#help-19

1 messages · Page 181 of 1

pallid trellis
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nothing

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just take a picture

glossy smelt
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Aight thx

pallid trellis
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send it to the bot

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and boom

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answer

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under 0.005 miliseconds

glossy smelt
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Nah but how do I find the curriculum

pallid trellis
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on google

vivid wyvern
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.close

pallid trellis
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.close

odd edgeBOT
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odd edgeBOT
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odd edgeBOT
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charred oasis
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i need help with this question

odd edgeBOT
late sinew
charred oasis
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why wouldn't it be 1/3?

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this is what i tried

late sinew
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x-6 is not equal to x(-2)(3)

charred oasis
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but i know it's not right because the next question is "why isn't it equivalant" 😭

late sinew
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x(-2)(3) is -6x

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not x-6

charred oasis
late sinew
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Well?

charred oasis
late sinew
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Ok sure you can do that

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But the numerator and denominator cannot be simplified no matter what you do

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$x-2 \neq 3(x-6)$

charred oasis
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why?

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what does that mean

clever fjordBOT
late sinew
charred oasis
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why

late sinew
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divide both sides of this by x-6

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so u get $\frac{x-2}{x-6}\neq \frac 13$

charred oasis
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i am very confused

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what does that prove how does that help

late sinew
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oh oops i meant 1/3

clever fjordBOT
late sinew
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Better now

charred oasis
late sinew
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expand the rhs and see

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if it is equal to the lhs

charred oasis
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whats rhs and lhs ;;

late sinew
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right hand side

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and left hand side

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ok lets start over

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@charred oasis

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what u need to show

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is that (x-2)/(x-6) is not equal to 1/3

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that is, $\frac{x-2}{x-6} \neq \frac 13$

clever fjordBOT
late sinew
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now, to prove this, let's see the cases where they are equal

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can you solve the equation $\frac{x-2}{x-6} = \frac 13$ for x

clever fjordBOT
charred oasis
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so

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there arent any

late sinew
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are you sure about that

late sinew
charred oasis
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i cant think of any 😓

late sinew
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solve the equation

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dont guess

charred oasis
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ok

glass vault
strange aspen
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<@&268886789983436800>

charred oasis
late sinew
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ok keep solving

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tho it wouldve been better to cross multiply

charred oasis
glass vault
charred oasis
late sinew
# charred oasis

that's unecessarily long and not really what you wanted either

glass vault
late sinew
clever fjordBOT
charred oasis
late sinew
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ok

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solve

charred oasis
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3x-6 = x-6

late sinew
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yes

charred oasis
late sinew
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why u dividing by 3

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once u get 3x=x

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u take the x on rhs to lhs

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or, subtract x from both sides

clever fjordBOT
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ImOakley

glass vault
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so this would not simplify to 1/3

charred oasis
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im a bit confused so 3x is the only way 1/3= (x-2)/(x-6)?

late sinew
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no

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you got the equation 3x=x

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do you not know how to solve that for x? (yes/no)

charred oasis
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i dont think i do

late sinew
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do you agree that we can subtract 1x from both sides of the equation 3x=x

charred oasis
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yes

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2x=0

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no

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uh

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2=0

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?

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mno

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2x=0

strange aspen
ancient pier
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man Ya'll are awsome TvT

charred oasis
strange aspen
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so the expression (x-2)/(x-6) ONLY simplifies to 1/3 when x=0 and other than that it won't

late sinew
charred oasis
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if the only condition is x=0?

strange aspen
charred oasis
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i mean how does that prove it as being unequivalant and (x-6)/(x-2) not simplify to 1/3

strange aspen
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it simply won't, test some values and find a counterexample and that would easily disprove it

charred oasis
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why

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why can't (x-6)/(x-2) = 1/3 because of that

odd edgeBOT
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@charred oasis Has your question been resolved?

sturdy cape
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Bit of logical reasoning - if that fraction does simplify to 1/3, then it shouldn't matter what value x is equal to

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However, that fraction can only be 1/3 if x = 0; you can try plugging in any other value for x (e.g. x = 1) and you can see that the fraction doesn't equal 1/3

odd edgeBOT
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ancient pier
odd edgeBOT
late sinew
#

.close

odd edgeBOT
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mystic saffron
odd edgeBOT
mystic saffron
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tried angle chasing but doesnt really work

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i was trying to prove that angle AED and AFD are equal if and only if T lies on AD

brittle plinth
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One idea is using Apollonius circle

odd edgeBOT
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@mystic saffron Has your question been resolved?

mystic saffron
brittle plinth
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wait a second

mystic saffron
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@brittle plinth do you have any breaktrhoughs?

brittle plinth
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so the problem I'm having now is

brittle plinth
brittle plinth
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might have already proved it idk

mystic saffron
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isnt there only one point?

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wait how do you know that point T lies on the circle

brittle plinth
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apollonius circle

mystic saffron
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ok

brittle plinth
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so suppose we know ET is the bisector of DEA

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We need to find F so that DAF = DAE and FT is the bisector of DFA

mystic saffron
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yup

brittle plinth
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hmm

ancient pier
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yall big brains T-T I dread going to school next month-

brittle plinth
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If F lies on that isoceles point then we're done

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if F lies on the "C" point...

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@mystic saffron ayy I managed to get a complete proof

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So there are 2 cases for F

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If F lies on F1 then you can easily finish the problem

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if F lies on F2 then we're going to prove that D, E and F2 are collinear

mystic saffron
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tbh

brittle plinth
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No it's not

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Because I'm reverse-engineering the positions of B and C from this

mystic saffron
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ohh alr

brittle plinth
brittle plinth
odd edgeBOT
#

@mystic saffron Has your question been resolved?

#
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charred oasis
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what does this mean

odd edgeBOT
charred oasis
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wouldn't it be a yes? if two expressions are simplified to the same expression

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it would be equivalant

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i feel like its quite obvious but im overthinking

graceful viper
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yeah you are right

rotund steeple
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Well consider the difference between $\frac{15}{3x + 9}$ and $\frac{5(x + 1)}{(x + 3)(x + 1)}$

clever fjordBOT
rotund steeple
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One of them has a hole at x = -1, the other doesn't

graceful viper
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oh right

eager tapir
charred oasis
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like if you have 2 expanded forms and you factor them down and theyr the same i think

quasi kindle
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ok im back on my main

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another question

quasi kindle
eager tapir
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Equivalent means two or more expressions which is equal in value

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"Equal-value" = Equivalent

quasi kindle
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if they factor down into the same wouuldnt they have the same value>

eager tapir
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So let's say you have a function f(x) = y, and g(x) = y

quasi kindle
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?

eager tapir
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Then would f(x) = g(x)?

quasi kindle
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if they both =y

eager tapir
quasi kindle
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then they represent the same

eager tapir
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Which means..?

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F(x) is equivalent to g(x), correct?

quasi kindle
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yes

eager tapir
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Scrap that, that is true

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My fault

graceful viper
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let us first establish this:
does 0/0 make sense to you, cat?

eager tapir
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Like for example 4/8 = 1/2 is equivalency, yeah

quasi kindle
graceful viper
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indeed!

graceful viper
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both of them "simplify" to 5/(x+3)

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do you agree?

quasi kindle
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yes

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i think

graceful viper
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the second one, however, has a hole (undefined) at x=-1

quasi kindle
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restrictions right?

graceful viper
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yes

quasi kindle
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different restrictions

graceful viper
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x/x = 1, yes?

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but there is an underlying assumption here

quasi kindle
graceful viper
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x≠0

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because then we'd have 0/0

quasi kindle
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mhm

graceful viper
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similarly, for $\frac{5(x + 1)}{(x + 3)(x + 1)}$

clever fjordBOT
graceful viper
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if x=-1 then we'd have 0/0

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we can cancel x+1 and simplify the expression given x≠-1

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however, 15/(3x+9) does not have that restriction

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it is defined for all x≠-3

quasi kindle
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so would it not be equivilant because of the different restrictions?

graceful viper
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yeah

odd edgeBOT
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@charred oasis Has your question been resolved?

quasi kindle
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yes but!

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i do believe this solution is correct for simplifying

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but the question is

graceful viper
graceful viper
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(x+3)/4 ≠ (x+3)/12

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(x-3)/6 ≠ (x-3)/12

quasi kindle
graceful viper
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a/4 = 4a/16

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you multiply 4 on both the numerator and denominator

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$\frac{x+3}{4}-\frac{x-3}{6}=\frac{(x+3)-(x-3)}{12}=\frac{6}{12}$

clever fjordBOT
graceful viper
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this is what they did

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they should multiply (x+3) by 3 as well and (x-3) by 2

quasi kindle
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where did the 12 come from ;; i understand how the 12 is there for the actual simplified denominator but why would it be half if only the numerators r multiplied

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wouldnt it be 24

graceful viper
clever fjordBOT
graceful viper
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but the student didnt multiply by 3 or 2

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also we take 12 as our denominator because it is the lcm of 4 and 6

quasi kindle
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ohh

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OHH Wait

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i forgot i could do that instead of

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just multiplying by the other denominator

odd edgeBOT
#
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tough jungle
#

iooo

odd edgeBOT
tough jungle
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hello so uh

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I have this problem where the denominator is always zero

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and I'm just trying to make a problem for me to solve because that's what they tasked us to do

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the denominator would always be equal to zero somehow

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it's always false

wooden python
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uhhh

tough jungle
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what changes can I make in the denominator for the equation to be definable?

wooden python
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are you sure you mean "always zero"...

tough jungle
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it always gets me to false

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somehow

wooden python
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you're trying to solve the equation x^6 + 3x^2 + 5 = 0

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and you're getting that it has no solutions?

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is that what you tried to say

tough jungle
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I'm never good at math, I'm looking at apps that says it's equal to 0

wooden python
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what grade are you in?

tough jungle
tough jungle
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junior

wooden python
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the exact opposite!

tough jungle
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oh?

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please enlighten me

wooden python
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that's the exact opposite of "denominator is always zero"! you get no solutions to x^6+3x^2+5=0,

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which means the denominator is NEVER zero!

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which means your fraction is defined for all real x!

tough jungle
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tell me more

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please

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because when I try to do it, the equation which where both can't be factored anymore

wooden python
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sadly i don't really know what you mean by "do it" here

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but the fact that you couldn't factor the denominator is in fact a direct consequence of it being never zero

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...do you know in general how to work with quadratic equations?

tough jungle
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sort of

wooden python
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in 11th grade this should be well known to you unless maybe you're in america and/or in a dogshit school

tough jungle
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I'm just working with dividing this quadratic function

wooden python
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hold on, forget about division

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im trying to get you to recall something earlier

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do you know the relationship between factorization and roots?

tough jungle
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like I said, I'm never good with math😓 so my answer should be no😭

wooden python
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ok maybe it's a language barrier thing? what's your native language

tough jungle
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actually my original equation was

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fx=4x^2+6x+3, gx=19x^2-8x-5

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but ive done modifications for the denominator (g)

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and yet undefined still

wooden python
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... hold on.

tough jungle
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😭😭

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so sorry

wooden python
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please do not call me "dude"!

tough jungle
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oh

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I'm sory

wooden python
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edit that word out, please.

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anyway... now i'm confused WTF you're trying to do.
so let me ask you a clarifying question: where did you get this whole problem from?

tough jungle
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we were tasked to create 5 examples of functions and I went with 2 linear, 1 quadratic, and 2 rational. Then from those 5 examples we have to pick 2 and operate functions on it from addition to division

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I'm done with linear, my problem is the quadratic function in division operation

wooden python
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okay? and what else? maybe you could send us the full problem statement and written instructions for what EXACTLY they want you to do?

tough jungle
wooden python
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that's it?

tough jungle
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yes

wooden python
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well...

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then you can just... write down the fraction?

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they don't ask you to find its domain

tough jungle
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hmm

wooden python
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so you simply don't really care about when your denominators are and aren't 0

tough jungle
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actually

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makes sense

tough jungle
wooden python
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wdym by "final form"

tough jungle
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well given in this example I've written but the given were also fractions

wooden python
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can you show your f(x) and your g(x)?

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btw i saw you write fx when you meant f(x) earlier. don't do that! you have to put the brackets every time.

tough jungle
wooden python
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god fuck. whichever.

tough jungle
wooden python
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ok

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f(x)/g(x) doesn't really simplify in any meaningful way

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for these

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you won't need to do any manipulation after just writing down f(x)/g(x) = (4x^2 + 6x + 3)/(19x^2 - 8x - 5)

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the bottom has two roots but they're ugly radicals and i wouldn't expect you to factor it

brittle plinth
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god I hate when the problem asks to make an example of linear functions and quadratic functions

tough jungle
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which means the equation should also be the answer?

wooden python
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which means that that fraction is the simplest form and yes it is the answer

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sometimes it be like that.

tough jungle
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thank you

wooden python
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i hope i won't have to rephrase it several more times before you understand it

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cause maybe i have been cryptic and unclear this whole time without even knowing it

tough jungle
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I'm like a kid learning how to walk

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but anyways

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thank you

#

.close

odd edgeBOT
#
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odd edgeBOT
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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ember wing
#

Can anyone help me😭my brains not functioning rn😓

mighty siren
#

you need to ask a genuine question haha

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what are you struggling with ?

vernal yacht
ember wing
#

My brain not functioning rn help:/

vernal yacht
#

what?

mighty siren
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are you in class right now ?

static totem
#

that's impossible

vernal yacht
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Is that everything?

mighty siren
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(There are probably informations about the kind of sequence this is)

static totem
#

cuz sequence doesn't mean arithmetic sequence

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they may mean arithmetic sequence though

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in that case it's easy, in the artithmetic sequence the middle would just be the arithmetic mean

vernal yacht
#

In case it's an geometric sequence
a1 = 46, a2, a3, a4, a5 = 23/648

a1 / a5 = 2^4 * 3^4

static totem
#

like grui says, the context is close by, previous slides would tell you what we'er talking about

vernal yacht
#

I'll leave this hint on the board.

ember wing
#

no,just studying bc it's our test tomm I'm prob COOKED🫩I still don't understand geometric sequence but arithmetic sequence and arithmetic means its too easy also series

lavish jackal
#

why did u leave this at last moment

outer meteor
#

yeah i also have a doubt in this can anyone explain this

lean yew
#

show working please

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i asked the OP to show his working in another channel and he merely thanked me, so i wanna see exactly what's going on

odd edgeBOT
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@ember wing Has your question been resolved?

odd edgeBOT
#

@ember wing Has your question been resolved?

ember wing
#

Almost

odd edgeBOT
ember wing
#

it's solve now:)

lean yew
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so that others can use it

ember wing
#

How do I close it,OMG my brain cells fr not functioning rn

faint knot
#

.close or .solved

ember wing
#

.solved

odd edgeBOT
#
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shrewd trellis
odd edgeBOT
shrewd trellis
#

some kind heart, please check my answer

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for the first 2

narrow crypt
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(b) nah; differnting f(t) gives 8t - 1

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(a) is correct

shrewd trellis
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where did I messs up

narrow crypt
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8th + 4h^2 - h

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divided by h is

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8t + 4h - 1

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take lim

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8t - 1

nimble blaze
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you lost the -h in the numerator, got semi covered up from crossing out the +2

nimble blaze
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partially covered

narrow crypt
#

u crossed it out unintentionally

nimble blaze
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obscured it, likely making you miss it / not see it

shrewd trellis
#

hold on I’ll redo the q

narrow crypt
#

-h is still there

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but u thought u've already crossed it

shrewd trellis
#

i got the same answe

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r

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oh

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bruh

nimble blaze
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ignored that -h again

shrewd trellis
#

got it

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so 8t-1

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thhanks

#

.close

odd edgeBOT
#
Channel closed

Closed by @shrewd trellis

Use .reopen if this was a mistake.

shrewd trellis
#

.reopen

odd edgeBOT
#

shrewd trellis
#

are these correct as well?

nimble blaze
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yes

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though its weird not seeing you express that x^-4 in d) as a fraction with positive powers like you did in the other parts

shrewd trellis
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oh yes i forgot about that

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are these correct too?

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or do i need to show further prove

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/not enough

nimble blaze
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didn't you ask this already a couple of weeks ago

shrewd trellis
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yes im re doing the practice test because

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our test got post poned

nimble blaze
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its enough

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direct observation from the graph, nothing else needed

shrewd trellis
#

correct?

nimble blaze
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yes

shrewd trellis
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am i on the right track?

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because like im stuck

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from here

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i cant cancel

narrow crypt
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factor 2 out

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from the bottom

nimble blaze
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factorise the (2x+6) further

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you actually did that last time iirc
but made a mistake elsewhere

shrewd trellis
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yes i assume this is my weak area

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why do we need to factoor 2x+6 out

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ik u need to cancel but

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isnt it already simplified

narrow crypt
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2(x+3)

nimble blaze
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the idea is to explictly get a common factor in the numerator and denominator

shrewd trellis
#

oh makes sense

narrow crypt
#

the thing cancels and remove the thing that makes it indeterminate

nimble blaze
#

you could cancel / divide directly if you can see it

shrewd trellis
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I just find it hard to recognise it

nimble blaze
#

in questions like these, its usually a good idea to factor as much as possible

#

also in the original expression,
its clear that 2 is a common factor of the terms in the denominator
so factoring that out first will make factoring the quadratic less tedious

shrewd trellis
#

i just feel like something is incorrect

#

or is it correct?

#

wait

#

yes i messed up

nimble blaze
#

you have a notation issue

#

ensure you have parentheses around the -3
$$\red{(\black{-3})}^2$$

clever fjordBOT
#

ℝαμOmeganato5

nimble blaze
#

if thats what you're squareing

shrewd trellis
#

which line?

#

everywhere there is an x?

#

such as ((-3)-3)

narrow crypt
#

this

#

[ (-3^2 = -9) \text{ and } ((-3)^2 = 9)]

clever fjordBOT
shrewd trellis
#

I see

#

so is my answer correct or incorrect, besides the notation issue

narrow crypt
#

,w lim_{x to -3}((x^4 - 81)/(2x^2 - 4x - 30))

clever fjordBOT
shrewd trellis
#

woohoo

#

so i should have done

#

((-3)^2+9)

#

or [(-3)^2+9]

narrow crypt
#

square or round bracket doesnt matter

#

(in normal algebra)

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

#
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shrewd trellis
odd edgeBOT
shrewd trellis
#

is my answer correct?

vivid wyvern
#

3x²+2 has a derivative too

wooden python
#

first you swallowed the ^2 in (3x**^2**+2)^4 on the denominator

#

then you swallowed that denominator wholesale

#

are you hungry? cause mathematical notation isn't very nutritious.

shrewd trellis
#

so two fumbles?

shrewd trellis
wooden python
#

ya got things outright MISSING in your work m8

#

where did the (3x^2+2)^3 go?

shrewd trellis
#

oh true

wooden python
#

the purple bit looks fine

#

the green bit you have to redo from scratch

shrewd trellis
#

is this correct now @wooden python

#

wait

#

let me know

wooden python
#

second line, you messed up factoring out (3x^2+2)

#

the stuff inside [these] should have been 5(3x^2+2)^2 - 12x(x^3+2x)

shrewd trellis
#

besides that

#

everything i scorrect?

#

is*

#

ik the answer will be wrong

#

but im talking about the working out after that

wooden python
#

line 3 can be salvaged but after that it's a no-go

#

you will need to fix the [] stuff

shrewd trellis
#

y

#

if i did ^2, that would make it

#

^3

wooden python
#

look at the first line

#

the 1st big product of brackets is 5(x^3+2x)^4 * (3x^2+2)^3

shrewd trellis
#

oh ur right

#

its like terms

#

but i thought that woudnt happen because there is subtration

#

@wooden python

wooden python
#

it's not like terms... this is just within the first term

#

fuck

#

ok let me just abstract this all away

#

let's call x^3 + 2x =: A and 3x^2 + 2 =: B

shrewd trellis
wooden python
#

your denominator from line 1 is $5A^4 \cdot B \cdot B^2 - 12x BA^5$

clever fjordBOT
wooden python
#

agree/disagree/disappear?

shrewd trellis
#

I dont understand this

#

nvm

#

i do

#

agree

#

btw be quick because i gotta leave in few mins

#

or we can discuss this once i come home

wooden python
#

there's no possible way i can be quick about this, sorry.

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

wheat prairie
# shrewd trellis

i tried this and yeah like Ann said, [] contains 5(3x^2+2)^2 and not 5(3x^2+2), this is i think the only problem with your attempt - after you fix that and simplify the [] expression, you should be good to go - but I will say, double check if anything could be factorised at the end

odd edgeBOT
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shrewd trellis
#

alr I’m home now

odd edgeBOT
shrewd trellis
shrewd trellis
wooden python
#

it keeps surprising me that you ask for clarification on the most transparent (from my pov) phrasings

shrewd trellis
#

So u want me to expand the bracket and multiply it and simplify

wooden python
#

i can't say it with full confidence but yes.

shrewd trellis
desert jolt
# shrewd trellis

One thing you can do is take the denominator to LHS and then use product rule

wooden python
#

what part of "simplify the stuff INSIDE the square brackets" was unclear?

#

sorry, but it's getting a bit frustrating having to go through this song and dance for the N'th time in a row!

desert jolt
wooden python
#

when i said inside, i meant inside, not inside plus a little bit outside!

#

like FUCK

desert jolt
wooden python
#

gah

desert jolt
wooden python
#

if you want quickness then op should have done it with logdiff

#

but i am not going to get into that

desert jolt
wooden python
#

he also doesn't know logdiff iirc.

shrewd trellis
#

Im not understanding

wooden python
#

im still frustrated at the fact that, even though i do my best to phrase things clearly,

shrewd trellis
#

can we restart?

wooden python
#

things are getting misunderstood

#

and i get asked to clarify things that are already as clear as i could possibly make them, short of drawing a thing in paint telling you exactly which sub-expression i want simplified

shrewd trellis
#

its okay then, ill get someone else to help me @wooden python

desert jolt
shrewd trellis
#

"One thing you can do is take the denominator to LHS and then use product rule"

desert jolt
#

Yes

shrewd trellis
#

thats a bit unclear

#

can u give me an example

desert jolt
#

Take (3x^2 + 2)^2 to LHS

shrewd trellis
#

like write it down

#

or use texit

desert jolt
#

So that it becomes f(x) * (3x^2 + 2)^2 = (x^3 + 2x)^5

desert jolt
desert jolt
shrewd trellis
#

then write it down

desert jolt
#

@shrewd trellis

shrewd trellis
#

the "appy the uv rule here" is vague

#

apply it where

desert jolt
#

I've literally drawn an arrow

#

As well as defined the functions

#

U =

#

V =

shrewd trellis
#

underneath the (3x^2+2)^2

desert jolt
#

That's V

shrewd trellis
#

yes

#

underneath v?

desert jolt
#

Nothing

#

Im not gonna solve the question for you

#

Youre gonna do that

#

Im only going to help you

shrewd trellis
#

thats what im asking, for help?

desert jolt
#

I've given you a pathway

#

Can you not follow it?

shrewd trellis
#

bro forget about it

#

very unclear

#

.close

odd edgeBOT
#
Channel closed

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Use .reopen if this was a mistake.

desert jolt
shrewd trellis
odd edgeBOT
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gloomy flower
#

.reopen

odd edgeBOT
manic sleet
#

<@&268886789983436800>

odd edgeBOT
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twin vigil
#

Find the value of m for which the coefficient of X in the expansion of (x^m + 1/x²)^22 is 1540

twin vigil
#

Further what I can do

steep mantle
#

binomial expansion gets that

twin vigil
#

Then after that what I would do

steep mantle
#

wait

steep mantle
# steep mantle

figure out what k would be so the coefficient matches with 1540

graceful viper
#
  1. what should the exponent be for the x term?
  2. what should 22 choose k be?
twin vigil
#
  1. 5040
#

That would be very long exapsio

#

why my mind do not work

#

Ill work out

#

. Close

#

.close

odd edgeBOT
#
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odd edgeBOT
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odd edgeBOT
#
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ivory grove
#

!msgdel

odd edgeBOT
#

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inner field
#

hi

odd edgeBOT
jaunty cliff
#

hi

vernal yacht
#

hiiii

inner field
#

im trying to prove special relitivity wrong

#

wait

#

i know what yall will say

crimson beacon
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
inner field
#

let me explain

#

i made something called the superdence burst theory

#

i need a minute let me pull it up

#

The Burst-Core Hypothesis proposes a theoretical mechanism for faster-than-light (FTL) travel through the uncontrolled release of energy from a highly compressed core. Encased in a multi-layered shell capable of withstanding neutron star-level heat and pressure, the burst core could, in theory, release an energy pulse strong enough to push an object beyond the speed of light. This process is theorized to be one-way and unsteerable, posing extreme risk but offering radical implications for superluminal exploration.

In Einstein's theory of relativity, no object with mass can reach or exceed the speed of light due to the infinite energy requirement. However, the Burst-Core Hypothesis circumvents this by not relying on continuous propulsion, but on an uncontrollable energy burst strong enough to create a one-time superluminal event. The idea rests on the possibility that unknown phenomena may occur when extreme energy is released under dense containment conditions.
And if you could get it to hit you You should be launched far by the beam as it is not just light but electromagnetic radiation. First to make the pod you would need reflective plasma armor layer, Hyperdense Compression Lattice layer, Magnetic Containment Field layer, and a Quantum Phase Layer

#

proposed by an 11 year old

crimson beacon
#

and furthermore a burst of EM radiation (light or other) can push objects (like solar sails), but only with finite momentum transfer. No arrangement of mirrors, plasma armor, or fields can amplify this effect to infinite velocity. Photons themselves always travel at c and they cannot push something faster than c.how do you explain that with this?

inner field
#

im not sure let me continue my research

crimson beacon
#

yeah .close

quasi sparrow
#

.close

odd edgeBOT
#
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mystic owl
#

Can we prove this inequality never holds true for integer value of p and positive integer value of q. Like either the upper bound is false or the lower bound is false. I tried taking cases like

  1. q is even and p is negative
  2. q is even and p is positive
  3. q is odd and p is positive
  4. q is odd and p is negative
mystic owl
#

Case 1 is trivial but the rest of the cases are a hassle

#

Also for case 2 and 3 I have tried taking sub case of the big bracket expression being 1) greater and 2) lesser than equal to 0.

digital kestrel
#

whats E_1(1)?

mystic owl
digital kestrel
#

i was already thinking of it as that haha

#

but what is it

mystic owl
#

It’s basically defined like this

#

E_1(1) is approximately 0.2193

#

<@&286206848099549185>

digital kestrel
#

exponential integral at 1, ok

odd edgeBOT
#

@mystic owl Has your question been resolved?

odd edgeBOT
#
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odd edgeBOT
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brave kelp
#

how do i solve this by using quadradic functions? pre calc 11 btw

shut nymph
#

What do you mean quadradic functions?

#

quadratic formula you mean?

brave kelp
#

yes sorry

shut nymph
#

do you know the formula?

brave kelp
#

its called quadradic functions in the course im taking

#

yes

shut nymph
#

ok so what does that give you here?

brave kelp
#

y = a(x - p) + q

shut nymph
#

ohh you mean canonic expression

#

not quadratic formula

brave kelp
#

wait

#

hold on

shut nymph
#

quadratic formula is with b^2 - 4ac

brave kelp
#

i forgot the square

shut nymph
#

yes (x-p)^2

brave kelp
#

yes

#

do i factor out -5 first??

shut nymph
#

well you need to complete the square like the prompt says

#

yes

brave kelp
#

okok

#

i need to go very very soon

shut nymph
#

in the first two terms

brave kelp
#

so its -5(x^2 - 7) + 8

shut nymph
#

you need to find something that resembles (a+b) ^2

shut nymph
brave kelp
#

thast the first step

#

right]

shut nymph
#

yes

brave kelp
#

what do i do next

shut nymph
#

you forgot the x with the 7

#

but ye

brave kelp
#

wow im dumb

shut nymph
#

$(a+b)^2 = a^2 + 2ab + b^2$

clever fjordBOT
#

TheVibe

shut nymph
#

You use this formula

#

So here you need to identify what is a and what is b

brave kelp
#

AHH sorry i need to go

shut nymph
#

no worries

brave kelp
#

thank you for the help

#

i will be back in an hour ish

shut nymph
#

i probably wont be here

#

but someone else probably

#

cya

willow furnace
#

whats up guys

#

anyone need help with anything?

#

guess not

odd edgeBOT
#

@brave kelp Has your question been resolved?

odd edgeBOT
#

@brave kelp Has your question been resolved?

signal oar
shut nymph
#

He said he would come back, he had to go for 1h

odd edgeBOT
#
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uneven burrow
#

can someone teach me races and gamesw

odd edgeBOT
digital kestrel
#

teach you what?

uneven burrow
#

races & games 😭

#

also

#

this too if possible in the easiest manner

digital kestrel
#

"this too" lmao

uneven burrow
#

;-;

#

man im freiaking out my edxam in 1:30 hrs 😭 🙏

nimble trail
#

matrix algebra??

digital kestrel
#

living up to your name

uneven burrow
#

s

nimble trail
#

it's honestly doable even without it

uneven burrow
nimble trail
#

that "Use matrix algebra" is the thing that i don't quite understand

uneven burrow
uneven burrow
#

basically u have to make 2 matrixes and multiply em

#

AB

#

thats it but

#

i cant make the matrix

nimble trail
#

Or I am stupid and didn't understand the question

digital kestrel
#

yea matrix algebra is weird there. it's just adding things up

uneven burrow
#

matrix algebra meaning = make ur own matrix

digital kestrel
#

i don't know why you would set up a matrix

uneven burrow
#

its a question bro

#

im in school chill 😭 🙏

nimble trail
#

||don't tell anybody, but use chatgpt atp||

uneven burrow
#

😭

atomic marlin
#

I am not sure what it means for using matrix algebra

#

But if it’s yo give a table with matrix it’s like this

#

For first row it’s calorie and second row is protein

#

First column is male second is female and third is coach

#

If this isn’t the method or this is, I don’t see the purpose of it though

uneven burrow
#

yooo its like this only

digital kestrel
#

the 1 x 3 matrices should be 3 x 1 matrices since you can't multiply a 2 x 3 matrix and a 1 x 3 matrix

#

but yea maybe that's what it's looking for

uneven burrow
#

it should be like this

atomic marlin
#

Take the transpose for the latter matrix

uneven burrow
#

[2500 65
1900 50
2000 52]

#

this should be the common in both

#

and then the teams

digital kestrel
#

yea you can also use that one instead

uneven burrow
#

take the common as X

digital kestrel
#

what emma did will be the same thing

uneven burrow
#

so AX and BX

#

yeee

#

tysm

#

😉

digital kestrel
#

just be careful with the dimensions

#

if you use that one, the person amount matrices (A and B) should be 1 x 3

odd edgeBOT
#

@uneven burrow Has your question been resolved?

#
Channel closed

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uneven burrow
#

someone find adj() for some reason im getting some values wrong according to chatgpt???

odd edgeBOT
#
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solid crescent
#

i need help, i am in a quantum box

odd edgeBOT
quasi sparrow
#

.close

odd edgeBOT
#
Channel closed

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zinc glacier
#

at least the troll was funny this time

brittle plinth
#

aww was about to make a joke

solid crescent
#

would you give me some food

brittle plinth
#

Can I bust out the hammer?

zinc glacier
#

dont worry, it wont become a problem soon enough

brittle plinth
solid crescent
#

whatever you want it is fine

#

i am alone

#

no one is watching me, i am feeling weird, like, another me... idk how to explain it

#

it ´s just... please, open the box

lavish jackal
#

!redir

odd edgeBOT
#

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

solid crescent
#

this is a help channel right?

#

would you like to help me ?

lavish jackal
#

only if u have a math problem sure

odd edgeBOT
#
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languid hull
#

Hey there, I'm finding the derivative for g(t) = (t^2+t)^2 * (2t-t^3)^-2, and I've gotten to the point of:
(2(t^2+t)(2t+1))/(2t-t^3)^2 - (2(t^2+t)^2(2-3t^2))/(2t-t^3)^3
(See the pdf for a better representation)
I'm having trouble simplifying this down, as my professor wants it to be as simplified as possible, and honestly I'm just kinda stuck lol

odd edgeBOT
#

@languid hull Has your question been resolved?

languid hull
#

<@&286206848099549185>

odd edgeBOT
languid hull
#

Ah my bad, I can change it

languid hull
#

Sorry if it's a bit hard to read

#

I pretty much just need help simplifying it or if I have any errors

tidal matrix
#

,w d/dx (x^2 + x)^2*(2x-x^3)^(-2)

tidal matrix
#

looks all good to me! that would be the fully simplified form, if you were to expand the numerator all the way out and simplify it

#

and its probably "simpler" to have it under one fraction, but id be happy with that response as a teacher - ig it depends how much yours wants simplification

languid hull
#

Ahh ok so my final answer as of now would be fine?

tidal matrix
# clever fjord

yeah it should be (again, depending on teacher a little bit). if you wanna go the extra mile, you can common factor the numerator a bit, and you should end up here

languid hull
#

Thank you!

#

.close

odd edgeBOT
#
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jade trout
#

Hellooo, i need help evaluating composition of functions(⁠⊙⁠_⁠◎⁠)

jade trout
narrow crypt
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
jade trout
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Please help, im abt to have a nosebleed🙏

narrow crypt
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Which step are u stuck

jade trout
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Uh i dont know where to begin

narrow crypt
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Ok

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Do u know what composite function is

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And how they work?

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[ f\circ g(x) = f(g(x))]

clever fjordBOT
jade trout
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Nope

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Ohhh ok i know that

narrow crypt
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For example let ${f(x) = x^2}$ and ${g(x) = x+1}$,
[ f\circ g(1) = f(g(1)) = f(1+1) = f(2) = (2)^2 = 4]
Meanwhile,
[ g\circ f(1) = g(f(1)) = g(1^2) = g(1) = 1+1 = 2]

clever fjordBOT
jade trout
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Can you like give me a full step by step example on how to solve it please(⁠・⁠–⁠・⁠;⁠)⁠ゞ

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Or like another example

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PLEASE

gritty spire
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what do you not understand?

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just like evaluate fog(x)=f(g(x))

jade trout
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I jus need an example so i can like use it as a guide on how to solve

strong sentinel
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I can help

gritty spire
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you can help

jade trout
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PLEASE HELP ME

strong sentinel
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I just picked some random functions but do you understand what I mean by define

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we got two different functions

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f(x) and g(x)

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u with me?

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@jade trout

jade trout
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Yessir

strong sentinel
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ok so if we want to find f(g(3))

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that's f of g(x) when x = 3

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so we are finding out what g(x) equals when x = 3

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and then we're plugging that number in f(x)

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so tell me what g(3) is equal to

jade trout
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HA

strong sentinel
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?

jade trout
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Im lost.

strong sentinel
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ok so do you understand what I meant when I said f(g(3))

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it's ok to say no

jade trout
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Nope sorry

strong sentinel
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so you know how f(x) is a function

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you plug in a number for X and you get a value

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that's what a function is

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so if f(x) = x²

if x = 1 then f(x) = 1²
if x = 2 then f(x) = 2²
if x = 3 then f(x) = 3²

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do you understand that ?

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@jade trout

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oop

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they not responding gg

jade trout
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SORRYYYYY

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😣

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My head is hurting from this🙏

wooden python
strong sentinel
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@jade trout

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it's all good

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but do u understand what i sent

jade trout
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Mhm a little

strong sentinel
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yea

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f(x) = x²

f(1) = 1²
f(2) = 2²
f(3) = 3²

tidal matrix
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another way of thinking about it that i really like:
Let's say $f(x) = 3x + 2.$ We can mess with the variable, $x$, as much as we want:
\begin{itemize}
\item $f(t) = 3t+2$
\item $f(\tau) = 3\tau + 2$
\item $f(\blacksquare) = 3\blacksquare + 2$
\item and so on\dots
\end{itemize}
So we can also (usually) put in $g(x):$
$f\left(g(x)\right) = 3\left(g(x)\right) + 2$ \
$f\left(g(3)\right) = 3\left(g(3)\right) + 2$

clever fjordBOT
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haseeb

jade trout
# jade trout

Can you guys solve one of these, and give me a step by step explanation😭

strong sentinel
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you need to understand how functions work

jade trout
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Mhm i do

strong sentinel
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ok so if g(x) = (2x-1) / 3

what's g(0)

jade trout
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3?

strong sentinel
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explain how u got that

lean yew
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maybe i can share a little bit of my personal notes about functions if it would help

jade trout
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Well uh i multiplied the 2 and 0

strong sentinel
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ok

jade trout
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YES PLEASE

lean yew
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here you go
you will still have to do your problems yourself, but i hope this will help you understand what people here are talking about

strong sentinel
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oh jesus

jade trout
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Wait ok now im confused

strong sentinel
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@jade trout

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$$ g(x) = \frac{2x - 1}{3} $$

clever fjordBOT
strong sentinel
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can you try and find g(0) again

jade trout
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So i replace the x with 0 yeah?

strong sentinel
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yea

lean yew
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remember, whenever x is replaced by a value, just find all of the x in the function and replace it by the same number

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that's all

jade trout
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Oh so g(0)=2(0)-1÷3?

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Is that right??

strong sentinel
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yea

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so what number is that

lean yew
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so far so good

jade trout
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Soooo -3?

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HELP

strong sentinel
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no

lean yew
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[2(0) - 1] / 3

jade trout
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Ohh 2?

strong sentinel
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no

lean yew
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the answer is a fraction

jade trout
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Huh.

lean yew
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show your steps?

strong sentinel
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lets evaluate the top part

jade trout
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Jesus

strong sentinel
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what's (2 times 0) - 1

jade trout
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-1

strong sentinel
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yess

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so the top part of the fraction is -1

jade trout
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MHMM YAY OH MY GOD

strong sentinel
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and the bottom part is 3

jade trout
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Ohh ok ok

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So are all the answers fractions??

lean yew
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not necessarily

strong sentinel
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$$ g(x) = \frac{2x - 1}{3} $$

clever fjordBOT
lean yew
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this is just an example

strong sentinel
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so can you now answer

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whats g(0)

jade trout
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-1/3

strong sentinel
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Yes ❤️

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🙏

jade trout
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SORRY IM STUPID AT MATH

lean yew
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what's g(5) then?

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same technique

strong sentinel
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yeah

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what's g(5)

jade trout
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9/3???

lean yew
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simplify

strong sentinel
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which is?

jade trout
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3/1? HELP

strong sentinel
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yea and anything divided by 1 is itself

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so 3/1 is 3

jade trout
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OHHHH OH MY GOD TYSM

lean yew
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you got it!

jade trout
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Im getting it🙏

strong sentinel
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ur not done yet

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but ur getting it

jade trout
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Oh.

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Im scared

lean yew
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the same applies for functions too, in case you need clarification

jade trout
lean yew
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for example, if wtf is a function, g(wtf) = [2(wtf) - 1] / 3

strong sentinel
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@jade trout back to the original question

jade trout
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Huhu

strong sentinel
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$$ f(x) = 2x^2 + x - 3 $$

jade trout
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Im stressin abt the g(wtf)

clever fjordBOT
strong sentinel
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so if we want to find f(g(0)

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we already know what g(0) is right, you found it earlier @jade trout

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can you respond

lean yew
strong sentinel
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@lean yew you can help them I give up they clearly don't care

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🏃

lean yew
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whoa, relax

jade trout
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Im sorry :,> i didnt mean it like that

lean yew
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i can tell she definitely needs help understanding functions

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well i'm on phone so hopefully i can type well

jade trout
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Im actually eating lunch rn...

lean yew
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ah, another gmt+7-9 guy. well, maybe you can think about this over lunch

jade trout
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So do i answer it rn??(⁠´⁠-⁠﹏⁠-⁠`⁠;⁠)

lean yew
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ofc