help-19

[rotund hawk]

.close

[odd edge]

Channel closed

Closed by @rotund hawk

Use .reopen if this was a mistake.

[odd edge]

✅

[meager juniper]

.close

[odd edge]

Channel closed

Closed by @meager juniper

Use .reopen if this was a mistake.

[mystic saffron]

second time

[meager juniper]

Nami already took care of the cause, see hlounge @mystic saffron

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[candid canyon]

im almost done with this question I am just confused on what to set n in the question that fufills the natural numbers rule of s.

[candid canyon]

so far i have plugged in the distance formula between (1,0) and (1/n + 1, 1/n) and i have gotten n = sqrt2 / epsilon

but because natural numbers can't be fractions of course i am having trouble defining an n that is a natural number that works for all epsilons

[brittle beacon]

how do you mean?

[candid canyon]

so to find a 0< d(P, Q) < epsilon i plugged in (1,0) for P and Q as the coords for S

meaning 1/n + 1, 1/n

[brittle beacon]

(I really think you want that to be n > sqrt{2}/eps rather than the equality that you said)

[candid canyon]

I see so something like floor(sqrt(2)/eps + 1)?

sorry for the bad explanation my brain has been running in circles

[odd edge]

@candid canyon Has your question been resolved?

[odd edge]

@candid canyon Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm swan]

can someone help?

[odd edge]

Please don't occupy multiple help channels.

[buoyant dagger]

what do you need help with

[velvet badger]

brother, u took a video of your entire test and expect someone to do it for you?

[storm swan]

its a study guide, the wording on the top is wrong, as well I was broad, I meant to say that I needed help with turning bisector based on the angle

[buoyant dagger]

oh really

[storm swan]

mainly numbers 3,6,7 are confusing

[buoyant dagger]

"this test replaces your lowest test grade"

[velvet badger]

loooooooooooooooooooooooool

[buoyant dagger]

bahhahahhaha

nt kid

[storm swan]

"wording on the top is wrong"

my guy

[buoyant dagger]

oh really

[storm swan]

re read my test

[velvet badger]

Do u think people are born yesterday?

[buoyant dagger]

https://tenor.com/view/side-eye-dog-suspicious-look-suspicious-doubt-dog-doubt-gif-23680990

[storm swan]

i just needed help

[velvet badger]

What have you tried?

[buoyant dagger]

show your work

[storm swan]

i lost it

erm

[velvet badger]

https://tenor.com/view/side-eye-dog-suspicious-look-suspicious-doubt-dog-doubt-gif-23680990

[buoyant dagger]

"my dog ate my hw" head ahhhhh

[storm swan]

ima be honest

[buoyant dagger]

you aint fooling us man

[storm swan]

this is my test

im just dumb

so plz

help me

[buoyant dagger]

you lie to us twice

now you want us to do your test for you

[lyric dust]

poopman

we are emotionally hurt from that

[velvet badger]

If you didn't lie the first time, we would have helped you out, but it's haram to help a liar.

[lyric dust]

it is time to turn a new page and live an honest life

suffer the fate of this exam and live an honest life after this

[velvet badger]

I agree.

[lyric dust]

come back and ask when ur exam is done

dont try to cheat

[velvet badger]

Cheating is haram.

[storm swan]

https://tenor.com/view/spongebob-spongebob-mocking-gif-15817237996465785395

[buoyant dagger]

while youre at it brother

.close this post

[steady tide]

go back to your #help-36

[velvet badger]

I agree.

[steady tide]

.close

[odd edge]

Channel closed

Closed by @steady tide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chilly bridge]

how does 1/costheta - costheta = (1-cos^2theta)/costheta

[meager juniper]

Multiply cos theta by cos theta/cos theta

\begin{align*}
\frac{1}{\cos \theta} - \cos \theta &= \frac{1}{\cos \theta} - \cos \theta \cdot 1 \
&= \frac{1}{\cos \theta} - \cos \theta \cdot \frac{\cos \theta}{\cos \theta} \
&= \frac{1}{\cos \theta} - \frac{\cos^2 \theta}{\cos \theta} \
&= \frac{1 - \cos^2 \theta}{\cos \theta}
\end{align*}

[clever fjord]

OmnipotentEntity

[meager juniper]

@chilly bridge ^ does the above help?

[chilly bridge]

yes thanks legend

.close

[odd edge]

Channel closed

Closed by @chilly bridge

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime vortex]

can someone help me understand how i get 875

[amber schooner]

invNorm(0.975, 845, 15)

[lime vortex]

ph

[amber schooner]

what

[lime vortex]

oh*

ty

.close

[odd edge]

Channel closed

Closed by @lime vortex

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shadow fractal]

can aynone help with this?

[rigid dragon]

What part?

That looks like three problems

[shadow fractal]

the first

[rigid dragon]

So what’s the definition of a blinded set

Bounded*

[shadow fractal]

u tell me 😭

[rigid dragon]

No that’s not how this works my friend

I know the definition

I guess you’re telling me you don’t?

That’s okay

But I want you to find it

In your notes or textbook

Can you do that for me?

[shadow fractal]

there is exist a lower and an upper bound ?

[rigid dragon]

yeah exactly

a precise way to state it could be there exists a real number b such that for all x in A |x| <= b

can you find a real number that bounds the set {xy : x,y in A}

[shadow fractal]

ohh

[shadow fractal]

can i

if x <= b

and y is also in A

so y <= b

x times y <= b^2

sothere is a bound

[rigid dragon]

yeah thats pretty much a proof

[shadow fractal]

is that it

[rigid dragon]

the only thing is use absolute values

[shadow fractal]

yeah

i couldnt bothertyping that in pc

[rigid dragon]

or be careful to define upper and lower bounds

[shadow fractal]

thankyou man

or woman

or

[rigid dragon]

np

[shadow fractal]

may u enlighten me further ?

[rigid dragon]

first off

translate it to english

[shadow fractal]

for any X there exists and n in N ]

[rigid dragon]

or whatever natural language youre most comfortable with

i assume english

since the problem is in english

[shadow fractal]

i know the first 2 parts

but then y comes

and idk how to read it anymore

[rigid dragon]

the best way it to add a "such that"

i know that usually you translate : as such that

but

its also good when connecting an existence statement

so i would read it as: For all x in R There exists a n in N such that for all y in R x^n = y

[shadow fractal]

ahh

[rigid dragon]

do you think its true?

[shadow fractal]

ill pause this question for a second but

what if there was a 4th

lets say z in R

[rigid dragon]

is it for all or there exists?

[shadow fractal]

any Z in R

[rigid dragon]

then just say there exists n in N such that for all y and z in R

you would jsut combine them in english

but you wouldnt combine tehm in the FOl language

youd still write A y in R, A z in R

but shorthand notation is allowed

i would write A y,z in R

[shadow fractal]

hmm

[rigid dragon]

where A is the for all symbol

and in is the little e symbol

theres technically a very formal approach

but math proofs are about convincing other mathematicians that your logic is sound

it doesnt matter really unless youre treying to do automated proof on a computer

then the syntax has to be very particular

you'll learn to write proofs and youll develop idiosyncrasies

[shadow fractal]

i have my introduction to analysis final in a bit hahahah

[rigid dragon]

this is analysis?

[shadow fractal]

it is not looking to well as of right now

ye

[rigid dragon]

it seems you maybe are cramming then

best of luck tho

im surprised you didnt do a proofs class or discrete maths first

[shadow fractal]

NOPE

[rigid dragon]

good

how can you give a counter example

[shadow fractal]

its whatever

[rigid dragon]

first i would suggest negating the statement

[shadow fractal]

let x= 0 and n any N

[rigid dragon]

do you rememebr how to do that?

[shadow fractal]

you have to reverse every sign or smth

[rigid dragon]

yeah that would work perfectly fine

[rigid dragon]

yeah so thee exists become for all and for all become there exists

and you have to prove tehya re not equal

[shadow fractal]

Ex in R and any n in N such that Ey such that x^n is not equal to y

[rigid dragon]

so there exists x in R such that for all n in N there exists a y in R where x^n != y

[shadow fractal]

E = exists

[rigid dragon]

so you x=0, n any natural, and y = 1

thats a counter example

[shadow fractal]

hmm

[rigid dragon]

that's all you need to prove that its false

[shadow fractal]

okay got it i think

i understand the 3rd one now too i think

i will try and make this question with my newly acquired knowledge

Completely wrong or?

[rigid dragon]

uhhh

not completely wrong no

but some erroes

errors

you didnt define m

you dropped the absolute value

well actually

nvm the abs isnt even needed at all because you know that x and y are positive

so jsut be careful that you define m and dont reuse b

and it looks fine

[shadow fractal]

Now?

[rigid dragon]

i would have just done there exists a u in R

idk what you mean by u in B

its probably fine now

i have to go

[shadow fractal]

Cant you correlate u being in B1, which implies it being in A1, which implies x,y in R

[shadow fractal]

Okay thank you so much for your help

[odd edge]

@shadow fractal Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd edge]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hoary marsh]

Hello

[hoary marsh]

Not sure how to start

[dense mirage]

you have two equations with A, substitute the first into the second

[hoary marsh]

wdym two equations?

[dense mirage]

in the last line

[hoary marsh]

What does A[3, 2, 1] mean?

[lyric dust]

is this a uni linear algebra course or highschool

[late dust]

Do you understand what A is?

[dense mirage]

A multiplied with [3.2.1]

[hoary marsh]

Uni line alge

[lyric dust]

just started? (not to sound condescending)

[hoary marsh]

Yes

[hoary marsh]

Retaking 💀

[late dust]

Ok then write it out

[hoary marsh]

[(2, 1, 3), (-1, 4, 1), a_3]

[late dust]

Ok, pick some variables for the components of a_3

[hoary marsh]

x_1, x_2, x_3

[late dust]

then just do the matrix-vector multiplication

[hoary marsh]

Ohhh wait

This is Ax = b form

Am I stupid

[late dust]

Yes (this is Ax = b)

[hoary marsh]

This is easy af

Thank you guys

I'm acc high

.close

[odd edge]

Channel closed

Closed by @hoary marsh

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[atomic dock]

I see that B is the right answer why? C is smaller than 0
And a should be equal to or lager than 1 because it opens upward

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[atomic dock]

3

[steep mantle]

the rhs would be -4 correct?

notice how any real number when squared would give a non negative number, so it must be subtracted by some ammount to get -4

if c<0 then it would be added by some ammount instead of subtracting, making it impossible

[odd edge]

@atomic dock Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eternal sorrel]

if we start by proving the statement "K is compact relative to Y if K is compact relative to X" then cant we just say that this statement is clearly true since the finite subcover of K contained in Y is also contained in X

[odd edge]

@eternal sorrel Has your question been resolved?

[eternal sorrel]

<@&286206848099549185>

[mystic saffron]

roger

[eternal sorrel]

gol d

[mystic saffron]

🧭

i could help if i knew

can you breakdown the question?

[eternal sorrel]

do you know a bit of topology ?

[mystic saffron]

in networks?, yes

uhm nope

[eternal sorrel]

no in math

[mystic saffron]

rubber sheet geometry is not for my age i suppose

im 16

[eternal sorrel]

i am 18 but i learn higher level math because i am interested in it so i deepen my knowledge in math and have fun at the same time

[mystic saffron]

oh glad to know that

if i had time, i could do the same thing but

i have to prepare for competitive exams

jee mains and advance

so yup

[eternal sorrel]

ohhh nice

[mystic saffron]

yess

[mystic saffron]

im going to do it when i join a college

[eternal sorrel]

gl i hope you ace in these exams

[mystic saffron]

thankss

[eternal sorrel]

you are going to major in math?

[mystic saffron]

.. i dont quite get you

[mystic saffron]

i think, yes?

either way i would study math

[eternal sorrel]

ohh good to hear that

[mystic saffron]

yup

its the language of universe

[eternal sorrel]

yes and the process of thinking needed is something else

it is so fun even when you struggle to solve a problem or understand an idea XD

[eternal sorrel]

anyway if you want i can explain to you a bit about what this means

.close

[odd edge]

Channel closed

Closed by @eternal sorrel

Use .reopen if this was a mistake.

[eternal sorrel]

.reopen

[odd edge]

✅

[eternal sorrel]

isnt any subset of a compact set compact?

let K be a compact set and let W be any subset of K, since K is compact then there exists a finite collection of open sets {G_i} with i=1,2,...,n such that K is a subset of their union which also means that {G_i} is an open cover of W and thus W is compact

so why would the author talk specifically about close subsets of K instead of any subset of it

[meager juniper]

Well, compact is the generalization of closed and bounded in Euclidean space, right?

So what if we have the following set in R: [1, 4]

And then we have the following subset: (2, 3)

Clearly this is a subset, but it isn't closed, therefore it is not compact.

[eternal sorrel]

ohh yes i see i just proved that every compact set is closed and forgot about this fact the instant i hopped to try proving this theorem

thank you so much for your illustration

.close

[odd edge]

Channel closed

Closed by @eternal sorrel

Use .reopen if this was a mistake.

[eternal sorrel]

.reopen

[odd edge]

✅

[eternal sorrel]

but can you please point out the mistake in what i said above

[eternal sorrel]

here

[eternal sorrel]

<@&286206848099549185>

[drowsy yew]

?

[gleaming turtle]

That's not the definition of a compact set

You'd need to show that every open cover has a finite subcover

Not that there exists a finite open cover

[eternal sorrel]

ohhh yes thats it tysm

.close

[odd edge]

Channel closed

Closed by @eternal sorrel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail reef]

Write 𝑇(𝑛) for a triangular board of side-length 2n which is subdivided into equi-
lateral triangles each of side length 1. If a triangle shares one (or two) of its sides
with the large triangle, then it is called an edge triangle. If it shares two of its sides
with the large triangle, then it is called a corner triangle. A (triangular) triomino is a
tile consisting of three adjacent triangles.
d. For which n is it possible to tile the remaining board with triangular triominos after
any (one) corner triangle is removed from 𝑇(𝑛)? Provide a proof by induction.
e. Go to ChatGPT and ask it to prove that 7! − 2! is divisible by 5 for all positive
integers 𝑛. Print out the proof the AI produces, highlight the errors in the proof, and
explain why each error you identify is an issue.

[frail reef]

it's mathematical structures

[odd edge]

@frail reef Has your question been resolved?

[frail reef]

No

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

Just a simple question, but convolving those two yields just h[n] surely right

x[n] is just several dirac deltas running from 0 to 5

so you are just sampling h[n]

nvm its not

.close

[odd edge]

Channel closed

Closed by @long folio

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady cargo]

I need help on the first step which is getting common bases, I know how to solve the rest.

[long tinsel]

factorize 16 and 4

[steady cargo]

what after?

i got 2 to the power of 4 for 16 and 2 to the power of 2 for 4

[long tinsel]

So I assume you now have $(2^4)^{\f 13}(2^2)^{\f 13}$

[clever fjord]

krypton

[steady cargo]

yes

[long tinsel]

right so $(a^b)^c = a^{bc}$ for $a > 0$ and $b, c \in \set R$

[clever fjord]

krypton

[steady cargo]

oh okay thanks

.close

[odd edge]

Channel closed

Closed by @steady cargo

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brave tiger]

can some help me with radical in maths im in the 8 grde but pls in call****

[odd edge]

Please don't occupy multiple help channels.

[brave tiger]

hi?

[crisp wadi]

Like the bot said, don't open multiple channels

[winter berry]

you already opened one channel, close this one

nvm

[brave tiger]

how?

[winter berry]

other one was already closed

[crisp wadi]

I closed the other one, continue here

[brave tiger]

thx

can u help me with radicals

[winter berry]

what are you having trouble with specifically?

what about radicals in specific

[odd edge]

@brave tiger Has your question been resolved?

Channel closed

Closed by @brave tiger

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble apex]

i need help checking 4 Questons

[nimble apex]

.close

[odd edge]

Channel closed

Closed by @nimble apex

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brave tiger]

ich brauche hilfe in mathe 8 klasse wurzeln

[wet ferry]

konntest du auf englisch fragen

ah nein frag einfach auf deutsch

if muss mein deutsch üben

[brave tiger]

oke

kannst du in call?

[wet ferry]

nein sorry

[brave tiger]

oke warte

dort die nummer 10

[wet ferry]

ich kann nichts lesen diggi

kannst du die Foto von näher nehmen

[odd edge]

@brave tiger Has your question been resolved?

[odd edge]

@brave tiger Has your question been resolved?

[odd edge]

@brave tiger Has your question been resolved?

[odd edge]

@brave tiger Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal horizon]

I need help

[kind shuttle]

post what you need help with

[vocal horizon]

I don’t get it…

[kind shuttle]

x is larger and equal to negative 3 and smaller and equal to 5

[vocal horizon]

So I flip the sign?

[kind shuttle]

also its not asking for the range and only the domain so 0<=x<=6 would not be needed

[vocal horizon]

Ohh ok

So it’s -3>=5?

[kind shuttle]

-3<=x<=5

[vocal horizon]

Oh so I just didn’t have the x in the middle

[kind shuttle]

domain is for the values of x while range is for the values of y

[vocal horizon]

Ok…

I’m try this problem

I think I got it 🙂

[vocal horizon]

I need help again.. ☹️

[kind shuttle]

whenb its a cirlce instead of a dot

that means its not equal to the value'

so remove the equal sign

[vocal horizon]

Ohhhhn Tysm!

[odd edge]

@vocal horizon Has your question been resolved?

Channel closed

Closed by @vocal horizon

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal jewel]

Why is this not also 1 as a restriction? Also if this was vice versa, like g(x) was f(x) and yeah, then would it have two restrictions (IF SOMEHOW the end result was still 1/(x+2)^2. So that means that only the one inside matters like f(g(x)) for restrictions and the final f(g(x)) as a whole. Not the f(x)'s restrictions by itself?

[odd edge]

@tidal jewel Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense stone]

What is area of line EF when there's square ABCD and area of lines are AB=9,AD=12,AC=14

[hushed island]

can you show the original problem

[quasi falcon]

lines have no area my man, please send original problem, i guess you want length

[odd edge]

@dense stone Has your question been resolved?

[clever fjord]

fish

[odd edge]

@dense stone Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense stone]

?

[odd edge]

@dense stone Has your question been resolved?

[cyan latch]

is the answer 2?

[livid spoke]

you already have the values for AE and EC just make an equation you will get EF once you subtract EC from AF

[dense stone]

But area of line AE is unknown

[livid spoke]

you know the values for both AE and FC; angle bisector theorem

[cyan latch]

i got 2 from using sine and cosine rule

[odd edge]

@dense stone Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

✅

[odd edge]

@dense stone Has your question been resolved?

[dense stone]

I tried to get area of BE by $◿ACB=129/2 then 129/2/14 = BE$

[clever fjord]

아리스킨충1
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dense stone]

$\triangle{ACB}=12\ast\frac{9}{2} then \frac{12\ast\frac{9}{2}}{14} = \overline{BE}$

[clever fjord]

아리스킨충1

[odd edge]

@dense stone Has your question been resolved?

[odd edge]

@dense stone Has your question been resolved?

[sick pulsar]

Use angle bisector theorem

[odd edge]

@dense stone Has your question been resolved?

[autumn vine]

DC=9cm이므로 내각이등분선정리에 의해 AF:FC=12:9 이고
비슷하게 ABC에서도 내각이등분선정리 사용하면 정답 ||2|| 나옵니다

그리고 질문 전에 AI 사용하셔서 제대로 번역해 주시면 더 빠르게 답을 받을 수 있을겁니다

[odd edge]

@dense stone Has your question been resolved?

[mystic saffron]

Math 😭

[odd edge]

@dense stone Has your question been resolved?

[odd edge]

@dense stone Has your question been resolved?

[mystic saffron]

혹시 수능 보시나요?

[fading pike]

한국어 할 줄 아세요?

[mystic saffron]

넵

저 한국에서 태어났습니ㅏ

당신은요?

[fading pike]

저는 대구에서 태어났습니다.

[mystic saffron]

아 그러시군요

혹시 실례가 안된다면

몇살이세요?

[fading pike]

열일곱 당신은 어떻습니까?

[mystic saffron]

저는 만으로 열일곱이요

전 지금 영국에 거주하고 있습니다..

[fading pike]

멋진

[mystic saffron]

님은요?

[fading pike]

호주

sydney

[mystic saffron]

아 멋있네요!

저랑 삷이 비슷하신거 같은데

친구하실레요?

[fading pike]

물론이지!

gtg

[mystic saffron]

me too

[dense stone]

지금 그게 문제가 아니라 내각이등분선정리가 뭔지 모르겠음

[tidal jewel]

WHAT THE HELLL IS THIS LANGAUGEGEGE

[umbral kite]

korean

[mystic saffron]

AF/FC = AD/DC

= 12/9 = 4/3

[honest forum]

WTF ARE THESE HIEROGLYPHS?!

[mystic saffron]

its korean bro

[honest forum]

wtf

is this even a language

[mystic saffron]

its for smart people

u don't need to know

🙂

[honest forum]

blud didnt evolve

from hieroglyphs

[peak heron]

korean

[peak heron]

yes

[umbral kite]

how did this turn into language class

[gusty wyvern]

isnt that...

hangul

calling hangul korean is like calling mandarin chinese

[polar sleet]

알겠어요

[left pier]

yeah

[neat frost]

taehyung stans spotted

[south lichen]

This thread is so dumb lol

[umbral kite]

wtf lmao

[pastel orbit]

mhm

[sharp anvil]

bye what

[near phoenix]

hello

[dense stone]

지금 이게 무슨상황임

[grand mural]

몰루

[grand mural]

이 공식 쓰셈

[mellow valve]

JAJAJA

[jaunty pumice]

I didn’t think there were people on the internet that didn’t know Korean existed 💀

[jaunty pumice]

Translation please

[manic rose]

Goooogleeeee

[manic rose]

i luv orange cats

[jaunty pumice]

A thought doesn’t go through its mind

It just stares into space and then sleeps

[dense stone]

그게 정확히 두개가 겹치지만 짧은쪽인 부분의 길이만 남기는건 아닌것같아요

[grand mural]

뭔소리세요

님 풀이과정 좀

[left pier]

Lmao same 😭😭

[dense stone]

9:12=x:y,x+y=14 로 놓고 하나라도 구하려고 했음

그랬더니 x는 6이나왔고

그럼 BE=FD=6 이여야하지만 그와동시에 x+y=14가 아니라서 이상해짐

BE를 x,FD를 y로 놓고푼결과

조건이 이상한건지 방정식을 틀리게푼건지 모르겠어서 더 복잡해진거고

[warped urchin]

Are you sure its not chinesse

[young forge]

Looks more like Korean for me

In chinese there is more intersections and curves

[jaunty pumice]

Its Korean you can tell because of the eclipses

[grand mural]

비례식이니까 9:12=x:y를 12x=9y로 바꿀수 있잖아

Korean: 이건 한국어입니다.
Chinese(Used in mainland): 这是中文。
Japanese: これは日本語です。

[mystic saffron]

네네

[strange bear]

is there a korean dude out here to translate this i lost my korean doulingo streak yesterday

[mystic saffron]

What’s going on here💀

이 한문제를 며칠동안 풀다니…

https://tenor.com/view/respect-hat-cap-kid-gif-7551965

[errant jewel]

그러니까 💀

[dense stone]

그렇게 쉽게 안풀림

[grand mural]

난이도 중인데 뭔소리냐

[grand mural]

이걸 쓰면 30초내에 풀린다고

저 도형을 직접 그려서 풀어봐

[slow sandal]

you mean ellipses?

[sonic socket]

.close

[jaunty pumice]

Ya

[dense stone]

결국 값을 구하긴했는데 뭔가 이상함

[grand mural]

뭐나왔는데

[dense stone]

BE=FD=6

[zenith ferry]

https://tenor.com/view/omg-new-jeans-hanni-oh-my-oh-my-god-ditto-gif-27515218

[left pier]

newjeans spotted !

[mystic saffron]

💀

[quiet kettle]

이분 원래 전부터 중학교 기하문제 간단한거 갖고 1달씩 끌고 그러셨음..

전에도 말했지만 개념을 정확히 되짚고 다시 풀어보시는걸 권장드립니다

[dense stone]

처음부터 공식을 알고있어야 한다는거부터가 전혀 간단한게 아닌거같은데

[quiet kettle]

?

공식을 이해하고 알고 있는게 수학 문제 풀이의 기본인데요

그 공식을 제대로 이해하고 적용할 수 있는지를 보는게 중학교 수학 문제인데

그리고 보통 중학교 수학 문제집 보면 문제 나오기 전에 그 문제들을 풀기 위한 개념 설명을 할텐데

그거도 안보고 푸시는 건가요

[grand mural]

K-잼민 미치겠다

[lean willow]

молоко я люблю тебя да

[dense stone]

공식도 외우기엔 너무많은데 그거까지 외우는건 거의 불가능임

[mystic saffron]

하...

[manic rose]

Don't memorize it then. To be honest no one cares if you don't. It's your issue not ours, right?

[errant vapor]

Rules say English right?

[manic rose]

@dense stone Bro just close the channel at this point

[dense stone]

But I still don't know answer

[dense stone]

I even used formula but seems like it has error

[noble solstice]

https://www.cuemath.com/diagonal-of-parallelogram-formula/ might help @dense stone

you know x, y and the diagonal, from there find the angle

after finding the angle just complete the triangles with sine rule and whatnot

[left summit]

ㅋㅋㅋㅋㅋㅋ

[dense stone]

Do I need to use triangular function to solve this

[runic pulsar]

공식을 완벽하게 익히는 것이야말로 이 단원의 문제를 푸는 데 정수 ― 혹은 그 이상 ― 입니다.

이 단원은 특히 공식을 외워 쓰지 않으면 ― 대부분의 경우 ― 푸는 데 시간이 오래 걸립니다.

특히 도형은 공식 기초를 다져 놓고 풀어야 풀기에 수월합니다.

물론 공식을 외우지 않고 풀 수도 있겠지요. 안 될 건 없습니다.

하지만 그러면 시간이 너무 오래 걸립니다. 시간 제한이 있는 시험에서는 아주 힘들겠지요.

암기하는 데 어러운 점이 있는 것은 이해합니다. 저도 그랬고요.

한문장 요약: 공식을 익혀 풀자.

[dense stone]

그럼 이것도 공식없이 푸는게 가능한거였음?

[fading pike]

gaesaekki is the only word ik in korean

[quiet kettle]

이론상 님이 매우 머리가 좋으면 가능합니다

근데 그렇게 푸는게 님이 공식을 직접 유도해서 푸는거랑 별반 다를게 없음

결론적으로 어떻게 이 문제를 풀든 결국 님은 문제를 풀기 위한 공식을 사용할 수 밖에 없어요

머리가 좋아 공식을 모르고도 푼게, 실상은 님이 직접 공식을 알아낸 것이기 때문이죠

근데 님이 직접 유도를 할 정도로 머리가 좋지 않다면 다른 머리 좋은 분이 직접 유도한 공식을 이해하고 써먹을 수 있어야죠

그게 초중고 문제 풀이의 기본입니다

저는 그렇게 생각해요

이 상황을 빗대어 생각해보죠

님이 높은 나무에 위치해 있는 사과(문제)를 따고 싶다고 다른 분들께 도움을 요청하는 상황인데

여기 계신 분들은 사과를 따기 위해 사다리(문제를 풀기 위한 방법, 혹은 공식)을 사용하라고 조언해주고 있어요

근데 님은 지금 사다리를 들고 오기 힘들다고 싫다면서 사과를 따기를 요구하는 거에요

이러면 조언을 하는 저희 입장에서는 어쩌라는건가 싶어요

높이 있는 사과를 따려면 사다리가 필수적인데, 그걸 안들고 오겠다는게 말이나 됩니까

다른분들 생각은 저랑 다르거나 비슷하실 수도 있지만 제 입장에서 살펴본 생각을 얘기해 봤습니다

[quiet kettle]

그래서 이분 말씀처럼, 적어도 질문을 하기 위한 기본(공식 알아오기)은 해와야 질문하세요

기본이 안된 상태로 질문에 대한 답을 해봤자 님은 이해하지도 못하고, 저희도 답답해요

저분도 비슷한 맥락에서 그냥 채널을 닫는게 낫다고 하신것 같아요

[worn swallow]

damn longest time i seen a channel alive for

if you wanna learn a formula you can just understand it, that way it will take to it more kindly

in my class the teachers always makes us derive the formulas

also you could you translate to english so more people can help

as a lot of people here do not speak south korean

[mystic saffron]

비유 대박 👍

[regal vine]

그냥 지가 공부 안하고 징징대는거지 뭐

[left summit]

ㅋㅋㅋ

위에 읽어보면 ab/ac=bd/dc 증명 있을걸요

가장 중요한 건 보내주신 문제 자체에서 어떤 방식으로 풀라고 특정 짓지 않았다는 거에요

공식 쓰면 뒤지는 병이 있어요?

[left summit]

https://youtu.be/1YhhuxPICZQ

영상도 있어요

[dense stone]

이제 알았음

[left summit]

.close

,close

[errant jewel]

드디어!

[runic pulsar]

이름(아리스킨충)을 보니깐 롤 좋아하시는 것 같아 윗글의 내용을 조금 이용해 추가로 롤에 비유해 설명해 보겠습니다.

우리가 라인전을 할 때 상대 챔프를 보잖아요?

우리는 그 상대 챔프를 보면서, 그 스킬을 생각하면서 라인전을 합니다.

만약 내가 상대 스킬을 모르면 라인전이 힘들고 계속 죽겠지요

그러니깐 우리는 상대 챔프를 잘 모를 때 인터넷이나 유튜브에 검색하잖아요

이처럼 수학도 똑같습니다.

수학 문제를 풀려면 그 공식을 알아야 풀기 쉽고 없으면 풀기가 어렵습니다

새 챔프가 나올 때 우리가 스킬을 찾아보는 것처럼 수학 공식도 만약 새로운 개념을 배웠을 때 우리가 공식을 알아야겠죠

하지만 이런 생각이 들 수도 있습니다

"그냥 스킬 몰라도 하다보면 저절로 익혀지는데?"

맞습니다, 하지만 공식을 쓰지 않았다고 생각하기엔 바르지 못합니다.

그래서 이긴다 해도 결국 그 챔프에 대한 파훼법(공식)을 스스로 깨달은 것이죠

하지만 그만큼 똑똑하지 않아서 (혹은 다른 이유로) 그 챔프에 대해 파훼법을 스스로 깨닫지 못한다면

유튜브 같은 곳에 잘하는 사람들이 올려 둔 영상들을 찾아서 봐야 알 수 있습니다. 당연한 것이지요

만약 안 그러면 사람들이 왜 자꾸 죽냐고 욕합니다. 특히 랭전에서는요

수학도 마찬가집니다.

질문할 때 최소한 공식 정도는 알아와야 사람들도 친절하게 알려줄 수 있고 답답해 하지도 않겠지요

이처럼 공식을 외워야 풀기가 훨씬 수월합니다.

[mystic saffron]

뭐임ㅋㅋ

[warped urchin]

디디 파티 같은 파티는 없지

[gaunt owl]

I need help

[wet raven]

Parallel lines will have the same slope, i.e., the same coefficients for y and x

And you should know that the slope-point form of a line of slope m and passing through (x1, y1) is y-y1=m(x-x1)

use both of those to find the answer

[cinder halo]

This is very simple. Find the height of the parallelogram.

Use the height and base as an orthogonal basis to get the coordinates of E and F.

Then apply the appropriate skew transformation and then find the distance between E and F.

[dense stone]

I found BC:CE=9:AE but it is not enough

[cunning wyvern]

채널 안닫아요?

[dense stone]

공식을 알아도 안풀림

[grand mural]

그냥 안풀린다라고 하지말고 니 풀이과정을 보여주던가 어디에 막혔던가 이걸 알려달라고

그래야 니를 도와주던 말던지 하지

[dense stone]

BC:CE=9:AE 라는식을 얻긴했는데 더이상 방법을 못찾아서 막힘

[runic pulsar]

AD = BC = 12cm

AB = CD = 9cm

내각 이등분선 정리 사용

||AF : EC = 4 : 3

AE : EC = 3 : 4

AF = AE + EF

AE : EF : FC = 3 : 1 : 3

14 × 1/(3+1+3)

2||

@dense stone

[bitter folio]

uh <@&268886789983436800> the rules say 'primarily english' so idk if this counts

sorry for the ping if nothing's wrong

[viscid flint]

is fine in question channels

[bitter folio]

ah okay ty for the clarification

sry for disturbing

[dense stone]

이제 풀렸음

[quiet kettle]

이제 채널 닫죠

[dense stone]

/close

.close

[odd edge]

Channel closed

Closed by @dense stone

Use .reopen if this was a mistake.

[dense stone]

아직도 안닫힌거같은데

[dense stone]

이거 왜이럼

[dense stone]

.close

[celest ingot]

Cuál es el signo sigma?

[mystic saffron]

이거 뭐꼬?

이 채널도 빡친듯

[pastel orbit]

oh hey, it's finally closed

[dense stone]

아직도아님

[manic rose]

lmao

[left summit]

그냥 아린스킨충1 님이 계정을 삭제하시는 게 더 빠를 듯

[drowsy venture]

안녕하세요 도움이 필요하신가요

[left pine]

This is awesome<3

[mystic saffron]

.reopen

。。

[kindred flume]

이, 이게뭐냐;;

[graceful elk]

안늉~

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[small pivot]

Does the -2 in front of the three factors have an impact or not?

[small pivot]

For the table of signes

[sand horizon]

Oui

Il y aura une ligne réservé au -2 avec que des moins tout le long

[quasi sparrow]

,rccw

[odd edge]

@small pivot Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

I know how to read steam and leaf diagrams, just not how to get the interquartile range

from here

[small pivot]

Merci, mais comment tu sais que je parle francais? Ah oui mais c'est aussi avec les nombres positives?

[mystic saffron]

[sand horizon]

#help-48 message

[sand horizon]

Sorry!

[mystic saffron]

It’s fine

Pfp is cute so I forgive him

[wanton bison]

word up

[quasi sparrow]

https://www.intellectualmath.com/finding-quartiles-from-stem-and-leaf.html

[quasi sparrow]

can you find median? then Q3 and Q1?

[mystic saffron]

I can do the median

Is it 50

[quasi sparrow]

Q1 = median of the minimum and median

[mystic saffron]

Oh

[quasi sparrow]

Q3 = median of the median and maximum

[mystic saffron]

im a bit confused

[quasi sparrow]

that was probably an abuse of words

consider this as a "new" stem leaf plot

50 is now the minimum and 64 is still the maximum

[quasi sparrow]

assuming you're correct

[mystic saffron]

I wouldn’t trust me

[quasi sparrow]

find the median of this "new" set

[mystic saffron]

ohk

[pastel orbit]

[mystic saffron]

Hi higher!

[mystic saffron]

is it 57

[quasi sparrow]

oh you're right about being wrong

52 is the median

[mystic saffron]

Wow

Im quitting maths forever

[quasi sparrow]

no just kidding i can't count

50 is right

[mystic saffron]

Ok one sec let me rub everything out

Oh

SMH

[quasi sparrow]

57 is right

[mystic saffron]

yay

[quasi sparrow]

so that's Q3

[mystic saffron]

Then do the same for the first portion?

[quasi sparrow]

yes

[mystic saffron]

Ok one sec

Is it 42

[quasi sparrow]

yes

[mystic saffron]

And then u do 57 - 42

To get 15

Is that the final answer

[quasi sparrow]

should be yea

[mystic saffron]

oh okk

tysmm

.close

[odd edge]

Channel closed

Closed by @drifting pelican

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy wasp]

Anyone know convex optimization? I found a projection for a set S representing hollow sphere in n dimensions with radius 1, (norm squared of x = 1 for all x in the n dimension) which is x / norm x if norm squared x != 0 and any pt in x if x = 0, how can I show that if norm squared x != 0 then norm of projection of x minus x <= norm of y - x for all y in the set S?

[odd edge]

@dreamy wasp Has your question been resolved?

[dreamy wasp]

<@&286206848099549185>

[odd edge]

@dreamy wasp Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone drift]

I have a math final in five days and my professor gave us a preview on the questions we should expect, he told us the best way to prepare would be to make new problems based on the study problems we did in class so I wanted to get help with that here. I didn't want to try and make them on my own since I'm worried I'll create questions that are too easy and won't let me understand what's being asked of me. Could I get help in this channel with making practice test questions here?

[mental storm]

try looking at your study problems and making variations on those

[odd edge]

@stone drift Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky hemlock]

yo

[dusky hemlock]

I need help finding teh derivative of ts

[velvet heart]

explain your steps

[dusky hemlock]

so from her

I got 2x for the first one

and then I was trying some product rule thing

after multiplying the four out

not product but qoutient

so I would get the [(0)(x^2)-(2x)(204800)]/x^2

and I simplieifed and took out the x

[velvet heart]

$x^2 + 4x \left( \frac{256000}{x^2} \right) = x^2 + \frac{4 \cdot 256000 \cdot x}{x \cdot x} = x^2 + \frac{4 \cdot 256000 \cdot \cancel{x}}{\cancel{x} \cdot x} = x^2 + \frac{1024000}{x}$

[clever fjord]

kaue

[velvet heart]

the second term can be simplified

[dusky hemlock]

so would the derivatvie be

2x-102400x^-2

[velvet heart]

yeah

[dusky hemlock]

alr thank you

[velvet heart]

three zeros tho

[dusky hemlock]

also w album chromakopia

ye I realised

[velvet heart]

true

[dusky hemlock]

real quick

fav song off it?

[velvet heart]

like him !

[dusky hemlock]

yessir

my fav aswell

.close

[odd edge]

Channel closed

Closed by @dusky hemlock

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden wave]

What are the dimensions of a can that has a 0.5 leater volume

[fossil current]

there are infinitely many possibilities, you need another constraint

[wooden wave]

just one of the pssiblitys

plz

[fossil current]

10cm x 10cm x 5cm

[wooden wave]

thanks

[fossil current]

bc 1 liter is 1000cm^3

[narrow crypt]

Any can with dimension that satisfies ${0.5 = \pi r^2 h}$?

[clever fjord]

k

[fossil current]

yes

oops i was thinking box lol

[odd edge]

@wooden wave Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rose pawn]

How do i find the Horizontal Asymptote

This is precalculus

[glad anchor]

i dont think it has one

[ancient rampart]

not sure how you'd analyse all this without calculus

[glad anchor]

if you perform polynomial long division i think you'll get the slant asymptote

just ignore the remainder term

(goes to 0)

[forest sky]

in general for rational functions, we have three cases:

• if the degree of the numerator is higher, there is no horizontal asymptote
• if the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is the ratio of the leading coefficients
• if the degree of the denominator is larger, the horizontal asymptote is 0

[odd edge]

@rose pawn Has your question been resolved?

Channel closed

Closed by @rose pawn

Use .reopen if this was a mistake.

[rose pawn]

.reopen

[odd edge]

✅

[rose pawn]

Tysm

.close

[odd edge]

Channel closed

Closed by @rose pawn

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith ledge]

can someone help me question ii

[main creek]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[zenith ledge]

i sent a screenshot with the start of what i did

[prisma egret]

Rotate \overrightarrow{AC} 90 deg. \overrightarrow{AC} \mapsto (-1, -2). Then \overrightarrow{AC} \dot \overrightarrow{AB}

[zenith ledge]

i think we can see that I don’t have an answer and that ive gotten stuck

[main creek]

do you know how to find a vector perpendicular to q?

[prisma egret]

of course, since i is solved

[odd edge]

@zenith ledge Has your question been resolved?

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade pagoda]

∀x∃yRxy→Pa entails ∀x∃y(Rxy→Pa)
is this a counter-model?
D={1,2}
a:1
P={}
R{<1,2>}

[odd edge]

@jade pagoda Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent wagon]

I need help with these

[odd edge]

@latent wagon Has your question been resolved?

[warped glacier]

what have you tried so far?

[latent wagon]

I think I got the first one with Y=0.3*x^2(x-2)(x+3)

But I’m so lost on the second one

[warped glacier]

ah okay, then just follow the same strategy as before

you have (x + 1)^2, (x - 2)^2, and (x - 4)

so you must have y = k (x + 1)^2 (x - 2)^2 (x - 4) for some real number k

[latent wagon]

I do but how do I get the y axis to 8

[warped glacier]

then you just sub in x = 0 and y = 8

so you can find k

[latent wagon]

Ok thank you

[warped glacier]

no worries!

[odd edge]

@latent wagon Has your question been resolved?

[warped glacier]

.close

[odd edge]

Channel closed

Closed by @warped glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin quarry]

ew is that inverse

[odd edge]

@heady plover Has your question been resolved?

[summer kite]

It's 4

The answer is 4

Trust pookie

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[peak maple]

Ik u integrate to get displacment

but why do they need that here

.close

[odd edge]

Channel closed

Closed by @peak maple

Use .reopen if this was a mistake.

[peak maple]

.reopen

[odd edge]

✅

[peak maple]

how do i do 6b

wait nvm

.close

[odd edge]

Channel closed

Closed by @peak maple

Use .reopen if this was a mistake.

[peak maple]

.reopen

[odd edge]

✅

[peak maple]

wait acc idk how to do it

I tried to integrate it

[cursive field]

just integrate and take the absolute value?

[odd edge]

Show your work, and if possible, explain where you are stuck.

[peak maple]

so integrating 8t-3/2t^2

[tacit wasp]

Or maybe you can recognize that is a uniformly decelerated motion

[cursive field]

aaaaaaaaand how does that help

[peak maple]

gives me 32t^2 - 1/2t^3

[cursive field]

no

no it doesn't

[peak maple]

+c

wait

[cursive field]

the t^3 term is correct

[peak maple]

lemme do that again

[cursive field]

no, c = 0

because at t = 0, the object is at the origin i.e. distance 0

[peak maple]

idk wtf im doing

[tacit wasp]

Oh sorry yeah that's velocity not the space

[peak maple]

haha

erm

4t^2

• 1/2t^3

[cursive field]

yep

[tacit wasp]

Forget this @peak maple
I was completely wrong

[cursive field]

4t^2 - 0.5t^3 + c

now what do you think "c" is?

[peak maple]

yeah i didnt get it anyway

[odd edge]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[peak maple]

i thought u said c is 0

[cursive field]

yes, but think about why

we won't always be there to tell you yk

[peak maple]

idk 🙉

[cursive field]

okay

[peak maple]

oh wait

u mentioned

[cursive field]

yeah?

😭

[peak maple]

i was thinking smthing about P being at origin as well

[cursive field]

good

[peak maple]

ye

[cursive field]

see the thing is

to isolate c

all the other terms must be zero

so you can set t = 0

but at t = 0 the object is at the origin (it's mentioned) so the distance is 0

i.e., x(0) = c = 0 -> c = 0

so you get x(t) = 4t^2 - 0.5t^3

now just set t = 4 and you're done

[peak maple]

ah ok thank you

.close

[odd edge]

Channel closed

Closed by @peak maple

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy grove]

someone explain me why this limit is indeterminate

[velvet heart]

its a cosine, so it probabilly oscillates

,w graph cos(pi*sqrt(x² + x))

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by wkaue

[velvet heart]

,w graph cos(pi*sqrt(x² + x)) from 0 to 100

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by wkaue

[velvet heart]

yeah

[icy grove]

this is why i asked that weird limit in the other channel

this is the solution my teacher gave me

i wasnt really satisfied with wolfram ai's answer, so here i am

[velvet heart]

i don't think (-1)^n * cos(pi/2) goes to 0

[native canopy]

nice

[velvet heart]

oh its pi

[native canopy]

cos (90)

0

alwahys

[velvet heart]

right

[native canopy]

regardless of n

[icy grove]

um

im confused

the graph suggests something else

this proof also seems convincing

[velvet heart]

,w graph (-1)^n cos(npi - pisqrt(n² + n)) from 0 to 20

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by wkaue

[icy grove]

ah ha!

found it

both the ns are not the same

right?

[native canopy]

seems good.... one thing is not limiting the (-1)^n seems a bit sus to me

[icy grove]

but wait a second, if n is large, we should be able to approximate it to the nearest integer

i dont get it

[native canopy]

you're trying to solve for L given n->inf right?

[velvet heart]

something is wrong on the step 1 to 2, as the first oscillates and the other shrinks to 0

[icy grove]

yes

[velvet heart]

,w cos(pisqrt(n² + n)) = (-1)^n * cos(npi - pi*sqrt(n² + n)) true or false

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by wkaue

[velvet heart]

,w lim_{n to infty} cos(pisqrt(n² + n)) = lim_{n to infty} (-1)^n * cos(npi - pi*sqrt(n² + n)) true or false

[icy grove]

i think the coefficient of pi and the n in the function are not the same

[clever fjord]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by wkaue

[icy grove]

<@&286206848099549185>

[odd edge]

@icy grove Has your question been resolved?

[autumn bolt]

infinity + infinity is infinity

we cant find out the value of trigonometric functions in infinity

(EXCEPT when it approaches some value)

but it oscillates here

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx sky]

hello

[mystic saffron]

hi

[onyx sky]

can someone help me solve this? im stuck on it

<@&286206848099549185>

[chilly narwhal]

Have you learned power of a point theorem? This should come in handy here I believe

[onyx sky]

tried it, couldnt manage

its cause i took this lesson months ago

and missed something and now i have to solve this thing and i forgot a bunch of stuff

do you know what x and y are here

[chilly narwhal]

I’m pretty sure I do

[onyx sky]

do u think u cn help

[chilly narwhal]

yes, first find x here

[onyx sky]

what?

[chilly narwhal]

You should first find what x is in the diagram

[onyx sky]

how can i do that

[chilly narwhal]

By power of a point theorem. Here is a link that gives some info and practice problems that use it as an exercise: https://artofproblemsolving.com/wiki/index.php/Power_of_a_Point_Theorem?srsltid=AfmBOoqfgB7oWe3cSlxAh9-Sau6FoZ-szh25WW2ja9L-3BDLbcGet1PY

[chilly narwhal]

notice that you have one line is a tangent and the other line is a secant. Then apply power of a point (aka pop) here

[chilly narwhal]

then once you find x here, you use pop again to find what y is

[onyx sky]

is x=9

[chilly narwhal]

no

[onyx sky]

thats what i came at with

[chilly narwhal]

wait, how?

could you show your working

[chilly narwhal]

isn’t the tangent length x here?

[onyx sky]

oh yes

so is this correct

[chilly narwhal]

yes

[onyx sky]

so x is 6.71?

[chilly narwhal]

roughly yes

do they allow that?

[onyx sky]

yes

[chilly narwhal]

okay