To find the decimal value of a percentage you divide by 100
#help-19
lost crane
lost crane
yes
lost crane
yes
lost crane
yes
pale trench
and then i round that right
lost crane
Yes money is usually rounded to the nearest cent (2dp)
pale trench
so uhhhh
13,680.19?
and it says "Assuming Lorna finances the remaining cost at an annual interest rate of 7.15% for 10 years, find the monthly payment."
odd edgeBOT
@pale trench Has your question been resolved?
languid ravine
and it says "Assuming Lorna finances the remaining cost at an annual interest ra...
so what is 7.15% of 64835?
pale trench
is it 4,638.53
hm, the answer (it gave me the answer after too many tries) says 576.42
languid ravine
don't use chatgpt, you just found 20% of 64835 in the second question
chatgpt can't do math
languid ravine
oh i read the question wrong i'm sorry
pale trench
it's okay!
pale trench
do i just subtract that
languid ravine
yes
pale trench
51,154.81 x 0.715?
languid ravine
0.0715
pale trench
3657.57?
languid ravine
yes
pale trench
how did the answer key get 576.42
languid ravine
i don't know, from what i can see 576.42 was your answer which is wrong
pale trench
that's so strange, the thing said that was the answer
wait let me retry, it might be buggy
HUH
i have 2 tries to get the answer right, and i put in the wrong answer one time, so the website gave me an answer which was 576.42 so i pressed enter and that was ALSO wrong, then Player helped me work out the problem and we got 3,657.57, which it says is ALSO wrong so i'm very confused
odd edgeBOT
Available help channel!
hearty kelp
am i right with A here?
vale vortex
wait <@788085606483361802> does that mean yes 😭
why not
just use a calculator
and keep doubling it
till u get
that number
and count how many times u doubled it?
brittle beacon
sorry to ping
My bio specifically says to ping 
and yep I agree with you 
hearty kelp
and count how many times u doubled it?
you're right yeah i did that
hearty kelp
My bio specifically says to ping <:catGiggle:668948717772079128> and yep I agree...
thank you so mch i didnt see that lol
vale vortex
ah gotcha
hearty kelp
.close
steep mantle
i mean you can see the bounds are the intersections
vale vortex
so
orchid garden
^ $$x^2-2x = -x^2+4x$$ is pretty simple to solve
clever fjordBOT
Bean Man
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
vale vortex
u set them equal to eachother
orchid garden
I have no idea why that didn't compile
steep mantle
$$x^2-2x = -x^2+4x$$ is pretty simple to solve
clever fjordBOT
Skissue ping4response
vale vortex
well 0 is given
but
its how u find the top bound
than u do some weird calc 2 formula shit
and integreate outer minus inner
squared maybe?
i forget the exact formula
orchid garden
It isn't volume
vale vortex
oh
u just integregrate
the outer bound
no
that makes no sense
thats def right
u have to subtract them
f(x) - g(x)
proven cape
$\int_{x_1}^{x_2} \int_{y_1(x)}^{y_2(x)}} dydx$
vale vortex
but its (-x^2 +4x) - (x^2 -2x)
lethal wharf
Hi
vale vortex
u gotta be careful with the negatives
clever fjordBOT
Wobble
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)
lethal wharf
vale vortex
actually im wrong
lethal wharf
Bros are cooking
proven cape
**Wobble**
Compile Error! Click the <:errors:504266556054962196> reaction for mo...
Where y_2 is the black function and y_1 the red one, and x 1 and x2 are the points x where they intersect
vale vortex
if ur stuck im confident i know how to find the bounds now
if thats what ur confused about
so
u have
-x^2 + 4x = x^2 - 2x
put it all on one side and tell me what u get
yes
also
just to be clear
i was exactly right
about the outer - inner
idk what that volume dude is talkin about
no
bruh'
like
add x^2
to both sides
till one side is 0
orchid garden
idk what that volume dude is talkin about
It has nothing to do with squaring it, you were thinking of volumes of revolution
vale vortex
and all terms are on one side
vale vortex
It has nothing to do with squaring it, you were thinking of volumes of revolutio...
oh u didnt respond to the squaring part
u left ur message open to interpretation
combine like terms
steep mantle
dint you just take the bounded integral of the 2 equations subtracted
vale vortex
ngl i have no idea what that means
if u mean outer minus inner thats what I said
correct
now factor
those are the bounds
u got it from there?
or u need more help
proven cape
**Wobble**
Compile Error! Click the <:errors:504266556054962196> reaction for mo...
Its this
vale vortex
or am i stupid
they need to be in ()
and there is a minus sign
in the middle
u need to be very careful with negatives
clever fjordBOT
Skissue ping4response
vale vortex
thats right
try integrating
and show me what u get
its really straight forward
dont plug the bounds in
show me the anti derivitive
u got
i cant help you than
if you dont send a ss of ur work
u can literally type out
what the anti derivitive is
if u want
u dont gotta take a pic
just show me what u got
and ill tell u where u went wrong if u did
you need
to integrate
do you know how
this is
a calc 2 problem
you learn integration in calc 1
if u dont know how to integrate u cant solve it
and theres too much too teach
u should just go watch a video or smth
on the different rules of integration
do you know how to take a derivitive?
whats the power rule
ok
good
so
the power rule for integration is
you add 1
to the exponent
and than divide by it (it being the exponent)
knowing that informaton you should be able to solve this problem
ill give u an example
the -x^2 would turn into -x^3 over 3
gl
.close
odd edgeBOT
odd edgeBOT
Available help channel!
mystic shard
given 0 ≤ θ ≤ 2π, solve 2sinθ-√2=0
How do i solve this problem?
pastel orbit
get it into the form sin(theta) = number, and then use the unit circle 
mystic shard
sin(θ)= √2/2
what do i do with the unit circle?
dapper canyon
sin(θ)= √2/2
what do i do with the unit circle?
what's sin0
dapper canyon
do you anything about sin and cos?
mystic shard
yeah
its the soh cah toa thing
to calculate the sides of a triangle
ohhh i think i get it now
sin(θ)= √2/2
=π/4
and that would be one solution
then π-(π/4) = 3/4π
and that would be the second solution
so θ = π/4, 3/4π
am i correct?
<@&286206848099549185> can you please check my work?
hardy mica
it seems right to me
just plug it back into the equation and check if it gives the correct answer
mystic shard
oh yeah it does
so what about something like this:
sin2θ=√3/2
where the 2 is inside of sin
hardy mica
consider the range for 2θ
mystic shard
oh so y=√3/2
meaning 0 ≤ 2θ ≤ 4π
then what?
oh then you go back to the chart
so it would be
2θ = π/3, 2/3π
right?
mystic shard
oh i forgot to clarify... the problem was
given 0 ≤ θ ≤ 2π, solve sin2θ=√3/2
you can't do anything to that 0 right?
hardy mica
yeah, we need to look at solutions for 2θ between 2π and 4π just as much as looking at solutions between 0 and 2π
mystic shard
yeah, if we are looking between 2π and 4π, and 0 and 2π, wouldn't the minimum be 0 and max be 4π?
making the inequality 0 ≤ 2θ ≤ 4π
hardy mica
how many solutions will there be between 0 and 4π?
mystic shard
i don't
hardy mica
just copied from google:
mystic shard
just made this from desmos
hardy mica
isn't that only to 3π tho
it continues infinitely in the same way
hardy mica
how long is a period of sinx
mystic shard
you said infinite?
hardy mica
(after how much x does sinx repeat itself)
mystic shard
oh after π
hardy mica
no
mystic shard
2π final answer
hardy mica
just list out the possible values of 2θ then solve for θ
mystic shard
what i am so confused
we don't know theta
how would we list for 2θ
if we don't know what it is
hardy mica
no, we try to solve for 2θ first then move on to find θ from that
hardy mica
ok we solve for 2θ and got π/3 and 2/3π
what are the other roots for 2θ?
mystic shard
idk
isn't that what we are trying to solve?
we r trying to find all 4 sollutions
so far we have 2
how would we find the other 2?
hardy mica
so it would be θ= π/6 and π/3
does the graph help?
mystic shard
nope 😀
hardy mica
like, how much is the part of the graph shifted to the right to have it be exactly the same as itself?
mystic shard
does the graph help?
wait wait where would these be on the graph?
mystic shard
like, how much is the part of the graph shifted to the right to have it be exact...
2pi
hardy mica
2pi
yup, a point of the graph will have the same y value after shifting to the right by 2π
mystic shard
it takes 2pi for the graph to repeat itself
mystic shard
yup, a point of the graph will have the same y value after shifting to the right...
ohhh yeah yeah
so 9/3pi - pi/3?
hardy mica
so what are the 2 other values for 2θ
mystic shard
so what are the 2 other values for 2θ
OHHH WIAT 7/3PI AND 8/3PI
THEN
theta = pi/6, pi/3, 7/6pi, 4/3pi
BOOOM
correct?
hardy mica
THEN
theta = pi/6, pi/3, 7/6pi, 4/3pi
yup
odd edgeBOT
odd edgeBOT
Available help channel!
signal perch
how do i figure this out?
odd edgeBOT
how do i figure this out?
charred spindle
Do you have notes about consumer surplus? Is it just S - D?
odd edgeBOT
@signal perch Has your question been resolved?
signal perch
Do you have notes about consumer surplus? Is it just S - D?
honestly not sure, I'm its due in 2 hours and I dont have time to finish the videos 😭
odd edgeBOT
@signal perch Has your question been resolved?
dim dew
odd edgeBOT
dim dew
for a)
When we count levels, we start with 0 not 1 correct?
So level of g would be level 2?
a = level 0
b,c,d = level 1
e,f,g,h,i,j = level 2
so g = level 2
hazy temple
right
dim dew
what about vertex k?
hazy temple
what about vertex k?
a = 0, c = 1, g = 2, k = 3
olive ledge
Edges
dim dew
okok
so height = longest level
or longest path
from root to any vertex
c) internal verticies = parents so they have children.
so we include a?
a,b,c,d,g,j Since they all reproduce?
olive ledge
Vertices are the nodes itself, edges are the lines that connect the nodes.
dim dew
Vertices are the nodes itself, edges are the lines that connect the nodes.
okok that makes sense
for d) leaves are all the children.
so they can't have any kids.
e,f,k,h,i,l,m
olive ledge
c) internal verticies = parents so they have children.
so we include a?
a,b,c,d,...
This is correct
dim dew
nicee
dim dew
e) parent of h
its d?
olive ledge
Right
dim dew
f) child of c = g
what if the question asked me child of e.
Would it be DNE? or 0? or nothing?
olive ledge
DNE
olive ledge
Yeah sure
dim dew
so 26 edges
20 internal verticies that means they are parents. IF i wanna find out leaves. its the children
but whats 5-ary? or 8-ary what is that
olive ledge
Every internal node will have exactly 5 children and similiary for 8-ary
dim dew
ohh ok
so m-ary the m only applies to internal node (excluding root)
so for 20 internal verticies.
Each will have. 5 children.
so 5*20 = 100 children.
but what about the root, that also has verticies
100+1 = 101??
wait no root is included in interrnal verticies
dim dew
hm
dim dew
okok
olive ledge
$L = I(N-1) + 1$
clever fjordBOT
ColdTe²
olive ledge
I is the number of internal nodes, N the number of children each node can have
L is the leaf nodes
olive ledge
Yes
olive ledge
81
dim dew
81?
olive ledge
Right
dim dew
okay so thats a formula I need to remember
L = I(M-1) +1
E = V -1
- E = V - 1
so E = 100-1
E = 99
olive ledge
10000
dim dew
oh wait yee
E = 10,000 -1
9,999
- I = 100
m = 5
V = ?
V = I + L
L = 100(5-1) + 1
L = 400 + 1
L = 401
V = 401 + 100 = 501?
olive ledge
Right
dim dew
or i was thinking
another. formula would be
V = I*m + 1
so V = 100*5 + 1
V = 500 + 1 = 501
for 18
i mean 19
hmm
olive ledge
another. formula would be
V = I*m + 1
These both are correct
dim dew
I = 1000
E = ?
Full binary so each vertex has 2 kids?
so 1000^2?
wait no
full binary = m-ary m = 2
2-ary?
so L = 1000(2-1) +1
L = 1001
V = L + I
so V = 1001 + 1000 = 2001
E = V - 1
so E = 2001 -1 = 2000
dim dew
I was thinking another way to do it would be
V = I * M +1
So V = 1000(2) + 1
SO V = 2001
E = 2001-1 = 2000
olive ledge
That's prolly the easier way
dim dew
I like the formula you gave, L = I(m-1) + 1
I can use it to double check work
thats the one that starts with 1
so 1
1.1, 1.2, 1.3
1.1.1, 1.1.2, 1.1.3 (under vertex 1.1)
1.2.1, 1.22. (under vertex 1.2)
1.3.1 (under vertex 1.3)
1.1.3.1 (under vertex 1.1.3)
or do we start from 0?
wait it would be 0 (root vertex)
1, 2, 3 (child of 0 or root vertex)
1.1, 1.2, 1.3 (child of vertex 1)
1.3.1 (child of vertex 1.3)
2.1, 2.2 (child of vertex 2)
3.1 (child of vertex 3)
olive ledge
The root should be numbered 0 other than that children are labelled 1,2,..N from left to right
dim dew
rightt
dim dew
wait it would be 0 (root vertex)
1, 2, 3 (child of 0 or root vertex)
1.1, 1.2, 1...
correction here
olive ledge
Right
dim dew
okok
there are three orders
Pre-Order, In-order, Post-order
Inorder = Left -> Root -> Right
olive ledge
What did you get as the postorder
dim dew
im still working through it
trying to look through examples
so for post order its Left right root. SO root comes very end.
So would it be e, f,k,g,b,h,i,c,j,d,a?
so parents come last?
olive ledge
That's right
Traverse through each sub-tree with that order
And that's basically it
dim dew
but thats basicallhy traversing it right?
that would be the answer e, f,k,g,b,h,i,c,j,d,a?
olive ledge
that would be the answer e, f,k,g,b,h,i,c,j,d,a?
Yes
dim dew
so what if we did this
but inorder, pre-order
so inorder = Left root right
e,b,f,k,g,a,h,c,i,j,d
Preorder = Root -> Left -> Right
a,b,e,f,g,k,c,h,i,d,j
Prorder = parents come first
odd edgeBOT
@dim dew Has your question been resolved?
olive ledge
@dim dew it's correct
dim gale
true
mighty locust
how do i do this
odd edgeBOT
how do i do this
olive ledge
If you sub u = x^2 + 4 then du = 2xdx not dx
mighty locust
i was trying to get dx alone so i can repalce it in the equation
so the du=2xdx turned into du/2x=dx
mighty locust
If you sub u = x^2 + 4 then du = 2xdx not dx
.
mighty locust
so i dont get it
olive ledge
$\f32 \int \frac{du}{u}$
clever fjordBOT
ColdTe²
olive ledge
$\f32 \ln(u) + C$
clever fjordBOT
ColdTe²
mighty locust
oh thats it
olive ledge
Pretty much just sub for u again
mighty locust
so i dont need to use the arc tan formula
olive ledge
Right
mighty locust
so will there be a situation where i wil have to use that formula instead of this
or will this always work
olive ledge
If in this case it was just dx instead then that would have been absolutely fine
odd edgeBOT
odd edgeBOT
Available help channel!
distant umbra
if i were to parametrise a plane
odd edgeBOT
if i were to parametrise a plane
desert tinsel
0,0,0--->1,3,7
Pretty sure you’d need three points, no?
distant umbra
Pretty sure you’d need three points, no?
i am trying to compute a line integral and they say you are moving from point A to B
forest sky
a plane requires two parameters. do you mean a line segment?
distant umbra
yeaa sorry
odd edgeBOT
odd edgeBOT
Available help channel!
distant umbra
here why are they multiplying with the magnitude?
odd edgeBOT
here why are they multiplying with the magnitude?
distant umbra
or is it that to convert DA to DS?
forest sky
that's the jacobian which converts from dS to dA, yes
odd edgeBOT
odd edgeBOT
Available help channel!
quasi roost
hey guys i did my exam and i skipped this question bc i dont know how to do it, help please 🥺❤️
question 7 on the page
inner horizon
hey guys i did my exam and i skipped this question bc i dont know how to do it, ...
can u get a clearer pic? i can't rlly c...
inner horizon
can u get a clearer pic? i can't rlly c...
nvm
@quasi roost
where r u
i can help u
...
bro posted the question and disappeared
odd edgeBOT
@quasi roost Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
true lodge
hi
true lodge
I had a question about paramterization
quartz trellis
send
true lodge
so something like lets say x^2 + z^2 = 4
thats a cylinder
If i wanted to paramterize
I know since there are no ys, its basically infinity on the y
so how would i paramterize it
im thinking <rcostheta, y, rsintheta>
so its going across y axis
so y = y
x = rcostheta
z=rsintheta
r(u,v) = r(r,theta)
odd edgeBOT
@true lodge Has your question been resolved?
lament stream
help
true lodge
huh
frozen stream
im thinking <rcostheta, y, rsintheta>
r is constant
lament stream
how to solve indefinite integrals
next loom
how to solve indefinite integrals
Using hands?
true lodge
huh
true lodge
r is constant
it is
Can someone tell me the steps needed to solve these?
Im thinking
- draw a rough sketch
- paramterize it (find its intervals)
- Plug in parametization to F
Then get r'(paramterization)
Idk
quartz trellis
wraith pelican
I need some help solving this integral. I already simplified a little using the given assumption, but I struggle on how to proceed with the two smaller integrals.
Any ideas?
wraith pelican
<@&286206848099549185>
odd edgeBOT
@wraith pelican Has your question been resolved?
odd edgeBOT
@wraith pelican Has your question been resolved?
strange glacier
is that capital A
odd edgeBOT
@wraith pelican Has your question been resolved?
frigid scroll
how would you calculate this limit knowing you have 0*infinite indetermination (idk if its a good word).
frigid scroll
i know that i have to use the criterion of the pincers
but i do not know how to apply it to an exercise
tepid pelican
how would you calculate this limit knowing you have 0*infinite indetermination (...
hmm
I'd try to squeeze it between 2 simpler sequences
the denominators are really ugly
it would be good to make them all of the same denominator
frigid scroll
I'd try to squeeze it between 2 simpler sequences
if i do that wont i have 2 more sequences that are zero*inifinite ?
tepid pelican
if i do that wont i have 2 more sequences that are zero*inifinite ?
yes
but maybe you will be able to find their limits more easily
tepid pelican
how would you calculate this limit knowing you have 0*infinite indetermination (...
What stops you from working with this a_n is the fact that they all have different denominator
so you cant nicely add those fractions up
tepid pelican
i could just use n^2+n
Yes, that's one of the series
tepid pelican
as it wont change anything
How do you know
frigid scroll
well
limit of n^2+k/n^2+n ,when n goes to infinite is still 1 no matter how big is k
tepid pelican
well, thats true, but it doesnt guarantee much
in this case it works out but not in general
tepid pelican
to do it more formally, notice that
$\frac{k}{n^{2}+n}\le\frac{k}{n^{2}+k}\le \frac{k}{n^{2}}$
then you can analyze both the bounding sequences
clever fjordBOT
MæthIsAlwaysRight
tepid pelican
anyway, try simplifying it with denominator n^2 + n now
what does a_n become? And what will the limit be?
frigid scroll
anyway, try simplifying it with denominator n^2 + n now
all the numbers in the sequence?
oh no
nvm
tepid pelican
all the numbers in the sequence?
Yes
frigid scroll
anyway, try simplifying it with denominator n^2 + n now
it would still be zero*infinite
tepid pelican
Define a new sequence $b_{n}=\frac{1}{n^{2}+n}+\frac{2}{n^{2}+n}+ \dots +\frac{n}{n^{2}+n}$ and analyze it
clever fjordBOT
MæthIsAlwaysRight
tepid pelican
it would still be zero*infinite
Correct
try simplifying that sum though
you can add up the fractions now
frigid scroll
i will write it now
tepid pelican
once you simplify it, you will be able to find the limit
tepid pelican
n(n+1)/2/n^2+n
Perfect
tepid pelican
$b_{n}=\frac{1}{n^{2}+n}+\frac{2}{n^{2}+n}+...+\frac{n}{n^{2}+n}=\frac{\frac{n\left(n+1\right)}{2}}{n^{2}+n}$
clever fjordBOT
MæthIsAlwaysRight
tepid pelican
1/2
Yep
now you could do the same thing for $c_{n}=\frac{1}{n^{2}}+\frac{2}{n^{2}}+...+\frac{n}{n^{2}}$
clever fjordBOT
MæthIsAlwaysRight
tepid pelican
and again find that the limit is 1/2
frigid scroll
n^2+n/2/n^2*
tepid pelican
and since
bn <= an <= cn, limit of an must be 1/2 as well
frigid scroll
wait but how is the limit of c_n 1/2
tepid pelican
$\frac{\frac{n\left(n+1\right)}{2}}{n^{2}}$
frigid scroll
n^2/2/n^2 + n/2/n^2
clever fjordBOT
MæthIsAlwaysRight
frigid scroll
still i dont see it
tepid pelican
$\frac{\frac{n\left(n+1\right)}{2}}{n^{2}}=\frac{\frac{n^{2}}{2}+\frac{n}{2}}{n^{2}}=\frac{1}{2}+\frac{1}{2n}$
clever fjordBOT
MæthIsAlwaysRight
tepid pelican
its just algebra
tepid pelican
in general, whenever you have polynomial / polynomial with same degrees, the limit is gonna be just the ratio of leading terms
fair olive
Help
ionic spoke
that one
fair olive
Yes
hexed patrol
fair olive
It is closed thanx bro i was looking everywhere for that channel
viscid flint
his bounds are wrong
fair olive
his bounds are wrong
You right
viscid flint
y varies from 0 to 2, not 0 to 4
fair olive
yes i know
viscid flint
try it with the correct bounds and you'll probably get the same answer
clever fjordBOT
viscid flint
there we go
fair olive
Let me do it by hand to be sure
odd edgeBOT
@fair olive Has your question been resolved?
odd edgeBOT
@fair olive Has your question been resolved?
hexed wadi
odd edgeBOT
hexed wadi
i used quotient rule and got 1/9
why does the answer key have -1/9
where did i go wrong 😭
odd edgeBOT
@hexed wadi Has your question been resolved?
spiral roost
Does anyone have any hints on how to approach this?
odd edgeBOT
Does anyone have any hints on how to approach this?
spiral roost
@pastel dew C_5 minor would be constructing a minor (collapsing edges, deleting vertices or edges) from the graph and obtaining a cycle with 5 vertices (C_5).
Complete bipartite graph is just 2 vertices in the first set, n-2 in the second and every vertex in the first has an edge to every vertex in the second partition
pastel dew
interesting
odd edgeBOT
@spiral roost Has your question been resolved?
spiral roost
<@&286206848099549185> ?
odd edgeBOT
@spiral roost Has your question been resolved?
odd edgeBOT
@spiral roost Has your question been resolved?
opal path
is this -1/81
odd edgeBOT
is this -1/81
fair olive
.reopen
opal path
bit too late for that lmao
pastel orbit
is this -1/81
how did you get that?
pastel orbit
pastel orbit
indeed
well, that's too many parentheses for me to keep track of 
,, G'(2) = -\frac{1}{(f^{-1}(2))^2} \cdot \frac{1}{f'(f^{-1}(2))}
clever fjordBOT
higher!
pastel orbit
that's just by the chain rule and inverse function thm
and when you evaluate this, you do indeed get -1
so congratulations!
pastel orbit
opal path
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odd edgeBOT
pastel orbit
odd edgeBOT
Available help channel!
fallow flame
help pls
royal herald
@fallow flame what have you tried
fallow flame
dividing 900 by 2
royal herald
for what reason
fallow flame
this is why I’m asking for help
royal herald
calculate how many grams of flour it takes to bake 1 bun
feral beacon
Jimmy has the letters for the state of MISSISSIPPI written on cards, one letter per card. He turns the cards over and mixes up the order. If he selects one card at a time without replacing the cards, what is the probability that he will spell the word MISS in order?
feral beacon
so here's my thing. I get 7920 as the total permutation, but this problem is messing with me so much because I'm not sure if the S's are considered different for the sake of the order
feral beacon
but I know I'm supposed to calculate another permutation and then take the probability of that
1/495
3/365
1/165
48/495
those are the choices
feral beacon
I've already made the educated guess on it but I just want to understand the framework of these types of problems of finding the probability of the order through the permutation, if I was really going to take the actual real world probability I'd do weights of it but it definitely wont apply to this problem
@vale vortex bad response. don't answer if you can't provide insight
amber schooner
It’s a open chat
yea but it’s intended for the person to get help and if you can’t provide it then don’t try
weary pelican
It’s a open chat
If a helpee does not want help from a certain helper, it's their choice
vale vortex
If a helpee does not want help from a certain helper, it's their choice
Sure
Never said it wasn’t
I didn’t plan on helping after i got it wrong anyway
weary pelican
So comply with their demand to leave if they do not want your help
vale vortex
So comply with their demand to leave if they do not want your help
You are not in charge
Though this is a help channel
So probably stop arguing here
vale vortex
Feel free I don’t give a shit I did nothing wrong
Bro is the kind of guy to tell on you to the teacher
weary pelican
I am a teacher in training
vale vortex
Adds up than
weary pelican
so...
amber schooner
then
elfin zodiac
Enough of this, the channel is not for discussion off topic
@feral beacon show your working
weary pelican
ok
feral beacon
either 11^4 or any other idea doesn't add up to those choices, and I'm not sure if any of the repeating letters count as seperate values or the same
its so semantic and frustrating but I'm just going to assume that they are completely different for the sake of this instance
the following questions follow a format as " given a set of cards 1-10 randomly flipped around what is the probability you draw the 1,2 and 3 cards in order"
sand horizon
I am a teacher in training
Damn congrats man
weary pelican
its so semantic and frustrating but I'm just going to assume that they are compl...
If you suppose every letter is different from each other then you can do that
don't forget to do the same assumption when computing how many "MISS" you can make
feral beacon
its basically probability = numbered of desired permutations divided by overall permutations right?
weary pelican
well prob = number of desired cases/total number of cases yes
feral beacon
that comes to 7920/39 million roughly and that answer choice isnt there
feral beacon
39916800 is 11!
weary pelican
but
11P4 is the total number of cases
you're choosing an arrangement of 4 letters out of those 11
and the "desired" cases is 'MISS'
feral beacon
yep yep
feral beacon
oh RIGHT
but then at that point how am I discerning the order
because im my mind im thinking that permutation selects order from the 11
weary pelican
aren't you already discerning the order?
you did 11P4
so you chose the letters in order
11C4 would have been the incorrect choice since it doesn't care about order
feral beacon
11p4 is the total permutations for the entire set then
so within that amount how would i go about getting the order
weary pelican
11P4 is the number of ways to choose and order 4 things from a pack of 11 things
weary pelican
so within that amount how would i go about getting the order
you mean getting the specific order "MISS"?
feral beacon
yeah
feral beacon
1/11
weary pelican
you mean 1
feral beacon
yeah
feral beacon
i dont know i guess
weary pelican
I should be the next letter right?
feral beacon
i dont know if each 'I' is counted individually
weary pelican
its so semantic and frustrating but I'm just going to assume that they are compl...
.
if you counted them individually in the total count
feral beacon
which i'm assuming it is, so it would be the same probability of each letter for each yeah
weary pelican
you're gonna have to be consistent
feral beacon
i am
weary pelican
alr
feral beacon
for the sake of this there are no repeating letters
so the chance of getting the M is the same as getting the S
feral beacon
yes
weary pelican
If you're counting each letter as a separate letter
meaning MISSISSIPPI and MISSISSIPPI are different
feral beacon
yes
weary pelican
so the chance of getting the M is the same as getting the S
"the same as getting the S"
I think you lost me there
because either you're talking about "the same as getting an S"
feral beacon
my bad. i meant the probability is the same for each letter regardless of obvious appearance
weary pelican
okok
feral beacon
meaning MI***S***SISSIPPI and MISSI***S***SIPPI are different
this is all I meant in my explanation yeah
feral beacon
same amount of choices we would have for the first letter minus 1
weary pelican
bear in mind we're trying to make the word "MISS"
we said there was only one choice for the first letter, since there's only one M
now we're moving on to the second letter
how many choices do we have
(still trying to make "MISS")
feral beacon
honestly it might be better to explain it as 1234567891011
if i were trying to make 1-2-3-4 appear
weary pelican
sure but "MISS" isn't given by a single digit sequence
it could be 1234
it could be 1534
it could be 1362
all of those sequences lead to the same 4 letter word
feral beacon
in the class I'm in it is asking for a single digit sequence
a single digit sequence in order
given the amount of permutations what is the probability this order appears as exact in a random shuffle
weary pelican
in the class I'm in it is asking for a single digit sequence
?
weary pelican
in the class I'm in it is asking for a single digit sequence
the problem here is that many sequences lead to MISS
so now the question is
how many sequences lead to MISS
that's what we were trying to find
notice that any sequence that spells "MISS" starts with "1"
because there's only one M to choose from
feral beacon
yeah yeah
weary pelican
so now when we have to choose the other "digits"
for example the second letter
how many possible digits can represent the second letter
feral beacon
my friend
feral beacon
meaning MI***S***SISSIPPI and MISSI***S***SIPPI are different
^ this is what I am referring to. this means that although there are multiple of the same letters, for this problem it needs to be seen as every letter is different
weary pelican
yes
feral beacon
how many choices do you have
by this logic i have the same amount of choices
weary pelican
wdym
feral beacon
all the i's and s's and p's are considered different
feral beacon
so I don't have choices between the i's or s's so the probability is the same
weary pelican
notice that it's an I
weary pelican
so I don't have choices between the i's or s's so the probability is the same
well
feral beacon
youre trying to solve the problem. I'm trying to understand the process of what to do after the first permutation
weary pelican
can the second letter be represented by the digit "3" for example
feral beacon
no
weary pelican
correct
because digit 3 is an S
how many digits can I choose from
to make the second letter
feral beacon
10
weary pelican
I doubt all of those 10 digits would make the second letter "I"...
feral beacon
1/10 is the probability of choosing that letter among what we have without replacement of this set
11 letters we start with
we hit on the M
weary pelican
ok, first of all
feral beacon
10 left, 1/10 to get the correct next letter
weary pelican
10 left, 1/10 to get the correct next letter
there is only 1/10 correct second digit?
feral beacon
yes
weary pelican
so
say I already chose the M
there is "ISSISSIPPI" left
are you sure that I only have 1/10 chance
to get an I?
for my second letter
feral beacon
2345678910 is left
weary pelican
23456789-10-11 but yes
feral beacon
yeah
weary pelican
huh
feral beacon
bro
feral beacon
I'm obviously aware there are multiple letters that fit. I am asking you personally to treat this as a unique sequence with no repeating values. this problem uses two permutations
feral beacon
even though it spells MISS as well?
you are clearly not understanding me
weary pelican
so, to be clear
feral beacon
and you said it yourself
feral beacon
yes
weary pelican
well, 1
if you had to use in that order, MISS from MISSISSIPPI
there is only one way to get it
feral beacon
yes
now what is the permutation after the total amount, what is the logic I am supposed to follow in constructing that
11P4 is total permutations for an 11 element set, inside that what is the permutation of getting the first 4
weary pelican
again, if you have 11 different elements lined up
there are 11P4 ways to pick and order 4 of them
and there is only one way out of 11P4 to pick and keep the order of the first 4
feral beacon
1/1980 is not a choice
weary pelican
yep
because the I in "MISS" can be reached by another I than the 2nd one
and the Ss can be different Ss
weary pelican
if you decide to treat the letters as different
you have to change the meaning of "getting MISS"
or at least understand that 1234 is not the only way
feral beacon
but that still doesnt really get me to it
Annie writes the numbers 1 through 10 on note cards. She flips the cards over so she cannot see the number and selects three cards from the stack. What is the probability that she has randomly selected the cards numbered 1, 2, and 3?
this is basically the same question, although explicitly doesnt want replacement
weary pelican
not really the same question
weary pelican
because initially the cards are already distinguishable from each other
here's a better one
feral beacon
process wise it is largely the same within the scope
and I'm simply having trouble with identifying the second permutation to fill out the probability, that's really my issue
weary pelican
I can start with a simpler example:
Annie wrote the word "MOM" with each letter on a separate card, turned the cards over and shuffles them. If she selects one card, what is the probability that it is "M"?
here we wouldn't have to do the same "letters are distinguishable and become numbers" trick
because there's much less of them
feral beacon
please my friend. I really shouldn't have used that example to start. I want to know how to approach getting the second permutation among a set of unique elements
weary pelican
and the problem is simpler
are you talking about the original question?
because there aren't just two permutations that work for MISS
feral beacon
okay i give in
weary pelican
if you want to compute the number of permutations that give MISS
considering every letter is "different"
you have 1 choice for the first letter since you only have one "M" to choose from
you have 4 Is in total
so you have 4 choices for the second letter
then you also have 4 Ss
so 4 choices for the third
feral beacon
if every letter is different how can you have multiple of the same letter
feral beacon
then they arent really different then are they
weary pelican
you decided to treat them differently
when you did 11P4
but they are all "I" in the end
feral beacon
oh
so i did half the problem
so I have to consolidate occurrences within the 7920 for the multiple letters
4 total letters
weary pelican
there are four total "different" letters that are Is
so when you have to choose an I as the second letter
you have four different "letters" to choose from
or digits when you viewed it as 1234567891011
choose between 2, 5, 8 and 11
feral beacon
right
weary pelican
alright
so just to recap
there are 11P4 ways to make a 4-lengthed sequence of numbers from 1 - 11 without repeat
and we're looking for the number of those 4-lengthed sequences
feral beacon
yeah
weary pelican
that will spell "MISS" in the end
feral beacon
yeah
weary pelican
so 1234 is one of those sequences but as we found out there are potentially more
feral beacon
yeah
weary pelican
so the sequences that spell MISS will always start with "1"
so one choice for the first digit
four choices for the second digit, right?
feral beacon
yes and yes
weary pelican
and then how many choices for third and fourth?
feral beacon
4 and 3
feral beacon
what so its 4 times 4 times 3 divided by 7920
weary pelican
yep
feral beacon
wow
yeah that makes sense, thank you so much that helps a lot
mentally i was thinking i had to do some other xPy calculation again so I was tunneling on that
.close
odd edgeBOT
odd edgeBOT
Available help channel!
junior iron
hey
junior iron
i have a few questions
in algebra 2
im struggling on
can somone help me
it is abbt square root functions
quasi sparrow
