#help-19

1 messages · Page 205 of 1

pastel steeple
#

you should probably find all the holes first before answering
this will also help for free response questions

odd edgeBOT
#

@atomic lotus Has your question been resolved?

odd edgeBOT
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next knoll
#

hey

odd edgeBOT
next knoll
#

is anyone there

mystic nova
next knoll
#

...

ornate bolt
#

yeah hello

mystic nova
#

Just send your question dude

next knoll
#

I need help with 1 thing

ornate bolt
#

xD

next knoll
#

what is Year 9 first term topics mainly?

strange aspen
next knoll
#

Uk

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if u mean school

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Ark john keats

mystic nova
#

England?

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Wow

wooden python
mystic nova
#

His school have a website lol and it lists everything pandascreams

odd edgeBOT
#

@next knoll Has your question been resolved?

odd edgeBOT
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summer nest
#

I've been doing a problem where I have to find out which of the following is larger:
1999^1999 or 2000^1998
My thoughts are shown above, to simplify, I've attempted to make the exponents the same but I don't see a clear way to continue. Is my method correct? What do I need to do next?

smoky nacelle
#

you can't use a calculator, right?

summer nest
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No

smoky nacelle
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oh lord

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but i don't think you gotta take the 1998 root out

safe vapor
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You sure line 3 -> 4 is correct?

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sqrt(a * b) is sqrt(a) * sqrt(b)

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not sqrt(a) * b

smoky nacelle
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i think it's an exponential problem

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not a square root thing

safe vapor
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Yeah, but OPs work is wrong regardless since he didnt distribute corretly

smoky nacelle
#

wait, the 1999(1999^1998) or smth?

wooden python
#

hold on

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are we allowed to use stuff involving logarithms

summer nest
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Yes

safe vapor
#

you can use the definition of e if that's allowed

summer nest
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The book doesn't cover logarithms at all though

wooden python
#

well step 1 would be to translate from comparing those big powers to comparing their logs

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i.e. $1999 \ln(1999)$ vs. $1995 \ln(2000)$

clever fjordBOT
wooden python
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and then maybe try to look at their difference

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and write $\ln(1999)$ as $\ln(2000) + \ln\paren{1 - \frac{1}{2000}}$

clever fjordBOT
summer nest
#

Is there anything you can recommend for learning logarithms? I've never learned them properly

summer nest
safe vapor
#

You can solve without logs if you want to use the definition of e

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You can even do so without e or log. what math do you know so far?

summer nest
#

I'm going into yr 11 (uk) if that helps

wooden python
#

my idea's a bit calculus-y in flavor tho

summer nest
safe vapor
#

inequalities is very broad

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does bernoulli's inequality ring a bell? What about induction?

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if not, have you learned e at all?

summer nest
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That's what this chapter specifically mentioned. I have learned induction & fairly basic things with e

noble ether
#

Wait

next knoll
#

no

safe vapor
#

Yeah that works if op knows limits/definition of e

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But in analysis contexts we typically can't cleanly define e or ln so its usually off limits

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Bernoulli's does the same thing effectively, but that's hard to know a priori

odd edgeBOT
#

@summer nest Has your question been resolved?

summer nest
#

Is there anyway to do that without e?

noble ether
#

Reasoning is one way

safe vapor
#

You can use bernoullis inequality

summer nest
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Haven't learned that

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I think I'm best off finishing the book and coming back to it. Thanks all for your help!

#

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odd edgeBOT
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last junco
#

I have the line -x + 4*y - z + 5 = 0, how do i find each of the variables cutting with their axes?

graceful viper
#

for example, the x intercept occurs when y=0 and z=0

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u can do this with other intercepts too

wooden python
#

!xy

odd edgeBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

last junco
last junco
#

.close

odd edgeBOT
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wide pollen
odd edgeBOT
wide pollen
#

i was needed to prove that the integral on the red brackets diverges

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so i did the inequalities as shown but with the integral, but now im thinking that doing those inequalities without the integral is even better

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then just show that the last inequality works so it diverges

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whats your opinion?

modern sundial
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I'm not sure what you are asking exactly, but it might help if you just review the statement of the integral comparison test

wanton bison
odd edgeBOT
#

@wide pollen Has your question been resolved?

wide pollen
#

thx yall

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celest zenith
#

I'm doing factorising by grouping and this is homework so it's okay for me to have the answer. I was wondering where I went wrong with my working out because I'm super confused on how to factorise this

waxen talon
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factoring does not work like that

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you are wrong from second line to the third line

glossy basin
celest zenith
#

thanks, i was pretty unconfident with my working out on those lines because I just didn't know what to do. I'm not sure how to do it either way

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i'm not sure what to do bc my notes and previous questions had an obvious hcf like these:

celest zenith
glossy basin
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you need something common in each term to take some factor out

celest zenith
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ok

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whats wrong with my second line because i feel like i tried to take out the hcf

waxen talon
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your second line is not wrong technically

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but you need to find something common as shubh said

celest zenith
waxen talon
celest zenith
#

oh

waxen talon
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oh and since you checked your answer

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uhm

celest zenith
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it's homework i don't think it's cheating

waxen talon
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but still

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knowing one factor

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and factor out the other based on that known factor is an important skill

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let me try to give you an example

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$x^2 + 3x + 2$

clever fjordBOT
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1 divided by 0 equals Infinity

waxen talon
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well if you use a calculator

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you would find $x = -2$ and $x = 1$

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
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if $x^2 + 3x + 2 = 0$

celest zenith
#

yea

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
#

so you would find yourself to have a factor of $x + 2$ and $x + 1$

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
#

so based on the factor $x + 2$ for example

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
#

you can split the $3x$ into $2x$ and $x$

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
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because $x^2 + 2x$ gives you $x(x + 2)$

clever fjordBOT
#

1 divided by 0 equals Infinity

waxen talon
clever fjordBOT
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1 divided by 0 equals Infinity

celest zenith
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ok

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im so lost can i close this channel anyways if it isn't solved

waxen talon
#

well if you want

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use .close

celest zenith
#

thanks for ur help

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.close

odd edgeBOT
#
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waxen talon
#

im not the only one helping here lol

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you forgot the other person

odd edgeBOT
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lofty kernel
#

hi can i get more explantion about the question

woeful briar
#

Weird question

south plume
#

no

woeful briar
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Oh yeah its x on the left mb

south plume
#

yup i also got fooled by that lol

woeful briar
#

Well that integral is bounded above by the integral of 1/2sqrt(x)

south plume
#

it simplifies quite nicely

woeful briar
lofty kernel
#

Like that?

woeful briar
#

Yeah

lofty kernel
#

can i get another hint i dont see how would i procced

woeful briar
#

Calculate that integral

woeful briar
lofty kernel
#

i calc the integral and got x^3/3

woeful briar
lofty kernel
woeful briar
lofty kernel
woeful briar
lofty kernel
#

yeah soryy

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sorry

woeful briar
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don't be sorry

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its fine

woeful briar
lofty kernel
woeful briar
#

but this is less helpful since we get x on both sides

woeful briar
lofty kernel
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no

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yes i need to write formal proof

woeful briar
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to show this fact you can use rolle's theorem (if for a differntiable function satisfies f(a)=f(b) then there is some point a < c < b where f'(c)=0)

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but anyway... assuming this fact, what you want to do is differntiate both sides and look at which derivative is bigger

lofty kernel
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isnt any otherway to solve this

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instead of derv

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@woeful briar

woeful briar
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I can't think of an easier way

lofty kernel
#

ok thanks

#

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odd edgeBOT
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frail phoenix
odd edgeBOT
frail phoenix
#

How the do I prove this?

wooden python
#

consider that this could also be written $a^2 \neq 4b+3$

clever fjordBOT
wooden python
#

which in turn translates to $a^2 \not\equiv 3 \pmod{4}$...

clever fjordBOT
frail phoenix
#

They just gave 2 letters and a number

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Do I root?

frail phoenix
wooden python
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a^2 = 4b+3 does imply a is odd, and you can go that way if you want, but it's going to be a bit long and unenlightening

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do you know modular arithmetic at all?

frail phoenix
wooden python
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right ok

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then sure put a=2k+1

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ig it will be cleaner to work with the equation a^2 = 4b+3 having started with an "assume towards a contradiction that such a and b do exist"\

frail phoenix
wooden python
#

not... quite, no.

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plug a=2k+1 into a^2 = 4b+3 for now, and show what you get.

frail phoenix
wooden python
#

right here is where you could have stopped, really.

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on the left you have something that's always a multiple of 4.

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on the right, something that decidedly isn't.

frail phoenix
#

Oh so it's a contradiction then

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I see

frail phoenix
#

Safe

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odd edgeBOT
#
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wooden python
#

but you're welcome.

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.reopen

odd edgeBOT
#

frail phoenix
wooden python
#

can you edit that word out please

frail phoenix
#

Done

#

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wooden python
#

ok thank you

odd edgeBOT
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reef sinew
#

How do I start this? Calc 1 no calculator.

wooden python
#

,rccw

clever fjordBOT
wooden python
#

c) ?

reef sinew
wooden python
#

sounds like they might expect you to make a to-scale graph with the points provided and then trace a smoothish curve through those and measure the slope of the tangent to that...

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i dont see anything else

reef sinew
#

Aw I was hoping I didn't have to do that

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Thanks

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slow cradle
odd edgeBOT
slow cradle
#

does anyone

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understand

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what the question is asking

woeful briar
#

there 5 graphs of 5 functions

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they ask which graph is of h(x)

slow cradle
#

yes

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oh wait

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nvm nvm

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worthy ravine
odd edgeBOT
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solar edge
odd edgeBOT
solar edge
#

i can't figure out how to do ii on part c

strange aspen
solar edge
#

i found these

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sinx = 2/sqrt(5)
cosx = 1/sqrt(5)
tanx = 2

cosy = 3/sqrt(10)
siny = 1/sqrt(10)
tany = 1/3

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do angle difference in reverse
idk what u mean by this

strange aspen
#

you know how to do sin(x-y) and cos(x-y) in general yeah ?

solar edge
#

yh

strange aspen
# solar edge yh

just go backwards as in
sin(x)cos(y)-sin(y)cos(x) = sin(x-y)
same with cosine

solar edge
#

and just see if i can do the arcsin or arccos of that without a calc?

strange aspen
#

it should give sqrt(2)/2 or 1/sqrt(2) in one way or another

solar edge
#

yh u were right thx

#

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simple oar
#

what does rotation about a unit vector or any vector mean?

bitter lagoon
#

And keeping the base same

zinc glacier
#

rotation about a vector just tells you the axis of rotation and the direction for right hand rule

simple oar
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but like what does 90 degrees about a unit vector mean?

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like if i were to rotate 1,0,0 90 degrees id get 0,1,0

amber veldt
#

example

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Earth is being rotated about its rotation axis

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which is not orthogonal to the plane through the equator

simple oar
#

yeah

amber veldt
#

for a unit vector, it would be poiunted along the rotation axis, but have norm 1

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for rotating a single point

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just pick your address on the globe

simple oar
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so if i rotate a 2d vec 0 degrees with relation to another vector

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they line up with each other?

amber veldt
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in R2, the "axis of rotation" becomes a point

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which is the origin usually

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but any rotation 0 degrees should do nothing at all to the vector no matter how you define it, right

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has to be

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for it to make sense

simple oar
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so example if i had this
with relation if i wanted to rotate it 10 degrees i would need to move green vector 10 degrees closer to the blue vector?

amber veldt
#

it's annoying because such a rotation would not be linear so i dont want to do it

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best to create a coordinate system where the point of rotation is the origin

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by a change of coordinates

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but the answer is no

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rotation rotates

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it's not a linear movement

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unless it's about the origin

simple oar
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yeah it rotates so the angle becomes 10 deg smaller but the vector keeps the same magnitude

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wont be a linear movement

amber veldt
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dont know what you mean by 10 deg smaller

simple oar
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so i want to rotate 1,0 10 degrees with respect to that 0.7, 0.7 vector

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if the angle between them is theta. Would rotation not just make that angle theta -10 ?

amber veldt
#

this would be rotating it about the vector

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do you realize that's what it does or did you have somethign else in mind

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because i think maybe you had something else in mind

simple oar
#

woah yeah im delusional

amber veldt
simple oar
#

okay so basically rotating around the vector

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is as if the end of that vector is the "new origin"

amber veldt
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is not a linear map

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unloess you make it the origin

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of course it's approximately linear for a small range of theta

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like if you wanted a rotation matrix for theta in (-9.9, 10.1)

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it would be approximately linear

simple oar
#

so we want somthing like this then we can sweep the vector theta degrees so if i wanted 90

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i would have 0,1 still

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?

amber veldt
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not sure what you mean sorry, if youre in R2 why do you have 3 coordinates

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what is (0,1,0)

simple oar
#

mb

amber veldt
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i'm saying simply this

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let's say you want to rotate a vector around the point (x,y)=(2,-3)

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im saying do a change of coordinates (u,v)=(x-2,y+3)

simple oar
#

okay wait lemme try

amber veldt
#

actually its tricky

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because if the determinant of the transformation you make isn't one

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the rotation won't be the same magnitude in the (u,v) plane

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hmm

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so you'd need to choose the right denominators

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to make the map have determinant 1

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i forgot the details sorry

simple oar
#

😭

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whats strange to me is i've touched determinants in other courses but not this one.

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I think he wants more of an intuitive way of rotation

amber veldt
#

if you're rotating a bout the origin everything is easier

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are you sure thats not what youre doing

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because if so, if you call the rotation map on vectors r, then the matrix you want is just [r(e1) r(e2)]

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like the general method of defining a linear map by what it does to a basis

simple oar
#

ngl

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im so lost

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and ive never seen stuff like this [r(e1) r(e2)] bearlain

amber veldt
#

have you learned about matrices

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what class is this for

simple oar
#

mechanics

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so its just vector maths and some physics laws mostly

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this is the OG question. I just think theres a more intuitive way of doing this than we have been approaching it

amber veldt
#

none of these are 2d vectors Nyxzore!

simple oar
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yeah i was just asking how to do 2d

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so i could take that concept higher to 3d

amber veldt
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okay i thought it was for linear algebra so i was using linear algebra notation

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my bad

simple oar
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np

amber veldt
#

anyway im goiong to have food now, so someone will have to take over

simple oar
#

ty for help!

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< 3

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.close

odd edgeBOT
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wanton bison
#

Subtract the white triangle from the great one

faint stump
#

How do I find the area of the white one

glass vault
#

does it say anything about the white triangles height

faint stump
#

No

glass vault
#

id assume white triangle is half the height of the black triangle

faint stump
#

Ok

glass vault
#

because otherwise its ambiguous and has no answer

ripe elbow
#

Nvm

restive fern
#

No because you have no other angle and you are missing 2 sides

faint stump
#

.close

quasi sparrow
faint stump
#

Wait I need help on a question

brazen hare
#

since there's that 'equal side' marker on the vertical height of it

odd edgeBOT
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sleek talon
#

I am trying to get several answer regarding probabilities. The problem stems from a game. The game involves random pets spawning. I have calculated the base probability of each pet. In total 675 pets come out every hour. Of those 675 pets, i have caculated that two base probabilities. 1 for the rarity of the pet and 1 for the type of pet:

From that information I am able to determine the probability rates in this attached picture.

The problems i need solved:

  1. Id like to know if the estimated drop rates and wait times are correct for the suggested probability. I am using AI to do these calculations and i keep getting different answers.

  2. I would also like to know the probability and wait times for a "special event" that occurs 15 minutes past every hour.
    During this special event, only two types of pets spawn. They alternate between normal and fire.
    Is it as simple as halving the base probability? or is it more complicated? I have again used AI to do these calculations and the wait times for fire event seem way off to me.

odd edgeBOT
#

@sleek talon Has your question been resolved?

sleek talon
#

The wait times for the graph posted seem okay at first but are really off once it reaches secret. For example i know that the average wait time for a secret normal pet is no where near 49 mins. A previous table gave me an answer of 6-7hours which sounded way more reasonable.

tidal matrix
#

you said the special event has "normal and fire," but i don't see a "fire" type. was it something else instead perhaps?

sleek talon
#

during the first hour only normal, gold, crystal and rainbow spawn. After every hour there is a special event that spawns only normal and fire type. During this time period every pet coming alternates between a fire pet and a normal

#

This is the first chart i made this morning. The times here appear way more reasonable. The biggest thing i did was drop the probability of secret rarity from 0.025 to 0.020. Along with that change i also rounded off most of the numbers in the base probability.

You can see in this graph a normal secret is listed as 6h26min spawn. But in the graph i posted earlier it now lists it as a 49 min spawn. With a lower probaility how does that make sense?

tidal matrix
#
  • how often do pets spawn normally?
  • is the normal spawn also running on top of the special event?
  • how often are spawns during the special event? how long is the special event?
  • what's the percentage of pets that are fire type?
    this would all factor into finding the wait time, specifically
sleek talon
#
  1. 675 pets per hour.
  2. yes? Only normal type and fire type run during the event. All rarities from common to secret.
  3. Spawn time between pets in the event is the same as during normal conditions (around 5 secs per spawn). The event lasts 15 minutes.
  4. 50/50. They come out 1 fire 1 normal during the fire event.
tidal matrix
#

ohh ok, sorry i thought you said 675 pets in the game - thats on me ;-;

#

i am unfortunately not fully sure on this. it might help to show what formulas your table uses. my instincts also tell me that this could be modelled by a poisson distribution, but i could be wrong

sleek talon
#

these are the probabilites i am using. and this is the graph it came up with

sleek talon
#

Can we start over... AI is all over the place. How would i calculate the estimated probability of each pet type and rarity using the following probabilites?

odd edgeBOT
#

@sleek talon Has your question been resolved?

odd edgeBOT
#
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umbral epoch
odd edgeBOT
umbral epoch
#

is it not the same

#

but w/o the brackets

faint knot
#

should be

umbral epoch
#

okay

#

what do i do for this one?

faint knot
#

your equations for (b) already do this

#

(d) wants a version of (b) where t=0 results in P and t=1 results in Q
since (b) already does this, you can copy-paste those for (d)

umbral epoch
#

🗿

#

okay so its the exact same as b?

#

oh yay it is

#

thank you

#

:3

#

idk why i did that cat face

#

sorry

#

.close

odd edgeBOT
#
Channel closed

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rough birch
#

don’t apologize

umbral epoch
#

i feel the shame

#

.reopen

odd edgeBOT
#

umbral epoch
#

for this

#

is P = (-1,0,2) and the direction vector <1,1,0> ?

#

idk what that means

#

like p comes from the parametrics

orchid torrent
#

Oh as if P is a point on the line?

#

Yeah sure

umbral epoch
#

😩

#

okay ill take it

#

how is this wrong

#

bvn

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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short terrace
#

That's a weird statement

#

RHS is a set, it's agnostic of x

#

What you're saying is, if 0 ≤ x ≤ 1 it's contained in the LHS, so you only need to worry about x > 1

wooden python
#

"Let x ∈ RHS. If x ≤ 1, we win. Otherwise, with x > 1, consider x=1+z and look at 1/z ..."

short terrace
#

Phrase it precisely

#

Yes but you should be making your statements properly

#

Even if people can vibe out what you mean, they shouldn't have to

warped glacier
#

well yeah so it would help to write $B_n = [0, 1] \cup [1, 1 + \frac{1}{n})$, so it is clear that $[0, 1]$ is a subset of $A$

short terrace
#

1/z can be greater than z

#

So this isn't necessarily true

clever fjordBOT
#

mq in his algebra/stats arc

short terrace
#

Yes but you need to prove that

#

It's a simple proof but you need it nonetheless

clever fjordBOT
#

mq in his algebra/stats arc

low locust
#

you should state z < 1 somewhere. its obvious from context but needed

short terrace
#

That's what I've been getting at yes

clever fjordBOT
#

mq in his algebra/stats arc

low locust
#

well it certainly helps with reading the proof

#

btw, surely you should already be allowed to claim that for any positive z there is n with 1/n < z ?

#

yeah on second thought its not needed

#

it was just in the back of my mind cause thats usually a thing that can fuck up proofs

#

if you forget about cases like this

#

<1 vs > 1 can often make a difference

short terrace
#

Yup

#

The argument is correct, we were all just trying to make it precise

#

One of the attempts was unnecessary apparently lol

clever fjordBOT
#

mq in his algebra/stats arc

low locust
#

x in RHS < 1
well...

clever fjordBOT
#

mq in his algebra/stats arc

#

mq in his algebra/stats arc

short terrace
#

(you can use \ge)

clever fjordBOT
#

mq in his algebra/stats arc

odd edgeBOT
#

@thin dagger Has your question been resolved?

warped glacier
#

you're missing the existential qualifiers

#

so, $\forall x \in A, \exists n \in \mathbb N: x > \frac{1}{n}$

clever fjordBOT
warped glacier
#

but yes that fact is just a corollary of the Archimedean property

#

ping

warped glacier
# clever fjord **south**

since $x > 0$, the Archimedean property says that there always exists $n \in \mathbb N$ such that $nx > y$, and then you just choose $y = 1$

clever fjordBOT
warped glacier
#

so then you can rearrange that to x > 1/n

#

since n can't be 0

#

oh well this goes back to whether N includes 0 and that book assumed that it doesn't, anyways

odd edgeBOT
#
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#
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iron stump
odd edgeBOT
wooden python
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
iron stump
#

2

#

actually

wooden python
#

show what you got thus far.

iron stump
#
  1. I cant find my calculator 😂
wooden python
#

go there

iron stump
#

ok

#

nvm I think i got it, but can I keep this channel for now? Because im going to need help on some future problems

wooden python
#

questions*

#

unless they're like very closely related

iron stump
#

ok

#

well it can be closed then

wooden python
#

you can .close it yourself

iron stump
#

.closse

#

.close

odd edgeBOT
#
Channel closed

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odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vale gale
#

I need help in this

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vale gale
#

2

odd edgeBOT
#

Show your work, and if possible, explain where you are stuck.

orchid torrent
#

(you should do this in general when asking for help - it saves everyone's time)

vale gale
#

I mean 1

orchid torrent
#

Note that we're going from a product of two numbers to a singular number

#

So what's a natural thing for us to do

vale gale
#

We multiply everything In bracket

wooden python
#

go do that then

#

it might help beforehand to write the sqrt(8) as 2*sqrt(2) though

vale gale
#

35-2sqrt 4

#

The 8 becomes-2sqrt2

#

So we multiply this by the integers in other bracket

#

@orchid torrent

orchid torrent
#

$(a+b)(c+d) \neq ac+bd$

clever fjordBOT
#

Civil Service Pigeon

orchid torrent
#

If it helps, think of it as $$(5-\sqrt{8})(7+\sqrt{2})=5(7+\sqrt{2})-\sqrt{8}(7+\sqrt{2})$$

clever fjordBOT
#

Civil Service Pigeon

orchid torrent
#

then use distributive property twice

vale gale
#

$$(35-\sqrt{16})

orchid torrent
vale gale
#

35-sqrt 16

orchid torrent
#

you're not doing $(5)(7)-(\sqrt 8)(\sqrt 2)$

clever fjordBOT
#

Civil Service Pigeon

orchid torrent
#

read what I said above

orchid torrent
vale gale
#

I am multiplying these terms pigeon

#

5x7

#

35

#

-8x2

#

Sqrd

#

Now help

#

Plsssssss

oak crown
#

,w is (5-sqrt(8))(7+sqrt(2))=35-sqrt(16)

#

Fuck you

oak crown
#

Gah

vale gale
#

Y so mean

oak crown
#

.w (5-sqrt(8))(7+sqrt(2))

wooden python
#

he was flipping off the bot, not you

#

anyway

vale gale
#

I'm reporting

#

U

wooden python
#

you're missing two of four terms in the expansion

#

$(5 - \sqrt{8})(7 + \sqrt{2})$ is \textbf{not} equal to $5 \times 7 - \sqrt{8} \times \sqrt{2}$.

clever fjordBOT
wooden python
#

capisce?

vale gale
#

OK then vat

#

I simplify -sqrt8

wooden python
#

ok, let's forget the roots for just a minute

vale gale
#

Ok

wooden python
#

do the words "distributive law" sound familiar to you?

vale gale
#

Nooooo9

#

I am in y10

wooden python
#

ah, see, that's the issue then.

#

but also this is sth you should definitely know by year 10.

#

it's like year 6 or thereabouts.

vale gale
#

No started y10

#

No idk

#

BTW I reported him

wooden python
#

aight lemme find you a video to get you started

vale gale
#

That guy who swore

wooden python
#

This algebra video tutorial focuses on the foil method. It explains how to multiply binomials, trinomials and polynomials together. It also includes foiling examples of binomials with exponents. In addition, this video goes over another technique known as the binomial theorem which goes along well with pascal's triangle. You can use the bino...

▶ Play video
wooden python
#

just so you know.

#

anyway, look up things like:

  • distributive law
  • distributive property
  • expanding brackets/parentheses
  • FOIL [maybe]
#

on khanacademy and the like

#

cause that's a gap you'll have to close, not only for this question but for definitely many others to come.

vale gale
#

But we didn't learn foil method

wooden python
#

you should have learned how to expand brackets like (a+b)(c+d) some time before year 10.

#

this i can tell you with near certainty.

#

no matter how it's called in your country.

#

"FOIL" is an Americanism.

#

but i give it because a lot of english-language math resources are American and you might stumble into these when searching on google.

vale gale
#

And sorry utterly I reported u to the police and discord and I am not in year 10 I am an fbi agent and suing all this thing and you and your friend

wooden python
#

<@&268886789983436800> we've got either a jokester or a legal threat.

#

im washing my hands of this and letting y'all figure out what to do here.

blazing shuttle
#

nice troll. take 2 days off

wooden python
#

.close ?

nimble blaze
#

.close

odd edgeBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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neon horizon
odd edgeBOT
solar peak
#

.

wooden python
neon horizon
#

AHH OK

wooden python
#

if you dont have a math question to ask, then .close this channel and go to #chill.

neon horizon
#

but can you say to me some tips to be better in math

nimble blaze
neon horizon
#

i created it my self

vernal yacht
nimble blaze
#

even worse

neon horizon
#

can anyone send good vid to learn more about math

vernal yacht
#

there are some good stuff in his channel

signal yacht
#

3b1b?

neon horizon
#

where

vernal yacht
#

YouTube ofc :))

neon horizon
#

th

odd edgeBOT
#

@neon horizon Has your question been resolved?

#
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jolly mica
#

Need help finding the best method to find AD

faint knot
#

do you already have a method to find AD?

jolly mica
#

well id do either Sine or Cosine

#

but i feel like im missing a piece

#

and cant figure it out for some reason

faint knot
#

keep in mind you can find angle DBC and angle ABD

#

with just regular angles instead of any trig

jolly mica
#

yeah i know

#

im just tryna think

faint knot
#

whats angle ABD?

jolly mica
#

98?

#

that was quick mental maths idk if its right

faint knot
#

thats correct

jolly mica
#

okay good

faint knot
#

now you only need trig to solve this

jolly mica
#

its not a right angle is it?

faint knot
#

98 is not a right angle

jolly mica
#

no proof of it

faint knot
#

is there a particular other side youll need beforehand?

jolly mica
#

no i mean ADC

#

ahhhh

#

cosine rule

#

AB and BD

faint knot
#

yes

jolly mica
#

98 is CosC

#

yep thanks lol

faint knot
#

np

jolly mica
#

dont know why that took me so long

faint knot
#

dw

jolly mica
#

first day back at school

#

started my new maths course

#

gotta impress my teacher

faint knot
#

btw, its not a right angle

#

oh wait I wrote the digit wrong

#

its possible that its a right triangle

#

youll just need to check that the 8 and 6 line up

#

then again youll need trig to check that, so its not worth the extra work

#

in general, if the numbers are all integers, then it never lines up

#

only exception is an equilateral triangle

jolly mica
#

i got

#

10.53cm

jolly mica
jolly mica
faint knot
#

what did you find BD as?

faint knot
jolly mica
#

i also needed to find the area of ABD

#

i got 23.06cm^2

faint knot
#

yep

#

nice

jolly mica
#

lets go

#

gotta impress my teacher

#

sorry how do i do this

#

how am i 16 and still struggling with this man

vivid wyvern
#

cosine rule

jolly mica
#

oh yeah rearrange

#

ive gotta think more

vivid wyvern
#

cosz=(xz²+yz²-xy²)/2(xz)(yz)

jolly mica
vivid wyvern
#

Yes

#

Same thing

jolly mica
#

ohh okay

vivid wyvern
#

I termed it according to ur maths

jolly mica
#

any easy way to do this?

#

or is it literally trial and error

#

and see which one is the smallest

vivid wyvern
#

In a triangle the angle opposite to the smallest side is the smallest angle

jolly mica
#

cool good to know

#

thank you

vivid wyvern
#

Np

jolly mica
#

so ill need 9 as a

#

in my cosine rule

vivid wyvern
#

Yes

jolly mica
#

thanks :)

#

how can i work out the bearing of B from A at 14:00?

odd edgeBOT
#

@jolly mica Has your question been resolved?

brazen hare
# jolly mica

Let the point of the port be P. Angle NPA is 80, and angle NPB is 152. Angle APB is 152 - 80 = 72.

First, work out the distances PA and PB using your distance-time-speed formula

jolly mica
#

60 and 75 km right?

brazen hare
#

yup

#

for PB and PA respectively

jolly mica
#

yeah cool got that

odd edgeBOT
#
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#
Available help channel!

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mystic saffron
#

Hello, quick one, I am trying to understand Borsuk's conjecture (out of curiosity I'm just a year 12 student (uk) and i have limited 'ball knowledge' per se) and I'm wondering what exactly the definition of 'diameter' is in regard to non circular shapes. See image for example from the Wikipedia page. (https://en.wikipedia.org/wiki/Borsuk's_conjecture)

orchid torrent
# mystic saffron Hello, quick one, I am trying to understand Borsuk's conjecture (out of curiosit...
mystic saffron
#

.close

odd edgeBOT
#
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odd edgeBOT
#
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tall shuttle
#

hello, I'm trying to find the distance between points and i dont know where im getting stuck, but its still being marked wrong, the points are (6,-5) (-7,8), im getting 18.38 with this formula

quasi sparrow
#

why is it -5 instead of 5

tall shuttle
#

my mistake

#

like that

#

i edited the message

#

it is supossed to be -5

quasi sparrow
#

show the entire question

tall shuttle
#

ok

quasi sparrow
#

try entering exact number without any operations

#

like $\sqrt{12345}$

clever fjordBOT
#

riemann

tall shuttle
#

hmm how do you mean?

quasi sparrow
#

your answer has minus signs, squaring

tall shuttle
#

i did try putting 18.38 and it said wrong, round to whole number

quasi sparrow
#

simplify all the numbers

quasi sparrow
#

18.38 is rounded

tall shuttle
#

ah so 18.38477631

quasi sparrow
#

.........

#

no

#

would you know how to simplify $\sqrt{2+3}$ ?

clever fjordBOT
#

riemann

tall shuttle
#

no i dont

quasi sparrow
#

2 + 3 = 5, so sqrt(2 + 3) = sqrt(5)

tall shuttle
#

oh ok

quasi sparrow
#

notice the expression on the right side doesn't have any operations, but the left side does

tall shuttle
#

yes

#

ok il try

#

Did I miss something?

quasi sparrow
#

yea so $\sqrt{338}$ is what you should enter

clever fjordBOT
#

riemann

tall shuttle
#

ok i will see

quasi sparrow
#

,calc 2 * 13^2

clever fjordBOT
#

Result:

338
tall shuttle
#

hmm its still wrong on here

quasi sparrow
#

show

tall shuttle
#

my mistake it is correct, its a very slow websight

#

please tell me why its that instead of 18.38?

quasi sparrow
#

18.38 is not equal to sqrt(338)

tall shuttle
#

is that not a more simplifed answer

quasi sparrow
#

sqrt(338) is a number that when you square it, you get 338

#

,calc 18.38^2

tall shuttle
#

oh because its infinite

clever fjordBOT
#

Result:

337.8244
quasi sparrow
#

337.8244 is not equal to 338, but it is close

#

sqrt(338) has infinite decimal expansion yes because 338 is not a perfect square

#

,calc sqrt(2)

clever fjordBOT
#

Result:

1.4142135623731
quasi sparrow
#

same with sqrt(2), but it's approximately equal to 1.4142

#

,calc 1.4142^2

clever fjordBOT
#

Result:

1.99996164
tall shuttle
#

Could you check my math on the second part aswell?

quasi sparrow
#

again, not equal to 2, but close

#

maybe

tall shuttle
#

Why is my midpoint so far off?

quasi sparrow
#

well 6 + (-7) = -1

#

so when you divide by 2 you should not get 2.5

#

get in the habit of simplifying before using a calculator

#

or learn to use a calculator better

tall shuttle
#

ok

quasi sparrow
#

,calc 6 + -7/2

clever fjordBOT
#

Result:

2.5
quasi sparrow
#

,calc (6 + -7)/2

clever fjordBOT
#

Result:

-0.5
quasi sparrow
tall shuttle
#

i see i will try

#

ok i got it right. thank you

odd edgeBOT
#

@tall shuttle Has your question been resolved?

#
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fossil vapor
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What are MUST KNOW topics for algebra 2

fossil vapor
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Js tryna gather up information before diving deeper into studying algebra 2

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Is that a bad question to ask

wanton bison
fossil vapor
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Algebra 1 i found easy

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Is it just algebra 1 but it covers deeper stuff

mystic saffron
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hi

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bru i said hi

fossil vapor
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Wut

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What yall use for practice problems

languid horizon
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May i just ask what exactly do you consider as algebra 1. As i feel like terminology is a little different based on location

fossil vapor
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Graphing, functions, and just simplifying algebraic equations

languid horizon
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Ok ok (because i normally hear Algebra only in context of abstract Algebra)

fossil vapor
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Alg 2 is just a deeper understanding of algebra

unkempt lichen
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i suppose trigonometric/circular, logarithmic and exponential functions have been covered in alg1? if not, get ready for them in alg2 i suppose

fossil vapor
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Im learning quad equations cus i didnt get into thay

unkempt lichen
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that too

fossil vapor
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Alright

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Thanks i hope i succeed in self studying

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Will a textbook help

unkempt lichen
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depends on your learning style

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but it won't hurt to have one

languid horizon
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I mean what i did. And what made me far ahead of other people is i watched some yt videos (like The Organic Chemistry Tutor) , just out of fun. And used something like photomath to solve stuff i didnt know.

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And i mostly solved some competitive math problems. Which made basically all the problems we did in school trivial for me

fossil vapor
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Yea i gotta start watching that guy

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Js do math in ur free time

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Quad formulas are kinda easy. Just very tedious in the simplifying

languid horizon
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Ive rarely needed to use the quadratic formula

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Like most quadratics can be solved by just factoring

fossil vapor
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Yea i’ve seen

languid horizon
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I mean ofc there will be problems that will make that basically impossible

pallid silo
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i like completing the square and grouping

unkempt lichen
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quad formula is one size fits all, but if there comes a time where your discrim is negative, then yeah

fossil vapor
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It takes up so much space

languid horizon
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Im guessing you know of the method like if you have
$$x^2 + ax + b$$ you find $2$ numbers such that $k + l = a$ and $kl = b$ then $$x^2 + ax + b = (x + k)(x + l)$$

clever fjordBOT
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casework

pallid silo
fossil vapor
fossil vapor
indigo dirge
# fossil vapor What that

dw about it, but its a method where you draw a 2x2 box and on the outside you put one binomial on the top side and one on the left

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you dont need to know it at all though

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just use what @languid horizon mentioned

languid horizon
fossil vapor
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“Use the quadratic formula to solve all equations”

indigo dirge
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but ig it makes it easier and more brainless

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just plug in a,b,c

pallid silo
fossil vapor
#

School js started a week ago for me too

pallid silo
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ahhh i see if you have it memorized you should be chilling just do some practice problems get enough sleep and don’t spike your cortisol over it

fossil vapor
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Alright ill js do practice problems for like 3 minutes

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30

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Minutes

languid horizon
fossil vapor
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I mean its easy to remember when u done enough problems

languid horizon
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Yeah but knowing how to derive it just gives you context why everything is how it is

indigo dirge
languid horizon
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Like why is there $2a$ in the denominator. Why is $b^2 - 4ac$ in the square root. Why is there a $\pm$ why is it a $-b$ and not $b$ etc...

fossil vapor
clever fjordBOT
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casework

languid horizon
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I mean by deriving i mean proving it

fossil vapor
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Ohhh

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I get ur mindset

languid horizon
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Aka going from
$$ax^2 + bx + c = 0$$
to
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

clever fjordBOT
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casework

fossil vapor
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Ohh alright

languid horizon
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The proof isnt that long. You can try it for yourself. ||I mean a hint would be to complete the square then take the square root||

fossil vapor
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So kinda prove the formula

languid horizon
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Yea. Its just some basic algebraic manipulations

fossil vapor
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Ah ok

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U must be very interested in math

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Math is fun once u get into the hang of what you’re learning

languid horizon
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Yea i mean i found it way easier once i could prove everything i knew.

fossil vapor
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W got all my practice problems right

odd edgeBOT
#

@fossil vapor Has your question been resolved?

#
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shrewd trellis
#

I’m not sure how to factorise this, but this is what I have done

shrewd trellis
unkempt lichen
#

if you did the working right (haven't checked you on this yet), you have a common factor of 16 across all four terms

late dust
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f(x) has a (x+3)^2 factor; you should check whether f'(x) has a (x+3) factor

steep mantle
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notice that x+3 is a factor

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(oh fuck i was lagging and didnt realized yaal have already responed oops)

odd edgeBOT
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@shrewd trellis Has your question been resolved?

shrewd trellis
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Is there a shortcut i could put in the calculator which gives me a common factor

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across multiple terms

unkempt lichen
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nvm i'm drunk, ignore me

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i thought x^3 has 18 for some reason and it mushed in my head

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but generally speaking, if you know your multiplication, you can spot numerical common factors fairly easily

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anyway, focus on the suggestion from the others

shrewd trellis
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I rely on calculator

unkempt lichen
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no comment other than to practice, i suppose, if you wanna eyeball common factors

shrewd trellis
shrewd trellis
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Because

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Where is it

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Unless if I factorise it

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Then maybe

late dust
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I mean yeah, you won't get a factor if you don't factorize...

shrewd trellis
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Yeah

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But idk how to factorise it

nocturne mica
#

well, they're all even. at least do the numbers first

#

after that, since you want to check if x+3 is a factor, polynomial divide your way through using your method of choice

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

shrewd trellis
#

I’ll just divide by 2 first

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But why do we need to check if (x+3) is a factor

nocturne mica
#

to reduce the cubic to a quadratic

shrewd trellis
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Didn’t I already do it here

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I could try to factorise that

late dust
nocturne mica
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admittedly i missed that too

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but yeah you can factor from there

late dust
#

If you're looking for the zeroes of that function, of course you want to factorize it

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And all you have to do is factorize a quadratic, that's easy

shrewd trellis
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Yeah easy stuff

late dust
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Can't tell if that was sarcasm

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

#
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languid orbit
#

hey whats the conclusion im supposed to reach here

languid orbit
#

its kind of a vague problem

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or should i post this elsewhere

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actually ill post this elsewhere nevermind

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.close

odd edgeBOT
#
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odd edgeBOT
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graceful shore
#

Hii

odd edgeBOT
graceful shore
#

can someone enlighten me on how to do this type of exercise??

nocturne mica
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what are you stuck on?

odd edgeBOT
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@graceful shore Has your question been resolved?

graceful shore
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the first

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the last one seems like I solved it

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but the first and second I've got no idea hpw

nocturne mica
#

so have you learnt about set complements?

graceful shore
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Mm, kind of

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the teacher only gave the theory

nocturne mica
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have you learnt of the effects of set complements on set inclusion?

graceful shore
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I don't have any example with the solved exercise.

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I don't think so

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at should I doM

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?

nocturne mica
#

if A is a proper subset of B, and we take the complements of both A and B, what do you think the relationship between A^c and B^c is?
(^c = complement)

graceful shore
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We take the complementare of both A and B, then it's the opposite of A and B

nocturne mica
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i mean yes, but what about the relationship between the two complements themselves?

graceful shore
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A is în B, but not equal

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But the complementary...

nocturne mica
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a visual example

graceful shore
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yes

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And we need to find?

nocturne mica
#

the relationship between the complement of B and the complement of A

graceful shore
#

The complement the B is the rectangle, and the complement of A is B and the rest, right?

nocturne mica
#

yeah. and the relationship will become?

graceful shore
#

Hmm

nocturne mica
#

if you can't think of it that way, consider which one is bigger - the complement of B, or the complement of A?

graceful shore
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Complement A

nocturne mica
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ofc it's A^c, right? because A^c contains B as well as the rest of U

graceful shore
#

Right

nocturne mica
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but B^c itself also contains the rest of U, but not B

graceful shore
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A

nocturne mica
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so B^c is (larger/smaller) than A^c?

graceful shore
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Larger

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no?

nocturne mica
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how can B^c be larger than A^c if A^c has B while B^c doesn't?

graceful shore
#

oh

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no

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smaller

nocturne mica
#

there we go

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and another way to say smaller is "proper subset"

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so that means, if A is a proper subset of B, the complement of B is a proper subset of the complement of A

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agreed?

graceful shore
#

Yep

nocturne mica
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ok so

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let's think about a third set C

graceful shore
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Yes

nocturne mica
#

when we write C \ A, what are we actually saying?

graceful shore
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C minus A

nocturne mica
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so we take everything in C that is also not in A

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agreed?

graceful shore
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yes