURE that you understand everything in both languages and can certify correctness!
swear on your entire family's lives?
do you have something helpful to contribute?
yeah, anyway, you'll still want to begin by working out X's finances in full detail, i.e.
- how much does the total grow to?
- how much does he withdraw, and how much of that is interest?
- how much does he pay in interest?
- in the end, how much cash does X have in hand in '10?
are you going to contribute in any meaningful way to this conversation or are you just going to try to shut me up and nothing else
this is incorrect
30% interest tax does NOT mean simply multiplying the interest rate by 0.7
<@&268886789983436800> harassment/toxicity?
how do i proceed after this?'
you're going to need to hold off on that calculator for a bit, that's for sure.
anyway, €9443.52 is Y's target for her investment operation.
she starts with an unknown principal. let's call it P.
she puts it in the bank at 2% p.a. for 2 years
can you give me an expression for the amount of money in there just before she withdraws it?
don't simplify anything yet.
are you telling me that Y will see the very same P at the end of '10
that would be grounds for her to call up the bank and stir up a shitstorm
cause her shitass bank didnt even fucking pay her any interest
don't you agree?
do you know how to calculate compound interest in general?
maybe at this point you could drop a formula.
but i will require you to tell me what each and every letter in it stands for.
ok let me try to make your formula-search a bit easier.
given a principal P, an interest rate r, and a duration t (in years), what will be the future value of a compound-interest deposit?
give me a formula for this.
only the formula for now, don't plug anything into it.
cool.
ok
now what we have here is that we know the interest rate (2%, so r=0.02) and duration (t=2 years),
but our principal right now is just P (unknown).
plug in the known bits, and keep the unknown bits as they are,
to give me an expression for the amount of money in Y's deposit account just before she withdraws it.
this is almost correct but you did one step that was unasked-for, unnecessary, and counterproductive.
i would have rather seen you say:
[FV = ] P * (1 + 0.02)^2
and it'll also be easier to combine that 1 + 0.02 into 1.02
so, in keeping with the spirit of narrating everything in full detail, we get this:
After 2 years, the sum in Y's deposit account grows to 1.02^2 * P.
Of this, we have P as principal and (1.02^2 - 1) * P as gross interest.
that make sense to you thus far?
aight wonderful.
can you get me an expression for the net interest (i.e. what remains of the interest after taking away 30% as tax)?
don't simplify any numbers.
you can begin your answer with NI =
@dense topaz
ok, shall we go into a reminder of how tax works at the most basic level
.
you definitely understand something wrong.
i have been trying to guide you through the correct thought process, but right now i feel like you're trying to throw it all to the ground and try to do your own thing.
this is both frustrating and upsetting for me.
are you willing to continue with what i'm guiding you through?
yes or no.
ok.
your current sticking point is that you don't know how to apply 30% tax on the interest, correct?
(not interest rate; the interest itself.)
you use something * 0.7, but that something isn't P.
also i am a bit unhappy that i didn't get a clear "yes" nor a clear "no" to my question.
ok, so your confusion is somewhere else?
to repeat something i said earlier:
After 2 years, the sum in Y's deposit account grows to 1.02^2 * P.
Of this, we have P as principal and (1.02^2 - 1) * P as gross interest.
i asked you whether you understood this, and you said yes.
what i now want you to do is to turn this gross interest into net interest by applying 30% tax to it.
Do you know how to do this?
A) "Yes; let me try."
B) "No; tell me how."
C) "Secret third option."
ok
do you know how to apply tax in general? or indeed how to apply any sort of percentage increase or decrease?
ok, how do you do it in general?
forget all this investment stuff and all of the problem data. tell me how to apply a tax (at a known rate) on a sum of money (also known)
that... is going backwards relative to what i'm asking.
the type of question i'm asking is more along these lines:
A fridge used to be sold for €600 but now it's discounted by 15%. How much is its price after the discount?
yes
would be better if you used * for multiplication rather than x
but yes 600 * 0.85 is correct for the new discounted price of the fridge
ok, so you understand that applying a 15% discount means multiplying the price by (1 - 0.15), which is 0.85
yes?
yes
mathematically tax works the same way, only it's applied to incomes and the difference between pre-tax (gross) and post-tax (net) is what the tax man takes away
so,
to apply a 30% tax on the interest, by what should we multiply the gross interest?
no
that would be slapping a seriously hefty 70% tax. you want to tax at 30% not at 70%.
right
so you need to multiply the gross interest by 1-0.3, or just 0.7.
which means, to drag us all the way back here,
that Y ends up with P as principal and 0.7 * (1.02^2 - 1) * P as net interest.
her total cash-in-hand at the end of '10 is thus P + 0.7 * (1.02^2 - 1) * P,
which is equal to [1 + 0.7*(1.02^2 - 1)] * P.
does this make sense to you?
no
i cant still calculate it
you're going to need to hold off on that calculator for a bit, that's for sure.
anyway, €9443.52 is Y's target for her investment operation.
she starts with an unknown principal. let's call it P.
P is Y's starting amount. it is her principal.
im not asking you to calculate anything yet.
im asking you to read the shit i say and tell me whether it makes sense to you 😭
when i want to get you calculating something, i tell you to go calculate it
ok, let's maybe recap the entire story.
i will even put it down on paper.
i think so
recap of all that we've discussed thus far.
please read all this carefully. do not run off to plug shit into any calculators -- i have more to say, but i need you to signal to me that you understand all of this.
when you're done reading, and are ready to continue, ping me.
yes i we can continue
right
now the first part of this rather long conversation was to figure out what condition actually needs to happen between X and Y.
and we got that they have to end up with the same cash-in-hand at the end of all their financial machinations.
yes
now, X ended up with €9443.52.
Y wants to end up with the same.
thus, we have: $$[1 + 0.7 \times (1.02^2-1)] \times P = 9443.52$$
Ann
capisce?
ok, we're one step away now
can you do it yourself
.... no
i think you need to reread my paper photo, tbh
cause we've already accounted for all interest and taxes.
there is zero need to try to apply tax a second time or interest a second time or some ex-recto service fee that we didn't know existed
okay
yes, but show me what you are planning to calculate before actually pressing the = button.
"switch" is definitely a bad way to phrase it.
multiply
Not the right action
You understood up to this point, right?
including how we arrived at it?
Is that to say (1+0.7*(1.02^2-1)) *9442.52?
ye
Because... no?
this is incorrect.
Firstly - just to clarify
A) "Let me try again."
B) "So what should I do?"
C) "Secret third option."
B
That bit in the square brackets is a mess, but it's a number, right?
So we have $[something] \times P = 9443.52$, right?
Waes (Wires)
let me strip it down to its barest essentials
forget about this equation for now and take a way simpler one with the same structure
$8 \times Z = 94$
Ann
how do you find Z in this? @dense topaz
mmm wrong notation.
i think you have the right idea, but try phrasing it better.
i divide both sides
you divide both sides by what?
z=94/8?
"I divide both sides by 8, and this gives z = 94/8."
yes thats correct
your equation looks like
[SCARYNUMBER] * P = 9443.52
do you see what to do now?
it does indeed!
wdym how do you continue
well,
in 8*Z = 94, you divided both sides by 8 because the Z was getting multiplied by 8.
now, in [scarynumber] * P = 9443.52, by the exact same logic, what should you do?
"everything written" is too imprecise.
what exactly are you dividing by?
mmmm okay that's gonna be a no.
what you did there is like
it's as if you saw 8 * Z = 94 and went off to calculate 94*8
try again
right, yes, correct.
so then P = ?
again show only the calculation
ie dont go putting anything into the calculator until i tell you to do it
first off, 9443.52
and second,
let's follow through on what you said,
and divide both sides by [scarynumber],
so you would have $$P = \frac{9443.52}{1 + 0.7(1.02^2-1)}$$
Ann
(i have filled the "scary number" in here)
do you understand this? @dense topaz
no calc yet
ok
now go put that in your calculator
,calc 9443.52/(1+0.7*(1.02^2-1))
Result:
9183.8020772552
alright uhhh
some cents of difference there, i guess?
but ok, good enough i guess. round it off to 2dp (because money) and you are good to go.
can i say one final thing that i would like you to take away from this
math is not and should never be about blindly plucking formulas and putting numbers into them without knowing what you're doing.
every single problem has some logic behind it, and unless it's the sort of thing you could do in your sleep, you should always always always talk it out as fully as you can.
yeah rushing is very bad
Closed by @dense topaz
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Closed by @wooden python
Use .reopen if this was a mistake.
than2s
yes
consider getting an external usb keyboard if yours is this borked
what in the world happened to your kb
5t w6r2s r6er3y b4t s60e sett5ng 5s d5st4rbed
does your kb use uiohjkbnm for a numpad
looks like the case, but either way get it checked yeah
the 2eyb6ard 5s a 3at6 2eyb6ard
wait i think i might know what this is
there 5s n6 n40*ad
does it have an fn key
maybe that thing's stuck and so it's reading your press of the o key as a numpad six etc
was about to ask if you had numlock on
okay
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
that looks like the wrong orientation after reflecting just over the x-axis
I forgot to reset it
what else would be the issue be?
I had to reset where it's position is
okay, and what problems do you have with this question?
other than the whole resetting position thingy that you have fixed
I keep getting it wrong, but I'm confused about translating 3 units to the right
can you do the reflection first?
It's do difficult
sure, do you have an idea where to start then, with the reflection?
you're right in that the triangle would end up on the other side of the x-axis for obvious reasons
but do you at least know how the triangle would be oriented?
if not, you can just reflect each point across the x-axis separately
you will still get the same result as if you considered the triangle as a whole
that's the y-axis
but you've gotten the right idea about reflection
now try doing the same, but reflecting across the x-axis instead
there we go
now from here, a translation 3 units to the right isn't too terribly complicated, i hope?
looks about right
3 units right
I got it correct, thanks for helping me:)
If you are done with this channel, please mark your problem as solved by typing .close
!done
If you are done with this channel, please mark your problem as solved by typing .close
.close
Closed by @jovial iris
Use .reopen if this was a mistake.
.reopen
✅
yo
anything else?
!occupied unfortunately
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
hi, welcome to the mathcord! check #❓how-to-get-help and open your own channel 
you can either calculate it or do it visually
for calculating, you can set D as the origin and then multiply all the coordinates by 2
to do it visually, do smth like this with the line you have and make sure the base is two times the original base
I don't usually know how scale factor of 2 looks like
@jovial iris Has your question been resolved?
@jovial iris Has your question been resolved?
Closed by @jovial iris
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
With permission, @amber veldt
Excersises on induction would be much appreciated ❤️
Sure
from Knuth
Define the Fibonacci sequence as follows:
$$F_0 = 0$$
$$F_1 = 1$$
$$F_n = F_{n-1} + F_{n-2} \text{ for } n \ge 2$$
gfauxpas
gfauxpas
gfauxpas
We will prove $F_n \le \phi^{n-1}$, and then as an exercise you will prove that $F_n \ge \phi^{n-2}$
gfauxpas
Call the property "$F_n \le \phi^{n-1}$" $P(n)$
gfauxpas
Oh, did not know that you can do that!
forgot to see we're proving it for all $n \ge 1$
gfauxpas
If $n=1$, then $F_1 = 1 = \phi^0 = \phi^{n-1}$, so $P(1)$ holds.
gfauxpas
so not n >= 2 okay
one is weak, the other is strong
lol
uhhh, does it have to do with boundaries?
strong induction is, instead of assuming it's true for some k, you assume it's true for all numbers up to k
it sounds stronger than induction, but you prove it by induction
that it works
okay, so different starting assumptions but same technique
gfauxpas
so P(1) and P(2) are both true
this is quite common, needing two base cases
okay so induction hypothesis:
assume P(1), P(2), P(3), ..., P(k) for some k
note that we're assuming then that
$$F_{n-1} \le \phi^{n-2}$$
$$F_{n} \le \phi^{n-1}$$
gfauxpas
adding these together we get
$$F_{n-1} + F_n = F_{n+1} \le \phi^{n-2}+\phi^{n-1} = \phi^{n-2}(1+\phi)$$
gfauxpas
$$=\phi^{n-2}\phi^2 = \phi^n$$
gfauxpas
we showed that $F_{n+1} \le \phi^{n+1-1}$ and the result follows by induction
gfauxpas
questions?
What is the name of the book and do you have the page number/excerise number?
The Art of Computer Programming Volume 1 by Donald Knuth
I'm taking screenshots and printing it out so I have something to do on the train
this was from section 1.2.1
Exercise 1.2.1.4 is:
Prove that the Fibonacci numbers satisfy $F_n \ge \phi^{n-2}$
Guess I'll loan the book from the library tomorrow then!
gfauxpas
I'm actually excited to attempt this in the morning
Is it okay if I ping you tomorrow to share my proof if I can't find the book/my proof differs from the books?
sure
Thank you once again Gfauxpas
I really, really am thankful ❤️
Screenshots printed, time to head to bed
Goodnight, Gfauxpas ❤️
.close
Closed by @elder wasp
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
can someone help pls
,rotate 180
@tawny coral Has your question been resolved?
<@&286206848099549185>
what have you tried?
i don’t even understand what the question is asking tbh
you're trying to cover the triangle in the diagram with a bunch of hexagons that are cut into equilateral triangles
ohhh
it gives you the length of the diagonal of the hexagon (which means you know the side length of the small triangles), and also the side length of the surface
can you take it from here?
no, the hexagon's diagonal is 20 cm
"the shortest distance between opposite vertices"
= diagonal
the 0.6 cm refers to the surface that's in the diagram
@tawny coral Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
How do I calculate the surface area of these figures
,rotate
addition and subtraction of areas of common figures
for the fist one consider drawing a rectangle around the triangle
there are some tricks you could apply for the second and third one:
move a piece somewhere else and you'll get simpler shapes to work with
what did you do after that?
there is a way to use the lengths you've determined to get the area using herons formula,
but that's quite tedious and not the method I was hinting towards
Pythagoras isn't needed here
did you do what I recommend and draw a rectangle around that triangle?
yup
now the sum of the areas of the
shaded and the 3 newly formed white triangles will give the area of that rectangle
i got a
calculated the entire rectangle
then the 3 new triangles
and did the entire rectangle area - the 3 triangles area
i got 5,5 cm2
yep
i meant that whoops
wrote it down withthe 2 tho
c is hard tho
i got 7,55 cm2
is that correct?
can you show your work?
and don't round
don't use decimal approximation for pi
leave pi as pi
and don't use a calculator for this, it's not needed
my head calculating is not that good so i used calculator
oh this couldve been way easier
the numbers are small enough that is more than reasonable to do on paper
and leaving pi as pi, you don't have to do anything with long decimals
move 1 piece of the circle to bottom right, then calculate half the circle and the rectangle
0,5 x pi x 1^2 = 1,57
1,57 + 6 = 7,57
but how do you calculate out of your head with pi
leave pi as pi
e.g 5pi would be 5pi and leave it as that
in your case leave 0.5pi as 0.5pi
or write that as pi/2
so you'd leave the final result as
pi/2 + 6
that makes sense
thank you
but what if r was more than 1
how would that work
dont know that from the top of my head
so if i write down 9pi on a test as an answer it should be correct
yes, unless told to round
okay, thank you very much
@opaque dagger Has your question been resolved?
Closed by @opaque dagger
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I know for a) the meaning of g(4) is if the insulation depth is 4 inches, the estimated annual heating/cooling cost is $2750
How would I explain b and c?
For b) I know that g(9) is 1500
well, look at what g outputs and what f is taking. does it make sense to use the output of g as the input to f?
(for b)
for c, do the same thing but with the input of g and the output of f
@earnest zenith Has your question been resolved?
Thanks
Closed by @earnest zenith
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Is the thing in the yellow right? I double checked using lhopitals but I used the trig Identity and I got 0.. but like I I have 0/0 since sin also approaches 0 so idk if it counts as being done
i don't really see how you just conclude that the limit is 0 in the second line
Do you even need a trig identity here? You can just seperate to $\lim_{t\to\0} \frac{1}{sin(8t} - \frac{cos(8t)}{sin(8t}$
fucking hell
$(\lim_{t\to 0}\left(\frac{1}{\sin(8t)}-\frac{\cos(8t)}{\sin(8t)}\right))$
Stitches
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
@dreamy totem Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hi im doing a chapter on the homomorphisms and the isomorphism theorems in group theory and was wondering if i could have a hint for this question
ive figured out that $ \mathbb Q /\mathbb Z$ comprises of cosets in the form $q \mathbb Z$ where $q \in \mathbb Q \cap [0,1)$
lifelong dumbass
disproving isomorphism of groups is way easier
by finding eg an element in one with some property that cannot ever possibly be satisfied in the other
a really easy property you can always check is orders of elements
lifelong dumbass
which has order 4
with exception to the identity, every element in $\mathbb Q $ has infinite order
so you can't produce an isomorphism
sorry is that wrong
or
no thats totally right
Closed by @languid orbit
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
with this, why did he write f’(x)>0, shoudnt he have written f’(2)>0
,rccw
I mean I guess you aren't wrong
looks like he wants you to first say that f'(x) > 0, then can you conclude it is increasing
Yea
Yeah you're not wrong, he was just trying to explain that if f'(x) > 0 at your point of itnerest (x = 2), function is increasing
You could also do f'(2)=56>0
Saying f'(2) > 0 would probably suffice, but you did neither
even f'(x)>0 is bad imo, u shouldve justified that f'(2)>0 though
My teachers accept that kind of presentation
Ion if yours would though
So next time I just write f’(2) >0 - increasing
Ye
@shrewd trellis Has your question been resolved?
Closed by @shrewd trellis
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I need some help on this
I'm so confused where to start
I feel like I should plug in 39 m/s in for t, but its not a time
But I'm also given two time intervals for each question
But how do I find the distance?
Divide the time intervals by the velocity?
to get position?
*multiply
Have you learnt integral mean value theorem
isnt this derivitives?
^^
Ye
Average velocity is displacement/time
from physics I feel like I should do this
So I guess you just integrate to find the displacement
Ye thats what I thought
That would give average acceleration
Well in this case it's a bit more complicated than that actually
Have you learnt integration yet
they don't need to know this for now
isnt this just avg rate of change not integral mean value theorem
acc
the average velocity is just (change in distance) / (change in time)
Oh nvm
very different
so $\frac{h(t_2) - h(t_1)}{t_2 - t_1}$
south
Welp alright ye
y2 - y1 / x2 - x1
vavg = (h(b)-h(a)) / b-a
oh yeah
Sorry bro I was holding my breath a few minutes before this fr
ah fuck its that formula
same thing i said
where do I start tho 💀
use the formula for the given points
then round
i think thats
literally it
I can't read I'm a deltarune fan
but how do I find f(x+h) ?
oh yeah mb
thats what I'm lost about
just write until 4 dec places
oh makes sense
just do (h(8) - h(7)) / (8-7)
for avg rate of change
damn bruh
no, h is the height function
that's not the same as the h for 'small change'
we're not using this kind of h cause we already have two different points
so we just sub in the numbers
vavg = h(b) - h(a) / a - b
vavg = h(7) - h(8) / 7 - 8
vavg = 232.33 - 258.88 / -1
vavg = -26.55/-1
vavg = 26.55
And the instructions also do say to round to 4 d.p
holy shit im cracked
So do round
mb
how the hell you get 7
h(7)
yeah i figured
was thinking abt a different formula
denominator should be 8-7 first off
h(7) is NOT 7
,calc 39 * 7 - 0.83 * 7^2
Result:
232.33
pretty sure he forgot the 8
Is see
why is h changing tho?
try #2
h is your function
the function isn't changing
im inputting 7 and 8
you put in two different time values ^
and then it gives me 232.33 and 258.88
Ok let me try something
No
the intuition behind AROC is that it is the gradient of the secant line connecting the two points (a, f(a)) and (b, f(b)).
you are getting a rough approximation of the overall change during the interval b-a
ur essentially just going back to grade 9 math and using advanced formulas to do them
ay man you done
same thing
it is
that is another formulation but u dont need that here
theres no use for +h
The process here is just this with smaller and smaller values of h for x=7
Right, thats the average.
arent we just using the given intervals but theyre already precalculated
I thought they were asking for the derivative
so we dont need to add or subtract h
which I was confused about
they are
they are not
Ye they aren't
the derivative is a local approximation
im a lil lost
they are asking for AROC
dont they solve for
not instantanous slope
the exact same
oh wait
they dont
yeah
cant you calculate the slope at a point using derivitives
yes u can
the essence of this exercise is that as h->0 (the increment in the x values), the local approximation for change gets better
gotchu gotchu
great
"ahead of my class" and its power rule
Its somewhere
derivative visualization
haku just a hater
Yes I see
yeah because being ahead of your class would be doing calc 1 in grade 9
which is what i did
Cool
Good for you
😔 🥀 🥀
I was employed
Surely this man is the genius of our generation
I couldn't
hey look all im saying is
you arent really ahead if power rule is quite literally the next lesson
I do know chain rule, quotient rule and some integral shit too
I just messed around with some stuff
Let a man have his victories 💔
Yes please
oh nice
wait is this
highschool calc or
uni calc
college
ye?
ah gotchu
wait
dont you learn all of this stuff in gr12
chain rule quotient rule all of that stuff
People have different paths in education
makes sense
idk jst a lil lost i dont live in america
just calc 1
I look at calc 2 and was like
uhhh
taylor series 👍
anyway @graceful viper @cyan cape @shell haven thank you for the help!
really helped a lot
I got one more question tho
if thats fine
Is there no limit?
I'm a lil lost
as x->10, what happens to 8?
Are horizontal lines
doesn't change???
because its not a coefficent of x
so it it just 8
Ye
yeah, '8' is a sneaky way of saying y = 8
and when you think about what y = 8 means, that means that y is always 8, no matter what x could be
cause the limit is always of some function
that function can be thought of as f(x) sure, so f(x) = 8
or it can be thought of as y, so y = 8
no worries!
I got one more
I can't figure this out
I thought is was 1
but its not
then I thought there was no limit and its not that either
OMG ITS -5 FUCK
one sec
yeah take your time to factor it
got it
dumb mistake
@warped glacier
Or this is something I forgot
it equals 0/0
I do a^2 - b^2 right?
or is that something else
yep!
Whats my b and a tho?
well, you can compare $25 - x = a^2 - b^2$
south
no
hm?
I'll give you another minute
clearly that's not 25 - x
so a = 25 and b = x doesn't work
so
(25-x)^2 - (5- root x)^2
?
$(25-x)^2 - (5- root x)^2
Why doesn't it do the thing
@warped glacier
$(25 - x)^2 - (5 - \sqrt{x})^2$
south
you're overcomplicating it
that what I said
here, $25 = a^2$ and $x = b^2$ will make it work
south
$south likes billies$
Adrift
w
hold on im working on it
@warped glacier is there no limit?
the bottom is zero
no
it's the same trick, factor something out so that you can cancel on top and bottom
you're still on this problem right
yes
can I factor 5?
but I don't understand because
wouldn't x need to be involved?
is it -5 @warped glacier ?
remember you wanted to find a and b here right
oh wait
so yes, a = 5 works
I have to multiply by the reciprocal right?
no
it's a difference of 2 squares like you said earlier
right?
i said -5
so what's b here then?
after that you can just sub into (a + b)(a - b) directly
oh you meant the conjugate
so 5 + sqrt(x)
yeah that works
@jaunty minnow Has your question been resolved?
Closed by @jaunty minnow
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Limit evaluation, eliminating radicals in expression with conjugates, is this correct? Offer feedback
$$ \lim_{h \to 0} $$
Kolo
in 1st pic
Appears fine yeah
Thanks, do you have any feedback?
Not really, your workings are clear, this is typically how you deal with limits that have square roots in them. Good job 
.solved
Closed by @restive lodge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
to the nearest integer
$4\log_2(3^-1)$ ?
Alexis_Fx
or
$\left(4\log_2(3)\right)^{-1}$
Alexis_Fx
bruhh
amazing
$4\log_2(3) - 1$
Alexis_Fx
yes
to the nearest int?
yes
Throw away the -1, put it back at the end
and the log 3 base 2
how do i do that
Can you use a calculator?
if i could would i have asked 💀
Fair enough
,calc 3^4
Result:
81
Why didn't you start with that
so its like 6
,wolf 4 log_2(3) - 1
they want [gif] in the original question so 5
yeah ok
yeah we can take one off in the end
yeah
$c \log_a(b) = \log_a (b^c)$
Percy
yeah that part i got
haan toh
how did they bring 6 and 7
oh
(iitb cs pakka)
at least youre studying
.close
Closed by @solar peak
Use .reopen if this was a mistake.
it was the last part of an advanced question
of integration
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Is there a Bose integral like identity for when n is an even integer
In particular, I’m interested in solving an integral of the form t^2/(e^t - 1)
Pretty sure you can do that using the geometric series
the best closed form for the bose integral that i know is $$I_n = \Gamma(n+1)\zeta(n+1) = n!\zeta(n+1).$$ So if $n$ is even, you are trying to find $\zeta$ of an odd integer, which i dont think has been done yet
haseeb
as for n=2, zeta(3) is known but we dont know a whole lot about it: we have some continued fractions, and whether it's transcendental is an open problem. so this method probably doesn't work :/
@tall cairn Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
guys i dont understand why they wanted to know the area between 2 and 3 first
then why did they minus by 1/2 at the end?
$$\int^{3}{m} f(x) \dd{x}=\int^{3}{2} f(x) \dd{x}-\int^{m}{2} f(x) \dd{x}$$ and $\int^{m}{2} f(x) \dd{x}=\frac{1}{2}$ by definition.
Civil Service Pigeon
@timber patio Hello?
yes
ohhhh
If you are done with this channel, please mark your problem as solved by typing .close
Closed by @timber patio
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hey i would like to know if my steps are legit :
what's p
uh ok first off am i meant to read this left to right or right to left
left to right lol
anyway uhh
kinda random but
why's there a random floating infinity in the 3rd line 😭
a lot of these inequalities are quite dodgy, including the pink ones
...due to those very same floating infinities
lmao yeh my bad
ignore those floating infinities lol
😅
ima fix it
this one without them floating infinites lol
ig theres a better sol
yes there is
first since we have p(x) and p(1/x) in the picture, it doesn't hurt to figure out what these guys approach as x->+∞ -- and you've already done that, getting +∞ and -1 resp.
now looking at this motherfucker.
yeh thats y i did those 1 and -1..
- deg(p) = 4 and the leading coeff of p is 1
- so the 2p(x) term behaves like 2x^4
- and 2x^4 - p(x) behaves like 2x^4 - x^4 = x^4
- p(1/x) approaches -1 and so behaves as a constant
- p(x)/(1+p(x)) -- you've worked this guy out separately, it approaches 1 and so is also a constant
yeah i object to the breaking of the limit over the fraction bar tbh
you cant do that to ∞/∞ limits so brazenly
has your class taught you big-o or little-o notation?
it is going to make things very convenient and workable here.
you mean bounds?
not yet
rip
ok then i guess you have to do something like
figure out ex recto that both num and denom behave as cx^4 plus some small bullshit
then divide num and denom by x^4
figure out that this makes them both have finite limits
compute those
also if ik each blue limit exists?
and win
the two left ones are infty.
youre right sry