We have an equivalent classes
#help-19
timid fiber
We say that by definition of equivalent classes
A intersects B must yields empty set
tepid pelican
A intersects B must yields empty set
How do you know what A and B are?
timid fiber
No you didn’t understand it
P is not an partition but an actual partition
By definition partition implies( X \ ~ )
tepid pelican
P is not an partition but an actual partition
Whats the difference
tepid pelican
By definition partition implies( X \ ~ )
Implies [a set]? Implication is used with statements
tepid pelican
By definition it is X/ ~
We were given a different definition
tepid pelican
X\ ~ is properly defined
No its not
timid fiber
X\ ~ is a partition
tepid pelican
Nobody defined X and ~
timid fiber
This is a set - theoretical notation
Just it used that stupid unconventional mathcal P which led confusion
tepid pelican
X and ~ dont have any special meaning there
They are just there to get the idea accross
But it actually doesnt define them
timid fiber
What Y?
tepid pelican
~, sorry
tepid pelican
You could instead define it using A and % and it would have exactly the same effect
X and ~ are just placeholders
The defn doesnt define them
timid fiber
I am just saying the problem of the asker
tepid pelican
Its unrelated tho
tepid pelican
This is a completely different definition
timid fiber
It formally established equivalent classes and partitions
timid fiber
Sorry it’s late in NL I thought it was a problem but a definition yes your lecture note is rigorous
It properly defined the partition only notation
timid fiber
We dont have any equivalence classes given to us
For the picture that he provided I guarantee it’s rigorous 🤭🤭
tepid pelican
For the picture that he provided I guarantee it’s rigorous 🤭🤭
Yeah, the defn is fine
The only problem is the exercise itself
tepid pelican
That exercise is poweset
Well, OP said its not
tepid pelican
That thing is undefined as partition
Yeah
tepid pelican
OP said that the P in P(A) is a partitiom
timid fiber
How can that be defined
Partitioning on what
No equivalent classes given
What is partitioned
tepid pelican
No equivalent classes given
Thats not the problem
timid fiber
Well it’s undefined eitherway
tepid pelican
This defn doesnt use equivalence classes
timid fiber
Well okay still it doesn’t matter
It is undefined
Partitions implies disjoint intersection yields empty set, and union of all disjoints yields X
However A and B are arbitrary
Like what the fuck are they
Like the OP must be able to tell what is being asked
I am completely confused if that partition
odd edgeBOT
@hoary flower Has your question been resolved?
wary violet
odd edgeBOT
wanton bison
29.10.2024 10 Uhr
wary violet
Ich mache vor der Prüfung kurz Wiederholung
Ich habe eine bisschen Problem, welche die Bedingung ist, zu bestimmen.
Warum ist dr erste Würfel zeigt eine 6 ereignis A
wanton bison
Bedingung ist dass zuerst eine 6 gewürfelt wurde
wary violet
Ich glaube mein deutsch ist nicht genug
wanton bison
P(A|B) Wahrscheinlichkeit von A, unter der Bedingung, dass B eingetreten ist
P("Erster Wurf 6" | "Augensumme gerade" )
wary violet
Ist es, weil augensunme gerade bevor wort „gegeben“erwähnt ist?
wanton bison
Moment ich hab es verkehrt rum
Wir wollen wissen wie die WK ist, dass eine 6 gewürfelt wurde unter der Bedingung, dass die Augensumme gerade ist
wanton bison
Ist es, weil augensunme gerade bevor wort „gegeben“erwähnt ist?
"... gegeben, dass die Summe der Augenzahlen gleich einer geraden Zahl n ist" das ist die Bedingung
wanton bison
das was gegeben ist, ist die Bedingung oder Annahme
\begin{align*}
\mathbb{P}(\text{"Erster Wurf 6"}|\text{"Augensumme gerade" })=\frac{\mathbb{P}(\text{"Augensumme gerade" }|\text{"Erster Wurf 6"}) \cdot \mathbb{P}(\text{"Erster Wurf 6"})}{\mathbb{P}(\text{"Augensumme gerade" })}
\end{align*}
clever fjordBOT
𝔸dωn𝓲²s
wanton bison
Satz von Bayes
wary violet
Danke2 ich habe verstanden.
wanton bison
Nichts verstanden.
odd edgeBOT
odd edgeBOT
Available help channel!
earnest mango
Does anyone have a good challenge problems for laws of logarithms/log functions/exponential functions? Simplifying, solving for x, etc.
earnest mango
thanks!
odd edgeBOT
If you are done with this channel, please mark your problem as solved by typing .close
velvet heart
youtube
earnest mango
@winged vortex do you have simplifying ones w/ log rules
amber granite
<@1254538022494666856> do you have simplifying ones w/ log rules
chatgpt is good at generating practice problems
im being serious
what
u can specify that you want challenging ones
chatgpt is smart but it cant read your mind
🧍♀️
odd edgeBOT
@earnest mango Has your question been resolved?
acoustic crest
Can someone explain how to solve this limit question? I'm having a hard time figuring out the steps to get to the solution.
feral scaffold
you can't separate an integral like that
use IBP
hearty kelp
am i right with A here?
odd edgeBOT
am i right with A here?
hearty kelp
<@&286206848099549185>
odd edgeBOT
<@&286206848099549185>
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
onyx cloak
am i right with A here?
yes
odd edgeBOT
odd edgeBOT
Available help channel!
heady plover
Any ideas?
green elm
should the last word be "diagonal" instead of "diagonalizable"?
green elm
you know there's a P that works for A
see if you can show that the same P works for B
if you let $D = P^{-1}AP$ and $B' = P^{-1}BP$ then if you left multiply your equation by $P^{-1}$ and right multiply it by $P$ and simplify, you get $$DB' = D - B'$$
clever fjordBOT
Bungo
heady plover
Idk how to utilize the condition AB=A-B
green elm
where D is diagonal
now compare the i,j elements of both sides of that equation
consider separately the cases i != j and i = j
by doing so i was able to show that the i,j entry of B' is zero if i!=j (thus B' is diagonal)
I can never come up with such a solution in my lifetime
heady plover
consider separately the cases i != j and i = j
And bii=λ/2?
green elm
what's λ
green elm
yea
clever fjordBOT
mayonnaise
green elm
actually i suggest doing the i != j case first
that will narrow things down to two possibilities
and you can exclude one of the possibilities by looking at the i = j case
and the only remaining possibility will be that B' is diagonal
that's how i did it anyway
odd edgeBOT
odd edgeBOT
Available help channel!
tardy horizon
How do you get (3.2)!
odd edgeBOT
How do you get (3.2)!
wanton bison
Gamma function
paper onyx
red reef
Why is the asymptotes specifically in that part of the graph
zinc glacier
a refursive definition of the factorial is (n-1)!=(n!)/n
this breaks when you get to numbers like 0
odd edgeBOT
@tardy horizon Has your question been resolved?
tardy horizon
a refursive definition of the factorial is (n-1)!=(n!)/n
Isn't that circular
Defining factorial as factorial
tardy horizon
https://en.m.wikipedia.org/wiki/Gamma_function
I see
odd edgeBOT
@tardy horizon Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
swift heron
Why is 3 - (3 + 2i) = 2i?
charred spindle
odd edgeBOT
@swift heron Has your question been resolved?
rich tusk
Need help attemtping to derive the following or check if it is correct : $\sum_{m=1}^\infty G(\chi, m) m^{2s-1} = G(\chi, 1) \cdot L(1-2s, \overline{\chi})$, where $G(\chi,m)$ is a gauss sum and $chi$ has conductor $q$
clever fjordBOT
M47R1XAdV#9685
rich tusk
<@&286206848099549185>
lean willow
Idk
rich tusk
how do you think should I approach it?
odd edgeBOT
@rich tusk Has your question been resolved?
rich tusk
<@&286206848099549185>
odd edgeBOT
@rich tusk Has your question been resolved?
odd edgeBOT
@rich tusk Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
minor lion
So ended up here
odd edgeBOT
So ended up here
minor lion
Cos(x)/x is obviously not integratable but wolfram still gave an answer
steady tide
which is?
minor lion
So ended up here
It equals 0 btw I mustve forgot it
steady tide
show me your wolframalpha prompt
steady tide
i am not qualified in ode enough to clear your doubt 
steady tide
others can help tho
minor lion
So ended up here
Kinda yapped this is the original ^
<@&286206848099549185>
Oh well
.close
odd edgeBOT
mystic saffron
dividation?
glossy lotus
Do you know Ruffini?
mystic saffron
synthetic division?
glossy lotus
Hmm let me do an example and you see if you can understand the process. Wait a sec
mystic saffron
it's just another way
glossy lotus
Yeah you can do it that way as well but this is more convenient when divided in the form of x-a
Sorry I had a minor error there
This is yours
Should have been like this
.
odd edgeBOT
@mystic saffron Has your question been resolved?
glossy lotus
For which one?
It is good to check if it is right by multiplying your result to the divisor to get the dividend
warped glacier
,w (2x^3 - 9x^2 + 3x + 4) / (x - 4) simplify
clever fjordBOT
warped glacier
This is yours
yeah so this is correct
glossy lotus
This is yours
Yes this is the sol for your problem. And the following image is for the sol of the example I put
Nah just my teachers taught me well
warm knoll
how do i find the joint distribution function
odd edgeBOT
how do i find the joint distribution function
@warm knoll Has your question been resolved?
odd edgeBOT
@warm knoll Has your question been resolved?
meager juniper
It looks like you just make sure the columns add up to pX(x) and the rows add up to pY(y) and everything adds up to 1.
@warm knoll
For instance, we are given that the first column is 1/6, ?, 5/12. We know that 1/6 + ? = 5/12, so it's possible to determine that the ? represents 1/4 because 1/6 + 1/4 = 2/12 + 3/12 = 5/12.
meager juniper
I mean, the table, the top four entries at least, is the joint distribution function.
warm knoll
I mean, the table, the top four entries at least, is the joint distribution func...
I don’t get it what do I write as an answer to that
meager juniper
You can simply write the function as cases.
[
p_{X,Y}(x, y) = \begin{cases}
1/6 & \text{if $x = 1$ and $y = 0$} \
1/4 & \text{if $x = 1$ and $y = 1$} \
\text{etc.}
\end{cases}
]
clever fjordBOT
OmnipotentEntity
meager juniper
@warm knoll
odd edgeBOT
Available help channel!
urban topaz
I need help factoring.x^2-x-42
odd edgeBOT
I need help factoring.x^2-x-42
green sage
what are your coefficients in this quadratic
if your quadratic is in the form ax^2 + bx + c, what is a, b, and c
urban topaz
im supposed to factor it. like splify it or sum
vagrant hazel
hes asking you because you need to know the a, b, and c to factorize it
urban topaz
i do?
vagrant hazel
you have the quadratic:
x^2 - x - 42
which is in the form:
ax^2 + bx + c
what are the values of a, b, and c in the quadratic?
well yeah its just what you need to know at first to start factoring it
urban topaz
a=1 b=1 c=42
velvet heart
you need to consider the signs
urban topaz
a=1 b=-1 c=-42?
vagrant hazel
correct
now basically how factoring works is its going backwards from distribution
so all you need to do is find two numbers that multiply to -42 and add up to -1
urban topaz
so (x-7)(x-6)?
urban topaz
(x-7)(x+6)
vagrant hazel
correct
urban topaz
ty
vagrant hazel
gets more complicated once you have an a value that is not 1 tho
still relatively easy though, just try to find two numbers that multiply to a*c while adding up to b
then just seperate the bx value into those two values
urban topaz
like x^2-6x-16 but its easier for me
vagrant hazel
?
urban topaz
its (x-8)(x+2)
vagrant hazel
yes
urban topaz
and if theres a number before x^2 i just dived everything by it
if theres extra varibles in ever part they go in the front?
vagrant hazel
well that only really works if you set it to 0
which is not the case all the time
think of something like 2x^2 + 7x - 15
you cant divide since its not set equal to 0
and you cant take out a 2 otherwise it turns into fractions
so what do you do? Simple: just try to find two numbers that multiply to a*c while adding up to b
then just seperate the bx value into those two values
and finally factor by grouping
if you didnt understand that i can go over each step
urban topaz
but like -3cx^3-6cx^2+72cx= -3cx(x+6)(x-4)
vagrant hazel
but like -3cx^3-6cx^2+72cx= -3cx(x+6)(x-4)
what about it
oh that
well yeah but that isnt exactly like what i said
thats kind of just taking out a common factor from each term
odd edgeBOT
@urban topaz Has your question been resolved?
urban topaz
yes
odd edgeBOT
odd edgeBOT
Available help channel!
spiral kindle
Can anyone here help explain to me inverse Matrixes
odd edgeBOT
Can anyone here help explain to me inverse Matrixes
fair olive
help
spiral kindle
fair olive
@Helper
swift heron
I have NO idea what this slide is saying
Do you know the property of matricies
swift heron
Like what does it mean for for a matrix to be an inverse by another
spiral kindle
Adding two matrixes
swift heron
Specifically what is A * A^-1
spiral kindle
Like what does it mean for for a matrix to be an inverse by another
When you multiply both of them they both equal reduced row echelon?
swift heron
Specifically, when you multiply A by its inverse, you get the identity matrix
spiral kindle
I don't know what an identity matrix is
swift heron
Thats why we row reduce [A | I] to find. A^-1
its just
[1 0 ; 0 1]
its kind of like
spiral kindle
but like in the slide what are they trying to get
Like why did they do 3R1+2R2
What was that supposed to find
gray shell
to remove bottom row
spiral kindle
Of A or I
swift heron
you're trying to get the LHS to I, and the RHS will be your inverse
if you can't create an identity matrix with the LHS you don't get a proper inverse
spiral kindle
I'm so sorry I am unfamiliar with what acronyms LHS and RHS mean 😭
swift heron
uh
spiral kindle
Lower half side?
spiral kindle
Ahh okay
swift heron
and right of that
spiral kindle
Is I
spiral kindle
so am I trying to turn A into RREF?
swift heron
yes
you want to turn the left part
into I
and whatever the right part turns into
spiral kindle
and I into A?
swift heron
is the inverse
spiral kindle
oh
swift heron
yes
if you cant get the left side
to I
you don't have a inverse
like in the example provided
swift heron
No problem
gray shell
this matrix doesnt have an inverse right?
swift heron
this matrix doesnt have an inverse right?
Yep
spiral kindle
There was no example problem after that now there's determinants 😬
swift heron
😭
spiral kindle
Okay so essentially this is saying
Instead of doing that one inverse method with LHS with RHS
I can find the determinant to find the inverse?
No wait hold on
ad-cb not equaling 0 means that there is an inverse to this matrix
and if I find that out then I can simply do 1/ad-cb
gray shell
just ask chatgpt, try this
gray shell
yes
spiral kindle
Can I see ur prompt
gray shell
ask it to give you example problems
"give me an example problem for inverse 2x2 matrixes with answers"
spiral kindle
"give me an example problem for inverse 2x2 matrixes with answers"
Thank you
I'm gonna go eat now closing this for now, thank you for the advice
.close
odd edgeBOT
odd marsh
and if I find that out then I can simply do 1/ad-cb
Yes
odd edgeBOT
Available help channel!
languid gorge
The integral of x^n is x^(n+1)/(n+1) +C and the integral of 1/x is ln(x). Does this mean x^(n+1)/(n+1) +C "approaches" ln(x) in some way?
fallen surge
The integral of x^n is x^(n+1)/(n+1) +C and the integral of 1/x is ln(x). Does t...
sort of, $$\ln(1-x) = -\sum^\infty_{i=1} \frac{x^i}{i}$$
clever fjordBOT
Bair
languid gorge
How does that relate to x^(n+1)/(n+1)?
fallen surge
How does that relate to x^(n+1)/(n+1)?
the right side is a sum of x^n/n
languid gorge
But I expect n to "approach" -1, not be added
fallen surge
im not sure what you mean by that
x^{n+1}/{n+1} will approach 0 if |x| <=1 and diverge otherwise
languid gorge
Ok, I have in my notes the following :
integral of x^n is x^(n+1)/(n+1) +C
Plug in n = -1, we get integral of x^-1 is x^0 / 0 + C, but division by zero is undefined, and instead we get that the integral is ln(x) + C.
But if we plug in n = -0.9999, we get x^0.001 / 0.001 + C
Since -0.999 is close to -1, integrals should be close too, so x^0.001 / 0.001 + C is "close to" ln(x) + C
fallen surge
ok i see, you want to compute $\lim_{y\to 0} \frac{x^y}{y}$, then indeed we can apply l'hopitals rule, to get $\lim_{y\to 0}\frac{\ln x\cdot x^y}{1}=\ln x$
clever fjordBOT
Bair
odd edgeBOT
mystic garden
how do you find the work done by friction without the coefficient of friction
odd edgeBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
mystic garden
ok so I have a roller coaster that i actually had to build irl. i need to find the work done by friction at certain points on the roller coaster. i have the mass, height, and distance.
mass is 0.008 kg
amber schooner
well what can you tell me about the change in energy of the system when all forces are conservative
there’s this important law in physics
amber schooner
yea
so U_1 + K_1 = U_2 + K_2 + W_f
W_f accounts for the remaining energy
so you can find the standard U + K and find the difference between that and the initial amount
amber schooner
gravitational potential and kinetic
mystic garden
k wait
doesnt this not work if I only have the ideal grav and kinetic without friction
amber schooner
wdym ideal
mystic garden
like
amber schooner
if they’re the same then there is no work done by friction
amber schooner
u2 + k2 is the same as u1 + k2
and do you mean u2 for the second part
or u1 rather
mystic garden
ye
amber schooner
and k1
amber schooner
yea but you’re using measurements yea
mystic garden
yes
amber schooner
you can’t find K if you don’t know v
mystic garden
I have velocity
mystic garden
i dont know what that is
amber schooner
i dont know what that is
measurement device for speed
mystic garden
oh
amber schooner
i assumed you were performing an experiment
mystic garden
i just calculated with mass and energy
amber schooner
it would be best if you send the original problem instead of having us try to guess what’s confusing you
i have to go eat though
if you still need help later lmk
mystic garden
i dont even rly have the original question
it was just to build a roller coaster
get mesurments
mystic garden
yes
amber schooner
alright well if you could provide the instructions that would be helpful
i’m going to go now though
maybe someone else will help
ebon vigil
Hello Sir! I am one of Gus’ group members
mystic garden
ebon vigil
Instructions were written using ChatGPT and not even our teacher understands them
This is our SOS.
SOMEONE PLEASE HELP
WE ARE SO LOST
IM BEGGING
PLEASE
<@&286206848099549185>
GUYS LIKE SERIOUSLY
velvet heart
open a channel
ebon vigil
jow do you do that
velvet heart
ebon vigil
WE HAVE A CHANNEL.
mystic garden
arent we in one
ebon vigil
THIS IS A SHARED CHANNEL.
velvet heart
oh right
ebon vigil
are you gonna help or…?
feral canopy
what’s up guys
ebon vigil
JUSTIN
mystic garden
thank you justin
ebon vigil
PLEASE HELP US
mystic garden
we need help
feral canopy
is this ap physics?
mystic garden
gr 11 physics
soft solstice
Hello
ebon vigil
no, just psycho teacher physics
soft solstice
So what exactly is your issue here?
ebon vigil
okay so we have this project where we needed to build a roller coaster
mystic garden
need to find work done by friction
soft solstice
Just take your time and please explain concisely
ebon vigil
and so we built a roller coaster, and then we have application questions to answer
soft solstice
need to find work done by friction
Okay
ebon vigil
and one of the questions is to find the work done by friction on the marble
but we dont know how to do that because we dont have coefficient of friction
soft solstice
So, work done by friction will naturally be attributed to any energy loss found between your two measurements
ebon vigil
and the following question is to find the actual mechanical energy, and we keep getting negative answers.
mystic garden
i mean energy sry
soft solstice
but we dont have measurments of friction
Yes that’s fine even theoretical values work
ebon vigil
can you help us please guy from the thing
soft solstice
But the theoretical system needs to account for friction, it can’t be ideal
soft solstice
U_1 + K_1 = U_2 + K_2 + W_f
Could I see your data set?
ebon vigil
Gus will send his
soft solstice
Please indicate to me which is potential and kinetic 1&2 respectively
I’m talking like an AI because I’m tired
But not too tired don’t worry
ebon vigil
we feel you
you know our physics teacher is always too tired to teach us so she uses chatgpt.
its very unfortunate we are all lost and failing
ebon vigil
are you british?
feral canopy
sounds like an average physics class
ebon vigil
JUSTIN WELCOME BACK
soft solstice
are you british?
Scottish to be specific but yes
ebon vigil
the more help the better guys
ebon vigil
Scottish to be specific but yes
NO WAY
mystic garden
so distance of track total: 3.45m
weight of ball 0.008kg
time taken from drop to stop: 2.87
point 1 height: 0.7m
point 2 height 0
Eg1: 0.055
Ek1: 0
Eg2: 0
Ek2: 0.055
lmk if u need more
and v at point 2 is 3.7m/s
odd edgeBOT
IM BEGGING
Helpers are just people volunteering their time to help you. Be polite and patient.
mystic garden
bot a little late
soft solstice
so distance of track total: 3.45m
weight of ball 0.008kg
time taken from drop to...
I feel like there must be a discrepancy in your rounding
Check to the 5 or 6th significant figure if these are identical
mystic garden
for which
ebon vigil
arent they supposed to be identical
soft solstice
so distance of track total: 3.45m
weight of ball 0.008kg
time taken from drop to...
Which of these have you rounded?
ebon vigil
because at the start there is only potential energy and at the end its just kinetic?
soft solstice
arent they supposed to be identical
Not if there is friction, as then you’re working in a non conservative energy field
(All this means is that you lose energy due to other factors, air resistance etc)
mystic garden
these are the ideal calculations
but i dont know how to do them with friction
without just using tools to measure it
soft solstice
@mystic garden
soft solstice
Alright
soft solstice
honestly its to late for me to redo all this
How do you mean redo?
soft solstice
Sorry there should be a 0 after the decimal point for Eg1
soft solstice
a formula to find force of friction
If Energy before = Energy after there can be no friction
That is just not how friction works
You need to find the difference
Or do the values you have given me not account for friction?
I mean, you said ideal
But then
If it is ideal there’s nothing to find
mystic garden
yeah they dont account for friction
mystic garden
but i need to calculate now with friction
soft solstice
You cannot
mystic garden
and i dont know how
thats what im saying yk
shouldnt be possible
and my teacher smells like shit
so im just in a rly bad place here
ebon vigil
she doesnt smell like shit just teaches like shit
soft solstice
thats what im saying yk
So you were given these values?
soft solstice
i calculated them
So did you do any measurements?
Right okay, tell me step by step what you’ve done in this lab
mystic garden
i built a roller coaster
i measured heights at different points, and the weight of ball
using that
i used mgh and mv^2/2 to calculate the energys
soft solstice
i used mgh and mv^2/2 to calculate the energys
So you were given v?
How did you get v
mystic garden
no i calculated it by using the energy i got and the equation Ek = mv^2/2
soft solstice
and k with mv^2/2
What do you mean "k"?
soft solstice
So you were given Ek or?
soft solstice
Yeah this is where that has went wrong
soft solstice
You have assumed that the system has no friction
soft solstice
You can't do that if you're finding friction
soft solstice
becasue thats what i first had to do
You were told to do this?
soft solstice
Crazy
soft solstice
So
In total
You measured height and time until stop or?
Because you also gave a t value
Also
What did this track look like?
mystic garden
i measured time with stopwatch
soft solstice
Okay
soft solstice
And you started measuring time at point 1 and ended at point 4 I presume?
mystic garden
yes
soft solstice
Was it at rest at point 4?
soft solstice
Do you know the height of the loop and the height of the hill?
soft solstice
And do you know the distance between point 1 and 2 and 2 to 3
Both horizontally and vertical
mystic garden
idk
just in length of trach
honestly
that distance can be pretty
much made up
soft solstice
Okay
viral sun
hello i am also from gus and maya's group
soft solstice
0.7m
This can't be right since that would assume it's straight down
Maybe like .9m?
viral sun
can you join our meet call and explain please
soft solstice
Alright
viral sun
could you explain on the meet?
viral sun
a google meet call
ebon vigil
soft solstice
I could do a discord call
I'm not really comfortable using my email for that, as it has my name in it
viral sun
okay, no problem thanks
ebon vigil
Sure
mystic garden
im lowkey gonna give up
viral sun
on life
mystic garden
can i have a note from you i can give to my teacher saying this is too hard
soft solstice
I mean I'm not a professor or anything just a university student
But this question is definitely possible
viral sun
maybe if you're in a deep state of psychosis
mystic garden
we have a sub today and he said "i dont know how she expects you to do that"\
and hes british
viral sun
hes a kiwi
soft solstice
we have a sub today and he said "i dont know how she expects you to do that"\
Damn
Well
ebon vigil
hes from new zealand
soft solstice
I have an idea
viral sun
whats your idea
soft solstice
Just measure the time the ball would take to cover each component ideally
Sum these together
This (Hopefully) will be lower than your actual real time
Then that is a proof of concept that friction exists
Then finding kinetic friction is possible
viral sun
this is getting theoretical im confused
mystic garden
ok i get it
but how do i measure ideal time
oh using the speeds
but wouldnt i need a lot of speeds
mystic garden
so how
soft solstice
As we are most likely working with a non linear change in velocity over time
Just break it into several parts and do it step by step
The first ramp from point one
mystic garden
i have 3 speeds
mystic garden
i have 0m/s at start, 3.7m/s at bottom of first hill 3m/s at top of loop and 3.47 m/s at top of hill
mystic garden
yep
soft solstice
i have 0m/s at start, 3.7m/s at bottom of first hill 3m/s at top of loop and 3.4...
Your speed at the bottom of the loop will be the same as the bottom of first hill at both the start of and the end of the loop (ideally)
soft solstice
And the speed at the end of the second hill will be the same as the start of the second hill again, 3.7ms
mystic garden
yes
soft solstice
So ideally you have a lot more measurements than you think
Just the time to do the loop and the second hill will be a lot more cumbersome
Make some easy notation for this by the way
Like for your specific system
Like t hill 1, t loop, t hill 2, t end (All ideal)
And you just need a couple more things
Like the width of hill 2 assuming it's a uniform half circle
mystic garden
do you agree this is too hard
viral sun
this is physics
soft solstice
Okay even then
viral sun
our teacher got this fro, chatgpt
soft solstice
Pre university physics certainly
mystic garden
thats what im sayin
soft solstice
Possibly not that's just my conjecture on the matter
mystic garden
ig theres multiple ways to do it
mystic garden
i just dont know the way she wants us to do it
soft solstice
I didn't learn about multiple ways of solving kinematics problems until 2nd year of university
soft solstice
i just dont know the way she wants us to do it
Whatever chat gpt said evidently
mystic garden
lmao
she deadass tells us to use chatgpt to help us
wait guys
SHE EXTENDED IT TO THURSDAY
im saved
tawny cove
I have no idea how to do questions like this A triangle with sides of 21cm 72cm and 75cm is cut into parts that form a quadrilateral. Find in cm^2, the area of the largest quadrilateral that can be formed.
tawny cove
I was wondering if you make the traingle in a sqaure
<@&286206848099549185>
I have no idea how to do questions like this A triangle with sides of 21cm 72cm and 75cm is cut into parts that form a quadrilateral. Find in cm^2, the area of the largest quadrilateral that can be formed.
YO
<@&286206848099549185>
.close
odd edgeBOT
odd edgeBOT
Available help channel!
scarlet pond
I need help simplifying this 😭😭
odd edgeBOT
I need help simplifying this 😭😭
scarlet pond
.close
static lance
In central difference method for approximating the derivative is there cases where it won't be applicable?
static lance
I found a case where there isn't enough information if we want to approximate 1/x close to 0.
but is there a general way to say it. I tried to search, but didn't find anything
pearl cargo
In central difference method for approximating the derivative is there cases whe...
if the derivative exists, you will always a good approximation if you use a small enough difference
pearl cargo
I found a case where there isn't enough information if we want to approximate 1/...
can you elaborate on what you mean by this?
static lance
can you elaborate on what you mean by this?
What I meant in general is that for some fucntion f(x+h) or f(x - h) might not exist, so we can't use central difference and should look for other methods.
pearl cargo
What I meant in general is that for some fucntion f(x+h) or f(x - h) might not e...
if f(x + h) or f(x - h) don't exist even as h -> 0, the function isn't differentiable at that point
static lance
if f(x + h) or f(x - h) don't exist even as h -> 0, the function isn't different...
Ah, you are correct. I thought if we want to approximate the derivative for ln(x) at x = 0.0001 we won't be able to use the central, but I was wrong because we can use a small enough h and it will be defined.
thank you so much.
pearl cargo
np!
static lance
.close
inner ore
hello
inner ore
you guys will love this one
imagine a true 50% probability coin flip or whatever u want, just true 50/50 odds
we move in steps of 1, and on one end we have -2, on the other end we have +2
what are the odds of us reaching either side first? every move in steps of 1 has a 50/50 odd
so lets say if we flip heads we will move left (-1), we flip tails we move right (+1)
are yall with me so far
wanton sierra
sounds like e shenanigans to me
inner ore
im going somewhere with this
inner ore
yes rain youre correct
wanton sierra
i suppose i overthought lol
inner ore
ok so now if one end had -4, and the other end had +2
inner ore
which will i reach first, what is my % probability of reaching either side first
inner ore
this is called a random walk
thank you, im not a math guy
wanton sierra
which will i reach first, what is my % probability of reaching either side first
my guess is 1/3 vs 2/3rd
inner ore
are u sure
so 33% chance of reaching -4, and 66% chance of reaching +2 roughly?
i have one final variation after this, and thats the final thing i need to know
wanton sierra
idk the more i think abt it the more i think thats wrong, i just looked at it as 2 steps left needed to offset 1 step right
inner ore
idk i came to u guys for help
because i dont know how to calculate it
@karmic umbra any input
im just gonna write the final variation anyway so that someone sees it , if u figure it out also @wanton sierra
finally i want to imagine 2 stages.
stage 1 : what are the odds of us reaching -2 vs +2 in a random walk moving in steps of 1, with a 50/50 true random odds?
stage 2 : what are the odds of us reaching -4 vs +2 in a random walk moving in steps of 1, with a 50/50 true random odds?
stage 3 - final question ; can we combine those 2 odds together? if we wanted to reach +2 in both stages. for example, there's a 50% chance i reach +2 in stage 1, then whatever % chance to reach +2 in stage 2, combine that together. tldr : the % chance of me reaching +2 in both stages first passing stage 1, then stage 2
karmic umbra
um if this is not homework
if this isnt homework you can just look this up
1d random walk
this is a classic problem
inner ore
if this isnt homework you can just look this up
id have to spend so much time tho
i have 0 math foundation
i come to smart people for help
inner ore
what is this for
it is very important, my NDA requires i cannot reveal anything else
@static totem you might be my last hope
i have returned once again seeking refuge in your knowledge
static totem
i don't know random walks unfortunately
inner ore
damn
odd edgeBOT
@inner ore Has your question been resolved?
inner ore
surely somebody that understands random walks helps with this ^
odd edgeBOT
@inner ore Has your question been resolved?
odd edgeBOT
@inner ore Has your question been resolved?
odd edgeBOT
@inner ore Has your question been resolved?
odd edgeBOT
@inner ore Has your question been resolved?
odd edgeBOT
@inner ore Has your question been resolved?
steel raven
some good 1d explanation here, as mentioned above.
https://en.wikipedia.org/wiki/Random_walk
you'll want to refine your question to those odds within a certain amount of steps. my stats is weak, but adding probabilities is usually pretty funky.
inner ore
some good 1d explanation here, as mentioned above.
https://en.wikipedia.org/wiki...
Appreciate it
summer cradle
i think you can solve this with probability generating functions
let me do my thang
summer cradle
hm it is a tough one. i will try something else
tired maple
do u need elp?
summer cradle
yea but not with math
tired maple
with wat ;o
summer cradle
so 33% chance of reaching -4, and 66% chance of reaching +2 roughly?
my algorithm agrees
and actually it seems that f(a,b) = [1 - a/(b-a), a/(b-a)]
paper onyx
my algorithm agrees
This answer is correct and can be proven
Even though your case 3 makes no sense to me
The event ends as soon as you reach 2 or -2
So it will be same as case 1
summer cradle
wdym
paper onyx
As in when you reach either 2 or -2
summer cradle
oh you're not talking to me
paper onyx
That's it the event ends
Your algorithm is correct
I was referring to case3 that @inner ore
Presented with
summer cradle
damn even without seeing it
paper onyx
It makes perfect sense
summer cradle
and actually it seems that f(a,b) = [1 - a/(b-a), a/(b-a)]
here are some random numbers to corroborate this also
,calc 15/(15+37)
clever fjordBOT
Result:
0.28846153846154
It's working because you just wrote sum of an infinite geometric progression
summer cradle
are you talking to me
paper onyx
I think so
summer cradle
my algorithm has nothing to do with that
paper onyx
.-.
summer cradle
it's a markov chain computation
paper onyx
I am confused
But still that's all I had to say case 3 makes no sense
Case 2 Is correct
That's all
inner ore
Can you guys finish the stage 3 I mentioned
Combining stage 1 and 2 together
That’s the one I’m stuck on
because individually it makes sense I don’t know how to add the 2 probabilities together
paper onyx
What does stage 3 even mean
inner ore
if the first one has a 50% chance of success, and the second has a 66% chance of success
summer cradle
so basically it will be like stage 1 then similar to stage 2 but you start at position 2?
inner ore
it’s not even a stage sorry I just need the odds of reaching +2 on both stages like combined
summer cradle
wdym 'combined'
inner ore
so for example, if I pass stage one and reach +2, then I attempt stage 2 and reach +2, what are the odds of that happening
paper onyx
Even if there were infinite numbers on both sides
inner ore
The chances of reaching 2 and -2 are the same
Yes so the first stage has a 50% possibility, then stage 2 is -4 on one end, and +2 on the other
paper onyx
Oh so like stage 1 happens
inner ore
so reaching +2 on the second stage has a 66% chance
paper onyx
then stage 2 happens
paper onyx
I understand the problem now
inner ore
so like, if stage one is a ‘success’ and I reach +2, I move to stage 2
now the parameters are -4 on one end, and +2 on the other end
paper onyx
So chances of reaching +2 = 1/2
inner ore
So chances of reaching +2 = 1/2
For stage 1 correct
quasi sparrow
i was answering it and then the channel closed
welcome back!
paper onyx
Wait
summer cradle
welcome back!
hi daddy
inner ore
resetting to 0 in between stages
Correct
I know I didn’t specify it well my bad
So you start from 0 on both stages
summer cradle
you can just multiply the probabilities together. 1/2 chance for success, then 2/3
paper onyx
.-.
inner ore
So my main question is : if I pass stage 1, and stage 2, altogether what is my % probability of passing both stages altogether
paper onyx
So answer is just 1/6
Completing stage 1 is 1/2
Completing stage 2 is 1/3
Multiply
paper onyx
Yes
paper onyx
Their a 1/6 chance you pass Stage 1 and not 2
And 1/2 chance you don't even reach stage 2
inner ore
Their a 1/6 chance you pass Stage 1 and not 2
Oh that is an interesting statistic…
paper onyx
And 1/2 + 1/3 + 1/6 =1
inner ore
Love that , very useful
inner ore
Essentially , once I pass stage one, there’s like a 5/6 odd I pass stage 2?
Or did I math bad
inner ore
Yea
paper onyx
Then probability of clearing stage 2 is just
1* 2/3