help-19

[merry finch]

What have you tried

[jagged maple]

iv) f isn't injective since you have f(4) = f(1) = 2

@wanton bison am i wrong?

[merry finch]

That’s great that you’re just doing his homework for him

Do you get paid?

[wanton bison]

You are supposed to help and not give out answers 😂

[jagged maple]

oh ok lol

well at least I'm saying out loud why it's injective or not

[merry finch]

They won’t learn anything if you do that

[wanton bison]

@lone elbow stop playing osu

ffs

[merry finch]

We’re not here to see how good you are at these problems

[lone elbow]

.close

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[thin latch]

guys can you tell me how to memorie all the formulas of trignometric eqn , do i just memorize them or what it too hard memorizing them

[odd edge]

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[wintry burrow]

What am I doing wrong?

[unkempt lichen]

!xy

[odd edge]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[unkempt lichen]

your mass is 5.37 instead of 5.34 for some reason

[wintry burrow]

ah

[unkempt lichen]

your length is also 0.791m instead of 0.721m

and the tension is 38.3N instead of 33.9N

so... just about every provided value was wrongly copied

[mystic nova]

-# Definitely need a better glasses

[wintry burrow]

never do math with a fried brain

[odd edge]

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[twin vigil]

How would I find displacement

Using l = r theta doesn't make any sense to calculate displacement

[languid dune]

Are you calculating the work dome by gravity?

[twin vigil]

Yes

[languid dune]

Then you only need to consider the vertical displacement

to calculate work done by gravity

Do you want me to frame my words nicely?

[crude pier]

Isnt this physics

[twin vigil]

Yes

Vertical displacement

[crude pier]

Movement in the y direction

[twin vigil]

Why vertical it moves right to left in arc?

[crude pier]

If you notice while moving left to right

It moves up too

[languid dune]

do you know that gravitational force is a conservative force?

[twin vigil]

Yes

[twin vigil]

Yes

[languid dune]

and do you know what a conservative force is?

[twin vigil]

Yes

I studied those forces but i can't recall it

Rn

[languid dune]

Good. As gravitational force is conservative in nature, the work done by it is irrelevant of the path taken. Work done only depends upon the final and initial position

[languid dune]

conservative forces are those forces for which the work done is same, no matter how we move a particle in its field if initial and final position is the same

[twin vigil]

That is why W_spring = -1/2k((x_f)²-(x_i)²

right?

[languid dune]

yea, no matter how you move your spring, the work done by it depends only on final and initial position

[twin vigil]

final and initial position is only for conservative forces rright?

ie spring force, gravitational force

[languid dune]

Ya

[languid dune]

Yes

but for friction (non conservative force) the path taken also influences the work done

[twin vigil]

it depends on the situation right?

[languid dune]

yea it depends how we move the object

[twin vigil]

plus surface as well

[languid dune]

'it depends on the path taken'

[twin vigil]

but surface is fine most of the times

[languid dune]

yea more friction more work done

[languid dune]

theoretically but not actually

[twin vigil]

then it is mg. l-lcos37°

[languid dune]

Yess

[twin vigil]

yes at microscopic level

[languid dune]

yeaa

[twin vigil]

I read this concept of work done till spring forces from hrk but I still couldn't reason this?

[languid dune]

concept of conservative forces?

[twin vigil]

not yet

I thought to practice questions of what I read

[twin vigil]

But studied once in class and don't understand quite well

[languid dune]

to check if a force is conservative, the work done, by it in a closed loop is 0.

What i mean by this is

Let's say you have a block of mass m at height h from a horizontal surface

And now you move it downwards and place it on the surface

What's the work done by gravity?

[twin vigil]

while raising it up it is negative and moving it down it is positive

[languid dune]

yea in this case we r moving it down so it is positive

[twin vigil]

Because force and displacement in the opposite direction?

[languid dune]

and now we move it "horizontally" to a distance d, what's the work done by gravity

[languid dune]

yea that's the case when we move it upwards

displacement would be up, and the force would be down

[twin vigil]

and vice versa for downwards

[languid dune]

Ya

[twin vigil]

0

[languid dune]

.?

Yupp

and now we move it again to a height h

[twin vigil]

no displacement at all by gravity

[languid dune]

whats the work donw

[languid dune]

yea, or you can say that force was perpendicular to the direction of displacement, resulting in no work done

[twin vigil]

Yes this is more technical

[twin vigil]

Negative

[twin vigil]

Since dot product is 0

[languid dune]

yup and it is equal to the magnitude of work done while moving it down

[languid dune]

Exxactlyy

[languid dune]

so what just happened, is that we just showed that work done by gravity in a closed loop is 0 , thus it is conservative

and for that pendulum problem, you could've imagined that first we moved the pendulum to left(horizontally) and then we move it down (vertically)

Although that's not how the pendulum goes but

since we know work done by gravity is only influenced by the final and initial position, the path taken doesn't matter

[languid dune]

and for simplicity we chose this path, as the horizontal displacement results in no work done leaving the vertical displacement to produce work done

[twin vigil]

Got it

Very much clear

[languid dune]

:)

[twin vigil]

I sent you a request to ask these small parts when I stuck

[languid dune]

Sure

[twin vigil]

.close

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[brittle vault]

don’t get what i did wrong answer is 26 (answer key

[brittle vault]

.clowe

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[lone elm]

Apparently the answer should be 1/2 +- 3/2i? Can someone explain why that and not what I got which is 3/2i +-1/2

[weary pelican]

the error is either on the textbook or you copying the question statement

not on your reasoning

[lone elm]

Oh okay so my answer is correct? I copied the question correctly but the textbook does have mistakes sometimes i just didn't know if it was one of them

[bronze citrus]

its correct

[lone elm]

Thank you!

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[trim kiln]

Hello! I need some help with a problem about functions and graphing, which I'm not great at. Screenshot is below!

[late flint]

what does x equal at a y-intercept?

[trim kiln]

0

[late flint]

yes

so you would substitute x = 0 into the equation h = 4x+28

this gives you one of the constants

[trim kiln]

Ok! That makes sense.
I'm still a bit confused about b

[indigo dirge]

similarly, what does y equal at the x-intercept?

[trim kiln]

Hold on-
So since a is 28 (4x0+28 is 28), I know the x intercept is 28, but what does that have to do w the y intercept?

So if I plug in 0 for y, what does that do? Does that mean 0 = 4x + 28?

[late flint]

you have your definitions of x and y intercepts flipped

y intercept is where the function touches the y axis

[late flint]

your last line is how you find the x intercept yes

because when y = 0, you're touching the x axis

[trim kiln]

Okay
So b = 28, right? Because it's the y intercept
I'm sorry I'm kind of slow, I'm still confused on what that has to do with the x axis

[late flint]

yes, b = 28

[trim kiln]

Oh wait um
So b = 28 ✅
The y intercept sets x to zero, which is how we find it
So uhh does that mean we set y to 0 and solve for 4x + 28 to find what equals zero to get a?

[late flint]

exactly

once you find the x that makes y equal zero, you found the x coordinate of the point (a,0)

[trim kiln]

Ok
Thank you! :))

That makes sense now

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[ivory steppe]

Hello! I am having trouble with Rational Functions. I would appreciate help. Thank you!

[next granite]

Which part are you struggling with?

[ivory steppe]

Domain, Range, x-intercept point, Vertical Asymptote, and Horizontal Asymptote. Specifically on that question itself

[next granite]

Okay so let's start with x intercept. The x intercept is basically asking when does the y value = 0 ? In this case where do you think y =0 on the x axis? Or where does the graph intersect the x axis

[ivory steppe]

The curve intersected on the origin?

[next granite]

Where do you see intersection on the curve? Can you tell me

[ivory steppe]

(1,0)

x axis

[next granite]

Correct so that's your x intercept

[ivory steppe]

(1,0)?

[next granite]

Yes

Now let's talk about asymptotes

Do you know what asymptotes are?

[ivory steppe]

guides for lines but do not meet or intersect

Im good with horizontal but its hard for me with vertical

[next granite]

well vertical asymptotes are bascially the same thing as horizontal asymptotes. you are approaching a value but never meeting or intersecting it like you said

in this case what value can you see both graphs approaching vertically?

[ivory steppe]

Around 18? Its the closest

[next granite]

this is what a vertical asymptote is

[ivory steppe]

Agh

Ahhh

Theres none in the graph?

[unkempt lichen]

there is one

[next granite]

there is an asymptote

if you look at the graph there is a value x= ____ that both graphs get reaaly really close to but never touch/intersect

look closely

[unkempt lichen]

draw the vertical line that separates the left side from the right, so to speak

[ivory steppe]

(-6,0)??

[unkempt lichen]

an asymptote is not a point btw

it's a line

[next granite]

you're looking at it horizontally

[unkempt lichen]

and x = -6 is not that line

[next granite]

look at it as a big line going from the top of the graph to the bottom.

[ivory steppe]

0?

[unkempt lichen]

closer but not quite

[unkempt lichen]

as you can see, the right curve crosses the y-axis, so it can't be x = 0

[ivory steppe]

1?

[next granite]

would it be +1?

[ivory steppe]

Yes

[unkempt lichen]

nope

when you come up with an answer, try drawing a vertical line at that point

if the line cuts the graph

it's not correct

mb, typing on phone

[ivory steppe]

Oh its at positive 4?

[unkempt lichen]

try drawing a vertical line at 4

i don't think it will work

and you're getting further away

instead of guessing, look at where your two curves head towards

ignoring the extreme right and left

they come together towards a certain vertical line but never quite meet it

[ivory steppe]

I need a hint😭

[unkempt lichen]

this is the hint

if you can't figure it out, for the left curve, draw the vertical line that the left curve tends towards

do the same for the right curve

you'll find that those two vertical lines are the same

[ivory steppe]

Around 9

[next granite]

forget the question you are doing and look at this graph

in this graph can you see the value x=2?

that x=2 represents a vertical asymptote. if you look at the behaviour of both graphs they get really really really close to the x=2 asymptote but never touch it.

so think about it like this: there is a line that seperates the left side of the graph and the right side of the graph. that line is the vertical asymptote.

and here is your hint.. the asymptote is on the left side of the graph ( the negative side )

[odd edge]

@ivory steppe Has your question been resolved?

[ivory steppe]

Yes

Is VA= -1?

I am sorry but atp i need the answers since thers only 20 mins left for the timer. I will still need to figure out how to get it ofc

@rancid moat

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[snow dragon]

If p:3q and 2q:r, what is p:q:r?

a few friends are in a debate if its 2:6:3 or 3:1:2?

[vernal yacht]

Could you send the original question? 🙂

[snow dragon]

This is the question on ratios

If p:3q and 2q:r, what is the ratio of p:q:r?

[vernal yacht]

hmm…..u mean p = 3q; 2q = r perchance?

[snow dragon]

yes you can take it as that i guess

but the answer needs to be the ratio between p:q:r

[vernal yacht]

Alr!! Do you have any idea in advance?

[noble ether]

If the ratioes are equal to 1, then the answer is 3:1:2

If not

Then let p/2q = a, 2q/r = b

Then p:q:r = 3ab: b :2

[vernal yacht]

Why are we making our lives difficult?

[noble ether]

Idk

[snow dragon]

Could you explain why the 2:6:3 is wrong?

Was thought of as
p:q = 1:3
p:q = 2:6

q:r = 2:1
q:r = 6:3

p:q:r = 2:6:3

[vernal yacht]

First of all, p:q is not 1:3

[noble ether]

Yes

[snow dragon]

Ohh mb I get it now

[noble ether]

This would imply ratioes are equivalent to 1

In which case

Answer is 3:1:2

Only

Not

2:6:3

[snow dragon]

Thank you for that :)

[noble ether]

Let It be some arbitrary constant not equivalent to zero

And solve

@snow dragon if it’s clear, u can use .close

[snow dragon]

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[young tapir]

uh what is the sqrt of 1 + 2

[young tapir]

im stuck

😢

[crystal charm]

sqrt(1+2)?

[young tapir]

sqrt(1) + 2

ts is tragic

[crystal charm]

don't troll in the help channels

[wanton bison]

if we only had calculators

[young tapir]

im sorry ok

[wispy peak]

I really wanna get the helpful role

[young tapir]

.close

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[wispy peak]

But these Qs are too hard

[young tapir]

i know right

[zinc glacier]

if you think about it, they say money is the root of all problems

maybe the answer is money+2

[vernal yacht]

#help-29

[wispy peak]

Ahahahhaha

[young tapir]

https://tenor.com/view/black-guy-shcoked-gif-27654754

[wispy peak]

-# I was being sarcastic here
But yea I saw this but Ann is already on it with the helpee

[young tapir]

my life savings are 218$

so the answer is 220?

[zinc glacier]

you do have to be a bit quick on the draw

[vernal yacht]

Just go leave some recommendations, every message counts

[wispy peak]

Yea not I’m quick at all

[wispy peak]

Ic tyy sky

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[trim kiln]

Hello! I'm a bit confused on this question and I'm unfamiliar with these kinds of problems. Screenshot is below!

[vernal yacht]

Alr!! What have you tried?

[trim kiln]

So, I've tried dividing 2x^3 + 42^2 + 208x by x+b but I'm not quite sure how that'll lead me to figure out how small b is

[vernal yacht]

Looks like a legit approach, could you show your work?

[trim kiln]

Yeah hold on, let me grab my notebook

So um
I kinda forgot how to divide two equations together but I've tried my best according to my work here

I'm pretty sure I was supposed to move b off to the side? I don't know

[modern sundial]

Just subtract them at this point

[trim kiln]

2x^3 + 42^2 + 208x minus x+b?

[modern sundial]

no, you take the top equation and you subtract from it the bottom equation

so 2x^3 +42x^2 +208x - (2x^3+2x^2b)

Then divide again until you have a remainder

[trim kiln]

What would 42x² - 2x² x b be? Would it be 40x² x b?

[modern sundial]

No, first don't write multiplication using an x when you are using the variable x. Just factor out the x^2 first.

e.g., ab - ac = a(b-c)

[trim kiln]

You mean first I divide the big equation by x²?

[modern sundial]

You specifically asked me what the difference of two things are. I said you were incorrect and described how to subtract them properly.

division comes after you subtract correctly.

[trim kiln]

Ok, hold on

[modern sundial]

You should probably just look at a webpage that fully explains polynomial long division. There is little benefit to trying to use an algorithm that you barely remember. e.g., https://courses.lumenlearning.com/waymakercollegealgebra/chapter/polynomial-long-division/

[trim kiln]

Ok! Thank you very much 🙏

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[shell marlin]

where do we need complex number and in general rotations in real life and are they really as imaginary as the name suggests?

[shell marlin]

like complex numbers are supposed to be able to represent a rotation, but where do we need that in real life

if negative numbers represent a 180 turn in direction

where do we need these other directions in real life

[low locust]

yes I have never rotated 90 degrees in real life

[graceful viper]

video game development might be a good place to look into

[low locust]

anything that oscillates can be very well represented with complex numbers.

which is very important in eg physics

[wooden python]

https://demoman.net/?a=trig-for-games

[modern sundial]

I can understand when people ask for the application of some tersely written theorem, but you should be able to imagine a situation where you rotate something.

[wooden python]

"imaginary" is a bad word that stuck around because history

[shell marlin]

I'm talking about rotation that is represented by complex numbers

[modern sundial]

I mean, take the entire field of data science for example. You often want to rotate a data set.

[low locust]

well you dont really need all the nice things about complex numbers for that. could just use a 2x2 real matrix

[shell marlin]

i dont know what that is, im newbie to math

[shell marlin]

isnt a rotation in game dev a 3 value thing, rather than complex numbers?

[graceful viper]

well really they use quaternions

[low locust]

rotation in 2d can be represented by complex numbers

among other representations

some more or less useful depending on the specific thing you wanna do

in 3d there are several different ways to represent rotations

one of them being quaternions which are similar to complex numbers

[shell marlin]

what can represent 3d and 4d rotations?

[shell marlin]

i see Im gonna look into that

[low locust]

freya holmer gave a nice talk about it

you can find it on yt

[shell marlin]

thanks yll

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[ebon oar]

I only know this but confused

[low locust]

what is happening to those 2s

[long tinsel]

Old notation for factorials

But I think this question isn't well defined

I'd expect you'd have to expand the taylor series for f(x) and then plug in x --> x/(1 + x^2)

But the value you plug into the derivative would be fixed, not variable

[wanton bison]

,w simplify x^2/(1 + x)-x

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[odd edge]

@ebon oar Has your question been resolved?

[ebon oar]

Could you explain more?

[odd edge]

@ebon oar Has your question been resolved?

[summer wave]

in your first image, notice that the f', f'' etc are evaluated at a, not x

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[supple jasper]

I am confused

[smoky nacelle]

confused what?

[supple jasper]

The test

By which the triangles will be congruent

[smoky nacelle]

i suggest you use a-s-a

as i’m seeing here that angle q is shared

[supple jasper]

s-a-s?

Because only one angle is given

[smoky nacelle]

the angle q is shared

and there r no other given equivalent side other than pq and rq

besides angle p=angle r

so it makes the test a-s-a

[supple jasper]

So the statement should be
∆PQT congruent to ∆RQS by a-s-a test

[smoky nacelle]

yes

[supple jasper]

This is the answer?

[smoky nacelle]

yes

[supple jasper]

ok ty

.close

[odd edge]

Channel closed

Closed by @supple jasper

Use .reopen if this was a mistake.

[smoky nacelle]

np

[odd edge]

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[austere mist]

guys is torque defined same way as the angular momentum i

[austere mist]

is

like

tao = r vector cross force vector

[odd edge]

@austere mist Has your question been resolved?

[odd edge]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[austere mist]

torque is the cause of angular acceleration

[austere mist]

it means that angular acceleration causes the torque right

[unkempt lichen]

the implication is backwards

torque is the cause of angular acceleration = torque causes angular acceleration

[austere mist]

but that dosent make sense

torque is a force that pierces the plane of two vectors

right ??

it is caused by angular acceleration no

??

if there is angular acceleration torque is produced

or am i missing something

[glass vault]

if force causes acceleration then torque causes angular acceleration

[austere mist]

yeaaaaaaaaaaaaahhhhh

ure right

can u help me picture it

[odd edge]

@austere mist Has your question been resolved?

[austere mist]

<@&286206848099549185>

[stark dock]

what is your question

[austere mist]

help me picture torque

bruh ure 11th

[stark dock]

yeah but a jee math aspirant

[austere mist]

i see

[stark dock]

could you locate

where it is

[austere mist]

huh

wha

[stark dock]

you are which grade

[austere mist]

12th idk if its the same out there with india

im from nepal

[stark dock]

locate i could nt find

i could do my best with that

[austere mist]

wth

what are u implying

[stark dock]

question

[golden sonnet]

ayo bro

[austere mist]

!! this is my question !!

[golden sonnet]

my man

[faint knot]

if you turn a screw with a wrench,

1. you are pushing the wrench, this is force
2. the wrench turns the screw, this is torque
3. the screw begins to start turning then turns faster as you keep putting in force, this is the angular acceleration

[austere mist]

hmm

[stark dock]

why

[austere mist]

can u give some more

[golden sonnet]

im from the same nation preparing for jee

[stark dock]

ohh

[austere mist]

guyss

stop discussing

and answer me

[stark dock]

which grade

[austere mist]

theres a discussion channel

[golden sonnet]

12

[stark dock]

i am scrolling my books get some ideas wait bro

[austere mist]

k k

[lean yew]

sure, but in the meantime try not to flood OP's channel with chatting

[austere mist]

seia i see ya

[stark dock]

ok

If you hit exactly at the center of mass, the ball flies straight - here force only
If you hit off-center, it spins as well - here force and torque

this would be easy to picture it

bro is it ok

[austere mist]

no

i dont get it

how do u know what is torque

its easy to define and understand force

i wanna feel something like that

[odd edge]

@austere mist Has your question been resolved?

[odd edge]

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Closed due to timeout

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen scroll]

this is not true right bc theres no 9 or 11 in M

[warped badger]

Yeah, it isn't true

[keen scroll]

sigmaa

i wish my sir provided the damn answer key

ty prim

.close

[odd edge]

Channel closed

Closed by @keen scroll

Use .reopen if this was a mistake.

[keen scroll]

this is correct right

everything of A that intersects with everything that is not B

might be cooked for tmrw exam

[dry fog]

Intersection of A and U\B

[keen scroll]

ye

wait what

[keen scroll]

U\B?

[dry fog]

B' here means U without B

[fast carbon]

"The intersection of A and the complement of B"

[unkempt lichen]

i don't think this is correct if an intersection is asked for

[vernal yacht]

[keen scroll]

but isnt the stuff outside also in a

[dry fog]

yes

[fast carbon]

Er... the stuff in A is specifically the stuff inside A's circle, so no, stuff outside the circles is not in A

[keen scroll]

wait

[dry fog]

by definition of subset, if an element is in A and not in B then A is not a subset of B

[unkempt lichen]

how is the stuff outside A in A though?

[keen scroll]

this

A intersection A

because if not b is A

Ohhhhhhhhhh

?

[fast carbon]

Yea

[keen scroll]

Sigggggma

im gonnaa pass tmrw

for ytall

[dry fog]

no, its empty set

[keen scroll]

fr

[dry fog]

wait

[keen scroll]

wat

[fast carbon]

Don't worry, the most recent picture is correct

[dry fog]

this correct one

[keen scroll]

oki

another q.

c would be this?

B union B

so everything in B and everything in B

[dry fog]

A' is also U

[fast carbon]

Don't think of A' as B. A' is not B.

[fast carbon]

Though, as it turns out, yes it is correct.

[keen scroll]

LOL

right for all the wrong reasons

[odd edge]

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen scroll]

mf what

[keen scroll]

.reopne

oh

i forgot to reopne

[keen scroll]

who is correct lol... u or abnaclut

[dry fog]

which one

c?

[keen scroll]

im feeling this is for C

everythong not A and B

[bronze citrus]

im studying the same thing rn lol

[keen scroll]

LOL

🤝

[dry fog]

entire B

[bronze citrus]

whats ur question

[fast carbon]

Sorry I mixed up a symbol at one point

[keen scroll]

going through them oe by one

[fast carbon]

I'll leave this to the others

[bronze citrus]

wich one u represented

[keen scroll]

this is d

A and everything thats nopt b

rihgt

\sigma.. im getting the hang of it

[unkempt lichen]

A or everything that's not B

[fast carbon]

You need all of A

[bronze citrus]

b' is the complementary right??

[keen scroll]

yes

[keen scroll]

or?

i thought intersction of a and bis everyhting in a and b in one set

[bronze citrus]

thats wrong

[keen scroll]

ig using or also makes sense

[keen scroll]

N ani

[unkempt lichen]

there's a slight difference between ORs and ANDs in mathematical logic

[dry fog]

missed part of A

[bronze citrus]

u didnt shade the intersection of A and B because its always a part of a

[keen scroll]

but i thought

b cant be included

?

[unkempt lichen]

oh didn't notice that part

[keen scroll]

cus not b

[unkempt lichen]

it's a union

[keen scroll]

heccin.

[unkempt lichen]

include everything that is in either set

[bronze citrus]

no one said that

[keen scroll]

i thought i was gonna do some past paper questions
but imma have to just finsih the fckin school w/s...........

[unkempt lichen]

this is why i used OR for union instead of AND

[keen scroll]

what do u use for intersctions

[keen scroll]

A or NOT B

[dry fog]

and

[unkempt lichen]

AND

[bronze citrus]

its just b' + A if you remove a part of A its like you hurted him thats not fair

[unkempt lichen]

when we say OR, it means either or both

AND requires both

[keen scroll]

let me try anotehr one

NOT ( A AND B )

[bronze citrus]

wrong

[keen scroll]

ive gotten all of the mwrong so far...

[bronze citrus]

look ill give you a tip

[dry fog]

don't shade the intersection

[keen scroll]

i didnt

[lean yew]

first consider A AND B

[bronze citrus]

shade B' with a color and A with another color

try this

[lean yew]

then shade everything except that

[keen scroll]

I DID

i didnt mean

for the line

go through

the intersection

[keen scroll]

let me try to cook with the logic of AND and OR first

[lean yew]

might wanna make it clear

because part of one of the lines is striking through the intersection

[keen scroll]

mouse

lol

[lean yew]

would recommend finer lines

well...

[keen scroll]

NOT a or b

[dry fog]

ye

[keen scroll]

yo this or not tign fire

let me tryt from the start

[bronze citrus]

[keen scroll]

A and not b

[dry fog]

good

[keen scroll]

so A and everything outside of b...?

[dry fog]

ye

[keen scroll]

YOOO

[whole gyro]

wromg

[keen scroll]

BRO.

[whole gyro]

that upside down u means intersection

[keen scroll]

yes....

[whole gyro]

so if you painted everything thats not b, then see whats common with a, you'll get your answer

[keen scroll]

OH

[whole gyro]

(intersection -> whats common)

[keen scroll]

brrrrrrrrrrrrrr

[dry fog]

wrong shading

[keen scroll]

im so scared

for my test tmrw

the ONE TIME I DONT REVISE A TOPIC

[bronze citrus]

dw

[keen scroll]

AFTER I LEARN IT

SHIT COMES FALLIN=G DOWN ON ME BRO

[whole gyro]

do the shading

[bronze citrus]

send me the pic ill send u the answers

and ull get c-

[keen scroll]

LOL

[whole gyro]

bruh the point is to learn smh

[bronze citrus]

ikr

[whole gyro]

nvm i got jebaited

[bronze citrus]

average cherry man

[dry fog]

just learn to use logic

[whole gyro]

correct

[keen scroll]

SSSSSSSSSSSSSSS

(NOT A) OR B

[whole gyro]

bruh you missed a part of b

[keen scroll]

excuse the shitty shading...

im on a shitty mouse that weighs 500g

[dry fog]

bad excuse

[whole gyro]

no like you missed a major part

the part thats common to a and b

[keen scroll]

wa

oh

BR

I LEGIT MADE THIS MSITAKE 5 MIN AGO

[whole gyro]

fill tool:

[keen scroll]

im using edge

lol

AIGHT

[whole gyro]

ok keep on edging 🥀

[keen scroll]

A OR (NOT B)

[dry fog]

skip

[unkempt lichen]

i would show the power of a mouse, but it's your channel rn

[dry fog]

same thing

[whole gyro]

correct

[keen scroll]

repeating

till i get the mcorrect

[bronze citrus]

lessgo

[keen scroll]

NOT(A AND B)

so just

shade everything but the intersection

shade the outside box

NOT (A OR B)

30 minutes left

[dry fog]

ye

[keen scroll]

ive been in 1 uqestion for 20 min

[whole gyro]

shade outside the two circles..

[dry fog]

you are fine now I think

[keen scroll]

absoliutely not

even close

this is the same question

[keen scroll]

Vrotato

[bronze citrus]

what about U' cmon u got that

[keen scroll]

NOT (A OR B)

this shade region is A OR B

so dont i just shade

[dry fog]

oh

[keen scroll]

everyhting outside of A OR B

[dry fog]

ye

[keen scroll]

SO just the white outer box..........

[dry fog]

ye

[keen scroll]

ok...

next q

complement of A would be to just shade legit everything but a right

yep

no sahding bc no intersction

just shade a and b

just shade b?

wait no

wait yes

[whole gyro]

wrong

[keen scroll]

CCCCCHERYYYYYYYYYYYYYYYYYYYYYYYYYYYY

[keen scroll]

NOT A AND B

[dry fog]

you can do the rest by yourself I think, use the logic u used before

[whole gyro]

you wont shade the part thats in b but common to a

[keen scroll]

wdym

the complement is with A

so not a

i wont shade anyhtign that has to do wit ha

and that part must

oh

trhat part msut have a intersection with B

so i jsut shade b

[whole gyro]

oh

here yeah

here you just shade b

[keen scroll]

yess

[whole gyro]

mb i didnt see the thing

[keen scroll]

nws ly for helping

A OR NOT B

i will sahde everyhting to do with a and not b

so shade everything but b?

[whole gyro]

yeah

[keen scroll]

SIGMA

IM GETITNG THE HANG OF IT SLOWLY

[whole gyro]

at least for this diagram

[keen scroll]

let me try that for the prev diagram

[keen scroll]

A OR NOT B

so shade a and

including intersection

and the box outsider

[whole gyro]

correct!!

is the whole set of questions about sets

[keen scroll]

nope

thers

surds

uh

sequences'

indicies

standard form

uhhhhhhhhhhh

[whole gyro]

they're in the test right? if you got the hang of sets we can maybe move on

[keen scroll]

i need to get the hang of sets

im good with the other stuff

i did it before

[whole gyro]

right next question

[keen scroll]

yesir

tysm

ru goated

NOT (A AND B)

so i shade everything outside of a and b

but there is no a and b

so i shade nothing?

[dry fog]

shade everything

since intersection is an empty set

[keen scroll]

oh

NOT nothing is

eegveryhting.......

complement of a is the box right

complemenbt of b is

[whole gyro]

yup

[keen scroll]

a shaded without b and the box

[whole gyro]

yeah

[keen scroll]

intersection of a and b is jsut b

a or b is just a

[whole gyro]

yeah yeah

[keen scroll]

not a and b

empty set?

[whole gyro]

yeah

[keen scroll]

cooking somehow

[bronze citrus]

thats an egg

[keen scroll]

egg cell

OVUM

mm

[whole gyro]

sunny side up

[keen scroll]

biology

we were thinking o diffenret eggs it seems

LMO

LMAO

[whole gyro]

loll

[keen scroll]

A or NOT B

[bronze citrus]

cherry cherryman

[keen scroll]

hmmm

[whole gyro]

bro is just a cat, think about that before you speak

[keen scroll]

so just the egg white?

[whole gyro]

its a u b' right?

[keen scroll]

wiat no

[keen scroll]

ye

A OR NOT B

[whole gyro]

well its the whole box @keen scroll

[bronze citrus]

when cherries starrted talking

[keen scroll]

vrochachinjo

EH

A or not b

[whole gyro]

normally b' is everything in the box except b, but joined with a, the hole is patched up

[keen scroll]

a or not b

[whole gyro]

right v?

[keen scroll]

thje parts

of

not b

that intersect iwth a

[whole gyro]

no no no not intersection, its union

[keen scroll]

oh

i read it wrong...

Vro

LOL

if it were

interseciton

then it would jsut be egg white right

[whole gyro]

yup

[keen scroll]

im not gunna do very good in tmrws exam

[whole gyro]

your gonna do great

continue

[whole gyro]

prolly cus its late there right

[keen scroll]

yes

everything but A intersection B

so

not nothing

so everyghting?

wait no

fuck

i was thikning

abt the wrong diagaram

[whole gyro]

in the egg diagram its everythomg except b

[keen scroll]

the egg white and everything outside of it

[whole gyro]

tya

[keen scroll]

didnt shate properly

[whole gyro]

correct

[keen scroll]

this is a beast

[whole gyro]

nice the real test

[keen scroll]

theres more

smaller qeustions

[whole gyro]

how about you do all of them at once

then send them together

this way it will be faster

[keen scroll]

Okayyyyyyyyyyyyyyy

ok imma just do this one

i dont have the capacity to do the rest of htem

i have learnt my lesson

[whole gyro]

about sets

[keen scroll]

ive revised everyhgting else quite well

yeeeeeeeeeeee

4b

[whole gyro]

correct

[keen scroll]

4c

4d

[whole gyro]

correct

[keen scroll]

e

[whole gyro]

correct

[keen scroll]

4f

[whole gyro]

correct

[keen scroll]

g

[whole gyro]

correct

[keen scroll]

h

[whole gyro]

correct

[keen scroll]

4i

holy shit did i get all fo the mcorrect

[whole gyro]

correct

damn you powered through

[keen scroll]

bro im not evne tyhinking

its just ocming to me

[whole gyro]

thats called the power of intuition

[whole gyro]

whats the problem

[keen scroll]

shade

[whole gyro]

correct

[keen scroll]

feel like this is wrong

[whole gyro]

cus it is

no wait

[keen scroll]

(C OR D) AND NOT E

[whole gyro]

oh yeah it is

reason it out

if you painted c or d, and then see whats not in e you get your answer

[keen scroll]

blue is C or d and red is not e

wait no

[whole gyro]

yeah

noooo earlier once was right

yah

see where blue and purple match

[keen scroll]

it matches where it is currently shaded 😭

[whole gyro]

nooooo

some purple is in e

[keen scroll]

this is tarightup gues

[whole gyro]

yah corct

[keen scroll]

let me think ab that

well

if i thik abt it

(C OR D) AND NOT E

it makes sense

beast

de morgan law to rescue

mf what

[whole gyro]

im just waiting for the moment you send the (unanswered) question, and the answer turns out to be null set so i can say correct right away

[keen scroll]

a nd c dont have a union

so everyhting?

[whole gyro]

they have bro

[keen scroll]

wot

[whole gyro]

paint everything thats in a or in c

[keen scroll]

NOT (A OR C)

[whole gyro]

i mean yeah

[whole gyro]

correct!!

[keen scroll]

ioooga booga

intuition carry

[whole gyro]

but you get why this works right?

[keen scroll]

nope i just shaded evertghing thats not a or c

let me go back to the last q

[whole gyro]

let me draw

in fact ill just directly do A' intersection C'

[keen scroll]

let me try

A U C for this

so

A OR C

[whole gyro]

red -> a complement (A')
green -> c complement (C')
blue -> everythings that common to red and green (A' intersection C')

do you get how i did it?

[keen scroll]

there is no blue tho...

is this blue

[whole gyro]

yeah

damn

[keen scroll]

tf

must be my

night filter

[whole gyro]

must be the colour blindness in the air

[keen scroll]

this is the complement of A U C

[whole gyro]

no

this is the intersection of a' and c'

[whole gyro]

im talking about the previous question this

like you wanted to know why

[keen scroll]

but u shaded

everything except a or c

oh wait

(A U C)' = A' intersction C'

okokokko

[whole gyro]

yeah

next q

[whole gyro]

correct!

[keen scroll]

SIGMA

[whole gyro]

bro unironically uses sigma in the big 25

[keen scroll]

x is intersection

wait

htat

is not right

13+10-x=20

3

?

[keen scroll]

im slow

[whole gyro]

one min

[keen scroll]

i stilll uise blud

[whole gyro]

x should be 8

hmm'

[keen scroll]

Vrotato

its 2mn frm 1am

my aprents r gonna kill me

[whole gyro]

hmmmmm

wait why is the outer part 20-x

[keen scroll]

ignore that

[keen scroll]

zis is the shit

[whole gyro]

bruh

wromg

[keen scroll]

eh

fck

its 1am

[whole gyro]

cus a u b is not equal to the universal set

[whole gyro]

time to find your longitude

[keen scroll]

lmao

ok im p sure this is not gonna come

i sleep

aaaaaa

ok idfk how to odh tis

i hgavent done this before

nor did we do thi in class

[whole gyro]

gg

[keen scroll]

should i gamble and sleep

?

[whole gyro]

yeah

obviously

sleeping is always better

[keen scroll]

yep

okay

gn

and wish me luck

wait

can u js

[bronze citrus]

[keen scroll]

real quick

show me how to do this

[whole gyro]

good luck

[keen scroll]

i have no clue