#help-19

1 messages · Page 202 of 1

keen scroll
#

and we didnt do it in class

whole gyro
#

send

keen scroll
whole gyro
#

write

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p intersection q has x elements

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meaning the rest of p has 10-x elements

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rest of q has 13-x elements

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now eveything except p or q has 5 elements

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and the universal set has 20 elements

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meaning p or q has a total of 20 - 5 = 15 elements

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so 10 -x + x + 13 - x = 15

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so x = 8

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@keen scroll got it?

keen scroll
#

holy shit

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no way this is comign

whole gyro
#

but did you understand

keen scroll
whole gyro
#

n ( P U Q)' = 5

keen scroll
#

oh

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given

#

ohh

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i kind of get it

#

need more practice

#

ty

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i sleep

whole gyro
#

bye

keen scroll
#

just 2 more q.

#

is it worth it

whole gyro
#

no

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sleep

keen scroll
#

sleep

#

gn

#

tysm

#

goated

#

lal ofu

#

ly

#

i wil pass this good grace down

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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shut zephyr
odd edgeBOT
#

@shut zephyr Has your question been resolved?

vernal yacht
#

.close

odd edgeBOT
#
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vernal yacht
#

You accidentally claim a channel

odd edgeBOT
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mystic saffron
#

Just to double check, is this answer correct? My answer sheet says x=7 but I got 3.5. But, if I plug in 3.5 to the 4x-7 I get 7

mystic saffron
#

Idk I’m just a lil paranoid

sturdy cape
mystic saffron
#

My drawings can be confusing sometimes, sorry. here’s the original

#

Should I have added those up and done something different?

sturdy cape
#

The small triangle, that's fine

#

Are you sure that's what you get for the big one?

mystic saffron
#

No probably not

#

I have to add the 6 and 3 for the big one don’t i?

sturdy cape
#

So instead of 6, that side-length on the big triangle should be...?

mystic saffron
#

9 😔

sturdy cape
#

yeeee

mystic saffron
#

lol

sturdy cape
#

[fwiw, your working out was otherwise correct, so you shouldn't have much difficulty getting to x = 7]

#

[do dw, it was just misinterpreting the diagram, was all]

mystic saffron
#

Thank you for correcting me lol I have the tendency to miss lil things like that

#

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odd edgeBOT
#
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odd edgeBOT
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coarse condor
#

hey using the trigonometric identity

$ y = \tan^{-1} \left( \frac{1}{x} \right) $

coarse condor
#

$$ y = \tan^{-1} \left( \frac{1}{x} \right) $$

clever fjordBOT
#

PHYSIC🅰HOLIC

sturdy cape
#

Don't put spaces before/after the dollars

coarse condor
#

$y = \tan^{-1} \left( \frac{1}{x} \right)$

clever fjordBOT
#

PHYSIC🅰HOLIC

coarse condor
#

wait a min let me reframe the question

short terrace
#

Yeah I was wondering what exactly you're asking

coarse condor
#

$$y = \tan^{-1} \left( \frac{1}{x} \right) = \cot^{-1} \left(x)$$

we see that the $tan^{-1} \left(\frac{1}{x}\right)$ is not differentiable at x=0 but the $cot^{-1}(x)$ is
so while changing tan inverse 1/x to cot inverse x how could we say its differentiable

clever fjordBOT
#

PHYSIC🅰HOLIC
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

coarse condor
#

hell how to write this language

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anyways i guess my question is clear

grand narwhal
#

I'm new and icl, ts is weird I mean, a dc server to do Mathematics?

CRAZY.

coarse condor
#

but they differe by a constant onlyy
for x < 0

tan inverse 1/x = cot inverse x - pi

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but as the pi is constant it turn zero while differentiating

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so for all x the differentiation of tan inverse 1/x = differentiation of cot inverse x

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i need to know what happened at x = 0 or very close to zero

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<@&286206848099549185>

zealous reef
zealous reef
tulip bolt
#

Guys I'm very basic at math whats this tan thing

coarse condor
#

$\int_{-1}^{1} \frac\left({d tan^{-1}\left(\frac{1}{x}\right)}\right){dx},dx$
then how to solve this

strange aspen
coarse condor
#

@zealous reef

zealous reef
clever fjordBOT
#

PHYSIC🅰HOLIC
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

zealous reef
#

so split it into the integral from -1 to 0 + the integral of 0 to 1

coarse condor
coarse condor
#

thnks for the help

#

guyzz

#

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#
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split badger
#
  1. Let p > 2 be an odd number and let n be a positive
    integer. Prove that p divides 1^p^n + 2^p^n ............ + (p-1)^p^n

How to approach this question?

obtuse nest
#

maybe using fermat's little theorem?

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oh wait nvm p isn't prime

odd edgeBOT
#

@split badger Has your question been resolved?

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deft viper
#

Can someone help with this

odd edgeBOT
lean yew
#

what do you understand about this, and what have you tried?

amber schooner
deft viper
#

It’s my summer work so I don’t know much about this

unkempt lichen
#

have you learnt about linear equations?

deft viper
#

Nope

#

Actually a lil bit

lean yew
#

so far, what have you learnt about them?

umbral jolt
#

Ochem tutor 🔥

turbid comet
odd edgeBOT
#

@deft viper Has your question been resolved?

odd edgeBOT
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frail lintel
#

which formula of integration is used here

faint knot
clever fjordBOT
faint knot
#

so $\int_0^v\frac{dv}{A+Bv}=\frac1B\left[\ln(A+Bv)\right]_0^v$

clever fjordBOT
frail lintel
#

OHH

faint knot
#

the constants hide that its a simple integral

frail lintel
#

its very standard

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okay yes right

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thank you got it

faint knot
#

np

frail lintel
#

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supple jasper
#

Need help with this corollary I have tried previously but it's wrong

supple jasper
supple jasper
bronze citrus
#

wait ill help you

#

<@&286206848099549185>

#

i helped you by pinning helpers

stable sequoia
#

i think you should

#

use the sine law on this one

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:3

hearty nest
#

let PQR be a triangle

stable sequoia
#

that works too... i guess...

hearty nest
stable sequoia
#

$\angle{A}=\angle{B}=\angle{C}$ so $\frac{a}{\sin{\angle{A}}}=\frac{b}{\sin{\angle{B}}}=\frac{c}{\sin{\angle{C}}}$ then just use the equality and $a=b=c$ ?

clever fjordBOT
#

parabolicinsanity

stable sequoia
#

unless sine law isn't

#

taught or something

#

then the isoceles triangle proof will do

hearty nest
stable sequoia
#

🥀 then yeah use the isoceles triangle proof

supple jasper
#

Guys I think we have to use the theorem

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As it is a part of it i said

hearty nest
#

but u cant prove a theorem by using that theorem

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idk

supple jasper
#

Bruh

supple jasper
hearty nest
#

its like saying a=b coz a=b

supple jasper
#

Man I am getting more confused

hearty nest
#

should i send solution

supple jasper
#

Ok

hearty nest
#

wait

#

@supple jasper

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hence proved

odd edgeBOT
#

@supple jasper Has your question been resolved?

supple jasper
#

Yea done

#

Ty

#

.close

odd edgeBOT
#
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visual cape
odd edgeBOT
visual cape
#

using this i got sqrt2*sin(3x-3pi/4)

#

answer is sqrt2 * sin(3x-5pi/4)

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the answers have these like this

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but isnt b = -1 and a =1?

summer wave
#

maybe because it's 3x - alpha and not 3x + alpha

visual cape
#

yeah i noticed that but i dont think it would have an effect on anything?

summer wave
#

expanding the right side gives $r\sin(3x-\alpha) = r\sin(-\alpha)\cos(3x) + r\cos(-\alpha)\sin(3x)$

clever fjordBOT
#

bloubbloub

summer wave
#

so this flips the sign of sin alpha

visual cape
#

cant you just let beta = -alpha

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then the formula is the same

summer wave
#

yeah

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but sin alpha = - sin beta

visual cape
#

sin -alpha = sin beta

summer wave
#

yeah

visual cape
#

so its the same

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oh its not

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-a = 3pi/4

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so a = 3pi/4

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and then 3x+3pi/4 is just the same as 3x-5pi/4

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oh so the answers just use cos-x = cosx and sin-x = -sinx

#

that makes more sense thank you

#

.close

odd edgeBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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vernal yacht
#

.

odd edgeBOT
vernal yacht
#

~~@summer wave ~~ @hollow sky post your question here

crystal charm
hollow sky
#

how do i find the centroid of a triangle

vernal yacht
#

mb

summer wave
#

what

vernal yacht
crystal charm
hollow sky
#

ok thank you

vernal yacht
hollow sky
#

no thank you

vernal yacht
#

Have a good one

#

.solved

odd edgeBOT
#
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vernal yacht
#

Let’s bring it to hlounge

odd edgeBOT
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bitter folio
odd edgeBOT
bitter folio
#

I need help with understandint why the first line of the complex number solution holds.

#

i.e. why is $d = 2 \cdot \frac{f + a + b - ab\overline{f}}{2} - b$

clever fjordBOT
bitter folio
#

i get that the foot from F to AB is $\frac{f + a + b - ab\overline{f}}{2}$

clever fjordBOT
bitter folio
#

But why the -b at the end? Help is appreciated

odd edgeBOT
#

@bitter folio Has your question been resolved?

bitter folio
#

<@&286206848099549185>

odd tartan
#

hi

vernal yacht
#

hi

bitter folio
#

帮帮我 pls

bitter folio
bitter folio
odd tartan
#

whats the question?

bitter folio
#

我几何是强项但是还是这么烂

odd tartan
bitter folio
#

我说的是简体字

#

我读不了繁体

odd tartan
bitter folio
#

thanks for helping or trying to help btw

odd tartan
# bitter folio

i want to know, do the lowercase letters indicate sides? if so, what sides?

bitter folio
#

in complex numbers

#

so for example 点 A <=> 复数 a

odd tartan
#

e sorry im not the best at geometry, but ill take a look

bitter folio
odd tartan
#

imma take a look at it to see if it makes any sense

bitter folio
#

什么鬼

#

!nogpt

odd edgeBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

bitter folio
#

sorry

odd tartan
#

(flip around and find out)

bitter folio
odd tartan
#

first things first, what does it mean to multiply 2 complex numbers?

(a+bi)(c+di)

ac+adi+bci-bd
(ac-bd)+(ad+bc)i

might be useful for understanding what all the point multiplications mean. this basically means that:

(a, b) x (c, d) = (ac-bd, ad+bc)

were getting somewhere..

lets try multiplying some points and see what happens!

(1, 0) x (0, 1) = (0, 1)

alright... interesting result

(1, 1) x (2, 3) = (-1, 5)

again.. interestin result. any pattern we can make sense of this? well, lets see how it looks if we make it a line!

the slope of the from (1, 1) to (-1, 5) is -2. the slope of the line from (1, 1) to (2, 3) is 2/1 = 2. interesting! it seems like we... made a perpendicular line!

#

lets try to generalize this:

(a, b) to (ac-bd, ad+bc) has a slope of (ad+bc-b)/(ac-bd-a)
(a, b) to (c, d) has a slope of (d-b)/(c-a)

(ad+bc-b)(c-a) = -(d-b)(ac-bd-a)?

bitter folio
#

hmm how does this help me

#

you are making complex numbers in terms of coordinate system geometry and introducing gradient

#

meanwhile the purpose of complex geometry is to get rid of that

#

really appreciate the effort tho

odd tartan
#

well, its a good way to see how we can translate complex geometry into coordinate geometry. to make it seem more clear

bitter folio
#

But i dont want to deal with coordinates, thats why i want to complex bash

#

if its easier i would have used coord geom but its not

odd tartan
#

are you in pre-uni or undergrad? just wondering

bitter folio
#

that's why complex is more viable in most options

bitter folio
odd tartan
#

which form?

bitter folio
#

odd tartan
#

im from hong kong (btw)

bitter folio
odd tartan
#

i heard that chinese maths education is much more rigorous than hong kong's

bitter folio
#

and i do olympiads

odd tartan
#

fun

#

i was always considered the person that was the best at maths. but its usually because i learned advanced mathematics (e.g. group theory, differential equations, etc..), not because i was good at the mathematics we were currently learning, albeit i was still good at that. still, im rusty with geometry and its my least favourite branch of math

#

id rather just do differential equations, theyre much more fun

bitter folio
#

been another 25

odd tartan
#

im stumped, so uhh yeah. imma see the solution when someone solves this so i know what happened

odd tartan
# bitter folio i am olympiad sweat

same here too, except the math olympiads here, you have to train for. its very hard to go into it directly, even if youre good at math. so even if youre really good or even gifted at math, you might still only get 3rd or 2nd prize (note: 3rd prize doesnt mean 3rd place)

#

basically its for people that joined multiple olympiad classes and just do 50 practice problems every day

bitter folio
#

singapore math olympiads arent that easy either look at our imo performance

#

i have very tough competition

odd tartan
# bitter folio yup thats me

its not a healthy lifestyle and really doesnt make you that much better at math. just makes you more competitive and feel 'better' at the subject, when what youre actually training for is just the problems that come out every single time, in some variation or another.

bitter folio
#

because i do physics olympiad as well

odd tartan
# bitter folio thats fine for me

really doesnt make you that much better at math
when what youre actually training for is just the problems that come out every single time, in some variation or another.

bitter folio
#

and i do so many things i have to time for rest

#

but i dont mind

#

i really dont mind

#

it feels so good topping my school in my level

odd tartan
#

yeah i do that too, except i dont train for olympiads religiously

#

i mean, its fine if you want

bitter folio
#

lmao

odd tartan
#

but i just dont recommend it

#

its not going to make you better at math, not by a lot, itll just make you better at the competition

bitter folio
#

i suppose..?

bitter folio
#

you have to define math competency here

odd tartan
#

you do previous test questions

#

that are the same thing but slightly different

#

over and over again, until your brain is crammed with some random formulas that you will (probably) never use in engineering, physics, or anything really

#

at least, thats just my perspective in hong kong

bitter folio
#

my goated teacher makes his own

#

and he has such a good personality that we love him

odd tartan
#

idk what singapore is like

bitter folio
#

messages didnt load mb

odd tartan
odd tartan
#

most of our teachers are just teachers that were paid to just be there, teach some random things, with 0 spirit, then leave

bitter folio
#

plus its mostly free for me because of 水平

odd tartan
#

also dang there are so many emojis

bitter folio
odd tartan
#

e ok

odd tartan
#

also why is no one (trying to) help(ing) you?

#

like its just me

bitter folio
odd tartan
#

look at this

bitter folio
#

bro pls dont clutter my channel

bitter folio
frank inlet
bitter folio
frank inlet
#

Its the formula

bitter folio
#

Which

frank inlet
#

D in exactly on the a and b intersection

bitter folio
#

How can two complex numbers intersect

frank inlet
#

d - a = f - ab/f

bitter folio
frank inlet
#

its an equation to solve two line

#

Ab and f

bitter folio
bitter folio
#

do you know what the question is saying

frank inlet
#

But still

#

well the question it to prove not solve

bitter folio
#

its fine

#

no worries its not easy anyway

frank inlet
frank inlet
bitter folio
#

see the complex bash

#

i dont get the first line of setup

frank inlet
#

oh the first image

bitter folio
#

indeed

frank inlet
#

kind of different from what ive learnt but if i say transform ad=ae into algebraic identity would u be confused?

#

ngl im confused too

bitter folio
#

<@&286206848099549185>

frank inlet
#

we can simplify the equation

simple inlet
#

Where is question

#

What is the question?

frank inlet
#

scroll up, sigma

odd tartan
#

im studying undergrad maths and even i dont know this opencry

simple inlet
#

Ok

odd tartan
#

but geometry has never been my subject

bitter folio
odd tartan
#

i just always found algebra and calculus more fun

bitter folio
#

so

bitter folio
frank inlet
odd tartan
#

YOUR CODE IS NOW IN BASH!

crystal charm
bitter folio
#

bruh

#

i have to say so many times to yall

bitter folio
#

ffs

odd tartan
crystal charm
#

type in ,iamnot studying in #bots if you wanna remove it joia

odd tartan
#

,iam notdying

clever fjordBOT
#

No selfroles matching notdying.
See ,selfroles --list for the list of valid selfroles.

odd tartan
#

,iamnot dying

clever fjordBOT
#

Removed the studying! role from you.

odd tartan
#

there we go

crystal charm
#

alright I guess here as well

odd tartan
#

ok yeah nvm im just gonna stick to advanceed-lounge

#

,iam dying

clever fjordBOT
#

Gave you the studying! selfrole.

frank inlet
odd tartan
#

love how they see 'dying' as 'studying' lol

bitter folio
#

please

bitter folio
frank inlet
#

geometra and algebra connected so you cant run

bitter folio
#

of course bruh thats why i am bashing

odd tartan
frank inlet
#

i want to show you the equation but ive been warned b4

odd tartan
#

are we all confused?

bitter folio
#

whatever im opening a new one later

frank inlet
#

ok wait

#

lemme try again

frank inlet
bitter folio
#

i am not asking that question

bitter folio
frank inlet
#

reallyMad so what?

bitter folio
frank inlet
#

i spoke english tho or u dont understand

bitter folio
#

why is the foot of the perpendicular having a -b term

#

do you understand that

frank inlet
#

@fair token

frank inlet
#

d must be expressed as a linear combination of ab, when u simply it, it'll subtract to b

#

it's not arbitrary

#

ur question is not exactly clear. u couldnt just say that i missed smth cuh

crystal charm
bitter folio
frank inlet
#

well i tried. really getting into your appreciation

bitter folio
#

.close

odd edgeBOT
#
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bitter folio
#

Have a great day @frank inlet

#

@odd tartan you too

digital shore
#

why is the name different

odd tartan
#

what

bitter folio
#

@crystal charm @vernal yacht

#

Have a great day

bitter folio
odd tartan
bitter folio
digital shore
#

oh ok

odd edgeBOT
#
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upbeat stump
odd edgeBOT
upbeat stump
#

Guys how to draw a cot graph? A sec graph and a 1/sin graph(I forgot the name)

unkempt lichen
#

(the last one is cosecant/cosec)

upbeat stump
#

Thanks👍

#

But like, idk wtf happens when I 1 over those graphs

#

Like how do ik the way the graph shifts

#

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wet ferry
#

does anyone know how to date a sample using the quantity of Carbon 14 as well as it's activity ?

wet ferry
#

cause the only methods i've seen is by calculating the ratio C14/C12

mystic saffron
#

like in irl

odd edgeBOT
#

@wet ferry Has your question been resolved?

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#
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odd shell
odd edgeBOT
odd shell
#

This question seems quite tough

errant gust
#

what have you tried? drawing a diagram would probably help

modest nacelle
#

What kind of notation is 1·2 m? Decimal point, or multiplication?

glass vault
#

first you should find the horizontal distance to the baloon so you have something to compare the 60 and 30 degree cases

odd shell
#

Let me try drawing a diagram

#

This is the diagram given

#

I am assuming to start with Triangle PST and write PS/ST= tan60

odd shell
magic hedge
#

Try and sketch a diagram on paper

odd shell
#

Ok

magic hedge
#

You can kinda neglect the girl's height here as it doesn't affect horizontal distance

odd shell
magic hedge
#

Now move onto triangle QTR

odd shell
#

Ah ok

magic hedge
#

Do the same thing

odd shell
#

I did it

#

Seems to be correct as per the book , thank you so much

magic hedge
#

That's right

#

Should be around 100.45m

odd shell
#

Yup

magic hedge
#

Alright cool

odd shell
#

Let me close this channel

#

Can you close for me ?

#

If possible ?

magic hedge
#

Uh I'll try

#

.close

#

I'm not sure how to do it 😅

magic hedge
#

I think you need to do it

#

Type ".close"

odd shell
#

.close

odd edgeBOT
#
Channel closed

Closed by @odd shell

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odd shell
#

Done

#

.close

magic hedge
#

It's been closed already

modest nacelle
odd shell
#

But yes , you are right

odd edgeBOT
#
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celest osprey
odd edgeBOT
celest osprey
#

Why is the region shaded the incorrect requirement for the solution?

vernal yacht
#

question 7?

north sparrow
#

pick a point in it like (100,50) and see which of the conditions break?

celest osprey
#

Yes

#

Q.7

#

@weary pelican if you say that W is not a number, then it is not a real number

#

If 27 is the only nice solution

#

It is the only real solution to the problem

#

Un nice solutions won't be considered as real solutions

celest osprey
#

Where does this 100 and 50 come from

#

Why do we need to see if the conditions break by the way

north sparrow
north sparrow
#

if it is not satisfied, the other side (the one not containing the test point) is the good one

celest osprey
#

Constraint?

north sparrow
#

x-2y>=0 is one of the 3 constraint on x and y for example

celest osprey
#

Oh the conditions

#

So after making the graph we also have to test which region satisfies

#

.close

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#
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#
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gusty jolt
#

I need help finding the equation for the red line in the image. I have no idea where to start from

amber veldt
gusty jolt
#

tangency point?

amber veldt
#

nope

#

for example

#

let's say a line goes through (0,0) and (-2,4)

#

can you find the equation of that line?

gusty jolt
#

yeah yeah

#

y=-2x

amber veldt
#

so you just need to find the two points here

gusty jolt
#

mhm

amber veldt
#

it looks like the red line and blue curve cross the x-axis at the same point

#

what are the roots of y=ln x?

#

where does y=lnx=0?

gusty jolt
#

so x=1

amber veldt
#

yup

#

so the first point of intersection is

#

(x,y)=?

gusty jolt
#

1,0

amber veldt
#

(1,0) you mean, yes

#

halfway there

#

for the other point, they tell you whjat the x-coordinate is

#

(e^a, ?) we just need the y-coordinate

#

any ideas

gusty jolt
#

nope

amber veldt
#

well if y=ln x is the general curve of the blue line

#

than y evaluated at x=some particular x is the y-coordinate of that point

#

for example, at x = 2, you have the point (2, ln 2)

gusty jolt
#

so at e^a would be (e^a, ln e^a)?

amber veldt
#

yes! but it simplifies

#

remember e^x and ln x are inverses of each other, meaning

#

e^(ln x) = x for all x >0
ln(e^x) = x for all x

gusty jolt
#

ohh

#

so it would be (e^a, a)

amber veldt
#

bingo

#

you have your two points now

gusty jolt
#

the slope would be a/e^a -1

#

y=a/e^a-1*(x-1) right?

amber veldt
#

needs more parentheses

gusty jolt
#

y=a/(e^a-1)*(x-1)

amber veldt
#

,w plot y=ln x, x=e^2, y=a/(e^2-1)(x-1)

gusty jolt
#

yeah exactly

amber veldt
#

bleh

#

wanted a picture but looks good

#

,w plot y=ln x, y=a/(e^2-1)(x-1)

amber veldt
#

noooo

#

whatever

#

its because i left in a

#

,w plot y=ln x, x=e^2, y=2/(e^2-1)(x-1), x = e^2

amber veldt
#

there we go

gusty jolt
#

thanks for your help

amber veldt
gusty jolt
#

.close

odd edgeBOT
#
Channel closed

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odd edgeBOT
#
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vast crater
#

Apparently one of these is wrong but i cannot figure out which one

unkempt lichen
#

2 and 3 look wrong

vast crater
#

wait why would that be

#

for #2 isnt it simmilar to the first one

#

where like x=0 and then y=0 and 0=0

#

for #3 simmilar thing

unkempt lichen
#

wait nvm my dumbass legit misread #2

#

#3 i can almost guarantee it's not a unique solution

#

look at row 3

vast crater
#

oh if a row is all 0

#

is it infinite

unkempt lichen
#

yes. if there is an all-zero row, there is at least one free variable

vast crater
#

thanks 🙂

#

a lot

#

i was abs bugging out

#

lol

#

.close

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#
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lavish slate
#

How does one get started on this?

odd edgeBOT
rough birch
#

whenever a problem has tangent circles, it's always a good idea to draw radii from centers of circles to tangent points

#

you often can form straight lines or right angles

#

draw those first, see what you can infer about the resulting shapes

lavish slate
#

It's late, so I will try tomorrow, but thanks

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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random thunder
#

arent these solutions wrong?

odd edgeBOT
random thunder
#

they seperate NRMA and country road but dont they earn interest together in the last 10 days leading up to the bill being paid?

#

like for eg i brope my answers down into two parts

#

3rd - 26th august: & 27-6th september

#

you get the same answer nvm

#

i realised there was an unrelated error in my calcs

#

.close

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serene patio
#

Cross Product
I watched 3blue1brown cross product in the light of transformation
At 8:23, he says that x(v₂* w₃ - v₃ * w₂) is the same as ihat(v₂* w₃ - v₃ * w₂) however ihat is a unit vector and is equal to 1 while x could be any number.

serene patio
#

can someone explain why is x and i hat can be said as same

wooden python
#

but i will repeat that "x and i are the same thing" is a misconception

#

they are 'related' in the sense that i, the vector, is parallel to the x-axis

#

!noclopen btw

odd edgeBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

#

@serene patio Has your question been resolved?

odd edgeBOT
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#
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toxic meteor
#

Guys does this have a limit

odd edgeBOT
toxic meteor
tall ivy
#

At 0?

toxic meteor
#

Yes

tall ivy
#

It should, yes

toxic meteor
#

How

tall ivy
#

Do you know the l'hopital rule

toxic meteor
#

Yes but cos/x isn’t the rule

#

It should be 1-cos/x

tall ivy
#

Ahhh yes, yeah it shouldn't, mb

toxic meteor
#

So it doesn’t have a limit

marble laurel
#

$\frac{\cos(x)}{\sin(x)} = \cot(x)$

tall ivy
#

I was counting on an extra x, but it's just gonna be 1/x

clever fjordBOT
#

VulcanOne

tall ivy
toxic meteor
#

Ok thanks

#

.close

odd edgeBOT
#
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ashen hatch
#

Let m and n be positive integers where m≥n
1/m+1/n=2/33

Find the maximum value of m-n

ashen hatch
#

pretty damn sure the answer is ||m=561, n=17. thus, it's 544||

mystic nova
#

,calc 1/561 + 1/17

clever fjordBOT
#

Result:

0.060606060606061
mystic nova
#

,calc 2/33

clever fjordBOT
#

Result:

0.060606060606061
mystic nova
#

That's a solution, not sure if it's the only one

#

What have you tried?

ashen hatch
#

I rearranged the terms as (2m-33)(2n-33)=1089

#

it is probably possible to rearrange in the form of 1m

mystic nova
#

,w factor 1089

ashen hatch
#

(nvm it's not. it wouldn't be an integer value)

ashen hatch
#

the most ideal solution is to set 2m-33=1089

#

and 2n-33=1

mystic nova
#

You can check for all cases

#

That shouldn't be too long

ashen hatch
#

its asking for maximized m-n, so I just maximized m

mystic nova
#

,calc 363*3

clever fjordBOT
#

Result:

1089
ashen hatch
#

for the case of 363

#

2m-33=363
2n-33=3

#

,calc (363+33)/2

clever fjordBOT
#

Result:

198
ashen hatch
#

m=198, n=18

mystic nova
#

There's one more case for m>n

#

,calc 121*9

clever fjordBOT
#

Result:

1089
mystic nova
#

Do you know how to find these cases?

ashen hatch
#

2m-33=121
m=72

ashen hatch
mystic nova
#

Yeah

#

That should be all the cases

#

I hope I don't miss any

ashen hatch
#

yuh

#

so 544 is the maximal value, I believe?

mystic nova
#

For m?

#

Yeah ig so

ashen hatch
#

m-n

#

k thanks

#

.close

odd edgeBOT
#
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#
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cedar path
#

Hi teacher, I have a question about proofs.

When we want to prove certain statements, we sometimes use proof by contradiction. This involves assuming a false statement, which then leads to a contradictory conclusion. From this, we can infer that the negation of our initial assumption must be true—and this negation is often the statement we set out to prove.My question arose while working on proving that the recursive sequence defined by $(x_n = \frac{2}{3}\left(x_{n-1} + \frac{1}{x_{n-1}}\right))$ converges to (\sqrt{2}), using Newton’s method (or more generally, when proving the convergence of this sequence to the square root of 2).I’ve looked at solutions where the approach is to assume the sequence converges to some limit A. After some steps, this leads to solving the equation (A^2 = 2). Here’s my confusion: shouldn’t we first prove that the sequence converges before assuming it has a limit A? why can we use the assumption as a tool, doesn't this lead to circular reasoning?

clever fjordBOT
#

Starland
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

summer wave
#

yeah you should prove it has a limit

wanton bison
#

This approach is more like a way of "guessing" some upper or lower bound which then hopefully you can use to prove the sequence is bounded

#

This is often done in combination with the monotone convergence theorem

cedar path
wanton bison
#

that's what is called a guess

cedar path
#

if the following implication make sense?

#

okay, fine

#

.close

odd edgeBOT
#
Channel closed

Closed by @cedar path

Use .reopen if this was a mistake.

cedar path
#

.reopen

odd edgeBOT
#

cedar path
#

what happend @summer wave

summer wave
#

I was wondering what you meant

summer wave
cedar path
#

sry, might be confusing, i'm a poor english speaker

#

😭

summer wave
#

np

#

in any case, you need to prove convergence before using limit laws

wanton bison
#

i was wondering too and then forgot this channel

#

btw closing/reopening shouldn't be done, so your channel appears above others

summer wave
#

no, I was typing after he closed, that's why

wanton bison
#

Though, I don't know what to say further; again, by taking the limit (even illegally) you are trying to find a possible upper/lower bound (depending on how your sequence behaves monotonically) that you can then use to prove your sequence is bounded somehow. That bound can fail to work of course, and also by "taking the limit" you are not trying to use that as a proof that the sequence converges, but rather you are doing scratch work.

#

this channel is occupied

#

you can get one in the available list

summer wave
#

Also, sometimes you can prove a sequence diverges by assuming it has a limit

mystic saffron
# cedar path Hi teacher, I have a question about proofs. When we want to prove certain state...

In the mathematical field of real analysis, the monotone convergence theorem is any of a number of related theorems proving the good convergence behaviour of monotonic sequences, i.e. sequences that are non-increasing, or non-decreasing. In its simplest form, it says that a non-decreasing bounded-above sequence of real numbers

...

odd edgeBOT
#

@cedar path Has your question been resolved?

summer wave
#

newton's method isn't always monotone though

faint knot
odd edgeBOT
#
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odd edgeBOT
#
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trim kiln
#

Hello! I'm working on math homework at the moment, and I need to figure out how to factor this trinomial. I couldn't do it using the X method my teacher taught me, so I'm kinda lost

trim kiln
summer wave
#

did you find any roots?

trim kiln
#

You mean √ the trinomial?

#

Also, I have a question- can you factor a trinomial by using the quadratic formula or am I misremembering

elfin zodiac
#

You can complete the square and after the difference of squares and you got your factored form.

late dust
#

Mind telling us what the "X method" is?

summer wave
#

after looking it up on the internet, it's a rather mysterious method...

#

I think it works on "nice" polynomials only

trim kiln
#

So basically, I was taught that a trick you can do is to multiply the first and last # in the trinomial, then split the center number into two factors that multiply to make one and add to make the other
Mb if it's worded weird

trim kiln
cursive pendant
late dust
#

Right, that method works but good luck finding the correct numbers in this case

summer wave
#

I would advise you to just doing the quadratic as well

elfin zodiac
#

You should start by factoring out 5, so your polynomial is easier

cursive pendant
#

cuz its not nice looking tbh

late dust
#

Tbh if you're going to use the quadratic formula, factoring 5 doesn't matter

#

(I mean kinda, depends if you understand it correctly)

elfin zodiac
#

he said no formula right?

#

maybe i missread

trim kiln
elfin zodiac
#

wasn't you talking about a mysterious x method? 😄

trim kiln
#

Ohhhh yeah that lmao

elfin zodiac
#

whatever, you can do this in tons of ways

#

learn them all

#

so you can choose the best on each case

late dust
#

Any other question?

trim kiln
#

Hold on, give me a moment

#

Okay, so I got
-40 ± 6√10

    10 

(Which I feel like I could probably simplify to -40 ± 6√10/10)

late dust
#

Just use parentheses

#

Can you state the quadratic formula?

trim kiln
#

This might be hard to write
Isn't it:
-b ± √b² - 4ac

 2a
late dust
#

Ok you can use sqrt(...) for the square root, b^2 for the square, and just parenthesize the numerator and denominator so you don't have to write it in multiple lines

#

So like that:
(-b +- sqrt(b^2 - 4ac)) / (2a)

#

(+- to be interpreted as "plus or minus" of course, not +(-(...)) )

#

Anyway, we have a = 5, b = 40, c = -10, right?

trim kiln
#

Yeah

late dust
#

(-40 +- sqrt(40^2 - 4*5*(-10))) / (2*5)

#

40^2 - 4*5*(-10) = 40^2 + 5*40 = (8+1)*5*40

#

Do you agree with that?

trim kiln
late dust
#

Just factoring

#

Ok hold on I'll try making it clearer

#

$$40^2 - 4 \cdot 5 \cdot (-10) = 40^2 + 5 \cdot 40$$
$$= 8 \cdot 5 \cdot 40 + 5 \cdot 40 = (8+1) \cdot 5 \cdot 40$$
$$= 3^2 \cdot 5^2 \cdot 2^2 \cdot 2 = 30^2 \cdot 2$$

trim kiln
#

Ohhh okay

clever fjordBOT
late dust
#

Yeah?

#

So (-40 +- sqrt(30^2 * 2) ) / (2*5)

#

= -4 +- 3sqrt(2)

#

(your 6sqrt(10) was off)

trim kiln
#

Alright
That kind of makes sense

late dust
#

It's just boring calculations, practice and you get better

noble ether
#

Can I share a fun fact

#

?

late dust
#

If it's related to the question, sure

trim kiln
noble ether
#

No

#

It comes by rationalisation of the original formula

#

It's just there

#

It's pretty neat

#

Tho

late dust
#

In some situations when you're doing numerical stuff you can get poor accuracy with one formula and better with the other

#

Probably used by some software, but idk enough about that

#

Not very useful to learn either way

trim kiln
#

Ok
Thank you!

late dust
#

So anyway, the factorization is 5(x - root1)(x - root2)

noble ether
#

Well

#

The first formula has a clear preference

#

Because if c = 0

#

Then the second one only yields one root

#

Yet

#

The other can be easily figured out

late dust
#

Tbh if c=0 you don't need a quadratic formula

noble ether
#

Yes

#

But

#

A formula must yield all the answers

late dust
#

Sure

noble ether
#

Yet if we consider the penultimate case, if a = 0, the original formula becomes undefined

#

As it isn't a quadratic

#

At that point

#

Neither does the second

#

So first better

trim kiln
#

.close

odd edgeBOT
#
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late dust
odd edgeBOT
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mighty granite
odd edgeBOT
mighty granite
#

im at after the quadratic formula my problem is with X2=-(5/3)

vivid wyvern
#

Can u show ur work?

mighty granite
#

sorry if a bit hard to read

vivid wyvern
mighty granite
#

i just put it into the quadratic formula and got those two

vivid wyvern
mighty granite
#

i did not, ill try

sweet dagger
vivid wyvern
mighty granite
vivid wyvern
mighty granite
#

and those are scary

mighty granite
#

yea, coz i have to put in the original formula to show that one side is equal to the other

#

like to show my work and stuff, thats what after i got those x1 and x2 i started putting them in the formula. coz i need to also write that why they would work

mighty granite
#

yea at the bottom u can see i tried X2, failed, put an asterisk to mark that i was having a problem and moved on

clever fjordBOT
mighty granite
#

yes i added together the -7 to it

#

and thats the fraction i got

#

26/5

#

OHHH

#

my bad

#

ill try again

vivid wyvern
#

Yea i did it and got the same answer on both sides,so it works

mighty granite
#

just checking real quick

#

i didnt somehow

#

(its an equal sign not -6/-52)

vivid wyvern
#

U get 27/26

#

On both sides

#

Dont u?

mighty granite
#

checked again, yes

#

thank u so much

vivid wyvern
#

Np,good work

mighty granite
#

.close

odd edgeBOT
#
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odd edgeBOT
#
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tiny talon
#

hi is there a way to deform a trefoil (where it has a rope and we only consider the surface) into a torus

tiny talon
#

im not sure if it is homeomorphic to torus but i dont see what else it could be

#

im looking for a more visual explanation than a formal proof, thanks

#

if this is not the right place to ask, can someone redirect me

west light
pastel orbit
tiny talon
#

im currently not at the level to know much topology and manifolds

pastel orbit
#

that means the trefoil is homeomorphic to S^1, which isn't homeo to the torus

tiny talon
#

hm

#

i am satisfied with the fact that it is not a torus

pastel orbit
#

I mean, one way to think about this is that a trefoil is 1-dimensional - if you stand on it, it looks locally like a line

tiny talon
#

i did try a lot of methods to try to turn it into one

pastel orbit
#

whereas the torus is 2-dimensional

#

it looks flat locally when you stand on its surface

#

so they can't possibly be the same object, no matter how we perform our deformation

tiny talon
#

sorry by trefoil i didnt mean the actual knot. i was describing how the shape looked, which consisted of a trefoil done by a rope, and isolating the surface of the rope

west light
#

Ah then yes that's homeomorhic to a torus.

tiny talon
#

im not sure how to deform it to make it a torus

west light
#

You can't

#

They're not isotopic.

tiny talon
#

i see. i think i was given a temporary definition

#

in which you could deform one to another and call it homeomorphic

#

sorry if that messed stuff up

west light
#

Yes, it does apply in one direction

#

If you can deform one to another continuously without self-intersection etc, then they're homeomorphic.

#

But not all homeomorphic objects can be deformed to each other in this way.

tiny talon
#

oh i see. i guess ill get to that later

#

this does solve my question though thanks

#

.close

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#
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odd edgeBOT
#
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blazing valve
odd edgeBOT
blazing valve
#

Im not understanding what this problem is asking for 😭

lone elbow
#

, rotate

clever fjordBOT
meager juniper
#

@blazing valve looks like a related rates problem

#

Notice that the point (x,y) is always on a particular circle. And notice that this point on the circle is a particular distance from some point. How can you relate, for instance, the distance from the top of the building to some point (x,y)?

#

Because this is a related rate problem, you'll be chaining together several different variables using a few different equations.

blazing valve
#

😭 uhh the a2 + y2

#

Is

#

C2

#

But im not understanding how the rope is changing rate

#

Like its pulled towards rhe building ?

meager juniper
#

The length of the rope is shrinking

#

Which pulls the pipe up

blazing valve
#

Ohh

#

So its asking for dx/dt

#

And dy/dt

meager juniper
#

Yup

#

And you're given ds/dt, so you need to find which derivatives?

blazing valve
#

Huh

#

.close

odd edgeBOT
#
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odd edgeBOT
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flat furnace
#

hi i need help doing basic algebra, i think its distributive property but i cant seem to find a yt vid for an equation like this, idk i just dont know how to look for it on yt, please help me understand

lavish jackal
#

which question?

flat furnace
#

um .. i guess just the concept in general

#

sorey im just struggling with this right now

lavish jackal
#

im guessing u stuck at 2nd question?

flat furnace
#

yeahhhh

lavish jackal
#

well try distributing 4.2(15+5x) first

flat furnace
#

okay

#

63 + 21x

indigo dirge
#

yep, that's right

#

and you set that equal to the right hand side, correct?

flat furnace
#

yup

indigo dirge
#

so 63 + 21x = -20x - 21 - x

#

now, you can simplify the rhs a bit, how?

flat furnace
#

uuuuuhhh

#

21x - 21 ?

#

or

#

uhmm

#

is it a negative x ? so would it be 19x - 21

lavish jackal
#

no

indigo dirge
flat furnace
#

OHH -21x

indigo dirge
#

yep!

#

so what's your equation now?

flat furnace
#

-21x - 21 ??

lavish jackal
#

yes

flat furnace
#

so then what do i do

lavish jackal
#

move the x's on left side and the numbers to the right side

#

just to make it easier to solve

#

for x

flat furnace
#

wait what do you mean

lavish jackal
#

move all terms involving x to one side and constants to the other

#

add 21x to both sides to bring all x to the left