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#help-19
odd edgeBOT
Available help channel!
mental marten
odd edgeBOT
mental marten
can someone help
steady tide
elfin zodiac
Do you know any theory implicit in your exercise?
mental marten
kinda
just help me pls
imma get beaten up
plssss
fasttt
i dont wanna get my butt whooped
green elm
someone will whoop your butt if you don't solve this?
mental marten
yes
my ada
dad
he gonna pull out that ancient belt
spank me with the BUCKLE
cause he angry
i was playing games while solving this
mental marten
im srry 😭
faint knot
i was playing games while solving this
(also thats your fault)
now youre trying to find a way to figure this out
thats good so far
faint knot
have you drawn the rhombus and the triangle yet
mental marten
no
mental marten
ok
faint knot
do you know how to draw a rhombus
faint knot
I havent seen the picture yet but thats promising
mental marten
leading to 3.5/7=2.5/5=?/8
faint knot
ooh
gaunt coral
hey guys~!
green elm
can you screenshot your picture? i'm too lazy to draw my own haha
faint knot
the triangle is scalene
gaunt coral
are the parallel lines in the rhombus
faint knot
so it wont be half
gaunt coral
the triangle is scalene
no one said that
faint knot
its given in the problem
gaunt coral
?
mental marten
??
gaunt coral
buddy idk waht ur saying
faint knot
anyways heres the picture
gaunt coral
cant the rhombus be in the other direction
faint knot
wdym
odd edgeBOT
mental marten
literally
odd edgeBOT
Available help channel!
mystic saffron
odd edgeBOT
mystic saffron
please show me how to do this I have no idea.
cold sage
is that fib, what a fellow
try looking at terms in threes and see what you can notice about the third term related to the first two
mystic saffron
the first two are both ones? and the third is just 2 i cant really see anyhting here
thers something about subtracting the second and first term but its different for all
ohh wait
a1+a2 = a3
but how do i convert this to an equation
mystic saffron
yeah but like how to convet to recursive cause i cant just but a1+a2=a3
clever fjordBOT
hayley!
mystic saffron
but what you want is a formula for $a_n$
how do i convert it?
viscid flint
uhhh
ok you have a1+a2 = a3
which is well and good for a3
but what about the rest of the sequence?
like
what about a4?
mystic saffron
a3+a4=a5 💀
viscid flint
do you see a pattern?
mystic saffron
yes
mystic saffron
uhh is the answer Fn = fn-1 + fn-2
viscid flint
yeah
mystic saffron
my friend told me but i didnt learn this yet
viscid flint
we were almost there
mystic saffron
thanks tho
viscid flint
can you at least see how you can use that formula
mystic saffron
w teacher for giving a question that i never learnt
viscid flint
to come up with the things you wrote?
odd edgeBOT
viscid flint
w teacher for giving a question that i never learnt
math is about applying things you know to new situations
odd edgeBOT
Available help channel!
bold shard
The problem and associated work is shown in the images. I do not understand what to do after getting the change in height over time (dh/dt). Supposedly the answer is 2/pi cm^3. Please let me know if you have any questions and I will respond as quickly as possible. This is related rates in Calculus 1 btw.
rare glade
The problem and associated work is shown in the images. I do not understand what...
Did you setup the relationship between the height and the radius?
bold shard
hey there! yeah, I believe it is r = (1/3)h, then I plugged it into the volume formula.
rare glade
hey there! yeah, I believe it is r = (1/3)h, then I plugged it into the volume f...
for the third step, would it 1/9 * h^3?
because it seemed you squared just the 1/3, not the h
bold shard
yes; my bad, it looks like a 2, but it is actually a 3. i wrote h^3 better on the step after that
rare glade
oh
bold shard
in the question it gives me that the volume of the water in the cup is 27pi cm^3 but Im not sure where I include that information
rare glade
well, from how I see it, height always stays constant
the radius changes as you move up and down the cone
so with 27, i think you need to solve for something
bold shard
well, from how I see it, height always stays constant
it is asking me what the change in height is, not radius, so idk
bold shard
so with 27, i think you need to solve for something
yup
rare glade
yup
oh, I think you need to solve for H when the volume is 27, ignore what i said earlier when H is constant
bold shard
oh shoot, lemme try that
ok so i got 9/100pi = h after substituting r with 30, so where do i plug that in?
rare glade
i got h = 9
rare glade
oh, i subbed the relationship between r and h with h, so I said h = 3r
bold shard
hmm
bold shard
oh fr??
bold shard
so instead of doing r in terms of h it's the other way around?
bold shard
interesting, I guess I am just confused as to why I can't do r = h/3, because it should still work..
rare glade
i mean, your dealing with a fraction there, it is possible, but its simpler to work with 3r instead of h/3
rare glade
yes
bold shard
yeah got the right answer finally! ty
rare glade
np
bold shard
.close
visual bison
The volume of a right circular cylinder is 12pie in³
(a) Express the height as a function of the radius.
visual bison
I know we want h(r), but I have no idea where to start
leaden widget
what's the formula for the volume of a circular cylinder?
visual bison
V = 1/3pie r²h
leaden widget
its PI not PIE
visual bison
IM SORRY
leaden widget
lol relax, just letting you know : )
visual bison
Wait I kinda know what to do
Ik we can divide PI on both sides
Then isolate for h
leaden widget
V = 1/3pie r²h
nope not quite
visual bison
But would I plug that back into the volume formula
leaden widget
it's just $V=\pi r^2h$
clever fjordBOT
Soosh
leaden widget
not sure where the 1/3 came from
visual bison
ITS A CYLINDER IM DUMB
leaden widget
maybe youre thinking of a pyramid or something
visual bison
I WAS LOOKING AT A CONE
leaden widget
anyway the V equation has r and h, now just solve for h (since you want an equation for h in terms of the other stuff)
visual bison
Ik h = 12 - r², but now I don't know where to plug h into. Would I just plug it into the volume equation to have:
H(r)= PIr²(12-r²)
clever fjordBOT
Soosh
leaden widget
$12=\pi r^2h$
clever fjordBOT
Soosh
clever fjordBOT
Soosh
leaden widget
and done...
leaden widget
wdym
visual bison
Wait is that it 😭
leaden widget
yeah, the problem wanted h expressed as a function as r, that's what we have isn't it?
$h(r)=\frac{12}{\pi r^2}$
clever fjordBOT
Soosh
visual bison
Soosh I want you to know your kinda helpful (thank you so much)
visual bison
Have a good day, and I hope to never see you again (THIS IS NOT MEANT IN A MEAN WAY I JUST HOPE THAT I UNDERSTAND MY MATH SO WELL I DON'T NEED HELP FROM YOU AMAZING PPL)
.close
odd edgeBOT
odd edgeBOT
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strange drum
odd edgeBOT
strange drum
am i right?
strange drum
for the 1st one im assuming in the 2nd inductive step the + will be =?
what?
scenic imp
i'm facing some difficulties understanding what u wrote for the 1st problem
strange drum
- is addition
odd edgeBOT
@strange drum Has your question been resolved?
odd edgeBOT
@strange drum Has your question been resolved?
rain tundra
Can someone help me out with (7)?
odd edgeBOT
Can someone help me out with (7)?
teal mirage
Hey, let me try to help you out
Did you already try something? Or were you unsure how to get started?
rain tundra
Did you already try something? Or were you unsure how to get started?
I'm unsure how to even get started
teal mirage
Okay, no worries. I'm assuming these questions are part of a chapter on number theory?
rain tundra
Nope, these are questions from chapter - Mathematical Reasoning and proof techniques
teal mirage
Ah okay!
Often when you need to prove something relating to integers specifically, it's useful to take a look at divisibility of those numbers
In the given equation, the only thing that really stands out is the 3, which tells you that the RHS must be divisible by 3, what does that tell you about the LHS?
rain tundra
LHS must be divisible by 3?
teal mirage
yup, what does that tell you about x and y?
teal mirage
That's true! But it isn't immediately obvious. We surely must have that either both of them are divisible by 3, or neither.
it turns out that 'neither' is impossible, but you'd need to prove that as well
rain tundra
hmm square of x is either of the form 3k or 3k+1, same for y, in case both are of the form 3k, resulting sum will be of the form 3k too, if both of the form 3k+1, resulting sum will be of the form 3k+2, if one of the from 3k, and other 3k+1 resulting sum will be of the form 3k+1, so only case one is valid?
teal mirage
Looks great!
So we now know that if the LHS is divisble by 3, both x and y are divisble by 3
rain tundra
Yup
teal mirage
Can we say anything more about the LHS at this point?
rain tundra
It is always positive?
teal mirage
Definitely, but also, since both x and y are divisble by 3, we have that x^2 and y^2 are divisble by 9
rain tundra
Ohh yeah how did I miss that
hmm so RHS must be divisible by 9 as well, that means z is also divisible by 3
teal mirage
yup!
rain tundra
We are moving in circles haha
teal mirage
exactly
rain tundra
Ohh I get it, what they meant by using infinite descent
teal mirage
nice!
rain tundra
Though it was fairly non trivial
teal mirage
It's a challenging proof if you've seen nothing like it before
teal mirage
You're very welcome!
rain tundra
.close
odd edgeBOT
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slender rampart
How can i solve (x^x-y^y)/(x-y)=0? i solved for x^x=y^y but only got one solution x=y but that obviously cant be a solution since the denominator is x-y here
quasi sparrow
How can i solve (x^x-y^y)/(x-y)=0? i solved for x^x=y^y but only got one solutio...
(x^x-y^y)/(x-y)=0
why do you need to solve this
odd edgeBOT
@slender rampart Has your question been resolved?
mystic saffron
Hey guys, I dont understand what's required of me. I dont need the answer or anything I just need someone to explain what I am required to do in part a because I don't know what they mean by "show that"
mystic saffron
<@&286206848099549185>
late flint
you just take the derivative of the function and show that it is the same as what was requested
mystic saffron
but its not the same
limber glade
and if you're wondering how to do it, use the product rule
mystic saffron
I already found y' and its not the same as whats being requested
am I doing something wrong orrr?
odd edgeBOT
limber glade
that was quick
mystic saffron
yep, im solving iit wth my friend and he just sent me a message abt it thats why
limber glade
iit?
odd edgeBOT
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mystic saffron
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odd edgeBOT
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regal lark
odd edgeBOT
regal lark
I'm unsure of how to do part b
normally my likelihood function would be L(\lambda) = \Pi_{i=1}^n \lambda e^{-\lambda x}
how would that change for b
I can go from there on my own
would I just change every lambda to 1/lambda?
odd edgeBOT
@regal lark Has your question been resolved?
odd edgeBOT
@regal lark Has your question been resolved?
strong knoll
how to solve trusses
odd edgeBOT
how to solve trusses
odd edgeBOT
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pure talon
odd edgeBOT
pure talon
I spent an hour deriving a formula and used substitution just for it not to work
I used m = Z* ((X-μ)/(σ/sqrt(n))
I found that sqrt(n) = mσ/Z*(X-μ)
and (X-μ) = m(sqrt(n))/Z*σ
so substituting the new (X-μ) into our derived sqrt(n) formula:
sqrt(n) = (m* σ)/Ζ* divided by m* sqrt(n)/Z*σ
which we then just multiply that by the reciprocal we get sqrt(n) = σ^2/sqrt(n)
which we then multiply out sqrt(n) by sqrt(n) to get that n = σ^2
odd edgeBOT
@pure talon Has your question been resolved?
odd edgeBOT
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formal bane
Give the real numbers of x from the interval [π;2π]:
sin x = 1/√2
cos x = 1/2
sin x = -1/2
cos x = -√3/2
formal bane
how do i solve this
sullen ferry
,tex .unit circle
clever fjordBOT
🫎 Moosey (MSC2020 55N31) 🫎
sullen ferry
pi to 2pi is the bottom half of the unit circle
formal bane
pi to 2pi is the bottom half of the unit circle
isn't it the full circle ?
sullen ferry
[0, 2pi) is full circle
formal bane
ahhh you're right
formal bane
and now what ?
sullen ferry
well first you have sin(x)=1/sqrt(2)=sqrt(2)/2
there's an issue if it's goin from pi to 2pi
formal bane
what is it
sullen ferry
there would be no solution in real numbers, as sin is always negative in this region (the y-coordinate)
formal bane
maybe the question is wrong ?
sullen ferry
so either the question has no solution as valid answer, or the question itself is phrased wrong/quoted wrong
if it's sin(x)=-1/sqrt(2) then it would have solutions
sullen ferry
**🫎 Moosey (MSC2020 55N31) 🫎**
look at this
do you see any y-coordinates with (-sqrt(2)/2)
formal bane
the 5pi/4 ?
sullen ferry
I see two, now look at the angle they correspond to
sullen ferry
the 5pi/4 ?
this is one angle yes
formal bane
am i blind or there's only one coordinate with (-sqrt(2)/2)
sullen ferry
look past 3pi/2
to the right
and remember I said y coordinate, so the second number
formal bane
**🫎 Moosey (MSC2020 55N31) 🫎**
i don't think they want me to go look in a circle with these ready angles and all
i'm probably supposed to calculate them
is it possible to do so ?
sullen ferry
you can do some triangle drawing yeah
and you should at least know the sign of cos/sin in each quadrant since they coorespond to x and y coordinates on unit circle
odd edgeBOT
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edgy flame
can somebody quickly explain what happened here? i cannot understand
fervent hound
they factored ln(1-x)
$x\times\ln(1-x)-\ln(1-x) = \left( x-1\right)\times \ln(1-x)$
clever fjordBOT
Adam Chebil
edgy flame
i know it's some sort of factorization, but why does it turn into (x-1)?
fervent hound
expand this : $\left( x-1\right)\times \ln(1-x)$
clever fjordBOT
Adam Chebil
edgy flame
thing is i don't know how this would be expanded
idle vessel
@edgy flame consider the distributive property a * (b+c) = ab + ac
now let a = ln(1-x), b = x, c = -1
edgy flame
... i'm still having trouble figuring it out...
fervent hound
can you distribute this : $A\times \left( x-1\right)$
clever fjordBOT
Adam Chebil
edgy flame
xa-a
fervent hound
now replace a with ln(1-x)
edgy flame
ln(1-x) . (x-1) = ln (x-1-x^2-x)
i think i'm doing it wrong, the ln confuses me
i don't think it's supposed to be squared right?
fervent hound
you know ln(x+1) is a composite function right ?
how would you distribute (x-1) * ln(x)
edgy flame
forgive my ignorance, what's a composite function?
how would that affect the distribution here?
idle vessel
forgive my ignorance, what's a composite function?
how would that affect the dis...
a composite function is basically a "function within a function"
so basically here the (1-x) function is "inside" the ln() function
edgy flame
a composite function is basically a "function within a function"
so basically he...
alright, so what should i distribute here then?
the ln is throwing me off
idle vessel
ln(1-x) . (x-1) = ln (x-1-x^2-x)
i think i'm doing it wrong, the ln confuses me
so you cant multiply (1-x) (x-1) directly like you did here, because the 1-x is "inside" the ln()
idle vessel
xa-a
the distribution is basically what you did here, but instead of a you have ln(1-x)
so (x-1) * ln(1-x) you "distribute" the ln(1-x) to the first term resulting in x * ln(1-x) and to the second term resulting in -1 * ln(1-x)
adding them together, you get xln(1-x) - ln(1-x)
edgy flame
oh i get it
so you basically just "move" the number behind in a way that it multiplies
idle vessel
so you basically just "move" the number behind in a way that it multiplies
wait wdym
edgy flame
wait wdym
so like (x-1) * ln(1-x)
you said that it results in x*ln(1-x) -ln(1-x)
so basically it moved behind it
idle vessel
so like (x-1) * ln(1-x)
you said that it results in x*ln(1-x) -ln(1-x)
so basica...
ig you can think of it that way yeah
the important thing to remember is that its the distribute property: a(b+c) = ab + ac
edgy flame
the important thing to remember is that its the distribute property: a(b+c) = ab...
yes, it's just the composite function that confused me
anyways, i understand it now
thank you!
@fervent hound sorry for pinging you, thanks!
.close
odd edgeBOT
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copper hedge
need help with # 53
odd edgeBOT
need help with # 53
copper hedge
not sure where to start
strange estuary
what are you supposed to be solving for?
copper hedge
Find the volume of the solid generated when R is
revolved about the given line.
odd edgeBOT
@copper hedge Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
lyric lintel
Hwkp
lyric lintel
Help*
How come this dont work:
And then to end off i would set equation equal to 0 then use quadratic formula
But doesnt work so one of my above steps is wrong
Plz lmk if u cant read my writing
leaden widget
hm, all you have to do is crunch the numbers on the right side of the equation, you already have B = blah blah, why are you moving B around to the other side etc.?
just evaluate the right side using a calculator
lyric lintel
Idk if my teAcher wanted us to square both sides
Cause that what we learning
But ic what u mean
leaden widget
don't, then you'll have just get B^2 = something and to solve for B you need to take the square root anyway
lyric lintel
But anyways why do i get a wrong
Answer
I will change my steps and just calculate
leaden widget
just stick 1.33 sq(50) - 3.49 in a calculator
leaden widget
because you didnt do that on the paper? you did...i dont even know what
lyric lintel
But it should wrk no?
Jus time wasting
But mathematically should wrk
Thas y im confused
Jus wna understand it
🙏🏽
leaden widget
i dunno im too lazy to check the numbers for work that doesn't make sense to do
leaden widget
13.3 defintielys seems wrong since the scale goes from 1 to 12 and 40km/h isn't particularly strong
leaden widget
just stick that in a calculator and youre done, i dont know what else to tell you
rounds up to 6 as you say
whole bobcat
Yo I have a question is statistics harder or pre calc
leaden widget
your way makes no sense, stop being attached to it just because you spent time on it is my advice
leaden widget
Yo I have a question is statistics harder or pre calc
!occupied
odd edgeBOT
Yo I have a question is statistics harder or pre calc
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
lyric lintel
But to me it makes sense
Can u explain
Y
Like when u say it dont make sense ur jus saying time wasting right?
leaden widget
But to me it makes sense
because you literally have B = whatever that's the ultimate goal when you are solving for B, any manipulations with moving B to the other side etc. is undoing the whole point of sovling for B lol
the equation is already solved for B
lyric lintel
Im jus making it a quadratic equation
leaden widget
anyway good luck, im moving on
lyric lintel
O
odd edgeBOT
@lyric lintel Has your question been resolved?
zealous dragon
There's a parabolic tunnel with a width of 20m and a height of 15m. What's the max width a truck can be to pass through if it's height is 10m
odd edgeBOT
@zealous dragon Has your question been resolved?
odd edgeBOT
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final wind
odd edgeBOT
mystic saffron
change cos 3/2pi + x to sinx and apply sin2x
final wind
ok so I got the first step
changing to sinx
I know that
but I don't know apply sin2x
mystic saffron
sin2x = 2sinxcosx
mystic saffron
ye
final wind
ok and then
final wind
ye
mystic saffron
nice
final wind
ye
mystic saffron
and set a random angle as a/2
mystic saffron
and get sin and cos
final wind
just got it
mystic saffron
ok
mystic saffron
nice
mystic saffron
square rooting and checking the angle
mystic saffron
nice
final wind
so my teacher made a typo?
mystic saffron
ye
mystic saffron
nice
final wind
.close
odd edgeBOT
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night rapids
odd edgeBOT
odd edgeBOT
@night rapids Has your question been resolved?
odd edgeBOT
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azure heron
How did we get from the upper row to there simplified ?
low locust
add 2x on both sides
azure heron
add 2x on both sides
Like?
low locust
wdym like
azure heron
add 2x on both sides
Where do you add the 2x
low locust
to the left side and to the right side of the equation
azure heron
to the left side and to the right side of the equation
are you allowed to do that, isn’t it supposed to go - when you add it after = ?
low locust
not sure what you mean
you can do whatever you want basically. as long as you do the same thing to both sides
you can also add 17 on both sides
or multiply by 4013
tho both of these steps arent really helpful
odd edgeBOT
@azure heron Has your question been resolved?
feral bone
(I'm new to combinatorics) How do I solve it?
I first thought that we somehow need to account for repeated outcomes, but it seems that there aren't any? (assuming we calculate it by 6^5)
supple cloak
(I'm new to combinatorics) How do I solve it?
I first thought that we somehow n...
yup, it's just $6^5$ here. there are no repeated outcomes because each sequence of rolls is considered its own distinct result
clever fjordBOT
Awesam
feral bone
yup, it's just $6^5$ here. there are no repeated outcomes because each sequence ...
thank u! 
.close
odd edgeBOT
feral bone
what's wrong with my solution? (the answer should be 4500)
First pick any digit from the list {0, 2, 4, 6, 8} which will be our last digit. There are 5 possiblities. For the next digit, we can choose from |{0, ..., 10} \ {0, 2, ..., 8}| = 5 possibilities. Then from 4 and then from 3
Hence the answer should be 5 • 5 • 4 • 3 = 300 << 4500
feral bone
.reopen
odd edgeBOT
✅
supple cloak
what's wrong with my solution? (the answer should be 4500)
First pick any digit...
for the second-to-last digit there are 9 possibilities, not 5. and then 8 for the next not 4, etc. but you also need to be careful to make sure the first digit isn't 0
odd edgeBOT
@feral bone Has your question been resolved?
feral bone
for the second-to-last digit there are 9 possibilities, not 5. and then 8 for th...
ooooouch, yeah, since we choose only 1 from those even endings. gotcha. thank you!
I guess I gotta learn how to count 😂
.close
odd edgeBOT
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vagrant kelp
Why is my method wrong?
odd edgeBOT
royal herald
ur not him
sharp oak
I am not
spiral basalt
<@&268886789983436800> may we accelerate how long this person is taking to find the leave server button ?
blazing shuttle
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lime vessel
Can someone please check if i am doing this correctly?
odd edgeBOT
Can someone please check if i am doing this correctly?
@lime vessel Has your question been resolved?
odd edgeBOT
@cloud pollen Has your question been resolved?
cloud pollen
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primal minnow
I’m stuck on the expressions circled in blue
odd edgeBOT
I’m stuck on the expressions circled in blue
primal minnow
odd edgeBOT
@primal minnow Has your question been resolved?
primal minnow
yea, i solved it myself :/
inland tartan
Could someone tell me what I'm doing wrong in this please
forest sky
they may also want the indexing to start at 0?
amber schooner
that too
inland tartan
maybe make the ratio -2/3
that's what it was originally
oh wait nvm this is correct
what i typed in
i submitted again and it said it was correct
can you guys help me with one more quetison please
nvm it's skewed
so there isn't an intesection point
thanks tho
have a good night
thorn palm
!done
odd edgeBOT
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@inland tartan Has your question been resolved?
bold aurora
odd edgeBOT
bold aurora
am I correct to make these assumptions
or is it not injective as x_1 can be positive or negative x_2
odd edgeBOT
@bold aurora Has your question been resolved?
supple cloak
or is it not injective as x_1 can be positive or negative x_2
it's not injective because for example $f(1) = f(-1)$. you went wrong when you assumed that $\pm x_1 = \pm x_2 \implies x_1 = x_2$
clever fjordBOT
Awesam
bold aurora
it's not injective because for example $f(1) = f(-1)$. you went wrong when you a...
thanks
.close
odd edgeBOT
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desert marlin
odd edgeBOT
desert marlin
For this, I want to say like
let lambda be an eigenvalue of T with eigenvector v then Tv=lambda v
and then,
T'(phi(v))=phi(T(v))
So,
T'(phi(v))=phi(T(v))=phi(lambda v)=lambda phi(v)
then lambda is an eigenvector of T' with eigenvector phi(v)
but I have a doubt because
phi(v) is technicically a field element if we're evaluating at v, so not a vector in V'
and it feels like the eigenvector needs to be more specific than just any linear functional
Am I mistaken?
leaden widget
but I have a doubt because
don't doubt sir
leaden widget
can you remind me what a dual operator is?
desert marlin
can you remind me what a dual operator is?
T' is a linear map from V' to V'
and V' is the space of linear functionals from V to F
odd edgeBOT
@desert marlin Has your question been resolved?
desert marlin
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desert marlin
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tender carbon
odd edgeBOT
tender carbon
in khan academy there have different formula:
so it is the same as in my book but only without magnitude of the vector product
sharp oak
Yeah there's a few ways to express this
tender carbon
and i did this:
tender carbon
Yeah there's a few ways to express this
they are like contradicting each other
one k is scalar while another is vector
sharp oak
Looks like khan is giving it as a vector, but your book is giving it as a magnitude
tender carbon
Looks like khan is giving it as a vector, but your book is giving it as a magnit...
yes
so
these are different things
sharp oak
Kind of
tender carbon
so what to do now
sharp oak
Khan's is more general, but if you only want the magnitude of that vector, then your book's is good enough
tender carbon
ok but the definition of k is |dT/ds|
which is scalar
why all the sudden it becomes vector
modern sundial
That Khan academy formula looks wrong to me at a glance but I don't want to check it
Are you sure that shouldn't be normed in the numerator? If kappa is curvature it obviously doesn't make sense for it to be a vector
tender carbon
Are you sure that shouldn't be normed in the numerator? If kappa is curvature it...
yes i agreed. so khan is wrong
decided
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merry beacon
why is that here they add 1 to rhs but they subtract 4
odd edgeBOT
why is that here they add 1 to rhs but they subtract 4
@merry beacon Has your question been resolved?
merry beacon
why is that here they add 1 to rhs but they subtract 4
south plume
is this completing the square?
south plume
why is that here they add 1 to rhs but they subtract 4
they are essentially completing two squares at the same time
would be helpful if you showed like 1-2 lines above
merry beacon
hyperbola standard equation
south plume
no i meant
what is your question
what is confusing you
they are adding +1 to both sides but subtracting -4*4 because the +4 is inside a bracket with -4 being mutliplied
merry beacon
to complete a square the number they must be subtracted outside as well right
south plume
"outside" as in..?
merry beacon
they are adding +1 to both sides but subtracting -4*4 because the +4 is inside a...
oh
sorry i had it backwards
here
like i thought if they add 1
i thought they should subtract here
but they take it to the other side so it becomes +1
ty u helped me understand it
.close
odd edgeBOT
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spring pebble
Hello can someone explain how to define X in:
2x (3x-1) = 10?
frigid canopy
you mean find x?
spring pebble
Yeah
leaden karma
Bring everything to one side first
And expand the brackets
Also you can cancel a 2 on both sides
spring pebble
But 2x multiplied by 3x is 6x² so it's not possible to solve this
leaden karma
Why not?
spring pebble
I'm in 8th grade by the way
leaden karma
But can’t I turn this into 2x(2x)
No in fact you cannot
languid horizon
I'm in 8th grade by the way
You are supposed to solve it by factoring?
spring pebble
You are supposed to solve it by factoring?
No
spring pebble
Holdup did you get this from a teacher or a classmate
Teacher
small sail
Original problem?
The digits go out to like the 9th decimal
No way an eighth grader solves it longhand
spring pebble
And does it say how are you supposed to solve it?
Post the brackets
leaden karma
Huh?
small sail
Solve it out yourself it goes out too long for the grade level
languid horizon
It isnt that hard
small sail
Solve it out yourself you aren’t brute forcing that
spring pebble
The problem is I didn't learn this in my school
Ik how to solve the brackets its ez but not with power
languid horizon
And how can we help?
leaden karma
Please don’t confuse OP if you don’t know the solution.
small sail
Is this homework or a challenge
leaden karma
Ik how to solve the brackets its ez but not with power
Can you expand the brackets on the left?
spring pebble
Can you expand the brackets on the left?
No I cannot
spring pebble
Yes
leaden karma
$a\cdot(b+c)=a\cdot b+a\cdot c$
clever fjordBOT
kheerii
small sail
Dude this is an eighth grader he ain’t gonna know that
languid horizon
Dude this is an eighth grader he ain’t gonna know that
He should
leaden karma
Why not?
small sail
I mean have you seen the answer
leaden karma
I don’t care what grade OP is in
I care about how much math they know
If they don’t know anything I’ll teach them
cursive field
@leaden karma with that absolute GIGACHAD mindset
leaden karma
If you don’t have anything to add to this then don’t clutter the chats
small sail
Ok but do me a favor first solve out for x and you’ll see why
leaden karma
Ok but do me a favor first solve out for x and you’ll see why
Okay the answer has a root
And?
spring pebble
So let me be more clear since some people don't understand.
2x (3x-1) = 10
So far what I know is first we multiply the 2x with 3x which gives us 6x² then 2x multiplied by -1 we get -2x so now we got so far 6x²-2x =10 But all I learned is to only solve the problem when it doesn't have power, ex: 6x-2x I can solve this but not 6x²-2x
spring pebble
Let me recheck for you
languid horizon
$$2\times (3x - 1) = 10$$
clever fjordBOT
casework
leaden karma
So let me be more clear since some people don't understand.
2x (3x-1) = 10
So ...
!original
odd edgeBOT
So let me be more clear since some people don't understand.
2x (3x-1) = 10
So ...
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
leaden karma
Please show us the EXACT original question
As in, a picture of the question
If you can
small sail
$$2\times (3x - 1) = 10$$
That’s a lot prettier
spring pebble
What if there is a mistake in interpretation
Nope
spring pebble
Please show us the EXACT original question
$$2\times (3x - 1) = 10$$
clever fjordBOT
7z09
spring pebble
No wait
leaden karma
This is much simpler
leaden karma
What?
leaden karma
As in, a picture of the question
.
spring pebble
$$2x (3x - 1) = 10$$
clever fjordBOT
7z09
spring pebble
There
leaden karma
have you been taught how to solve those?
spring pebble
No
small sail
Would you happen to have a picture of the posted question?
leaden karma
Okay
leaden karma
have you been taught how to solve those?
.
small sail
Yes but there may have been a mistake in translation
leaden karma
What methods have you been taught
spring pebble
Yes but there may have been a mistake in translation
I'm sure
Solve X is the problem
small sail
But you’re posting a quadratic when at most you would be given a solve for x
leaden karma
Solve for x doesn’t mean it can’t be a quadratic
spring pebble
But you’re posting a quadratic when at most you would be given a solve for x
There isn't
languid horizon
Do you know what a square root is?
spring pebble
You gotta solve
small sail
Solve for x doesn’t mean it can’t be a quadratic
If you were a teacher would you give an eighth grader a quadratic
spring pebble
Do you know what a square root is?
Who doesn't
leaden karma
If you were a teacher would you give an eighth grader a quadratic
I’m not a teacher, and I have no idea what country OP is in, and I don’t care honestly
Please stop bringing this up
small sail
You’re ignoring the problem of grade level
leaden karma
Have you heard of the quadratic formula?
spring pebble
No
spring pebble
You’re ignoring the problem of grade level
Its ok I learned sin cosin by myself in 10mins
small sail
The formula or the theory
small sail
Like the formulas or the why and how the formulas work
languid horizon
It is one to know what trigonometry is. It is on a whole another level to know how/when/why to use it
leaden karma
Why does trigonometry come into this?
small sail
No idea
spring pebble
Like the formulas or the why and how the formulas work
I don't know the whole quadratic
small sail
Yeah so it doesn’t make sense that your instructor would assign it
spring pebble
Yeah so it doesn’t make sense that your instructor would assign it
True. I was confused, thus I came here.
leaden karma
@spring pebble the quadratic formula states that any equation of the form $ax^2+bx+c=0$ has solutions $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
clever fjordBOT
kheerii
small sail
True. I was confused, thus I came here.
Please take a photo of the original problem it could just be an error of signs
spring pebble
You might thing it's 3 times but it's 3 X cuz it's how my teacher writes
There is a lil curve on top
Top of 3X
small sail
I have to ask are you 100% sure that 2X is actually an x or is it a different variable
spring pebble
I have to ask are you 100% sure that 2X is actually an x or is it a different va...
X
languid horizon
There is
small sail
The a,b,c are different quotients
spring pebble
Oh right sorry
small sail
It’s less confusing then saying something like x,x1,x2, etc
languid horizon
Your equation is of the form $ax^2 + bx + c = 0$ where $a , b , c \in \mathbb{R}$
small sail
Is this coursework or something he just scribbled down to give you extra work?
clever fjordBOT
casework
spring pebble
Is this coursework or something he just scribbled down to give you extra work?
I honestly have no idea
Can I just have the answer please
languid horizon
$\pm$?
clever fjordBOT
casework
spring pebble
Yeah
languid horizon
That plus/minus. It means both + and - sqrt is the solution
As quadratic has 2 solutions
Like if $x = 3 \pm 1$ that means $x = 2$ and $x = 4$
clever fjordBOT
casework
languid horizon
Its just a preference
spring pebble
It impacts the whole answer tho doesn't it?
languid horizon
Its like asking me how you would write a 4
languid horizon
It impacts the whole answer tho doesn't it?
Umm no its just how you write a symbol that does same thing in both cases
spring pebble
Am I good here
clever fjordBOT
7z09
spring pebble
Am I good here
<@&286206848099549185>
languid horizon
Am I good here
Not really
odd edgeBOT
@spring pebble Has your question been resolved?
odd edgeBOT
spring pebble
Multiply everything and move to 1 side everythin <@1000888918838874118>
How do I multiply
odd edgeBOT
Available help channel!
reef frost
i want to say its because x and z are elements of X so then like obviously a subset of X
reef frost
but i dont think its that simple
reef frost
is it not because d(x,z) less than or equal to r
low locust
why does that matter
reef frost
because that means its endpoints are included ?
low locust
what do you mean by endpoints
reef frost
like the boundary of the ball
low locust
ok and why does the boundary being included mean that the subset is closed?
reef frost
because only if all the boundary points are included in the set is it a closed set?
reef frost
uhh
i think the definition that the prof gave us for closet subset was just that its not open
low locust
and did you prove some other equivalent condition in the meantime?
also thats false
it should be that its the complement of an open set
low locust
R\U is the complement of U
reef frost
and did you prove some other equivalent condition in the meantime?
what do you mean
low locust
did you prove some lemma saying "a set is closed if and only if (...)"
low locust
also why is this over R but your question asks for a general metric space
reef frost
no 😔
reef frost
also why is this over R but your question asks for a general metric space
it was just a definition from the class notes sorry
low locust
well not the relevant definition
reef frost
i think thats all i got man
low locust
I very much doubt that. but ok I dont have your script so who knows
reef frost
i want to say its because x and z are elements of X so then like obviously a sub...
no like thats the whole question
low locust
well the question is fine. but I doubt that you dont have a proper definition for what closed means in a metric space
reef frost
unless i missed it in class or something its just that the complement is open
low locust
well ok but what does open mean in a metric space
you cant talk about intervals in a metric space
low locust
well would you look at that
low locust
and now thats the definition you have to show
again, unless you proved some other result later which might be easier to prove
reef frost
wdym
low locust
nvm
vernal pier
odd edgeBOT
vernal pier
me was stuck for a long time
leaden karma
!status
odd edgeBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
clever fjordBOT
smidgin
vernal pilot
Can you see how to being now?
clever fjordBOT
smidgin
vernal pilot
How about now?
vernal pier
damn
haven't thought like that
so then we make it all equal to cos(x) ?
like substitute i mean
vernal pilot
Yes
leaden widget
like substitute i mean
you can do u-sub with u = cos x and you have the single sin x left-over for being part of the du
vernal pilot
Yes
vernal pilot
Yes it is slightly long
vernal pilot
Why? You only need to apply power rule
vernal pier
thanks a bunch math lords
vernal pier
Why? You only need to apply power rule
ik but the starting integral was what I was stuck on
at one point i did 1/2(sin^5(x)cos^5(x))(cos^13(x))
vernal pilot
Oh to get sin(2x)?
vernal pilot
If you don't have any more questions you should close the channel
odd edgeBOT
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frosty plover
can anyone explain how Z/7Z[x] is a PID? I still dont understand how PID's work. Is it like an integral domain with unique elements?
low locust
Saturn lul
frosty plover
ikr
low locust
they could at least have asked something like N