help-19

[rapid ice]

How would i write it tho

10?

[pastel steeple]

that is 16 in hex yes

[rapid ice]

So 25 would be 19

Correct?

[pastel steeple]

exactly

[rapid ice]

Ok

[pastel steeple]

it's no different than decimal

it's just with 6 more digits

[rapid ice]

Then what about 44, that’s what I’m stuck on

[pastel steeple]

well how many 16s is that

[rapid ice]

2

With 12 remaining

[pastel steeple]

what is 12 in hexadecimal

[rapid ice]

2C?

[pastel steeple]

i think thats right

[rapid ice]

Alr

I’m gonna trust you

🤷‍♂️

[pastel steeple]

i work with hex daily i would hope i know these things 😭

[rapid ice]

💀💀

Okay tyty

.close

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[prisma holly]

which two-digit numbers 10x+y satisfy the condition 10x+yx^2+y^2+xy?

[prisma holly]

hints how to do this

pls

[pastel steeple]

um what condition

that doesn't equal anything

[gritty oar]

for x not 0, consider both expressions mod x

you get $y\equiv y^2 \mod x$

[clever fjord]

chebyshev's infinite pee norm

[gritty oar]

gives you an initial list of cases to consider

you can also take the original expressions mod 10

to get a second condition to eliminate further cases

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[trail lintel]

Can someone please help me prove this

[slender night]

Did you use quadratic equation?

I'm not sure if it's the right method. But that could be used for trial and error for now...

[elfin zodiac]

What do you know about the problem? Can you explain with your own words what do you think you are being asked?

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[sleek galleon]

So, I dont know how to continue. I was just trying to understand the algebraic simplifications and different things my proffesor wrote, but tbh I dont even know why he converts the initial expression to that.

[sleek galleon]

https://media.discordapp.net/attachments/328208536029102081/1229461871229272084/20240415_130155.jpg?ex=662fc498&is=661d4f98&hm=4129aacb02d232cc734cb225bb713b472061a0d55384ffcdac3ebf645f839d5b&=&format=webp

[gritty oar]

which part do you not understand

the (2n+2)! part?

[sleek galleon]

I'm here now.

bue idk how to proceed.

I'm stuck here and I cant continue with the next excercise

could someone plz help :C

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[wintry viper]

When its say the instant its collids

[wintry viper]

is this before or after?

[ember oak]

Before

Pretty sure

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[wintry viper]

Where did the tan (90 - theta) come from?

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[hardy bluff]

How do I further calculate this please

[cold sage]

youve evaluated backwards (its top - bottom limit)

[narrow cove]

You have a lower top limit than bottom limit though which seems somewhat odd, is that intentional or are your limits backwards meaning the error of evaluating backwards has negated the limit error lmao

[hardy bluff]

Oh I see

Also

I have a question

How do I evaluate sin 2

And pi/2 to the power of 2

@cold sage

@narrow cove

[cold sage]

pi/2 squares is pi^2/4 as you expect

and sin(2), just leave it as sin 2

[hardy bluff]

Why

[sick plaza]

it has no other closed form

[hardy bluff]

What does that mean

[sick plaza]

at least not a commonly known one

it means that the only way to write sin(2) in a limited number of characters

[cold sage]

,calc sin(2)

[clever fjord]

Result:

0.90929742682568

[sick plaza]

is to write it as sin(2) or things that you can turn into sin(2)

[cold sage]

better to just leave things simple (if you round then: )

[sick plaza]

otherwise you get 0.90929742682568............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

etc

[hardy bluff]

Oh I see

[sick plaza]

infinite number of numbers

[hardy bluff]

Ok let me try

I got it wrong

The correct answer is pi^2 plus 1

This is what I did

[gritty oar]

are you sure your lower bound isn't supposed to be 0 then

[hardy bluff]

Yes

It’s not

Oh never mind

U r right

[gritty oar]

well either you don't have the right integrand, you don't have the right bounds, or their answer is wrong

[hardy bluff]

Wait

How did u know that

[hardy bluff]

It is

[sick plaza]

cuz if you look at your result before plugging it in

if you plug in 0 the result gives 0

and if you plug in pi/2 the result gives pi^2 + 1

[hardy bluff]

Ok but without knowing the result and initially doing this question

How would I know what to do

Like how it’s 0

For the lower part

[sick plaza]

without knowing the answer you wouldn't know

[hardy bluff]

Then how would I solve this

[sick plaza]

knowing that the answer is supposed to be pi^2 + 1 is what let (best name in life) know that the lower bound is probably 0

apart from the fact that you accidentally plugged in 2 in the upper bound and pi/2 in the lower bound you did it correctly

the indefinite integral is correct i think

[hardy bluff]

I am expected to solve this without knowing the answer

And get that same answer

[gritty oar]

(best name in life)

[hardy bluff]

Please keep this in chill channel

[sick plaza]

chebyshev best polynomials

[hardy bluff]

Not here

[sick plaza]

get outa here with your bessel or legendre

pfft

anyway

back on topic

[gritty oar]

i mean you just used the wrong lower bound

[sick plaza]

that

[gritty oar]

if you used the right one, you would have gotten the right answer

and yes i just saw that using 0 as the lower bound gives the appropriate answer

[hardy bluff]

BRO IM SO DUMB IM SO SO SORRY

[sick plaza]

if we were given that integral with those bounds

[hardy bluff]

THE QUESTIOM LITERALLY SAID 0

[sick plaza]

we would've had the same answer as you did

[hardy bluff]

NOT 2

OMG

Time for glasses

Sorry guys

[sick plaza]

🤣

[hardy bluff]

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[stiff kettle]

Why did the teacher say that the 5 has to be negative?

like I understand everything else

but ii did r^2 = x^2 + y^2

and x was positive

[fresh ruin]

for equations like x^2+y^2=r^2, technically any variable there can be positive or negative and it's fine. when you solve x^2=25, both x=5 and x=-5 work, so you have to use something to determine which one to choose

the picture is like this

but the quesiton says use QIII, the third quadrant, which is where x and y are always negative

[stiff kettle]

@fresh ruin right so why is this not -5 then

if its in the fourth Quadrent

(this is a diffeent question)

[fresh ruin]

x and y can be negative, but r is special

[stiff kettle]

ohhh righttt

[fresh ruin]

it's just a distance/radius, so you always go positive

[stiff kettle]

right I forgot ahah thank you so muchh

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[hollow olive]

can someone help me on B?

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[young briar]

<@&286206848099549185>

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[rigid brook]

hey

[rigid brook]

just a quick question

if I have a flat bounded surface like a traingular plane

and I want to calculate the flux through it

if I'm able to find the area and normal vector but the vector field is non constant

wont I be left with an expression that looks something like

im confused if I did something you're not supposed to with integrals

cause I wouldnt know how to integrate this since there is no longer a variable im integrating with respect to

[fresh ruin]

should be fine to split it like that and integrate separately

[rigid brook]

yes but dA is a scalar now so im confused

I think maybe the issue is that im viewing dA as a scalar

nvm im just confusing myself

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[mild kindle]

Help pleasee

😭

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[proud osprey]

Would it be 1 to e ln(y) to 1 7dxdy?

[proud osprey]

I originally put 1 to e, 1 to lny 7dxdy but that got marked wrong

yup i got it right

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[slow haven]

Hi just needed help on how to approach this;-;

[nimble blaze]

plug and chug

[slow haven]

i did but i feel like the answers wrong or smth lmao then tysm

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[spice brook]

How would i go about proving this fact:
For arbitrary odd number $s\geq3$, there exist odd primes $p_1<p_2<\dots<p_s$ such that $p_1+p_2>p_s$.

[clever fjord]

🇵🇸Mína🔆

[spice brook]

I'm not well versed on prime gap theorems

Note: $p_1,p_2$ and so on do not denote the actual first/second/whatever prime number, the indeces just denote the relative size.

[clever fjord]

🇵🇸Mína🔆

[spice brook]

<@&286206848099549185>

it is given in a proof of the unboundedness of cyclotomic polynomials by Emma Lehmer kinda as a known fact

I just don't know where I'd even find a proof of that

like intuitively it's true

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[wooden swan]

idk how to do this

is it -42P^12

[open crown]

yes

[wooden swan]

do i need to show my work while doing it?

or no

cuz idk how to show work

[open crown]

Honestly, u dont need to show work for this

Since its a simple simplification

[wooden swan]

is this right?

[signal oar]

Yes

$\big(a^b\big)^c = a^{bc}$

[wooden swan]

4p^16?

[open crown]

The square also applied for 2

[open crown]

So yeah

[wooden swan]

x^9

y^7

[open crown]

.

[wooden swan]

oh sorry

[open crown]

Not quite

[wooden swan]

you would multiple 5 by 4

so 20

[open crown]

(a^b)^c = a^b*c

[open crown]

Yep

[open crown]

Same for y

[wooden swan]

so 12

do i need to show my work for this one?

do you think

[open crown]

If u want to?

You could distribute the ^4 to each element

[wooden swan]

but do you think i would need to

[open crown]

no honestly

[wooden swan]

so would the first part me 256x^20

[open crown]

Sure

But I dont think calling 4x^5 as a part is a good way of thinking

4 should be treated as its own thing

[open crown]

But this is still correct

[wooden swan]

then y^6 would be

y^24

then z woudl be z^4

[open crown]

correct

U know how to do it then, I dont think you would need any help with this kind of problem! Just be confident about ur answer

[wooden swan]

there is 3 questions i dont konw how to do

they are the only ones left

[open crown]

Just send them here

[open crown]

Well

a^b/a^c = a^(b-c)

[wooden swan]

8p^-45

[open crown]

yeah

[open crown]

Good job

U should be able to do the rest then

[wooden swan]

since its negitive i need to transfer it to positive

for my course

[open crown]

?

Wdym

[wooden swan]

like the answers needs to be one of these

[open crown]

Here's another rule

a^-1 = 1/a

[hasty saddle]

Oh

[open crown]

@wooden swan

[wooden swan]

wait can i explain wghat i know

[open crown]

Basically, p^-45 = p^(45 * -1)

[wooden swan]

if i had 8^-45

[open crown]

Then applied this rule

[wooden swan]

i was told to do this

[wooden swan]

1/8^45

i was told it would turn into that

8^-45=1/8^45

where does the P go

in this case though

[clever fjord]

faiyrose

[open crown]

The ^-45 applied on p, not 8

[wooden swan]

okay

[wooden swan]

so what does 8p^-45 turn into

im trying to understand

[open crown]

U need to seperate -45 into -1 * 45

Then applied this rule: a^-1 = 1/a

[wooden swan]

i dont get it

[clever fjord]

faiyrose

faiyrose

[wooden swan]

i thought it was this though

or is that the same thing

since 1 cant be changed

[clever fjord]

faiyrose

[wooden swan]

yeah i did

but is that correct?

is it the same thing here?

$(\frac {1}{p})^45$

[clever fjord]

faiyrose

[wooden swan]

okay yes

now what happens to the 8

[open crown]

Nothing

Nothing applied to the 8

[wooden swan]

i multiple 8 with 1?

[open crown]

Hmm

[clever fjord]

faiyrose

[wooden swan]

so why doesnt it turn p into 8p

[open crown]

@wooden swan Take out a piece of paper

Then try to do this whole thing from the start to end

[wooden swan]

why

[open crown]

Trust me

[wooden swan]

why

[open crown]

U will get it

[open crown]

Just this part

Step by step

If u get stuck, take a pic of ur work and send it here

But I doubt that u will get stuck, u seem like a smart kid

[wooden swan]

i think i get it

[open crown]

Yeah

[wooden swan]

x^13?

12**

[open crown]

???

[open crown]

Good

y?

[wooden swan]

12

aswell

[open crown]

Okay

[wooden swan]

let me rewrite this on my paper

okay so the top

11^3

[open crown]

1331 probably

[wooden swan]

1331x^12

then z is z^3

then 2y^4 is

[open crown]

"becomes"

[wooden swan]

8y^12

[open crown]

Welldone!

[wooden swan]

nice 👍

[open crown]

Yeah

[wooden swan]

i did a few on my own too

but they where easy so yeah

[open crown]

You can try making ur own questions and practice

[wooden swan]

okay that was just revison of last year

now for what the revison was for

[wooden swan]

😭 out oh

[open crown]

Seem easy

Take it bit by bit

[wooden swan]

where should i start

[open crown]

There's 2 ways

Either u convert all the exponent of each side to one single exponent

Or just deal with it, then convert it once all terms are merged

Not sure if this makes sense cause English is not my first language

[wooden swan]

it doesnt make sense but prob not cuz of that

but for this i know that i can convert the exponents into one

[open crown]

Here's let focus on this part

[wooden swan]

i got (3/5)^-12

[open crown]

3?

[wooden swan]

(2/5)^-12

and then

[open crown]

I dislike the -

Convert it to +

[wooden swan]

(2/5)^-16

[wooden swan]

wait first

if you divided 2/5 divied by 2/5

how does that = 2/5

[open crown]

?

what r u talking abt

[wooden swan]

in this example

how does step 2 = step 3

like how do they juyst combine 2 of the same thing

[open crown]

-8+6=-2

[wooden swan]

no but the other part

[open crown]

Do u remember the rule a^-1 = 1/a

In a sense, -1 just flip the fraction

numerator becomes denominator, viceversa

[wooden swan]

no

but how

[open crown]

a^-1 = 1/a

[wooden swan]

how does this work

[open crown]

a^b * a^c = a^(b+c)

a = -3/2

The exponent is b and c

[wooden swan]

i know this is the anwer for hteo ne we just did

[wooden swan]

2^15

over

2^4

[open crown]

?

use the rule

[wooden swan]

idk what rule

[open crown]

a^b / a^c = a^(b-c)

[wooden swan]

can you use latex

i dont get it

just written like that

[open crown]

I dont know how to use Latex

[wooden swan]

well that makes two of us 😭

[wooden swan]

can you jsut explain for this specifc question what we would do first

[open crown]

I need some sleep rn

Maybe tmr

[wooden swan]

<@&286206848099549185>

what do i do first

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[sharp bough]

How do i determine if this function is a regulated function on the interval [0,1] -> R
I don't get at the moment, which characteristics i do have to consider here.

Hope that someone can help me regarding my problem 🙂

[sharp bough]

https://en.wikipedia.org/wiki/Regulated_function

<@&286206848099549185>

[sharp bough]

I do know, that i have to check the equivalent conditions:

• that i have left and right limits in the open interval

But i don't know how

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@sharp bough Has your question been resolved?

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[gilded locust]

i need help in the formula of the split plot design

[gilded locust]

i did the SPSS (application work) i need to do it manually on paper

so i need the formula

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@gilded locust Has your question been resolved?

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[pine drift]

Nooo bro why

[strange drum]

idk what im doing

[odd edge]

@strange drum Has your question been resolved?

[strange drum]

wheres everyone

<@&286206848099549185>

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[gritty leaf]

only part im confused on is, when we set cos(pi t) = 1-2t

how does that imply t=1, t=0, t=1/2

like how does one solve that equation?

[odd edge]

@gritty leaf Has your question been resolved?

[gritty leaf]

<@&286206848099549185>

[fringe bough]

In general there isn't really a great way to solve equations like that

I think it's reasonable to expect that you could find t=0 by inspection

Since there's a pi in the cosine function, maybe you'd check a couple other simple numbers including t=0 and t=1/2

But probably, I'd just graph both functions and pray that the intersections are easily identifyable rational numbers. Which, in this case, they are.

[echo ginkgo]

here you can cross check with sin(pi * t) = 0

sin(pi*t) = 0 only for integer t

[gritty leaf]

so i just sub in 1, -1, 2, 2 into cos eq

and see that

[echo ginkgo]

and from cos(pi * t) = 1 -2t, you need to have 0 <= t <= 1

[gritty leaf]

the 2s work and 1s dont

[echo ginkgo]

otherwise 1-2t is out of range of cos

[gritty leaf]

oh

right

ye

[echo ginkgo]

so only have to check 0 and 1

and they both work

[gritty leaf]

ok i see

thanks

wait actually

do u have time to help on a simple rights hand rule stokes theorem thing

theres no maths involved

i just dont get it

[echo ginkgo]

if only I knew stokes

¯_(ツ)_/¯

[gritty leaf]

aw

stokes isnt mandatory in multivariable calc?

[echo ginkgo]

I haven't taken multivar calc actually

[gritty leaf]

ohh ok

[echo ginkgo]

my multivar knowledge is limited to some prof leonard lectures I watched + a bit of ML stuff

never took the time looking at these fancy integration theorems in detail

[gritty leaf]

oh right

whats your degree?

[echo ginkgo]

comp sci

[gritty leaf]

oh right makes sense then

[echo ginkgo]

[gritty leaf]

lol just that u didnt take multivar calc since itd be compulsary for maths majors i think

<@&286206848099549185> im not sure why c1 is clockwise around n and c2, c3 is anticlockwise around n by the right hand rule

also i dont understand how the right hand rule works

[odd edge]

@gritty leaf Has your question been resolved?

[gritty leaf]

<@&286206848099549185>

[gritty leaf]

<@&286206848099549185> i beg

[fresh ruin]

right hand rules is like this, you put your right thumb in the n direction to see what C should be for a positive direction

it's kind of awkward with this weird surface but you can sort of bend the surface behind the holes to see where to point your hand

for C3 n ought to be to the left

so point your thumb that way and your fingers curl like that arrow does, so c3 is a +

[gritty leaf]

sorry i dont understand what the red part actually shows

[fresh ruin]

I'm like squeezing the pants

[gritty leaf]

oh

[fresh ruin]

so that it's more flat with the hole

[gritty leaf]

n ought?

[fresh ruin]

n should*

the normal vector in green

[gritty leaf]

oh right yes

wait

i didnt see that green n lol

ok

why has n gone that way when squeezed?

nvm

i get it

[fresh ruin]

this picture has better right angles

that's just to show that you put your thumb left for C3 and right for C1 and C2

[gritty leaf]

im bad at visualizing so im having difficulty what squeezing the pant actually does

so i point my thumb

in the direction of the green arrows

i think i get c3

im still confused on c1 tho

[fresh ruin]

c1 you point right

and my fingers oppose the arrow so there's a -

[gritty leaf]

here is a thumb pointing right

how do the fingers oppose the arrow?

[fresh ruin]

up vs. down

[gritty leaf]

yes but for c1

its not down and also down?

[fresh ruin]

for c1 you point your thumb left

so it flips

[gritty leaf]

oh

you said right

[fresh ruin]

wait I'm backwards

what I said before was good

c3 goes with the arrows

c1 goes against

[gritty leaf]

im so confused 😭

u are right

but i dont understand how

[gritty leaf]

hm

is this not matching?

why is the left upwards

the same as the downwards finger curling

Oh

nvm not oh

still confused

[fresh ruin]

uh it's a 3d picture

C is in front

and the downward fingers are in front

just use the closest thing forward for all these

[gritty leaf]

Ohhhhhhhhh

omg

Wow

i get it

what a stupid picture

i was thinking the arrow was at the back of the pant

ok youve helped

thanks

.close

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[woven oriole]

So far I drew a diagram of the given triangle

[woven oriole]

In △ABC, point E is on AB, so that AE =
1
2EB. Find CE if AC = 4, CB = 5, and AB = 6.

.close

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[mystic saffron]

!status

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1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[mystic saffron]

.close

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[keen swan]

Unsure of how to do root test on this

I understand the N's normally cancel, but theres a 2N there

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[frank spruce]

help@how do i find the perimeter

[open crown]

Cut it into triangles

[frank spruce]

How

[open crown]

wdym how

[frank spruce]

what triangles

[open crown]

Look at the shape

Cut it into triangle

[frank spruce]

what now 😭

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[frank spruce]

.close

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[gentle herald]

dude this is basic

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[snow thunder]

Is this right?

[sharp oak]

a) is wrong

c) is wrong

But b) is right

[snow thunder]

Is it 0

[sharp oak]

a) should be 0 yes

[snow thunder]

I’m confused on c

@sharp oak

<@&286206848099549185>

[prime loom]

Think about what the idea of intersection means

[snow thunder]

3?

[prime loom]

That is not what the idea of intersection is

[snow thunder]

Where both the g and f meet

[prime loom]

Ye so where are those points

On that graph

[snow thunder]

3 and 1

[prime loom]

You must give the corresponding y value for it to be a point

[prime loom]

(3,) and (1,)

[snow thunder]

-2,3 and 1,0

[prime loom]

Right my bad

So now what does the point mean

What does a point on a line mean

[snow thunder]

Where they intersect

[prime loom]

I mean yeah but you can go further than that

Do you know how to convert a point to a table

Or a list of points

[snow thunder]

Yea

[prime loom]

Then do that

[snow thunder]

Oh nvm I don’t

[prime loom]

Here this might help

A point can be defined as an x value with its corresponding y value

So if you have some y_1 = f(x_1) then that specific point would be (x_1,y_1)

[snow thunder]

I don’t get it

[prime loom]

(-2,3)

Would be 3=f(-2)

[snow thunder]

OOHHH now I get it

[prime loom]

The intersection point is where they are equal to each other

Cause you get the same values on the functions

Which is true for any 2 or more functions that intersect

Hope that helps

[prime loom]

Ye so both f(-2) and g(-2) = 3 same goes for f(1) and g(1)=0

[snow thunder]

Oh alright thanks!

[prime loom]

So the values of x such that f(x) =g(x) are x = -2 and x= 1

[snow thunder]

That makes sense thank you for the help!

[prime loom]

No problem

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[polar crystal]

So I'm trying to simplify (1+ tan^2 x)(1-sin^2 x) but couldn't so I found a video and saw a comment with an easier but I don't understand it. Our answer key says the answer is 1 but I can't figure out how the teacher did it

[polar crystal]

This is what we're using except the cofunction identities

[timid cairn]

Which part of the comment don’t you understand

[polar crystal]

how multiplying them together crosses out the denominator

[timid cairn]

Both of the identities in the comment are in here

[timid cairn]

cos^2(x) * 1/cos^2(x) ? Yea it cancels

[polar crystal]

oh my god

im washed. ive been doing my hw for 4+ hours i didnt even see that simple simplification

thank you

😭

[timid cairn]

lol you’re good

Happens

[polar crystal]

.close

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[gray shuttle]

when i sub in pn=cn2*n i end up with a LHS of zero

am i doing smt wrong or is it the q?

[timid cairn]

Uh how are you subbing that in I don’t understand

[gray shuttle]

bc when the recurrence is in that form we sub pn=cn2*n right

hol on i think i made a mistake in subbing

yep my b lol

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[simple drift]

Didn't get that modulo 8 part..:/

Like where it states $3^m+3^n=0 (mod 8)$

[clever fjord]

ideal_37

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[steep dagger]

need help with a little bit of trignometry

[steep dagger]

I found this on instagram

h2 and h1 are "yaw" values
yaw is how much a player is looking left and right

b is the number of blocks from coordinates (0,0)

but whats the logic behind it

[fresh ruin]

something like this

at least to explain the tan(h1)-tan(h2) part

[steep dagger]

oh thanks

.close

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[mystic saffron]

How do I do c? (Blue circle)

The fraction is confusing me

Never seen that before

[zenith tartan]

it doesnt really matter

just put different values of x and see what values of y u getting

its gonna be a straight line

[mystic saffron]

@zenith tartan

[zenith tartan]

oh mb lol i didnt saw that

[potent sphinx]

First of all the x coordinates of every point is going to double

And the y coordinate of every point sign will change

[mystic saffron]

But I’m confused by the blue circle fraction bro

How do I get it into normal form?

[mystic saffron]

Like how all the other questions (a,B,d) are

@zenith tartan @potent sphinx

[zenith tartan]

i'm sorry but i havent studied graph transformations yet

[potent sphinx]

The x/2?

[mystic saffron]

Yeah

That’s what’s confusing me

I don’t know what to do

@potent sphinx

[odd edge]

@mystic saffron Has your question been resolved?

[mystic saffron]

@potent sphinx

Please bro someone help

<@&286206848099549185>

.close

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[mystic saffron]

where

are you stuck

[steady tide]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[lapis oasis]

i dont know where to begin

like the approach

could you perhaps hint me the start of the approach, and ill try solving it, if i need more help ill ping you? if that works for u

[chilly remnant]

just take the derivative lol

[lapis oasis]

☠️ -

[chilly remnant]

for e^f(x)

the second x^n, just bring the n to the front and minus the exponent by 1, giving n*x^(n-1)

so on.

[lapis oasis]

damn what

[lapis oasis]

i never knew this

thank you

[chilly remnant]

do you know all the derivative formula?

[lapis oasis]

um

i know the basics

veryyy basics

[chilly remnant]

yeah just apply the rules. all you need is power rule and e for this

[lapis oasis]

wait

this is the power rule?

[lapis oasis]

i dont know what this is

[lapis oasis]

this is okay

[lapis oasis]

what is this though

[chilly remnant]

your equation e^(a+b+.....), (a+b+....) is a function

[lapis oasis]

okay, understood

[chilly remnant]

just take the derivative of that and bring it to front

[lapis oasis]

mhm

[chilly remnant]

and leave e the same

[lapis oasis]

okay

[chilly remnant]

from this rule

[lapis oasis]

is that another derivative rule?

[chilly remnant]

no you just need those two for this question

[lapis oasis]

nono,

what im askin gis

[lapis oasis]

is this a rule?

[chilly remnant]

there are product rule and quotient rules

yes

[lapis oasis]

oh

well

[chilly remnant]

and there is product rule

[lapis oasis]

i know 2 power rules

e^x is just e^x

[lapis oasis]

but if its something like

constant^x

let constant be a

a^x = lna + a^x

[chilly remnant]

ah

[lapis oasis]

isnt it this

[lapis oasis]

cuz i dont know how u got this 🫠

[chilly remnant]

the e function for your question

taking the derivative uses that rule

[lapis oasis]

oh

shi man

how would i know

[chilly remnant]

it asked dy/dx

[lapis oasis]

that i was supposed to use this

[lapis oasis]

yes

[chilly remnant]

well they shouldve gave you the rules. otherwise you woulda used first principles 😂

[lapis oasis]

i mean they gave us rules and principles

but this is alien to me

[chilly remnant]

well you can ask why the teacher gave you that without teaching you. but that's the derivative rule

there's also one for natural logarithms ln

[lapis oasis]

can u send that too 🙏

[lapis oasis]

isnt lnx just 1/x

[chilly remnant]

lemme pull it up

[lapis oasis]

and btw, in questions of derivations, if they just give log (without specifying base), do we assume its the natural base (e)

[lapis oasis]

ight man

[lapis oasis]

i got the answer btw :)

[chilly remnant]

yeah great!

[lapis oasis]

okay..

um i have one more doubt

[chilly remnant]

just ask your teacher. this isnt hard to remember

[lapis oasis]

its apparently something called implicit differentiation

if they give us

x^2 + y^2 = 9

find y' and x'

[chilly remnant]

start a new channel for that 😂 i dont even know lol

or watch yt

anways if you're finished,

!done

[odd edge]

If you are done with this channel, please mark your problem as solved by typing .close

[lapis oasis]

yeah

i was

but i cant understand

https://youtu.be/M0SMSWM2oZA?si=ggosdTlZ8yHBGigV

he did something from timestamp (2:51 to 4:00) which i dont understand

if you have the time please do check it out

[chilly remnant]

lemme see

[lapis oasis]

thankyou

[chilly remnant]

yeah start a new channel 😂

good luck though

[lapis oasis]

☠️

thankyou for your time 🫶

,close

[chilly remnant]

np

[lapis oasis]

oops

.close

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[mystic saffron]

Hey I need help with 6b I tried to use the table from the parent graph and then transform it but it didn’t work out as u can see can someone teach me how to graph B

[odd edge]

@mystic saffron Has your question been resolved?

[chilly remnant]

i think c has a modulus.

confirm this please

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[granite root]

Question 6 a. Please

[merry kestrel]

What have you tried?

[granite root]

I'm just completely unsure on how to solve it

[honest turtle]

Cancel out the common ones, like 2 and x.

[fluid tundra]

you want to move everything to one side of the equation (so you can start by subtracting 16x from both sides, for example)

then, you want to try to factor the expression you have

[granite root]

Ah ok thanks everyone

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[thorn radish]

Just have no clue on this one

[odd edge]

@thorn radish Has your question been resolved?

[thorn radish]

<@&286206848099549185>

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Use .reopen if this was a mistake.

[thorn radish]

.reopen

[odd edge]

✅

[thorn radish]

Sorry thought I knew

How am I meant to find the velocity?

Wait

So do I just find the displacement as according to my diagram, and then i just chuck that over 1 second

And that’s the velocity

[dusk spire]

ok

wait a sec

[swift rock]

just use head to tail rule to find resultant velocity

[thorn radish]

What’s that?

[dusk spire]

put arrows on the end of your lines

to show where they are going

[swift rock]

search it , it would be better for ur understanding

[dusk spire]

and put the "head" of one arrow to the head of the other

[thorn radish]

Thanks

[dusk spire]

then use sine rule/pythagorus to solve for the velocity

[thorn radish]

Like that

Right?

[dusk spire]

no

you have to move one of the lines from the origin

that does technically work to get the velocity but you need to get the direction too

[odd edge]

@thorn radish Has your question been resolved?

[thorn radish]

I’ll just look it up thanks

[odd edge]

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[hybrid gyro]

Why cant we take r=-5/2?

[wooden pasture]

the sum of an infinite series is only $\frac{a}{1-r}$ if $|r| > 1$

[clever fjord]

math X meth ✓

[wooden pasture]

wait wrong symbol

[wooden pasture]

incorrect

the sum of an infinite series is only $\frac{a}{1-r}$ if $|r| < 1$

[clever fjord]

math X meth ✓

[wooden pasture]

this

[hybrid gyro]

For it to be convergent? Also nice name

[wooden pasture]

yeah

but $|\frac{-5}{2}| > 1$

[clever fjord]

math X meth ✓

[wooden pasture]

damn why text so big

[hybrid gyro]

Look at case 2

So for divergences it has to be greater?

[wooden pasture]

yes

[hybrid gyro]

Okay

Thanks for the meth help

[wooden pasture]

anytime

[hybrid gyro]

.close

[odd edge]

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[odd edge]

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[wraith schooner]

Anyone knows how how can I use comparison test on improper integrals of type 2? For example for D

[odd edge]

@wraith schooner Has your question been resolved?

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[elfin warren]

"The function f at its critical point a has the quadratic form Q(h), so that f(a+h) = f(a)+ 12!Q(h).
Determine the signature of the quadratic form Q(h) and determine whether a is a local extremum or not, if..."

[elfin warren]

am i right in thinking that a has a local maximum point?

[odd edge]

@elfin warren Has your question been resolved?

[odd edge]

@elfin warren Has your question been resolved?

[elfin warren]

haha i am still on this

but its the last question thankfully!

[wanton bison]

I also have no clue either

I might ask my professor for a hint

I find this intersting

[elfin warren]

its just the quadratic form that is hard

yes please!

[wanton bison]

I find hard to interpret what they mean with h

[elfin warren]

yes i know he always writes his questions weird

[wanton bison]

Q(h,k) to Q(h)

I will ask him this evening and tell you 😅

[elfin warren]

okay thank you!

its not due until tomorrow at midnight

[wanton bison]

Why dont you ask your professor also

The one who created it lol

If there is confusion

[elfin warren]

haha yeah your right i could ask him tomorrow

[wanton bison]

Yea do that

We may compare

I find your tasks interesting and sometimes challenging

[elfin warren]

yes, i just find them challenging haha

i honestly think you just need to look a the leading term in front of h^2. if its positive it has a local minimum point and if its negativ it has a local maximum point

[elfin warren]

.close

[odd edge]

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[acoustic grotto]

can someone please help me with this question?

[tepid pelican]

sqrt(3) / 3 is strange tbh

[mystic saffron]

Maby is over 2

[tepid pelican]

sqrt(3)/3 is far less than 2, the problem here is that the angles alpha and beta wont have a nice form

[mystic saffron]

Did not mean this but okay.

[acoustic grotto]

wdym

[gritty oar]

cos(a) / tan(b) = cos(a)cos(b)/sin(a) = [cos90 + cos0]/(2sina) = 1/(2sin a)

[tepid pelican]

seems incorrect?

[gritty oar]

wait

a-b isn't 0

[tepid pelican]

a+b is 90 tho

[gritty oar]

[cos90 + cos(a-b)]/(2sina) = cos(a-b)/(2sin a)

[tepid pelican]

i think this is overcomplicating it a bit

let the angles be a and b

[gritty oar]

oh

yeah your approach faster

[tepid pelican]

then since a + b + 90 = 180, we can say b = 90-a

so sin(a) / tan(b) = sin(a) / tan(90-a)

and note that tan(90-a) = cot(a)