#help-19

1 messages · Page 124 of 1

tacit haven
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yes

nocturne belfry
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no need for examples you can write out the solutions explicitly

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$\pm 3 \sqrt{\frac 89 n - 1 }$

clever fjordBOT
#

jan Niku

nocturne belfry
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take $x_1, x_2$ are the roots of this

clever fjordBOT
#

jan Niku

nocturne belfry
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your solutions should be all n such that $x_1 \leq \pm 3 \sqrt{ \frac 89 n -1} \leq x_2$

clever fjordBOT
#

jan Niku

nocturne belfry
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well, all x such that n satisfies that i guess

tacit haven
#

ah ok

nocturne belfry
#

the n arent solutions

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but really this is just solving $\frac{x^2+9}{8} = \floor x$ in disguise

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make sense?

clever fjordBOT
#

jan Niku

tacit haven
#

yep

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Ty

nocturne belfry
tacit haven
#

.close

odd edgeBOT
#
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cloud basin
#

I have a question.

odd edgeBOT
elder vault
#

I love you

cinder elk
cinder elk
elder vault
cloud basin
#

What are the units of precalc and list them in chronological order.

cinder elk
#

That can vary from teacher/professor and institute

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But generally they cover more complicated algebra techniques

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Unit 4 wasn't covered in my pre-calc class

cloud basin
#

Is that normal precalc?

cinder elk
#

I think AP precalc

forest sky
cloud basin
forest sky
#

precalculus varies between schools, but most likely it does

cloud basin
odd edgeBOT
#

@cloud basin Has your question been resolved?

cloud basin
#

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unique gazelle
#

can anyone help me find the limit of this series please

robust pollen
#

What is u?

odd edgeBOT
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@unique gazelle Has your question been resolved?

unique gazelle
#

ah forgot to show more vital informations

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here

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suppose we have a serie of numbers (U(n)) that are defined by

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with every n ∈ N*

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find the lim of the serie

summer river
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Hmm

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Yes @unique gazelle

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Can you try to derive a general formula for u_n

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Write out what u_2 and u_3 is

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And u_4

unique gazelle
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for predicting the structure of the general formula right?

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i do remember that this problem has a hint that we have to set up some unrevelant numbers

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like this

summer river
unique gazelle
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now we let V_n be (n+2)(n+1)n*u_n then

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we have a serie that defined by

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and V_n is a geometric progression have a merit q= 3

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=> V_n=9.3^(n-1)=3^(n+1)

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what your description

odd edgeBOT
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@unique gazelle Has your question been resolved?

odd edgeBOT
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near owl
#

hi, im stuck on factorizing trinomials, i dont know if my method is correct,
in the first line i multiplied the first term with the third one
in the third line i splited the 5x, so i could factorize,
but i dont know what to do after i did factorized that, could anyone help me if someone sees an error or how to do my problem?

lucid hollow
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hello

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r u there

near owl
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yeah im here

lucid hollow
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ok

near owl
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could u tell me what do i need to do or what did i had wrong?

lucid hollow
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why is -3 now -6x^2

mystic saffron
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you dont have to actually physicaly multiply them in the equation because that just changes the eqn

near owl
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whats eqn?

mystic saffron
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sry

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the polynomial

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you only multiply coefficients i.e 3 and 2

lucid hollow
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i have a way that we don't have to multiply 2x^2 with 3

near owl
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oh,

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what way?

lucid hollow
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$2x^2 + 5x -3 = 2x^2 + 6x - x - 3$

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right

near owl
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why is there a two? at the end?

clever fjordBOT
#

Nguyễn Tuấn Minh

lucid hollow
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just a typo

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right (for real)?

near owl
#

alright, i think i understand

#

ty

#

.close

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soft wharf
#

guys

odd edgeBOT
lucid hollow
#

??

fluid tundra
odd edgeBOT
#

@soft wharf Has your question been resolved?

soft wharf
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devout sierra
odd edgeBOT
devout sierra
#

<@&286206848099549185>

fluid tundra
odd edgeBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

devout sierra
tepid pelican
devout sierra
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Not really

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it doesnt say the number of real solutions in that interval

tepid pelican
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We also need to know whether or not is there a perfect square factor

devout sierra
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since its a 6th degree polynomial, we can see that it has 6 roots R or C

tepid pelican
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or (x-2)^3(x+i)(x+1)(x-i)

fossil hawk
# devout sierra

At 1 it's negative and at infinity and -ve infinity it's +ve so atleast 2 real roots

tepid pelican
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it would be easier to just check that it's negative at 0 lol

fossil hawk
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And by Descartes rule of sign change atmost 2 real roots

fluid tundra
fluid tundra
devout sierra
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are you sure?

fossil hawk
fluid tundra
devout sierra
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because i asked and the teacher said to give the exact number of real roots

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he said descartes rule of signs wont be enough

devout sierra
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so we have to see how many roots are real and not just come up with a lazy answer that isnt even a proper answer to the question.

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according to him at least

fluid tundra
fluid tundra
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according to descartes' rule of signs, there is exactly 1 positive real root and exactly 1 negative real root

tepid pelican
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the problem is that we still need to find the number of complex roots

fluid tundra
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when the problem says "imaginary" does that mean of form 0 + bi

tepid pelican
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hmm that would simplify stuff

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but I think it means non-real

devout sierra
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no i know but my teacher doesnt want us to use the table and write the appropriate possibilities

fluid tundra
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exactly 2 real roots implies 4 non-real roots

devout sierra
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yeah but he wants to know how we get that number without using descartes rule of signs and without graphing the polynomial

tepid pelican
iron bear
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without using descartes rule of signs specifically?

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descartes rule of signs gives you the exact number of real roots here

zinc glacier
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doesnt it only give parity

fluid tundra
devout sierra
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He said that we have to count the number of distinct real roots and locate them in intervals. By subdividing the intervals containing some roots, it can isolate the roots into arbitrarily small intervals, each containing exactly one root.

iron bear
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no it's an upper bound and parity

zinc glacier
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oh right ok

iron bear
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descartes rule of signs handles all of that in one go though

devout sierra
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yeah but he doesnt count that as an answer

iron bear
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so it's just banned as a solution??

devout sierra
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basically

iron bear
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even though it gives the right answer

devout sierra
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yeah

iron bear
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okay you can walk your path of pain then

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IVT time

devout sierra
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because he says “its just a lazy way of doing math. you need to show your work by using any method to find those roots in given intervals whether its a arbitrarily small interval. it should give you the amount of real roots which arent complex.”

iron bear
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using a true theorem to prove your result is "a lazy way of doing math"?

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you need to get a better teacher

devout sierra
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well he doesnt count descartes rule of signs as a theorem

tepid pelican
iron bear
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of course, why hadn't i thought of that

devout sierra
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guess we should all be damn math prodigies according to my teacher

iron bear
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i'll come back to you in 2937392919191 years after i've proven that 1 + 1 = 2

devout sierra
#

man i hate him

fluid tundra
tepid pelican
devout sierra
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alright lets just move on to the other 3 questions. ill just ask him tomorrow what he wants for that problem

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now its just solving polynomials haha

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so yeah thats the easy part

tepid pelican
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You could just accidentally copy over proof of descartes rule of signs and accidentally rediscover some theorem, of which you didnt know is banned

merry finch
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that's what newton said

devout sierra
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so he gave us a few polynomials to solve

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$x^4+4x^3-9x^2-32x+8=0$

clever fjordBOT
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ビジヨン

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ビジヨン

devout sierra
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how do we do that?

iron bear
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quartic depression

devout sierra
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okay

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$x=y-1$

clever fjordBOT
#

ビジヨン

devout sierra
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thus i get $y^4-15y^2-6y+28=0$

clever fjordBOT
#

ビジヨン

devout sierra
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but i still need to remove the linear term

devout sierra
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@fluid tundra

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@tepid pelican

odd edgeBOT
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@devout sierra Has your question been resolved?

mystic saffron
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u supposed find the number of roots?

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nvm brah

odd edgeBOT
#

@devout sierra Has your question been resolved?

odd edgeBOT
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urban timber
#

i dont know how to do this quwstion

odd edgeBOT
hardy panther
urban timber
#

10

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sorry for not clarifying

proper solstice
#

use 1/2 ab sin(C)?

urban timber
#

yeah but i dont understand the 3QR = 4PR thing

proper solstice
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let PR be x

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it means that 3 times the lenght of QR is the same as 4 times the lenght of PR

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so 3*QR = 4x

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QR = 4/3 x

urban timber
#

.close

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woeful rivet
#

guys can u help me

odd edgeBOT
woeful rivet
#

where is the derivative used and applied in a real world context

copper quarry
#

hello bum chicken

woeful rivet
mental lotus
#

Derivatives are used in many places, you use them in any and all kinds of simulations

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Stock market predictions

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Animations

woeful rivet
#

should i do population growth

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i wanted to do a water slide

copper quarry
#

u should do astrophysics and rockets 😎

woeful rivet
#

wait ima do acceleration

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wait but i dont even know how rockets work tf

copper quarry
#

Lol

woeful rivet
copper quarry
#

only in y10

woeful rivet
#

they suc fr

copper quarry
#

they are free marks

woeful rivet
#

mine doesnt have a marking key

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😭

copper quarry
#

gg

woeful rivet
#

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wide drift
fossil hawk
#

Try to make cases
When b is a multiple of a
When a and b are coprime etc

odd edgeBOT
#

@mystic saffron Has your question been resolved?

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quartz bridge
odd edgeBOT
quartz bridge
#

Can someone help me with this

clever fjordBOT
tepid pelican
#

Q8?

quartz bridge
#

9

tepid pelican
#

Okay

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let's start with the parallel line

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parallel line should have the same slope, right?

quartz bridge
#

Yes

tepid pelican
#

so we are looking for a line of form 3x + 2y = k, that passes through point (3, 5)

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this way the slope stays the same

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and we are able to shift it up and down

tepid pelican
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(do you understand it till now btw? Or is something unclear)

quartz bridge
#

Am confused ngl

tepid pelican
#

Okay

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so we have the line 3x + 2y = 8

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and we want to find a line that is parallel to this one and has the same slope

tepid pelican
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can you rearrange it to the slope-intercept form?

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So that we can easily read of the slope and y-intercept

quartz bridge
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What does 3x + 2y mean

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Like it goes right 3 up 2 right

tepid pelican
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x is the coordinate in horizontal direction

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y is the coordinate in vertical direction

tepid pelican
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so e.g. the point (0, 4) would sit on that line

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because 3*0 + 2*4 = 8

tepid pelican
#

(2, 1)

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we can again verify that 3*2 + 2*1 = 8

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this is how the whole graph looks like

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we can also rearrange the equation like this

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3x + 2y = 8
2y = 8 - 3x
y = -3/2 x + 4

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this is the so called slope-intercept form

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-3/2 is the slope of this line

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4 is the y-intercept

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and when we want to find a line that's parallel to this one, we want the slope to stay the same, and only the y-intercept to change

quartz bridge
#

I think I get it

tepid pelican
#

cool

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so we can now set up an equation of line like this:
y = -3/2 x + c

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where c is some number we dont know yet

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and we want this line to pass through the point (3,5)

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so we need to set up an equation and solve for c

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the way we do it is that we plug in the coordinates (3,5) to the equation y = -3/2 x + c

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so we get 5 = -(3/2)*3 + c

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can you solve for c now?

quartz bridge
#

C is 3,5 right?

tepid pelican
quartz bridge
#

Is c the y intercept

tepid pelican
#

yep

tepid pelican
quartz bridge
#

I mean we need to find the line that goes through there right

tepid pelican
#

not the line that has y-intercept 3.5

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this is a line with y-intercept 3.5, and the point above it is (3, 5)

quartz bridge
#

Oh I meant that, didn’t mean to be confusing how do we find it

tepid pelican
#

you can see that the line doesnt pass throug hthat point

tepid pelican
#

y = -3/2 x + c
So we have this general equation

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and we need to find c, such that it goes through the point (3,5)

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to do that, we set up an equation by plugging in the coordinates (3,5) in the equation y = -3/2 x + c

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so we get 5 = -3/2 * 3 + c

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and using this equation, we solve for c

quartz bridge
#

Where did the 5 come from

tepid pelican
#

5 is the y-coordinate of the point (3, 5)

quartz bridge
#

Oh

tepid pelican
#

because we want to make sure that it passes through point (x, y) = (3, 5)

quartz bridge
#

👍

tepid pelican
#

so then we get this equation

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5 = -3/2 * 3 + c

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try solving it now

quartz bridge
#

Ngl I got to go can you finish it cause my teacher won’t let me on my phone and I can just read it later

odd edgeBOT
#

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hearty kite
#

would someone be able to tell me what the degrees of freedom is for this questions? I feel like my answer is wrong

hearty kite
#

<@&286206848099549185>

fossil hawk
hearty kite
#

bruh i had a feeling somone would say this

#

shall we keep it in the context of statistics?

fossil hawk
#

Was jk wut sry

sudden lotus
hearty kite
#

yeah sick

#

really helpful

#

.close

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sudden lotus
#

wait I could probably help you from that problem

hearty kite
#

oh?

sudden lotus
#

just give me a minutes to let me try solve this problem

odd edgeBOT
#

@sudden lotus Has your question been resolved?

sudden lotus
#

this is the answer hehe

#

Yepsss

#

@hearty kite here's the answer

odd edgeBOT
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sudden lotus
#

Reopen

odd edgeBOT
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smoky estuary
#

I'm confused by a coding challenge I'm working on. Imagine an Equilateral triangle where you are given the orientation of one side (radians away from the positive x-axis), the side length, and the center x,y coordinates. How would you "find the rotation" around the z-axis? Isn't that just the orientation?

ivory dock
#

Depends

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on where the center is

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also depends on the initial orientation

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try to sketch some cases for yourself

smoky estuary
#

Initial orientation wasn't give, so I assume 0 radians. say the center is (225.05, 265.596). Orientation of one of the sides is 1.87115 radians.

#

I guess my real question is how is orientation supposed to affect the values I'm asked to calculate? Assume we are looking at the 2D shapes through a camera in 3D space. We're asked to provide the area, perimeter, and centroids for each shape along with other geometric properties. Wouldn't orientation have zero affect on other geometric properties?

ivory dock
#

Note that you know the orientation of A side, not the baseline side

smoky estuary
#

correct

ivory dock
#

Suppose you're given this blue side, see how the placement of the center can change the orientation?

#

The image won't send 😦

smoky estuary
#

Yes

ivory dock
#

So the orientation of the given line does not singlehandedly define the orientation of the triangle since it's not necessarily the baseline

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Or even if you view it as such, there's always at least 2

smoky estuary
#

So what I'm hearing you say is that more information is needed to calculate rotation around the z-axis?

ivory dock
#

more than the rotation of the one side

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which is why you get the point

smoky estuary
#

Got it

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Well wait

#

The center coordinates are given

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along with orientation of one side, wouldn't that define the orientation/rotation (not sure the difference now) of the entire triangle?

ivory dock
#

yup

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you asked if the side is enough

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it's not

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but the side and the point are

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or at least if I understood your question right

smoky estuary
#

But my question is, how would orientation (taking all other information we have into account) affect whatever information I can provide about this shape? In order words, what can I say about this shape and/or its position in space that is affected by orientation. Initially, I'm asked to provide area, perimeter, and centroid, which of course don't depend on orientation. Then, I'm later asked to describe the rotation of the shape around the z-axis. What does that mean? Isn't the orientation, again with all other information taken into account, the rotation about the z-axis? What more information is there for me to deduce?

ivory dock
#

Well I guess you have to deduce if the orientation is on one or the other side

#

based on the point

odd edgeBOT
#

@smoky estuary Has your question been resolved?

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limpid notch
#

i'm stuck in multiplying a trinomial and a binomial, the problem is the following:

(x^2 + xy + y^2) times (x - y)

I was simplifying by distributing and multiplying x^2 by x which got me x^3, and multiplying x^2 by -y which got me -xy^3, but when i get to xy times x i completely fall apart in that step

help would be much appreciated

tacit wasp
#

Well, first you multiply x² by each term on the other brackets

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So x³ - x²y

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Now do the same but with xy
You get x²y - xy²

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And finally the same but with y², which leads you to xy² - y³

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If you sum the three results you get x³ - y³

odd edgeBOT
#

@limpid notch Has your question been resolved?

limpid notch
#

i worked it out now

odd edgeBOT
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merry finch
#

So I’m sort of confused about systems of odes and I’m terrible at understanding them

merry finch
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So there’s just weird A that pops up

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And it’s the matrix with the coefficients of the system given

crystal zinc
#

At first glance A is an operator

merry finch
#

Of course it’s a matrix so it needs to be written wrt some basis

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What is this basis?

crystal zinc
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depends on your specific equation

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or system

merry finch
#

Let’s say like this

crystal zinc
#

presumably you mean a set of linear ODES?

merry finch
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Uh yes linear odes

crystal zinc
#

where f=(f_1, f_2)^t

merry finch
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Yes

crystal zinc
#

you usually want to diagonalise the matrix

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here A is ((2,1),(1,2))

merry finch
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Ok but first

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What’s the basis of this matrix

crystal zinc
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matrices don't have a basis?

merry finch
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Well matrices need to be written wrt some basis

crystal zinc
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not particularly

merry finch
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So I need a basis of C² and C¹ no?

crystal zinc
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what is the function space C^2? twice differentiable functions?

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sorry been a while for me

merry finch
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I have 2 linear operators d/dt and A, and I want to say that they do the same thing to some special f’s

crystal zinc
#

ah, in that case, let's not get into what the bases of those vector spaces are

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because that's not important

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all your matrix is going here is encoding information about a system into a more easily digestible form

merry finch
# merry finch

Well I don’t agree from here that A is what you said it is

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I would need to be given bases to write down the numbers in the matrix

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But it seems to be given in the form by the question being a system

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Thats sort of what I’m confused about

crystal zinc
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let me write the solution down

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,w diagonalise ((2,1),(1,2))

crystal zinc
merry finch
#

So the first line is fine

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2nd line is the question?

crystal zinc
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indeed

merry finch
#

I still don’t really get why A is that matrix

crystal zinc
#

the crux is just the last two lines

merry finch
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Third line is fine

crystal zinc
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have you done linear algebra before?

merry finch
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Fourth is okay as well

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And now why do we have on the 5th line that S^-1 d/dt = d/dt S^-1

merry finch
crystal zinc
#

you've done systems of linear equations?

merry finch
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I’m just really stuck on the part where a matrix is only a representation of some linear transformation with respect to some basis on the domain and the codomain

crystal zinc
merry finch
#

A matrix can’t just pop up by itself

crystal zinc
#

okay

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let's do the reverse

merry finch
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But S^-1 is not a multiplication with a scalar

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Ok let’s leave S^-1 for now

crystal zinc
#

write a general matrix ((a00, a01)...)

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and multiply it by a general vector

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(x1, x2)

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and tell me what you get

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should get another vector as a sanity check

merry finch
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But matrix multiplication is weird and archaic

crystal zinc
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do it

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you're the one wanting to understand

merry finch
#

I understand that you do get what is desired

crystal zinc
merry finch
#

Is there not a basis-free version of this

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And I don’t even see a basis anywhere

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Matrices written without basis are meaningless

crystal zinc
#

you don't need to know the basis is my point

crystal zinc
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which don't really need a basis to work

merry finch
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They’re only linear maps wrt some basis

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The numbers in the matrix depend on the basis you pick

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So when you say it’s (1,2),(2,1), what basis did you pick to say that

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That’s what doesn’t make sense to me

crystal zinc
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in that case, f1 and f2

merry finch
#

But somehow when you do (1,2),(2,1)f it does indeed recover the conditions given

crystal zinc
#

that's your basis

merry finch
#

Huh

crystal zinc
#

i really don't understand what you don't understand

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because you understand where the numbers in the matrix come from

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and then you understand how to make it solve your odes

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(i think)

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@merry finch you still here/need any help?

merry finch
#

I’m thinking

crystal zinc
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on the matrix bit?

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okay lets consider a one dimensional basis of one meter

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i can use a linear transformation which is a stretch of 1000 to make the new basis a unit of a kilometre

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but i could use the same transformation to map a gram to a kilogram

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hell i could map a banana to a kilobanana but that's probably enough potassium to cause ten heart attacks

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@merry finch I'm off bed, gn

odd edgeBOT
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@merry finch Has your question been resolved?

odd edgeBOT
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graceful parrot
odd edgeBOT
graceful parrot
#

What is 5.a. Even asking me to do?

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Find average velocity of the pebble for t=4 you just put 4 in the y= equation right

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But what does and lasting part mean

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Ok so I’m wrong and dumb

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Can someone explain please

brittle beacon
#

You'd want the average between two times, so they tell you that you "start" your time at t = 4, and they give you three choices of how long you'll be measuring for

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So from t = 4 to each of t = 4.1, 4.05 and 4.01 respectively

graceful parrot
#

Oh ok so like y(4.1)-y(4)/4.1-4

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@brittle beacon how would I find the instantaneous velocity in 5b?

brittle beacon
#

Well, as you do each of those averages, you should, theoretically, see that they approach a certain value, and what you think it'd end up as should be your estimate for the instanteneous velocity

graceful parrot
#

So like my guess what be

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Whatever it approaches to at like 0.0001

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0

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To 0

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I mean

brittle beacon
#

Yeah, the instantaneous velocity is basically what happens to your average velocity when the time period you take it over shrinks to zero

graceful parrot
#

And see where it approaches

brittle beacon
graceful parrot
brittle beacon
#

Into the average velocity, or?

graceful parrot
#

For the instantaneous

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Instead of doing 1.0001

brittle beacon
#

As in, doing ( y(1) - y(1) ) / (1 - 1), or do you mean something else?

graceful parrot
#

Like 10(1)-1.86(1)^2

brittle beacon
#

That only tells you your position, and not even a rate, is why

#

As @copper quarry is hinting at, there is a way you could skip a lot of work and just put in t = 1 "somewhere", but it isn't into the equation for y as it is

graceful parrot
#

Yes

brittle beacon
#

(assumedly you're probably at a point where they're motivating the definition of the derivative, so they're first making you do stuff "the long way")

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compact steppe
#

is there a way to simplify this furhter : $$(\ln n)^{\ln (\ln n)} = e^{\ln((\ln n)^{\ln (\ln n)})}=(e^{\ln (\ln(n))})^{\ln(\ln(n))}$$

clever fjordBOT
compact steppe
#

ideally i'd like to have n as the base, instead of e

odd edgeBOT
#

@compact steppe Has your question been resolved?

compact steppe
#

<@&286206848099549185>

#

for context, the original problem is this $\sum \frac{1}{(\ln n)^{\ln (\ln n)}}$

clever fjordBOT
compact steppe
#

i.e. it should be solved by comparison test im p sure, i just need to transform the denominator so that i can bound it

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which is what i tried above but i didnt get anything easily boundable

odd edgeBOT
#

@compact steppe Has your question been resolved?

sly egret
#

there sure is a way

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$e^{(ln(ln(x)))^2}$

clever fjordBOT
#

NulledOutChicken

compact steppe
#

@sly egret thanks, but I don't see how to proceed from here

odd edgeBOT
#

@compact steppe Has your question been resolved?

somber vault
#

Condensation test- the sum converges iff-
Sum{2ⁿ/(ln(2ⁿ)^(ln(2ⁿ)))}=Sum{2ⁿ/(nln(2))^nln(2))}≤Sum{(2/ln(2)n)ⁿ}

somber vault
#

If you're only trying to show convergence and don't care about the actual value

compact steppe
#

@somber vault thanks, but a very similar problem $\sum \frac{1}{(\ln n)^{\ln n}}$ I've seen solved with comparison test, so I'm trying to do the same. although the slight difference might make it unsolvable w solely comparison as I intended

clever fjordBOT
compact steppe
#

and I'd especially like to learn whatever logarithm manipulation is needed to make it happen/make the problem approachable

somber vault
#

But yh give solutions <@&286206848099549185> with only comparison if existant

odd edgeBOT
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@compact steppe Has your question been resolved?

odd edgeBOT
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@compact steppe Has your question been resolved?

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maiden badger
#

This shi is clearly no solution

odd edgeBOT
maiden badger
#

what the hell so i write than?

forest sky
#

reduce it to RREF. the augment column is treated as a regular column in the matrix for this

maiden badger
#

so basically make a_12 a 0?

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and a_22 a 1?

forest sky
#

no

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you have two pivots, each of them should be alone in their column

maiden badger
#

im sorry im lost its my first day of linear

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wdym pivots

forest sky
#

leading 1's

maiden badger
#

.close

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full crane
odd edgeBOT
earnest nebula
#

and add them to the y=mx=c equation

#

gradient = y2-y1/x2-x1

#

intercept is the point where the line cuts the y axis

#

for example, in the first question intercept is 4

odd edgeBOT
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@full crane Has your question been resolved?

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rancid ingot
odd edgeBOT
rancid ingot
#

Wood cutter in the shape of the function cuts into a piece of wood

#

Defined between 0 and 1

#

Im having more issue with the understanding how this translates into an equation i guess, and how the function gets put to the power of 2, the equations below are the answers

#

If i just put the f(x) in an integral in calculator it doesnt know the answer

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Nvm, i just wana know how f(x) can be put to the power of 2

#

How does that work

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hollow quarry
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south musk
#

can anyone help how to start this question

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naive sigil
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carmine vault
#

Hey, we need some help for our linear algebra course, we are working 2022 exam to study and we are stuck on this problem.

in question a we calcuated the determinant easily and we got -3a + 18
In question b we used the fact if the determinant is 0 then there is pivot collumn therefore there is only one unique solution
in part 3 where there is no solution we are completly stuck. We have an idea in regards to free variables but we can't compute any solution.
MATLAB/Python is allowed for us if that helps.
Thanks.

tulip niche
carmine vault
tulip niche
#

So, to have exactly one solution to a linear system (with a square matrix), you need the determinant to be nonzero

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If the determinant is 0, then either you have no solutions, or you’ll have infinitely many solutions

carmine vault
#

Ah gotcha, probably mixed up my definitions

tulip niche
#

Yeahhhh sometimes that’s how it goes

carmine vault
#

Any ideas for c on a conceptual level? If i had a way to get started then I'll go and write some code, but no ideas on how to get started

crystal zinc
#

Well you check for when determinant is zero

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That gives you your not unique exact solutions case

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And then you check for whether there are any solutions

tulip niche
#

Yes, so if the determinant is 0 and there’s at least one solution, then there must be infinitely many solutions

carmine vault
#

o7 thanks for the tips

#

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elfin bear
#

y=a
prove: y'=0

odd edgeBOT
elfin bear
#

I only get y'=1

green sage
#

limit definition, no?

elfin bear
green sage
#

limit as h goes to 0 of (a-a)/h

tacit haven
elfin bear
green sage
#

yea but x-x is always 0

elfin bear
green sage
#

that’s not how limits work

tacit haven
#

since y = a is a line you can directly find the slope of it

elfin bear
green sage
#

since x-x is always 0

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and h is not always 0

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the limit must be 0

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since 0/anything = 0

elfin bear
#

ty

#

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quaint panther
#

Hello

odd edgeBOT
quaint panther
#

Answer is 10 but i have no idea why and how

#

Could someone help me?

tepid pelican
quaint panther
#

Okey

tepid pelican
#

then if we separate all the 3's from there, we will be left with 3^x * A

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and since we've seperated all 3's, the x will be maximal

quaint panther
#

One sec

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But how do i prime factorize 26!

tepid pelican
quaint panther
#

Alright

tepid pelican
#

we actually don't need to do whole the factorization

quaint panther
#

Thanks btw

tepid pelican
#

we only need to count how many 3's are in there

quaint panther
#

👍 yup

tepid pelican
#

note that 26! = 1 * 2 * 3 * 4 * 5 * 6 * 7 * ... * 26

quaint panther
#

Exactly

tepid pelican
#

obviously, numbers like 2, 4, 5, 7... which aren't multiples of 3 won't contribute any 3's to the overall count

quaint panther
#

Okey

mystic saffron
# quaint panther

u just need the amount of 3's here, since question has nothing to do with A , but does with x

tepid pelican
#

on the other hand, numbers like 3, 6, 9, 12, 15... which are multiples of 3, will contribute 3's to the overall count

quaint panther
#

Okey

mystic saffron
#

answer is 10?

tepid pelican
#

so it would be a good idea to count the number of multiple of 3, up to 26

quaint panther
mystic saffron
#

should be 8 no??

tepid pelican
#

ill explain why soon

tepid pelican
quaint panther
#

Yea

#

One sec

#

3-6-9-12-15-18-21-24-

tepid pelican
#

okay! you have even listed them

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that'll be useful now

#

how many 3's does each of them contribute to the prime factorization?

mystic saffron
#

right

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3*2 is 6

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that way

quaint panther
#

Wait how

mystic saffron
#

got it 10

mystic saffron
quaint panther
#

2

mystic saffron
#

no brother

#

1

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6=3*2

quaint panther
#

How 3+3

mystic saffron
#

so it has 1 3

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i meant multiuplication

quaint panther
#

Ahh we look at multiplication

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Okey

#

İt has 1

tepid pelican
tepid pelican
quaint panther
#

Then okey

#

One sec

#

3 = one 3
6 = 1
9 =3x3 = 2
12 = 1

#

İs that true so far

mystic saffron
#

yep

#

now do that for each number, the ones youve listed

quaint panther
#

15 = 3x5 = 1
18 = 3*6 so 1?

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Or is 18 2

mystic saffron
#

6 has a 3 too

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so 2

quaint panther
#

Okey

mystic saffron
#

2

#

lowest factors

quaint panther
#

21 has 1
24 has 1

tepid pelican
quaint panther
#

Then it should add up to 10

tepid pelican
quaint panther
#

So know i know why its 10 thank you all for that but now i have another quick question

quaint panther
#

The tesbook show hiw to do it

tepid pelican
#

it probably does stuff like 26/3 and 26/9, right?

quaint panther
#

Yea

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How does this work

tepid pelican
#

26/3 counts the number of multiples of 3

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so instead of listing them all, we can just count them

tepid pelican
#

so there are 8 multiples of 3

quaint panther
#

But we just divided it with 26 not with 26!

mystic saffron
#

@tepid pelican dont ,ind me asking, youre a professor? u seem like u know ur shit.

tepid pelican
quaint panther
#

Okey

tepid pelican
#

and we want to count how many multiples of 3 are in that sequence 1, 2, 3, ... 26

quaint panther
#

Yes

mystic saffron
tepid pelican
#

so we dont care about 26! anymore, we just want to count the number of multiples of 3 up to 26

#

and every third number is a multiple of 3

#

so we divide 26 by 3

quaint panther
#

Ahh okey yea

tepid pelican
#

when we round it down

#

but there are also some multiples of 3, that contribute with more than one 3 to the factorization

#

namely, 9 and 18

#

those are multiples of 3^2 (9)

quaint panther
#

Yep

#

They have 2 threes in them

tepid pelican
#

correct

#

we already counted them once, because they are also multiples of 3

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but we need to count them for the second time now

#

so we do 26/9

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and we get 2

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so we do 8 + 2

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and we get 10

quaint panther
#

Hmm okey

#

İ think i kinda got it

#

But if its like this

#

Why is there an A in the question

tepid pelican
#

and also to make you think about it a bit more

quaint panther
#

Okey thanks a lot!

tepid pelican
#

to be specific, you have to realize that A can't be a multiple of 3, otherwise x wouldnt be maximal

#

and then the key idea is counting 3's in factorization of 26!

quaint panther
#

Ahh yes thats true

mystic saffron
#

if A would be a multiple. then again powers would add up as per the exponential rules

#

and then maximum wouldnt be attained

quaint panther
#

True

#

Thanks both of you for helping

#

And sorry that i took your time

#

Have a nice day

mystic saffron
#

youre good homie

tepid pelican
quaint panther
#

Thanks!

#

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worldly sleet
#

How to solve x^4 -1

odd edgeBOT
worldly sleet
#

I’ve started to factorise

#

But don’t know how to continue

stoic torrent
#

Well keep going haha

#

Thats the way you solve it

#

Where have you gotten ?

craggy jasper
stoic torrent
#

Yes

worldly sleet
stoic torrent
#

Ok

#

Try factorising more

worldly sleet
#

Okok

stoic torrent
#

For any polynom

#

If you find a root

#

You can factorise by x-root

#

And keep going

craggy jasper
stoic torrent
#

Here you found x-1

stoic torrent
worldly sleet
stoic torrent
#

Yes

#

Can you factorize x²+1 further ?

#

ie finding more roots

worldly sleet
#

Even further

worldly sleet
#

But maybe you can

stoic torrent
#

Correct

#

The two remaining roots are not real numbers

#

If you only study real numbers

mystic saffron
#

x²+1 = p

#

0*

#

+- i

stoic torrent
#

You can not go any further, that is an irreducible polynom

#

Which are degree 2 polynoms with no roots

#

Or x + a

#

Here you have 2 degree 1 polynoms

#

1 irreducible

#

That gives you all the possible solutions

worldly sleet
#

Okey cool then i get 4 roots in total

stoic torrent
#

If you count the imaginary ones yes

mystic saffron
#

yes

stoic torrent
#

Counting imaginary roots and double roots as 2, a degree n polynom always has n roots

mystic saffron
#

its +-sqrt(-1)

#

not sqrt1

worldly sleet
mystic saffron
#

no

#

third line

worldly sleet
#

Okey i see

#

Thanks 👍

mystic saffron
#

gud

#

np

worldly sleet
#

.close

odd edgeBOT
#
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odd edgeBOT
#
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errant atlas
#

Hello, I had a quick question. I am trying to figure out how to convert 60kg of downward force in gravity to newtons. I haven't done anything relating to anything like this in maths before so I just need some general help

uneven osprey
#

either way

errant atlas
#

I understand that gravity is 9.8m/s so what would be the equation from there?

uneven osprey
#

Force = Mass times the Acceleration

errant atlas
#

oh my god

uneven osprey
errant atlas
#

and what unit comes out the end?

#

kg/f or n?

uneven osprey
proper solstice
#

wait

errant atlas
#

holy shit 588N that's a lot for what I'm doing

#

Thanks very much

proper solstice
#

the unit of force is N not kg

uneven osprey
#

And Newton= kg meters per second^2

proper solstice
#

so downward force can't be in kg

#

if you're asking the downward foce of an object of mass 60kg, on earth it's mass * g (acceleration due to gravity) = 60 kg* 9.8 m/s^2 = 588 N

Note:
1N = 1kg m/s^2
9.8 m/s^2 is an approximation only. Sometimes g = 10 m/s^2 is taken for ease.

odd edgeBOT
#

@errant atlas Has your question been resolved?

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weary compass
#

My question says "ten times the sum of half a number and 6"

weary compass
#

How would I make that into a equation

#

Like would I do 10 (1/2x +6) or 10 • 1/2x + 6

nimble blaze
#

expression not equation,

#

you'd go with the first

weary compass
#

Also why is it the first and not second

nimble blaze
#

sum of: [what follows here is expected to be a list of expressions]

#

the latter would be something like
sum of ten times half a number and six

mystic saffron
weary compass
#

Wait isn't sum just mean like plus

nimble blaze
#

in this case its a list of two expressions separated by "and"

#

its associated with +

#

sum is the result of addition

#

sum of: ...
is the result of adding those things together

mystic saffron
nimble blaze
#

e.g. sum of 5 and 7 is
5 + 7

weary compass
#

.close

odd edgeBOT
#
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odd edgeBOT
#
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slim summit
odd edgeBOT
slim summit
#

Do I use pv=nRT for this

forest sky
#

yes

odd edgeBOT
#

@slim summit Has your question been resolved?

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#
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limber quarry
#

Hey so we are told to calculate the fourier transform of this graph but what i dont understand is that in the solution theyve said that due to the linearity property of fourier transforms, we can simply add together the fourier transforms of each segement. However, for the rectangle parts theyve used the general fourier transformation of rectangular signal but we dont actually have a signal at the top (ie. by the dotted lines) so how come we can use the fourier transformation of rectangular signals there?

odd edgeBOT
#

@limber quarry Has your question been resolved?

odd edgeBOT
#
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sage helm
#

If M is a matrix, and i-hat is the basis vector [1, 0, 0], is the following result correct?

sage helm
#

It's supposed to be multiplied by the vector... forgot to show it

sharp girder
#

you could do the multiplication and check yourself

sage helm
#

The learning material that I'm learning from uses row vectors. I'm trying to verify if my column-vector answer is correct.

sharp girder
#

well it would be correct

#

but you can also check it by doing the multiplication yourself

#

row x collumn

sage helm
#

.close

odd edgeBOT
#
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odd edgeBOT
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young sedge
odd edgeBOT
young sedge
#

my P'(t) = 520 * ((210-2t^2)/(70+t^2)^2

silk quail
#

$P'(t)=570\left(\frac{3}{70+t^2}-\frac{6t^2}{(70+t^2)^2}\right)$

clever fjordBOT
young sedge
#

the one goes to zero

#

the derivative of 1 = 0 i mean

silk quail
#

yes

young sedge
#

i used quotient rule for the other term

#

then plugged that into the product rule

silk quail
#

yes, also you have to use chain rule for the t^2 at the bottom

young sedge
#

the (70+t^2)^2?

silk quail
#

well, the t^2 inside it

young sedge
#

its not chain rule

#

(70+t^2) = g(x)

#

so i just get 2t

silk quail
#

that is chain rule, multiply by 2t

#

in the second product

young sedge
#

brah im so lost theres a gazillion steps 😭

silk quail
#

3 is already there, so you get -6t^2, which simplifies fully to $P'(t)=570\left(\frac{270+3t^2-6t^2}{(70+t^2)^2}\right)$

clever fjordBOT
#

fish
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

young sedge
#

right so 270-3t^2

silk quail
#

yes

#

i mean 210

#

not 270

young sedge
#

i cant get it right wtf

#

wait

#

its 570 * 3 right

silk quail
#

yeah, but you can just multiply all the stuff in the parenthesis

young sedge
#

im going insane

silk quail
#

let me try going step by step

young sedge
#

okay so we have

#

570(270-3t^2/(70+t^2)^2)

silk quail
#

it's 210 by the way, i made a mistake

#

since it's 3*70

young sedge
#

its 8.53

#

lol my process was technically right i just had some miscalculations

silk quail
#

yeah that's correct

young sedge
#

ty

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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drowsy timber
#

Hey, I'm doing work for AP Calculus and I was wondering if this answer would be 1/2 or -1.

drowsy timber
#

I got told that if both sides approaching the limit on the first one go up, I should take into account the left side if it its split on the second f but I don't know if this applies here as there is a hole on the left side

orchid torrent
#

$\lim_{x \to -1} f(f(x))=f \left(\lim_{x \to -1} f(x) \right)$

clever fjordBOT
#

Civil Service Pigeon

orchid torrent
#

Now, consider ||the “direction” that f approaches 3 from as x approaches -1||

drowsy timber
#

yeah I understand up to that point, I just repeat the process but with x=3

orchid torrent
#

Uh sure ig

drowsy timber
#

but I get confused the second time

#

will the final answer be -1 or 1/2

orchid torrent
#

This determines the direction you approach 3 from

drowsy timber
#

so from - or below

#

that means that although there is a hole on the left side, it does not matter, and the answer is -1?

orchid torrent
#

Yes

drowsy timber
#

thank you so much mate, I really appreciate what you are doing and I hope you have a great day

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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visual iris
#

is this statement true or false?

odd edgeBOT
low locust
#

what do you think

visual iris
#

it could be false right?

slate hinge
#

why do you think so?

#

what was your process?

visual iris
#

coz if A = 1 B = {1,2,3} and C = {{1,2,3},4,5}

#

A in B

#

and B in C

#

but C has the set in the set

#

not specificly 1

#

does it work like that or am i doing too much

slate hinge
#

yes, well, the question doesn't define is A B C are elements, sets

#

just, random topological spaces

visual iris
#

oh right

slate hinge
#

but I think they want the answer to be yes

visual iris
#

that makes more sense

#

cool thanks 🙏

low locust
slate hinge
#

Set's are complicated

slate hinge
low locust
#

so you just want to sow confusion?

#

like the example shows, the statement is false

visual iris
#

wait now im confused 💀

#

would it be true or false?

low locust
#

your example shows that it is false

slate hinge
#

you presented an exemple where is false, it is enough to show that it's not always true.

visual iris
#

oh ok

#

thanks