#help-19
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Aight thx
Nah but how do I find the curriculum
on google
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i need help with this question
x-6 is not equal to x(-2)(3)
but i know it's not right because the next question is "why isn't it equivalant" 😭
oh
Well?
Ok sure you can do that
But the numerator and denominator cannot be simplified no matter what you do
$x-2 \neq 3(x-6)$
wdym
why
oh oops i meant 1/3
Better now
where did this come from?
whats rhs and lhs ;;
right hand side
and left hand side
ok lets start over
@charred oasis
what u need to show
is that (x-2)/(x-6) is not equal to 1/3
that is, $\frac{x-2}{x-6} \neq \frac 13$
now, to prove this, let's see the cases where they are equal
can you solve the equation $\frac{x-2}{x-6} = \frac 13$ for x
are you sure about that

i cant think of any 😓
ok
could you do proof by contradiction?
<@&268886789983436800>
yeah its a bad idea to make a fraction thats set to zero
how would i do that
that's unecessarily long and not really what you wanted either
you multiply both sides by the denominators
$\frac ab = \frac cd \implies ad= bc$
3x-6 = x-6
yes
why u dividing by 3
once u get 3x=x
u take the x on rhs to lhs
or, subtract x from both sides
ImOakley
so this would not simplify to 1/3
im a bit confused so 3x is the only way 1/3= (x-2)/(x-6)?
i dont think i do
do you agree that we can subtract 1x from both sides of the equation 3x=x
here just solve for x
man Ya'll are awsome TvT
yep
so the expression (x-2)/(x-6) ONLY simplifies to 1/3 when x=0 and other than that it won't
Welcome to mathcord! 
and that proves that it can't be simplified
if the only condition is x=0?
how did you come up with that ?
MEANT x=0
i mean how does that prove it as being unequivalant and (x-6)/(x-2) not simplify to 1/3
it simply won't, test some values and find a counterexample and that would easily disprove it
@charred oasis Has your question been resolved?
Bit of logical reasoning - if that fraction does simplify to 1/3, then it shouldn't matter what value x is equal to
However, that fraction can only be 1/3 if x = 0; you can try plugging in any other value for x (e.g. x = 1) and you can see that the fraction doesn't equal 1/3
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Thxssssss
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tried angle chasing but doesnt really work
i was trying to prove that angle AED and AFD are equal if and only if T lies on AD
One idea is using Apollonius circle
@mystic saffron Has your question been resolved?
could you please explain?
wait a second
@brittle plinth do you have any breaktrhoughs?
so the problem I'm having now is
if T lies AD and if we suppose that the bisector of angle E goes through it, there are actually 2 points for F
I don''t think so
apollonius circle
ok
so suppose we know ET is the bisector of DEA
We need to find F so that DAF = DAE and FT is the bisector of DFA
yup
hmm
yall big brains T-T I dread going to school next month-
If F lies on that isoceles point then we're done
if F lies on the "C" point...
@mystic saffron ayy I managed to get a complete proof
So there are 2 cases for F
If F lies on F1 then you can easily finish the problem
if F lies on F2 then we're going to prove that D, E and F2 are collinear
i think considering this will be enough
tbh
ohh alr
We know that C is the intersection of AF and DE so if we proved this then C and F2 must be congruent, from that you can quickly prove that something weird has to happen
So from this E be congruent to B and so D lies on BC
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what does this mean
wouldn't it be a yes? if two expressions are simplified to the same expression
it would be equivalant
i feel like its quite obvious but im overthinking
yeah you are right
Well consider the difference between $\frac{15}{3x + 9}$ and $\frac{5(x + 1)}{(x + 3)(x + 1)}$
Elite
One of them has a hole at x = -1, the other doesn't
oh right
What would "equivalent" generally mean in your definition?
if you were to simplify a function
like if you have 2 expanded forms and you factor them down and theyr the same i think
Not quitte
really?
Equivalent means two or more expressions which is equal in value
"Equal-value" = Equivalent
if they factor down into the same wouuldnt they have the same value>
So let's say you have a function f(x) = y, and g(x) = y
?
Then would f(x) = g(x)?
if they both =y
Yes but not necessarily
then they represent the same
yes
Hmm
Scrap that, that is true
My fault
let us first establish this:
does 0/0 make sense to you, cat?
Like for example 4/8 = 1/2 is equivalency, yeah
0/0 is undefined
indeed!
now let us look at this example
both of them "simplify" to 5/(x+3)
do you agree?
the second one, however, has a hole (undefined) at x=-1
restrictions right?
yes
different restrictions
yes
mhm
similarly, for $\frac{5(x + 1)}{(x + 3)(x + 1)}$
dj
if x=-1 then we'd have 0/0
we can cancel x+1 and simplify the expression given x≠-1
however, 15/(3x+9) does not have that restriction
it is defined for all x≠-3
so would it not be equivilant because of the different restrictions?
yeah
@charred oasis Has your question been resolved?
yes but!
i do believe this solution is correct for simplifying
but the question is
your simplification looks good
here, they forgot to scale the numerators
(x+3)/4 ≠ (x+3)/12
(x-3)/6 ≠ (x-3)/12
what does scaling the numerators mean
a/4 = 4a/16
you multiply 4 on both the numerator and denominator
$\frac{x+3}{4}-\frac{x-3}{6}=\frac{(x+3)-(x-3)}{12}=\frac{6}{12}$
dj
where did the 12 come from ;; i understand how the 12 is there for the actual simplified denominator but why would it be half if only the numerators r multiplied
wouldnt it be 24
what should have happened was
$\frac{x+3}{4}=\frac{3(x+3)}{12},\quad
\frac{x-3}{6}=\frac{2(x-3)}{12}$
dj
but the student didnt multiply by 3 or 2
also we take 12 as our denominator because it is the lcm of 4 and 6
ohh
OHH Wait
i forgot i could do that instead of
just multiplying by the other denominator
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iooo
hello so uh
I have this problem where the denominator is always zero
and I'm just trying to make a problem for me to solve because that's what they tasked us to do
the denominator would always be equal to zero somehow
it's always false
uhhh
what changes can I make in the denominator for the equation to be definable?
are you sure you mean "always zero"...
you're trying to solve the equation x^6 + 3x^2 + 5 = 0
and you're getting that it has no solutions?
is that what you tried to say
I'm never good at math, I'm looking at apps that says it's equal to 0
what grade are you in?
yes, which makes the original equation undefinable
no!
the exact opposite!
that's the exact opposite of "denominator is always zero"! you get no solutions to x^6+3x^2+5=0,
which means the denominator is NEVER zero!
which means your fraction is defined for all real x!
tell me more
please
because when I try to do it, the equation which where both can't be factored anymore
sadly i don't really know what you mean by "do it" here
but the fact that you couldn't factor the denominator is in fact a direct consequence of it being never zero
...do you know in general how to work with quadratic equations?
sort of
in 11th grade this should be well known to you unless maybe you're in america and/or in a dogshit school
I'm just working with dividing this quadratic function
hold on, forget about division
im trying to get you to recall something earlier
do you know the relationship between factorization and roots?
like I said, I'm never good with math😓 so my answer should be no😭
ok maybe it's a language barrier thing? what's your native language
actually my original equation was
fx=4x^2+6x+3, gx=19x^2-8x-5
but ive done modifications for the denominator (g)
and yet undefined still
... hold on.
even in my native language, I wouldn't understand much because I specialize in humanities
😭😭
so sorry
please do not call me "dude"!
edit that word out, please.
anyway... now i'm confused WTF you're trying to do.
so let me ask you a clarifying question: where did you get this whole problem from?
we were tasked to create 5 examples of functions and I went with 2 linear, 1 quadratic, and 2 rational. Then from those 5 examples we have to pick 2 and operate functions on it from addition to division
I'm done with linear, my problem is the quadratic function in division operation
okay? and what else? maybe you could send us the full problem statement and written instructions for what EXACTLY they want you to do?
that's it?
yes
well...
then you can just... write down the fraction?
they don't ask you to find its domain
hmm
so you simply don't really care about when your denominators are and aren't 0
well I really wanted my answer to be in its final form, but whenever I try, the equation is the answer
wdym by "final form"
can you show your f(x) and your g(x)?
btw i saw you write fx when you meant f(x) earlier. don't do that! you have to put the brackets every time.
the modified one or the previous?
god fuck. whichever.
noted!
f(x)=4x²+6x+3
g(x)=19x²-8x-5
ok
f(x)/g(x) doesn't really simplify in any meaningful way
for these
you won't need to do any manipulation after just writing down f(x)/g(x) = (4x^2 + 6x + 3)/(19x^2 - 8x - 5)
the bottom has two roots but they're ugly radicals and i wouldn't expect you to factor it
god I hate when the problem asks to make an example of linear functions and quadratic functions
which...?
which means the equation should also be the answer?
which means that that fraction is the simplest form and yes it is the answer
sometimes it be like that.
thank you
i hope i won't have to rephrase it several more times before you understand it
cause maybe i have been cryptic and unclear this whole time without even knowing it
I'm sorry, I've never been an expert with mathematics😭🙏
I'm like a kid learning how to walk
but anyways
thank you
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Can anyone help me😭my brains not functioning rn😓
u wat question?
My brain not functioning rn help:/
what?
are you in class right now ?
that's impossible
Is that everything?
(There are probably informations about the kind of sequence this is)
cuz sequence doesn't mean arithmetic sequence
they may mean arithmetic sequence though
in that case it's easy, in the artithmetic sequence the middle would just be the arithmetic mean
In case it's an geometric sequence
a1 = 46, a2, a3, a4, a5 = 23/648
a1 / a5 = 2^4 * 3^4
like grui says, the context is close by, previous slides would tell you what we'er talking about
I'll leave this hint on the board.
no,just studying bc it's our test tomm I'm prob COOKEDI still don't understand geometric sequence but arithmetic sequence and arithmetic means its too easy also series
why did u leave this at last moment
yeah i also have a doubt in this can anyone explain this
show working please
i asked the OP to show his working in another channel and he merely thanked me, so i wanna see exactly what's going on
@ember wing Has your question been resolved?
@ember wing Has your question been resolved?
Almost
!noclopen
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it's solve now:)
please close the channel if it's done
so that others can use it
How do I close it,OMG my brain cells fr not functioning rn
.close or .solved
.solved
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you lost the -h in the numerator, got semi covered up from crossing out the +2
Semi covered?
partially covered
u crossed it out unintentionally
obscured it, likely making you miss it / not see it
hold on I’ll redo the q
ignored that -h again
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.reopen
✅
yes
though its weird not seeing you express that x^-4 in d) as a fraction with positive powers like you did in the other parts
oh yes i forgot about that
are these correct too?
or do i need to show further prove
/not enough
didn't you ask this already a couple of weeks ago
yes
factorise the (2x+6) further
you actually did that last time iirc
but made a mistake elsewhere
yes i assume this is my weak area
why do we need to factoor 2x+6 out
ik u need to cancel but
isnt it already simplified
2(x+3)
the idea is to explictly get a common factor in the numerator and denominator
oh makes sense
the thing cancels and remove the thing that makes it indeterminate
you could cancel / divide directly if you can see it
I just find it hard to recognise it
in questions like these, its usually a good idea to factor as much as possible
also in the original expression,
its clear that 2 is a common factor of the terms in the denominator
so factoring that out first will make factoring the quadratic less tedious
i just feel like something is incorrect
or is it correct?
wait
yes i messed up
you have a notation issue
ensure you have parentheses around the -3
$$\red{(\black{-3})}^2$$
ℝαμOmeganato5
if thats what you're squareing
k
,w lim_{x to -3}((x^4 - 81)/(2x^2 - 4x - 30))
@shrewd trellis Has your question been resolved?
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is my answer correct?
3x²+2 has a derivative too
you fumbled in several places
first you swallowed the ^2 in (3x**^2**+2)^4 on the denominator
then you swallowed that denominator wholesale
are you hungry? cause mathematical notation isn't very nutritious.
so two fumbles?
wdym
oh true
second line, you messed up factoring out (3x^2+2)
the stuff inside [these] should have been 5(3x^2+2)^2 - 12x(x^3+2x)
besides that
everything i scorrect?
is*
ik the answer will be wrong
but im talking about the working out after that
line 3 can be salvaged but after that it's a no-go
you will need to fix the [] stuff
wdym i did factorise it out properl
y
if i did ^2, that would make it
^3
look at the first line
the 1st big product of brackets is 5(x^3+2x)^4 * (3x^2+2)^3
oh ur right
its like terms
but i thought that woudnt happen because there is subtration
@wooden python
it's not like terms... this is just within the first term
fuck
ok let me just abstract this all away
let's call x^3 + 2x =: A and 3x^2 + 2 =: B
your denominator from line 1 is $5A^4 \cdot B \cdot B^2 - 12x BA^5$
Ann
agree/disagree/disappear?
I dont understand this
nvm
i do
agree
btw be quick because i gotta leave in few mins
or we can discuss this once i come home
there's no possible way i can be quick about this, sorry.
@shrewd trellis Has your question been resolved?
i tried this and yeah like Ann said, [] contains 5(3x^2+2)^2 and not 5(3x^2+2), this is i think the only problem with your attempt - after you fix that and simplify the [] expression, you should be good to go - but I will say, double check if anything could be factorised at the end
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alr I’m home now
Simplify the [] expression?
I agree btw
yes, simplify the stuff inside the []
it keeps surprising me that you ask for clarification on the most transparent (from my pov) phrasings
So u want me to expand the bracket and multiply it and simplify
i can't say it with full confidence but yes.
inc this?
One thing you can do is take the denominator to LHS and then use product rule
what part of "simplify the stuff INSIDE the square brackets" was unclear?
sorry, but it's getting a bit frustrating having to go through this song and dance for the N'th time in a row!

when i said inside, i meant inside, not inside plus a little bit outside!
like FUCK
I believe this would be much quicker
gah
Chill chill 
if you want quickness then op should have done it with logdiff
but i am not going to get into that
Wasn't he complaining about using quotient rule on such a big expression
he also doesn't know logdiff iirc.
Im not understanding
im still frustrated at the fact that, even though i do my best to phrase things clearly,
can we restart?
things are getting misunderstood
and i get asked to clarify things that are already as clear as i could possibly make them, short of drawing a thing in paint telling you exactly which sub-expression i want simplified
its okay then, ill get someone else to help me @wooden python
Did you read what I said
"One thing you can do is take the denominator to LHS and then use product rule"
Yes
Take (3x^2 + 2)^2 to LHS
So that it becomes f(x) * (3x^2 + 2)^2 = (x^3 + 2x)^5
You understand this?
I dont know how to texit
then write it down
underneath the (3x^2+2)^2
That's V
Nothing
Im not gonna solve the question for you
Youre gonna do that
Im only going to help you
thats what im asking, for help?
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If 3 people tryna help you and you are the one getting confused maybe its your fault
Ill get someone else to help
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.reopen
<@&268886789983436800>
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Find the value of m for which the coefficient of X in the expansion of (x^m + 1/x²)^22 is 1540
Then after that what I would do
wait
figure out what k would be so the coefficient matches with 1540
- what should the exponent be for the x term?
- what should 22 choose k be?
- 5040
That would be very long exapsio
why my mind do not work
Ill work out
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hi
hi
hiiii
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
let me explain
i made something called the superdence burst theory
i need a minute let me pull it up
The Burst-Core Hypothesis proposes a theoretical mechanism for faster-than-light (FTL) travel through the uncontrolled release of energy from a highly compressed core. Encased in a multi-layered shell capable of withstanding neutron star-level heat and pressure, the burst core could, in theory, release an energy pulse strong enough to push an object beyond the speed of light. This process is theorized to be one-way and unsteerable, posing extreme risk but offering radical implications for superluminal exploration.
In Einstein's theory of relativity, no object with mass can reach or exceed the speed of light due to the infinite energy requirement. However, the Burst-Core Hypothesis circumvents this by not relying on continuous propulsion, but on an uncontrollable energy burst strong enough to create a one-time superluminal event. The idea rests on the possibility that unknown phenomena may occur when extreme energy is released under dense containment conditions.
And if you could get it to hit you You should be launched far by the beam as it is not just light but electromagnetic radiation. First to make the pod you would need reflective plasma armor layer, Hyperdense Compression Lattice layer, Magnetic Containment Field layer, and a Quantum Phase Layer
proposed by an 11 year old
well a single energy pulse,even of extreme magnitude ; does not inherently allow superluminal travel. High-speed particles (like cosmic rays) never exceed light speed despite enormous energies. They approach c but never cross it. There is no known mechanism by which momentum transfer alone can break this limit.
and furthermore a burst of EM radiation (light or other) can push objects (like solar sails), but only with finite momentum transfer. No arrangement of mirrors, plasma armor, or fields can amplify this effect to infinite velocity. Photons themselves always travel at c and they cannot push something faster than c.how do you explain that with this?
im not sure let me continue my research
yeah .close
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Can we prove this inequality never holds true for integer value of p and positive integer value of q. Like either the upper bound is false or the lower bound is false. I tried taking cases like
- q is even and p is negative
- q is even and p is positive
- q is odd and p is positive
- q is odd and p is negative
Case 1 is trivial but the rest of the cases are a hassle
Also for case 2 and 3 I have tried taking sub case of the big bracket expression being 1) greater and 2) lesser than equal to 0.
whats E_1(1)?
You can think of it as a constant
It’s basically defined like this
E_1(1) is approximately 0.2193
<@&286206848099549185>
exponential integral at 1, ok
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how do i solve this by using quadradic functions? pre calc 11 btw
yes sorry
do you know the formula?
ok so what does that give you here?
y = a(x - p) + q
quadratic formula is with b^2 - 4ac
i forgot the square
yes (x-p)^2
in the first two terms
so its -5(x^2 - 7) + 8
you need to find something that resembles (a+b) ^2
thats not the final form no
yes
next you need to do this
$(a+b)^2 = a^2 + 2ab + b^2$
TheVibe
AHH sorry i need to go
no worries
@brave kelp Has your question been resolved?
@brave kelp Has your question been resolved?
Are you still going about this?
He said he would come back, he had to go for 1h
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can someone teach me races and gamesw
teach you what?
"this too" lmao
matrix algebra??
living up to your name
it's honestly doable even without it
we being related 🔥
that "Use matrix algebra" is the thing that i don't quite understand
no like ion understand how to make it i did it once but now i cant do it for some reason
its just given to confuse
basically u have to make 2 matrixes and multiply em
AB
thats it but
i cant make the matrix
Or I am stupid and didn't understand the question
yea matrix algebra is weird there. it's just adding things up
matrix algebra meaning = make ur own matrix
i don't know why you would set up a matrix
||don't tell anybody, but use chatgpt atp||
😭
I am not sure what it means for using matrix algebra
But if it’s yo give a table with matrix it’s like this
For first row it’s calorie and second row is protein
First column is male second is female and third is coach
If this isn’t the method or this is, I don’t see the purpose of it though
yooo its like this only
the 1 x 3 matrices should be 3 x 1 matrices since you can't multiply a 2 x 3 matrix and a 1 x 3 matrix
but yea maybe that's what it's looking for
Yes
it should be like this
Take the transpose for the latter matrix
yea you can also use that one instead
take the common as X
what emma did will be the same thing
just be careful with the dimensions
if you use that one, the person amount matrices (A and B) should be 1 x 3
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someone find adj() for some reason im getting some values wrong according to chatgpt???
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i need help, i am in a quantum box
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at least the troll was funny this time
aww was about to make a joke
Can I bust out the hammer?
dont worry, it wont become a problem soon enough
sure will give you some radium
whatever you want it is fine
i am alone
no one is watching me, i am feeling weird, like, another me... idk how to explain it
it ´s just... please, open the box
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
only if u have a math problem sure
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Hey there, I'm finding the derivative for g(t) = (t^2+t)^2 * (2t-t^3)^-2, and I've gotten to the point of:
(2(t^2+t)(2t+1))/(2t-t^3)^2 - (2(t^2+t)^2(2-3t^2))/(2t-t^3)^3
(See the pdf for a better representation)
I'm having trouble simplifying this down, as my professor wants it to be as simplified as possible, and honestly I'm just kinda stuck lol
@languid hull Has your question been resolved?
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Ah my bad, I can change it
Sorry if it's a bit hard to read
I pretty much just need help simplifying it or if I have any errors
,w d/dx (x^2 + x)^2*(2x-x^3)^(-2)
looks all good to me! that would be the fully simplified form, if you were to expand the numerator all the way out and simplify it
and its probably "simpler" to have it under one fraction, but id be happy with that response as a teacher - ig it depends how much yours wants simplification
Ahh ok so my final answer as of now would be fine?
yeah it should be (again, depending on teacher a little bit). if you wanna go the extra mile, you can common factor the numerator a bit, and you should end up here
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Hellooo, i need help evaluating composition of functions(⊙_◎)
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Please help, im abt to have a nosebleed🙏
Which step are u stuck
Uh i dont know where to begin
Ok
Do u know what composite function is
And how they work?
[ f\circ g(x) = f(g(x))]
k
For example let ${f(x) = x^2}$ and ${g(x) = x+1}$,
[ f\circ g(1) = f(g(1)) = f(1+1) = f(2) = (2)^2 = 4]
Meanwhile,
[ g\circ f(1) = g(f(1)) = g(1^2) = g(1) = 1+1 = 2]
k
Can you like give me a full step by step example on how to solve it please(・–・;)ゞ
Or like another example
PLEASE
I jus need an example so i can like use it as a guide on how to solve
I can help
you can help
PLEASE HELP ME
so if we define
f(x) = x²
g(x) = 3x
I just picked some random functions but do you understand what I mean by define
we got two different functions
f(x) and g(x)
u with me?
@jade trout
Yessir
ok so if we want to find f(g(3))
that's f of g(x) when x = 3
so we are finding out what g(x) equals when x = 3
and then we're plugging that number in f(x)
so tell me what g(3) is equal to
HA
?
Im lost.
Nope sorry
so you know how f(x) is a function
you plug in a number for X and you get a value
that's what a function is
so if f(x) = x²
if x = 1 then f(x) = 1²
if x = 2 then f(x) = 2²
if x = 3 then f(x) = 3²
do you understand that ?
@jade trout
oop
they not responding gg
better to say f(1) = 1^2, f(2) = 2^2, f(3) = 3^2
Mhm a little
another way of thinking about it that i really like:
Let's say $f(x) = 3x + 2.$ We can mess with the variable, $x$, as much as we want:
\begin{itemize}
\item $f(t) = 3t+2$
\item $f(\tau) = 3\tau + 2$
\item $f(\blacksquare) = 3\blacksquare + 2$
\item and so on\dots
\end{itemize}
So we can also (usually) put in $g(x):$
$f\left(g(x)\right) = 3\left(g(x)\right) + 2$ \
$f\left(g(3)\right) = 3\left(g(3)\right) + 2$
haseeb
Can you guys solve one of these, and give me a step by step explanation😭
you need to understand how functions work
Mhm i do
ok so if g(x) = (2x-1) / 3
what's g(0)
3?
explain how u got that
maybe i can share a little bit of my personal notes about functions if it would help
Well uh i multiplied the 2 and 0
ok
YES PLEASE
here you go
you will still have to do your problems yourself, but i hope this will help you understand what people here are talking about
oh jesus
Wait ok now im confused
r
can you try and find g(0) again
So i replace the x with 0 yeah?
yea
remember, whenever x is replaced by a value, just find all of the x in the function and replace it by the same number
that's all
so far so good
no
[2(0) - 1] / 3
Ohh 2?
no
the answer is a fraction
Huh.
show your steps?
lets evaluate the top part
Jesus
what's (2 times 0) - 1
-1
MHMM YAY OH MY GOD
and the bottom part is 3
not necessarily
$$ g(x) = \frac{2x - 1}{3} $$
r
this is just an example
-1/3
SORRY IM STUPID AT MATH
9/3???
simplify
which is?
3/1? HELP
OHHHH OH MY GOD TYSM
you got it!
Im getting it🙏
the same applies for functions too, in case you need clarification

for example, if wtf is a function, g(wtf) = [2(wtf) - 1] / 3
@jade trout back to the original question
Huhu
$$ f(x) = 2x^2 + x - 3 $$
Im stressin abt the g(wtf)
r
so if we want to find f(g(0)
we already know what g(0) is right, you found it earlier @jade trout
can you respond
if so, ignore my message for now
whoa, relax
Im sorry :,> i didnt mean it like that
i can tell she definitely needs help understanding functions
well i'm on phone so hopefully i can type well
Im actually eating lunch rn...
ah, another gmt+7-9 guy. well, maybe you can think about this over lunch
So do i answer it rn??(´-﹏-`;)
ofc
