help-19

[modest nacelle]

!noping

[odd edge]

Please do not ping individual helpers unprompted.

[noble swallow]

Ummm

I pinged the role?

[modest nacelle]

Also, please put the question at the very first of the message. Not ping nor hello

[noble swallow]

Understandable. Will do

[short topaz]

u also suppose to wait like 30 or 15 min before pinging helpers

[modest nacelle]

Also, I meant

!15m

[odd edge]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[noble swallow]

Understood, my bad.

[short topaz]

just read #❓how-to-get-help
once

[noble swallow]

Ok

[modest nacelle]

In Latex, that would be
$$(0.5)^{\log_{3} \log_{1/5} x^2 - \frac{4}{3}} \leq 0$$
, right?

[clever fjord]

Xwtek

[noble swallow]

Indeed

[modest nacelle]

And the question is?

[noble swallow]

Interval

Of x

Wavy curve solving

[modest nacelle]

That looks impossible to me.

Exponentiation function always results in strictly positive answers.

!original

[odd edge]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[noble swallow]

It is like

Write .5 as 0.5 power 0

[modest nacelle]

$$0.5^0 = 1$$

[clever fjord]

Xwtek

[noble swallow]

So yeah the exponential part is ≤ 0

[modest nacelle]

Uh what?

[noble swallow]

The base is same

[modest nacelle]

You can't have an inequality as an exponent.

[noble swallow]

My bad the question

Is actually

[rapid reef]

@noble swallow send a photo of the question

[noble swallow]

1

[modest nacelle]

No, i mean, you can only have a number raised with another number, not an inequality

[noble swallow]

Same as this but > 1

[modest nacelle]

Does $$5^{x\leq 3}$$ make sense to you?

[noble swallow]

But that is not what it is

[clever fjord]

Xwtek

[noble swallow]

Also not that

Just remove the base

They are the same

[modest nacelle]

Wait, please write the Latex for us, because the formula is confusing right now. Better is the original screenshoot

[noble swallow]

In Latex, that would be
$$(0.5)^{\log_{3} \log_{1/5} x^2 - \frac{4}{3}} \g 1$$
, right?

[clever fjord]

SusGusInaBus
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[noble swallow]

I do not know latex sorry :c

[modest nacelle]

\geq, not \g

[rapid reef]

,, 0.5^{ \log_3 \log_{1/5}( x^2 - \frac 43 ) } > 1

[clever fjord]

shsgd

[rapid reef]

This?

[noble swallow]

Yes

Thank

You

So yeah, what my teach did was write 1 as $$ 0.5^{0}$$

[modest nacelle]

Surround the formula with $$

[clever fjord]

SusGusInaBus

[noble swallow]

Oo yeah

[modest nacelle]

Yeah, $0.5^0 = 1$ indeed

[clever fjord]

Xwtek

[noble swallow]

And then

He wrote log part is less than 1

My first doubt is why did he switch the sign?

If $$2^x > 2^2$$ then x is greater than 2

[clever fjord]

SusGusInaBus

[modest nacelle]

Uh, $$\log_3 \log{1/5} (x^2-\frac{4}{3}) < 1$$? That doesn't look right.

[clever fjord]

Xwtek

[noble swallow]

It should be greater than shouldnt it

[modest nacelle]

It should be less than, but not 1

[leaden karma]

Yeah

[noble swallow]

Oh yeah

Sorry

0

But why less than

[leaden karma]

When the base is less than 1, the inequality flips

$2^2>2^1$, but $0.5^2<0.5^1$

[clever fjord]

kheerii

[noble swallow]

Ohh yeah

Makes sense

Ok after that?

[leaden karma]

Same thing when you compare logs

If the base is less than one the inequality flips

[noble swallow]

Mhm

Now after this what could I do

[modest nacelle]

After that it's trivial

[noble swallow]

Now ig I could write zero as

Log 1 base 3

And do it again

Lol no way that worked xDDDD

Close

@close

.close

[odd edge]

Channel closed

Closed by @noble swallow

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd edge]

Please don't occupy multiple help channels.

[lusty marsh]

.close

[odd edge]

Channel closed

Closed by @lusty marsh

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal wharf]

$\sin(2\theta) = 0,953$

[clever fjord]

jandro

[lethal wharf]

how can i find theta?

[north jasper]

Try to take inverse sine on both sides?

[lethal wharf]

i dont know mathematically

how to write that

[north jasper]

arcsin() is the inverse of sin()

[lethal wharf]

yep

[mystic saffron]

sin(nx) doesn't equal 953 for any value of x

[lethal wharf]

i mean its $\approx$

[clever fjord]

jandro

[slow sandal]

sin(2x) = 0.953

arcsin(0.953) = 2x

x = arcsin(0.953)/2

,w arcsin(0.953)/2

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by diddletoucher

[slow sandal]

@lethal wharf

[lethal wharf]

wait

im checking on photomat your solution

@slow sandal i think i need to do that

arcsin(0,953) = 72 degree

then /2

[slow sandal]

what is your question jandro

[lethal wharf]

yep now its good

[lethal wharf]

i mean

$\theta = \frac{\arcsin(0,953)}{2}$

[clever fjord]

jandro

[lethal wharf]

i need the result to be in degree

[slow sandal]

,w arcsin(0.953)/2 in degrees

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by diddletoucher

[lethal wharf]

yep

thanks

@slow sandal are you still here?

[slow sandal]

ye

[lethal wharf]

can you explain your calc

[lethal wharf]

.

[slow sandal]

do you know what arcsin is

[lethal wharf]

sin inverse

[slow sandal]

use sin inverse on btoh sdies

[lethal wharf]

.close

[odd edge]

Channel closed

Closed by @lethal wharf

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole anvil]

what is the difference between these two?

[whole anvil]

the one to the left makes sense when you are finding the derivative of something

but I don't understand the application of the one to the right

[slow sandal]

where have you seen the one on the right used

[icy kindle]

the one on the right is the average rate of change

[crisp wadi]

delta t approaches 0 on the first case and 1 on the second case

[whole anvil]

I don't remember

[whole anvil]

but what is the application

like

the one on the left can be used to describe derivatives

like this

[icy kindle]

it's the average rate of change from t to t+1

[crisp wadi]

The question is too broad I think, that's the same as asking the application of limits

[whole anvil]

damn

[whole anvil]

found it

no

nvm

that is sigma

I don't remember where I saw it

have any of you used a limit where the variable approaches 1?

[leaden karma]

it's not uncommon

we have $$\lim_{x\to 1}\frac{x^n-1}{x-1}=n$$ as a random example off the top of my head

[clever fjord]

kheerii

[leaden karma]

the limiting value can be really absolutely anything you want it to be

[leaden karma]

in this context it's a little weird but we need the full context

[whole anvil]

I don't understand where it is used

[whole anvil]

is this right?

or am I missunderstanding

if we put x =2

and n = 4

then that equation gives us n = 15

[leaden karma]

what...?

do you understand what a limit is?

[whole anvil]

or am I missunderstanding how limits work?

[whole anvil]

I'm not too sure anymore

I don't understand how you do calculations with them

[whole anvil]

it makes sense in this example

the way it has been explained to me

thanks anyways^^

.close

[odd edge]

Channel closed

Closed by @whole anvil

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing thistle]

need help with statistics

[blazing thistle]

i dont know how to find variance

i tried 14872.59/80 =185.90 but i dont know if thats the right answer

i used this formula

.close

[odd edge]

Channel closed

Closed by @blazing thistle

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tender pike]

i don't understand how to do this question. ive had a look at the mark scheme and still do not understand.

[leaden karma]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[leaden karma]

so you're telling me you have NO IDEA what the Binomial theorem is?

[tender pike]

maybe.

i've forgotten

[leaden karma]

then you have no business doing this exercise

[leaden karma]

$(a+b)^n = \sum_{r=0}^n \binom{n}{r}a^{n-r}b^r$

[clever fjord]

kheerii

[leaden karma]

do you recognise this formula at all?

[tender pike]

yes, i have just forgotten how to apply it

[tepid pelican]

https://www.khanacademy.org/math/precalculus/x9e81a4f98389efdf:series/x9e81a4f98389efdf:binomial/v/binomial-theorem

[tender pike]

OHHH this has helped spark my memory thank you !

.close

[odd edge]

Channel closed

Closed by @tender pike

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[umbral elk]

I need help with this problem

[umbral elk]

Like what formula i need to use

[velvet temple]

We don't even know what you're trying to solve 😆

[umbral elk]

.comands

[past mango]

you mean 1+cospi+cos2pi...cos2024pi?

[umbral elk]

Yeah

Until 2019

[past mango]

oh

[umbral elk]

It was a comand to rotate the photo

!comand

[velvet temple]

It justs alternates between 1 or 0

[velvet temple]

1->1
1 + cos(pi) -> 0
1 + cos(pi) + cos(2pi) -> 1
1 + cos(pi) + cos(2pi) + cos(3pi) -> 0

[past mango]

yep

[umbral elk]

like why is 1 + cos(pi) = 0 ?

[past mango]

because cos(pi)=-1

[umbral elk]

and cos of 2pi ?

[past mango]

1

because cos2pi=cos0

[velvet temple]

Well, I guess it would depend on how you're mathematical system is built, which is not really something I'm familiar with. So I'll just answer "That's how the cos function is defined"

[umbral elk]

like i remember at school i needed to learn sin/cos of 30/45/60

[umbral elk]

this are just for sin and cos ?

[velvet temple]

You can define the other trigonometric functions from only sin and cos

[umbral elk]

thx man

[latent quiver]

you can use astc rule for this

[umbral elk]

tell me more

[latent quiver]

you can divide the cartesian plane into 4 parts

and label each quadrent by A,S,T,C repectively

this will tell which trignometric functions are positive in which quadrants

for A-> all functions

for S-> sine

[latent quiver]

T -> tan

[latent quiver]

yeah exactly as above

thx

[past mango]

CAST

[latent quiver]

this tends to cause mistakes cuz people tend to label from first quadrant usually

[past mango]

ik just kidding

[latent quiver]

now according to the astc rule every odd multiple of pi will give -1 for cosine as output

and every even multiple will give +1 as output

[latent quiver]

is the last one supposed to be 2024 pi?

you can make pairs of cos functions like:

(cos(pi) + cos(2pi)) + (cos(3pi) + cos(4pi)) +.....

and each pair tends to cancel out to get 0

therefore 6.1 + 0 = 6.1

your last output shouldnt be 0 but 6.1

[odd edge]

@umbral elk Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual bough]

The question is whether is integral converges or diverges, i know i should use the fact that this expression is smalled that 2/(x^2 +4), but i dont know how to show that 2/(x^2 +4) converges

[orchid torrent]

,w integrate 1/(x^2+a^2)

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by civil_service_pigeon

[orchid torrent]

@visual bough ^

[visual bough]

do i typically need to prove this or is it usually given

because it isnt given on my profferors notes

[orchid torrent]

Idk depends what you’re given

It’s pretty easy to derive using trig sub

But it’s a fairly standard result

[visual bough]

yea... we dont use trig sub yet...

[cold swift]

then you can factor out a 4

in the denominator

and use a u sub

[orchid torrent]

You could compare it to 2/x^2 ig

[visual bough]

yea i could

okey thats it, thanks a lot!

.close

[odd edge]

Channel closed

Closed by @visual bough

Use .reopen if this was a mistake.

[grim cradle]

(It's not smaller than that. e^y>0 for all y)

[visual bough]

what

[orchid torrent]

Oh I didn’t even read the original question

.reopen

[odd edge]

✅

[grim cradle]

what?

[visual bough]

its it e^-x tho?

[grim cradle]

let y=-x?

[visual bough]

the whole expression would change then tho

[grim cradle]

?

e^(-2x)>0 for all x

since e^y>0 for all y

obv

[visual bough]

yea but its also smaller that 1 after x=1 if its reaised to -x

[grim cradle]

,calc e^(-2*1)

[clever fjord]

Result:

0.13533528323661

[grim cradle]

notice how it is >0?

[visual bough]

yes

also smaller than 1 tho

i mean to put 3/(x^2 +4) mb

[odd edge]

@visual bough Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt gazelle]

Im not sure how the first equality was obtained

w_i denotes ith root of unity

ah okay i think I get it, is it because $w_1^3,w_2^3,w_3^3,w_4^3,w_5^3$ are all also distinct fifth roots of unity so their sum is 0

[clever fjord]

slong

[burnt gazelle]

.close

[odd edge]

Channel closed

Closed by @burnt gazelle

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest sky]

x is a member of the set of real numbers

[surreal mountain]

x is a real number

[odd edge]

Channel closed

Closed by @wraith marten

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal latch]

Hey people

[tidal latch]

How do you know whether to factorise into double brackets or singular brackets

Is the only thing that needs double brackets quadratic s

This is pre-university math

[forest sky]

what do you mean by "double brackets"?

[odd edge]

@tidal latch Has your question been resolved?

[tidal latch]

I’m not sure how to explain its two brackets

Like this

[wanton bison]

linear factors?

[tidal latch]

Probably all I know is that I’m doing quadratics

[wanton bison]

singular "brackets" means that it has one double solution

usually it's two brackets if you have two distinctive solutions

(ax+b)(cx+d) two real solutions

(ax+b)² one real solution

[latent quiver]

This is the representation of a quadratic expression in the form of product of 2 linear expressions

[wanton bison]

if it has no real solutions you can't factorize it with real numbers

[latent quiver]

each factor can be equated to zero to get the zeroes of the quadratic equation

[tidal latch]

Ohhh ok

[odd edge]

@tidal latch Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gleaming schooner]

can anyone give me a hint on how to approach this problem

[sullen ferry]

well, what do you know?

You know formula for volume, and formula for surface area for a rectangular prism

[gleaming schooner]

surface area of the rectangle is 2(xy + yz + zx) right

and volume xyz

[sullen ferry]

yep

mhm

[gleaming schooner]

i gotta minimize f(x,y,z) = 2(xy + yz + zx)

[dawn tiger]

they say the box is open, does that mean that you wouldn't include one of those sides' areas?

[gleaming schooner]

right

ok ignoring z

[dawn tiger]

not ignoring z completely

[gleaming schooner]

hmm

[dawn tiger]

let's say the box is four walls, the floor, and a ceiling

and this open box has no ceiling

you'll include 2 pairs of opposite walls

so you can call them 2xy + 2yz

[gleaming schooner]

yep

[dawn tiger]

and just the floor

so you wouldn't completely remove a term

[gleaming schooner]

i see

[dawn tiger]

but instead of all of them being in pairs of two, two of them have a coefficient of 2 while the other one has a coefficient of 1

since one of the six sides is gone

[gleaming schooner]

ah yes i get it

so just

2(xy+yz) + zx

[dawn tiger]

so yeah you're minimizing that

[gleaming schooner]

as opposed to the earlier one

[dawn tiger]

you also need to relate that to the volume

[gleaming schooner]

yes about that
f(x,y,z) = 2(xy+yz) + zx
for a 2 variable function I'd go about finding f_x, f_y, setting those to 0, followed by a double derivative test

i assume xyz = 58 is a constraint

[dawn tiger]

yeah that's what i'm seeing

is there a way to turn the three variable function into a two variable function, using the constraint?

[gleaming schooner]

ohhhhhh

[dawn tiger]

lol

[gleaming schooner]

z = 58/xy

[clever fjord]

TheRuleOfEngineering

[gleaming schooner]

so $$f_x = 2y - \frac {116}{x^2}$$ and $$f_y = 2x - \frac {58}{y^2}$$

[clever fjord]

TheRuleOfEngineering

[gleaming schooner]

bruh setting those to 0 and solving is a hassle lol

this gives
$$ x = \frac {29}{14.5^{2/3}}$$ and
$$ y = 14.5^{1/3} $$

[clever fjord]

TheRuleOfEngineering

[gleaming schooner]

so now do I have to calculate f_xx, f_yy, f_yx and put them into a hessian matrix?

holy hell

$$ f_{xx} = \frac {232}{x^3}, f_{yy} = \frac {116} {y^3}, f_{xy} = 2 $$
calculating the determinant of the hessian matrix formed by those gives me:
$$ D = \frac {26912}{x^3y^3} - 4 $$

[clever fjord]

TheRuleOfEngineering

[gleaming schooner]

ok hell nah im using a calculator for that

also, @dawn tiger sorry for the ping but do I need to be doing all of this?

[gleaming schooner]

plugging in x and y into D gives D=12 which is > 0
and f_xx at the given (x,y) gives f_xx = 2 which is also > 0
which means the values found for (x,y) above are the local minimum.

ok that worked, but could I have just done all that without calculating the determinant of the hessian matrix?

[odd edge]

@gleaming schooner Has your question been resolved?

Channel closed

Closed by @gleaming schooner

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich sage]

Hello, can anyone solve this question fully, i have no idea how to get past the domaine part

[wanton bison]

are there restrictions?

[rich sage]

No,

[wanton bison]

then the domain is R

[odd edge]

@rich sage Has your question been resolved?

[rich sage]

What about the coordinate of the origin?

Yo, anybody help me on here

[odd edge]

@rich sage Has your question been resolved?

[silk valve]

@rich sage

[long knot]

Why are you called Nutella

Isnt that chocolate

[odd edge]

@rich sage Has your question been resolved?

[rich sage]

Yeah, i’m a damn good chocolate

[odd edge]

Channel closed

Closed by @rich sage

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich sage]

Can anyone help me with this question

[rich sage]

This is the equation

[torn marlin]

isnt this just differentiating

you can find the other functions

[odd edge]

@rich sage Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[somber fern]

please help

i cant think of any nouns to make them work

[sonic nova]

This seems like a ridiculous math homework; my condolences

[somber fern]

indeed

any1???

[sonic nova]

I'm trying xD i cant think of anything either

[somber fern]

okay lol i looked it up too couldnt find anything

[proven beacon]

for b you could probably continue what you did with number one

dollar dimes and nickels

for c i have no clue

[somber fern]

oh yeah thank u

[sonic nova]

Good call on that one

[proven beacon]

oh

for c its time

[somber fern]

this was there too Hint: think about money, time, measurements, cooking, etc.

[proven beacon]

days hours minutes

[somber fern]

OMG

[sonic nova]

Niceeee

[somber fern]

You're a genius thank you

[proven beacon]

This is the strangest math homework ive ever seen

[somber fern]

yep

its math literacy lol

[sonic nova]

It's like a riddle instead of math

[somber fern]

yea

[forest sky]

for the second one you can use coins

for the third one, you can use time

[odd edge]

@somber fern Has your question been resolved?

Channel closed

Closed by @somber fern

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint maple]

help plz

[flint maple]

i understand its a similar triangle question

but im not 100% sure still

ok nvm i understan

.close

[odd edge]

Channel closed

Closed by @flint maple

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eternal aurora]

when plugging in arcsin, why is the negative ignored for 4/7?

[odd edge]

@eternal aurora Has your question been resolved?

[odd edge]

@eternal aurora Has your question been resolved?

[odd veldt]

I think it might just be a poorly phrased question

By "Reference angle" it could be referring to the answer to arcsin(4/7), which you would then use to solve arcsin(-4/7)

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid wren]

this problem deals with some graph theory stuff in discrete mathematics. i understand what the question is asking and i have a graph labeled correctly (?), but i am not sure how to go about counting it and unsure how to answer the table at the bottom

[vapid wren]

vertex A for History is supposed to have the pencil circle symbol my bad u can barley see it in the pic

[odd edge]

@vapid wren Has your question been resolved?

[odd edge]

@vapid wren Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush saddle]

help pls

[light agate]

what have you tried so far

[plush saddle]

well i watched a khan acedemy video which only focused on finding the turning point and x intercepts

but i don't know where to go from there

[light agate]

turning point meaning the vertex?

[plush saddle]

yeah

mb

[light agate]

nw. so the standard form is $y = a(x-h)+k$

[clever fjord]

esca (@ with reply)

[light agate]

where (h,k) is your turning point/vertex

[plush saddle]

ok

[light agate]

so you find the vertex and plug it in for h and k

what do you get

[plush saddle]

h=-4 and k= 6

lemme jst work it out

wait so whats a?

[light agate]

er actually

its not exactly that

okay so youll want to do this by identifying the roots/zeroes of the function

how can you do that

[plush saddle]

idk

[light agate]

so the roots of a parabola are just the points where it intersects the x axis

[plush saddle]

oh ok

the roots are -6 and -2.5

[light agate]

yep

now you can just express it in factored form

which is $(x - a)(x-b) = y$ where a and b are your roots

[clever fjord]

esca (@ with reply)

[plush saddle]

oh ok

[light agate]

so what do you get

[plush saddle]

x^2-2.5x-6x+15

[light agate]

hmm not quite

[light agate]

plug in the roots directly

remember, if you have $(x-a)(x-b)=0$ your roots are positive a and positive b

[clever fjord]

esca (@ with reply)

[plush saddle]

ohhhhhh

i completely forgot abou that rule

(x+2.5)(x+6)

[light agate]

yep

theres an extra step though

[plush saddle]

do i expand the brackets?

x^2+2.5x+6x+15

[light agate]

well yeah but after that

[plush saddle]

i don't really know

[light agate]

so your answers are all in integer form

so if you have a root like (x-2.5) = 0, this is the same as saying (2x-5) = 0 right

[plush saddle]

ye..

[light agate]

so that's your last step

[plush saddle]

ok, ill do it

would the final answer then be -(2x+5)(x+6)=y?

@light agate u still there?

[light agate]

yeah i believe so

[plush saddle]

yep i got it right!

thank you sooo much

.close

[odd edge]

Channel closed

Closed by @plush saddle

Use .reopen if this was a mistake.

[plush saddle]

.reopen

[odd edge]

✅

[plush saddle]

how did u go from $(x-2.5) = 0$ to $(2x-5) = 0$ ???

[clever fjord]

Bahnies

[light agate]

solve them

youll get the same answer

[plush saddle]

i still kinda don't get it, can you dumb it down for me pls?

[leaden karma]

You can just double the equation

[upper onyx]

multiply both sides by 2.

[plush saddle]

yep i jst got it

thx

.close

[odd edge]

Channel closed

Closed by @plush saddle

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tender raft]

can someone help with this question

but question is asking for the value of z

30

the perimeter is 30

[marsh cedar]

6l

where l is the length of one of its sides

(they are all the same)

[tender raft]

where did you get 6 from

6

don't we need to add all of them?

no wht i meant

6(z+5) + 6(z+5) + 6(z+5) and so on

alr so the total sides is 6 and that's the perimeter whts the point of the five then

why are you highlighting it

i can see it

why is there a 5

yes

why is there a 5

there is no purpose of it

is there ?

the sides are not the same so that's a bit confusing

there are 4

sides

no

wait

4(3z+7)

4(z-8)

I rlly need to go sleep could you help me fast with this

yes

yees

3z+7 + z-8 + 3z+7 + z-8

how

6 + 4z

6

8

I don't understand

[clever fjord]

faiyrose

[tender raft]

8z

-1

1

1

idk

alr

i need to go

thx

[odd edge]

@tender raft Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean hamlet]

hello, i have a question. I have to find a basis of this. Rank is 1 so there are 2 free variables, i put y = a and z = b and got that (x, y, z) = ((-a-b)/2, a, b) = (-a/2, a, 0) + (-b/2, 0, b) = a(-1/2, 1, 0) + b(-1/2, 0, 1) so a basis is {(-1/2, 1, 0), (-1/2, 0, 1)}.

[ocean hamlet]

The site where I got the exercise from puts x = a and y = b and gets that (x, y, z) = (a, b, -2a-b) = a(1, 0, -2) + b(0, 1, -1) so a basis is {(1, 0, -2), (0, 1, -1)}

is it the same thing?

[forest sky]

you can find many (infinitely many, in fact) bases for the same space

[ocean hamlet]

i mean, can we choose the free variables as we want or is there a "rule"

[ocean hamlet]

yea i know they're infinite

[forest sky]

the convention is to let the pivot variables be fixed and the others be free (which corresponds to what you did) but that's not a requirement

[ocean hamlet]

okay thank you! just wanted to be sure

.close

[odd edge]

Channel closed

Closed by @ocean hamlet

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid frost]

I'm really stuck on how to find the angle, can someone help

[green elm]

can you find vectors parallel to each line?

[odd edge]

@vapid frost Has your question been resolved?

[vapid frost]

the two lines already seem to come from the same point tho

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful rivet]

is thus hiw i find A

[frigid canopy]

yes

[woeful rivet]

daym that needed so much thinking

but me understand now

thx

.close

[odd edge]

Channel closed

Closed by @woeful rivet

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[long tinsel]

basically

[clever fjord]

Bob l'éponge

[odd edge]

@mystic saffron Has your question been resolved?

[upper onyx]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

Ii dont know where to begin

[upper onyx]

you know what your asked?

[undone basin]

[undone basin]

this is your question right?

[mystic saffron]

i just have 0 clue how to approach it tis review for exam but i forgot it tbh

yes

[upper onyx]

should you solve geometrically or via calculator?

[mystic saffron]

via calculator since the solution is in decimals

itsi also not using pi its decimals

[upper onyx]

divide by cos x

[mystic saffron]

wdym

[upper onyx]

what i have written. what is not clear?

you asked sin x = cos x, i think divide by cos x is a clear advice,

[mystic saffron]

but how do you find the coordinates

[upper onyx]

what did you get after following my advice?

[mystic saffron]

tanx=1

[upper onyx]

well,

[mystic saffron]

ahh

i see thank you

!close

.close

[odd edge]

Channel closed

Closed by @vagrant apex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty heath]

hullo

[jaunty heath]

I don't have the formulas for this lesson

[proud sleet]

whats the ques

[proud sleet]

in this image

[jaunty heath]

2

[proud sleet]

cody's large suv has a 90l fuel tanka dna fuel efficiency of 13.9l/per 100 km

whats that "(1.d.p)

[jaunty heath]

Yeah I don't know the formula for this

How am I figuring out the distance it travels

13.9L > 100km, tanks 90L

[proud sleet]

647 km

is it correct

beacsue 90/13.9 = ~6.47

that multipled by 100 is 647 kms

so answer is approx 647 kms

yep the answer is 647kms for sure

u got any doubt?

@jaunty heath

[odd edge]

@jaunty heath Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid canopy]

(a)

(0,0,0) is an element

so it satisfies that condition

next to verify if $v+u$ is closed in the sub-space

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

I feel it is

[pastel orbit]

try it!

[frigid canopy]

as if u=(x_1,x_2,x_3) ; v (y_1, y_2, y_3)

we have $(2x_1,2y_1,2z_1_)$

[clever fjord]

ƒ(Why am. I here)=I don't Know
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[pastel orbit]

what

[frigid canopy]

brain fart

wait a minute

$x_1+y_1, x_2+y_2,x_3+y_3$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

which can be redefined to be x,y,z

and which will then satisfy x+2y+3z=0

[tepid pelican]

this is something you need to show

why should those x, y, z satisfy it?

[frigid canopy]

because they are elements of $F^3$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[low locust]

so?

(1,2,3) is an elements of F^3 but it doesnt satisfy 1*1+2*2+3*3=0

[frigid canopy]

hmm

true

[pastel orbit]

it's fine to call those components z_1, z_2, and z_3 if it helps you

[frigid canopy]

I don't see how that helps

let me think a little '

[pastel orbit]

what do you need to do to show that this is in the set?

[frigid canopy]

show that x+2y+3z=0

[gritty oar]

remember that (x1, x2, x3) and (y1, y2, y3) come from the subset in question and as such, they satisfy...

and in order for (x1 + y1, x2 + y2, x3 + y3) to be in that set, it needs to satisfy...

[frigid canopy]

$x_1+y_1+2(x_2+y_2)+3(x_3+y_3)=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

is what I have tot show

[gritty oar]

yes

[frigid canopy]

$x_1+2x_2+3x+3=0

[pastel orbit]

[frigid canopy]

and $y_1+2y_2+3y_3=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

is that it?

[low locust]

you wrote two other random equations. why do those help

connect the dots

[frigid canopy]

which equations?

[frigid canopy]

this?

[pastel orbit]

Denascite meant this one

[pastel orbit]

and this one

try to connect the dots

[pastel orbit]

we have this sum, but you can't say that it's equal to 0 yet

you have to show that!

[frigid canopy]

they independently satisfy teh given conditions

so I'm regrouping them

[pastel orbit]

right

can you show it?

[frigid canopy]

$(x_1+2x_2+3x_3)+(y_!+2y_2+3y_3)=0+0=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[pastel orbit]

you missed showing one step, but I think you got it?

[frigid canopy]

which step

[pastel orbit]

expanding

[frigid canopy]

ah

thanls

[frigid canopy]

here b isn't a subspace at it doesn't satisfy the additive identity

[wanton bison]

0+0=0

[frigid canopy]

what

[frigid canopy]

C satisfies the additive identity

It's closed under addition too

if $x_1x_2x_3+y_1y_2y_3=0+0=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

and $\aleph x_1x_2x_3=\aleph 0 \implies \aleph x_1x_2x_3=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

is that right?

or do I have to prove $\aleph 0=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

oh, hi charbit!

[wanton bison]

what

[brittle beacon]

And not quite: the idea is that the set is such that "the product of all entries of said vector is zero", so you either wanna show that if $(x_1, x_2, x_3)$ and $(y_1, y_2, y_3)$ are in the set (I'll call it $C$), then their sum $(x_1, x_2, x_3) + (y_1, y_2, y_3)$ is also in $C$, or find a counterexample

[clever fjord]

@brittle beacon

[wanton bison]

(x1+y1)(x2+y2)(x3+y3) = 0 ?

[frigid canopy]

oh

okay so I want to prove $(x_1+y_1, x_2+y_2, x_3+y_3) \in C$?

[clever fjord]

ƒ(Why am. I here)=I don't Know

[brittle beacon]

You want to prove that, sure (or, instead, hint hint-)

[frigid canopy]

or find a counter example ?

[brittle beacon]

Si, counterexample

[frigid canopy]

hmm, $x_1=1,x_2=1,x_3=0$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

$y_1=0;y_2=1,y_3=1$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

that;s it?

so it;s not a subspace

[brittle beacon]

Yep, basically, (1, 1, 0) and (0, 1, 1) are members of that set, but their sum, (1, 2, 1), is not

[frigid canopy]

how did you notice that so fast

[brittle beacon]

You'll generally get a feel for what is and isn't a subspace when you work with them enough, stuff like products there have a massive hint of "why would sums/products also preserve that defining property?", similar with linear combination restrictions where there's some nonzero constant added (see the last few examples we did where we needed a constant to be zero)

[frigid canopy]

I see , thanks

[frigid canopy]

now d satisfies the additive identity

It's closed under scalar multiplication too

[merry finch]

A good thing about LA is that a lot of us know it quite well so you’ll get plenty of help

[frigid canopy]

as always, I need to attach this https://creativecommons.org/licenses/by-nc/4.0, which is the creative commons lisence for this chapter

addition is closed too

[frigid canopy]

awsome

I hope to reach that position one day

heck this server motovated me to choice maths for my Bachelors

[merry finch]

I was in your position like a year ago, it just takes time and dedication

You can go through my message history and see me so frickin confused about LA about a year ago

Also these were 2 pretty interesting questions I came across

[frigid canopy]

I'll try solving them once I finish chapter one of axler

which book is this from

[merry finch]

Its from my uni lol

[frigid canopy]

oh

ok

[brittle beacon]

(hint: you should be able to do at least one of them right now!)

[iron bear]

the constructions are very geometrically motivated

[merry finch]

^^

They sort of are yeah

[frigid canopy]

problem 12, I think

[merry finch]

It’s good either way for building intuition of what is and isn’t a Subspace

[iron bear]

for example i would call things that satisfy 1. cones, and things that satisfy 2. lattices

[frigid canopy]

1)$\Xi (i+j)$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

where $\Xi in R$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

and i and j have their regular meanings

[merry finch]

Do you know how to use set builder notation

[frigid canopy]

yes

[merry finch]

Use that

[frigid canopy]

oops

[merry finch]

Also idk what “regular meanings” mean

[frigid canopy]

I read the question wrong

wait, is scalar multiplication teh dot product

[merry finch]

No

You don’t have a dot product yet

[iron bear]

multiplication by scalars

[merry finch]

It’s the operation between the field and the vectors

[frigid canopy]

hmm

did these problems take you long

[merry finch]

A bit of time yeah

Maybe like 15mins?

I just tried a bunch of stuff until I found something that resembled what I wanted

[frigid canopy]

I'm currently thinking that the answer may be a region

like an inequality

[merry finch]

Perhaps

[frigid canopy]

hmm

$\phi$?

[clever fjord]

ƒ(Why am. I here)=I don't Know

[iron bear]

funnily enough, this set is closed under vector addition

[merry finch]

What’s phi o.o

[iron bear]

if you mean the empty set

[frigid canopy]

yeah

[merry finch]

Oh

[iron bear]

in maths, there's often the concept of "generation"

[merry finch]

That’s a really good place to start actually

[iron bear]

like given some elements, you should be able to find the smallest set which contains those elements and also satisfies some certain properties

you'd say that you generate the blah using those elements

here, you can apply the same trick

[frigid canopy]

hmm

ok

[iron bear]

if you place a single vector into your set for 1., what must the set now contain for it to be closed under scalar multiplication?

[frigid canopy]

just a minute

I'm thinking

[iron bear]

answering this question tells you how vectors generate closed-under-scalar-multiplication subsets

[frigid canopy]

all reals

wait no

all vectors having the same direction cosines

[iron bear]

cosines?

[frigid canopy]

same slope

[iron bear]

you might say that it's all multiples of the vector

if $v \in S$ and $S$ satisfies 1., then $\lambda v \in S$ for all $\lambda$

[iron bear]

this is completely forced

so use this to generate a set S that isn't closed under addition

[frigid canopy]

how

[merry finch]

Try some stuff

[frigid canopy]

so essentially all elements shouldn't be covered

but that's not possible IMO

[merry finch]

So you’ve got a set S that you want closed under scalar multiplication but not vector addition right?

[frigid canopy]

hmm

oh right

so essentially the vector sum shouldn't be in teh set

so say the set containing multiple of i and j unit vectors

just the axes essentially

[merry finch]

You tried adding (1, 0) to S, then generate closure under scalar multiplication, your set S now looks like {(x, y) ∈ ℝ²| (x, y) = a(1, 0), a ∈ ℝ}

[merry finch]

Yeah

[frigid canopy]

that was fun, ngl

[merry finch]

There’s still another one 👀

[merry finch]

It was the only question on my tutorial question sheet I had to think about 💀

My exam for it is in 5 hours

[iron bear]

you have a LA exam?

[merry finch]

Yeah

[iron bear]

damn

[frigid canopy]

good luck

[merry finch]

Change of basis!! Woah so hard!

Linear transformations as matrices!! Oh man!

Inner products and Fourier basis!!

Wow so hard

[iron bear]

wait until it's jordan decomposition

[merry finch]

Keeping in mind this unit is taken by engineers

[iron bear]

oh

[merry finch]

I don’t think a math major at this uni learns this in undergrad

🙂

[iron bear]

[merry finch]

They also don’t know what the dual space is so

A lot of missing knowledge

[uneven lodge]

🤺 space

[frigid canopy]

is the second one even possible

[merry finch]

Of course!

[frigid canopy]

I mean if vector addition and subtraction are closed

[merry finch]

Oh

[frigid canopy]

that basically covers the entire coordinate plane

[merry finch]

The question is wrong

It shouldn’t say vector subtraction

That’s not real

That’s a fake thing

Vector subtraction is really wack

Don’t worry about it

[frigid canopy]

even then, the entire coordinate plane is covered

[merry finch]

Nope

[frigid canopy]

just by adding any two vectors

except for the axes

[merry finch]

Try the generating method again

[frigid canopy]

$if v\in \aleph$

[clever fjord]

ƒ(Why am. I here)=I don't Know

[frigid canopy]

nope nothing comes to mind

let me think about this a bit more

[iron bear]

lol

[merry finch]

Pick a more concrete v

[frigid canopy]

it's midnight here, I'll try this tomorrow

[merry finch]

Clearly if you just pick the 0 vector it won’t work because it’s just a vector space already by itself

So you’d need something else

So just pick a particular vector and put it in S and then close it under the appropriate operation

[frigid canopy]

thanks

.close

[odd edge]

Channel closed

Closed by @frigid canopy

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal quartz]

how do I find horizontal and vertical asymptote?

[latent scaffold]

Horizontal asymptotes -> take limits at infinity and -infinity
Vertical asymptotes -> whenever the denominator is 0 (and the numerator nonzero)

[vernal quartz]

Okay

makes sense but how do I find the numberical value?

.close

[odd edge]

Channel closed

Closed by @vernal quartz

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lost crown]

am i stupid

[proven beacon]

there is an isosceles triangle in the figure

[fallen surge]

use inscribed angle theorem

[lost crown]

i felt like thats what i have to do but i cant see where to apply it

can u please highlight or smthing idk

[proven beacon]

do you need to do that

[lusty nova]

sum of angles in a triangle is 180

[proven beacon]

this is isosceles

radii

[lusty nova]

use the fact that the triangle is isosceles

2x + 122 = 180

[fallen surge]

you don't need to do this, inscribed angle theorem gives it to you immediately, x has to be precisely half of 58 since subtend the same arc

[lost crown]

oh i see where the inscribed angle is now

[fallen surge]

oh it might not be a diameter though

never mind, use what they are telling you

[lusty nova]

x=29

[lost crown]

how do you know it's an isosceles triangle?

[fallen surge]

i guess it is correct in this case

[lusty nova]

radius of a circle

[proven beacon]

radii

or radius

[lusty nova]

or radar

nvm

[lost crown]

oh omg i was looking at the bigger triangle instead of the radius

okay

thank u guys so much

.close

[odd edge]

Channel closed

Closed by @lost crown

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

3. Find the point of intersection between f(x)= sin2x and g(x)= cos2x over the first two cycles.

[regal leaf]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[regal leaf]

<@&268886789983436800>

[lusty nova]

solve sin2x=cos2x for x

[merry finch]

Perhaps try sinx and cosx first

[lusty nova]

$sin2x=cos2x$ when $2x = \frac{\pi}{4} + k\pi$

[warped grove]

This is someone else's help channel, please take casual discussion to #discussion

[clever fjord]

Calculus Tutor

[odd edge]

@mystic saffron Has your question been resolved?

[mystic saffron]

its decimals not pi, but the only thing im confused about is for the 2nd question the point of intersections are increasing by 180 but for the third they only increase by 90

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight mauve]

the question is solve the given differential equation. this is the given equation and its solution

[midnight mauve]

this is what i did and i dont really know what im doing wrong besides probably the e^2 and i guess maybe my intergral separation is an illegal move

i tried looking up worked out solutions but i dont understand them because they do a u-sub and a 2 comes out but they dont incorporate the 2 back into their work? like this

[merry finch]

There’s a 2 in the numerator

[midnight mauve]

im aware

[merry finch]

Then what’s the problem

The 2dx gets replaced by -du

So there’s a - out the front of the ln

[midnight mauve]

ohh i see

hold on let me try to do it again

wait

can you explain to me where in my work i made the mistake

i separated the fraction of my intergral incorrectly right

that is my issue?

[midnight mauve]

is the solution to this worked example the same as the textbook solution??

where did the x=0 come from and how did they go from the first circled step to the second