#help-19

1 messages · Page 177 of 1

narrow crypt
#

so what is f(0)

hollow copper
#

0

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oh

#

0

narrow crypt
#

f(t) = 500^(0.5) (t/12)

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f(1) = 500 (0.5)^(1/12)

hollow copper
#

what why do we put the number in the brackets

narrow crypt
#

oh dear

#

to represent what is our input

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for the function

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say f(x) = my rizz in x days after today

ocean bramble
#

the surface would be a depth of zero, not 1

narrow crypt
#

and tmr, i have no rizz

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f(1) = 0

narrow crypt
warped glacier
#

the surface is 0 millimeters below the surface

hollow copper
#

what

ocean bramble
hollow copper
#

shouldnt it be on the surface

narrow crypt
#

not related to the question

warped glacier
#

on the surface is 0 millimeters below the surface if you think about it

narrow crypt
hollow copper
#

thats what im sayinnnn

ocean bramble
warped glacier
#

yeah so you have t = 0

narrow crypt
#

what is this

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a steel beam? 😭

ocean bramble
#

that's a glorious drawing of the beam going through the surface

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and it has less particles the more it goes through it

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because some particles get angry and say YOU KNOW WHAT, i'm tired of penetrating the surface

narrow crypt
ocean bramble
#

yes

hollow copper
#

if t is 0

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then

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anything to the power of 0 is 1

copper quarry
narrow crypt
hollow copper
#

so then

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500 x 1 is 500

narrow crypt
#

yup

ocean bramble
hollow copper
#

so then

#

the answer is 500

narrow crypt
#

yes

hollow copper
narrow crypt
hollow copper
#

YAY

narrow crypt
#

(for now)

copper quarry
#

k gaslighted u into thinking u were wrong 🤣

narrow crypt
#

i mean

#

😭

narrow crypt
ocean bramble
#

"replace t for 0"
"physics"
bruh

copper quarry
#

ts just a skill issue not physics issue 💔

narrow crypt
#

physics just estimates everything

copper quarry
#

where is the estimation vro 🥀

narrow crypt
#

lets see

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mircoscope magnification formula

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wave interference formula is based on

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[ \sin\theta \approx \tan\theta]

clever fjordBOT
narrow crypt
#

assume its parralel but its not actually parralel

copper quarry
#

bro its just a math question its not that deep

hollow copper
#

okay guys

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whats this

narrow crypt
#

just add up the area of each side

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its a cube without a lid

hollow copper
#

ohhhh

narrow crypt
#

when're u taking the sat 🥀

hollow copper
#

how many faces and edges are there on a cube

hollow copper
narrow crypt
hollow copper
#

alrr

narrow crypt
hollow copper
#

even tho i dont know these questions that look so easy for u 😭 ??

narrow crypt
#

some ppl just come in here and say stuff like 'guys. i have my calc 3 exam in 12 hours how do i do calc1'

late sinew
narrow crypt
#

anyhow cubes have 6 sides

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(havent removed the lid yet)

hollow copper
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so 29 x 5

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145

#

ez

narrow crypt
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not yet

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area = side^2

hollow copper
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oki

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so 29^2

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841

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whats |

narrow crypt
#

now 5 sides

hollow copper
#

so 841 + 145

narrow crypt
#

,calc (29^2)* 5

clever fjordBOT
#

Result:

4205
hollow copper
#

oh

#

ohhh

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okay

ocean bramble
#

those vertical bars means "absolute value of"

hollow copper
#

oooo okay

narrow crypt
#

move 45 to rhs

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and split into two cases

hollow copper
#

|x - 9| = 18

narrow crypt
#

how split into two cases

hollow copper
#

two cases?

narrow crypt
#

ye

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one positive, one negative

hollow copper
#

(x + 19)(x - 19) = 18

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?

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@narrow crypt

narrow crypt
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no

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case 1: x-9 = 18
case 2: -(x-9) = 18

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or u can do

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case 1: x-9=18
case 2: x-9=-18

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depending on ur preferance

hollow copper
#

okay so

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now whatg'

narrow crypt
#

find x

hollow copper
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x = 37, x = 1

narrow crypt
#

huh

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plz solve it again

hollow copper
#

x - 19 = 18

narrow crypt
#

its not 19

hollow copper
#

ohhh wait

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x = 27, x = -9

narrow crypt
#

nicee

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,w |x-9| + 45= 63

clever fjordBOT
narrow crypt
#

well done

hollow copper
#

dude

copper quarry
#

x = 9 + 18e^i*n ✅

hollow copper
#

i cant enter two solutions

narrow crypt
#

so what is the full question asking

hollow copper
copper quarry
#

💀

narrow crypt
#

just add the two solutions together then

copper quarry
#

next time show the full question vro

hollow copper
narrow crypt
#

what are the choices 😭

hollow copper
narrow crypt
#

hint: factor something out

hollow copper
#

oh man why is the sat so hard

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english section is easy just the maths section is hard

narrow crypt
#

gang

hollow copper
#

anyways

narrow crypt
#

i beg to differ

hollow copper
narrow crypt
#

its something else

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[ \frac{42 \cdot a}{k} + 42 \cdot a \cdot k]

clever fjordBOT
narrow crypt
#

what is the lcm

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between them

hollow copper
#

42

narrow crypt
#

just 42?

hollow copper
#

yeah

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wait no

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42a

narrow crypt
#

bingo

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so can u factor that expresison for me

hollow copper
#

factor means to multiply them?

narrow crypt
#

no

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factor out

hollow copper
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so like

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6 x 7a

narrow crypt
#

like this

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polynomial factorisation

hollow copper
#

uhm

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wait

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ohhhh

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42a(1/k + k)

narrow crypt
#

yup

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so combining it

hollow copper
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42a/k + 42ak

narrow crypt
#

no

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just inside the bracket

hollow copper
narrow crypt
#

[ 42a\left( \frac{1}{k} + k\right)]

clever fjordBOT
narrow crypt
#

how did u link

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chatgpt to game

hollow copper
#

LOLLL

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you download premid

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and it shows any website presence

narrow crypt
#

ohh

hollow copper
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but even with chatgpt im struggling so ig its skill issue

narrow crypt
#

if u try hard enough, ull understand it some day

hollow copper
narrow crypt
#

at least the gpt gives a correct answer this time

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(it sucks at calculus)

hollow copper
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got the chatgpt premium so idk

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its pretty good for me

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how did it get 1 + k^2/ k

narrow crypt
hollow copper
#

ohhh

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cross multiplication

odd edgeBOT
#

@hollow copper Has your question been resolved?

amber veldt
odd edgeBOT
#
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wanton bison
#

Say I have a complex function f(z). Can I always write f(z) as f(z) = f(x,y) = u(x,y) + iv(x,y). where u and v are real valued functions?

tepid pelican
wanton bison
#

Yes

tepid pelican
#

u(x, y) = Re(f(x + iy))
v(x, y) = Im(f(x + iy))

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so yeah, you can

wanton bison
#

I actually think I figured it, given f is analytic we can express f as a power series...

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Then we can group real and imaginary parts

tepid pelican
#

Why'd you need that

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why not just literally take the real and imaginary part

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that works for non-analytic functions

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why go through that power series thing

wanton bison
#

What if you have something like cos(z) I thought or some nasty rational function where it's just hard

tepid pelican
#

u(x, y) = Re(cos(x + iy))

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v(x, y) = Im(cos(x + iy))

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both u and v are real valued

wanton bison
#

bruh I see

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😭

#

Ok thanks Mathew

#

.solved

odd edgeBOT
#
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wanton bison
#

.unsolved

odd edgeBOT
#

wanton bison
#

Or does not exist, or am I tripping?

tepid pelican
wanton bison
#

Oh ok.

tepid pelican
#

if f(z) is defined and is complex, then the result will be a complex number

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and every complex number consists of real and imaginary part

wanton bison
#

true, I was tripping

#

thanks again!

#

.solved

odd edgeBOT
#
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odd edgeBOT
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analog raven
#

the probability that a student is chosen as the school prefct is 0.15,if ther are 11 males and only seniors can be elceted,how many females are there

can someone please help me?

amber veldt
analog raven
#

well you are supposed to find how many females there are based on the number of males and the probability that the person is female

amber veldt
#

I don't see how it's solvable unless there's some sort of relationship between gender and being a prefect

static totem
#

there has to be more numbers

#

seniors and stuff

amber veldt
#

otheriwse it's like saying
the probability that a student is chosen as the school prefct is 0.15,if ther are 11 people who play Skyrim and only people over 2 meters tall can be elected,how many non-skyrim players are there?

rose coral
#

-# loving these pronouns

amber veldt
#

there's something missing about the way you presented the problem

#

because otherwise Skyrim and being over 2 meters tall are just as relevant as being male or female

analog raven
#

number 34

amber veldt
#

oooh you miswrote the question

analog raven
#

oh,i did?

amber veldt
#

you said the probability that a student is elected

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but it's specifically the probability of a female student

analog raven
#

oh

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so whats the answer?

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@amber veldt

amber veldt
#

do you know the law of total probability?

analog raven
#

no

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im pretty new to all of this

amber veldt
#

know what a partition is?

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in English ,if not in math?

analog raven
#

nope

amber veldt
#

it's when you divide something into categories such that:

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no categories overlap

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everything is in exactly one category

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so for example

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a high school can be partititioned in: freshmen, sophomore, junior, senior

analog raven
#

oh so that everyone belongs to oe group only

amber veldt
#

exactly

#

know what an "event" is in probability?

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it just means a thing that can happen or not happen

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here's the rule of total probability:

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if the possible events are partitioned into categories P1,P2,...,Pn

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then:

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$$\mathbb{P}(X)=\mathbb{P}(X|P_1) + \mathbb{P}(X|P_2)+\cdots +\mathbb{P}(X|P_n)$$

clever fjordBOT
#

gfauxpas

amber veldt
#

let's give an example

analog raven
#

then?

amber veldt
#

suppose I have a collection of candies

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they are either sour or sweet

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and I want to know the probability that a candy is broken

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then

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$$\mathbb{P}(\text{broken})=\mathbb{P}(\text{broken}|\text{sour})+\mathbb{P}(\text{broken}|\text{sweet})$$

#

make sense?

clever fjordBOT
#

gfauxpas

amber veldt
#

do you understand the example?

analog raven
#

i think i do

amber veldt
#

actually i used the wrong notation

#

it's

#

$$\mathbb{P}(X)=\mathbb{P}(X \text{and} P_1) + \mathbb{P}(X \text{and} P_2)+\cdots +\mathbb{P}(X \text{and} P_n)$$

clever fjordBOT
#

gfauxpas

amber veldt
#

$$\mathbb{P}(\text{broken})=\mathbb{P}(\text{broken and sour})+\mathbb{P}(\text{broken and sweet})$$

clever fjordBOT
#

gfauxpas

amber veldt
#

I was using the | incorrectly, anyway

#

what's the probability of ANYONE being elected prefect?

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presumably the prefect election has to have a winner

analog raven
#

oh so its like the probability that anyone is elected is ,the total of nominees,plus boys,plus the total nominees plus girls

#

?

amber veldt
#

you have the right idea but let's make it precise

#

assuming a candy is not both sour and sweet, and is either sour OR sweet and not neither

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you can split up candies into sour candies and sweet candies

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for the election, let's split up the people running for prefect into males and females

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it's a partition because math problems don't deal with intersex people and the like

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right?

analog raven
#

yh

amber veldt
#

$$\mathbb{P}(\text{prefect is elected})=$$
$$\mathbb{P}(\text{male prefect is elected}) + \mathbb{P}(\text{female prefect is elected})$$

clever fjordBOT
#

gfauxpas

amber veldt
#

you know two out of three of these values

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which ones?

analog raven
#

the male and the probabilty that 1 is elected

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?

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@amber veldt

amber veldt
analog raven
#

the probability that a female is elected and the number of maled

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males

amber veldt
#

you also know the probability that a prefect is elected

analog raven
amber veldt
#

it's like saying

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what's the probability that there will be a president/prime minister victorious in the next election?

analog raven
#

100 percent?

amber veldt
#

exactly

#

so the probability that a prefect is elected is 100%, or 1

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the probability that a male prefect is elected? we dont know yet

#

prob that a female prefect is elected? they tell us

analog raven
#

oh ok

amber veldt
#

solve for the probability a male prefect is elected now

analog raven
#

99.75?

amber veldt
#

how'd you get that?

#

first of all, probabilities are always from 0 to 1, or from 0% to 100%

analog raven
#

idk if thats correct

amber veldt
#

1-0.15, not 100

analog raven
#

oh ok

#

so its 0.75

amber veldt
#

and 1-0.15 is not 0.75

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because 0.75+0.15 is not 1

analog raven
#

my bad

#

0.85

amber veldt
#

yeah

#

alright!

#

progress

#

how many males are there?

analog raven
#

11

amber veldt
#

trying to think of how to do this the easiest, simplest way

analog raven
#

ok,ill be waiting

amber veldt
#

what does (SHORT WORK-10 Sec) mean?

#

youre supposed to do it in 10 seconds?

#

if you're supposed to do it in 10 seconds, there's some shortcut im not seeing

analog raven
#

sample question

amber veldt
#

i'm going to pass this question to <@&286206848099549185> then because the way im thinking of is time consuming and im pretty sdure there's a shortcut im not seeing

analog raven
#

ok

#

but still continue tho so that ill get the answer

#

the shorter method can wait

#

@amber veldt

amber veldt
#

yeahokay

#

shortcut way

#

the probability that a female student is elected

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okay

#

it has to be

#

the only way that I can see you do this problem

#

is to assume everyone has an equal chance of being elected

#

which is idiotic

tidal matrix
#

i might have another way: if only the senior students can be elected, 15% chance of being elected = 15% of total class

#

equivalently, 85% chance of being elected = 85% of the class = 11 males

#

does this work?

amber veldt
#

the problem is only solvable if you assume every candidate has an equal chance to win

tidal matrix
#

ohh sorry, i thought you meant irrespective of gender

amber veldt
#

nope, you were on the nose

#

I was not assumign that because that's not how elections work but

#

anyway, haseeb will take over now

tidal matrix
#

unfortunately the mathematical world is idealized

tidal matrix
analog raven
#

yh

#

but how do we find the number of females based of only the probabilities?

tidal matrix
#

well, if 85% of the class = 11 males, we can make an equation where x = size of entire class

#

do you see how?

analog raven
#

i think i do

tidal matrix
#

give it a try :)

analog raven
#

so basically,85/100 of x =11

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85 when simplified is 17,100 is 20

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so 17 over 20 of x =11

#

which gives 12.94?

tidal matrix
#

yep exactly! if you have a calculator, you could do 0.85x = 11 too

tidal matrix
#

because next we need to find 15% of class, i.e. 0.15(x)

analog raven
#

so the answer is 13?

#

if everyone has an equal chance?

tidal matrix
#

no, that's the total class size

#

we need to find the number of women

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if 15% of women can get elected, then 15% of the class is women, considering equal chance

analog raven
#

oh ok'

#

so its 3

#

2

#

sorry

tidal matrix
#

yeah 2 lol

#

i think considering it is short work, you can assume an equal chance and do something like this

analog raven
#

thnx

tidal matrix
#

you can also make it faster: we divided by 0.85 and multiplied by 0.15, so just do (11 / 0.85) * 0.15 in one step

#

but if thats too confusing, better to do it right than do it fast :)

analog raven
#

ok

#

thnx

tidal matrix
#

npnp! best of luck :)

#

!done btw

odd edgeBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

analog raven
#

.close

odd edgeBOT
#
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limpid juniper
odd edgeBOT
limpid juniper
#

I js don understand this question

#

What is a term to term rule

#

There are no common difference

analog raven
#

there doesnt need to be

#

you just need to multiply each value given by the figures in the rule

limpid juniper
#

really
i thought there is always a common difference in arithmatic sequnce

analog raven
#

1*2+3=5

limpid juniper
#

1?

analog raven
limpid juniper
#

..

analog raven
#

okarun

#

oka-run

limpid juniper
#

yes

#

how do u find the 1st term

analog raven
#

=1

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then 1*2+3 =5

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and so on

limpid juniper
#

ic its totally different when u are given a rule

latent scaffold
limpid juniper
#

its not nessecary that 1st term n = 1, 2nd term n = 2

analog raven
#

m is an integer that must be added,subtracted,divided or multiplied by the first given value to get the next number in the sequence i think

limpid juniper
#

ok so for 2nd term m = 1, for 3rd m = 2 like this

analog raven
#

exactly

#

actually no

latent scaffold
#

That's not what I meant

limpid juniper
#

yeah figured

#

yeah can u go a bit slowly

analog raven
#

ok

limpid juniper
#

i can ask the answer but i want to understand it too, thats why im asking too many q

latent scaffold
#

m is fixed. For any m fixed, say m=4, the rule "Add 4" generates an arithmetic sequence

#

This is different from this problem, as the rule isn't "Add <insert fixed value here>"

#

But the idea is the same. You're given starting terms and the way to generate the next term from a previous term.

analog raven
#

so basically,you apply the same formula for every new value you find in the sequence

#

in order to find the next one

#

do you get it?

limpid juniper
#

yeah

analog raven
#

so whats the next numbr in the sequence

limpid juniper
#

we find the next term relative to the previous term

#

13 multiply 2 then add 3

#

29

#

thats it

analog raven
#

yh

#

you undertsand it

limpid juniper
#

.close

odd edgeBOT
#
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dreamy totem
#

How do I simplify this? The absolute value signs are so confusing

feral halo
#

let u = |x+1| ig

strange aspen
feral halo
#

its easier to visualise if you sub

atomic void
#

@dreamy totem , notice that (-5)^2 = 5^2. Squaring doesnt depend on the sign

#

so u can safely yeet out the absolute value in the firsst term

feral halo
atomic void
#

yep

odd edgeBOT
#

@dreamy totem Has your question been resolved?

odd edgeBOT
#
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fathom orchid
#

Super confused on what I’m supposed to do cuz the answer I got for elasticity was like 13 sum that can’t be right!!!

fathom orchid
#

I think there’s sum wrong with those formulas at the end like why r we dividing by 2 here

odd edgeBOT
#

@fathom orchid Has your question been resolved?

odd edgeBOT
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Ask your math question in a clear, concise manner.
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haughty jungle
#

help

odd edgeBOT
rose coral
odd edgeBOT
haughty jungle
#

it was accounting

#

here is my progress, I am stuck in adjusted trial balance

our professor said, our ending balance should be same TOTAL and not unequal

ivory grove
#

Can you post a specific problem using an image file?

#

!filetype

odd edgeBOT
#

Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

haughty jungle
#

I've already made journal entries, tried to recheck 3x as well.

Adjusting entries was correct as well.

Adjusting TRIAL Balance is correct as well

But in un-adjusted TRIAL BALANCE is i don't know why it is still not equal, and it must be

#

I'm stuck for about 2hours like wth

#

I'm done thank you for nothing, but still I don't know how i get the answer

#

I mistakenly put a utilities expense on cr side, that should be on dr side

I'm still confused AF, how 5k on service revenue add from its previous one

#

.close

odd edgeBOT
#
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zenith crane
#

can someone check my answer i got 175pi+(2/3pi*125) for volume but that doesnt seem right

zenith crane
#

i dont remember

mystic nova
#

Is the top part a half of Sphere

zenith crane
#

it doesnt say

#

but im assuming it is

stable sequoia
#

just plug the volume formulae

#

and sum them up

zenith crane
#

i did

#

thats what i got

desert jolt
#

It’s correct

#

I don’t see anything wrong

zenith crane
#

alr

#

what about this one i got 180+36pi

#

ignore the 4s

desert jolt
#

Is 6 the height?

zenith crane
#

yeah

desert jolt
#

Oh ok

#

Is that a cube or cuboid

zenith crane
#

wth is a cuboid

#

it looks like a cube to me

desert jolt
#

Then why are there 2 side lengths

zenith crane
#

there arent

#

the teacher put the 6 feet over 4 feet

desert jolt
#

So we’re gonna ignore the 4?

zenith crane
#

yeah

desert jolt
#

How did you get your answer

zenith crane
#

oh wait no

#

i had that as surface area

#

i got 216+27pi for volume

desert jolt
#

@zenith crane

zenith crane
#

yeah

#

?

odd edgeBOT
#

@zenith crane Has your question been resolved?

desert jolt
#

Sorry for the late response

#

@zenith crane

odd edgeBOT
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patent parcel
#

Question 10) is the answer of this question 5!•5!

narrow crypt
#

E O E O E O E O

#

smth like this

patent parcel
#

Yea

mystic nova
narrow crypt
#

five spots for even. five for odds

mystic nova
#

can't

patent parcel
narrow crypt
#

why

patent parcel
patent parcel
narrow crypt
#

not u

patent parcel
#

Kk

narrow crypt
#

also

#

does

#

O E O E O E ... count?

mystic nova
#

I mean 0925476183 count?

patent parcel
narrow crypt
patent parcel
#

Even first

#

Oh

narrow crypt
patent parcel
#

We r assuming 0 even here

patent parcel
narrow crypt
#

if O E O E O E... counts too

patent parcel
#

Wait then again my answer is correct

narrow crypt
#

should multiply by 2

#

if not ur ans should be ifne

mystic nova
patent parcel
#

5!5!

#

Evens and odds both r 5

#

Integers

#

So

mystic nova
#

We have odd first and even first are two cases that why he say multiply by 2

patent parcel
#

Ok right

#

I get it

#

2•5!5!

#

Considering odd integer first can be case it doesn't violate anything in question

#

Thankyou guys

mystic nova
#

you are welcome

patent parcel
#

Could u guys check other question answer
Question 12) is it P(39,7)

#

The case is there's no club card in any lineup

#

So removeing 13 cards we get 39

mystic nova
#

I have no idea what a club is since I have never played card 😂

patent parcel
#

7-Permutations from 39 is P(39,7)

patent parcel
#

I will give u some information about it not that much tho

#

There are 4 suits

#

each suits contains 13 cards

#

Hearts, diamonds , clubs and spades (they r actually four suits)

#

So clubs contains 13 cards

mystic nova
patent parcel
mystic nova
#

Yeah, I think you're right, I can't think of any countercase

patent parcel
#

Thanks alexis
Ig Im doing correct

#

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#
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kind smelt
odd edgeBOT
kind smelt
#

i tried expanding the denominator for both sin and cos but the 3 angles are ugh

iron current
kind smelt
#

yeah

upbeat wharf
#

if you let $S = \alpha + \beta + \gamma$, you have $$\sin(\alpha) + \sin(\beta) + \sin(\gamma) = 2 \sin(S)$$
and likewise $$\cos(\alpha) + \cos(\beta) + \cos(\gamma) = 2 \cos(S)$$

clever fjordBOT
kind smelt
#

okay

upbeat wharf
#

try and wrestle this into the form $e^{i \theta} = \cos(\theta) + i \x \sin(\theta)$

#

so maybe multiply one of the equations by $i$

clever fjordBOT
kind smelt
#

Oh complex numbers

clever fjordBOT
kind smelt
#

isn't there a way to do this using Q.E, sequence and series, Trigo, basic maths?

leaden karma
#

Write cos(alpha+beta) as cos(S-gamma)

#

and the same for the rest of the terms

kind smelt
#

ok yes

leaden karma
#

then expand and use the two identities

leaden karma
kind smelt
#

which two identities?

kind smelt
leaden karma
#

sin(a)+sin(b)+sin(c)=2sin(S) and cos(a)+cos(b)+cos(c)=2cos(S)

#

yes

kind smelt
#

i got 6 terms which i tried factorising

#

after expanding

kind smelt
leaden karma
leaden karma
#

yes

kind smelt
leaden karma
kind smelt
#

.close

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#
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fleet lake
#

hi

odd edgeBOT
narrow crypt
#

hi pandawow

fleet lake
#

find max value of f(x)=|x+1|-2|x-1|

turbid comet
#

What have you tried

fleet lake
#

nothing

#

i dont know from where to start

wooden python
#

write a piecewise function defn for this function

#

from this sketch its graph

fleet lake
#

How?

#

idk even that

wooden python
#

do you know what piecewise functions are in general

fleet lake
#

like ik graphs

wooden python
#

bruh ok

#

then how were you taught the modulus function

#

like how was it introduced to you

fleet lake
#

u mean Cases like x>1 etc

turbid comet
fleet lake
#

true

wooden python
#

write a definition for f(x) that doesnt involve absolute value but does use cases

fleet lake
#

done

fleet lake
#

different for each peicewise f^n

#

?

turbid comet
#

The graph for each interval is different

fleet lake
#

yeah

wooden python
fleet lake
#

done

wooden python
#

do you understand the meaning of the word "show"

fleet lake
#

x<-1
x-3

-1<=x<1
2-x

x>1
-x

wooden python
#

this looks wrong to me. show your work.

turbid comet
#

The graph ??

fleet lake
turbid comet
#

There is an error in the last one

wooden python
#

i think all of his sub-expressions are wrong here

turbid comet
#

The first one is correct i think

fleet lake
#

yeah -1<=x<1
is 3x😅

nimble grove
wooden python
#

would have liked to see it on paper but given op's history of bad handwriting im afraid to ask

fleet lake
fleet lake
turbid comet
#

Can you show your working

#

2-x doesn't seem right

fleet lake
#

shall i write it proper

nimble grove
#

just show it

fleet lake
#

first

wooden python
#

im asking to have x's that actually look like x and not n or u or h or k

magic ledge
#

hey guys

#

im new

#

😃

turbid comet
#

This is a help channel though

#

Not the right place

magic ledge
#

??

#

wym?

turbid comet
#

Anyways welcome to the server

magic ledge
#

ty

fleet lake
#

I'm sorry I was doing so rough work and silly mistakes

magic ledge
#

im having so much trouble w my goddamn monitor

#

whats the question bud

#

btw im Rao

Im 15

#

im now learning Tangents in circle

nimble grove
turbid comet
#

In the third one it is +2

fleet lake
#

3-x now

#

For case-3

nimble grove
#

perfect

magic ledge
#

im learning

tangent angle in a circle

#

so who knows what is it

fleet lake
#

everyone here💀 know that

magic ledge
#

In the diagram below, PQRS is a cyclic quadrilateral.

Find the value of x.

68°

82°

106°

115°

turbid comet
#

!occupied

odd edgeBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

magic ledge
#
  • im js 15 :/
fleet lake
#

ik i meant just ask dont ask if u can ask

#

im js 15 too

magic ledge
#

ouh u too

#

w

#

im confused abt it

nimble grove
#

Now you have your 3 cases, check the slopes of those 3 cases respectively (the coeffecient of x in each case)

turbid comet
#

You sent

nimble grove
#

If its positive, its an increasing slope. If negative, its a decreasing slope

magic ledge
magic ledge
turbid comet
nimble grove
magic ledge
#

ouh ok

#

sorry

nimble grove
#

Hey @turbid comet , so sorry for the ping and unrelated chat but this is my first time helping someone here as this question happened to be around my skill level and current knowledge. Is there anything I should note for further questions?

fleet lake
nimble grove
fleet lake
#

Graphs drawn

nimble grove
#

now back to your question

nimble grove
fleet lake
nimble grove
#

Yes, that works too

#

Now find where it's max and plug it into f(x)

#

That should be your answer!

fleet lake
#

case?

nimble grove
#

plot the 3 cases and find if their graphs are increasing or decreasing

fleet lake
#

im saying taht 3x-1 graph is the most increasing

nimble grove
#

oh ok and that lies in which range?

#

-1 >= x > 1

fleet lake
#

[-4,2)

nimble grove
#

so therefore it increases uptil 1 and then starts decreasing which implies your max is at x = 1 !

nimble grove
fleet lake
#

oh u mean domain

nimble grove
#

My terminology is getting rusty

#

Now just plug it into f(x)

#

That will give you max value

fleet lake
#

2

nimble grove
fleet lake
#

.close

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#
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errant elk
#

can someone explain for me why a=b=t because we set t=a+b/2 first , im confused a bit

errant elk
#

Its an inequality problem

atomic void
nimble grove
errant elk
#

we already set a+b/2=t tho , I just don't get it 😅

atomic void
#

Imagine this,u have the function f(x) = x^2

#

obviously, f(a) = a^2 right? Just a change of variables anyways

#

then if u want to set t = a/2

#

f(t) = t^2 anyways

#

doesnt matter what u set t as

#

just now u can write f(t) = t^2 = (a/2)^2 = a^2 / 4

#

@errant elk u got it?

errant elk
#

I got it thank u sm😭

atomic void
#

!done

odd edgeBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

errant elk
#

Close

atomic void
#

a dot at the bacl

#

" .close "

errant elk
#

.close

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#
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frosty sundial
odd edgeBOT
frosty sundial
#

I needed help and 2 different ai gave 2 different answers

#

this was my last resor

tepid pelican
#

Can you state the conditions in terms of decreasing/increasing and convex/concave

ivory grove
frosty sundial
#

f'(x)>0 is increasing and less than is decreasing. f''(x)>0 is concave up and less than is concave down

frosty sundial
tepid pelican
#

On which intervals is f increasing

#

Of A B C

frosty sundial
#

A

#

not wait

#

B

#

the other intervals

#

f is also somewhat decreasing

tepid pelican
frosty sundial
#

A?

tepid pelican
#

No

#

Increasing means that if you were walking from left to right, youd be walking uphill

frosty sundial
#

C

tepid pelican
#

Yeah

frosty sundial
#

but part of c is also cocave down

tepid pelican
#

F is increasing on both B and C

frosty sundial
#

like at the end

tepid pelican
#

So f'' < 0 at C

#

What about B

#

Is f concave up or down there

frosty sundial
#

concave up

#

f''>0 there

#

so its the only correct option

#

right?

tepid pelican
#

Yep

frosty sundial
#

ok

#

wait

#

ima check if i got it right

#

stay here

#

I DID

#

thanks for the help @tepid pelican

#

.close

odd edgeBOT
#
Channel closed

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tepid pelican
#

Np

frosty sundial
#

im back

#

yo somebody help

#

basically

#

mach each graph, with the appropriate form of the function

#

ie f(x)=I, f'(x)=II, and f''(x)=III

#

thats the gist of it

#

yo

#

somebody

#

<@&286206848099549185>

#

yo

#

help

#

new problem

#

i got the other one wrong

#

.close

#

.close

#

.reopene

#

.reopen

odd edgeBOT
#

#

@frosty sundial Has your question been resolved?

narrow crypt
#

is this

#

khan academy?

odd edgeBOT
#
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hidden escarp
#

Hello I need some help with this

odd edgeBOT
hidden escarp
narrow crypt
#

translate plz

strange aspen
hidden escarp
#

A numerical sequence with u0=2 as the first term and u(n+1) =....

#

Calculate the lim of Sn

solar peak
#

what have u tried

hidden escarp
#

Umm nothing yet

#

Only found that limun=0

solar peak
#

limun?

brittle beacon
solar peak
#

oh

hidden escarp
#

Yes

brittle beacon
#

(did you try working out some of the S_n's?)

solar peak
#

yeah write a few terms

#

in terms of u0

hidden escarp
#

Yeah the values keep getting smaller and smaller

#

Any help ?

solar peak
#

one second im trying something

solar peak
#

is the answer C?

hidden escarp
#

Yeah I asked ai it said C

#

But its methods are not convenient

solar peak
#

u can use the options

#

all the terms are positive

#

and it starts from 2

#

so it cant be option 1

#

or option 4

#

the 2nd term is very small but still it wont be 2

#

so by that logic i would say it has to be C

#

i hope u get a proper explanation tho, this is the best i could do

hidden escarp
#

Ohh ok thats nice thanks

#

.close

odd edgeBOT
#
Channel closed

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solar peak
hidden escarp
#

.reopen

odd edgeBOT
#

hidden escarp
#

I didn't understand why it can't be 2 tho

solar peak
#

its 0.27

hidden escarp
#

Yeah

solar peak
#

my thought process was its very unlikely that 2.27 + ... is approximated to 2

brittle plinth
#

the series starts from k=0

hidden escarp
#

Ohh ok

brittle plinth
#

and all the terms after it is positive

#

still doesnt really explain why it is divergent

solar peak
#

yeah

brittle plinth
#

unless there's some horrible way to write out the general term

bitter sleet
#

Why not use series convergence test

odd edgeBOT
#

@hidden escarp Has your question been resolved?

hidden escarp
odd edgeBOT
#

@hidden escarp Has your question been resolved?

#
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tropic vale
#

why are parabolas for conic sections specifically the parameters x=at^2 and y=2at or y^2=4ax?

narrow crypt
#

What😭

tropic vale
#

yk like for the focus and directrix of a parabola?

narrow crypt
#

y^2 = 4ax is from the defn that parabola is locus of points equidistant from directrix and focus

#

Derived from distance formula

tropic vale
#

what's the distance formula?

narrow crypt
#

[ D = \sqrt{(\Delta x)^2 + (\Delta y)^2} ]

clever fjordBOT
tropic vale
#

how does that derive to y^2 = 4ax?

narrow crypt
#

Consider the simplest case

tropic vale
#

focus at a

#

directrix is -a

#

y=0

narrow crypt
#

Focus is at (a, 0)

tropic vale
#

right?

narrow crypt
#

Ye

narrow crypt
#

Since both are in the square root

#

And are never negative

#

It suffices to only consider the inside

tropic vale
#

[ D = \sqrt{(x-a)^2 + (y)^2} ]

#

hm

#

how do i use texit?

elfin zodiac
#

writting correctly

tropic vale
#

thanks sherlock

tribal ingot
#

surround your latex with $

tropic vale
#

thank you

tribal ingot
#

$a^2$

#

like that

clever fjordBOT
#

satvik

tropic vale
#

$D = \sqrt{(x-a)^2 + (y)^2}$

tribal ingot
#

$D = \sqrt{(x-a)^2 + (y)^2}$

clever fjordBOT
#

satvik

tropic vale
#

that

#

simplest case right?

clever fjordBOT
narrow crypt
#

How abt the distance to the directrix?

tropic vale
#

isn't it x+a?

#

or sorry |x| + |a|

#

since x + a = 0

narrow crypt
#

(x + a)^2

narrow crypt
tropic vale
#

right

#

i got it

#

i see

#

cheers

#

.close

odd edgeBOT
#
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modest kite
#

a six sided dice is thrown twice. What is the expected value of:
$E(\max(X,Y)|Y=k)=\sum^6_{x=1}x\cdot P(\max(X,Y)=x|Y=k)$?

clever fjordBOT
#

McMake

modest kite
#

I only get a value with k as a result. I know the technical value with the chances of k, but dont know the formal way to get there

#

could someone help?

quasi sparrow
#

break it down into cases when x < k and x >= k

odd edgeBOT
#

@modest kite Has your question been resolved?

odd edgeBOT
#
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modest kite
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hello. my internet went out. Its the same question:
a six sided dice is thrown twice. What is the expected value of:
$E(\max(X,Y)|Y=k)=\sum^6_{x=1}x\cdot P(\max(X,Y)=x|Y=k)$?

clever fjordBOT
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McMake

modest kite
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yeah but I get $\frac{k^2-k}{12}+3.5$

clever fjordBOT
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McMake

modest kite
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from $\frac{1}{6}\left(k^2+21-\frac{k^2+k}{2}\right)$

clever fjordBOT
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McMake

modest kite
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this is my seperation:
$\frac{1}{6}\left(\sum^k_{x=1}k+\sum^6_{x=k+1}x\right)$

clever fjordBOT
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McMake

modest kite
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I don't know how to formally get k in there

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im basically asking how do I break this down?

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$\sum^6_{x=1}x\frac{P[\max(X,Y)=x,Y=k]}{P[Y=k]}$

clever fjordBOT
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McMake

quasi sparrow
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k is a constant with respect to x

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k + k + ... + k = ?