maybe
#help-19
onyx cloak
mystic saffron
so its a cubic equation
xyz = t
2t^3 + 3t^2 -1 <0
(t+1)^2(2t-1) <0
now whattt
😩
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onyx cloak
3/4 is when it's (0,1)
i don't get why it would be that for [0,1] tho
can't u just plug x=y=z=1 and get -1 (which u did)
mystic saffron
can't u just plug x=y=z=1 and get -1 (which u did)
nope for some reason
want explanation for that too
onyx cloak
3/4 is when it's (0,1)
but why
even if it's (0,1)
plug x=y=z=0.99, you still get negative answer
why is 3/4 min
odd edgeBOT
@mystic saffron Has your question been resolved?
odd edgeBOT
@mystic saffron Has your question been resolved?
odd edgeBOT
@mystic saffron Has your question been resolved?
cerulean spindle
I was given a math assignment and I'm pretty sure this question is wrong;
For this question, you're supposed to both complete the square and partial factor this equation: f(x) = -x^2 + 2x - 5, once you're done that you have to state the vertex and min/max
I got the vertex 1 and -4 for completing the square, but I got -1 and -8 for partial factoring.
I've been trying to double check my work, but I really don't see a mistake on my part, any help?
mystic saffron
show ur work
proven harbor
can you show us your work?
cerulean spindle
forest sky
x - 2 = 0 means x2 = -2?
cerulean spindle
ignore the min on completing square
cerulean spindle
ahhhh
got you
alr ill make sure to double check my work next time lol
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cerulean spindle
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cerulean spindle
wait it still doesnt solve the question though
because the x vertex would be 1
and you would substitute it in -(1)^2
so it would still be -1
oh wait
im stupid
IM STUPID
IM SORRY
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odd edgeBOT
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granite plover
find the equation of a straight line that passes through the points A(3,-3) and B (4,-2). What is the gradient of the straight line?
mystic saffron
the formula for the gradient is:
y2-y1 divided by x2-x1
let y = mx + b be the equation of this line
put m found above as the gradient
Then put y = -3 or -2 from the two points satisfying and find b (the y intercept)
You equation is now complete
granite plover
my question is do i find out the equation of the straight line passing through first, then find out the gradient or find the gradient of both points
random bane
The gradient will be the same at the two points: it is the constant m in the form y=mx+b
You need to find the gradient to find the equation
granite plover
im still kinda confused
like i found the gradient out
now do i use the y=mx+b formula
upper pike
in this formula, m is the gradient
granite plover
like in class the teacher used the point slope formula
thick fiber
then use y-y1 = m(x-x1)
they are just different forms of the same equation of the line
granite plover
ic
thick fiber
then use y-y1 = m(x-x1)
m is gradient, y1 and x1 from any point you choose
granite plover
like
thick fiber
the gradient you mean?
random bane
Yeah but usually we write it in terms of y
Not exactly, be careful with the negative signs
upper pike
isnt b=-6
random bane
It should be y=x-6
odd edgeBOT
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neon quail
how does the top one become the lower?
odd edgeBOT
how does the top one become the lower?
quasi sparrow
$\frac{1}{x} \cdot y = \frac{y}{x}$
clever fjordBOT
riemann
neon quail
so, since the numerator on the left is 1, then the factor on the right becomes the numerator?
west hull
$\frac{a}{x} \cdot y = \frac{ay}{x}$
clever fjordBOT
mari
raven parcel
I'm not sure how to approach this, my guess would be plug into sin-1(x)
amber schooner
only problem is inverse sin gives values in Q4 and Q1
so you’ll have to do more work
raven parcel
sure, if you even have a youtube video on the topic that would be fine too
but i really dont know what to do
raven parcel
what do i do
amber schooner
think of arcsin as giving you the reference angle
raven parcel
then what
amber schooner
i’m not going to give you the answer lol you can try and figure it out
we want the angle to be in Q3
are you not familiar with reference angles?
raven parcel
because its negative, go clockwise into quadrant 3, and go -9.693 past 180?
i am familiar
amber schooner
well 9.693 after 180 but yea
raven parcel
but its negative
clever fjordBOT
clever fjordBOT
amber schooner
bruh
amber schooner
yea
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faint acorn
How does 33 and 1 over 3% end up being 0.6%?
odd edgeBOT
How does 33 and 1 over 3% end up being 0.6%?
quasi sparrow
markup is 60% which is 0.60 in decimal form
faint acorn
so what is that 33 there for?
quasi sparrow
nothing in the solution suggests they used 33 and 1/3%
faint acorn
my teacher is just playin w me than
quasi sparrow
¯_(ツ)_/¯
faint acorn
ive been looking
at this bs
for like 30 mins
this one question
even chatgpt called me a idiot
anyway ty lmao
@quasi sparrow do those multiply to 212.80?
my calc is giving me sumn else
faint acorn
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bold current
help
bold current
i have no idea how to approach this
can anyone give me a starting point
i just corrrcted that expansion and simplifies to 3!
but that can’t be a partial fraction
quasi sparrow
i just corrrcted that expansion and simplifies to 3!
The entire fraction doesn't equal 3!
use (n+3)! = (stuff) * n!
Find stuff from the definition of factorial
quasi sparrow
use (n+3)! = (stuff) * n!
You didn't do this yet
(n+3)! = (n+3) * (n+2)!
Repeat two more times
quasi sparrow
use (n+3)! = (stuff) * n!
Then find what stuff equals
odd edgeBOT
@bold current Has your question been resolved?
bold current
ah ok i didn’t realise i could expand it like that i think i missed the lesson on factorials w variables
i think i’m getting there now will continue this
quasi sparrow
I don't know why you still have n!
quasi sparrow
use (n+3)! = (stuff) * n!
Should have been cancelled with this
You correctly have stuff = (n+3)(n+2)(n+1)
Also after you set up your A/(...) + B/(...) + C/(...) = 6, you didn't multiply all denominators
Only the B fraction is correct
bold current
got that now
naive field
1+1=?
bold current
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stuck rock
Honestly I'm not sure how to do this problem because the absent harvesting is tricking me. Is the question essentially implying I'm adding a harvest +-c that I need to figure out the equilibrium for? (The most optimal, where sqrt(KM^2-4kh) = 0?)
stuck rock
Also that y(0) = 510. That means that at the start of the fishing, the population is 510?
mystic saffron
Also that y(0) = 510. That means that at the start of the fishing, the populatio...
usually after solving a D.E you are left a constant c whose value is not known
inorder to find it, you are given a condition(inthis case the initial condition)
substituting it helps in finding the value of c
stuck rock
Hmm
So should I integrate this or does C just kind of exist here to make the condition true?
Ok wait I see
It's a function of t so I can't plug into this eqn
mystic saffron
what happens when you integrate a function ?
yu are left with a constant!
mystic saffron
It's a function of t so I can't plug into this eqn
have you already solved the D.E ?
stuck rock
No I didn't even think of that
Most of the autonomous equations section didn't really involve much integration at all
mystic saffron
It's a function of t so I can't plug into this eqn
then what is the equation that you mentioned over here?
mystic saffron
what?
stuck rock
My initial condition is a function of time
mystic saffron
is this a test ?
stuck rock
No
mystic saffron
okay
stuck rock
On lumen you wouldn't see score idt
mystic saffron
i believe you should solve the D.E
then
say its y(t)
lets say at the start of first year the fish population is y(t_1)
and at the end after harvesting x fish(whcih is constant every year) we are left with y(t_1)-x
again at the start of 2nd year (i.e before fishing) we have y(t_2) new fish and also the existing Y(t_1)-x fish
so total would be
y(t_1)+y(t_2)-x
after fishing we are left with y(t_1)+y(t_2)-2x
noww this should be equal to the number of fish we had in first year
which is y(t_1)
so we have y(t_2)=2x
voila
but this feels so wrong
logic is good though
makes sense
stuck rock
It does
It just feels like that is far from what the lecture was poking at
Most of the harvesting equations I've done where I need to find the optimal h has been with the quadratic equation where the radical is equal to 0
but here it's absent of harvesting originally
Let me try just arbitrarily adding an H
Maybe I'm overcomplicating this
odd edgeBOT
@stuck rock Has your question been resolved?
stuck rock
Yeah I'm just not sure at all honestly this doesn't seem to be working
So that should be my optimal harvesting
odd edgeBOT
@stuck rock Has your question been resolved?
dapper raptor
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dapper raptor
How does it go from last equation to the vector projection formula?
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@weak ferry Has your question been resolved?
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hollow socket
Pls help me to understand metrics
odd edgeBOT
Pls help me to understand metrics
hollow socket
first 2 lines I kinda understand because its related to functions
but then metric density and integral confuse me completely
<@&286206848099549185>
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@hollow socket Has your question been resolved?
hollow socket
<@&286206848099549185>
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@hollow socket Has your question been resolved?
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@hollow socket Has your question been resolved?
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@hollow socket Has your question been resolved?
hollow socket
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vernal pelican
?
sinful spruce
?
vernal pelican
Is this physics or maths?
hollow socket
metric spaces has nothing to do with physix
fringe solstice
Pls help me to understand metrics
the last integral here is the arc length of a real, differentiable, one-variable function f: [0,1] -> R
frankly I don't think it has much to do with the previous line since it seems you're trying to define a metric in a more general domain D in some R^n?
in that case, you should be able to do so picking some positive continuous function $\rho: D \to (0,+\infty)$ as in there
clever fjordBOT
derivada.schwarziana
fringe solstice
and then considering path integrals of that function
hollow socket
in that case, you should be able to do so picking some positive continuous funct...
yes it was introductory class to metric spaces (and won't go much further than that since this is real analysis I course) but things escalated really quickly and I couldn't follow hence why I am confused
what about completeness and compactness in a metric space?
like what's the definition
fringe solstice
what about completeness and compactness in a metric space?
a metric space is complete if every Cauchy sequence converges, i.e. has a limit point
a metric space, or a subset of it is compact if every covering of it by open sets has a finite subcovering
there are other equivalent definitions of compactness, e.g. every sequence has a convergent subsequence
hollow socket
there are other equivalent definitions of compactness, e.g. every sequence has a...
ohh is this Bolzano Weierstrass theorem? I think I learned it by that name
fringe solstice
ohh is this Bolzano Weierstrass theorem? I think I learned it by that name
yep that's it
hollow socket
yep that's it
okay, so umm what are density and geodetic line? Density seems to be related to compactness, completeness and sequences in metric spaces but I don't see the point of geodetic line being introduced here
fringe solstice
okay, so umm what are density and geodetic line? Density seems to be related to ...
a geodesic is, in simple terms, the shortest path between two points in some space; doesn't seem like this is what's being introduced here
and I don't think densities are immediately related to any of these things either
"density" has varying meanings in math but the most usual one is density relative to e.g. a measure
which is kinda what's being done here: a "density" relative to the euclidean distance
basically it's a function that assigns more "weight" or "more distance" to certain points in the space
hollow socket
basically it's a function that assigns more "weight" or "more distance" to certa...
okay thanks
odd edgeBOT
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late halo
Find dy/dx if y^2= x^2+sinxy
odd edgeBOT
Find dy/dx if y^2= x^2+sinxy
late halo
Hello
If anyone would like to assist me here
i’m trying to understand calc
i’m stuck here
nimble blaze
you essentially have a linear equation in y'
distribute,
separate thems with and without y'
pretty much do what you'd do if asked to solve
p +qt = r(t + s)
for t
nimble blaze
you've pretty much already done the calculus component
you don't need to worry about calculus anymore
late halo
oh
nimble blaze
the rest is basic algebra
pretty much do what you'd do if asked to solve
p +qt = r(t + s)
for t
nimble blaze
do what i just quoted
late halo
> pretty much do what you'd do if asked to solve
> p +qt = r(t + s)
> for t
I sukc so don’t mind me but erm wouldn’t it be
r(t+s)= t= (r-s)
or would it be t(r/s)
nimble blaze
neither
late halo
oh yeah i’m cooked
nimble blaze
you'd need to go back and review algebra
it'd really slow you down with calculations
solving for a variable is one of the first things that are taught
late halo
yeah
signal rampart
odd edgeBOT
signal rampart
im done w/ 9a, but im super confused about 9b
honestly i think in general i dont understand implicit differentiation
mystic saffron
I think we have to find the derivative of root3/4 (s^2)
signal rampart
could you write that in traditional notation? Sorry, it’s a bit confusing to read rn
signal rampart
I think we have to find the derivative of root3/4 (s^2)
also one question, why is dydx of y^2 equal to 2y(dydx)?
odd edgeBOT
@signal rampart Has your question been resolved?
torn sparrow
do you know the chain rule ?
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plush birch
How do I complete this and find the real solutions? Throwing factions in the exponents seems to have completely wiped my mind of how to even start solving this
plush birch
How do I complete this and find the real solutions? Throwing factions in the exp...
I would use the quadratic formula but the exponents are throwing me off
topaz tangle
changing variables doesn't work? like, set $z = x^{\frac{1}{3}}$
clever fjordBOT
combinatorics hater please
odd edgeBOT
@plush birch Has your question been resolved?
plush birch
changing variables doesn't work? like, set $z = x^{\frac{1}{3}}$
okay ty, ive been trying for the last few minutes but ive only been getting 8 and -1/8
which it says isnt the right answer, so im not sure where to go from here when it comes to the solution set
topaz tangle
,ask solve 8z^2 - 15z - 2 ==0,z
clever fjordBOT
plush birch
hm
I GOT IT
I CHANGED THE VARIABLES AND THEN SOLVED FOR THE VARIABLES
THANK YOU
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outer wadi
Im a bit confused on something
odd edgeBOT
Im a bit confused on something
outer wadi
so I was trying to solve this problem explaining my way through it, but I came across soemthing I dont think I understand
is this information right
At the end there I was going to finish that statement but I wasnt sure if it is completely true
I'm trying to use this
but in this case p = (x,y) in R2
where in my question z = x + iy in C
and I believe when we parametrize z it is z = a1(t) + ia2(t)
but can we say z = a(t) = (a1(t), a2(t))
I read that z = a + bi corresponds to the point (a,b)
so if we have z = a1(t) + ia2(t)
is that equal to (a1(t) , a2(t))
sinful grove
I read that z = a + bi corresponds to the point (a,b)
I would say yes, but it depends on the definition. Commonly they’re defined that way atleast or up to isomorphism
outer wadi
I would say yes, but it depends on the definition. Commonly they’re defined that...
so if we have a piecewise smooth parametrization of Gamma in C, say a, then we can treat all z in Gamma as (a1(t), a2(t))?
outer wadi
and that allows us to represent the integral f(z) on Gamma as this?
sinful grove
Iirc yeah basically
sinful grove
and that allows us to represent the integral f(z) on Gamma as this?
Though the integral being written specifically like that is more due to differential forms
outer wadi
hmm its just kind of hard to accept z = a + ib = (a, b) because I dont really understand why we can say that in this case
it makes sense
but I dont really understand why we can do it
like in the book
sinful grove
I’m actually a bit unsure if it “follows” from viewing complex numbers as a pair of real numbers. I would say the reason (if that’s the formula you were given) is just due to definition
outer wadi
they replace z with gamma(t)
sinful grove
I’ll let someone else chime in, because I’m a bit unsure now
outer wadi
they said recall if gamma is parametrized by gamma(t) then that follows, but they only mentioned that if gamma was in R2 earlier in the book
sinful grove
Hm feels more like reassuring the reader that it feels acceptable to define something similar, unless of course this is due to how they’re defining complex numbers (as pair of real numbers)
outer wadi
hmm ill just take it as is for now and maybe ill understand more when I take a complex analyis course rather than complex variables
idk if you can advertise in here 😭
but like i'd imagine thered have to be some reasoning that treating z as if it were in R2 doesn't affect the value of the integral, like here they are basically saying the integral in R2 and C would give the same value I believe
sinful grove
like in the book
Like I get that since the real and imagery parts are strictly real numbers and they’re integrals in this case we can just view Gamma as a set in R^2, but it’s this viewing Gamma as R^2 which heavily depends on definition if it’s equality or otherwise as isomorphic, but I’m not sure that ensures we have the same value for the integral as a whole. Hopefully someone else can chime in and make that more clear!
outer wadi
hopefully but if not I could always ask my professor whenever I get the chance
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dapper raptor
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dapper raptor
how does the 1st question make sense? Why should we set it to 1?
near gazelle
The derivative of x wrt x is 1
winged leaf
the question is "The x-intercept of the function g(x) = 1/2x - 3 lies between which 2 integers?" i got that the x int is 6. which answer choice should i choose
winged leaf
would i pick between 6 and 7 or between 5 and 6?
i just realized i put the negative so samll on paper i couldnt read it 💀
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dapper raptor
what's linear and quadratic factors?
odd edgeBOT
what's linear and quadratic factors?
icy kindle
factors of a polynomial that are degree 1 or 2, and not themselves factorable
like, x^3 - x^2 + x -1 = (x - 1)(x^2 + 1) has a linear factor x - 1 and a quadratic factor x^2 + 1
dapper raptor
wheat flame
there is a usual factorization for the sum of two cubes, search it up
it will be one linear and one quadratic factor
dapper raptor
is it the (a-b)(a+b)^2?
icy kindle
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earnest cairn
im watching video about gcf, for 60 why did he split it into 15x4? instead of 30x2,20x3,12x5 etc. he didnt say
earnest cairn
does it have to be split into specific numbers?
cold sage
not really, id probably have done it as prime factors too, but as long as you get there in the end you can split it however you want
odd edgeBOT
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void echo
just wanted to see if i solved it right
odd edgeBOT
just wanted to see if i solved it right
odd edgeBOT
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tame tendon
I've been super confused on this question and need help understanding it. The example used and everything has confused me. I need a clear explanation on this whole problem.
onyx cloak
they are all straight lines
and you have 2 points for each of them
use the two point form equation of line
you dont need to use two point form for this one tho
tame tendon
I have to use rise/run though correct?
tame tendon
Okay
odd edgeBOT
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hallow rover
- Find the interval/s where the function f(x) = x^3 − 2x is (a) increasing,
(b) decreasing, and (c) constant. I know that I need the derivative for this. So I got that and solved for x and got square root of 2/3. I didn't know where to proceed from there so I checked the answers and they started plugging -1,0,1 into the f(x) but I don't know what any of this means I don't want to just mechanically repeat it
odd edgeBOT
9. Find the interval/s where the function f(x) = x^3 − 2x is (a) increasing,
(b)...
@hallow rover Has your question been resolved?
hallow rover
- Identify the local maxima and minima for the function y = x^3 + 4x^2 + 5x + 2 over the interval R. Theres also this similar question i sort of lost track after finding the critical point, are the answers simply testing whats in between in that sign diagram ? between -5/3 and -1 ? and just test any random number into f'(X)
odd edgeBOT
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hallow rover
<@&286206848099549185>
grizzled tide
10. Identify the local maxima and minima for the function y = x^3 + 4x^2 + 5x + ...
yes
I didn't check your work but the idea is right
hallow rover
I didn't check your work but the idea is right
Oh nah thats the answers
grizzled tide
do you have a specific question about it?
hallow rover
Yeah, I don't know where to proceed from the x = -5/3 and x = -1 part
Is the diagram what they mean by interval over real numbers ?
grizzled tide
its larger than -1
hallow rover
oh i thought its between -5/3 and -1
grizzled tide
for the critical points a, b you need to check (-inf, a), (a,b), (b, inf)
they did those 3
hallow rover
Ohh, so for when you had f'(x) = 0, and then once you've gotten both of the x, you have to test something bigger than the f('x), smaller than the f'(x) and then equal or within the range of the f'(x)
hallow rover
Am i right ? ..
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frosty shell
are rhombus and parallelogram the same? google says yes
tender merlin
are rhombus and parallelogram the same? google says yes
No, they are not the same
brittle beacon
Any rhombus is a parallelogram, but not conversely
frosty shell
ohhhhh
mystic saffron
a parallelogram does not require all sides to be equal
brittle beacon
(similar to how all squares are rectangles, but not all rectangles are squares)
frosty shell
so rhombus is a type of it but that doesnt mean its a parallelogram?
ohhhh i see
boeuoguoboe
tender merlin
Every rhombus is a parallelogram. Not every parallelogram is a rhombus.
Parallelogram has opposite sides of equal lengths. Since rhombus has 4 equal sides, this rule applies to it.
frosty shell
thank you so much guys. cus i need to make a code for it. jajargenjang is parallelogram
how do i close
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mystic saffron
i need desperate help4
odd edgeBOT
i need desperate help4
mystic saffron
limber glade
is there aything else given?
onyx cloak
intersecting chords theorem
mystic saffron
i have like one other geometry question after this
onyx cloak
mystic saffron
oh that makes sense
wait no it dont
so 36/9?
oh shit thats 4
mb gang
what about this one
limber glade
try to find similar triangles
limber glade
the upper small triangle and the big triangle are similar, just find out which corresponding sides are similar to each other
limber glade
well how did you get x = 2?
mystic saffron
i got the hypotenuse for the small triangle too be 4
and the big one is 8
so i thought the ratio was 1:2
idk where i got 2 ngl
limber glade
umm yeah then?
mystic saffron
my guy im lost from here
mystic saffron
wait lemme draw rq
limber glade
so i thought the ratio was 1:2
you're going good till here
limber glade
👏
mystic saffron
HUZZZAHHH
limber glade
and it's done
onyx cloak
why is the small triangle similar to the big triangle tho
mystic saffron
i think smthn too fo with the fact its a right angle triangle
onyx cloak
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limber glade
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limber glade
how did you
onyx cloak
i have the helpful role
limber glade
oh
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fathom steppe
Can anyone help me solve this inequality? I don’t know where to begin
lethal spoke
Can anyone help me solve this inequality? I don’t know where to begin
First the denominator should be less than or greater than 0
Not equal to
So just solve for when the numerator and denominator have opposite signs
fathom steppe
So just solve for when the numerator and denominator have opposite signs
I know, but how should I write it? Can you show me please?
midnight halo
6x=7x-x and factorise
fathom steppe
6x=7x-x and factorise
6x=6x? Did you make a typo?
elfin zodiac
No, he wants you to factor
lethal spoke
I know, but how should I write it? Can you show me please?
You might have one of the equations something like √(x+4)-1=0
and x²+6x-7≠0
√(x+4)-1<0
and x²+6x-7>0,
√(x+4)-1>0
and x²+6x-7<0
jagged dock
Can anyone help me solve this inequality? I don’t know where to begin
Is it solved?
fathom steppe
Is it solved?
Nope
fathom steppe
Is it solved?
Can you help me?
jagged dock
Can you help me?
Sure
elfin zodiac
Can you help me?
Factor the denominator as suggested before
Then create a sign table with critical points
And points of sign change and u will get the answ
!nosols
odd edgeBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
elfin zodiac
Also thats wrong
jagged dock
Why?
elfin zodiac
Sqrt of negative number
lethal spoke
Where
jagged dock
Sqrt of negative number
If x=-3 then x+4 would be 1 it is not negative
Ohh i see now
elfin zodiac
You said -inf, -7 too
jagged dock
Sorry got it
elfin zodiac
Factor the denominator as suggested before
Thats why i said this
elfin zodiac
As a helper, please do not give out answers that could be copied as a homework s...
.
elfin zodiac
Just delete the images and wait for the one who asked to solve it
odd edgeBOT
@fathom steppe Has your question been resolved?
lethal spoke
@fathom steppe you are supposed to attempt
fathom steppe
<@1169030606856921128> you are supposed to attempt
I’m trying but I don’t understand the advice you gave me
lethal spoke
The fraction will be ≤ 0 when
The top and bottom have opposite signs
And when only the top = 0
fathom steppe
Isn't it x≠-7
Oh yeah sorry I got distracted
fathom steppe
I agree
lethal spoke
Okay so x = -3
Is when it is = 0
But what about when it is LESS than or equal to zero
lethal spoke
But what about when it is LESS than or equal to zero
Note the denominator should have the opposite sign of the numerator
√(x+4)-1<0
and x²+6x-7>0,
√(x+4)-1>0
and x²+6x-7<0
fathom steppe
Right right
lethal spoke
$\sqrt{(x+4)}-1<0
and x^2+6x-7>0,
\sqrt{(x+4)}-1>0
and x^2+6x-7<0$
While x $\color{red}{\neq}$ 1,-7 and x $\color{red}{not less than}$ -4
clever fjordBOT
David
fathom steppe
Got it!
lethal spoke
What did you get 😁
mild quail
.close
odd edgeBOT
Available help channel!
mystic saffron
it should be 2^2 + 2^18 right?
odd edgeBOT
it should be 2^2 + 2^18 right?
mystic saffron
if... find the value of...
viscid flint
uf que complicado
mystic saffron
es simple
solo estoy revisando
y creo que está estaba mal
pero no estoy segura
mystic saffron
uf que complicado
por qué crees eso
viscid flint
$M = \frac1{4^4} + 4^4$
verbal sandal
what lang man
clever fjordBOT
hayley is not layla
mystic saffron
yes
viscid flint
so 2^10 yea you're right
viscid flint
ye
mystic saffron
so 2^2 + 2^18
viscid flint
yea way bigger than 8
viscid flint
looks like it
mystic saffron
thx
what does your phrase means
in your bio
in french
I'm learning french
and I don't quite understand it fully
viscid flint
ne joue pas les curieux, de peur d'être vexé
it's my translation of “Peer not through the keyhole, lest ye be vexed" which is attributed to a variety of people
quartz trellis
and idk why I can't copy it
CTRL + C
viscid flint
it's not a literal translation btw
mystic saffron
viscid flint
basically the point is -- don't stick your nose into other people's business just to look for things to get offended at
mystic saffron
> ne joue pas les curieux, de peur d'être vexé
it's my translation of “Peer not ...
I don't understand those words either in english, I'll search those up
viscid flint
lest is a fairly uncommon word which means "for fear of"
bronze cradle
what lang man
Spanish
mystic saffron
CTRL + C
idk why it doesn't work like that, perhaps people have different laptops and configurations for the keyboards
mystic saffron
it's not a literal translation btw
ohhh okay
verbal sandal
lest ye be vexed
that's some high lvl english
mystic saffron
basically the point is -- don't stick your nose into other people's business jus...
mm oh okay, thanks for the help
.close
odd edgeBOT
odd edgeBOT
Available help channel!
wooden swan
odd edgeBOT
wooden swan
For this unit you need to find the roots
warped glacier
,rccw
clever fjordBOT
wooden swan
At this point we didn't learn the quadratic function, so are you suppost to just plug a tone of numbers into the corresponding function
Till you get a y=0
warped glacier
At this point we didn't learn the quadratic function, so are you suppost to just...
no, you can just look at the graph since it is provided
wooden swan
no, you can just look at the graph since it is provided
There is cases it isn't,
warped glacier
oh then you should wait till you learn more stuff, if you don't have the graph
wooden swan
In those cases do I just plug random stuff into y till I find two zeros or 1 zero or none
warped glacier
this is the discriminant by the way, b^2 - 4ac
wooden swan
oh then you should wait till you learn more stuff, if you don't have the graph
But we solved questions as a class in this unit
warped glacier
b^2 - 4ac < 0 is the first image
= 0 is the 2nd image
0 is the 3rd image
wooden swan
I know the discriminate now
warped glacier
okok
wooden swan
But in this unit we didn't
So did we just plug random stuff into y till we found 0s
I think that's what we did
But that seems stupid
Because I ain't tryna plug in every number possible
warped glacier
So did we just plug random stuff into y till we found 0s
yeah that's stupid
wooden swan
Wait here me out
Should I just use my groaning calculator
Grpahing
To find the roots
Then plug in the correct bumebrs
Numbers
So it seems like I did it the way they asked
warped glacier
depends on how your teacher wants you to do it
wooden swan
Even tho I just knew the answer from my calc
wooden swan
depends on how your teacher wants you to do it
Ik but I'll write it out as if I didn't use my calc but I did to know what the proper number to plug in was
That would theoretically work right?
warped glacier
That would theoretically work right?
I guess
yeah plugging in numbers till you get y = 0 is a dumb idea anyways
wooden swan
Also if a question asks to graph it and I don't have time to calculate the vertex
Can I just mark down the roots
Or should I plug something random in to have 2 more points
Or 1 in some cases if it is the vertex
warped glacier
Also if a question asks to graph it and I don't have time to calculate the verte...
there's always time to calculate the vertex
wooden swan
😔
warped glacier
you can just do x coordinate of vertex = -b/(2a)
wooden swan
Okay
warped glacier
you kinda need it to graph a quadratic function anyway
it's hard to graph it without the vertex
wooden swan
you can just do x coordinate of vertex = -b/(2a)
What's the other formula to get the vertex from standard form
Don't need you need two
warped glacier
Don't need you need two
then you can sub that x-coordinate back into the quadratic
to find the y-coordinate of the vertex
wooden swan
Ok
Anyways tysm for the help
That's all I want to do for now and I'll study with some practice questions later
wooden swan
to find the y-coordinate of the vertex
Have a good day!
odd edgeBOT
odd edgeBOT
Available help channel!
wooden swan
odd edgeBOT
wooden swan
I need to do this on my test
warped glacier
what about it?
warped glacier
What's a good way to know the names of the steps
oh, so they are following the process of completing the square
wooden swan
Yep
warped glacier
it's much easier to complete the square if you have x^2 instead of ax^2, so you divide everything by a
and then you add (middle term / 2)^2 = (b/2a)^2 to both sides to complete the square
after that you just simplify, making sure you remember the $\pm$ when you square root both sides
clever fjordBOT
higher's secret twin brother
warped glacier
square root both sides then subtract b/2a to get x
odd edgeBOT
hey guys
To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.
odd edgeBOT
@wooden swan Has your question been resolved?
wooden swan
also if you are interested, there are so many ways!
Alr tysm
rough badge
Does this look right?
odd edgeBOT
Does this look right?
long tinsel
yes
odd edgeBOT
long tinsel
that looks like your handwriting ngl
You haven't seen my handwriting have you
odd edgeBOT
✅
buoyant ocean
Can x^(-1/2) / 2sqrt(x) be simplified to 1/2x?
yes
also in this pic
ln(x^a) = aln(x)
that follows from properties of logarithms
so $\frac{d}{dx} ln(x^{\frac{1}{2}})$ can be rewritten as $\frac{d}{dx} \frac{1}{2} ln(x)$
rough badge
Ohh that makes it a lot easier lol thanks
clever fjordBOT
void
rough badge
I always forget log properties
lone elbow
Find the coordinates of the matrix $\begin{pmatrix} 1 & -1 \ 3 & 2 \end{pmatrix}$
in the basis B $\B = \left{ \begin{pmatrix} -1 & 2 \ 1 & -1 \end{pmatrix}, \begin{pmatrix} 0 & 1 \ 1 & 2 \end{pmatrix}, \begin{pmatrix} 1 & 1 \ 1 & 1 \end{pmatrix}, \begin{pmatrix} 0 & 1 \ 0 & 3 \end{pmatrix} \right}$.
clever fjordBOT
ඞඞඞ
quasi sparrow
4 equations 4 unknowns 
lone elbow
let B=<b1,b2,b3,b4>
Let M :( 1 -1)
(3 2)
a×b1+b×b1+cb3+db4=M
unless I am tripping
and we solve for a,b,c,d
we get a system of equations
unless I am tripping
@quasi sparrow
<@&286206848099549185>
quasi sparrow
4 equations 4 unknowns <:catthumbsup:614540188747563008>
Did you read this
quasi sparrow
can you show a latex of the system
Write it on paper yourself
lone elbow
comprehend how to get a system out of this
ye, I anticipatedb you were going to say that
but how do I wrote it
write
quasi sparrow
a×b1+b×b1+cb3+db4=M
Find the constants
lone elbow
wanton bison
by finding the constants
quasi sparrow
a×b1+b×b1+cb3+db4=M
Write out using the given b
lone elbow
im trying
wanton bison
comprehend how to get a system out of this
would "component" wise make sense to you
every first components forms the first equation
wanton bison
do u mind show me the latex
i have to become like riemann
quasi sparrow
do u mind show me the latex
Use paper
lone elbow
lone elbow
I told you friday I went kfc man
wanton bison
lets rref this
no
lone elbow
?
lone elbow
@wanton bison
@quasi sparrow
,w rref {{-1,0,1,0,1},{2,1,1,1,-1},{1,1,1,0,3},{-1,2,1,3,2}}
clever fjordBOT
quasi sparrow
<@261933205387477002> I did
You're getting help already stop pinging me
lone elbow
can you guys check my solution
no need to make a big deal about a ping also
also you told me to grab pen and paper and I juat wanted to ping to show you my work, im sorry
wanton bison
<@587715738484211754>
You're getting help already stop pinging me
wanton bison
your coordinate vector is literally the 5th column
lone elbow
purrfect
i got this calc that can calculate the linear systems
ty for the help as always
.solved
odd edgeBOT
graceful parrot
idk if that image even makes sense
odd edgeBOT
wanton bison
idk if that image even makes sense
no image no sense
odd edgeBOT
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
prisma geyser
my apologies
wanton bison
You see that it was closed bruh
prisma geyser
i was on this channel for like an hour, i wasnt lookin
wanton bison
i was on this channel for like an hour, i wasnt lookin
it's okay dont worry
wanton bison
this is a good soing
i will try that soing 
wanton bison
https://www.youtube.com/watch?v=ZNGqBDRJgvo&ab_channel=Lyn-Topic
your school entrance soing
lethal spoke
Lol
lethal spoke
this is a good soing
*song
odd edgeBOT
Available help channel!
graceful parrot
can i ask why is 4,inf seperate?
odd edgeBOT
can i ask why is 4,inf seperate?
snow cypress
but why are they seperate
tectonic plates
graceful parrot
ok.
cursive field
tectonic plates
cube stop spamming in channels or i will report you again
lethal spoke
cube stop spamming in channels or i will report you again
I think I should
cursive field
i do not understand still
okay
the interval (2, 4) means
all numbers between 2 and 4
graceful parrot
yes
cursive field
but NOT 2 and 4 themselves
graceful parrot
yea
snow cypress
cube stop spamming in channels or i will report you again
Clearly Not Sigma, Leme help my fellow people
cursive field
[2, 4] means 2, 4, and all the numbers in between
graceful parrot
yes
lethal spoke
Clearly Not Sigma, Leme help my fellow people
<@&268886789983436800>
cursive field
Clearly Not Sigma, Leme help my fellow people
<@&268886789983436800> this is getting annoying, he's been posting random gen-alpha slang in several channels
graceful parrot
but shouldn tit still be increasing? there are still + signs on both sides
i dont know how u knew
it stoopped
like it dont increase
at 4
cursive field
i'm not sure what you're talking about
odd edgeBOT
but shouldn tit still be increasing? there are still + signs on both sides
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
cursive field
i'm assuming you're referring to the set notation?
graceful parrot
(2,4) and 4,inf are seperate how do you know 4 isnt still increasing
snow cypress
<@&268886789983436800> this is getting annoying, he's been posting random gen-al...
I've Not But Okay
graceful parrot
Please show the original problem, **exactly as it was stated to you**, with the ...
(sorry this is the problem example) theres no question
halcyon lava
but why are they seperate
(2, 4) U (4, inf) = (2, inf) - {4}
graceful parrot
(2, 4) U (4, inf) = (2, inf) - {4}
ic
cursive field
and smay's here too
viscid flint
I've Not But Okay
you've already been told to stop spamming by a mod; consider this your second warning
odd edgeBOT
cursive field
bro keeps DMing me 💀
graceful parrot
@wanton bison do u think a lot of new gen music is good
i dont think so
i think a lot are bad
wanton bison
<@587715738484211754> do u think a lot of new gen music is good
we might wanna do this in #discussion
or private
pulsar elbow
bro keeps DMing me 💀
message modmail if it’s rude etc
cursive field
message modmail if it’s rude etc
nah
i won't bother you guys with this sorta stuff
i blocked him already
who tf skulled that 
odd edgeBOT
Available help channel!
manic ibex
can someone help me solve $2 \log_4 x - \frac{1}{2} \log_2 (x^2 - 3x + 2) \leq \frac{1}{2}$ ?
clever fjordBOT
JustANormalTeo
mystic saffron
what have you tried
wanton bison
you might wanna consider a change of base for log_4
manic ibex
i mean im not sure if $2 \log_4 x$ turns into $ \frac{2}{2} \log_2 x$
wanton bison
essentially trying to prove that there is an absolute maximum for the left side
wanton bison
i mean im not sure if $2 \log_4 x$ turns into $ \frac{2}{2} \log_2 x$
dont leave spaces with $
clever fjordBOT
JustANormalTeo
manic ibex
yes!!!!