#help-19
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no need for examples you can write out the solutions explicitly
$\pm 3 \sqrt{\frac 89 n - 1 }$
jan Niku
take $x_1, x_2$ are the roots of this
jan Niku
your solutions should be all n such that $x_1 \leq \pm 3 \sqrt{ \frac 89 n -1} \leq x_2$
jan Niku
well, all x such that n satisfies that i guess
ah ok
the n arent solutions
but really this is just solving $\frac{x^2+9}{8} = \floor x$ in disguise
make sense?
jan Niku

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I have a question.
I love you

I also have a question 
I love you too
What are the units of precalc and list them in chronological order.
That can vary from teacher/professor and institute
But generally they cover more complicated algebra techniques
Unit 4 wasn't covered in my pre-calc class
Is that normal precalc?
I think AP precalc
you can see the units for khan academy's precalculus course here:
https://www.khanacademy.org/math/precalculus
the AP precalculus curriculum is listed here:
https://apstudents.collegeboard.org/courses/ap-precalculus
does khan cover everything for precalc
precalculus varies between schools, but most likely it does
can someone tutor me
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can anyone help me find the limit of this series please
What is u?
@unique gazelle Has your question been resolved?
just like a ordinary variable mate
ah forgot to show more vital informations
here
suppose we have a serie of numbers (U(n)) that are defined by
with every n ∈ N*
find the lim of the serie
Hmm
Yes @unique gazelle
Can you try to derive a general formula for u_n
Write out what u_2 and u_3 is
And u_4
for predicting the structure of the general formula right?
i do remember that this problem has a hint that we have to set up some unrevelant numbers
like this
Keep going
now we let V_n be (n+2)(n+1)n*u_n then
we have a serie that defined by
and V_n is a geometric progression have a merit q= 3
=> V_n=9.3^(n-1)=3^(n+1)
what your description
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hi, im stuck on factorizing trinomials, i dont know if my method is correct,
in the first line i multiplied the first term with the third one
in the third line i splited the 5x, so i could factorize,
but i dont know what to do after i did factorized that, could anyone help me if someone sees an error or how to do my problem?
yeah im here
ok
could u tell me what do i need to do or what did i had wrong?
why is -3 now -6x^2
you dont have to actually physicaly multiply them in the equation because that just changes the eqn
i have a way that we don't have to multiply 2x^2 with 3
why is there a two? at the end?
Nguyễn Tuấn Minh
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guys
??
yes?
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<@&286206848099549185>
descartes' rule of signs
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but how do i find the exact number of real roots
Is that sufficient?
We also need to know whether or not is there a perfect square factor
since its a 6th degree polynomial, we can see that it has 6 roots R or C
what if it was e.g. (x-3)^6?
or (x-2)^3(x+i)(x+1)(x-i)
At 1 it's negative and at infinity and -ve infinity it's +ve so atleast 2 real roots
it would be easier to just check that it's negative at 0 lol
And by Descartes rule of sign change atmost 2 real roots
in this case yes
no the answer is yes
are you sure?
So there should be 2 real roots and rest imaginary
this is not necessary descartes' rule of signs already accounts for multiplicity
because i asked and the teacher said to give the exact number of real roots
he said descartes rule of signs wont be enough
even for non-real roots
so we have to see how many roots are real and not just come up with a lazy answer that isnt even a proper answer to the question.
according to him at least
multiplicity of non-real roots has no bearing on the number of real roots
this makes no sense
according to descartes' rule of signs, there is exactly 1 positive real root and exactly 1 negative real root
their approach is right for real roots
the problem is that we still need to find the number of complex roots
when the problem says "imaginary" does that mean of form 0 + bi
no i know but my teacher doesnt want us to use the table and write the appropriate possibilities
but
exactly 2 real roots implies 4 non-real roots
yeah but he wants to know how we get that number without using descartes rule of signs and without graphing the polynomial
what if there are perfect squares in the factorization
without using descartes rule of signs specifically?
descartes rule of signs gives you the exact number of real roots here
doesnt it only give parity
for this specific polynomial it is exact
He said that we have to count the number of distinct real roots and locate them in intervals. By subdividing the intervals containing some roots, it can isolate the roots into arbitrarily small intervals, each containing exactly one root.
no it's an upper bound and parity
oh right ok
descartes rule of signs handles all of that in one go though
yeah but he doesnt count that as an answer
so it's just banned as a solution??
basically
even though it gives the right answer
yeah
because he says “its just a lazy way of doing math. you need to show your work by using any method to find those roots in given intervals whether its a arbitrarily small interval. it should give you the amount of real roots which arent complex.”
using a true theorem to prove your result is "a lazy way of doing math"?
you need to get a better teacher
well he doesnt count descartes rule of signs as a theorem
Yeah, everyone should probably start from axioms and re-derive whole math themselves. Just don't be lazy
of course, why hadn't i thought of that
haha
guess we should all be damn math prodigies according to my teacher
i'll come back to you in 2937392919191 years after i've proven that 1 + 1 = 2
man i hate him
(doesn't matter. the problem makes no distinction between non-unique roots)
If we also count multiplicity, then ye, it should be doable quite easily
alright lets just move on to the other 3 questions. ill just ask him tomorrow what he wants for that problem
now its just solving polynomials haha
so yeah thats the easy part
You could just accidentally copy over proof of descartes rule of signs and accidentally rediscover some theorem, of which you didnt know is banned
that's what newton said
how do we do that?
quartic depression
ビジヨン
thus i get $y^4-15y^2-6y+28=0$
ビジヨン
but i still need to remove the linear term
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i dont know how to do this quwstion
which question, trucknut?
use 1/2 ab sin(C)?
yeah but i dont understand the 3QR = 4PR thing
let PR be x
it means that 3 times the lenght of QR is the same as 4 times the lenght of PR
so 3*QR = 4x
QR = 4/3 x
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guys can u help me
where is the derivative used and applied in a real world context
hello bum chicken
hi
Derivatives are used in many places, you use them in any and all kinds of simulations
Stock market predictions
Animations
u should do astrophysics and rockets 😎
hows it used in rockets
wait ima do acceleration
wait but i dont even know how rockets work tf
Lol
do u do investigations in nsw
only in y10
they are free marks
gg
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Try to make cases
When b is a multiple of a
When a and b are coprime etc
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Can someone help me with this
Q8?
9
Okay
let's start with the parallel line
parallel line should have the same slope, right?
Yes
so we are looking for a line of form 3x + 2y = k, that passes through point (3, 5)
this way the slope stays the same
and we are able to shift it up and down
Try making an equation that will find k
(do you understand it till now btw? Or is something unclear)
Am confused ngl
Okay
so we have the line 3x + 2y = 8
and we want to find a line that is parallel to this one and has the same slope
so let's start in a different way, by finding slope of this line
can you rearrange it to the slope-intercept form?
So that we can easily read of the slope and y-intercept
x is the coordinate in horizontal direction
y is the coordinate in vertical direction
3x + 2y = 8
Graph of this equation would be the set of all points (x, y), such that 3x + 2y = 8
so e.g. the point (0, 4) would sit on that line
because 3*0 + 2*4 = 8
Now if we go 3 units down and 2 units right, then we get another point on the line
(2, 1)
we can again verify that 3*2 + 2*1 = 8
this is how the whole graph looks like
we can also rearrange the equation like this
3x + 2y = 8
2y = 8 - 3x
y = -3/2 x + 4
this is the so called slope-intercept form
-3/2 is the slope of this line
4 is the y-intercept
and when we want to find a line that's parallel to this one, we want the slope to stay the same, and only the y-intercept to change
I think I get it
cool
so we can now set up an equation of line like this:
y = -3/2 x + c
where c is some number we dont know yet
and we want this line to pass through the point (3,5)
so we need to set up an equation and solve for c
the way we do it is that we plug in the coordinates (3,5) to the equation y = -3/2 x + c
so we get 5 = -(3/2)*3 + c
can you solve for c now?
C is 3,5 right?
not quite
Is c the y intercept
yep
how did you get 3.5?
I mean we need to find the line that goes through there right
no, we want line that goes through point (3, 5)
not the line that has y-intercept 3.5
this is a line with y-intercept 3.5, and the point above it is (3, 5)
Oh I meant that, didn’t mean to be confusing how do we find it
you can see that the line doesnt pass throug hthat point
alright
y = -3/2 x + c
So we have this general equation
and we need to find c, such that it goes through the point (3,5)
to do that, we set up an equation by plugging in the coordinates (3,5) in the equation y = -3/2 x + c
so we get 5 = -3/2 * 3 + c
and using this equation, we solve for c
Where did the 5 come from
5 is the y-coordinate of the point (3, 5)
Oh
we are basically plugging in y = 5 and x = 3 in the equation y = -3/2 x + c
because we want to make sure that it passes through point (x, y) = (3, 5)
👍
Ngl I got to go can you finish it cause my teacher won’t let me on my phone and I can just read it later
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would someone be able to tell me what the degrees of freedom is for this questions? I feel like my answer is wrong
<@&286206848099549185>
Degrees of freedom 
The number of independent ways in which a molecule of gas can move
bruh i had a feeling somone would say this
shall we keep it in the context of statistics?
Was jk
sry
that could statistic and probability problem?
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wait I could probably help you from that problem
oh?
just give me a minutes to let me try solve this problem
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I'm confused by a coding challenge I'm working on. Imagine an Equilateral triangle where you are given the orientation of one side (radians away from the positive x-axis), the side length, and the center x,y coordinates. How would you "find the rotation" around the z-axis? Isn't that just the orientation?
Depends
on where the center is
also depends on the initial orientation
try to sketch some cases for yourself
Initial orientation wasn't give, so I assume 0 radians. say the center is (225.05, 265.596). Orientation of one of the sides is 1.87115 radians.
I guess my real question is how is orientation supposed to affect the values I'm asked to calculate? Assume we are looking at the 2D shapes through a camera in 3D space. We're asked to provide the area, perimeter, and centroids for each shape along with other geometric properties. Wouldn't orientation have zero affect on other geometric properties?
Note that you know the orientation of A side, not the baseline side
correct
Suppose you're given this blue side, see how the placement of the center can change the orientation?
The image won't send 😦
Yes
So the orientation of the given line does not singlehandedly define the orientation of the triangle since it's not necessarily the baseline
Or even if you view it as such, there's always at least 2
So what I'm hearing you say is that more information is needed to calculate rotation around the z-axis?
Got it
Well wait
The center coordinates are given
along with orientation of one side, wouldn't that define the orientation/rotation (not sure the difference now) of the entire triangle?
yup
you asked if the side is enough
it's not
but the side and the point are
or at least if I understood your question right
ah, I misunderstood you here
But my question is, how would orientation (taking all other information we have into account) affect whatever information I can provide about this shape? In order words, what can I say about this shape and/or its position in space that is affected by orientation. Initially, I'm asked to provide area, perimeter, and centroid, which of course don't depend on orientation. Then, I'm later asked to describe the rotation of the shape around the z-axis. What does that mean? Isn't the orientation, again with all other information taken into account, the rotation about the z-axis? What more information is there for me to deduce?
Well I guess you have to deduce if the orientation is on one or the other side
based on the point
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i'm stuck in multiplying a trinomial and a binomial, the problem is the following:
(x^2 + xy + y^2) times (x - y)
I was simplifying by distributing and multiplying x^2 by x which got me x^3, and multiplying x^2 by -y which got me -xy^3, but when i get to xy times x i completely fall apart in that step
help would be much appreciated
Well, first you multiply x² by each term on the other brackets
So x³ - x²y
Now do the same but with xy
You get x²y - xy²
And finally the same but with y², which leads you to xy² - y³
If you sum the three results you get x³ - y³
@limpid notch Has your question been resolved?
thank you so much
i worked it out now
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So I’m sort of confused about systems of odes and I’m terrible at understanding them
So there’s just weird A that pops up
And it’s the matrix with the coefficients of the system given
At first glance A is an operator
Of course it’s a matrix so it needs to be written wrt some basis
What is this basis?
presumably you mean a set of linear ODES?
Uh yes linear odes
where f=(f_1, f_2)^t
Yes
matrices don't have a basis?
Well matrices need to be written wrt some basis
not particularly
So I need a basis of C² and C¹ no?
what is the function space C^2? twice differentiable functions?
sorry been a while for me
I have 2 linear operators d/dt and A, and I want to say that they do the same thing to some special f’s
ah, in that case, let's not get into what the bases of those vector spaces are
because that's not important
all your matrix is going here is encoding information about a system into a more easily digestible form
Well I don’t agree from here that A is what you said it is
I would need to be given bases to write down the numbers in the matrix
But it seems to be given in the form by the question being a system
Thats sort of what I’m confused about
indeed
I still don’t really get why A is that matrix
the crux is just the last two lines
Third line is fine
have you done linear algebra before?
Fourth is okay as well
And now why do we have on the 5th line that S^-1 d/dt = d/dt S^-1
Yes
you've done systems of linear equations?
I’m just really stuck on the part where a matrix is only a representation of some linear transformation with respect to some basis on the domain and the codomain
because multiplication by a scalar and differentiation are commutative
A matrix can’t just pop up by itself
write a general matrix ((a00, a01)...)
and multiply it by a general vector
(x1, x2)
and tell me what you get
should get another vector as a sanity check
But matrix multiplication is weird and archaic
I understand that you do get what is desired
this is why you don't understand what's happening
Is there not a basis-free version of this
And I don’t even see a basis anywhere
Matrices written without basis are meaningless
you don't need to know the basis is my point
no they are not, more abstractly they are linear maps
which don't really need a basis to work
They’re only linear maps wrt some basis
The numbers in the matrix depend on the basis you pick
So when you say it’s (1,2),(2,1), what basis did you pick to say that
That’s what doesn’t make sense to me
in that case, f1 and f2
But somehow when you do (1,2),(2,1)f it does indeed recover the conditions given
that's your basis
Huh
i really don't understand what you don't understand
because you understand where the numbers in the matrix come from
and then you understand how to make it solve your odes
(i think)
@merry finch you still here/need any help?
I’m thinking
on the matrix bit?
okay lets consider a one dimensional basis of one meter
i can use a linear transformation which is a stretch of 1000 to make the new basis a unit of a kilometre
but i could use the same transformation to map a gram to a kilogram
hell i could map a banana to a kilobanana but that's probably enough potassium to cause ten heart attacks
@merry finch I'm off bed, gn
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What is 5.a. Even asking me to do?
Find average velocity of the pebble for t=4 you just put 4 in the y= equation right
But what does and lasting part mean
Ok so I’m wrong and dumb
Can someone explain please
You'd want the average between two times, so they tell you that you "start" your time at t = 4, and they give you three choices of how long you'll be measuring for
So from t = 4 to each of t = 4.1, 4.05 and 4.01 respectively
Oh ok so like y(4.1)-y(4)/4.1-4
@brittle beacon how would I find the instantaneous velocity in 5b?
Well, as you do each of those averages, you should, theoretically, see that they approach a certain value, and what you think it'd end up as should be your estimate for the instanteneous velocity
So like my guess what be
Whatever it approaches to at like 0.0001
0
To 0
I mean
Yeah, the instantaneous velocity is basically what happens to your average velocity when the time period you take it over shrinks to zero
Ok cool
Same thing for 6? Like do 1.00001 into the equation
And see where it approaches
Basically yea, as you do each of the 6a intervals, you see (at least in theory) that it gets closer and closer to something, and what it gets closer to is your instantaneous velocity
Why can’t I just insert 1?
Into the average velocity, or?
As in, doing ( y(1) - y(1) ) / (1 - 1), or do you mean something else?
Like 10(1)-1.86(1)^2
That only tells you your position, and not even a rate, is why
As @copper quarry is hinting at, there is a way you could skip a lot of work and just put in t = 1 "somewhere", but it isn't into the equation for y as it is
Yes
(assumedly you're probably at a point where they're motivating the definition of the derivative, so they're first making you do stuff "the long way")
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is there a way to simplify this furhter : $$(\ln n)^{\ln (\ln n)} = e^{\ln((\ln n)^{\ln (\ln n)})}=(e^{\ln (\ln(n))})^{\ln(\ln(n))}$$
atif
ideally i'd like to have n as the base, instead of e
@compact steppe Has your question been resolved?
<@&286206848099549185>
for context, the original problem is this $\sum \frac{1}{(\ln n)^{\ln (\ln n)}}$
atif
i.e. it should be solved by comparison test im p sure, i just need to transform the denominator so that i can bound it
which is what i tried above but i didnt get anything easily boundable
@compact steppe Has your question been resolved?
NulledOutChicken
@sly egret thanks, but I don't see how to proceed from here
@compact steppe Has your question been resolved?
Condensation test- the sum converges iff-
Sum{2ⁿ/(ln(2ⁿ)^(ln(2ⁿ)))}=Sum{2ⁿ/(nln(2))^nln(2))}≤Sum{(2/ln(2)n)ⁿ}
That's a start
If you're only trying to show convergence and don't care about the actual value
@somber vault thanks, but a very similar problem $\sum \frac{1}{(\ln n)^{\ln n}}$ I've seen solved with comparison test, so I'm trying to do the same. although the slight difference might make it unsolvable w solely comparison as I intended
atif
and I'd especially like to learn whatever logarithm manipulation is needed to make it happen/make the problem approachable
You can compare it to 1/n^ln(n) probably and from there use the condensation test (or not)
But yh give solutions <@&286206848099549185> with only comparison if existant
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This shi is clearly no solution
what the hell so i write than?
reduce it to RREF. the augment column is treated as a regular column in the matrix for this
leading 1's
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get the gradient and get the intercept
and add them to the y=mx=c equation
gradient = y2-y1/x2-x1
intercept is the point where the line cuts the y axis
for example, in the first question intercept is 4
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Wood cutter in the shape of the function cuts into a piece of wood
Defined between 0 and 1
Im having more issue with the understanding how this translates into an equation i guess, and how the function gets put to the power of 2, the equations below are the answers
If i just put the f(x) in an integral in calculator it doesnt know the answer
Nvm, i just wana know how f(x) can be put to the power of 2
How does that work
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There are multiple things that notation can refer to but in this, it means (f(x))^2
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can anyone help how to start this question
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Hey, we need some help for our linear algebra course, we are working 2022 exam to study and we are stuck on this problem.
in question a we calcuated the determinant easily and we got -3a + 18
In question b we used the fact if the determinant is 0 then there is pivot collumn therefore there is only one unique solution
in part 3 where there is no solution we are completly stuck. We have an idea in regards to free variables but we can't compute any solution.
MATLAB/Python is allowed for us if that helps.
Thanks.
Hmm for part b, you’d want the determinant to be nonzero for a unique solution
wait what? :D Could you please explain this in a bit more detail?
So, to have exactly one solution to a linear system (with a square matrix), you need the determinant to be nonzero
If the determinant is 0, then either you have no solutions, or you’ll have infinitely many solutions
Ah gotcha, probably mixed up my definitions
Yeahhhh sometimes that’s how it goes
Any ideas for c on a conceptual level? If i had a way to get started then I'll go and write some code, but no ideas on how to get started
Well you check for when determinant is zero
That gives you your not unique exact solutions case
And then you check for whether there are any solutions
Yes, so if the determinant is 0 and there’s at least one solution, then there must be infinitely many solutions
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y=a
prove: y'=0
I only get y'=1
limit definition, no?
show ne
limit as h goes to 0 of (a-a)/h
the definition for derivatives
h is 0, h=x-x0
yea but x-x is always 0
therefore cancels out and 1
that’s not how limits work
since y = a is a line you can directly find the slope of it
I want a rigirous proof
you can use table method to verify, but that only works if they both go to zero at the same rate
since x-x is always 0
and h is not always 0
the limit must be 0
since 0/anything = 0
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Hello
okay, so we will need to consider prime factorization of 26!
Okey
then if we separate all the 3's from there, we will be left with 3^x * A
and since we've seperated all 3's, the x will be maximal
We will get to it right now
Alright
we actually don't need to do whole the factorization
Thanks btw
we only need to count how many 3's are in there
👍 yup
note that 26! = 1 * 2 * 3 * 4 * 5 * 6 * 7 * ... * 26
Exactly
obviously, numbers like 2, 4, 5, 7... which aren't multiples of 3 won't contribute any 3's to the overall count
Okey
u just need the amount of 3's here, since question has nothing to do with A , but does with x
on the other hand, numbers like 3, 6, 9, 12, 15... which are multiples of 3, will contribute 3's to the overall count
Okey
Aight
answer is 10?
so it would be a good idea to count the number of multiple of 3, up to 26
Yea
should be 8 no??
Hmm okey
do you think you can do that?
okay! you have even listed them
that'll be useful now
how many 3's does each of them contribute to the prime factorization?
Wait how
got it 10
6 has how many 3s?
2
How 3+3
indeed, because that's what factorization is
correct
Okey
21 has 1
24 has 1
18 is 2, we wanna find the maximum x and so we wanna use all the 3's
Then it should add up to 10
indeed it does
Okey
So know i know why its 10 thank you all for that but now i have another quick question
okay, sure
The tesbook show hiw to do it
it probably does stuff like 26/3 and 26/9, right?
okay i'll explain it
26/3 counts the number of multiples of 3
so instead of listing them all, we can just count them
and we need to round it down btw
so there are 8 multiples of 3
But we just divided it with 26 not with 26!
@tepid pelican dont ,ind me asking, youre a professor? u seem like u know ur shit.
lol no, im 16
26! = 1 * 2 * 3 * 4 * 5 * ... * 26
Okey
and we want to count how many multiples of 3 are in that sequence 1, 2, 3, ... 26
Yes
damn
so we dont care about 26! anymore, we just want to count the number of multiples of 3 up to 26
and every third number is a multiple of 3
so we divide 26 by 3
Ahh okey yea
and we get 8
when we round it down
but there are also some multiples of 3, that contribute with more than one 3 to the factorization
namely, 9 and 18
those are multiples of 3^2 (9)
correct
we already counted them once, because they are also multiples of 3
but we need to count them for the second time now
so we do 26/9
and we get 2
so we do 8 + 2
and we get 10
Hmm okey
İ think i kinda got it
But if its like this
Why is there an A in the question
it's just to formulate the question correctly
and also to make you think about it a bit more
Okey thanks a lot!
to be specific, you have to realize that A can't be a multiple of 3, otherwise x wouldnt be maximal
and then the key idea is counting 3's in factorization of 26!
Ahh yes thats true
if A would be a multiple. then again powers would add up as per the exponential rules
and then maximum wouldnt be attained
True
Thanks both of you for helping
And sorry that i took your time
Have a nice day
youre good homie
you too :)
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How to solve x^4 -1
Use the identity a² - b² = (a + b)(a - b)
Yes
Okok
Do you know how to solve a cubic equation
Here you found x-1
Bruh general solution is impractical
Yez
Yes
Can you factorize x²+1 further ?
ie finding more roots
Even further
Correct
The two remaining roots are not real numbers
If you only study real numbers
You can not go any further, that is an irreducible polynom
Which are degree 2 polynoms with no roots
Or x + a
Here you have 2 degree 1 polynoms
1 irreducible
That gives you all the possible solutions
Okey cool then i get 4 roots in total
If you count the imaginary ones yes
yes
Counting imaginary roots and double roots as 2, a degree n polynom always has n roots
I did that no?
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Hello, I had a quick question. I am trying to figure out how to convert 60kg of downward force in gravity to newtons. I haven't done anything relating to anything like this in maths before so I just need some general help
isn't it supposed to be physics?

either way
I understand that gravity is 9.8m/s so what would be the equation from there?
Force = Mass times the Acceleration
oh my god
ig this is fine for your work
unit of force in Newton
wait
the unit of force is N not kg
And Newton= kg meters per second^2
so downward force can't be in kg
if you're asking the downward foce of an object of mass 60kg, on earth it's mass * g (acceleration due to gravity) = 60 kg* 9.8 m/s^2 = 588 N
Note:
1N = 1kg m/s^2
9.8 m/s^2 is an approximation only. Sometimes g = 10 m/s^2 is taken for ease.
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My question says "ten times the sum of half a number and 6"
How would I make that into a equation
Like would I do 10 (1/2x +6) or 10 • 1/2x + 6
Idk homework says translate description into equation
Also why is it the first and not second
sum of: [what follows here is expected to be a list of expressions]
the latter would be something like
sum of ten times half a number and six
you're multiplying 10 by whatever (x/2 + 6) is, whereas with the second you're multiplying 10 by x/2 and then adding 6 to that. If x were 4, for example, the first options would give 80 and the second would give you 26
this
Wait isn't sum just mean like plus
in this case its a list of two expressions separated by "and"
its associated with +
sum is the result of addition
sum of: ...
is the result of adding those things together
yes, the sum of [half a number and (+) 6]
e.g. sum of 5 and 7 is
5 + 7
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Do I use pv=nRT for this
yes
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Hey so we are told to calculate the fourier transform of this graph but what i dont understand is that in the solution theyve said that due to the linearity property of fourier transforms, we can simply add together the fourier transforms of each segement. However, for the rectangle parts theyve used the general fourier transformation of rectangular signal but we dont actually have a signal at the top (ie. by the dotted lines) so how come we can use the fourier transformation of rectangular signals there?
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If M is a matrix, and i-hat is the basis vector [1, 0, 0], is the following result correct?
you could do the multiplication and check yourself
The learning material that I'm learning from uses row vectors. I'm trying to verify if my column-vector answer is correct.
well it would be correct
but you can also check it by doing the multiplication yourself
row x collumn
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my P'(t) = 520 * ((210-2t^2)/(70+t^2)^2
$P'(t)=570\left(\frac{3}{70+t^2}-\frac{6t^2}{(70+t^2)^2}\right)$
fish
yes
yes, also you have to use chain rule for the t^2 at the bottom
the (70+t^2)^2?
well, the t^2 inside it
brah im so lost theres a gazillion steps 😭
3 is already there, so you get -6t^2, which simplifies fully to $P'(t)=570\left(\frac{270+3t^2-6t^2}{(70+t^2)^2}\right)$
fish
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right so 270-3t^2
yeah, but you can just multiply all the stuff in the parenthesis
im going insane
let me try going step by step
yeah that's correct
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Hey, I'm doing work for AP Calculus and I was wondering if this answer would be 1/2 or -1.
I got told that if both sides approaching the limit on the first one go up, I should take into account the left side if it its split on the second f but I don't know if this applies here as there is a hole on the left side
$\lim_{x \to -1} f(f(x))=f \left(\lim_{x \to -1} f(x) \right)$
Civil Service Pigeon
Now, consider ||the “direction” that f approaches 3 from as x approaches -1||
yeah I understand up to that point, I just repeat the process but with x=3
Uh sure ig
… ?
This determines the direction you approach 3 from
so from - or below
that means that although there is a hole on the left side, it does not matter, and the answer is -1?
Yes
thank you so much mate, I really appreciate what you are doing and I hope you have a great day
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is this statement true or false?
what do you think
it could be false right?
coz if A = 1 B = {1,2,3} and C = {{1,2,3},4,5}
A in B
and B in C
but C has the set in the set
not specificly 1
does it work like that or am i doing too much
yes, well, the question doesn't define is A B C are elements, sets
just, random topological spaces
oh right
but I think they want the answer to be yes
are you just trying to throw in random words?
Set's are complicated
maybe think of it as "San Francisco is in California, California is in US, therefore San Francisco is in US"
your example shows that it is false
you presented an exemple where is false, it is enough to show that it's not always true.