#help-19

1 messages · Page 174 of 1

magic notch
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<@&286206848099549185>

warm sentinel
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wasup

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what do i do

magic notch
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i got a vry off answer i think

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thanks

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What did i do wrong

magic notch
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<@&286206848099549185>

desert jolt
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Form a DE by using fbds

magic notch
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whats fbds

desert jolt
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Free body diagram

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DE means differential equations

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Have you learnt how to solve ODEs?

magic notch
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no

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this is resisted motion

desert jolt
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Yeah which translates to ode after writing the equations

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a = (kv^2)/m + g

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a = dv/dt

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@magic notch you've done the intellectual shit nicely

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I believe now its just some writing mistake or silly mistakes somewhere

magic notch
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hmm

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but it feels wrong since you dont get a solvable v0 equation

desert jolt
magic notch
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ok i will try

desert jolt
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Wrongly integrated here

magic notch
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shii

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forgot the 2 constant

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and did the same thing on the down equation

late sinew
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Thats not the problem

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The problem is v is squared

magic notch
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but u have a v on top so how is that an issue

late sinew
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Oh oops

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Yeah just forgot the 2 then

magic notch
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does that even change it tho

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bcuz if ur subbing x = 0 then the 2 doesnt matter

desert jolt
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Do you have the answer @magic notch

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?

magic notch
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no

odd edgeBOT
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@magic notch Has your question been resolved?

magic notch
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:(

desert jolt
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I think you did some sign errors

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While going downwards and upwards

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Cuz im getting an answer

odd edgeBOT
#

@magic notch Has your question been resolved?

odd edgeBOT
#
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wooden oar
#

Hi! Could someone check my solution for task 1.9 and 1.10?
For 1.9 i answered A = {1, 2, 3}, B = {4} and C = {3, 4, 5, 6}.
For 1.10 i chose A = {1} and B = {2, 3}.
Also, if the translation is a bit unclear, tell mee.

wooden oar
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Thanks in advance.

wooden oar
wooden python
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yup i second that

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your answers are correct

wooden oar
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Alsoo, i am not sure how to prove task (1.11). By definition, a set A is a subset of a set B if all elements in A are also elements in B. Lets say we have a set X, and now someone says that X is a subset of X, how do i prove it? I would say, because they are equal, they would contain the same elements, therefore X would be a subset of X (itself), right? But i dont think its enough to say that for a proof..

cold depot
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I think what you said with the definition is enough. Just say let x be arbitrary element of X. Then x is in X. Since x is arbitrary, any element of X is in X. Therefore, X is subset of X

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I know it feels redundant/weird, but these simpler proofs are usually this way

wooden oar
cold depot
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It's a way to generalize to all elements of the set, which you often must do to ensure there are no "holes"/counterexamples in your proof

wooden oar
wooden oar
# cold depot Yes yes

got it, but can i prove "the empty set is a subset of X" similarly? cause a counterexample wouldnt make sense - "the empty set is not a subset of X, cause not all elements in the empty set are in X" however, an empty set has no elements, its empty, and so therefore we can say that it is a subset of X?

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i cant think of any other way to prove that "the empty set is a subset of X" is true..

warped glacier
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the empty set is a subset of anyset

warped glacier
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np

cold depot
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For the empty set, there are no elements that are outside of X, therefore it is a subset of X

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It's what they mean with vacously (there are no counterexamples)

wooden oar
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thanks!

odd edgeBOT
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@wooden oar Has your question been resolved?

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patent parcel
#

Hello

odd edgeBOT
patent parcel
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~(matrix A is invertible)
Is it correct in question 2

steel quarry
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thonkzoom this question kind of sucks

patent parcel
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Anything else from u

steel quarry
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Nvm you're right

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You've been given 4 definite forms to choose from

patent parcel
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According to u what should it be

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Is it funny 🤣 i think so

steel quarry
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Nothing, you're correct

patent parcel
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Ok

patent parcel
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Ni

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No wait

steel quarry
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notice how $\cup$ and $\vee$ look similar

clever fjordBOT
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jewels!

patent parcel
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I didn't get

wanton bison
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It's not necessarily and

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x can only be for example in A and it would still be in the union of A and B

patent parcel
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Oh right

wanton bison
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So it can be in A or in B or both

patent parcel
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Or right?

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Ok

wanton bison
patent parcel
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Oh

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Great

wanton bison
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\cup refers to union
\vee to logical OR

patent parcel
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Ok i got iy

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It*

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Ok last one question 12
are they two statements
With "And"

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What second statement should be to form symbolic way

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"happy family are all alike but each unhappy family is unhappy in its own way"

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S_1: Happy family are all alike

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S_2: unhappy family are all alike

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S_1 and not S_2

patent parcel
wanton bison
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Hmm, why and?

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Wait no, it should be right

patent parcel
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Ok

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Thanks universe

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.close

odd edgeBOT
#
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odd edgeBOT
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obtuse saddle
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how can I prepare for precalc ? I got precalc coming in 48 days and was wondering if I can do anything to prepare for the class I'm pretty rusty tbh

wooden python
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precalc class?

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or precalc exam

obtuse saddle
wooden python
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right

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algebra, algebra, algebra

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and arithmetic i'd say

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make sure you're able to manipulate algebraic expressions without hitting snags

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factorization's a big thing

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applying things like (a ± b)^2 = a^2 ± 2ab + b^2 or difference of squares as well

obtuse saddle
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so would khan academy be a good option ? like algebra 1 and 2 ?

wooden python
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yes

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perhaps even look through their precalc stuff to see a sampler of what might be coming

plain ruin
obtuse saddle
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so is there anything I can skip to save time or would I have to go through all units in both like for example this is the algebra 1 section

wooden python
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don't skip anything

sand horizon
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Functions in algebra?

obtuse saddle
mystic saffron
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Maths is a field where your knowledge builds onto itself, dont skip anything so you have a well rounded foundational knowledge for future application

sand horizon
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Might apply to any science

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So take this text for all your subject

mystic saffron
plain ruin
mystic saffron
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You will surely cover all those concepts once you start regardless

wooden python
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but if you're pressed on time i would at least get your feet wet in every section

obtuse saddle
wooden python
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oh it's 17 units my bad

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you showed the first 9

mystic saffron
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What maths have you done before

obtuse saddle
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not 2

obtuse saddle
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it was basically algebra 2 and a bit of precalc

obtuse saddle
wooden python
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<@&268886789983436800> advertising

errant galleon
wooden python
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advertising is still against server policy and this includes personal discords.

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in any case you're intruding in an occupied help channel too

mystic saffron
# obtuse saddle yeah thats what I am saying so Im not sure I have enough time

Looking at that khan academy course, my piece of advice is don't stress over it too much, most of those concepts, atleast from your maths knowledge, should be relatively easy to pick up – I doubt it will take 48 days to revise algebra 1, but that will depend on how quickly you pick up maths and your dedication to learning

wooden python
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^

obtuse saddle
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then I burnout

wooden python
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that and also there's gonna be a review thing at the beginning of your class

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so like even if you dont get everything in thats not something to worry about

obtuse saddle
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alr so I'm gonna just go through as much as i can for algebra 1 and 2 I've already done 2 units in algebra 1 so I'm gonna continue there

wooden python
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yeah fair

odd edgeBOT
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@obtuse saddle Has your question been resolved?

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oblique cargo
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Can someone help me with this question?

solar peak
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according to ur ans its independant of t?

oblique cargo
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this is what I did

solar peak
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oh sorry have no clue what leibniz rule is..wait for someone else to help

oblique cargo
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alright

odd edgeBOT
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@oblique cargo Has your question been resolved?

quasi sparrow
oblique cargo
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that's the preview of what I wrote in the box

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I think I messed up something when I did the u sub

quasi sparrow
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Well your input isn't fully shown

oblique cargo
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the preview box above is the output

quasi sparrow
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,tex .FTC2

clever fjordBOT
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riemann

quasi sparrow
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Did you use this

oblique cargo
quasi sparrow
quasi sparrow
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Oh f is a function of x too

quasi sparrow
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Show the leibniz rule you learned then

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Should just be an additional term

oblique cargo
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the other term is just 0

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d/dx (1) = 0

odd edgeBOT
#
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weak fossil
odd edgeBOT
tepid pelican
# weak fossil

I'd just count the total number of ways and then subtract those which make some row empty

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there aren't that many of them

odd edgeBOT
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@weak fossil Has your question been resolved?

weak fossil
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but the answer is 5760

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<@&286206848099549185>

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
weak fossil
odd edgeBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

fervent pewter
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Forget the constraint of "no row remains empty" for now..how will u place the 5 letters amongst the 8 boxes?

fervent pewter
inner moth
# weak fossil

correct me if i'm wrong, i'm not really good at combinatorics
Chose 3 out of 5 letters to fill in the 3 rows in different orders using 5P3, then count the number of left boxes after filling one box in each row (which is 5) and chose 2 of them for the rest 3 letters, so it's 5C3, now 5P3*5C3

weak fossil
fervent pewter
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I will help u with that thought process

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answer my intial question first

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tell me the no. of ways u will place the 5 letters amongst the 8 boxes

fervent pewter
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no it will be more..the letters are unique and u can permute them

inner moth
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oh right, that's wrong sorry, let me try again

weak fossil
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so 8P5?

fervent pewter
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yes correct!

weak fossil
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but we're only talking about placing right and not about arranging are we..?

fervent pewter
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arrangement is important as well

inner moth
weak fossil
fervent pewter
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now try to think the cases in which any row will be empty

weak fossil
fervent pewter
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it will be less and easier to identify

weak fossil
inner moth
weak fossil
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4 ways?

fervent pewter
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tell me those 4

weak fossil
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wait row is horizontal right?

fervent pewter
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yes

late sinew
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Wrong channel lol sry

weak fossil
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wait i get 3

fervent pewter
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ok explain those 3

weak fossil
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  1. first and second row filled, 3rd row empty
    2)second and third row filled, 1st row empty
    3)third and first row filled, 2nd row empty
fervent pewter
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great!

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now for each tell me the no. of ways

weak fossil
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wdym

inner moth
# weak fossil wdym

each row filled will have different order of arrangements(called permutations)

weak fossil
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5! * 3?

fervent pewter
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for each of those cases count no. of ways of placing 5 letters in the 2 filled rows

inner moth
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so he's asking the number of ways you can arrange the letters in the filled rows

fervent pewter
weak fossil
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yeah like if a row has to be left empty then in the provided 2 row we can interchange the given 5 alphabets in 5! ways isn't it?

fervent pewter
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no not in all cases..what about the case of 3rd row being empty? You sure it will be 5!?

weak fossil
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ohh

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is it 5! * 4! in that particular case??

fervent pewter
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no

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think again

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u have 6 boxes and 5 letters..tell me the no. of ways to place those 5 letters in those 6 boxes

weak fossil
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6p5 or 6!

fervent pewter
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good!

weak fossil
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Ohhh got it

fervent pewter
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the remaining 2 cases will be 5! each

weak fossil
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right

fervent pewter
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now subtract these values from the original 8P5..u will have ur answer

weak fossil
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so 8P5-5! * 5! * 6!?

fervent pewter
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woah no!!

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u messed up right at the end!

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why are u multiplying the cases??

weak fossil
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right, are we supposed to add?

fervent pewter
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yes

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the cases needs to be removed from the original 8p5

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those cases and other cases in which none of the rows add up to give 8P5..

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I guess we are done..u can close before leaving

weak fossil
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damn

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i got the answer

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5760

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Thanks a lot

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i have a couple of more doubts but anyway i'll start them in new channels

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really grateful to you cause i actually understood the problem inc the concept

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.close

odd edgeBOT
#
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odd edgeBOT
#
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shrewd trellis
odd edgeBOT
clever fjordBOT
shrewd trellis
#

what did i do wrong?

tacit wasp
#

An x has disappeared

late sinew
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forgot the x

shrewd trellis
#

which line

late sinew
#

figure it out

shrewd trellis
#

oh x on the

sick plaza
#

try keeping the 2/3 outside of the fraction

shrewd trellis
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numerator

sick plaza
#

yes

shrewd trellis
sick plaza
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i think the 2 in the 2/3 was obscuring the x

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as you fill in x = 2

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so you might've mistaken that 2 as the x =

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2

shrewd trellis
#

oh yeah true

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.close

odd edgeBOT
#
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odd edgeBOT
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steady edge
#

How does the step from the top to the below goes?

steady edge
#

I dont get it

graceful viper
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hmm do you know the null factor theorem?

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if xy=0 then x=0 or y=0

steady edge
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No

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I dont get why theres (x+7)(x-1)

sharp oak
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If you multiply out (x+7)(x-1), you get x² + 6x - 7. So, they're the same

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We say that (x+7)(x-1) is the "factored form" of x² + 6x - 7, we call the practice of finding this "factoring"

steady edge
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But what happens to the 2x²... is it the null facotr theorem, so u say tahts 0?

sharp oak
#

If AB = 0, we can choose to look at each of the factors individually. That is, we can look at A = 0, and we can look at B = 0

still depot
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im assuming they deal with that later

sharp oak
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Yes, they will probably look at the 2x² ... later

steady edge
#

Why do they do the step with the(x+7)... ?

still depot
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Basically, both [(x^2) + 6x - 7] = 0, and [2(x^2) - 5x - 3) = 0 are solutions to the equation

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So

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To find the solutions for x^2 + 6x - 7 = 0

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they factor it out

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Getting (x + 7) • (x - 1) = 0. This means the solutions for that one are -7 and +1. But that's just the first part

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Is factoring the part your trying to understand better?

steady edge
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Oh i got it now

still depot
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Then they have to do the 2x^2... = 0 part

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by also factoring

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did that make sense lol

steady edge
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After the (x + 7) • (x - 1) = 0 they did rhe null factor theorem again with x+7=0,
-7=x right?

still depot
#

yes correct and x = 1

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its like 4 inside of one

steady edge
#

Ok thanks veey much

#

.close

odd edgeBOT
#
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steady edge
#

.reopen

odd edgeBOT
#

steady edge
#

@still depot i got an question, is there any trick / rule to make the equation from x²+6x-7 to (x+7)(x-1)

still depot
#

uhm

graceful hatch
#

first into last method ?

still depot
#

There's methods

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and people prefer different factoring methods

steady edge
#

I mean did rhey just make this in their head

graceful hatch
steady edge
#

No lemme check

graceful viper
still depot
#

goated oct

graceful hatch
graceful hatch
still depot
#

There's the diamond method

still depot
restive kayak
#

or else the general formula

graceful viper
#

everyone is going to name a method they learnt in middle school. just watch the video

graceful hatch
#

Sorry. Are there some rules to shut up when others are discussing?

still depot
#

lol

restive kayak
#

x-x

still depot
graceful hatch
still depot
#

its a love or hate drink

#

tbh

steady edge
#

Ok ty i would close now, or u wanna chat?

late sinew
#

Close it

steady edge
#

.close

late sinew
#

Chatting can be done in discussy

odd edgeBOT
#
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graceful hatch
#

@steady edge yk, while they were teaching us these typa equations we had two methods to solve it. Either the first into last method or the quadratic equations method. So, idk whether yk this but, let's see ok:
As in your eqn look at the numbers in the ends. We got 7 and x². Multiply the two. You get 7x². Now, look at the middle number. It's 6. Now, look at the sign after the second number, it's a minus. Now, you gotta think of two numbers whose product is 7 and when you subtract them, you get 6. So, you it's 7 and 1. You gotta put it like it's replaceable yk like:
= x²+6x-7
=x²+(7-1)x-7
=x²+7x-x-7
=x(x+7)-1(x+7)
=(x+7)(x-1)

It only works when the exponents match tho. Like in this question you got x². You just gotta get it. I can further explain in dm. Sorry i am annoying. I just wanted to help.

odd edgeBOT
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shrewd trellis
#

which rule should be used? I believe the quiotient rule should be used

tribal thorn
shrewd trellis
#

but its not

#

function over a function

steep mantle
#

x and x^2+1 are both functions

shrewd trellis
#

this is the same thing right?

tacit wasp
#

Yes

shrewd trellis
#

and 1 is not a function

tacit wasp
#

It is! Why not?

green elm
#

f(x) = 1, there, it's a function

shrewd trellis
#

what about

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3/x^2?

tacit wasp
#

Wdym?

shrewd trellis
#

is that a function?

tacit wasp
#

Of course!!

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Why not??

shrewd trellis
#

my friend said

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"thats just 3x^-2
its not a function over a function"

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"is 3 a function or a constant"

tacit wasp
#

Both

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But why should it be relevant?

shrewd trellis
#

Im trying to pick what rule

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i need to use

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or is "better"

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in any cases

tacit wasp
#

Sometimes there are more than one rule that can be applied

shrewd trellis
#

yep, i know that

tacit wasp
#

But some are of course quicker

solemn zenith
shrewd trellis
tacit wasp
#

The power rule is only when you have... a power

tacit wasp
shrewd trellis
#

ooh

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why?

tacit wasp
#

Because that's not a power, it's not x^something

solemn zenith
shrewd trellis
tacit wasp
#

Sure

solemn zenith
#

yea suree

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but then

tacit wasp
#

And you can use product rule

solemn zenith
#

u.v Would Appear

shrewd trellis
#

but the quiotient rule, there is also u and v

steep mantle
#

i like product+chain cause i cant memorize quotient rhle

tacit wasp
shrewd trellis
solemn zenith
shrewd trellis
#

I understand how to use the product role but are u saying the quotient rule is easier

#

in this case?

solemn zenith
#

i can solve it both ways

tacit wasp
solemn zenith
#

u can solve it however u like

tacit wasp
#

But there's no that big difference

solemn zenith
tacit wasp
#

Best is: try both ways and find the most comfortable for you

shrewd trellis
tacit wasp
#

Or course, yes

#

But that is taken for granted 😅

solemn zenith
shrewd trellis
#

ya i do

solemn zenith
#

but wait a sec

#

i think the question cant be manipulated

#

😔🙏

solemn zenith
#

i think quotient is the way to go

#

but if u cant remember the formula

#

then u can use product rule

#

i actually prefer quotient

#

and it is not that hard to remember

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

carmine idol
#

It's basically which you are more comfortable with

odd edgeBOT
#
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carmine idol
#

All ways to differentiate get the same answer

odd edgeBOT
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outer sun
#

hi please help

odd edgeBOT
#

Please don't occupy multiple help channels.

outer sun
#

.close

odd edgeBOT
#
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shrewd trellis
odd edgeBOT
shrewd trellis
#

is this correct?

modest hare
#

hmm

#

so u used the chain rule

#

so correct

shrewd trellis
#

u sure?

modest hare
#

lemme read it

shrewd trellis
#

oh i need to factorise the square bracket

#

they want me to

modest hare
#

i assume yk how to factor

shrewd trellis
#

ofc

modest hare
#

haha im playing ik you do

shrewd trellis
modest hare
#

ok u factor out the gcf correct

shrewd trellis
#

yep

modest hare
#

u got it correct

#

are there more questions?

shrewd trellis
#

do i needed to put the

#

square brackets?

modest hare
#

nah

#

its multiplying

#

so theres no dsitrubtion

#

so the order dont matter

shrewd trellis
#

i seee

#

let me see if i have more qs

modest hare
#

ight

#

you have the question?

#

@shrewd trellis you there?

shrewd trellis
#

wait

modest hare
#

got it

shrewd trellis
#

7, b

modest hare
#

did u solve it yet

shrewd trellis
#

i solved it but its incorect

modest hare
#

wat were ur solutions

#

or answers

#

cuz theres 3

shrewd trellis
modest hare
#

ok so it looks like u expanded

#

you dont have to

shrewd trellis
#

yh

modest hare
#

since they are multyping each of the factors must be equal to zero

#

so u can set each of them to 0

shrewd trellis
#

ohh ok i knowww the ans

modest hare
#

goood

shrewd trellis
#

(2x-1) is a dooble root right

modest hare
#

yup yup

shrewd trellis
#

but i wonde

#

r

#

why i got the ans incorrect

#

even with expansion

modest hare
#

so looks like u grouped

shrewd trellis
#

yp

modest hare
#

that x

shrewd trellis
#

oh

modest hare
#

so in the end dont expand

#

makes it alot harder

shrewd trellis
#

can i show u my other problems i had before?

modest hare
#

sure

shrewd trellis
modest hare
#

which one did u have problems

solemn zenith
#

he is saying b

modest hare
#

ohhh

#

can u show ur work

solemn zenith
modest hare
#

f'(x)=m

shrewd trellis
modest hare
#

ight

#

we assume you know first principles

shrewd trellis
#

ofc

modest hare
#

got it

#

@solemn zenith can u sub in i have to use the washroom rq

solemn zenith
#

ok

modest hare
#

alr thx im bck

celest osprey
#

(a) F'x = 2pi

solemn zenith
#

he is still solving ig

modest hare
#

so funny

wooden python
celest osprey
#

Na^n-1 when a^n

shrewd trellis
#

oh

#

i got m

wooden python
#

and bad notation on top of that

modest hare
#

F means integral

solemn zenith
safe kiln
brittle plinth
wooden python
#

also you should not drop the brackets in function notation

#

you should never ever EVER write fx for f(x)

celest osprey
#

OK thanks

merry finch
#

Hey never say never, sometimes it’s convenient to write fx

modest hare
#

u also did 1/x?

shrewd trellis
#

im gonna do a

modest hare
#

alr

shrewd trellis
#

yea i did the rest

modest hare
#

a should be easy to shw

wooden python
#

like i get linear algebra where such parenthesis-dropping is appropriate sure

shrewd trellis
wooden python
#

pi^2 - pi^2 is not 1

modest hare
#

1/h would be undefined cuz the left and right but yeah ann is correct

shrewd trellis
#

cuz the left and right?

modest hare
#

from both sides 1/h would be DNE

shrewd trellis
wooden python
#

yes

shrewd trellis
#

i mean

wooden python
#

pure 0, at that

shrewd trellis
#

1*

wooden python
#

no!!!

modest hare
#

x-x=0

wooden python
#

pi^2 - pi^2 is 0.

shrewd trellis
#

i thought thats only when u cancel

#

the numerator would become 0

wooden python
#

when you subtract a number from itself you get 0.

shrewd trellis
#

if there was notihing

wooden python
#

this is basic arithmetic even

celest osprey
modest hare
#

wheres [the f(x+h)-f(x)]/h

#

and its not x

#

its h

#

approaching 0

celest osprey
shrewd trellis
#

for example with this one

wooden python
shrewd trellis
#

the numerator would become 0?

#

or 1

nimble hull
#

it only becomes 1 when you divide (because x/x = 1 for the most part)

#

if you subtract, it becomes 0 (because x-x=0)

modest hare
#

for those it would become 1 but dont forget the domain and range

wooden python
#

you need to distinguish dividing sth by itself (which gives 1) vs subtracting sth from itself (which gives 0)

shrewd trellis
modest hare
#

x cant be -3 or -7

wooden python
#

until you do that, the word "cancel" is on the top shelf for you

solemn zenith
#

apple-apple=nothing(0)

dawn scarab
shrewd trellis
#

One last question, im sure this one will be tricky

celest osprey
#

Tricky or treaty?

shrewd trellis
#
  1. D
celest osprey
#

These are implicit functions

modest hare
#

u would set it to -2?

toxic rose
#

!status

modest hare
#

the derivative

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
copper quarry
#

how many helpers do you have cuh

shrewd trellis
#

I just coudnt solve the last question

toxic rose
#

because honestly if ur done with a,b,c i think u can do d

shrewd trellis
#

I have solved for the first 3 but i may have lost the answers

celest osprey
#

First differentiate 3x³ then 3x² then x then 1 separately

toxic rose
shrewd trellis
#

this was questions from a while ago

toxic rose
toxic rose
celest osprey
#

K

modest hare
#

ok uu

#

for the last one

#

i assume u found the derivative

shrewd trellis
#

yep

urban jackal
toxic rose
#

okay yeah i give up do wtever tf u want

modest hare
#

i was helping uu a while ago can i continue

urban jackal
shrewd trellis
#

just need 1 person

modest hare
#

ok uu we check the slope of the linear right

urban jackal
#

u didnt understand?

urban jackal
shrewd trellis
modest hare
#

we find if any point is tangent to it

urban jackal
#

@shrewd trellis did u get what i said

modest hare
#

rewriting y=1-2x as y=-2x+1 seems easier

urban jackal
#

what diff does it make

shrewd trellis
modest hare
#

so we set the derivatives equal

celest osprey
#

,rotate

clever fjordBOT
modest hare
#

he knows how to differentiate

solemn zenith
#

i am not sure how u got x

modest hare
#

so we check if any point of f'(x) has a slope of -2

solemn zenith
#

u forgetting smth?

modest hare
#

thats the whole question

#

uu u there?

shrewd trellis
#

iye

#

yes

#

im here

celest osprey
#

Sorry, 3x² 🙏

urban jackal
#

for lines to be parallel there slopes have to be equal and the last lines slope is -2 so u have to differenetiate the first line and equate it to -2 then u will come to understand there is no solution of x which satisfies the equation

modest hare
#

i aint reading allat (joke)

solemn zenith
#

how did dx/dx = x?

celest osprey
#

So it's 9x² + 9x + x

#

Answer.

shrewd trellis
solemn zenith
modest hare
#

sure

#

dexa is ok though

solemn zenith
celest osprey
#

9x²-9x+x

#

OK do we use chain rule here?

urban jackal
copper quarry
#

lowkey u trolling

celest osprey
#

I am calling it quits for this morn

#

I suck at maths it seems

urban jackal
urban jackal
#

then its discriminant is lessthan 0

#

so it is imaginary

solemn zenith
urban jackal
#

yeah

#

show that it doesnt have a root

#

i mean no point

#

so which obviously means no value of x

solemn zenith
urban jackal
solemn zenith
#

yess

urban jackal
#

so question is solved ig?

solemn zenith
#

we just need derivative for (a)

#

which is already solved?

urban jackal
#

he was asking about the last subquestion

solemn zenith
#

my badddd

#

yes ur correct

#

no real ans

urban jackal
#

its fine

#

@shrewd trellis

shrewd trellis
#

@urban jackal gimme a sec

urban jackal
#

kk

odd edgeBOT
#

@shrewd trellis Has your question been resolved?

modest hare
#

hes almost there

odd edgeBOT
#
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odd edgeBOT
#
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mystic saffron
#

Can someone help me understand what this identity is? How does this make any sense at all?

wooden python
#

do you need help deciphering the notation or do you need it explained why this thing is true

rich wasp
#

here

#

it's a concise way to use sigma notation

#

sum alpha beta means alpha*beta + beta*gamma + gamma*alpha

#

if you want a proof of the identity, recall (a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

#

now use the above stated sigma notation to get the desired form

stable sequoia
#

symmetric sum notation 🤔

brittle plinth
#

!occupied

odd edgeBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

shrewd trellis
#

oops

odd edgeBOT
#

@mystic saffron Has your question been resolved?

odd edgeBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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vagrant orbit
#

can someone help me with this

odd edgeBOT
dense star
#

isn't there a physics server

vagrant orbit
#

none

brittle plinth
odd edgeBOT
#

@vagrant orbit Has your question been resolved?

desert jolt
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
odd edgeBOT
#

@vagrant orbit Has your question been resolved?

dense star
#

you should probably ask here

odd edgeBOT
#

@vagrant orbit Has your question been resolved?

odd edgeBOT
#

@vagrant orbit Has your question been resolved?

modern palm
#

can someone help me solve this polynomial division?

outer jolt
odd edgeBOT
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#
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coarse ocean
#

can someone explain why 0

odd edgeBOT
oak crown
#

Calculate it

narrow crypt
#

determinant like that kinds find a volume, no?

dapper canyon
#

c1 + c2 - (a+b+c)*c3 = 0

#

so the columns are linearly dependent

#

hence det 0

dapper canyon
#

which is the same as signed volume of rows

#

more precisely, the volume of the parallelipiped formed by the column/row vectors

#

with sign accounting for orientation

coarse ocean
#

thank you

solar peak
odd edgeBOT
#
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odd edgeBOT
#
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manic grail
#

can someone explain this formula

odd edgeBOT
manic grail
#

or show how we get it

#

i am famuliar of how to get it when the differential isnt a vector but idk here

#

the only difference is that the r'(t) isnt a norm

green elm
#

wdym by "how we get it", it's a definition

#

are you asking how to calculate it?

odd edgeBOT
#

@manic grail Has your question been resolved?

manic grail
#

its not definition its parametrization

desert jolt
desert jolt
wanton bison
manic grail
#

and then what

manic grail
narrow crypt
# manic grail or show how we get it

Since we are doing a line integral along ${C}$ parameterised by ${\vec{r}}$, we can see that ${\vec{F}}$ along the line is ${\vec{F(\vec{r}}}$.
Also, by chain rule,
[ d\vec{r} = \frac{d\vec{r}}{dt} dt]
So, combining these two
[ \int_{t=a}^{t=b} \vec{F}(\vec{r}) \cdot \vec{r'}(t) dt]

manic grail
#

but not sure about it now

clever fjordBOT
manic grail
#

then why is it a norm when its not a vector

narrow crypt
#

or u can divide the line integral into small panels as usual

manic grail
#

when dr isnt a vector

green elm
narrow crypt
#

wdym

#

dr is a vector

manic grail
#

as i said

#

when we dont have a vector

#

but dS

wanton bison
#

There are two versions, one for vector fields and one for scalar fields

manic grail
#

ds = sqrt ...

#

and dt goes in the sqrt to give f(r(t)) norm r'(t) dt

quasi sparrow
green elm
#

that's calculating something different

quasi sparrow
manic grail
#

in that case its norm

#

but why dont we do the same here

#

where we got dr and r is a vector

#

its still a small vector dr in the curve we are integrating

green elm
#

that's the analogue to "area under a function", whereas the one with the dot product is capturing the notion of "net work done by a force on a particle that travels along the path r(t)"

manic grail
#

what

#

no

manic sleet
#

that dS and the norm came from when f(x) was scalar

manic grail
#

i meant when we have f(x,y) dS over a curve

manic sleet
#

here it is a vector function

manic grail
#

we use Pythagorean theorem

#

to replace dS with root dx^2 + dy^2

green elm
#

and?

manic sleet
green elm
#

that's not what you are computing here, it has nothing to do with that

manic sleet
#

here f:R3->R3

manic grail
# green elm and?

why dont we replace dr with dx vector squared and dy vector squared here too

green elm
#

because the goal is to calculate what i said above

manic grail
manic sleet
manic sleet
#

in the img you asked about

manic grail
#

here in the vector field

manic sleet
#

the function is f:R3->R3

manic grail
#

f is outputing 3 value

#

i see

#

and why wouldnt the pythagorean theorem work here

#

to make it dx^2 vector etc

#

and put dt inside

green elm
#

you could do that but it would just be computing the "scalar" integral of the three components of f

#

which is not the same thing

manic grail
#

how though

manic sleet
#

this integrals means computing the "work" done by the vector field over the curve C

manic grail
#

if i used purely correct mathematical equalities the last part should be the same as first

#

where is the mistake

#

which part isnt correct

manic grail
#

where am i making a mistake

green elm
#

for one thing, if you compute the integral of f times dS and f is a vector, then the result is a vector, not a scalar

#

whereas the integral of f . dr is a scalar

manic grail
#

no no wait

#

thats not what i said

#

i said if we have the integral of vector function F dot dr

#

why dont we sub in sqrt dx^2 +dy^2 + dz^2

#

as in vectors dx dy dz

green elm
#

dr is a vector

manic grail
#

yes

green elm
#

dx^2 +dy^2 + dz^2 is a scalar

manic grail
#

we use dx and dy and dz vectors

green elm
#

how would you "substitute" that?

manic grail
#

dx with x being a vector

manic sleet
#

dx, dy, and dz are not inehrently vectors

wanton bison
manic sleet
#

they're scalars representing how "fast" the function is moving is one direction, dr=<dx,dy,dz>

#

which is why dr is a vector and dx, dy, and dz are not

manic grail
green elm
#

dr is the vector whose components are dx, dy, dz

#

it's not a sum

manic grail
#

or that wouldnt help into calculating the integral

manic sleet
#

you mean dr=<dx,0,0>+<0,dy,0>+<0,0,dz>?

manic grail
#

yes

#

or thats making it harder to calculate

manic sleet
#

well wouldn't that just be <dx,dy,dz> pandathink

manic grail
manic grail
#

yea i see there is no point in doing it

green elm
#

even if you do that, the length of dr isn't gonna be involved

#

you are still computing a dot product

manic grail
#

yes and now i have (dx + dy + dz) vectors

#

its more complicated like this yea nvm

#

ok so we just multiply by dt/dt

#

and use one dt as derivative of vector r

odd edgeBOT
#
Channel closed

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manic grail
#

.reopen

odd edgeBOT
#

manic grail
#

but how do we show that dr = dr/dt dt

#

isnt dt a symbolization rather than a number/variable

tidal matrix
# manic grail to replace dS with root dx^2 + dy^2

wanted to also point out: if we used this same strategy on a vector field F, then we would have (some scalar) * vector (field), which would only stretch the vectors. we want the area of the rectangles instead, hence F(r) · r'(t)

manic grail
tidal matrix
#

i mean, it would change something, just not in a helpful way

heavy brook
#

impressive

manic grail
#

Can someone explain how dr = dr/dt dt

green elm
manic grail
#

since dt is a symbolization how would this be proven

heavy brook
#

i wish i was smart enough to do this shit

tidal matrix
manic grail
narrow crypt
#

Let ${\vec{r} = g(t)\hat{i} + k(t)\hat{j} + h(t)\hat{k}}$.
[ d\vec{r} = \frac{d}{dt}\left( g(t)\hat{i} + k(t)\hat{j} + h(t)\hat{k} \right) \cdot dt]
By differential, i think?

clever fjordBOT
manic grail
manic grail
#

we can we devide by dt and multiply by it

manic grail
#

i was taught not to treat dt as a multiple or do math with it

narrow crypt
#

dt represents an infisimal cahnge

manic grail
#

yes we cant just move it around always

oak crown
narrow crypt
oak crown
#

You know how u-subsitution works?

manic grail
#

yes

oak crown
#

Ok

narrow crypt
manic grail
oak crown
#

Let's take $\int_a^bf(x^2)2xdx$, for example

clever fjordBOT
manic grail
#

yes there we take dt from denominator

#

and move it to other side

oak crown
manic grail
#

yes there we do do that

#

but is it true always

oak crown
#

Yes

manic grail
#

like dx/dt = 3 means always dx = 3dt

narrow crypt
#

ye

manic grail
#

ok

narrow crypt
#

differential

oak crown
#

This is basically the entire concept of differentials

narrow crypt
#

[ \dd f = f'(x) \dd x]

clever fjordBOT
oak crown
#

d(variable) is approaching zero

manic grail
#

yes i recently started using that notation

oak crown
#

It is not necessarily zero

narrow crypt
#

its from single val calc

manic grail
#

but i was always using '

#

and not d / dt

tidal matrix
#

another "proof:" Pick a variable that isn't involved, like $x$. Then by the Leibiniz Chain Rule, $$\dv{\vec{r}}{x} = \dv{\vec{r}}{t} \cdot \dv{t}{x}.$$ Integrate both sides $\dd x$ to get $$\int \dv{\vec{r}}{x} \dd x = \int \dv{\vec{r}}{t} \cdot \dv{t}{x} = \dv{\vec{r}}{t} \int \dv{t}{x} \dd x,$$ treating $\dv{\vec{r}}{t}$ as a constant relative to $x.$ Then apply FTC on both sides to get $$\dd \vec{r} = \dv{\vec{r}}{t} \cdot \dd t. \quad \blacksquare$$

oak crown
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This is a more rigorous proof, I would say

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skul how is there still a compile error

tidal matrix
#

latex hates me specifically i guess

manic sleet
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I think its not recognizing the vv command

tidal matrix
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oh you're right 😩

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i thought vv was native?

manic sleet
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I usually do \vec or \mathbf for vectors

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but idk what vv does

oak crown
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YAY

tidal matrix
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WOO

oak crown
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the comma looks ugly, pls fix

manic grail
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uhm

tidal matrix
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anyways i hope that helps with the rigourous part

oak crown
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We had a bit of a TeX session there

clever fjordBOT
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haseeb

manic grail
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chain rule has proof?

narrow crypt
oak crown
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Yeah

narrow crypt
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using approximation of a function

manic grail
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yea that basically what im asking

oak crown
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What type are you looking for

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skul

manic grail
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wdym type

oak crown
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There's one from first princples

tidal matrix
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my calc 1 prof wrote one using the epsilon delta definition it was like 5 pages long

manic grail
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a correct proof

manic grail
narrow crypt
oak crown
manic grail
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sorry idk the english names

narrow crypt
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i left that shit since limit

clever fjordBOT
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PajamaMamaLlama

oak crown
clever fjordBOT
oak crown
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God how the FUCK do you have that just at the ready

manic sleet
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this is one I wrong from a while ago, ignore hte epsilon stuff idk wtf I was doing there 😭

tidal matrix
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aww how come his compiles perfectly

manic sleet
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wanted to prove everything from calc

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from the ground up

manic grail
narrow crypt
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blud's doing real analysis

manic sleet
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my proof of the exponential rule is crazy lmao

south plume
manic grail
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yes but to split the limits

narrow crypt
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f(x) approximation 🥀

manic grail
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we need to know k(x) is differentiable

lyric dust
manic grail
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to know the limit exists

tidal matrix
oak crown
manic grail
#

ok

tidal matrix
manic grail
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alr uhm 1 more thing

lyric dust
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u can

manic grail
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what is bro doign here

narrow crypt
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representing dr

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again

manic grail
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how he get that

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why is dr = T ds

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i dont see it

narrow crypt
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dr/ds = T

manic sleet
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remember how ds=||r'(t)||dt

oak crown
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bahaha

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discord fail

narrow crypt
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but u get the idea

manic grail
narrow crypt
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from the tnb frame fuckass unit

oak crown
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I pray you know what ds is

manic grail
manic grail
narrow crypt
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unit tangent => unit change vector per arc length

manic grail
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i need to translate this 1 sec

manic sleet
manic grail
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what is unit tangent

manic sleet
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damn I failed LaTeX pandaohno

manic grail
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translation doesnt make sense

narrow crypt
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unit tangent vector

clever fjordBOT
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PajamaMamaLlama

manic grail
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show or explain

narrow crypt
manic sleet
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when we have a tangent vector it can be any length (and still have the same direction)

manic grail
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i prob know but idk it in english 💔

manic sleet
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we like it to have a length of 1